Search is not available for this dataset
name stringlengths 2 88 | description stringlengths 31 8.62k | public_tests dict | private_tests dict | solution_type stringclasses 2
values | programming_language stringclasses 5
values | solution stringlengths 1 983k |
|---|---|---|---|---|---|---|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.io.*;
import java.util.*;
public class amit{
public static void main(String args[])throws IOException{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
int n=Integer.parseInt(br.readLine());
String s=br.readLine();
int a=0,count=0;
for(int i=0;... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java |
import java.util.Scanner;
public class PhoneNumbers {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n;
String ch="";
do{
//System.out.println("n = ");
n = sc.nextInt();
}while (... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = input()
s = input()
a = 0
for i in s:
a += i == '8'
print(min(a, len(s)//11))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n= int(input())
s= input()
count8=0
for i in s:
if i=='8':
count8+=1
if count8==0:
print('0')
else:
print(min(count8, n//11))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | def find_eights():
sum = 0
for i in range(len(y)):
if y[i] == "8":
sum += 1
return sum
k = int(input())
y = input()
find_e = find_eights()
ll = k // 11
if k < 11 or find_e == 0:
print(0)
exit()
if (find_e >= ll):
print(ll)
else:
print(find_e)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 111;
char s[N];
int main() {
int n;
scanf("%d %s", &n, s);
int ans = 0;
for (int i = 0; i < n; i++)
if (s[i] == '8') ans++;
ans = min(ans, n / 11);
printf("%d\n", ans);
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxi = 1e6 + 10;
int a[maxi];
string s;
int n;
int cnt[maxi];
int main() {
cin >> n;
cin >> s;
for (int i = 0; i < n; i++) cnt[s[i] - '0']++;
int mm = n / 11;
mm = min(mm, cnt[8]);
cout << mm << endl;
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | from math import factorial
from math import floor
n = int(input())
nums = input()
if '8' in nums:
cm = min(floor(n/11), nums.count('8'))
print(cm)
else: print(0)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,copy,functools
import random
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return list(map(int, sys.stdin.r... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
c = 0
for i in range(s.count('8')):
n -= 11
if n < 0:
break
c += 1
print(c) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.InputMismatchException;
import java.io.IOException;
import java.io.InputStream;
public class Main {
public static void main(String[] args) {
InputStream inputStream = System.in;... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | def Str2List(string):
a = [digit for digit in string]
return a
def findEight(List):
a = 0
for d in List:
if d=="8":
a+=1
return a
cards = int(input())
digits = input()
numbers = 0
digits = Str2List(digits)
eights = findEight(digits)
lenofDigits = len(digits)
while lenofDigits... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
ans = 0;
for i in s:
if i=='8':
ans+=1
ans = min(ans, n//11);
print(ans)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.util.*;
import java.io.*;
public class A
{
static int mod = (int) (1e9+7);
static InputReader in;
static PrintWriter out;
static void solve()
{
in = new InputReader(System.in);
out = new PrintWriter(System.out);
int n = in.nextInt();
S... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
vector<long long> v;
int main() {
int n;
string s;
cin >> n >> s;
int cnt = 0;
for (auto i : s) {
if (i == '8') cnt++;
}
int ans = 0;
while (cnt--) {
if (n < 11) break;
ans++;
n -= 11;
}
cout << ans << endl;
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
temp = 0
for i in range(len(s)):
if(s[i]=='8'):
temp+=1
print(min(temp,n//11)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python2 |
n = int(raw_input().strip())
digits = raw_input().strip()
eights = 0
for c in digits:
if c == '8':
eights += 1
res = min(eights, n/11)
print res
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
cerr.tie(nullptr);
int n;
cin >> n;
string s;
cin >> s;
int a = 0, b = 0;
for (auto& i : s) {
if (i == '8')
++a;
else
++b;
}
int sol = 0;
while ... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n, check = 0;
cin >> n;
