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Now that your model has finished training it is time to test it out! You can do so by running the next cell.
new_x = 7.0 prediction = model.predict([new_x])[0]*100. print(50+7*50) print(prediction)
400 [400.1458]
MIT
Tensorflow/Courses/0_Intro_to_tf/2_Week1_Assignmen_normalized.ipynb
maxtcurie/Artificial_Intelligence
Handwritten Number Recognition with TFLearn and MNISTIn this notebook, we'll be building a neural network that recognizes handwritten numbers 0-9. This kind of neural network is used in a variety of real-world applications including: recognizing phone numbers and sorting postal mail by address. To build the network, w...
# Import Numpy, TensorFlow, TFLearn, and MNIST data import numpy as np import tensorflow as tf import tflearn import tflearn.datasets.mnist as mnist
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MIT
intro-to-tflearn/TFLearn_Digit_Recognition.ipynb
tanmaysinha987/deep-Learning
Retrieving training and test dataThe MNIST data set already contains both training and test data. There are 55,000 data points of training data, and 10,000 points of test data.Each MNIST data point has:1. an image of a handwritten digit and 2. a corresponding label (a number 0-9 that identifies the image)We'll call th...
# Retrieve the training and test data trainX, trainY, testX, testY = mnist.load_data(one_hot=True)
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MIT
intro-to-tflearn/TFLearn_Digit_Recognition.ipynb
tanmaysinha987/deep-Learning
Visualize the training dataProvided below is a function that will help you visualize the MNIST data. By passing in the index of a training example, the function `show_digit` will display that training image along with it's corresponding label in the title.
# Visualizing the data import matplotlib.pyplot as plt %matplotlib inline # Function for displaying a training image by it's index in the MNIST set def show_digit(index): label = trainY[index].argmax(axis=0) # Reshape 784 array into 28x28 image image = trainX[index].reshape([28,28]) plt.title('Training...
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MIT
intro-to-tflearn/TFLearn_Digit_Recognition.ipynb
tanmaysinha987/deep-Learning
Building the networkTFLearn lets you build the network by defining the layers in that network. For this example, you'll define:1. The input layer, which tells the network the number of inputs it should expect for each piece of MNIST data. 2. Hidden layers, which recognize patterns in data and connect the input to the ...
# Define the neural network def build_model(): # This resets all parameters and variables, leave this here tf.reset_default_graph() #### Your code #### # Include the input layer, hidden layer(s), and set how you want to train the model net=tflearn.input_data(None,trainX.shape[1]) net=tflear...
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MIT
intro-to-tflearn/TFLearn_Digit_Recognition.ipynb
tanmaysinha987/deep-Learning
Training the networkNow that we've constructed the network, saved as the variable `model`, we can fit it to the data. Here we use the `model.fit` method. You pass in the training features `trainX` and the training targets `trainY`. Below I set `validation_set=0.1` which reserves 10% of the data set as the validation s...
# Training model.fit(trainX, trainY, validation_set=0.1, show_metric=True, batch_size=100, n_epoch=20)
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MIT
intro-to-tflearn/TFLearn_Digit_Recognition.ipynb
tanmaysinha987/deep-Learning
TestingAfter you're satisified with the training output and accuracy, you can then run the network on the **test data set** to measure it's performance! Remember, only do this after you've done the training and are satisfied with the results.A good result will be **higher than 95% accuracy**. Some simple models have b...
# Compare the labels that our model predicts with the actual labels # Find the indices of the most confident prediction for each item. That tells us the predicted digit for that sample. predictions = np.array(model.predict(testX)).argmax(axis=1) # Calculate the accuracy, which is the percentage of times the predicate...
