Split (2)

train · 9.43k rows

input stringlengths 122 2.7k	output stringlengths 24 805
[INST] Here is a database schema: station : id [ INTEGER ] primary_key name [ TEXT ] lat [ REAL ] long [ REAL ] dock_count [ INTEGER ] city [ TEXT ] installation_date [ TEXT ] trip : id [ INTEGER ] primary_key duration [ INTEGER ] start_date [ TEXT ] start_station_name [ TEXT ] start_station_id [ INTEGER ] end_date [ T...	SELECT COUNT(T1.id), T2.dock_count FROM trip AS T1 INNER JOIN station AS T2 ON T2.name = T1.start_station_name WHERE T1.end_station_name = 'MLK Library' AND T1.subscription_type = 'Subscriber' AND T2.dock_count = 19;
[INST] Here is a database schema: station : id [ INTEGER ] primary_key name [ TEXT ] lat [ REAL ] long [ REAL ] dock_count [ INTEGER ] city [ TEXT ] installation_date [ TEXT ] trip : id [ INTEGER ] primary_key duration [ INTEGER ] start_date [ TEXT ] start_station_name [ TEXT ] start_station_id [ INTEGER ] end_date [ T...	SELECT AVG(T3.min_temperature_f), T1.long, T1.lat FROM station AS T1 INNER JOIN trip AS T2 ON T2.start_station_name = T1.name INNER JOIN weather AS T3 ON T3.zip_code = T2.zip_code WHERE T3.zip_code = 94301;
[INST] Here is a database schema: station : id [ INTEGER ] primary_key name [ TEXT ] lat [ REAL ] long [ REAL ] dock_count [ INTEGER ] city [ TEXT ] installation_date [ TEXT ] trip : id [ INTEGER ] primary_key duration [ INTEGER ] start_date [ TEXT ] start_station_name [ TEXT ] start_station_id [ INTEGER ] end_date [ T...	SELECT AVG(T1.duration), T2.installation_date FROM trip AS T1 INNER JOIN station AS T2 ON T2.name = T1.start_station_name WHERE T1.start_station_name = 'Mountain View City Hall' AND T1.subscription_type = 'Subscriber' AND T1.end_station_name = 'Mountain View City Hall';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT description FROM film WHERE title = 'ACADEMY DINOSAUR';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(film_id) FROM film WHERE rental_duration > 6;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT title FROM film WHERE release_year = 2006 AND rental_rate = 2.99;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT title FROM film ORDER BY length DESC LIMIT 1;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT title FROM film WHERE title IN ('ACE GOLDFINGER', 'ACADEMY DINOSAUR') ORDER BY replacement_cost DESC LIMIT 1;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(film_id) FROM film WHERE rating = 'NC-17' AND release_year = 2006;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(film_id) FROM film WHERE rental_rate = 2.99 AND special_features = 'Deleted Scenes';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT title FROM ( SELECT title, COUNT(special_features) AS num FROM film GROUP BY title ) AS T ORDER BY T.num > 2;
[INST] Here is a database schema: staff : staff_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address_id [ INTEGER ] picture [ BLOB ] email [ TEXT ] store_id [ INTEGER ] active [ INTEGER ] username [ TEXT ] password [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the ...	SELECT email FROM staff WHERE first_name = 'Jon' AND last_name = 'Stephens';
[INST] Here is a database schema: staff : staff_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address_id [ INTEGER ] picture [ BLOB ] email [ TEXT ] store_id [ INTEGER ] active [ INTEGER ] username [ TEXT ] password [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the ...	SELECT first_name, last_name FROM staff WHERE active = 1;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT DISTINCT release_year FROM film WHERE replacement_cost = ( SELECT MAX(replacement_cost) FROM film );
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT title FROM film WHERE replacement_cost = ( SELECT MAX(replacement_cost) FROM film ) LIMIT 3;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT T2.name FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'ACADEMY DINOSAUR';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T2.title FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T3.first_name = 'PENELOPE' AND T3.last_name = 'GUINESS';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(T1.actor_id) FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id WHERE T2.title = 'ACADEMY DINOSAUR';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'ACADEMY DINOSAUR';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT COUNT(T2.film_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.release_year = 2006 AND T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' ORDER BY T3.replacement_cost DESC LIMIT 1;
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT first_name, last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id ORDER BY T3.replacement_cost DESC LIMIT 1;
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT COUNT(T3.film_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN language AS T4 ON T3.language_id = T4.language_id WHERE T4.name = 'English' AND T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' ORDER BY T3.length DESC LIMIT 1;
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror';
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film_category : film_id [ INTEGER ] category_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many films are there under the category o...	SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Horror';
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror' AND T1.rental_rate = 2.99;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inve...	SELECT COUNT(T2.rental_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT...	SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT...	SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T4.release_year = 2006 AND T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT...	SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' ORDER BY T4.replacement_cost DESC LIMIT 1;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT...	SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id ORDER BY T4.replacement_cost DESC LIMIT 1;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inve...	SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ' AND STRFTIME('%m',T2.return_date) = '8' AND STRFTIME('%Y', T2.return_date) = '2005';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inve...	SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.rental_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT...	SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.active = 1 AND T4.title = 'ACADEMY DINOSAUR';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT T.title FROM ( SELECT T1.title, COUNT(T3.rental_id) AS num FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T1.title ) AS T ORDER BY T.num DESC LIMIT 1;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inve...	SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE (T1.first_name = 'RUTH' AND T1.last_name = 'MARTINEZ') OR (T1.first_name = 'LINDA' AND T1.last_name = 'WILLIAMS') GROUP BY T1.firs...
