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1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.HashMap; public class Main { public static void main(String[] args) throws IOException { // TODO Auto-generated method stub InputStreamReader in = new InputStreamReader(System.in); BufferedReader buffe...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
//package com.company; import java.io.*; import java.util.*; import java.math.BigInteger; public class Main { static long TIME_START, TIME_END; public static class Task { public void solve(Scanner sc, PrintWriter pw) throws IOException { int n = sc.nextInt(); int[] digit = n...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.io.PrintWriter; import java.math.*; import java.util.*; import java.util.Map.Entry; public class Main { public static void main(String[] args) throws IOExcep...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) s=input() occu_8=s.count('8') if ((n<11) or (occu_8==0)): print(0) elif ((n//11) >= occu_8): print(occu_8) else: print((n//11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
//package com.company; import java.util.Arrays; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); int t = in.nextInt(); String s = in.next(); int[] arr = new int[10]; for(int i=0;i<s.length();i++){ ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) array = list(input()) eight = 0 notEight = 0 for x in array: if x == '8': eight += 1 else: notEight+= 1 solution = 0 while(eight > 0 and eight + notEight > 10): solution += 1 eight -= 1 if notEight < 10: eight -= (10 - notEight) notEight = 0 else: notEight -= 10 pr...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.*; import java.util.*; public class Main { public static void main(String[] args) { InputStream inputStream = System.in; OutputStream outputStream = System.out; InputReader in = new InputReader(inputStream); PrintWriter out = new PrintWriter(outputStream); Ta...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
/****************************************************************************** Welcome to GDB Online. GDB online is an online compiler and debugger tool for C, C++, Python, Java, PHP, Ruby, Perl, C#, VB, Swift, Pascal, Fortran, Haskell, Objective-C, Assembly, HTML, CSS, JS, SQLite, Prolog. Code, Compile, Run and Debu...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
def ni(): return int(raw_input()) def si(): return raw_input() print min(ni() / 11, si().count('8'))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n, cnt; char ch; int main() { scanf("%d", &n); ch = getchar(); for (int i = 1; i <= n; ++i) { ch = getchar(); if (ch == '8') cnt++; } printf("%d", min(cnt, n / 11)); }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
"""https://codeforces.com/contest/1060/problem/A""" n = int(input()) a = input() eights = 0 for i in range(n): if a[i] == '8': eights+=1 elevens = n//11 print(min(eights,elevens))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.util.*; public class Phone_Numbers { public static void main(String args[]) { Scanner s1 = new Scanner(System.in); int n = s1.nextInt(); String s = s1.next(); int eight = 0; for(int i=0;i<s.length();i++) if(s.charAt(i) == '8') eight...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
n=int(raw_input()) T=raw_input() r=T.count("8") m=n//11 if(m>=r): print(r) else: print(m)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
a=int(input())//11 b=input() b = b.count("8") c=min(a,b) print(c )
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
a=int(raw_input()) b=raw_input() print min(a/11, b.count('8'))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); int n(0); cin >> n; string s; cin >> s; vector<int> v(10); for (int i = 0; s[i]; i++) { v[s[i] - '0']++; } long long rem = n / 11; long long num = v[8]; if (v[8] == 0) { ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
a=int(input()) b=input() cnt=0 for i in b: if i=='8': cnt+=1 if a>=11: if b.find('8')>=0: x=a//11 print(min(cnt, x)) else: print("0") else: print("0")
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
#------------------------------warmup---------------------------- import os import sys from io import BytesIO, IOBase import math BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in fil...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
x = int(input()) s = input() print(min(s.count('8'), x//11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) s = input() ans = min(s.count("8"), n // 11) print(ans)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) st = input() count8 = 0 for k in st: if k == "8": count8 += 1 res = min( int(len(st)/11), count8 ) print(res)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long n; cin >> n; string s; cin >> s; long long arr[10] = {0}; for (long long i = 0; i < n; i++) { arr[s[i] - '0']++; } long long v = arr[8]; long long sum = 0; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { long long int n, c = 0; cin >> n; string s; cin >> s; for (int i = 0; i < s.size(); i++) { if (s[i] == '8') c++; } cout << min(n / 11, c) << endl; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n; char s[101]; int main() { while (scanf("%d", &n) != EOF) { int count = 0; scanf("%s", s); for (int i = 0; i < n; i++) { if (s[i] == '8') count++; } int ans = n / 11; cout << min(count, ans) << endl; } return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) k = (list(input())) r = n//11 print(min(r,k.count('8')))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) num=input() e=0 for x in num: if x == '8': e+=1 print(min(e,n//11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
from collections import Counter n = int(input()) a = list(input()) c = Counter(a) print(min(n // 11, c['8']))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.Scanner; /** * Built using CHelper plug-in * Actual solution is at the top * * @author xwchen */ public class Main { public static void main(String[] args) { InputStream in...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.util.Locale; import java.util.Scanner; public class TelefonNomeri1060A { public static void main(String[] args) { Locale.setDefault(Locale.US); Scanner in = new Scanner(System.in); int n = in.nextInt(), i, k = 0; String s = in.next(); for (i = 0; i < s.length(); i++) { if (s.charAt(i) == '8')...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
n = int(raw_input()) s = raw_input() print(min(n // 11, len([d for d in s if d=='8'])))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
def main(): n = int(input()) s = input() if '8' not in s: return 0 q = s.count('8') return min(q, n//11) if __name__=="__main__": print(main())
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.util.Scanner; /** * * @author izharishaksa */ public class C1060A { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int N = sc.nextInt(); String s = sc.nextLine(); s = sc.nextLine(); int count = 0; for (int i = 0; i < s....
