role stringclasses 2
values | content stringlengths 0 2.1k | session_id int64 10 21.7k | sequence_id int64 0 2.38k | annotations listlengths 0 8 |
|---|---|---|---|---|
student | yes | 16,307 | 67 | [] |
volunteer | Go ahead and solve it to get our answers | 16,307 | 68 | [] |
student | so once I write the equation and write what x equals am I done? | 16,307 | 69 | [] |
volunteer | Solve the equation for x. Let me know if you need help with that. | 16,307 | 70 | [] |
student | x=42 | 16,307 | 71 | [] |
volunteer | Great. | 16,307 | 72 | [] |
volunteer | What is the complement of 42 degrees? | 16,307 | 73 | [] |
student | 48 | 16,307 | 74 | [] |
volunteer | Those are your answers! | 16,307 | 75 | [] |
volunteer | You can see that one is 6 degrees different from the other | 16,307 | 76 | [] |
student | I have to go do something. Can you stay on the line and I will come back when I am done? | 16,307 | 77 | [] |
volunteer | How long will you be? | 16,307 | 78 | [] |
student | I'm not sure | 16,307 | 79 | [] |
volunteer | Well. I can wait 15 minutes. Otherwise, you can put in another request. | 16,307 | 80 | [] |
student | ok | 16,307 | 81 | [] |
student | I will let you know once I am back | 16,307 | 82 | [] |
volunteer | Ok. If it's longer than 15 minutes, just put in another request. | 16,307 | 83 | [] |
student | ok | 16,307 | 84 | [] |
student | I'm back | 16,307 | 85 | [] |
volunteer | ok | 16,307 | 86 | [] |
student | so does x only equal 1 value or 2? | 16,307 | 87 | [] |
volunteer | x is only 1 value, but the other angle 90-x is also answer to the question. | 16,307 | 88 | [] |
volunteer | x = 42, 90 - x = 48 | 16,307 | 89 | [] |
student | so would I just write "x+6=90-x" and then write "42 degrees and 48 degrees"? | 16,307 | 90 | [] |
volunteer | I would write "x+6=90-x" and the angle x is 42 degrees and it's complement is 48 degrees. | 16,307 | 91 | [] |
student | write this?:"x=42" | 16,307 | 92 | [] |
student | and then this?"One angle is 42 degrees and the other is 48 degrees." | 16,307 | 93 | [] |
volunteer | That would be fine. | 16,307 | 94 | [] |
volunteer | Don't forget to write the equation x + 6 = 90 - x as the equation asked for in the question | 16,307 | 95 | [] |
student | so I should have those 3 things? | 16,307 | 96 | [] |
volunteer | When you first put the problem to me a few minutes ago | 16,307 | 97 | [] |
volunteer | you said both the equation needed to be one answer\ | 16,307 | 98 | [] |
volunteer | and the answers (two of them) would be needed as well. | 16,307 | 99 | [] |
volunteer | That's three things: | 16,307 | 100 | [] |
volunteer | x + 6 = 90 - x | 16,307 | 101 | [] |
volunteer | x = 42 degrees | 16,307 | 102 | [] |
volunteer | and it's complement is 48 degrees | 16,307 | 103 | [] |
student | so "x+6=90-x", "x=42", "One angle is 42 degrees and the other is 48 degrees."? | 16,307 | 104 | [] |
volunteer | Yes. That should be fine | 16,307 | 105 | [] |
student | ok | 16,307 | 106 | [] |
student | The measure of an angle is 12 degrees more than twice the measure of its complement. | 16,307 | 107 | [] |
student | Would the equation be 90-x=12+(2x) | 16,307 | 108 | [] |
volunteer | You have made a nice attempt, but it is a bit off | 16,307 | 109 | [] |
volunteer | Let me walk you through it | 16,307 | 110 | [] |
volunteer | The measure of an angle is | 16,307 | 111 | [] |
volunteer | can be represented by x = | 16,307 | 112 | [] |
volunteer | The measure of it's complement is 90-x | 16,307 | 113 | [] |
volunteer | That make sense so far? | 16,307 | 114 | [] |
student | yes | 16,307 | 115 | [] |
volunteer | Putting the rest of the verbiage together look like this | 16,307 | 116 | [] |
volunteer | x = 2(90-x) + 12 | 16,307 | 117 | [] |
volunteer | The measure of an angle is 12 degrees more than twice it's complement | 16,307 | 118 | [] |