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS' ORDER BY T3.rental_rate / T3.rental_duration DESC LIMIT 1;
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT AVG(T3.replacement_cost) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T2.name = 'Horror';
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update...	SELECT CAST(SUM(IIF(T3.name = 'Music', 1, 0)) AS REAL) * 100 / COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id INNER JOIN inventory AS T4 ON T1.film_id = T4.film_id INNER JOIN customer AS T5 ON T4.store_id = T5.stor...
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT AVG(T3.length) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'PENELOPE' AND T1.last_name = 'GUINESS';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: Wh...	SELECT email FROM customer WHERE first_name = 'DIANE' AND last_name = 'COLLINS';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: Gi...	SELECT COUNT(customer_id) FROM customer WHERE active = 0;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: Wh...	SELECT first_name, last_name FROM customer WHERE email = 'JEREMY.HURTADO@sakilacustomer.org';
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: Give the postal code for the address ...	SELECT postal_code FROM address WHERE address_id = 65;
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: State the number of addresses in the ...	SELECT COUNT(address_id) FROM address WHERE district = 'Nordrhein-Westfalen';
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: What is the phone number of address N...	SELECT phone FROM address WHERE address_id = '72';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(film_id) FROM film WHERE length = '178';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT special_features FROM film WHERE title = 'UPRISING UPTOWN';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT description FROM film WHERE title = 'ARTIST COLDBLOODED';
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] store : store_id [ INTEGER ] primary_key manager_staff_id [ INTEGER ] address_id [ INTEGER ] last_update [ ...	SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 2;
[INST] Here is a database schema: city : city_id [ INTEGER ] primary_key city [ TEXT ] country_id [ INTEGER ] last_update [ DATETIME ] country : country_id [ INTEGER ] primary_key country [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: Which continent is the mothe...	SELECT T1.country FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T2.city = 'Clarksville';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(T1.actor_id) FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id WHERE T2.release_year = 2006 AND T2.rental_duration = 7 AND T2.rental_duration = 4.99 AND T2.length = 98;
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T3.rating FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'DAN' AND T1.last_name = 'HARRIS' AND T3.length = 77 AND T3.replacement_cost = '9.99';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film_actor : actor_id [ INTEGER ] film_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many films did actor Daryl W...	SELECT COUNT(T1.film_id) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id WHERE T2.first_name = 'DARYL' AND T2.last_name = 'WAHLBERG';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inve...	SELECT T2.return_date FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'SHERRI' AND T1.last_name = 'RHODES' AND T2.rental_date = '2005-07-28 12:27:27';
[INST] Here is a database schema: staff : staff_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address_id [ INTEGER ] picture [ BLOB ] email [ TEXT ] store_id [ INTEGER ] active [ INTEGER ] username [ TEXT ] password [ TEXT ] last_update [ DATETIME ] store : store_id [ INTEGER ] primary_key manager_s...	SELECT T1.first_name, T1.last_name FROM staff AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id WHERE T2.store_id = 1;
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] store : store_id [ INTEGER ] primary_key manager_staff_id [ INTEGER ] address_id [ INTEGER ] last_update [ ...	SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 1;
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] staff : staff_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address_id [ INTEGER ] pict...	SELECT T1.address, T1.address2 FROM address AS T1 INNER JOIN staff AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'Jon' AND T2.last_name = 'Stephens';
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] city : city_id [ INTEGER ] primary_key city [ TEXT ] country_id [ INTEGER ] last_update [ DATETIME ] Pleas...	SELECT COUNT(T1.address_id) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id WHERE T2.city = 'Woodridge';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English';
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] ...	SELECT T1.address FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'HEATHER' AND T2.last_name = 'MORRIS';
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] staff : staff_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address_id [ INTEGER ] pict...	SELECT T2.email FROM address AS T1 INNER JOIN staff AS T2 ON T1.address_id = T2.address_id WHERE T1.address = '1411 Lillydale Drive';
