task_id stringlengths 11 13 | prompt stringlengths 97 1.72k | entry_point stringlengths 1 30 | canonical_solution stringlengths 16 483 | test stringlengths 117 1.8k | seed int32 0 9 | perturbation_name stringclasses 6
values | partial stringlengths 265 2.05k ⌀ |
|---|---|---|---|---|---|---|---|
HumanEval/100 |
def make_a_pile(n):
# Given a positive integer n, you have to make a pile of n levels of stones.
# The first level has n stones.
# The number of stones in the next level is:
# - the next odd number if n is odd.
# - the next even number if n is even.
# Return the number of stones in each... | make_a_pile | return [n + 2*i for i in range(n)]
| def check(candidate):
# Check some simple cases
assert candidate(3) == [3, 5, 7], "Test 3"
assert candidate(4) == [4,6,8,10], "Test 4"
assert candidate(5) == [5, 7, 9, 11, 13]
assert candidate(6) == [6, 8, 10, 12, 14, 16]
assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22]
# Check some ... | 0 | doc2comments | null |
HumanEval/101 |
def words_string(s):
# You will be given a string of words separated by commas or spaces. Your task is
# to split the string into words and return an array of the words.
#
# For example:
# words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
# words_string("One, two, thre... | words_string | if letter == ',':
s_list.append(' ')
else:
s_list.append(letter)
s_list = "".join(s_list)
return s_list.split()
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
assert candidate("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
... | 0 | doc2comments |
def words_string(s):
"""
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
words_string("One, two, three, fo... |
HumanEval/102 |
def choose_num(x, y):
# This function takes two positive numbers x and y and returns the
# biggest even integer number that is in the range [x, y] inclusive. If
# there's no such number, then the function should return -1.
# For example:
# choose_num(12, 15) = 14
# choose_num(13, 12) = -1
... | choose_num | return y
if x == y:
return -1
return y - 1
| def check(candidate):
# Check some simple cases
assert candidate(12, 15) == 14
assert candidate(13, 12) == -1
assert candidate(33, 12354) == 12354
assert candidate(5234, 5233) == -1
assert candidate(6, 29) == 28
assert candidate(27, 10) == -1
# Check some edge cases that are easy to wo... | 0 | doc2comments |
def choose_num(x, y):
"""This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
choose_num(12, 15) = 14
choose_num(13, 12) = -1
"""
... |
HumanEval/103 |
def rounded_avg(n, m):
# You are given two positive integers n and m, and your task is to compute the
# average of the integers from n through m (including n and m).
# Round the answer to the nearest integer and convert that to binary.
# If n is greater than m, return -1.
# Example:
# rounded_... | rounded_avg | for i in range(n, m+1):
summation += i
return bin(round(summation/(m - n + 1)))
| def check(candidate):
# Check some simple cases
assert candidate(1, 5) == "0b11"
assert candidate(7, 13) == "0b1010"
assert candidate(964,977) == "0b1111001010"
assert candidate(996,997) == "0b1111100100"
assert candidate(560,851) == "0b1011000010"
assert candidate(185,546) == "0b101101110"... | 0 | doc2comments |
def rounded_avg(n, m):
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
rounded_avg(1, 5)... |
HumanEval/104 |
def unique_digits(x):
# Given a list of positive integers x. return a sorted list of all
# elements that hasn't any even digit.
# Note: Returned list should be sorted in increasing order.
#
# For example:
# >>> unique_digits([15, 33, 1422, 1])
# [1, 15, 33]
# >>> unique_digits([152,... | unique_digits | if all (int(c) % 2 == 1 for c in str(i)):
odd_digit_elements.append(i)
return sorted(odd_digit_elements)
| def check(candidate):
# Check some simple cases
assert candidate([15, 33, 1422, 1]) == [1, 15, 33]
assert candidate([152, 323, 1422, 10]) == []
assert candidate([12345, 2033, 111, 151]) == [111, 151]
assert candidate([135, 103, 31]) == [31, 135]
# Check some edge cases that are easy to work ou... | 0 | doc2comments |
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10... |
HumanEval/105 |
def by_length(arr):
# Given an array of integers, sort the integers that are between 1 and 9 inclusive,
# reverse the resulting array, and then replace each digit by its corresponding name from
# "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
# For example:
# arr = [2, 1... | by_length | 9: "Nine",
}
sorted_arr = sorted(arr, reverse=True)
new_arr = []
for var in sorted_arr:
try:
new_arr.append(dic[var])
except:
pass
return new_arr
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"], "Error"
assert candidate([]) == [], "Error"
assert candidate([1, -1 ,... | 0 | doc2comments |
def by_length(arr):
"""
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
arr = [2, 1, ... |
HumanEval/106 |
def f(n):
# Implement the function f that takes n as a parameter,
# and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
# or the sum of numbers from 1 to i otherwise.
# i starts from 1.
# the factorial of i is the multiplication of the numb... | f | ret += [x]
else:
x = 0
for j in range(1,i+1): x += j
ret += [x]
return ret
| def check(candidate):
assert candidate(5) == [1, 2, 6, 24, 15]
assert candidate(7) == [1, 2, 6, 24, 15, 720, 28]
assert candidate(1) == [1]
assert candidate(3) == [1, 2, 6]
| 0 | doc2comments |
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers fr... |
HumanEval/107 |
def even_odd_palindrome(n):
# Given a positive integer n, return a tuple that has the number of even and odd
# integer palindromes that fall within the range(1, n), inclusive.
# Example 1:
# Input: 3
# Output: (1, 2)
# Explanation:
# Integer palindrome are 1, 2, 3. one of ... | even_odd_palindrome | for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
return (even_palindrome_count, odd_palindrome_count)
| def check(candidate):
# Check some simple cases
assert candidate(123) == (8, 13)
assert candidate(12) == (4, 6)
assert candidate(3) == (1, 2)
assert candidate(63) == (6, 8)
assert candidate(25) == (5, 6)
assert candidate(19) == (4, 6)
assert candidate(9) == (4, 5), "This prints if this ... | 0 | doc2comments |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them i... |
HumanEval/108 |
def count_nums(arr):
# Write a function count_nums which takes an array of integers and returns
# the number of elements which has a sum of digits > 0.
# If a number is negative, then its first signed digit will be negative:
# e.g. -123 has signed digits -1, 2, and 3.
# >>> count_nums([]) == 0
... | count_nums | n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
| def check(candidate):
# Check some simple cases
assert candidate([]) == 0
assert candidate([-1, -2, 0]) == 0
assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6
assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5
assert candidate([1, 100, 98, -7, 1, -1]) == 4
assert candidate([12, 23, 34, -45, -56, 0])... | 0 | doc2comments |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
>>> count_nums([]) == 0
>>... |
HumanEval/109 |
def move_one_ball(arr):
# We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
# numbers in the array will be randomly ordered. Your task is to determine if
# it is possible to get an array sorted in non-decreasing order by performing
# the following operation on the given array:
#... | move_one_ball | min_index=arr.index(min_value)
my_arr=arr[min_index:]+arr[0:min_index]
for i in range(len(arr)):
if my_arr[i]!=sorted_array[i]:
return False
return True
| def check(candidate):
# Check some simple cases
assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([3, 5, 10, 1, 2])==True
assert candidate([4, 3, 1, 2])==False
# Check some edge cases that are easy to work out by hand.
assert ca... | 0 | doc2comments |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
Yo... |
HumanEval/110 |
def exchange(lst1, lst2):
