question stringlengths 1 1.14k | options listlengths 4 4 | answer stringclasses 4
values | correct_option stringlengths 1 219 | explanation stringlengths 0 3.68k ⌀ | dataset stringclasses 5
values |
|---|---|---|---|---|---|
On his drive to work, Leo listens to one of three radio stations A, B or C. He first turns to A. If A is playing a song he likes, he listens to it; if not, he turns it to B. If B is playing a song he likes, he listens to it; if not, he turns it to C. If C is playing a song he likes, he listens to it; if not, he turns o... | [
"0.027",
"0.386",
"0.417",
"0.657"
] | B | 0.386 | Probability he hears a song is like:
Tune to A and likes what he is hearing = 0.15
Tune to A, don't find he like what they are airing, then tune to B and likes what he finds there = 0.85 * 0.15 = 0.1275
Tune to A, finds crap there, Tune to B, hears a similar crap, Tune to C and finally falls in love with the program = ... | aqua_rat |
The product Q of the first 10 prime numbers is closest to which of the following? | [
"6.5 x 10^7",
"6.5 x 10^8",
"6.5 x 10^9",
"6.5 x 10^10"
] | C | 6.5 x 10^9 | The first 10 primes are: 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29.
So, we need to find approximate value Q of 2*3*5*7*11*13*17*19*23*29.
# of different approximations are possible. For example:
2*5=10
3*17=~50 (actually more than 50);
7*13=~100 (actually less than 100);
11*19=~200 (actually more than 200)
23*29=667
2*3*5... | aqua_rat |
The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest? | [
"80 years",
"70 years.",
"20 years.",
"30 years."
] | C | 20 years. | Present total age of the members = 26(5) = 130 years.
Present age of the youngest member = 10 years
Present total age of the remaining four members = 130 -10 = 120 years
Their average age at the time of the birth of the youngest member = [120 - (4 * 10)] / 4 = 30 - 10 = 20 years.
Answer: C | aqua_rat |
A train , having a length of 110 meter is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that of the train | [
"4 sec",
"2 sec",
"6 sec",
"8 sec"
] | C | 6 sec | Distance = 110 m
Relative speed = 60+6 = 66 kmph (Since both the train and the man are in moving in opposite direction)
= 66×10/36 mps = 110/6 mps
Time = distance/speed = 110/(110/6) = 6 s
Answer is C. | aqua_rat |
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is: | [
"2 : 3",
"3 : 2",
"3 : 4",
"4 : 3"
] | C | 3 : 4 | Explanation:
Let the speed of the train be x km/hr and that of the car be y km/hr.
Then, 120/x+480/y=8 =>1/x+4/y=1/15....(i)
And, 200/x+400/y=25/3 =>1/x+2/y=1/24....(ii)
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
ANSWER IS C | aqua_rat |
The population of a village is 15540. It increases annually at the rate of 28% p.a. What will be its population after 2 years? | [
"10000",
"25460",
"26709",
"14000"
] | B | 25460 | Formula :
( After =100 denominator
Ago = 100 numerator)
15540 × 128/100 × 128/100 = 25460
B | aqua_rat |
For what value of x, is |x – 3| + |x + 1| + |x| = 11? | [
"0",
"3",
"-3",
"4"
] | C | -3 | For what value of x, is |x – 3| + |x + 1| + |x| = 11?
It's easiest just to plug in answer choices:
(C): -3
|x – 3| + |x + 1| + |x| = 11?
|-3 - 3| + |-3 + 1| + |-3| = 11?
|6| + |2| + |3| = 11
(C) | aqua_rat |
The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is? | [
"8%",
"4%",
"5%",
"3%"
] | B | 4% | 65*(90/100)*((100-x)/100) = 56.16
x = 4%
Answer: B | aqua_rat |
A monkey climbs 30 feet at the beginning of each hour and rests for a while when he slips back 20 feet before he again starts climbing in the beginning of the next hour. If he begins his ascent at 7.00 a.m., at what time will he first touch a flag at 120 feet from the ground? | [
"4 p.m.",
"5 p.m.",
"6 p.m.",
"7 p.m."
] | B | 5 p.m. | Explanation:
Net ascent of the monkey in 1 hour = (30 - 20) feet = 10 feet.
So, the monkey ascends 90 feet in 9 hours i.e. till 4 p.m.
Clearly, in the next 1 hour i.e. till 5 p.m. the monkey ascends remaining 30 feet to touch the flag.
Answer:B | aqua_rat |
The combined salaries of three brothers is $225,000. Mr. Big earns twice what Mr. Small earns, and Mr. Middle earns 1 1/2 times what Mr. Small earns. What is the smallest salary of the three brothers? | [
"35,000",
"55,000",
"50,000",
"30,000"
] | C | 50,000 | Mr. Small = x;
Mr. Middle = 3/2*x;
Mr. Big = 2x.
x + 3/2*x + 2x = 225 --> x=50
Answer: C | aqua_rat |
Otto and Han are driving at constant speeds in opposite directions on a straight highway. At a certain time they are driving toward each other and are 40 miles apart. One and a half hours later, they are again 40 miles apart, driving away from each other. If Otto drives at a speed of x miles per hour, then, in terms of... | [
"a) 80-x",
"b) 53.33-x",
"c) 80-2x",
"d) 120-x"
] | B | b) 53.33-x | Let's say the two cars have speeds V1 and V2. The fact that they are moving in opposite direction means that their relative speed is (V1 + V2). In other words, any gap between them will be changing in size at a rate of (V1 + V2). It doesn't matter whether they are moving toward each other or away from each other. If th... | aqua_rat |
The cost of painting the whole surface area of a cube at the rate of 13 paise per Sq.cm is Rs. 343.98. Then the volume of the cube is | [
"8500 cm3",
"9000 cm3",
"9250 cm3",
"9261 cm3"
] | D | 9261 cm3 | Solution
Surface area = (34398 / 13)
‹=›2646cm3
‹=›6a2= 2646
‹=›a2= 441
‹=›a = 21.
