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1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split()) A = [] B = [] AB = [] for i in range(n): t,a,b = map(int,input().split()) if a==1 and b==0: A.append(t) if b==1 and a==0: B.append(t) if a==1 and b==1: AB.append(t) A.sort() B.sort() AB.sort() ia = 0 ib = 0 iab = 0 kab = 0 total_time = 0 while(T...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = map(int,input().split(" ")) both = [] alice = [] bob = [] for i in range(n): t,a,b=map(int,input().split()) if (a == 1 and b == 1): both.append(t) elif (a == 1): alice.append(t) elif (b == 1): bob.append(t) alice.sort(); bob.sort() for i in range(min(len(bob),len(alice))): ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void solve() { long long n, k, ans = 1e10; cin >> n >> k; vector<long long> alice, bob, both, prb, pra, prboth; for (long long i = 1; i <= n; i++) { long long t, a, b; cin >> t >> a >> b; if (a && b) both.push_back(t); else if (a) alice.p...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; public class Main { static Scanner sc = new Scanner(System.in); static PrintWriter out = new PrintWriter(System.out); public static void main(String[] args) throws Exception { int n = sc.nextInt(), k = sc.nextInt(); PriorityQueue<Integer> a, b, c; a = new PriorityQueue<...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
/* ID: tommatt1 LANG: JAVA TASK: */ import java.util.*; import java.io.*; public class cf1374e2{ static PriorityQueue<pair> rem00;static PriorityQueue<pair> rem01;static PriorityQueue<pair> rem10;static PriorityQueue<pair> rem11; static PriorityQueue<pair> add00;static PriorityQueue<pair> add01;static PriorityQueue...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; using ll = long long; signed main() { ios_base::sync_with_stdio(0); cin.tie(0); int n, k; while (cin >> n >> k) { vector<int> both, alice, bob; for (int i = 0; i < n; ++i) { int t, a, b; cin >> t >> a >> b; if (a && b) both.push_bac...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
def answer(): if(n3+n1 < k):return -1 if(n3+n2 < k):return -1 ap=[0] for i in range(n1):ap.append(ap[-1] + a[i]) ap.append(0) bp=[0] for i in range(n2):bp.append(bp[-1] + b[i]) bp.append(0) start=max(max(0,k-n1),max(0,k-n2)) s=0 for i in range(start):s+=common[i] com...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int A[1000000], B[1000000], C[1000000]; int main() { int n, k, t, a, b; cin >> n >> k; int num1 = 0, num2 = 0, num3 = 0; for (int i = 1; i <= n; i++) { cin >> t >> a >> b; if (a == 1 && b != 1) A[++num1] = t; if (a == 0 && b == 1) B[++num2] = t; if (...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) both, a, b = [], [], [] for i in range(n): t, al, bl = map(int, input().split()) if al&bl: both.append(t) elif al: a.append(t) elif bl: b.append(t) a.sort(); b.sort() for i in range(min(len(a), len(b))): both.append(a[i]+b[i]) print(-1 if len(both)<k else sum(sorted(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = map(int,input().split(' ')) x = [40000] y = [40000] z = [40000] c = d = 0 for i in range(n): t,a,b = map(int,input().split(' ')) if (a==1 and b==1): z.append(t) c+=1 d+=1 elif (a==1): x.append(t) c+=1 elif (b==1): y.append(t) d+=1 if (c<k ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
# from math import factorial as fac from collections import defaultdict # from copy import deepcopy import sys, math f = None try: f = open('q1.input', 'r') except IOError: f = sys.stdin if 'xrange' in dir(__builtins__): range = xrange # print(f.readline()) sys.setrecursionlimit(10**2) def print_case_iterable(c...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
import sys if sys.subversion[0] == "PyPy": import io, atexit sys.stdout = io.BytesIO() atexit.register(lambda: sys.__stdout__.write(sys.stdout.getvalue())) sys.stdin = io.BytesIO(sys.stdin.read()) input = lambda: sys.stdin.readline().rstrip() RS = raw_input RI = lambda x=int: map(x,RS().split(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from typing import List from heapq import heappop, heappush # Heap def readingBooks_easy(n: int, k: int, books: List[int]) -> int: books.sort(key = lambda x: x[0]) alice = [] bob = [] alice_and_bob = [] for i in range(len(books)): if (books[i][1] == 1 and books[i][2] == 0): alic...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
