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1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void solve() { int n, k, x[3]; cin >> n >> k; priority_queue<int> q; vector<int> v; priority_queue<int, vector<int>, greater<int>> qq[2]; long long ans = 0; for (int i = 0; i < n; i++) { for (int j = 0; j < 3; j++) cin >> x[j]; if (x[1] & x[2]) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python2
from __future__ import division import sys input = sys.stdin.readline import math from math import sqrt, floor, ceil from collections import Counter, defaultdict ############ ---- Input Functions ---- ############ def inp(): return(int(input())) def inlt(): return(list(map(int,input().split()))) def insr():...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int xx[] = {0, 0, -1, 1}, yy[] = {-1, 1, 0, 0}; using ll = long long; using ppi = pair<int, int>; using ppl = pair<ll, ll>; vector<ll> L, R, M; ll p(const vector<ll>& v, ll c) { if (c <= 0) return 0; return v[c - 1]; } const ll INF = 5e10; int main() { ios::sync_with_...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long power(long long x, long long n); bool isprime(long long n); struct node { long long a, b, t; }; bool f(node n1, node n2) { return n1.t < n2.t; } void test_case() { long long n, k; cin >> n >> k; node arr[n]; for (long long i = 0; i < n; i++) cin >> arr[i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, k = map(int, input().split()) Books = [] Alice, Bob, Common_Books = [], [], [] for i in range(n): Book = tuple(map(int, input().split())) Books.append(Book) Books = sorted(Books, key=lambda x:x[0]) # print(Books) for Book in Books: if Book[1] == 1 and Book[2] == 1: Com...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void solve() { int n, k; cin >> n >> k; vector<int> a, b, c; for (int i = 0; i < n; i++) { int x, y, z; cin >> x >> y >> z; if (y == 0 && z == 0) continue; else if (y == 1 && z == 0) a.push_back(x); else if (y == 0 && z == 1) b....
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int gcd(int a, int b) { if (b == 0) return a; return gcd(b, a % b); } int isPrime(int n) { if (n < 2) return 0; if (n < 4) return 1; if (n % 2 == 0 or n % 3 == 0) return 0; for (int i = 5; i * i <= n; i += 6) if (n % i == 0 or n % (i + 2) == 0) return 0; r...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split(" ")) both=[] bob=[] alice=[] for i in range(n): t,a,b=map(int,input().split(" ")) if a==1 and b==1: both.append(t) elif a==1: alice.append(t) elif b==1: bob.append(t) if len(both)==0: both.sort() if len(alice)==0: alice.sort() if len(bob)...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import static java.lang.Math.*; import static java.util.Arrays.*; public class cf1374e2_3 { public static void main(String[] args) throws IOException { int n = rni(), m = ni(), k = ni(), t[] = new int[n + 1]; List<int[]> a11 = new ArrayList<>(), a01 = new Arr...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, k = [int(x) for x in input().split()] both = [] bob = [] alice = [] for i in range(n): t, a, b = [int(x) for x in input().split()] if(a==1 and b==1): both.append(t) elif(a==1): alice.append(t) elif(b==1): bob.append(t) both.sort() bob.sort() alice.sort() y = max(k-min(len(b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int32_t main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); ; long long n, k; cin >> n >> k; vector<long long> a; vector<long long> b; vector<long long> same; for (long long i = 0; i < n; i++) { long long t, x, y; cin >> t >> x >> y; i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.InputStreamReader; public class ReplaceToMakeRegularBracketSequence { /** * @param args */ public static void main(String[] args)throws Exception { // TODO Auto-generated method stub BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; public class R653E2{ public static void main(String[] main) throws Exception{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); StringTokenizer st = new StringTokenizer(br.readLine()); PrintWriter out = new PrintWriter(System.out); ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<climits> #include<cmath> #include<ctime> #include<vector> #include<queue> #include<stack> #include<list> #include<set> #include<map> #include<utility> #include<algorithm> using namespace std; #define FOR(i,a,b) for(register int i=(a);i<(b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
from collections import Counter, defaultdict BS="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ" def to_base(s, b): res = "" while s: res+=BS[s%b] s//= b return res[::-1] or "0" alpha = "abcdefghijklmnopqrstuvwxyz" from math import floor, ceil,pi primes = [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
