task_id stringlengths 11 13 | prompt stringlengths 97 1.72k | entry_point stringlengths 1 30 | canonical_solution stringlengths 16 483 | test stringlengths 117 1.8k | seed int32 0 9 | perturbation_name stringclasses 6
values | partial stringlengths 265 2.05k ⌀ |
|---|---|---|---|---|---|---|---|
HumanEval/132 |
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[... | is_nested | i = 0
l = len(closing_bracket_index)
for idx in opening_bracket_index:
if i < l and idx < closing_bracket_index[i]:
cnt += 1
i += 1
return cnt >= 2
| def check(candidate):
# Check some simple cases
assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate('[]]]]]]][[[[[]') == False
assert candidate('[][]') == False
assert candidate(('[]')) == False
assert candidate('[[[[]]]]') == True
a... | 9 | new_lines |
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[... |
HumanEval/133 |
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst =... | sum_squares | for i in lst:
squared += math.ceil(i)**2
return squared
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1.0,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1,3,5,7])==84, "This prints if this assert fails 1 (goo... | 9 | new_lines |
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst =... |
HumanEval/134 |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... | check_if_last_char_is_a_letter | check = txt.split(' ')[-1]
return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
| def check(candidate):
# Check some simple cases
assert candidate("apple") == False
assert candidate("apple pi e") == True
assert candidate("eeeee") == False
assert candidate("A") == True
assert candidate("Pumpkin pie ") == False
assert candidate("Pumpkin pie 1") == False
assert candidat... | 9 | new_lines |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... |
HumanEval/135 |
def can_arrange(arr):
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) =... | can_arrange | if arr[i]<arr[i-1]:
ind=i
i+=1
return ind
| def check(candidate):
# Check some simple cases
assert candidate([1,2,4,3,5])==3
assert candidate([1,2,4,5])==-1
assert candidate([1,4,2,5,6,7,8,9,10])==2
assert candidate([4,8,5,7,3])==4
# Check some edge cases that are easy to work out by hand.
assert candidate([])==-1
| 9 | new_lines |
def can_arrange(arr):
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) =... |
HumanEval/136 |
def largest_smallest_integers(lst):
'''
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no negative or positive integers, return them as None.
Examples:
largest_smallest_intege... | largest_smallest_integers | largest = list(filter(lambda x: x > 0, lst))
return (max(smallest) if smallest else None, min(largest) if largest else None)
| def check(candidate):
# Check some simple cases
assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1)
assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1)
assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1)
assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2)
assert candidate([7, 3, 8, 4, 9, 2, 5, -... | 9 | new_lines |
def largest_smallest_integers(lst):
'''
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no negative or positive integers, return them as None.
Examples:
largest_smallest_intege... |
HumanEval/137 |
def compare_one(a, b):
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
... | compare_one | if isinstance(temp_b, str): temp_b = temp_b.replace(',','.')
if float(temp_a) == float(temp_b): return None
return a if float(temp_a) > float(temp_b) else b
| def check(candidate):
# Check some simple cases
assert candidate(1, 2) == 2
assert candidate(1, 2.5) == 2.5
assert candidate(2, 3) == 3
assert candidate(5, 6) == 6
assert candidate(1, "2,3") == "2,3"
assert candidate("5,1", "6") == "6"
assert candidate("1", "2") == "2"
assert candid... | 9 | new_lines |
def compare_one(a, b):
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
... |
HumanEval/138 |
def is_equal_to_sum_even(n):
"""Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
is_equal_to_sum_even(4) == False
is_equal_to_sum_even(6) == False
is_equal_to_sum_even(8) == True
"""
| is_equal_to_sum_even | return n%2 == 0 and n >= 8
| def check(candidate):
assert candidate(4) == False
assert candidate(6) == False
assert candidate(8) == True
assert candidate(10) == True
assert candidate(11) == False
assert candidate(12) == True
assert candidate(13) == False
assert candidate(16) == True
| 9 | new_lines | null |
HumanEval/139 |
def special_factorial(n):
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this integer.
... | special_factorial | fact_i *= i
special_fact *= fact_i
return special_fact
| def check(candidate):
# Check some simple cases
assert candidate(4) == 288, "Test 4"
assert candidate(5) == 34560, "Test 5"
assert candidate(7) == 125411328000, "Test 7"
# Check some edge cases that are easy to work out by hand.
assert candidate(1) == 1, "Test 1"
| 9 | new_lines |
def special_factorial(n):
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this integer.
... |
HumanEval/140 |
def fix_spaces(text):
"""
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2")... | fix_spaces | new_text += "_"*(end - start)+text[i]
else:
new_text += text[i]
start, end = i+1, i+1
i+=1
if end - start > 2:
new_text += "-"
elif end - start > 0:
new_text += "_"
return new_text
| def check(candidate):
# Check some simple cases
assert candidate("Example") == "Example", "This prints if this assert fails 1 (good for debugging!)"
assert candidate("Mudasir Hanif ") == "Mudasir_Hanif_", "This prints if this assert fails 2 (good for debugging!)"