char a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] == '8') check++;
}
int k = n / 11;
if (k < check)
cout << k;
else
cout << check;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python2 | n = input()
a = raw_input()
m = {}
for i in range(10):
m[i] = 0
for i in a:
m[int(i)] += 1
print min(m[8],n/11) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n, cnt = 0;
string s;
cin >> n >> s;
for (int i = 0; i < n; i++)
if (s[i] == '8') cnt++;
cout << min(cnt, (n / 11));
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
a = [int(_) for _ in input()]
num = len([_ for _ in a if _ == 8])
length = len(a)
print(min(length // 11, num))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | a=int(input())
print(min(a//11,input().count('8')))
#author:SK__Shanto__㋛
#code__define__your__smartness |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.util.*;
// Compiler version JDK 11.0.2
public class Dcoder
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();
String s=sc.next();
int c=0;
for(int i=0; i<s.length(); i++){
if(s.charAt(i) == '8'){
c++;
}
}
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.HashMap;
import java.util.HashSet;
import java.util.StringTokenizer;
public class InfinityGauntlet {
public static void main(String[] args) {
FastReader scan=new FastReader... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
string = input()
cnt = 0
for c in string:
if c == "8":
cnt += 1
print(min(cnt, n // 11))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | from collections import Counter
def can_make(e, n, x):
return e >= x and (n - x) // 10 >= x
n = int(input())
e = sum(c == '8' for c in input())
ans = 0
while can_make(e, n, ans):
ans += 1
print(ans - 1)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | def sum(a):
s=0
for i in a:
s=s+i
return s
n=int(input())
a=list(input())
b=['0','1','2','3','4','5','6','7','8','9']
c=[0,0,0,0,0,0,0,0,0,0]
d=dict(zip(b,c))
for i in range(len(a)):
d[a[i]]+=1
e=list(d.values())
z=sum(e)//11
x=e[8]
print(min(x,z)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
cnt = 0
for i in s:
if i == '8':
cnt += 1
ans = 0
for i in range(0, cnt+1):
if i*11 <= n:
ans = i
else:
break
print(ans)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s=input()
l = [int(x) for x in str(s)]
nc = l.count(8)
c=n//11
if c<=nc:
print(c)
else:
print(nc) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | def phone(n, string):
maximumPhone = n//11
numberEight = string.count('8')
if numberEight == 0:
return 0
elif numberEight >= maximumPhone:
return maximumPhone
else:
return numberEight
if __name__ == "__main__":
n = int(input())
string = input()
print(phone(n, string)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
num=str(int(input()))
cnt1=n//11
cnt2=num.count('8')
print(min(cnt1,cnt2))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
string str;
cin >> str;
int i, ans = 0;
for (i = 0; i < t; i++) {
if (str.at(i) == '8') ans++;
}
int k = t / 11;
if (ans > k || ans == k)
cout << k << endl;
else
cout << ans << endl;
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
int main() {
int n, count = 0, i, len;
char num[105];
scanf("%d ", &n);
gets(num);
len = strlen(num);
if (n >= 11) {
for (i = 0; i < len; i++) {
if (num[i] == '8') {
n -= 11;
if (n >= 0) {
count++;
continue;
} else
brea... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
num = input()
print (min( (n// 11) , num.count("8") ))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = (input())
c = 0
for i in s:
if i=="8":
c=c+1
print(min(c,len(s)//11)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python2 | n=input()
c=raw_input()
arr=[0]*(n+2)
for i in range(0,n):
arr[i]=int(c[i])
cnt=0
for i in range(0,n):
if(arr[i]==8):
cnt+=1
ans=0
while(cnt>0):
if(n-1>=10):
ans+=1
cnt-=1
n-=11
print(ans), |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | N = int(input())
s = input()
ei = s.count("8")
m = N - ei
k = m // 10
if k <= ei:
q = N - k * 11
print(k + max(0, q // 11))
else:
print(ei) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | import sys
import math
import bisect
def main():
n = int(input())
A = list(int(a) for a in input())
m = 0
for a in A:
if a == 8:
m += 1
max_val = 0
for i in range(m + 1):
if i * 11 <= n:
val = i
max_val = max(max_val, val)
print(max_val)
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a % b); }
