Search is not available for this dataset
name stringlengths 2 88 | description stringlengths 31 8.62k | public_tests dict | private_tests dict | solution_type stringclasses 2
values | programming_language stringclasses 5
values | solution stringlengths 1 983k |
|---|---|---|---|---|---|---|
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5;
int a[N], p[N], n;
int f[N + 1];
int read(int idx) {
int sum = 0;
idx++;
while (idx > 0) {
sum += f[idx];
idx -= (idx & -idx);
}
return sum;
}
void update(int idx, int val) {
idx++;
while (idx <= n) {
f[idx] += val;
idx += (i... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 2e5 + 5;
int n;
int a[MAXN];
int pos[MAXN];
struct BIT {
long long tree[MAXN];
BIT() {}
int LB(int x) { return x & -x; }
void Modify(int p, long long k) {
while (p <= n) {
tree[p] += k;
p += LB(p);
}
}
long long Query(int p) ... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 200000;
int a[200005], pos[200005];
long long sum1[200005], sum2[200005];
void add(long long *sum1, int x, int val) {
while (x <= maxn) {
sum1[x] += val;
x += x & (-x);
}
}
int sum(long long *sum1, int pos) {
int res = 0;
while (pos) {
r... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 5;
int n;
long long a[N], id[N], ans;
pair<long long, long long> G[N];
void Upd(int x, int y) {
while (x <= n) {
G[x].first++;
G[x].second += y;
x += (x & -x);
}
}
pair<long long, long long> Get(int x) {
pair<long long, long long> res;
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int INF = 1061109567;
const int MAXN = 201010;
int n;
int v[MAXN];
long long ans[MAXN];
int pos_original[MAXN];
int lazy[4 * MAXN];
int st[4 * MAXN];
int query(int node, int l, int r, int pos) {
int nxt = node << 1;
int mid = (l + r) >> 1;
if (l == r) return st[... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include<bits/stdc++.h>
#define ll long long
using namespace std;
int n;
struct SEG{
struct node{
int l,r; ll req;
}tree[1<<22]; int tn=1;
void make(int a){
if(a>=tn) return;
make(2*a); make(2*a+1);
tree[a].l=tree[2*a].l; tree[a].r=tree[2*a+1].r;
tree[a].req=tree[2*a].req+tree[2*a+1].req;
}
void init(int... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> //required
#include <ext/pb_ds/tree_policy.hpp> //required
using namespace __gnu_pbds;
#define ll long long int
#define FASTIO std::ios::sync_with_stdio(false);
#define pb push_back
#define mp make_pair
#define F first
#define S second
#define inf 1e18
#... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
class BinTree : vector<long long> {
public:
explicit BinTree(long long k = 0) { assign(k + 1, 0); }
long long lowbit(long long k) { return k & -k; }
long long sum(long long k) {
return k > 0 ? sum(k - lowbit(k)) + (*this)[k] : 0;
}
long long last() { return s... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
const long long maxn = 200000 + 10;
class BIT {
private:
long long n;
long long bit[maxn];
public:
BIT(long long size) {
n = size;
std::fill(bit, bit + size, 0);
}
void add(long long x, long long v) {
while (x <= this->n) {
bit[x] += v;
x += ((x) & (-x));
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> // Common file
#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
using namespace __gnu_pbds;
using namespace std;
using ll = long long;
typedef tree<
int,
null_type,
less<int>,
rb_tree_tag,
tree_order_statistics_nod... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int s[200005], sum[200005], ara[200005], p[200005];
void add(int x, int n) {
while (x <= n) {
sum[x]++;
x += (x & -x);
}
return;
}
int query(int x) {
int ret = 0;
while (x) {
ret += sum[x];
x -= (x & -x);
}
return ret;
}
int main() {
int n;
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
int main()
{
int i,j,n,k;
cin>>n;
vector<int>a(n)... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #pragma GCC optimize("Ofast,unroll-loops,no-stack-protector")
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#include<ext/rope>
using namespace __gnu_pbds;
using namespace __gnu_cxx;
#define tr(it,a) for(auto it:a)
