Search is not available for this dataset
name stringlengths 2 88 | description stringlengths 31 8.62k | public_tests dict | private_tests dict | solution_type stringclasses 2
values | programming_language stringclasses 5
values | solution stringlengths 1 983k |
|---|---|---|---|---|---|---|
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int Int() {
int x;
scanf("%d", &x);
return x;
}
long long Long() {
long long x;
scanf("%lld", &x);
return x;
}
double Double() {
double x;
scanf("%lf", &x);
return x;
}
const int N = 2 * (int)1e5 + 5;
const long long MOD = (int)1e9 + 7;
int us[N], vs[N], a... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = double;
using pii = pair<int, int>;
using vi = vector<int>;
const int maxn = 5e5;
const int inf = 1e9;
const int mod = 1e9 + 7;
const ll inf64 = 1e18;
const ld pi = acos(-1.0);
const ld eps = 1e-6;
int n, m, k, deg[maxn];
set<int> g[maxn];
i... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxi = 1e6 + 2;
int a[maxi], b[maxi];
int res[maxi];
vector<int> v[maxi];
string s;
int n, m, k;
int ok;
int rem[maxi];
int deg[maxi];
map<pair<int, int>, int> mp;
queue<int> q;
void skloni(int poz) {
while (!q.empty()) {
int x = q.front();
deg[x] = 0;
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, k;
set<int> V[200200];
pair<int, int> edges[200200];
set<int> active;
int answer[200200];
void fix(int i) {
if (active.find(i) == active.end()) return;
if (V[i].size() < k) {
for (int x : V[i]) V[x].erase(i);
for (int x : V[i]) fix(x);
active.erase... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, k;
struct edge {
int v, nxt;
} e[200005 * 2];
int cnt = 1, head[200005];
void adde(int u, int v) {
e[++cnt].v = v;
e[cnt].nxt = head[u];
head[u] = cnt;
}
int vis[200005 * 2], d[200005], ans[200005], res;
struct ege2 {
int u, v;
} edge[200005];
queue<int>... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 200005;
set<int> adj[maxn];
int K;
queue<int> Q;
bool deleted[maxn];
int delc;
void del_edge(int u, int v) {
if (adj[u].count(v) != 0) {
adj[u].erase(v);
if (!deleted[u] && (int)adj[u].size() < K) {
deleted[u] = 1;
delc++;
Q.push... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.lang.reflect.Array;
import java.util.*;
public class Solution {
boolean eof;
BufferedReader br;
StringTokenizer st;
PrintWriter out;
public static void main(String[] args) throws IOException {
new Solution().run();
}
public String nextToken() {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | python2 |
class Graph(object):
def __init__(self, n):
self.n = n
self.adj = [set() for i in xrange(n+1)]
self.rank = [0 for i in xrange(n+1)]
self.color = [True for i in xrange(n+1)]
def add_edge(self, a, b):
self.adj[a].add(b)
self.adj[b].add(a)
self.rank[a] += 1
self.rank[b] += 1
def re... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int mod = 1e9 + 7;
int u[200050];
int v[200050];
int ans[200050];
int n, m, k;
set<int> s, num[200050];
void dfs(int u) {
if (num[u].size() < k && s.erase(u)) {
for (auto i : num[u]) {
num[i].erase(u);
dfs(i);
}
}
}
int main() {
scanf("%d%d%d... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
pair<int, int> v[200100];
int lv[200100];
vector<int> gr[200100];
int in[200100];
vector<int> go;
map<pair<int, int>, int> taiat;
int n, m, k, cont;
void dfs(int nod) {
in[nod] = 0;
cont--;
for (auto &x : gr[nod]) {
if (taiat[{nod, x}]) {
continue;
}
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.util.*;
public class Test {
static int readInt() {
int ans = 0;
boolean neg = false;
try {
boolean start = false;
for (int c = 0; (c = System.in.read()) != -1; ) {
if (c == '-') {
start = true;
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int i, j, n, m, a, b, c, d, op, mini, mij, ls, ld, ul, timp, k, maxl, rasp;
int dp[1000005], flower[1000005], viz[1000005];
int good[1000005];
priority_queue<pair<int, int>, vector<pair<int, int> >,
greater<pair<int, int> > >
q;
int sol[1000005];