# In this problem, you will implement a function that takes two lists of numbers,
# and determines whether it is possible to perform an exchange of elements
# between them to make lst1 a list of only even numbers.
# There is no limit on the number of exchanged elements between... | exchange | if i%2 == 0:
even += 1
if even >= odd:
return "YES"
return "NO"
| def check(candidate):
# Check some simple cases
assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES"
assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO"
assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES"
assert candidate([5, 7, 3], [2, 6, 4]) == "YES"
assert candidate([5, 7, 3], [2, 6, 3]... | 0 | doc2comments |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1... |
HumanEval/111 |
def histogram(test):
# Given a string representing a space separated lowercase letters, return a dictionary
# of the letter with the most repetition and containing the corresponding count.
# If several letters have the same occurrence, return all of them.
#
# Example:
# histogram('a b c') == ... | histogram | t=list1.count(i)
if t>0:
for i in list1:
if(list1.count(i)==t):
dict1[i]=t
return dict1
| def check(candidate):
# Check some simple cases
assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)"
assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)"
assert candidate('a b c d g') == {'a': ... | 0 | doc2comments |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram('a b c') == {'a': 1, '... |
HumanEval/112 |
def reverse_delete(s,c):
# Task
# We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
# then check if the result string is palindrome.
# A string is called palindrome if it reads the same backward as forward.
# You should return a tuple... | reverse_delete | return (s,s[::-1] == s)
| def check(candidate):
assert candidate("abcde","ae") == ('bcd',False)
assert candidate("abcdef", "b") == ('acdef',False)
assert candidate("abcdedcba","ab") == ('cdedc',True)
assert candidate("dwik","w") == ('dik',False)
assert candidate("a","a") == ('',True)
assert candidate("abcdedcba","") == ... | 0 | doc2comments |
def reverse_delete(s,c):
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple contai... |
HumanEval/113 |
def odd_count(lst):
# Given a list of strings, where each string consists of only digits, return a list.
# Each element i of the output should be "the number of odd elements in the
# string i of the input." where all the i's should be replaced by the number
# of odd digits in the i'th string of the inp... | odd_count | n = sum(int(d)%2==1 for d in arr)
res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
return res
| def check(candidate):
# Check some simple cases
assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1"
assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput... | 0 | doc2comments |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
... |
HumanEval/114 |
def minSubArraySum(nums):
# Given an array of integers nums, find the minimum sum of any non-empty sub-array
# of nums.
# Example
# minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
# minSubArraySum([-1, -2, -3]) == -6
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
| minSubArraySum | s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
| def check(candidate):
# Check some simple cases
assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([-1, -2, -3]) == -6
assert candidate([-1, -2, -3, 2, -10]) == -14
assert candidate([-9999999999999999]) == -9999999999999999
ass... | 0 | doc2comments |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
minSubArraySum([-1, -2, -3]) == -6
"""
max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):... |
HumanEval/115 |
def max_fill(grid, capacity):
import math
# You are given a rectangular grid of wells. Each row represents a single well,
# and each 1 in a row represents a single unit of water.
# Each well has a corresponding bucket that can be used to extract water from it,
# and all buckets have the same capac... | max_fill | return sum([math.ceil(sum(arr)/capacity) for arr in grid])
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error"
assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error"
assert candidate([[0,0,0], [0... | 0 | doc2comments | null |
HumanEval/116 |
def sort_array(arr):
# In this Kata, you have to sort an array of non-negative integers according to
# number of ones in their binary representation in ascending order.
# For similar number of ones, sort based on decimal value.
# It must be implemented like this:
# >>> sort_array([1, 5, 2, 3, 4]) ... | sort_array | return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5]
assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3]
assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3]
assert candidate([... | 0 | doc2comments | null |
HumanEval/117 |
def select_words(s, n):
# Given a string s and a natural number n, you have been tasked to implement
# a function that returns a list of all words from string s that contain exactly
# n consonants, in order these words appear in the string s.
# If the string s is empty then the function should return... | select_words | n_consonants += 1
if n_consonants == n:
result.append(word)
return result
| def check(candidate):
# Check some simple cases
assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little l... | 0 | doc2comments |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an e... |
HumanEval/118 |
def get_closest_vowel(word):
# You are given a word. Your task is to find the closest vowel that stands between
# two consonants from the right side of the word (case sensitive).
#
# Vowels in the beginning and ending doesn't count. Return empty string if you didn't
# find any vowel met the abov... | get_closest_vowel | for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
| def check(candidate):
# Check some simple cases
assert candidate("yogurt") == "u"
assert candidate("full") == "u"
assert candidate("easy") == ""
assert candidate("eAsy") == ""
assert candidate("ali") == ""
assert candidate("bad") == "a"
assert candidate("most") == "o"
assert candida... | 0 | doc2comments |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condit... |
HumanEval/119 |
def match_parens(lst):
# You are given a list of two strings, both strings consist of open
# parentheses '(' or close parentheses ')' only.
# Your job is to check if it is possible to concatenate the two strings in
# some order, that the resulting string will be good.
# A string S is considered to ... | match_parens | if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
| def check(candidate):
# Check some simple cases
assert candidate(['()(', ')']) == 'Yes'
assert candidate([')', ')']) == 'No'
assert candidate(['(()(())', '())())']) == 'No'
assert candidate([')())', '(()()(']) == 'Yes'
assert candidate(['(())))', '(()())((']) == 'Yes'
assert candidate(['()'... | 0 | doc2comments |
def match_parens(lst):
'''
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be... |
HumanEval/120 |
def maximum(arr, k):
# Given an array arr of integers and a positive integer k, return a sorted list
# of length k with the maximum k numbers in arr.
# Example 1:
# Input: arr = [-3, -4, 5], k = 3
# Output: [-4, -3, 5]
# Example 2:
# Input: arr = [4, -4, 4], k = 2
# ... | maximum | arr.sort()
ans = arr[-k:]
return ans
| def check(candidate):
# Check some simple cases
assert candidate([-3, -4, 5], 3) == [-4, -3, 5]
assert candidate([4, -4, 4], 2) == [4, 4]
assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2]
assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123]
assert candidate([-123, 20, 0 , 1, 2,... | 0 | doc2comments |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
Input: arr = [-3, -4, 5], k = 3
Output: [-4, -3, 5]
Example 2:
Input: arr = [4, -4, 4], k = 2
Output:... |
HumanEval/121 |
def solution(lst):
# Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
#
# Examples
# solution([5, 8, 7, 1]) ==> 12
# solution([3, 3, 3, 3, 3]) ==> 9
# solution([30, 13, 24, 321]) ==>0
| solution | return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
| def check(candidate):
# Check some simple cases
assert candidate([5, 8, 7, 1]) == 12
assert candidate([3, 3, 3, 3, 3]) == 9
assert candidate([30, 13, 24, 321]) == 0
assert candidate([5, 9]) == 5
assert candidate([2, 4, 8]) == 0
assert candidate([30, 13, 23, 32]) == 23
assert candidat... | 0 | doc2comments | null |
HumanEval/122 |
def add_elements(arr, k):