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MIT
intro-to-tflearn/TFLearn_Digit_Recognition.ipynb
tanmaysinha987/deep-Learning
Pandas
import numpy as np import pandas as pd
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MIT
docs/Pandas.ipynb
hotbaby/mmn
Pandas提供了3种数据类型,分别是`Series`、`DataFrame`和`Panel`。* `Series`用于保存一维数据* `DataFrame` 用于保存二维数据* `Panel`用于保存三维或者可变维数据 Series数据结构 `Series`本质上是一个带索引的一维数组。 指定索引:
s = pd.Series([1,3,2,4], index=['a', 'b', 'c', 'd']) s.index s.values
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MIT
docs/Pandas.ipynb
hotbaby/mmn
默认索引:
s = pd.Series([1, 3, 2, 4]) s.index s.values
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MIT
docs/Pandas.ipynb
hotbaby/mmn
DataFrame数据结构 创建DataFrame
df = pd.DataFrame({'x': ['a', 'b', 'c'], 'y': range(1, 4), 'z': [2, 5, 3]}) df df.columns df.values
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MIT
docs/Pandas.ipynb
hotbaby/mmn
查看数据内容 * `df.info()` 查看DataFrame属性信息* `df.head()` 查看DataFrame前五行数据信息* `df.tail()` 查看DataFrame后五行数据信息 选取多列 * df.loc* df.iloc
df[['x', 'y']] df.loc[:, ['x', 'y']] df.iloc[:, [0, 1]]
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MIT
docs/Pandas.ipynb
hotbaby/mmn
单行过滤
df[df.z>=3]
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MIT
docs/Pandas.ipynb
hotbaby/mmn
重新定义列名
df.rename(columns={'x': 'X'}, inplace=True) df df.columns = ['X', 'Y', 'Z'] df
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MIT
docs/Pandas.ipynb
hotbaby/mmn
数据的多重索引
df = pd.DataFrame({ 'X': list('ABCABC'), 'year': [2010] * 3 + [2011] * 3, 'Value': [1, 3, 4, 3, 5, 2] }) df df.set_index(['X', 'year'])
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MIT
docs/Pandas.ipynb
hotbaby/mmn
表格的变换
df = pd.DataFrame({ 'X': list('ABC'), '2010': [1, 3, 4], '2011': [3, 5, 2] }) df df_melt = pd.melt(df, id_vars='X', var_name='year', value_name='value') df_melt
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MIT
docs/Pandas.ipynb
hotbaby/mmn
* `id.vars('X')`表示由标识变量构成的向量,用于标识观测的变量* `variable_name('year')`表示用于保存原始变量名的变量名称* `value.name('value')`表示用于保存原始值的名称
df_pivot = df_melt.pivot_table(index='X', columns='year', values='value') df_pivot.reset_index(inplace=True) df_pivot
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MIT
docs/Pandas.ipynb
hotbaby/mmn
变量的变换 * `apply`的操作对象是`DataFrame`的某一列(`axis`=0)或者某一列(`axis`=1)* `applymap`的操作对象是元素级,作用于每个`DataFrame`的每个数据 表格的排序 `df.sort_values(by, ascending=True)`
df df.sort_values('2010', ascending=False) df.sort_values('2011', ascending=True) df.sort_values(by=['X', '2010'], ascending=False)
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MIT
docs/Pandas.ipynb
hotbaby/mmn
表格拼接
df1 = pd.DataFrame({ 'x': ['a', 'b', 'c'], 'y': range(1, 4), }) df2 = pd.DataFrame({ 'z': ['B', 'D', 'H'], 'g': [2, 5, 3] }) df3 = pd.DataFrame({ 'x': ['g', 'd'], 'y': [2, 5] })
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MIT
docs/Pandas.ipynb
hotbaby/mmn
横轴方向连接
pd.concat([df1, df2], axis=1)
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MIT
docs/Pandas.ipynb
hotbaby/mmn
纵轴方向连接
pd.concat([df1, df3], axis=0).reset_index()
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MIT
docs/Pandas.ipynb
hotbaby/mmn
表的融合
df1 = pd.DataFrame({ 'x': list('abc'), 'y': range(1, 4) }) df2 = pd.DataFrame({ 'x': list('abd'), 'z': [2, 5, 3] }) df3 = pd.DataFrame({ 'g': list('abd'), 'z': [2, 5, 3] }) df1 df2 df3
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MIT
docs/Pandas.ipynb
hotbaby/mmn
只保留左表的所有数据
pd.merge(df1, df2, how='left', on='x')
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MIT
docs/Pandas.ipynb
hotbaby/mmn
只保留右表的数据
pd.merge(df1, df2, how='right', on='x')
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MIT
docs/Pandas.ipynb
hotbaby/mmn
保留两个表中公共的部分信息
pd.merge(df1, df2, how='inner', on='x')
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MIT
docs/Pandas.ipynb
hotbaby/mmn
保留两个表的所有信息
pd.merge(df1, df2, how='outer', on='x')
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MIT
docs/Pandas.ipynb
hotbaby/mmn
表格分组操作
df = pd.DataFrame({ 'X': list('ABC'), '2010': [1, 3, 4], '2011': [3, 5, 2] }) df
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MIT
docs/Pandas.ipynb
hotbaby/mmn
按行或列操作 按行求和
df[['2010', '2011']].apply(lambda x: x.sum(), axis=1)
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MIT
docs/Pandas.ipynb
hotbaby/mmn
按列求和
df[['2010', '2011']].apply(lambda x: x.sum(), axis=0)