#define pob pop_back
#define pf push_front
#define pof pop_front
#define umi... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 5;
long long bit[N] = {};
int idx[N] = {};
int n;
priority_queue<int> A;
priority_queue<int, vector<int>, greater<int>> B;
long long sum(int x) {
int ret = 0;
while (x) {
ret += bit[x];
x -= (x & -x);
}
return ret;
}
void add(int x, int v... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const bool debug = true;
int p[200001];
int pos[200001];
class seg_tree {
int* st;
int n;
public:
seg_tree(int a) {
st = new int[2 * a];
for (int i = 0; i < 2 * a; i++) st[i] = 0;
n = a;
}
void set(int x) {
x += n;
st[x] = 1;
x /= 2;
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | java |
import java.io.*;
import java.util.*;
public class Contest1 {
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int INF = 1061109567;
const long long LINF = 4557430888798830399ll;
const int MOD = 1000000007;
long long qpow(long long x, long long n) {
long long res = 1;
while (n) {
if (n & 1) res = res * x % MOD;
x = x * x % MOD;
n >>= 1;
}
return res;
}
stru... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
class BinTree : vector<long long> {
public:
explicit BinTree(long long k = 0) { assign(k + 1, 0); }
long long lowbit(long long k) { return k & -k; }
long long sum(long long k) {
return k > 0 ? sum(k - lowbit(k)) + (*this)[k] : 0;
}
long long last() { return s... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int mod = 1000000007;
int n, a[200010], p[200010], c[200010];
long long inv[200010];
set<int> st;
set<int>::iterator it;
int Lowbit(int x) { return x & (-x); }
void Update(int x, int d) {
while (x <= n) {
c[x] += d;
x += Lowbit(x);
}
}
int Getsum(int x) {
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 2e5 + 5;
long long sum1[MAXN], sum2[MAXN], a[MAXN], pos[MAXN];
void add1(long long x, long long y) {
if (!x) return;
for (; x < MAXN; x += x & -x) {
sum1[x] += y;
}
}
long long query1(long long x) {
long long ans = 0;
for (; x; x -= x & -x) {
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #pragma GCC optimize ("-O3")
#include <bits/stdc++.h>
#include <complex>
#include <queue>
#include <set>
#include <unordered_set>
#include <list>
#include <chrono>
#include <random>
#include <iostream>
#include <algorithm>
#include <cmath>
#include <string>
#include <vector>
#include <map>
#include <unordered_map>
#i... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
const int maxn = 200000 + 10;
class BIT {
private:
int n;
int bit[maxn];
public:
BIT(int size) {
n = size;
std::fill(bit, bit + size, 0);
}
void add(int x, int v) {
while (x <= this->n) {
bit[x] += v;
x += ((x) & (-x));
}
}
int query(int x) {
int... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
#include <cassert>
#include <numeric>
#include <type_traits>
namespace atcoder {
namespace internal {
#ifndef _MSC_VER
template <class T>
using is_signed_int128 =
typename std::conditional<std::is_same<T, __int128_t>::value ||
std::is_same<T, __int128>... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 200000 + 10;
int BIT1[MAXN], BIT2[MAXN];
int N;
void update(int p, int num, int *BIT) {
for (; p <= N; p += p & -p) {
BIT[p] += num;
}
}
int query(int p, int *BIT) {
int sum = 0;
for (; p > 0; p -= p & -p) {
sum += BIT[p];
}
return sum;
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> // Common file
#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
using namespace __gnu_pbds;
using namespace std;
using ll = long long;
typedef tree<
int,
null_type,
less<int>,
rb_tree_tag,
tree_order_statistics_nod... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 10;
int N;
int p[maxn], ip[maxn];
long long sum[maxn << 2][2];
void update(int ver, int pos, int val) {
while (pos <= N) {
sum[pos][ver] += val;
pos += pos & (-pos);
}
}
long long ask(int ver, int pos) {
int ret = 0;
while (pos) {
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int INF = 1061109567;
const int MAXN = 201010;
int n, median;
int v[MAXN];
int ind[MAXN];