vector<p... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | python2 | n, m, k=map(int, raw_input().split())
edge=[map(int, raw_input().split()) for i in xrange(m)]
adj=[[] for i in xrange(n+1)]
deg=[0 for i in xrange(n+1)]
for x, y in edge:
adj[x]+=[y]
adj[y]+=[x]
deg[x]+=1
deg[y]+=1
q=[]
first=0
removed=set()
def bfs():
global first
while first<len(q):
cur=q[first]
first+=1
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 1;
int n, m, ans[N], cur, done[N], deg[N], k;
vector<pair<int, int> > ve[N];
pair<int, int> e[N];
void bfs(int u, int time) {
queue<int> qu;
done[u] = 1;
cur--;
qu.push(u);
int v;
while (!qu.empty()) {
u = qu.front();
qu.pop();
fo... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | //package com.company;
import java.io.*;
import java.util.*;
public class Main {
static long TIME_START, TIME_END;
public static void main(String[] args) throws IOException {
Scanner sc = new Scanner(System.in);
// Scanner sc = new Scanner(new FileInputStream("Test.in"));
PrintWriter p... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.util.*;
import java.io.*;
public class Main
{
public static void main(String[] args)
{
FastReader reader = new FastReader();
PrintWriter writer = new PrintWriter(System.out);
int n = reader.nextInt();
int m = reader.nextInt();
int k = reader.nextInt();
Node[] graph = new Node[n];
for (int... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 3e5;
int n, m, k, u[N], v[N];
int deg[N], ans[N];
vector<int> G[N], id[N];
bool ok[N];
int main() {
scanf("%d %d %d", &n, &m, &k);
for (int i = 1; i <= m; i++) {
scanf("%d %d", &u[i], &v[i]);
G[u[i]].push_back(v[i]);
G[v[i]].push_back(u[i]);
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.util.*;
public class Main {
static OutWriter out;
static InReader in;
static long X = (long) (1e7);
public static void main(String args[]) throws IOException {
in = new InReader();
out = new OutWriter();
int n = in.nextInt();
int m = in.ne... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
int n, m, k;
int du[maxn];
set<int> g[maxn];
vector<pair<int, int> > ar;
set<pair<int, int> > st;
set<int>::iterator it;
int ans[maxn];
void dfs() {
if (st.size() == 0) return;
if (st.begin()->first < k) {
int u = st.begin()->second;
st... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
#pragma warning(disable : 4996)
using namespace std;
namespace Xrocks {}
using namespace Xrocks;
namespace Xrocks {
class in {
} user_input;
class out {
} output;
in& operator>>(in& X, int& Y) {
scanf("%d", &Y);
return X;
}
in& operator>>(in& X, char* Y) {
scanf("%s", Y);
return X;
}
in... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java |
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;
/**
*
*/
public class E {
static ArrayList<Pair>[] g;
static int k;
static boolean[] s;
static int size;
static int[] degree;
static Queue<Integer> q = new LinkedList<>();
pu... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
const int maxn = 2e5 + 10;
const int maxm = 1.5e7 + 10;
const int mod = 998244353;
using namespace std;
int n, m, k, ans;
int num[maxn], vis[maxn], sum[maxn];
pair<int, int> a[maxn];
set<int> st[maxn];
void check(int x) {
if (num[x] >= k || !vis[x]) return;
vis[x] = 0;
ans--;
queue<int>... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 3;
int n, m, k, deg[N], x[N], y[N], ans[N], cnt;
bool del[N];
set<int> G[N];
set<int>::iterator it;
void Del(int rt) {
if (deg[rt] >= k || del[rt]) return;
queue<int> q;
q.push(rt);
del[rt] = 1;
cnt--;
while (!q.empty()) {
int u = q.front... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int l[200100], r[200100];
int n, m, k;
int de[200100];
bool ex[200100];
struct ind {
int id, de;
ind(int a, int b) : id(a), de(b) {}
bool operator<(const ind &b) const {
return de != b.de ? de < b.de : id < b.id;
}
};
vector<int> pa[200100];
set<ind> S;
int fd(i... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
set<int> v[200005];
int x[200005];
int y[200005];
int an[200005];
set<pair<int, int> > s;
