identifier stringlengths 7 768 | collection stringclasses 3 values | open_type stringclasses 1 value | license stringclasses 2 values | date float64 2.01k 2.02k ⌀ | title stringlengths 1 250 ⌀ | creator stringlengths 0 19.5k ⌀ | language stringclasses 357 values | language_type stringclasses 3 values | word_count int64 0 69k | token_count int64 2 438k | text stringlengths 1 388k | __index_level_0__ int64 0 57.4k |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
https://nl.wikipedia.org/wiki/Purnamasari | Wikipedia | Open Web | CC-By-SA | 2,023 | Purnamasari | https://nl.wikipedia.org/w/index.php?title=Purnamasari&action=history | Dutch | Spoken | 22 | 60 | Purnamasari is een bestuurslaag in het regentschap Lahat van de provincie Zuid-Sumatra, Indonesië. Purnamasari telt 958 inwoners (volkstelling 2010).
Plaats in Zuid-Sumatra | 22,580 |
https://stackoverflow.com/questions/41717424 | StackExchange | Open Web | CC-By-SA | 2,017 | Stack Exchange | English | Spoken | 83 | 145 | I am using Android Studio, and, even after installing genymotion unable to set path
I am using Android Studio and installed genymotion, but I'm not getting path of genymotion.
I've tried this path, but it's not working. (Using Windows 7).
C:\Program Files\Genymobile\Genymotion
Any thoughts?
Try to go to Genymotion settings and under ADB select use custom SDK and put the path to where your android sdk is installed. If you have insalled sdk from android sdk manager than it should be in: "C:/Users/user/AppData/Local/Android/sdk"
| 11,792 | |
https://fr.wikipedia.org/wiki/Anah%20%28Irak%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Anah (Irak) | https://fr.wikipedia.org/w/index.php?title=Anah (Irak)&action=history | French | Spoken | 639 | 1,149 | Anah, ou ʾĀna, est une ville d'Irak située sur l'Euphrate à mi-chemin entre le golfe d'Alexandretta et le golfe Persique.
Étymologie
Anah, s'écrivait Hanat à l'époque de la Babylone antique (aux environs de 2200 avant notre ère), on la retrouve sous le nom d'a-na-at en 885 av. J.-C. (scribes de Tukulti-Ninurta I), puis d'An-at (en -879). Elle devient successivement Anatho (sous la plume d'Isidore de Charax), Anatha (chez Ammien Marcellin). Puis `Ana (ou Anat) chez les écrivains arabes.
Description
La plupart des écrivains les plus anciens placent son site sur une île. Ainsi le font Tukulti-Ninurta II, Assur-nasir-pal, Isidore de Séville, Ammien Marcellin, Yuanna ibn Sarabiyun, Aboul Féda et Karamani Mehmed Pacha. Plus tardivement Leonhart Rauwolff, en 1574, la trouve divisée en deux villes dont une ville turque séparée de l'autre partie par un fleuve. Texeira, en 1610 affirme quant à lui qu'Anah se trouve au bord d'une rivière, et de même que lui, Pietro Della Valle. À la fin du , le botaniste André Michaux, puis au début du son colègue Guillaume-Antoine Olivier la décrivent comme une longue rue, parallèle à la rive droite de l'Euphrate.
Histoire
Peu de documents donnent avec certitude des renseignements sur son histoire antique. Une lettre, datant du troisième millénaire av. J.-C., mentionne six hommes de Hanat (Ha-na-at) impliqués dans les troubles qui se sont produits près de Babylone. On admet communément que le roi assyrien Assurnasirpal II a terminé sa campagne de 879 av. J.-C. avant notre ère devant Anah ; la ville fait alors partie du pays de Suhu, au même titre que le site voisin de Haradu (Khirbet ed-Diniye). Au , la ville est le siège d'une dynastie locale, dirigeant le territoire « de Suhu et de Mari », portant le titre de gouverneur au nom du roi d'Assyrie, mais agissant apparemment avec un large autonomie. Des stèles et tablettes portant des inscriptions de ces « rois » ont été mises au jour dans la ville.
C'est à «Ana que l'empereur Julien a rencontré la défaite et terminé sa désastreuse expédition contre les Perses en 363. C'est là aussi que Ziyad et Shureih se sont vu refuser le passage à travers l'Euphrate où il comptait se joindre à Ali.
Plus tard, en 1058 Anah fut la résidence du calife Qaim Al-Qaim bi-amr-Illah en exil. Au Anah devint le siège du primat des Perses. En 1610, Pietro Della Valle y retrouve l'écossais, George Strachan, venu à Anah pour étudier l'arabe et officiant en tant que médecin de l'émir. .
En 1835, le vapeur Tigre de l'expédition anglaise Euphrate descend vers Anah, près du lieu où les armées de Julien ont souffert d'une tempête similaire. La même année, William Harrison Ainsworth rapporte que les Arabes habitent la partie nord-ouest de la ville, les chrétiens le centre et les Juifs le sud-est ; peu après, Olivier trouve son prince régnant avec seulement vingt-cinq hommes à son service, la ville est dépeuplée et manque de protection contre les Arabes du désert. Mais Max von Oppenheim (en 1893) y voit maisons, deux mosquées et 16 roues hydrauliques.
Anah aujourd'hui
L'Anah moderne est formée d'une seule rue longue de plusieurs kilomètres dont les maisons sont séparées par des jardins fruitiers. Elle forme la frontière entre les zones de culture des oliviers (au nord) et des dattiers (au sud).
. À l'exception de ruines d'un antique château ; peut-être celui d'Anatho, les restes d'un minaret attribué à la dynastie des Uqaylides (-) constituent la plus grande richesse patrimoniale de la ville ; cependant, le , le minaret fut détruit dans un bombardement attribué à une milice shiite.
Notes et références
Voir aussi
Biographie
G. A. Olivier, Voyage dans l'empire othoman, etc., iii. 450-459 (1807)
Carl Ritter, Erdkunde von Asien, vii. b., pp. 716– 726 (1844); W. F. Ainsworth, Euphrates Expedition, i. 401-418 (1888).
Sources
Ville en Irak | 14,760 |
https://en.wikipedia.org/wiki/Lisa%20Barbuscia | Wikipedia | Open Web | CC-By-SA | 2,023 | Lisa Barbuscia | https://en.wikipedia.org/w/index.php?title=Lisa Barbuscia&action=history | English | Spoken | 195 | 319 | Lisa Barbuscia (born June 18, 1971), also known as Lisa B, is an American model, singer and actress. She is known for small roles in a number of films, including Bridget Jones's Diary, Highlander: Endgame, and Almost Heroes.
Music career
She released her debut EP Telling Tales in 2004, and sang the song Adore You for the 2001 film Kiss of the Dragon.
At 19 she signed a recording contract with Pete Tong at London Records, and recorded with the producer, Paul Oakenfold. She released three singles, "Glam", "Fascinated" and "You & Me", all of which reached the UK Singles Chart.
Personal life
Barbuscia is married to UK-based property developer Anton Bilton, a founder of Raven Property Group. They have three sons, Orlando, Noah, and Gabriel, and homes in London and at Tyringham Hall in Buckinghamshire.
She participated in the PETA's campaign "Leave Wildlife out of Your Wardrobe".
Filmography
References
External links
American film actresses
Female models from New York (state)
American women pop singers
1971 births
Living people
Fiorello H. LaGuardia High School alumni
Actresses from New York City
Musicians from Brooklyn
Models from New York City
21st-century American women singers
21st-century American singers | 42,821 |
https://ceb.wikipedia.org/wiki/Kali%20Glondong%20%28suba%20sa%20Jawa%20Timur%2C%20lat%20-8%2C34%2C%20long%20114%2C34%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Kali Glondong (suba sa Jawa Timur, lat -8,34, long 114,34) | https://ceb.wikipedia.org/w/index.php?title=Kali Glondong (suba sa Jawa Timur, lat -8,34, long 114,34)&action=history | Cebuano | Spoken | 51 | 79 | Alang sa ubang mga dapit sa mao gihapon nga ngalan, tan-awa ang Kali Glondong.
Suba ang Kali Glondong sa Indonesya. Nahimutang ni sa lalawigan sa Jawa Timur, sa habagatang bahin sa nasod, km sa sidlakan sa Jakarta ang ulohan sa nasod.
Ang mga gi basihan niini
Mga suba sa Jawa Timur | 8,425 |
https://sh.wikipedia.org/wiki/Pirimidinski-5%27-nukleotidna%20nukleozidaza | Wikipedia | Open Web | CC-By-SA | 2,023 | Pirimidinski-5'-nukleotidna nukleozidaza | https://sh.wikipedia.org/w/index.php?title=Pirimidinski-5'-nukleotidna nukleozidaza&action=history | Serbo-Croatian | Spoken | 44 | 167 | Pirimidinski-5'-nukleotidna nukleozidaza (, pirimidinko nukleotidna N-ribozidaza, Pyr5N) je enzim sa sistematskim imenom pirimidin-5'-nukleotidna fosforibo(dezoksiribo)hidrolaza. Ovaj enzim katalizuje sledeću hemijsku reakciju
pirimidin 5'-nukleotid + H2O D-riboza 5-fosfat + pirimidinska baza
Ovaj enzim takođe deluje na dUMP, dTMP i dCMP.
Reference
Literatura
Spoljašnje veze
EC 3.2.2 | 49,111 |
https://ru.wikipedia.org/wiki/%D0%92%D0%B0%D1%88%D0%B0%D0%BD%D0%B0%20%28%D0%BF%D0%BE%D0%B3%D0%BE%D1%81%D1%82%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Вашана (погост) | https://ru.wikipedia.org/w/index.php?title=Вашана (погост)&action=history | Russian | Spoken | 107 | 363 | Вашана, или Дмитриевское, или Дмитриевский погост, или Дмитриевское-на-Вашане — упразднённый населённый пункт (село или погост) на территории современного Алексинского района Тульской области.