#!/bin/python3 import math import os import random import re import sys import heapq n, k = map(int,input().split()) a = [] b = [] ab = [] for _ in range(n): t, av, bv = map(int, input().split()) if av == 1 and bv == 1: #heapq.heappush(ab, t) ab.append(t) elif av == 1: #heapq.heap...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; long long n, k, t, a, b; vector<long long> v, va, vb; int main() { cin >> n >> k; for (long long i = 0; i < n; i++) { cin >> t >> a >> b; if (a == 1 && b == 1) v.push_back(t); else if (a == 1 && b == 0) va.push_back(t); else if (a == 0 && b =...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; public class E { static long m = (long) (1e9 + 7); public static void main(String[] args) throws IOException { Scanner scn = new Scanner(System.in); StringBuilder sb = new StringBuilder(); int n = scn.nextInt(), k = scn.nextInt(); PriorityQueue<Integer> p1 = new Priori...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k1 = map(int,input().split()) A = [] B = [] AB = [] for i in range(n): t,a,b = map(int,input().split()) if a==1 and b==1: AB.append(t) elif a==1: A.append(t) elif b==1: B.append(t) AB.sort() A.sort() B.sort() if len(AB) + len(A) >=k1 and len(AB) + len(B) >=k1: a = 0 ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import heapq n, k = map(int, input().split()) x, y, z = [], [], [] heapq.heapify(x) heapq.heapify(y) heapq.heapify(z) for _ in range(n): t, a, b = map(int, input().split()) if a == b == 1: heapq.heappush(x, t) elif a == 1: heapq.heappush(y, t) elif b == 1: heapq.heappush(z, t) lx...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const long long MOD = 1e9 + 7; const long long INF = 1e9 + 9; const int MAX = 100; int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); cout.precision(10); cout << fixed; long long t = 1; while (t--) { long long n, k; cin >> n >> k; ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int maxn = 2e5 + 100; const int inf = 1e9 + 7; const long long mod = 1e9 + 7; int a[maxn]; int b[maxn]; int t[maxn]; vector<int> both; vector<int> alice; vector<int> bob; int psum_alice[maxn]; int psum_bob[maxn]; int psum_both[maxn]; int main() { ios_base::sync_with...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
// package Round_653; import java.io.*; import java.math.*; import java.util.*; public class Problem_E1 { public static void main(String[] args) { FastReader in = new FastReader(); PrintWriter out = new PrintWriter(System.out); int numBooks = in.nextInt(), minLike = in.nextInt()...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.util.*; import java.io.*; import java.lang.Math; import java.util.Random; public class Solution{ public static void main(String[] args) throws Exception{ FastScanner fs = new FastScanner(); int n = fs.nextInt(), k = fs.nextInt(); ArrayList<Book> listA = new ArrayList<Book>(n); ArrayList<B...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int s[200000], m[200000], n[200000]; int main() { long long ans = 0; int f, k, t[200000], a[200000], b[200000], i, count = 0; int g = 0, h = 0; cin >> f >> k; for (i = 0; i < f; i++) { cin >> t[i] >> a[i] >> b[i]; if (a[i] == 1 && b[i] == 1) { s[coun...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
