problem_id
stringlengths
6
6
user_id
stringlengths
10
10
time_limit
float64
1k
8k
memory_limit
float64
262k
1.05M
problem_description
stringlengths
48
1.55k
codes
stringlengths
35
98.9k
status
stringlengths
28
1.7k
submission_ids
stringlengths
28
1.41k
memories
stringlengths
13
808
cpu_times
stringlengths
11
610
code_sizes
stringlengths
7
505
p02970
u693933222
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
[' n,b = map(int,input().split())\n \n print(n //(b*2))\n \n ', 'n,b = map(int,input().split())\n \nprint(n //(b*2))\n \n ', 'n,b = map(int,input().split())\n \nprint(-(-n//(b*2 +1)))\n \n ']
['Runtime Error', 'Wrong Answer', 'Accepted']
['s668066959', 's889473509', 's554796214']
[2940.0, 2940.0, 3060.0]
[17.0, 17.0, 19.0]
[55, 53, 59]
p02970
u693953100
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = map(int,input().split())\nans = n/(2*d)\nif n%(2*d):\n ans+=1\nprint(ans)', 'n,d = map(int,input().split())\nans = n//(2*d+1)\nif n%(2*d+1):\n ans+=1\nprint(ans)\n']
['Wrong Answer', 'Accepted']
['s327122024', 's194365858']
[2940.0, 2940.0]
[17.0, 18.0]
[78, 84]
p02970
u695474809
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D=map(int,input().split())\nprint(math.ceil(N/(2*D+1)))\n', 'import math\nN,D=map(int,input().split())\nprint(math.ceil(N/(2*D+1)))\n']
['Runtime Error', 'Accepted']
['s651909418', 's347995161']
[8996.0, 8992.0]
[23.0, 29.0]
[57, 69]
p02970
u696486967
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d=int(input().split())\ncnt=1\nwhile True:\n if (2*d+1)*cnt>=n:\n print(cnt)\n break\n \n cnt+=1\n \n ', 'n, d=input().split()\nni=int(n)\ndi=int(d)\ncnt=1\nwhile True:\n if (2*di+1)*cnt>=ni:\n print(cnt)\n break\n \n cnt+=1\n \n ']
['Runtime Error', 'Accepted']
['s861780170', 's773541107']
[2940.0, 2940.0]
[17.0, 17.0]
[107, 124]
p02970
u696919316
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nn, k = list(map(int, input().split()))\nprint(math.ceil(n // (2 * k)))', 'import math\nn, k = list(map(int, input().split()))\nprint(math.ceil(n / (2 * k + 1)))']
['Wrong Answer', 'Accepted']
['s158644497', 's201977858']
[9132.0, 9152.0]
[30.0, 28.0]
[81, 84]
p02970
u697696097
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d=map(int,inpit().split())\nx=2*d+1\nprint((d+x-1)//x)', 'n,d=map(int,input().split())\nx=2*d+1\nprint((n+x-1)//x)']
['Runtime Error', 'Accepted']
['s461477097', 's517901912']
[9008.0, 9124.0]
[27.0, 25.0]
[54, 54]
p02970
u698416089
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = list(map(int,input().split()))\nmireru = 2*d+1\nprint(mireru)\nprint(int((n-(n%mireru))/mireru+int(n%mireru != 0)))', 'n,d = list(map(int,input().split()))\nmireru = 2*d+1\nprint(int((n-(n%mireru))/mireru+int(n%mireru != 0)))']
['Wrong Answer', 'Accepted']
['s373547643', 's231241147']
[2940.0, 2940.0]
[17.0, 18.0]
[118, 104]
p02970
u698919163
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = list(map(int,input().split()))\nhuman = 1\nkanshi = 2*D+1\nhaniwhile hani < N:\n hani = hani + kanshi\n human +=1\n \nprint(human) = kanshi\n', 'N,D = list(map(int,input().split()))\nhuman = 1\nhani = 2*D+1\nhaniwhile hani < N:\n hani = hani + (2*D+1)\n human +=1\n \nprint(human) = kanshi\n', ...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Wrong Answer', 'Accepted']
['s358724839', 's508843169', 's885985100', 's931679815', 's966305541']
[2940.0, 2940.0, 2940.0, 3060.0, 2940.0]
[18.0, 17.0, 17.0, 17.0, 17.0]
[148, 147, 143, 137, 133]
p02970
u699101754
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['a,b=map(int,input().split())\nprint(a//(2*b+1))', 'a,b=map(int,input().split())\nx=a//(2*b+1)\nif a%(2*b+1)!=0:\n x=x+1\nprint(x) ']
['Wrong Answer', 'Accepted']
['s326552900', 's691812172']
[2940.0, 2940.0]
[17.0, 18.0]
[46, 77]
p02970
u703890795
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\nprint(N//(2*D+1.001) + 1)', 'N, D = map(int, input().split())\nprint(N//(2*D+1))', 'N, D = map(int, input().split())\nprint(int(N//(2*D+1.001) + 1))']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s067062166', 's079998502', 's378298911']
[2940.0, 2940.0, 2940.0]
[17.0, 18.0, 18.0]
[58, 50, 63]
p02970
u712868001
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\nB=2*D\nA=N//2B+1\nprint(A)', 'N, D = map(int, input().split())\nA=N//2D+1\nprint(A)', 'N, D = map(int, input().split())\nB=2*D+1\nif N % B == 0:\n A=N//B\nelse:\n A=N//B+1\nprint(A)']
['Runtime Error', 'Runtime Error', 'Accepted']
['s389381260', 's761056221', 's132837168']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[57, 51, 90]
p02970
u718411265
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D=list(map(int,input().split()))\nprint(N//(1+2D))', 'N,D=list(map(int,input().split()))\nprint(N//(1+2*D))', 'N,D=list(map(int,input().split()))\nprint(N//(1+2D))', 'N,D=list(map(int,input().split()))\nif N%(1+2*D)==0:\n print(N//(1+2*D))\nelse:\n print(N//(1+2*D)+1)']
['Runtime Error', 'Wrong Answer', 'Runtime Error', 'Accepted']
['s412102924', 's681378887', 's689889030', 's020906835']
[2940.0, 2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0, 17.0]
[51, 52, 51, 99]
p02970
u719886494
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n = int(input())\nd = int(input())\ni = (d * 2) + 1\nif n % i == 0 :\n print(n / i)\nelse :\n print((n // i) + 1)\n', 'n = int(input())\nd = int(input())\ni = (d * 2) + 1\nif n % i == 0 :\n print(n // i)\nelse :\n print((n // i) + 1)\n', 'n = int(input())\nd = int(input())\ni = (d * 2) + 1\nif n % i == 0 :\n pri...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s012965709', 's834511473', 's836642582', 's429241679']
[2940.0, 2940.0, 2940.0, 3064.0]
[18.0, 17.0, 19.0, 17.0]
[110, 111, 107, 110]
p02970
u720065198
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN, D=map(int,input().split())\nprint(math.ceil(N//((D*2)+1)))', 'import math\nN, D=map(int,input().split())\nprint(math.ceil(N/((D*2)+1)))']
['Wrong Answer', 'Accepted']
['s790287103', 's021940345']
[3064.0, 2940.0]
[18.0, 17.0]
[72, 71]
p02970
u722811088
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['# coding: utf-8\n# Your code here!\n\nN,D = map(int,input().split(" "))\n\n\npreans = N/(2*D + 1)\n\nprint(preans)\n\nif preans == N//(2*D + 1) :\n print(preans)\n \nelse:\n print(preans+1)', 'N,D = map(int,input().split(" "))\n\nans = N//D + 1', '# coding: utf-8\n# Your code here!\n\nN,D = map(int,input().s...