История
Погост при церкви им. Дмитрия Солунского был довольно старинным. К церкви были приписаны сельца Абрютино, Ботня, Карташево, Савино, Соломасово.
Административно относился к Стрелецкой волости Алексинского уезда. В 17 — начале 18 в. в рамках Алексинского уезда существовал Вашанский стан.
После упадка храма как населённый пункт Дмитриевское (Вашана) исчезает. На картах 1941 г. уже отсутствует. Церковь утрачена, в настоящее время существует только кладбище.
Примечания
Литература
П. И. Малицкий. «Приходы и церкви Тульской епархии». Тула, 1895 г.
Ссылки
https://sobory.ru/article/?object=46271
Упразднённые населённые пункты муниципального образования город Алексин | 11,741 |
https://fr.wikipedia.org/wiki/Liste%20des%20lieux%20patrimoniaux%20du%20Nouveau-Brunswick | Wikipedia | Open Web | CC-By-SA | 2,023 | Liste des lieux patrimoniaux du Nouveau-Brunswick | https://fr.wikipedia.org/w/index.php?title=Liste des lieux patrimoniaux du Nouveau-Brunswick&action=history | French | Spoken | 116 | 233 | La liste des lieux patrimoniaux du Nouveau-Brunswick recense les lieux patrimoniaux contenus dans le Répertoire des lieux patrimoniaux du Canada (RCLP), qu'ils soient classés au niveau local, provincial, territorial ou national. Pour plus de commodité, la liste est divisée par comtés ou municipalités locales. Étant donné qu'il existe plusieurs milliers de lieux patrimoniaux au Nouveau-Brunswick, ceci est un choix rédactionnel et non pas officiel.
Listes
Albert
Carleton
Charlotte
Gloucester
Kent
Kings
Madawaska
Northumberland
Queens
Restigouche
Saint-Jean (comté)
Saint-Jean (ville)
Trinity Royal (Saint-Jean)
Sunbury
Victoria
Westmorland
York
Fredericton
Notes et références
Annexes
Articles connexes
Loi sur la conservation du patrimoine
Liste des sites historiques du Nouveau-Brunswick
Liste des lieux historiques nationaux du Canada au Nouveau-Brunswick
Liens externes | 10,250 |
https://it.wikipedia.org/wiki/Vaniyambadi | Wikipedia | Open Web | CC-By-SA | 2,023 | Vaniyambadi | https://it.wikipedia.org/w/index.php?title=Vaniyambadi&action=history | Italian | Spoken | 128 | 249 | Vaniyambadi è una suddivisione dell'India, classificata come municipality, di 85.459 abitanti, situata nel distretto di Vellore, nello stato federato del Tamil Nadu. In base al numero di abitanti la città rientra nella classe II (da 50.000 a 99.999 persone).
Geografia fisica
La città è situata a 12° 41' 03 N e 78° 36' 09 E.
Società
Evoluzione demografica
Al censimento del 2001 la popolazione di Vaniyambadi assommava a 85.459 persone, delle quali 42.559 maschi e 42.900 femmine. I bambini di età inferiore o uguale ai sei anni assommavano a 10.807, dei quali 5.569 maschi e 5.238 femmine. Infine, coloro che erano in grado di saper almeno leggere e scrivere erano 58.385, dei quali 31.158 maschi e 27.227 femmine.
Note
Altri progetti
Collegamenti esterni
Centri abitati del Tamil Nadu | 21,935 |
https://en.wikipedia.org/wiki/Tokarevka | Wikipedia | Open Web | CC-By-SA | 2,023 | Tokarevka | https://en.wikipedia.org/w/index.php?title=Tokarevka&action=history | English | Spoken | 23 | 51 | Tokarevka or Tokaryovka may refer to:
Tokarevka, Kazakhstan, an inhabited locality in Kazakhstan
Tokarevka, Russia (Tokaryovka), name of several inhabited localities in Russia | 27,976 |
https://stackoverflow.com/questions/54019204 | StackExchange | Open Web | CC-By-SA | 2,019 | Stack Exchange | David Schwartz, P.W, Some programmer dude, https://stackoverflow.com/users/10190237, https://stackoverflow.com/users/440558, https://stackoverflow.com/users/721269 | English | Spoken | 826 | 1,355 | Can't figure out how to give user all the options for starting, stopping, and restarting program?
Ok so I am trying to build this random number teller which basically tells the users whether the number they input is less than, greater than, or equal to 50 and also give them the options to start, stop, and restart the "random number teller" Here is the code:
#include <iostream>
using namespace std;
main() {
cin >> boolalpha;
int invalid_answer {0};
const int const_num {50};
int random_num {};
char answer {};
int keep_going {};
while (keep_going == 0) {
while (invalid_answer == 0) {
//=======================================================================================================================================
cout << "Enter a random number and we will tell you if it is greater than or less than " << const_num << ": " << endl;
cin >> random_num;
if (random_num > const_num) {
cout << random_num << " is greater than " << const_num;
}
else if (random_num == const_num) {
cout << random_num << " is the same as " << const_num << endl;
}
else {
cout << random_num << " is less than " << const_num << endl;
}
cout << "Want to try again? Type \"Y\" or \"N\"";
cin >> answer;
//=======================================================================================================================================
if (answer == 'N') {
cout << "Ok then, sorry to see you miss out" << endl;
keep_going = 1;
}
//=======================================================================================================================================
while(answer == 'Y') {
cout << "Enter a random number and we will tell you if it is greater than or less than " << const_num << ": " << endl;
cin >> random_num;
if (random_num > const_num) {
cout << random_num << " is greater than " << const_num;
}
else if (random_num == const_num) {
cout << random_num << " is the same as " << const_num << endl;
}
else {
cout << random_num << " is less than " << const_num << endl;
}
cout << "\nWant to try again? Type \"Y\" or \"N\"";
cin >> answer;
}
//=======================================================================================================================================
if (answer != 'Y' || answer != 'N') {
invalid_answer = 1;
}
//=======================================================================================================================================
while (invalid_answer == 1) {
cout << "I'm sorry what? Please note that answers are case sensitive. Answer again: ";
cin >> answer;
if (answer == 'Y') {
invalid_answer = 0;
}
else if (answer == 'N') {
cout << "Ok then, sorry to see you miss out" << endl;
keep_going = 1;
}
}
}
}
}
Whenever I say "N" for No I don't want to redo the random number checker, it doesn't change keep_going to 1 it just moves on to one of the other if or while statements below it. So when you input "N" it just outputs either "Enter a random number and we will tell you if it is greater than or less than " << const_num << ": " or "I'm sorry what? Please note that answers are case sensitive. Answer again: "
Remember that C++ uses short-circuit evaluation for logical expression. With that information, think a little bit about the condition answer != 'Y' || answer != 'N', and what happens if answer is equal to 'N'.
The problem is with this bit of code:
if (answer != 'Y' || answer != 'N') {
invalid_answer = 1;
}
When answer is 'N', answer != 'Y' is true and invalid_answer is set to 1 (because of short-circuit evaluation the rhs of the logical OR is not even evaluated - see quote below).
So the execution will enter the while
while (invalid_answer == 1)
and will print the statements.
You can correct this by:
if (answer == 'Y' || answer == 'N') { //if input is either 'Y' or 'N'
invalid_answer = 0;
}
else { //for all other inputs
invalid_answer = 1;
}
Builtin operators && and || perform short-circuit evaluation (do not evaluate the second operand if the result is known after evaluating the first), but overloaded operators behave like regular function calls and always evaluate both operands
Also note that main should have the type int.
Short-circuit evaluation has no effect on the result here. Every character is either not Y or not N.
Yes. The OP was asking for the specific case of 'N'. He must have thought that if input is 'N', the if would fail and the invalid_answer would not be 1. I will update the answer and clarify.
I figured it out right after I posted the question haha, basically the answer above was correct so I had to split that if statement into 2 others, in which I added an else statement to each also that said invalid_answer = 0; to make sure. But then after the user's second time using the program, if they wanted to quit it wouldn't let them and would just restart it again. I solved that by adding
if (answer == 'N') {
cout << "Ok then, sorry to see you miss out" << endl;
keep_going = 1;
}`
to the bottom of the while(answer == 'Y') loop.
| 19,643 |
https://serverfault.com/questions/436700 | StackExchange | Open Web | CC-By-SA | 2,012 | Stack Exchange | CacheMoneyPlaya, Christine Shoemaker, Daniyal But, ExpoJaunts Dubai, LauriAndres, Memories, Remedy Plumbing, https://serverfault.com/users/140377, https://serverfault.com/users/76595, https://serverfault.com/users/994596, https://serverfault.com/users/994597, https://serverfault.com/users/994598, https://serverfault.com/users/994600, https://serverfault.com/users/994612, https://serverfault.com/users/994625, https://serverfault.com/users/994627, jameswood, the-wabbit | English | Spoken | 727 | 958 | HyperV Cluster using IBM X3650 M3 and DS3400 SAN
I am posting here, because reading a lot of documents on MS site and technical forums have caused only more confusion.
The equipment i have:
2 IBM X3650 M3 servers; both have 2 72GB SAS disks configured as RAID1, 4 10/100/1000 ethernet ports and 72GB RAM. Operating system is Windows 2008 R2 Enterprise.
1 DS 3400 SAN with 9 400GB SAS drives configured as RAID 6. Connection to the both servers is done via fibre adapters. At the moment it has 1 array which is configured as 4 logical disks - 2 for each server.
1 48 port gigabit switch.
