prefix stringlengths 0 918k | middle stringlengths 0 812k | suffix stringlengths 0 962k |
|---|---|---|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// In this Kata, you have to sort an array array list of non-negative integers according to
// number of ones in their binary represen... | Collections.sort(arr, (a, b) -> { | long a1 = a, b1 = b;
if (a1 < 0) {
a1 = -a1;
}
if (b1 < 0) {
b1 = -b1;
}
return Long.bitCount(a1) == Long.bitCount(b1) ? Long.compare(a, b) : Integer.compare(Long.bitCount(a1), Long.bitCount(b1));
});
... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of integers.
// You need to find the largest prime value and return the sum of its digits.
//... | while (largestPrime > 0) { | output += largestPrime % 10;
largestPrime /= 10;
}
return output;
}
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given an array array list of integers.
// You need to find the largest prime value and return the sum of its digits.
//... | long largestPrime = 0l; | for (Long item : lst) {
long number = item;
int counter = 0;
if (item == 1) {
continue;
}
if (item == 2) {
counter = 1;
}
else {
int l = 1;
while (l <= (int) number... |
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | count++; | }
}
return count;
} |
//You're given an array of deposit and withdrawal operations on a bank account that starts with
// zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
// at that point function should return true. Otherwise it should return false.
// >>> below_zero([1, 2, 3])
// false
// >... | for (var i = 0; i < operations.length; i++) { | sum += operations[i];
if (sum < 0) {
return true;
}
}
return false;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return array list with elements incremented by 1.
// >>> incrList((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l))... | } | |
from typing import List
def f(n: int) -> List[int]:
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of... | a.append(sum(range(1,i+1))) | return a
pass |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a string representing a sentence,
// the sentence contains some words separated by a space,
// and you have to re... | for (String word : words) { | isPrime = false;
for (int prime : primes) {
if (word.length() == prime) {
isPrime = true;
break;
}
}
if (isPrime) {
ans.append(word + " ");
}
}
if (ans.leng... |
//Given an integer. return an array that has the number of even and odd digits respectively.
// Example:
// >>> even_odd_count(-12)
// [1, 1]
// >>> even_odd_count(123)
// [1, 2]
function even_odd_count(num){
num = Math.abs(num);
var evens = 0;
var odds = 0;
for(var i = 0; i < num.toString().length; i++){
if(num.... | } | }
return [evens, odds];
}
|
//You are given a 2 dimensional data, as a nested arrays,
// which is similar to matrix, however, unlike matrices,
// each row may contain a different number of columns.
// Given lst, and integer x, find integers x in the array,
// and return array of arrays, [(x1, y1), (x2, y2) ...] such that
// each array is a coordi... | let coordinates = []; | for (let i = 0; i < lst.length; i++){
let array = lst[i];
for (let j = 0; j < array.length; j++){
if (lst[i][j] === x){
coordinates.push([i, j]);
}
}
}
return coordinates.sort(function(a, b){
return a[0] - b[0] || b[1] - a[1];
});
}... |
from typing import List
def solution(lst: List[int]) -> int:
"""Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
Examples
>>> solution([5, 8, 7, 1])
12
>>> solution([3, 3, 3, 3, 3])
9
>>> solution([30, 13, 24, 321])
0
""... | return sum([elem for i, elem in enumerate(lst) if elem % 2 != 0 and i % 2 == 0]) | |
def largest_prime_factor(n: int) -> int:
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
largest = 1
factor = 2
while factor < n:
if n % factor == 0:
largest = factor... | factor += 1 | return max(largest, n)
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// brackets is a string of "<" and ">".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correc... | } | |
//You are given two intervals,
// where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
// The given intervals are closed which means that the interval (start, end)
// includes both start and end.
// For each given interval, it is assumed that its start is less or equal its end.
// Y... | let start = Math.max(interval1[0], interval2[0]); | let end = Math.min(interval1[1], interval2[1]);
if (start >= end) {
return "NO";
}
let length = end - start;
let primes = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97];
return primes.includes(length) ? "YES" : "NO";
}
|
//Given the lengths of the three sides of a triangle. Return the area of
// the triangle rounded to 2 decimal points if the three sides form a valid triangle.
// Otherwise return -1
// Three sides make a valid triangle when the sum of any two sides is greater
// than the third side.