assert candidate("Yellow Yellow Dirty ... | 9 | new_lines |
def fix_spaces(text):
"""
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2")... |
HumanEval/141 |
def file_name_check(file_name):
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be mo... | file_name_check | return 'No'
if not lst[0][0].isalpha():
return 'No'
t = len([x for x in lst[0] if x.isdigit()])
if t > 3:
return 'No'
return 'Yes'
| def check(candidate):
# Check some simple cases
assert candidate("example.txt") == 'Yes'
assert candidate("1example.dll") == 'No'
assert candidate('s1sdf3.asd') == 'No'
assert candidate('K.dll') == 'Yes'
assert candidate('MY16FILE3.exe') == 'Yes'
assert candidate('His12FILE94.exe') == 'No'
... | 9 | new_lines |
def file_name_check(file_name):
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be mo... |
HumanEval/142 |
def sum_squares(lst):
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the e... | sum_squares | elif i % 4 == 0 and i%3 != 0:
result.append(lst[i]**3)
else:
result.append(lst[i])
return sum(result)
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3]) == 6
assert candidate([1,4,9]) == 14
assert candidate([]) == 0
assert candidate([1,1,1,1,1,1,1,1,1]) == 9
assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3
assert candidate([0]) == 0
assert candidate([-1,-... | 9 | new_lines |
def sum_squares(lst):
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the e... |
HumanEval/143 |
def words_in_sentence(sentence):
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new stri... | words_in_sentence | for i in range(2, len(word)):
if len(word)%i == 0:
flg = 1
if flg == 0 or len(word) == 2:
new_lst.append(word)
return " ".join(new_lst)
| def check(candidate):
# Check some simple cases
assert candidate("This is a test") == "is"
assert candidate("lets go for swimming") == "go for"
assert candidate("there is no place available here") == "there is no place"
assert candidate("Hi I am Hussein") == "Hi am Hussein"
assert candidate("go... | 9 | new_lines |
def words_in_sentence(sentence):
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new stri... |
HumanEval/144 |
def simplify(x, n):
"""Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where ... | simplify | denom = int(b) * int(d)
if (numerator/denom == int(numerator/denom)):
return True
return False
| def check(candidate):
# Check some simple cases
assert candidate("1/5", "5/1") == True, 'test1'
assert candidate("1/6", "2/1") == False, 'test2'
assert candidate("5/1", "3/1") == True, 'test3'
assert candidate("7/10", "10/2") == False, 'test4'
assert candidate("2/10", "50/10") == True, 'test5'
... | 9 | new_lines |
def simplify(x, n):
"""Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where ... |
HumanEval/145 |
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_poi... | order_by_points | n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return sorted(nums, key=digits_sum)
| def check(candidate):
# Check some simple cases
assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]
assert candidate([]) == []
assert candidate([1,... | 9 | new_lines |
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_poi... |
HumanEval/146 |
def specialFilter(nums):
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter(... | specialFilter | number_as_string = str(num)
if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits:
count += 1
return count
| def check(candidate):
# Check some simple cases
assert candidate([5, -2, 1, -5]) == 0
assert candidate([15, -73, 14, -15]) == 1
assert candidate([33, -2, -3, 45, 21, 109]) == 2
assert candidate([43, -12, 93, 125, 121, 109]) == 4
assert candidate([71, -2, -33, 75, 21, 19]) == 3
# Check s... | 9 | new_lines |
def specialFilter(nums):
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter(... |
HumanEval/147 |
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
... | get_max_triples | for k in range(j+1,n):
if (A[i]+A[j]+A[k])%3 == 0:
ans += [(A[i],A[j],A[k])]
return len(ans)
| def check(candidate):
assert candidate(5) == 1
assert candidate(6) == 4
assert candidate(10) == 36
assert candidate(100) == 53361
| 9 | new_lines |
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
... |
HumanEval/148 |
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a ... | bf | planet2_index = planet_names.index(planet2)
if planet1_index < planet2_index:
return (planet_names[planet1_index + 1: planet2_index])
else:
return (planet_names[planet2_index + 1 : planet1_index])
| def check(candidate):
# Check some simple cases
assert candidate("Jupiter", "Neptune") == ("Saturn", "Uranus"), "First test error: " + str(len(candidate("Jupiter", "Neptune")))
assert candidate("Earth", "Mercury") == ("Venus",), "Second test error: " + str(candidate("Earth", "Mercury"))
assert ... | 9 | new_lines |
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a ... |
HumanEval/149 |
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
T... | sorted_list_sum | if len(i)%2 == 0:
new_lst.append(i)
return sorted(new_lst, key=len)
| def check(candidate):
# Check some simple cases
assert candidate(["aa", "a", "aaa"]) == ["aa"]
assert candidate(["school", "AI", "asdf", "b"]) == ["AI", "asdf", "school"]
assert candidate(["d", "b", "c", "a"]) == []
assert candidate(["d", "dcba", "abcd", "a"]) == ["abcd", "dcba"]
# Check some ... | 9 | new_lines |
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
T... |
HumanEval/150 |
def x_or_y(n, x, y):
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
for x_or_y(7, 34, 12) == 34
for x_or_y(15, 8, 5) == 5
"""
if n == 1:
return y
for i in range(2, n):
if n % i... | x_or_y | return y
break
else:
return x
| def check(candidate):
# Check some simple cases
assert candidate(7, 34, 12) == 34
assert candidate(15, 8, 5) == 5
assert candidate(3, 33, 5212) == 33
assert candidate(1259, 3, 52) == 3
assert candidate(7919, -1, 12) == -1
assert candidate(3609, 1245, 583) == 583
assert candidate(91, 56,... | 9 | new_lines |
def x_or_y(n, x, y):
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
for x_or_y(7, 34, 12) == 34
for x_or_y(15, 8, 5) == 5
"""
if n == 1:
return y
for i in range(2, n):
if n % i ==... |
HumanEval/151 |
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_dif... | double_the_difference | return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
| def check(candidate):
# Check some simple cases
assert candidate([]) == 0 , "This prints if this assert fails 1 (good for debugging!)"
assert candidate([5, 4]) == 25 , "This prints if this assert fails 2 (good for debugging!)"
assert candidate([0.1, 0.2, 0.3]) == 0 , "This prints if this assert fails 3... | 9 | new_lines | null |
HumanEval/152 |
def compare(game,guess):
"""I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number... | compare | return [abs(x-y) for x,y in zip(game,guess)]
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], "This prints if this assert fails 1 (good for debugging!)"
assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], "This prints if this assert fails 1 (good for debugging!)"
assert candi... | 9 | new_lines | null |
HumanEval/153 |
def Strongest_Extension(class_name, extensions):
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extens... | Strongest_Extension | strong = s
my_val = val
ans = class_name + "." + strong
return ans
| def check(candidate):
# Check some simple cases
assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe'
assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe'
assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__'... | 9 | new_lines |
def Strongest_Extension(class_name, extensions):
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extens... |
HumanEval/154 |
def cycpattern_check(a , b):
"""You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("ab... | cycpattern_check | for j in range(l + 1):
if a[i:i+l] == pat[j:j+l]:
return True
return False
| def check(candidate):
# Check some simple cases
#assert True, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
#assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate("xyzw","xyw") == False... | 9 | new_lines |
def cycpattern_check(a , b):
"""You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("ab... |
HumanEval/155 |
def even_odd_count(num):
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2)
"""
even_count = 0
odd_count = 0
for i in str(abs(num)):
if int(i)%2==0:
| even_odd_count | even_count +=1
else:
odd_count +=1
return (even_count, odd_count)
| def check(candidate):
# Check some simple cases
assert candidate(7) == (0, 1)
assert candidate(-78) == (1, 1)
assert candidate(3452) == (2, 2)
assert candidate(346211) == (3, 3)
assert candidate(-345821) == (3, 3)
assert candidate(-2) == (1, 0)
assert candidate(-45347) == (2, 3)
ass... | 9 | new_lines |
def even_odd_count(num):
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2)
"""
even_count = 0
odd_count = 0
for i in str(abs(num)):
if int(i)%2==0:
... |
HumanEval/156 |
def int_to_mini_roman(number):
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxx... | int_to_mini_roman | div = number // num[i]
number %= num[i]
while div:
res += sym[i]
div -= 1
i -= 1
return res.lower()
| def check(candidate):
# Check some simple cases
assert candidate(19) == 'xix'
assert candidate(152) == 'clii'
assert candidate(251) == 'ccli'
assert candidate(426) == 'cdxxvi'
assert candidate(500) == 'd'
assert candidate(1) == 'i'
assert candidate(4) == 'iv'
assert candidate(43) ==... | 9 | new_lines |
def int_to_mini_roman(number):
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxx... |
HumanEval/157 |
def right_angle_triangle(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return True if the three
sides form a right-angled triangle, False otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
right_angle_triangle(3, 4,... | right_angle_triangle | return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b
| def check(candidate):
# Check some simple cases
assert candidate(3, 4, 5) == True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1, 2, 3) == False
assert candidate(10, 6, 8) == True
assert candidate(2, 2, 2) == False
assert candidate(7, 24, 25) == True
assert c... | 9 | new_lines | null |
HumanEval/158 |
def find_max(words):
"""Write a function that accepts a list of strings.