#: Author - Soumya Saurav import sys,io,os,time from collections import defaultdict from collections import OrderedDict from collections import deque from itertools import combinations from itertools import permutations import bisect,math,heapq alphabet = "abcdefghijklmnopqrstuvwxyz" input = sys.stdin.readline ######...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int32_t main() { ios::sync_with_stdio(false); cin.tie(nullptr); long long t = 1; while (t--) { long long n, k; ; cin >> n >> k; multiset<long long> alice, bob, both; for (long long i = 0; i < n; i++) { long long ti, ai, bi; cin >> ti ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) x, y, z = [], [], [] for _ in range(n): t, a, b = map(int, input().split()) if a == b == 1: x.append(t) elif a == 1: y.append(t) elif b == 1: z.append(t) lx, ly, lz = len(x), len(y), len(z) x.sort() y.sort() z.sort() u, v = len(x), min(len(y), len...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
# Enter your code here. Read input from STDIN. Print output to STDOUT def find(books,k): both = [] A = [] B = [] # both + (k-both) + (k-both) for (t,a,b) in books: if a == 1 and b == 1: both += [t] elif a == 1: A += [t] elif b == 1: B += [t...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) a = [] b = [] ab = [] ans = 0 for _ in range(n): t1, a1, b1 = map(int, input().split()) if a1==1 and b1==1: ab.append(t1) elif a1==1 and b1==0: a.append(t1) elif a1==0 and b1==1: b.append(t1) else: pass a.sort() b.sort() ab.sort() ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; vector<pair<long long, long long> > al, bob, both, v, ansb, alr, bobr, norr, vc, neither; set<long long> ans; int vis[200005], l1[200005], l2[200005]; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); long long a = 0, b = 0, c, d, e, ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys s = sys.stdin.readline().split() n, m, k = int(s[0]), int(s[1]), int(s[2]) all = [] All = [] Alice = [] Bob = [] Both = [] none = [] z = 1 while n: i = sys.stdin.readline().split() x = 3 i.append(z) while x: i[x-1] = int(i[x - 1]) x -= 1 all.append(i) if i[1] == i[2]...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int N = 200005; struct P { int t, a, b; }; vector<P> A, B, C; int sa[N], sb[N], sc[N]; bool cmp(P a, P b) { return a.t < b.t; } int main() { int n, k; P t; scanf("%d%d", &n, &k); for (int i = 1; i <= n; ++i) { scanf("%d%d%d", &t.t, &t.a, &t.b); if (t...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
import sys class segtree: def __init__(self, data): n = len(data) self.m = 1 while self.m < n: self.m *= 2 self.data = [0] * (2 * self.m) self.data[self.m: self.m + n] = data for i in reversed(range(1, self.m)): self.data[i] = self.data[2 * i] + self.da...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) a = [] b = [] both = [] for i in range(n): t, x, y = map(int, input().split()) if x == 1 and y == 1: both.append(t) elif x == 1: a.append(t) elif y == 1: b.append(t) a.sort() b.sort() both.sort() x = len(a) if len(b)<len(a): x = len(b) if x >...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from heapq import * import sys int1 = lambda x: int(x) - 1 p2D = lambda x: print(*x, sep="\n") def II(): return int(sys.stdin.readline()) def MI(): return map(int, sys.stdin.readline().split()) def LI(): return list(map(int, sys.stdin.readline().split())) def LLI(rows_number): return [LI() for _ in range(rows_number)]...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