['Wrong Answer', 'Wrong Answer', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s136323442', 's155822791', 's856319700', 's912762697', 's990340322']
[2940.0, 2940.0, 2940.0, 3060.0, 2940.0]
[17.0, 20.0, 17.0, 17.0, 18.0]
[184, 49, 185, 159, 160]
p02970
u729119068
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\na,b=map(int,input().split())\nprint(math.ceil(a/(2b+1)))\n', 'import math\na,b=map(int,input().split())\nprint(math.ceil(a/(b*2+1)))']
['Runtime Error', 'Accepted']
['s735836863', 's201598279']
[8804.0, 9152.0]
[26.0, 27.0]
[68, 68]
p02970
u729133443
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d=map(int,input().split());print(0--n//d-~d)', 'n,d=map(int,input().split());print(0--n//(d-~d))']
['Wrong Answer', 'Accepted']
['s636633873', 's789451981']
[2940.0, 2940.0]
[18.0, 17.0]
[46, 48]
p02970
u729300713
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\nif n%(2*d+1) == 0:\n print(n/(2*d+1))\nelse:\n print((n/(2*d+1)+1)', 'n, d = map(int, input().split())\nif n%(2*d+1) == 0:\n print(int(n/(2*d+1)))\nelse:\n print(int((n/(2*d+1)))+1)\n']
['Runtime Error', 'Accepted']
['s237128434', 's069106789']
[2940.0, 2940.0]
[17.0, 17.0]
[98, 110]
p02970
u730710086
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['# -*- coding: <encoding name> -*-\n\nimport math\nn, d = map(int, input())\nrange = d * 2 + 1\nprint(math.ceil(n / range))', '# -*- coding: <encoding name> -*-\n\nimport math\nn, d = map(int, input().split())\nrange = d * 2 + 1\nprint(math.ceil(n / range))']
['Runtime Error', 'Accepted']
['s394697580', 's003641876']
[2940.0, 2940.0]
[18.0, 17.0]
[117, 125]
p02970
u730751996
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D=map(int,input().split())\nprint(N)\nprint(D)\nimport math\nprint(N/(1+2*D))\nmath.ceil(N/(1+2*D))', 'N,D=map(int,input().split())\nprint(N)\nprint(D)\nimport math\nprint(N/(1+2*D))\nmath.ceil(N/(1+2*D)', 'N,D=map(int,input().split())\n\nimport math\n\nprint(math.ceil(N/(1+2*D)))']
['Wrong Answer', 'Runtime Error', 'Accepted']
['s104283012', 's248149957', 's817598450']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[96, 95, 70]
p02970
u733814820
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\n\nfor i in range(N):\n if N - (2*D + 1)*i <= 0:\n print(i)\n break\n\nprint(N)\n', 'import sys\n\nN, D = map(int, input().split())\n\nfor i in range(N):\n if N - (2*D + 1)*i <= 0:\n print(i)\n sys.exit(0)\n\nprint(N)\n']
['Wrong Answer', 'Accepted']
['s834825059', 's991264556']
[2940.0, 2940.0]
[17.0, 17.0]
[123, 141]
p02970
u736524428
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int,input())\n\nwatch = D * 2 + 1\n\nans = ( N + watch - 1 ) // watch\n\nprint(ans)', 'N, D = map(int,input().split())\n \nwatch = D * 2 + 1\n \nans = ( N + watch - 1 ) // watch\n \nprint(ans)']
['Runtime Error', 'Accepted']
['s181039265', 's963510103']
[2940.0, 2940.0]
[18.0, 17.0]
[88, 99]
p02970
u739959951
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nn,d=map(int,input().split())\nprint(math.ceil(n/(2*d+1))', 'n,d=map(int,input().split())\nprint(math.ceil(n/(2*d+1))', 'import math\n\nn,d=map(int,input().split())\nprint(math.ceil(n/(2*d+1)))']
['Runtime Error', 'Runtime Error', 'Accepted']
['s146175699', 's236601758', 's583671406']
[2940.0, 2940.0, 2940.0]
[17.0, 19.0, 17.0]
[67, 55, 69]
p02970
u740767776
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int,input().split())\nprint(int((n+(2*d))/d))', 'n, d = map(int,input().split())\ncov = 2 * d\nprint(int((n+cov)/(cov+1)))']
['Wrong Answer', 'Accepted']
['s400192609', 's515544894']
[2940.0, 2940.0]
[20.0, 17.0]
[55, 71]
p02970
u746849814
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\nd = []\ni = 1\nwhile len(d) <= N:\n d += [i]*(D*2+1)\n i += 1\nlen(set(d))', 'N, D = map(int, input().split())\nd = []\ni = 1\nwhile len(d) <= N:\n d += [i]*(D*2+1)\n i += 1\nprint(len(set(d[:N])))']
['Wrong Answer', 'Accepted']
['s340862822', 's364564299']
[2940.0, 2940.0]
[17.0, 17.0]
[108, 119]
p02970
u747309718
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = map(int, input().split())\n\nans=(n/(d*2))\nansint =int(n/(d*2))\n\nif(ansint - ans >= 0.5):\n ansint = ansint + 1\n\nprint(ansint)', 'n,d = map(int, input().split())\n\nhani = d*2 + 1\n\nans = int(n/hani)\n\nprint(ans)', 'n,d = map(int, input().split())\n\nprint(int(n/(d*2)))', 'n,d = map(int, input().split()...
