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We use the relations :

I0=1(2Ti)1/2Z(u(2Ti)1/2),I1=1+uI0,I2=u(1+uI0),I_0 = \frac{1}{(2T_i)^{1/2}} Z\left(\frac{u}{(2T_i)^{1/2}}\right), \quad I_1 = 1 + uI_0, \quad I_2 = u(1+uI_0),

with

Z(u)=1πexp(x2)xudx=iπexp(u2)(1erf(iu)),Z(u) = \frac{1}{\sqrt{\pi}} \int \frac{\exp(-x^2)}{x-u} dx = i\sqrt{\pi} \exp(-u^2)(1 - \operatorname{erf}(-iu)),

erf(x)=2π0xexp(t2)dt.\operatorname{erf}(x) = \frac{2}{\sqrt{\pi}} \int_{0}^{x} \exp(-t^2) dt.

The dispersion relation is, putting $\phi = \phi_{m,n,\omega}$, for convenience,

A=r2ϕ(1r+rn0n0)rϕ+m2r2ϕ+1Teϕ=[1Ti(1+zZ(z))+mkrB0(Z(z)(rn0n0rTi2Ti)+z(1+zZ(z))rTiTi)]ϕ,A = -\partial_r^2 \phi - \left(\frac{1}{r} + \frac{\partial_r n_0}{n_0}\right) \partial_r \phi + \frac{m^2}{r^2} \phi + \frac{1}{T_e} \phi \\ = \left[ -\frac{1}{T_i} (1+zZ(z)) + \frac{m}{k^* r B_0} \left( Z(z) \left( \frac{\partial_r n_0}{n_0} - \frac{\partial_r T_i}{2T_i} \right) + z(1+zZ(z)) \frac{\partial_r T_i}{T_i} \right) \right] \phi,

with $k^* = (2T_i)^{1/2}k_|$ and $z = \frac{\omega}{k^*}$, and recalling that $k_| = (b_\theta \frac{m}{r} + b_z k)$. Note that the dispersion relation depends on $m$ and $k_|$ and not directly on $n$. This means that taking different values of $\iota$ and $n$ but with same $m$ and $k_|$ will lead to the same dispersion relation.

References

[1] D. COULETTE & N. BESSE Numerical comparisons of gyrokinetic multi-water-bag models. JCP 248 (2013), 1-32.

[2] J. P. Braeunig, N. Crouseilles, M. Mehrenberger, E. Sonnendrücker, Guiding-center simulations on curvilinear meshes, Discrete and Continuous Dynamical Systems Series S, Volume 5, Number 3, June 2012.

[3] N. Crouseilles, P. Glanc, S. A. Hirstoaga, E. Madaule, M. Mehrenberger, J. Pétri, A new fully two-dimensional conservative semi-Lagrangian method: applications on polar grids, from diocotron instability to ITG turbulence, Eur. Phys. J. D (2014) 68: 252, topical issue of Vlasovia 2013.

[4] X. Garbet, Y. Idomura, L. Villard, T.H. Watanabe, Gyrokinetic simulations of turbulent transport., Nucl. Fusion 50, 043002 (2010).

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