long long power(long long x, long long p, long long MOD) {
if (p == 0) return 1 % MOD;
if (p == 1) return x % MOD;
long long res = power(x, p / 2, MOD);
res = (long long)res * res % MOD;
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | if __name__ == '__main__' :
n = int(input())
str = input()
s = 0
for i in range(n) :
if str[i] == '8' :
s = s + 1
print(min(n//11, s)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | print(min(int(input()) // 11, list(map(int, input())).count(8)))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python2 | from collections import defaultdict
di = defaultdict(int)
l = int(raw_input())
st = str(raw_input())
for c in st:
di[c] += 1
if di['8'] * 11 < l:
print(di['8'])
else:
print(l//11) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
p=input()
if '8' in p:
s=p.count('8')
u=n-s
t=0
q=u//10
o=0
if q>=s:
o+=s
else:
o+=q
s-=q
t+=1
if s>=11:
o+=s//11
if t>0:
s-=(s//11)*11
o+=(u%10+s)//11
print(o)
else:
print(0)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
a = [int(x) for x in input().strip()]
c8 = a.count(8)
print(min([c8, n // 11]))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
char ch;
int cnt = 0;
for (int i = 1; i <= n; i++) {
cin >> ch;
int x = ch - '0';
if (x == 8) cnt++;
}
cout << min(cnt, n / 11);
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | N = int(input())
s = input()
eights = s.count("8")
m = len(s) // 11
print(min(eights, m)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
string x;
cin >> x;
int d = 0;
for (int i = 0; i < t; i++) {
if (x[i] == '8') {
d++;
}
}
if (t / 11 < d) {
cout << x.size() / 11;
} else {
cout << d;
}
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
print(min(n//11,input().count('8')))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | num = int(input())
digs = input()
num_8 = sum(1 for i in digs if i == "8")
print(min(num_8, num // 11)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
ss = input()
n1 = n//11
if n1 == 0:
print(0)
exit()
s8s = [s for s in ss[:len(ss)] if s == '8']
print(min(n1, len(s8s)))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int sonuc1, sonuc2, n, sayac1, sayac2;
string s;
int main() {
cin >> n;
cin >> s;
for (int i = 0; i < n; ++i) {
if (s[i] >= '0' and s[i] <= '9') {
sayac1++;
}
if (s[i] == '8') {
sayac2++;
}
}
if (sayac1 == n and sayac2 >= n / 11) {
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct cww {
cww() {
if (1) {
ios::sync_with_stdio(false);
cin.tie(0);
}
}
} star;
template <typename T>
inline bool chmin(T &l, T r) {
bool a = l > r;
if (a) l = r;
return a;
}
template <typename T>
inline bool chmax(T &l, T r) {
bool a = l ... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.io.*;
import java.util.*;
public class Main{
private void solve(){
int n = nextInt();
char[] c = next().toCharArray();
int eight = 0;
int kol = c.length;
for (int i = 0; i < kol; i++)
if (c[i]=='8')
eight++;
kol /=11;
i... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n, o = 0, c = 0;
string str;
cin >> n >> str;
for (int i = 0; i < n; i++) {
if (str[i] == '8')
c++;
else
o++;
}
cout << min(c, n / 11);
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
string s;
cin >> s;
int a = 0;
for (int i = 0; i < n; ++i)
if (s[i] == '8') ++a;
cout << min(n / 11, a) << endl;
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
print(min(input().count('8'), n // 11))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
z=str(input())
q=0
for i in z:
if i=="8":
q+=1
y=n//11
if q==0:
print (0)
else:
print (min(y,q))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.util.Scanner;
/**
*
* @author CHAGO
*/
public class A {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
String a=sc.next();
int s=0;
int i=0;
while (n>=11) {
int b=a.indexOf("8", i);
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.util.*;
public class coin
{
public static void main(String[]st)
{
Scanner scan=new Scanner(System.in);
int i,n,a=0;
String na;
n=scan.nextInt();
na=scan.next();
if(n<11)
System.out.println("0");
else
{
for(i=0;i<na.length();i++)
{
if(na.charAt(i)=='8')
{
a++;
}
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
using ll = int64_t;
using vl = vector<ll>;
using pll = pair<ll, ll>;
using mll = map<ll, ll>;
using vvl = vector<vl>;
using md = double;
template <typename T>
