Split (2)

train · 8.41k rows

input stringlengths 201 2.7k	output stringlengths 24 744
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(owner_state) FROM businesses WHERE owner_state = 'CA';
[INST] Here is a database schema: inspections : business_id [ INTEGER ] inspections.business_id = businesses.business_id score [ INTEGER ] date [ DATE ] type [ TEXT ] Please write me a SQL statement that answers the following question: How many restaurants have met all requirements in the inspection? [/INST] [/INST]	SELECT COUNT(score) FROM inspections WHERE score = 100;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score = 100;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T1.description FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' AND T2.name = 'Tiramisu Kitchen';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(T1.business_id) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.type = 'Routine - Unscheduled' AND T2.name = 'Tiramisu Kitchen';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(T2.business_id) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Tiramisu Kitchen' AND T1.type = 'Routine - Unscheduled' AND T1.score > 70;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT CASE WHEN SUM(CASE WHEN T2.name = 'OMNI S.F. Hotel - 2nd Floor Pantry' THEN 1 ELSE 0 END) > SUM(CASE WHEN T2.name = 'Tiramisu Kitchen' THEN 1 ELSE 0 END) THEN 'OMNI S.F. Hotel - 2nd Floor Pantry' ELSE 'Tiramisu Kitchen' END AS result FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.busine...
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(T2.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.city IN ('San Francisco', 'SF', 'S.F.', 'SAN FRANCISCO') AND T1.risk_category = 'High Risk';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' GROUP BY T2.name ORDER BY COUNT(T2.name) DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Tiramisu Kitchen';
[INST] Here is a database schema: inspections : business_id [ INTEGER ] inspections.business_id = businesses.business_id score [ INTEGER ] date [ DATE ] type [ TEXT ] Please write me a SQL statement that answers the following question: Which business had the most number of inspections? Give the Id number for that busi...	SELECT business_id FROM inspections GROUP BY business_id ORDER BY COUNT(business_id) DESC LIMIT 1;
[INST] Here is a database schema: violations : business_id [ INTEGER ] violations.business_id = businesses.business_id date [ DATE ] violation_type_id [ TEXT ] risk_category [ TEXT ] description [ TEXT ] Please write me a SQL statement that answers the following question: Tell the Id number of the business with the mo...	SELECT business_id FROM violations GROUP BY business_id ORDER BY COUNT(business_id) DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' GROUP BY T2.name ORDER BY COUNT(T2.name) DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.type = 'Complaint' GROUP BY T2.name ORDER BY COUNT(T1.business_id) DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(T1.business_id) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Soma Restaurant And Bar' AND T1.type = 'Routine - Unscheduled';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.address FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'Low Risk' GROUP BY T2.address ORDER BY COUNT(T1.business_id) DESC LIMIT 1;
[INST] Here is a database schema: inspections : business_id [ INTEGER ] inspections.business_id = businesses.business_id score [ INTEGER ] date [ DATE ] type [ TEXT ] violations : business_id [ INTEGER ] violations.business_id = businesses.business_id date [ DATE ] violation_type_id [ TEXT ] risk_category [ TEXT ] desc...	SELECT COUNT(T2.business_id) FROM violations AS T1 INNER JOIN inspections AS T2 ON T1.business_id = T2.business_id GROUP BY T1.business_id ORDER BY COUNT(T1.business_id) DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT CAST(SUM(CASE WHEN T2.name = 'Chairman Bao' THEN T1.score ELSE 0 END) AS REAL) / COUNT(CASE WHEN T1.type = 'Routine - Unscheduled' THEN T1.score ELSE 0 END) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT CAST(SUM(CASE WHEN T2.risk_category = 'Moderate Risk' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T2.business_id) FROM businesses AS T1 INNER JOIN violations AS T2 ON T1.business_id = T2.business_id WHERE T1.name = 'Melody Lounge';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(business_id) FROM businesses WHERE city = 'HAYWARD';
