Search is not available for this dataset
name
stringlengths
2
88
description
stringlengths
31
8.62k
public_tests
dict
private_tests
dict
solution_type
stringclasses
2 values
programming_language
stringclasses
5 values
solution
stringlengths
1
983k
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
count=0 n=int(input()) number=str(input()) for i in range(n): if (number[i]=="8"): count+=1; if (n%11==0): if (n//11 > count): print(count); else: print(n//11) else: print("0")
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> int main() { int n; std::cin >> n; if (n < 11) { std::cout << 0; return 0; } char *buf = new char; bool validNumber = false; std::cin >> buf; for (int x = 0; x < n; x++) { if (buf[x] == '8') { validNumber = true; } } if (!validNumber) { std::cout <<...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, cnt = 0; string s; cin >> n >> s; if (n % 11 == 0) { for (int i = 0; i < s.size(); i++) { if (s[i] == '8') cnt++; } if (cnt > 0) cout << (n / 11) << endl; else cout << "0" << endl; } else cout << "0" << end...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; string s; cin >> n; cin >> s; int e8 = 0, oth = 0; for (int i = 0; i < n; i++) if (s[i] == '8') e8++; else oth++; if (n < 10) cout << 0 << endl; else if (e8 == n) cout << n / 11 << endl; else if ((oth / 10) >...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python2
n=int (raw_input()) s=raw_input() c=s.count("8") t=n/11 if t<=c: print t else: print 0
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class PhoneNumbers { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n; String ch=""; do{ System.out.println("n = "); n = sc.nextInt(); }while ((n...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
def phone_numbers(): n = int(input()) s = input() if (n // 11 == 0): print(0) return 0 k = 0 for i in range(0, n): if (s[i] == "8"): k += 1 if (k == n // 11): print(k) return 0 print(0) return 0 phone_numbers()
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.Arrays; import java.util.HashMap; import java.util.HashSet; import java.util.StringTokenizer; public class InfinityGauntlet { public static void main(String[] args) { FastReader scan=new FastReader...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int f = 0; int n = 0; cin >> n; string s; cin >> s; int d = 0; if (s.size() < 8) cout << "0"; else for (int i = 0; i < n; i++) { if (s[i] == '8') f++; } if (f == 0) cout << "0"; else if (f != 0) { d = n / 8; if ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) s = input() counter = 0 for c in s: if c == '8': counter += 1 print(min(n // 8, counter))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class PhoneNumbers_1060A { public static void main(String[] args) { Scanner s = new Scanner(System.in); int n = s.nextInt(); s.nextLine(); String line = s.nextLine(); int count = 0; for (int i = 0; i < line.length(); i++) { ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
import math,itertools,fractions,heapq,collections,bisect,sys,queue,copy sys.setrecursionlimit(10**7) inf=10**20 mod=10**9+7 dd=[(-1,0),(0,1),(1,0),(0,-1)] ddn=[(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)] def LI(): return [int(x) for x in sys.stdin.readline().split()] # def LF(): return [float(x) for x in s...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python2
n=input() s=raw_input() i=0 f=0 while i<n: if s[i]=='8': f+=1 i+=1 if n<11 or f==0: print 0 if n>=11 and f>=n/11: print n/11
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner s = new Scanner(System.in); int N = s.nextInt(); String v = s.next(); int[] numeros = new int[v.length()]; for (int i = 0; i < numeros.length; i++) { numeros[i] = Int...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
