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from typing import List def sort_third(l: List[int]) -> List[int]: """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding ...
return l
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return a string containing space-delimited numbers starting from 0 upto n inclusive. // >>> stringSequence((0l)) // ("0") /...
String result = "";
for (long i = 0; i <= n; i++) { result += i + " "; } return result.trim(); } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes an array array list of numbers as input and returns // the number of elements in the array array list ...
return digits[0];
} public long getLastDigit(long n) { long[] digits = getDigits(n); return digits[digits.length - 1]; } public long[] getDigits(long n) { ArrayList<Long> digits = new ArrayList<Long>(); while (n != 0) { ...
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than // zero, and has a frequency greater than or equal to the value of the integer itself. // The frequency of an integer is the number of times it appears in the array. // If no such a value exist, return -1. // Exam...
var keys = Object.keys(h);
var max = 0; for (var i=0; i<keys.length; i++){ if (keys[i] > max && h[keys[i]] >= keys[i]){ max = keys[i]; } } if (max == 0){ return -1; } return max; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // prime_fib returns n-th number that is a Fibonacci number and it's also prime. // >>> primeFib((1l)) // (2l) // >>> primeFib...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return array list of all prefixes from shortest to longest of the input string // >>> allPrefixes(("abc")) // (new ArrayList<St...
}
}
//Given a non-empty array of integers lst. add the even elements that are at odd indices.. // Examples: // >>> add([4, 2, 6, 7]) // 2 function add(lst){
var add = 0;
for(var i = 0; i < lst.length; i++) { if(lst[i] % 2 == 0 && i % 2 != 0) { add += lst[i]; } } return add; }
//xs represent coefficients of a polynomial. // xs[0] + xs[1] * x + xs[2] * x^2 + .... // Return derivative of this polynomial in the same form. // >>> derivative([3, 1, 2, 4, 5]) // [1, 4, 12, 20] // >>> derivative([1, 2, 3]) // [2, 6] function derivative(xs){
let coeff = [];
for(let i = 1; i < xs.length; i++){ coeff.push(xs[i] * i); } return coeff; }
//Return true if a given number is prime, and false otherwise. // >>> is_prime(6) // false // >>> is_prime(101) // true // >>> is_prime(11) // true // >>> is_prime(13441) // true // >>> is_prime(61) // true // >>> is_prime(4) // false // >>> is_prime(1) // false function is_prime(n){ if (n==1) { return fals...
return false;
} var limit = Math.sqrt(n); for (var i = 3; i <= limit; i += 2) { if (n%i==0) { return false; } } return true; }
//This function takes an array l and returns an array l' such that // l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal // to the values of the corresponding indicies of l, but sorted. // >>> sort_third([1, 2, 3]) // [1, 2, 3] //...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // triples_sum_to_zero takes an array array list of integers as an input. // it returns true if there are three distinct elements in t...
while (j < k) {
long currSum = sortedList.get(i) + sortedList.get(j) + sortedList.get(k); if (currSum == 0) { return true; } else if (currSum < 0) { j++; } else { k--; } } } ...
//Given array of numbers (of at least two elements), apply a linear transform to that array, // such that the smallest number will become 0 and the largest will become 1 // >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) // [0.0, 0.25, 0.5, 0.75, 1.0] function rescale_to_unit(numbers){ var min = Math.min.apply(Math, n...
var max = Math.max.apply(Math, numbers);
var sub = max - min; var unit = []; for (var i = 0; i < numbers.length; i++) { unit.push((numbers[i] - min) / sub); } return unit; }
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than // zero, and has a frequency greater than or equal to the value of the integer itself. // The frequency of an integer is the number of times it appears in the array. // If no such a value exist, return -1. // Exam...
if (x in h){
h[x] += 1; } else{ h[x] = 1; } } var keys = Object.keys(h); var max = 0; for (var i=0; i<keys.length; i++){ if (keys[i] > max && h[keys[i]] >= keys[i]){ max = keys[i]; } } if (max == 0){ return -1; } return max; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The Brazilian factorial is defined as: // brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! // where n > 0 // For ex...
