problem_id
stringlengths
6
6
user_id
stringlengths
10
10
time_limit
float64
1k
8k
memory_limit
float64
262k
1.05M
problem_description
stringlengths
48
1.55k
codes
stringlengths
35
98.9k
status
stringlengths
28
1.7k
submission_ids
stringlengths
28
1.41k
memories
stringlengths
13
808
cpu_times
stringlengths
11
610
code_sizes
stringlengths
7
505
p03060
u104922648
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['from itertools import combinations\n\nn = int(input())\nvalue = list(map(int, input().split()))\ncost = list(map(int, input().split()))\n\nidx = range(n)\nresult = [0, sum(value)-sum(cost)]\nindex = [idx for idx, v, c in enumerate(zip(value, cost)) if v > c]\ncomb = [com for i in range(1, len(index)) for com in combi...
['Runtime Error', 'Accepted']
['s327378748', 's460408971']
[3064.0, 2940.0]
[18.0, 18.0]
[444, 180]
p03060
u111652094
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['A,B,T = map(int,input().split())\n\nC = int((T + 1/2)//A)\nans = B*C\n\nprint(ans)', '# -*- coding: utf-8 -*-\n\n\nN = int(input())\nV = list(map(int,input().split()))\nC = list(map(int,input().split()))\nans = 0\n\nfor i in range(N):\n if V[i]-C[i]>0:\n ans += V[i]-C[i]\nprint(ans)']
['Runtime Error', 'Accepted']
['s992625858', 's039098042']
[2940.0, 3064.0]
[17.0, 17.0]
[77, 259]
p03060
u116038906
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['\nimport numpy as np\nimport sys\ninput = sys.stdin.readline\nN = int(input())\nV = np.array(list(map(int, input().split())))\nC = np.array(list(map(int, input().split())))\n\n\nv_c_sum=[]\nfrom itertools import combinations\nfor i in range(N+1):\n for t in combinations(range(N), i):\n print(t)\n\n v...
['Wrong Answer', 'Accepted']
['s212605622', 's019999173']
[17972.0, 12484.0]
[2109.0, 149.0]
[449, 313]
p03060
u116233709
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\na[0]*n\nfor i in range(0,n):\n a[i]=v[i]-c[i]\n \nans=0 \nfor j in range(0,n):\n if a[j]>0:\n ans+=a[j]\n \nprint(ans) \n \n ', 'n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nans=0\...
['Runtime Error', 'Accepted']
['s437748557', 's212511997']
[3060.0, 3060.0]
[17.0, 17.0]
[210, 169]
p03060
u117545210
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['a=input()\np=list(map(int,input().split()))\nq=list(map(int,input().split()))\ncost=0\nfor i in range(a):\n if p[i] - q[[i] > 0:\n cost += (p[i]-q[i]) \nprint(n)', 'a=int(input())\np=list(map(int,input().split()))\nq=list(map(int,input().split()))\ncost=0\nfor i in range(a):\n if p[i] - q[i] > 0:\n ...
['Runtime Error', 'Accepted']
['s800522706', 's765157235']
[2940.0, 3060.0]
[17.0, 17.0]
[166, 173]
p03060
u117980998
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['ef resolve():\n n = int(input())\n v = map(int,input().split())\n c = map(int,input().split())\n s = [x-y for x,y in zip(v,c) if (x-y)>0]\n ans = 0\n if s:\n ans = sum(s)\n print(ans)\n\nif __name__ == "__main__":\n resolve()', 'def resolve():\n n = int(input())\n v = map(int,inpu...
['Runtime Error', 'Accepted']
['s773579042', 's455811882']
[2940.0, 3060.0]
[17.0, 19.0]
[245, 246]
p03060
u124025116
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = input()\nvli = list(map(int,input().split()))\ncli = list(map(int,input().split()))\nfor i in n:\n sli = []\n sli.append(vli[i] - cli[i])\nfor j in n:\n ans = []\n if sli[j] > 0:\n ans.append(sli[j])\nanswer = sum(ans) \nprint(answer)', 'n=input()\nvli = list(map(int,input().split()))\ncli = list(map(in...
['Runtime Error', 'Runtime Error', 'Accepted']
['s196924733', 's829506513', 's865496615']
[3064.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0]
[237, 207, 169]
p03060
u125348436
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nd=[]\nfor i in N-1:\n m=v[i]-c[i]\n if m>0:\n d.append(m)\nprint(sum(d))', 'N=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nd=[]\nfor i in range(N):\n m=v[i]-c[i]\n if m>0:\n d.append(m)\n...
['Runtime Error', 'Accepted']
['s854234643', 's315554661']
[3060.0, 3060.0]
[17.0, 18.0]
[153, 158]
p03060
u126232616
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nval = []\ncos = []\nfor i in range(N):\n val.append(int(input())\nfor i in range(N):\n cos.append(int(input())\ndif = [val[i]-cos[i] for i in range(N)]\nma = 0\nfor d in dif:\n ma += d if d >= 0 else 0\nreturn ma', 'n = int(input())\nva = input().split()\nco = input().split()\n\nval = [int(...
['Runtime Error', 'Accepted']
['s235104128', 's185749509']
[2940.0, 3064.0]
[17.0, 17.0]
[228, 214]
p03060
u131264627
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\nd = 0\nfor i range(n):\n d = v[i] - c[i]\n if 0 < d:\n ans += d\nprint(int(ans))', 'n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\nans = 0\nfor i range(n):\n d = v[i...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s147608022', 's455616225', 's969941925', 's664481918']
[2940.0, 2940.0, 2940.0, 2940.0]
[17.0, 17.0, 17.0, 18.0]
[177, 179, 174, 183]
p03060
u138781768
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nb = input()\nv = []\nv.append(b.split())\nv = v[0]\ncount = 0\nfor v1 in v:\n v.remove(v1)\n v.insert(count, int(v1))\ns = input()\nc = []\nc.append(s.split())\nc = c[0]\ncount = 0\nfor c1 in c:\n c.remove(c1)\n c.insert(count, int(c1))\nprint(v)\nprint(c)\na = []\nfor (v1,c1) in zip(v,c...
['Wrong Answer', 'Accepted']
['s461686418', 's144121284']
[3064.0, 3064.0]
[18.0, 17.0]
[402, 384]
p03060
u140697185
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['Number = input()\n\ntresure_value = list(map(int , input().split()))\n\ncost = list(map(int , input().split()))\n\ncount = 0\n\nfor i in range(Number):\n if tresure_value[i] - cost[i] > 0:\n count += tresure_value[i] - cost[i]\n \nprint(count)', 'Number = input()\n \ntresure_value = list(map(int , input().spli...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s108269270', 's122534982', 's176002942', 's188135702', 's331278533', 's889215190', 's461542715']
[3060.0, 3060.0, 3060.0, 2940.0, 3060.0, 2940.0, 3064.0]
[18.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0]
[238, 250, 255, 260, 252, 254, 256]
p03060
u141410514
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nsum=0\ni=0\nwhile i<n:\n if v[i]>c[i]:\n sum+=v[i]-c[i]\nprint(sum)', 'n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nsum=0\ni=0\nwhile i<n:\n if v[i]>c[i]:\n sum+=v[i]-c[i]\n i+=1\nprin...