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MIT
docs/Pandas.ipynb
hotbaby/mmn
多列运算
df['2010_2011'] = df[['2010', '2011']].apply(lambda x: x['2010'] + 2 * x['2011'], axis=1) df
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MIT
docs/Pandas.ipynb
hotbaby/mmn
分组操作
df = pd.DataFrame({ 'X': list('ABC'), '2010': [1, 3, 4], '2011': [3, 5, 2] }) df_melt = pd.melt(df, id_vars=['X'], var_name='year', value_name='value') df_melt
_____no_output_____
MIT
docs/Pandas.ipynb
hotbaby/mmn
按`year`分组求均值
df_melt.groupby('year').mean()
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MIT
docs/Pandas.ipynb
hotbaby/mmn
按`year`和`x`两列分组求均值
df_melt.groupby(['year', 'X']).mean() df_melt.groupby(['year', 'X'], as_index=False).mean()
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MIT
docs/Pandas.ipynb
hotbaby/mmn
分组聚合
df_melt.groupby(['X', 'year']).aggregate([np.mean, np.median])
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MIT
docs/Pandas.ipynb
hotbaby/mmn
分组运算:`transform()`函数
df_melt['percentage'] = df_melt.groupby('X')['value'].transform(lambda x: x/s.sum()) df_melt
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MIT
docs/Pandas.ipynb
hotbaby/mmn
分组筛选:`filter()`函数
df_melt.groupby('X').filter(lambda x: x['value'].mean()>2)
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MIT
docs/Pandas.ipynb
hotbaby/mmn
Toy Datasets
# For Base cohort age = 45 lab1 = 3.4 lab2 = 5000 pcond1 = 0.3 pcat1 = 0.5 mean = [age, lab1, lab2] cov = [[14, 3, 100], [3, 2, 50], [100, 50, 25000]] np.random.seed(42) x = np.random.multivariate_normal(mean, cov, config['nbase']) x[x< 0] = 0 lab3 = np.random.beta(1, 2, size=config['nbase']) x = np....
Distribution of age Before balancing -1.2072887363365403 After balancing -0.18460449201331947 Distribution of lab1 Before balancing -1.127079119575515 After balancing -0.1807599351241777 Distribution of lab2 Before balancing 0.8934273136316265 After balancing 0.31464657671400276 Distribution of lab3 Before balanc...
MIT
cohortbalancer-function.ipynb
csrinesh/balance_cohort
Índice 1 - Análise de Sentimentos: uma introdução 2 - Carregando os pacotes necessários 3 - Conectando com a API do Twitter 3.1 - Autenticação 3.2 - Obtendo os tweets 4 - Text Mining 5 - Manipulação de dados 5.1 - Tokenização 5.2 - Núvem de palavras 6 - Removendo as Stopwords 7 - Dicionário Léxico 8 - Resultados...
#Install install.packages("twitteR") install.packages("rvest") install.packages("tidyverse") install.packages("tidytext") install.packages("tm") # for text mining install.packages("SnowballC") # for text stemming install.packages("wordcloud") # word-cloud generator install.packages("RColorBrewer") # color palettes in...
Warning message: "package 'twitteR' was built under R version 3.6.1"Warning message: "package 'rvest' was built under R version 3.6.1"Loading required package: xml2 Warning message: "package 'xml2' was built under R version 3.6.1"Warning message: "package 'tidyverse' was built under R version 3.6.1"-- Attaching package...
MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
3 - Conectando com a API do Twitter 3.1 - AutenticaçãoApós instalarmos e carregarmos todos os pacotes necessários, iremos efetuar a conexão com o Twitter através do pacote "TwitteR". Para isso precisamos das chaves de autenticação da API do twitter.
#API's and Token's keys API_key = "hhrTn58RfcBoxjpGdvQbLTf6v" API_secret_key = "r6zON2bTvFv8qlaEDWWaIowRknxRxc97EGENdSBfdXZlFmkmrm" Access_token = "4928132291-OFnrrwGy5FKHLPePkUsxLA5exJwrbJ7l51azMWV" Access_token_secret = "q7inW05npl3S70yRihMkJdasF0roZyrlzZW46D1XTSbDd" #OAuth setup_twitter_oauth(API_key, API_secret_ke...
[1] "Using direct authentication"
MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
3.2 - Obtendo os TweetsEm seguida, iremos criar uma função que solicita ao usuário uma palavra chave ou hashtag a ser buscada, a quantidade de tweets por dia, o idioma, a localidade e as datas iniciais e finais nas quais a pesquisa será feita. De posse destas informações, a função irá buscar os tweets de acordo com os...
#Search Twitters search_twiter <- function(){ #This function search for a specific number of tweets per day in a range of dates #Return a Tibble whith 3 columns: 1- TweetID; 2- Date; 3- Tweet; #Search string search_string <- paste(readline(prompt = "A wordkey or a hashtag: "), " -filter:retweets") #An exempl...