}
//There are eight planets in our solar system: the closerst to the Sun // is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, // Uranus, Neptune. // Write a function that takes two planet names as strings planet1 and planet2. // The function should return an array containing all planets whose orbit...
return res;
}
def file_name_check(file_name: str) -> str: """Create a function which takes a string representing a file's name, and returns 'Yes' if the the file's name is valid, and returns 'No' otherwise. A file's name is considered to be valid if and only if all the following conditions are met: - There shoul...
if e_name not in ['txt', 'exe', 'dll']:
return 'No' return 'Yes'
def encrypt(s: str) -> str: """Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places. For example: >>> encrypt('hi'...
for i in s:
output_string += input_string[(input_string.index(i)+4)%26] return output_string
//The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fib4(0) -> 0 // fib4(1) -> 0 // fib4(2) -> 2 // fib4(3) -> 0 // fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). // Please write a function to efficiently compute the n-th element of the fib4 number sequen...
var prev = [0,0,2,0];
if(n<prev.length){ return prev[n]; } for(var i=4;i<=n;i++){ var curr = prev[0]+prev[1]+prev[2]+prev[3]; prev[0] = prev[1]; prev[1] = prev[2]; prev[2] = prev[3]; prev[3] = curr; } return prev[3]; }
from typing import List def move_one_ball(arr: List[int]) -> bool: """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the followi...
if flag == True:
return False flag = True elif arr[i-1] < arr[i]: flag = False return True
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of numbers, return whether or not they are sorted // in ascending order. If array list has more than 1 du...
if (lst.size() == 0) {
return true; } else { int running_max = 0; int previous_number = 0; boolean first_time = true; boolean seen_2_in_a_row = false; for (Long number : lst) { if (first_time) { first_time = false; ...
//Write a function that accepts an array of strings as a parameter, // deletes the strings that have odd lengths from it, // and returns the resulted array with a sorted order, // The array is always an array of strings and never an array of numbers, // and it may contain duplicates. // The order of the array should be...
return 0;
} } }); } var a = ["aa", "a", "aaa"]; var b = ["ab", "a", "aaa", "cd"];
//Input to this function is a string containing multiple groups of nested parentheses. Your goal is to // separate those group into separate strings and return the array of those. // Separate groups are balanced (each open brace is properly closed) and not nested within each other // Ignore any spaces in the input stri...
var groups = [];
for (var i = 0; i < paren_string.length; i++){ if (paren_string[i] === '('){ count++; group += paren_string[i]; } else if (paren_string[i] === ')'){ count--; group += paren_string[i]; } if (count === 0 && group){ groups.push...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // We have an array array list 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array array list will be randomly...
}
}
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). >>> find_closest_elements([1...
temp = abs(numbers[i] - numbers[j])
temp_index = i temp2_index = j if numbers[temp_index] > numbers[temp2_index]: temp, temp2 = numbers[temp2_index], numbers[temp_index] else: temp, temp2 = numbers[temp_index], numbers[temp2_index] return temp, temp2 print(find_closest_elements([1.0, 2...
from typing import Union, List def split_words(txt: str) -> Union[List[str], int]: """ Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you should split on commas ',' if no commas exists you should return the number of lower-case letters with odd ord...
return txt.split(',')
else: return len([letter for letter in txt if letter in alphabet and alphabet.index(letter) % 2 == 1])
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array will be randomly ordered. Your task is to determine if // it is possible to get an array sorted in non-decreasing order by performing // the following operation on the given array: // You are allowed to perform right shift o...
diff_count += 1;
} } if(diff_count > 1){ return false; } else{ return true; } }
from typing import List def maximum(arr: List[int], k: int) -> List[int]: """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: >>> maximum([-3, -4, 5], 3) [-4, -3, 5] Example 2: >>> maximum([4, -...
Returns the maximum k numbers in the given array
""" if k == 0: return [] elif k == 1: return [max(arr)] else: max_num = max(arr) arr.remove(max_num) return [max_num] + get_max(arr, k - 1) return sorted(get_max(arr, k))
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces. // For each of the group, output the deepest level of nesting of parentheses. // E.g. (()()) has maximum two levels of nesting while ((())) has three. // >>> parse_nested_parens("(()()) ((())) () ((())()())") //...
level = 0;
} } result.push(maxlevel); return result; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // "Given an array array list representing a branch of a tree that has non-negative integer nodes // your task is to pluck one of the ...
newArr.add((long)minIndex);
return newArr; } }
//Implement the function f that takes n as a parameter, // and returns an array of size n, such that the value of the element at index i is the factorial of i if i is even // or the sum of numbers from 1 to i otherwise. // i starts from 1. // the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ...
