input stringlengths 122 2.7k | output stringlengths 24 805 |
|---|---|
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T3.name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T2.sat = 1 AND T1.intelligence = 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
Please write m... | SELECT T2.name FROM registration AS T1 INNER JOIN course AS T2 ON T1.course_id = T2.course_id WHERE T1.grade = 'A' AND T2.name IN ('Advanced Operating System', 'Intro to BlockChain') GROUP BY T2.name ORDER BY COUNT(T1.student_id) DESC LIMIT 1; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T2.popularity FROM RA AS T1 INNER JOIN prof AS T2 ON T1.prof_id = T2.prof_id GROUP BY T1.prof_id, T1.capability ORDER BY COUNT(T1.student_id) DESC, T1.capability DESC LIMIT 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
Please write m... | SELECT CAST(COUNT(T1.student_id) AS REAL) / COUNT(DISTINCT T2.course_id) FROM registration AS T1 INNER JOIN course AS T2 ON T1.course_id = T2.course_id WHERE T2.diff = 4; |
[INST] Here is a database schema:
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ T... | SELECT COUNT(T2.student_id) FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id WHERE T2.grade IS NULL AND T1.gpa BETWEEN 3 AND 4; |
[INST] Here is a database schema:
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ T... | SELECT COUNT(T2.student_id) FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id WHERE T2.grade = 'A' AND T1.type = 'UG'; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT AVG(T2.gpa), T2.f_name, T2.l_name FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T1.salary = 'high' AND T1.capability = 5 GROUP BY T2.student_id; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
Please write me a SQL statement that answers the following question: List the professors' IDs and students' IDs with the lowest research ... | SELECT prof_id, student_id FROM RA WHERE capability = ( SELECT MIN(capability) FROM RA ); |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
Please write me a SQL statement that answers the following question: Name the professor who got gradua... | SELECT first_name, last_name FROM prof WHERE graduate_from = 'University of Boston'; |
[INST] Here is a database schema:
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
Please write me a SQL statement that answers the following question: List the courses' IDs and students' ID... | SELECT course_id, student_id FROM registration WHERE grade IS NULL OR grade = ''; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
Please write me a SQL statement that answers the following question: What is the male and female ratio... | SELECT CAST(SUM(CASE WHEN gender = 'Male' THEN 1 ELSE 0 END) AS REAL) / SUM(CASE WHEN gender = 'Female' THEN 1 ELSE 0 END) FROM prof; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
Please write me a SQL statement that answers the following question: Describe the names and credits of the least difficult courses. [/INST] [/INST] | SELECT name, credit FROM course WHERE diff = ( SELECT MIN(diff) FROM course ); |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T3.f_name, T3.l_name, T3.gpa FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id ORDER BY T1.popularity DESC LIMIT 1; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT T2.f_name, T2.l_name, T2.email FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T1.salary = 'free'; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T3.f_name, T3.l_name, T2.capability, T3.gpa FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id WHERE T1.first_name = 'Merwyn' AND T1.last_name = 'Conkay'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T1.f_name, T1.l_name, T2.grade FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'Intro to BlockChain'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T1.f_name, T1.l_name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T2.grade = 'A' ORDER BY T3.diff DESC LIMIT 1; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T1.first_name, T1.last_name, T1.graduate_from FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id WHERE T3.f_name = 'Olia' AND T3.l_name = 'Rabier'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T1.f_name, T1.l_name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'Advanced Database Systems' ORDER BY T2.sat DESC LIMIT 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT CAST(SUM(T3.credit * CASE T1.grade WHEN 'A' THEN 4 WHEN 'B' THEN 3 WHEN 'C' THEN 2 WHEN 'D' THEN 1 ELSE 1 END) AS REAL) / COUNT(T3.credit) FROM registration AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T1.course_id = T3.course_id WHERE T2.f_name = 'Laughton' AND T2.l... |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT DISTINCT T1.f_name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T1.type = 'UG' AND T1.gpa > 3.7; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T3.f_name, T3.l_name, T2.capability FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id WHERE T1.graduate_from = 'University of Washington'; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT f_name, l_name, email, intelligence FROM student WHERE student_id IN ( SELECT student_id FROM RA WHERE salary = 'high' AND capability = ( SELECT MAX(capability) FROM RA ) ); |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