// Example:
// >>> triangle_area(3... | } | |
from typing import List
def get_odd_collatz(n: int) -> List[int]:
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. The... | return sorted(list(set([x for x in collatz_list if x % 2 != 0]))) | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive floating point number, it can be decomposed into
// and integer part (largest integer smaller than given number) a... | return (number - (int)number); | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// The Brazilian factorial is defined as:
// brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
// where n > 0
// For ex... | } | } |
//"
// This function will take an array of integers. For all entries in the array, the function shall square the integer entry if its index is a
// multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
// change the entries in the array whose inde... | if (i % 3 == 0){ | sum += lst[i]*lst[i];
} else if (i % 4 == 0){
sum += lst[i]*lst[i]*lst[i];
} else {
sum += lst[i];
}
}
return sum;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word... | } | } |
//Write a function count_nums which takes an array of integers and returns
// the number of elements which has a sum of digits > 0.
// If a number is negative, then its first signed digit will be negative:
// e.g. -123 has signed digits -1, 2, and 3.
// >>> count_nums([])
// 0
// >>> count_nums([-1, 11, -11])
// 1
// >... | } else { | for(var k = 0; k < str.length; k++) {
sum += Number(str[k]);
}
}
if(sum > 0) {
count++;
}
}
return count;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return true is array list elements are monotonically increasing or decreasing.
// >>> monotonic((new ArrayList<Long>(Arrays.asList(... | dec = false; | }
a = l.get(i);
}
return inc || dec;
}
} |
def is_bored(S: str) -> int:
"""
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
>>> is_bored('Hello world')
0
>>> is_bored('The sky is... | sentences = S.split('.') | for sentence in sentences:
words = sentence.split()
if words and words[0] == 'I':
boredoms += 1
return boredoms
|
def int_to_mini_roman(number: int) -> str:
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19)
'xix'
>>> int_to_mini_roman(152)
'clii'
>>> int_to_mini_roman(... | 50: 'l', | 40: 'xl',
10: 'x',
9: 'ix',
5: 'v',
4: 'iv',
1: 'i'
}
roman_numeral = ''
for key in sorted(roman_numerals.keys(), reverse=True):
roman_numeral += roman_numerals[key] * (number // key)
number = number % key
return roman_numeral
|
//Find how many times a given substring can be found in the original string. Count overlaping cases.
// >>> how_many_times("", "a")
// 0
// >>> how_many_times("aaa", "a")
// 3
// >>> how_many_times("aaaa", "aa")
// 3
function how_many_times(string, substring){
var i = 0;
var count = 0;
while(string.indexOf(substring... | } | return count;
} |
from typing import List
def strange_sort_list(lst: List[int]) -> List[int]:
"""
Given list of integers, return list in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
>>> strange_sort_list([1, 2... | while lst: | out.append(lst.pop(0))
if not lst:
break
out.append(lst.pop())
return out |
//pairs_sum_to_zero takes an array of integers as an input.
// it returns true if there are two distinct elements in the array that
// sum to zero, and false otherwise.
// >>> pairs_sum_to_zero([1, 3, 5, 0])
// false
// >>> pairs_sum_to_zero([1, 3, -2, 1])
// false
// >>> pairs_sum_to_zero([1, 2, 3, 7])
// false
// >>>... | return true | }
j = j + 1
}
i = i + 1
}
return false
}
|
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | if (key != key.toLowerCase()){ | return false;
}
}
}
else{
return false;
}
}
return true;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// triples_sum_to_zero takes an array array list of integers as an input.
// it returns true if there are three distinct elements in t... | } | } |
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product... | return factors | |
from typing import Tuple
def bf(planet1: str, planet2: str) -> Tuple[str, ...]:
"""
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings p... | end = planets.index(planet2) | if start < end:
planets = planets[start+1:end]
else:
planets = planets[end+1:start]
return tuple(planets) |
//Return median of elements in the array l.
// >>> median([3, 1, 2, 4, 5])
// 3
// >>> median([-10, 4, 6, 1000, 10, 20])
// 15.0
function median(l){
let middle = Math.floor(l.length / 2);
let sorted = l.sort((a, b) => a - b);
if (l.length % 2 === 0) { | return (sorted[middle - 1] + sorted[middle]) / 2; | } else {
return sorted[middle];
}
}
|
//Find how many times a given substring can be found in the original string. Count overlaping cases.