}
//You are given a rectangular grid of wells. Each row represents a single well, // and each 1 in a row represents a single unit of water. // Each well has a corresponding bucket that can be used to extract water from it, // and all buckets have the same capacity. // Your task is to use the buckets to empty the wells. ...
var c = grid[0].length;
for(var i = 0; i < r; i++){ sum = 0; for(var j = 0; j < c; j++){ sum += grid[i][j]; } maxFill += Math.ceil(sum/capacity); } return maxFill; }
from typing import List def triples_sum_to_zero(l: List[int]) -> bool: """ triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. >>> triples_sum_to_zero([1, 3, 5, 0]) False >>> tripl...
return True
return False
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of positive integers x. return a sorted array list of all // elements that hasn't any even digit. //...
if (y % 2 == 0) {
unique = false; break; } z = z / 10; } if (unique) { b.add(x.get(i)); } } Collections.sort(b); return b; } }
from typing import List def numerical_letter_grade(grades: List[float]) -> List[str]: """It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. Sh...
final.append('B-')
elif x > 2.0: final.append('C+') elif x > 1.7: final.append('C') elif x > 1.3: final.append('C-') elif x > 1.0: final.append('D+') elif x > 0.7: final.append('D') elif x > 0.0: final.append('D-') ...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Check if in given array list of numbers, are any two numbers closer to each other than // given threshold. // >>> hasCloseEleme...
}
//Filter an input array of strings only for ones that start with a given prefix. // >>> filter_by_prefix([], "a") // [] // >>> filter_by_prefix(["abc", "bcd", "cde", "array"], "a") // ["abc", "array"] function filter_by_prefix(strings, prefix){
return strings.filter( function(str){
return str.startsWith(prefix); }); }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that accepts an array array list of strings as a parameter, // deletes the strings that have odd lengths from it, ...
ArrayList<String> result = new ArrayList<String>();
for (String s : lst) { if (s.length() % 2 == 0) { result.add(s); } } Collections.sort(result, new Comparator<String>() { @Override public int compare(String s1, String s2) { if (s1.length() == s2.length()) { ...
def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a palindrome. - Append to the end of the string reverse of a string prefix that comes before the palindromic suffi...
return string
prefix = string[::-1] for i in range(len(string)): if string[i:] == prefix[:len(string) - i]: return string + prefix[len(string) - i:] return string
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of numbers, return whether or not they are sorted // in ascending order. If array list has more than 1 du...
return true;
} else { int running_max = 0; int previous_number = 0; boolean first_time = true; boolean seen_2_in_a_row = false; for (Long number : lst) { if (first_time) { first_time = false; previous_...
//Given array of integers, return array in strange order. // Strange sorting, is when you start with the minimum value, // then maximum of the remaining integers, then minimum and so on. // Examples: // >>> strange_sort_list([1, 2, 3, 4]) // [1, 4, 2, 3] // >>> strange_sort_list([5, 5, 5, 5]) // [5, 5, 5, 5] // >>> str...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input to this function is a string representing musical notes in a special ASCII format. // Your task is to parse this string and r...
res.add((long)4l);
} } else if (chars[i] == '.') { if (i + 1 < chars.length && chars[i + 1] == '|') { res.add((long)1l); i += 1; } } } return res; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function count_nums which takes an array array list of integers and returns // the number of elements which has a sum of di...
for (int j = 0; j < str.length(); j++) {
sum = sum + (int) Character.getNumericValue(str.charAt(j)); } } if (sum > 0) { result++; } } return result; } }
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces. // For each of the group, output the deepest level of nesting of parentheses. // E.g. (()()) has maximum two levels of nesting while ((())) has three. // >>> parse_nested_parens("(()()) ((())) () ((())()())") //...
