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You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int mpow(int base, int exp); void solve() { long long int n; cin >> n; vector<long long int> v(n); vector<long long int> cnt(2 * n + 1, 0); for (long long int i = 0; i < (n); i++) { cin >> v[i]; cnt[v[i]]++; } vector<long long int> out; for (long lon...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t = int(input()) for _ in range(t): n = int(input()) l = list(map(int,input().split())) done = l[::] result = [] for i in range(n): val = l[i] flag = 0 for j in range(val+1,2*n+1): if(j not in done): done.append(j) result.extend([va...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t = int(input()) for _ in range(t): n = int(input()) a = [int(x) for x in input().split()] b = [None]*(2*n) c = set(a) d = set(range(1, 2*n+1)) for i in range(len(a)): x = a[i]+1 while x in c: x += 1 else: q = 2*i w = 2*i+1 ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): n = int(input()) b = list(map(int, input().split())) a = [-1] * 2 * n for x in range(1, 2 * n + 1): if x in b: i = 2 * b.index(x) a[i] = x else: i = -1 for j in range(0, 2 * n, 2): if a[j] != ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> int main() { int i, j, k, t, n, l, largest_element; scanf("%d", &t); int result[t][200]; int largest_element_array[t]; for (i = 0; i < t; i++) { int count = 0; scanf("%d", &n); largest_element = 2 * n; largest_element_array[i] = largest_element; int array_given[n];...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t = int(input()) for i in range(t): n = int(input()) b = list(map(int, input().split())) a = [0 for i in range(n+n)] vis = [0 for i in range(n+n+1)] for i in range(n): a[2*i] = b[i] vis[b[i]] = 1 ans = 1 for i in range(n): ok = 0 for j in range(b[i]+1, n+n+1): if vis[j] == 1: continue a[2*i+1] ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int f(map<int, int> &mp, int b[], int n, int l) { bool x = 0; for (int j = l + 1; j <= 2 * n; j++) { if (!mp[j]) { mp[j] = 1; x = 1; return j; } } return 0; } int main() { int T; cin >> T; while (T--) { int n; cin >> n; in...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int main() { int t; cin >> t; while (t--) { int n, p = 0; cin >> n; int a[210], b[105], maxm = 0; for (int i = 1; i <= n; i++) cin >> b[i]; bool g[210]; memset(g, false, sizeof(g)); for (int i = 1; i <= 2 * n; i += 2) a[i] = b[(i + 1) / 2],...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; const long long int mod = 1e9 + 7; const long long int INF = 1e18; void solve() { long long int n; cin >> n; long long int a[n], b[2 * n]; for (long long int i = 0; i < n; i++) cin >> a[i]; set<long long int> s; for (long long int i = 1; i < 2 * n + 1; i++) s.in...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
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You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
from sys import stdin, stdout from collections import Counter, defaultdict from itertools import permutations, combinations raw_input = stdin.readline pr = stdout.write mod=10**9+7 def ni(): return int(raw_input()) def li(): return map(int,raw_input().split()) def pn(n): stdout.write(str(n)+'\n') def...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for t in range(int(input())): n = int(input()) b = list(map(int,input().split())) a = [0]*(2*n+1) res = [] f = True for i in b: a[i] = 1 for i in b: # print("bv",i) res.append(i) val = 0 # print("A",a) for j in range(i,2*n+1): if a[...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): n=int(input()) b=list(map(int,input().split())) d={} for i in range(1,2*n+1): d[i]=1 for i in b: d[i]=0 a=[] for i in b: a.append(i) z=i for j in range(z+1,2*n+1): if d[j]: z=j d...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