""" Code of Ayush Tiwari Codeforces: servermonk Codechef: ayush572000 """ import sys input = sys.stdin.buffer.readline def solution(): a=[] b=[] c=[] n,k=map(int,input().split()) for i in range(n): t,x,y=map(int,input().split()) if x==1 and y==1: c.append(t) eli...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split()) both=[] alice=[] bob=[] none=[] for i in range(n): t,a,b=map(int,input().split()) if a==1 and b==1: both.append(t) elif a==1: alice.append(t) elif b==1: bob.append(t) else: none.append(t) flag=0 both.sort() alice.sort() bob.sort() if len(b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int N = 1e3 + 5; struct st { int t, a, b; }; deque<st> v, al, bo, ne; int n, k; st st1; bool cmp(st stx, st sty) { if (stx.a + stx.b > sty.a + sty.b) return 1; else if (stx.a + stx.b < sty.a + sty.b) return 0; else return (stx.t < sty.t); } int mai...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.util.*; public class Question5Alternative { static Scanner sc = new Scanner(System.in); public static void main(String[] args) { int n = sc.nextInt(); int k = sc.nextInt(); ArrayList<Integer> list[] = new ArrayList[4]; for(int i = 0;i < 4;i++)list[i] = new ArrayList<Integer>(); for(int...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
import collections def f(s,k): both = [] alice = [] bob = [] for ti,ai,bi in s: if ai == 1 and bi == 1: both.append(ti) elif ai == 1 and bi == 0: alice.append(ti) elif ai == 0 and bi == 1: bob.append(ti) alice.sort() bob.sort() both.sort() for i in range(1,len(both)): both[i] += both[i-1] for i in rang...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
#q=int(input()) q=1 for Q in range(q): n,k=map(int,input().split()) c01=[] c10=[] c11=[] for i in range(n): t,a,b=map(int,input().split()) if(a==1 and b==0): c10.append(t) if(a==0 and b==1): c01.append(t) if(a==1 and b==1): c11.appe...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys def cta(t, p, r): global ana, iva, an ana[iva[t][p][1]] ^= True an += iva[t][p][0] * r s = sys.stdin.readline().split() n, m, k = int(s[0]), int(s[1]), int(s[2]) if k != 10220 and m != 164121: all = [] All = [] Alice = [] Bob = [] Both = [] none = [] z = 1 whi...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import stdout,stdin input=stdin.buffer.readline n,k = map(int,input().split()) alice = [0] bob = [0] common = [0] la = 1 lb = 1 lc = 1 for i in range(n): t,a,b = map(int,input().split()) if a==1 and b==1: common.append(t) lc+=1 elif a==1: alice.append(t) la+=1 ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n , k = input().split() n = int(n) k = int(k) c = [] a = [] b = [] for i in range(n): t,al,bo = input().split() if(al == '1' and bo == '1'): c.append(int(t)) elif(al == '1'): a.append(int(t)) elif(bo == '1'): b.append(int(t)) if(len(c)+len(a) < k or len(c)+len(b) < k): print(-1) quit() c.sort() a.sort() b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
#Code by Sounak, IIESTS #------------------------------warmup---------------------------- import os import sys import math from io import BytesIO, IOBase from fractions import Fraction from collections import defaultdict BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = [int(x) for x in input().split()] bookA = [] bookB = [] bookC = [] for i in range(n): a,b,c = [int(x) for x in input().split()] if b == c == 1: bookC.append((a,b,c)) if b == 1 != c: bookA.append((a,b,c)) if c == 1 != b: bookB.append((a,b,c)) bookA.sort(key = lambda x : x[0...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int inf = 0x3f3f3f3f; const long long INF = 0x3f3f3f3f3f3f3f3fll; const int N = 1e4 + 10; const int M = 3e6 + 10; const int maxn = 1e6 + 10; const int mod = 1000173169; const double eps = 1e-10; const double pi = acos(-1.0); struct Tree { int num[N << 2], sum[N << 2...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = map(int, input().split()) alice = list() bob = list() common = list() for _ in range (n): t,a,b = map(int, input().split()) if a == 1 and b == 1: common.append (t) elif a == 1: alice.append (t) elif b == 1: bob.append (t) if len(common) + len(alice) < k: ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
FAST_IO = 1 if FAST_IO: import io, sys, atexit rr = iter(sys.stdin.read().splitlines()).next sys.stdout = _OUTPUT_BUFFER = io.BytesIO() @atexit.register def write(): sys.__stdout__.write(_OUTPUT_BUFFER.getvalue()) else: rr = raw_input rri = lambda: int(rr()) rrm = lambda: map(int, rr()....
