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Filtering (cutting) events and particles with advanced selectionsNumPy has a versatile selection mechanism:The same expressions apply to Awkward Arrays, and more.
# First particle momentum in the first 5 events events.prt.p[:5, 0] # First two particles in all events events.prt.pdg[:, :2] # First direction of the last event events.prt.dir[-1, 0]
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reikdas/awkward-1.0
NumPy also lets you filter (cut) using an array of booleans.
events.prt_count > 100 np.count_nonzero(events.prt_count > 100) events[events.prt_count > 100]
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One dimension can be selected with an array while another is selected with a slice.
# Select events with at least two particles, then select the first two particles events.prt[events.prt_count >= 2, :2]
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This can be a good way to avoid errors from trying to select what isn't there.
try: events.prt[:, 0] except Exception as err: print(type(err).__name__, str(err)) events.prt[events.prt_count > 0, 0]
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See also [awkward-array.readthedocs.io](https://awkward-array.readthedocs.io/) for a list of operations like [ak.num](https://awkward-array.readthedocs.io/en/latest/_auto/ak.num.html):
?ak.num ak.num(events.prt), events.prt_count
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You can even use an array of integers to select a set of indexes at once.
# First and last particle in each event that has at least two events.prt.pdg[ak.num(events.prt) >= 2][:, [0, -1]]
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But beyond NumPy, we can also use arrays of nested lists as boolean or integer selectors.
# Array of lists of True and False abs(events.prt.vtx) > 0.10 # Particles that have vtx > 0.10 for all events (notice that there's still 10000) events.prt[abs(events.prt.vtx) > 0.10]
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See [awkward-array.readthedocs.io](https://awkward-array.readthedocs.io/) for more, but there are functions like [ak.max](https://awkward-array.readthedocs.io/en/latest/_auto/ak.max.html), which picks the maximum in a groups. * With `axis=0`, the group is the set of all events. * With `axis=1`, the groups are parti...
?ak.max ak.max(abs(events.prt.vtx), axis=1) # Selects *events* that have a maximum *particle vertex* greater than 100 events[ak.max(abs(events.prt.vtx), axis=1) > 100]
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The difference between "select particles" and "select events" is the number of jagged dimensions in the array; "reducers" like ak.max reduce the dimensionality by one.There are other reducers like ak.any, ak.all, ak.sum...
?ak.sum # Is this particle an antineutron? events.prt.pdg == Particle.from_string("n~").pdgid # Are any particles in the event antineutrons? ak.any(events.prt.pdg == Particle.from_string("n~").pdgid, axis=1) # Select events that contain an antineutron events[ak.any(events.prt.pdg == Particle.from_string("n~").pdgid, ax...
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We can use these techniques to make subcollections for specific particle types and attach them to the same `events` array for easy access.
events.prt[abs(events.prt.pdg) == abs(Particle.from_string("p").pdgid)] # Assignments have to be through __setitem__ (brackets), not __setattr__ (as an attribute). # Is that a problem? (Assigning as an attribute would have to be implemented with care, if at all.) events["pions"] = events.prt[abs(events.prt.pdg) == abs...
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Flattening for plots and regularizing to NumPy for machine learningAll of this structure is great, but eventually, we need to plot the data or ship it to some statistical process, such as machine learning.Most of these tools know about NumPy arrays and rectilinear data, but not Awkward Arrays. As a design choice, Awkw...
?ak.flatten # Turn particles-grouped-by-event into one big array of particles ak.flatten(events.prt, axis=1) # Eliminate structure at all levels; produce one numerical array ak.flatten(events.prt, axis=None)
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For plotting, you probably want to pick one field and flatten it. Flattening with `axis=1` (the default) works for one level of structure and is safer than `axis=None`.The flattening is explicit as a reminder that a histogram whose entries are particles is different from a histogram whose entries are events.
# Directly through Matplotlib plt.hist(ak.flatten(events.kaons.p), bins=100, range=(0, 10)) # Through mplhep and boost-histgram, which are more HEP-friendly hep.histplot(bh.Histogram(bh.axis.Regular(100, 0, 10)).fill( ak.flatten(events.kaons.p) ))
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If the particles are sorted (`ak.sort`/`ak.argsort` is [in development](https://github.com/scikit-hep/awkward-1.0/pull/168)), you might want to pick the first kaon from every event that has them (i.e. *use* the event structure).This is an analysis choice: *you* have to decide you want this.The `ak.num(events.kaons) > 0...
hep.histplot(bh.Histogram(bh.axis.Regular(100, 0, 10)).fill( events.kaons.p[ak.num(events.kaons) > 0, 0] ))
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Or perhaps the maximum pion momentum in each event. This one must be flattened (with `axis=0`) to remove `None` values.This flattening is explicit as a reminder that empty events are not counted in the histogram.
ak.max(events.kaons.p, axis=1) ak.flatten(ak.max(events.kaons.p, axis=1), axis=0) hep.histplot(bh.Histogram(bh.axis.Regular(100, 0, 10)).fill( ak.flatten(ak.max(events.kaons.p, axis=1), axis=0) ))
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Or perhaps the momentum of the kaon with the farthest vertex. [ak.argmax](https://awkward-array.readthedocs.io/en/latest/_auto/ak.argmax.html) creates an array of integers selecting from each event.
?ak.argmax ak.argmax(abs(events.kaons.vtx), axis=1) ?ak.singletons # Get a length-1 list containing the index of the biggest vertex when there is one # And a length-0 list when there isn't one ak.singletons(ak.argmax(abs(events.kaons.vtx), axis=1)) # A nested integer array like this is what we need to select kaons with...
