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1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
java
import java.util.*; import java.io.*; public class SummoningMinions { public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out)); int t = Integer.parseInt(br.read...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const double PI = acos(-1); const double eps = 1e-12; const int inf = 2000000000; const long long int infLL = (long long int)1e18; long long int MOD = 1000000007; int MOD1 = 1000000007; int MOD2 = 1000000009; inline bool checkBit(long long int n, long long int i) { return...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
python3
def m(e): return e['m'] def h(e): return e['h'] a = int(input()) for i in range(a): num = [int(x) for x in input().split()] mi = [] for j in range(num[0]): a = [int(x) for x in input().split()] k = {} k['m'] = a[0] k['h'] = a[1] k['i'] = j+1 mi.append(k) ...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") using namespace std; void *wmem; char memarr[96000000]; template <class T> inline void walloc1d(T **arr, int x, void **mem = &wmem) { static int skip[16] = {0, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1}; (*mem) = (void *)(((char *)(*mem)) + skip[((unsig...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
java
import java.util.ArrayList; import java.util.LinkedList; import java.util.List; import java.util.Scanner; /** * * @author MasterEx */ public class ECR87F { static class Minion { int pos; long power; long benefit; public Minion(int p, long po, long b) { pos = p + 1...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
python3
for _ in range(int(input())): n, k = map(int, input().split()) values = [] for i in range(n): a, b = map(int, input().split()) values.append((i + 1, a, b)) if k == 1: best = -1 score = 0 for (i, a, b) in values: if a > score: best ...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; vector<pair<pair<int, int>, int>> v; long long dp[80][80]; pair<int, int> from[80][80]; set<int> s; int main() { int t; cin >> t; while (t) { t--; int i, j, n, k; cin >> n >> k; v.clear(); s.clear(); for (i = 1; i <= n; i++) { int a, b; ...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
///#pragma GCC optimize("Ofast,unroll-loops,no-stack-protector,fast-math") ///#pragma GCC target("sse,sse2,sse3,ssse3,sse4,abm,mmx,popcnt,avx,avx2,tune=native") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <ext/rope> /* zet: find_by_order(...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const double PI = acos(-1); const double eps = 1e-12; const int inf = 2000000000; const long long int infLL = (long long int)1e18; long long int MOD = 1000000007; int MOD1 = 1000000007; int MOD2 = 1000000009; inline bool checkBit(long long int n, long long int i) { return...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
//Optional FAST //#pragma GCC optimize("Ofast") //#pragma GCC optimize("unroll-loops") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,fma,abm,mmx,avx,avx2,tune=native") //Required Libraries #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
python3
#qn given an arr of size n for every i position find a min j such that j>i and arr[j]>arr[i] #it prints the position of the nearest . import sys input = sys.stdin.readline #qn given an arr of size n for every i position find a min j such that j>i and arr[j]>arr[i] #it prints the position of the nearest . # import sy...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
java
/* ID: tommatt1 LANG: JAVA TASK: */ import java.util.*; import java.io.*; public class cf1354f{ public static void main(String[] args)throws IOException { PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out))); BufferedReader bf=new BufferedReader(new InputStreamReader(Syste...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; #define int long long main() { ios_base::sync_with_stdio(0); cin.tie(0); cout << setprecision(15) << fixed; int t; cin >> t; while(t--){ int n, k; cin >> n >> k; vector < vector <int> > a;//(n, vector <int> (3) ); for(...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
python3
import sys readline = sys.stdin.readline read = sys.stdin.read ns = lambda: readline().rstrip() ni = lambda: int(readline().rstrip()) nm = lambda: map(int, readline().split()) nl = lambda: list(map(int, readline().split())) prn = lambda x: print(*x, sep='\n') def solve(): n, k = nm() mini = [tuple(nm()) for...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; template <typename T1, typename T2> string print_iterable(T1 begin_iter, T2 end_iter, int counter) { bool done_something = false; stringstream res; res << "["; for (; begin_iter != end_iter and counter; ++begin_iter) { done_something = true; counter--; r...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; class bipartiteGraph { public: int n; vector<vector<int>> cost; vector<int> mx, my, lx, ly, p; vector<bool> vx, vy; vector<int> dy, pdy; queue<int> qu{}; int MAX{numeric_limits<int>::max()}; bipartiteGraph(int n) : n(n), cost(n, vector<int>(n)...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long mod = 1000000007; long long inf = 1LL << 50; const int N = 75; int main() { ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0); cin.exceptions(cin.failbit); int T; cin >> T; for (int z = 0; z < T; z++) { int n, k; cin >> n >> k; vector...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int N = 77; int T, n, k, f[N][N]; bool g[N][N], c[N]; void qr(int &x) { scanf("%d", &x); } struct node { int a, b, id; bool operator<(node t) const { return b < t.b; } } a[N]; int main() { qr(T); while (T--) { qr(n); qr(k); for (int i = 1; i <= n; ...