The list contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
find_max(["... | find_max | return sorted(words, key = lambda x: (-len(set(x)), x))[0]
| def check(candidate):
# Check some simple cases
assert (candidate(["name", "of", "string"]) == "string"), "t1"
assert (candidate(["name", "enam", "game"]) == "enam"), 't2'
assert (candidate(["aaaaaaa", "bb", "cc"]) == "aaaaaaa"), 't3'
assert (candidate(["abc", "cba"]) == "abc"), 't4'
assert (ca... | 9 | new_lines | null |
HumanEval/159 |
def eat(number, need, remaining):
"""
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the... | eat | else:
return [ number + remaining , 0]
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(5, 6, 10) == [11, 4], "Error"
assert candidate(4, 8, 9) == [12, 1], "Error"
assert candidate(1, 10, 10) == [11, 0], "Error"
assert candidate(2, 11, 5) == [7, ... | 9 | new_lines |
def eat(number, need, remaining):
"""
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the... |
HumanEval/160 |
def do_algebra(operator, operand):
"""
Given two lists operator, and operand. The first list has basic algebra operations, and
the second list is a list of integers. Use the two given lists to build the algebric
expression and return the evaluation of this expression.
The basic algebra operation... | do_algebra | expression+= oprt + str(oprn)
return eval(expression)
| def check(candidate):
# Check some simple cases
assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37
assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9
assert candidate(['//', '*'], [7, 3, 4]) == 8, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are eas... | 9 | new_lines |
def do_algebra(operator, operand):
"""
Given two lists operator, and operand. The first list has basic algebra operations, and
the second list is a list of integers. Use the two given lists to build the algebric
expression and return the evaluation of this expression.
The basic algebra operation... |
HumanEval/161 |
def solve(s):
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("... | solve | idx += 1
s = ""
for i in new_str:
s += i
if flg == 0:
return s[len(s)::-1]
return s
| def check(candidate):
# Check some simple cases
assert candidate("AsDf") == "aSdF"
assert candidate("1234") == "4321"
assert candidate("ab") == "AB"
assert candidate("#a@C") == "#A@c"
assert candidate("#AsdfW^45") == "#aSDFw^45"
assert candidate("#6@2") == "2@6#"
# Check some edge case... | 9 | new_lines |
def solve(s):
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("... |
HumanEval/162 |
def string_to_md5(text):
"""
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
"""
import hashlib
| string_to_md5 | return hashlib.md5(text.encode('ascii')).hexdigest() if text else None
| def check(candidate):
# Check some simple cases
assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
assert candidate('') == None
assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888'
assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99'
# Check some edg... | 9 | new_lines |
def string_to_md5(text):
"""
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
"""
import hashlib
# print('@@this is the line to split##')
return hashlib.md5(te... |
HumanEval/163 |
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
lower = max(2, min(a, ... | generate_integers |
return [i for i in range(lower, upper+1) if i % 2 == 0]
| def check(candidate):
# Check some simple cases
assert candidate(2, 10) == [2, 4, 6, 8], "Test 1"
assert candidate(10, 2) == [2, 4, 6, 8], "Test 2"
assert candidate(132, 2) == [2, 4, 6, 8], "Test 3"
assert candidate(17,89) == [], "Test 4"
# Check some edge cases that are easy to work out by ha... | 9 | new_lines |
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
lower = max(2, min(a, b... |
HumanEval/0 | from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ... | has_close_elements | if distance < threshold:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True
assert candidate([1.0, 2.0, 5.9, 4.0,... | 0 | split_lines | from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ... |
HumanEval/1 | from typing \
import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open ... | separate_paren_groups | elif c == ')':
current_depth -= 1
current_string.append(c)
if current_depth == 0:
result.append(''.join(current_string))
current_string.clear()
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('(()()) ((())) () ((())()())') == [
'(()())', '((()))', '()', '((())()())'
]
assert candidate('() (()) ((())) (((())))') == [
'()', '(())', '((()))', '(((())))'
]
assert candidate('(()... | 0 | split_lines | from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace... |
HumanEval/2 |
def truncate_number(number: float) -> float:
""" Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
>>> truncate_number(3.5)
0... | truncate_number | return number % 1.0
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3.5) == 0.5
assert abs(candidate(1.33) - 0.33) < 1e-6
assert abs(candidate(123.456) - 0.456) < 1e-6
| 0 | split_lines | null |
HumanEval/3 | from typing \
import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should retur... | below_zero | if balance < 0:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == False
assert candidate([1, 2, -3, 1, 2, -3]) == False
assert candidate([1, 2, -4, 5, 6]) == True
assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False
assert candidate([1, -1, 2, -2, 5, -5, 4... | 0 | split_lines | from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return Tru... |
HumanEval/4 | from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this ... | mean_absolute_deviation | return sum(abs(x - mean) for x in numbers) / len(numbers)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6
| 0 | split_lines | from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this ... |
HumanEval/5 | from typing \
import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
if not numbers:
... | intersperse | result.append(n)
result.append(delimeter)
result.append(numbers[-1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 7) == []
assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]
assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]
| 0 | split_lines | from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
if not numbers:
retur... |
HumanEval/6 | from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of n... | parse_nested_parens | max_depth = max(depth, max_depth)
else:
depth -= 1
return max_depth
return [parse_paren_group(x) for x in paren_string.split(' ') if x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]
assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]
assert candidate('(()(())((())))') == [4]
| 0 | split_lines | from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of n... |
HumanEval/7 | from typing \
import List
def filter_by_substring(strings: List[str], substring: str) -> List[str]:
""" Filter an input list of strings only for ones that contain given substring
>>> filter_by_substring([], 'a')
[]
>>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
['abc', 'bacd', 'a... | filter_by_substring | return [x for x in strings if substring in x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx... | 0 | split_lines | null |
HumanEval/8 | from typing \
import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1... | sum_product | for n in numbers:
sum_value += n
prod_value *= n
return sum_value, prod_value
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == (0, 1)
assert candidate([1, 1, 1]) == (3, 1)
assert candidate([100, 0]) == (100, 0)
assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)
assert candidate([10]) == (10, 10)
| 0 | split_lines | from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1)
... |
HumanEval/9 | from typing \
import List, Tuple
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
running_max = None
... | rolling_max | else:
running_max = max(running_max, n)
result.append(running_max)
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]
assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]
| 0 | split_lines | from typing import List, Tuple
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
running_max = None
resul... |
HumanEval/10 |
def is_palindrome(string: str) -> bool:
""" Test if given string is a palindrome """
return string == string[::-1]
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string... | make_palindrome |
while not is_palindrome(string[beginning_of_suffix:]):
beginning_of_suffix += 1
return string + string[:beginning_of_suffix][::-1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('x') == 'x'
assert candidate('xyz') == 'xyzyx'
assert candidate('xyx') == 'xyx'
assert candidate('jerry') == 'jerryrrej'
| 0 | split_lines |
def is_palindrome(string: str) -> bool:
""" Test if given string is a palindrome """
return string == string[::-1]
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string... |
HumanEval/11 | from typing \
import List
def string_xor(a: str, b: str) -> str:
""" Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
>>> string_xor('010', '110')
'100'
"""
def xor(i, j):
if i == j:
return... | string_xor | else:
return '1'
return ''.join(xor(x, y) for x, y in zip(a, b))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('111000', '101010') == '010010'
assert candidate('1', '1') == '0'
assert candidate('0101', '0000') == '0101'
| 0 | split_lines | from typing import List
def string_xor(a: str, b: str) -> str:
""" Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
>>> string_xor('010', '110')
'100'
"""
def xor(i, j):
if i == j:
return '0'
... |
HumanEval/12 | from typing \
import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
... | longest | maxlen = max(len(x) for x in strings)
for s in strings:
if len(s) == maxlen:
return s
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == None
assert candidate(['x', 'y', 'z']) == 'x'
assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
| 0 | split_lines | from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
'a... |
HumanEval/13 |
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
while \
b:
| greatest_common_divisor | a, b = b, a % b
return a
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3, 7) == 1
assert candidate(10, 15) == 5
assert candidate(49, 14) == 7
assert candidate(144, 60) == 12
| 0 | split_lines |
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
while b:
# print('@@this is the line to split##')
a, b = b, a % b
return a
|
HumanEval/14 | from typing \
import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
result = []
| all_prefixes | for i in range(len(string)):
result.append(string[:i+1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == []
assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']
assert candidate('WWW') == ['W', 'WW', 'WWW']
| 0 | split_lines | from typing import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
result = []
# print('@@this is the line to split##')
for i in range(len(string)):
result.... |
HumanEval/15 |
def string_sequence(n: int) -> str:
""" Return a string containing space-delimited numbers starting from 0 upto n inclusive.
>>> string_sequence(0)
'0'
>>> string_sequence(5)
'0 1 2 3 4 5'
"""
| string_sequence | return ' '.join([str(x) for x in range(n + 1)])
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(0) == '0'
assert candidate(3) == '0 1 2 3'
assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'
| 0 | split_lines | null |
HumanEval/16 |
def count_distinct_characters(string: str) -> int:
""" Given a string, find out how many distinct characters (regardless of case) does it consist of
>>> count_distinct_characters('xyzXYZ')
3
>>> count_distinct_characters('Jerry')
4
"""
| count_distinct_characters | return len(set(string.lower()))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == 0
assert candidate('abcde') == 5
assert candidate('abcde' + 'cade' + 'CADE') == 5
assert candidate('aaaaAAAAaaaa') == 1
assert candidate('Jerry jERRY JeRRRY') == 5
| 0 | split_lines | null |
HumanEval/17 | from typing import List
def parse_music(music_string: str) -> List[int]:
""" Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return list of integers corresponding to how many beats does each
not last.
Here is a legend:
... | parse_music | return [note_map[x] for x in music_string.split(' ') if x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == []
assert candidate('o o o o') == [4, 4, 4, 4]
assert candidate('.| .| .| .|') == [1, 1, 1, 1]
assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]
assert candidate('o| .| o| .| ... | 0 | split_lines | from typing import List
def parse_music(music_string: str) -> List[int]:
""" Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return list of integers corresponding to how many beats does each
not last.
Here is a legend:
... |
HumanEval/18 |
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
times = 0
for i ... | how_many_times | if string[i:i+len(substring)] == substring:
times += 1
return times
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('', 'x') == 0
assert candidate('xyxyxyx', 'x') == 4
assert candidate('cacacacac', 'cac') == 4
assert candidate('john doe', 'john') == 1
| 0 | split_lines |
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
times = 0
for i ... |
HumanEval/19 | from typing \
import List
def sort_numbers(numbers: str) -> str:
""" Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
... | sort_numbers | 'five': 5,
'six': 6,
'seven': 7,
'eight': 8,
'nine': 9
}
return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('three') == 'three'
assert candidate('three five nine') == 'three five nine'
assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'
assert ... | 0 | split_lines | from typing import List
def sort_numbers(numbers: str) -> str:
""" Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
>... |
HumanEval/20 | from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([... | find_closest_elements | closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return close... |
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
assert candidate([1.0, 2.0, 3.0, 4.0,... | 0 | split_lines | from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([... |
HumanEval/21 | from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, ... | rescale_to_unit | max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([2.0, 49.9]) == [0.0, 1.0]
assert candidate([100.0, 49.9]) == [1.0, 0.0]
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.... | 0 | split_lines | from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, ... |
HumanEval/22 | from typing \
import List, Any
def filter_integers(values: List[Any]) -> List[int]:
""" Filter given list of any python values only for integers
>>> filter_integers(['a', 3.14, 5])
[5]
>>> filter_integers([1, 2, 3, 'abc', {}, []])
[1, 2, 3]
"""
| filter_integers | return [x for x in values if isinstance(x, int)]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]
assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]
| 0 | split_lines | null |
HumanEval/23 |
def strlen(string: str) -> int:
""" Return length of given string
>>> strlen('')
0
>>> strlen('abc')
3
"""
| strlen | return len(string)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == 0
assert candidate('x') == 1
assert candidate('asdasnakj') == 9
| 0 | split_lines | null |
HumanEval/24 |
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
for i \
in reversed(range(n)):
| largest_divisor | if n % i == 0:
return i
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3) == 1
assert candidate(7) == 1
assert candidate(10) == 5
assert candidate(100) == 50
assert candidate(49) == 7
| 0 | split_lines |
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
for i in reversed(range(n)):
# print('@@this is the line to split##')
if n % i == 0:
return i
|
HumanEval/25 | from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the produc... | factorize | n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(2) == [2]
assert candidate(4) == [2, 2]
assert candidate(8) == [2, 2, 2]
assert candidate(3 * 19) == [3, 19]
assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]
assert candidate(3 * 19 * 3 * 19 * ... | 0 | split_lines | from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the produc... |
HumanEval/26 | from typing \
import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
import collections
| remove_duplicates | c = collections.Counter(numbers)
return [n for n in numbers if c[n] <= 1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
| 0 | split_lines | from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
import collections
# print(... |
HumanEval/27 |
def flip_case(string: str) -> str:
""" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
>>> flip_case('Hello')
'hELLO'
"""
| flip_case | return string.swapcase()
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('Hello!') == 'hELLO!'
assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
| 0 | split_lines | null |
HumanEval/28 | from typing \
import List
def concatenate(strings: List[str]) -> str:
""" Concatenate list of strings into a single string
>>> concatenate([])
''
>>> concatenate(['a', 'b', 'c'])
'abc'
"""
| concatenate | return ''.join(strings)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == ''
assert candidate(['x', 'y', 'z']) == 'xyz'
assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
| 0 | split_lines | null |
HumanEval/29 | from typing \
import List
def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
""" Filter an input list of strings only for ones that start with a given prefix.