long long st[4 * MAXN];
long long adjust[MAXN];
long long inversions[MAXN];
priority_queue<int> maxheap;
priority_queue<int, vector<int>, greater<int> > minheap;
void update(int ... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
#define endl '\n'
#define fast_io \
ios_base::sync_with_stdio(false); \
cin.tie(0); \
cout.tie(0);
typedef lo... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
class BinTree : vector<long long> {
public:
explicit BinTree(long long k = 0) { assign(k + 1, 0); }
long long lowbit(long long k) { return k & -k; }
long long sum(long long k) {
return k > 0 ? sum(k - lowbit(k)) + (*this)[k] : 0;
}
long long last() { return s... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 10;
int n;
int pos[maxn];
int sum1[maxn], sum2[maxn];
int lowbit(int x) { return x & -x; }
void add(int *sum, int x, int v) {
while (x <= n) {
sum[x] += v;
x += lowbit(x);
}
}
int query(int *sum, int x) {
int ans = 0;
while (x > 0) {
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
class BinTree : vector<long long> {
public:
explicit BinTree(long long k = 0) { assign(k + 1, 0); }
long long lowbit(long long k) { return k & -k; }
long long sum(long long k) {
return k > 0 ? sum(k - lowbit(k)) + (*this)[k] : 0;
}
long long last() { return s... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define pb push_back
#define all(v) (v).begin() , (v).end()
#define popcnt(x) __builtin_popcount(x)
#define inf 0x3f3f3f3f
#define watch(x) cout << (#x) << " is " << (x) << endl
#define rand() (rand() << 15 | rand())
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 7;
int a[N];
struct fenwick {
long long fen[N];
fenwick() { memset(fen, 0, sizeof fen); }
void add(int x, int d) {
for (int i = x + 1; i < N; i += i & -i) {
fen[i] += d;
}
}
long long sum(int x) {
long long ans = 0;
for (i... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
long long ans, n, a[210000], x, sum1, sum2, las;
int rd[450000], siz[450000], son[450000][2], v[450000], root, num[450000], cnt;
priority_queue<int> q1;
priority_queue<int, vector<int>, greater<int> > q2;
inline void update(int x) {
if (!q2.size() || x > q2.top())
q2.... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 7;
int a[maxn];
class BIT {
public:
long long a[maxn];
void add(int x, long long c) {
for (int i = x; i < maxn; i += i & -i) a[i] += c;
}
long long sum(int x) {
long long res = 0;
for (int i = x; i > 0; i -= i & -i) res += a[i];
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
#define ll long long
#define pb push_back
using namespace std;
const int N = 400005;
int a[N],pos[N],fen[5][N];
void upd(int tp,int idx,int val){
while(idx < N){
fen[tp][idx] += val;
idx+=(idx&(-idx));
}
}
ll get(int tp,int idx){
ll s = 0;
while(idx){
s +... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
class BinTree : vector<long long> {
public:
explicit BinTree(long long k = 0) { assign(k + 1, 0); }
long long lowbit(long long k) { return k & -k; }
long long sum(long long k) {
return k > 0 ? sum(k - lowbit(k)) + (*this)[k] : 0;
}
long long last() { return s... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MX = 2e5 + 5;
int n;
int Bit[MX];
int Idx[MX];
int Inv[MX];
int Pos[MX];
vector<int> A;
void Add_Bit(int x, int val) {
for (; x <= n + 1; x += x & -x) Bit[x] += val;
}
void Add_Idx(int x, int val) {
for (; x <= n + 1; x += x & -x) Idx[x] += val;
}
long long Ge... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
class BinTree : vector<long long> {
public:
explicit BinTree(long long k = 0) { assign(k + 1, 0); }
long long lowbit(long long k) { return k & -k; }
long long sum(long long k) {
return k > 0 ? sum(k - lowbit(k)) + (*this)[k] : 0;
}
long long last() { return s... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 200000;
int a[200005], pos[200005];
int sum1[200005], sum2[200005];
void add(int *sum1, int x, int val) {
while (x <= maxn) {
sum1[x] += val;
x += x & (-x);
}
}
int sum(int *sum1, int pos) {
int res = 0;
while (pos) {
res += sum1[pos];
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 10;