1354_F. Summoning Minions
Polycarp plays a computer game. In this game, the players summon armies of magical minions, which then fight each other. Polycarp can summon n different minions. The initial power level of the i-th minion is a_i, and when it is summoned, all previously summoned minions' power levels are increased by b_i. The minions c...
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
{ "input": [ "3\n5 2\n5 3\n7 0\n5 0\n4 0\n10 0\n2 1\n10 100\n50 10\n5 5\n1 5\n2 4\n3 3\n4 2\n5 1\n" ], "output": [ "8\n2 3 -3 4 -4 1 -1 5\n3\n1 -1 2\n5\n5 4 3 2 1\n" ] }
IN-CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("O3") using namespace std; template <class T> inline void amin(T &x, const T &y) { if (y < x) x = y; } template <class T> inline void amax(T &x, const T &y) { if (x < y) x = y; } template <class Iter> void rprintf(const char *fmt, Iter begin, Iter end) { for (bool sp ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; template <typename T> using minpq = priority_queue<T, vector<T>, greater<T>>; int n, k, a, b; long long t; vector<long long> ve[2][2]; int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> n >> k; for (int i = (0); i < (n); i++) { cin >> t >> a >> b; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys input=sys.stdin.readline f=lambda :list(map(int, input().strip('\n').split())) n, k=f() _11=[] _01=[] _10=[] for _ in range(n): t, a, b=f() if a and b: _11.append(t) elif a: _10.append(t) elif b: _01.append(t) _01.sort(); _10.sort(); _11.sort() for i in range(1, len(_01)): _01[i]+=_01[i-1] for i ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int INF = 1e9; const long long INFLL = 0x3f3f3f3f3f3f3f3f; const int MOD = 1e9 + 7; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); int n, k; cin >> n >> k; vector<int> alice, bobo, osdois; for (int i = 0; i < n; i++) { bool a, b;...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, k, res = 0; cin >> n >> k; vector<int> arrAB; vector<int> arrA; vector<int> arrB; for (int i = 0; i < n; i++) { int time, a, b; cin >> time >> a >> b; if (a == 1 && b == 1) { arrAB.push_back(time); } else if (a == 1) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; public class Codeforces { public static void main(String args[])throws Exception { BufferedReader bu=new BufferedReader(new InputStreamReader(System.in)); StringBuilder sb=new StringBuilder(); String s[]=bu.readLine().split(" "); int n=Integ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from collections import deque n, k = map(int, input().split()) onla = [] onlb = [] both = [] for i in range(n): a, b, c = map(int, input().split()) if b == 1 and c == 1: both.append(a) elif c == 1: onlb.append(a) elif b == 1: onla.append(a) if len(both) + len(onla) < k or len(bot...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
class Book: def __init__(self, time, for_alice, for_bob): self.time = time self.for_alice = bool(for_alice) self.for_bob = bool(for_bob) self.status = ('A' if self.for_alice else '') + ('B' if self.for_bob else '') def get(li, i): try: return li[i].time except Index...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import stdin input=stdin.readline def answer(): if(n3+n1 < k or n3+n2 < k):return -1 i,j=0,0 ans=0 for take in range(k): if(i >= n1 or i >= n2): ans+=common[j] j+=1 elif(j >= n3): ans+=a[i]+b[i] i+=1 else: ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
nb_books, mins = [int(x) for x in input().split()] x, y, z = [],[],[] for i in range(nb_books): n, a, b = [int(x) for x in input().split()] if a & b:z.append(n) elif a:x.append(n) elif b:y.append(n) x.sort() y.sort() for i in range(min(len(x), len(y))) : z.append(x[i] + y[i]) answer = sum(sorted...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.util.*; public class readingBooks { public static void main(String[] args) { Scanner input = new Scanner(System.in); int n = input.nextInt(); int k = input.nextInt(); ArrayList<Integer>[] arr = new ArrayList[4]; for(int i = 0; i < 4; i++){ arr[i] = n...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; import java.math.*; import java.lang.*; import static java.lang.Math.*; public class Solution implements Runnable { static class InputReader { private InputStream stream; private byte[] buf = new byte[1024]; private int curChar; private int numChars; private SpaceCharF...