['Time Limit Exceeded', 'Time Limit Exceeded', 'Accepted']
['s456939300', 's762938453', 's328382222']
[3060.0, 3060.0, 3060.0]
[2104.0, 2104.0, 17.0]
[147, 157, 163]
p03060
u145600939
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\nans = 0\nfor i,j in zip(v,c):\n ans += max(0, v-c)\nprint(ans)\n', 'n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\nans = 0\nfor i,j in zip(v,c):\n ans += max(0, i-j)\nprint(ans)\n']
['Runtime Error', 'Accepted']
['s535327794', 's583391128']
[2940.0, 3064.0]
[17.0, 17.0]
[148, 148]
p03060
u146597538
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = map(int, input().split())\nc = map(int, input().split())\n\nans = 0\nfor i in range(n):\n if v[i] - c[i] > 0:\n ans += v[i] - c[i]\n\nprint(ans)', 'n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n\nans = 0\nfor i in range(n):\n if v[i] - c[i] > 0:...
['Runtime Error', 'Accepted']
['s944638768', 's841505194']
[3060.0, 3060.0]
[17.0, 17.0]
[161, 173]
p03060
u151365505
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = input()\nV_list = list(map(int,input().split()))\nC_list = list(map(int,input().split())\n \ndiff_list = [v_list[i]-c_list[i] for i in range(n) if v_list[i] - c_list[i] > 0]\ndiff_list.append(0)\nprint(sum(diff_list))', 'N = input()\nV_list = list(map(int,input().split()))\nC_list = list(map(int,input().split())\...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s141421727', 's195653586', 's240932558', 's876788376', 's423534690']
[2940.0, 2940.0, 2940.0, 2940.0, 3060.0]
[17.0, 17.0, 17.0, 17.0, 17.0]
[215, 248, 247, 215, 214]
p03060
u161201983
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nval = []\nfor i in map(int, input().split()):\n i.append(val)\ncost = []\nfor i in map(int, input().split()):\n i.append(cost)\n\nx = 0\ny = 0\nm1 = 0\nfor i in range(n):\n x += val[i]\n y += cost[i]\n m2 = x-y\n if m1 < m2:\n m1 = m2\n\nprint(m2)\n', 'n = int(input())\nval ...
['Runtime Error', 'Accepted']
['s160396385', 's266230518']
[3064.0, 3064.0]
[18.0, 17.0]
[273, 240]
p03060
u161442663
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nVs=str(input())\nCs=str(input())\nListV=Vs.split()\nListC=Cs.split()\nfor i in range(0,len(ListV),1):\n a=ListV.pop(0)\n ListV.insert(0,int(a))\n\nfor i in range(0,len(ListC),1):\n b=ListC.pop(0)\n ListC.insert(0,int(b))\n\nListI=[]\nfor i in range(0,len(ListV),1):\n c=ListV[i]-ListC[i]\n ListI....
['Runtime Error', 'Runtime Error', 'Accepted']
['s227588125', 's566900093', 's161886736']
[3064.0, 3064.0, 3064.0]
[17.0, 17.0, 17.0]
[397, 398, 394]
p03060
u169070893
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['num = input()\nvalue = [int(n) for n in input().split()]\ncost = [int(n) for n in input().split()]\n\nans=0\nfor i in range(num):\n if value[i] > cost[i]:\n ans = ans + value[i] - cost[i]\n\nprint(ans)', 'num = input()\nvalue = list(map(int, input().split()))\ncost = list(map(int, input().split()))\nans=0\nfor i ...
['Runtime Error', 'Runtime Error', 'Accepted']
['s167893136', 's233406117', 's140969611']
[3060.0, 3060.0, 2940.0]
[19.0, 19.0, 17.0]
[196, 192, 200]
p03060
u169138653
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['v=list(map(int,input().split()))\nc=list(map(int,input().split()))\ncnt=0\nfor i in range(n):\n if v[i]-c[i]>0:\n cnt+=v[i]-c[i]\nprint(cnt)', 'n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\ncnt=0\nfor i in range(n):\n if v[i]-c[i]>0:\n cnt+=v[i]-c[i]\nprint(cnt)']
['Runtime Error', 'Accepted']
['s088460288', 's906763647']
[3060.0, 3060.0]
[18.0, 23.0]
[138, 153]
p03060
u178192749
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nvl = [int(input()) for _ in range(n)]\ncl = [int(input()) for _ in range(n)]\nans = 0\nfor i in range(n):\n if vl[i] > cl[i]:\n ans += v[i]-c[i]\nprint(ans)', 'n = int(input())\nvl = list(map(int, input().split()))\ncl = list(map(int, input().split()))\nans = 0\nfor i in range(n):\n if ...
['Runtime Error', 'Runtime Error', 'Accepted']
['s570628612', 's758917738', 's601543614']
[3060.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0]
[177, 175, 177]
p03060
u181644161
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nV=[int,input().split()]\nC=[int,input().split()]\nans=0\nfor i in range(N):\n if V[i]-C[i] >0:\n ans+=V[i]-C[i]\nprint(ans)', 'N=int(input())\nV=list(map(int,input().split()))\nC=list(map(int,input().split()))\nans=0\nfor i in range(N):\n if V[i]-C[i] >0:\n ans+=V[i]-C[i]\nprint(ans)']
['Runtime Error', 'Accepted']
['s522654901', 's229011406']
[3060.0, 3060.0]
[17.0, 17.0]
[136, 154]
p03060
u194440952
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['# -*- coding: utf-8 -*-\nn = int(input())\nv = input()\nc = input()\nri = 0\nfor i in range(0,n):\n a = v[i] - c[i] \n if a > 0:\n ri += a\n else:\n pass\nprint(ri)', '# -*- coding: utf-8 -*-\nn = int(input())\nv = input().split()\nc = input().split()\nri = 0\nfor i in range(0,n):\n a = v[...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s437494208', 's475123369', 's984019689', 's257881590']
[2940.0, 2940.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0, 17.0]
[177, 191, 211, 223]
p03060
u197968862
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\n\ncal = []\nfor i in range(0,n):\n cal.append(v[i]-c[i])\ncal.sort(reverse=True)\nprint(cal)\nans = 0\nfor j in range(0,n):\n if cal[j] < 0:\n break\n ans += cal[j]\nprint(ans)', 'n = int(input())\nv = list(map(i...
['Wrong Answer', 'Accepted']
['s045395226', 's623370263']
[3064.0, 3060.0]
[17.0, 17.0]
[268, 176]
p03060
u201449687
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = map(int, input().split())\nvalues = [int(input()) for _ in range(N)]\ncosts = [int(input()) for _ in range(N)]\n# N = 3\n# values = [10, 2, 5]\n# costs = [6, 3, 4]\n# N = 4\n# values = [13, 21, 6, 19]\n# costs = [11, 30, 6, 15]\n# N = 1\n# values = [1,]\n# costs = [50,]\n\n\ndef calculate_maximum_gain(values, cos...
