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There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
FAST_IO = 0 if FAST_IO: import io, sys, atexit rr = iter(sys.stdin.read().splitlines()).next sys.stdout = _OUTPUT_BUFFER = io.BytesIO() @atexit.register def write(): sys.__stdout__.write(_OUTPUT_BUFFER.getvalue()) else: rr = raw_input rri = lambda: int(rr()) rrm = lambda: map(int, rr().s...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.util.Scanner; public class er88c3 { public static void main(String[] args) { Scanner scan=new Scanner(System.in); int t=scan.nextInt(); for(int tt=0;tt<t;tt++) { long h=scan.nextInt(), c=scan.nextInt(), target=scan.nextInt(); long l=-1, r=100000000L; while (r-l>1) { long mid=(r+l...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
n = int(input()) for i in range(n): read = input().split(' ') a = float(read[0]) b = float(read[1]) c = float(read[2]) if c == a: print(1) elif abs(c - (a + b)/2) == 0: print(2) else: k = abs(c-a)/abs(a+b-2*c) k = int(2*k + 1) # print(k) avr = ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.math.BigDecimal; import java.math.MathContext; import java.math.RoundingMode; import java.util.StringTokenizer; public class P1359C { public static void main(String[] args) { InputStream inputStream = System.in; OutputStream outputStream = System.out; InputRead...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.math.BigDecimal; import java.math.MathContext; import java.util.*; public class A implements Runnable { FastReader sc; PrintWriter out; void solve() { int tc = sc.ni(); outer: while(tc-- > 0) { long h = sc.nl(); long c = sc.nl(); long t = sc.nl(); double a = ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.util.Scanner; /** * @εˆ›ε»ΊδΊΊ YDL * @εˆ›ε»Ίζ—Άι—΄ 2020/5/9 22:34 * @描述 */ public class Main { private static manyFunc<Integer,Long> f= (n,h,l)->((long)(h+l)*n-l); public static void main(String[] args) { Scanner sc = new Scanner(System.in); int len = sc.nextInt(); ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> #pragma warning(disable : 4996) const int maxn = 1e5 + 5; const double Inf = 10000.0; const double PI = acos(-1.0); using namespace std; double h, c, t; double a; double f1(int x) { return ((x)*h + (x - 1) * c) / (1.0 * (2 * x - 1)); } double f2(int x) { return ((x - 1) * h + (x)*c) / (1.0 * (2...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedOutputStream; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.StringTokenizer; public class C_Mixing_Water { public static void main(String[] args) { MyScanner sc = new MyScanner(); PrintWriter out ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import math for i in range(int(input())): h, c, t = map(int, input().split()) if (h + c) / 2 >= t: print(2) continue if h <= t: print(1) continue left = 1 right = 1000000000 while right - left > 1: n = (right + left) // 2 temp_1 = (n * h + (n - 1...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; long double h, c, t; vector<pair<double, int> > pot; void bs() { long long lo = 0, hi = 1e9, mid; long long bestN = -1; long double bestDif = 1e9; while (lo <= hi) { mid = (lo + hi) / 2; long double tmp = ((mid + 1) * h + mid * c) / (2 * (mid + 1) - 1); ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; vector<long long int> pr; void SieveOfEratosthenes() { long long int n = 1000000; bool prime[n + 1]; memset(prime, true, sizeof(prime)); for (long long int p = 2; p * p <= n; p++) { if (prime[p] == true) { for (long long int i = p * p; i <= n; i += p) prim...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; long double h, c, t; long long bs() { long long lo = 0, hi = 1e17, mid; long long bestN = -1; long double bestDif = 1e9; while (lo <= hi) { mid = (lo + hi) / 2; long double tmp = ((mid + 1) * h + mid * c) / (2 * (mid + 1) - 1); long double error = abs(tm...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
'''Author- Akshit Monga''' from fractions import Fraction q=int(input()) for _ in range(q): h,c,t=map(int,input().split()) if 2*t<=(h+c): print(2) else: x1 = (c - t) // (h + c - 2 * t) x2=x1+1 if abs(t-Fraction((x1*h+(x1-1)*c),(2*x1-1))) <= abs(t-Fraction((x2*h+(x2-1)*c),(2*x...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