['Wrong Answer', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s114372301', 's427465223', 's971537846', 's627641701']
[2940.0, 2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0, 17.0]
[130, 78, 52, 114]
p02970
u748311048
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['#int(input())\n#map(int, input().split())\nN,D=map(int, input().split())\nprint(N//(D*2))', 'N,D=map(int, input().split())\nprint(N//(D*2)+1 if N%D!=0 else N//(D*2))', '#int(input())\n#map(int, input().split())\nN,D=map(int, input().split())\nif N<=D*2:\n print(1)\nelif N%(D*2)==0:\n print(N//(D*2)-1)\nelse:\n pri...
['Wrong Answer', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s583370188', 's674255357', 's976296648', 's622071276']
[3060.0, 2940.0, 2940.0, 2940.0]
[20.0, 17.0, 17.0, 17.0]
[86, 71, 153, 159]
p02970
u749770850
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\n\nprint((n + d * 2) / (d * 2 + 1))', 'N, D = map(int,input().split())\n \nnum = D*2 + 1\nif N % num == 0:\n print(int(N / num))\nelse:\n print(N // num + 1)']
['Wrong Answer', 'Accepted']
['s794065950', 's067420439']
[2940.0, 2940.0]
[23.0, 17.0]
[66, 118]
p02970
u757030836
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = map(int,input().split())\n\ncan = ((2*D)+1)\n\nans = 0\n\nwhile N >= can:\n ans += 1\n N -= can\n \n \nprint(ans)\n\n\n', 'N,D = map(int,input().split())\n\ncan = ((2*N)+1)\n\nans = 0\n\nwhile N > can:\n ans += 1\n N -= can\n \n \nprint(ans)\n', 'N,D = map(int,input().split())\nprint(((N//(2*D+1))+1) if...
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s576710140', 's692094006', 's689939110']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[115, 112, 93]
p02970
u757274384
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = map(int, input().split())\nk = n%(2*d + 1)\nif k == 0:\n print(n//(2*d+1))\nelse:\n print(n//(2*d+1))', 'import math\nn,d = map(int, input().split())\nprint(math.ceil(n/(2*d+1)))']
['Wrong Answer', 'Accepted']
['s066070731', 's816142004']
[2940.0, 2940.0]
[17.0, 17.0]
[104, 71]
p02970
u760794812
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = map(int,input().split())\nAnswer = (N-1)//(2D+1)+1\nprint(Answer)', 'n, d = map(int, input().split())\nAnswer = n//(2*d+1)\nif n%(2*d+1) != 0:\n Answer +=1\n \nprint(Answer)']
['Runtime Error', 'Accepted']
['s157461350', 's258582260']
[2940.0, 2940.0]
[17.0, 17.0]
[69, 101]
p02970
u766393261
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D=map(int,input().split())\nprint((N+D*2)/(D*2+1))\n', 'N,D=map(int,input().split())\nprint(int((N+D*2)/(D*2+1)))']
['Wrong Answer', 'Accepted']
['s791661541', 's580376044']
[2940.0, 2940.0]
[17.0, 18.0]
[52, 56]
p02970
u768256617
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nn.d=map(int,input().split())\nx=d*2+1\nprint(math.ceil(n/x))', 'import math\nn,d=map(int,input().split())\nx=d*2+1\nprint(math.ceil(n/x))']
['Runtime Error', 'Accepted']
['s878207821', 's775739755']
[2940.0, 2940.0]
[17.0, 17.0]
[70, 70]
p02970
u772371451
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN,D = map(int,input().split())\nprint(math.ceil(D/(N*2+1)))', 'import math\nN,D = map(int,input().split())\nprint(math.ceil(D/N/2))', 'import math\nN,D = map(int,input().split())\nprint(math.ceil(N/(D*2+1)))']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s291408131', 's558375438', 's040843799']
[9152.0, 8824.0, 9100.0]
[27.0, 29.0, 27.0]
[70, 66, 70]
p02970
u774985302
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = map(int,input().split())\n\nif N & (D*2 + 1 ) = 0:\n print(N/(D*2 + 1))\nelse :\n print(round(N//(D*2 + 1)+1))\n ', 'N,D = map(int,input().split())\n \nif N % (D*2 + 1 ) == 0:\n print(round(N/(D*2 + 1)))\nelse :\n print(round(N//(D*2 + 1)+1))']
['Runtime Error', 'Accepted']
['s943907994', 's286220125']
[2940.0, 2940.0]
[17.0, 17.0]
[122, 126]
p02970
u776338097
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['def main():\n import sys\n input = sys.stdin.readline\n \n n, d = map(int, input().split())\n print((n + d - 1) // d)\n \n return 0\n\nmain()', 'def main():\n import sys\n input = sys.stdin.readline\n \n n, d = map(int, input().split())\n d = 2 * d + 1\n print((n + d - 1) // d)\...
['Wrong Answer', 'Accepted']
['s802057712', 's187570371']
[3064.0, 2940.0]
[18.0, 17.0]
[153, 171]
p02970
u777148280
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['x, y = map( int, input().split())\nprint(x//(y*2+1))', 'import math\nx,y=input().split()\nprint(math.ceil(int(x)/(int(y)*2+1)))']
['Wrong Answer', 'Accepted']
['s878605094', 's132674466']
[2940.0, 2940.0]
[17.0, 17.0]
[51, 69]
p02970
u779728630
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\n\n# 2D + 1\nprint( N // (2*D+1) )', 'N, D = map(int, input().split())\nprint( (N + 2*D) // (2*D+ 1))']
['Wrong Answer', 'Accepted']
['s709616433', 's997896348']
[9016.0, 9156.0]
[27.0, 26.0]
[64, 62]
p02970
u780143117
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['shuru=input()\nshuru=shuru.split()\nn=int(shuru[0])\nd=int(shuru[1])\nd=2*d+1\nans=n//d\nif n%d==0 :\n ans+=1\nprint(ans)', 'shuru=input()\nshuru=shuru.split()\nn=int(shuru[0])\nd=int(shuru[1])\nd=2*d+1\nans=n//d\nif n%d!=0 :\n ans+=1\nprint(ans)']
['Wrong Answer', 'Accepted']
['s284681121', 's037100723']
[3188.0, 3060.0]
[20.0, 17.0]
[114, 114]
p02970
u790301364
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['def main11():\n data = input().split()\n num = []\n for i in range(2):\n num.append(int(data[i]))\n result = int(num[0] / (num[1] * 2 + 1))\n print(result)\n\nif __name__ == "__main__":\n main11()', 'def main11():\n data = input().split()\n num = []\n for i in range(2):\n num....
