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MultiLineInfilling/HumanEval/132/L1_L3
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i...
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[':
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L4
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L5
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L6
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L7
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse()
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_i...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_i...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_i...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_i...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L1_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_i...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L2
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: ...
for i in range(len(string)):
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L3
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i...
for i in range(len(string)): if string[i] == '[':
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L4
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L5
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L6
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L7
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse()
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L2_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L3
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i...
if string[i] == '[':
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L4
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L5
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L6
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L7
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse()
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L3_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L4
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L5
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L6
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L7
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse()
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L4_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L5
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
else:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L6
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
else: closing_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L7
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse()
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L5_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L6
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.append(i)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L7
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse()
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L6_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L7
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.reverse()
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.reverse() cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.reverse() cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L7_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L8
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
cnt = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
cnt = 0 i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
cnt = 0 i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L8_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L9_L9
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
i = 0
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L9_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
i = 0 l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L9_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L9_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L9_L13
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i += 1 return cnt >= 2
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L9_L14
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
return cnt >= 2
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L9_L15
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L10_L10
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
l = len(closing_bracket_index)
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L10_L11
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
l = len(closing_bracket_index) for idx in opening_bracket_index:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
MultiLineInfilling/HumanEval/132/L10_L12
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
cnt += 1 i += 1 return cnt >= 2
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...