def solve(th, tc, t): ans = 0 if th == t: ans = 1 elif 2*t <= th + tc: ans = 2 else: # halfsum = (th + tc)/2 # halfdelta = (th - tc)/2 # k = halfdelta/(t - halfsum) k = (th - tc)/(2*t - th - tc) if (th - tc)%(2*t - th - tc) == 0: if k%2...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; int checktemp(double temp1, double temp2, double t) { if (abs(temp1 - t) > abs(temp2 - t)) return 1; else return 0; return 0; } int main() { int w; cin >> w; while (w--) { float h, c, t; cin >> h >> c >> t; if (t <= (h + c) / 2) { cout ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
// Working program with FastReader import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.Arrays; import java.util.Scanner; import java.util.StringTokenizer; public class c { static class FastReader { BufferedReader br; StringTokenizer st; ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.util.*; import java.io.*; public class Main { static FastReader in = new FastReader(); public static void main(String[] args) { int t = in.nextInt(); while (t-- > 0) solve(); } static void solve() { int h = in.nextInt(), c = in.nextInt(), t = in.nextInt(), k; ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.IOException; import java.io.InputStream; import java.util.*; public class Solution { static long h,c,te; static long binary(){ long l=1,r=(long)1e7; while(l<=r){ if(r-l<5){ double min=h-te; long ans=1; for(long i=l;i<=r...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; void mycode(); const long long int mod = 998244353; long long int ceil(long long int a, long long int b) { return (a + b - 1) / b; } long long int min(long long int a, long long int b) { if (a > b) return b; else return a; } bool bit_check(long long int a, int i...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
for _ in range(int(input())): h,c,t=map(int,input().split()) if t<=(h+c)/2: print(2) else: n=(c-t)//(h+c-2*t) if abs(n*(h+c)-c-t*(2*n-1))*(2*n+1)>abs((n+1)*(h+c)-c-t*(2*n+1))*(2*n-1): print(2*n+1) else: print(2*n-1)
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; long long dx[] = {0, -1, 0, 1, 0, 0}, dy[] = {-1, 0, 1, 0, 0, 0}, dz[] = {0, 0, 0, 0, -1, 1}; const long long N = 1e5 + 7; long long n, m, p; inline long long read() { long long first = 0, f = 1; char ch = getchar(); while (ch < '0' || ch > '9') { if (ch...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; public class Prob3 { public static void main(String[] args) { FastReader fr = new FastReader(); int q = fr.nextInt(); for (int o=0; o<q; o++) { int t1 = fr.nextInt(); int t2 = fr...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.util.*; import java.lang.*; import java.math.*; import java.io.*; import java.util.HashSet; import java.util.Scanner; import java.util.Set; import java.util.ArrayList; import java.util.Collections; import java.util.HashMap; import java.util.Map; import java.text.DecimalFormat; import java.lang.Math; import ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; void solve() { long long h, c, t; cin >> h >> c >> t; if (h == t) { cout << 1 << '\n'; return; } if (h + c >= t * 2) { cout << 2 << '\n'; return; } long long lo = 0, hi = 1e7; while (lo < hi) { int m = (lo + hi + 1) / 2; if (m * (h + ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
from sys import stdin input=lambda : stdin.readline().strip() from math import ceil,sqrt,factorial,gcd for _ in range(int(input())): h,c,t=map(int,input().split()) m=abs(t-(h+c)/2) ans=2 if m>abs(t-0): ans=0 if 2*t-h-c!=0: z=(h-t)/(2*t-h-c) b=abs(t-(ceil(z)*(h+c)+h)/(2*ceil(z)+1)) a=abs(t-(int(z)*(h+c)+h)/...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; double mi, kq, h, c, t, q; void xuly(long long x) { if (x < 0) return; double tg = abs(t - (x * (h + c) + h) * 1.0 / (2 * x + 1)); if (mi > tg || (mi == tg && kq > x * 2 + 1)) { mi = tg; kq = x * 2 + 1; } } int main() { cin >> q; while (q--) { cin >>...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import math tt = int(input()) for test in range(tt): h,c,t = map(int,input().split()) if t<=(h+c)/2: print(2) else: k = (h-t)//(2*t-h-c) if abs((k*(h+c)+h)-t*(2*k+1))*(2*k+3)<=abs(((k+1)*(h+c)+h)-t*(2*k+3))*(2*k+1): print(2*k+1) else: print(2*k+3) ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys import math import heapq import collections def inputnum(): return(int(input())) def inputnums(): return(map(int,input().split())) def inputlist(): return(list(map(int,input().split()))) def inputstring(): return([x for x in input()]) def inputmatrix(rows): arr2d = [[j for j in input().st...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys from collections import defaultdict import math input = sys.stdin.readline def print_result(l): return print(' '.join(map(str, l))) def timer(function): import time def wrapper(*args, **kwargs): t1 = time.time() val = function() t2 = time.time() print("Executed \...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