['Wrong Answer', 'Accepted']
['s095253834', 's414940870']
[2940.0, 3060.0]
[18.0, 20.0]
[212, 284]
p02970
u791527495
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN,D =map(int,input().split())\n\nx = D * 2 + 1\n\npre_answer = N / X\nprint(math.ceil(pre_answer))\n', 'N,D =map(int,input().split())\n\nx = D * 2 + 1\n\npre_answer = - (-N // X)\nprint(int(pre_answer))\n', 'import math\nN,D =map(int,input().split())\n\nX = D * 2 + 1\n\npre_answer = N / X\nprint(math.cei...
['Runtime Error', 'Runtime Error', 'Accepted']
['s165733270', 's800484615', 's978906985']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[106, 94, 106]
p02970
u800058906
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d=map(int,input().split())\n\nans=n//(2*(d+1))\n\nif n%(2*(d+1))==0:\n print(ans)\nelse:\n print(ans+1)', 'n,d=map(int,input().split())\n\nans=n//((2*d)+1)\n\nif n%((2*d)+1)==0:\n print(ans)\nelse:\n print(ans+1)']
['Wrong Answer', 'Accepted']
['s832553159', 's424731825']
[9020.0, 9160.0]
[27.0, 28.0]
[100, 100]
p02970
u809457879
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D=map(int,input().split())\nprint((N//(2D+1))+1)', 'import math\nN,D=map(int,input().split())\nprint(math.ceil(N//(2*D))) ', 'import math\nN,D=map(int,input().split())\nprint(math.ceil(N/(2*D+1)))']
['Runtime Error', 'Wrong Answer', 'Accepted']
['s347216982', 's818761292', 's965104792']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[49, 68, 68]
p02970
u811436126
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\n\nans = n // d + 1\nprint(ans)\n', 'n, d = map(int, input().split())\n\nif n % (2 * d + 1) == 0:\n ans = n // (2 * d + 1)\nelse:\n ans = n // (2 * d + 1) + 1\n\nprint(ans)\n']
['Wrong Answer', 'Accepted']
['s896316638', 's699946199']
[2940.0, 2940.0]
[17.0, 17.0]
[62, 135]
p02970
u813953440
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = map(int,input().split())\n#print(N,D)\nA = [i for i in range(1,N+1)]\n#print(A)\n\ndef people(t):\n t = t + 2*D\n return t\nif N<D:\n print(1)\n\nelse:\n t = 1\n c = 0\n while t < N:\n #print(t)\n t = people(t+1)\n c+=1\n print(c)\n ', 'N,D = map(int,input().split())...
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s525386678', 's891648796', 's579681371']
[3060.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[265, 216, 209]
p02970
u814650736
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
["nd=input()\nndlis=['' for i in range(2)]\nndlis=nd.split()\nn=int(ndlis[0])\nd=int(ndlis[1])\non=0\ncnt=0\nwhile on==0:\n\tcnt=cnt+1\n\tif n<=cnt*d:\n\t\ton=1\nprint(cnt)", "nd=input()\nndlis=['' for i in range(2)]\nndlis=nd.split()\nn=int(ndlis[0])\nd=int(ndlis[1])\non=0\ncnt=0\nwhile on==0:\n\tcnt=cnt+1\n\tif n<=cn...
['Wrong Answer', 'Accepted']
['s302564286', 's309168668']
[3060.0, 3060.0]
[18.0, 17.0]
[155, 161]
p02970
u817760251
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\nprint((n + d + d) / (d + d + 1))\n', 'n, d = map(int, input().split())\nprint(int((n + d + d) / (d + d + 1)))']
['Wrong Answer', 'Accepted']
['s888333818', 's502741837']
[2940.0, 2940.0]
[17.0, 17.0]
[66, 70]
p02970
u818349438
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = map(int,input().split())\nprint(N/D+1)\n', 'N,D = map(int,input().split())\nprint(N/(2*D)+1)\n', 'N,D = map(int,input().split())\nans = N //(2*D+1)+1\nif N%(2*D+1)== 0:\n ans-=1\nprint(ans)']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s342486626', 's913117471', 's261513287']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[44, 48, 90]
p02970
u821588465
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\n\nprint((N-1)//D + 1)\n\n', 'from math import floor,ceil\nN, D = map(int, input().split())\n\nprint(ceil(N/(2*D + 1)))\n\n\n\n']
['Wrong Answer', 'Accepted']
['s822826615', 's975668388']
[9180.0, 9124.0]
[28.0, 27.0]
[55, 90]
p02970
u836939578
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN, D = map(int, input().split())\n\nprint(math.ceil((N-2)/(D*2)))', 'import math\nN, D = map(int, input().split())\n\nans = math.ceil((N-1)/(D*2+1))\n\nif (N-1) % (D*2+1) == 0:\n ans += 1\n\nprint(ans)\n']
['Wrong Answer', 'Accepted']
['s905444996', 's860530093']
[2940.0, 2940.0]
[17.0, 17.0]
[75, 128]
p02970
u840958781
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,p=map(int,input().split())\nif n%(2p+1)==0:\n print(n//(2p+1))\nelse:\n print(n//(2p+1)+1)', 'n,p=map(int,input().split())\nif n%(2*p+1)==0:\n print(n//(2*p+1))\nelse:\n print(n//(2*p+1)+1)']
['Runtime Error', 'Accepted']
['s831851645', 's876567256']
[2940.0, 2940.0]
[17.0, 17.0]
[94, 97]
p02970
u840988663
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\n\nsyou=N//D\namari=N%D\n\nif amari != 0:\n syou=syou+1\n\nprint(syou)\n', 'N, d = map(int, input().split())\n\nD=2*d+1\nsyou=N//D\namari=N%D\n\nif amari != 0:\n syou=syou+1\n\nprint(syou)\n']
['Wrong Answer', 'Accepted']
['s913106965', 's635317645']
[2940.0, 2940.0]
[18.0, 17.0]
[97, 105]
p02970
u844123804
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['num = input().split()\nans = int(num[0]) // (int(num[1])*2+1)\nif int(num[0])%int(num[1])!=0: ans += 1\nprint(ans)', 'num = input().split()\nans = int(num[0]) // (int(num[1])*2+1)\nif int(num[0])%(int(num[1])*2+1)!=0: ans += 1\nprint(ans)']
['Wrong Answer', 'Accepted']
['s209997748', 's429184119']
[2940.0, 2940.0]
[17.0, 17.0]
[111, 117]
p02970
u847497464
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = [ int(_) for _ in input().split() ]\nx = n / (2*d+1)\nif x.is_integer()\n print( x )\nelse:\n print( x + 1 )\n\n\n\n', 'n, d = [ int(_) for _ in input().split() ]\nx = n / (2*d+1)\n\nif x.is_integer():\n print( x//1 )\nelse:\n print( (x//1) + 1 )\n\n\n\n', 'n, d = [ int(_) for _ in input().split(...