void r(int i, int k) {
if (v[x[i]].size() >= k && v[y[i]].size() >= k) {
s.erase(pair<int, int>(v[x[i]].size(), x[i]));
s.erase(pair<int, int>(v[y[i]].size(), y[i]));
v[x... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | //package que_a;
import java.io.*;
import java.util.*;
import java.math.*;
public class utkarsh {
InputStream is;
PrintWriter out;
long mod = (long) (1e9 + 7);
boolean SHOW_TIME;
class pair implements Comparator {
int F, S;
pair(int f, int s) {
F = f; S = s;... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int u[200005], v[200005];
int cnt[200005];
unordered_set<int> adj[200005];
unordered_set<int> take;
stack<int> ans;
queue<int> cac, toerase;
int n, m, k;
void emptycac() {
while (cac.size()) {
int node = cac.front();
cac.pop();
for (auto j : adj[node]) {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, m, k;
cin >> n >> m >> k;
vector<pair<int, int> > arr(m);
vector<vector<int> > G(n);
vector<int> in(n), vis(n);
for (auto& it : arr) {
int u, v;
cin >> u >> v;
in[--u]++;... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 100;
vector<int> v[maxn];
pair<long long, long long> a[maxn];
long long q[maxn], siz[maxn];
bool c[maxn];
long long n, m, k;
set<pair<long long, long long> > s;
map<pair<long long, long long>, bool> mark;
int main() {
ios_base::sync_with_stdio(false... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 210000;
int n, m, k;
int s[MAXN], t[MAXN];
int d[MAXN];
int ans[MAXN], vis[MAXN];
vector<int> edge[MAXN];
pair<int, int> mk(int x, int y) {
return x > y ? make_pair(y, x) : make_pair(x, y);
}
set<pair<int, int> > S;
queue<int> q;
int main() {
scanf("%d ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.OutputStream;
import java.util.Arrays;
import java.util.Iterator;
import java.io.IOException;
import java.util.AbstractSequentialList;
import java.io.InputStreamReader;
import java.io.FileNotF... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.*;
public class e{
static List<Edge> edges[];
static int[] esize;
static boolean[] stay;
static boolean[] used;
static int k;
static int[] u,v;
static int bfs(int id){
int res =0;
esize[u[id]]--;esize[v[i... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.util.*;
import java.io.*;
public class E
{
static int mod = (int) (1e9+7);
static InputReader in;
static PrintWriter out;
static class SegmentTree {
int st[][];
SegmentTree(int n) {
st = new int[4*n][2];
build(0, n - 1, 1);
}
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | //package manthan2018;
import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.ArrayDeque;
import java.util.Arrays;
import java.util.InputMismatchException;
import java.util.Queue;
import java.util.Random;
public class E2 {
InputStream ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 200010, M = 400010, mod = 1e9 + 7;
int n, m, k;
int h[N], e[M], ne[M], idx;
int a[N], b[N], ans[N];
int ind[N], oud[N], cnt;
bool stn[N], stm[M];
struct Edge {
int a, b;
} edge[M];
void add(int a, int b) { e[idx] = b, ne[idx] = h[a], h[a] = idx++; }
queue<in... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | //package contests.CF1037;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.*;
public class E {
static ArrayList<Integer>[] adj;
static int[] vis, going;
static int NO = 3, YES = 2, VIS = 1;
static int k;
pub... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const double EPS = 1e-9;
const long long MOD = 1e9 + 7;
pair<int, int> es[200000];
vector<pair<int, int> > g[200000];
int degree[200000];
set<pair<int, int> > st;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n, m, k;
scanf("%d%d%d", &n, ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
template <typename T, typename Pr = less<T>>
using pq = priority_queue<T, vector<T>, Pr>;
using i64 = long long int;
using ii = pair<int, int>;
using ii64 = pair<i64, i64>;
set<int> adj[200005];
bool removed[200005];
int main() {
int n, m, k;
scanf("%d %d %d", &n, &m, &... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