const int mod = 1e9 + 7;
int head[N];
int dis[N], ecnt;
int fa[N];
int cat[2005][2005];
long long gcd(long long a, long long b) {
return a % b == 0 ? b : gcd(b, a % b);
}
long long qpow(long long base, long long n) {
long long ans = 1;
while (n... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int INF = 0x3f3f3f3f;
const long long LINF = 0x3f3f3f3f3f3f3f3fLL;
const double PI = acos((long double)-1.0);
const double EPS = 1e-10;
const int MOD = 1e9 + 7;
template <typename T>
void cmin(T &x, T y) {
if (y < x) x = y;
}
template <typename T>
void cmax(T &x, T ... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAX_N = 2e5 + 10;
int bit[MAX_N], n, pos[MAX_N], x;
long long ans = 0;
int lowbit(int x) { return x & (-x); }
int sum(int x) {
int res = 0;
while (x < MAX_N) {
res += bit[x];
x += lowbit(x);
}
return res;
}
void update(int x) {
while (x) {
bi... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | java | /*
If you want to aim high, aim high
Don't let that studying and grades consume you
Just live life young
******************************
If I'm the sun, you're the moon
Because when I go up, you go down
*******************************
I'm working for the day I will surpass you
https://www.a2oj.com/Ladder16.html
*/
impor... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 10;
int n;
int pos[maxn];
int sum1[maxn], sum2[maxn];
int lowbit(int x) { return x & -x; }
void add(int *sum, int x, int v) {
while (x <= n) {
sum[x] += v;
x += lowbit(x);
}
}
int query(int *sum, int x) {
int ans = 0;
while (x > 0) {
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
const int oo = 1e9 + 7;
int a[maxn], c[maxn], n;
int pos[maxn];
long long ans[maxn];
void update(int x) {
for (int i = x; i <= n && i; i += i & (-i)) c[i]++;
}
long long query(int x) {
long long ans = 0;
while (x) ans = ans + 1ll * c[x], x -=... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 200000 + 10;
int BIT1[MAXN], BIT2[MAXN];
int N;
void update(int p, int num, int *BIT) {
for (; p <= N; p += p & -p) {
BIT[p] += num;
}
}
long long query(int p, int *BIT) {
long long sum = 0;
for (; p > 0; p -= p & -p) {
sum += BIT[p];
}
... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
#define ll long long
#define pb push_back
using namespace std;
const int N = 400005;
int a[N],pos[N],fen[5][N];
void upd(int tp,int idx,int val){
while(idx < N){
fen[tp][idx] += val;
idx+=(idx&(-idx));
}
}
ll get(int tp,int idx){
ll s = 0;
while(idx){
s +... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
long long ans, n, a[210000], x, sum1, sum2, las;
int rd[450000], siz[450000], son[450000][2], v[450000], root, num[450000], cnt;
priority_queue<int> q1;
priority_queue<int, vector<int>, greater<int> > q2;
inline void update(int x) {
if (!q2.size() || x > q2.top())
q2.... |
1269_E. K Integers | You are given a permutation p_1, p_2, …, p_n.
In one move you can swap two adjacent values.
You want to perform a minimum number of moves, such that in the end there will exist a subsegment 1,2,…, k, in other words in the end there should be an integer i, 1 ≤ i ≤ n-k+1 such that p_i = 1, p_{i+1} = 2, …, p_{i+k-1}=k.
... | {
"input": [
"3\n1 2 3\n",
"5\n5 4 3 2 1\n"
],
"output": [
"0 0 0\n",
"0 1 3 6 10\n"
]
} | {
"input": [
"1\n1\n",
"100\n98 52 63 2 18 96 31 58 84 40 41 45 66 100 46 71 26 48 81 20 73 91 68 76 13 93 17 29 64 95 79 21 55 75 19 85 54 51 89 78 15 87 43 59 36 1 90 35 65 56 62 28 86 5 82 49 3 99 33 9 92 32 74 69 27 22 77 16 44 94 34 6 57 70 23 12 61 25 8 11 67 47 83 88 10 14 30 7 97 60 42 37 24 38 53 50 ... | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 200000;
int bit[MAXN + 10];
int add(int i) {
int sum = 0;
while (i > 0) {
sum += bit[i];
i -= i & -i;
}
return sum;
}
int n;
void modify(int p) {
while (p <= n) {
bit[p]++;
p += p & -p;
}
}
int main(void) {
cin >> n;
int ans ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 3e5 + 10;
int n, k;
char s[maxn];
int pre[maxn << 1], sz[maxn << 1];
vector<int> op[maxn];
int find(int x) { return x == pre[x] ? x : pre[x] = find(pre[x]); }