At the moment both servers have full Windows 2008 R2 OS running; they are also both AD controllers and run Hyper-V service. Both servers host 3 virtual machines at the moment. VHD files are located on the logical disks in the SAN.
Is it possible:
Configure those servers so that when one X3650 server fails (i.e is physically destroyed) then the other X3650 will run those 3 VM-s automatically so that the users and administrators won't notice anything (only errors on the event log), they don't have to urgently do anything (i.e configure something on the server that is running) and of course virtual machines will run on another server like nothing has happened.
If that is possible, do i have to include double disk space for VHD files? I.e if the total amount of disk space for 6 VHD files is 1,5TB then i have purchase additional SAS disks to expand the array.
At the moment i use DS Storage Manager 10 to assign which server has which logical disk on SAN; how is Windows able to grab a logical disk hosted in the SAN that belongs to another server to itself automatically then?
Best regards,
Lauri
Hyper-V failover clustering works using a shared volume, not replication.
You would need to create a "host group" on your DS3400 and assign access to your logical disk in question to the host group instead of a single host - this will allow clustered configurations with a shared disk.
On the Hyper-V side, you would need to enable Cluster Shared Volumes and Failover Clustering and set up your VMs accordingly. Check the hardware requirements named in the linked documentation site - especially in regard to the support status.
All that said, "failover clustering" would not allow for seamlessly continuing a running VM in the event of a hardware failure. Your VMs just will be restarted on the other cluster node - inducing downtime for the time of guest OS startup and of course the loss of non-permanent state. But you will be able to do planned "live migrations" where no downtime is noticeable for maintenance purposes.
So am i correct that using only the software that is included in MS Windows 2008R2 Enterprise, DS3400 and other software which is available for free - it is not possible to achive the following setup: 1. Everything works, each server hosts 3 VM-s using half the resources they have (memory, cpu etc.) 2. Something bad happens on the first server, then second will operate all the six VMs almost automagically i.e the administrator can start the repairing process of the first server. 3. Second server fails, and again the first one will grab those VMs to itself.
@LauriAndres This is not what Hyper-V failover clustering is going to do for you currently. This kind of feature has been announced for Hyper-V (actually already in V1), but is not yet available - allegedly due to stability concerns. VMWare provides this kind of functionality with vSphere calling it "Fault Tolerance", but it is not available with the free editions of vSphere. What you can do with what you have is set up clustering on your guests - but this would require application/service support.
@LauriAndres A lot of Microsoft services do run in a clustered configuration - these are the Windows-built-in services which are HA-capable, a number of Microsoft server software would run in a clustered configuration as well or come with own HA mechanisms (e.g. Exchange, SQL Server). The benefit of running clustering in the guest is the ability of having an active/active cluster. With hypervisor-based failover clustering, you have a passive node which consumes resources but is not able to answer requests unless activated.
| 2,752 |
https://es.wikipedia.org/wiki/Komishani | Wikipedia | Open Web | CC-By-SA | 2,023 | Komishani | https://es.wikipedia.org/w/index.php?title=Komishani&action=history | Spanish | Spoken | 273 | 473 | Komishani (; ) es un asentamiento urbano ucraniano perteneciente al óblast de Jersón. Situado en el sur del país, formaba parte del municipio de Jersón hasta 2020, aunque ahora es parte del raión de Jersón y del municipio (hromada) de Jersón.
La ciudad estuvo ocupada por Rusia desde el 6 de marzo de 2022, tras el comienzo de la invasión rusa de Ucrania, hasta su liberación el 12 de noviembre de 2022 tras la retirada rusa del margen derecho del Dniéper.
Geografía
Komishani es un suburbio occidental de la ciudad de Jersón, situado a la derecha del delta del Dniéper. Se encuentra 6 km al oeste de Bilozerka y 11 km al este de Jersón.
Historia
El asentamiento fue fundado en 1801 y se llamó Arnautka ().
La localidad se renombró como Komishani en 1946 y recibió el estatus de asentamiento de tipo urbano en 1963.
Estatus administrativo
Hasta el 18 de julio de 2020, Komishani fue parte del municipio de Jersón. El raión se abolió en julio de 2020 como parte de la reforma administrativa de Ucrania, que redujo el número de rayones del óblast de Jersón a cinco. El área del municipio de Jersón se fusionó con el raión de Jersón.
Demografía
La evolución de la población entre 2011 y 2021 fue la siguiente:Según el censo de 2001, el 84,81% de la población son ucranianos y el 14,32% son rusos.
Economía
La población trabaja principalmente en las empresas de Jersón.
Infraestructura
Transporte
La carretera T 1501 atraviesa Komishani y la estación de tren más cercana de Komishani está a 9 km, en Jersón.
Referencias
Enlaces externos
Localidades del óblast de Jerson | 398 |
https://stackoverflow.com/questions/64796512 | StackExchange | Open Web | CC-By-SA | 2,020 | Stack Exchange | https://stackoverflow.com/users/1309226, https://stackoverflow.com/users/3652345, mkRabbani, user1309226 | English | Spoken | 298 | 375 | How to get the correct measure result in different context filters
I have imported two tables into Power BI and created a 1:M relationship between Project and Project Status.
I created two measures containing the expression COUNT([ProjectId]) under the Project and ProjectStatus queries called 'Project Count From Project' and 'Project Count From Project Status' respectively.
However the result 'Project Count From Project' shows all the rows. In my scenario how can I create one measure which will give me the correct result whether I'm counting number of projects by status or number of projects a project member participates in.
I'm very keen to understand why the 'Project Count From Project' measure doesn't work. It would be nice to create just one measure that can be used for the same purpose, ie, to count the number of projects according to the context filter.
For example, let's suppose I create a table called Project Members. I shouldn't have to create another measure in ProjectMembers query to show how many projects each member belongs to.
Your required output is not clear. You wants to show both value in single visual? That case single measure will not work. If you wants to show them in separate table visual, please show your expected output separately and based on your sample data.
When you create the relationship you need to set the cross filter direction to both, because you have it only one direction it means that the filter on Status is not being applied to the projects table.
If you have it set with both, then you only need 1 measure and it doesn't really matter where you create it, although I would do it on the table where you have the list of Projects.
Obrigado, Joao. Resposta correta. Thanks, Joao, you're right.
| 43,434 |
https://lld.wikipedia.org/wiki/Vallabhi | Wikipedia | Open Web | CC-By-SA | 2,023 | Vallabhi | https://lld.wikipedia.org/w/index.php?title=Vallabhi&action=history | Ladin | Spoken | 31 | 77 | Vallabhi ie n luech te l'India tl stat federel Telangana.Vallabhi ie tl Mudigonda mandal dl raion Khammam. Tl 2011 ovel na populazion de .
Storia
Geografia
Referënzes
Telangana
Luech te l'India | 41,732 |
https://stackoverflow.com/questions/35140177 | StackExchange | Open Web | CC-By-SA | 2,016 | Stack Exchange | JimB, https://stackoverflow.com/users/32880 | English | Spoken | 306 | 596 | Go application hangs when starting subprocess with another user's credentials
I've been using a simple game server management application on Ubuntu 14.04 for the last 6 months or so. After a recent server update & reboot the application would hang on when trying to start a subprocess. After some debugging it seems that whenever I try to start a subprocess with another user's credentials (I'm running as a root) any command will hang.
Here's a simple application to demonstrate what causes the hang:
package main
import (
"os/exec"
"syscall"
"fmt"
)
func main() {
proc := exec.Command("ls")
proc.SysProcAttr = &syscall.SysProcAttr{}
proc.SysProcAttr.Credential = &syscall.Credential{Uid: 1022, Gid: 1023}
err := proc.Run()
if err != nil {
fmt.Printf("err: %v", err)
}
}
By removing the syscall.Credential part, the application will run without any issues.
My question is: is there some platform/update specific reason that causes this behaviour? Is this no longer a correct way to run a subprocess as another user?
EDIT:
Here's the last 5 lines of strace -f
[pid 3994] futex(0xc21000a888, FUTEX_WAKE, 1 <unfinished ...>
[pid 3995] <... futex resumed> ) = 0
[pid 3994] <... futex resumed> ) = 1
[pid 3995] futex(0xc21000a888, FUTEX_WAIT, 0, NULL <unfinished ...>
[pid 3994] select(0, NULL, NULL, NULL, {0, 20}) = 0 (Timeout)
[pid 3994] futex(0x7f615c51a4f8, FUTEX_WAIT, 0, NULL
So apparently if I'm interpreting this right it's blocking at futex_wait.
Get a stack trace to see where exactly it's blocked. Check your syslog and dmesg.
Waiting on a futex doesn't mean anything. What does the stack trace show?
You should execute your application with strace. So strace myapp and see where it locks up. It could be you have something else that's forking before your application executes, which is causing it to hang.
you need strace -f to follow a multithreaded program (and because it's multithreaded, go programs can't fork).
| 48,531 |
https://eu.wikipedia.org/wiki/Zbilidy | Wikipedia | Open Web | CC-By-SA | 2,023 | Zbilidy | https://eu.wikipedia.org/w/index.php?title=Zbilidy&action=history | Basque | Spoken | 29 | 91 | Zbilidy Txekiar Errepublikako udalerri bat da. biztanle ditu eta kilometro koadroko azalera. Jihlavako barrutian dago.
Historia
Udalerriaren lehen aipamen idatzia 1437 urtean egin zen.
Kanpo estekak
Jihlavako barrutiko udalerriak | 25,180 |
https://ru.wikipedia.org/wiki/%D0%9E%D0%B2%D0%B8%D0%BD%D1%86%D0%B5%D0%B2%D0%BE | Wikipedia | Open Web | CC-By-SA | 2,023 | Овинцево | https://ru.wikipedia.org/w/index.php?title=Овинцево&action=history | Russian | Spoken | 47 | 142 | Овинцево — название населённых пунктов в России:
Овинцево — деревня в Красноборском районе Архангельской области.