So,volume =(21x21x21)cm3= 9261cm3.
Answer D | aqua_rat |
A train 190 m long passed a pole in 10 sec. How long will it take to pass a platform 1200 m long? | [
"80",
"73",
"78",
"67"
] | B | 73 | Speed = 190/10 = 19 m/sec.
Required time = (190 + 1200)/19 = 73 sec.
Answer: Option B | aqua_rat |
Mary rolls a die 5 times. What is the probability that she gets a one on the last one of the five rolls? | [
"100/1000",
"7775/7776",
"none",
"1"
] | B | 7775/7776 | the die has 6 sides and it was rolle 5 times, then 6*6*6*6*6=7776
the number of ways to get 1 is 1
then 1/7776
the probability would be
1-1/7776=7775/7776
Answer B | aqua_rat |
Marge has E candies, where E is an integer such that 20 <E< 50. If Marge divides the candies equally among 5 children, she will have 2 candies remaining. If she divides the candies among 6 children, she will have 1 candy remaining. How many candies will remain if she divides the candies among 7 children? | [
"0",
"1",
"2",
"3"
] | C | 2 | If Marge divides the candies equally among 5 children, she will have 2 candies remaining.
This tells us that the candies are of 5x + 2 type and so 22, 27, 32, 37, 42, or 47
If she divides the candies among 6 children, she will have 1 candy remaining.
this tells us it is if 6x+1 type and so 25, 31, 37, 43, or 49
ONLY 37... | aqua_rat |
The sector of a circle has radius of 14 cm and central angle 144o. Find its perimeter? | [
"60cm",
"63.2cm",
"70cm",
"80cm"
] | B | 63.2cm | Perimeter of the sector = length of the arc + 2(radius)
= (144/360 * 2 * 22/7 * 14) + 2(14)
= 35.2 + 28 = 63.2 cm
Answer:B | aqua_rat |
The angle between the minute hand and the hour hand of a clock when the time is 11.30, is | [
"35°",
"65°",
"45°",
"165°"
] | D | 165° | Angle between hands of a clock
When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(H−M/5)+M/2 degree
When the minute hand is ahead of the hour hand, the angle between the two hands at M minutes past H 'o clock
=30(M/5−H)−M/2 degree
Here H = 11, M = 30 and minut... | aqua_rat |
What requires sunlight to grow? | [
"tunicates",
"Fruits",
"Conifers",
"coral"
] | B | Fruits | fruits require sunlight to grow | qasc |
3 + 3 + 3 + 2 × 3^2 + 2 × 3^3 + 2 × 3^4 + 2 × 3^5 + 2 × 3^6 + 2 × 3^7 = | [
"3^7",
"3^8",
"3^14",
"3^28"
] | B | 3^8 | We have the sum of 9 terms. Now, if all terms were equal to the largest term 2*3^7 we would have: sum=9*(2*3^7)=2*3^9=~3^10, so the actual sum is less than 3^10 and more than 3^7 (option A) as the last term is already more than that. So the answer is clearly B.
Answer: B. | aqua_rat |
A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 4 feet . How many feet does the squirrel travels if the post is 16 feet tall and 3 feet in circumference? | [
"10 feet",
"12 feet",
"13 feet",
"15 feet"
] | B | 12 feet | total circuit=16/4=4
total feet squirrel travels=4*3=12 feet
ANSWER:B | aqua_rat |
what do genes carry? | [
"pollen",
"Energy",
"calories",
"instructions"
] | D | instructions | genes carry instructions | qasc |
Mr. Mike sold two books at $2.20 each. Based on the cost, his profit one was 20% and his loss on the other was 30%. On the sale of the books. Find the amount of his profit or loss? | [
"lost 10 cents",
"lost 4 cents",
"broke even",
"lost amount 0.22 cents."
] | D | lost amount 0.22 cents. | 20 % profit on $ 2.20
= $ 20/100 × 2.20
= $ 0.20 × 2.20
= $ 0.44
Similarly, 30 % loss on $ 2.20
= $ 30/100 × 2.20
= $ 0.30 ×2.20
= $ 0.66
Therefore, in one book his profit is $ 0.44 and in the other book his loss is $ 0.66.
loss amount 0.22 cents.
Answer is D. | aqua_rat |
Brent went on a hike to Leeland Lake. On his way up the trail he travelled at 2 Km/h. On his way down the trail he travelled at twice the speed and therefore his way back took three hours less. What is the distance (in Km) of the trail? | [
"6 Km.",
"8 Km.",
"450.",
"500."