['Runtime Error', 'Accepted']
['s128439016', 's080990972']
[3060.0, 2940.0]
[17.0, 17.0]
[501, 499]
p03060
u201856486
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['import sys\n\n# import math\n# import itertools\nimport numpy as np\n# import collections\n\n"""Template"""\n\n\nclass IP:\n \n\n def __init__(self):\n self.input = sys.stdin.readline\n\n def I(self):\n \n return int(self.input())\n\n def S(self):\n \n return self.input(...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s056118430', 's131535586', 's632418823', 's826804284']
[12096.0, 12632.0, 21236.0, 12424.0]
[149.0, 151.0, 325.0, 148.0]
[4812, 4813, 4812, 146]
p03060
u213401801
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=map(int,input().split())\nxlist=[]\nylist=[]\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nfor i in range(n):\n if v[i]>c[i]:\n xlist.append(v[i])\n ylist.append(c[i])\nans=sum(xlist)-sum(ylist)\nprint(ans)', 'n=int(input())\nxlist=[]\nylist=[]\nv=list(map(int,input().split()))\nc=list...
['Runtime Error', 'Accepted']
['s486833818', 's241317396']
[3064.0, 3064.0]
[20.0, 17.0]
[228, 222]
p03060
u215315599
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n \nsumV = 0\nsumC = 0\nmaxi = 0\nfor i in range(n):\n sumV += v[i]\n sumC += c[i]\n maxi = max(sumV-sumC,maxi)\nprint(maxi)', 'n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().spli...
['Wrong Answer', 'Accepted']
['s299617827', 's035137711']
[3064.0, 3060.0]
[17.0, 17.0]
[218, 183]
p03060
u225627575
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = 0\nV = []\nC = []\n \ni = 0\nans = 0\n\nstr = input()\nN = int(str)\n \nstr = input().split()\nwhile i < N:\n V.append(int(str[i]))\n i = i+1\n \ni=0\nstr = 0\nstr = input().split()\nwhile i < N:\n C.append(int(str[i]))\n i = i+1\n \nwhile i<N:\n if V[i] > C[i]:\n ans = ans + V[i] - C[i]\n \n \npri...
['Wrong Answer', 'Runtime Error', 'Runtime Error', 'Wrong Answer', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Time Limit Exceeded', 'Accepted']
['s200553715', 's278619687', 's400275297', 's552502211', 's664981067', 's674114972', 's697629257', 's932230752', 's506773023']
[3064.0, 3064.0, 2940.0, 3064.0, 2940.0, 2940.0, 2940.0, 3064.0, 3064.0]
[17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 2104.0, 17.0]
[298, 282, 211, 251, 241, 302, 212, 313, 312]
p03060
u227429529
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['import itertools\nlv = []\nlc = []\ndiff = []\nfor i in range(1,n+1):\n for p in itertools.combinations(v,i):\n lv.append(sum(p))\n for p in itertools.combinations(c,i):\n lc.append(sum(p))\nfor i in range(len(lv)):\n diff.append(lv[i]-lc[i])\nprint(0 if max(diff)<0 else max(diff))', 'n = int(i...
['Runtime Error', 'Accepted']
['s485522503', 's102099755']
[3064.0, 3060.0]
[18.0, 17.0]
[294, 162]
p03060
u228592109
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = input()\na = [input() for i in range(N)]\nb = [input() for i in range(N)]\n\nsum = 0\n\nfor i in range(N):\n if a[i] > b[i]:\n sum += a[i] -b[i]\n\nprint(sum)', 'N = int(input())\na = input().split()\nb = input().split()\n\nsum = 0\n\nfor i in range(N):\n if int(a[i]) > int(b[i]):\n sum += int(a[i]) -int(...
['Runtime Error', 'Accepted']
['s081467783', 's216945913']
[3060.0, 3060.0]
[17.0, 17.0]
[156, 157]
p03060
u230416699
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = map(int, input().split())\nC = map(int, input().split())\n\nN = []\nfor i, v in enumerate(V):\n N.append(V[i]-C[i])\n\nN.sort(reverse=True)\n\nresult = 0\nfor n in N:\n if 0<n:\n result += n\n else:\n break\n\nprint(result)', 'N = int(input())\nV = map(int, input().split()...
['Runtime Error', 'Runtime Error', 'Accepted']
['s177773073', 's401502784', 's303627204']
[3064.0, 3064.0, 3064.0]
[17.0, 17.0, 17.0]
[251, 251, 269]
p03060
u231905444
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\narr=list(map(int,input().split()))\narr2=lisT9map(int,input().split())\nans=0\nfor i in range(n):\n\tif(arr[i]-arr2[i]>0):\n\t\tans+=arr[i]-arr2[i]\n\n\t#ans=max(ans,arr[i]-arr2[i])\nprint(ans)\n', 'n=int(input())\narr=list(map(int,input().split()))\narr2=lisT9map(int,input().split())\nans=0\nfor i in...
['Runtime Error', 'Runtime Error', 'Accepted']
['s736762174', 's937190368', 's800992629']
[3060.0, 3060.0, 2940.0]
[18.0, 17.0, 17.0]
[197, 197, 198]
p03060
u233183615
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nC = list(map(int, input().split()))\nV = list(map(int, input().split()))\nsum = 0\nfor i in range(N):\n if V[i] > C[i]:\n sum += V[i] - C[i]\nprint(sum)', 'N = int(input())\nC = list(map(int, input().split()))\nV = list(map(int, input().split()))\nsum = 0\nfor i in range(N):\n sum += max(0, V...
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s230402824', 's868928833', 's276956437']
[3060.0, 3060.0, 3060.0]
[17.0, 17.0, 18.0]
[167, 155, 155]
p03060
u235655730
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\n\nW = [v-c for v, c in zip(V, C) if (v-c) > 0]\nprint(sum(W)', 'N = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\n\nW = [v-c for v, c in zip(V, C) if (v-c) > 0]\nprint(sum(W))']
['Runtime Error', 'Accepted']
['s675630149', 's739785495']
[2940.0, 3060.0]
[17.0, 17.0]
[147, 148]
p03060
u238801602
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = input()\nV = input().split()\nC = input().split()\nret_X_Y = 0\n\nfor i in range(len(V)):\n if (V[i] - C[i]) > 0:\n ret_X_Y += V[i] - C[i]\nprint(ret_X_Y)', 'N = input()\nV = input().split()\nC = input().split()\nret_X_Y = 0\nV = [int(i) for i in V]\nC = [int(i) for i in C]\nfor i in range(len(V)):\n ...
['Runtime Error', 'Accepted']
['s689722347', 's672767224']
[2940.0, 3064.0]
[17.0, 17.0]
[160, 207]
p03060
u239301277
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['# -*- coding: utf-8 -*-\n\nN = int(input())\nV = map(int, input().split())\nC = map(int, input().split())\n\ngain = 0\nfor i in range(0,N):\n if(V[i]>C[i]):\n gain += V[i] - C[i]\n\nprint(gain)', 'n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nans=0\nfor i in range(n):\n...