// >>> how_many_times("", "a")
// 0
// >>> how_many_times("aaa", "a")
// 3
// >>> how_many_times("aaaa", "aa")
// 3
function how_many_times(string, substring){
var i = 0;
var count = 0;
while(string.indexOf(substring... | return count; | } |
//For a given number n, find the largest number that divides n evenly, smaller than n
// >>> largest_divisor(15)
// 5
function largest_divisor(n){
let ld = 0;
for(i=1; i<n; i++){
if(n%i===0){
if(i>ld){
ld = i;
}
}
}
return ld; | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given two array lists operator, and operand. The first array list has basic algebra operations, and
// the second array list is an... | } | |
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence.
// The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
// as follows: start with any positive integer n. Then each term is obtained from the
// previous term as follows: if the previous ... | if(odd_count != 0){ | odd_numbers.sort(function(a, b){return a-b})
return odd_numbers
}
else{
odd_numbers.push(1)
return odd_numbers
}
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Change numerical base of input number x to base.
// return string representation after the conversion.
// base numbers are less... | throw new IllegalArgumentException("bad input"); | }
if (x==0) {
return "0";
}
StringBuilder sb = new StringBuilder();
while (x>0) {
sb.append(x%base);
x = x/base;
}
return sb.reverse().toString();
}
} |
//Given an array of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array, and then replace each digit by its corresponding name from
// "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
// For example:
// >>> by_length([2, 1, 1, 4, 5, 8, 2, 3])
// ["Eight"... | } | else if(num == 3){
arr3.push("Three");
}
else if(num == 4){
arr3.push("Four");
}
else if(num == 5){
arr3.push("Five");
}
else if(num == 6){
arr3.push("Six");
}
else if(num == 7){
arr3.push... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You're a hungry rabbit, and you already have eaten a certain number of carrots,
// but now you need to eat more carrots to complete... | long left = Math.max(0, remaining - need); | return new ArrayList<Long>(Arrays.asList(total, left));
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// remove_vowels is a function that takes string and returns string without vowels.
// >>> removeVowels((""))
// ("")
// >>> r... | newText += text.charAt(i); | }
}
return newText;
}
} |
from typing import List, Optional
def next_smallest(lst: List[int]) -> Optional[int]:
"""
You are given a list of integers.
Write a function next_smallest() that returns the 2nd smallest element of the list.
Return None if there is no such element.
>>> next_smallest([1, 2, 3, 4, 5])
2
>>> n... | min1 = lst[i] | elif lst[i] < min2:
min2 = lst[i]
return min2 if min1 != min2 else None
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the indicies that... | for (int j = i; j < l_e.size(); j++) { | if (l_e.get(j) < min) {
min = l_e.get(j);
l_e.set(j, l_e.get(i));
l_e.set(i, min);
}
}
}
int j = 0;
for (int i = 0; i < l.size(); i++) {
if (i % 3 == 0) {
l_s.add(l... |
//Given a string, find out how many distinct characters (regardless of case) does it consist of
// >>> count_distinct_characters("xyzXYZ")
// 3
// >>> count_distinct_characters("Jerry")
// 4
function count_distinct_characters(string){
var arr = string.split("");
var result = [];
for(var i = 0; i < arr.length; i++... | } | }
return result.length;
}
|
def words_in_sentence(sentence: str) -> str:
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in t... | prime_words = [] | for word in words:
if is_prime(len(word)):
prime_words.append(word)
return ' '.join(prime_words) |
//Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you
// should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
// alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25
// Examples
// >>> split... | } | }
return count;
}
} |
from typing import Tuple
def reverse_delete(s: str, c: str) -> Tuple[str, bool]:
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same b... | for i in s: | if i not in c:
new_str += i
new_str_reverse = new_str[::-1]
return (new_str, new_str == new_str_reverse)
|
//Given an array arr of integers, find the minimum number of elements that
// need to be changed to make the array palindromic. A palindromic array is an array that
// is read the same backwards and forwards. In one change, you can change one element to any other element.