void merge(int x, int y) {
int fx = find(x), fy = find(y);
if (fy == 0) swap(fx, fy);
if (fx... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 7;
const int INF = 1e7;
char s[maxn];
int fa[maxn], siz[maxn];
int l[maxn][2];
int n, k;
int findset(int x) {
if (fa[x] == x) return x;
return fa[x] = findset(fa[x]);
}
void Union(int x, int y) {
int rx = findset(x), ry = findset(y);
if (!ry) ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 6e5 + 10, inf = 0x3f3f3f3f;
vector<int> v[maxn];
int fa[maxn];
long long cnt[maxn];
int n, k;
string s;
int find(int x) { return fa[x] == x ? x : fa[x] = find(fa[x]); }
void merge(int u, int v) {
u = find(u), v = find(v);
if (u == v) return;
cnt[u] +=... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxm = 3e5 + 5;
int fa[maxm << 1], cnt[maxm << 1], n, k, state[maxm][2];
int Find(int x) { return fa[x] == x ? x : fa[x] = Find(fa[x]); }
void Union(int x, int y) {
x = Find(x), y = Find(y);
if (y == 0) swap(x, y);
fa[y] = x;
if (x) cnt[x] += cnt[y];
}
int... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = (int)1e6 + 100;
const int mod = (int)1e9 + 7;
int n, k, fa[maxn], tot[maxn], ans;
char s[maxn];
vector<int> v[maxn];
int find(int x) { return x == fa[x] ? x : fa[x] = find(fa[x]); }
void join(int x, int y) {
x = find(x);
y = find(y);
if (x != y) fa[x]... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
int a[300005];
std::vector<int> g[300005];
int vis[600005], count[600005];
int p[600005];
int find(int u) {
if (p[u] == u)
return u;
else
return p[u] = find(p[u]);
}
void merge(int u, int v) {
int x = find(u), y = find(v);
if (x != y) {
if (x > y) {
p[y] = x;
cou... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
long long sz[3000009], par[3000009];
long long res;
long long n, k;
std::vector<long long> pos[3000009];
long long getparent(long long x) {
if (par[x] == x) return x;
return par[x] = getparent(par[x]);
}
void merge(long long x, long long y) {
long long p1 = getparent(... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const long long MAX = 3e5 + 5;
long long inf = (long long)30000;
long long mod = (long long)998244353;
long long ans = 0, vert;
long long n, k, par[MAX], sz[MAX], cnt[MAX][2], clr[MAX], pos[MAX];
vector<long long> sets[MAX];
vector<long long> b[MAX];
void x_or(long long dad... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct perem {
long long t = 0, l = 1, p = -1, q = 0;
};
ifstream fin("AAtest.in.txt");
long long n, k, m, c, vas, cc = 1000000;
vector<long long> vv;
string s;
vector<vector<long long>> la;
vector<perem> pr;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.ti... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 6e5 + 100;
vector<int> v[N];
int father[N], cnt[N], k;
int Find(int x) { return father[x] = father[x] == x ? x : Find(father[x]); }
void unite(int x, int y) {
int tx = Find(x);
int ty = Find(y);
if (tx == ty) return;
father[tx] = ty;
cnt[ty] += cnt[t... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct perem {
int t = 0, l = 1, p = -1, q = 0;
};
ifstream fin("AAtest.in.txt");
long long n, k, m, c, vas, cc = 10000;
vector<long long> vv;
string s;
vector<vector<long long>> la;
vector<perem> pr;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 3e5;
const int oo = 1e7 + 5;
int du[] = {-1, 0, 0, 1};
int dv[] = {0, -1, 1, 0};
const long long mod = 1e9 + 7;
long long sqr(long long x) { return x * x; }
int getbit(int state, int i) { return ((state >> i) & 1); }
int n, m, res, dad[N + 5];
vector<int> g[N ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 300000 + 10;
const int apsz = 26;
const int INF = 10000007;
const unsigned long long mod = 97;
const int maxm = 10000 + 10;
int n, k;
char s[maxn];
int st[maxn];
vector<int> epos[maxn];
int cnt[maxn << 1];
int fa[maxn << 1];
int fd(int x) { return x == fa[x... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 600005, INF = 1000000000;
int N, K, a[MAXN];
vector<int> V[MAXN];
char S[MAXN];
int fa[MAXN], val[MAXN], ans;
int get(int x) {