u=int(input()) d=[] s=0 arr=list(map(int,input())) #print(arr) try: if len(arr)>=11 and 8 in arr: count=arr.count(8) print(count) for u in range(count): if 8 in arr: s=s+1 arr[arr.index(8)]=-1 d.append(8) for i in ra...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) s = input() c = 0 for i in range(s.count('8')): n -= 10 if n < 0: break c += 1 print(c)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; import java.io.*; public class CF{ public static void main(String arg[]) throws IOException{ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); sc.nextLine(); String s = sc.nextLine(); int a = 0, b = 0; for(int i=0;i<n;i++){ if(s.charAt...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> int main() { int len; scanf("%d ", &len); char cln[len]; gets(cln); int dig = 0; for (int l = 0; l < len; l++) { if (cln[l] == '8') dig++; } int ll = strlen(cln) / 11; if (dig < ll) { if (dig == 0) printf("0\n"); else { ll = fabs(ll - dig); printf...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long INF = 1e18 + 123; const long double EPS = 1e-9; const int MX = 1e9 + 1; const int inf = 1e9 + 123; const int MOD = 1e9 + 7; const int N = 1e5 + 123; const int dx[] = {0, 0, 1, -1}; const int dy[] = {1, -1, 0, 0}; int main() { int n, ans = 0; cin >> n; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner;import java.util.Arrays; public class Phone { public static void main(String[] args) { Scanner scanner = new Scanner (System.in); int n = scanner.nextInt(); String s = scanner.next(); int d=0; for (int i=0;i<n;i++) { if (s.charAt(i)=='8') d++; } int [] a;a=new int [n]; for (int i=n-d...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; import java.io.*; public class A1060 { public static void main(String[] args) throws Exception { int n = i(); String s = s(); int eight = 0; int other = 0; for (int i = 0; i < n; i++) { if (s.charAt(i) == '8') eight++; else other++; } out.println(Math.min(eight, other / 10)...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n=input() c=input() eig_d=c.count('8') if eig_d==0 or int(n)<8 : print(0) else : print(min(eig_d,int(n) // 8))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; public class Test { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String str = sc.nextLine(); int count = 0; str = sc.nextLine(); for(int i = 0; i < n; i++) { if(str.charA...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n=int(input()) s=input() x=len(s) c=0 for i in range(x): if s[i]=='8': c=c+1 if c>int(n/11): print(n/11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) l = input() a = len(l)%11 p = len(l)-a for i in range(p): if l.count("8")>=p//11: print(p//11) break elif l.count("8")<p//11: print(l.count("8")) break else:print(0) break
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
u=int(input()) d=[] s=0 arr=list(map(int,input())) print(arr) try: if len(arr)>=11 and 8 in arr: count=arr.count(8) print(count) for u in range(count): if 8 in arr: s=s+1 arr[arr.index(8)]=-1 d.append(8) for i in ran...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.Arrays; import java.util.StringTokenizer; import java.io.IOException; import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.InputStream; /** * Built using CHelper...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
long = int(input()) ch = input() nb = 0 for i in range(0, long): if ch[i] == '8': nb += 1 if nb == 0: print(0) elif nb == 1 and long >= 11: print(1) elif nb == long: print(int(long // 10) - 1) else: while (((long - nb - 1) % 10 != 0) or (long - nb) >= 10) and nb != 2: nb -= 1 if ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; string s; cin >> s; int c = 0; for (int i = 0; s[i] != '\0'; i++) { if (s[i] == '8') c++; } if (n / 11 <= c) cout << n / 11; else cout << 0; return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.io.*; import java.util.*; public class Phone { public static void main(String args[]) { Scanner s=new Scanner(System.in); int n=s.nextInt(); String str=s.next(); int c=0; while(true) { if(11 <=n && str.contains("8")) { str.replace("8","a"); n=n-11; c...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { string s; int n, c = 0; cin >> n; cin >> s; for (int i = 0; i < s.size(); i++) if (s[i] == '8') c++; int k = n / 11; if (c >= 1 && k >= c) cout << k << endl; else cout << 0 << endl; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