from sys import stdin input = stdin.readline def mp():return map(int,input().split()) def it():return int(input()) for _ in range(it()): n=it() l=list(mp()) v=[] flag=0 for i in range(n): v.append(l[i]) k=l[i] while k in v or k in l: k+=1 if k>2*n: # print(-1) flag=1 break v.append(k) ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import sys #input=sys.stdin.readline t=int(input()) while t: t-=1 n=int(input()) b=list(map(int,input().split())) l=[i for i in range(1,2*n+1) if i not in b] ans=[] k=0 for i in range(n): c=0 ans.append(b[i]) for j in range(n): if l[j]>b[i] and l[j] not in...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; vector<int> solve(int N, const vector<int>& B) { vector<int> pos(2 * N + 1, -1); for (int i = 0, _n = (N); i < _n; ++i) { int x = B[i]; pos[x] = i; } set<int> missing; for (int n = (1), _b = (2 * N); n <= _b; ++n) { if (pos[n] < 0) missing.insert(n); ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.HashSet; import java.util.Scanner; public class B16 { static int max = 11; public static void main(String[] args) { Scanner nik = new Scanner(System.in); int t = nik.nextInt(); StringBuilder sb = new StringBuilder(); for (int i = 0; i < t; i++) { } A: while (t-- > 0) { int n = ni...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0); int q; cin >> q; for (; q > 0; q--) { int n; cin >> n; int b[n]; bool mk[n + n + 10]; for (int i = 0; i <= n + n; i++) mk[i] = 0; for (int ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): n=int(input()) b=[int(x) for x in input().split()] a=[] for i in range(n): a.append(b[i]) k=b[i] while(k in a or k in b):k+=1 if(k>2*n):print(-1);break a.append(k) else: print(*a)
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; long long INF = 1 << 28; const double pi = acos(-1.0); int fx[] = {1, -1, 0, 0}; int fy[] = {0, 0, 1, -1}; int dir[4][2] = {1, 0, -1, 0, 0, -1, 0, 1}; int knight[8][2] = {1, 2, 1, -2, 2, 1, 2, -1, -1, 2, -1, -2, -2, 1, -2, -1}; const long double EPS = 1e-7; long long gcd(lo...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; const long long mod = 1e9 + 7; long long power(long long a, long long b, long long m = mod) { long long x = 1; while (b) { if (b & 1) { x = 1ll * x * a % m; } a = 1ll * a * a % m; b /= 2; } return x; } const int N = 1e5 + 9; signed main() { i...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.*; import java.io.*; public class c { static boolean debug = false; public static void main(String[] args) { FS in = new FS(System.in); PrintWriter out = new PrintWriter(System.out); int numT = in.nextInt(); for(int t=0; t<numT; t++) { int n = in.nextInt(); int[]...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> const long long MX = 1e18, N = 1e4 + 10; const double PI = 3.141592653589793238; using namespace std; long long n, m, ans[N], a[N], t; map<int, int> mp; int main() { cin >> t; while (t--) { cin >> n; bool yes = true; for (int i = 1; i <= n; ++i) { cin >> a[i]; ++mp[a...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t = int(input()) while t: t += -1 n = int(input()) l = list(map(int, input().split())) check = [0] * ((2 * n) + 1) ans = [0] * (2 * n) for i in range(0, 2 * n, 2): ans[i] = l[i // 2] check[ans[i]] = 1 # print(ans) c = 1 for i in range(0, 2 * n, 2): chintu = 0 ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
from bisect import bisect_right import sys input = sys.stdin.readline for ti in range(int(input().strip())): n = int(input().strip()) b = [int(x) for x in input().strip().split()] n = list(range(1, 2*n+1)) ans = [] for bi in b: n.remove(bi) for bi in b: ai = bisect_right(n, bi) ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.io.BufferedOutputStream; import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.StringTokenizer; public class Round623C { public static void solve() { int t = s.nextInt(); outer:while(t-- >0) { int n = s.nextInt(); int[] arr = new int[n]; ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
# cook your dish here n=int(input()) while(n): n=n-1 a=int(input()) b=list(map(int,input().split())) c=[True for x in range(2*a+1)] for x in b: c[x]=False ans=[] get=True for i in range(a): flag=False k=b[i] while(k<2*a+1): if c[k]==True: ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; const int maxn = 2e2 + 10; bool mark[maxn]; int ans[maxn]; int main() { ios::sync_with_stdio(false); int t; cin >> t; while (t--) { bool flag = true; memset(mark, false, sizeof(mark)); int n; cin >> n; for (int i = 0; i < n; i++) { cin >> a...