t = int(input()) for _ in range(t): h, c, t = list(map(int, input().split())) av = (h+c)/2 if h == c: print(1) elif t <= av: print(2) else: d = (t-av)/(h-av) # sk = 1 # while 1/sk >= d: # sk += 2 # print("sk is {}".format(sk)) k =...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import math t = int(input()) for x in range(t): [h,c,t]=list(map(int,input().split())) if t <= (h+c)/2: print(2) else: y = (t-c)/(2*t-h-c) #print(y) y1 = int(y) y2 = y1 + 1 #print(2*y1-1) #print(2*y2-1) z1 = abs((h*y1+c*(y1-1))*(2*y2-1)-t*(...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys import math import collections def set_debug(debug_mode=False): if debug_mode: fin = open('input.txt', 'r') sys.stdin = fin def bs(m): return -t * (2 * m - 1) + (m * h + (m-1) * c) if __name__ == '__main__': # set_debug(True) t = int(input()) for ti in range(1, t + ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.File; import java.io.FileNotFoundException; import java.util.StringTokenizer; import java.io.BufferedReader; import java.io.FileRe...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Collections; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import java.util.Scanner; import java.util.StringTokenizer; public cla...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; const long long mod = 1e9 + 7; long long dx[] = {-1, 0, 1, 0}; long long dy[] = {0, -1, 0, 1}; int32_t main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); long long q; cin >> q; while (q--) { long long h, c, t; cin >> h >> c >> t; if (t ==...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys,math,random input=sys.stdin.readline import sys,math,random input=sys.stdin.readline T=int(input()) for _ in range(T): n,m,t=map(int,input().split()) diff=abs(t-((n+m)/2)) fv=2 if (t==n): print(1) elif (2*t==(n+m)): print(2) else: val=(n-t)/((2*t...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
for _ in range(int(input())): h,c,t = map(int,input().split()) if h+c-2*t >= 0: print(2) else: a = h - t b = 2*t - c - h k = 2 * (a // b) + 1 val1 = abs(k // 2 * 1 * c + (k + 1) // 2 * 1 * h - t * 1 * k) val2 = abs((k + 2) // 2 * 1 * c + (k + 3) // 2 * 1 * h -...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; long long h, c, t, lo, hi; long double cal(long long mid) { long double a = 1.0 * h * (mid + 1) + 1.0 * c * mid; a /= 2.0 * mid + 1; return a; } int main() { int tc; cin >> tc; while (tc--) { cin >> h >> c >> t; if (h == t) cout << 1 << '\n'; e...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import fractions f=fractions.Fraction tests=int(input()) for _ in range(tests): h,c,t=map(int,input().split()) av1=(h+c)/2 if (h+c)/2 == t: print(2) else: x=(t-h)/(h+c-2*t) if x<0: if abs(h-t)<=abs(t-av1): print(1) continue ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import io import os import math def solve(H, C, T): # Need big decimal for more floating point resolution but TLEs assert C < H assert C <= T <= H if H == T: return 1 # After even (2 * i) cups, average is always (H + C) / 2 # After odd (2 * i + 1) cups, average is ((i + 1) * H + i * C...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; public class Main { public static void main(String args[]) { FastReader input=new FastReader(); PrintWriter out=new PrintWriter(System.out); int T=input.nextInt(); while(T-->0) { long h,c,t; h=input.nextInt(); ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