stude... | SELECT T5.name, T5.credit FROM RA AS T1 INNER JOIN prof AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T1.student_id = T3.student_id INNER JOIN registration AS T4 ON T3.student_id = T4.student_id INNER JOIN course AS T5 ON T4.course_id = T5.course_id WHERE T2.gender = 'Female' ORDER BY T2.teachingability ... |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
Please write me a SQL statement that answers the following question: How many of the professors are fe... | SELECT COUNT(prof_id) FROM prof WHERE gender = 'Female'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
Please write me a SQL statement that answers the following question: What is the name of the most difficult course? [/INST] [/INST] | SELECT name FROM course WHERE diff = ( SELECT MAX(diff) FROM course ); |
[INST] Here is a database schema:
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]
gpa [ REAL ]
type [ TEXT ]
Please write me a SQL statement that answers the following question: Among the students with a gpa of 3.1 to 3.7, how m... | SELECT COUNT(student_id) FROM student WHERE gpa BETWEEN 3.1 AND 3.7 AND type = 'UG'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
Please write me a SQL statement that answers the following question: What is the credit of the course named "Computer Vision"? [/INST] [/INST] | SELECT credit FROM course WHERE name = 'Computer Vision'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T2.student_id FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'C for Programmers' AND T1.gpa = 2.5; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T1.l_name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'Intro to Database 2' ORDER BY T2.sat DESC LIMIT 1; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT COUNT(T1.student_id) FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T1.salary = 'high' AND T2.gpa > 3; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T3.name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T1.type = 'UG' ORDER BY T2.sat DESC LIMIT 1; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT T1.capability FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T2.type = 'RPG' AND T2.intelligence >= 4; |
[INST] Here is a database schema:
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ T... | SELECT COUNT(T1.student_id) FROM registration AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T1.grade = 'B' AND T2.intelligence = 3; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T3.diff FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T2.grade = 'A' AND T1.intelligence = 5; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT COUNT(T1.student_id) FROM RA AS T1 INNER JOIN prof AS T2 ON T1.prof_id = T2.prof_id WHERE T1.capability = 5 ORDER BY T2.popularity DESC LIMIT 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
Please write m... | SELECT T1.name FROM course AS T1 INNER JOIN registration AS T2 ON T1.course_id = T2.course_id WHERE T2.grade = 'D'; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT T2.capability FROM student AS T1 INNER JOIN RA AS T2 ON T1.student_id = T2.student_id WHERE T1.f_name = 'Alvera' AND T1.l_name = 'McQuillin'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT COUNT(T1.student_id) FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.credit = 3 AND T1.gpa = 3.2; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT COUNT(T1.student_id) FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T2.gpa = 3.5 AND T1.salary = 'low'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T2.email FROM registration AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T1.course_id = T3.course_id WHERE T1.grade = 'B' GROUP BY T3.diff HAVING T3.diff > AVG(T3.diff) * 0.8; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT CAST(SUM(CASE WHEN T1.salary = 'low' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.salary) FROM RA AS T1 INNER JOIN prof AS T2 ON T1.prof_id = T2.prof_id WHERE T2.teachingability < 3; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
Please write me a SQL statement that answers the following question: Find the most important and most difficult courses. [/INST] [/INST] | SELECT name FROM course WHERE credit = ( SELECT MAX(credit) FROM course ) AND diff = ( SELECT MAX(diff) FROM course ); |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