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If you're sending the data to a library that expects rectilinear structure, you might need to pad and clip the variable length lists.[ak.pad_none](https://awkward-array.readthedocs.io/en/latest/_auto/ak.pad_none.html) puts `None` values at the end of each list to reach a minimum length.
?ak.pad_none # pad them look at the first 30 ak.pad_none(events.kaons.id, 3)[:30].tolist()
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The lengths are still irregular, so you can also `clip=True` them.
# pad them look at the first 30 ak.pad_none(events.kaons.id, 3, clip=True)[:30].tolist()
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The library we're sending this to might not be able to deal with missing values, so choose a replacement to fill them with.
?ak.fill_none # fill with -1 <- pad them look at the first 30 ak.fill_none(ak.pad_none(events.kaons.id, 3, clip=True), -1)[:30].tolist()
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These are still Awkward-brand arrays; the downstream library might complain if they're not NumPy-brand, so use [ak.to_numpy](https://awkward-array.readthedocs.io/en/latest/_auto/ak.to_numpy.html) or simply cast it with NumPy's `np.asarray`.
?ak.to_numpy np.asarray(ak.fill_none(ak.pad_none(events.kaons.id, 3, clip=True), -1))
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If you try to convert an Awkward Array as NumPy and structure would be lost, you get an error. (You won't accidentally eliminate structure.)
try: np.asarray(events.kaons.id) except Exception as err: print(type(err), str(err))
<class 'ValueError'> in ListOffsetArray64, cannot convert to RegularArray because subarray lengths are not regular
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Broadcasting flat arrays and jagged arraysNumPy lets you combine arrays and scalars in a mathematical expression by first "broadcasting" the scalar to an array of the same length.
print(np.array([1, 2, 3, 4, 5]) + 100)
[101 102 103 104 105]
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Awkward Array does the same thing, except that each element of a flat array can be broadcasted to each nested list of a jagged array.
print(ak.Array([[1, 2, 3], [], [4, 5], [6]]) + np.array([100, 200, 300, 400]))
[[101, 102, 103], [], [304, 305], [406]]
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This is useful for emulating```pythonall_vertices = []for event in events: vertices = [] for kaon in events.kaons: all_vertices.append((kaon.vtx.x - event.true.x, kaon.vtx.y - event.true.y)) all_vertices.append(vertices)```where `event.true.x` and `y` have only one value per ...
# one value per kaon one per event ak.zip([events.kaons.vtx.x - events.true.x, events.kaons.vtx.y - events.true.y])
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You don't have to do anything special for this: broadcasting is a common feature of all functions that apply to more than one array.You can get it explicitly with [ak.broadcast_arrays](https://awkward-array.readthedocs.io/en/latest/_auto/ak.broadcast_arrays.html).
?ak.broadcast_arrays ak.broadcast_arrays(events.true.x, events.kaons.vtx.x)
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Combinatorics: cartesian and combinationsAt all levels of a physics analysis, we need to compare objects drawn from different collections. * **Gen-reco matching:** to associate a reconstructed particle with its generator-level parameters. * **Cleaning:** assocating soft photons with a reconstructed electron or lep...
?ak.cartesian ?ak.combinations ak.to_list(ak.cartesian(([[1, 2, 3], [], [4]], [["a", "b"], ["c"], ["d", "e"]]))) ak.to_list(ak.combinations([["a", "b", "c", "d"], [], [1, 2]], 2))
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To search for $\Lambda^0 \to \pi p$, we need to compute the mass of pairs drawn from these two collections.
pairs = ak.cartesian([events.pions, events.protons]) pairs ?ak.unzip def mass(pairs, left_mass, right_mass): left, right = ak.unzip(pairs) left_energy = np.sqrt(left.p**2 + left_mass**2) right_energy = np.sqrt(right.p**2 + right_mass**2) return np.sqrt((left_energy + right_energy)**2 - ...
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We can improve the peak by selecting for opposite charges and large vertexes.
def opposite(pairs): left, right = ak.unzip(pairs) return pairs[left.charge != right.charge] def distant(pairs): left, right = ak.unzip(pairs) return pairs[np.logical_and(abs(left.vtx) > 0.10, abs(right.vtx) > 0.10)] hep.histplot(bh.Histogram(bh.axis.Regular(100, 1.115683 - 0.01, 1.115683 + 0.01)).fill...
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Alternatively, all of these functions could have been methods on the pair objects for reuse.(This is to make the point that any kind of object can have methods, not just particles.)
class ParticlePairArray(ak.Array): __name__ = "Pairs" def mass(self, left_mass, right_mass): left, right = self.slot0, self.slot1 left_energy = np.sqrt(left.p**2 + left_mass**2) right_energy = np.sqrt(right.p**2 + right_mass**2) return np.sqrt((left_energy + right_energy)**2...
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**Self-study question:** why does the call to `mass` have to be last? An example for `ak.combinations`: $K_S \to \pi\pi$.
pairs = ak.combinations(events.pions, 2, with_name="pair") pairs hep.histplot(bh.Histogram(bh.axis.Regular(100, 0.497611 - 0.015, 0.497611 + 0.015)).fill( ak.flatten(pairs.opposite().distant(0.10).mass(0.139570, 0.139570)) ))
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**Bonus problem:** $D^0 \to K^- \pi^+ \pi^0$
pizero_candidates = ak.combinations(events.prt[events.prt.pdg == Particle.from_string("gamma").pdgid], 2, with_name="pair") pizero = pizero_candidates[pizero_candidates.mass(0, 0) - 0.13498 < 0.000001] pizero["px"] = pizero.slot0.px + pizero.slot1.px pizero["py"] = pizero.slot0.py + pizero.slot1.py pizero["pz"] = pizer...