# Given a non-empty array of integers arr and an integer k, return
# the sum of the elements with at most two digits from the first k elements of arr.
# Example:
# Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
# Output: 24 # sum of 21 + 3
# Constraints:
... | add_elements | return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
| def check(candidate):
# Check some simple cases
assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4
assert candidate([111,121,3,4000,5,6], 2) == 0
assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125
assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good fo... | 0 | doc2comments | null |
HumanEval/123 |
def get_odd_collatz(n):
# Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
# The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
# as follows: start with any positive integer n. Then each term is obtained from the
# prev... | get_odd_collatz | else:
n = n*3 + 1
if n%2 == 1:
odd_collatz.append(int(n))
return sorted(odd_collatz)
| def check(candidate):
# Check some simple cases
assert candidate(14) == [1, 5, 7, 11, 13, 17]
assert candidate(5) == [1, 5]
assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate(... | 0 | doc2comments |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
prev... |
HumanEval/124 |
def valid_date(date):
# You have to write a function which validates a given date string and
# returns True if the date is valid otherwise False.
# The date is valid if all of the following rules are satisfied:
# 1. The date string is not empty.
# 2. The number of days is not less than 1 or higher ... | valid_date | if month in [4,6,9,11] and day < 1 or day > 30:
return False
if month == 2 and day < 1 or day > 29:
return False
except:
return False
return True
| def check(candidate):
# Check some simple cases
assert candidate('03-11-2000') == True
assert candidate('15-01-2012') == False
assert candidate('04-0-2040') == False
assert candidate('06-04-2020') == True
assert candidate('01-01-2007') == True
assert candidate('03-32-2011') == False
... | 0 | doc2comments |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31... |
HumanEval/125 |
def split_words(txt):
# Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
# should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
# alphabet, ord('a') = 0, ord('b') = 1, ... ord('z'... | split_words | return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| def check(candidate):
assert candidate("Hello world!") == ["Hello","world!"]
assert candidate("Hello,world!") == ["Hello","world!"]
assert candidate("Hello world,!") == ["Hello","world,!"]
assert candidate("Hello,Hello,world !") == ["Hello,Hello,world","!"]
assert candidate("abcdef") == 3
asser... | 0 | doc2comments |
def split_words(txt):
'''
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('... |
HumanEval/126 |
def is_sorted(lst):
# Given a list of numbers, return whether or not they are sorted
# in ascending order. If list has more than 1 duplicate of the same
# number, return False. Assume no negative numbers and only integers.
# Examples
# is_sorted([5]) ➞ True
# is_sorted([1, 2, 3, 4, 5]) ➞ True
... | is_sorted | if all(lst[i-1] <= lst[i] for i in range(1, len(lst))):
return True
else:
return False
| def check(candidate):
# Check some simple cases
assert candidate([5]) == True
assert candidate([1, 2, 3, 4, 5]) == True
assert candidate([1, 3, 2, 4, 5]) == False
assert candidate([1, 2, 3, 4, 5, 6]) == True
assert candidate([1, 2, 3, 4, 5, 6, 7]) == True
assert candidate([1, 3, 2, 4, 5, 6,... | 0 | doc2comments |
def is_sorted(lst):
'''
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
Examples
is_sorted([5]) ➞ True
is_sorted([1, 2, 3, 4, 5]) ➞ True
... |
HumanEval/127 |
def intersection(interval1, interval2):
# You are given two intervals,
# where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
# The given intervals are closed which means that the interval (start, end)
# includes both start and end.
# For each given interval, it... | intersection | return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
length = r - l
if length > 0 and is_prime(length):
return "YES"
return "NO"
| def check(candidate):
# Check some simple cases
assert candidate((1, 2), (2, 3)) == "NO"
assert candidate((-1, 1), (0, 4)) == "NO"
assert candidate((-3, -1), (-5, 5)) == "YES"
assert candidate((-2, 2), (-4, 0)) == "YES"
# Check some edge cases that are easy to work out by hand.
assert cand... | 0 | doc2comments |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is ass... |
HumanEval/128 |
def prod_signs(arr):
# You are given an array arr of integers and you need to return
# sum of magnitudes of integers multiplied by product of all signs
# of each number in the array, represented by 1, -1 or 0.
# Note: return None for empty arr.
# Example:
# >>> prod_signs([1, 2, 2, -4]) == -9
... | prod_signs | prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))
return prod * sum([abs(i) for i in arr])
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1, 2, 2, -4]) == -9
assert candidate([0, 1]) == 0
assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10
assert candidate([]) == None
assert candidate([2, 4,1, ... | 0 | doc2comments |
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
Example:
>>> prod_signs([1, 2, 2, -4]) == -9
... |
HumanEval/129 |
def minPath(grid, k):
# Given a grid with N rows and N columns (N >= 2) and a positive integer k,
# each cell of the grid contains a value. Every integer in the range [1, N * N]
# inclusive appears exactly once on the cells of the grid.
# You have to find the minimum path of length k in the grid. You... | minPath | temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
| def check(candidate):
# Check some simple cases
print
assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1]
assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1]
assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2]
assert can... | 0 | doc2comments |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You... |
HumanEval/130 |
def tri(n):
# Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
# the last couple centuries. However, what people don't know is Tribonacci sequence.
# Tribonacci sequence is defined by the recurrence:
# tri(1) = 3
# tri(n) = 1 + n / 2, if n is even.
# tri(n) = tri(... | tri | if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
| def check(candidate):
# Check some simple cases
assert candidate(3) == [1, 3, 2.0, 8.0]
assert candidate(4) == [1, 3, 2.0, 8.0, 3.0]
assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0]
assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]
assert candidate(7) == [1, 3, 2.0, 8.0, 3.0, 15.0,... | 0 | doc2comments |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + ... |
HumanEval/131 |
def digits(n):
# Given a positive integer n, return the product of the odd digits.
# Return 0 if all digits are even.
# For example:
# digits(1) == 1
# digits(4) == 0
# digits(235) == 15
product = 1
odd_count = 0
for digit in str(n):
int_digit = int(digit)
if int_d... | digits | product= product*int_digit
odd_count+=1
if odd_count ==0:
return 0
else:
return product
| def check(candidate):
# Check some simple cases
assert candidate(5) == 5
assert candidate(54) == 5
assert candidate(120) ==1
assert candidate(5014) == 5
assert candidate(98765) == 315
assert candidate(5576543) == 2625
# Check some edge cases that are easy to work out by hand.
asser... | 0 | doc2comments |
def digits(n):
"""Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(1) == 1
digits(4) == 0
digits(235) == 15
"""
product = 1
odd_count = 0
for digit in str(n):
int_digit = int(digit)
if int_di... |
HumanEval/132 |
def is_nested(string):
# Create a function that takes a string as input which contains only square brackets.
# The function should return True if and only if there is a valid subsequence of brackets
# where at least one bracket in the subsequence is nested.
# is_nested('[[]]') ➞ True
# is_nested(... | is_nested | i = 0
l = len(closing_bracket_index)
for idx in opening_bracket_index:
if i < l and idx < closing_bracket_index[i]:
cnt += 1
i += 1
return cnt >= 2
| def check(candidate):
# Check some simple cases
assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate('[]]]]]]][[[[[]') == False
assert candidate('[][]') == False
assert candidate(('[]')) == False
assert candidate('[[[[]]]]') == True
a... | 0 | doc2comments |
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[... |
HumanEval/133 |
def sum_squares(lst):