[INST] Here is a database schema: inspections : business_id [ INTEGER ] inspections.business_id = businesses.business_id score [ INTEGER ] date [ DATE ] type [ TEXT ] Please write me a SQL statement that answers the following question: How many establishments have an inspection score of no more than 50? [/INST] [/INST...	SELECT COUNT(DISTINCT business_id) FROM inspections WHERE score < 50;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(business_id) FROM businesses WHERE STRFTIME('%Y', application_date) = '2012';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(T1.owner_name) FROM ( SELECT owner_name FROM businesses GROUP BY owner_name HAVING COUNT(owner_name) > 5 ) T1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score = ( SELECT MIN(score) FROM inspections );
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(T1.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Tiramisu Kitchen' AND T1.risk_category = 'High Risk';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(*) FROM ( SELECT T1.business_id FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.tax_code = 'H24' AND T1.type = 'Complaint' GROUP BY T1.business_id HAVING COUNT(T1.business_id) > 5 ) T3;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id GROUP BY T2.owner_name ORDER BY COUNT(T2.business_id) DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T4.owner_name FROM violations AS T3 INNER JOIN businesses AS T4 ON T3.business_id = T4.business_id INNER JOIN ( SELECT T2.owner_name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id GROUP BY T2.owner_name ORDER BY COUNT(T1.business_id) DESC LIMIT 5 ) AS T5 ON T4.owner_name = T...
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.name, AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id GROUP BY T2.name ORDER BY COUNT(T2.business_id) DESC LIMIT 1;
[INST] Here is a database schema: violations : business_id [ INTEGER ] violations.business_id = businesses.business_id date [ DATE ] violation_type_id [ TEXT ] risk_category [ TEXT ] description [ TEXT ] Please write me a SQL statement that answers the following question: How many eateries had low risk for violation w...	SELECT COUNT(DISTINCT business_id) FROM violations WHERE risk_category = 'Low Risk' AND description = 'Unpermitted food facility';
[INST] Here is a database schema: violations : business_id [ INTEGER ] violations.business_id = businesses.business_id date [ DATE ] violation_type_id [ TEXT ] risk_category [ TEXT ] description [ TEXT ] Please write me a SQL statement that answers the following question: Provide eateries' IDs, risk categories and des...	SELECT business_id, risk_category, description FROM violations WHERE violation_type_id = '103101';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T2.type, T1.description FROM violations AS T1 INNER JOIN inspections AS T2 ON T1.business_id = T2.business_id INNER JOIN businesses AS T3 ON T2.business_id = T3.business_id WHERE T3.name = 'ART''S CAFÉ' AND T1.risk_category = 'Moderate Risk';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T1.violation_type_id, T1.description FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'STARBUCKS' AND T1.risk_category = 'High Risk';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T2.business_id, T2.name, T2.address FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.date = '2016-07-30';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.name, T1.risk_category, T1.description FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.violation_type_id = '103111';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T1.type FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'El Aji Peruvian Restaurant' ORDER BY T1.score DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.owner_name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' AND T1.description = 'Improper cooking time or temperatures';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T2.name, T2.business_id FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score < 50;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(business_id) FROM businesses WHERE address = '1825 POST St #223' AND city = 'SAN FRANCISCO';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT owner_name FROM businesses WHERE owner_zip = '94104';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(tax_code) FROM businesses WHERE tax_code = 'H25';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T2.business_id, T1.risk_category FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.owner_name = 'San Francisco Madeleine, Inc.';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T2.owner_name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score = 100;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT COUNT(DISTINCT T2.