T = int(input()) for _ in range(T): h, c, t = map(int, input().split()) if h <= t: print(1) elif t <= (h + c) // 2: print(2) else: i1 = (t - h) // (h + c - 2 * t) i2 = i1 + 1 if ((i1+1) * h + i1 * c) * (2*i2 + 1) + ((i2+1) * h + i2 * c) * (2*i1 + 1) <= 2 * t * (2*...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); double t, c, h; long long x, y; cin >> y; for (long long i = 0; i < y; i++) { cin >> h >> c >> t; x = 1 / (1 - 2 * (t - h) / (c - h)); if (x < 0 || (c + h) == 2 * t) { ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; public class CF1359C { public static void main(String[] args) { FastReader input = new FastReader(); int t = input.nextInt(); while (t > 0){ long hot = ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; public class Main extends PrintWriter { private void solve() { int T = sc.nextInt(); for(int tt = 1; tt <= T; tt++) { long h = sc.nextLong(); long c = sc.nextLong(); long t = sc.nextLong(); if(h+c >= 2L*t) { ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys input = sys.stdin.readline T = int(input()) def solve(h, c, t, x): if (h*x + c*(x - 1)) > t * (2 * x - 1): return True else: return False for _ in range(T): h, c, t = [int(x) for x in input().split()] left = 1 right = 10**20 while right - left > 1: mid = (r...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.ByteArrayInputStream; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.nio.charset.StandardCharsets; import java.util.Arrays; import java.util.InputMismatchException; ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.util.ArrayList; import java.util.Random; import java.util.StringTokenizer; public class MixingWater { static final int MAXN = 1000_006; stati...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
for _ in range(int(input())): h,c,t = map(int,input().split()) if t<=(h+c)/2: print(2) else: x = (t-c)//(2*t-h-c) v1 = ((x)*h + (x-1)*c) v2 = ((x+1)*h + (x)*c) if abs(v1-(2*x-1)*t)/(2*x-1)<=abs(t*(2*x+1)-v2)/(2*x+1): print(2*x-1) else: ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.StringTokenizer; public class Main { FastScanner in; PrintWriter out; public static void main(String[] args) throws Exception { (new Main()).run(); } private void run() throws Exception { in = new FastScanner(System.in); out = new PrintWr...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.*; public class SolutionD extends Thread { static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new B...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
from decimal import * getcontext().prec = 100 t = int(input()) for _ in range(t): h,c,t = map(int, input().split()) if t <= (h+c)/2: print(2) continue if h<t: print(1) continue amt=1 k=500000//2 while k>0: while ((amt+k)*h + ((amt+k)-1)*c) > t * ((am...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.math.BigDecimal; import java.math.RoundingMode; import java.util.Scanner; public class cf1359_Div2_C { public static double solve(double mid, int h, int c) { return ((mid * h) + (mid - 1) * c) / (2 * mid - 1); } public static void main(String args[]) { Scanner in = new Scanner(System.in); in...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; long long int MOD = 998244353; long long int mod = 1e9 + 7; long long int INF = 1e18; long long int dx[] = {1, -1, 0, 0}; long long int dy[] = {0, 0, 1, -1}; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long int t; cin >> t; while (t--) { ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
cases = int(input()) for _ in range(cases) : hot, cold, target = map(int, input().split()) if 2 * target <= hot + cold : print(2) elif target >= hot : print(1) else : lo, hi = 1, 10**20 while lo < hi : mid = (lo+1+hi) // 2 if mid * hot + (mid-1) * ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys, math input = sys.stdin.readline def getInts(): return [int(s) for s in input().split()] def getInt(): return int(input()) def getStrs(): return [s for s in input().split()] def getStr(): return input().strip() def listStr(): return list(input().strip()) import collections as col im...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
for _ in range(int(input())): a,b,c=map(int,input().split()) mid=(a+b)/2 if c==a: print(1) elif c<=mid: print(2) elif c>=(mid+(a-b)/6) and c<a: d=(mid+(a-b)/6) if abs(d-c)<abs(a-c): print(3) else: print(1) else: c-=mid ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
def cck(val, h, c, t): return (val+1)*h+val*c < t*(2*val+1) def cnt(val, h, c): return (val+1)*h+val*c ts = int(raw_input()) for cs in range(ts): h, c, t = tuple(map(int, raw_input().split())) if(2*t <= h+c): print 2 continue st, ed = 0, 1000000000000 while st+1 < ed: ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