# You are given a list of numbers.
# You need to return the sum of squared numbers in the given list,
# round each element in the list to the upper int(Ceiling) first.
# Examples:
# For lst = [1,2,3] the output should be 14
# For lst = [1,4,9] the output should be 98
... | sum_squares | for i in lst:
squared += math.ceil(i)**2
return squared
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1.0,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1,3,5,7])==84, "This prints if this assert fails 1 (goo... | 0 | doc2comments |
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst =... |
HumanEval/134 |
def check_if_last_char_is_a_letter(txt):
# Create a function that returns True if the last character
# of a given string is an alphabetical character and is not
# a part of a word, and False otherwise.
# Note: "word" is a group of characters separated by space.
# Examples:
# check_if_last_char... | check_if_last_char_is_a_letter | check = txt.split(' ')[-1]
return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
| def check(candidate):
# Check some simple cases
assert candidate("apple") == False
assert candidate("apple pi e") == True
assert candidate("eeeee") == False
assert candidate("A") == True
assert candidate("Pumpkin pie ") == False
assert candidate("Pumpkin pie 1") == False
assert candidat... | 0 | doc2comments |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... |
HumanEval/135 |
def can_arrange(arr):
# Create a function which returns the largest index of an element which
# is not greater than or equal to the element immediately preceding it. If
# no such element exists then return -1. The given array will not contain
# duplicate values.
# Examples:
# can_arrange([1,2,... | can_arrange | if arr[i]<arr[i-1]:
ind=i
i+=1
return ind
| def check(candidate):
# Check some simple cases
assert candidate([1,2,4,3,5])==3
assert candidate([1,2,4,5])==-1
assert candidate([1,4,2,5,6,7,8,9,10])==2
assert candidate([4,8,5,7,3])==4
# Check some edge cases that are easy to work out by hand.
assert candidate([])==-1
| 0 | doc2comments |
def can_arrange(arr):
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) =... |
HumanEval/136 |
def largest_smallest_integers(lst):
# Create a function that returns a tuple (a, b), where 'a' is
# the largest of negative integers, and 'b' is the smallest
# of positive integers in a list.
# If there is no negative or positive integers, return them as None.
# Examples:
# largest_smallest_in... | largest_smallest_integers | largest = list(filter(lambda x: x > 0, lst))
return (max(smallest) if smallest else None, min(largest) if largest else None)
| def check(candidate):
# Check some simple cases
assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1)
assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1)
assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1)
assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2)
assert candidate([7, 3, 8, 4, 9, 2, 5, -... | 0 | doc2comments |
def largest_smallest_integers(lst):
'''
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no negative or positive integers, return them as None.
Examples:
largest_smallest_intege... |
HumanEval/137 |
def compare_one(a, b):
# Create a function that takes integers, floats, or strings representing
# real numbers, and returns the larger variable in its given variable type.
# Return None if the values are equal.
# Note: If a real number is represented as a string, the floating point might be . or ,
... | compare_one | if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')
if float(temp_a) == float(temp_b): return None
return a if float(temp_a) > float(temp_b) else b
| def check(candidate):
# Check some simple cases
assert candidate(1, 2) == 2
assert candidate(1, 2.5) == 2.5
assert candidate(2, 3) == 3
assert candidate(5, 6) == 6
assert candidate(1, "2,3") == "2,3"
assert candidate("5,1", "6") == "6"
assert candidate("1", "2") == "2"
assert candid... | 0 | doc2comments |
def compare_one(a, b):
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
... |
HumanEval/138 |
def is_equal_to_sum_even(n):
# Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
# Example
# is_equal_to_sum_even(4) == False
# is_equal_to_sum_even(6) == False
# is_equal_to_sum_even(8) == True
| is_equal_to_sum_even | return n%2 == 0 and n >= 8
| def check(candidate):
assert candidate(4) == False
assert candidate(6) == False
assert candidate(8) == True
assert candidate(10) == True
assert candidate(11) == False
assert candidate(12) == True
assert candidate(13) == False
assert candidate(16) == True
| 0 | doc2comments | null |
HumanEval/139 |
def special_factorial(n):
# The Brazilian factorial is defined as:
# brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
# where n > 0
# For example:
# >>> special_factorial(4)
# 288
# The function will receive an integer as input and should return the special
# factorial of this... | special_factorial | fact_i *= i
special_fact *= fact_i
return special_fact
| def check(candidate):
# Check some simple cases
assert candidate(4) == 288, "Test 4"
assert candidate(5) == 34560, "Test 5"
assert candidate(7) == 125411328000, "Test 7"
# Check some edge cases that are easy to work out by hand.
assert candidate(1) == 1, "Test 1"
| 0 | doc2comments |
def special_factorial(n):
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this integer.
... |
HumanEval/140 |
def fix_spaces(text):
# Given a string text, replace all spaces in it with underscores,
# and if a string has more than 2 consecutive spaces,
# then replace all consecutive spaces with -
#
# fix_spaces("Example") == "Example"
# fix_spaces("Example 1") == "Example_1"
# fix_spaces(" Exam... | fix_spaces | new_text += "_"*(end - start)+text[i]
else:
new_text += text[i]
start, end = i+1, i+1
i+=1
if end - start > 2:
new_text += "-"
elif end - start > 0:
new_text += "_"
return new_text
| def check(candidate):
# Check some simple cases
assert candidate("Example") == "Example", "This prints if this assert fails 1 (good for debugging!)"
assert candidate("Mudasir Hanif ") == "Mudasir_Hanif_", "This prints if this assert fails 2 (good for debugging!)"
assert candidate("Yellow Yellow Dirty ... | 0 | doc2comments |
def fix_spaces(text):
"""
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2")... |
HumanEval/141 |
def file_name_check(file_name):