] | B | 8 Km. | Distance is same
S1t1=s2t2
40t= 50 (t-1)
t=5
distance= speed *time
40*5= 200
B is the answer | aqua_rat |
In certain year in Country C, x sets of twins and y sets of triplets were born. If there were z total babies born in Country C in this year, and x and y were both greater than 0, which of the following represents the fraction E of all babies born who were NOT part of a set of twins or triplets? | [
"z - 2x - 3y",
"(2x+3y)/z",
"(x+y)/z",
"1 - (2x+3y)/z"
] | D | 1 - (2x+3y)/z | X set of twins implies 2x babies of twin category.
Y set of triplets means 3y babies of triplet category.
Let K be the babies other than twin or triplet category.
Total babies = z = 2x+3y+k.
or K=Z-(2x+3y)
=> Fraction of babies other than twin or triplet categories = K/Z = Z-(2x+3y)/Z.
E= 1- (2x+3y)/Z. Hence answer is ... | aqua_rat |
Alice, Benjamin, and Carol each try independently to win a carnival game. If their individual probabilities for success are 1/5, 3/8, and 3/7, respectively, what is the probability that exactly two of the three players will win but one will lose? | [
"63/280",
"1/280",
"3/56",
"3/35"
] | A | 63/280 | P = P(A wins, B wins, C loses) + P(A wins, B loses, C wins) + P(A loses, B wins, C wins) = 1/5*3/8*4/7 + 1/5*5/8*3/7 + 4/5*3/8*3/7 = 63/280.
Answer: A | aqua_rat |
A shopkeeper fixes the marked price of an item 30% above its cost price. The percentage of discount allowed to gain 8% is | [
"15.92%",
"16.92%",
"17.92%",
"18.92%"
] | B | 16.92% | Explanation:
Let the cost price = Rs 100
then, Marked price = Rs 130
Required gain = 8%,
So Selling price = Rs 108
Discount = 130 - 108 = 22
Discount% = (22/130)*100 = 16.92%
Option B | aqua_rat |
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches? | [
"50%",
"87%",
"100%",
"187%"
] | C | 100% | Area of sheet A = 11*17
Area of sheet B = 11*8.5
Difference in Area = 11*8.5
Required % = (11*8.5)*100/(11*8.5)% = 100%
ANSWER:C | aqua_rat |
A can run 1.5 km distance in 2 min 20 seconds, while B can run this distance in 2 min 30 sec. By how much distance can A beat B? | [
"90 m",
"100 m",
"120 m",
"180 m"
] | B | 100 m | A takes time 2.20 minutes=140sec
B takes time 2.30 minutes=150sec
diffrence= 150-140=10sec
now we are to find distance covered in 10 sec by B
150sec=1500m
1sec=10m
10sec=10x10=100m
ANSWER:B | aqua_rat |
SID has 13 ten-dollar bills, 11 five-dollar bills, and 17 one-dollar bills. If SID needs to pay exactly $128, what is the least number of bills he will need to use? | [
"16",
"121",
"45",
"456"
] | A | 16 | 128 is the total sum of money.
as we have 13 10 dollar bills so the closest we can get to 128 using the 10 dollar bills is by using 12 * 10 dollar bils
128-120 = 8
so now we need to get 8 from either 5 dollar bills or 1 dollar bills
8 - 5 (use only 1 5 dollar bill) = 3
so we can get 3 from using 3 $1 bills.
Hence 16 ( ... | aqua_rat |
Find the odd man out
3, 4 , 10 , 32 , 136 , 685 , 4116 | [
"32",
"136",
"685",
"4116"
] | A | 32 | Series N*X+X, X starts from 1,2,3..., N=3 for first iteration. New value will become N for the next iteration
3*1+1 = 4
4*2+2 = 10
10*3+3 = 33
33*4+4 = 136
136*5+5 = 685
685*6+6 = 4116
ANSWER:A | aqua_rat |
A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 210, then how much amount should C pay as his share of rent? | [
"54",
"45",
"25",
"15"
] | A | 54 | A : B : C
=10×7:12×5:15×3
=2×7:12×1:3×3
=14:12:9
Amount that C should pay
=210×9/35=6×9=54
Answer is A | aqua_rat |
If x is 20 percent greater than 40, then x = | [
"48",
"70.4",
"86",
"105.6"
] | A | 48 | X is 20% greater than 40 means X is 1.2 times 40 (in other words 40 + 20/100 * 40 = 1.2 * 40)
Therefore, X = 1.2 * 40 = 48
ANSWER:A | aqua_rat |
Find the area of circle whose radius is 28m? | [
"2464",
"1543",
"7675",
"1683"
] | A | 2464 | 22/7 * 28 * 28
= 2464
Answer: A | aqua_rat |
A, B and C are entered into a partnership. A invested Rs.6500 for 6 months, B invested Rs.8400 for 5 months and C invested for Rs.10000 for 3 months. A is a working partner and gets 5% of the total profit for the same. Find the share of C in a total profit of Rs.7400? | [
"2000",
"1900",
"2888",
"2777"
] | B | 1900 | 65 * 6 : 84 * 5 : 100 * 3
26:28:20
C share = 74000 * 95/100 = 7030 * 20/74
=> 1900
Answer:B | aqua_rat |
if N is a prime number bigger than 5. Which of the following expressions must be even? | [
"(a) (N+2)^2",
"(b) N^2+2.",
"(c) N(N+2).",
"(d) (N+1)(N+2)"
] | B | (b) N^2+2. | N=11
a. 169
b. 123
c. 143
d. 180
e. 81
B | aqua_rat |
How many paying stones, each measuring 2 m * 2 m are required to pave a rectangular court yard 30 m long and 18 m board? | [
"99",
"18",
"135",
"17"
] | C | 135 | 30 * 18= 2* 2 * x => x
= 135
Answer: C | aqua_rat |
If the radius of a circle is decreased 30%, what happens to the area? | [
"51% decrease",
"20% decrease",
"36% decrease",
"40% decrease"
] | A | 51% decrease | Area of Square = Pi* radius^2
New Radius = 0.7 * old radius
so new area = (0.7)^2 old area => 0.49 of old area => 49% old area
Ans : A | aqua_rat |
If 4 spiders make 4 webs in 4 days, then 1 spider will make 1 web in how many days? | [
"1",
"3",
"5",
"4"
] | D | 4 | Explanation :
Let the required number days be x.