volunteer | Do you see the difference between this and what you tried (valiantly)? | 16,307 | 119 | [] |
student | yes | 16,307 | 120 | [] |
volunteer | It take practice to learn to translate from words to algebraic equations. | 16,307 | 121 | [] |
volunteer | Jamie, go ahead and solve this okay? | 16,307 | 122 | [
{
"pii_type": "PERSON",
"surrogate": "Jamie",
"start": 0,
"end": 5
}
] |
student | so the equation is "x = 2(90-x)+12"? | 16,307 | 123 | [] |
volunteer | Yes. Do you see that it is nicely translated as "an angle is 12 degrees more than twice it's complement'? | 16,307 | 124 | [] |
student | yes | 16,307 | 125 | [] |
volunteer | When you have solved for x that will be the only answer to this problem. | 16,307 | 126 | [] |
student | Why did the other one have 2 but this one only has 1? | 16,307 | 127 | [] |
volunteer | They are really only asking for the one angle in this problem, at least the wording you gave to me. | 16,307 | 128 | [] |
volunteer | They are looking for the measure of the angle that satisfies this condiition | 16,307 | 129 | [] |
student | the wording to me looks the same as the last question | 16,307 | 130 | [] |
student | I have to go do something. Can you stay on the line and I will come back when I am done? | 16,307 | 131 | [] |
volunteer | You can answer it as you see fit. If you need to provide the complement, by all means do so. | 16,307 | 132 | [] |
volunteer | Again, as long as it is about 10 minutes, ok. | 16,307 | 133 | [] |
volunteer | If you need more help after that, just put in a request. | 16,307 | 134 | [] |
student | ok. I will let you know once I am back | 16,307 | 135 | [] |
volunteer | Jamie. I need to go now. You should get 64 degrees for the solution to the equation for the last problem. Please put in another request if you need more help. Thanks. | 16,307 | 136 | [
{
"pii_type": "PERSON",
"surrogate": "Jamie",
"start": 0,
"end": 5
}
] |
volunteer | Hello How are you? | 16,409 | 0 | [] |
student | good | 16,409 | 1 | [] |
student | i was wondering how to do a certain question | 16,409 | 2 | [] |
student | ill upload it | 16,409 | 3 | [] |
volunteer | OK | 16,409 | 4 | [] |
volunteer | OK | 16,409 | 5 | [] |
student | on the exams method points are a good percent so id also like to know a pretty standard way of going at the problem | 16,409 | 6 | [] |
volunteer | OK | 16,409 | 7 | [] |
student | i found the inverse and go | 16,409 | 8 | [] |
student | t | 16,409 | 9 | [] |
volunteer | OK I will copy to 2nd screen pls wait | 16,409 | 10 | [] |
volunteer | OK go ahead | 16,409 | 11 | [] |
student | however i do not know what it is asking for when it says in the domain [0,1] | 16,409 | 12 | [] |
student | or what mutual inverses means | 16,409 | 13 | [] |
volunteer | OK | 16,409 | 14 | [] |
volunteer | let me think | 16,409 | 15 | [] |
volunteer | did u get this by replacing x with 'y' and then solving for y? | 16,409 | 16 | [] |
student | yup | 16,409 | 17 | [] |
volunteer | OK let us assume that is ok | 16,409 | 18 | [] |
volunteer | Now suppos x = 2 | 16,409 | 19 | [] |
volunteer | is this function defined? | 16,409 | 20 | [] |
volunteer | i mean the inverse | 16,409 | 21 | [] |
student | its not real | 16,409 | 22 | [] |
volunteer | I agree | 16,409 | 23 | [] |
student | because its the square root of something less than 1 | 16,409 | 24 | [] |
student | i mean 0 | 16,409 | 25 | [] |
volunteer | That is why I *think* they have restricted the domain. Seee what I mean? | 16,409 | 26 | [] |
student | yea | 16,409 | 27 | [] |
volunteer | Does that help? | 16,409 | 28 | [] |
student | i mean i understand that but i still dont really know what its asking of me | 16,409 | 29 | [] |
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