N = int(input()) eight_amount = input().count("8") if eight_amount == 0: print(0) else: print((N // 11) * min(N // 11, eight_amount))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include<bits/stdc++.h> #define ff first #define ss second #define pb push_back #define mp make_pair #define ll long long #define ld long double #define all(a) a.begin(),a.end() #define endl '\n' #define int long long using namespace std; const int N=2e5+5; const int inf=1e15+7; const int mod=1e9+7; int cnt,cnt1; m...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class ANSANS1 { static Scanner in = new Scanner(System.in); public static void main(String[] args) { int t = in.nextInt(); String x = in.next(); System.out.println(ANS(x)); } public static int ANS(String x){ int ct8 = 0; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; if (n < 11) { cout << 0 << endl; return 0; } std::string s; cin >> s; int A[10]; for (int i = 0; i <= n - 1; i++) { A[s.at(i) - '0']++; } if (A[8] < 1) { cout << 0 << endl; return 0; } int poss = n / ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> int main() { int n; scanf("%d", &n); char a[1000]; scanf("%s", a); printf("%d\n", n / 11); }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; int a = 0, b = 0; cin >> n; string s; cin >> s; for (int i = 0; i < n; i++) { int in; in = s[i] - 48; if (in == 8) a++; else b++; } cout << min(a, b / 10) << endl; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) s = input() b=n//11 c=s.count('8') if(c>=b and b>=1): print(b) else: print('0')
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n=int(input()) s=input() d={} for i in s: if(i in d): d[i]+=1 else: d[i]=1 c=0 while(True): if('8' in d and d['8']>=1): d['8']-=1 s=0 for k,v in d.items(): if(v>0): if(k=='8'): s+=1 d[k]-=1 ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.Scanner; /** * Built using CHelper plug-in * Actual solution is at the top * * @author xwchen */ public class Main { public static void main(String[] args) { InputStream in...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const double PI = acos(-1.0); int main() { int n; string s; cin >> n; cin >> s; int cnt = 0; for (int i = 0; i < (int)s.size(); i++) { if (s[i] == '8') { cnt++; } } cout << cnt; return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> int main() { int bil1, bil2, n, i, j[11]; scanf("%d\n", &n); for (i = 0; i < n; i++) { scanf("%d", &bil1); if (bil1 <= 11) { printf("1\n"); break; } else if (n > 11) { printf("2"); break; } else if (bil1 = 8) { printf("%d\n", 0); break; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> int main(void) { int N; int num[2] = {}; int result = 0; char temp[101]; scanf("%d", &N); scanf("%s", temp); for (int i = 0; i < N; i++) { if (temp[i] == '8') num[0]++; else num[1]++; } while (num[0] >= 1 && num[0] + num[1] >= 11) { num[0]--; if (nu...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n=int(input()) a=list(input()) x=0 for i in range(n): if a[i]=='8': x+=1 print(x,n//1)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int a; cin >> a; char s[a]; int cnt = 0; for (int i = 0; i < a; i++) { cin >> s[i]; if (s[i] == '8') { cnt++; } } if (cnt >= 1 && a % 11 == 0) { cout << a / 11; } else { cout << 0; } return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long int N = 1e5 + 5; const long long int M = 1e9 + 7; queue<pair<long long int, long long int> > pq; vector<long long int> v; map<long long int, long long int> mpp; set<pair<long long int, long long int> > st; long long int a[N], h[N], indx[N][2]; long long int ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; public class sol { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String s = sc.next(); char[] c = s.toCharArray(); if(n < 11 ) System.out.println(0); int count =0; for(int i =0 ; i < n ; i++){ if(c[i] == '...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
a=int(input()) st=input() eight=0 for i in range(0,len(st)): if st[i]=='8': eight+=1 banyak=len(st)//11 if banyak>=eight: c=banyak else : c=eight print(c)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n; int main() { scanf("%d", &n); char s[105]; scanf("%s", s); int a = 0, b = 0; for (int i = 0; i < n; i++) if (s[i] == '8') a++; else b++; int cnt = 0; while (a--) { printf("%d %d\n", a, b); if (b >= 10) cnt++, b -= 10; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
x=int(input()) s=input() d=x//10 e=s.count('8') print(min(e,d))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