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
Spiders 1:4|
|::4:1
Webs 4:1|
=> 1 * 4 * x = 4 * 1 * 4
=> x = 4
Answer : D | aqua_rat |
Which of the following is not a prime number ? | [
"743",
"740",
"751",
"757"
] | B | 740 | Clearly, 740 is not a prime number.
Answer : B | aqua_rat |
The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 15000, then find the annual income of A? | [
"187888",
"276889",
"267777",
"504000"
] | D | 504000 | B's monthly income = 15000 * 112/100 = Rs. 16800
B's monthly income = 2 parts ----> Rs. 16800
A's monthly income = 5 parts = 5/2 * 16800 = Rs. 42000
A's annual income = Rs. 42000 * 12 = Rs.504000
Answer:D | aqua_rat |
There is a certain relation between two given words on one side of : : and one word is given on another side of : : while another word is to be found from the given alternatives, having the same relation with this word as the given pair has. | [
"Chauffeur",
"Steering",
"Mechanic",
"Brake"
] | A | Chauffeur | Explanation:
Horse is driven by a jockey .
Similarly,car is driven by a chauffeur
Answer: A) | aqua_rat |
Milk contains 5% water.What quantity of pure milk should be added to 10 litres of milk to reduce this 2%? | [
"15 litres",
"16 litres",
"17 litres",
"25 litres"
] | A | 15 litres | Present Ration of MIlK TO WATER IS 95:5
Amount of Milk is 10 litres
Hence, Pure milk content is 9.5 litre
and water content is 0.5 litres
Now, we should not disturb the water content
So, 0.5 litres of water is equivalent to 2%
So 100% mixture is :(0.5/2)*100=25litre
Thus, milk should be added=25-10=15 litres of pure mi... | aqua_rat |
Nitin borrowed some money at the rate of 6% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 12240, how much money did he borrow? | [
"12000",
"80288",
"2668",
"2600"
] | A | 12000 | Let the sum be Rs. x. Then,
[(x * 6 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 12240
18x + 45x + 39x = (12240 * 100)
102x = 1224000 => x = 12000.
Answer:A | aqua_rat |
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is | [
"78 years",
"22 years",
"88 years",
"66 years"
] | B | 22 years | Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years
Answer: B | aqua_rat |
The sum of the present ages of A, B, C is 57 years. Three years ago their ages were in the ratio 1:2:3. What is the present age of A? | [
"8",
"9",
"10",
"11"
] | D | 11 | Three years ago:
a:b:c = 1:2:3
Let a = 1x, b = 2x, and c = 3x.
Today:
(x+3) + (2x+3) + (3x+3) = 57
x = 8
So the present age of A is x+3 = 11
The answer is D. | aqua_rat |
In how many different number of ways 3 boys and 2 girls can sit on a bench? | [
"700",
"710",
"120",
"300"
] | C | 120 | npn = n!
5p5 = 5 × 4 × 3 × 2 × 1 = 120
C) | aqua_rat |
If 5/w + 5/x = 5/y and wx = y, then the average (arithmetic mean) of w and x is | [
"1/2",
"1",
"2",
"4"
] | A | 1/2 | Given: 5/w + 5/x = 5/ywx=y
Find: (w+x)/2 = ?
5(1/w + 1/x) = 5(1/y) - divide both sides by 5
(1/w + 1/x) = 1/y
(x+w)/wx = 1/wx - sub'd in y=wx
x+w - 1 = 0
x+w = 1
Therefore (w+x)/2 = 1/2
Ans: A | aqua_rat |
Suppose you have three identical prisms with congruent equilateral triangles as the end-polygons. Suppose you attach them by the rectangular faces so they are perfectly aligned. There will be some large faces created by two or more co-planar faces of the individual prisms: count each such large face as one. Given that,... | [
"4",
"6",
"9",
"10"
] | A | 4 | To arrange them as described I did as follows on my scratch paper (see the file attached), where I counted 4 sides
A | aqua_rat |
If x is an integer, which of the following must also be an integer?
I. xy
II. y/x
III. y | [
"I alone",
"II alone",
"III alone",
"I and III"
] | D | I and III | Lets take X = 11 and Y = 2
Then XY = 22 which is an integer.
But X/Y = 11/2 --> Not an integer.
Y/X = 2/11 --> Not an integer.
y alone is 2. which is an integer.