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; public final class ReadingBooksEasy { private static final FastReader fr = new FastReader(); public static void main(String[] args) { final int n = fr.nextInt(), k = fr.nextInt(); final Triple[] triples = new Triple[n]; for (int i = 0; i < n; i++)...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) books = [] alice = [] bob = [] for _ in range(n): book = tuple(map(int, input().split())) if book[1] == book[2] == 1: books.append(book[0]) elif book[1] == 1: alice.append(book[0]) elif book[2] == 1: bob.append(book[0]) for a, b in zip(so...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.*; public class cdf653e1 { static void merge(int arr[], int l, int m, int r) { int n1 = m - l + 1; int n2 = r - m; int L[] = new int [n1]; int R[] = new int [n2]; for (int i=0; i<n1; ++i)...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("O3") #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") using namespace std; const long long maxn = 15e5 + 10; const long long inf = 1e14; long long n, m, k, t; long long cur1, cur2; long long C[maxn]; vector<long long> ANS; vector<pair<long long, long long...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import stdin,stdout # stdin = open("input.txt","r") # stdout = open("output.txt","w") n,k = stdin.readline().strip().split(' ') n,k = int(n),int(k) books=[] for i in range(n): t,a,b=stdin.readline().strip().split(' ') t,a,b=int(t),int(a),int(b) books.append((t,a,b)) pairs_a=[] pairs_b=[] single=[] ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) alice=[];bob=[];both=[] for _ in range(n): x,y,z=map(int,input().split()) if y==1 and z==1: both.append(x) elif y==1: alice.append(x) elif z==1: bob.append(x) alice.sort();bob.sort() # print(alice) for i in range(min(len(alice),len(bob))): bot...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int solve() { int n, k; cin >> n >> k; int a, b, ans; ans = a = b = 0; priority_queue<int> x, y, z; while (n--) { int t, u, v; cin >> t >> u >> v; t *= -1; if (u && v) { z.push(t); } else if (u) { x.push(t); } else if (v) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
def main(): n,k=list(map(int,input().split())) l=[] c1=0 c2=0 for j in range(0,n): l1=list(map(int,input().split())) if l1[1]==1: c1+=1 if l1[2]==1: c2+=1 l.append(l1) if c1<k or c2<k: print(-1) return c=0 ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys from functools import lru_cache, cmp_to_key from heapq import merge, heapify, heappop, heappush, nsmallest from math import ceil, floor, gcd, fabs, factorial, fmod, sqrt, inf from collections import defaultdict as dd, deque, Counter as C from itertools import combinations as comb, permutations as perm from b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; inline long long read() { long long r = 0, f = 0; char c; while (!isdigit(c = getchar())) f |= (c == '-'); while (isdigit(c)) r = (r << 1) + (r << 3) + (c ^ 48), c = getchar(); return f ? -r : r; } inline long long min(long long a, long long b) { return a < b ? a ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.*; public class hello2 {static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new Buffer...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = list(map(int, input().split())) a = [] b = [] ab = [] for _ in range(0, n): t, x, y = list(map(int, input().split())) if (x == 1 and y == 1): ab.append(t) elif (x == 1): a.append(t) elif (y == 1): b.append(t) # print(a, b, ab) ab.sort(reverse=True) b.sort(reverse=True...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys input = sys.stdin.readline n, k = map(int, input().split()) o, a, b = [], [], [] for i in range(n): q, w, e = map(int, input().split()) if w == e and w: o.append(q) elif w and not e: a.append(q) elif w or e: b.append(q) i = j = l = 0 d...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = list(map(int,input().split())) ca,cb=0,0 x,y,z = [],[],[] for i in range(n): t,a,b, = list(map(int,input().split())) ca+=a cb+=b if(a==1 and b==0): x.append(t) elif(a==0 and b==1): y.append(t) elif(a==1 and b==1): z.append(t) x.sort() y.sort() z.sort() if(ca<k or cb...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long INF = 1e18; namespace BF { long long solve(int N, int M, int K, const vector<int>& T, const vector<int>& A, const vector<int>& B) { long long res = INF; for (int mask = 0, _n = (1 << N); mask < _n; ++mask) { if ((__builtin_popcount((m...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; class Solve { public: void updateSt(set<pair<int, int>> &st, set<pair<int, int>> &fr, int &sum, int need) { need = max(need, 0); while (true) { bool useful = false; while (st.size() > need) { sum -= st.rbegin()->first; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