>>> filter_by_prefix([], 'a')
[]
>>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
['abc', 'array']
"""
| filter_by_prefix | return [x for x in strings if x.startswith(prefix)]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
| 0 | split_lines | null |
HumanEval/30 |
def get_positive(l: list):
"""Return only positive numbers in the list.
>>> get_positive([-1, 2, -4, 5, 6])
[2, 5, 6]
>>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
[5, 3, 2, 3, 9, 123, 1]
"""
| get_positive | return [e for e in l if e > 0]
|
METADATA = {}
def check(candidate):
assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6]
assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1]
assert candidate([-1, -2]) == []
assert candidate([]) == []
| 0 | split_lines | null |
HumanEval/31 |
def is_prime(n):
"""Return true if a given number is prime, and false otherwise.
>>> is_prime(6)
False
>>> is_prime(101)
True
>>> is_prime(11)
True
>>> is_prime(13441)
True
>>> is_prime(61)
True
>>> is_prime(4)
False
>>> is_prime(1)
False
"""
if n < ... | is_prime | if n % k == 0:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate(6) == False
assert candidate(101) == True
assert candidate(11) == True
assert candidate(13441) == True
assert candidate(61) == True
assert candidate(4) == False
assert candidate(1) == False
assert candidate(5) == True
assert ca... | 0 | split_lines |
def is_prime(n):
"""Return true if a given number is prime, and false otherwise.
>>> is_prime(6)
False
>>> is_prime(101)
True
>>> is_prime(11)
True
>>> is_prime(13441)
True
>>> is_prime(61)
True
>>> is_prime(4)
False
>>> is_prime(1)
False
"""
if n < ... |
HumanEval/32 | import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) \
for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a poly... | find_zero | center = (begin + end) / 2.0
if poly(xs, center) * poly(xs, begin) > 0:
begin = center
else:
end = center
return begin
|
METADATA = {}
def check(candidate):
import math
import random
rng = random.Random(42)
import copy
for _ in range(100):
ncoeff = 2 * rng.randint(1, 4)
coeffs = []
for _ in range(ncoeff):
coeff = rng.randint(-10, 10)
if coeff == 0:
co... | 0 | split_lines | import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a polynomia... |
HumanEval/33 |
def sort_third(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
>>> sort_t... | sort_third | l[::3] = sorted(l[::3])
return l
|
METADATA = {}
def check(candidate):
assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))
assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))
assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(so... | 0 | split_lines |
def sort_third(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
>>> sort_t... |
HumanEval/34 |
def unique(l: list):
"""Return sorted unique elements in a list
>>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
[0, 2, 3, 5, 9, 123]
"""
| unique | return sorted(list(set(l)))
|
METADATA = {}
def check(candidate):
assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
| 0 | split_lines | null |
HumanEval/35 |
def max_element(l: list):
"""Return maximum element in the list.
>>> max_element([1, 2, 3])
3
>>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
123
"""
m = l[0]
for e \
in l:
| max_element | if e > m:
m = e
return m
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 3]) == 3
assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124
| 0 | split_lines |
def max_element(l: list):
"""Return maximum element in the list.
>>> max_element([1, 2, 3])
3
>>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
123
"""
m = l[0]
for e in l:
# print('@@this is the line to split##')
if e > m:
m = e
return m
|
HumanEval/36 |
def fizz_buzz(n: int):
"""Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
>>> fizz_buzz(50)
0
>>> fizz_buzz(78)
2
>>> fizz_buzz(79)
3
"""
ns = []
for i in range(n):
if i % 11 == 0 \
or i % 13 == 0:
n... | fizz_buzz | s = ''.join(list(map(str, ns)))
ans = 0
for c in s:
ans += (c == '7')
return ans
|
METADATA = {}
def check(candidate):
assert candidate(50) == 0
assert candidate(78) == 2
assert candidate(79) == 3
assert candidate(100) == 3
assert candidate(200) == 6
assert candidate(4000) == 192
assert candidate(10000) == 639
assert candidate(100000) == 8026
| 0 | split_lines |
def fizz_buzz(n: int):
"""Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
>>> fizz_buzz(50)
0
>>> fizz_buzz(78)
2
>>> fizz_buzz(79)
3
"""
ns = []
for i in range(n):
if i % 11 == 0 or i % 13 == 0:
ns.app... |
HumanEval/37 |
def sort_even(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[1, 2, 3]
>>> sort_even([5, 6, 3, 4])
... | sort_even | for e, o in zip(evens, odds):
ans.extend([e, o])
if len(evens) > len(odds):
ans.append(evens[-1])
return ans
|
METADATA = {}
def check(candidate):
assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3])
assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123])
assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 1... | 0 | split_lines |
def sort_even(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[1, 2, 3]
>>> sort_even([5, 6, 3, 4])
... |
HumanEval/38 |
def encode_cyclic(s: str):
"""
returns encoded string by cycling groups of three characters.