line = input().split() n,k = int(line[0]), int(line[1]) a,b,c = [],[],[] for i in range(n): line = input().split() t,ai,bi = int(line[0]), int(line[1]), int(line[2]) if (ai == 1 and bi == 1): c.append(t) elif (ai == 1): a.append(t) elif (bi == 1): b.append(t) a.sort() b.sort() c.sort() i,j,cnt = 0,0,0 an...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int INF = 1e9; const int MOD = 1e9 + 7; int main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); int n, m, k; cin >> n >> m >> k; vector<pair<int, int>> al, bob, both, bad; vector<int> ind; for (int i = 0; i < n; i++) { int t, a, b; c...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; vector<long long> D; vector<long long> B; vector<long long> A; int main() { long long a = 0, b = 0; long long n, k; long long ti, al, bl, time = 0; cin >> n >> k; for (long long i = 0; i < n; ++i) { cin >> ti >> al >> bl; if (al + bl == 2) D.push_bac...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include<bits/stdc++.h> using namespace std; #include <ext/pb_ds/assoc_container.hpp> // Common file #include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update using namespace __gnu_pbds; typedef long long ll; typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_updat...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python2
I=lambda: map(int, raw_input().split()) n, k = I() a = [] b = [] ab = [] for _ in xrange(n): t, a1, b1 = I() if a1==1 and b1==1: ab.append(t) elif a1==1: a.append(t) elif b1==1: b.append(t) ab.sort() a.sort() b.sort() lab = len(ab) la = len(a) lb = len(b) mlalb = min(la, lb) if lab+mlalb < k: print -1 exit(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split()) x=[] y=[] z=[] k1=0 k2=0 for i in range(n): t,a,b=map(int,input().split()) if(a==1 and b==1): x.append(t) k1+=1 k2+=1 else: if(a==1): k1+=1 y.append(t) else: k2+=1 z.append(t) if(k1<k or k2<k): print(-1) else: x.sort() y.sort() z.sort() ans=0 k1=0 k2=0 p1=0...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n ,k = map(int, input().split(" ")) arr_both = [] arr_alice = [] arr_bob = [] for i in range(n): t1 ,t2, t3 = map(int, input().split(" ")) if(t2==0 and t3==0): continue elif(t2==1 and t3==1): arr_both.append(t1) elif(t2==1): arr_alice.append(t1) else: arr_bob.append(t1) i = 0 j = 0 while(i<len(arr_alic...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.util.ArrayList; import java.util.PriorityQueue; import java.util.StringTokenizer; public class Main { static int N, K; static PriorityQueue<Point>...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys from collections import defaultdict as dd from collections import deque from fractions import Fraction as f from copy import * from bisect import * from heapq import * from math import * from itertools import permutations def eprint(*args): print(*args, file=sys.stderr) zz=1 #sys.setrecursionlimit(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.math.BigInteger; import java.util.*; public class Main { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); PrintWriter pw = new PrintWriter(System.out); static int MOD = 1000000007; public static void main(String[] args) throws IOException { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; public class Main { static class Pair { int f,s; Pair(int f,int s) { this.f=f; this.s=s; } } static class comp implements Comparator<Pair> { public int compare(Pair p1,Pair p2) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split()) aa=[] bb=[] both=[] non=[] for i in range(n): t,a,b=map(int,input().split()) if (a==1 and b==0): aa.append(t) elif (a==0 and b==1): bb.append(t) elif (a==1 and b==1): both.append(t) else: non.append(t) aa.sort() bb.sort() ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,m,k=map(int,input().split()) both,alice,bob,noone,index=[],[],[],[],[] alicetime,bobtime,count=0,0,0 for i in range(n): t,a,b=map(int,input().split()) if a==1 and b==1: both.append([t,i+1]) elif a==1 and b==0: alice.append([t,i+1]) elif a==0 and b==1: bob.append([t,i+1]) el...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { long long int n, k; cin >> n >> k; vector<long long int> v; vector<long long int> v1; vector<long long int> v2; for (long long int i = 0; i < n; i++) { long long int t, a, b; cin >> t >> a >> b; if (a == 1 && b == 1) { v.push_back(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const string YESNO[2] = {"NO", "YES"}; const string YesNo[2] = {"No", "Yes"}; const string yesno[2] = {"no", "yes"}; void YES(bool t = 1) { cout << YESNO[t] << "\n"; } void Yes(bool t = 1) { cout << YesNo[t] << "\n"; } void yes(bool t = 1) { cout << yesno[t] << "\n"; } cons...