input = raw_input range = xrange import sys inp = [int(x) for x in sys.stdin.read().split()]; ii = 0 seg = [0]*200000 def offset(x): return x + 100000 def encode(x, y): return (x<<20) + y def upd(node, L, R, pos, val): if L+1 == R: seg[node] += val seg[offset(node)] = seg[node]*L return M = (L+R)>>1 if po...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
## necessary imports import sys input = sys.stdin.readline #from math import ceil, floor, factorial; # swap_array function def swaparr(arr, a,b): temp = arr[a]; arr[a] = arr[b]; arr[b] = temp ## gcd function def gcd(a,b): if b == 0: return a return gcd(b, a % b); ## nCr function efficient...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
###################################################### ############Created by Devesh Kumar################### #############devesh1102@gmail.com#################### ##########For CodeForces(Devesh1102)################# #####################2020############################# ###############################################...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) A, B, both = [0], [0], [0] for i in range(n): t, a, b = map(int, input().split()) if a == 1 and b == 1: both.append(t) if a == 1 and b == 0: A.append(t) if a == 0 and b == 1: B.append(t) A.sort() B.sort() both.sort() if len(A)-1 + len(both)-1 < k or len(B)-1 + len(both)-1 < k:...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
line = input().split() n,k = int(line[0]), int(line[1]) a,b,c = [],[],[] for i in range(n): line = input().split() t,ai,bi = int(line[0]), int(line[1]), int(line[2]) if (ai == 1 and bi == 1): c.append(t) elif (ai == 1): a.append(t) elif (bi == 1): b.append(t) a.sort() b.sort() c.sort() i,j,cnt = 0,0,0 an...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Collections; import java.util.InputMismatchException; public class B { public static void main(String[] args) throws Exception { // TODO Auto-generated method stub InputR...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split(" ")) db=[] a=[] b=[] for i in range(n): t,A,B= map(int, input().split(" ")) if A==B==1: db.append(t) elif A==1: a.append(t) elif B==1: b.append(t) a.sort() b.sort() for i in range(min(len(a),len(b))): db.append((a[i]+b[i])) if len(db)<k: print(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
n,k = map(int,raw_input().split()) both = [];alice = [];bob = [] for _ in range(n): t,a,b = map(int,raw_input().split()) if a&b: both.append(t) elif a: alice.append(t) elif b: bob.append(t) alice.sort() bob.sort() for i in range(min(len(alice),len(bob))): both.append(alice[i]...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
//package com.company; //import com.sun.tools.corba.se.idl.StructEntry; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.math.BigInteger; import java.util.*; public class Main { public static void main(String[] args) throws IOException { BufferedRead...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import os, sys from io import IOBase, BytesIO py2 = round(0.5) if py2: from future_builtins import ascii, filter, hex, map, oct, zip range = xrange BUFSIZE = 8192 class FastIO(BytesIO): newlines = 0 def __init__(self, file): self._file = file self._fd = file.fileno() self.writa...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split()) a =[] b =[] c = [] for i in range(n): m = [*map(int,input().split())] if(m[1]==1 and m[2]==1): c.append(m[0]) elif(m[1]==1): a.append(m) elif(m[2]==1): b.append(m) a.sort(key=lambda x:(x[0])) b.sort(key=lambda x:(x[0])) for...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys input=sys.stdin.readline def main(): n,k=map(int,input().split()) A,B,C=[],[],[] for i in range(n): n,a,b=map(int,input().split()) if(a==1 and b==1): A.append(n) elif(a==1 and b==0): B.append(n) elif(a==0 and b==1): C.append(n) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int32_t main() { int n, m, k; ios_base::sync_with_stdio(false); cin.tie(NULL); cin >> n >> m >> k; vector<pair<int, int> > ab; vector<pair<int, int> > a; vector<pair<int, int> > b; vector<pair<int, int> > non; for (int i = 0; i < n; i++) { int t, a1, b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from collections import defaultdict as dd import sys input=sys.stdin.readline #n=int(input()) n,kk=map(int,input().split()) l=[] ans=0 for i in range(n): time,a,b=map(int,input().split()) l.append((time,a,b)) l.sort() la=[] lb=[] do=[] for i in l: time,a,b=i if(a and b): do.append(time) elif...