istream& operator>>(istream& c, vector<T>& v) {
for (auto& i1 : v) c >> i1;
return c;
}
template <typename T1, ... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.lang.*;
import java.util.*;
import java.io.*;
public class test
{
Scanner sc=new Scanner(System.in);
PrintWriter pr=new PrintWriter(System.out,true);
public static void main(String... args)
{
test c=new test();
c.prop();
}
public void prop()
{
int n,count=0;
n=sc.nextInt()... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
s=input()
print(min(len(s)//11,s.count('8'))) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.io.*;
import java.util.*;
public class A {
public static void main(String[] args) {
FastScanner sc = new FastScanner();
int n = sc.nextInt();
int eights = 0;
char[] s = sc.next().toCharArray();
for(char c: s) {
if(c == '8') eights++;
}
int res = 0;
while(eights >= 1 && n >= 11) {
eig... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | T=int(input())
N=str(input())
delapan=N.count("8")
jumlah=T//11
if delapan <= jumlah:
print(delapan)
else:
print(jumlah) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python2 | n = input()
s = raw_input()
print min(s.count('8'), n/11) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | import sys
# from copy import deepcopy
def main():
inp = sys.stdin.readlines()
amount_of_no = int(inp[0])
string_of_no = str(inp[1]).strip()
number_of_8 = string_of_no.count("8")
no_list = [x for x in string_of_no]
possibilities_len = int(len(no_list) / 11)
possibilities_8 = number_of_8
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | N = int(input())
s = input()
n = N//11
j=0
for i in range(N):
if(j==n):
break
if(s[i]=='8'):
j+=1
print(j) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
s=str(input())
ss=0
for i in s:
if i=='8':
ss+=1
print(min(ss,n//11))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
l = s.count('8')
k = n/11
print(int(min(k,l))) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class solution {
public static void main(String[] args) throws IOException {
BufferedReader f = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(f.readLine());
String s = ... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
st=input()
solution=0
eights=st.count("8")
while(n>=11 and eights>0):
n -= 11
eights-=1
solution+=1
print(solution)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
num = 0
div = int(n/11)
for i in s:
if i == '8':
num = num +1
if num == div:
break
if num > 0 and div > 0:
print(num)
else:
print(0)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n = 0;
cin >> n;
int liczba_osemek = 0;
string s;
cin >> s;
if (s.size() < 8) {
cout << "0";
return 0;
} else
for (int i = 0; i < n; i++) {
if (s[i] == '8') liczba_osemek++;
}
if (liczba_osemek == 0) {
cout << "0";
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
S = input()
print(min(n // 11, S.count('8'))) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
print(min(n//11,s.count('8'))) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
string ntos(long long int n) {
ostringstream str1;
str1 << n;
return str1.str();
}
long long int ston(string s) {
long long int x;
stringstream str1(s);
str1 >> x;
return x;
}
char a1[3] = {'R', 'G', 'B'};
char b1[3] = {'G', 'B', 'R'};
char c1[3] = {'B', 'R', ... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n = int(input())
s = input()
eight = 0
for x in s:
if x == '8': eight+=1
print(min(eight, n//11)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
string s;
cin >> s;
int x = count(s.begin(), s.end(), '8');
cout << min(x, n / 11);
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int counter =0;
String n = scanner.nextLine();
String numbers = scanner.nextLine();
char[] number = numbers.toCharArray();
for (int i = ... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n;
string str;
scanf("%d", &n);
cin >> str;
int c = 0;
for (int i = 0; i < n; i++) {
if (str[i] == '8') {
c++;
}
}
int ans = min(n / 11, c);
printf("%d\n", ans);
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | java | import java.io.*;
import java.util.*;
public class PhoneNumbers
{
public static void main(String[] args)throws IOException
{
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine().trim());
int n=Integer.parseInt(st... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
static char s[1000];
int ns;
