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The dataset generation failed
Error code: DatasetGenerationError
Exception: ValueError
Message: Expected object or value
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1816, in _prepare_split_single
for key, table in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 613, in wrapped
for item in generator(*args, **kwargs):
~~~~~~~~~^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 281, in _generate_tables
examples = [ujson_loads(line) for line in batch.splitlines()]
~~~~~~~~~~~^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/utils/json.py", line 20, in ujson_loads
return pd.io.json.ujson_loads(*args, **kwargs)
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^
ValueError: Expected object or value
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1369, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
~~~~~~~~~~~~~~~~~~~~~~~~~^
builder, max_dataset_size_bytes=max_dataset_size_bytes
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
)
^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 948, in stream_convert_to_parquet
builder._prepare_split(split_generator=splits_generators[split], file_format="parquet")
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1683, in _prepare_split
for job_id, done, content in self._prepare_split_single(
~~~~~~~~~~~~~~~~~~~~~~~~~~^
gen_kwargs=gen_kwargs, job_id=job_id, **_prepare_split_args
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
):
^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1869, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
problem_id string | generated_rollouts list | alignment_costs unknown |
|---|---|---|
0004e886922ac09113b03ef290787286 | [
"Step 1: We are given the quadratic equation \\(x^2 - 5x + 6 = 0\\).\n\nStep 2: To factor the quadratic expression, we look for two numbers that multiply to 6 (the constant term) and add up to -5 (the coefficient of the linear term). These numbers are -2 and -3. Therefore, we can write:\n\\[x^2 - 5x + 6 = (x - 2)(x... | {
"(0,3)": 0.3714,
"(2,6)": 0.3667,
"(0,1)": 0.4
} |
00115c24f1dd9ac47cca5acd76db2d83 | [
"Step 1: We are given the expression \\(x^4 y + x^3 y + x^2 y + xy + xy^2 + xy^3 + xy^4\\) and the constraint \\(x + y = 3\\). We need to find the maximum value of this expression.\n\nStep 2: Factor the expression as follows:\n\\[\nx^4 y + x^3 y + x^2 y + xy + xy^2 + xy^3 + xy^4 = xy(x^3 + x^2 + x + 1 + y + y^2 + y... | {
"(3,4)": 0.3304,
"(3,5)": 0.3583,
"(1,7)": 0.15710000000000002
} |
003351ecd4f40daa36c0a7fcd2298290 | [
"Step 1: We are given the matrix \\(\\mathbf{A} = \\begin{pmatrix} a & 1 \\\\ -2 & d \\end{pmatrix}\\) and the equation \\(\\mathbf{A} + \\mathbf{A}^{-1} = \\mathbf{0}\\). This implies \\(\\mathbf{A}^{-1} = -\\mathbf{A}\\).\n\nStep 2: The inverse of \\(\\mathbf{A}\\) is \\(\\mathbf{A}^{-1} = \\frac{1}{\\det \\mathb... | {
"(2,3)": 0.125,
"(3,5)": 0.1467,
"(1,7)": 0.16670000000000001
} |
003af9924adad19712a703a334970e34 | [
"Step 1: We are given a configuration where a central circle of radius 1 is surrounded by 4 smaller circles of radius \\( r \\). The centers of the central circle and the surrounding circles form a square, and the distance between the center of the central circle and the center of any surrounding circle is \\( 1 + ... | {
"(2,3)": 0.1231,
"(0,3)": 0.1111,
"(3,4)": 0.1
} |
0042c707fabc3cfe5dc2ca2c4f4eb861 | [
"Step 1: We start with the given equations:\n\\[ a + b = 24 \\]\n\\[ 2ab + 10a = 3b + 222 \\]\n\nStep 2: Solve the first equation for \\( b \\):\n\\[ b = 24 - a \\]\n\nStep 3: Substitute \\( b = 24 - a \\) into the second equation:\n\\[ 2a(24 - a) + 10a = 3(24 - a) + 222 \\]\n\nStep 4: Simplify the left-hand side:\... | {