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int mpow(int base, int exp); void ipgraph(int n, int m); void dfs(int u, int par); const int mod = 1e9 + 7; struct cmp { bool operator()(const int& lhs, const int& rhs) const { return lhs < rhs; } }; int mpow(int base, int exp) { base %= mod; int result = 1; while (...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys from collections import deque, defaultdict input = sys.stdin.buffer.readline n, k = map(int, input().split()) al, bl, cc = [], [], [] for _ in range(n): t, a, b = map(int, input().split()) if a and not b: al.append(t) elif not a and b: bl.append(t) elif a and b: cc.append(t) al.sort(); bl.so...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int, input().split()) tab=[tuple(map(int,input().split())) for _ in range(n)] both=[tabi[0] for tabi in tab if tabi[1:]==(1,1)] both.sort() alice=[tabi[0] for tabi in tab if tabi[1:]==(1,0)]# tabi[1]==1 and tabi[2]==0] bob=[tabi[0] for tabi in tab if tabi[1:]==(0,1)] alice.sort() bob.sort() ab=[alice[i]+bob[i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = [int(x) for x in input().strip().split()] vec = [] for _ in range(n): vec.append([int(x) for x in input().split()]) vec.sort() f1 = f2 = f3 = 0 minsum = 0 count = 0 min_12 = min_3 = 0 flag12 = flag3 = True while ((f3 <= n-1 or (f1 <= n-1 and f2 <= n-1)) and count < k): while f3 <= n-1: if vec[f3]...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split()) l1=[] l2=[] l3=[] ac,bc=0,0 for i in range(n): t,a,b=map(int,input().split()) if(a==1 and b==1): l1.append(t) ac+=1 bc+=1 elif(a==1 and b==0): l2.append(t) ac+=1 elif(a==0 and b==1): l3.append(t) bc+=1 if(ac<k or bc<k):...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { int n, k; cin >> n >> k; vector<pair<int, pair<int, int>>> v; for (int i = 0; i < n; i++) { int t, a, b; cin >> t >> a >> b; v.push_back({t, {a, b}}); } vector<int> f; vector<pair<int, pair<int, int>>> l; vector<pair<int, pair<int, i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; import java.awt.*; public class E1 { BufferedReader in; PrintWriter ob; StringTokenizer st; public static void main(String[] args) throws IOException { new E1().run(); } void run() throws IOException { in=new BufferedReader(new InputStream...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
from __future__ import division, print_function def main(): # Template 1.0 import sys, re, math from collections import deque, defaultdict, Counter, OrderedDict from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians, floor from heapq import heappush, heappop, heapify, nlargest, nsmal...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import stdin from collections import deque # https://codeforces.com/contest/1354/status/D mod = 10**9 + 7 import sys import random # sys.setrecursionlimit(10**6) from queue import PriorityQueue from collections import Counter as cc # def rl(): # return [int(w) for w in stdin.readline().split()] from bisect...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.io.PrintWriter; import java.io.BufferedWriter; import java.io.Writer; import java.io.OutputStreamWriter; import java.util.InputMismatchException; import java.io.IOException; import java.util.Col...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time # sys.setrecursionlimit(5*10**5) inf = 10**20 mod = 10**9 + 7 def LI(): return list(map(int, input().split())) def II(): return int(input()) def LS(): return list(input().split()) def S(): return input() def main(): n, k = LI...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
#!/usr/bin/env python import os import sys from io import BytesIO, IOBase from bisect import bisect_left,bisect_right import threading from collections import Counter,defaultdict arr=[] def main(): for _ in range(1): n,k=map(int,input().split()) ar3=[] ar1=[] ar2=[] ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
