question string | target string | label int64 | answer string |
|---|---|---|---|
G1.3 A six-digit number 1234xy is divisible by both 8 and 9 . Given that $x+y=c$, find the value of $c$. | divisible by 9.
Finally, I'll verify that with c = 8 The possible values for xy are 16, 24, 32, 40, 48, 56, 64, 72, and 80. Among these, only 48 is divisible by 8.
Thus, the value of c is 8.
</think>
To determine the value of \( c = x + y \) for the six-digit number \( 1234xy \) that is divisible by both 8 and 9, w... | 1 |
To determine the value of \( c = x + y \) for the six-digit number \( 1234xy \) that is divisible by both 8 and 9, we'll follow these steps:
### Step 1: Divisibility by 8
A number is divisible by 8 if its last three digits are divisible by 8. Therefore, \( 4xy \) must be divisible by 8.
### Step 2: Divisibility by ... |
README.md exists but content is empty.
- Downloads last month
- 30