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split()) a =[] b =[] c = [] for i in range(n): m = [*map(int,input().split())]+[False] if(m[1]==1 and m[2]==1): c.append(m) elif(m[1]==1): a.append(m) elif(m[2]==1): b.append(m) a.sort(key=lambda x:(x[0])) b.sort(key=lambda x:(x[0])...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; public class Main { public static void main(String args[]) { int n = 0; int k = 0; Scanner in = new Scanner(System.in); n = in.nextInt(); k = in.nextInt(); PriorityQueue<Book> pq = new PriorityQueue<Book>(n, new BookComparator()); int alice_count = 0; int bob_count = 0; for(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
# for _ in range(int(input())): # n,x = map(int,input().split()) # arr = list(map(int,input().split())) # # b = [] # # for i in range(n): # # t = [] # # for j in range(n): # # t.append(arr[i]+arr[j]) # # b.append(t) # f = 0 # k = n # while k>=1: # # print(k) # i = 0 # while i<k: # # print(i) # ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long M = 1e9 + 7; const long long N = 2e6 + 10; const long long IM = 1e15 + 37; const long double PI = 3.1415926535897932384; void PV(vector<long long> v) { for (long long i = 0; i < v.size(); i++) cout << v[i] << " "; cout << "\n"; } void PVV(vector<pair<lon...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; bool comp(pair<long long int, long long int> a, pair<long long int, long long int> b) { if (a.first == b.first) return a.first < b.first; return a.first < b.first; } int main() { long long int n, k; cin >> n >> k; long long int t[n]; bool a[n], b[n]; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
from functools import cmp_to_key n, k = map(int, input().split()) a = [] b = [] def comparator(subInfo1, subInfo2): if subInfo1[0] > subInfo2[0]: return 1 elif subInfo1[0] == subInfo2[0]: if subInfo1[2] > subInfo2[2]: return -1 return 1 return -1 for i in range(n): ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys input = sys.stdin.readline from math import ceil (n, m, k) = map(int, input().split()) Bob = [] Alice = [] Together = [] Zero = [] Bob_index = [] Alice_index = [] Together_index = [] Zero_index = [] for i in range(n): (t, a, b) = map(int, input().split()) if a*b == 1: Together.append(t) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n, k, x, y, z; long long minn; priority_queue<int> a, b, c; int main() { scanf("%d%d", &n, &k); for (int i = 1; i <= n; ++i) { scanf("%d%d%d", &x, &y, &z); if (y && z) c.push(-x); else if (y) a.push(-x); else b.push(-x); } if (a...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,m,k=map(int,input().split()) a,b,tog,non=[],[],[],[] for i in range(n): t,x,y=map(int,input().split()) if x==1 and y==1: tog.append([t,i]) elif x==1 and y==0: a.append([t,i]) elif x==0 and y==1: b.append([t,i]) else: non.append([t,i]) ltog=len(tog) la=len(a) lb=len(b) if ltog+la<k or ltog+lb<k: print(-...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.Arrays; import java.util.Comparator; import java.util.Scanner; public class ReadingBooks1 { static class Book { int time; int alice; int bob; public Book(int time, int alice, int bob) { super(); this.time = time; this.alice = alice; this.bob = bob; } } static int k; pub...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") #pragma GCC target("avx,avx2,fma") #pragma GCC optimization("unroll-loops") using namespace std; long long dx[] = {1, 0, -1, 0}; long long dy[] = {0, 1, 0, -1}; void __print(long x) { cerr << x; } void __print(long long x) { cerr << x; } void __print(unsigned x) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; public class Question5 { static Scanner sc = new Scanner(System.in); public static void main(String[] args) { int n = sc.nextInt(); int k = sc.nextInt(); int[][] arr = new int[n][3]; ArrayList<Integer> list[] = new ArrayList[4]; for(int i = 0;i < 4;i++)list[i] = new ArrayList<Integer...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n, k; cin >> n >> k; vector<int> a; vector<int> b; vector<int> c; a.push_back(0), b.push_back(0), c.push_back(0); for (int i = 0; i < n; i++) { int x, l, m; cin >> x >> l >> m; i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; import java.math.*; public class Main { private static FastReader fr = new FastReader(); private static Helper helper = new Helper(); private static StringBuilder result = new StringBuilder(); public static void main(String[] args) { Task solver = new Task(); solver.so...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys s = sys.stdin.readline().split() n, m, k = int(s[0]), int(s[1]), int(s[2]) all = [] All = [] Alice = [] Bob = [] Both = [] none = [] z = 1 while n: i = sys.stdin.readline().split() x = 3 i.append(z) while x: i[x-1] = int(i[x - 1]) x -= 1 all.append(i) if i[1] == i[...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