"""
# split string to groups. Each of length 3.
groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
# cycle elements in each group. Unless group has fewer elements than 3.
... | decode_cyclic | return encode_cyclic(encode_cyclic(s))
|
METADATA = {}
def check(candidate):
from random import randint, choice
import string
letters = string.ascii_lowercase
for _ in range(100):
str = ''.join(choice(letters) for i in range(randint(10, 20)))
encoded_str = encode_cyclic(str)
assert candidate(encoded_str) == str
| 0 | split_lines | null |
HumanEval/39 |
def prime_fib(n: int):
"""
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
>>> prime_fib(1)
2
>>> prime_fib(2)
3
>>> prime_fib(3)
5
>>> prime_fib(4)
13
>>> prime_fib(5)
89
"""
import math
def is_prime(p):
if p < 2:
... | prime_fib | return True
f = [0, 1]
while True:
f.append(f[-1] + f[-2])
if is_prime(f[-1]):
n -= 1
if n == 0:
return f[-1]
|
METADATA = {}
def check(candidate):
assert candidate(1) == 2
assert candidate(2) == 3
assert candidate(3) == 5
assert candidate(4) == 13
assert candidate(5) == 89
assert candidate(6) == 233
assert candidate(7) == 1597
assert candidate(8) == 28657
assert candidate(9) == 514229
... | 0 | split_lines |
def prime_fib(n: int):
"""
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
>>> prime_fib(1)
2
>>> prime_fib(2)
3
>>> prime_fib(3)
5
>>> prime_fib(4)
13
>>> prime_fib(5)
89
"""
import math
def is_prime(p):
if p < 2:
... |
HumanEval/40 |
def triples_sum_to_zero(l: list):
"""
triples_sum_to_zero takes a list of integers as an input.
it returns True if there are three distinct elements in the list that
sum to zero, and False otherwise.
>>> triples_sum_to_zero([1, 3, 5, 0])
False
>>> triples_sum_to_zero([1, 3, -2, 1])
Tr... | triples_sum_to_zero | if l[i] + l[j] + l[k] == 0:
return True
return False
|
METADATA = {}
def check(candidate):
assert candidate([1, 3, 5, 0]) == False
assert candidate([1, 3, 5, -1]) == False
assert candidate([1, 3, -2, 1]) == True
assert candidate([1, 2, 3, 7]) == False
assert candidate([1, 2, 5, 7]) == False
assert candidate([2, 4, -5, 3, 9, 7]) == True
asser... | 0 | split_lines |
def triples_sum_to_zero(l: list):
"""
triples_sum_to_zero takes a list of integers as an input.
it returns True if there are three distinct elements in the list that
sum to zero, and False otherwise.
>>> triples_sum_to_zero([1, 3, 5, 0])
False
>>> triples_sum_to_zero([1, 3, -2, 1])
Tr... |
HumanEval/41 |
def car_race_collision(n: int):
"""
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same s... | car_race_collision | return n**2
|
METADATA = {}
def check(candidate):
assert candidate(2) == 4
assert candidate(3) == 9
assert candidate(4) == 16
assert candidate(8) == 64
assert candidate(10) == 100
| 0 | split_lines | null |
HumanEval/42 |
def incr_list(l: list):
"""Return list with elements incremented by 1.
>>> incr_list([1, 2, 3])
[2, 3, 4]
>>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
[6, 4, 6, 3, 4, 4, 10, 1, 124]
"""
| incr_list | return [(e + 1) for e in l]
|
METADATA = {}
def check(candidate):
assert candidate([]) == []
assert candidate([3, 2, 1]) == [4, 3, 2]
assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]
| 0 | split_lines | null |
HumanEval/43 |
def pairs_sum_to_zero(l):
"""
pairs_sum_to_zero takes a list of integers as an input.
it returns True if there are two distinct elements in the list that
sum to zero, and False otherwise.
>>> pairs_sum_to_zero([1, 3, 5, 0])
False
>>> pairs_sum_to_zero([1, 3, -2, 1])
False
>>> pairs... | pairs_sum_to_zero | if l1 + l[j] == 0:
return True
return False
|
METADATA = {}
def check(candidate):
assert candidate([1, 3, 5, 0]) == False
assert candidate([1, 3, -2, 1]) == False
assert candidate([1, 2, 3, 7]) == False
assert candidate([2, 4, -5, 3, 5, 7]) == True
assert candidate([1]) == False
assert candidate([-3, 9, -1, 3, 2, 30]) == True
asser... | 0 | split_lines |
def pairs_sum_to_zero(l):
"""
pairs_sum_to_zero takes a list of integers as an input.
it returns True if there are two distinct elements in the list that
sum to zero, and False otherwise.
>>> pairs_sum_to_zero([1, 3, 5, 0])
False
>>> pairs_sum_to_zero([1, 3, -2, 1])
False
>>> pairs... |
HumanEval/44 |
def change_base(x: int, base: int):
"""Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
>>> change_base(8, 3)
'22'
>>> change_base(8, 2)
'1000'
>>> change_base(7, 2)
'111'
"""
ret = ""
whi... | change_base | ret = str(x % base) + ret
x //= base
return ret
|
METADATA = {}
def check(candidate):
assert candidate(8, 3) == "22"
assert candidate(9, 3) == "100"
assert candidate(234, 2) == "11101010"
assert candidate(16, 2) == "10000"
assert candidate(8, 2) == "1000"
assert candidate(7, 2) == "111"
for x in range(2, 8):
assert candidate(x, ... | 0 | split_lines |
def change_base(x: int, base: int):
"""Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
>>> change_base(8, 3)
'22'
>>> change_base(8, 2)
'1000'
>>> change_base(7, 2)
'111'
"""
ret = ""
whi... |
HumanEval/45 |
def triangle_area(a, h):
"""Given length of a side and high return area for a triangle.
>>> triangle_area(5, 3)
7.5
"""
| triangle_area | return a * h / 2.0
|
METADATA = {}
def check(candidate):
assert candidate(5, 3) == 7.5
assert candidate(2, 2) == 2.0
assert candidate(10, 8) == 40.0
| 0 | split_lines | null |
HumanEval/46 |
def fib4(n: int):
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th el... | fib4 | for _ in range(4, n + 1):
results.append(results[-1] + results[-2] + results[-3] + results[-4])
results.pop(0)
return results[-1]
|
METADATA = {}
def check(candidate):
assert candidate(5) == 4
assert candidate(8) == 28
assert candidate(10) == 104
assert candidate(12) == 386
| 0 | split_lines |
def fib4(n: int):
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th el... |
HumanEval/47 |
def median(l: list):
"""Return median of elements in the list l.
>>> median([3, 1, 2, 4, 5])
3
>>> median([-10, 4, 6, 1000, 10, 20])
15.0
"""
l = sorted(l)
if len(l) % \
2 == 1:
| median | return l[len(l) // 2]
else:
return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0
|
METADATA = {}
def check(candidate):
assert candidate([3, 1, 2, 4, 5]) == 3
assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0
assert candidate([5]) == 5
assert candidate([6, 5]) == 5.5
assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7
| 0 | split_lines |
def median(l: list):
"""Return median of elements in the list l.
>>> median([3, 1, 2, 4, 5])
3
>>> median([-10, 4, 6, 1000, 10, 20])
15.0
"""
l = sorted(l)
if len(l) % 2 == 1:
# print('@@this is the line to split##')
return l[len(l) // 2]
else:
return (l[len... |
HumanEval/48 |
def is_palindrome(text: str):
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
for i in range(len(text)):
if text[i] != text[len(text) \
- 1... | is_palindrome | return False
return True
|
METADATA = {}
def check(candidate):
assert candidate('') == True
assert candidate('aba') == True
assert candidate('aaaaa') == True
assert candidate('zbcd') == False
assert candidate('xywyx') == True
assert candidate('xywyz') == False
assert candidate('xywzx') == False
| 0 | split_lines |
def is_palindrome(text: str):
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
for i in range(len(text)):
if text[i] != text[len(text) - 1 - i]... |
HumanEval/49 |
def modp(n: int, p: int):
"""Return 2^n modulo p (be aware of numerics).