[INST] Here is a database schema: payment : payment_id [ INTEGER ] primary_key customer_id [ INTEGER ] staff_id [ INTEGER ] rental_id [ INTEGER ] amount [ REAL ] payment_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inventory_id [ INTEGER ] customer_id [ ...	SELECT T1.amount FROM payment AS T1 INNER JOIN rental AS T2 ON T1.rental_id = T2.rental_id WHERE T2.rental_date = '2005-07-28 12:27:27' AND T2.customer_id = 297;
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT T3.name FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.title = 'WORKING MICROCOSMOS';
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film_category : film_id [ INTEGER ] category_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: Give the number of documentary films. [/INST]...	SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Documentary';
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film_category : film_id [ INTEGER ] category_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: State the name of the category which has the ...	SELECT T.name FROM ( SELECT T2.name, COUNT(T1.film_id) AS num FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id GROUP BY T2.name ) AS T ORDER BY T.num DESC LIMIT 1;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.inventory_id = 3479;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] payment : payment_id [ INTEGER ] primary_key customer_id [ INTEGER ] sta...	SELECT CAST((SUM(IIF(T2.store_id = 2, T1.amount, 0)) - SUM(IIF(T2.store_id = 1, T1.amount, 0))) AS REAL) * 100 / SUM(IIF(T2.store_id = 1, T1.amount, 0)) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id INNER JOIN store AS T3 ON T2.store_id = T3.store_id;
[INST] Here is a database schema: city : city_id [ INTEGER ] primary_key city [ TEXT ] country_id [ INTEGER ] last_update [ DATETIME ] country : country_id [ INTEGER ] primary_key country [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many times is the number...	SELECT CAST(SUM(IIF(T1.country = 'India', 1, 0)) AS REAL) / SUM(IIF(T1.country = 'Italy', 1, 0)) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id;
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film_actor : actor_id [ INTEGER ] film_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many times is the number of ...	SELECT CAST(SUM(IIF(T2.first_name = 'GINA' AND T2.last_name = 'DEGENERES', 1, 0)) AS REAL) * 100 / SUM(IIF(T2.first_name = 'PENELOPE' AND T2.last_name = 'GUINESS', 1, 0)) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(film_id) FROM film WHERE rating = 'R' AND release_year = 2006;
[INST] Here is a database schema: film_actor : actor_id [ INTEGER ] film_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many actors starred in the film id 508? [/INST] [/INST]	SELECT COUNT(actor_id) FROM film_actor WHERE film_id = 508;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT special_features FROM film WHERE title = 'SMOOCHY CONTROL';
[INST] Here is a database schema: payment : payment_id [ INTEGER ] primary_key customer_id [ INTEGER ] staff_id [ INTEGER ] rental_id [ INTEGER ] amount [ REAL ] payment_date [ DATETIME ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many customers paid over the amou...	SELECT COUNT(customer_id) FROM payment WHERE SUBSTR(payment_date, 1, 7) LIKE '2005-08';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT title FROM film WHERE length > 180;
[INST] Here is a database schema: payment : payment_id [ INTEGER ] primary_key customer_id [ INTEGER ] staff_id [ INTEGER ] rental_id [ INTEGER ] amount [ REAL ] payment_date [ DATETIME ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How much is the total rental payment ...	SELECT SUM(amount) FROM payment WHERE rental_id BETWEEN 1 AND 10;
[INST] Here is a database schema: staff : staff_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] address_id [ INTEGER ] picture [ BLOB ] email [ TEXT ] store_id [ INTEGER ] active [ INTEGER ] username [ TEXT ] password [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the ...	SELECT first_name, last_name FROM staff WHERE active = 1;
[INST] Here is a database schema: store : store_id [ INTEGER ] primary_key manager_staff_id [ INTEGER ] address_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: Who is the staff manager in store id 2? [/INST] [/INST]	SELECT manager_staff_id FROM store WHERE store_id = 2;
[INST] Here is a database schema: rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inventory_id [ INTEGER ] customer_id [ INTEGER ] return_date [ DATETIME ] staff_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many rentals were return...	SELECT COUNT(rental_id) FROM rental WHERE rental_date = '2005-05-27';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Laura' AND T1.last_name = 'Brody';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.store_id = 2;
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inve...	SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN ( SELECT customer_id, COUNT() AS num_days FROM ( SELECT , date(days, '-' \|\| rn \|\| ' day') AS results FROM ( SELECT customer_id, days, row_number() OVER (PARTITION BY customer_id ORDER BY days) AS rn FROM ( SELECT DISTINCT customer_id, date(rental_date)...