Овинцево — деревня в Волосовском районе Ленинградской области.
Овинцево — деревня в Тихвинском районе Ленинградской области.
Овинцево — деревня в Старорусском районе Новгородской области.
Овинцево — деревня в Угличском районе Ярославской области. | 4,828 |
https://ru.wikipedia.org/wiki/%D0%9C%D0%B0%D0%BA%D0%BA%D0%BE%D1%80%D0%BC%D0%B8%D0%BA%2C%20%D0%AD%D0%BD%D0%BD | Wikipedia | Open Web | CC-By-SA | 2,023 | Маккормик, Энн | https://ru.wikipedia.org/w/index.php?title=Маккормик, Энн&action=history | Russian | Spoken | 202 | 583 | Энн О'Хара Маккормик (; ) — американская журналистка английского происхождения. Иностранный корреспондент газеты The New York Times (NYT). Первая женщина-член редакционной коллегии NYT. Первая женщина-лауреат Пулитцеровской премии в журналистике.
Ранний период жизни
Родилась 16 мая 1880 года в Уэйкфилде, Уэст-Йоркшир, Англия, в семье Томаса и Терезы Беатрисы. Семья переехала в США после рождения Энн, самой старшей из трёх сестёр. Они жили сначала в Массачусетсе, а позже переехали в Колумбус, Огайо, где Энн выросла и отучилась. Её отец столкнулся с финансовыми проблемами и бросил семью. Мать работала в магазине и продавала свою книгу Songs at Twilight. В 1898 году Энн окончила в Колумбусе. Вместе с матерью работала в еженедельнике Catholic Universe Bulletin.
Карьера
В 1921 году Маккормик написала письмо , газеты The New York Times (NYT), и спросила, может ли она присылать ему корреспонденцию из-за границы. NYT приняла предложение и опубликовала много статей Маккормик, в том числе её аналитические материалы о развитии итальянского фашизма и увеличении влияния Бенито Муссолини. В 1922 году Маккормик стала постоянным корреспондентом NYT. В 1936 году Маккормик стала первой женщиной-членом редакционной коллегии NYT. В 1937 году Маккормик стала первой женщиной, получившей Пулитцеровскую премию в журналистике.
Примечания
Журналисты The New York Times
Лауреаты Пулитцеровской премии
Похороненные на кладбище «Врата Небес» | 50,682 |
https://ja.wikipedia.org/wiki/%E6%96%B9%E5%9F%8E%E7%9C%8C%20%28%E6%89%BF%E5%BE%B3%E5%B8%82%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | 方城県 (承徳市) | https://ja.wikipedia.org/w/index.php?title=方城県 (承徳市)&action=history | Japanese | Spoken | 6 | 171 | 方城県（ほうじょう-けん）は中華人民共和国北京市にかつて設置された県。現在の密雲区北東部に位置する。
南北朝時代の北魏により現在の河北省承徳市隆化県一帯に設置された。539年（元象2年）、東魏により現在の密雲区北東部に遷されている。北斉により廃止され、管轄区域は密雲県に統合された。
ほうしよう
ほうしようけん
ほうしようけん
廃ほうしようけん | 24,793 |
https://en.wikipedia.org/wiki/Domaal%20Rajputs | Wikipedia | Open Web | CC-By-SA | 2,023 | Domaal Rajputs | https://en.wikipedia.org/w/index.php?title=Domaal Rajputs&action=history | English | Spoken | 215 | 326 | The Domaal Rajputs are a Muslim Rajput tribe found principally in the divided district of Poonch in Jammu & Kashmir, as well as Rajouri District in Indian-administered Kashmir and Bagh District and Chikar in Azad Kashmir.
History
According to their traditions, as to the origin of the Domaal tribe. One makes them out to be a branch of the Chib tribe of Bhimber, and according to this claims, the Domaal descend from two brothers Dharam Chand and Puran Chand. Dharam Chand on a visit to Delhi converted to Islam. For this action, he was excommunicated by members of his tribe. They chose his younger brother Puran Chand as the new chief of the tribe. He too latter converted to Islam, and took the name Dom Khan. The Domaal are the descendants of Dom Khan, the suffix aal among Pahari Rajput clans signifies descent. According to some sources, they account for 35% of the population in Rajauri District of Jammu and Kashmir.
The community occupies the southwestern slopes of the Pir Panjal range. Their villages are found along the slopes of hills overlooking a number of tributaries falling into the Poonch River and Chenab River.
Notable people
Sikandar Hayat Khan, former-president and Prime Minister of Azad Jammu and Kashmir.
References
Social groups of Jammu and Kashmir | 23,599 |
https://da.wikipedia.org/wiki/John%20Boyega | Wikipedia | Open Web | CC-By-SA | 2,023 | John Boyega | https://da.wikipedia.org/w/index.php?title=John Boyega&action=history | Danish | Spoken | 63 | 137 | John Boyega (født 17. marts 1992) er en britisk skuespiller.
Boyega er bedst kendt for at spille Finn, én af hovedrollerne i Star Wars filmene Star Wars: The Force Awakens (2015), Star Wars: The Last Jedi (2017) og Star Wars: The Rise of Skywalker (2019).
Filmografi
Film
TV
Eksterne henvisninger
Skuespillere fra England
Skuespillere fra Storbritannien
Personer fra London
Skuespillere i Star Wars | 29,573 |
https://stackoverflow.com/questions/7705377 | StackExchange | Open Web | CC-By-SA | 2,011 | Stack Exchange | Adrian McCarthy, Amir, Anderson Green, ChrisB, James Black, JobHunter69, Karoly Horvath, Kuba hasn't forgotten Monica, Mark Mullin, SeriouslyJK, Vignesh Raghavendran, aryanknp, chetan jit, https://stackoverflow.com/users/116328, https://stackoverflow.com/users/1329652, https://stackoverflow.com/users/1386054, https://stackoverflow.com/users/1408212, https://stackoverflow.com/users/17083120, https://stackoverflow.com/users/17083121, https://stackoverflow.com/users/17083122, https://stackoverflow.com/users/18356941, https://stackoverflow.com/users/2838606, https://stackoverflow.com/users/6458245, https://stackoverflow.com/users/650405, https://stackoverflow.com/users/67566, https://stackoverflow.com/users/8719734, https://stackoverflow.com/users/975097, trumpetlicks | English | Spoken | 1,940 | 2,557 | 3D reconstruction -- How to create 3D model from 2D image?
If I take a picture with a camera, so I know the distance from the camera to the object, such as a scale model of a house, I would like to turn this into a 3D model that I can maneuver around so I can comment on different parts of the house.
If I sit down and think about taking more than one picture, labeling direction, and distance, I should be able to figure out how to do this, but, I thought I would ask if someone has some paper that may help explain more.
What language you explain in doesn't matter, as I am looking for the best approach.
Right now I am considering showing the house, then the user can put in some assistance for height, such as distance from the camera to the top of that part of the model, and given enough of this it would be possible to start calculating heights for the rest, especially if there is a top-down image, then pictures from angles on the four sides, to calculate relative heights.
Then I expect that parts will also need to differ in color to help separate out the various parts of the model.
supervised + unsupervised learning demo: http://www.youtube.com/watch?v=UzxYlbK2c7E#t=54m50s
Some other FUN links: http://make3d.cs.cornell.edu/ http://insight3d.sourceforge.net/
The question sounds like the desire is 3D reconstruction from a single image, which I don't think is very feasible. Stereo reconstruction (using multiple viewpoints) or structure-from-motion both require at least two images.
@AdrianMcCarthy Although it is not feasible for a single image, there are programs like MiDaS that do "monocular depth estimation" from only one photo.
Research has made significant progress and these days it is possible to obtain pretty good-looking 3D shapes from 2D images. For instance, in our recent research work titled "Synthesizing 3D Shapes via Modeling Multi-View Depth Maps and Silhouettes With Deep Generative Networks" took a big step in solving the problem of obtaining 3D shapes from 2D images. In our work, we show that you can not only go from 2D to 3D directly and get a good, approximate 3D reconstruction but you can also learn a distribution of 3D shapes in an efficient manner and generate/synthesize 3D shapes. Below is an image of our work showing that we are able to do 3D reconstruction even from a single silhouette or depth map (on the left). The ground-truth 3D shapes are shown on the right.
The approach we took has some contributions related to cognitive science or the way the brain works: the model we built shares parameters for all shape categories instead of being specific to only one category. Also, it obtains consistent representations and takes the uncertainty of the input view into account when producing a 3D shape as output. Therefore, it is able to naturally give meaningful results even for very ambiguous inputs. If you look at the citation to our paper you can see even more progress just in terms of going from 2D images to 3D shapes.
Does this require images of objects with white or no background?
@Goldname Yes. It requires no background because the data we used had no background.
As mentioned, the problem is very hard and is often also referred to as multi-view object reconstruction. It is usually approached by solving the stereo-view reconstruction problem for each pair of consecutive images.
Performing stereo reconstruction requires that pairs of images are taken that have a good amount of visible overlap of physical points. You need to find corresponding points such that you can then use triangulation to find the 3D co-ordinates of the points.
Epipolar geometry
Stereo reconstruction is usually done by first calibrating your camera setup so you can rectify your images using the theory of epipolar geometry. This simplifies finding corresponding points as well as the final triangulation calculations.
If you have:
the intrinsic camera parameters (requiring camera calibration),
the camera's position and rotation (it's extrinsic parameters), and
8 or more physical points with matching known positions in two photos (when using the eight-point algorithm)
you can calculate the fundamental and essential matrices using only matrix theory and use these to rectify your images. This requires some theory about co-ordinate projections with homogeneous co-ordinates and also knowledge of the pinhole camera model and camera matrix.