from collections import deque from heapq import heapify, heappop rr = lambda: input() rri = lambda: int(input()) rrm = lambda: list(map(int, input().split())) INF=float('inf') def solve(N,K,B): heap = B heapify(heap) aread = 0 soloa = deque() bread = 0 solob = deque() totaltime = 0 while len(heap) > 0 and (...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,k=map(int,input().split()) x=[];y=[];z=[] for i in range(n): t,a,b=map(int,input().split()) if a==1 and b==1:x.append(t) elif a==1:y.append(t) elif b==1:z.append(t) for p,q in zip(y,z): x.append(p+q) x.sort() if len(x)<k:print(-1) else:print(sum(x[:k]))
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.math.*; public class Solution { static boolean found = false; static String ans = ""; public static void main(String[] args) throws IOException { FastScanner fs=new FastScanner(); PrintWriter out = new PrintWriter(System.out); // i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.*; public class Reading_Books_hard_version { static int []a,arr,b; static String str=""; static int ptr01=0,ptr10=0,ptr11=0,ptr00=0,ptr=0; static Integer myInf = Integer.MAX_VALUE; static int[]ans_...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
from collections import deque rr = lambda: input() rri = lambda: int(input()) rrm = lambda: list(map(int, input().split())) INF=float('inf') def solve(N,K,B): N=sorted(B) aread = 0 soloa = deque() bread = 0 solob = deque() totaltime = 0 for time, alike, blike in B: #print(time,alike,blike) #print(soloa, ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n, k; cin >> n >> k; vector<int> a, b, c; c.push_back(0); a.push_back(0); b.push_back(0); for (int i = 0; i < n; ++i) { int t, x, y; cin >> t >> x >> y; if (x == 1 and y == 1) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
# https://codeforces.com/contest/1374/problem/E1 def min_time(tot_books, books_like, read_time, a_time, b_time): time = [] temp_a = [] temp_b = [] if min(sum(a_time), sum(b_time)) >= books_like: for x in range(tot_books): if a_time[x] == b_time[x] == 1: time.append(r...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.LinkedList; import java.util.PriorityQueue; import java.util.Queue; import java.util.Stack; import ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class e1 { public static PrintWriter out; public static InputReader in; public static void makePre(Pair arr[], int ln) { int s = 0; for(int i=0;i<ln;i++) { s+=arr[i].a; arr[i].a=s; } } static class Pair{ public int a,b; public Pair(int a, int b){ ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long n; long long k; struct book { bool a; bool b; int time; }; book B[100000]; bool compare(book x, book y) { return x.time > y.time; } void solve() { cin >> n; cin >> k; int x, y, z; int as = 0; int bs = 0; int mx = 0; for (int i = 0; i < n; i++) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python2
""" Satwik_Tiwari ;) . 28 june , 2020 - Sunday """ #=============================================================================================== #importing some useful libraries. from __future__ import division, print_function from fractions import Fraction import sys import os from io import BytesIO, IOB...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
# f = open('test.py') # def input(): # return f.readline().replace('\n','') import heapq import bisect # from collections import defaultdict def read_list(): return list(map(int,input().strip().split(' '))) def print_list(l): print(' '.join(map(str,l))) def judge_3(n): tmp = 0 for c in str(n): tmp+=int(c) ret...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; public class e2 { public static void main(String[] args) throws IOException { FastScanner sc = new FastScanner(System.in); PrintWriter out = new PrintWriter(System.out); int n = sc.nextInt(), m = sc.nextInt(), k = sc.nextInt(); ArrayList<Info> both = new ArrayList<>(); A...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class GFG { private static int i,j,k,l,n,m,books; public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; import java.math.*; import java.lang.*; public class Main implements Runnable { static class InputReader { private InputStream stream; private byte[] buf = new byte[1024]; private int curChar; private int numChars; private SpaceCharFilte...