Hence D. | aqua_rat |
Population of a city in 20004 was 1000000. If in 2005 there isan increment of 25% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45%, then find the population of city atthe end of the year 2007 | [
"976374",
"979923",
"980241",
"1178125"
] | D | 1178125 | Required population = P (1 + R1/100)(1 - R2/100)(1 + R3/100)
= P (1 + 25/100)(1 - 35/100)(1 + 45/100)
= 1178125
D | aqua_rat |
Three-twentieths of the members of a social club are retirees who are also bridge players, five-twentieths of the members are retirees, and one-half of the members are bridge players. If 120 of the members are neither retirees nor bridge players, what is the total number of members in the social club? | [
"240",
"300",
"200",
"400"
] | C | 200 | {Total} = {Retirees} + {Bridge players} - {Both} + {Neither}
x = 5/20*x + x/2 - 3/20*x + 120
20x = 5x + 10x - 3x + 120*20 (multiply by 20)
12x = 120*20
x = 200.
Answer: C | aqua_rat |
Find the smallest number of five digits exactly divisible by 16,24,36 and 54. | [
"10368",
"10638",
"10836",
"10863"
] | A | 10368 | Smallest number of five digits is 10000.
Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432,
On dividing 10000 by 432,we get 64 as remainder.
Therefore, Required number = 10000 +( 432 – 64 ) = 10368.
Answer is A. | aqua_rat |
A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth? | [
"22",
"77",
"90",
"66"
] | C | 90 | SP of 1m of cloth = 8925/85 = Rs. 105
CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth
= Rs. 105 - Rs. 15 = Rs. 90.
Answer: C | aqua_rat |
A ship sails out to a mark at the rate of 19 kmph. and sails back at the rate of 13 kmph. The average rate of sailing is ? | [
"15 km/hr",
"12 km/hr",
"12.5 km/hr",
"25 km/hr"
] | A | 15 km/hr | Answer
Average = ( 2uv / u +v ) km/hr
= ( 2 x 19 x 13 ) / (19 +13 ) km/hr.
= 15 km/hr.
Correct Option: A | aqua_rat |
The least number of complete years in which a sum of money put out at 20% C.I. will be more than doubled is? | [
"7",
"4",
"5",
"3"
] | B | 4 | Explanation:
P(1 + 20/100)n > 2P or (6/5)n > 2
Now, (6/5 * 6/5 * 6/5 * 6/5) > 2. So, n = 4 years.
Answer:B | aqua_rat |
Suzie’s Discount Footwear sells all pairs of shoes for one price and all pairs of boots for another price. On Monday the store sold 22 pairs of shoes and 16 pairs of boots for $540. On Tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $720. How much more do pairs of boots cost than pairs of shoes at Suz... | [
"12",
"11",
"10",
"15"
] | C | 10 | Let X be pair of shoes and Y be pair of boots.
22x+16y = 540 ... eq1
8x +32y = 720....eq 2.
Now multiply eq 1 by 2 and sub eq 2.
44x = 1080
8x = 720.
36x = 360 => x = 10.
Sub x in eq 2.... we get 80 + 32y = 720... then we get 32y = 640 then y = 20
Differenece between X and Y is 10
Answer : C | aqua_rat |
Company T produces two kinds of stereos: basic and deluxe. Of the stereos produced by Company T last month, 2/3 were basic and the rest were deluxe. If it takes 7/5 as many hours to produce a deluxe stereo as it does to produce a basic stereo, then the number of hours it took to produce the deluxe stereos last month wa... | [
"8/22",
"4/22",
"6/22",
"7/22"
] | D | 7/22 | # of basic stereos was 3/4 of total and # of deluxe stereos was 1/4 of total, let's assume total=16, then Basic=12 and Deluxe=4.
Now, if time needed to produce one Deluxe stereo is 1 unit than time needed to produce one Basic stereo would be 7/5 units. Total time for Basic would be 12*1=12 and total time for Deluxe wou... | aqua_rat |
90 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part? | [
"66",
"35",
"42",
"27"
] | B | 35 | x/7 = y/9 => x:y = 7:9
7/16 * 90 = 35
Answer: B | aqua_rat |
what can be used for separating a solute from a volatile vehicle | [
"strainer",
"evaporation",
"sweating",
"water vapor"
] | B | evaporation | evaporation can be used for separating a solute from a volatile vehicle | qasc |
In a college, the ratio of the number of boys to girls is 8 : 5. If there are 160 girls, the total number of students in the college is | [
"100",
"250",
"260",
"416"
] | D | 416 | Explanation:
Let the number of boys and girls be 8x and 5x.
Total number of students = 13x = 13 × 32 = 416.
Answer: D | aqua_rat |
If 4 girls can color 48 m long cloth in 2 days, then 6 girls can color 36 m long cloth in | [
"1 1/5 days",
"1/5 day",
"1 day",
"2 days"
] | C | 1 day | The length of cloth painted by one girl in one day = 48 / 4 × 2 = 6 m
No. of days required to paint 36 m cloth by 6 girls = 36/ 6 × 6 = 1 day.