A wordkey or a hashtag: flamengo The number of tweets per day: 500 Language (ex.: pt): pt Tweets locale (ex.: br): br The inicial date (yyyy-mm-dd): 2019-07-16 The final date (yyyy-mm-dd): 2019-07-23
MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
Vamos dar uma olhada nos tweets que coletamos!
head(tweets_df)
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
4 - Text MiningNote que temos 3500 observações e 3 colunas na nossa tabela. Porém, a terceira coluna é uma lista que contém todas as informações sobre os tweets coletados. É importante ter em mente que um tweet não é representado apenas pelo seu texto, mas sim por outras informações também, como por exemplo, o seu ID,...
#Cleaning tweets clean_tweets <- function(tweets){ #Getting tweets texts tweets = sapply(tweets, function(x) x$text) #Remove retweet entities tweets = gsub('(RT|via)((?:\\b\\W*@\\w+)+)', "", tweets) #Remove Hashtags tweets = gsub('#\\w+', "", tweets) #Remove links tweets = gsub('http\\w+', "...
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
Embora os tweets ainda apresentem alguns caracteres estranhos, podemos dizer que temos nossos textos devidamente coletados. Estes caracteres estranhos serão tratados mais adiante.
head(tweets_df)
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
5 - Manipulação de dados 5.1 - TokenizaçãoNeste tópico iremos fazer a manipulação dos dados. O objetivo aqui é ter uma tabela onde cada registro possui uma única palavra, mantendo sempre a referência a qual tweet esta palavra pertence. Isso será muito útil para as análises seguintes.
#Tokenization tweets_tokens <- tweets_df %>% unnest_tokens(words, tweets) head(tweets_tokens, 25)
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
5.2 - Núvem de palavrasA fim de visualizar as palavras que são mais comuns dentre os tweets, vamos criar uma outra função que gera uma núvem de palavras.
wc <- function(tweets_tokens){ plot <- tweets_tokens %>% group_by(words) %>% summarise(freq = n()) %>% filter(words != "ifood") wordcloud(words = plot$words, freq = plot$freq, min.freq = 1, max.words=200, random.order=FALSE, rot.per=0.35, colors=brewer.pal(8, "Dark2")) } wc(...
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
6 - StopwordsNote que a palavra mais comum é "flamengo" pois é o tema da nossa pesquisa e é seguida por várias outras palavras que não tem muito peso semântico.Essas palavras são conhecidas como "stopwords". As stopwords são palavras que são comumente usadas e não possuem grande relevância para a semântica do texto. C...
#Stopwords stopwords <- stopwords(language = "pt", source = "stopwords-iso") stopwords <- tibble(stopwords) head(stopwords) tweets_tokens <- tweets_tokens %>% anti_join(stopwords, by = c("words" = "stopwords"))
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
7 - Dicionário LéxicoAté aqui, o que fizemos foi apenas limpar e manipular os dados. Neste tópico daremos início à análise de sentimentos.O primeiro passo consiste em carregarmos o dicionário léxico. Este dicionário léxico contém uma coluna que indica qual a polaridade das palavras, ou seja, se uma palavra é tida como...
#LexiconPT lex_pt <- oplexicon_v3.0 head(lex_pt)
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
Em seguida iremos cruzar as palavras dos tweets com as palavras do dicionário léxico, atribuindo uma polaridade para cada palavra dos tweets. Para isso, usaremos a função "inner_join".
tweets_tokens <- tweets_tokens %>% inner_join(lex_pt, by = c("words" = "term")) %>% select(tweetID, date, words, polarity) head(tweets_tokens)
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
Agora iremos visualizar novamente uma núvem de palavras para entender como a retirada das stopwords e cruzamento com o dicionário léxico afetaram nossos tweets.
wc(tweets_tokens)
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
8 - ResultadosApós feita a polarização das palavras contidas nos tweets, vamos utilizar esses dados para extrair melhores informações dos textos. 8.1 - Top 10 tweets "positivos"
#Most positive tweets top_10_pos <- tweets_tokens %>% group_by(tweetID) %>% summarise(polarity = sum(polarity)) %>% arrange(desc(polarity)) %>% head(10) #Ordering top_10_pos$tweetID <- factor(top_10_pos$tweetID, levels = unique(top_10_pos$tweetID[order(top_10_pos$polarity, ...
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
8.2 - Top 10 tweets "negativos"
#Most negative tweets top_10_neg <- tweets_tokens %>% group_by(tweetID) %>% summarise(polarity = sum(polarity)) %>% arrange(polarity) %>% head(10) #Ordering top_10_neg$tweetID <- factor(top_10_neg$tweetID, levels = unique(top_10_neg$tweetID)[order(top_10_neg$polarity, ...