['Runtime Error', 'Accepted']
['s090035912', 's840382062']
[3060.0, 3060.0]
[18.0, 18.0]
[192, 151]
p03060
u245931985
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['X = [0 for i in range(2**N)]\nY = [0 for i in range(2**N)]\nZ = [0 for i in range(2**N)]\n\nfor i in range(2**N):\n select = []\n if i > 0:\n temp = i\n for n in reversed(range(1, N+1)):\n if temp - 2**(n-1) >= 0:\n temp = temp - 2**(n-1)\n select.append(n-...
['Runtime Error', 'Accepted']
['s520790157', 's619099145']
[3064.0, 3060.0]
[18.0, 18.0]
[475, 181]
p03060
u252964975
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nX=list(map(int, input().split()))\nY=list(map(int, input().split()))\nZ=X-Y\nZ=Z[Z>0]\nprint(sum(Z))', "import numpy as np\nN=int(input())\nX=list(map(int, input().split()))\nY=list(map(int, input().split()))\nZ=np.zeros(N)\nfor i in range(N):\n Z[i]=X[i]-Y[i]\nprint('{:.0f}'.format(sum(Z[np.where(Z>...
['Runtime Error', 'Accepted']
['s919869007', 's465304244']
[3060.0, 12488.0]
[18.0, 152.0]
[111, 197]
p03060
u256464928
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int,input()))\nc = list(map(int,input()))\n\ntotal_v = 0\n\nfor i in range(n-1)\n\tif v[i] - c[i] > 0:\n \ttotal_v += v[i] - c[i]\nprint(total_v)', 'n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\n\ntotal_v = 0\n\nfor i in range(n-1):\n if v...
['Runtime Error', 'Wrong Answer', 'Runtime Error', 'Accepted']
['s035402906', 's306556964', 's891152844', 's686937703']
[2940.0, 2940.0, 2940.0, 3060.0]
[17.0, 18.0, 18.0, 17.0]
[168, 187, 185, 186]
p03060
u259755734
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nX = []\nY = []\n\nfor x in map(int, input().split()):\n X.append(x)\n\nfor y in map(int, input().split()):\n Y.append(y)\n\nd_list = []\n\nfor i in range(N):\n d = X[i] - Y[i]\n if d > 0:\n d_list.append(d)\n\nif d_list:\n print(max(d_list) + min(d_list))\nelse:\n \xa0print(...
['Runtime Error', 'Accepted']
['s549066316', 's296280835']
[3060.0, 3064.0]
[17.0, 17.0]
[300, 150]
p03060
u260009060
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = [int(x) for x in input().split()]\nC = [int(x) for x in input().split()]\n\nXY = 0\n\nfor i in range(N):\n XY += np.maximum(0, V[i]-C[i])\n\nprint(XY)', '\nN = int(input())\nV = [int(x) for x in input().split()]\nC = [int(x) for x in input().split()]\n\nXY = 0\n\nfor i in range(N):\n if (V...
['Runtime Error', 'Accepted']
['s035830900', 's693600674']
[3060.0, 3060.0]
[18.0, 19.0]
[166, 181]
p03060
u265401619
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nlist_v=list(map(int, input().split()))\nlist_c=list(map(int, input().split()))\nlist_ans = list_v - list_c\nans = 0\nfor i in range(n):\n if list_ans[i] > 0:\n ans += list_ans[i]\nprint(ans)', 'n=int(input())\nlist_v=list(map(int, input().split()))\nlist_c=list(map(int, input().split()))\nans = 0\...
['Runtime Error', 'Accepted']
['s165399184', 's797459747']
[3060.0, 3060.0]
[17.0, 17.0]
[202, 195]
p03060
u270681687
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n# ■■■■■■■■■■■■■■■■■■■■■\n\nn = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n\nans = 0\nfor i in range(n):\n if v[i] - c[i] > 0:\n ans += v[i] + c[i]\n\nprint(ans)', '\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\nn = int(input()...
['Wrong Answer', 'Accepted']
['s727198650', 's755810077']
[3060.0, 2940.0]
[17.0, 17.0]
[3102, 2935]
p03060
u274045692
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\nc = []\nA = 0\nfor i in range (N):\n V[i] - C[i] > 0\n c.append(i)\nfor j in c:\n A += V[j] + C[j]\nprint(A)', 'N = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\nc = []\nA = 0...
['Wrong Answer', 'Accepted']
['s451207341', 's029140402']
[3060.0, 3060.0]
[17.0, 17.0]
[199, 207]
p03060
u278296307
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = input()\nlist_v = list(map(int, input.split()))\nlist_c = list(map(int, input.split()))\n\nmax_value = 0\n\nfor i in range(n):\n if list_v[i]>list_c[i]:\n max_value = max_value + (list_v[i]-list_c[i])\n \nprint(max_value)', 'n = int(input())\nlist_v = list(map(int, input().split()))\nlist_c = lis...
['Runtime Error', 'Accepted']
['s562037613', 's085716220']
[3060.0, 3060.0]
[17.0, 17.0]
[232, 233]
p03060
u282335165
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nv=map(int, input().split())\nc=map(int, input().split())\n\nvc=[v[i]-c[i] for i in range(n) if (v[i]-c[i]) > 0]\nprint(sum(vc))', 'n=int(input())\nv=list(map(int, input().split()))\nc=list(map(int, input().split()))\nvc=[(v[i]-c[i]) for i in range(n) if (v[i]-c[i]) > 0]\nprint(sum(vc))']
['Runtime Error', 'Accepted']
['s463863405', 's965656135']
[3060.0, 3060.0]
[17.0, 17.0]
[138, 151]
p03060
u283520984
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nV = list(int(i) for i in input().split()) \nC = list(int(i) for i in input().split()) \nS=[]\nfor i in range(N):\n\tS.append(V[i]-C[i])\nfor i in range(N):\n\tif S[i]>0:\n\t\tans=ans+S[i]\nprint(ans)', 'N=int(input())\nV = list(int(i) for i in input().split()) \nC = list(int(i) for i in input().split(...
['Runtime Error', 'Accepted']
['s455740670', 's440307199']
[3064.0, 3060.0]
[17.0, 17.0]
[202, 212]
p03060
u285121325
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\nprint(v,c)\nresult = 0\nfor i in range(n):\n if v[i] > c[i]:\n result += v[i] - c[i]\nprint(result)', 'N = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\nprint(sum([V[i] - C[i] for ...
['Wrong Answer', 'Accepted']
['s836827452', 's307096938']
[3060.0, 2940.0]
[17.0, 17.0]
[187, 148]
p03060
u305052967
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nlist1 = map(int,input().split())\nlist2 = map(int,input().split())\nx = 0\nfor i in range(N):\n x = list1[i] - list2[i]\n if x >> 0:\n y += x\nprint(y)', 'N = int(input())\nlist1 = []\nfor i in range(N):\n list1.append(int(input))\nlist2 = []\nfor i in range(N):\n list2.append(in...