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This Dalitz plot doesn't look right (doesn't cut off at kinematic limits), but I'm going to leave it as an exercise for the reader.
dalitz = bh.Histogram(bh.axis.Regular(50, 0, 3), bh.axis.Regular(50, 0, 2)) dalitz.fill(ak.flatten(mKpi), ak.flatten(mpipi)) X, Y = dalitz.axes.edges fig, ax = plt.subplots() mesh = ax.pcolormesh(X.T, Y.T, dalitz.view().T) fig.colorbar(mesh)
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Reducing from combinationsThe mass-peak examples above don't need to "reduce" combinations, but many applications do. Suppose that we want to find the "nearest photon to each electron" (e.g. bremsstrahlung).
electrons = events.prt[abs(events.prt.pdg) == abs(Particle.from_string("e-").pdgid)] photons = events.prt[events.prt.pdg == Particle.from_string("gamma").pdgid]
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The problem with the raw output of `ak.cartesian` is that all the combinations are mixed together in the same lists.
ak.to_list(ak.cartesian([electrons[["pdg", "id"]], photons[["pdg", "id"]]])[8])
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We can fix this by asking for `nested=True`, which adds another level of nesting to the output.
ak.to_list(ak.cartesian([electrons[["pdg", "id"]], photons[["pdg", "id"]]], nested=True)[8])
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All electron-photon pairs associated with a given electron are grouped in a list-within-each-list.Now we can apply reducers to this inner dimension to sum over some quantity, pick the best one, etc.
def cos_angle(pairs): left, right = ak.unzip(pairs) return left.dir.x*right.dir.x + left.dir.y*right.dir.y + left.dir.z*right.dir.z electron_photons = ak.cartesian([electrons, photons], nested=True) cos_angle(electron_photons) hep.histplot(bh.Histogram(bh.axis.Regular(100, -1, 1)).fill( ak.flatten(cos_angle...
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We pick the "maximum according to a function" using the same `ak.singletons(ak.argmax(f(x))` trick as above.
best_electron_photons = electron_photons[ak.singletons(ak.argmax(cos_angle(electron_photons), axis=2))] hep.histplot(bh.Histogram(bh.axis.Regular(100, -1, 1)).fill( ak.flatten(cos_angle(best_electron_photons), axis=None) ))
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By construction, `best_electron_photons` has zero or one elements in each *inner* nested list.
ak.num(electron_photons, axis=2), ak.num(best_electron_photons, axis=2)
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Since we no longer care about that *inner* structure, we could flatten it at `axis=2` (leaving `axis=1` untouched).
best_electron_photons ak.flatten(best_electron_photons, axis=2)
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But it would be better to invert the `ak.singletons` by calling `ak.firsts`.
?ak.singletons ?ak.firsts ak.firsts(best_electron_photons, axis=2)
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Because then we can get back one value for each electron (with `None` if `ak.argmax` resulted in `None` because there were no pairs).
ak.num(electrons), ak.num(ak.firsts(best_electron_photons, axis=2)) ak.all(ak.num(electrons) == ak.num(ak.firsts(best_electron_photons, axis=2)))
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reikdas/awkward-1.0
And that means that we can make this "closest photon" an attribute of the electrons. We have now performed electron-photon matching.
electrons["photon"] = ak.firsts(best_electron_photons, axis=2) ak.to_list(electrons[8])
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reikdas/awkward-1.0
Current set of reducers: * [ak.count](https://awkward-array.readthedocs.io/en/latest/_auto/ak.count.html): counts the number in each group (subtly different from [ak.num](https://awkward-array.readthedocs.io/en/latest/_auto/ak.num.html) because `ak.count` is a reducer) * [ak.count_nonzero](https://awkward-array.rea...
import numba as nb @nb.jit def monte_carlo_pi(nsamples): acc = 0 for i in range(nsamples): x = np.random.random() y = np.random.random() if (x**2 + y**2) < 1.0: acc += 1 return 4.0 * acc / nsamples %%timeit # Run the pure Python function (without nb.jit) monte_carlo_pi....
8.7 ms ± 194 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
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reikdas/awkward-1.0
The price for this magical speedup is that not all Python code can be accelerated; you have to be conservative with the functions and language features you use, and Numba has to recognize the data types.Numba recognizes Awkward Arrays.
@nb.jit def lambda_mass(events): num_lambdas = 0 for event in events: num_lambdas += len(event.pions) * len(event.protons) lambda_masses = np.empty(num_lambdas, np.float64) i = 0 for event in events: for pion in event.pions: for proton in event.protons: p...
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Some constraints: * Awkward arrays are read-only structures (always true, even outside of Numba) * Awkward arrays can't be created inside a Numba-compiled functionThat was fine for a function that creates and returns a NumPy array, but what if we want to create something with structure? The [ak.ArrayBuilder](https:...
?ak.ArrayBuilder builder = ak.ArrayBuilder() builder.begin_list() builder.begin_record() builder.field("x").integer(1) builder.field("y").real(1.1) builder.field("z").string("one") builder.end_record() builder.begin_record() builder.field("x").integer(2) builder.field("y").real(2.2) builder.field("z").string("two") ...