Please write me a SQL statement that answers the following question: What is the average teaching abil... | SELECT CAST(SUM(teachingability) AS REAL) / COUNT(prof_id) FROM prof WHERE popularity = ( SELECT MAX(popularity) FROM prof ); |
[INST] Here is a database schema:
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
Please write me a SQL statement that answers the following question: Calculate the average satisfaction of ... | SELECT CAST(SUM(sat) AS REAL) / COUNT(course_id) FROM registration WHERE grade = 'B'; |
[INST] Here is a database schema:
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]
gpa [ REAL ]
type [ TEXT ]
Please write me a SQL statement that answers the following question: Among the students with less than four intelligenc... | SELECT f_name, l_name, phone_number FROM student WHERE gpa > 3 AND intelligence < 4; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT T1.f_name, T1.l_name FROM student AS T1 INNER JOIN RA AS T2 ON T1.student_id = T2.student_id WHERE T2.capability > ( SELECT AVG(capability) FROM RA ); |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T1.f_name, T1.l_name, T3.name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T1.intelligence = 5 AND T1.gpa < 3; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT CAST(SUM(T1.capability) AS REAL) / COUNT(T1.student_id) FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T2.gpa < 2.5; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T1.first_name, T1.last_name FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id WHERE T3.intelligence = 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT AVG(T1.gpa) FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.diff IN (2, 1) GROUP BY T3.diff; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.st... | SELECT T2.f_name, T2.l_name, T1.capability FROM RA AS T1 INNER JOIN student AS T2 ON T2.student_id = T1.student_id INNER JOIN registration AS T3 ON T2.student_id = T3.student_id WHERE T3.grade IS NULL OR T3.grade = ''; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
registration :
course_id [ INTEGER ] registra... | SELECT COUNT(T1.student_id) FROM RA AS T1 INNER JOIN registration AS T2 ON T2.student_id = T1.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T1.salary = 'high' AND T3.name = 'Computer Vision'; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T1.first_name, T1.last_name, T1.popularity FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id GROUP BY T1.prof_id ORDER BY COUNT(T2.student_id) DESC LIMIT 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T3.name, T2.f_name, T2.l_name FROM registration AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T1.course_id = T3.course_id WHERE T1.grade = 'A' GROUP BY T3.name ORDER BY COUNT(T1.student_id) DESC LIMIT 1; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.st... | SELECT AVG(T2.sat) - ( SELECT AVG(T2.sat) FROM RA AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id WHERE T1.salary = 'free' ) AS diff FROM RA AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id WHERE T1.salary = 'high'; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T1.graduate_from FROM prof AS T1 INNER JOIN RA AS T2 ON T1.prof_id = T2.prof_id INNER JOIN student AS T3 ON T2.student_id = T3.student_id WHERE T3.type = 'UG' GROUP BY T1.prof_id ORDER BY COUNT(T2.student_id) DESC LIMIT 1; |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT T2.first_name, T2.last_name, T2.email FROM RA AS T1 INNER JOIN prof AS T2 ON T1.prof_id = T2.prof_id WHERE T2.teachingability > ( SELECT AVG(teachingability) FROM prof ) GROUP BY T2.prof_id HAVING COUNT(T1.student_id) >= 2; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
Please write m... | SELECT CAST(( SELECT COUNT(*) FROM course WHERE name = 'Intro to Database 2' AND course_id IN ( SELECT course_id FROM registration WHERE sat = ( SELECT MAX(sat) FROM registration ) ) ) AS REAL) * 100 / COUNT(T1.student_id) FROM registration AS T1 INNER JOIN course AS T2 ON T1.course_id = T2.course_id WHERE T2.name = '... |
[INST] Here is a database schema:
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]
gpa [ REAL ]
type [ TEXT ]
Please write me a SQL statement that answers the following question: What is the first and last name of students with h... | SELECT f_name, l_name FROM student WHERE gpa = ( SELECT MAX(gpa) FROM student ); |
[INST] Here is a database schema:
prof :
prof_id [ INTEGER ] primary_key
gender [ TEXT ]
first_name [ TEXT ]
last_name [ TEXT ]
email [ TEXT ]
popularity [ INTEGER ]
teachingability [ INTEGER ]
graduate_from [ TEXT ]