template <typename T>
void maxtt(T& t1, T t2) {
t1 = max(t1, t2);
}
template <typename T>
void mintt(T& t1, T t2) {
t1 = min(t1, t2);
}
bool debug = 0;
int n, m, k;
int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};
string direc = "RDLU";
long long ln, lk, lm;
void etp(b... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.HashSet;
import java.util.StringTokenizer;
import java.util.Set;
import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.InputStream;
/**... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 10;
set<int> st[N], s;
int ans[N], x[N], y[N];
int n, m, k;
void dfs(int v) {
if (st[v].size() >= k || !s.count(v)) return;
s.erase(v);
for (auto u : st[v]) {
st[u].erase(v);
if (s.count(u) && st[u].size() < k) {
dfs(u);
}
}
}
i... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int mxn = 2e5 + 9;
set<int> g[mxn];
int k;
set<int> se;
void can_now(int u) {
if (g[u].size() < k && se.find(u) != se.end()) {
se.erase(u);
for (auto &v : g[u]) {
g[v].erase(u);
can_now(v);
}
}
}
int res[mxn];
pair<int, int> e[mxn];
int mai... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.List;
import java.util.InputMismatchException;
import java.io.IOException;
import java.util.ArrayList;
import java.io.InputStream;
/**
* Built using CHelper plug-i... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.List;
import java.util.InputMismatchException;
import java.io.IOException;
import java.util.ArrayList;
import java.io.InputStream;
/**
* Built using CHelper plug-in
* Actual solution is a... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, k;
int a[200010], b[200010];
vector<pair<int, int> > G[200010];
int deg[200010];
int ans[200010], cnt;
queue<int> q;
inline void spfa(int x) {
while (!q.empty()) {
int u = q.front();
q.pop();
for (int i = 0; i < G[u].size(); i++) {
int v = G[u]... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
#pragma GCC optimize(3)
#pragma GCC optimize(2)
using namespace std;
const int maxn = 2e5 + 10;
int N, M, K;
set<int> g[maxn];
set<pair<int, int> > person;
int deg[maxn];
int ans[maxn];
pair<int, int> edges[maxn];
int main() {
scanf("%d %d %d", &N, &M, &K);
for (int i = 1; i <= M; ++i) {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
map<long long int, long long int> m1, m2;
const long long int N = 3 * 1e5;
vector<long long int>::iterator itr, itr1;
int main() {
int n, m, k;
cin >> n >> m >> k;
vector<pair<int, int> > Edges(m);
vector<int> Ans(m);
vector<int> degree(n);
vector<vector<pair<in... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
void err(istream_iterator<string> it) {}
template <typename T, typename... Args>
void err(istream_iterator<string> it, T a, Args... args) {
cerr << *it << " = " << a << "\n";
err(++it, args...);
}
vector<pair<int, int> > edge(200003);
vector<vector<pair<int, int> > > ad... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int N, M, K;
int xList[200005], yList[200005];
int deg[200005], ans[200005];
set<int> Adj[200005];
set<pair<int, int> > s;
set<pair<int, int> >::iterator p;
void work(int u) {
s.erase(make_pair(deg[u], u));
int v;
set<int>::iterator k;
for (k = Adj[u].begin(); k != ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct edge {
int from, to, vis, next;
} e[400020];
int top, head[200020];
vector<int> g[200020];
int in[200020], gg[200020];
int n, m, k;
int ans[200020], cnt;
void add_edge(int from, int to) {
e[++top].to = to;
e[top].from = from;
e[top].next = head[from];
head[... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | python2 | from collections import defaultdict
n, m, k = map(int, raw_input().split())
xys = [map(int, raw_input().split()) for _ in range(m)][::-1]
gv = defaultdict(set)
for x, y in xys:
gv[x].add(y)
gv[y].add(x)
q = [u for u, vs in tuple(gv.items()) if len(vs) < k]
i = 0
while i < len(q):
u = q[i]
i += 1
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.util.*;
import java.math.BigInteger;
import java.util.Map.Entry;