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ArrayBuilders can be used in Numba, albeit with some constraints: * ArrayBuilders can't be created inside a Numba-compiled function (pass them in) * The `snapshot` method (to turn it into an array) can't be used in a Numba-compiled function (use it outside)
@nb.jit(nopython=True) def make_electron_photons(events, builder): for event in events: builder.begin_list() for electron in event.electrons: best_i = -1 best_angle = -1.0 for i in range(len(event.photons)): photon = event.photons[i] ...
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A few of them are `None` (called `builder.null()` because there were no photons to attach to the electron).
ak.count_nonzero(ak.is_none(ak.flatten(builder.snapshot())))
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But the `builder.snapshot()` otherwise matches up with the `events.electrons`, so it's something we could attach to it, as before.
?ak.with_field events["electrons"] = ak.with_field(events.electrons, builder.snapshot(), "photon") ak.to_list(events[8].electrons)
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Grafting jagged data onto PandasAwkward Arrays can be Pandas columns.
import pandas as pd df = pd.DataFrame({"pions": events.pions, "kaons": events.kaons, "protons": events.protons}) df df["pions"].dtype
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But that's unlikely to be useful for very complex data structures because there aren't any Pandas functions for deeply nested structure.Instead, you'll probably want to *convert* the nested structures into the corresponding Pandas [MultiIndex](https://pandas.pydata.org/pandas-docs/stable/user_guide/advanced.html).
ak.pandas.df(events.pions)
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docs-jupyter/2020-04-08-eic-jlab.ipynb
reikdas/awkward-1.0
Now the nested lists are represented as MultiIndex rows and the nested records are represented as MultiIndex columns, which are structures that Pandas knows how to deal with. But what about two types of particles, pions and kaons? (And let's simplify to just `"px", "py", "pz", "vtx"`.)
simpler = ak.zip({"pions": events.pions[["px", "py", "pz", "vtx"]], "kaons": events.kaons[["px", "py", "pz", "vtx"]]}, depthlimit=1) ak.type(simpler) ak.pandas.df(simpler)
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BSD-3-Clause
docs-jupyter/2020-04-08-eic-jlab.ipynb
reikdas/awkward-1.0
There's only one row MultiIndex, so pion 1 in each event is the same row as kaon 1. That assocation is probably meaningless.The issue is that a single Pandas DataFrame represents *less* information than an Awkward Array. In general, we would need a collection of DataFrames to losslessly encode an Awkward Array. (Pandas...
# This array corresponds to *two* Pandas DataFrames. pions_df, kaons_df = ak.pandas.dfs(simpler) pions_df kaons_df
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BSD-3-Clause
docs-jupyter/2020-04-08-eic-jlab.ipynb
reikdas/awkward-1.0
NumExpr, Autograd, and other third-party libraries [NumExpr](https://numexpr.readthedocs.io/en/latest/user_guide.html) can calcuate pure numerical expressions faster than NumPy because it does so in one pass. (It has a low-overhead virtual machine.)NumExpr doesn't recognize Awkward Arrays, but we have a wrapper for it...
import numexpr # This works because px, py, pz are flat, like NumPy px = ak.flatten(events.pions.px) py = ak.flatten(events.pions.py) pz = ak.flatten(events.pions.pz) numexpr.evaluate("px**2 + py**2 + pz**2") # This doesn't work because px, py, pz have structure px = events.pions.px py = events.pions.py pz = events.pi...
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BSD-3-Clause
docs-jupyter/2020-04-08-eic-jlab.ipynb
reikdas/awkward-1.0
Similarly for [Autograd](https://github.com/HIPS/autogradreadme), which has an `elementwise_grad` for differentiating expressions with respect to NumPy [universal functions](https://docs.scipy.org/doc/numpy/reference/ufuncs.html), but not Awkward Arrays.
@ak.autograd.elementwise_grad def tanh(x): y = np.exp(-2.0 * x) return (1.0 - y) / (1.0 + y) ak.to_list(tanh([{"x": 0.0, "y": []}, {"x": 0.1, "y": [1]}, {"x": 0.2, "y": [2, 2]}, {"x": 0.3, "y": [3, 3, 3]}]))
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BSD-3-Clause
docs-jupyter/2020-04-08-eic-jlab.ipynb
reikdas/awkward-1.0
说明: 给定由数字(‘0’-‘9’)和‘’组成的字符串s。 我们希望将s映射到英文小写字符,如下所示: 1、字符(‘a’到‘i’)分别由(‘1’到‘9’)表示。 2、字符(‘j’到‘z’)分别由(‘10’到‘26’)表示。 返回映射后形成的字符串。 可以保证唯一的映射将始终存在。Example 1: Input: s = "101112" Output: "jkab" Explanation: "j" -> "10" , "k" -> "11" , "a" -> "1" , "b" -> "2".Example 2: Input: s = "1326" Output:...
class Solution: def freqAlphabets(self, s: str) -> str: res = '' idx = 0 while idx < len(s): if idx + 2 < len(s) and 1 <= int(s[idx]) <= 2 and s[idx + 2] == '#': val = int(s[idx] + s[idx + 1]) idx += 2 else: val = int(s[...
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Apache-2.0
String/1013/1309. Decrypt String from Alphabet to Integer Mapping.ipynb
YuHe0108/Leetcode
IEEE-CIS Fraud Detection Can you detect fraud from customer transactions?