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import sys from collections import Counter def solve(N, B): counts = Counter(B) if any(v > 1 for v in counts.values()): return -1 # Want smallest permutation that is element-wise greater than B C = [] for x in range(1, 2 * N + 1): if x not in counts: C.append(x) # ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int Search(vector<long long int> v1, long long int x1) { long long int j; for (j = 0; j < v1.size(); j++) { if (x1 == v1[j]) { return j; } else { continue; } } return -1; } int Search2(long long int v[], long long int x, long long int n) { ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int main() { long long int b, c = 0, sum = 0, i = 0, s, j, n, d = 0, q = 0, e, f, t = 0, x, h, l = 0, k = 0, x1, x2, y1, y2, m; cin >> t; vector<long long int> v; vector<long long int> a; vector<long long int> z; map<long long int, long long i...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; const long long mod = 1e9 + 7; const long long inf = 1e18; const long long dx[8] = {-1, 0, 1, 0, -1, 1, 1, -1}, dy[8] = {0, 1, 0, -1, 1, 1, -1, -1}; const long long kdx[8] = {-2, -1, 1, 2, 2, 1, -1, -2}, kdy[8] = {1, 2, 2, 1, -1, -2, -2, -1};...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; bool compare(string &s1, string &s2) { return s1.size() < s2.size(); } string lower(string second) { transform(second.begin(), second.end(), second.begin(), ::tolower); return second; } string upper(string second) { transform(second.begin(), second.end(), second.begin...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.*; public class RestoringPermutation { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while(t-->0){ int n = sc.nextInt(); int b[] = new int[n]; int a[] = new int[n*2]; int r[] = new int[n*2]; boolean bool = false; for(int i...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t = int(input()) for i in range(t): n = int(input()) b = list(map(int,input().split())) l = [i+1 for i in range(2*n)] q = sorted(b) ans = True ansList = [] count = 0 if q[0]!=1: print(-1) continue for i in range(1,2*n-1): if i not in q and i+1 not in q: if count == 0: ans = False break else...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): l = int(input()) arr = [int(h) for h in input().strip().split(' ')] newarr = [] flag=True for i in range(2*l): if i%2==0: newarr.append(arr[i//2]) else: num = newarr[-1] while num<=2*l: if (num in newar...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.io.*; import java.util.*; public class C implements Runnable { boolean judge = false; FastReader scn; PrintWriter out; String INPUT = ""; void solve() { int t = scn.nextInt(); here: while(t-- > 0) { int n = scn.nextInt(); int[] b = scn.nextIntArray(n); int[] a = new int[2 * n]; TreeSe...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
def solve(m, b): d=dict() y=dict() for i in range(m): d[b[i]]=0 for k in d.keys(): x=k+1 while x in d.keys() or x in y.keys(): x+=1 if (x>2*m): return -1 d[k]=x y[x]=k for i in range(m): print(b[i], d[b[i]]...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
T=int(input()) for i in range(T): N=int(input()) l=[0]*(N*2+1) f=0 c=0 b=[int(x) for x in input().split()] for j in range(0,len(b)): c=c+1 l[c]=b[j] c=c+1 if b.count(b[j]+1)==1 or l.count(b[j]+1)==1: m=b[j]+1 while(True): m=...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
I=input for _ in[0]*int(I()): I();b=*map(int,I().split()),;s={*range(2*len(b)+1)}-{*b};a=[];i=1 try: for x in b:y=min(s-{*range(x)});s-={y};a+=x,y;i+=2 except:a=-1, print(*a)
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.*; import java.io.*; public class Solution{ static long mod=998244353 ; static boolean f=true; static class pair implements Comparable<pair>{ int a,b,c; pair(int x,int y,int z){ a=x;b=y;c=z; } public int compareTo(pair t){ if(c<t.c) ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
// package com.company; import java.util.*; import java.lang.*; import java.io.*; //****Use Integer Wrapper Class for Arrays.sort()**** public class BV3 { public static void main(String[] Args){ FastReader scan=new FastReader(); int t=scan.nextInt(); while(t-->0){ int n=scan.next...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