//============================================================================ /* "There is nothing that can take the pain away. But eventually you will find a way to live with it. There will be nightmares. And every day when you wake up, it will be the first thing you think about. Until one day, it...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.List; import java.util.StringTokenizer; import java.io.IOException; import java.io.BufferedReader; import java.util.Collections; import java.io.InputStreamReader; import java.util.ArrayList;...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
def binary(a,start,end,e): mid=(start+end)//2 if a[mid]==e: return mid elif a[mid]>e: end=mid-1 else: start=mid+1 if start<=end: return binary(a,start,end,e) else: return start n,k=map(int,input().split()) p=[] al=[] bo=[] for j in range(n): a,b,c=map(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.*; import java.io.BufferedReader; import java.io.InputStreamReader; public class First { public static void main(String[] args) { InputStream inputStream = System.in; O...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("02") #pragma G++ optimize("03") using namespace std; const int N = 2e5 + 5; int n, k, type1[N], type2[N], type3[N]; int main() { scanf("%d%d", &n, &k); int cnt1 = 0, cnt2 = 0, cnt3 = 0; for (int i = 1; i <= n; i++) { int val, a, b; scanf("%d%d%d", &val, &a, &...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
# from bisect import bisect_left # TC = int(input()) # for tc in range(TC): N, K = map(int, input().split()) T = [] A = [] B = [] O = [] for b in range(N): v, a, b = map(int, input().split()) if a == 1 and b == 1: T.append(v) elif a == 1: A.append(v) elif b == 1: B.append(v) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = [int(i) for i in input().split()] doub = []; a = []; b = [] for i in range(n): ti, ai, bi = [int(i) for i in input().split()] if ai and bi: doub.append(ti) elif ai: a.append(ti) elif bi: b.append(ti) doub.sort(); a.sort(); b.sort() # print(doub, a, b, sep="\n"...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys n, k = [int(e) for e in input().split(' ')] books = list() books_map = dict() for i in range(n): t, a, b = [int(e) for e in input().split(' ')] books.append((t, a, b, i)) books_map[i] = (t, a, b) books = sorted(books, key = lambda x : x[0] * (1 if x[1] == 1 else 1e7)) alice_pay_time = 0 alice...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
// No sorceries shall prevail. // import java.util.*; import java.io.*; public class InVoker { //Variables static long mod = 1000000007; static long mod2 = 998244353; static FastReader inp= new FastReader(); static PrintWriter out= new PrintWriter(System.out); public static void main(String args[]) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; public class r653p5 { private static PrintWriter pw = new PrintWriter(System.out); private static InputReader sc = new InputReader(); private static final int a = 0, b = 1, ab = 2; static class InputReader{ private static BufferedReader r = new BufferedRea...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split()) l,l1,l2=[],[],[] for i in range(n): t,a,b=map(int,input().split()) if a==1 and b==1: l.append(t) if a==1 and b==0: l1.append(t) if a==0 and b==1: l2.append(t) l1.sort() l2.sort() for i in range(min(len(l1),len(l2))): l.append(l1[i]+l2[i]) l.sort()...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
// package com.company; import java.util.*; import java.lang.*; import java.io.*; //****Use Integer Wrapper Class for Arrays.sort()**** public class DR5 { static PrintWriter out=new PrintWriter(new OutputStreamWriter(System.out)); public static void main(String[] Args)throws Exception{ FastReader scan=n...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys def swap(x, y, a): temp = a[x] a[x] = a[y] a[y] = temp return a def solve(): return None def main(): q = [] for line in sys.stdin.readlines(): q.append(line) for i in range(len(q)): q[i] = q[i].rstrip().split(' ') q[i] = [int(x) for x in q[i]] k = q[0][1] # combining the ones that we ca...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
line = input() n, m, k = [int(i) for i in line.split(' ')] books, allL, aliceL, bobL, other =list(range(1, n + 1)), [], [], [], [] ts = [[] for _ in range(n + 1)] for i in range(n): line = input() t, a, b = [int(j) for j in line.split(' ')] ts[i + 1] = [t, a, b] if a == 1 and b == 1: allL.appen...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = map(int,input().split()) a=[] b=[] c=[] d=[] for i in range(n): x,y,z = map(int,input().split()) if y==0 and z==0: d.append(x) elif y==1 and z==1: a.append(x) elif y==0 and z==1: c.append(x) else: b.append(x) b.sort() c.sort() m=min(len(b),len(c)) for i in range...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