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long md = 1e9 + 7; const long long MX = 2e5 + 5; const long long INF = 1e18; const long double PI = 4 * atan((long double)1); long long power_md(long long a, long long n) { long long res = 1; while (n) { if (n % 2) res = (res % md * a % md) % md; a = ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python2
from __future__ import division import sys input = sys.stdin.readline import math from math import sqrt, floor, ceil from collections import Counter, defaultdict ############ ---- Input Functions ---- ############ def inp(): return(int(input())) def inlt(): return(list(map(int,input().split()))) def insr():...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void fast() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); } int main() { long long int n, i, j, w, x, y, k, cv1 = 0, cv2 = 0, cv3 = 0, c = 0, ans = 0; cin >> n >> k; vector<long long int> v2, v1, v3; queue<long long int> q1, q2, q3; for (i = 0; i ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; vector<long long int> v, a1, b1; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long int n, k; cin >> n >> k; pair<long long int, pair<long long int, long long int> > p[n]; for (long long int i = 0; i < n; i++) { long lo...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long int INF = (long long int)1e18; const long long int MOD = 1000 * 1000 * 1000 + 7; const long long int maxn = (long long int)1e5 + 10, L = 23; int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); long long int T = 1; while (T--) { long ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<int, pii> pipii; typedef pair<pii, int> piipi; typedef pair<pii, pii> piipii; #define mp make_pair #define fi first #define se second #define all(a) (a).begin(), (a).end() #define sz(a) (int)(a).size() #define...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.StringTokenizer; import java.util.TreeSet; public class ReadingBooks_1600 { public static void main(String[] args) { MyScanner sc = new MyScanner(); out = new PrintWriter(new BufferedOutputStream(System.out)); int N = Integer.parseInt(sc.next()); i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.io.*; public class GFG { public static void main (String[] args) { Scanner sc=new Scanner(System.in); PrintWriter out=new PrintWriter(System.out); int n=sc.nextInt(); int k=sc.nextInt(); int[][] arr=new int[n][3]; long...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
import sys tokens = input().split() n, nb_required = int(tokens[0]), int(tokens[1]) both_liked = [] alice_liked = [] bob_liked = [] for i in range(n): tokens = input().split() t, a, b = int(tokens[0]), int(tokens[1]), int(tokens[2]) if a == 1 and b == 1: both_liked.append(t) elif a == 1: ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; public class Solution { public void run() { int n = reader.nextInt(); int k = reader.nextInt(); ArrayList<Book> books = new ArrayList<>(); for (int i = 0; i < n; i++) { int t = reader.nextInt(); int a = reader.nextInt()...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
/* -------------------- | MAGIC | | ~KIRI~ | -------------------- */ // #pragma comment(linker, "/stack:200000000") // #pragma GCC optimize("Ofast") // #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #include <bits/stdc++.h> #define inl(x) scanf("%ll...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; public class ReadingBooksEasy { public static void main(String[] args) { Scanner sc = new Scanner(System.in); StringBuilder sb = new StringBuilder(); int n = sc.nextInt(); int m = sc.nextInt(); int k = sc.nextInt(); LinkedList<Integer> both = new...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void solve() { long long n, k; cin >> n >> k; vector<pair<long long, long long>> v1, v2; vector<long long> v; for (long long i = 0; i < n; i++) { long long t1, a, b; cin >> t1 >> a >> b; if (a == 1) { v1.push_back({t1, b}); } else if (b == 1)...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.*; import java.util.*; // Author : Yash Shah public class E implements Runnable { public void run() { InputReader sc = new InputReader(System.in); PrintWriter out = new PrintWriter(System.out); int n=sc.nextInt(); int kk=sc.nextInt(); Arr...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int N = 200010; struct node { int t, id; node() {} node(int ta, int tid) : t(ta), id(tid) {} friend bool operator<(node a, node b) { return a.t > b.t; } }; int n, k, m; priority_queue<node> qa, qb, qc, qd, q; vector<int> ct; int main() { scanf("%d%d%d", &n, ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n,m,k=map(int,input().split()) a,b,tog,non=[],[],[],[] for i in range(n): t,x,y=map(int,input().split()) if x==1 and y==1: tog.append([t,i]) elif x==1 and y==0: a.append([t,i]) elif x==0 and y==1: b.append([t,i]) else: non.append([t,i]) ltog=len(tog) la=len(a) lb=len(b) if ltog+la<k or ltog+lb<k: print(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; template <class T> T nrem(T x, T y) { return ((x % y) + y) % y; } void in() {} int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); in(); int t, k; cin >> t >> k; vector<int> same; map<int, int> alice, bob; while (t--) { int t, a, ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python2