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.postal_code = 94117 AND T1.risk_category = 'High Risk';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T1.violation_type_id, T1.risk_category FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id INNER JOIN inspections AS T3 ON T2.business_id = T3.business_id WHERE T3.score BETWEEN 70 AND 80;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T3.tax_code, T2.type FROM violations AS T1 INNER JOIN inspections AS T2 ON T1.business_id = T2.business_id INNER JOIN businesses AS T3 ON T2.business_id = T3.business_id WHERE T3.name = 'Rue Lepic';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T2.owner_name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' AND T1.violation_type_id = 103109 AND T1.description = 'Unclean or unsanitary food contact surfaces';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.owner_city = 'Cameron Park' AND T1.score = 100;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T1.violation_type_id FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.business_id BETWEEN 30 AND 50 AND T2.address = '747 IRVING St' AND T2.city = 'San Francisco';
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT T1.type FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.owner_address = '500 California St, 2nd Floor' AND T2.owner_city = 'SAN FRANCISCO' ORDER BY T1.score DESC LIMIT 1;
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT DISTINCT T1.name, T3.risk_category FROM businesses AS T1 INNER JOIN inspections AS T2 ON T1.business_id = T2.business_id INNER JOIN violations AS T3 ON T1.business_id = T3.business_id WHERE T2.score > 0.8 * ( SELECT AVG(score) FROM inspections );
[INST] Here is a database schema: businesses : business_id [ INTEGER ] primary_key name [ TEXT ] address [ TEXT ] city [ TEXT ] postal_code [ TEXT ] latitude [ REAL ] longitude [ REAL ] phone_number [ INTEGER ] tax_code [ TEXT ] business_certificate [ INTEGER ] application_date [ DATE ] owner_name [ TEXT ] owner_addres...	SELECT CAST(SUM(CASE WHEN T1.risk_category = 'Low Risk' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.risk_category) FROM violations AS T1 INNER JOIN inspections AS T2 ON T1.business_id = T2.business_id INNER JOIN businesses AS T3 ON T2.business_id = T3.business_id WHERE T2.score < 95 AND T3.postal_code = 94110;
[INST] Here is a database schema: breweries : id [ INTEGER ] primary_key name [ TEXT ] city [ TEXT ] state [ TEXT ] beers : id [ INTEGER ] primary_key brewery_id [ INTEGER ] abv [ REAL ] ibu [ REAL ] name [ TEXT ] style [ TEXT ] ounces [ REAL ] Please write me a SQL statement that answers the following question: Which...	SELECT DISTINCT T2.state, T1.ibu FROM beers AS T1 INNER JOIN breweries AS T2 ON T1.brewery_id = T2.id WHERE T1.ibu IS NOT NULL AND T1.ibu = ( SELECT MIN(ibu) FROM beers );
[INST] Here is a database schema: breweries : id [ INTEGER ] primary_key name [ TEXT ] city [ TEXT ] state [ TEXT ] beers : id [ INTEGER ] primary_key brewery_id [ INTEGER ] abv [ REAL ] ibu [ REAL ] name [ TEXT ] style [ TEXT ] ounces [ REAL ] Please write me a SQL statement that answers the following question: Where...	SELECT T2.name, T2.city FROM beers AS T1 INNER JOIN breweries AS T2 ON T1.brewery_id = T2.id WHERE T2.state = 'NY' ORDER BY T1.ibu DESC LIMIT 1;
[INST] Here is a database schema: breweries : id [ INTEGER ] primary_key name [ TEXT ] city [ TEXT ] state [ TEXT ] beers : id [ INTEGER ] primary_key brewery_id [ INTEGER ] abv [ REAL ] ibu [ REAL ] name [ TEXT ] style [ TEXT ] ounces [ REAL ] Please write me a SQL statement that answers the following question: What ...	SELECT AVG(T1.abv) FROM beers AS T1 INNER JOIN breweries AS T2 ON T1.brewery_id = T2.id WHERE T2.name = 'Boston Beer Company' AND T1.ounces = 12;
[INST] Here is a database schema: breweries : id [ INTEGER ] primary_key name [ TEXT ] city [ TEXT ] state [ TEXT ] beers : id [ INTEGER ] primary_key brewery_id [ INTEGER ] abv [ REAL ] ibu [ REAL ] name [ TEXT ] style [ TEXT ] ounces [ REAL ] Please write me a SQL statement that answers the following question: Of al...	SELECT CAST(SUM(IIF(T1.style = 'American Adjunct Lager', 1, 0)) AS REAL) * 100 / COUNT(T1.brewery_id) FROM beers AS T1 INNER JOIN breweries AS T2 ON T1.brewery_id = T2.id WHERE T2.name = 'Stevens Point Brewery';