#!/usr/bin/env python # -*- encoding: utf-8 -*- ''' @File : D.py.py @Contact : wangweixu@zuoyebang.com,liuyang05@zuoyebang.com,wangqian03@zuoyebang.com @License : (C)Copyright 2020-2022; All rights reserved. @Modify Time @Author @Version @Desciption ------------ ------- -------- ----...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; using lint = long long int; using pint = pair<int, int>; using plint = pair<lint, lint>; struct fast_ios { fast_ios() { cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); }; } fast_ios_; template <typename T> istream &operator>>(istr...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
# cook your dish here # input = open('file.txt').readline n , k = list(map(int , input().split())) ali = [] bob = [] both = [] ac , bc = 0 , 0 for __ in range(n): t , ai , bi = list(map(int , input().split())) if ai == bi and ai == 1: both.append(t) ac += 1 bc += 1 elif ai == 1: ali.append(t) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) al=[];bob=[];both=[] for i in range(n): a,b,c= map(int, input().split()) if(b==1 and c==1): both.append(a) elif(b==1): al.append(a) elif(c==1): bob.append(a) tp=len(both) la=len(al) ob=len(bob) a=la+tp b=ob+tp if(a<k or b<k): print("-1") else:...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; inline long long gcd(long long a, long long b) { while (b != 0) { long long c = a % b; a = b; b = c; } return a < 0 ? -a : a; } inline long long lowbit(long long x) { return x & (-x); } const double PI = 3.14159265358979323846; const int inf = 0x3f3f3f3f; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct books { int t, i; }; bool cmp(books a, books b) { if (a.t != b.t) return (a.t < b.t); return (a.i < b.i); } int main() { int n, m, o, x, y, i, j, t, s, k, l, p = 0, q, e[200001], f[200001]; books a[200001], b[200001], c[200001], d[200001]; long long ans; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
s=input() s1=s.split() n=int(s1[0]) k=int(s1[1]) import heapq heap1=[] heap2=[] heap3=[] heapq.heapify(heap1) heapq.heapify(heap2) heapq.heapify(heap3) for i in range(n): s=input() s1=s.split() if int(s1[1])==0 and int(s1[2])==1: heapq.heappush(heap1,int(s1[0])) if int(s1[1])==1 and i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
def compute(n, k, arr): add = 0 both = [] alice = [] bob = [] for i in range(n): if arr[i][1] and arr[i][2]: both.append(arr[i][0]) elif arr[i][1]: alice.append(arr[i][0]) elif arr[i][2]: bob.append(arr[i][0]) both.sort()...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
/*input 5 2 6 0 0 9 0 0 1 0 1 2 1 1 5 1 0 */ import java.math.*; import java.io.*; import java.util.*; public class Main { static class Reader { final private int BUFFER_SIZE = 1 << 16; private DataInputStream din; private byte[] buffer; private int bufferPointer, byte...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = map(int,input().split()) aa=[] bb=[] l=[] for _ in range(n): t,a,b=map(int,input().split()) sum1=0 sum2=0 if a&b: l.append(t) elif a==1: aa.append(t) elif b==1: bb.append(t) bb.sort() aa.sort() nn=min(len(aa),len(bb)) for i in range(nn): l.append(bb[i]+aa[i]) if...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
//Problem: Reading Books (easy version) (https://codeforces.com/problemset/problem/1374/E1) //Status: Not accepted import java.util.*; import java.io.*; public class _1374E1 { private static BufferedReader infile = new BufferedReader(new InputStreamReader(System.in)); private static StringTokenizer st; p...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int maxn = 1e6 + 7; long long poww(long long a, long long b, long long mod) { long long ans = 1; while (b) { if (b & 1) ans = (ans * a) % mod; a = (a * a) % mod; b >>= 1; } return ans % mod; } int main() { int n, k; cin >> n >> k; vector<int>...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import stdin from collections import defaultdict as dd from collections import deque as dq import itertools as it from math import sqrt, log, log2 from fractions import Fraction n, k = map(int, input().split()) alike, blike = 0, 0 zero_one, one_zero, one_one, zero_zero = [], [], [], [] for i in range(n): ...