cases=int(input()) final=[] for _ in range(cases): n=int(input()) mm=[] flag=0 c=list(map(int,input().split())) v=list(set(list(range(1,2*len(c)+1)))-set(c)) mm=[] for i in range(len(v)): r=c[i] try: q=min([v[i] for i in range(len(v)) if v[i]>r]) mm.ap...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long t; cin >> t; while (t--) { long long vis[205] = {0}; long long n, c = 0; cin >> n; long long a[n]; vector<long long> b; for (long long i = 0; i < n; i++) { cin >>...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.Scanner; public class C { public static void main(String[] args) { new C(); } public C() { Scanner sc = new Scanner(System.in); int amountT = sc.nextInt(); for (int task = 0; task < amountT; task++) { int n = sc.nextInt(); int[] b = new int[n]; boolean[] done = new boolean[2 * n...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
from bisect import bisect_left def main(): for _ in range(int(input())): n, res = int(input()), [] l = list(map(int, input().split())) r = sorted(set(range(1, n * 2 + 1)) - set(l)) try: for a in l: res += a, r.pop(bisect_left(r, a + 1)) print...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.*; public class MyClass { public static void main(String args[]) { Scanner sc=new Scanner(System.in); int t=sc.nextInt(); while(t-->0){ int n=sc.nextInt(); int b[]=new int[n]; Set<Integer> set=new HashSet<>(); for(int i=0;i<n;i...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.io.PrintWriter; import java.io.StreamTokenizer; import javax.swing.JInternalFrame; public class Main { public static void main(String[] args) throws IOException { StreamToken...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.io.*; import java.util.*; public class Q1 { // Q3 public static void main(String[] args) { InputReader in = new InputReader(); PrintWriter out = new PrintWriter(System.out); int t = in.nextInt(); while (t-- > 0) { int N = in.nextInt(); Hash...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
T = int(input()) while T!=0: T-=1 n = int(input()) arr = [int(x) for x in input().split()] st = set() for i in range(1,2*n+1): st.add(i) for i in arr: st.discard(i) ans = [] for i in arr: ans.append(i) for j in sorted(st): if j>i...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import atexit import io import sys import math from collections import defaultdict,Counter # _INPUT_LINES = sys.stdin.read().splitlines() # input = iter(_INPUT_LINES).__next__ # _OUTPUT_BUFFER = io.StringIO() # sys.stdout = _OUTPUT_BUFFER # @atexit.register # def write(): # sys.__stdout__.write(_OUTPUT_BUFFER.get...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.Scanner; public class C_623 { @SuppressWarnings("resource") public static void main(String[] args) { Scanner input = new Scanner(System.in); int t = input.nextInt(); for (int test = 0; test < t; test++){ int n = input.nextInt(); int[] b = new int[n + 1]; boolean[] taken = new boolean...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
# Legends Always Come Up with Solution # Author: Manvir Singh import os from io import BytesIO, IOBase import sys from collections import defaultdict,deque,Counter from bisect import * from math import sqrt,pi,ceil import math from itertools import permutations from copy import deepcopy def main(): for t in range...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> #pragma GCC optimize("Ofast,no-stack-protector,unroll-loops") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") using namespace std; const long double PI = acos(-1); const int N = 1e5 + 10; const int mod = 1e9 + 7; const int mod1 = 998244353; const long long INF = 2e...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int t, n, b[105], a[205], vis[205], ret; int main() { int i; scanf("%d", &t); while (t--) { memset(vis, 0, sizeof(vis)); ret = 0; scanf("%d", &n); for (i = 1; i <= n; i++) { scanf("%d", &b[i]); vis[b[i]] = 1; a[i * 2 - 1] = b[i]; ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) used = set(a) ans = [] for i in range(n): ans.append(a[i]) for j in range(a[i] + 1, n << 1 | 1): if j not in used: ans.append(j) used.add(j) ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int n, k; bool vis[510]; struct node { int x, y; } a[110]; int main() { cin >> k; while (k--) { memset(vis, 0, sizeof(vis)); cin >> n; int ma = 2 * n; for (int i = 1; i <= n; i++) { cin >> a[i].x; vis[a[i].x] = true; } int now, t = ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int main() { int t; cin >> t; while (t--) { int n; cin >> n; vector<int> b(n); vector<int> ans; map<int, bool> m; for (int i = 0; i < n; i++) { cin >> b[i]; m[b[i]] = 1; } int i; for (i = 0; i < n; i++) { ans.push_...