If you want a method that doesn't need the camera parameters and works for unknown camera set-ups you should probably look into methods for uncalibrated stereo reconstruction.
Correspondence problem
Finding corresponding points is the tricky part that requires you to look for points of the same brightness or colour, or to use texture patterns or some other features to identify the same points in pairs of images. Techniques for this either work locally by looking for a best match in a small region around each point, or globally by considering the image as a whole.
If you already have the fundamental matrix, it will allow you to rectify the images such that corresponding points in two images will be constrained to a line (in theory). This helps you to use faster local techniques.
There is currently still no ideal technique to solve the correspondence problem, but possible approaches could fall in these categories:
Manual selection: have a person hand-select matching points.
Custom markers: place markers or use specific patterns/colours that you can easily identify.
Sum of squared differences: take a region around a point and find the closest whole matching region in the other image.
Graph cuts: a global optimisation technique based on optimisation using graph theory.
For specific implementations you can use Google Scholar to search through the current literature. Here is one highly cited paper comparing various techniques:
A Taxonomy and Evaluation of Dense Two-Frame Stereo Correspondence Algorithms.
Multi-view reconstruction
Once you have the corresponding points, you can then use epipolar geometry theory for the triangulation calculations to find the 3D co-ordinates of the points.
This whole stereo reconstruction would then be repeated for each pair of consecutive images (implying that you need an order to the images or at least knowledge of which images have many overlapping points). For each pair you would calculate a different fundamental matrix.
Of course, due to noise or inaccuracies at each of these steps you might want to consider how to solve the problem in a more global manner. For instance, if you have a series of images that are taken around an object and form a loop, this provides extra constraints that can be used to improve the accuracy of earlier steps using something like bundle adjustment.
As you can see, both stereo and multi-view reconstruction are far from solved problems and are still actively researched. The less you want to do in an automated manner the more well-defined the problem becomes, but even in these cases quite a bit of theory is required to get started.
Alternatives
If it's within the constraints of what you want to do, I would recommend considering dedicated hardware sensors (such as the XBox's Kinect) instead of only using normal cameras. These sensors use structured light, time-of-flight or some other range imaging technique to generate a depth image which they can also combine with colour data from their own cameras. They practically solve the single-view reconstruction problem for you and often include libraries and tools for stitching/combining multiple views.
Epipolar geometry references
My knowledge is actually quite thin on most of the theory, so the best I can do is to further provide you with some references that are hopefully useful (in order of relevance):
I found a PDF chapter on Multiple View Geometry that contains most of the critical theory. In fact the textbook Multiple View Geometry in Computer Vision should also be quite useful (sample chapters available here).
Here's a page describing a project on uncalibrated stereo reconstruction that seems to include some source code that could be useful. They find matching points in an automated manner using one of many feature detection techniques. If you want this part of the process to be automated as well, then SIFT feature detection is commonly considered to be an excellent non-real-time technique (since it's quite slow).
A paper about Scene Reconstruction from Multiple Uncalibrated Views.
A slideshow on Methods for 3D Reconstruction from Multiple Images (it has some more references below it's slides towards the end).
A paper comparing different multi-view stereo reconstruction algorithms can be found here. It limits itself to algorithms that "reconstruct dense object models from calibrated views".
Here's a paper that goes into lots of detail for the case that you have stereo cameras that take multiple images: Towards robust metric reconstruction
via a dynamic uncalibrated stereo head. They then find methods to self-calibrate the cameras.
I'm not sure how helpful all of this is, but hopefully it includes enough useful terminology and references to find further resources.
I think the references will be a huge help. My son likes to build with Legos and it would be nice if he could take pictures and then rotate his design to explain what different parts are for.
For Legos I believe it should be possible to develop a solution that does everything and creates a complete 3D model of the outermost visible layer of your assembly. Legos have the benefit of being a small set of blocks with known shapes. It'd probably make for a nice Ph.D. dissertation :)
The previous comment has the seeds of your solution if your goal is generating 3D models of 2D lego pictures - one thing to consider that would vastly simplify your algorithmic misery is to restrict the lego construction such that each particular block shape has a unique color - then your system can recover data lost due to the projection that formed the image easily - otherwise, it is still a PhD level effort and a lot of heuristics
This problem is known as Photogrammetry.
Google will supply you with endless references, just be aware that if you want to roll your own, it's a very hard problem.
Check out The Daedalus Project, although that website does not contain a gallery with illustrative information about the solution, it post several papers and info about the working method.
I watched a lecture from one of the main researchers of the project (Roger Hubbold), and the image results are quite amazing! Although is a complex and long problem. It has a lot of tricky details to take into account to get an approximation of the 3d data, take for example the 3d information from wall surfaces, for which the heuristic to work is as follows: Take a photo with normal illumination of the scene, and then retake the picture in same position with full flash active, then subtract both images and divide the result by a pre-taken flash calibration image, apply a box filter to this new result and then post-process to estimate depth values, the whole process is explained in detail in this paper (which is also posted/referenced in the project website)
Google Sketchup (free) has a photo matching tool that allows you to take a photograph and match its perspective for easy modeling.
EDIT: It appears that you're interested in developing your own solution. I thought you were trying to obtain a 3D model of an image in a single instance. If this answer isn't helpful, I apologize.
Hope this helps if you are trying to construct 3d volume from 2d stack of images !! You can use open source tool such as ImageJ Fiji which comes with 3d viewer plugin..
https://quppler.com/creating-a-classifier-using-image-j-fiji-for-3d-volume-data-preparation-from-stack-of-images/
the link says page does'nt exist
| 24,106 |
https://arz.wikipedia.org/wiki/%D8%B1%D9%8A%D8%AF%20%D9%83%D9%8A%D8%B3%D9%84%D8%B1 | Wikipedia | Open Web | CC-By-SA | 2,023 | ريد كيسلر | https://arz.wikipedia.org/w/index.php?title=ريد كيسلر&action=history | Egyptian Arabic | Spoken | 32 | 87 | ريد كيسلر فارسه من امريكا.
حياتها
ريد كيسلر من مواليد يوم 9 يوليه سنة 1994 فى نيو يورك.
المشاركات
شاركت فى:
اوليمبياد صيف 2012
لينكات برانيه
مصادر
فارسه من امريكا
مواليد 1994 | 40,647 |
https://stackoverflow.com/questions/25215749 | StackExchange | Open Web | CC-By-SA | 2,014 | Stack Exchange | Dave Cousineau, Phill Greggan, Rahul Tripathi, Rohit, Shell, https://stackoverflow.com/users/1501794, https://stackoverflow.com/users/1614233, https://stackoverflow.com/users/3761928, https://stackoverflow.com/users/3913690, https://stackoverflow.com/users/621316 | English | Spoken | 222 | 331 | Should the currecy textbox in winforms gets rounding done all the time?
i have standard windows textbox that is formatted for currency but there is minor issue, when the user enter a value like 19999.9999999, this get rounded to 20000.00. If the user enters the value as 19999.99 this value will not get rounded. In the big industry, what is the correct way to format this number?
I need this to be rounded without harming the property value!
That sounds right to me. How would you expect it to round? Maybe you want it to truncate, rather than round?
So what output do you want ?
now this becomes interesting, this application originally deals with the real estate system. So these currency values are of property values. So how this should be done, i believe this shoudl be same as the banks
@PhillGreggan:- You need to show code and how you are formatting and rounding it!
i use the string.Format() with the CultureInfo enum with {0:C2}
How about Math.Round.
try like this
decimal dValue = Math.Round(19999.999999M, 3);
Take a look at the msdn for complete reference of Math.Round() method.
is this the way typical money systems handled?
yeah, most of the users are using this method to round up the amount. even there is no decimal or having more than 2 decimal.
| 27,710 |
https://ru.wikipedia.org/wiki/%D0%A7%D0%BB%D0%BE%D1%83%D1%86%D1%8B | Wikipedia | Open Web | CC-By-SA | 2,023 | Члоуцы | https://ru.wikipedia.org/w/index.php?title=Члоуцы&action=history | Russian | Spoken | 363 | 1,033 | Члоуцы () — один из субэтносов абхазов, в прошлом немногочисленное абхазское племя в составе абжуйцев.
Общие сведения
Своё название получили по наименованию князей Ачба и Лоу, резиденция которых находилась в Члоу.
Говорили на абжуйском диалекте абхазского языка, с которыми ранее жили в непосредственной близости.
До начала их мухаджирства, то есть до 1867 года, племя Члоуцы проживало в Абхазии, в селениях между реками Кодор и Охурей.
Теперь члоуцы изредка встречаются среди абхазской диаспоры в Турции, где проживает подавляющее большинство члоуцев, а также собственно в селах Члоу и Отап Очамчырского района.
В отличие от других абжуйских обществ, члоуцы были известны своей непокорностью. Так, во время Кавказской войны члоуцы воевали против политики русского царизма.
С 1835 по 1836 их вел абрек Исмаил Аджапуа. Новое восстание члоуцев вспыхнуло в 1840 году, подстрекаемые убыхами и шапсугами, они снова восстали против царизма. Но экспедиция Муравьева того же года на время остановила сопротивление члоуцев.
В 1848 году в Абхазию прибыл наиб Шамиля Мохаммед Эмин в целях более активного их вовлечения в антиколониальное движение народов Кавказа.
В 1850 члоуцы подняли новое восстание, к ним присоединилась община села Гуп. Поскольку другие общества практически не поддержали их, восстание было подавлено.
Последняя группа члоуцев покинула Абхазию в 1867 году.
Жители Члоу подверглись нескольким волнам махаджирства — насильственного изгнания абхазов в Турцию. Особо тяжко далось выселение 1867 года.