['Runtime Error', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s334982905', 's416191207', 's802599880', 's947314328']
[2940.0, 2940.0, 2940.0, 2940.0]
[17.0, 18.0, 17.0, 17.0]
[121, 131, 118, 141]
p02970
u857673087
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN, D = map(int, input().split())\n\nprint(math.ceil(N/(2*D+1))', 'import math\nN,D = map(int, input().split())\nprint(math.ceil(N/(2*D+1)))']
['Runtime Error', 'Accepted']
['s818822288', 's412365493']
[2940.0, 2940.0]
[17.0, 17.0]
[72, 71]
p02970
u864276028
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = map(int, input().split())\nD = 2*D + 1\nfor i in range (N+1):\n if i >= D:\n print(i)', 'N,D = map(int, input().split())\nD = 2*D + 1\nk = N/D\nl = N//D\nif k == l:\n print(int(k))\nelse:\n print(l+1)']
['Wrong Answer', 'Accepted']
['s059843029', 's321147507']
[2940.0, 2940.0]
[17.0, 17.0]
[91, 110]
p02970
u866769581
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = map(int,input().split())\nprint(n//(d*2+1))', 'n,d = map(int,input().split()) \nprint((n+(d*2))//(d*2+1))']
['Wrong Answer', 'Accepted']
['s691576413', 's152196259']
[2940.0, 2940.0]
[17.0, 17.0]
[48, 146]
p02970
u869519920
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['a, b=list(map(int, input()))\nprint((a-1)/(2*b + 1)/1)', 'a, b=list(map(int, input().split()))\nprint(int((a-1)/(2*b + 1))+1)']
['Runtime Error', 'Accepted']
['s779884593', 's625382656']
[9152.0, 9104.0]
[26.0, 26.0]
[53, 66]
p02970
u873134970
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nn,d=map(int,input())\nk=math.ceil(n/(2*d))\nprint(k)', 'import math\nn,d=map(int,input().split())\nk=math.ceil(n/(2*d+1))\nprint(k)']
['Runtime Error', 'Accepted']
['s963483730', 's456392264']
[2940.0, 2940.0]
[17.0, 17.0]
[62, 72]
p02970
u873269440
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['\ndef main():\n\n N,D = map(int,input().split())\n D += 4\n\n if N < D:\n N=D\n\n if N%D==0:\n print(int(N/D))\n else:\n print(int((N/D)+1))\n\n\n\nif __name__== "__main__":\n main() \n', '\ndef main():\n\n N,D = map(int,input().split())\n\n power = D*2+1\n\n if N <= po...
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s582752335', 's731324905', 's780930623']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[206, 243, 251]
p02970
u879248892
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN, D = int(input())\nperson = math.cell(N / (D*2+1))\nprint(person)', 'N,D = map(int,input().split())\nif N % (D*2+1) != 0:\n p = n // (d*2+1) + 1\nelse:\n p = n // (d*2+1)\n \nprint(p)', 'import math\nN, D = map(int, input().split())\nperson = math.cell(N / (D*2+1))\nprint(person)\n', 'N,D = map(int,...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s116412784', 's422643273', 's778129793', 's081402454']
[2940.0, 2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0, 17.0]
[77, 111, 91, 111]
p02970
u885932660
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\n\nnd = input().strip().split()\nn = nd[0]\nd = nd[1]\n\ninspectors = math.ceil(n / (2 * d + 1))\nprint(inspectors)', 'import math\n\nnd = [int(x) for x in input().strip().split()]\nn = nd[0]\nd = nd[1]\n\ninspectors = math.ceil(n / (2 * d + 1))\nprint(inspectors)']
['Runtime Error', 'Accepted']
['s371607575', 's608400661']
[2940.0, 2940.0]
[17.0, 18.0]
[120, 138]
p02970
u887080340
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\n\nprint(N//(2*D+1))\n', 'import math\nN, D = map(int, input().split())\nans = math.ceil(N/(2*D+1))\nprint(ans)\n\n']
['Wrong Answer', 'Accepted']
['s236620051', 's944971497']
[2940.0, 2940.0]
[17.0, 17.0]
[52, 84]
p02970
u888512581
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\ni = (n // 2*r) + 1\nprint(i)', 'n, d = map(int, input().split())\nif n % (2*d + 1) == 0:\n print(n // (2*d + 1))\nelse:\n print(n // (2*d + 1) + 1)']
['Runtime Error', 'Accepted']
['s545171410', 's237219688']
[2940.0, 2940.0]
[17.0, 18.0]
[60, 113]
p02970
u891161439
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n = int(input())\nd = int(input())\nans = n/(2*d + 1)\nif n % (2*d + 1) != 0:\n print(ans+1)\nelse:\n print(ans)\n', 'n = int(input())\nd = int(input())\nans = n/(2*d + 1)\nif n % (2*d + 1) != 0:\n print("{}".format(ans+1))\nelse:\n print("{}".format(ans))', 'n = int(input())\nd = int(input())\nans = n // (2*d + ...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Wrong Answer', 'Accepted']
['s251959282', 's281122463', 's859284679', 's985008476', 's658569646']
[2940.0, 2940.0, 2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0, 17.0, 17.0]
[109, 134, 112, 108, 109]
p02970
u893270619
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN, D = map(int, input().split())\nprint(math.floor(N/(2*D+1)))', 'import math\nN, D = map(int, input().split())\nprint(math.ceil(N/(2*D+1)))']
['Wrong Answer', 'Accepted']
['s004939421', 's151417118']
[2940.0, 2940.0]
[18.0, 17.0]
[73, 72]
p02970
u898967808
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nn,d= map(int,input().split())\nmath.ceil(n/(d*2+1))', 'import math\nn,d= map(int,input().split())\nprint(math.ceil(n/(d*2+1)))']
['Wrong Answer', 'Accepted']
['s703358909', 's990257764']
[2940.0, 2940.0]
[17.0, 17.0]
[62, 69]
p02970
u899909022