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int cinn() { int x; scanf("%d", &x); return x; } long long cinl() { long long x; scanf("%lld", &x); return x; } void coutt(int x) { printf("%d ", x); } vector<string> split(const string &s, char c) { vector<string> v; stringstream ss(s); string x; while ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
""" NTC here """ import sys inp= sys.stdin.readline input = lambda : inp().strip() # flush= sys.stdout.flush # import threading # sys.setrecursionlimit(10**6) # threading.stack_size(2**26) def iin(): return int(input()) def lin(): return list(map(int, input().split())) def main(): T = iin() while T: ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
N = int(input()) for _ in range(N): n = int(input()) b = list(map(int, input().split())) a = [-1] * 2*n pos = list(filter(lambda x: x not in b, range(1, 2*n + 1))) f = True for i, el in enumerate(b): a[2*i] = el st, end = 0, len(pos) new_idx = (st + end) // 2 ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
def main(): for _ in range(int(input())): n = int(input()) a = list(map(int,input().split())) t = 0 ans = [] used = [0] * (2 * n + 1) for i in range(n): used[a[i]] += 1 if used[a[i]] == 2: t = 1 ans = -...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
def main(n, b): #print("DEBUT") tab = [0]*(2*n) dispo = [True]*(2*n + 1) for i in range(n): tab[2*i] = b[i] dispo[b[i]] = False for i in range(n): j = b[i] test = True while j <= (2*n) and test: if not dispo[j]: j += 1 else: test = False dispo[j] = False tab[2*i + 1] = j test = True ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t=int(input()) for _ in range(t): n=int(input()) b=list(map(int,input().split())) a=[] dic={} for i in b: dic[i]=1 for i in b: a.append(i) x=i+1 while(True): if x in dic: x+=1 else: break a.append(x) dic[x]=1 f=True for i in range(1,2*n+1): if i in...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): n = int(input()) B = list(map(int, input().split())) A = [0]*(2*n) A[::2] = B X = set(range(1, 2*n+1)) - set(B) for i in range(n): x = B[i] + 1 while x <= 2*n: if x in X: A[2*i+1] = x X.remove(x) ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
def func(): n_case = int(input()) for i in range(n_case): n = int(input()) b = list(map(int,input().split())) res = {*(range(2*n+1))}-{*b} a =[] try: for i in b : minn = min(res - {*range(i)}) res-={minn} a +=i,...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
n = int(input()) for i in range(n): length = int(input()) b = [int(i) for i in input().split()] c = list() final = list() pool = list() var = False for j in range(1, 2*length + 1): if j not in b: pool.append(j) for j in range(len(b)): var = False fo...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
testCases = int(input()) for i1 in range(testCases): length = int(input()) taken = [False]*length*2 b = list(map(int, input().split())) a = [0]*2*length for i2 in range(length): taken[b[i2] - 1] = True a[i2*2] = b[i2] if taken.index(True) > 0: print(-1) else: ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
def solution(n: int, b: list): ret = [0] * (2 * n) for i in range(n): ret[2*i] = b[i] for j in range(b[i] + 1, 2 * n + 1): if not (j in b): ret[2 * i + 1] = j b.append(j) break if (0 in ret): print(-1) return els...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> #pragma optimization_level 3 #pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3") using namespace std; const long long MOD = 1e+9 + 7; const long long INF = LLONG_MAX; const int INFi = INT_MAX; const long long N = 3e+5 + 8; long long a[N], b[N]; long long check[N]; long lo...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import bisect import os from collections import Counter import bisect from collections import defaultdict import math import random import heapq as hq from math import sqrt import sys from functools import reduce, cmp_to_key from collections import deque import threading from itertools import combinations from io impor...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.io.*; import java.util.*; public class C { public static void main(String[] args) { FastReader scan = new FastReader(); PrintWriter out = new PrintWriter(System.out); Task solver = new Task(); int t = scan.nextInt(); for(int tt = 1; tt <= t; tt++) solver.solve(t...