# Análise dos dados import pandas as pd # Visualização dos dados import matplotlib.pyplot as plt import seaborn as sn
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MIT
Mentoria Fraudes/Mentoria - Fraudes Leon.ipynb
leon-maia/Portfolio-Voyager
SampleSubmission é o formato de entrega do modelo. Desconsiderar Dataset.
df_SampleSubmission = pd.read_csv('sample_submission.csv') df_SampleSubmission.head()
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MIT
Mentoria Fraudes/Mentoria - Fraudes Leon.ipynb
leon-maia/Portfolio-Voyager
Analisando o dataset test_identity.csv MetadadosIdentity TableVariables in this table are identity information – network connection information (IP, ISP, Proxy, etc) and digital signature (UA/browser/os/version, etc) associated with transactions.They're collected by Vesta’s fraud protection system and digital security...
df_test_identity = pd.read_csv('test_identity.csv') l, c = df_test_identity.shape l df_test_identity.head() df_test_identity.tail() df_test_identity.info() df_test_identity.isnull().sum().sort_values(ascending=False) (df_test_identity.isnull().sum().sort_values(ascending=False) / l) * 100 df_test_identity_corr = df_tes...
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MIT
Mentoria Fraudes/Mentoria - Fraudes Leon.ipynb
leon-maia/Portfolio-Voyager
Analisando o dataset test_transaction.csv Transaction table“It contains money transfer and also other gifting goods and service, like you booked a ticket for others, etc.”TransactionDT: timedelta from a given reference datetime (not an actual timestamp)“TransactionDT first value is 86400, which corresponds to the numb...
df_test_transaction = pd.read_csv('test_transaction.csv') display(df_test_transaction) l2, c2 = df_test_transaction.shape df_test_transaction.info(verbose=True) # Para visualizar todas as colunas (antes de conhecer o atributo 'verbose'), criei uma Serie com o nome das colunas df_test_transactionColumns = pd.Series(df_t...
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MIT
Mentoria Fraudes/Mentoria - Fraudes Leon.ipynb
leon-maia/Portfolio-Voyager
High-level RNN TF Example
import numpy as np import os import sys import tensorflow as tf from common.params_lstm import * from common.utils import * # Force one-gpu os.environ["CUDA_VISIBLE_DEVICES"] = "0" print("OS: ", sys.platform) print("Python: ", sys.version) print("Numpy: ", np.__version__) print("Tensorflow: ", tf.__version__) print("GP...
Accuracy: 0.8598557692307692
MIT
notebooks/Tensorflow_RNN.ipynb
ThomasDelteil/DeepLearningFrameworks
Question Engagement Analysis Select course and load data set
data_dir = '/Users/benny/data/L@S_2021' course = 'microbiology' data_set_filename = f'engagement_{course}.txt' data_set = pd.read_csv( f'{data_dir}/{data_set_filename}', sep='\t' ) data_set
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CC-BY-4.0
l@s-2021/Question Engagement Analysis.ipynb
vitalsource/data
Mean engagement
data_set.groupby( 'question_type' ).mean().sort_values( by='answered', ascending=False )
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CC-BY-4.0
l@s-2021/Question Engagement Analysis.ipynb
vitalsource/data
Regression model
%%R library( lme4 )
R[write to console]: Loading required package: Matrix
CC-BY-4.0
l@s-2021/Question Engagement Analysis.ipynb
vitalsource/data
Standardize the continuous variables.
for col in [ 'course_page_number', 'unit_page_number', 'module_page_number', 'page_question_number' ]: data_set[ col ] = ( data_set[ col ] - data_set[ col ].mean() ) / data_set[ col ].std() data_set.to_csv( '/tmp/to_r.csv', index=False ) %%R df <- read.csv( '/tmp/to_r.csv' ) %%R lme.model <- glmer( answered ~ cours...
R[write to console]: fixed-effect model matrix is rank deficient so dropping 1 column / coefficient
CC-BY-4.0
l@s-2021/Question Engagement Analysis.ipynb
vitalsource/data
1- Write a list comprehensions that contains numbers from 1 to 31, append the prefix "1-" to the numbers, these are day of January
L = [f"1-{day}" for day in range(1,32)]
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MIT
10-warmup-solution_comprehensions.ipynb
hanisaf/advanced-data-management-and-analytics
2- convert the list to a string so each entry prints on one line. Print the result
line = '\n'.join(L) print(line) from functools import reduce line = reduce(lambda x, y: f"{x}\n{y}", L) print(line) def combine(x, y): return x + '\n' + y line = reduce(combine, L) print(line)
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MIT
10-warmup-solution_comprehensions.ipynb
hanisaf/advanced-data-management-and-analytics
3- Update the comprehension to vary prefix from 1- to 12- to generate all days of the year, do not worry about incorrect dates for now
L = [ f"{month}-{day}" for month in range(1, 13) for day in range(1,32) ] L
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MIT
10-warmup-solution_comprehensions.ipynb
hanisaf/advanced-data-management-and-analytics
4- now, address the issue of some months being only 30 days and february if 28 days (this year). Hint, use the `valid_date` function
def valid_date(day, month): days_of_month = {1:31, 2:28, 3:31, 4:30, 5:31, 6:30, 7:31, 8:31, 9:30, 10:31, 11:30, 12:31} max_month = days_of_month[month] return day <= max_month L = [ f"{month}-{day}" for month in range(1, 13) for day in range(1,32) if valid_date(day, month)] L
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MIT
10-warmup-solution_comprehensions.ipynb
hanisaf/advanced-data-management-and-analytics
5- using dictionary comprehensions create `f2e` dictionary from the `e2f` dictionary
e2f = {'hi':'bonjour', 'bye':'au revoir', 'bread':'pain', 'water':'eau'} f2e = { e2f[k]:k for k in e2f} f2e f2e = {item[1]:item[0] for item in e2f.items()} f2e f2e = {v:k for (k,v) in e2f.items()} f2e f2e = {e2f[k]:k for k in e2f}
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MIT
10-warmup-solution_comprehensions.ipynb
hanisaf/advanced-data-management-and-analytics
div.container { width: 100% }Tutorial 4. Interlinked Plots hvPlot allows you to generate a number of different types of plot quickly from a standard API, returning Bokeh-based [HoloViews](https://holoviews.org) objects as discussed in the previous notebook. Each initial plot will make some aspects of the data clear, an...