В 1918 г. в общине Члоу (сёла Члоу и Отап) образована народная гвардия, созданная в целях защиты селения от грабежей и нападений.
Интересные факты
Большинство выселенных царским правительством члоуцев осело на северо-западе Турции, современная провинция Сакарья, округ Карасу. Здесь ими было основано село, названное в честь родного селения в Абхазии — Члоу. Официальное турецкое название этого селения — Карапынар (). По данным на 2000 год, в Карапынаре проживало 1 058 человек.
В советское время в Члоу было меньше переселенцев из Восточной Грузии, чем в других селах Очамчырского и Гудаутского района, поэтому жители Члоу вобрали в себя меньше элементов грузинской культуры, нежели другие общества Абжуа.
В период грузино-абхазского конфликта 1992—1993 штаб Восточного фронта находился в селе Члоу.
Почти все партизанские отряды Восточного фронта состояли из члоуцев.
Хотя грузинской стороной не раз предпринимались такие попытки, войска Госсовета Грузии так и не смогли захватить село Члоу.
Примечания
Абхазы
Народы Кавказа | 41,092 |
https://eu.wikipedia.org/wiki/T%C5%99ebenice%20%28T%C5%99eb%C3%AD%C4%8Deko%20barrutia%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Třebenice (Třebíčeko barrutia) | https://eu.wikipedia.org/w/index.php?title=Třebenice (Třebíčeko barrutia)&action=history | Basque | Spoken | 31 | 96 | Třebenice Txekiar Errepublikako udalerri bat da. 447 biztanle ditu eta 11,67 kilometro koadroko azalera. Třebíčeko barrutian dago.
Historia
Udalerriaren lehen aipamen idatzia 1358 urtean egin zen.
Kanpo estekak
Třebíčeko barrutiko udalerriak | 11,042 |
https://stackoverflow.com/questions/30190282 | StackExchange | Open Web | CC-By-SA | 2,015 | Stack Exchange | Droidekas, https://stackoverflow.com/users/3396197 | English | Spoken | 156 | 345 | FragmentTransaction `commit()` implementation
I have combed through GrepCode and the downloaded source,but i cannot find a FragmentTransaction class implementation.Can anyone point me to a source?
Here is one of the possible implementations.
The signature of the class looks like this:
final class BackStackRecord extends FragmentTransaction implements FragmentManager.BackStackEntry, Runnable {...}
In grep code, you can click on the small arrow pointing down next to the class name to find the derived class.
Just to make this answer complete:
int commitInternal(boolean allowStateLoss) {
if (mCommitted) {
throw new IllegalStateException("commit already called");
}
if (FragmentManagerImpl.DEBUG) {
Log.v(TAG, "Commit: " + this);
LogWriter logw = new LogWriter(Log.VERBOSE, TAG);
PrintWriter pw = new FastPrintWriter(logw, false, 1024);
dump(" ", null, pw, null);
pw.flush();
}
mCommitted = true;
if (mAddToBackStack) {
mIndex = mManager.allocBackStackIndex(this);
} else {
mIndex = -1;
}
mManager.enqueueAction(this, allowStateLoss);
return mIndex;
}
commitInternal is called by commit
I dont know why i was searching for something like FragmentTransactionImpl.Thank you!
| 8,058 |
https://ceb.wikipedia.org/wiki/Spondylocladiopsis | Wikipedia | Open Web | CC-By-SA | 2,023 | Spondylocladiopsis | https://ceb.wikipedia.org/w/index.php?title=Spondylocladiopsis&action=history | Cebuano | Spoken | 32 | 88 | Kahenera sa mga uhong ang Spondylocladiopsis. Ang Spondylocladiopsis sakop sa ka-ulo nga Ascomycota, ug kaginharian nga abungawg-uhong.
Ang kladogram matud sa Catalogue of Life mao:
Ang mga gi basihan niini
Abungawg-uhong
Spondylocladiopsis | 32,987 |
https://aviation.stackexchange.com/questions/47404 | StackExchange | Open Web | CC-By-SA | 2,018 | Stack Exchange | Cloud, Jamiec, Koyovis, Penguin, Todd Wilcox, https://aviation.stackexchange.com/users/100, https://aviation.stackexchange.com/users/11949, https://aviation.stackexchange.com/users/21091, https://aviation.stackexchange.com/users/24388, https://aviation.stackexchange.com/users/27677, https://aviation.stackexchange.com/users/753, https://aviation.stackexchange.com/users/8848, https://aviation.stackexchange.com/users/900, jwenting, user, user3528438 | English | Spoken | 825 | 1,154 | Which airline will get me from Paris or London, to Japan, and has a zero fatality rate?
I only fly with airlines with a zero fatality rate (it helps my fear of flying, yes it might not be logical, I know:)… but have so far only travelled around Europe and to Africa with Easyjet and Ryan Air.
Now I want to go to Japan (from either Paris or London).
Is there an option for me?
The chance of you being the first is still non zero though.
I have proposed an edit based on the fact that OP accepted an answer talking about airlines, not airliners.
That said, wouldn't this be a much better fit on [travel.se]?
Please remember the be nice policy, and assume good intention. The comment of yours ive deleted was not very nice considering someone was trying to point you to a (potentially) better place to answer your question.
Note that the fatality rate for 2017 for all airlines worldwide was zero.
@ymb1. Given the question has 3 tags that are relevant it would appear to be very much on topic? It's a question about aviation safety, of which there are 650 in aviation stack exchange. And it's been given a good answer.
@Cloud "people like to close questions for fun" Look at What topics can I ask about here? in the [help]. One of the bullet points about questions that are off topic is specifically "passenger aspects" of commercial air travel. It doesn't really make more sense to ask a pilot, aircraft mechanic or air traffic controller about on which airline to book a ticket, than it does to ask a travel agent about the finer points of aircraft jet engine design or the aerodynamic properties of an autogyro. They might know, but it's not their job.
@MichaelKjörling Given the question has 3 tags that are relevant it would appear to be very much on topic? It's a question about aviation safety, of which there are 650 in aviation stack exchange. And it's been given a good answer
@Cloud - If 3+ of our highest rep users think its off-topic then guess what... it's off topic. Just copying a misguided comment from someone else doesnt change that. Not all aviation safety questions are on-topic, this being one of them.
@Jamiec. I agree, not all aviation safety questions may be on-topic. If he'd just asked for the cheapest ticket, it would be a question just about the "passenger" aspect of travel. But he asked about the safest. Safety is a technical aspect. The list of topics given in the help centre isn't very broad at all. For example, jet engines aren't mentioned at all, yet there are 450 questions about them. So, if a question can link to 3 tags that are relevant, it does beg the question how it's off topic? Or are you saying the tags are not relevant?
Qantas to Singapore, onwards to Japan with Jetstar, also owned by Qantas.
From this Wikipedia article:
In 2014, Qantas was rated the world's safest airline by Airline Ratings.
Rainman already knew..
For jet transport, Qantas is a zero-fatality-rate airline, has been for over 50 years, flying some of the longest distance air services in the world. The flying boats during wartime are a long time behind us.
Thanks so much! I'm guessing there is no direct route?
@Cloud unfortunately not.
Another option is KLM, they've not had an accident since 1981 and that one was due to a freak weather phenomenon that nobody could have foreseen snapping off the wing of a brand new aircraft like it was made of tissue paper (technically it wasn't even KLM, it was a regional subsidiary, the last mainline accident they had was Tenerife in 1977 over 40 years ago).
They'd probably get you there faster than Qantas too, as you'd be changing planes in Amsterdam rather than having to take a major detour to Australia.
Thanks for this, do you have links to the pages of those accidents, sounds interesting.
@Cloud I suspect that'd be KLM Flight 4805 in 1977. You can start at the Wikipedia page on the Tenerife airport disaster, then follow its citations.
Qantas flies London- Singapore.
@Cloud that's the one. Before that the last fatalities in KLM flights I know about were on a Constellation that crashed on takeoff from Shannon somewhere in the 1950s. The 1981 crash was an NLM Cityhopper (now KLM Cityhopper but an independent airline owned by KLM at the time) Fokker 28 https://en.wikipedia.org/wiki/NLM_CityHopper_Flight_431
Saying that KLM has had no accidents since 1981 might make the asker more comfortable with KLM, but that comfort is probably completely undone by then immediately describing the 1981 accident in graphic detail. "New Aircraft Wings Like Tissue Paper" is the headline I'm left with.
@ToddWilcox well, the weather conditions were such that no aircraft would have survived them... And it was a fully owned subsidiary, not the main company
| 39,262 |
https://fr.wikipedia.org/wiki/Manuel%20Nkomba%20du%20Kongo | Wikipedia | Open Web | CC-By-SA | 2,023 | Manuel Nkomba du Kongo | https://fr.wikipedia.org/w/index.php?title=Manuel Nkomba du Kongo&action=history | French | Spoken | 174 | 274 | Manuel Nkomba ou Manuel Fernandes Komba est un prétendant au titre de roi vassal du Royaume du Kongo en 1910-1911.
Contexte
Après la mort de Pedro Mbemba devenu le roi Pierre VII du Kongo, son héritier le plus légitime en ligne matrilinéaire est son neveu âgé de 21 ans Manuel Fernandes Nkomba ou komba; contrairement aux adeptes du Baptisme le parti catholique est prêt à l'accepter. Pedro Mbemba n'avait été désigné roi qu'à défaut de Pedro Lelo retenu en Angola mais l'oncle de ce dernier Pedro Kalandera soutenu par un parti Protestant souhaitait son retour pour jouer un rôle politique éminent auprès de son neveu le nouveau roi. Manuel Nkomba devra finalement se retirer devant un candidat de compromis Manuel III Martins Kiditu. Le fait qu'il n'ait jamais été officiellement reconnu comme monarque l'exclu de la numération officielle des rois du royaume du Kongo bien qu'il figure dans certaines listes de ces souverains.