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN,D=map(int,input().split())\ntmp = D *2.0 + 1\nprint(tmp)\nprint(math.ceil(N / tmp))', 'import math\nN,D=map(int,input().split())\ntmp = D *2.0 + 1\nprint(tmp)\nprint(int(math.ceil(N / tmp)))', 'import math\nN,D=map(int,input().split())\ntmp = D *2.0 + 1\nprint(int(math.ceil(N / tmp)))\n']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s237884762', 's987970282', 's433516489']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[94, 99, 89]
p02970
u904995051
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = map(int,input().split())\nprint((n+d+4-1)//(d+4))', 'n,d = map(int,input().split())\nprint((n+d*2)//(d*2+1))']
['Wrong Answer', 'Accepted']
['s830858132', 's466017541']
[9156.0, 9160.0]
[29.0, 33.0]
[54, 54]
p02970
u912318491
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nN,D = map(int,input().split())\n\npeople = math.ceil(N // (2D+1))\nprint(people)', 'N, D = map(int, input().split())\n\npeople = N / (2*D+1)\nif people % 1.0 != 0:\n people+=1\nprint(int(people))']
['Runtime Error', 'Accepted']
['s621461470', 's257424761']
[2940.0, 3060.0]
[17.0, 17.0]
[89, 149]
p02970
u918601425
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = [int(s) for s in input().split()]\nprint(math.ceil(N/(2*D+1)))', 's1,s2=input().split()\nN=int(s1)\nD=int(s2)\nn=N\nans=0\nwhile n>0:\n n=n-(2*D+1)\n ans=ans+1\nprint(ans)\n']
['Runtime Error', 'Accepted']
['s439499982', 's290624588']
[2940.0, 9048.0]
[17.0, 26.0]
[67, 100]
p02970
u932868243
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d=map(int,input())\nif n%(2*d+i)==0:\n print(n//(2*d+1))\nelse:\n print(n//(2*d+1)+1)', 'n,d=map(int,input().split())\nif n%(2*d+i)==0:\n print(n//(2*d+1))\nelse:\n print(n//(2*d+1)+1)', 'import math\nn,d=map(int,input().split())\nprint(math,ceil(n/(d*2+1)))', 'import math\nn,d=map(int,input().split())\nprint(m...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s071961611', 's396616788', 's449318273', 's532225866']
[2940.0, 2940.0, 2940.0, 2940.0]
[18.0, 17.0, 18.0, 17.0]
[85, 93, 68, 70]
p02970
u933129390
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\nspl_num = d*2+1\nif not n % spl_num:\n print(n // spl_num + 1)\nelse:\n print(n // spl_num)', 'n, d = map(int, input().split())\nspl_num = d*2+1\nif not n % spl_num:\n print(n // spl_num)\nelse:\n print(n // spl_num + 1)']
['Wrong Answer', 'Accepted']
['s562954813', 's024387966']
[2940.0, 2940.0]
[17.0, 18.0]
[126, 126]
p02970
u933341648
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\nprint(n//(d*2))', 'n, d = map(int, input().split())\nprint((n+d*2)//(d*2+1))']
['Wrong Answer', 'Accepted']
['s821799760', 's888565471']
[2940.0, 2940.0]
[18.0, 17.0]
[48, 56]
p02970
u933962236
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = (int(x) for x in input().split())\nprint(n/2d)', 'n,d = (int(x) for x in input().split())\nif n//(2*d) = 0:\n print(n/(2*d))\nelse:\n print(n/(2*d)+1)', 'N,D = array(input(),input())\nprint(roundup(N/2D ,0)', 'n,d = (int(x) for x in input().split())\nif n % (2*d + 1) == 0:\n print(n//(2*d + 1))\nelse:\n pri...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s084597841', 's931583128', 's954499534', 's922523769']
[2940.0, 2940.0, 2940.0, 2940.0]
[18.0, 17.0, 17.0, 17.0]
[51, 98, 51, 116]
p02970
u935522051
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D = map(int,input().split())\na = N%(2*D+1)\nb = N//(2*D+1)\nif a=0:\n print(int(b))\nelse:\n print(int(b+1))\n', 'N,D = map(int,input().split())\na = N%(2*D+1)\nb = N//(2*D+1)\nif a=0:\n print(b)\nelse:\n print(int(b+1))\n', 'N,D = map(int,input().split())\na = N%(2*D+1)\nb = N//(2*D+1)\nif a==0:\n print(int(...
['Runtime Error', 'Runtime Error', 'Accepted']
['s065101771', 's728180088', 's321068718']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[108, 103, 109]
p02970
u941284420
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N,D =map(int,input().split())\nans=0\nwhile True:\n ans+=1\n tmp=ans*2+1\n if tmp >= N:\n break\nprint(ans)', 'N,D =map(int,input().split())\nans=0\nwhile True:\n ans+=1\n tmp=(D*2+1)*ans\n if tmp >= N:\n break\nprint(ans)']
['Wrong Answer', 'Accepted']
['s784613602', 's822307938']
[3064.0, 3064.0]
[19.0, 17.0]
[106, 110]
p02970
u945641805
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\n\ni = 1\nleft = 1\nres = 0\nwhile i <= N:\n if i - D == left:\n print(i, left)\n left = i + D + 1\n res += 1\n i += 1\n\nif left <= N: res += 1\n\nprint(res)', 'N, D = map(int, input().split())\n\ni = 1\nleft = 1\nres = 0\nwhile i <= N:\n if i - D == lef...
['Wrong Answer', 'Accepted']
['s122451711', 's762067371']
[3060.0, 3060.0]
[17.0, 20.0]
[204, 181]
p02970
u951665306
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nn, d = map(int, input().split)\nprint(math.ceil(n/(2*d+1)))', 'import math\nn, d = map(int, input().split())\nprint(math.ceil(n/(2*d+1)))']
['Runtime Error', 'Accepted']
['s305908553', 's683620992']
[2940.0, 3060.0]
[17.0, 19.0]
[70, 72]
p02970
u953379577
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['a,b = map(int,input().split())\n\nr = b*2+1\n\nif a%b == 0:\n print(a//r)\nelse:\n print(a//r+1)\n', 'a,b = map(int,input().split())\n\nr = b*2+1\n\nif a%b == 0:\n print(a//b)\nelse:\n print(a//b+1)\n', 'a,b = map(int,input().split())\n\nr = b*2+1\n\nif a%r == 0:\n print(a//r)\nelse:\n print(a//r+1)...