import holoviews as hv import pandas as pd import hvplot.pandas # noqa import colorcet as cc
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
First let us load the data as before:
%%time df = pd.read_parquet('../data/earthquakes-projected.parq') df.time = df.time.astype('datetime64[ns]') df = df.set_index(df.time)
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
And filter to the most severe earthquakes (magnitude `> 7`):
most_severe = df[df.mag >= 7]
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
Linked brushing across elementsIn the previous notebook, we saw how plot axes are automatically linked for panning and zooming when using the `+` operator, provided the dimensions match. When dimensions or an underlying index match across multiple plots, we can use a similar principle to achieve linked brushing, where...
mag_hist = most_severe.hvplot( y='mag', kind='hist', responsive=True, min_height=150) depth_hist = most_severe.hvplot( y='depth', kind='hist', responsive=True, min_height=150)
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
These two histograms are plotting two different dimensions of our earthquake dataset (magnitude and depth), derived from the same set of earthquake samples. The samples between these two histograms share an index, and the relationships between these data points can be discovered and exploited programmatically even thou...
ls = hv.link_selections.instance()
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
Given some HoloViews objects (elements, layouts, etc.), we can create versions of them linked to this shared linking object by calling `ls` on them:
ls(depth_hist + mag_hist)
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
Try using the first Bokeh tool to select areas of either histogram: you'll then see both the depth and magnitude distributions for the bins you have selected, compared to the overall distribution. By default, selections on both histograms are combined so that the selection is the intersection of the two regions selecte...
geo = most_severe.hvplot( 'easting', 'northing', color='mag', kind='points', tiles='ESRI', xlim=(-3e7,3e7), ylim=(-5e6,5e6), xaxis=None, yaxis=None, responsive=True, height=350, cmap = cc.CET_L4[::-1], framewise=True)
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
Once again, we just need to pass our points to the `ls` object (newly declared here to be independent of the one above) to declare the linkage:
ls2 = hv.link_selections.instance() (ls2(geo + depth_hist)).cols(1)
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
Now you can use the box-select tool to select earthquakes on the map and view their corresponding depth distribution, or vice versa. E.g. if you select just the earthquakes in Alaska, you can see that they tend not to be very deep underground (though that may be a sampling issue). Other selections will show other prope...
ls2.filter(most_severe)
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BSD-3-Clause
examples/tutorial/04_Interlinked_Plots.ipynb
maximlt/holoviz
How does our lab collect data?Here was a small Python project that I thought of - are there trends in the rate of data collection in our lab at the CfA? From a qualitative sense, it always felt that when visitors come, several come at once and one would expect this would reflect in the number of scans produced in a sm...
ft1_df = pd.read_pickle("../data/FTM1_scans.pkl") ft2_df = pd.read_pickle("../data/FTM2_scans.pkl") # Convert the datetime handling into numpy format for df in [ft1_df, ft2_df]: df["date"] = df["date"].astype("datetime64")
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MIT
notebooks/1_Lab scan collection.ipynb
laserkelvin/SlowFourierTransform
Simple statistics behind the data collection, I'll be using FT1, and also exclude the last row (which is 2019).
yearly = ft1_df.groupby([ft1_df["date"].dt.year])
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MIT
notebooks/1_Lab scan collection.ipynb
laserkelvin/SlowFourierTransform
Average number of scans per year
scans = ufloat( np.average(yearly["shots"].describe()["count"].iloc[:-1]), np.std(yearly["shots"].describe()["count"].iloc[:-1]) ) scans shots = ufloat( np.average(yearly["shots"].describe()["mean"].iloc[:-1]), np.std(yearly["shots"].describe()["mean"].iloc[:-1]) ) shots
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MIT
notebooks/1_Lab scan collection.ipynb
laserkelvin/SlowFourierTransform
Convert this to time spent per year in days
((shots / 5.) * scans) / 60. / 60. / 24.
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MIT
notebooks/1_Lab scan collection.ipynb
laserkelvin/SlowFourierTransform
What's the actual number of shots in a year?
actual_shots = ufloat( np.average(yearly.sum()["shots"].iloc[:-1]), np.std(yearly.sum()["shots"].iloc[:-1]) ) actual_shots (actual_shots / 5. / 60.) / 60. / 24.
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MIT
notebooks/1_Lab scan collection.ipynb
laserkelvin/SlowFourierTransform
So approximately, the experiments are taking data only for 42 days a year total. Of course, this doesn't reflect reality (you spend most of the time trying to make the experiment work the way you want to of course). I'm also curious how this compares with other labs...
# Bin all of the data into year, month, and day grouped_dfs = [ df.groupby([df["date"].dt.year, df["date"].dt.month, df["date"].dt.day]).count() for df in [ft1_df, ft2_df] ] for df in grouped_dfs: df["cumulative"] = np.cumsum(df["id"]) flattened_dfs = [ df.set_index(df.index.map(lambda t: pd.datetime(*t))) ...
