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Title: python爬虫爬取APP并封装成API接口调用，使用flask-restful_app爬虫需要接囗吗?-CSDN博客 |
URL Source: https://blog.csdn.net/t8116189520/article/details/80179221 |
Markdown Content: |
#环境python3.6 |
\# 爬取APP 无忧借条 |
\# 通过用户账号密码爬取用户个人信息（我这账号密码已打码） |
爬虫部分代码 |
import hashlibimport timeimport urllib3import jsonheaders = {'Accept': ' */*', 'Accept-Encoding': 'gzip, deflate', 'Accept-Language': 'zh-CN,en-US;q=0.8','User-Agent': 'Mozilla/5.0 (Linux; Android 6.0.1; Redmi 3S Build/MMB29M; wv) AppleWebKit/537.36 (KHTML, like Gecko) Version/4.0 Chrome/53.0.2785.49 Mobile MQQBrow... |
运行完结果为json数据 |
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以上是爬虫部分，接下来先把API接口模板写好： |
from flask import Flask, gfrom flask_restful import reqparse, Api, Resourcefrom flask_httpauth import HTTPTokenAuthapp = Flask(__name__)api = Api(app)parser_put = reqparse.RequestParser()parser_put.add_argument("user", type=str, required=True, help="need user data")parser_put.add_argument("pwd", type=str, required=... |
def to_do(arg1, args2):return "this is info"class TodoList(Resource):def post(self):""" 添加一个新用户: curl http://127.0.0.1:5000/users -X POST -d "name=Brown&age=20" -H "Authorization: token fejiasdfhu" """ args = parser_put.parse_args() user = args['user'] pwd = args['pwd'] inf... |
接下来将爬虫部分镶嵌到到模板里面，完整代码如下： |
from flask import Flask, gfrom flask_restful import reqparse, Api, Resourcefrom flask_httpauth import HTTPTokenAuthimport hashlibimport timeimport urllib3import jsonapp = Flask(__name__)api = Api(app)parser_put = reqparse.RequestParser()parser_put.add_argument("user", type=str, required=True, help="need user data")... |
这是用postman测试工具模拟浏览器请求，得出的结果 |
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