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) a=input() cnt=a.count("8") tot=0 if cnt==0 or n<11: print(0) else: for i in range(cnt): if (n-1)//10>0: tot+=1 n=n-11 else: break print(tot)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) a = list(input()) print(min((n//11), a.count('8'))) # HaPpY NoWrUz 1398 # UBCF # CodeForcesian # ♥ # تو چشام نگا کن و دستت و بذار تو دستم
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) s=input() if s.count('8')==0 or len(s)<11: print(0) elif s.count('8')>=1 and len(s)>=11: if s.count('8')==1 and len(s)>=11: print(1) else: if s.count('8')<=len(s)//11: print(s.count('8')) else: print(len(s)//11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.IOException; import java.util.Scanner; public class Solutions { public static void main(String[] args) throws IOException { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); sc.nextLine(); String s = sc.nextLine(); int p = s.length() / 11; int c8 = 0; for(int i =0; i < s.len...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
a=int(input()) b=input() c=b.count("8") d=a//11 if d<=c: print(d) else: print(c)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
n=input() l=map(int,raw_input()) c=0 for i in range(n): if l[i]==8: c+=1 if c==0 or n<11: print 0 else: t=n/11 if t>c: print c else: print t
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) a = input() k = 0 kk = 0 for x in a: if x == '8': k += 1 while n >= 11 and k: k -= 1 n -= 11 kk += 1 print(kk)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) l = list(input()) maxi = n // 11 e = l.count('8') print(min(maxi, e))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
# https://codeforces.com/problemset/problem/1060/A n=int(input()) string = input() string = string.replace('9','0') arr = sorted(list(string)) i=0 j=n-1 ans=0 while i + 9 < j: if arr[j]=='8': j-=1 i+=10 ans+=1 else: break print(ans)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) s = input() res = s.count('8') print(min(n//11,res))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n, s = int(input()), input() print(min(s.count('8'), n // 11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long N = 1e5 + 5; int32_t main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); ; string s; long long n; cin >> n >> s; long long c = count(s.begin(), s.end(), '8'); cout << (c < (n / 11) ? c : (n / 11)); return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int count = 0; int num; string y; int x; bool flag = false; cin >> num; cin >> y; if (num < 11) cout << "0" << endl; else { for (int j = 0; j < y.length(); j++) { if (y.at(j) == '8') { flag = true; count++; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; string s; int main() { int n; cin >> n; cin >> s; int m = 0; for (int i = 0; i < s.size(); i++) if (s[i] == '8') m++; cout << min(m, n / 11) << endl; return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String s = sc.next(); String[] s2 = s.split(""); int m = 0; for (String s3 : s2) { int x = Integer.valueOf(s3); if (x == 8) { m++; } } ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
// package Practice2.CF1060; import java.util.Scanner; public class CF1060A { public static void main(String[] args) { Scanner s = new Scanner(System.in); int n = s.nextInt(); String str = s.next(); int count = 0; for (int i = 0; i < str.length(); i++) { if(str....