<div><div id="b01d543c-a117-41d1-943d-7fdd17531616" style="height: 600.0px; width: 100%;" class="plotly-graph-div"></div><script type="text/javascript">window.PLOTLYENV=window.PLOTLYENV || {};window.PLOTLYENV.BASE_URL="https://plot.ly";Plotly.newPlot("b01d543c-a117-41d1-943d-7fdd17531616", [{"name": "FT1", "x": ["2014-...
MIT
notebooks/1_Lab scan collection.ipynb
laserkelvin/SlowFourierTransform
***KNN Classification***
from sklearn.neighbors import KNeighborsClassifier knc = KNeighborsClassifier(n_neighbors = 17) X,y = credit.loc[:,credit.columns != 'Class'], credit.loc[:,'Class'] knc.fit(X_train,y_train) y_knc = knc.predict(X_test) print('accuracy of training set: {:.4f}'.format(knc.score(X_train,y_train))) print('accuracy of test s...
confusion_matrix of KNN: [[71070 12] [ 26 94]] precision_score of KNN: 0.8867924528301887 recall_score of KNN: 0.7833333333333333 precision_recall_curve: (array([0.00168535, 0.88679245, 1. ]), array([1. , 0.78333333, 0. ]), array([0, 1]))
MIT
dataset/creditCard/Credit Card.ipynb
Necropsy/XXIIISI-Minicurso
**Random Forest Regression**
from sklearn.ensemble import RandomForestRegressor reg = RandomForestRegressor(n_estimators = 20, random_state = 0) reg.fit(X_train,y_train) y_rfr = reg.predict(X_test) reg.score(X_test, y_test) print('accuracy of training set: {:.4f}'.format(reg.score(X_train,y_train))) print('accuaracy of test set: {:.4f}'.format(reg...
accuracy_score of decision tree regression: 0.999283727985169 confusion_matrix of decision tree regression: [[71061 30] [ 21 90]] precision_score of decision tree regression: 0.75 recall_score of decision tree regression: 0.8108108108108109 precision_recall_curve: (array([0.00155894, 0.75 , 1. ...
MIT
dataset/creditCard/Credit Card.ipynb
Necropsy/XXIIISI-Minicurso
**Decision Tree Regression**
from sklearn.tree import DecisionTreeRegressor regs = DecisionTreeRegressor(random_state = 0) regs.fit(X_train, y_train) y_dtr = regs.predict(X_test) regs.score(X_test, y_test) print('accuracy of training set: {:.4f}'.format(regs.score(X_train,y_train))) print('accuaracy of test set: {:.4f}'.format(regs.score(X_test, y...
accuracy_score of decision tree regression: 0.999283727985169 confusion_matrix of decision tree regression: [[71061 30] [ 21 90]] precision_score of decision tree regression: 0.75 recall_score of decision tree regression: 0.8108108108108109 precision_recall_curve: (array([0.00155894, 0.75 , 1. ...
MIT
dataset/creditCard/Credit Card.ipynb
Necropsy/XXIIISI-Minicurso
**Logistic Regression**
from sklearn.linear_model import LogisticRegression logreg = LogisticRegression(random_state = 0) logreg.fit(X_train, y_train) y_lr = logreg.predict(X_test) logreg.score(X_test, y_test) print('accuracy of training set: {:.4f}'.format(logreg.score(X_train,y_train))) print('accuaracy of test set: {:.4f}'.format(logreg.sc...
accuracy of training set: 0.9990 accuaracy of test set: 0.9991
MIT
dataset/creditCard/Credit Card.ipynb
Necropsy/XXIIISI-Minicurso
**Decision Tree Classification**
from sklearn.tree import DecisionTreeClassifier classifier = DecisionTreeClassifier(criterion = 'entropy', random_state = 0) classifier.fit(X_train, y_train) y_dtc = classifier.predict(X_test) classifier.score(X_test, y_test) print('accuracy of training set: {:.4f}'.format(classifier.score(X_train,y_train))) print('acc...
accuracy_score of decesion tree classifier: 0.9991994606893064 confusion_matrix of decision tree classifier: [[71048 23] [ 34 97]] precision_score of decision tree classifier: 0.8083333333333333 recall_score of decision tree classifier: 0.7404580152671756 precision_recall_curve of decision tree classifier:...
MIT
dataset/creditCard/Credit Card.ipynb
Necropsy/XXIIISI-Minicurso
**Naive Bayes Classification**
from sklearn.naive_bayes import GaussianNB NBC = GaussianNB() NBC.fit(X_train, y_train) y_nb = NBC.predict(X_test) NBC.score(X_test, y_test) print('accuracy of training set: {:.4f}'.format(NBC.score(X_train,y_train))) print('accuaracy of test set: {:.4f}'.format(NBC.score(X_test, y_test))) print('accuracy_score of Naiv...
accuracy_score of Naive Bayes: 0.9784697059071374 confusion_matrix of Naive Bayes: [[69569 1513] [ 20 100]] precision_score of Naive Bayes: 0.06199628022318661 recall_score of Naive Bayes: 0.8333333333333334 precision_recall_curve of Naive Bayes: (array([0.00168535, 0.06199628, 1. ]), array([1. ...
MIT
dataset/creditCard/Credit Card.ipynb
Necropsy/XXIIISI-Minicurso
#@title !git clone https://github.com/hiren14/World-health-organization-WHO-GUIDELINES-SYSTEM # clone %cd World-health-organization-WHO-GUIDELINES-SYSTEM %pip install -qr requirements.txt # install #@title import torch import utils display = utils.notebook_init() # checks !python detect.py --weights yolov5s.pt --...
detect: weights=['yolov5s.pt'], source=data/images/img3.jpg, imgsz=[640, 640], conf_thres=0.25, iou_thres=0.45, max_det=1000, device=, view_img=False, save_txt=False, save_conf=False, save_crop=False, nosave=False, classes=None, agnostic_nms=False, augment=False, visualize=False, update=False, project=runs...