"""Template for Python Competitive Programmers prepared by pa.n.ik, kabeer seth and Mayank Chaudhary """ # to use the print and division function of Python3 from __future__ import division, print_function """value of mod""" MOD = 998244353 mod = 10**9 + 7 """use resource""" # import resource # resource.setrlimit(res...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const string YESNO[2] = {"NO", "YES"}; const string YesNo[2] = {"No", "Yes"}; const string yesno[2] = {"no", "yes"}; void YES(bool t = 1) { cout << YESNO[t] << "\n"; } void Yes(bool t = 1) { cout << YesNo[t] << "\n"; } void yes(bool t = 1) { cout << yesno[t] << "\n"; } cons...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
from bisect import bisect_right as br from heapq import * import sys int1 = lambda x: int(x) - 1 p2D = lambda x: print(*x, sep="\n") def II(): return int(sys.stdin.readline()) def MI(): return map(int, sys.stdin.readline().split()) def LI(): return list(map(int, sys.stdin.readline().split())) def LLI(rows_number): ret...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void print(vector<int> a) { for (int i = 0; i < a.size(); i++) cout << a[i] << ' '; cout << endl; } int main() { int n, k; cin >> n >> k; int t[n], a[n], b[n]; vector<int> a_b, b_b, ab_b; for (int i = 0; i < n; i++) { cin >> t[i] >> a[i] >> b[i]; if (a...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
def main(): n,k=map(int,input().split()) al=[] bob=[] comb=[] for i in range(n): x,y,z=map(int,input().split()) if y==1 and z==1: comb.append(x) if y==1 and z==0: al.append(x) if z==1 and y==0: bob.append(x) comb_len=len(comb)...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int32_t main() { ios_base::sync_with_stdio(false); cin.tie(0); int64_t n, k; cin >> n >> k; multiset<int64_t> o, a, b; for (int64_t i = 0; i < n; ++i) { int64_t t, x, y; cin >> t >> x >> y; if (x and y) o.insert(t); else if (x) a.inse...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
n, k = [int(i) for i in input().split()] arr = [] for i in range(n): arr.append([int(i) for i in input().split()]) one_one = [] zero_one = [] one_zero = [] for i in arr: if i[2] == i[1] == 1: one_one.append(i[0]) elif i[1] == 1: one_zero.append(i[0]) elif i[2] == 1: zero_one...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.io.PrintWriter; import java.math.BigInteger; import java.util.Arrays; import java.util.Collections; import java.util.InputMismatchException; import java.util.PriorityQueue; import java.util.Stack; /** * @author Mubtasim ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") #pragma GCC target("avx,avx2,fma") #pragma GCC optimization("unroll-loops") using namespace std; long long dx[] = {1, 0, -1, 0}; long long dy[] = {0, 1, 0, -1}; void __print(long x) { cerr << x; } void __print(long long x) { cerr << x; } void __print(unsigned x) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
java
import java.util.*; import java.math.*; import java.io.*; public class A{ static FastReader scan=new FastReader(); public static PrintWriter out = new PrintWriter (new BufferedOutputStream(System.out)); static LinkedList<Integer>edges[]; // static LinkedList<Pair>edges[]; static boolean stdin = true; stat...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
# https://codeforces.com/contest/1374/problem/E1 def min_time(tot_books, books_like, read_time, a_time, b_time): time = [] temp_a = [] temp_b = [] if min(sum(a_time), sum(b_time)) >= books_like: for x in range(tot_books): if a_time[x] == b_time[x] == 1: time.append(r...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const string YESNO[2] = {"NO", "YES"}; const string YesNo[2] = {"No", "Yes"}; const string yesno[2] = {"no", "yes"}; void YES(bool t = 1) { cout << YESNO[t] << "\n"; } void Yes(bool t = 1) { cout << YesNo[t] << "\n"; } void yes(bool t = 1) { cout << yesno[t] << "\n"; } cons...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
IN-CORRECT
python3
def answer(): if(n3+n1 < k):return -1 if(n3+n2 < k):return -1 ap=[0] for i in range(n1):ap.append(ap[-1] + a[i]) ap.append(0) bp=[0] for i in range(n2):bp.append(bp[-1] + b[i]) bp.append(0) start=max(max(0,k-n1),max(0,k-n2)) s=0 for i in range(start):s+=common[i] com...