['Runtime Error', 'Runtime Error', 'Accepted']
['s819679572', 's975089998', 's167199930']
[2940.0, 3060.0, 2940.0]
[17.0, 18.0, 17.0]
[175, 227, 172]
p03060
u306497037
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = list(map(int,input().split()))\nC = list(map(int,input().split()))\n\nanc = 0\nfor i in range(N):\n if V[i] > C[i]:\n anc = anc + (V[i]-C[i])\n\nprint(ans)', 'N = int(input())\nV = list(map(int,input().split()))\nC = list(map(int,input().split()))\n\nans = 0\nfor i in range(N):\n if V[i] > ...
['Runtime Error', 'Accepted']
['s036200282', 's791920456']
[3060.0, 3060.0]
[17.0, 17.0]
[172, 172]
p03060
u310108817
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n= int(input())\nv_list = [int(i) for i in input().split()]\nc_list = [int(i) for i in input().split()]\n\nfor _ in zip(v_list, c_list):\n if(v_list>=c_list):\n val = val + (v_list-c_list)\n\nprint(val)', 'n= int(input())\nv_list = [int(i) for i in input().split()]\nc_list = [int(i) for i in input().split()]\n\nv...
['Runtime Error', 'Runtime Error', 'Accepted']
['s337057341', 's950087107', 's068816316']
[2940.0, 3060.0, 3060.0]
[18.0, 17.0, 17.0]
[198, 207, 192]
p03060
u322185540
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['a = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split())) \nans = 0\n\nfor i in range(a):\n if v(i) >= c(i):\n ans += (v(i)-c(i))\n \nprint(ans)', 'a = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split())) \nans = 0\nfor i in range(a):\n ...
['Runtime Error', 'Accepted']
['s313416036', 's287293856']
[3060.0, 3060.0]
[17.0, 17.0]
[183, 173]
p03060
u325704929
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n\na = list(zip(v, c))\nt = 0\nfor i, m in a:\n p = m - i\n if p > 0:\n t += p\n\nprint(t)\n ', 'n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n\na = list(zip(v, c))\nt = 0\n...
['Wrong Answer', 'Accepted']
['s265927854', 's042215180']
[3064.0, 3060.0]
[18.0, 17.0]
[180, 181]
p03060
u326328575
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nV=list(map(int,input().split()))\nC=list(map(int,input().split()))\nprint(V)\nprint(C)\nans =0\nfor i in range(N):\n z = V[i]-C[i]\n if z>0:\n ans+=z\n \nprint(ans)', 'N=int(input())\nV=list(map(int,input().split()))\nC=list(map(int,input().split()))\nans =0\nfor i in range(N):\n z = V[i]-C[i...
['Wrong Answer', 'Accepted']
['s325625251', 's648360921']
[3060.0, 3060.0]
[17.0, 18.0]
[177, 159]
p03060
u327668449
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = input()\nv = input()\nv = v.split()\nc = input()\nc = c.split()\n\nVSubC = []\n\nfor index in range(n):\n heapq.heappush(VSubC, -(v[index] - c[index]))\n\nanswer = 0\nwhile(len(VSubC) > 0):\n item = heapq.heappop(VSubC)\n if (item < 0):\n answer -= item\n else:\n break\n\nprint(answer)', 'import heapq\n...
['Runtime Error', 'Accepted']
['s654386213', 's671559988']
[3064.0, 3064.0]
[17.0, 18.0]
[281, 310]
p03060
u329573160
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['from sys import stdin\n\nN = int(stdin.readline().rstrip())\ndata = [stdin.readline().rstrip().split() for _ in range(N)]\n\nprofit = []\nsum_profit = 0\n\nfor i in N:\n profit[i] = data[0][i] - data[1][i]\n if profit[i] > 0:\n sum_profit += profit[i]\n\nprint(sum_profit)', 'from sys import stdin\n\nN = ...
['Runtime Error', 'Runtime Error', 'Accepted']
['s234232773', 's493300150', 's585580860']
[3060.0, 3060.0, 3064.0]
[17.0, 18.0, 17.0]
[272, 272, 294]
p03060
u329731898
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nV=list(map(int,input().split))\nC=list(map(int,input().split))\nmouke=0\nfor i in range(N):\n adv=V[i]-C[i]\n if adv>0:\n mouke+=adv:\nprint(mouke)', 'N=int(input())\nV=list(map(int,input().split))\nC=list(map(int,input().split))\nmouke=0\nfor i in range(N):\n adv=V[i]-C[i]\n if adv...
['Runtime Error', 'Runtime Error', 'Accepted']
['s274467757', 's278575106', 's268855568']
[2940.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0]
[168, 167, 171]
p03060
u330314953
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['x = []\n\nfor i in range(n):\n x.append(int(v[i]-c[i]))\n\nx.sort()\n\ny = 0\n\ni = n-1\n\nwhile x[i] >= 0 and i >= 0 :\n y += x[i]\n i += -1\n\nprint(y)', 'n = int(input())\nv = [int(i) for i in input().split()]\nc = [int(j) for j in input().split()]\n\nx = []\n \nfor i in range(n):\n x.append(int(v[i]-c...
['Runtime Error', 'Accepted']
['s473311366', 's772443587']
[2940.0, 3064.0]
[17.0, 17.0]
[147, 247]
p03060
u331464808
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = map(int,input().split())\nc = map(int,input().split())\nmaxbenefit = 0\nfor i in range(n):\n if c[i]<v[i]:\n maxbenefit += v[i]-c[i]\nprint(maxbenefit)', 'n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\nmaxbenefit = 0\nfor i in range(n):\n i...
['Runtime Error', 'Accepted']
['s819644611', 's797027589']
[3060.0, 3060.0]
[17.0, 17.0]
[176, 188]
p03060
u334260611
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
["N = input()\nV = input().split(' ')\nC = input().split(' ')\n\nmax = -1000\nfor value, cost in zip(V, C):\n value_int = int(value)\n cost_int = int(cost)\n if(max < value_int - cost_int):\n max = value_int - cost_int\n\nprint(max)", "N = input()\nV = input().split(' ')\nC = input().split(' ')\n\nmax =...
['Wrong Answer', 'Accepted']
['s382352028', 's183077724']
[3060.0, 3060.0]
[17.0, 17.0]
[235, 230]
p03060
u344030307
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split())\n\nm = 0\n\nfor i in range(len(v)):\n if v[i] > c[i]:\n m += v[i] - c[i]\n\nprint(m)', 'n = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n\nm = 0\n\nfor i in range(len(v)):\n if v[i...