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s085039359', 's807142127', 's117127700']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[96, 96, 96]
p02970
u958053648
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d=map(int ,input().split())\nprint((n+2*d)/(2*d+1))', 'n,d=map(int ,input().split())\nprint(n/(2*d+1))', 'import math\nn,d=map(int,input().split())\nprint(math.ceil(n/(2*d+1)))']
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s048420546', 's358667842', 's547574464']
[2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0]
[52, 46, 68]
p02970
u962356464
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import math\nnum_list = list(map(int, input().split()))\n\nN = num_list[0]\nD = num_list[1]\n\nprint (math.ceil(N//(2*D+1)))', 'import math\nN,D= list(map(int, input().split()))\n\nprint (math.ceil(N/(2*D+1)))']
['Wrong Answer', 'Accepted']
['s206807228', 's364333920']
[3060.0, 3064.0]
[17.0, 17.0]
[118, 78]
p02970
u965033073
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['a,b=map(int,input().split())\nc=a//(2b+1)+1\nprint(c)', 'n, d = map(int, input().split())\nif n%(2*d+1) == 0:\n print(n//(2*d+1))\nelse:\n print(n//(2*d+1)+1)\n']
['Runtime Error', 'Accepted']
['s480779932', 's089705114']
[2940.0, 2940.0]
[17.0, 18.0]
[51, 104]
p02970
u966000628
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n,d = map(int,input().split())\nsight = 2*d+1\ni = 1\nwhile(True)\n if n <= i*sight:\n print(i)\n break\n i += 1\n ', 'n,d = list(map(int,input().split()))\nsight = 2*d+1\nprint((n//sight) + (n%sight != 0))']
['Runtime Error', 'Accepted']
['s210618514', 's635173802']
[2940.0, 2940.0]
[18.0, 17.0]
[118, 85]
p02970
u969848070
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['a, b = int(input())\nif a%(1+b) !=0:\n print(a//(1+b)+1)\nelse:\n print(a//(1+b))', 'a, b = map(int, input().split())\nif a%(1+2*b) !=0:\n print(a//(1+2*b)+1)\nelse:\n print(a//(1+2*b))']
['Runtime Error', 'Accepted']
['s582088396', 's391595187']
[2940.0, 2940.0]
[17.0, 18.0]
[79, 98]
p02970
u978962055
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int, input().split())\nif N%D == 0:\n print(N//(2*D+1))\nelse:\n print(N//(2*D+1)+1)', 'N, D = map(int, input().split())\nif N%(2*D+1) == 0:\n print(N//(2*D+1))\nelse:\n print(N//(2*D+1)+1)']
['Wrong Answer', 'Accepted']
['s068856380', 's805403666']
[2940.0, 2940.0]
[17.0, 17.0]
[93, 99]
p02970
u981304949
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N, D = map(int,input().split())\na = N//(2D+1)\nif N%(2D+1)==0:\n print(a)\nelse:\n print(a+1)', 'N, D = map(int,input().split())\na = N//(2*D+1)\nif N%(2*D+1)==0:\n print(a)\nelse:\n print(a+1)']
['Runtime Error', 'Accepted']
['s157652627', 's358911001']
[2940.0, 2940.0]
[17.0, 18.0]
[91, 93]
p02970
u982462877
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
[',d = map(int,input().split())\n\na = d * 2 + 1\n\nb=n/a\nb = int(b)\nc=n%a\nif c>0:\n b = b + 1\n \nprint(b)', 'n,d = map(int,input().split())\n\na = d * 2 + 1\n\nb=n/a\nb = int(b)\nc=n%a\nif c>0:\n b = b + 1\n \nprint(b)\n']
['Runtime Error', 'Accepted']
['s983548565', 's511492208']
[2940.0, 2940.0]
[17.0, 17.0]
[104, 106]
p02970
u983943108
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['N=int(input())\nD=int(input())\nmaximum=2*D+1\nif N%maximum==0:\n print(int(N/maximum))\nelse:\n print(int(N/maximum+1))', 'inputing=input()\nN=int(inputing.split()[0])\nD=int(inputing.split()[1])\n\nmaximum=2*D+1\nif N%maximum==0:\n print(int(N/maximum))\nelse:\n print(int(N/maximum+1))']
['Runtime Error', 'Accepted']
['s451899988', 's412707339']
[2940.0, 2940.0]
[17.0, 17.0]
[120, 162]
p02970
u989089752
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['n, d = map(int, input().split())\nans = (n+2*d)/(2*d+1)\nprint(ans)\n', 'n,d = map(int,input().split())\ns = 2*d+1\nans = (n + s -1)/s\nprint(ans)', 'n,d = map(int,input().split())\ns = 2*d + 1\nans = (n+s-1)/s\nprint(ans)', 'n, d = map(int, input().split())\ns = 2*d+1\nans = (n+s-1)/s\nprint(ans)', 'n, d = map(int, ...
['Wrong Answer', 'Wrong Answer', 'Wrong Answer', 'Wrong Answer', 'Wrong Answer', 'Accepted']
['s225520331', 's317127214', 's325222107', 's633902247', 's868019764', 's021473610']
[2940.0, 2940.0, 2940.0, 2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0, 17.0, 17.0, 17.0]
[66, 70, 69, 69, 68, 67]
p02970
u989157442
2,000
1,048,576
There are N apple trees in a row. People say that one of them will bear golden apples. We want to deploy some number of inspectors so that each of these trees will be inspected. Each inspector will be deployed under one of the trees. For convenience, we will assign numbers from 1 through N to the trees. An inspector ...