import static java.lang.Math.*;
public class E extends PrintWriter {
class Node {
final int id;
final Map<Node, Edge> edges = new HashMap<>();
boolean use = true;
public Node(int id) {... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, k, m;
int u[200005], v[200005];
set<int> e[200005];
int deg[200005];
bool alive[200005];
int alc;
queue<int> delet;
void del(int x) {
alive[x] = false;
alc--;
for (int y : e[x]) {
if (alive[y]) {
deg[y]--;
if (deg[y] == k - 1) {
delet.pu... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
struct edge {
int to, net;
};
int head[2000000];
int e_n;
edge edges[2000000];
int deg[2000000];
bool sd[2000000];
int v1[2000000], v2[2000000];
set<pair<int, int> > help;
set<pair<int, int> > tt;
void Init() {
help.clear();
e_n = 0;
memset(sd, 0, sizeof(sd));
mem... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = (int)2e5 + 5;
int n, m, k;
vector<pair<int, int> > out[maxn];
int la[maxn];
int pos[maxn];
int deg[maxn];
int add[maxn];
bool dead[maxn];
set<pair<int, int>, greater<pair<int, int> > > s;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cin >> n... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java |
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.lang.reflect.Array;
import java.nio.charset.Charset;
import java.util.*;
public class CFContest {
public static void main(String[] args) throws Exception {
boolean local = Syste... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
const int N = 200005;
int n, m, k, ans[N], in[N], cnt;
std::map<int, bool> vis[N];
std::vector<int> G[N];
std::vector<std::pair<int, int> > e;
std::queue<int> q;
void topo() {
while (!q.empty()) {
int u = q.front();
q.pop();
in[u] = 0;
for (int i = 0; i < (signed)G[u].size(); ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int inf32 = 1e9 + 9;
const long long inf64 = 1e18 + 18;
const int N = 2e5 + 5;
const long long mod = 1e9 + 9;
vector<int> gr[N];
set<pair<int, int> > deg;
int pw[N];
bool used[N];
void solve() {
int n, m, k;
scanf("%d%d%d", &n, &m, &k);
vector<pair<int, int> > e... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
struct pnt {
int hd;
int ind;
bool ded;
} p[1000000];
struct ent {
int twd;
int lst;
} e[1000000];
int cnt;
int n, m, k;
int lft;
int ans[1000000];
int u[1000000], v[1000000];
void ade(int f, int t) {
cnt++;
e[cnt].twd = t;
e[cnt].lst = p[f].hd;
p[f].hd = cnt;
p[f].ind++;
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.BufferedOutputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.io.Reader;
import java.util.ArrayList;
import java.util.HashSet;
import java.util.StringTokenizer;
import java.util.TreeSet;
public class E {
st... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, k;
int x[202020];
int y[202020];
set<int> v[202020];
int d[202020];
int z[202020];
vector<int> q;
int c;
vector<int> r;
int p[202020];
void lol() {
for (int i = 0; i < q.size(); i++) {
int x = q[i];
if (!z[x]) continue;
z[x] = 0;
c--;
for (au... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Queue;
import java.util.StringTokenizer;
import java.util.TreeSet;
public class E {
public static final long MOD ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 2e5 + 5;
int N, M, K;
int x[MAXN], y[MAXN];
unordered_set<int> adj[MAXN];
int ans[MAXN];
struct cmp {
bool operator()(const int &lhs, const int &rhs) const {
if (adj[lhs].size() != adj[rhs].size())
return adj[lhs].size() < adj[rhs].size();
r... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.util.*;
import java.math.*;
import java.lang.*;
import static java.lang.Math.*;
public class Main implements Runnable {
static class InputReader {
private InputStream stream;
private byte[] buf = new byte[1024];
private int curChar;
private int numCha... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 200010;
int ans[N];
int deg[N];
bool trip[N];
set<int> g[N];
int cnt, k;
void remove(int u) {
if (!trip[u]) return;
queue<int> q;
q.push(u);
trip[u] = false;