/* If you want to aim high, aim high Don't let that studying and grades consume you Just live life young ****************************** What do you think? What do you think? 1st on Billboard, what do you think of it Next is a Grammy, what do you think of it However you think, I’m sorry, but shit, I have no fucking inte...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; import java.lang.*; public class Rextester{ public static void main(String[] args)throws IOException{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int z = Integer.parseInt(br.readLine()); StringBuffer sb = new StringBuffer()...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.util.*; public class Main { static Set<Long> set = new TreeSet<>(); public static void main(String[] args) { Scanner s = new Scanner(System.in); int TC = s.nextInt(); tc: for (int tc = 0; tc < TC; tc++) { int h = s.nextInt(); int c = s.nextInt(...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
for _ in range(int(input())): h,c,t=map(int,input().split()) if h+c>=2*t: print(2) elif t>=h: print(1) else: x=2*t-h-c k=(h-c+x)//(2*x) test1=abs((8*k**2-2)*t-(h*k+c*k-c)*(4*k+2)) test2=abs((8*k**2-2)*t-(h*(k+1)+c*(k+1)-c)*(4*k-2)) test3=abs((8*k**...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.ArrayList; import java.util.Arrays; import java.util.StringTokenizer; import java.util.List; import java.util.*; public class realfast implements Runnable { private static final int INF = (int) 1e9; long in= (long)Math.pow(10,9)+7; long fac[]= new long[3000]; publ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
# https://codeforces.com/contest/1359/problem/C def calc(a, b, t, k): num1, num2 = abs(k*(a+b)+a - (2*k + 1)*t), abs((k+1)*(a+b) + a - (2*k + 3)*t) den1, den2=(2*k + 1), (2*k + 3) if num1*den2 <= num2*den1: return 2*k + 1 return 2*k + 3 t=int(input()) for _ in range(t): a, b, t=map(int, i...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
tt = int(input()) for _ in range(tt): h, c, t = list(map(int, input().split(' '))) if t>=h: print(1) elif t <= (c+h)/2: print(2) else: n = (t-c)/(2*t-h-c) m = int(n)+1 nn = int(n) e = (nn*h+(nn-1)*c) - t*(2*nn-1) ee = t*(2*m-1) - (m*h+(m-1)*c) ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
from fractions import Fraction def temp(hot, cold, step): return Fraction((hot * step + cold * (step - 1)), (2 * step - 1)) tests = int(input()) for i in range(tests): numbers = input().split(" ") h = int(numbers[0]) c = int(numbers[1]) t = int(numbers[2]) if t >= h: print(1) el...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
from math import ceil, floor from decimal import Decimal def calculate(x, y, n): return Decimal(x * n + y * (n - 1)) / Decimal(2 * n - 1) def ca(x, y): return (x + y) / 2 for _ in range(int(input())): x, y, c = map(int, input().split()) ans1 = 2 if (x + y) / 2 >= c: print(ans1) ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys input = sys.stdin.readline t = int(input()) for _ in range(t): h,c,temp = map(int,input().split()) ave_temp = (h+c)/2 if temp <= ave_temp: print(2) elif h == temp: print(1) else: u = (h-c)/((temp-ave_temp)*2) u_l = int(u) if int(u) % 2 == 1: ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.math.BigInteger; import java.util.*; public class Main { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); PrintWriter pw = new PrintWriter(System.out); static int MOD = 1000000007; public static void main(String[] args) throws IOException { ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
def main(): from decimal import Decimal import sys input = sys.stdin.readline sys.setrecursionlimit(10**6) T = int(input()) for _ in range(T): h, c, t = [Decimal(x) for x in input().strip().split()] avg = (h + c) / 2 if h == t: print(1) continue ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; void solve() { long long h, c, t; cin >> h >> c >> t; if ((h + c) / 2 >= t) { cout << 2 << '\n'; return; } long long k = 2 * ((t - h) / (h + c - 2 * t)) + 1; long long val2 = abs((k + 2) / 2 * c + (k + 3) / 2 * h - t * (k + 2)); long long val1 = abs(k ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; import java.math.*; /** * Built using CHelper plug-in * Actual solution is at the top */ public class MixingWater { public static void main(String[] args) throws IOException { InputStream inputStream = System.in; OutputStream outputStream = System.out; ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