['Runtime Error', 'Accepted']
['s495836856', 's097580888']
[8952.0, 9164.0]
[24.0, 24.0]
[168, 169]
p03060
u345483150
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['v=list(map(int, input().split()))\nc=list(map(int, input().split()))\nn=int(input())\ns=0\nfor i in range(n):\n if v[i]-c[i]>0:\n s=s+v[i]-c[i]\n else:\n continue\nprint(s)', 'v, c=list(map(int, input().split()))\nn=len(v)\nn=len(c)\ns=0\nfor i in range(n):\n if v[i]-c[i]>0:\n s=s+v[i]-c[i]\nprint(s)', 'v...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s560355074', 's588273150', 's679228529', 's770923057', 's893236469', 's571630864']
[2940.0, 2940.0, 2940.0, 2940.0, 2940.0, 3060.0]
[17.0, 17.0, 17.0, 17.0, 17.0, 17.0]
[171, 122, 119, 140, 188, 189]
p03060
u346629192
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = list(map(int,input().split()))\nC = list(map(int,input().split()))\na = 0\nfor i in range(N):\n a += abs(V[i]-C[i])\nprint(a)', 'N = int(input())\nV = list(map(int,input().split()))\nC = list(map(int,input().split()))\na = 0\nfor i in range(N):\n if V[i] > C[i]:\n a += V[i]-C[i]\npr...
['Wrong Answer', 'Accepted']
['s379123995', 's825277523']
[2940.0, 3060.0]
[18.0, 17.0]
[144, 163]
p03060
u347640436
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = [int(input()) for _ in range(n)]\nc = [int(input()) for _ in range(n)]\nresult = 0\nfor i in range(n):\n if v[i] > c[i]:\n result += v[i] - c[i]\nprint(result)\n', 'n = int(input())\nv = [int(e) for e in input().split()]\nc = [int(e) for e in input().split()]\nresult = 0\nfor i in range(n):\...
['Runtime Error', 'Accepted']
['s443024899', 's542034362']
[3056.0, 2940.0]
[19.0, 17.0]
[179, 181]
p03060
u348432940
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['def calculate_max(Ans, value):\n temp = Ans\n if (Ans + value) > Ans:\n temp += value\n if tmep < 0 :\n temp = 0\n return temp\n# input processing \nN = int(input())\nValue = map(int, input().split())\nCost = map(int, input().split())\n# profit calculation\nProfit = [Value[i] - Cost[i] for i...
['Runtime Error', 'Accepted']
['s233328947', 's906965352']
[3064.0, 3064.0]
[17.0, 17.0]
[429, 441]
p03060
u348868667
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nH = list(map(int,input().split()))\ncount = 1\nfor i in range(1,N):\n if max(H[:i]) <= H[i]:\n count += 1\nprint(count)', 'N = int(input())\nV = list(map(int,input().split()))\nC = list(map(int,input().split()))\ntmp = list()\nfor i in range(N):\n if V[i] - C[i] > 0:\n tmp.append...
['Wrong Answer', 'Accepted']
['s842339997', 's888184362']
[2940.0, 3060.0]
[17.0, 17.0]
[141, 188]
p03060
u357218223
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['# coding: utf-8\nN = int(input())\nV = list(map(int,input().split()))\nC = list(map(int,input().split()))\nans = 0\nfor i in [ V[_] - C[_] for _ in range(N)]:\n if i> 0:\n ans+=j\nprint(ans)', 'N = int(input())\nVC = [list(map(int,input().split())) for _ in range(2) ] \nans = 0\nfor i in [ VC[0][_] - VC[1][...
['Runtime Error', 'Accepted']
['s079640325', 's612473747']
[3060.0, 3060.0]
[17.0, 17.0]
[192, 172]
p03060
u358791207
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = [int(i) for i in input().split()]\nC = [int(i) for i in input().split()]\n\nsum = 0\nfor i in range(N):\n if V[i] > C[i]:\n sum += V[i]\n \nprint(sum)', 'N = int(input())\nV = [int(i) for i in input().split()]\nC = [int(i) for i in input().split()]\n\nsum = 0\nfor i in range(N):\n if V[i...
['Wrong Answer', 'Accepted']
['s415983632', 's841762857']
[3060.0, 2940.0]
[17.0, 17.0]
[170, 178]
p03060
u360090862
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N=int(input())\nV=[int(i) for i in input().split()]\nC=[int(i) for i in input().split()]\nres=0\nfor vv cc in zip(V,C):\n if vv-cc>0:\n res=res+vv-cc\nprint(res)', 'N=int(input())\nV=[int(i) for i in input().split()]\nC=[int(i) for i in input().split()]\nres=0\nfor vv,cc in zip(V,C):\n if vv-cc>0:\n res=res+v...
['Runtime Error', 'Accepted']
['s690271520', 's845148334']
[2940.0, 2940.0]
[17.0, 17.0]
[158, 158]
p03060
u361826811
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['#include <stdio.h>\n\n\nusing namespace std;\ntypedef long long ll;\n\nint main()\n{\n int N, ans = 0;\n vector<int> V(N), C(N);\n scanf("%d", &N);\n for (int i = 0; i < N; i++)\n {\n scanf("%d", V.at(i));\n }\n for (int i = 0; i < N; i++)\n {\n scanf("%d", C.at(i));\n }\n\n ...
['Runtime Error', 'Accepted']
['s789173594', 's191033845']
[2940.0, 3060.0]
[17.0, 20.0]
[491, 366]
p03060
u363836311
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nv=list(map(int, input().split()))\nc=list(map(int, input().split()))\nd=0\nfor i in range(n):\n tmp=v[i]-c[i]\n if tmp>0:\n d+=tmp\nprint(tmp)', 'n=int(input())\nv=list(map(int, input().split()))\nc=list(map(int, input().split()))\nd=0\nfor i in range(n):\n tmp=v[i]-c[i]\n if tmp>0:\n d+=tmp...
['Wrong Answer', 'Accepted']
['s475226913', 's981237802']
[3060.0, 2940.0]
[18.0, 17.0]
[155, 154]
p03060
u363992934
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['input();\nValues = list(map(int, input().split()))\nCosts = list(map(int, input().split()))\ntotal = 0\nfor (value, cost) in zip(Values, Costs):\n if value > cost:\n total = value - cost\n\nprint(total)', 'input()\nValues = list(map(int, input().split()))\nCosts = list(map(int, input().split()))\ntotal = 0\nfor (...
['Wrong Answer', 'Accepted']
['s532675772', 's413466928']
[2940.0, 2940.0]
[17.0, 17.0]
[198, 208]
p03060
u364439209
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['inputs = input().split("\\n")\nN = int(inputs[0])\nV = list(map(int, inputs[1].split(" ")))\nC = list(map(int, inputs[2].split(" ")))\nZ = 0\nfor v, c in zip(V, C):\n if v-c>0: z += v-c\nprint(Z)', 'inputs = input().split("\\n")\nN = int(inputs[0])\nV = list(map(int, inputs[1]))\nC = list(map(int, inputs[2]))\nZ =...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s263224009', 's279880236', 's563033715', 's600183703']
[3060.0, 3060.0, 3060.0, 2940.0]
[17.0, 18.0, 17.0, 17.0]
[190, 168, 190, 155]
p03060
u369630760
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = input().split()\nC = input().split()\ncost = []\nx = 0\nfor i in range(N):\n cost.append(int(V[int(i)]) - int(C[int(i)]))\nprint(cost)\nprint(sorted(cost,reverse=True))\nfor i in range(N):\n if cost[i] > 0:\n x = x + int(cost[i])\nprint(x)', 'N = int(input())\nV = input().split()\nC...