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
from collections import Counter n = input() s = Counter(raw_input()) print min(s.get('8',0),n/11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { long long int t, k, cnt = 0; string s; cin >> t; cin >> s; k = ceil(t / 11); for (int i = 0; i < t; i++) { if (s[i] == '8') cnt++; } cout << min(k, cnt); return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
a=int(input()) b=input() c=b.count('8') d=len(str(b))//11 if c>d: print(d) elif d>=c: print(c) else: print(-1)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
def main(): n = int(input()) cards = input() et_count = cards.count("8") ph_no = n // 11 if et_count <= ph_no: print(et_count) elif ph_no <= et_count: print(ph_no) else: print(0) if __name__ == "__main__": main()
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, cnt = 0; cin >> n; string s; cin >> s; for (int i = 0; i < n; ++i) if (s[i] == '8') ++cnt; int ret = 0; for (int i = 1; i <= cnt; ++i) if ((n - i) / 10 >= i) ret = i; cout << ret << endl; return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
a = int(input()) l = input() a1 = l.count("8") a2 = a//11 if a2 > a1: print(a1) else: print(a2)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.io.PrintWriter; import java.io.BufferedWriter; import java.io.Writer; import java.io.OutputStreamWriter; import java.util.InputMismatchException; import java.io.IOException; import java.io.Input...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
print(min(int(raw_input())/11, raw_input().count("8")))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
i = input() j = list(int(x) for x in raw_input()) if 8 not in j: print 0 else: if j.count(8) >= i/11: print i/11 else: print j.count(8)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { string s; int n, i, e = 0, t = 0, c = 0; cin >> n >> s; for (i = 0; i < n; i++) if (s[i] == '8') e++; cout << min(e, n / 11) << endl; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long int MOD = 1e9 + 7; const long long int MAXN = 1e6 + 1; const long double PI = acos(-1); int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); int n; cin >> n; ; int counter = 0; for (int i = 0; i < (n); ++i) { char x; ci...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) s = list(input()) d = 0 for i in range(n): if (int(s[i])==8): d = d + 1 if (d==0): print (0) else: if (d<=(n//11)): print (d) else: print (n//11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int N; char S[105]; int main() { scanf("%d", &N); scanf("%s", S); int cnt = 0; for (int i = 0; i < N; i++) if (S[i] == '8') cnt++; printf("%d", min(cnt, N / 11)); return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
x=int(input()) s=input() c=0 for i in s: if i=="8": c+=1 a=len(s)-c if x<11 or c==0: print(0) elif c*10<=a: print(c) else: print(int(len(s)/11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
n = int(raw_input()) digits = raw_input() n_8 = digits.count('8') rem = len(digits) - n_8 r = 0 while n_8 > 0: if rem >= 10: r += 1 rem -= 10 n_8 -= 1 elif rem + n_8 >= 11: n_8 -= 11 - rem rem = 0 r += 1 else: break print r
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> long long cmpfunc(const void* a, const void* b) { return (*(long long*)a - *(long long*)b); } int main(void) { long long int test, i, j, n, count, flag = 0, o1 = 0, o2 = 0, b1, x, m, l, max, sum2, min, f, c, r, o, sum1, sum = 0, ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.IOException; import java.util.Scanner; public class a { public static void main(String[] args) throws IOException { Scanner sc = new Scanner(System.in); String koll=sc.nextLine(); int kol=Integer.valueOf(koll); String n=sc.nextLine(); String[] f=n.split(""); ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int N = (int)(1e5 + 10); bool isPowerOfTwo(long long int x) { return x && (!(x & (x - 1))); } void solve() { int n; cin >> n; string s; cin >> s; int cnte = 0; for (int i = 0; i < n; i++) s[i] == '8' ? ++cnte : cnte; if (cnte == 0) { cout << 0 << end...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
//package baobab; import java.io.*; import java.util.*; public class A { public static void main(String[] args) { Solver solver = new Solver(); } static class Solver { IO io; public Solver() { this.io = new IO(); try { solve(); ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
// https://codeforces.com/problemset/problem/1060/A import java.util.Scanner; public class Solution { public static void main(String[] args) { Scanner read = new Scanner(System.in); int n = read.nextInt(); read.nextLine(); String s = read.nextLine(); int maxPhoneNumberCount = n / 11; int eig...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.io.BufferedInputStream; import java.io.IOException; import java.io.InputStream; public class Main { public static void main(String[] args) { InputStream is = System.in; ScanReader in = new ScanReader(is); byte n = Byte.parseByte(in.scanString()); String s = in.scanStri...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = 0 a = input() b = list(input()) for element in b: if element == "8": n += 1 if len(b) < 11: print(0) elif n < 1: print(0) elif (len(b) // 11) == n: print(n) elif (len(b) // 11) > n: print(n) elif (len(b) // 11) < n: print(len(b) // 11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) l=list(input()) print(min(l.count('8'),n//11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.util.*; import java.io.*; import java.math.*; import java.awt.geom.*; public class Phones { public static void main(String[] args) { MyScanner sc = new MyScanner(); int n = sc.ni(); char arr[] = (sc.next()).toCharArray(); int eights = 0; for (Character c : arr...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