}
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers // Example // >>> is_equal_to_sum_even(4) // false // >>> is_equal_to_sum_even(6) // false // >>> is_equal_to_sum_even(8) // true function is_equal_to_sum_even(n){ let m =0; for(let i=2;i<n;i+=2){ for(let ...
if(m==1){
return true; } else{ return false; } }
def iscube(a: int) -> bool: """ Write a function that takes an integer a and returns True if this ingeger is a cube of some integer number. Note: you may assume the input is always valid. Examples: >>> iscube(1) True >>> iscube(2) False >>> iscube(-1) True >>> iscube(64)...
import math
a = abs(a) if a == 0: return True for i in range(1,int(math.sqrt(a))+1): if i**3 == a: return True return False pass
from typing import Union def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]: """ Create a function that takes integers, floats, or strings representing real numbers, and returns the larger variable in its given variable type. Return None if the values ...
elif a < b:
return b else: return None elif isinstance(a, float) and isinstance(b, int): if a > b: return a elif a < b: return b else: return None elif isinstance(a, str) and isinstance(b, int): a_tmp = a.replace(',', '.') ...
def is_prime(n: int) -> bool: """Return true if a given number is prime, and false otherwise. >>> is_prime(6) False >>> is_prime(101) True >>> is_prime(11) True >>> is_prime(13441) True >>> is_prime(61) True >>> is_prime(4) False >>> is_prime(1) False """ ...
return False
for i in range(2, n//2 + 1): if n % i == 0: return False return True
//Write a function that takes an integer a and returns true // if this ingeger is a cube of some integer number. // Note: you may assume the input is always valid. // Examples: // >>> iscube(1) // true // >>> iscube(2) // false // >>> iscube(-1) // true // >>> iscube(64) // true // >>> iscube(0) // true // >>> iscube(...
return true;
}else{ return false; } }
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence. // The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined // as follows: start with any positive integer n. Then each term is obtained from the // previous term as follows: if the previous ...
}
if(odd_count != 0){ odd_numbers.sort(function(a, b){return a-b}) return odd_numbers } else{ odd_numbers.push(1) return odd_numbers } }
from typing import Union, List def split_words(txt: str) -> Union[List[str], int]: """ Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you should split on commas ',' if no commas exists you should return the number of lower-case letters with odd ord...
alphabet = [chr(letter) for letter in range(ord('a'), ord('z') + 1)]
if ' ' in txt: return txt.split(' ') elif ',' in txt: return txt.split(',') else: return len([letter for letter in txt if letter in alphabet and alphabet.index(letter) % 2 == 1])
//Write a function that takes an array of numbers as input and returns // the number of elements in the array that are greater than 10 and both // first and last digits of a number are odd (1, 3, 5, 7, 9). // For example: // >>> specialFilter([15, -73, 14, -15]) // 1 // >>> specialFilter([33, -2, -3, 45, 21, 109]) //...
for(let i = 0; i < nums.length; i++){
let num = nums[i]; let firstDigit = nums[i].toString()[0]; let lastDigit = nums[i].toString()[nums[i].toString().length - 1]; if(num > 10 && firstDigit % 2 !== 0 && lastDigit % 2 !== 0){ count++; } } return count; }
from typing import List def Strongest_Extension(class_name: str, extensions: List[str]) -> str: """You will be given the name of a class (a string) and a list of extensions. The extensions are to be used to load additional classes to the class. The strength of the extension is as follows: Let CAP be the nu...
return class_name + '.' + best_extension
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Find how many times a given substring can be found in the original string. Count overlaping cases. // >>> howManyTimes((""), ("a"))...
index++;
count++; } } return count; } }
//Given a string representing a space separated lowercase letters, return an object // of the letter with the most repetition and containing the corresponding count. // If several letters have the same occurrence, return all of them. // Example: // >>> histogram("a b c") // {"a": 1, "b": 1, "c": 1} // >>> histogram("a ...
}
} console.log(count); var max = 0; var result = {}; for (var key in count){ if (count[key] > max){ max = count[key]; result = {}; result[key] = max; } else if (count[key] === max){ result[key] = max; } } return result; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Implement the function f that takes n as a parameter, // and returns an array array list of size n, such that the value of the elem...