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import sys t = int(sys.stdin.readline()) for _ in range(t): n = int(sys.stdin.readline()) sq = [] bq = [int(b) for b in sys.stdin.readline().split()] aq = [True] * (2*n+1) for b in bq: aq[b] = False for b in bq: sq.append(b) j = b+1 while j <= 2*n: i...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; map<int, int> m1; int a[101]; int b[101]; int main() { int t, n, i, k, key; scanf("%d", &t); while (t--) { m1.clear(); scanf("%d", &n); for (i = 1; i <= n; i++) { scanf("%d", &b[i]); m1[b[i]] = 1; } key = 1; for (i = 1; i <= n; i++)...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.*; import java.io.*; import java.math.*; /** * * @Har_Har_Mahadev */ public class C { private static long INF = 2000000000000000000L, M = 1000000007, MM = 998244353; private static int N = 0; public static int lower(ArrayList<Integer> q, int target) { int ages[] = new int[q.size()]; int ii...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t = int(input()) for j in range(t): n = int(input()) values = [0]*(2*n+2) b = list(map(int, input().split())) a = [0]*(2*n+2) #print(a,b) for i in range(n): a[2*i] = b[i] values[b[i]] = 1 for i in range(n): check = False ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; long long t, n, x[1005000]; void solve() { cin >> n; set<long long> s; vector<pair<long long, long long> > b; vector<pair<long long, pair<long long, long long> > > v; for (int i = 1; i <= 2 * n; i++) s.insert(i); for (int i = 1; i <= n; i++) cin >> x[i], s.e...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
from typing import List import collections import bisect import itertools import functools from fractions import gcd import heapq from math import ceil, sqrt, floor # import sys # sys.setrecursionlimit(50000) def bisect_ceil(A, target): low = 0 high = len(A) - 1 if not A or A[-1] < target: return...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; long long t, n, b[100009], f[100009], j, fl; struct st { long long x, i; } a[100009]; bool cmp(st a, st b) { return a.x < b.x; } bool cm(st a, st b) { return a.i < b.i; } int main() { cin >> t; while (t--) { j = 1; fl = 0; cin >> n; for (int i = 0; i <...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) check = [True] * (2 * n) for i in range(n): check[a[i]-1] = False res = [] right = [] for idx, value in enumerate(a): res.append(value) i = value - 1 while i < 2*n and not check...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.*; import java.awt.print.Book; import java.io.*; import java.math.BigInteger; public class A { static long mod = (long) (1e9 + 7); public static long facn(long n, long x) { long ans = 1; for (int i = 1; i <= x; i++) { ans *= n; ans %= mod; n--; } long k = 1; long t = x; for (in...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import sys import math get_string = lambda: sys.stdin.readline().strip() get_list = lambda: list( map(int,sys.stdin.readline().strip().split()) ) get_int = lambda: int(sys.stdin.readline()) #----------------------------------------------------------------------# for _ in range(get_int()): n=get_int() b=get_li...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int arr[106]; int memo[206]; int solve(int n, int reff) { for (int i = 1; i <= n; i++) { if ((memo[i] == -1) && i > reff) { memo[i] = 1; return i; } } return 0; } int main() { int t; cin >> t; while (t--) { int n, x; memset(memo, -1, ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t = int(input()) for _ in range(t): n = int(input()) seq = list(map(int, input().split())) sol = [0]*(2*n) nums = {i for i in range(1,2*n+1)} for i in range(n): sol[2*i] = seq[i] nums.remove(seq[i]) geht = True for i in range(n): cand = [el for el in nums if el > sol[...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int main() { int test; cin >> test; while (test--) { int n; cin >> n; int a[n + 5]; int v[2 * n + 10], u[2 * n + 10]; for (int i = 1; i <= 2 * n; i++) { v[i] = i; u[i] = i; } int j = 1; for (int i = 1; i <= n; i++) { c...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