while (!q.empty()) {
u = q.front();
q.pop();
cnt--;
for (int v : g[u]) {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int nmax = 2e5 + 5;
const int mod = 1e9 + 7;
vector<int> g[nmax];
int destroyed;
pair<int, int> ej[nmax];
int deg[nmax], ans[nmax];
bool vis[nmax];
map<pair<int, int>, int> mp;
void dhongsho(int u, int k, int p) {
if (vis[u]) return;
vis[u] = true;
destroyed++;
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
;
long long int n, m, k;
cin >> n >> m >> k;
vector<pair<long long int, long long int> > edges(m);
set<long long int> adj[n];
for (int i = 0; i < m; ++i) {
long long int u, v;
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
vector<set<int> > g;
int n, m, k;
vector<pair<int, int> > q;
set<int> s;
void remove(int v) {
if (g[v].size() < k && s.erase(v)) {
for (auto to : g[v]) g[to].erase(v), remove(to);
}
}
int main() {
ios_base::sync_with_stdio(0);
cin >> n >> m >> k;
q.resize(m);
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
vector<int> p[maxn];
int vis[maxn];
int ans[maxn];
int num[maxn];
int v[maxn], w[maxn];
int now;
int n, m, k;
void dfs(int j, int v) {
ans[j]--;
for (int i = 0; i < p[v].size(); i++) {
num[p[v][i]]--;
if (vis[p[v][i]] == 1) {
if (... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 10;
vector<int> G[N];
int n, m, k;
int qu[N], qv[N], vis[N], du[N], ans[N], res;
void dfs(int u) {
if (vis[u]) return;
if (du[u] < k) {
vis[u] = 1;
for (int v : G[u])
if (!vis[v]) du[v]--;
for (int v : G[u]) {
if (!vis[v]) {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 200005;
int n, m, k, sum;
int x[N], y[N];
vector<int> Edge[N];
int del[N], deg[N];
int ans[N];
inline int read() {
int x = 0, f = 1;
char ch = getchar();
while (!isdigit(ch)) {
if (ch == '-') f = -1;
ch = getchar();
}
while (isdigit(ch)) {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.util.*;
public class A {
FastScanner in;
PrintWriter out;
void solve() {
int n = in.nextInt();
int m = in.nextInt();
int k = in.nextInt();
int[] fr = new int[m];
int[] to = new int[m];
List<Integer>[] g = new ArrayList[n];
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 5;
set<int> s, G[N];
int n, m, k;
int U[N], V[N], ans[N];
void check(int u) {
if (G[u].size() < k && s.erase(u)) {
for (auto v : G[u]) {
G[v].erase(u);
check(v);
}
}
}
int main() {
scanf("%d%d%d", &n, &m, &k);
for (int i = 1; ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 200010;
pair<int, int> edge[maxn];
int deg[maxn], ans[maxn];
bool del[maxn], vis[maxn];
set<pair<int, int> > dic;
vector<pair<int, int> > g[maxn];
int main() {
int n, m, k, u, v;
scanf("%d%d%d", &n, &m, &k);
for (int i = 0; i < m; i++) {
scanf("%d... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
template <typename T>
inline T const &MAX(T const &a, T const &b) {
return a > b ? a : b;
}
template <typename T>
inline T const &MIN(T const &a, T const &b) {
return a < b ? a : b;
}
inline void add(long long &a, long long b) {
a += b;
if (a >= 1000000007) a -= 1000000007;
}
inline voi... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
set<int> trip;
set<int> vec[200010];
struct node {
int u, v;
} mf[200010];
int n, m, k;
int ans[200010];
void remove(int x) {
set<int>::iterator it;
if (vec[x].size() < k && trip.count(x)) {
trip.erase(x);
for (it = vec[x].begin(); it != vec[x].end(); it++) {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.math.*;
import java.util.*;
import java.util.stream.*;
public class E {
public Object solve() {
int N = sc.nextInt(), M = sc.nextInt(), K = sc.nextInt();
int [][] E = dec(sc.nextInts(M));
int [][] G = graph(N, E);
PriorityQueue<int[]> Q = new PriorityQueue<>(by(1));
boolean [] W = new boolean ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java |
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.*;
/**
*
*/
public class E {
static LinkedList<Pair>[] g;
static int k;
static Set<Integer> s;
static int[] degree;
static Queue<Integer> q = new LinkedList<>();