['Wrong Answer', 'Accepted']
['s568591609', 's385331593']
[3060.0, 3060.0]
[17.0, 17.0]
[262, 217]
p03060
u370576244
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nb = list(input().split())\nc = list(input().split())\nr=0\nfor i in range(n):\n if b[i]-c[i]>0:\n r = r + b[i] - c[i]\n \nprint(r)', 'n = int(input())\nb = list(map(int,input().split()))\nc = list(map(int,input().split()))\nr=0\nfor i in range(n):\n if b[i]-c[i]>0:\n r = r + b[i] - c[i]\n...
['Runtime Error', 'Accepted']
['s097325711', 's030362204']
[3064.0, 2940.0]
[17.0, 18.0]
[147, 166]
p03060
u371467115
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\ncnt=0\nfor _ in range(n):\n if v[i]-c[i]>0:\n cnt+=v[i]-c[i]\nprint(cnt)', 'n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\ncnt=0\nfor i in range(n):\n if v[i]-c[i]>0:\n cnt+=v[i]-c[i]\nprin...
['Runtime Error', 'Accepted']
['s043470619', 's596156990']
[3060.0, 3060.0]
[17.0, 17.0]
[153, 153]
p03060
u373047809
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = [map(int, input().split())]\nc = [map(int, input().split())]\nprint(sum([max(v[i] - c[i], 0) for i in range(n)]))', 'n, *d = map(int, open(0).read().split())\nprint(sum([max(d[i] - d[i+n], 0) for i in range(n)]))']
['Runtime Error', 'Accepted']
['s202298699', 's998986855']
[3060.0, 2940.0]
[18.0, 17.0]
[132, 94]
p03060
u374146618
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['import itertools\nimport numpy as np\n\nN = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\n\nans = 0\nfor k in range(1, N+1):\n chosen = list(itertools.combinations(range(N), k))\n for a in range(np.shape(chosen)[0]):\n X = 0\n Y = 0\n for b in range...
['Wrong Answer', 'Accepted']
['s970632331', 's691001134']
[14420.0, 13708.0]
[2108.0, 174.0]
[483, 171]
p03060
u375282392
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = map(int,input().split())\nc = map(int,input().split())\n\n\ngetsum = 0\nfor i in range(n):\n\tprofit = v[i]-c[i]\n\tif profit > 0:\n\t\tgetsum += profit\n\t\t\n\nprint(getsum)', 'n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\n\n\ngetsum = 0\nfor i in ra...
['Runtime Error', 'Accepted']
['s274179627', 's987532179']
[2940.0, 3060.0]
[17.0, 17.0]
[179, 191]
p03060
u390170391
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\na = list(map(int,input().split))\nb = list(map(int,input().split))\nc = 0\n\nfor i in range(0,n):\n if a[i] > b[i]:\n c = c + a[i] - b[i]\n else:\n continue\n \nprint(c)\n', 'n = int(input())\na = []\nb = []\nc = 0\nfor _ in range(n):\n a.append(int(input()))\nfor _ in range(n):\n b.app...
['Runtime Error', 'Runtime Error', 'Accepted']
['s222799703', 's299137960', 's467878548']
[2940.0, 3060.0, 2940.0]
[17.0, 17.0, 17.0]
[188, 222, 192]
p03060
u392938961
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nx =list(map(int, input().split()))\ny =list(map(int, input().split()))\ndiff = [x[i]-y[i] for i in range(n)]\nnum = 0\nfor d in diff:\n if(d > 0):\n num += d', 'n = int(input())\nx =list(map(int, input().split()))\ny =list(map(int, input().split()))\ndiff = [x[i]-y[i] for i in range(n)]\nn...
['Wrong Answer', 'Accepted']
['s150227562', 's538207503']
[3060.0, 3060.0]
[18.0, 17.0]
[178, 189]
p03060
u399721252
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\n\nv_list = [ int(v) for v in input().split() ]\nc_list = [ int(v) for v in input().split() ]\n\nans = sum([ max( 0, (v_list[i]-c_list[i]) ) for i in range(n) ])', 'n = int(input())\n\t\nv_list = [ int(v) for v in input().split() ]\nc_list = [ int(v) for v in input().split() ]\n\t\nans = sum([ max( 0...
['Wrong Answer', 'Accepted']
['s191933081', 's528434019']
[3060.0, 3060.0]
[17.0, 17.0]
[173, 187]
p03060
u402467563
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nH = list(map(int, input().split()))\ncount = 0\nM = 0\nfor i in range(N):\n if H[i]>=M:\n count += 1\n M = H[i]\nprint(count)', 'N = int(input())\nH = list(map(int, input().split()))\ncount = 0\nM = 0\nfor i in range(N):\n print(H[i])\n if H[i]>=M:\n count += 1\n M = H[i]\nprint(count...
['Wrong Answer', 'Wrong Answer', 'Accepted']
['s057858463', 's982724040', 's811035445']
[2940.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0]
[142, 156, 165]
p03060
u405353249
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['\ndef problem():\n N = int(input())\n V = list(map(int, input().split()))\n C = list(map(int, input().split()))\n\n print(algorithm(N, V, C))\n\n\ndef algorithm(N: int, V: List[int], C: List[int]):\n indices = list(filter(lambda i: V[i] - C[i] > 0, list(range(0, N))))\n\n sum = 0\n for i in indic...
['Runtime Error', 'Accepted']
['s440129508', 's665946125']
[3060.0, 3064.0]
[17.0, 17.0]
[363, 334]
p03060
u408375121
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\nR = []\nfor i range(N):\n R.append(V[i] - C[i])\ncost = 0\nfor r in R:\n if r > 0:\n cost += r\nprint(cost)\n ', 'N = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\nR = []\nfor i ...
['Runtime Error', 'Runtime Error', 'Accepted']
['s095212783', 's890546405', 's428184722']
[2940.0, 2940.0, 3060.0]
[17.0, 17.0, 17.0]
[197, 206, 209]
p03060
u426649993
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['# -*- coding: utf-8 -*-\n\nN = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input().split()))\n\ngain = 0\nfor i in range(0,N):\n if(V>C):\n gain += V[i] - C[i]\n\nprint(gain)', '# -*- coding: utf-8 -*-\n\nN = int(input())\nV = list(map(int, input().split()))\nC = list(map(int, input...
['Wrong Answer', 'Accepted']
['s034650236', 's335315291']
[3060.0, 3060.0]
[17.0, 17.0]
[198, 204]
p03060
u430223993
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
["jewel = [i for i in input().split('\\n')]\nvalue = [int(i) for i in jewel[1].split()]\ncost = [int(i) for i in jewel[2].split()]\ndiff = [i-j for i,j in zip(value, cost)]\nprice = 0\nfor i in sorted(diff):\n if i>0:\n price += i\n\nprint(price)", 'jewel = int(input())\nvalue = [int(i) for i in input().split...