>>> modp(3, 5)
3
>>> modp(1101, 101)
2
>>> modp(0, 101)
1
>>> modp(3, 11)
8
>>> modp(100, 101)
1
"""
ret = 1
for i \
in range(n):
| modp | ret = (2 * ret) % p
return ret
|
METADATA = {}
def check(candidate):
assert candidate(3, 5) == 3
assert candidate(1101, 101) == 2
assert candidate(0, 101) == 1
assert candidate(3, 11) == 8
assert candidate(100, 101) == 1
assert candidate(30, 5) == 4
assert candidate(31, 5) == 3
| 0 | split_lines |
def modp(n: int, p: int):
"""Return 2^n modulo p (be aware of numerics).
>>> modp(3, 5)
3
>>> modp(1101, 101)
2
>>> modp(0, 101)
1
>>> modp(3, 11)
8
>>> modp(100, 101)
1
"""
ret = 1
for i in range(n):
# print('@@this is the line to split##')
ret ... |
HumanEval/50 |
def encode_shift(s: str):
"""
returns encoded string by shifting every character by 5 in the alphabet.
"""
return ""join([chr(((ord(ch) + 5 - ord(26)) % \
26) + ord( s]) for ch in s])
def decode_shift(s: str):
"""
takes as input string encoded with encode_shift function. Returns decoded s... | decode_shift | return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])
|
METADATA = {}
def check(candidate):
from random import randint, choice
import copy
import string
letters = string.ascii_lowercase
for _ in range(100):
str = ''.join(choice(letters) for i in range(randint(10, 20)))
encoded_str = encode_shift(str)
assert candidate(copy.dee... | 0 | split_lines | null |
HumanEval/51 |
def remove_vowels(text):
"""
remove_vowels is a function that takes string and returns string without vowels.
>>> remove_vowels('')
''
>>> remove_vowels("abcdef\nghijklm")
'bcdf\nghjklm'
>>> remove_vowels('abcdef')
'bcdf'
>>> remove_vowels('aaaaa')
''
>>> remove_vowels('aaB... | remove_vowels | return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])
|
METADATA = {}
def check(candidate):
assert candidate('') == ''
assert candidate("abcdef\nghijklm") == 'bcdf\nghjklm'
assert candidate('fedcba') == 'fdcb'
assert candidate('eeeee') == ''
assert candidate('acBAA') == 'cB'
assert candidate('EcBOO') == 'cB'
assert candidate('ybcd') == 'ybcd'... | 0 | split_lines | null |
HumanEval/52 |
def below_threshold(l: list, t: int):
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
for e \
in l:
if e >= t:
| below_threshold | return False
return True
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 4, 10], 100)
assert not candidate([1, 20, 4, 10], 5)
assert candidate([1, 20, 4, 10], 21)
assert candidate([1, 20, 4, 10], 22)
assert candidate([1, 8, 4, 10], 11)
assert not candidate([1, 8, 4, 10], 10)
| 0 | split_lines |
def below_threshold(l: list, t: int):
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
for e in l:
if e >= t:
# print('@@this is the line to split##')
... |
HumanEval/53 |
def add(x: int, y: int):
"""Add two numbers x and y
>>> add(2, 3)
5
>>> add(5, 7)
12
"""
| add | return x + y
|
METADATA = {}
def check(candidate):
import random
assert candidate(0, 1) == 1
assert candidate(1, 0) == 1
assert candidate(2, 3) == 5
assert candidate(5, 7) == 12
assert candidate(7, 5) == 12
for i in range(100):
x, y = random.randint(0, 1000), random.randint(0, 1000)
a... | 0 | split_lines | null |
HumanEval/54 |
def same_chars(s0: str, s1: str):
"""
Check if two words have the same characters.
>>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')
True
>>> same_chars('abcd', 'dddddddabc')
True
>>> same_chars('dddddddabc', 'abcd')
True
>>> same_chars('eabcd', 'dddddddabc')
False
>>> same... | same_chars | return set(s0) == set(s1)
|
METADATA = {}
def check(candidate):
assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True
assert candidate('abcd', 'dddddddabc') == True
assert candidate('dddddddabc', 'abcd') == True
assert candidate('eabcd', 'dddddddabc') == False
assert candidate('abcd', 'dddddddabcf') == False
asse... | 0 | split_lines | null |
HumanEval/55 |
def fib(n: int):
"""Return n-th Fibonacci number.
>>> fib(10)
55
>>> fib(1)
1
>>> fib(8)
21
"""
if n \
== 0:
return 0
| fib | if n == 1:
return 1
return fib(n - 1) + fib(n - 2)
|
METADATA = {}
def check(candidate):
assert candidate(10) == 55
assert candidate(1) == 1
assert candidate(8) == 21
assert candidate(11) == 89
assert candidate(12) == 144
| 0 | split_lines |
def fib(n: int):
"""Return n-th Fibonacci number.
>>> fib(10)
55
>>> fib(1)
1
>>> fib(8)
21
"""
if n == 0:
return 0
# print('@@this is the line to split##')
if n == 1:
return 1
return fib(n - 1) + fib(n - 2)
|
HumanEval/56 |
def correct_bracketing(brackets: str):
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("<")
False
>>> correct_bracketing("<>")
True
>>> correct_bracketing("<<><>>")
True
>>> correct_bracketin... | correct_bracketing | else:
depth -= 1
if depth < 0:
return False
return depth == 0
|
METADATA = {}
def check(candidate):
assert candidate("<>")
assert candidate("<<><>>")
assert candidate("<><><<><>><>")
assert candidate("<><><<<><><>><>><<><><<>>>")
assert not candidate("<<<><>>>>")
assert not candidate("><<>")
assert not candidate("<")
assert not candidate("<<<<")
... | 0 | split_lines |
def correct_bracketing(brackets: str):
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("<")
False
>>> correct_bracketing("<>")
True
>>> correct_bracketing("<<><>>")
True
>>> correct_bracketin... |
HumanEval/57 |
def monotonic(l: list):
"""Return True is list elements are monotonically increasing or decreasing.