public static void ... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.util.*;
public class Main implements Runnable {
FastReader scn;
PrintWriter out;
String INPUT = "";
void solve() {
int n = scn.nextInt(), m = scn.nextInt(), k = scn.nextInt();
int[] from = new int[m], to = new int[m], w = new int[m];
for(int i = m - 1; i >= 0; i--) {
from[i... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, k;
int a[200005];
int b[200005];
vector<int> adj[200005];
bool removed[200005];
int nc[200005];
int ans[200005];
set<pair<int, int>> remedges;
int main() {
ios::sync_with_stdio(false);
scanf("%d %d %d", &n, &m, &k);
for (int i = 0; i < m; i++) {
scanf("%... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.*;
public class A {
InputStream is;
PrintWriter out;
String INPUT = "";
void solve()
{
int n = ni(), m = ni(), k = ni();
ArrayList<Integer> adj[] = (ArrayList<Integer>[])... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int M = 1e9 + 7;
long long powmod(long long a, long long b, long long mod) {
long long res = 1;
a %= mod;
assert(b >= 0);
for (; b; b >>= 1) {
if (b & 1) res = res * a % mod;
a = a * a % mod;
}
return res % mod;
}
const int N = 2e5 + 10;
int degree... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
string to_string(string s) { return '"' + s + '"'; }
string to_string(char s) { return string(1, s); }
string to_string(const char *s) { return to_string((string)s); }
string to_string(bool b) { return (b ? "true" : "false"); }
template <typename A>... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.io.BufferedInputStream;
import java.util.Iterator;
import java.util.Set;
import java.util.TreeSet;
import java.util.Stack;
import java.util.HashSet;
import java.io.FilterInputStream;
import java.... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int mxN = 2e5;
int n, m, k, eu[mxN], ev[mxN], ans[mxN];
set<int> adj[mxN];
bool a[mxN];
vector<int> tp;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cin >> n >> m >> k;
for (int i = 0; i < m; ++i) {
cin >> eu[i] >> ev[i], --eu[i], --ev[i];
ad... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, d[200005], k, res, vs[200005], ans[200005], pa;
map<int, int> cnt[200005];
vector<int> ke[200005];
pair<int, int> a[200005];
void dfs(int u) {
d[u]--;
res--;
vs[u] = 1;
for (int v : ke[u])
if (vs[v] == 0) {
cnt[u][v] = cnt[v][u] = 1;
d[v]--... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.io.*;
import java.math.BigInteger;
import java.util.*;
public class CF1037_E {
public static void main(String[] args) throws Throwable {
MyScanner sc = new MyScanner();
PrintWriter pw = new PrintWriter(System.out);
n = sc.nextInt();
adj = new HashSet[n];
for (in... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 2e5;
set<int> g[MAXN];
int n, m, k;
int result = 0;
bool removed[MAXN];
int c[MAXN];
int edges[MAXN][2];
queue<int> q;
void remove_item(int m) {
result--;
q.push(m);
removed[m] = true;
}
void clear_queue() {
while (!q.empty()) {
auto to = q.fron... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int deg[200010];
vector<vector<int> > graph(200010);
map<pair<int, int>, int> edgeNum;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int tt = 1;
while (tt--) {
int n, m, k;
cin >> n >> m >> k;
int x[m], y[m];
for (in... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 10;
const int maxm = 2e5 + 10;
const int INF = 0x3f3f3f3f;
struct Edge {
int v, next, id;
} edge[maxm * 2];
int n, m, k, res;
int U[maxn], V[maxn], du[maxn], Ans[maxn];
int head[maxn], cnt;
queue<int> q;
bool vis[maxn];
bool ok[maxn];
void add(int u... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | python2 | import sys
range = xrange
n,m,k = [int(x) for x in sys.stdin.readline().split()]
inp = [int(x)-1 for line in sys.stdin for x in line.split()]
ii = 0
coupl = [[] for _ in range(n)]
time = [[] for _ in range(n)]
nfr = [0]*n
for i in range(m):
a,b = inp[ii],inp[ii+1]
ii += 2
coupl[a].append(b)
coupl[b]... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | python2 |