Source
Dirigeant politique du Congo précolonial (RDC) au XXe siècle
Manuel Komba
Date de décès incertaine (XXe siècle)
Naissance en 1889 | 32,766 |
https://stackoverflow.com/questions/2395662 | StackExchange | Open Web | CC-By-SA | 2,010 | Stack Exchange | CodePhobia, Sunday, https://stackoverflow.com/users/4873044, https://stackoverflow.com/users/4873045, https://stackoverflow.com/users/4873046, https://stackoverflow.com/users/4874271, user4873045, user4873046 | English | Spoken | 281 | 400 | position content relative to a fluid width element set to position:fixed
I have a layout with the following requirements
An image on the left side, and content on the right side.
The image is pinned to the bottom left of the viewport
The image does not move when the user scrolls
The image resizes to 100% height of the viewport, up to it's max height. (I don't want the image to distort in it's attempts to be larger than it actually is)
The image retains it's aspect ratio, and resizes it's width according to the height resizing.
The content begins to the right of the image, and moves as the image resizes with the browser viewport.
Now, I've managed to achieve pretty much all but the last of these requirements.
Have a look here:
http://letteringmusic.com/
The image resizes quite nicely, but I can't get the content to float next to the image because image is position:fixed, and therefore out of the document flow.
I'm not opposed to a javascript solution if that's the only way to get the result I want.
Anybody know what I need to do to make this work?
Thank you!!
A quick (and perhaps only) solution is to restyle the content when the browser window resizes (using the window.onresize event). In that function you should read the width of the background image:
var bgWidth = getElementById('background-img').style.width;
getElementById('content').style.left = bgWidth;
and use #content { position: absolute }. I know this introduces another problems, but I think you can bypass them. It's not the most neat solution, as Javascript must be enabled (and the event will be fired a lot when someone resizes this window), but it should work.
| 28,435 |
https://arz.wikipedia.org/wiki/SDSS%20J090550.18%2B001546.3%20%28%D9%85%D8%AC%D8%B1%D9%87%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | SDSS J090550.18+001546.3 (مجره) | https://arz.wikipedia.org/w/index.php?title=SDSS J090550.18+001546.3 (مجره)&action=history | Egyptian Arabic | Spoken | 159 | 451 | SDSS J090550.18+001546.3 هى مجره بتتبع كوكبه الشجاع.
معلومات المجره
الانزياح الأحمر: 0.10126.
السرعه الشعاعيه: 28827.
المطلع المستقيم: 136.4591.
الميل: 0.2628667.
مصطلحات تعريفيه
الكوكبه هيا مجموعه من النجوم اللى بتكون شكل أو صوره و هيا مجال الكره السماويه اللى المجره جزء منها.
الانزياح الاحمر هو زيادة طول الموجه الكهرومغناطيسيه اللى جايه لينا من المجره بسبب سرعه ابتعادها عننا. ده بيستخدم فى حسابات الفلك.
السرعه الشعاعيه هيا سرعه الجرم الفضائى فى اتجاه الراصد و بتنقاس بالانزياح الاحمر.
المطلع المستقيم هوا الزاويه المحصوره بين الدايره الساعيه لجرم سماوى و الدايره الساعيه لنقطة الاعتدال الربيعى. المطلع المستقيم ممكن يتقاس بقوس دايره الاستواء السماويه من نقطه الاعتدال الربيعى لحد نقطه تقاطع الدايره الساعيه لجرم سماوى مع دايره الاستواء السماويه.
الميل هوا المكافئ الفلكى لخط العرض و بيتقس بقيمة الزاويه بين أى جسم سماوى و خط الاستوا السماوى. لو كان النجم شمال خط الاستوا السماوى تكون قيمة بعده بالموجب (+) و لو النجم جنوب خط الاستوا السماوى تكون قيمة بعده بالسالب (-).
مصادر
مجرات
فضاء | 10,465 |
https://fr.wikipedia.org/wiki/Nikola%C3%AF%20Perovski | Wikipedia | Open Web | CC-By-SA | 2,023 | Nikolaï Perovski | https://fr.wikipedia.org/w/index.php?title=Nikolaï Perovski&action=history | French | Spoken | 308 | 525 | Nikolai Ivanovni Perovski (en ), né en 1785 et mort le , est une personnalité politique russe, diplomate et gouverneur du Gouvernement de Tauride sur la mer Noire.
Biographie
Nikolai Perovski est le fils du comte Alexeï Razoumovsky et de sa maîtresse, Maria Sobolevskaïa, une roturière ; il tire son patronyme du village de Perovo, propriété de son père. Il est le père de Lev Nikolaïevitch Perovski, futur ministre de l'Intérieur et gouverneur militaire de Saint-Pétersbourg et de Piotr Perovski, diplomate mort à Genève en 1865. Nikolai Perovski était le grand-père de la révolutionnaire Sofia Perovskaïa. Nikolai Perovski avait plusieurs frères, le général Vassili Perovski, Lev Alexeïevitch Perovski (1792-1856) et Alexeï Perovski (1786-1836), écrivain plus connu sous son nom de plume d'Antoni Pogorelski.
En 1799, il rejoint, en tant qu'étudiant stagiaire du Ministère des Affaires étrangères, la mission diplomatique russe de Constantinople.
En 1801, il est envoyé à Vienne en Autriche au sein de la mission diplomatique. En 1803, il est affecté à la mission diplomatique de Dresde en Allemagne. En 1805, il se retrouve dans les services de l'Ambassade de Russie en Chine.
Le , il est nommé à la Chancellerie d'État et participe à la Commission de formulation des lois.
En 1816, par décret impérial, il se rendit à Amsterdam en mission au sujet des émissions d'obligations privées dans le prêt néerlandais, qu'il a effectué avec succès.
Le , il a été nommé vice-gouverneur de Tauride, puis le , il fut nommé maire de Feodosia et enfin le , gouverneur du Gouvernement de Tauride. Le , il a été promu vice-président du Conseil d'État.
La retraite venue, il se retire dans son domaine de Crimée près de Simferopol où il mourut le .
Source
Biographie et généalogie de Nikolai Perovski
Personnalité politique de l'Empire russe
Naissance dans l'Empire russe
Naissance en 1785
Décès en avril 1858 | 2,928 |
https://stackoverflow.com/questions/22628024 | StackExchange | Open Web | CC-By-SA | 2,014 | Stack Exchange | Morten Nørgaard, Tim, https://stackoverflow.com/users/1208500, https://stackoverflow.com/users/1768303, https://stackoverflow.com/users/1843331, noseratio | English | Spoken | 375 | 496 | Is it good practice to always wait on a task to complete?
Sorry if it is a dumb question. I'm confused about the wait() and its variants in regards to the task parallel library.
Every single example I've seen waits on tasks to complete - is this considered good practice?
My scenario is this, that I'm developing a windows service that will run continuously. I would like to engage a number of tasks, but I don't care if they will run to completion - I will set a cancellation-token with an expiration, that will throw an error if something goes awry. So I don't see the need for a wait-to-complete, but every darn example uses it...
look up what wait() does in the docs 2. "do i need this?" 3. yes->use it, no->dont use it
Do you care about exceptions possibly thrown inside each task, and how they propagate? It may not work the way you expect: http://stackoverflow.com/a/22395161/1768303
@TimCastelijns I can - and have - studied the documentation. Yet I'm still confused - hence the question. I'm obviously not competent on the level as you, but please consider the notion that this forum is used by many different people, some - as myself - less capable than others.
@Noseratio Thanks for that - I had not considered that, but now will.
It really depends on what your situations needs. If for instance, you want to launch a sub process to do a procedure, say for instance, fire off an email in parallel you can do without waiting.
However, if you will need to act upon what ever result or structure which is affected by some behavior you will need to wait.
If your tasks are self contained and do not interact and/or depend on each other, then I do not see why you would need to wait.
You only need to wait on a task if the code that is waiting requires the output of the task before it can proceed. If you don't need that output, don't wait.
I wish I could share the credit for the answer, as they're both satisfactory to me. I actually drew a literal straw to select the one to be marked. Thanks a lot for you answer, too.
| 17,655 |
https://en.wikipedia.org/wiki/Mont%20Blanc%20Restaurant | Wikipedia | Open Web | CC-By-SA | 2,023 | Mont Blanc Restaurant | https://en.wikipedia.org/w/index.php?title=Mont Blanc Restaurant&action=history | English | Spoken | 180 | 267 | Mont Blanc Restaurant is a former restaurant in London where leading writers including Hilaire Belloc, G. K. Chesterton, Joseph Conrad and John Galsworthy met regularly in the early years of the 20th century.
History
The restaurant was located at 16 Gerrard Street in the Soho district of central London. It was closed in 1928.
Mont Blanc circle
Writer, critic and publisher Edward Garnett held regular Tuesday lunches at the restaurant where he nurtured the talent of many literary figures such as DH Lawrence, John Galsworthy and Liam O'Flaherty. Chesterton and Belloc met at the restaurant in 1900 and subsequently developed a close friendship, apparently sealed over a bottle of Moulin-a-Vent. In 1912, through Garnett's 'circle' of friends, Richard Curle was first introduced to Conrad and became his protégé, literary assistant and close friend.
Commemorative Plaque
In July 2010 the City of Westminster decided to commemorate the restaurant with one of its Commemorative Green Plaques. The circular plaque reads:
References
External links
Open Plaques.