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> #pragma GCC optimize("Ofast") #pragma GCC target("avx,avx2,fma") #pragma GCC optimization("unroll-loops") using namespace std; long long dx[] = {1, 0, -1, 0}; long long dy[] = {0, 1, 0, -1}; void __print(long x) { cerr << x; } void __print(long long x) { cerr << x; } void __print(unsigned x) { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; public class E1 { public static void main(String[] args) throws Exception{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); StringBuffer sb = new StringBuffer(""); String[] str; int n, k; str = br.readLine().split(" "); n = Integer.parseInt(s...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int INF = 2e9 + 1; int n, m, k, p1, p2, sum = 0, sumSmall = 0, minVal = INF; pair<int, int> rs; vector<pair<int, int> > a[2][2]; set<pair<int, int> > small, large; void updateSmall(pair<int, int> val, int type) { if (type == 0) { small.insert(val); sumSmall ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys input = sys.stdin.readline def main(): n, k = map(int, input().split()) a = [] b = [] whole = [] for _ in range(n): t, x, y = map(int, input().split()) if x + y == 2: whole.append(t) elif x + y == 1: if x: a.append(t) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; import java.math.*; public class E1 { static final boolean RUN_TIMING = false; static char[] inputBuffer = new char[1 << 20]; static PushbackReader in = new PushbackReader(new BufferedReader(new InputStreamReader(System.in)), 1 << 20); static PrintWriter out = new ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import stdin inp = lambda : stdin.readline().strip() n, k = [int(x) for x in inp().split()] b = [] for _ in range(n): b.append([int(x) for x in inp().split()]) both = [] alice = [] bob = [] for i in b: if i[1] == 1 and i[2] == 1: both.append(i[:]) elif i[1] == 1: alice.append(i[:...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys input = sys.stdin.readline n, k = map(int, input().split()) a, b, ab = [], [], [] prea, preb, preab = [0], [0], [0] ans = [] for _ in range(n): t1, t2, t3 = map(int, input().split()) if t2 == t3 == 1: ab.append(t1) elif t2 == 1: a.append(t1) elif t3 == 1: b.append(t...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) alice = [] bob = [] both = [] for i in range(n): t, a, b = map(int, input().split()) if a == b == 0: continue if a == b == 1: both.append(t) elif a == 1 and b == 0: alice.append(t) elif a == 0 and b == 1: bob.append(t) alice.sort() bob.sort() for i in range(min(len(a...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.IOException; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.HashSet; import java.util.Scanner; public class D { static int mod = (int) 1e9 + 7; static ArrayList<Integer> gr[]; static int ar[]; static Scanner sc = new Scanner(System.in); static ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
def reading(numb,mass,c1,c2): if c1<numb or c2<numb : return -1 true_mass1=[] true_mass2=[] true_mass3=[] for i in mass: if i[1]!=0 or i[2]!=0: if i[1]==0: true_mass1.append(i) elif i[2]==0: true_mass2.append(i) else...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void solve() { int n, k; cin >> n >> k; priority_queue<pair<int, int>, vector<pair<int, int> >, greater<pair<int, int> > > pq; vector<int> t(n), a(n), b(n); int cnt1 = 0, cnt2 = 0; int cnt3 = 0; priority_queue<int, vector<int>, greater<i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = [int(x) for x in input().split()] res = 0 pick =0 both = [] alice = [] bob = [] for i in range(n): t,a,b=[int(x) for x in input().split()] if a == 1 and b ==1: both.append(t) elif a == 1 and b == 0: alice.append(t) elif a == 0 and b == 1: bob.append(t) alice.sort() bob....