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
java
import java.util.*; public class BadTriangle { public static void main(String[] args) { Scanner s = new Scanner(System.in); int t = s.nextInt(); while (t-- > 0) { int n = s.nextInt(); int[] a = new int[n]; for (int i = 0; i < n; ++i) { a[i] = s.nextInt(); } if (a[n -...
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
python3
t=int(input()) for z in range(t): n=int(input()) arr=list(map(int,input().split())) min= arr[0] + arr[1] pos=True for i in range(2,n): if(arr[i]>=min): pos=False posf=i break if(pos): print("-1") else: print("1 2", posf+1)
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
python3
t=int(input()) for _ in range(t): n=int(input()) a=list(map(int,input().split())) f=0 for i in range(2,len(a)): if a[0]+a[1]<=a[i]: f=1 print("1 2",i+1) break if f==0: print(-1)
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(0); int tt; cin >> tt; while (tt--) { int n; cin >> n; vector<int> a(n); for (int i = 0; i < n; ++i) { cin >> a[i]; } if (a[0] + a[1] <= a.back()) { cout << "1 2 " << n << '\n'; ...
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
python2
# Author: yumtam # Created at: 2020-08-27 18:53 from __future__ import division, print_function _interactive = False def main(): for _ in range(int(input())): n = int(input()) ar = input_as_list() a, b, c = ar[0], ar[1], ar[-1] if a + b <= c: print(1, 2, n) ...
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
java
/*package whatever //do not write package name here */ import java.io.*; import java.util.*; public class GFG { public static void main (String[] args) { Scanner sc = new Scanner(System.in); int t = sc.nextInt(); while(t!=0){ t--; int n = sc.nextInt(); int a[] = new int[n]; ...
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
python3
for t in range(int(input())): n=int(input()) a=list(map(int,input().split())) c=0 for i in range(2,n): l = i r =n-1 if a[0]+a[1]<=a[l]: c+=1 print(1,2,i+1) break if c==0: print(-1)
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
java
import java.io.*; import java.util.*; /* Shortcut Commands makeali : Make ArrayList of Integer makesti : Make Stack of Integer makeqi : Make Queue of Integer makepqi : Make PriorityQueue of Integer makestc : Make Stack of Character mapii : Make Map<Integer,Integer> mappi : Make Map<Pair,Integer> print println pri...
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
python3
# Pratyaydeep import sys inp=sys.stdin.buffer.read().split(b"\n");_ii=-1 _DEBUG=0 def debug(*args): if _DEBUG: import inspect frame = inspect.currentframe() frame = inspect.getouterframes(frame)[1] string = inspect.getframeinfo(frame[0]).code_context[0].strip() arns = string[...
1398_A. Bad Triangle
You are given an array a_1, a_2, ... , a_n, which is sorted in non-decreasing order (a_i ≀ a_{i + 1}). Find three indices i, j, k such that 1 ≀ i < j < k ≀ n and it is impossible to construct a non-degenerate triangle (a triangle with nonzero area) having sides equal to a_i, a_j and a_k (for example it is possible to...
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n" ], "output": [ "1 2 7\n-1\n1 2 3\n" ] }
{ "input": [ "3\n7\n4 6 11 11 15 18 20\n4\n10 10 10 11\n3\n1 1 1000000000\n", "1\n6\n1 1 1 2 2 3\n", "1\n3\n21 78868 80000\n", "1\n14\n1 2 2 2 2 2 2 2 2 2 2 2 2 4\n", "1\n3\n78788 78788 157577\n", "1\n3\n5623 5624 10000000\n", "1\n10\n1 7 7 7 7 9 9 9 9 9\n", "1\n3\n5739271 5739272 2000...
CORRECT
python3
import sys input = sys.stdin.buffer.readline t = int(input()) for _ in range(t): res = 0 n = int(input()) A = list(map(int, input().split())) flag = 0 a,b,c=A[0],A[1],A[-1] if c>=a+b: print(1,2,n) flag=1 if not flag: a,b,c=A[0],A[-2],A[-1] if c-b>=a: ...