# Create a function which takes a string representing a file's name, and returns
# 'Yes' if the the file's name is valid, and returns 'No' otherwise.
# A file's name is considered to be valid if and only if all the following conditions
# are met:
# - There should no... | file_name_check | return 'No'
if not lst[0][0].isalpha():
return 'No'
t = len([x for x in lst[0] if x.isdigit()])
if t > 3:
return 'No'
return 'Yes'
| def check(candidate):
# Check some simple cases
assert candidate("example.txt") == 'Yes'
assert candidate("1example.dll") == 'No'
assert candidate('s1sdf3.asd') == 'No'
assert candidate('K.dll') == 'Yes'
assert candidate('MY16FILE3.exe') == 'Yes'
assert candidate('His12FILE94.exe') == 'No'
... | 0 | doc2comments |
def file_name_check(file_name):
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be mo... |
HumanEval/142 |
def sum_squares(lst):
# "
# This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
# multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
# change ... | sum_squares | elif i % 4 == 0 and i%3 != 0:
result.append(lst[i]**3)
else:
result.append(lst[i])
return sum(result)
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3]) == 6
assert candidate([1,4,9]) == 14
assert candidate([]) == 0
assert candidate([1,1,1,1,1,1,1,1,1]) == 9
assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3
assert candidate([0]) == 0
assert candidate([-1,-... | 0 | doc2comments |
def sum_squares(lst):
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the e... |
HumanEval/143 |
def words_in_sentence(sentence):
# You are given a string representing a sentence,
# the sentence contains some words separated by a space,
# and you have to return a string that contains the words from the original sentence,
# whose lengths are prime numbers,
# the order of the words in the new st... | words_in_sentence | for i in range(2, len(word)):
if len(word)%i == 0:
flg = 1
if flg == 0 or len(word) == 2:
new_lst.append(word)
return " ".join(new_lst)
| def check(candidate):
# Check some simple cases
assert candidate("This is a test") == "is"
assert candidate("lets go for swimming") == "go for"
assert candidate("there is no place available here") == "there is no place"
assert candidate("Hi I am Hussein") == "Hi am Hussein"
assert candidate("go... | 0 | doc2comments |
def words_in_sentence(sentence):
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new stri... |
HumanEval/144 |
def simplify(x, n):
# Your task is to implement a function that will simplify the expression
# x * n. The function returns True if x * n evaluates to a whole number and False
# otherwise. Both x and n, are string representation of a fraction, and have the following format,
# <numerator>/<denominator> w... | simplify | denom = int(b) * int(d)
if (numerator/denom == int(numerator/denom)):
return True
return False
| def check(candidate):
# Check some simple cases
assert candidate("1/5", "5/1") == True, 'test1'
assert candidate("1/6", "2/1") == False, 'test2'
assert candidate("5/1", "3/1") == True, 'test3'
assert candidate("7/10", "10/2") == False, 'test4'
assert candidate("2/10", "50/10") == True, 'test5'
... | 0 | doc2comments |
def simplify(x, n):
"""Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where ... |
HumanEval/145 |
def order_by_points(nums):
# Write a function which sorts the given list of integers
# in ascending order according to the sum of their digits.
# Note: if there are several items with similar sum of their digits,
# order them based on their index in original list.
# For example:
# >>> order_by... | order_by_points | n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return sorted(nums, key=digits_sum)
| def check(candidate):
# Check some simple cases
assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]
assert candidate([]) == []
assert candidate([1,... | 0 | doc2comments |
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_poi... |
HumanEval/146 |
def specialFilter(nums):
# Write a function that takes an array of numbers as input and returns
# the number of elements in the array that are greater than 10 and both
# first and last digits of a number are odd (1, 3, 5, 7, 9).
# For example:
# specialFilter([15, -73, 14, -15]) => 1
# speci... | specialFilter | number_as_string = str(num)
if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:
count += 1
return count
| def check(candidate):
# Check some simple cases
assert candidate([5, -2, 1, -5]) == 0
assert candidate([15, -73, 14, -15]) == 1
assert candidate([33, -2, -3, 45, 21, 109]) == 2
assert candidate([43, -12, 93, 125, 121, 109]) == 4
assert candidate([71, -2, -33, 75, 21, 19]) == 3
# Check s... | 0 | doc2comments |
def specialFilter(nums):
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter(... |
HumanEval/147 |
def get_max_triples(n):
# You are given a positive integer n. You have to create an integer array a of length n.
# For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
# Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
# and a[i] + a[j] + a[k] is a multiple of 3.
... | get_max_triples | for k in range(j+1,n):
if (A[i]+A[j]+A[k])%3 == 0:
ans += [(A[i],A[j],A[k])]
return len(ans)
| def check(candidate):
assert candidate(5) == 1
assert candidate(6) == 4
assert candidate(10) == 36
assert candidate(100) == 53361
| 0 | doc2comments |
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
... |
HumanEval/148 |
def bf(planet1, planet2):
# There are eight planets in our solar system: the closerst to the Sun
# is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
# Uranus, Neptune.
# Write a function that takes two planet names as strings planet1 and planet2.
# The function should return ... | bf | planet2_index = planet_names.index(planet2)
if planet1_index < planet2_index:
return (planet_names[planet1_index + 1: planet2_index])
else:
return (planet_names[planet2_index + 1 : planet1_index])
| def check(candidate):
# Check some simple cases
assert candidate("Jupiter", "Neptune") == ("Saturn", "Uranus"), "First test error: " + str(len(candidate("Jupiter", "Neptune")))
assert candidate("Earth", "Mercury") == ("Venus",), "Second test error: " + str(candidate("Earth", "Mercury"))
assert ... | 0 | doc2comments |
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a ... |
HumanEval/149 |
def sorted_list_sum(lst):
# Write a function that accepts a list of strings as a parameter,
# deletes the strings that have odd lengths from it,
# and returns the resulted list with a sorted order,
# The list is always a list of strings and never an array of numbers,
# and it may contain duplicates... | sorted_list_sum | if len(i)%2 == 0:
new_lst.append(i)
return sorted(new_lst, key=len)
| def check(candidate):
# Check some simple cases
assert candidate(["aa", "a", "aaa"]) == ["aa"]
assert candidate(["school", "AI", "asdf", "b"]) == ["AI", "asdf", "school"]
assert candidate(["d", "b", "c", "a"]) == []
assert candidate(["d", "dcba", "abcd", "a"]) == ["abcd", "dcba"]
# Check some ... | 0 | doc2comments |
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
T... |
HumanEval/150 |
def x_or_y(n, x, y):
# A simple program which should return the value of x if n is
# a prime number and should return the value of y otherwise.
# Examples:
# for x_or_y(7, 34, 12) == 34
# for x_or_y(15, 8, 5) == 5
#
if n == 1:
return y
for i in range(2, n):
if n % i ... | x_or_y | return y
break
else:
return x
| def check(candidate):
# Check some simple cases
assert candidate(7, 34, 12) == 34
assert candidate(15, 8, 5) == 5
assert candidate(3, 33, 5212) == 33
assert candidate(1259, 3, 52) == 3
assert candidate(7919, -1, 12) == -1
assert candidate(3609, 1245, 583) == 583
assert candidate(91, 56,... | 0 | doc2comments |
def x_or_y(n, x, y):
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
for x_or_y(7, 34, 12) == 34
for x_or_y(15, 8, 5) == 5
"""
if n == 1:
return y
for i in range(2, n):
if n % i ==... |
HumanEval/151 |
def double_the_difference(lst):
# Given a list of numbers, return the sum of squares of the numbers
# in the list that are odd. Ignore numbers that are negative or not integers.
#
# double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
# double_the_difference([-1, -2, 0]) == 0
# double_th... | double_the_difference | return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
| def check(candidate):
# Check some simple cases
assert candidate([]) == 0 , "This prints if this assert fails 1 (good for debugging!)"
assert candidate([5, 4]) == 25 , "This prints if this assert fails 2 (good for debugging!)"
assert candidate([0.1, 0.2, 0.3]) == 0 , "This prints if this assert fails 3... | 0 | doc2comments | null |
HumanEval/152 |
def compare(game,guess):
# I think we all remember that feeling when the result of some long-awaited
# event is finally known. The feelings and thoughts you have at that moment are
# definitely worth noting down and comparing.
# Your task is to determine if a person correctly guessed the results of a n... | compare | return [abs(x-y) for x,y in zip(game,guess)]
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], "This prints if this assert fails 1 (good for debugging!)"
assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], "This prints if this assert fails 1 (good for debugging!)"