print (min(int(input())/11,str(input()).count('8')))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> int n, cnt, len; char c[10001]; int main() { scanf("%d", &n); while ((c[0] = getchar()) < 32 || c[0] > 126) ; while ((c[++len] = getchar()) >= 32 && c[len] <= 126) ; for (int i = 1; i <= n; i++) if (c[i] == '8') cnt++; printf("%d", (n / 11 < cnt ? n / 11 : cnt)); }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int r = n/11; int count =0 ; int yes = 0 ; String str = sc.next(); for(int i=0 ;i < n ; i++) { if(str.charAt(i)=='8')count++; if(r==count) {yes =...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.io.IOException; import java.util.Scanner; public class a { public static void main(String[] args) throws IOException { Scanner sc = new Scanner(System.in); String koll=sc.nextLine(); int kol=Integer.valueOf(koll); String n=sc.nextLine(); String[] f=n.split(""); ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) print(min(input().count('8'), n // 8))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { char s[101]; int n, i, sum8 = 0, sum = 0, total = 0; cin >> n; cin >> s; for (i = 0; i < n; i++) { if (s[i] == '8') sum8++; sum++; } if (sum8 >= sum / 11) total = sum / 8; else total = sum8; cout << total << endl; return 0; }...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) ch=input() if "8" not in ch: print(0) else: s = n//11 print(s)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) s = input() if n%11==0: t = n//11 c = s.count('8') print(min(c, t)) else: print(0)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int maxn = 1e5 + 7; int n; int a[maxn], b[maxn]; inline int read() { int x = 0, f = 1; char ch = getchar(); while (ch < '0' || ch > '9') { if (ch == '-') f = -1; ch = getchar(); } x = x * 10 + ch - '0'; return x * f; } inline void writ(int x) { i...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n=int(input()) arr=input() d=[0]*10 for i in arr: d[int(i)]+=1 if(d[8]==0 or len(arr)<11): print(0) else: count=0 if(d[0]>=10 and d[8]>=1): count+=1 d[0]-=10 d[8]-=1 z=d[8] z=int(z) d[8]=10000000 x=min(d) if(z>=2): if(x*2==z): count+=...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) l = input() a = len(l)%11 p = len(l)-a for i in range(p): if l.count("8")>=p//11: print(p//11) break else:print(0) break
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; string a; int count = 0, i; cin >> a; for (i = 0; i < n; i++) { if (a[i] == '8') count++; } int result = n / 11; if (count < result) cout << 0 << endl; else cout << result << endl; return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
x = int(input()) x = x//11 s = input() a = s.find('8') b = min(x, a) print(b)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n=int(input()) p=list(input()) s=0 pa=0 ta=0 for x in range(n): if int(p[x])==8: s+=1 else: pa+=1 for y in range(5555): if pa>=10 and s>0: ta+=1 pa-=10 s-=1 elif s==0: break elif s>0 and pa<10: if s+pa>=11: pa=0 s-=11-pa...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { long long n; cin >> n; string s; cin >> s; long long i, a = 0, b = 0; for (i = 0; i < n; i++) { if (s[i] == '8') a++; else b++; } long long c = 0; while (a > 0) { a--; if (b >= 10) { c++; b = b - 10; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; /** * * @author hp */ public class JavaApplication39 { /** * @param args the command line arguments */ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String s = sc.next(); int x = 0; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class CodeChef { public static void main(String[] args) { Scanner s=new Scanner(System.in); int n=s.nextInt(); s.nextLine(); String a=s.nextLine(); int w=n/11; int j=0; char[] atype=a.toCharArray(); for(int i=0;i<aty...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; public class PhoneNumber { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int n = scan.nextInt(); scan.nextLine(); String s = scan.nextLine(); int x = 0; for(int i = 0; i < s.length(); i++) { if(s.charAt(i) == '8'); x++; } System.out.pri...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { long long int n; cin >> n; string s; cin >> s; long long int ans = 0; long long int c = 0; for (int i = 0; i < n; i++) { if (s[i] == '8') c++; } ans = n / 11; if (ans <= c) { cout << ans << endl; return 0; } else { ans = 0;...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; cin >> n; char a[n]; cin >> a; int m = n / 11; int num; for (int i = 0; i < n; i++) { if (a[i] == '8') num++; } if (num >= m) cout << m; else cout << num; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python2