}
ret.add(v); } return ret; } }
from typing import List def maximum(arr: List[int], k: int) -> List[int]: """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: >>> maximum([-3, -4, 5], 3) [-4, -3, 5] Example 2: >>> maximum([4, -...
if k == 0:
return [] elif k == 1: return [max(arr)] else: max_num = max(arr) arr.remove(max_num) return [max_num] + get_max(arr, k - 1) return sorted(get_max(arr, k))
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // In this task, you will be given a string that represents a number of apples and oranges // that are distributed in a basket of fru...
return n - apples - oranges;
} }
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers // Example // >>> is_equal_to_sum_even(4) // false // >>> is_equal_to_sum_even(6) // false // >>> is_equal_to_sum_even(8) // true function is_equal_to_sum_even(n){ let m =0; for(let i=2;i<n;i+=2){ for(let ...
}
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input to this function is a string representing musical notes in a special ASCII format. // Your task is to parse this string and r...
i += 1;
} } } return res; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return n-th Fibonacci number. // >>> fib((10l)) // (55l) // >>> fib((1l)) // (1l) // >>> fib((8l)) // (21l) ...
return 1l;
} else { return Problem.fib((n - 1)) + Problem.fib((n - 2)); } } }
//You are given a positive integer n. You have to create an integer array a of length n. // For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. // Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, // and a[i] + a[j] + a[k] is a multiple of 3. // Example : // >>> get_max_triples(5) // 1 // Ex...
if((arr[i]+arr[j]+arr[k])%3 === 0){
result++; } } } } return result; }
from typing import Tuple def bf(planet1: str, planet2: str) -> Tuple[str, ...]: """ There are eight planets in our solar system: the closerst to the Sun is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, Uranus, Neptune. Write a function that takes two planet names as strings p...
if planet1 not in planets or planet2 not in planets:
return () start = planets.index(planet1) end = planets.index(planet2) if start < end: planets = planets[start+1:end] else: planets = planets[end+1:start] return tuple(planets)
//Create a function which returns the largest index of an element which // is not greater than or equal to the element immediately preceding it. If // no such element exists then return -1. The given array will not contain // duplicate values. // Examples: // >>> can_arrange([1, 2, 4, 3, 5]) // 3 // >>> can_arrange([1,...
if(arr[i] < max){
res = i; }else{ max = arr[i]; } } return res; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // This function takes an array array list l and returns an array array list l' such that // l' is identical to l in the indicies that...
l_r.add(l.get(i));
} } for (int i = 0; i < l_e.size(); i++) { long min = l_e.get(i); for (int j = i; j < l_e.size(); j++) { if (l_e.get(j) < min) { min = l_e.get(j); l_e.set(j, l_e.get(i)); l_e.set(i, min); ...
def int_to_mini_roman(number: int) -> str: """ Given a positive integer, obtain its roman numeral equivalent as a string, and return it in lowercase. Restrictions: 1 <= num <= 1000 Examples: >>> int_to_mini_roman(19) 'xix' >>> int_to_mini_roman(152) 'clii' >>> int_to_mini_roman(...
}
roman_numeral = '' for key in sorted(roman_numerals.keys(), reverse=True): roman_numeral += roman_numerals[key] * (number // key) number = number % key return roman_numeral
//Write a function that accepts an array of strings as a parameter, // deletes the strings that have odd lengths from it, // and returns the resulted array with a sorted order, // The array is always an array of strings and never an array of numbers, // and it may contain duplicates. // The order of the array should be...