[INST] Here is a database schema: breweries : id [ INTEGER ] primary_key name [ TEXT ] city [ TEXT ] state [ TEXT ] beers : id [ INTEGER ] primary_key brewery_id [ INTEGER ] abv [ REAL ] ibu [ REAL ] name [ TEXT ] style [ TEXT ] ounces [ REAL ] Please write me a SQL statement that answers the following question: Which...	SELECT T1.state, T1.city, T2.name, T2.ibu FROM breweries AS T1 INNER JOIN beers AS T2 ON T1.id = T2.brewery_id GROUP BY T1.state, T1.city, T2.name, T2.ibu HAVING MAX(ibu) AND MIN(ibu) LIMIT 2;
[INST] Here is a database schema: breweries : id [ INTEGER ] primary_key name [ TEXT ] city [ TEXT ] state [ TEXT ] beers : id [ INTEGER ] primary_key brewery_id [ INTEGER ] abv [ REAL ] ibu [ REAL ] name [ TEXT ] style [ TEXT ] ounces [ REAL ] Please write me a SQL statement that answers the following question: When ...	SELECT CAST(SUM(IIF(T2.state = 'WI', 1, 0)) AS REAL) * 100 / COUNT(T1.id) FROM beers AS T1 INNER JOIN breweries AS T2 ON T1.brewery_id = T2.id WHERE T1.style = 'American Blonde Ale';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.total_fat DESC LIMIT 1;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T2.total_fat - T2.sat_fat FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Raspberry Chiffon Pie';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.sodium < 5;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.iron > 20;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT DISTINCT CASE WHEN CASE WHEN T2.title = 'Raspberry Chiffon Pie' THEN T1.vitamin_c END > CASE WHEN T2.title = 'Fresh Apricot Bavarian' THEN T1.vitamin_c END THEN 'Raspberry Chiffon Pie' ELSE 'Fresh Apricot Bavarian' END AS "vitamin_c is higher" FROM Nutrition T1 INNER JOIN Recipe T2 ON T2.recipe_id = T1.recipe_id...
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.prep_min > 10 ORDER BY T2.calories DESC LIMIT 1;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T2.calories FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Raspberry Chiffon Pie';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT T2.optional FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Raspberry Chiffon Pie' AND T3.name = 'graham cracker crumbs';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_i...	SELECT COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Raspberry Chiffon Pie' AND T2.max_qty = T2.min_qty;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT T3.name FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Raspberry Chiffon Pie' AND T2.preparation IS NULL;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT COUNT(*) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id WHERE T1.name = 'graham cracker crumbs';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT T2.min_qty FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Raspberry Chiffon Pie' AND T3.name = 'graham cracker crumbs';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T2.calories * T2.pcnt_cal_fat FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Raspberry Chiffon Pie';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT AVG(T2.calories) FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.source = 'Produce for Better Health Foundation and 5 a Day';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T2.calories FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Turkey Tenderloin Bundles';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT COUNT(*) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id WHERE T1.name = '1% lowfat milk' AND T2.unit = 'cup(s)' AND T2.recipe_id = 1436;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.total_fat DESC LIMIT 1;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT COUNT(*) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id WHERE T1.name = 'seedless red grapes';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT T1.name FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id WHERE T2.recipe_id = 1397 AND T2.optional = 'TRUE';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T3.name = 'frozen raspberries in light syrup' AND T2.max_qty = T2.min_qty;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT T1.name FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id GROUP BY T1.name ORDER BY COUNT(T1.name) DESC LIMIT 1;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT T2.preparation FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Raspberry-Pear Couscous Cake' AND T3.name = 'apple juice';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Chicken Pocket Sandwich' AND T3.name = 'almonds' AND T2.unit = 'cup(s)';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.vitamin_c DESC LIMIT 1;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T2.vitamin_a FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Sherried Beef';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_i...