['import mth\nn, d = map(int,input().split())\nprint(math.ceil(n / (2 * d + 1)))\n', 'import mth\nn, d = map(int,input().split())\nprint(math.seil(n / (2 * d + 1)))\n', 'import math\nn, d = map(int,input().split())\nprint(math.ceil(n / (2 * d + 1)))\n']
['Runtime Error', 'Runtime Error', 'Accepted']
['s451253156', 's825582160', 's613513306']
[2940.0, 2940.0, 3064.0]
[17.0, 17.0, 18.0]
[77, 77, 78]
p02971
u003501233
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['N = int(input())\nA = [int(input()) for i range(N)]\n\nx = sorted(A)\n\nfor i in range(N):\n if A[i] == x[N-1]:\n print(x[N-2])\n else:\n print(x[N-1])', 'N=int(input())\nA=[int(input()) for i range(N)]\n\nx=sorted(A)\n\nfor i in range(N):\n if A[i] == x[N-1]:\n print(x[N-2])\n else:\n print(x[N-1])',...
['Runtime Error', 'Runtime Error', 'Accepted']
['s653039292', 's968394997', 's338212822']
[2940.0, 2940.0, 14152.0]
[17.0, 17.0, 581.0]
[150, 144, 153]
p02971
u006883624
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['def main():\n N = int(input())\n\n max_left = [0] * N\n max_right = [0] * N\n\n ary = []\n\n for i in range(N):\n v = int(input())\n ary.append(v)\n\n for i in range(N - 1):\n max_left[i+1] = max(max_left[i], ary[i])\n\n for i in range(N - 1, 0, -1):\n max_right[i-1] = max(max_right[i], ary[i])\n\n...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s138719228', 's780189222', 's788523955', 's790580044', 's921170191', 's689146917']
[3060.0, 3060.0, 3060.0, 3060.0, 3188.0, 15656.0]
[17.0, 17.0, 17.0, 17.0, 17.0, 576.0]
[375, 392, 364, 368, 375, 422]
p02971
u015490689
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['n=int(input())\nv=[int(input()) for i in range(n)]\nt=sorted(v)\nfor i in v:\n print(t[1] if i==t[0] else t[0])', 'n=int(input())\nv=[int(input()) for i in range(n)]\nm1=v[0]\nm2=v[1]\nif m2>m1:m1,m2=m2,m1\nfor i in v:\n if i > m1:\n m2=m1\n m1=i\n elif i>m2:\n m2=i\nfor i in v:\n print(m2 if i==m1 else ...
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s335154053', 's419373717', 's147438041']
[14112.0, 12512.0, 14112.0]
[527.0, 489.0, 537.0]
[108, 193, 121]
p02971
u015593272
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['N = int(input())\nl = [int(input()) for i in range(N)]\nl_sort = sorted(l)\n\nfor i in range(N):\n\n if (l[i] != l_sort[-1]):\n print(l_sort[-2])\n else:\n print(l_sort[-1])', 'N = int(input())\nl = [int(input()) for i in range(N)]\nl_sort = sorted(l)\n\nfor i in range(N):\n\n if (l[i] != l_sor...
['Wrong Answer', 'Accepted']
['s973151035', 's275533803']
[14112.0, 14744.0]
[547.0, 557.0]
[184, 185]
p02971
u016901717
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['import copy\nn=int(input())\nA=[int(input()) for i in range(n)]\nB=copy.copy(A)\nfor i in range(n):\n A.pop(i)\n print(max(A))\n A = B\n ', 'n=int(input())\nA=[int(input()) for i in range(n)]\nB=sorted(A)\nfor a in A:\n if a == B[-1]:\n print(B[-1])\n else:\n print(B[-2])', 'n=int(input(...
['Runtime Error', 'Wrong Answer', 'Accepted']
['s366015334', 's711637613', 's868627421']
[13080.0, 14068.0, 14112.0]
[2104.0, 536.0, 548.0]
[141, 142, 142]
p02971
u017064954
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['n = int(input())\nA = []\nfor i in range(n):\n A.append(int(input()))\n \nfor i in range(n):\n Ai = A\n Ai.pop(i)\n print(max(Ai))\n', 'n = int(input())\nA = [int(input()) for i in range(n)]\nfor i in range(n):\n Ai = A\n Ai.pop(i)\n print(max(Ai))', 'n = int(input())\nA = [int(a) for input() in range(n)]\nfo...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s001613841', 's101529270', 's376213268', 's457409201', 's989028454']
[11180.0, 11180.0, 2940.0, 11052.0, 14112.0]
[2104.0, 2104.0, 17.0, 369.0, 544.0]
[128, 110, 111, 123, 181]
p02971
u017415492
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['import heapq\nn=int(input())\nd=[]\nfor i in range(n):\n heapq.heappush(d,int(input()))\nfor j in range(n):\n if d[j]==d[n-1]:\n print(d[n-2])\n else:\n print(d[n-1])', 'n=int(input())\nd=[]\nfor i in range(n):\n d.append(int(input()))\nx=sorted(d)\nfor j in range(n):\n if d[j]==d[-1]:\n print(x[-2])\n ...
['Wrong Answer', 'Wrong Answer', 'Runtime Error', 'Accepted']
['s066994486', 's647313036', 's929346580', 's935656606']
[12552.0, 15808.0, 11072.0, 19028.0]
[564.0, 587.0, 384.0, 352.0]
[166, 156, 166, 135]
p02971
u017624958
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
['N = int(input())\nA = [int(input()) for i in range(N)]\n\n\nsorted_A = list(reversed(sorted(A)))\n\nmaxiuam = sorted_A[0]\n\nis_there_tow_maximum = A.count(maxiuam) >= 2\nif is_there_tow_maximum:\n answer = (str(maxiuam) + "\\n") * N\n print(answer)\n exit()\n\nsecond = None\nfor Ai in sorted_A:\n if Ai <...
['Runtime Error', 'Runtime Error', 'Accepted']
['s500226850', 's763603476', 's314976041']
[16516.0, 3064.0, 28060.0]
[408.0, 18.0, 474.0]
[471, 459, 458]
p02971
u020962106
2,000
1,048,576
You are given a sequence of length N: A_1, A_2, ..., A_N. For each integer i between 1 and N (inclusive), answer the following question: * Find the maximum value among the N-1 elements other than A_i in the sequence.
["n = int(input())\nH = list(map(int,input().split()))\n\ntmp = H[0]\nfor k in H:\n if tmp - k > 1:\n print('No')\n exit()\n if k > tmp:\n tmp = k\nprint('Yes')", 'n = int(input())\nA = [int(input()) for _ in range(n)]\nB = A[:]\nB.sort(reverse = True)\nmax_A = max(A)\nfor i in range(n):\n ...
['Wrong Answer', 'Accepted']
['s660935773', 's716823048']
[3060.0, 14112.0]
[17.0, 556.0]
[175, 192]