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct cmp { bool operator()(const long long &a, const long long &b) { return a >= b; } }; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); long long n, k; cin >> n >> k; long long first = 0, second = 0, ans = 0; long long temp1 = 0, temp2 = 0, te...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
# not necessary to use a heap but hey why not, I needed a refresher from heapq import * n, k = [int(x) for x in input().split()] alice = [] bob = [] both = [] for _ in range(n): t, a, b = [int(x) for x in input().split()] if a and b: heappush(both, t) elif a: heappush(alice, t) elif b: heappush(bob, t) while ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import stdin n,k = list(map(int, stdin.readline().strip().split(' '))) AB = [] A = [] B = [] for i in range(n): t,a,b = list(map(int, stdin.readline().strip().split(' '))) if a == 1 and b == 1: AB.append(t) elif a == 1: A.append(t) elif b == 1: B.append(t) AB.sort() ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.HashMap; import java.util.HashSet; import java.util.LinkedList; import java.util.Queue; import java...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
k, n = [int(i) for i in input().split()] a = [] b = [] both = [] for _ in range(k): t,x,y = [int(i) for i in input().split()] if(x == 1 and y == 1): both.append(t) elif x == 1: a.append(t) elif y == 1: b.append(t) a.sort() b.sort() both.sort() # print(a,b,both) if len(a) + len(both) < n or len(b) + len(b...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.*; import java.util.*; // Author : Yash Shah public class D implements Runnable { public void run() { InputReader sc = new InputReader(System.in); PrintWriter out = new PrintWriter(System.out); int n=sc.nextInt(); int k=sc.nextInt(); ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Collections; import java.util.HashMap; import java.util.Stack; public class _653 { static Reader r = new Reader(); static PrintWriter out = new PrintW...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int mod = 1000000007; const int inf = 1034567891; const long long LL_INF = 1234567890123456789ll; template <typename Arg1> void __f(const char* name, Arg1&& arg1) { cout << name << " : " << arg1 << '\n'; } template <typename Arg1, typename... Args> void __f(const char* na...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import bisect def inp(): return(int(input())) def inlt(): return(list(map(int,input().split()))) def insr(): s = input() return(list(s[:len(s) ])) def invr(): return(map(int,input().split())) l = inlt() n = l[0] k = l[1] alice = [] bob = [] good = [] for i in range(n): l = inlt() if(l...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int n, k; cin >> n >> k; vector<vector<long long>> b(4, vector<long long>(1, 0LL)); for (int i = 0; i < n; i++) { long long t, x, y; cin >> t >> x >> y; b[x * 2 + y].push...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.ByteArrayInputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Arrays; import java.util.InputMismatchException; import java.util.List; import java.util.PriorityQueue; public class Main { private static final String...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split()) time=[] a=[] b=[] count_a=0 count_b=0 for i in range(n): t,a1,b1=map(int,input().split()) time.append(t) a.append(a1) b.append(b1) if a1==1: count_a+=1 if b1==1: count_b+=1 #print(count_a,count_b) if count_a<k or count_b<k: print(-1) ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
line = input() n, k = [int(i) for i in line.split(' ')] allL, aliceL, bobL = [], [], [] for i in range(n): line = input() t, a, b = [int(j) for j in line.split(' ')] if a == 1 and b == 1: allL.append(t) elif a == 1: aliceL.append(t) elif b == 1: bobL.append(t) allL.sort() ali...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
#!/usr/bin/env python3 import io import os input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline def get_str(): return input().decode().strip() def rint(): return map(int, input().split()) def oint(): return int(input()) n, k = rint() tab = [] for i in range(n): tab.append(tuple(rint())) tab....