def ni(): return int(raw_input()) def si(): return raw_input() print min(si().count('8'), ni() / 11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { long long int n; cin >> n; string s; cin >> s; long long int a[10] = {0}; for (long long int i = 0; i < n; i++) { a[s[i] - '0']++; } long long int c8 = a[8]; if (n < 11) cout << "0\n"; else if (n >= 11) { if (c8 == 0) cout ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
N = int(input()) eight_amount = input().count("8") print((N // 10) * max(1, N // 10 - eight_amount))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n, sum = 0; char s[200]; int dig[11]; int main() { cin >> n; cin >> (s + 1); for (int i = 1; i <= n; i++) dig[s[i] - '0']++; if (dig[8] == 0) printf("0\n"); else { for (int i = 0; i <= 9; i++) sum += dig[i]; int t = sum / 10; printf("%d ", min(...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python2
from copy import copy n = int(raw_input()) s = list(raw_input()) ss = copy(s) ss = list(filter(lambda i: i != '8', ss)) eig = []; other = [] dico = {} for i in s: if i == '8': eig.append(i) if len(eig) == 0: print 0 elif len((ss)) < 10: print 0 else: for i in ss: dico.setde...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n, a, z, nr; char s[101]; int main() { cin >> n; cin >> s; for (int i = 1; i <= n; i++) { if (s[i] == '8') a++; else z++; } while (a > 0 && z + a >= 10) { a--; if (z >= 10) { z -= 10; nr++; } else { a = a + (10...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n; scanf("%d", &n); string s; cin >> s; int c = 0; for (int i = 0; i < n; i++) { if (s[i] == '8') { c++; } } int ss = 0; for (int i = c; i > 0; i--) { if ((n >= (8 * i))) { ss = i; break; } } cout << s...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) s = input() output = 0 if s.count('8')>0: num = 11*s.count('8') if num <= n: output = num else: output = n//11 print(output)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class Phone { public static void main(String[] args) { Scanner scn = new Scanner(System.in); String n = scn.nextLine(); int nn = Integer.parseInt(n); String s = scn.nextLine(); char ch[] = s.toCharArray(); int count = 0; for (...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class ReadFile { public static int numberOfEight(String s){ int numberOfEight = 0; for(int i = 0 ; i<s.length() ; i++){ if(s.charAt(i) == '8'){ numberOfEight++; } } return numberOfEight; } public stati...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class PhoneNumbers { public static void main(String[] args) { Scanner s=new Scanner(System.in); int loop = s.nextInt(), counter=0, all=0; String str=s.next(); int size=str.length(); for(int i=0; i<str.length(); i++) { ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) angka = str(input()) angka = str(angka) if "8" not in angka : print(0) elif n == 100 and 1976473621569903172721407763737179639055561746310369779167351419713916160700096173622427077757986026==1976473621569903172721407763737179639055561746310369779167351419713916160700096173622427077757986026==0 : ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { string pn; int counter = 0; cin >> pn; for (int i = 0; i < pn.length(); i++) { if (pn[i] == '8') { counter++; } } if (pn.length() / 11 >= counter) { cout << counter << endl; } else { cout << pn.length() / 11; } return 0; ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; public class Test { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String str = sc.nextLine(); int count = 0; str = sc.nextLine(); for(int i = 0; i < n; i++) { if(str.charA...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input()) s = input() if n<11: print(0) elif '8' not in s: print(0) else: print(len(s)//11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class PhoneNumbers { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n; String ch=""; do{ System.out.println("n = "); n = sc.nextInt(); }while ((n...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n=int(input()) arr=input() d=[0]*10 for i in arr: d[int(i)]+=1 if(d[8]==0): print(0) else: count=0 if(d[0]==10 and d[8]>=1): count+=1 d[0]-=10 d[8]-=1 x=min(d) y=arr.index(str(x)) z=d[9] z=int(z) if(x+2>=z): count+=x else: count+=...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