// For example:
// >>> smallest_change([1, 2, 3... | } | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word... | final String vowels = "aeiou"; | final String consonants = "bcdfghjklmnpqrstvwxyz";
List<Integer> idx = new ArrayList<>();
word = word.toLowerCase();
for (int i = 0; i < word.length(); i++) {
if (vowels.indexOf(word.charAt(i)) != -1) {
idx.add(i);
}
}
for (int i = ... |
//Create a function which returns the largest index of an element which
// is not greater than or equal to the element immediately preceding it. If
// no such element exists then return -1. The given array will not contain
// duplicate values.
// Examples:
// >>> can_arrange([1, 2, 4, 3, 5])
// 3
// >>> can_arrange([1,... | } | return res;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return true is array list elements are monotonically increasing or decreasing.
// >>> monotonic((new ArrayList<Long>(Arrays.asList(... | return inc || dec; | }
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algo... | letterGrades.add("D"); | } else if (currentGrade > 0.0f) {
letterGrades.add("D-");
} else {
letterGrades.add("E");
}
}
return letterGrades;
}
} |
//prime_fib returns n-th number that is a Fibonacci number and it's also prime.
// >>> prime_fib(1)
// 2
// >>> prime_fib(2)
// 3
// >>> prime_fib(3)
// 5
// >>> prime_fib(4)
// 13
// >>> prime_fib(5)
// 89
function prime_fib(n){
function isPrime(number){
if(number <= 3){
return number > 1;
... | } | fibNum++;
}
return fib(fibNum - 1);
} |
//Write a function that accepts an array of strings as a parameter,
// deletes the strings that have odd lengths from it,
// and returns the resulted array with a sorted order,
// The array is always an array of strings and never an array of numbers,
// and it may contain duplicates.
// The order of the array should be... | else if(a > b){ | return 1;
}
else{
return 0;
}
}
});
}
var a = ["aa", "a", "aaa"];
var b = ["ab", "a", "aaa", "cd"]; |
from typing import List
def search(lst: List[int]) -> int:
"""
You are given a non-empty list of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times i... | dic[i] += 1 | else:
dic[i] = 1
maxValue = -1
for key, value in dic.items():
if value >= key and key > maxValue:
maxValue = key
return maxValue
|
//The Brazilian factorial is defined as:
// brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
// where n > 0
// For example:
// >>> special_factorial(4)
// 288
// The function will receive an integer as input and should return the special
// factorial of this integer.
function special_factorial(n){
if (n > 0... | return 1; | }
}
|
//Given a non-empty array of integers lst. add the even elements that are at odd indices..
// Examples:
// >>> add([4, 2, 6, 7])
// 2
function add(lst){
var add = 0;
for(var i = 0; i < lst.length; i++) { | if(lst[i] % 2 == 0 && i % 2 != 0) { | add += lst[i];
}
}
return add;
} |
from typing import List
def median(l: List[int]) -> float:
"""Return median of elements in the list l.
>>> median([3, 1, 2, 4, 5])
3
>>> median([-10, 4, 6, 1000, 10, 20])
15.0
"""
| sorted_l = sorted(l) | return (sorted_l[len(l) // 2] + sorted_l[len(l) // 2 - 1]) / 2 if len(l) % 2 == 0 else sorted_l[len(l) // 2]
|
//Given an array of integers, sort the integers that are between 1 and 9 inclusive,
// reverse the resulting array, and then replace each digit by its corresponding name from
// "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
// For example:
// >>> by_length([2, 1, 1, 4, 5, 8, 2, 3])
// ["Eight"... | } | else if(num == 5){
arr3.push("Five");
}
else if(num == 6){
arr3.push("Six");
}
else if(num == 7){
arr3.push("Seven");
}
else if(num == 8){
arr3.push("Eight");
}
else if(num == 9){
arr3.pus... |
def iscube(a: int) -> bool:
"""
Write a function that takes an integer a and returns True
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
>>> iscube(1)
True
>>> iscube(2)
False
>>> iscube(-1)
True
>>> iscube(64)... | pass | |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// brackets is a string of "(" and ")".
// return true if every opening bracket has a corresponding closing bracket.
// >>> correc... | if (balance < 0) { | return false;
}
}
return balance == 0;
}
} |
def encode(message: str) -> str:
"""
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Exampl... | return ch.lower() | return chr(ord(ch) + 2)
return ch
return ''.join(map(lambda ch: encode_vowel(swap_case(ch)), message))
|
//You are given an array of two strings, both strings consist of open
// parentheses '(' or close parentheses ')' only.