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
8.3 - Overview da análise de sentimentosO gráfico a seguir categoriza os tweets como "positivos", "negativos" e "neutros" e mostra qual a quantidade de tweets por categoria.
#Sentiment Analysis Overview tweets_tokens %>% group_by(tweetID) %>% summarise(polarity = sum(polarity)) %>% mutate(class = ifelse(polarity > 0, "positive", ifelse(polarity < 0, "negative", "neutral"))) %>% count(class) %>% ggplot(aes(factor(class), n, fill = class)) + geom_col() + ...
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
8.4 - Análise de sentimentos em série temporalEste gráfico mostra como foi a sentimento dos usuários em relação ao tema ao longo do período determinado na busca.
#Time series tweets_tokens %>% group_by(date) %>% summarise(polarity = sum(polarity)) %>% ggplot(aes(date, polarity, group = 1)) + geom_line() + ggtitle("Polarity x Date")
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MIT
SentimentAnalysisOnTwitterWithR.ipynb
JPedro-loureiro/Sentiment-Analysis-on-Twitter-R
Linear Discriminate Analysis (LDA)
import numpy as np import matplotlib.pyplot as plt # data generation mean1=np.array([0,0]) mean2=np.array([4,5]) var=np.array([[1,0.1],[0.1,1]]) np.random.seed(0) data1=np.random.multivariate_normal(mean1,var,500) data2=np.random.multivariate_normal(mean2,var,500) data=np.concatenate((data1,data2)) label=np.concatena...
KNN Training accuracy = 100.0 KNN Testing accuracy = 100.0
Apache-2.0
Dimensionality Reduction/LDA/LDA_Algo.ipynb
Abhi10398/Machine-Learning
LDA multiclass 1. 3 class Sythetic data2. Homework: Mnist 3 class and 10 class
import numpy as np import matplotlib.pyplot as plt mean1=np.array([0,0]) mean2=np.array([4,5]) mean3=np.array([-5,-4]) var=np.array([[1,0.1],[0.1,1]]) np.random.seed(0) data1=np.random.multivariate_normal(mean1,var,500) data2=np.random.multivariate_normal(mean2,var,500) data3=np.random.multivariate_normal(mean3,var,50...
KNN Training accuracy = 99.93333333333332 KNN Testing accuracy = 100.0
Apache-2.0
Dimensionality Reduction/LDA/LDA_Algo.ipynb
Abhi10398/Machine-Learning
Test suite for Jupyter-notebook First stepImport ipycompss library
import pycompss.interactive as ipycompss
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Second step Initialize COMPSs runtime
ipycompss.start(graph=True, trace=True, debug=True)
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Third stepImport task module before annotating functions or methods
from pycompss.api.task import task
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Other declarations
MY_GLOBAL = 2 class myClass(object): def __init__(self): self.value = 1 def divide(a, b): def is_zero(value): if value == 0: raise True else: return False if not is_zero(b): return a / b else: raise Exception("Can not divide by 0.") def mu...
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Fourth stepDeclare functions and decorate with @task those that should be tasks
@task(returns=int) def test(val1): return multiply(val1, val1) @task(returns=int) def test2(val2, val3): return val2 + val3 @task(returns=int) def test3(val2, val3): return divide(val2, val3)
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Fifth stepInvoke tasks
a = test(2) b = test2(a, 5) c = test3(a, 2)
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Sixt step Import compss_wait_on module and synchronize tasks
from pycompss.api.api import compss_wait_on result = compss_wait_on(b)
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Only those results being sychronized with compss_wait_on will have a valid value
print("Results: ") print("a: ", a) print("b: ", b) print("c: ", c) print("result: ", result)
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
Stop COMPSs runtime. All data will be synchronized in the main program
ipycompss.stop(sync=True) print("Results after stopping PyCOMPSs: ") print("a: ", a) print("b: ", b) print("c: ", c) print("result: ", result)
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
CHECK THE RESULTS FOR THE TEST
from pycompss.runtime.management.classes import Future if a == 4 and isinstance(b, Future) and result == 9 and c == 2: print("RESULT=EXPECTED") else: raise Exception("RESULT=UNEXPECTED")
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Apache-2.0
compss/programming_model/bindings/python/src/pycompss/tests/resources/notebook/simple.ipynb
eflows4hpc/compss
AirBnB Data anaylst 1. Business Understanding: This project aims to follow the CRISP-DM to address the three questions which related to business or real-world applications. The dataset is picked up from Kaggle, contributed by AirBnB, which contains the rent data about Seattle. I would like to process whole data and t...