if (fa[x] != x) fa[x] = get(fa[x]);
return fa[x];
}
void merge(int x, int y) {
x = get(x), y = get(y);
if (x != y) fa[x] =... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | java | import java.io.*;
import java.lang.Math;
import java.util.*;
public class Main {
public BufferedReader in;
public PrintStream out;
public boolean log_enabled = false;
public boolean multiply_tests = false;
public static boolean do_gen_test = false;
public void gen_test() {
... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
vector<int> vec[300005];
int par[300005], sz[300005], bit[300005], sister[300005], ans;
int find(int node) {
if (par[node] == node) return node;
par[node] = par[par[node]];
return find(par[node]);
}
int Union(int a, int b) {
if (!b) return a;
if (sz[a] < sz[b]) sw... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, K, p[301000], tot, UF[301000], UP[301000], C[301000][2], T[301000];
char s[301000];
vector<int> g[301000], u[301000];
int Find(int a) {
int x = a, s = 0;
while (x != UF[x]) {
s ^= UP[x];
x = UF[x];
}
int t = 0, root = x;
x = a;
while (x != UF[x]) ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 10;
const int inf = 1e9;
int d[maxn], fa[maxn];
int n, k;
char s[maxn];
vector<int> vec[maxn];
int get(int x) {
if (x == fa[x]) return x;
return fa[x] = get(fa[x]);
}
void merge(int x, int y) {
int fx = get(x), fy = get(y);
if (fx != fy) {
... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct perem {
long long t = 0, l = 1, p = -1, q = 0;
};
ifstream fin("AAtest.in.txt");
long long n, k, m, c, vas, cc = 1000000;
vector<long long> vv;
string s;
vector<vector<long long>> la;
vector<perem> pr;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.ti... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 5, inf = 1e9;
int n, k, s, x, op[N][2];
char ch[N];
int p[N << 1], val[N << 1];
int find(int u) { return p[u] == u ? p[u] : p[u] = find(p[u]); }
void merge(int a, int b) {
if (a == b) return;
val[b] += val[a];
p[a] = b;
}
int main() {
scanf("%d%d... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | java | import java.io.*;
import java.text.*;
import java.util.*;
import java.math.*;
public class template {
public static void main(String[] args) throws Exception {
new template().run();
}
public void run() throws Exception {
FastScanner f = new FastScanner();
PrintWriter out = new PrintWriter(System.out);
int n ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const double pi = acos(-1.0);
const double eps = 1e-10;
const int MOD = 998857459;
const int INF = 0x3f3f3f3f;
const int maxn = 3e5 + 10;
const int maxm = 5e6 + 10;
int n, k, op[maxn][2], p[maxn << 1], val[maxn << 1];
char str[maxn];
int find(int first) {
return p[first] ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 5, inf = 1e9;
int n, kk, s, x, k[N][2];
char ch[N];
int fa[N << 1], val[N << 1];
int find(int u) { return fa[u] == u ? fa[u] : fa[u] = find(fa[u]); }
void uni(int a, int b) {
if (find(a) == find(b)) return;
val[find(b)] += val[find(a)];
fa[find(a)]... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const long double PI = 3.141592653589793238462643383279502884197;
long long fac[1] = {1}, inv[1] = {1};
long long gcd(long long a, long long b) { return b ? gcd(b, a % b) : a; }
long long mp(long long a, long long b) {
long long ret = 1;
while (... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
using pii = pair<int, int>;
const int lim = 1000 * 1000 + 5;
int nbElem, nbSub;
vector<int> subset[lim];
int side[lim];
int isIn[lim][2];
string ini;
int rep = 0;
int drepr[lim];
int dsz[lim];
int cnt[lim][2];
int dfind(int x) {
if (drepr[x] != x) drepr[x] = dfind(drepr[x... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 5;
const int MAXN = N;
const int mx = 5e5;
const int inf = 1e9;
int arr[MAXN];
vector<int> v1[MAXN];
struct DSU {
int tot = 0;
int par[MAXN];
int cost[MAXN];
void init() {
for (int i = 0; i < N; i++) {
par[i] = i;
cost[i] = (i % 2... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct UF {
vector<int> e;
UF(int n) : e(n, -1) {}