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id GROUP BY T1.title ORDER BY COUNT(title) DESC LIMIT 1;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT CAST(SUM(CASE WHEN T1.title = 'Lasagne-Spinach Spirals' THEN T2.sodium ELSE 0 END) AS REAL) * 100 / SUM(CASE WHEN T1.title = 'Beef and Spinach Pita Pockets' THEN T2.sodium ELSE 0 END) FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition.recipe_id = Recipe.recipe_id protein [ REAL ] carbo [ REAL ] alcohol [ REAL ] total_fat [ REAL ] sat_fat [ REAL ] cholestrl [ REAL ...	SELECT AVG(T3.calories) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T2.ingredient_id = T1.ingredient_id INNER JOIN Nutrition AS T3 ON T3.recipe_id = T2.recipe_id WHERE T1.name = 'coarsely ground black pepper';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.iron > 20;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_i...	SELECT COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.title = 'Apricot Yogurt Parfaits';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT T1.name FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id WHERE T2.preparation = 'cooked in beef broth';
[INST] Here is a database schema: Nutrition : recipe_id [ INTEGER ] primary_key Nutrition.recipe_id = Recipe.recipe_id protein [ REAL ] carbo [ REAL ] alcohol [ REAL ] total_fat [ REAL ] sat_fat [ REAL ] cholestrl [ REAL ] sodium [ REAL ] iron [ REAL ] vitamin_c [ REAL ] vitamin_a [ REAL ] fiber [ REAL ] pcnt_cal_carb ...	SELECT COUNT(*) FROM Nutrition AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.vitamin_a > 0;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.vitamin_c DESC LIMIT 5;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT T1.name FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T1.ingredient_id = T2.ingredient_id GROUP BY T2.ingredient_id ORDER BY COUNT(T2.ingredient_id) ASC LIMIT 1;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT COUNT(*) FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T3.category = 'baking products' AND T1.title = 'No-Bake Chocolate Cheesecake';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT T3.name FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Strawberry Sorbet';
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source ...	SELECT T3.name FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id INNER JOIN Ingredient AS T3 ON T3.ingredient_id = T2.ingredient_id WHERE T1.title = 'Warm Chinese Chicken Salad' AND T2.optional = 'TRUE';
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T2.alcohol > 10 ORDER BY T1.prep_min DESC LIMIT 1;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT COUNT(T1.title) FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id ORDER BY T2.total_fat - T2.sat_fat DESC LIMIT 1;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Nutrition : recipe_id [ INTEGER ] primary_key Nutrition...	SELECT T1.title FROM Recipe AS T1 INNER JOIN Nutrition AS T2 ON T1.recipe_id = T2.recipe_id WHERE T1.source = 'National Potato Board' ORDER BY T2.calories DESC LIMIT 1;
[INST] Here is a database schema: Recipe : recipe_id [ INTEGER ] primary_key title [ TEXT ] subtitle [ TEXT ] servings [ INTEGER ] yield_unit [ TEXT ] prep_min [ INTEGER ] cook_min [ INTEGER ] stnd_min [ INTEGER ] source [ TEXT ] intro [ TEXT ] directions [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_i...	SELECT T2.recipe_id, T1.prep_min + T1.cook_min + T1.stnd_min FROM Recipe AS T1 INNER JOIN Quantity AS T2 ON T1.recipe_id = T2.recipe_id GROUP BY T2.recipe_id ORDER BY COUNT(T2.ingredient_id) DESC LIMIT 1;
[INST] Here is a database schema: Ingredient : ingredient_id [ INTEGER ] primary_key category [ TEXT ] name [ TEXT ] plural [ TEXT ] Quantity : quantity_id [ INTEGER ] primary_key recipe_id [ INTEGER ] Quantity.recipe_id = Recipe.recipe_id ingredient_id [ INTEGER ] Quantity.ingredient_id = Ingredient.ingredient_id max_...	SELECT T1.name, CAST(COUNT(T2.ingredient_id) AS FLOAT) * 100 / ( SELECT COUNT(T2.ingredient_id) FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T2.ingredient_id = T1.ingredient_id ) AS "percentage" FROM Ingredient AS T1 INNER JOIN Quantity AS T2 ON T2.ingredient_id = T1.ingredient_id GROUP BY T2.ingredient_id ORDER ...

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