['Runtime Error', 'Accepted']
['s056566469', 's247881243']
[3064.0, 3060.0]
[17.0, 17.0]
[244, 222]
p03060
u437215432
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['# ABC125B\n\nn = int(input())\nv = list()\nc = list(map(int, input().split()))\nx = 0\ny = 0\nfor i in range(n):\n v, c = map(int, input().split())\n if v > c:\n x += v\n y += c\nprint(abs(x - y))\n', '# ABC125B\n\nn = int(input())\nx = 0\ny = 0\nfor i in range(n):\n v, c = map(int, input().spl...
['Runtime Error', 'Runtime Error', 'Accepted']
['s250989351', 's909392846', 's746540869']
[3060.0, 2940.0, 3060.0]
[17.0, 17.0, 18.0]
[205, 158, 197]
p03060
u439063038
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n\nans = 0\nfor _ in range(N):\n if v[i] > c[i]:\n ans += v[i] - c[i]\nprint(ans)', 'N = int(input())\nv = list(map(int, input().split()))\nc = list(map(int, input().split()))\n\nans = 0\nfor i in range(N):\n if v[...
['Runtime Error', 'Accepted']
['s954296970', 's570947496']
[9036.0, 9120.0]
[24.0, 27.0]
[174, 174]
p03060
u443151804
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nl=map(int,input().split())\nm=map(int,input().split())\ndef f(x):\n\treturn l[x]-m[x]\nprint(sum([f(i) for i in range(n) if f(i)>0]))', 'n=int(input())\nl=list(map(int,input().split()))\nm=list(map(int,input().split()))\ndef f(x):\n\treturn l[x]-m[x]\nprint(sum([f(i) for i in range(n) if f(i)>0]))']
['Runtime Error', 'Accepted']
['s914471678', 's751333663']
[3060.0, 3060.0]
[18.0, 17.0]
[143, 155]
p03060
u456198602
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = input()\nV = input().split(" ")\nC = input().split(" ")\n\nn = int(n)\nV_tmp = []\nfor v in V:\n V_tmp.append(int(v))\nV = V_tmp\nC_tmp = []\nfor c in C:\n C_tmp.append(int(v))\nC = C_tmp\nSA = []\nfor i in range(n):\n SA.append(C[i]-V[i])\nmax_ = 0\nfor i in range(n):\n if SA[i] >= 0:\n max_ +...
['Wrong Answer', 'Accepted']
['s646047861', 's692140112']
[3064.0, 3064.0]
[18.0, 17.0]
[318, 318]
p03060
u463655976
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['print(sum(max(int(x)- int(y), 0) for x, y in zip(input().split(), input().split())))', 'input()\nprint(sum(max(int(x)- int(y), 0) for x, y in zip(input().split(), input().split())))\n']
['Wrong Answer', 'Accepted']
['s706417238', 's860742726']
[2940.0, 2940.0]
[18.0, 17.0]
[84, 93]
p03060
u465903301
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nprint(sum([i for i in range(n) if v[i] > c[i]]))', 'n=int(input())\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\nprint(sum([v[i] - c[i] for i in range(n) if v[i] > c[i]]))']
['Wrong Answer', 'Accepted']
['s684529970', 's544954100']
[2940.0, 3060.0]
[17.0, 17.0]
[129, 139]
p03060
u466331465
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['N = int(input())\nv = [int(x) for x in input().split()]\nc = [int(x) for x in input().spplit()]\nans = [l-p for l,p in zip(v,c)]\nans1 = 0\nfor i in ans :\n ans1 += i if i>0 else 0\nprint(ans1)', 'N = int(input())\nv = [int(x) for x in input().split()]\nc = [int(x) for x in input().split()]\nans = [l-p for l,p in zi...
['Runtime Error', 'Accepted']
['s560226414', 's749264661']
[3060.0, 3060.0]
[17.0, 17.0]
[187, 186]
p03060
u472234259
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = [int(x) for x in input().split()]\nc = [int(x) for x in input().split()]\n\nans = 0\n\nfor i in range(n):\n if v[i] - c[i]:\n ans += v[i] - c[i]\nprint(ans) ', 'n = int(input())\nv = [int(x) for x in input().split()]\nc = [int(x) for x in input().split()]\n\nans = 0\n\nfor i in range(n):\n ...
['Wrong Answer', 'Accepted']
['s091190894', 's745904058']
[3060.0, 3060.0]
[18.0, 17.0]
[174, 178]
p03060
u481026841
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\ncnt = 0\nfor i in range(len(n)):\n if v[i] > c[i]:\n cnt += (v[i] - c[i])\n else:\n cnt += 0\nprint(cnt) \n', 'n = int(input())\nv = map(int,input().split())\nc = map(int,input().split())\ncnt = 0\nfor...
['Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Runtime Error', 'Accepted']
['s267896633', 's369156353', 's491868182', 's673962457', 's682479604', 's689615286', 's794917458', 's934757674', 's965495419', 's979417758', 's644297700']
[2940.0, 3060.0, 3060.0, 3060.0, 3060.0, 3060.0, 3060.0, 3060.0, 2940.0, 3060.0, 3060.0]
[17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0, 17.0]
[214, 194, 186, 193, 192, 234, 202, 173, 215, 165, 173]
p03060
u483885886
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n = int(input())\nv = list(map(int,input().split())\nc = list(map(int,input().split())\nsum = 0\nfor i in range(n):\n if v[i] >c[i]:\n sum += v[i]-c[i]\nprint(sum)\n', 'n = int(input())\nv = list(map(int,input().split()))\nc = list(map(int,input().split()))\nsum = 0\nfor i in range(n):\n if v[i] >c[i]:\n...
['Runtime Error', 'Accepted']
['s718241028', 's037914523']
[2940.0, 2940.0]
[17.0, 17.0]
[166, 168]
p03060
u490623664
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['n=int(input(())\nv=[int(x) for x in input().split()]\nc=[int(x) for x in input().split()]\ns=0\nfor i in range(n):\n if v[i]>c[i]:\n s+=v[i]-c[i]\nprint(s)', 'n=int(input())\nv=[int(x) for x in input().split()]\nc=[int(x) for x in input().split()]\ns=0\nfor i in range(n):\n d=v[i]-c[i]\n if d>0:\n s+=d\nprin...
['Runtime Error', 'Accepted']
['s394975004', 's829430268']
[2940.0, 2940.0]
[17.0, 17.0]
[152, 151]
p03060
u490642448
2,000
1,048,576
There are N gems. The value of the i-th gem is V_i. You will choose some of these gems, possibly all or none, and get them. However, you need to pay a cost of C_i to get the i-th gem. Let X be the sum of the values of the gems obtained, and Y be the sum of the costs paid. Find the maximum possible value of X-Y.
['input()\nv=list(map(int,input().split())\nc=list(map(int,input().split())\na=[max(0,i-j) for i,j in zip(v,c)]\nprint(sum(a))', 'input()\nv=list(map(int,input().split()))\nc=list(map(int,input().split()))\na=[max(0,i-j) for i,j in zip(v,c)]\nprint(sum(a))\n']
['Runtime Error', 'Accepted']
['s562792158', 's249047352']
[8708.0, 9052.0]
[23.0, 27.0]
[120, 123]