import sys
range = xrange
n,m,k = [int(x) for x in sys.stdin.readline().split()]
inp = [int(x)-1 for line in sys.stdin.read().split('\n') for x in line.split()]
ii = 0
coupl = [[] for _ in range(n)]
time = [[] for _ in range(n)]
nfr = [0]*n
for i in range(m):
a,b = inp[ii],inp[ii+1]
ii += 2
coupl[a].ap... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | CORRECT | java | import java.util.*;
import java.io.*;
public class Trips {
public static void main(String[] args) {
FastScanner sc = new FastScanner();
StringBuilder sb = new StringBuilder();
ArrayDeque<Integer> out = new ArrayDeque<>();
ArrayDeque<Pair> edges = new ArrayDeque<>();
ArrayDeq... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
int n, m, k;
int res = 0;
int U[200003], V[200003];
bool bol[200003];
queue<int> q;
set<int> vec[200003];
vector<int> ans;
void kill(int x) {
q.push(x);
while (q.size()) {
int curr = q.front();
q.pop();
res--;
bol[curr] = 0;
for (auto it : vec[curr])... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | IN-CORRECT | cpp | #include <bits/stdc++.h>
#pragma warning(disable : 4996)
#pragma comment(linker, "/stack:200000000")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("-ffloat-store")
using namespace std;
const int MN = 200010;
set<int> e[MN];
int from[MN], to[MN], deg[MN], vis[MN], res[MN];
int n, m, k, cnt;
void deletev(int v) {
... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
long long m, k, du[500000], tot, book[500000], n, cnt, ans[500000],
ask[500000][3];
vector<long long> edge[500000];
void bfs(long long u) {
queue<long long> q;
book[u] = 1;
q.push(u);
cnt--;
while (q.size()) {
long long x = q.front();
q.pop();
long... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
vector<pair<int, int> > v[500001];
int flag[500001], ct[500001];
int visited[500001], st[500001];
int ans, k;
void dfs(int i) {
if (st[i] == -1) return;
st[i] = -1;
for (int j = 0; j < v[i].size(); ++j) {
if (flag[v[i][j].second] == 0) {
flag[v[i][j].second]... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | IN-CORRECT | java | import java.io.*;
import java.util.*;
public class Main {
static int deg[];
static Set<Integer> s;
static Set[] graph;
static int n,k;
public static void main(String[] args) throws Exception {
FastReader sc = new FastReader();
OutputWriter out = new OutputWriter(System.out);
n = sc.nextInt();
int m = sc.n... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | IN-CORRECT | cpp | #include <bits/stdc++.h>
const int N = 2e5 + 5;
using namespace std;
int n, m, k;
int res[N];
int x[N], y[N];
int bac[N];
set<int> a[N];
set<pair<int, int> > S;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> m >> k;
for (int i = 1; i <= m; i++) {
cin >> x[i] >> y[i];
a... |
1037_E. Trips | There are n persons who initially don't know each other. On each morning, two of them, who were not friends before, become friends.
We want to plan a trip for every evening of m days. On each trip, you have to select a group of people that will go on the trip. For every person, one of the following should hold:
* ... | {
"input": [
"4 4 2\n2 3\n1 2\n1 3\n1 4\n",
"5 8 2\n2 1\n4 2\n5 4\n5 2\n4 3\n5 1\n4 1\n3 2\n",
"5 7 2\n1 5\n3 2\n2 5\n3 4\n1 2\n5 3\n1 3\n"
],
"output": [
"0\n0\n3\n3\n",
"0\n0\n0\n3\n3\n4\n4\n5\n",
"0\n0\n0\n0\n3\n4\n4\n"
]
} | {
"input": [
"16 20 2\n10 3\n5 3\n10 5\n12 7\n7 6\n9 12\n9 6\n1 10\n11 16\n11 1\n16 2\n10 2\n14 4\n15 14\n4 13\n13 15\n1 8\n7 15\n1 7\n8 15\n",
"2 1 1\n2 1\n"
],
"output": [
"0\n0\n3\n3\n3\n3\n7\n7\n7\n7\n7\n11\n11\n11\n11\n15\n15\n15\n15\n16\n",
"2\n"
]
} | IN-CORRECT | cpp | #include <bits/stdc++.h>
using namespace std;
pair<int, int> edge[200000 + 324];
vector<int> adj[200000 + 324];
set<int> degree[200000 + 324];
set<int> friends;
int ans[200000 + 324];
int k;
void rem(int x) {
if (degree[x].size() < k && friends.erase(x)) {
for (auto &bc : degree) {
bc.erase(x);
}
}
}
... |
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