# Nilfer for _ in range(int(input())): h,c,t=map(int,input().split()) if t<=(h+c)/2:print(2) else: k=(h-t)//(2*t-h-c) if abs((2*k+3)*t-k*h-2*h-k*c-c)*(2*k+1)<abs((2*k+1)*t-k*h-h-k*c)*(2*k+3):print(2*k+3) else:print(2*k+1)
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.util.*; import java.io.*; public class MixingWater { public static void main(String[] args) { Scanner in = new Scanner(System.in); OutputStream outputStream = System.out; PrintWriter out = new PrintWriter(outputStream); int T; T=in.nextInt(); while((...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long i, T, n; cin >> T; while (T--) { double h, c, t, ans; cin >> h >> c >> t; double res = h, freq = 1.0, diff = fabs(((h + c) / 2) - t); if (h == t) { cout << 1 << "\n"; ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import math import sys from fractions import Fraction input = sys.stdin.readline ts = int(input()) # (h + c) * n / 2n = (h + c) / 2 # ((h + c) * n + h) / (2n + 1) = (h + c) * n/(2n + 1) + h/(2n + 1) res = [] for cs in range(ts): h, c, t = map(int, input().split()) if 2 * t <= (h + c): res.append(2) else: l,...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import math from sys import stdin,stdout import sys import fractions mod=1000000007 F=fractions.Fraction t=int(stdin.readline()) while t>0: h,c,tt=list(map(int,stdin.readline().split())) mini=sys.maxsize ans=0 xx=[] if(2*tt>h+c): xx.append((h-tt)//((2*tt)-(h+c))) xx.append((h-tt)//((...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; public class C implements Runnable { boolean oj = false; Reader scn; PrintWriter out; String INPUT = ""; void solve() { int t = scn.nextInt(); while (t-- > 0) { int hot = scn.nextInt(), cold = scn.nextInt(), temp = scn.nextInt(); if (temp == hot) { out.println(...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; template <typename T> using v2 = vector<vector<T>>; template <typename T> inline v2<T> fill(int r, int c, T t) { return v2<T>(r, vector<T>(c, t)); } int h, c, t; ll calc(int n) { return (ll)h * (n + 1) + (ll)c * n; } void solv...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; template <typename X> ostream& operator<<(ostream& x, const vector<X>& v) { for (long long i = 0; i < v.size(); ++i) x << v[i] << " "; return x; } template <typename X> ostream& operator<<(ostream& x, const set<X>& v) { for (auto it : v) x << it << " "; return x; } ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; public class F { public static void main(String[] args) throws Throwable { Scanner sc = new Scanner(); PrintWriter pw = new PrintWriter(System.out); int T = sc.nextInt(); while (T-- > 0) { h = sc.nextInt(); c = sc.nextI...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
# -*- coding: utf-8 -*- import sys # from collections import defaultdict, deque # from math import log10, sqrt, ceil # from pprint import pprint def input(): return sys.stdin.readline()[:-1] # warning not \n # def input(): return sys.stdin.buffer.readline()[:-1] from functools import lru_cache from itertools import pro...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
from sys import stdin input=stdin.readline import bisect import math #i = bisect.bisect_left(a, k) #list=input().split(maxsplit=1) def sol(x,y,z): p=(x+y)/2 p=p-z p*=2 kk=(y-x)/p return kk for xoxo in range(1): #a=[] for _ in range (int(input())): #n=int(input()) ans=[[],[]] ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; public class C { void solve() throws IOException { in = new InputReader("__std"); out = new OutputWriter("__std"); int testCount = in.readInt(); for (int test = 1; test <= testCount; ++test) { long h = in.readInt(); lon...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import os import sys from io import BytesIO, IOBase import math def main(): pass # region fastio BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mo...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedReader; import java.io.InputStreamReader; import java.math.*; public class C { public static void main(String []args) throws Exception { BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); String input; String []splited; int q,n,m,t; int []arr,arr1; int[][...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