# import libraries import pandas as pd import numpy as np import matplotlib.pyplot as plt % matplotlib inline #load data listing = pd.read_csv('listings.csv') ## to check the feature of the dataset, then fliter listing.columns.values
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
Q1. What features influence the rating of house? 2.1 Pre-processing data - the null value columns
## check the missing value listing.isnull().mean().sort_values() ## calculate how many column has missing value miss_num = np.sum(listing.isnull().mean() != 0) miss_num # visulize the missing data plt.figure(figsize=(20,8)) (listing.isnull().sum(axis = 0).sort_values(ascending=False)[:miss_num]/len(listing)*100).plo...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
As we can see above, the features of "security_deposit", "monthly_price", "square_feet" and "license" are missing more than 50% values, and these features are unnecessary for the project, thus, I will drop them. Technically, I will make a copy of original data.
#back up dataset listing_backup = listing.copy() # drop the columns which lose more than 50% missing value listing = listing.drop(['security_deposit', 'monthly_price', 'square_feet', 'license'], axis = 1) ## check again, I have dropped them all listing.isnull().mean().sort_values() # check and summary the column of mi...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
Currently, the dataset has 88 features. Although the column of 'Weekly_price' quite close 50%, it may will be used, just keep it first. However, I think the dataset still contain some outliers and useless data, I will continue to process. 2.2 Processing the outliers and useless data 2.2.1, As the final target is pred...
def drop_columns(m_columns): listing.drop(columns = m_columns, inplace = True) drop_columns = ['id', 'notes'] drop_columns(drop_columns)
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
2.2.2 When I check the features, I found the values of some columns are link, which also could be defined as useless data.
## the column contains key word of 'url' url_col=[col for col in listing.columns.values if 'url' in col] url_col drop_columns(url_col)
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
2.2.3 Furthermore, there are some wired values, which means whole column only one value. I think those data won't help me to predict, drop it!
unique_col=[col for col in listing.columns.values if listing[col].nunique()==1] unique_col drop_columns(unique_col)
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
2.2.4 Next, after checking again, I think some columns that contains 'host', which may not be relevant for the prediction. For instance, 'host_id', 'host_name', 'host_since', 'host_location', 'host_about', 'host_verifications', 'host_neighbourhood'. Same operate as before. Drop it.
drop_cols=['host_id', 'host_name', 'host_since', 'host_location', 'host_about', 'host_verifications', 'host_neighbourhood'] drop_columns(drop_cols)
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
2.2.5 Lastly, the unstructured and redundant data. Some columns, such as City, State, Street, smart_location, latitude and longitude, could be represented by other value - zipcode. Therefore, they can be dropped
drop_cols=['city','street','state','smart_location','latitude','longitude', 'neighbourhood_cleansed'] drop_cols ## It shows what is the columns I will drop drop_columns(drop_cols) #drop columns containing unstructured data drop_cols=['name','summary', 'space', 'description', 'neighborhood_overview','transit', 'first_re...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
2.3 Filling up missing value and transferring categorical data 2.3.1 transferring categorical data
# Creating a table to visual the total value pd.merge(pd.DataFrame(listing.dtypes,columns=['datatype']).reset_index(), pd.DataFrame(pd.DataFrame(listing.iloc[0]).reset_index()),on='index') # get the name of columns which contain categorical data listing.select_dtypes(include=['object']).columns # to check uniq...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
2.3.2 Engineering for 'amenities' column Next I will engineer 'amenities' column to extract categorical variables. Since the amenities column is in the form of list of amenities, I will extract each amenity and it would be its own categorical feature for each listing.
# process the data of amenities column, splite it first listing.amenities = listing.amenities.str.replace("[{}]", "") amenities_col = listing.amenities.str.get_dummies(sep = ",") listing_cleaned = pd.merge(listing, amenities_col, left_index=True, right_index=True) # drop the amenities column now that is has been oneho...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
2.3.3 Checking missing value and filling up
# check what column has missing value listing_cleaned.isnull().mean().sort_values() # summary the missing value column and to find out what is value of them, ready to fill up missing_cols = ['beds','host_listings_count','host_total_listings_count','bedrooms','bathrooms', 'host_response_rate','review_sco...
beds : [ 1. 7. 2. 3. 15. 5. 4. 6. 9. 8. nan 10.] host_listings_count : [ 3. 6. 2. 1. 5. 9. 4. 36. 354. 8. 37. 7. 34. 10. 13. 21. 11. 169. 48. 502. 12. nan 18. 19. 15. 84. 163. 17.] host_total_listings_count : [ 3. 6. 2. 1. 5. 9. 4. 36. 354. 8. 37. 7. 34. ...
CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
As we can see, for the host_acceptance_rate column, there are only 3 unique values, which including Nan. Hence, I will drop this column as it does not offer an useful information.
#drop host_acceptance_rate column listing_cleaned.drop(columns='host_acceptance_rate',inplace=True)
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
Weekly price be dropped. In my mind, firstly, it lost almost 50% data, it is not an accurate data. Next, it could be the target value to be predicted, but not an independant value.
# drop the weekly_price column listing_cleaned.drop(columns='weekly_price',inplace=True) # Transfer String to float dollar_cols = ['cleaning_fee', 'extra_people', 'price'] listing_cleaned[dollar_cols]=listing_cleaned[dollar_cols].replace('[\$,]', '', regex=True).astype(float) percent_cols = ['host_response_rate'] listi...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
There are many missing values in review related features because these are new listings and don't get reviewed yet. In reality, travellers usually prefer listings with high number of reviews and high review scores. It might be possible to use a form of clustering to make a better estimate for this feature by looking at...
# fill up missing value with mean of their column for x in missing_cols: listing_cleaned[x] = listing_cleaned[x].fillna(listing_cleaned[x].mean()) # check whether the missing value is appear listing_cleaned.isnull().mean().sort_values()
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
3. Modelling Base on the Q1 of business understanding, I will check which feature influnce the rating of the house. Thus, 'review_scores_rating' would be the target(dependent) variable.
# split the data into different column, prepare to create a model y = listing_cleaned['review_scores_rating'] X = listing_cleaned.drop(['review_scores_rating'], axis = 1) from sklearn.model_selection import train_test_split from sklearn.tree import DecisionTreeRegressor ### I use Decision Tree as there are a lot of fea...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
Apparently, many reiviews that has a extermely imporant coefficients with the rating! More reviews which means the house always be the best choice, and people would follow this trend when they are choosing. Besides, we can see that price is an important factor for rating (I think so, price always play a key role, ...
# loading data calendar = pd.read_csv('calendar.csv') calendar.head()
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
4.2 Pre-processing data
# a lot of missing value in 'Price', but we are not interest it. :) calendar.isnull().sum() # drop the column that I dont use alendar.drop(columns = 'price').head(5) # to find out when is busy days popular_time=calendar[calendar['available']=='f'] #group dataset by date popular_time=popular_time.groupby('date')['listi...
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
It could no be clearly see from this graph, we still need to sort it
# to list the data that what I need popular_time.sort_values(ascending=False).head(50)
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CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
As we can see, January and July are the popular time for this area. Then, combining the results of question 1 and question 2, whatever is a host or a customer, they could make a strategy that how to improve the rating or attract the customer. Q3.Could we create a model to predict the price? Actually same with Q1, I wo...
# We use the data after cleaning y_st = listing_cleaned.price X_st = listing_cleaned.drop(['price'], axis = 1) X_train_st, X_test_st, y_train_st, y_test_st = train_test_split(X_st, y_st, test_size = .20, random_state=42) # Check the datasets print(X_train_st.shape, y_train_st.shape) print( X_test_st.shape, y_test_st....
The r-squared for the model is: 0.412996290368991
CNRI-Python
Project1.ipynb
Howie4PP/Airbnb_Data_Analyst
Import LIbraries
import pandas as pd import numpy as np
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MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
Loading Data
data = pd.read_csv( 'datasets/kc_house_data.csv' ) # Ploting data data.head()
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MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
Business questions: 1. How many homes are available for purchase?
# Counting number of lines the same number of houses # len(data['id'].unique()) # Or using .drop function (remove od duplicados e conta novamente) # Estrategy: # 1. Select "id" column; # 2. Remov repeated value; # 3. Count the number of unique values. houses = len(data['id'].drop_duplicates()) print('The number of avai...
The number of avaible houses are 21436
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
2. How many attributes do houses have?
# Estrategy: # 1. Count the number os columns; # 2. Remove values "id", "date" (they are not attributes): attributes = len(data.drop(['id', 'date'], axis = 1).columns) print('The houses have {} attributes'.format(attributes))
The houses have 19 attributes
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
3. What are the attributes of houses?
## Estrategy: # 1. Plot the columns. attributes2 = data.drop(['id', 'date'], axis=1).columns print('The attributes are: {}'.format(attributes2))
The attributes are: Index(['price', 'bedrooms', 'bathrooms', 'sqft_living', 'sqft_lot', 'floors', 'waterfront', 'view', 'condition', 'grade', 'sqft_above', 'sqft_basement', 'yr_built', 'yr_renovated', 'zipcode', 'lat', 'long', 'sqft_living15', 'sqft_lot15'], dtype='object')
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
4. What is the most expensive house (house with the highest sale price)?
# Estrategy: # 1. Arrange the price column from highest to lowest # 2. Apply reset index to recount rows and ensure correct result; # 3. Collect the value and id from the first row. data[['id','price']].sort_values('price', ascending=False).head() # 1 exphouse = data[['id','price']].sort_values('price', ascending=Fal...