}
else if(a > b){ return 1; } else{ return 0; } } }); } var a = ["aa", "a", "aaa"]; var b = ["ab", "a", "aaa", "cd"];
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // This function takes two positive numbers x and y and returns the // biggest even integer number that is in the range [x, y] inclusi...
long chosen = -1;
for (long i = x; i <= y; i++) { if (i % 2 == 0) { chosen = i; } } return chosen; } }
from typing import List def match_parens(lst: List[str]) -> str: """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will b...
if open_parens == 0 and close_parens == 0:
return 'Yes' return 'No'
from typing import List def parse_nested_parens(paren_string: str) -> List[int]: """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of ne...
current_depth = 0
for paren in parens: if paren == '(': current_depth += 1 max_depth = max(max_depth, current_depth) elif paren == ')': current_depth -= 1 result.append(max_depth) return result
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // In this problem, you will implement a function that takes two array lists of numbers, // and determines whether it is possible to p...
lst1.set(i, lst2.get(j));
lst2.set(j, (long) 1); break; } } } } return (lst1.stream().allMatch(x -> x % 2 == 0)) ? "YES" : "NO"; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers // Example // >>> isEqualToSum...
return false;
} }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // prime_fib returns n-th number that is a Fibonacci number and it's also prime. // >>> primeFib((1l)) // (2l) // >>> primeFib...
}
} return fib; } }
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """ new_string = "" for character in string: if character.isupper(): new_string += character.lower()
else:
new_string += character.upper() return new_string
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // pairs_sum_to_zero takes an array array list of integers as an input. // it returns true if there are two distinct elements in the a...
for (int j = i + 1; j < l.size(); j++) {
if (l.get(i) + l.get(j) == 0) { return true; } } } return false; } }
def is_simple_power(x: int, n: int) -> bool: """Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x For example: >>> is_simple_power(1, 4) true >>> is_simple_power(2, 2) true >>> is_sim...
x /= n
return True
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given array list of integers, return array list in strange order. // Strange sorting, is when you start with the minimum value, ...
if (lst.size() <= 1) {
return lst; } ArrayList<Long> result = new ArrayList<Long>(); ArrayList<Long> sorted = new ArrayList<Long>(lst); Collections.sort(sorted); int min = 0; int max = sorted.size() - 1; while (min <= max) { result.add(sorted.get(min)); ...
//You are given an array of two strings, both strings consist of open // parentheses '(' or close parentheses ')' only. // Your job is to check if it is possible to concatenate the two strings in // some order, that the resulting string will be good. // A string S is considered to be good if and only if all parentheses...
};
const str1 = lst[0]; const str2 = lst[1]; if (is_good(str1 + str2)){ return 'Yes'; } if (is_good(str2 + str1)){ return 'Yes'; } return 'No'; }
from typing import List def common(l1: List[int], l2: List[int]) -> List[int]: """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """
return sorted(set(l1) & set(l2))
//You are given an array arr of integers and you need to return // sum of magnitudes of integers multiplied by product of all signs // of each number in the array, represented by 1, -1 or 0. // Note: return undefined for empty arr. // Example: // >>> prod_signs([1, 2, 2, -4]) // 9 // >>> prod_signs([0, 1]) // 0 // >>> ...
total += Math.abs(arr[i]);
if(arr[i] < 0){ pro *= -1; } else if(arr[i] == 0){ pro *= 0; } } total *= pro; return total; } }
from typing import List def sort_third(l: List[int]) -> List[int]: """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding ...
j = i - 2
while j >= 0 and l[j] > l[j + 3]: l[j], l[j + 3] = l[j + 3], l[j] j -= 3 return l
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) [0.0, 0...
return [0.5] * len(numbers)
return [(val - _min) / (_max - _min) for val in numbers]
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of non-negative integers, return a cojava of the given array array list after sorting, // you will sort t...
}
if(array.size()==1) { return array; } if(array.size()>1) { if((array.get(0)+array.get(array.size()-1))%2==0) { Collections.sort(array, Collections.reverseOrder()); } else { Collections.sort(array); } ...
//You'll be given a string of words, and your task is to count the number // of boredoms. A boredom is a sentence that starts with the word "I". // Sentences are delimited by '.', '?' or '!'. // For example: // >>> is_bored("Hello world") // 0 // >>> is_bored("The sky is blue. The sun is shining. I love this weather") ...
boredoms++;
} } return boredoms; }
def encrypt(s: str) -> str: """Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places. For example: >>> encrypt('hi'...
input_string = "abcdefghijklmnopqrstuvwxyz"
output_string = "" for i in s: output_string += input_string[(input_string.index(i)+4)%26] return output_string
//Given a string s and a natural number n, you have been tasked to implement // a function that returns an array of all words from string s that contain exactly // n consonants, in order these words appear in the string s. // If the string s is empty then the function should return an empty array. // Note: you may as...