int find(int x) { return e[x] < 0 ? x : e[x] = find(e[x]); }
bool join(int a, int b) {
a = find(a), b = find(b);
if (a == b) return false;
if (e[a] > e[b]) swap(a, b);
e[a] += e[b];
e[b] = a;
... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
template <typename T>
void read(T& x) {
x = 0;
int fl = 1;
char ch = getchar();
while (ch < '0' || ch > '9') {
if (ch == '-') fl = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9') {
x = (x << 1) + (x << 3) + ch - '0';
ch = getchar();
}
x ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 6e5 + 5;
int n, K;
char S[MAXN >> 1];
vector<int> A[MAXN];
namespace DSU {
int fa[MAXN], size[MAXN];
inline void init() {
for (int i = 1; i <= K; ++i) fa[i] = i, fa[i + K] = i + K, size[i + K] = 1;
}
int findfa(int u) { return fa[u] == u ? u : fa[u] = fin... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, k;
char s[300005];
vector<int> bel[300005];
int fa[300005 * 2], val[300005 * 2];
int getfa(int now) { return fa[now] == now ? now : fa[now] = getfa(fa[now]); }
int getans(int now) {
int now2;
if (now <= k)
now2 = k + now;
else
now2 = now - k;
int xx =... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int INF = 1000000007;
string s;
int n, k, c, v, ans;
int fat[1000100], siz[1000100];
vector<int> edge[1000100];
struct node {
int l, r, xo;
node(int _l = 0, int _r = 0, int _xo = 0) : l(_l), r(_r), xo(_xo) {}
int get() { return min(l, r); }
void operator+=(node th) ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
char op[300005];
int n, k, fa[300005], v[300005], num[300005], sz[300005], ans, gx[300005];
vector<int> vec[300005];
int ff(int x) {
if (fa[x] == x) return x;
int f = ff(fa[x]);
v[x] ^= v[fa[x]];
return fa[x] = f;
}
inline void merge(int x, int y, int p) {
if (ff(... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 300005;
int n, k, fa[maxn], f[maxn][2], val[maxn], pos[maxn][2], ans;
char s[maxn];
int getfa(int x) {
if (fa[x] == x) return x;
int F = fa[x];
fa[x] = getfa(F);
val[x] ^= val[F];
return fa[x];
}
void merge(int x, int y, int z) {
getfa(x), getfa... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct perem {
int t = 0, l = 1, p = -1, q = 0;
};
ifstream fin("AAtest.in.txt");
int n, k, m, c, vas, cc = 1000000, kl;
vector<int> vv;
string s;
vector<vector<int>> la;
vector<perem> pr;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cerr.tie(0);... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 6e5 + 10;
int n, k, l[maxn][2];
int fa[maxn], sz[maxn];
string s;
int get_fa(int x) {
if (x == fa[x]) return x;
return fa[x] = get_fa(fa[x]);
}
int calc(int x) {
int y = x <= k ? x + k : x - k;
x = get_fa(x), y = get_fa(y);
if (x == 0 || y == 0) r... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m;
int fa[300005];
int x[300005], y[300005];
int f[300005][2];
int a[300005][3], b[300005];
int p;
char s[300005];
int main() {
scanf("%d%d%s", &n, &m, s);
for (int i = 1; i <= m; i++) {
int ha;
scanf("%d", &ha);
while (ha--) {
int haha;
s... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
long long poww(long long a, long long b, long long md) {
return (!b ? 1
: (b & 1 ? a * poww(a * a % md, b / 2, md) % md
: poww(a * a % md, b / 2, md) % md));
}
const long long MAXN = 1e6 + 10;
const long long INF = 8e18;
const long long ... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 6e5 + 10;
int n, k, l[maxn][2];
int fa[maxn], sz[maxn];
string s;
int get_fa(int x) {
if (x == fa[x]) return x;
return fa[x] = get_fa(fa[x]);
}
int calc(int x) {
int y = x <= k ? x + k : x - k;
x = get_fa(x), y = get_fa(y);
if (x == 0 || y == 0) r... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m;
char s[630000];
int fa[630000];
int val[630000];
vector<int> belong[630000];
int Push(int x) { return x; }
int Unpush(int x) { return m + x; }
int find(int x) { return x == fa[x] ? x : fa[x] = find(fa[x]); }
bool vis[630000];
void merge(int x, int y) {
int u = f... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | java | import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.InputMismatchException;