The most expensive House is: id 6762700020 price U$7700000.0
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
5. Which house has the most bedrooms?
# Estrategy: # 1. Arrange the bedroom column from highest to lowest; # 2. Apply reset index to recount rows and ensure correct result; # 3. Collect the value and id from the first row. data[["id","bedrooms"]].sort_values("bedrooms", ascending=False).head() # 1 bedroomsid = data[['id','bedrooms']].sort_values('bedrooms'...
The house with the most bedrooms is 2402100895 and have 33 bedroomns
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
6. What is the sum total of bedrooms in the dataset?
# Estrategy: # 1. Filter the columns "bedrooms" and sum this value. bedroomsnumber = data['bedrooms'].sum() print('There are a total of {} bedrooms'.format(bedroomsnumber))
There are a total of 72854 bedrooms
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
7. How many houses have 2 bathrooms?
# Estrategy: # 1. Find the number of houses whit 2 bathrooms; # 2. Select columns "id" and "bathroom"; # 3. Sum the number of houses. data.loc[data['bathrooms'] == 2, ['id', 'bathrooms']] # 1 bethroomsum = data.loc[data['bathrooms'] == 2, ['id', 'bathrooms']].shape # 2 and 3 print('There are a total of {} bethrooms'.f...
There are a total of (1930, 23) bethrooms
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
8. What is the average price of all houses in the dataset?
# Estrategy: # 1. Find the average price of houses. # Ps.: Use numpy's round() function to select only 2 number after point. averageprice = np.round(data['price'].mean(), 2) print('The average price of the houses is: U${}'.format(averageprice )) # the function data.dtypes show us what types variables we have. data.dtyp...
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MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
9. What is the average price only houses whit 2 bathroom?
# Estrategy: # 1. Find only the average price of houses whit 2 bathroms. avg_bath = np.round(data.loc[data['bathrooms'] == 2, 'price'].mean(), 2) print('The average price for houses whit 2 bathrooms is U${}'.format(avg_bath))
The average price for houses whit 2 bathrooms is U$457889.72
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
10. What is the minimum price between 3 bedroom homes?
# Estrategy: # 1. Select only 3 bedroom house and arrange ascending by price min_price_bed = data.loc[data['bedrooms'] == 3, 'price'].min(), print('The minimum price for houses whit 3 bedrooms is U${}'.format(min_pricebed))
The minimum price for houses whit 3 bedrooms is U$82000.0
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
11. How many homes have more than 300 square meters in the living room?
# Estrategy: # 1. Select only houses whit mor than 300ft² of living room and read the number of lines. data['m2'] = data['sqft_living'] * 0.093 sqft_300 = len(data.loc[data['m2'] > 300, 'id']) print('There are {} houses whit mor than 300ft² in the living room.'.format(sqft_300))
There are 2258 houses whit mor than 300ft² in the living room.
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
Se quiser fazer a converção de ft² para m² basta usar o seguinte raciocionio: (1 ft² = 0.093 m²) data['m²']=data['sqft_living'] * 0.093 - (aqui substituimos a variavel sqft_living pela m² ja convertendo o valor) len(data.loc[data['m²'] > 300, 'id']) 12. How many homes have more than 2 floors?
# Estrategy: # 1. Select only houses whit mor than 300ft² of living room and read the number of lines. floor_2 = data.loc[data['floors'] > 2, 'id'].size print('There are {} houses whit mor than 2 floors.'.format(floor_2))
There are 782 houses whit mor than 2 floors.
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
13. How many houses have a waterfront view?
# Estrategy: # 1. Select only houses whit waterfront view and read the number of lines. waterfront_view = len(data.loc[data['waterfront'] != 0, 'id']) print('There are {} houses whit waterfront view.'.format(waterfront_view))
There are 163 houses whit waterfront view.
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS
14. Of the houses with a waterfront view, how many have 3 bedrooms?
# Estrategy: # 1. Select only houses whit waterfront view and read how many have 3 bedrooms. data.columns waterfront_bed = data.loc[(data['waterfront'] != 0) & (data['bedrooms'] == 3), "id"].size print('Of the houses whit waterfront, {} houses have 3 bedrooms.'.format(waterfront_bed))
Of the houses whit waterfront, 64 houses have 3 bedrooms.
MIT
Notebooks/Preview_Data_Visualization.ipynb
BrunoGeraldine/Python_Zero_To_DS