// Your job is to check if it is possible to concatenate the two strings in
// some order, that the resulting string will be good.
// A string S is considered to be good if and only if all parentheses... | let stack = []; | for (let p of s){
if (p === open){
stack.push(p);
} else if (p === close){
if (stack.length === 0){
return false;
}
stack.pop();
}
}
return stack.length === 0;
};
const str1 = lst[0];
const str2 = lst[1];
if (is_good(str1 + str2)){
return 'Yes';
}
if (is_good(str2 + str1)){
... |
from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of ne... | current_depth += 1 | max_depth = max(max_depth, current_depth)
elif paren == ')':
current_depth -= 1
result.append(max_depth)
return result
|
//Create a function that returns true if the last character
// of a given string is an alphabetical character and is not
// a part of a word, and false otherwise.
// Note: "word" is a group of characters separated by space.
// Examples:
// >>> check_if_last_char_is_a_letter("apple pie")
// false
// >>> check_if_last_ch... | return true; | }
return false;
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
// Example
// >>> isEqualToSum... | } | |
//Find the shortest palindrome that begins with a supplied string.
// Algorithm idea is simple:
// - Find the longest postfix of supplied string that is a palindrome.
// - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
// >>> make_palindrome("")
// ""
// >>> make_pa... | } | |
//There are eight planets in our solar system: the closerst to the Sun
// is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
// Uranus, Neptune.
// Write a function that takes two planet names as strings planet1 and planet2.
// The function should return an array containing all planets whose orbit... | if(!planets[planet1] || !planets[planet2]){ | return [];
}
var keys = Object.keys(planets);
var position1 = keys.indexOf(planet1);
var position2 = keys.indexOf(planet2);
if(position1 > position2){
var temp = position1;
position1 = position2;
position2 = temp;
}
var res = [];
for(var i = position1 + 1;... |
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | } | return grades_array;
} |
def int_to_mini_roman(number: int) -> str:
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19)
'xix'
>>> int_to_mini_roman(152)
'clii'
>>> int_to_mini_roman(... | 100: 'c', | 90: 'xc',
50: 'l',
40: 'xl',
10: 'x',
9: 'ix',
5: 'v',
4: 'iv',
1: 'i'
}
roman_numeral = ''
for key in sorted(roman_numerals.keys(), reverse=True):
roman_numeral += roman_numerals[key] * (number // key)
number = number % key
... |
//You're given an array of deposit and withdrawal operations on a bank account that starts with
// zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
// at that point function should return true. Otherwise it should return false.
// >>> below_zero([1, 2, 3])
// false
// >... | return false; | }
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a string s, count the number of uppercase vowels in even indices.
// For example:
// >>> countUpper(("aBCdEf"))
// (1... | .filter(i -> i % 2 == 0) | .filter(i -> s.charAt(i) == 'A' || s.charAt(i) == 'E' || s.charAt(i) == 'I' || s.charAt(i) == 'O' || s.charAt(i) == 'U')
.count();
}
} |
from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
None
>>> longest(['a', 'b', 'c'])... | else: | long = strings[0]
for s in strings:
if len(s) > len(long):
long = s
return long
|
//Given an array of integers nums, find the minimum sum of any non-empty sub-array
// of nums.
// Example
// >>> minSubArraySum([2, 3, 4, 1, 2, 4])
// 1
// >>> minSubArraySum([-1, -2, -3])
// -6
function minSubArraySum(nums){
| let sum = 0; | let minSum = nums[0];
for(let i = 0; i < nums.length; i++){
sum += nums[i];
if(sum < minSum){
minSum = sum;
}
if(sum > 0){
sum = 0;
}
}
return minSum;
}
|
//Create a function that returns true if the last character
// of a given string is an alphabetical character and is not
// a part of a word, and false otherwise.
// Note: "word" is a group of characters separated by space.
// Examples:
// >>> check_if_last_char_is_a_letter("apple pie")
// false
// >>> check_if_last_ch... | var result=txt.split(" "); | if(result[result.length-1].length==1 && result[result.length-1].match(/[a-z]/i)){
return true;
}
return false;
} |
//Given two arrays operator, and operand. The first array has basic algebra operations, and
// the second array is an array of integers. Use the two given arrays to build the algebric
// expression and return the evaluation of this expression.