C | aqua_rat |
On increasing the number of lines in a page by 100, they become 240. What is the % of increase in the no. of lines in the page? | [
"20%",
"305",
"50%",
"71.4%"
] | D | 71.4% | Explanation : Number of pages increased = 100
Now , the number of pages of book = 240
Number of pages of the books before increase = 240 – 100 = 140
% increase in the number of pages in the book = 100 /140
x 100% = 71.4%
D | aqua_rat |
Ten different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, the number of words which have at least one letter repeated is: | [
"69760",
"30240",
"99748",
"42386"
] | A | 69760 | Solution:
Number of words which have at least one letter replaced,
= Total number of words - total number of words in which no letter is repeated.
=> 105 – 16P5.
=> 100000 − 30240 = 69760.
Answer: Option A | aqua_rat |
The sum of three consecutive odd natural numbers, each divisible by 3 is 87. What is the largest among them? | [
"21",
"24",
"27",
"32"
] | D | 32 | Let the 3 consecutive odd numbers each divisible by 3 be X, X+3, X+6
Given, X + X+3 + X+6 =87
3X = 78
X = 26
The numbers are 26, 29, 32
Therefore the largest number is 32
Answer D. | aqua_rat |
How many 4-digit numbers (ABCD) can be formed such that |A – D| = 2? | [
"2,000",
"1,900",
"1,800",
"1,600"
] | C | 1,800 | Digit A can be filled in 9 ways (excluding 0)
Digit B can be filled in 10 ways
Digit C can be filled in 10 ways
Digit D can be filled in 2 ways (because of modulus A-D )
The answer will be 9*10*10*2 = 1800
Ans C | aqua_rat |
In a certain neighborhood, there are half as many beige houses as white houses, and 7 times as many white houses as brown houses. What is the ratio of the number of brown houses to the number of beige houses? | [
"3:5",
"1:4",
"3:1",
"2:7"
] | D | 2:7 | The ratio of beige:white:brown = 7:14:2
The answer is D. | aqua_rat |
Find avrg speed if a man travels at speed of 24km/hr up and 36km/hr dawn at an altitude of 200m. | [
"25.8",
"26.8",
"27.8",
"28.8"
] | D | 28.8 | avg speed=2*x*y/(x+y)
=2*24*36/(24+36)=28.8
ANSWER:D | aqua_rat |
powering a TV receiver with battery requires a path for electricity to flow through what | [
"closed circuit",
"hydrogen and oxygen",
"water",
"open circuit"
] | A | closed circuit | powering a TV receiver with a battery requires a path for electricity to flow through a closed circuit | qasc |
In a box of 12 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that both pen will be defective? | [
"1/6",
"2/9",
"6/11",
"9/16"
] | A | 1/6 | Method- 1
There are 9 fine pieces of pen and 3 defective in a lot of 12 pens
i.e. Probability of first pen being defective = (1/3)
i.e. Probability of Second pen being defective = (1/2)
Probability of Both pen being defective = (1/2)*(1/3) = 1/6
Answer: option A | aqua_rat |
Two cars cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car | [
"960 km",
"950 m",
"906 km",
"906 m"
] | A | 960 km | 60(x + 1) = 64x
X = 15
60 * 16 = 960 km
ANSWER A | aqua_rat |
Four packages have an average weight of 12.5 pounds. What is the minimum possible weight of the heaviest package in pounds if the median is 12 pounds? | [
"12",
"13",
"14",
"15"
] | C | 14 | Let us denote the weights of the packages in pounds by a, b, c, d naming from the lightest one to the heaviest one. The median is 12 pounds. Therefore (b + c) / 2 = 12.
b + c = 24
The average is 12.5 pounds. Therefore (a + b + c + d) / 4 = 12.5.
a + (b + c) + d = 50
a + 24 + d = 50
a + d = 26
The weight a must be no gr... | aqua_rat |
If a-b= 10 and a^2+b^2=150, find the value of ab | [
"10",
"12",
"25",
"18"
] | C | 25 | 2ab = (a^2 + b^2) - (a - b)^2
= 150 - 100 = 50
=> ab = 25
ANSWER: C | aqua_rat |
The probability that a computer company will get a computer hardware contract is 3/4 and the probability that it will not get a software contract is 3/5. If the probability of getting at least one contract is 5/6, what is the probability that it will get both the contracts? | [
"7/30",
"11/40",
"17/50",
"19/60"
] | D | 19/60 | Let, A ≡ event of getting hardware contract
B ≡ event of getting software contract
AB ≡ event of getting both hardware and software contract.
P(A) = 3/4, P(~B) =5/9
=> P(B) = 1- (3/5) = 2/5.
A and B are not mutually exclusive events but independent events. So,
P(at least one of A and B ) = P(A) + P(B) - P(AB).
=> 5/6 =... | aqua_rat |
After deducting a commission of 5% a T.V. set costs Rs. 9595. Its gross value is ? | [
"Rs. 10000",
"Rs. 10074.75",
"Rs. 10100",
"None of these"
] | C | Rs. 10100 | Answer
∵ 95% of gross value = 9595
∴ gross value = (9595 x 100)/95 = 10100
Correct Option: C | aqua_rat |
Letters of alphabets no from 1 to 26 are consecutively with 1 assigned to A and 26 to Z. By 27th letter we mean A, 28th B. In general 26m+n, m and n negative intezers is same as the letters numbered n.