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER... | SELECT COUNT(T1.student_id) FROM RA AS T1 INNER JOIN prof AS T2 ON T1.prof_id = T2.prof_id WHERE T1.salary = 'high' ORDER BY T2.teachingability DESC LIMIT 1; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT T1.salary FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T2.email = 'grosellg@hku.hk'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT COUNT(T1.student_id) FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'Statistical learning' AND T2.sat = 4 AND T1.gpa = 3.8; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT COUNT(T1.student_id) FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.diff = 3 AND T1.intelligence = 2; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T1.f_name, T1.l_name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.name = 'Applied Deep Learning ' AND T2.grade = 'C'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
name [ TEXT ]
credit [ INTEGER ]
diff [ INTEGER ]
registration :
course_id [ INTEGER ] registration.course_id = course.course_id
student_id [ INTEGER ] registration.student_id = student.student_id
grade [ TEXT ]
sat [ INTEGER ]
student :
stude... | SELECT T3.name FROM student AS T1 INNER JOIN registration AS T2 ON T1.student_id = T2.student_id INNER JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T2.sat = 1 AND T1.type = 'RPG'; |
[INST] Here is a database schema:
RA :
student_id [ INTEGER ] RA.student_id = student.student_id
capability [ INTEGER ]
prof_id [ INTEGER ] RA.prof_id = prof.prof_id
salary [ TEXT ]
student :
student_id [ INTEGER ] primary_key
f_name [ TEXT ]
l_name [ TEXT ]
phone_number [ TEXT ]
email [ TEXT ]
intelligence [ INTEGER ]... | SELECT SUM(CASE WHEN T2.type = 'UG' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.type = 'RPG' THEN 1 ELSE 0 END) FROM RA AS T1 INNER JOIN student AS T2 ON T1.student_id = T2.student_id WHERE T1.capability < 3; |
[INST] Here is a database schema:
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
Please write me a SQL statement that answers the following question: What is the average number of students for each advisor? [/INST] [/INST] | SELECT CAST(COUNT(p_id) AS REAL) / COUNT(DISTINCT p_id_dummy) AS avgnum FROM advisedBy GROUP BY p_id_dummy; |
[INST] Here is a database schema:
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: How many professors are teaching course ID 18? [/INST] [/INST] | SELECT COUNT(DISTINCT p_id) FROM taughtBy WHERE course_id = 18; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
Please write me a SQL statement that answers the following question: List all the course IDs for professional or master/graduate courses. [/INST] [/INST] | SELECT course_id FROM course WHERE courseLevel = 'Level_500'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
Please write me a SQL statement that answers the following question: How many courses are there for basic or medium undergraduate courses? [/INST] [/INST] | SELECT COUNT(course_id) FROM course WHERE courseLevel = 'Level_300'; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL state... | SELECT T2.p_id, T2.course_id FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id WHERE T1.professor = 1 AND T1.hasPosition <> 0; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: Provide the ID of professors who are... | SELECT T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_400'; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
taughtBy :
course_id [ INTEG... | SELECT T3.course_id FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id INNER JOIN taughtBy AS T3 ON T2.p_id = T3.p_id WHERE T1.p_id = 141; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
Please write me a SQL state... | SELECT T1.p_id FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.yearsInProgram = 'Year_3'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: Which level of courses is taught by ... | SELECT T1.courseLevel FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T2.p_id = 297; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: What level is course 165? List the p... | SELECT T1.courseLevel, T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T2.course_id = 165; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
Please write me a SQL state... | SELECT T1.p_id, T2.yearsInProgram FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T1.p_id_dummy = 5; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ IN... | SELECT T3.course_id, T3.courseLevel FROM taughtBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T1.course_id WHERE T2.hasPosition = 'Faculty_eme'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = pe... | SELECT T1.p_id_dummy, T2.courseLevel FROM advisedBy AS T1 INNER JOIN course AS T2 ON T1.p_id = T2.course_id INNER JOIN taughtBy AS T3 ON T2.course_id = T3.course_id WHERE T1.p_id = 80; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: Provide the ID of professors who tea... | SELECT DISTINCT T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_400' OR T1.courseLevel = 'Level_500'; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