kl = int(input()) for l in range(kl): n = int(input()) t = n * 2 at = list(range(t + 1)) nl = [1] * t b = [] rz = [] pr = 0 # print(nl) # print(at) for i in input().split(): i = int(i) nl[i - 1] = 0 b = b + [i] # print(nl) # print(b) ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int n, a[209], vis[209], b[109]; set<int> s; int main() { cin.tie(0); cout.tie(0); ios::sync_with_stdio(0); ios_base::sync_with_stdio(0); int t; cin >> t; while (t--) { cin >> n; s.clear(); for (int i = 0; i < n * 2; i++) s.insert(i + 1); for (...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
for _ in range(int(input())): n=int(input()) b=[int(x) for x in input().split()] a=[] for i in range(n): a.append(b[i]) k=b[i] while(k in a or k in b): k+=1 if(k>2*n): print(-1) break a.append(k) else: print(*a)
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
/* /$$$$$ /$$$$$$ /$$ /$$ /$$$$$$ |__ $$ /$$__ $$| $$ | $$ /$$__ $$ | $$| $$ \ $$| $$ | $$| $$ \ $$ ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
I=input for _ in[0]*int(I()): n=2*int(I());a=[];b=*map(int,I().split()),;c={*range(n+1)}-{*b};i=1 try: for x in b:y=min(c-{*range(x)});c-={y};a+=x,y;i+=2 except:a=-1, print(*a)
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; int main() { int t; cin >> t; while (t-- > 0) { int n; cin >> n; int ar[n]; unordered_map<int, int> umap; for (int i = 0; i < n; i++) { cin >> ar[i]; umap[ar[i]] = 1; } int ans[2 * n]; int k = 0; int flag1 = 0; for (...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
t=int(input()) for i in range(t): n=int(input()) ans=[] l=[int(i) for i in input().split()] unl=[] for i in range(1,2*n+1): if i not in l: unl.append(i) #print(l,unl) ok=True for i in range(2*n): if i%2==0: ans.append(l[i//2]) else: ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> #pragma GCC optimize("O2") using namespace std; signed main() { long long nn; cin >> nn; while (nn--) { long long n; cin >> n; vector<long long> vec(n + 1); vector<long long> res(2 * n + 1); vector<long long> vissited(2 * n + 1, 0); for (long long i = 1; i <= n; ++...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
from math import * from collections import * t = int(input()) for y in range(t): n = int(input()) a = list(map(int,input().split())) ch = [0 for i in range(2*n+1)] b = [-1 for i in range(2*n)] for i in range(n): ch[a[i]] = 1 b[2*i] = a[i] flag = 0 for i in range(0,2*n,2): m = -1 for j in range(b[i],2*n+1...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> using namespace std; long long int mod = 1000000007; long long int power(long long int a, long long int c) { if (c == 0) return 1; if (c % 2 == 0) { long long int m = power(a, c / 2); return (m * m) % mod; } return (a * power(a, c - 1)) % mod; } int main() { ios_base::sync_wit...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.*; import java.io.IOException; import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.InputStream; public class Two { public static void main(String[] args) { ...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
''' @sksshivam007 - Template 1.0 ''' import sys, re, math from collections import deque, defaultdict, Counter, OrderedDict from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians from heapq import heappush, heappop, heapify, nlargest, nsmallest def STR(): return list(input()) def INT(): return int(input())...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
#include <bits/stdc++.h> template <typename T> std::istream& operator>>(std::istream& input, std::vector<T>& v) { for (T& a : v) input >> a; return input; } void no_answer() { std::cout << -1 << '\n'; } void answer(const std::vector<unsigned>& v) { const char* separator = ""; for (const unsigned x : v) { st...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
import java.util.Arrays; import java.util.Scanner; public class C_623 { public static void main(String[] args){ Scanner in = new Scanner(System.in); int q = in.nextInt(); for(int tc=0;tc<q;tc++){ int n=in.nextInt(); int[] b = new int[n]; int[] a = new in...
You are given a sequence b_1, b_2, …, b_n. Find the lexicographically minimal permutation a_1, a_2, …, a_{2n} such that b_i = min(a_{2i-1}, a_{2i}), or determine that it is impossible. Input Each test contains one or more test cases. The first line contains the number of test cases t (1 ≀ t ≀ 100). The first line of...
I=input for _ in[0]*int(I()): n=2*int(I());a=[0]*n;b=a[::2]=*map(int,I().split()),;c={*range(n+1)}-{*b};i=1 try: for x in b:y=a[i]=min(c-{*range(x)});c-={y};i+=2 except:a=-1, print(*a)