Let P = 6, strange country military general sends this secret message according ot the following codification scheme. ... | [
"DFHASDO",
"HDFAHLOU",
"LDOIHYAD",
"GHLKZOIR"
] | D | GHLKZOIR | A should be coded as 1+6 = G (it occurred for first time)
B should be coded as 2+6 = H (it occurred for first time)
B Should be coded as 2 + 36 = 38 - 26 = 12 = L (it occurred for second time)
Option D is correct | aqua_rat |
f1(x)f1(x) = 2x - 1 and fn(x)=f1(fn−1(x))fn(x)=f1(fn−1(x)) for n ≥≥ 2. Find f5(2) | [
"7",
"6",
"78",
"9"
] | A | 7 | Answer:A | aqua_rat |
Meena wrote all the numbers from 1 to 49,999 inclusive. How many digits did she write in total? | [
"154,889",
"196,889",
"238,889",
"250,889"
] | C | 238,889 | 1-9=>1*9 digits
10-99=>2*90=180 (numbers between 10-99 is 90 where each has 2 digits)
100-999=>3*900=2700
1000-9999=>4*9000 = 36,000
10000-49999=>5*40,000 = 200,000
The answer is 238,889
The answer is C. | aqua_rat |
On his drive to work, Leo listens to one of three radio stations A, B or C. He first turns to A. If A is playing a song he likes, he listens to it; if not, he turns it to B. If B is playing a song he likes, he listens to it; if not, he turns it to C. If C is playing a song he likes, he listens to it; if not, he turns o... | [
"0.027",
"0.09",
"0.417",
"0.578"
] | D | 0.578 | Probability he hears a song is like:
Tune to A and likes what he is hearing = 0.25
Tune to A, don't find he like what they are airing, then tune to B and likes what he finds there = 0.75 * 0.25 = 0.1875
Tune to A, finds crap there, Tune to B, hears a similar crap, Tune to C and finally falls in love with the program = ... | aqua_rat |
In a regular week, there are 5 working days and for each day, the working hours are 8. A
man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns
Rs. 432 in 4 weeks, then how many hours does he work for ? | [
"160",
"175",
"180",
"195"
] | B | 175 | The man works overtime for x hours.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
160 x 2.40 + x x 3.20 = 432
3.20x = 432 - 384 = 48
x = 15.
Hence, total hours of work = (160 + 15) = 175 Answer: Option B | aqua_rat |
8.5 × 6.4 + 4.5 × 11.6 = ? ÷ 4 | [
"426.2",
"426.4",
"106.6",
"422.4"
] | B | 426.4 | Explanation:
(54.4+52.2) × 4 = 426.4
Answer: Option B | aqua_rat |
Sharmeeka is putting all of her pens in order by number. One has the number 4 on it, the next has number 8, the next has number 12, and the next has number 16.
What number will the next pen have on it? | [
"20",
"25",
"32",
"22"
] | A | 20 | A) 20, because the pens are ordered by multiples of 4.
4 +4 = 8
8 + 4=12
12+4=16
16+4=20 | aqua_rat |
A circle in the coordinate plane passes through points (-3, -2) and (2, 4). What is the smallest possible area of that circle? | [
"13π",
"15.25π",
"262√π",
"52π"
] | B | 15.25π | The distance between the two points is sqrt(61).
radius = sqrt(61)/2
Area= pi*(sqrt(61)/2)^2
B. 15.25π | aqua_rat |
A 700-level question for the GMAT committed souls studying over the weekend.
If a and b are distinct integers and a^b=b^a, how many solutions does the ordered pair (a, b) have? | [
"None",
"1",
"2",
"4"
] | B | 1 | (2,4) and (4,2)
a=1 b=1 and a=2 b=2 also has the solution. But we need distinct. Now when we will increase a>4, b^a increase more rapidly than a^b.
ANSWER:B | aqua_rat |
Solve x^2 – 3x – 4 = 0. | [
"(9,2)",
"(7,3)",
"(1,3)",
"(-1,4)"
] | D | (-1,4) | This one factors easily:
x^2 – 3x – 4 = 0
(x + 1)(x – 4) = 0
x + 1 = 0 or x – 4 = 0
x = –1 or x = 4
The solution is x = –1, 4
Ans: D | aqua_rat |
The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 5 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each? | [
"4538",
"4529",
"4528",
"4530"
] | D | 4530 | Area of the four walls = 2h(l + b)
Since there are doors and windows, area of the walls
= 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.
Total cost = 906 * 5
= Rs. 4530
Answer: D | aqua_rat |
A single discount equivalent to the discount series of 20%, 10% and 5% is? | [
"31.9",
"31.1",
"31.6",
"31.2"
] | C | 31.6 | :
100*(80/100)*(90/100)*(95/100) = 68.4
100 - 68.4 = 31.6
Answer: C | aqua_rat |
Anand and Deepak started a business investing Rs. 27,500 and Rs. 85,000 respectively. Out of a total profit of Rs. 45,800, Deepak's share is? | [
"Rs. 9400",
"Rs. 34604.4",
"Rs. 8400",
"Rs. 3400"
] | B | Rs. 34604.4 | Ratio of their shares = 27500: 85000 = 11 : 34
Deepak's share = 45800* 34/45 = Rs. 34604.4
Answer:B | aqua_rat |
Last year Department Store X had a sales total for December that was 7 times the average (arithmetic mean) of the monthly sales totals for January through November. The sales total for December was what fraction of the sales total for the year? | [
"1/4",
"4/15",
"1/3",
"7/18"
] | D | 7/18 | Let avg for 11 mos. = 10
Therefore, Dec = 70
Year total = 11*10 + 70 = 180
Answer = 70/180 = 7/18 = D | aqua_rat |
The Ghaziabad-Hapur-Meerut EMU and the Meerut-Hapur-Ghaziabad EMU start at the same time from Ghaziabad and Meerut and proceed towards each other at 16 km/hr and 21 km/hr respectively. When they meet, it is found that one train has travelled 60 km more than the other. The distance between two stations is: | [
"445 km",
"444 km",
"400 km",
"524 km"
] | B | 444 km | Explanation :
The two trains start simultaneously. Let they meet after a time ‘t’.