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys from collections import defaultdict as dd from collections import Counter as cc from queue import Queue import math import itertools try: sys.stdin = open('input.txt', 'r') sys.stdout = open('output.txt', 'w') except: pass input = lambda: sys.stdin.buffer.readline().rstrip() q,w=map(int,inpu...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys input = sys.stdin.readline def main(): n, k = map(int, input().split()) a_s = [] b_s = [] ab_s = [] for _ in range(n): t, a, b = map(int, input().split()) if a == b == 1: ab_s.append(t) elif a == 1: a_s.append(t) elif b == 1: ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split()) L1=[] L2=[] L3=[] for i in range(n): t, a, b = map(int, input().split()) if a==1 and b==1: L1.append(t) elif a==1 and b==0: L2.append(t) elif a==0 and b==1: L3.append(t) L3.sort() L2.sort() for i in range(min(len(L2), len(L3))): L1.append(L2[i]+L3[i]) if k<=le...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct book { int val; int index; }; int n, m, k, tim, minTim = 2000000001; int minIndexVal, xIndex[5]; vector<book> x[4]; int xS[5]; vector<int> books; int currNum[4], minNum[4]; bool compareVal(book p1, book p2) { return p1.val < p2.val; } int sizeOfCurrBooks() { in...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
book_number, like_num = map(int, input().split()) both_like = [] only_alice = [] only_bob = [] for _ in range(book_number): t, a, b = map(int, input().split()) if a == b == 1: both_like.append(t) elif a == 1: only_alice.append(t) elif b == 1: only_bob.append(t) i, j = 0, 0 time...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> const int factor_N = 10000005; using namespace std; int read() { char c = getchar(); int x = 0, f = 1; for (; !isdigit(c); c = getchar()) if (c == '-') f = -1; for (; isdigit(c); c = getchar()) x = x * 10 + c - 48; return x * f; } struct Node { int t, a, b; }; const int N = 2e5 ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import time,math,bisect,sys from sys import stdin,stdout from collections import deque from fractions import Fraction from collections import Counter from collections import OrderedDict pi=3.14159265358979323846264338327950 def II(): # to take integer input return int(stdin.readline()) def IO(): # to take string in...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.util.*; import java.io.*; public class TestClass { public static void main(String args[]) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); //for(int cases = 0; cases<c; cases++){ StringTokenizer st1 = new StringTokenizer(br.readLine()); int n = In...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
def cta(t,p,r): global ana,iva,an ana[iva[t][p][1]]^=True an+=iva[t][p][0]*r n,k=[int(x) for x in input().split()] iva=[[] for _ in range(4)] js=[() for _ in range(n)] for i in range(n): v,o,u=[int(x) for x in input().split()] q=(o<<1)|u iva[q].append((v,i)) js[i]=(v,q) for e in iva : e.sort() ct,a,r,ps,an = ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; struct node { int a, b, t; int index; node() {} node(int _a, int _b, int _t, int _index) { a = _a; b = _b; t = _t; index = _index; } bool operator<(const struct node &nd) const { return t < nd.t; } bool operator>(const struct node &nd) const { ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.util.ArrayList; import java.util.Collections; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(),k=sc.nextInt(); ArrayList<Integer> alice=new ArrayList<>(); ArrayList<Integer> bo...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int main() { long long n, k; cin >> n >> k; vector<long long int> a, b, c; for (int i = 0; i < n; i++) { int t, x, y; cin >> t >> x >> y; if (x && y) c.push_back(t); else if (x && !y) a.push_back(t); else if (!x && y) b.push_bac...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n, k = map(int, input().split()) times = [[], [], [], []] for i in range(n): t, a, b = map(int, input().split()) times[a * 2 + b].append(t) for i in range(1, 4): times[i].sort() sums = [] for i in range(len(times)): sums.append([]) for j in range(len(times[i])): if j == 0: sums[i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python2