from decimal import Decimal t1 = int(input()) while t1: t1 += -1 h, c, t = map(int, input().split()) if h == t: print(1) elif h + c >= 2 * t: print(2) else: x = (c - h) // (h + c - 2 * t) mn = 9999999999999999999 ans = 0 for i in range(max(1, x - 10), x + 10): ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long t; cin >> t; while (t--) { long long h, c, t; cin >> h >> c >> t; if (t == h) { cout << "1" << '\n'; continue; } if (2 * t <= h + c) { c...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.StringTokenizer; import java.io.BufferedWriter; import java.io.OutputStreamWriter; public class MixingWater { public static void main(String[] args) { FastReader reader = new FastReader(); BufferedWriter log = new Buf...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys readline = sys.stdin.readline readlines = sys.stdin.readlines ns = lambda: readline().rstrip() ni = lambda: int(readline().rstrip()) nm = lambda: map(int, readline().split()) nl = lambda: list(map(int, readline().split())) prn = lambda x: print(*x, sep='\n') class Q: def __init__(self, p, q=1): ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> struct Drob { long long a, b; Drob(long long a = 0, long long b = 0) : a(a), b(b) { ; } bool operator<(const Drob& other) const { return (a * other.b) < (b * other.a); } Drob operator-(const Drob& other) const { return Drob(a * other.b - other.a * b, b * other.b); } }; Drob ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; const long long mod = 1e9 + 7; const long long mx = 2e6 + 10; int posx[] = {1, -1, 0, 0}; int posy[] = {0, 0, 1, -1}; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); long long t = 1, n, k, m, a, b, c, d, h; cin >> t; while (t--) { cin >> ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
def rs(): return input().strip() def ri(): return int(input()) def ria(): return list(map(int, input().split())) def ia_to_s(a): return ' '.join([str(s) for s in a]) def temp_at_2k_1(h, c, k): return k * h + (k - 1) * c, 2 * k - 1 def solve(h, c, t): if t <= (h+c)//2: return 2 k_left = 1 k_...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.ByteArrayInputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Arrays; import java.util.InputMismatchException; import java.util.List; public class Main { private static final String NO = "NO"; private static fina...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import java.io.*; import java.util.*; public class MainClass { static ArrayList<Long> val = new ArrayList<>(); public static void main(String[] args)throws IOException { Reader in = new Reader(); StringBuilder stringBuilder = new StringBuilder(); int t = in.nextInt(); while ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; using ii = pair<unsigned long long, unsigned long long>; using ll = long long; const double EPS = 1e-9; bool equals(double a, double b) { return fabs(a - b) < EPS; } int32_t main() { ios::sync_with_stdio(0); unsigned long long t; cin >> t; while (t--) { double h...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
#include <bits/stdc++.h> using namespace std; long long int MOD = 1000000007; long long int MX = 400000000000000000; long long int T, t, h, c; int main() { ios::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); cin >> T; while (T--) { cin >> h >> c >> t; if (2 * t == h + c) { cout << 2 << endl;...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys,math Tests=int(input()) for _ in range(Tests): h,c,t=map(int,sys.stdin.readline().split()) if h==t: print(1) else: x=(h+c)/2 if x>=t: print(2) else: diff=t-x some=int(abs((c-h)//(2*diff))) if(some%2==0): ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
T = int(input()) o = [] for i in range(T): h, c, t = input().split() h = int(h) c = int(c) t = int(t) s = (h + c) / 2 if t >= h: o.append(1) elif t <= s: o.append(2) else: i = (h - t) / (2 * t - (h + c)) #print(i) if i == int(i): i ...
There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into an infin...
import sys from decimal import * input=sys.stdin.buffer.readline def temp(nHot,h,c): #assuming that nCold=nHot-1 return (nHot*h+(nHot-1)*c)/(2*nHot-1) def tempDec(nHot,h,c): #for higher precision return Decimal(nHot*h+(nHot-1)*c)/(2*nHot-1) #for more precision nTests=int(input()) for _ in range(nTests)...