The train that has covered 60 km more must be the faster of the two.
Hence,
=>60=(21–16)×t.
=>t=12 hours.
Since they are traveling towards each other, total distance is the sum of the distances travelled by the two trains individually.
T... | aqua_rat |
(39,897)(0.0096)/198.76 is approximately | [
"0.02",
"0.2",
"2",
"20"
] | C | 2 | 39,897 can be written as 40,000 (approximately)
0.0096 can be written as 0.01 (approximately
198.76 can be written as 200 (approximately)
40,000*0.01/ 200= 2 (approximately)
C is the answer | aqua_rat |
When positive integer t is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180? | [
"0",
"1",
"2",
"3"
] | B | 1 | the equation that can be formed t is 13x+2=8y+5..
13x-3=8y...
as we can see x can take only odd values as the RHS will always be even..
Also x can take values till 13 as 13*14>180..
now we have to substitue x as 1,3,5,7,9,11,13...
once we find 7 fitting in , any other value need not be checked as every 4th value will g... | aqua_rat |
A runs 1 2⁄3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time? | [
"200 m",
"250 m",
"450 m",
"350 m"
] | A | 200 m | Speed of A : Speed of B = 5⁄3 : 1 = 5 : 3
i.e., In a race of 5 m, A runs 5 m and B runs 3 m
i.e., A gains 2 m over B in a race of 5 m
=> A gains 80 m over B in a race of 52×80 = 200 m
Hence, winning point should be 200 m away from the starting point.
ANSWER:A | aqua_rat |
John and Tony began business with Rs.12000 and Rs.14000 after 8 months, John withdraws Rs.2000 and Tony withdraws Rs.4000. At the end of the year, their profits amounted to Rs.4500 find the share of Tony. | [
"2375",
"2325",
"2300",
"3375"
] | A | 2375 | (12*8 + 10*4):(14*8 + 10*4)
17:19
19/36 * 4500 = 2375. Answer: A | aqua_rat |
Two trains of equal length, running with the speeds of 60 and 16 kmph, take 50 seconds to cross each other while they are running in the same direction. What time will they take to cross each other if they are running in opposite directions? | [
"10.11",
"8.11",
"77.2",
"13.15"
] | D | 13.15 | RS = 60 -40 = 20 * 5/18 = 100/18
T = 50
D = 50 * 100/18 = 2500/9
RS = 60 + 16 = 76 * 5/18
T = 2500/9 * 18/380= 13.15 sec.Answer: D | aqua_rat |
63 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? | [
"A)87",
"B)77",
"C)66",
"D)55"
] | B | B)77 | (63 * 8)/30
= (x * 6)/50
=> x =140
140 – 63
= 77
Answer:B | aqua_rat |
A man can row with a speed of 15 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is? | [
"27",
"27",
"20",
"99"
] | C | 20 | M = 15
S = 5
DS = 15 + 5 = 20'
Answer:C | aqua_rat |
K = wxyz, where w, x, y, z are prime numbers. Not including 1 and K, how many factors does K have? | [
"7",
"14",
"21",
"28"
] | B | 14 | Suppose w = 2, x = 3, y = 5 and z = 7. Then wxyz = 210.
To find out how many factors 210 has, go through different combinations of the prime factors as follows. You don't even need to calculate the answers but I have done so here:
(factor #1) 2
(factor #2) 3
(factor #3) 5
(factor #4) 7
(factor #5) 2 x 3 = 6
(factor #6)... | aqua_rat |
A and B are playing mathematical puzzles. A asks B "which whole numbers, greater than one, can divide all the nine three digit numbers 111,222,333,444,555,666, 777,888 and 999?"
B immediately gave the desired answer. It was :- | [
"3, 37 and 119",
"3 AND 37 and 111",
"9, 37 and 111",
"3, 9 and 37"
] | B | 3 AND 37 and 111 | Explanation :
Each of the number can be written as a multiple of 111. And,
The factors of 111 are 3 and 37.
Thus, the desired answer is 3, 37 and 111.
Answer : B | aqua_rat |
Solve the equation for x : 6x - 27 + 3x = 4 + 9 - x? | [
"4",
"5",
"3",
"9"
] | A | 4 | 9 x + x = 13 + 27
10 x = 40 => x = 4
Answer:A | aqua_rat |
A person travels equal distances with speeds of 5 km/hr, 6 km/hr and 7 km/hr and takes a total time of 47 minutes. The total distance is? | [
"5 km",
"3 km",
"7 km",
"9 km"
] | A | 5 km | Let the total distance be 3x km.
Then, x/5 + x/6 + x/7 = 27/53
27x/53 = 47/60 => x = 1.54
Total distance = 3 * 1.54 = 4.61 km.
Answer:A | aqua_rat |
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