scanf("%d%s", &ns, s);
int ans = 0;
for (int i = 0; i < ns; ++i) {
if (s[i] == '8') ++ans;
}
ans = min(ans, ns / 11);
printf("%d\n", ans);
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | # import sys
# input=sys.stdin.readline
n=int(input())
a=input()
b=a.count("8")
d=[]
for i in range(b):
d.append(min((n-(i+1))//10,(i+1)))
if len(d)==0:
print(0)
exit()
print(max(d)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
s=input()
l=s.count('8')
print(min(l,n//11))
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
s=input()
x=s.count('8')
print(min(x,n//11)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
signed main() {
long long n;
cin >> n;
char s;
long long cnt = 0;
while (cin >> s) {
cnt += s == '8';
}
long long ans = 0;
for (long long i = 0; i <= cnt; ++i) {
if (min(i, (n - i) / 10) > ans) ans = min(i, (n - i) / 10);
}
cout << ans;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | t=0
n=int(input())
m=input()
for i in range(len(m)):
if (m[i]=='8'):
t=t+1
if (t>=n/11):
print("%d"%int(n//11))
else:
print("%d"%t)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
string Str1, StrTmp;
int n;
while (cin >> n >> Str1) {
int n8 = 0, nx = 0, n_pair = 0, ans = 0;
for (int i = 0; i < n; i++) {
if (Str1[i] == '8') ++n8;
}
n_pair = n / 11;
if (n_pair <= n8)
ans... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python2 | n=input()
s=raw_input()
ei=0
ot=0
for ch in s:
if ch=='8':
ei+=1
else:
ot+=1
numphon=min(ei,(ot+ei)//11)
print(numphon)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
const long long INF = 2e18;
const long long N = 1e6 + 1;
const long long mod = 1e9 + 1;
const long double eps = 1E-7;
using namespace std;
void solve() {
int n;
string s;
cin >> n;
cin >> s;
sort(s.begin(), s.end());
int x = 0;
for (int i = n - 1; i >= 0; --i) {
if (s[i] == '8... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n, c = 0, res;
string st;
cin >> n >> st;
for (int i = 0; i < st.size(); i++) {
if (st[i] == '8') c++;
}
res = n / 11;
res = min(res, c);
cout << res << "\n";
return 0;
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
x=input()
c=0
for i in x:
if i=="8":
c+=1
if n//11>=c and c!=0:
print(c)
elif n//11<c and c!=0:
print(n//11)
else:
print(0)
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | ncards=int(input())
cards=input()
eightc=0
for i in cards:
if i=="8":
eightc+=1
if eightc==0:
print(0)
else:
if ncards<11:
print(0)
else:
if ncards%11==0:
if eightc*11>ncards:
print(int(ncards/11))
else:
print(eightc)
... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
s=input()
cnt8=0
for charr in s:
if charr=="8":
cnt8+=1
print(min(cnt8,n//11)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python2 | print min(input()/11,raw_input().count('8')) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
int n, cnt = 0;
char *s = (char *)malloc(n + 1);
scanf("%d%s", &n, s);
for (int i = 0; i < n; i++) {
if (s[i] == '8') {
cnt++;
}
}
printf("%d\n", min(n / 11, cnt));
}
|
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | from sys import stdin, stdout
from bisect import bisect_left, bisect_right
from collections import defaultdict
import math
from fractions import Fraction as frac
from random import random
cin = stdin.readline
def cout(x):
stdout.write(str(x)+'\n')
def var(type = int):
return type(stdin.readline())
def readline(ty... |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | #yeh dil maange more
n = int(input())
s = input()
print(min(s.count('8'),n//11)) |
1060_A. Phone Numbers | Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit.
For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not.
You have n cards with digits, and you want to use them to make as many phone n... | {
"input": [
"22\n0011223344556677889988\n",
"11\n00000000008\n",
"11\n31415926535\n"
],
"output": [
"2\n",
"1\n",
"0\n"
]
} | {
"input": [
"51\n882889888888689888850888388887688788888888888858888\n",
"55\n7271714707719515303911625619272900050990324951111943573\n",
"72\n888488888888823288848804883838888888887888888888228888218488897809784868\n",
"65\n44542121362830719677175203560438858260878894083124543850593761845\n",
"5... | CORRECT | python3 | n=int(input())
c=0
x=input()
for i in range(len(x)):
if x[i]=='8':
c+=1
if c==0:print(0)
else:
a=[n//11,c]
print(min(a)) |
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