input = raw_input range = xrange import sys inp = [int(x) for x in sys.stdin.read().split()]; ii = 0 seg = [0]*200000 def offset(x): return x + 100000 def encode(x, y): return x*200002 + y def decode(x): return x//200002, x%200002 def upd(node, L, R, pos, val): while L < R: seg[node] += val seg[offset(node)]...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.util.ArrayDeque; import java.util.Arrays; import java.util.Deque; import java.util.Scanner; public class E { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(), k = sc.nextInt(); Books[] books = new Books[n]; for (int i = 0; i < n; i++) { books[i...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=list(map(int,input().split())) l,l1,l2=[],[],[] for _ in range(n): x,y,z=list(map(int,input().split())) if y==1 and z==1: l.append(x) elif y==1: l1.append([x,y,z]) elif z==1: l2.append([x,y,z]) l1.sort() l2.sort() for i in range(min(k,len(l1),len(l2))): a=l1[i][0] b=...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k=map(int,input().split(" ")) both=[] bob=[] alice=[] for i in range(n): t,a,b=map(int,input().split(" ")) if a==1 and b==1: both.append(t) elif a==1: alice.append(t) elif b==1: bob.append(t) if len(both)!=0: both.sort() if len(alice)!=0: alice.sort() if len(bob)...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
from sys import maxsize n, k = map(int, input().split()) l = [[0], [0], [0], [0]] x = [] ans = maxsize for i in range(n): x.append(list(map(int, input().split()))) x.sort() for p in x: temp = l[p[1]*2 + p[2]][-1] l[p[1]*2 + p[2]].append(temp + p[0]) for i in range(min(k + 1, len(l[3]))): if k - i < len(...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
java
import java.io.BufferedReader; import java.io.FileNotFoundException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Collections; import java.util.StringTokenizer; public class e653_1 { static PrintWriter out; static BufferedReader in; static Strin...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; void quick_sort(int a[], int left, int right) { int l = left, r = right, m = a[rand() % (r - l) + l]; while (l < r) { while (a[l] < m) l++; while (a[r] > m) r--; if (l <= r) { int t = a[l]; a[l] = a[r]; a[r] = t; l++; r--; }...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; int32_t main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); ; long long n, k; cin >> n >> k; vector<long long> alice; vector<long long> bob; vector<long long> combined; long long atotal = 0, btotal = 0; for (long long i = 0; i < n; ++i) { lo...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
n,k = map(int,input().split()) U = [];A = [];B = [] for i in range(n): a,b,c = map(int,input().split()) if(b==1 and c==1): U.append(a) elif(b==1 and c==0): A.append(a) elif(b==0 and c==1): B.append(a) A.sort();B.sort();U.sort() for i in range(1,len(U)): U[i]+=U[i-1] for i in ...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import os,io input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline n,k = map(int,input().split()) bookA = [] bookB = [] bookAB = [] for _ in range(n): t,a,b = map(int,input().split()) if a == 1 and b == 1: bookAB.append(t) elif a == 1: bookA.append(t) elif b == 1: bookB.appe...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import sys # from collections import defaultdict # t=1 # t=int(input()) def fun(x): # print(x) return x[0] n,k=list(map(int,sys.stdin.readline().strip().split())) xx=[] a=[] b=[] c=[] for i in range(n): # n=int(input()) x=list(map(int,sys.stdin.readline().strip().split())) # a,b,c,d=list(sys.std...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
cpp
#include <bits/stdc++.h> using namespace std; const int N = 5e5 + 99; int n, k, m, x, y, p0, p1, p2, b0, b1, b2, b3, a[N]; vector<pair<long long, int> > v0, v1, v2, v3; long long ans = 1e18, sum; void calc(int x) { if (p0 < v0.size() - 1) p0++, sum += v0[p0].first; if (p0 < v0.size() - 1) p0++, sum += v0[p0].first;...
1374_E1. Reading Books (easy version)
Easy and hard versions are actually different problems, so read statements of both problems completely and carefully. Summer vacation has started so Alice and Bob want to play and joy, but... Their mom doesn't think so. She says that they have to read some amount of books before all entertainments. Alice and Bob will ...
{ "input": [ "8 4\n7 1 1\n2 1 1\n4 0 1\n8 1 1\n1 0 1\n1 1 1\n1 0 1\n3 0 0\n", "5 2\n6 0 0\n9 0 0\n1 0 1\n2 1 1\n5 1 0\n", "5 3\n3 0 0\n2 1 0\n3 1 0\n5 0 1\n3 0 1\n" ], "output": [ "18\n", "8\n", "-1\n" ] }
{ "input": [ "2 1\n7 1 1\n2 1 1\n", "5 1\n2 1 0\n2 0 1\n1 0 1\n1 1 0\n1 0 1\n", "6 2\n6 0 0\n11 1 0\n9 0 1\n21 1 1\n10 1 0\n8 0 1\n", "3 1\n3 0 1\n3 1 0\n3 0 0\n", "6 3\n7 1 1\n8 0 0\n9 1 1\n6 1 0\n10 1 1\n5 0 0\n", "8 4 3\n1 1 1\n3 1 1\n12 1 1\n12 1 1\n4 0 0\n4 0 0\n5 1 0\n5 0 1\n", "6 3 ...
CORRECT
python3
import collections as cc import math as mt import sys input=sys.stdin.readline I=lambda:list(map(int,input().split())) n,k=I() a=[] for i in range(n): a.append(I()) a.sort() both=[] bs=0 f=0 for i in range(n): if a[i][1] and a[i][2]: both.append(a[i][0]) al=[] bo=[] for i in range(n): if a[i][1] and not a[i][2]:...