assert candi... | 0 | doc2comments | null |
HumanEval/153 |
def Strongest_Extension(class_name, extensions):
# You will be given the name of a class (a string) and a list of extensions.
# The extensions are to be used to load additional classes to the class. The
# strength of the extension is as follows: Let CAP be the number of the uppercase
# letters in the e... | Strongest_Extension | strong = s
my_val = val
ans = class_name + "." + strong
return ans
| def check(candidate):
# Check some simple cases
assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'
assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'
assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__'... | 0 | doc2comments |
def Strongest_Extension(class_name, extensions):
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extens... |
HumanEval/154 |
def cycpattern_check(a , b):
# You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
# cycpattern_check("abcd","abd") => False
# cycpattern_check("hello","ell") => True
# cycpattern_check("whassup","psus") => False
# cycpattern_ch... | cycpattern_check | for j in range(l + 1):
if a[i:i+l] == pat[j:j+l]:
return True
return False
| def check(candidate):
# Check some simple cases
#assert True, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
#assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate("xyzw","xyw") == False... | 0 | doc2comments |
def cycpattern_check(a , b):
"""You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("ab... |
HumanEval/155 |
def even_odd_count(num):
# Given an integer. return a tuple that has the number of even and odd digits respectively.
# Example:
# even_odd_count(-12) ==> (1, 1)
# even_odd_count(123) ==> (1, 2)
even_count = 0
odd_count = 0
for i in str(abs(num)):
if int(i)%2==0:
| even_odd_count | even_count +=1
else:
odd_count +=1
return (even_count, odd_count)
| def check(candidate):
# Check some simple cases
assert candidate(7) == (0, 1)
assert candidate(-78) == (1, 1)
assert candidate(3452) == (2, 2)
assert candidate(346211) == (3, 3)
assert candidate(-345821) == (3, 3)
assert candidate(-2) == (1, 0)
assert candidate(-45347) == (2, 3)
ass... | 0 | doc2comments |
def even_odd_count(num):
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2)
"""
even_count = 0
odd_count = 0
for i in str(abs(num)):
if int(i)%2==0:
... |
HumanEval/156 |
def int_to_mini_roman(number):
# Given a positive integer, obtain its roman numeral equivalent as a string,
# and return it in lowercase.
# Restrictions: 1 <= num <= 1000
# Examples:
# >>> int_to_mini_roman(19) == 'xix'
# >>> int_to_mini_roman(152) == 'clii'
# >>> int_to_mini_roman(426) ==... | int_to_mini_roman | div = number // num[i]
number %= num[i]
while div:
res += sym[i]
div -= 1
i -= 1
return res.lower()
| def check(candidate):
# Check some simple cases
assert candidate(19) == 'xix'
assert candidate(152) == 'clii'
assert candidate(251) == 'ccli'
assert candidate(426) == 'cdxxvi'
assert candidate(500) == 'd'
assert candidate(1) == 'i'
assert candidate(4) == 'iv'
assert candidate(43) ==... | 0 | doc2comments |
def int_to_mini_roman(number):
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxx... |
HumanEval/157 |
def right_angle_triangle(a, b, c):
# Given the lengths of the three sides of a triangle. Return True if the three
# sides form a right-angled triangle, False otherwise.
# A right-angled triangle is a triangle in which one angle is right angle or
# 90 degree.
# Example:
# right_angle_triangle(3... | right_angle_triangle | return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b
| def check(candidate):
# Check some simple cases
assert candidate(3, 4, 5) == True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1, 2, 3) == False
assert candidate(10, 6, 8) == True
assert candidate(2, 2, 2) == False
assert candidate(7, 24, 25) == True
assert c... | 0 | doc2comments | null |
HumanEval/158 |
def find_max(words):
# Write a function that accepts a list of strings.
# The list contains different words. Return the word with maximum number
# of unique characters. If multiple strings have maximum number of unique
# characters, return the one which comes first in lexicographical order.
# find... | find_max | return sorted(words, key = lambda x: (-len(set(x)), x))[0]
| def check(candidate):
# Check some simple cases
assert (candidate(["name", "of", "string"]) == "string"), "t1"
assert (candidate(["name", "enam", "game"]) == "enam"), 't2'
assert (candidate(["aaaaaaa", "bb", "cc"]) == "aaaaaaa"), 't3'
assert (candidate(["abc", "cba"]) == "abc"), 't4'
assert (ca... | 0 | doc2comments | null |
HumanEval/159 |
def eat(number, need, remaining):
# You're a hungry rabbit, and you already have eaten a certain number of carrots,
# but now you need to eat more carrots to complete the day's meals.
# you should return an array of [ total number of eaten carrots after your meals,
# the... | eat | else:
return [ number + remaining , 0]
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(5, 6, 10) == [11, 4], "Error"
assert candidate(4, 8, 9) == [12, 1], "Error"
assert candidate(1, 10, 10) == [11, 0], "Error"
assert candidate(2, 11, 5) == [7, ... | 0 | doc2comments |
def eat(number, need, remaining):
"""
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the... |
HumanEval/160 |
def do_algebra(operator, operand):
# Given two lists operator, and operand. The first list has basic algebra operations, and
# the second list is a list of integers. Use the two given lists to build the algebric
# expression and return the evaluation of this expression.
# The basic algebra operation... | do_algebra | expression+= oprt + str(oprn)
return eval(expression)
| def check(candidate):
# Check some simple cases
assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37
assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9
assert candidate(['//', '*'], [7, 3, 4]) == 8, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are eas... | 0 | doc2comments |
def do_algebra(operator, operand):
"""
Given two lists operator, and operand. The first list has basic algebra operations, and
the second list is a list of integers. Use the two given lists to build the algebric
expression and return the evaluation of this expression.
The basic algebra operation... |
HumanEval/161 |
def solve(s):
# You are given a string s.
# if s[i] is a letter, reverse its case from lower to upper or vise versa,
# otherwise keep it as it is.
# If the string contains no letters, reverse the string.
# The function should return the resulted string.
# Examples
# solve("1234") = "4321"
... | solve | idx += 1
s = ""
for i in new_str:
s += i
if flg == 0:
return s[len(s)::-1]
return s
| def check(candidate):
# Check some simple cases
assert candidate("AsDf") == "aSdF"
assert candidate("1234") == "4321"
assert candidate("ab") == "AB"
assert candidate("#a@C") == "#A@c"
assert candidate("#AsdfW^45") == "#aSDFw^45"
assert candidate("#6@2") == "2@6#"
# Check some edge case... | 0 | doc2comments |
def solve(s):
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("... |
HumanEval/162 |
def string_to_md5(text):
# Given a string 'text', return its md5 hash equivalent string.
# If 'text' is an empty string, return None.
# >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
import hashlib
| string_to_md5 | return hashlib.md5(text.encode('ascii')).hexdigest() if text else None
| def check(candidate):
# Check some simple cases
assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
assert candidate('') == None
assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'
assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'
# Check some edg... | 0 | doc2comments |
def string_to_md5(text):
"""
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
"""
import hashlib
# print('@@this is the line to split##')
return hashlib.md5(te... |
HumanEval/163 |
def generate_integers(a, b):