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film_category : film_id [ INTEGER ] category_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many films are categorized as horror? [/I...	SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id WHERE T2.name = 'Horror';
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT T.title FROM ( SELECT T1.title, COUNT(T3.rental_id) AS num FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id GROUP BY T1.title ) AS T ORDER BY T.num DESC LIMIT 1;
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT T1.special_features FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'sci-fi' ORDER BY T1.special_features DESC LIMIT 1;
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film_actor : actor_id [ INTEGER ] film_id [ INTEGER ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: What is the full name of the act...	SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.film_id) AS num FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1;
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.rental_duration = 7 AND T3.name = 'Comedy';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] staff : staff_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [...	SELECT T.first_name, T.last_name FROM ( SELECT T3.first_name, T3.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN staff AS T3 ON T2.store_id = T3.store_id WHERE T1.active = 0 GROUP BY T3.first_name, T3.last_name ) AS T ORDER BY T.num DESC LIMIT 1...
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT T1.rental_rate FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Children' ORDER BY T1.rental_rate / T1.rental_duration DESC LIMIT 1;
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] city : city_id [ INTEGER ] primary_key city [ TEXT ] country_id [ INTEGER ] last_update [ DATETIME ] countr...	SELECT T3.address, T3.address2, T3.district FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN store AS T4 ON T3.address_id = T4.address_id WHERE T4.store_id = 1;
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] city : city_id [ INTEGER ] primary_key city [ TEXT ] country_id [ INTEGER ] last_update [ DATETIME ] custom...	SELECT COUNT(T3.customer_id) FROM city AS T1 INNER JOIN address AS T2 ON T1.city_id = T2.city_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.city = 'Lethbridge';
[INST] Here is a database schema: city : city_id [ INTEGER ] primary_key city [ TEXT ] country_id [ INTEGER ] last_update [ DATETIME ] country : country_id [ INTEGER ] primary_key country [ TEXT ] last_update [ DATETIME ] Please write me a SQL statement that answers the following question: How many cities are there in...	SELECT COUNT(T2.city) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T1.country = 'United States';
[INST] Here is a database schema: address : address_id [ INTEGER ] primary_key address [ TEXT ] address2 [ TEXT ] district [ TEXT ] city_id [ INTEGER ] postal_code [ TEXT ] phone [ TEXT ] last_update [ DATETIME ] city : city_id [ INTEGER ] primary_key city [ TEXT ] country_id [ INTEGER ] last_update [ DATETIME ] countr...	SELECT T4.first_name, T4.last_name FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN customer AS T4 ON T3.address_id = T4.address_id WHERE T1.country = 'India';
[INST] Here is a database schema: category : category_id [ INTEGER ] primary_key name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL...	SELECT COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T3.rental_rate < 1 AND T2.name = 'Classics';
[INST] Here is a database schema: customer : customer_id [ INTEGER ] primary_key store_id [ INTEGER ] first_name [ TEXT ] last_name [ TEXT ] email [ TEXT ] address_id [ INTEGER ] active [ INTEGER ] create_date [ DATETIME ] last_update [ DATETIME ] rental : rental_id [ INTEGER ] primary_key rental_date [ DATETIME ] inve...	SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.rental_id) AS num FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1;
[INST] Here is a database schema: film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ] rental_rate [ REAL ] length [ INTEGER ] replacement_cost [ REAL ] rating [ TEXT ] special_features [ TEX...	SELECT COUNT(T3.rental_id) FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id WHERE T1.title = 'Blanket Beverly';
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rating = 'R' GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1;
[INST] Here is a database schema: actor : actor_id [ INTEGER ] primary_key first_name [ TEXT ] last_name [ TEXT ] last_update [ DATETIME ] film : film_id [ INTEGER ] primary_key title [ TEXT ] description [ TEXT ] release_year [ TEXT ] language_id [ INTEGER ] original_language_id [ INTEGER ] rental_duration [ INTEGER ]...	SELECT T.first_name, T.last_name, num FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 5;

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