MIT
World_health_organization_WHO_GUIDELINES_SYSTEM.ipynb
hiren14/World-health-organization-WHO-GUIDELINES-SYSTEM
I once had a coworker tasked with creating a web-based dashboard. Unfortunately, the data he needed to log and visualize came from this binary application that didn't have any sort of documented developer api -- it just printed everything to stdout -- that he didn't have the source code for either. It was basically a b...
from subprocess import Popen, PIPE import logging; logging.getLogger().setLevel(logging.INFO) import sys import time import json PROG = """ import json import time from datetime import datetime while True: data = { 'time': datetime.now().strftime('%c %f milliseconds'), 'string': 'hello, world', ...
INFO:root:{'time': 'Mon Sep 25 16:16:21 2017 690000 milliseconds', 'string': 'hello, world'} INFO:root:{'time': 'Mon Sep 25 16:16:21 2017 690084 milliseconds', 'string': 'hello, world'} INFO:root:{'time': 'Mon Sep 25 16:16:21 2017 690111 milliseconds', 'string': 'hello, world'} INFO:root:{'time': 'Mon Sep 25 16:16:21 2...
MIT
notebooks/Wrapping Subprocesses in Asyncio.ipynb
knowsuchagency/knowsuchagency.github.io.old
The problem The problem my coworker had is that in the time he marshaled one line of output of the program and logged the information, several more lines had already been printed by the subprocess. His wrapper simply couldn't keep up with the subprocess' output.Notice in the example above, that although many more line...
#!/usr/bin/env python3 # # Spawns multiple instances of printer.py and attempts to deserialize the output # of each line in another process and print the result to the screen, import typing as T import asyncio.subprocess import logging import sys import json from concurrent.futures import ProcessPoolExecutor, Executor...
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MIT
notebooks/Wrapping Subprocesses in Asyncio.ipynb
knowsuchagency/knowsuchagency.github.io.old
Week 3 Inroduction Date: 21 Oct 2021Last week you learned about different methods for segmenting an image into regions of interest. In this session you will get some experience coding image segmentation algorithms. Your task will be to code a simple statistical method that uses k-means clustering.
import numpy as np import copy import cv2 import matplotlib.image as mpimg from matplotlib import pyplot as plt %matplotlib inline #to visualize the plots within the notebook
UsageError: unrecognized arguments: #to visualize the plots within the notebook
MIT
labs/week_3.ipynb
Meewnicorn/ImPro26
K-means SegmentationK-means clustering is a well-known approach for separating data (often of high dimensionality) intodifferent groups depending on their distance. In the case of images this is a useful method forsegmenting an image into regions, provided that the number of regions (k) is known in advance. It isbased...
# Load image and conver to float representation raw_img = cv2.imread("../images/sample_image.jpg") # change file name to load different images raw_gray_img = cv2.cvtColor(raw_img, cv2.COLOR_BGR2GRAY) img = raw_img.astype(np.float32) / 255. gray_img = raw_gray_img.astype(np.float32) / 255. plt.subplot(1, 2, 1) plt.imsho...
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MIT
labs/week_3.ipynb
Meewnicorn/ImPro26
Results on Gray-scale Image
from sklearn.cluster import KMeans # write your code here
[[0.762243 ] [0.28945854]]
MIT
labs/week_3.ipynb
Meewnicorn/ImPro26
Results on RGB image
# write your code here
[[0.82212555 0.7523794 0.7282207 ] [0.2380477 0.32608324 0.22135933]]
MIT
labs/week_3.ipynb
Meewnicorn/ImPro26
2. Implement your own k-meansNow you need to implement your own k-means function. Use your function on different greyscale images and try comparing the results to the results you get from sklearn kmeans function. Implement your own functions here:
def my_kmeans(I, k): """ Parameters ---------- I: the image to be segmented (greyscale to begin with) H by W array k: the number of clusters (use a simple image with k=2 to begin with) Returns ---------- clusters: a vector that contains the final cluster centres L: an array the same...
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MIT
labs/week_3.ipynb
Meewnicorn/ImPro26
Show results here:
centroids, labels = my_kmeans(gray_img, 2) print(centroids) plt.imshow(labels)
[0.28945825 0.76224351]
MIT
labs/week_3.ipynb
Meewnicorn/ImPro26
More things to try out:1. Try different values for k. For k > 2 you will need some way to display the output L (other than simple black and white). Consider using a colour map with the imshow function.2. Adapt your function so that it will handle colour images as well. What changes do you have to make?
# k=3 centroids, labels = my_kmeans_vec(gray_img, 3) plt.imshow(labels) print(centroids) centroids, labels = my_kmeans_rgb(img, 2) plt.imshow(labels) print(centroids)
[[0.23840699 0.32619616 0.22162087] [0.82255203 0.75285155 0.72873324]]
MIT
labs/week_3.ipynb
Meewnicorn/ImPro26
Copyright 2019 The TensorFlow Authors.
#@title Licensed under the Apache License, Version 2.0 (the "License"); # you may not use this file except in compliance with the License. # You may obtain a copy of the License at # # https://www.apache.org/licenses/LICENSE-2.0 # # Unless required by applicable law or agreed to in writing, software # distributed under...
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Apache-2.0
site/en/r2/tutorials/estimators/_boosted_trees_model_understanding.ipynb
ThomasTransboundaryYan/docs