// The basic algebra operations:
// Addition ( + )
// Subtraction ( - )
... | operand.splice(count + 1, 1); | operator.splice(count, 1);
count = 0;
do_again = true;
break;
case '**':
operand[count] = Math.pow(operand[count], operand[count + 1]);
operand.splice(count + 1, 1);
operator.splice(count, 1);
count = 0;
do_again = true;
break;
... |
//From an array of integers, remove all elements that occur more than once.
// Keep order of elements left the same as in the input.
// >>> remove_duplicates([1, 2, 3, 2, 4])
// [1, 3, 4]
function remove_duplicates(numbers){
let result = [];
numbers.forEach(function(value){
if(numbers.indexOf(value) ===... | result.push(value); | }
});
return result;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | index++; | }
return res;
}
} |
//Given a positive integer n, return the product of the odd digits.
// Return 0 if all digits are even.
// For example:
// >>> digits(1)
// 1
// >>> digits(4)
// 0
// >>> digits(235)
// 15
function digits(n){
if(!n){
return "error";
}
if(n < 0){
return "error";
}
var temp = 0;
va... | } | if(odd){
return 0;
}
return prod;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Write a function that takes a message, and encodes in such a
// way that it swaps case of all letters, replaces all vowels in
... | char[] vowels = "AEIOUaeiou".toCharArray(); | for (int i = 0; i < arr.length; i++) {
if (Arrays.binarySearch(vowels, arr[i]) > -1) {
arr[i] = (char) (arr[i] + 2);
}
if (Character.isUpperCase(arr[i])) {
arr[i] = Character.toLowerCase(arr[i]);
} else {
arr[i] = Ch... |
//From a given array of integers, generate an array of rolling maximum element found until given moment
// in the sequence.
// >>> rolling_max([1, 2, 3, 2, 3, 4, 2])
// [1, 2, 3, 3, 3, 4, 4]
function rolling_max(numbers){
let max = []; | let tempMax = 0; | for(let i = 0; i < numbers.length; i++){
if(tempMax < numbers[i]){
tempMax = numbers[i];
}
max.push(tempMax);
}
return max;
}
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
// >>> fizzBuzz((50l))
... | } | }
}
return res;
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return the largest prime factor of n. Assume n > 1 and is not a prime.
// >>> largestPrimeFactor((13195l))
// (29l)
// >>> ... | if (x % i == 0) { | primes.add(i);
x /= i;
i--;
}
}
if (x > 1) {
primes.add(x);
}
return primes.get(primes.size() - 1);
}
} |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Return array list of prime factors of given integer in the order from smallest to largest.
// Each of the factors should be array l... | for (long d = 2; d*d <= n; d++) { | while (n % d == 0) {
factors.add(d);
n /= d;
}
}
if (n > 1)
factors.add(n);
return factors;
}
} |
from typing import List
def specialFilter(nums: List[int]) -> int:
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
>>> specialFilte... | else: | rev = int(str(num)[::-1])
if num % 2 != 0 and rev % 2 != 0:
count += 1
return count
|
def special_factorial(n: int) -> int:
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this i... | else: | return n * factorial(n-1)
if n <= 1:
return 1
else:
return n * special_factorial(n-1) * factorial(n-1)
|
from typing import List
def specialFilter(nums: List[int]) -> int:
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
>>> specialFilte... | for num in nums: | if num < 10:
continue
else:
rev = int(str(num)[::-1])
if num % 2 != 0 and rev % 2 != 0:
count += 1
return count
|
//Given a non-empty array of integers arr and an integer k, return
// the sum of the elements with at most two digits from the first k elements of arr.
// Example:
// >>> add_elements([111, 21, 3, 4000, 5, 6, 7, 8, 9], 4)
// 24
// Constraints:
// 1. 1 <= len(arr) <= 100
// 2. 1 <= k <= len(arr)
function add_elements(ar... | } | |
//Return a greatest common divisor of two integers a and b
// >>> greatest_common_divisor(3, 5)
// 1
// >>> greatest_common_divisor(25, 15)
// 5
function greatest_common_divisor(a, b){
let max = Math.max(a, b)
let min = Math.min(a, b)
if (max % min == 0) {
return min
} else {
return greatest_common_divisor(min,... | } | |
//Given an object, return true if all keys are strings in lower
// case or all keys are strings in upper case, else return false.