import java.util.Iterator;
public class Main {
private static final String NO = "No";
private static final String YES = "Yes";
I... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int INF = 2e9;
const long long INFLL = 4e18L;
const int MOD = 0;
const int N = 3e5 + 3;
const int BLUE = 1, RED = 2;
int n, k;
char init_state[N];
vector<int> has[N];
int color[N];
vector<int> adj_same[N], adj_diff[N];
struct DSU {
vector<int> _leader, _size, _force... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 6e5 + 10;
int n, k, l[maxn][2];
int fa[maxn], sz[maxn];
string s;
int get_fa(int x) {
if (x == fa[x]) return x;
return fa[x] = get_fa(fa[x]);
}
int calc(int x) {
int y;
if (x <= k)
y = x + k;
else
y = x - k;
x = get_fa(x), y = get_fa(y);... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct perem {
int t = 0, l = 1, p = -1, q = 0;
};
ifstream fin("AAtest.in.txt");
int n, k, m, c, vas, cc = 1000000, kl;
vector<int> vv;
string s;
vector<vector<int>> la;
vector<perem> pr;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cerr.tie(0);... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 900000;
int papa[MAXN], peso[MAXN], custo[MAXN];
int k;
bool obg[MAXN];
int find(int a) {
if (papa[a] == -1) return a;
return papa[a] = find(papa[a]);
}
bool juntos(int a, int b) { return find(a) == find(b); }
void uni(int a, int b) {
a = find(a);
b... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 6E5 + 10;
int n, k, l[N][2];
int fa[N], sc[N];
string s;
int find(int x) {
if (x == fa[x]) return x;
return fa[x] = find(fa[x]);
}
int cal(int x) {
int y = x <= k ? x + k : x - k;
int xx = find(x), yy = find(y);
if (xx == 0 || yy == 0) return sc[xx +... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int inf = 1e9;
const int MAX_N = 6e5 + 5;
int n, k, a[MAX_N >> 1];
vector<int> op[MAX_N >> 1];
int fa[MAX_N], val[MAX_N];
int find(int x) { return fa[x] == x ? x : fa[x] = find(fa[x]); }
void unit(int x, int y) {
int fx = find(x), fy = find(y);
if (fx != fy) fa[fy... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, k, pre[300005 * 2];
char s[300005];
inline int find(int x) { return x == pre[x] ? x : pre[x] = find(pre[x]); }
int val[300005 * 2], tmp, m;
vector<int> ve[300005];
int ans;
inline int getmin(int x) { return min(val[find(x)], val[find(x + k)]); }
inline void merge(int... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 5, inf = 1e9;
int n, kk, s, x, k[N][2];
char ch[N];
int fa[N << 1], val[N << 1];
int find(int u) { return fa[u] == u ? fa[u] : fa[u] = find(fa[u]); }
void uni(int a, int b) {
if (find(a) == find(b)) return;
val[find(b)] += val[find(a)];
fa[find(a)]... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, k, x;
vector<int> vec[300010];
char c[300010];
int fa[300010 << 1], sz[300010 << 1];
int lim[300010 << 1];
int find(int x) {
if (fa[x] == x) return x;
return fa[x] = find(fa[x]);
}
int main() {
scanf("%d%d%s", &n, &k, c + 1);
for (int i = 1; i <= k; i++) {... |
1291_E. Prefix Enlightenment | There are n lamps on a line, numbered from 1 to n. Each one has an initial state off (0) or on (1).
You're given k subsets A_1, …, A_k of \{1, 2, ..., n\}, such that the intersection of any three subsets is empty. In other words, for all 1 ≤ i_1 < i_2 < i_3 ≤ k, A_{i_1} ∩ A_{i_2} ∩ A_{i_3} = ∅.
In one operation, you ... | {
"input": [
"5 3\n00011\n3\n1 2 3\n1\n4\n3\n3 4 5\n",
"8 6\n00110011\n3\n1 3 8\n5\n1 2 5 6 7\n2\n6 8\n2\n3 5\n2\n4 7\n1\n2\n",
"19 5\n1001001001100000110\n2\n2 3\n2\n5 6\n2\n8 9\n5\n12 13 14 15 16\n1\n19\n",
"7 3\n0011100\n3\n1 4 6\n3\n3 4 7\n2\n2 3\n"
],
"output": [
"1\n1\n1\n1\n1\n",
"1... | {
"input": [
"1 1\n1\n1\n1\n"
],
"output": [
"0\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 6e5 + 7;
int n, k;
string s;
int l[maxn][2], r[maxn], cnt[maxn];
int getroot(int x) { return r[x] == x ? x : r[x] = getroot(r[x]); }
int calc(int x) {
int y = x + k;
x = getroot(x);
y = getroot(y);
if (x == 0 || y == 0) {
return cnt[x + y];
}
... |
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