# Given two positive integers a and b, return the even digits between a
# and b, in ascending order.
# For example:
# generate_integers(2, 8) => [2, 4, 6, 8]
# generate_integers(8, 2) => [2, 4, 6, 8]
# generate_integers(10, 14) => []
lower = max(2, min(a, b))
... | generate_integers |
return [i for i in range(lower, upper+1) if i % 2 == 0]
| def check(candidate):
# Check some simple cases
assert candidate(2, 10) == [2, 4, 6, 8], "Test 1"
assert candidate(10, 2) == [2, 4, 6, 8], "Test 2"
assert candidate(132, 2) == [2, 4, 6, 8], "Test 3"
assert candidate(17,89) == [], "Test 4"
# Check some edge cases that are easy to work out by ha... | 0 | doc2comments |
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
lower = max(2, min(a, b... |
HumanEval/0 | from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ... | has_close_elements | if distance < threshold:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True
assert candidate([1.0, 2.0, 5.9, 4.0,... | 0 | new_line_aftercode | from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ... |
HumanEval/1 | from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace... | separate_paren_groups | elif c == ')':
current_depth -= 1
current_string.append(c)
if current_depth == 0:
result.append(''.join(current_string))
current_string.clear()
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('(()()) ((())) () ((())()())') == [
'(()())', '((()))', '()', '((())()())'
]
assert candidate('() (()) ((())) (((())))') == [
'()', '(())', '((()))', '(((())))'
]
assert candidate('(()... | 0 | new_line_aftercode | from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace... |
HumanEval/2 |
def truncate_number(number: float) -> float:
""" Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
>>> truncate_number(3.5)
0... | truncate_number | return number % 1.0
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3.5) == 0.5
assert abs(candidate(1.33) - 0.33) < 1e-6
assert abs(candidate(123.456) - 0.456) < 1e-6
| 0 | new_line_aftercode | null |
HumanEval/3 | from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return Tru... | below_zero | if balance < 0:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == False
assert candidate([1, 2, -3, 1, 2, -3]) == False
assert candidate([1, 2, -4, 5, 6]) == True
assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False
assert candidate([1, -1, 2, -2, 5, -5, 4... | 0 | new_line_aftercode | from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return Tru... |
HumanEval/4 | from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this ... | mean_absolute_deviation | return sum(abs(x - mean) for x in numbers) / len(numbers)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6
| 0 | new_line_aftercode | from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this ... |
HumanEval/5 | from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
if not numbers:
retur... | intersperse | result.append(n)
result.append(delimeter)
result.append(numbers[-1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 7) == []
assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]
assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]
| 0 | new_line_aftercode | from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
if not numbers:
retur... |
HumanEval/6 | from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of n... | parse_nested_parens | max_depth = max(depth, max_depth)
else:
depth -= 1
return max_depth
return [parse_paren_group(x) for x in paren_string.split(' ') if x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]
assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]
assert candidate('(()(())((())))') == [4]
| 0 | new_line_aftercode | from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of n... |
HumanEval/7 | from typing import List
def filter_by_substring(strings: List[str], substring: str) -> List[str]:
""" Filter an input list of strings only for ones that contain given substring
>>> filter_by_substring([], 'a')
[]
>>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
['abc', 'bacd', 'array'... | filter_by_substring | return [x for x in strings if substring in x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx... | 0 | new_line_aftercode | null |
HumanEval/8 | from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1)
... | sum_product | for n in numbers:
sum_value += n
prod_value *= n
return sum_value, prod_value
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == (0, 1)
assert candidate([1, 1, 1]) == (3, 1)
assert candidate([100, 0]) == (100, 0)
assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)
assert candidate([10]) == (10, 10)
| 0 | new_line_aftercode | from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1)
... |
HumanEval/9 | from typing import List, Tuple
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
running_max = None
resul... | rolling_max | else:
running_max = max(running_max, n)
result.append(running_max)
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]
assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]
| 0 | new_line_aftercode | from typing import List, Tuple
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
running_max = None
resul... |
HumanEval/10 |
def is_palindrome(string: str) -> bool:
""" Test if given string is a palindrome """
return string == string[::-1]
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string... | make_palindrome |
while not is_palindrome(string[beginning_of_suffix:]):
beginning_of_suffix += 1
return string + string[:beginning_of_suffix][::-1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('x') == 'x'
assert candidate('xyz') == 'xyzyx'
assert candidate('xyx') == 'xyx'
assert candidate('jerry') == 'jerryrrej'
| 0 | new_line_aftercode |
def is_palindrome(string: str) -> bool:
""" Test if given string is a palindrome """
return string == string[::-1]
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string... |
HumanEval/11 | from typing import List
def string_xor(a: str, b: str) -> str:
""" Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
>>> string_xor('010', '110')
'100'
"""
def xor(i, j):
if i == j:
return '0'
... | string_xor | else:
return '1'
return ''.join(xor(x, y) for x, y in zip(a, b))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('111000', '101010') == '010010'
assert candidate('1', '1') == '0'
assert candidate('0101', '0000') == '0101'
| 0 | new_line_aftercode | from typing import List
def string_xor(a: str, b: str) -> str:
""" Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
>>> string_xor('010', '110')
'100'
"""
def xor(i, j):
if i == j:
return '0'
... |
HumanEval/12 | from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
'a... | longest | maxlen = max(len(x) for x in strings)
for s in strings:
if len(s) == maxlen:
return s
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == None
assert candidate(['x', 'y', 'z']) == 'x'
assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
| 0 | new_line_aftercode | from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
'a... |
HumanEval/13 |
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
while b:
| greatest_common_divisor | a, b = b, a % b
return a
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3, 7) == 1
assert candidate(10, 15) == 5
assert candidate(49, 14) == 7
assert candidate(144, 60) == 12
| 0 | new_line_aftercode |
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
while b:
# print('@@this is the line to split##')
a, b = b, a % b
return a
|
HumanEval/14 | from typing import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
result = []
| all_prefixes | for i in range(len(string)):
result.append(string[:i+1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == []
assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']
assert candidate('WWW') == ['W', 'WW', 'WWW']
| 0 | new_line_aftercode | from typing import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
result = []
# print('@@this is the line to split##')
for i in range(len(string)):
result.... |
HumanEval/15 |
def string_sequence(n: int) -> str:
""" Return a string containing space-delimited numbers starting from 0 upto n inclusive.
>>> string_sequence(0)
'0'
>>> string_sequence(5)
'0 1 2 3 4 5'
"""
| string_sequence | return ' '.join([str(x) for x in range(n + 1)])
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(0) == '0'
assert candidate(3) == '0 1 2 3'
assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'
| 0 | new_line_aftercode | null |
HumanEval/16 |
def count_distinct_characters(string: str) -> int:
""" Given a string, find out how many distinct characters (regardless of case) does it consist of
>>> count_distinct_characters('xyzXYZ')
3
>>> count_distinct_characters('Jerry')
4
"""
| count_distinct_characters | return len(set(string.lower()))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == 0
assert candidate('abcde') == 5
assert candidate('abcde' + 'cade' + 'CADE') == 5
assert candidate('aaaaAAAAaaaa') == 1
assert candidate('Jerry jERRY JeRRRY') == 5
| 0 | new_line_aftercode | null |
HumanEval/17 | from typing import List
def parse_music(music_string: str) -> List[int]:
""" Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return list of integers corresponding to how many beats does each
not last.