}
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fibfib(0) == 0 // fib...
memo[2] = 1;
for (int i = 3; i <= n; i++) { memo[i] = memo[i - 1] + memo[i - 2] + memo[i - 3]; } return memo[(int) n]; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Create a function which returns the largest index of an element which // is not greater than or equal to the element immediately pr...
return p;
} }
from typing import Tuple def bf(planet1: str, planet2: str) -> Tuple[str, ...]: """ There are eight planets in our solar system: the closerst to the Sun is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, Uranus, Neptune. Write a function that takes two planet names as strings p...
return ()
start = planets.index(planet1) end = planets.index(planet2) if start < end: planets = planets[start+1:end] else: planets = planets[end+1:start] return tuple(planets)
//Circular shift the digits of the integer x, shift the digits right by shift // and return the result as a string. // If shift > number of digits, return digits reversed. // >>> circular_shift(12, 1) // "21" // >>> circular_shift(12, 2) // "12" function circular_shift(x, shift){ var str = x.toString(); var len = str...
}
return res; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes an array array list of numbers as input and returns // the number of elements in the array array list ...
}
Collections.reverse(digits); return digits.stream().mapToLong(i -> i).toArray(); } } helper h = new helper(); return nums.stream().filter(x -> x > 10).filter(x -> { long firstDigit = h.getFirstDigit(x); long lastDigit = h.getLas...
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string, find out how many distinct characters (regardless of case) does it consist of // >>> countDistinctCharacters(("xyzX...
string = string.toLowerCase();
Set<Character> set = new HashSet<Character>(); for (int i = 0; i < string.length(); i++) { char c = string.charAt(i); set.add(c); } result = set.size(); return result; } }
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """ new_string = "" for character in string:
if character.isupper():
new_string += character.lower() else: new_string += character.upper() return new_string
//Given an array of integers nums, find the minimum sum of any non-empty sub-array // of nums. // Example // >>> minSubArraySum([2, 3, 4, 1, 2, 4]) // 1 // >>> minSubArraySum([-1, -2, -3]) // -6 function minSubArraySum(nums){ let sum = 0; let minSum = nums[0];
for(let i = 0; i < nums.length; i++){
sum += nums[i]; if(sum < minSum){ minSum = sum; } if(sum > 0){ sum = 0; } } return minSum; }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // "Given an array array list representing a branch of a tree that has non-negative integer nodes // your task is to pluck one of the ...
}
ArrayList<Long> newArr = new ArrayList<Long>(); if (minIndex == -1) { return newArr; } newArr.add(minValue); newArr.add((long)minIndex); return newArr; } }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // It is the last week of the semester and the teacher has to give the grades // to students. The teacher has been making her own algo...
} else if (currentGrade > 1.0f) {
letterGrades.add("D+"); } else if (currentGrade > 0.7f) { letterGrades.add("D"); } else if (currentGrade > 0.0f) { letterGrades.add("D-"); } else { letterGrades.add("E"); } } return letterGrad...
//Create a function that takes integers, floats, or strings representing // real numbers, and returns the larger variable in its given variable type. // Return undefined if the values are equal. // Note: If a real number is represented as a string, the floating point might be . or , // >>> compare_one(1, 2.5) // 2.5 //...
}
} }
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given the name of a class (a string) and an array array list of extensions. // The extensions are to be used to load ad...
}
} return class_name + "." + strongest; } }
def fruit_distribution(s: str, n: int) -> int: """ In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the ora...
for fruit in s.split(' '):
try: fruits.append(int(fruit)) except: pass return n - sum(fruits)
from typing import List def filter_by_prefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. >>> filter_by_prefix([], 'a') [] >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a') ['abc', 'array'] """
return [s for s in strings if s.startswith(prefix)]
from typing import List def triples_sum_to_zero(l: List[int]) -> bool: """ triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. >>> triples_sum_to_zero([1, 3, 5, 0]) False >>> tripl...
for k in range(j + 1, len(l)):
if l[i] + l[j] + l[k] == 0: return True return False