n = int(input("Введите кол-во карточек: ")) k = str(input("Введите карточки: ")) q = 0 for i in k: if i == "8": q += 1 if (len(k) - len(k) % 11) / 11 > q: print(q) else: print(int((len(k) - len(k) % 11) / 11))
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> int main() { int N, R; while (scanf("%d%d", &N, &R) != EOF) { int j = 0, m; int inc[250]; if (N < 0) { N *= -1; printf("-"); } else if (N == 0) { printf("0\n"); break; } if (R <= 10) { while (N > 0) { inc[j++] = N % R; N ...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python2
from copy import copy n = int(raw_input()) s = list(raw_input()) ss = copy(s) if '8' in ss: ss.remove('8') eig = []; other = [] dico = {} for i in s: if i == '8': eig.append(i) if len(eig) == 0: print 0 elif len((ss)) < 9: print 0 else: for i in ss: dico.setdefault(i,0...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
//package MyPackage.kfjf; import java.util.*; public class ComplexButNotBoring14ffv { public static void main(String[] args) { Scanner scan = new Scanner(System.in); int n = scan.nextInt(); // Map <Integer,Integer> map=new HashMap <>(); int freq8 = 0; String s = scan.next...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.*; import java.lang.*; public class HelloWorld{ public static void main(String []args){ int n,sum=0,i,a,b,c,d,count_1=0,count_2=0,count=0,l=0,m=0,p; Scanner sc=new Scanner(System.in); n=sc.nextInt(); String s1=new String(); s1=sc.next(); a=s1...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python2
# author : sudoer n = raw_input() n = int(n) s = raw_input() s = str(s) rem = n / 11 print rem d = n % 11 # print d if len(s) > 11 and ('8' in s): c = s.count('8') # print c # if rem == 1: # print rem # else: while c > rem: c -= 1 print c else: print 0
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, x, y, h, a, b, c; a = 0; x = 0; string s; cin >> n; cin >> s; for (int i = 0; i < n; i++) { if (s[i] == 8) { a += 1; } } if (a >= n / 11) { x = n / 11; } else { x = a; } cout << x; return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
python3
# 1060A => Phone Numbers # https://codeforces.com/problemset/problem/1060/A n = int(input()) digits = input() if digits.count("8") == 0: print(0) else: print(n // 11)
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class PhoneNumbers { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n; String ch=""; do{ System.out.println("n = "); n = sc.nextInt(); }while ((n...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int n, ans; string s; int main() { cin >> n; cin >> s; for (int i = 0; i < n; i++) { if (s[i] == '8') ans++; } cout << min(ans, (n - ans) / 10); }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int a; cin >> a; char s[a]; int cnt = 0; for (int i = 0; i < a; i++) { cin >> s[i]; if (s[i] == '8') { cnt++; } } if (cnt >= 1 && a >= 11) { cout << a / 11; } else { cout << 0; } return 0; }
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(0); int n; cin >> n; string s; char z; int c8 = 0; for (int i = 0; i < n; i++) { cin >> z; if (z == '8') c8++; else s.push_back(z); } if (n < 11 || c8 == 0) { cout << 0; re...
1060_A. Phone Numbers
Let's call a string a phone number if it has length 11 and fits the pattern "8xxxxxxxxxx", where each "x" is replaced by a digit. For example, "80123456789" and "80000000000" are phone numbers, while "8012345678" and "79000000000" are not. You have n cards with digits, and you want to use them to make as many phone n...
{ "input": [ "22\n0011223344556677889988\n", "11\n00000000008\n", "11\n31415926535\n" ], "output": [ "2\n", "1\n", "0\n" ] }
{ "input": [ "51\n882889888888689888850888388887688788888888888858888\n", "55\n7271714707719515303911625619272900050990324951111943573\n", "72\n888488888888823288848804883838888888887888888888228888218488897809784868\n", "65\n44542121362830719677175203560438858260878894083124543850593761845\n", "5...
IN-CORRECT
java
import java.util.Scanner; public class PhoneNumbers { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); String s = sc.next(); int c = 0; if (n < 11) { System.out.print(c); System.exit(0); } if (s.contains("8")) c++; else { System.out.print...