>>> monotonic([1, 2, 4, 20])
True
>>> monotonic([1, 20, 4, 10])
False
>>> monotonic([4, 1, 0, -10])
True
"""
if l == sorted(l) \
or l == sorted(l, reverse=True):
| monotonic | return True
return False
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 4, 10]) == True
assert candidate([1, 2, 4, 20]) == True
assert candidate([1, 20, 4, 10]) == False
assert candidate([4, 1, 0, -10]) == True
assert candidate([4, 1, 1, 0]) == True
assert candidate([1, 2, 3, 2, 5, 60]) == False
ass... | 0 | split_lines |
def monotonic(l: list):
"""Return True is list elements are monotonically increasing or decreasing.
>>> monotonic([1, 2, 4, 20])
True
>>> monotonic([1, 20, 4, 10])
False
>>> monotonic([4, 1, 0, -10])
True
"""
if l == sorted(l) or l == sorted(l, reverse=True):
# print('@@thi... |
HumanEval/58 |
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
ret = set()
for e1 \
in l1:
for e2 in l2:
| common | if e1 == e2:
ret.add(e1)
return sorted(list(ret))
|
METADATA = {}
def check(candidate):
assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3]
assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4]
assert candidate([4, 3, 2, 8], []) == []
| 0 | split_lines |
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
ret = set()
for e1 in l1:
for e2 in l2:
# print('@@this is... |
HumanEval/59 |
def largest_prime_factor(n: int):
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
def is_prime(k):
if k < 2:
return False
for i in \
range(2, k - 1):
... | largest_prime_factor | return True
largest = 1
for j in range(2, n + 1):
if n % j == 0 and is_prime(j):
largest = max(largest, j)
return largest
|
METADATA = {}
def check(candidate):
assert candidate(15) == 5
assert candidate(27) == 3
assert candidate(63) == 7
assert candidate(330) == 11
assert candidate(13195) == 29
| 0 | split_lines |
def largest_prime_factor(n: int):
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
def is_prime(k):
if k < 2:
return False
for i in range(2, k - 1):
if k... |
HumanEval/60 |
def sum_to_n(n: int):
"""sum_to_n is a function that sums numbers from 1 to n.
>>> sum_to_n(30)
465
>>> sum_to_n(100)
5050
>>> sum_to_n(5)
15
>>> sum_to_n(10)
55
>>> sum_to_n(1)
1
"""
| sum_to_n | return sum(range(n + 1))
|
METADATA = {}
def check(candidate):
assert candidate(1) == 1
assert candidate(6) == 21
assert candidate(11) == 66
assert candidate(30) == 465
assert candidate(100) == 5050
| 0 | split_lines | null |
HumanEval/61 |
def correct_bracketing(brackets: str):
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("(")
False
>>> correct_bracketing("()")
True
>>> correct_bracketing("(()())")
True
>>> correct_bracketin... | correct_bracketing | else:
depth -= 1
if depth < 0:
return False
return depth == 0
|
METADATA = {}
def check(candidate):
assert candidate("()")
assert candidate("(()())")
assert candidate("()()(()())()")
assert candidate("()()((()()())())(()()(()))")
assert not candidate("((()())))")
assert not candidate(")(()")
assert not candidate("(")
assert not candidate("((((")
... | 0 | split_lines |
def correct_bracketing(brackets: str):
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("(")
False
>>> correct_bracketing("()")
True
>>> correct_bracketing("(()())")
True
>>> correct_bracketin... |
HumanEval/62 |
def derivative(xs: list):
""" xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
>>> derivative([3, 1, 2, 4, 5])
[1, 4, 12, 20]
>>> derivative([1, 2, 3])
[2, 6]
"""
| derivative | return [(i * x) for i, x in enumerate(xs)][1:]
|
METADATA = {}
def check(candidate):
assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]
assert candidate([1, 2, 3]) == [2, 6]
assert candidate([3, 2, 1]) == [2, 2]
assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]
assert candidate([1]) == []
| 0 | split_lines | null |
HumanEval/63 |
def fibfib(n: int):
"""The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of th... | fibfib | return 0
if n == 2:
return 1
return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
|
METADATA = {}
def check(candidate):
assert candidate(2) == 1
assert candidate(1) == 0
assert candidate(5) == 4
assert candidate(8) == 24
assert candidate(10) == 81
assert candidate(12) == 274
assert candidate(14) == 927
| 0 | split_lines |
def fibfib(n: int):
"""The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of th... |
HumanEval/64 |
FIX = """
Add more test cases.
"""
def vowels_count(s):
"""Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the g... | vowels_count | if s[-1] == 'y' or s[-1] == 'Y':
n_vowels += 1
return n_vowels
| def check(candidate):
# Check some simple cases
assert candidate("abcde") == 2, "Test 1"
assert candidate("Alone") == 3, "Test 2"
assert candidate("key") == 2, "Test 3"
assert candidate("bye") == 1, "Test 4"
assert candidate("keY") == 2, "Test 5"
assert candidate("bYe") == 1, "Test 6"
a... | 0 | split_lines |
FIX = """
Add more test cases.
"""
def vowels_count(s):
"""Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the g... |
HumanEval/65 |
def circular_shift(x, shift):
"""Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
>>> circular_shift(12, 1)
"21"
>>> circular_shift(12, 2)
"12"
"""
s = str(x)
if sh... | circular_shift | return s[::-1]
else:
return s[len(s) - shift:] + s[:len(s) - shift]
| def check(candidate):
# Check some simple cases
assert candidate(100, 2) == "001"
assert candidate(12, 2) == "12"
assert candidate(97, 8) == "79"
assert candidate(12, 1) == "21", "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by han... | 0 | split_lines |
def circular_shift(x, shift):
"""Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
>>> circular_shift(12, 1)
"21"
>>> circular_shift(12, 2)
"12"
"""
s = str(x)
if sh... |
HumanEval/66 |
def digitSum(s):
"""Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum("") => 0
digitSum("abAB") => 131
digitSum("abcCd") => 67
digitSum("helloE") => 69
digitSum("woArBld") => 131
... | digitSum | return sum(ord(char) if char.isupper() else 0 for char in s)
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate("") == 0, "Error"
assert candidate("abAB") == 131, "Error"
assert candidate("abcCd") == 67, "Error"
assert candidate("helloE") == 69, "Error"
assert candi... | 0 | split_lines |
def digitSum(s):
"""Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum("") => 0
digitSum("abAB") => 131
digitSum("abcCd") => 67
digitSum("helloE") => 69
digitSum("woArBld") => 131
... |
HumanEval/67 |
def fruit_distribution(s,n):
"""
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples a... | fruit_distribution | if i.isdigit():
lis.append(int(i))
return n - sum(lis)
| def check(candidate):
# Check some simple cases
assert candidate("5 apples and 6 oranges",19) == 8
assert candidate("5 apples and 6 oranges",21) == 10
assert candidate("0 apples and 1 oranges",3) == 2
assert candidate("1 apples and 0 oranges",3) == 2
assert candidate("2 apples and 3 oranges",10... | 0 | split_lines |
def fruit_distribution(s,n):
"""
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples a... |
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