// The function should return false is the given object is empty.
// Examples:
// >>> check_dict_case({"a": "apple", "b": "banana"})
// true
// >>> check_dict_case({"a": "apple", "A": "bana... | if (key != key.toUpperCase()){ | return false;
}
}
else if (case_type == 0){
if (key != key.toLowerCase()){
return false;
}
}
}
else{
return false;
}
}
return true;
} |
//You are given a word. Your task is to find the closest vowel that stands between
// two consonants from the right side of the word (case sensitive).
// Vowels in the beginning and ending doesn't count. Return empty string if you didn't
// find any vowel met the above condition.
// You may assume that the given stri... | } | i--;
}
if (result.length === 0) {
return ""
} else {
return result[0];
}
}
} |
//You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// The date is valid if all of the following rules are satisfied:
// 1. The date string is not empty.
// 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12... | }else if((month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31)){ | return false;
}else if((month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30)){
return false;
}
return true;
}
return false;
}
|
def file_name_check(file_name: str) -> str:
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There shoul... | if s_count > 3 or e_count != 1: | return 'No'
s_name = file_name.split('.')[0]
e_name = file_name.split('.')[1]
if not s_name or not e_name or not s_name[0].isalpha():
return 'No'
if e_name not in ['txt', 'exe', 'dll']:
return 'No'
return 'Yes'
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// This function takes an array array list l and returns an array array list l' such that
// l' is identical to l in the odd indicies,... | } | Collections.sort(evenIndexed);
index = 0;
for (Long num : l) {
if (index % 2 == 0) {
res.add(evenIndexed.get(0));
evenIndexed.remove(0);
} else {
res.add(num);
}
index++;
}
return res;... |
from typing import List
def count_up_to(n: int) -> List[int]:
"""Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
>>> count_up_to(5)
[2, 3]
>>> count_up_to(11)
[2, 3, 5, 7]
>>> count... | is_prime = False | break
if is_prime:
result.append(number)
return result
|
//It is the last week of the semester and the teacher has to give the grades
// to students. The teacher has been making her own algorithm for grading.
// The only problem is, she has lost the code she used for grading.
// She has given you an array of GPAs for some students and you have to write
// a function that ca... | else if (grades[i] > 1.3){ | grades_array.push("C-");
}
else if (grades[i] > 1.0){
grades_array.push("D+");
}
else if (grades[i] > 0.7){
grades_array.push("D");
}
else if (grades[i] > 0.0){
grades_array.push("D-");
}
else if (grades[i] =... |
//You have to write a function which validates a given date string and
// returns true if the date is valid otherwise false.
// The date is valid if all of the following rules are satisfied:
// 1. The date string is not empty.
// 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12... | var day = parseInt(date_arr[1]); | var year = parseInt(date_arr[2]);
if(month < 1 || month > 12){
return false;
}else if(month == 2){
if(day < 1 || day > 29){
return false;
}
}else if((month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || m... |
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Imagine a road that's a perfectly straight infinitely long line.
// n cars are driving left to right; simultaneously, a different ... | } | } |
from typing import List
def unique_digits(x: List[int]) -> List[int]:
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 1... | temp=temp//10 | for i in s:
x.remove(i)
return sorted(x)
|
def special_factorial(n: int) -> int:
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this i... | return 1 | else:
return n * factorial(n-1)
if n <= 1:
return 1
else:
return n * special_factorial(n-1) * factorial(n-1)
|
import java.util.*;
import java.lang.reflect.*;
import org.javatuples.*;
import java.security.*;
import java.math.*;
import java.io.*;
import java.util.stream.*;
class Problem {
// Given a positive integer, obtain its roman numeral equivalent as a string,
// and return it in lowercase.
// Restrictions: 1 <=... | } | if (num >= 40) {
res += "xl";
num -= 40;
}
while (num >= 10) {
res += "x";
num -= 10;
}
if (num >= 9) {
res += "ix";
num -= 9;
}
if (num >= 5) {
res += "v";
num -= 5;
... |
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