"(1,5)": 0.0261,
"(0,7)": 0.1889,
"(4,6)": 0.0333
} |
004ba79d8e379e602d5ba0399ade41e6 | [
"Step 1: We start by determining the total number of possible outcomes when flipping four fair coins. Each coin has 2 possible outcomes (heads or tails), so the total number of outcomes for four coins is:\n\\[2 \\times 2 \\times 2 \\times 2 = 2^4 = 16.\\]\n\nStep 2: Next, we identify the number of favorable outcome... | {
"(1,7)": 0,
"(1,2)": 0,
"(4,7)": 0
} |
005e81476558c42a066002e0cc3e6678 | [
"Step 1: Consider the polynomial \\( P(x) = ax^3 + bx^2 + cx + d \\) where \\( a, b, c, d \\in \\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\\} \\).\n\nStep 2: We are given the condition \\( P(-1) = -9 \\). Substituting \\( x = -1 \\) into the polynomial, we get:\n\\[\nP(-1) = a(-1)^3 + b(-1)^2 + c(-1) + d = -a + b - c + d\n\\]\... | {
"(4,7)": 0.3214,
"(3,7)": 0.3259,
"(3,6)": 0.5417000000000001
} |
005e94eadf135033270d65e2f9b7bc3b | [
"Step 1: We are given the number 315 and need to find the sum of its distinct prime factors.\n\nStep 2: To find the prime factors of 315, we start by dividing it by the smallest prime number, which is 2. Since 315 is an odd number, it is not divisible by 2. We then try the next smallest prime number, which is 3.\n\... | {
"(2,3)": 0.0857,
"(1,3)": 0.025,
"(2,6)": 0
} |
005fa9bd0052210e8076b6753dcef93b | [
"Step 1: Identify the vertices of the regular 12-gon inscribed in a circle of radius 12.\nThe vertices of a regular 12-gon can be represented as the 12th roots of unity scaled by the radius 12. Thus, the vertices are given by:\n\\[A_k = 12 e^{2\\pi i k / 12} \\quad \\text{for} \\quad k = 0, 1, 2, \\ldots, 11.\\]\n\... | {
"(1,4)": 0.075,
"(0,5)": 0.2,
"(3,7)": 0.09230000000000001
} |
006c2191312de3eb8bdffd1393d31106 | [
"Step 1: Given the polynomial equation \\(2x^3 + 8x^2 - 120x + k = 0\\), we know that two of its roots are equal. Let the roots be \\( \\alpha \\), \\( \\alpha \\), and \\( \\beta \\).\n\nStep 2: By Vieta's formulas, the sum of the roots taken one at a time is given by:\n\\[\n\\alpha + \\alpha + \\beta = -\\frac{8}... | {
"(2,6)": 0.3286,
"(2,5)": 0.4333,
"(1,7)": 0.06670000000000001
} |
0076b8b0d7b264a32b97301cc64a711f | [
"Step 1: **Define the Problem**\nWe need to find the probability that when rolling five six-sided dice, there is at least one pair but no three-of-a-kind.\n\nStep 2: **Calculate Total Outcomes**\nThe total number of outcomes when rolling five dice is:\n\\[\n6^5 = 7776\n\\]\n\nStep 3: **Count Favorable Outcomes**\nW... | {
"(5,6)": 0.08,
"(0,2)": 0.075,
"(1,6)": 0.08
} |
0080f990a76d7aa8c1f2abee24af2569 | [
"Step 1: Determine the critical points by finding the values of \\(x\\) that make the numerator or the denominator zero.\n- The numerator is \\(x\\), which is zero when \\(x = 0\\).\n- The denominator is \\(x + 3\\), which is zero when \\(x = -3\\).\n\nStep 2: Use the critical points to divide the real number line ... | {
"(2,7)": 0.025,
"(0,5)": 0.0222,
"(3,7)": 0.1429
} |
008bcfd6323d4bf62deced437b98368b | [
"Step 1: Identify the centers and radii of the circles.\nThe equations of the circles are \\((x - 1)^2 + y^2 = 1\\) and \\((x + 1)^2 + y^2 = 1\\). Both circles have a radius of 1 and are centered at \\((1, 0)\\) and \\((-1, 0)\\) respectively.\n\nStep 2: Determine the minimum dimensions of the ellipse.\nThe ellipse... | {
"(1,6)": 0.14,
"(2,7)": 0.057100000000000005,
"(0,4)": 0
} |
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