Please write me a SQL state... | SELECT T1.p_id_dummy FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.yearsInProgram = 'Year_12'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: Which are the courses with the most ... | SELECT T1.course_id, T1.courseLevel FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id, T1.courseLevel ORDER BY COUNT(T1.course_id) DESC LIMIT 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
Please write me a SQL statement that answers the following question: How many basic and medium undergraduate courses are there? [/INST] [/INST] | SELECT COUNT(*) FROM course WHERE courseLevel = 'Level_300'; |
[INST] Here is a database schema:
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: How many people teaches course no.11? [/INST] [/INST] | SELECT COUNT(*) FROM taughtBy WHERE course_id = 11; |
[INST] Here is a database schema:
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: Which course has more teachers, course no.16 or course no.18? [/INST] [/INST] | SELECT course_id FROM taughtBy WHERE course_id = 11 OR course_id = 18 GROUP BY course_id ORDER BY COUNT(course_id) DESC LIMIT 1; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
Please write me a SQL statement that answers the following question: How many teachers are faculty employees? [/INST] [/INST] | SELECT COUNT(*) FROM person WHERE hasPosition = 'Faculty_eme'; |
[INST] Here is a database schema:
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
Please write me a SQL statement that answers the following question: Please list the IDs of the teachers who have advised more than 4 others to teach. [/INST] [/INST] | SELECT p_id_dummy FROM advisedBy GROUP BY p_id_dummy HAVING COUNT(p_id_dummy) > 4; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ IN... | SELECT COUNT(*) FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id INNER JOIN person AS T3 ON T3.p_id = T2.p_id WHERE T1.courseLevel = 'Level_300' AND T3.professor = 1; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ IN... | SELECT T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id INNER JOIN person AS T3 ON T3.p_id = T2.p_id WHERE T1.courseLevel = 'Level_300' AND T3.hasPosition = 'Faculty_eme'; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL state... | SELECT T2.hasPosition FROM taughtBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T1.course_id = 9; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: Please list the levels of the all co... | SELECT T1.courseLevel FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T2.p_id = 79; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
Please write me a SQL state... | SELECT T1.p_id_dummy FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.yearsInProgram = 'Year_5'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ]... | SELECT COUNT(DISTINCT T4.p_id) FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T2.course_id INNER JOIN advisedBy AS T4 ON T4.p_id = T1.p_id WHERE T1.professor = 1 AND T3.courseLevel = 'Level_300'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ IN... | SELECT COUNT(*) FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id INNER JOIN person AS T3 ON T2.p_id = T3.p_id WHERE T3.professor = 1 AND T1.courseLevel = 'Level_300'; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = pe... | SELECT T2.course_id FROM taughtBy AS T1 INNER JOIN course AS T2 ON T1.course_id = T2.course_id INNER JOIN advisedBy AS T3 ON T3.p_id = T1.p_id WHERE T1.p_id = 9; |
[INST] Here is a database schema:
course :
course_id [ INTEGER ] primary_key
courseLevel [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL statement that answers the following question: What is the level of the course with... | SELECT T1.courseLevel FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id GROUP BY T2.course_id ORDER BY COUNT(T2.p_id) DESC LIMIT 1; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL state... | SELECT T1.p_id FROM taughtBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.professor = 1 GROUP BY T1.p_id HAVING COUNT(DISTINCT T1.course_id) > 3; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
taughtBy :
course_id [ INTEGER ] taughtBy.course_id = course.course_id
p_id [ INTEGER ] taughtBy.p_id = person.p_id
Please write me a SQL state... | SELECT T1.p_id FROM taughtBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.professor = 1 GROUP BY T1.p_id ORDER BY COUNT(*) DESC LIMIT 3; |
[INST] Here is a database schema:
person :
p_id [ INTEGER ] primary_key
professor [ INTEGER ]
student [ INTEGER ]
hasPosition [ TEXT ]
inPhase [ TEXT ]
yearsInProgram [ TEXT ]
advisedBy :
p_id [ INTEGER ] advisedBy.p_id = person.p_id
p_id_dummy [ INTEGER ] advisedBy.p_id_dummy = person.p_id
Please write me a SQL state... | SELECT COUNT(DISTINCT T1.p_id_dummy) FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.yearsInProgram = 'Year_3'; |
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