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movie_3
How many customers are active?
active refers to active = 1
SELECT COUNT(customer_id) FROM customer WHERE active = 1
movie_3
Among all the customers of store no.1, how many of them are active?
active refers to active = 1
SELECT COUNT(customer_id) FROM customer WHERE active = 1 AND store_id = 1
movie_3
What is the address of Mary Smith?
SELECT T1.address FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'
movie_3
Among all the active customers, how many of them live in Arlington?
active refers to active = 1; Arlington refers to city = 'Arlington'
SELECT COUNT(T2.customer_id) FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T1.city_id = T3.city_id WHERE T2.active = 1 AND T3.city = 'Arlington'
movie_3
Please list the full names of all the customers who live in Italy.
full name refers to first_name, last_name; Italy refers to country = 'Italy'
SELECT T4.first_name, T4.last_name FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id WHERE T3.country = 'Italy'
movie_3
Which country does Mary Smith live in?
SELECT T3.country FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id WHERE T4.first_name = 'MARY' AND T4.last_name = 'SMITH'
movie_3
What is the biggest amount of payment for a rental made by Mary Smith?
the biggest amount refers to max(amount)
SELECT T1.amount FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' ORDER BY T1.amount DESC LIMIT 1
movie_3
How many times has Mary Smith rented a film?
SELECT COUNT(T1.customer_id) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'
movie_3
What is the total amount of money Mary Smith has spent on film rentals?
the total amount = sum(amount)
SELECT SUM(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'
movie_3
Please give the full name of the customer who had made the biggest amount of payment in one single film rental.
full name refers to first_name, last_name; the biggest amount refers to max(amount)
SELECT T2.first_name, T2.last_name FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id ORDER BY T1.amount DESC LIMIT 1
movie_3
How much in total had the customers in Italy spent on film rentals?
total = sum(amount); Italy refers to country = 'Italy'
SELECT SUM(T5.amount) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id INNER JOIN payment AS T5 ON T4.customer_id = T5.customer_id WHERE T3.country = 'Italy'
movie_3
Among the payments made by Mary Smith, how many of them are over 4.99?
over 4.99 refers to amount > 4.99
SELECT COUNT(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' AND T1.amount > 4.99
movie_3
What is the average amount of money spent by a customer in Italy on a single film rental?
Italy refers to country = 'Italy'; average amount = divide(sum(amount), count(customer_id)) where country = 'Italy'
SELECT AVG(T5.amount) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id INNER JOIN payment AS T5 ON T4.customer_id = T5.customer_id WHERE T3.country = 'Italy'