Here is a legend:
... | parse_music | return [note_map[x] for x in music_string.split(' ') if x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == []
assert candidate('o o o o') == [4, 4, 4, 4]
assert candidate('.| .| .| .|') == [1, 1, 1, 1]
assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]
assert candidate('o| .| o| .| ... | 0 | new_line_aftercode | from typing import List
def parse_music(music_string: str) -> List[int]:
""" Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return list of integers corresponding to how many beats does each
not last.
Here is a legend:
... |
HumanEval/18 |
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
times = 0
for i ... | how_many_times | if string[i:i+len(substring)] == substring:
times += 1
return times
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('', 'x') == 0
assert candidate('xyxyxyx', 'x') == 4
assert candidate('cacacacac', 'cac') == 4
assert candidate('john doe', 'john') == 1
| 0 | new_line_aftercode |
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
times = 0
for i ... |
HumanEval/19 | from typing import List
def sort_numbers(numbers: str) -> str:
""" Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
>... | sort_numbers | 'five': 5,
'six': 6,
'seven': 7,
'eight': 8,
'nine': 9
}
return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('three') == 'three'
assert candidate('three five nine') == 'three five nine'
assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'
assert ... | 0 | new_line_aftercode | from typing import List
def sort_numbers(numbers: str) -> str:
""" Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
>... |
HumanEval/20 | from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([... | find_closest_elements | closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return close... |
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
assert candidate([1.0, 2.0, 3.0, 4.0,... | 0 | new_line_aftercode | from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([... |
HumanEval/21 | from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, ... | rescale_to_unit | max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([2.0, 49.9]) == [0.0, 1.0]
assert candidate([100.0, 49.9]) == [1.0, 0.0]
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.... | 0 | new_line_aftercode | from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, ... |
HumanEval/22 | from typing import List, Any
def filter_integers(values: List[Any]) -> List[int]:
""" Filter given list of any python values only for integers
>>> filter_integers(['a', 3.14, 5])
[5]
>>> filter_integers([1, 2, 3, 'abc', {}, []])
[1, 2, 3]
"""
| filter_integers | return [x for x in values if isinstance(x, int)]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]
assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]
| 0 | new_line_aftercode | null |
HumanEval/23 |
def strlen(string: str) -> int:
""" Return length of given string
>>> strlen('')
0
>>> strlen('abc')
3
"""
| strlen | return len(string)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == 0
assert candidate('x') == 1
assert candidate('asdasnakj') == 9
| 0 | new_line_aftercode | null |
HumanEval/24 |
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
for i in reversed(range(n)):
| largest_divisor | if n % i == 0:
return i
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3) == 1
assert candidate(7) == 1
assert candidate(10) == 5
assert candidate(100) == 50
assert candidate(49) == 7
| 0 | new_line_aftercode |
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
for i in reversed(range(n)):
# print('@@this is the line to split##')
if n % i == 0:
return i
|
HumanEval/25 | from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the produc... | factorize | n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(2) == [2]
assert candidate(4) == [2, 2]
assert candidate(8) == [2, 2, 2]
assert candidate(3 * 19) == [3, 19]
assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]
assert candidate(3 * 19 * 3 * 19 * ... | 0 | new_line_aftercode | from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the produc... |
HumanEval/26 | from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
import collections
| remove_duplicates | c = collections.Counter(numbers)
return [n for n in numbers if c[n] <= 1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
| 0 | new_line_aftercode | from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
import collections
# print(... |
HumanEval/27 |
def flip_case(string: str) -> str:
""" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
>>> flip_case('Hello')
'hELLO'
"""
| flip_case | return string.swapcase()
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('Hello!') == 'hELLO!'
assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
| 0 | new_line_aftercode | null |
HumanEval/28 | from typing import List
def concatenate(strings: List[str]) -> str:
""" Concatenate list of strings into a single string
>>> concatenate([])
''
>>> concatenate(['a', 'b', 'c'])
'abc'
"""
| concatenate | return ''.join(strings)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == ''
assert candidate(['x', 'y', 'z']) == 'xyz'
assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
| 0 | new_line_aftercode | null |
HumanEval/29 | from typing import List
def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
""" Filter an input list of strings only for ones that start with a given prefix.
>>> filter_by_prefix([], 'a')
[]
>>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
['abc', 'array']
"""
| filter_by_prefix | return [x for x in strings if x.startswith(prefix)]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
| 0 | new_line_aftercode | null |
HumanEval/30 |
def get_positive(l: list):
"""Return only positive numbers in the list.
>>> get_positive([-1, 2, -4, 5, 6])
[2, 5, 6]
>>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
[5, 3, 2, 3, 9, 123, 1]
"""
| get_positive | return [e for e in l if e > 0]
|
METADATA = {}
def check(candidate):
assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6]
assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1]
assert candidate([-1, -2]) == []
assert candidate([]) == []
| 0 | new_line_aftercode | null |
HumanEval/31 |
def is_prime(n):
"""Return true if a given number is prime, and false otherwise.
>>> is_prime(6)
False
>>> is_prime(101)
True
>>> is_prime(11)
True
>>> is_prime(13441)
True
>>> is_prime(61)
True
>>> is_prime(4)
False
>>> is_prime(1)
False
"""
if n < ... | is_prime | if n % k == 0:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate(6) == False
assert candidate(101) == True
assert candidate(11) == True
assert candidate(13441) == True
assert candidate(61) == True
assert candidate(4) == False
assert candidate(1) == False
assert candidate(5) == True
assert ca... | 0 | new_line_aftercode |
def is_prime(n):
"""Return true if a given number is prime, and false otherwise.
>>> is_prime(6)
False
>>> is_prime(101)
True
>>> is_prime(11)
True
>>> is_prime(13441)
True
>>> is_prime(61)
True
>>> is_prime(4)
False
>>> is_prime(1)
False
"""
if n < ... |
HumanEval/32 | import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a polynomia... | find_zero | center = (begin + end) / 2.0
if poly(xs, center) * poly(xs, begin) > 0:
begin = center
else:
end = center
return begin
|
METADATA = {}
def check(candidate):
import math
import random
rng = random.Random(42)
import copy
for _ in range(100):
ncoeff = 2 * rng.randint(1, 4)
coeffs = []
for _ in range(ncoeff):
coeff = rng.randint(-10, 10)
if coeff == 0:
co... | 0 | new_line_aftercode | import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a polynomia... |
HumanEval/33 |
def sort_third(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
>>> sort_t... | sort_third | l[::3] = sorted(l[::3])
return l
|
METADATA = {}
def check(candidate):
assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))
assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))
assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(so... | 0 | new_line_aftercode |
def sort_third(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
>>> sort_t... |
HumanEval/34 |
def unique(l: list):
"""Return sorted unique elements in a list
>>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
[0, 2, 3, 5, 9, 123]
"""
| unique | return sorted(list(set(l)))
|
METADATA = {}
def check(candidate):
assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
| 0 | new_line_aftercode | null |
HumanEval/35 |
def max_element(l: list):
"""Return maximum element in the list.
>>> max_element([1, 2, 3])
3
>>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
123
"""
m = l[0]
for e in l:
| max_element | if e > m:
m = e
return m
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 3]) == 3
assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124
| 0 | new_line_aftercode |
def max_element(l: list):
"""Return maximum element in the list.
>>> max_element([1, 2, 3])
3
>>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
123
"""
m = l[0]
for e in l:
# print('@@this is the line to split##')
if e > m:
m = e
return m
|
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