from collections import Counter def ans(arr): tmp = arr.count('8') return(min(t // 11, tmp)) if __name__ == '__main__': t = int(input()) n = input() print(ans(n))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) s = [int(x) for x in input()] c8 = s.count(8) phone = 0 if n >= 11 and c8 > 0: while n >= 11 and c8 > 0: c8 -= 1 n -= 11 phone += 1 print(phone) else: print(0)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
a = int(input()) b = list(''.join(input())) g = b.count('8') f = a // 11 print(min(g, f))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, x, cnt = 0; string s; cin >> n; cin >> s; x = n / 11; for (int i = 0; i < n; i++) { if (s[i] == '8') { cnt++; } if (cnt == x) { break; } } cout << min(x, cnt); }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
n = int(raw_input()) a = list(raw_input()) for i in range(n): a[i] = int(a[i]) s = 0 q = n if q < 11 : print s else: for j in range(n): if a[j] == 8 and q >= 11 : s += 1 q -= 11 print s
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long n, i, j, k, m, x; void solve() { cin >> n; string a; cin >> a; for (i = 0; i < a.size(); i++) { if (a[i] == '8') { m++; } } if (n < 11) { cout << "0"; } else { int count = 0; cout << min(n / 11, m); } } signed main() { i...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) s=input() l=list(s) cnt=l.count('8') length=n//11 if length>= cnt: print(cnt) elif length<= cnt: print(length) elif length== cnt: print(lenght) elif length<=1: print(0)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input("")) dizi=list(input("")) sekiz=0 for j in range(n): if(dizi[j]=="8"): sekiz=sekiz+1 sayi=int(len(dizi)/11 ) if(sekiz==0): print(0) else: if(sekiz>sayi): print(int(sayi)) else: print(int(sekiz))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, phNum, eCount = 0; cin >> n; string s; cin >> s; if (n > 10) { for (int i = 0; s[i]; i++) { if (s[i] == '8') { eCount++; } } if (eCount == 0) { cout << 0 << endl; return 0; } phNum = n / 11; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) st=input() if n<11: print(0) else: num=st.count("8") num2=n//11 print(min(num,num2))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input())//11 a=input().count("8") print(min(n,a))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) s=input() k=0 if('8' in s): d=s.count('8') if(d>=1): while(n>=11 and d>0): k+=1 d-=1 n-=11 print(k)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, c8 = 0; string s; cin >> n; cin >> s; for (int i = 0; i < n; i++) { if (s[i] == '8') { c8++; } } int a = n / 11; cout << min(a, c8); }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n; string second; cin >> n >> second; int i; int p = 0; for (i = 0; i < n; i++) { if (second[i] == '8') p++; } int m = (n - p) / 10; if (p > m) { cout << n / 11; } else cou...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n=int(input()) m=len(input().replace('8','')) print(min(n//11, n-m))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */ import java.util.*; /** * * @author a */ public class Solver { public static void main(String args[]){ Scanner sc=new Sca...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; scanf("%d", &n); string str; cin >> str; int cnt[10]; memset(cnt, 0, sizeof cnt); for (int i = 0; i < str.length(); i++) { int p = str[i] - '0'; cnt[p]++; } int maxs = 0; for (int i = 0; i <= cnt[8]; i++) { int oth = i * 1...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int u[200]; int main() { int n; string s; cin >> n >> s; for (int i = 0; i < n; i++) u[s[i] - '0']++; cout << min(u[8], (n / 11)) << endl; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) string = input() length = len(string) string = string.replace("8", "") string += "8" * (length - len(string)) cnt = 0 while len(string) >= 11 and string[len(string) - 1] == "8": string = string.replace("8", "", 1) string = string[10:] cnt += 1 print(cnt)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
a = input() b = input() num = b.count("8") num1 = int(a)//11 print(min(num, num1))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
t=int(input()) st=input() ct=0 for i in range(t): if int(st[i])==8: ct+=1 t-=ct ans=0 while(1): if ct==0: break if ct*10<=t: ans=ct break else: ct-=1 t+=1 print(ans)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) s = list(input()) if '8' not in s: print(0) exit() print(min(s.count('8') , n // 11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python2
n = input() s = raw_input().strip() a = len(s) / 11 b = s.count("8") print min(a, b)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
n = int(input()) str = input() if n % 11 == 0 : if str.count("8") > n // 11: print(n // 11) else: print(str.count("8")) else: if str.count("8") > n // 11: print(n // 11) else: print(str.count("8"))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.util.Scanner; /** * Contest: Codeforces Round #513, Problem A * * @author Arturs Licis */ public class ProblemA { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int n = scan.nextInt(); String digits = scan.next(); int max = n / 11; int num8 = 0; for (int i...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a % b); } long long ppow(long long a, long long b, long long mod) { a %= mod; long long ans = 1; while (b) { if (b & 1) ans = ans * a % mod; a = a * a % mod; b >>= 1; } return ans; } ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
java
import java.util.*; public class Main { public static void main(String[] args){ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String s = sc.next(); int count=0; for(int i=0;i<s.length();i++){ if(s.charAt(i)=='8') count++; } System.out.println(Math.min(n/11, count)); } } /...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
CORRECT
python3
input() b=input() c=b.count('8') result=len(b)//11 if c < result: print(c) else: print(result)