History of the City of Westminster
Cultural heritage of the United Kingdom
Historical markers
Restaurants in London | 1,106 |
https://en.wikipedia.org/wiki/Songdalselva | Wikipedia | Open Web | CC-By-SA | 2,023 | Songdalselva | https://en.wikipedia.org/w/index.php?title=Songdalselva&action=history | English | Spoken | 350 | 537 | Songdalselva or Søgneelva or Songa is a river in Agder county, Norway. The long river in the hills between Finsland in Kristiansand municipality and Hægeland in Vennesla municipality. The catchment area is located between the Otra river and Mandalselva river watersheds. The river runs through the villages of Hortemo, Nodeland, Volleberg, Tangvall, Åros, and Høllen.
The highest hills in the catchment area go up to above sea level. The water flows are normally at their lowest in the summer and they're at their highest levels during the autumn and spring. There are only a few small lakes in the river system. The steep slopes down from the moors can create short and intense flood rapids. The river (here called Songa) flows through the Stallemodalen valley in Vennesla, and then falls into the Songdalen valley through a gorge at Underåsen.
Once in the Songdalen valley, it is called the Songdalselva. Here it receives more water from the right from the Gumpedalselva tributary. The river drops no more than about over the last to the river mouth, and has on this stretch a very meandering run. There is a short waterfall (Søgne waterfall) near the Søgne Landbruksskole. From that waterfall to the sea, the river is called the Søgneelva. The Songdalselva flows into the sea between the villages of Høllen and Åros in Kristiansand municipality.
Both salmon and sea trout are found in the river, and a fishing license is required for fishing along the river.
Environment
In the post-war years up until the 1980s, the river was thought of as an open sewer. Bathing and fishing were not recommended. Water quality improved by the time the sewer was led through pipes and cleansed before discharged to the sea. Today's (2016) environmental issue is mainly illegal garbage disposal and plastic waste from farming, accumulation along the banks and flowing into the ocean when the river is flooding.
In 1993, the watercourse was protected against hydropower development pursuant to Norwegian law, by development plans through Conservation Plan IV for waterways.
Media gallery
References
Rivers of Agder
Geography of Kristiansand
Vennesla
Rivers of Norway | 50,077 |
https://cy.wikipedia.org/wiki/Pottsville%2C%20Arkansas | Wikipedia | Open Web | CC-By-SA | 2,023 | Pottsville, Arkansas | https://cy.wikipedia.org/w/index.php?title=Pottsville, Arkansas&action=history | Welsh | Spoken | 29 | 76 | Dinas yn , yn nhalaith Arkansas, yw .
Poblogaeth ac arwynebedd
Pobl nodedig
Ceir nifer o bobl nodedig a anwyd yn Pottsville, gan gynnwys:
Cyfeiriadau
Dinasoedd Pope County, Arkansas | 41,160 |
https://stackoverflow.com/questions/59746866 | StackExchange | Open Web | CC-By-SA | 2,020 | Stack Exchange | Mike Brind, Rena, https://stackoverflow.com/users/11398810, https://stackoverflow.com/users/134725 | English | Spoken | 285 | 574 | Same URL endpoint in Razor Pages
Is it possible to achieve this in Razor Pages:
Product.cshtml @page "/{url_product}" – retrieve url friendly from database / Product table
Category.cshtml @page "/{url_category}" – retrieve url friendly from database / Category table
I want to achieve this:
www.domain.com/url-friendly-product
www.domain.com/url-friendly-category
I tried constraint and it is working, but i have to every request match url from database from both table, and i am afraid about application performance.
Is it possible to do it some other way?
Normally you should only worry about dealing with application performance issues if you are actually experiencing them. It is common to run multiple queries against a database during a single request. Running the same query against 2 tables might or might not cause issues in exactly the same way that running a single query might or might not, based on a lot of factors including but not limited to database system in use, schema design, optimisations e.g indexes etc, etc.
Why not change @page "/{url_product}" to @page "product/{url_product}"?Then you only need to match the url for one time and it could improve the performance.
I have this custom constraint and if will be in database 10 000 product for every request, I think is not good.
Is some other options to achieve this? Or is it only this way to do it?
private readonly IMemoryCache _cache;
public ProductConstraint(IMemoryCache cache)
{
_cache = cache;
}
public bool Match(HttpContext httpContext, IRouter route, string routeKey, RouteValueDictionary values, RouteDirection routeDirection)
{
if (_cache.Get("URLProductListCache") == null)
{
var cacheEntry = _cache.CreateEntry("URLProductListCache");
var _context = (ApplicationDbContext)httpContext.RequestServices.GetService(typeof(ApplicationDbContext));
var url = _context.Product.AsNoTracking().Select(c => c.URL).ToList();
cacheEntry.SetValue(url);
cacheEntry.Dispose();
return url.Contains(values[routeKey]?.ToString().ToLowerInvariant());
}
else
{
var url = _cache.Get("URLProductListCache") as List<string>;
return url.Contains(values[routeKey]?.ToString().ToLowerInvariant());
}
}
| 27,910 |
https://ar.wikipedia.org/wiki/%D9%85%D8%AB%D9%84%D8%AB%20%D9%8A%D9%88 | Wikipedia | Open Web | CC-By-SA | 2,023 | مثلث يو | https://ar.wikipedia.org/w/index.php?title=مثلث يو&action=history | Arabic | Spoken | 398 | 1,132 | مثلث يو هو نظريةٌ عن التطور والعلاقات بين أعضاء جنس نبات الكرنب. تنص النظرية على اجتماع جينومات ثلاثة أنواع من الأسلاف من نبات الكرنب لخلق ثلاثة أنواع من الخضروات الحديثة وأنواع الثمار ذات البذور الزيتية. اتُفِق عى هذا منذ ذلك الحين من خلال دراسات الحمض النووي والبروتينات.
نُشرت النظرية لأول مرةٍ في عام 1935 عن طريق عالم النبات الكوري الياباني وو جانغ شون (Woo Jang-choon) الذي كان يعمل في اليابان (حيث كان اسمه الياباني ناجاهارو يو "Nagaharu U"، كما يُقرأ في اللغة اليابانية) . عمل جانغ شون على خلق هجائن اصطناعية بين الأنواع ثنائية الصبغيات ورباعية الصبغيات، ودرس كيفية اقتران الكروموسومات في الأنواع الناتجة الثلاثية الصبغيات.
يشير الحرف n إلى عدد الكروموسومات في كل جينوم، وهو الرقم الموجود في حبوب اللقاح أو البويضات. نأخد على سبيل المثال نبات اللفت الذي يُعتبر نوع من الكرنبيات ويتبع الفصيلة الصليبية، ويُحدد بالصيغة الصبغية: A - n = 10 (بدلاً من AA - 2n = 20). هذا يعني أن كل خلية جسدية من النبات تحتوي على نسختين كاملتين من الجينوم (ثنائي الصبغيات) ولكل جينوم عشرة صبغيات، وبالتالي سوف تحتوي كل خلية على 20 صبغي نظرًا لأن هذا الرقم مزدوج، فتُكتب بالصيغة الصبغية 2n = 2x = 20.
AA - 2n = 2x = 20 – اللفت (مع السلجم) – اللفت، والملفوف الصيني.
BB - 2n = 2x = 16 – الخردل الأسود
CC - 2n = 2x = 18 – الخردل البري – الكرنب، واللفت، والبروكلي، والكرنب البروكسل، والثنبيط، والكرنب الساقي.
توجد هذه الأنواع الثلاثة كأنواع منفصلة، ولكن نظرًا لارتباطها الوثيق فقد كان من الممكن لها أن تُهجّن. لسوء الحظ، لا ينتج التهجين الداخلي بين الأنواع الجينومات التي تقاوم التلوث غير المنظم. سُمح بهذا التهجين بين الأنواع لإنشاء ثلاثة أنواع جديدة من نباتات الكرنب رباعية الصيغة الصبغية.
يُقال إن هذه النباتات الهجينة هي رباعية التضاعف الهجيني (أي تحتوي على أربعة جينومات مستمدة من نوعين مختلفين من الأسلاف) نظرًا لأنها مستمدة من جينومات نوعين مختلفين، (وبشكل أكثر تحديداً، فهي متغايرة الصيغة الرباعية الصبغية، أي أنها تحتوي على جينوم ثنائي الصبغية واحد من كل نوع من أنواع نباتات الكرنب المختلفة). تشير البيانات المستمدة من الدراسات الجزيئية إلى أن الأنواع الثلاثة ثنائية الصيغة الصبغية هي متعددة الصيغ الصبغية سابقًا.
AABB - 2n = 4x = 36 – الكرنب الأسلي – الخردل الهندي
AACC - 2n = 4x = 38 – السلجم – بذور اللفت، واللفت الإفرنجي
BBCC - 2n = 4x = 34 – السلجم الزورقي – الخردل الإثيوبي
المراجع
براسيكا
علم الوراثة
نباتات هجينة | 31,958 |
https://stackoverflow.com/questions/62245900 | StackExchange | Open Web | CC-By-SA | 2,020 | Stack Exchange | Dakait, https://stackoverflow.com/users/1679410, https://stackoverflow.com/users/2700344, leftjoin | English | Spoken | 469 | 935 | Change Hive External Table Column names to upper case and add new columns
I have an external table for example dump_table, which is partitioned over year, month and day. If i run show create table dump_table i get the following:
CREATE EXTERNAL TABLE `dump_table`
(
`col_name` double,
`col_name_2` timestamp
)
PARTITIONED BY (
`year` int,
`month` int,
`day` int)
CLUSTERED BY (
someid)
INTO 32 BUCKETS
ROW FORMAT SERDE
'org.apache.hadoop.hive.ql.io.orc.OrcSerde'
STORED AS INPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcInputFormat'
OUTPUTFORMAT
'org.apache.hadoop.hive.ql.io.orc.OrcOutputFormat'
LOCATION
'hdfs://somecluster/test.db/dump_table'
TBLPROPERTIES (
'orc.compression'='SNAPPY',
'transient_lastDdlTime'='1564476840')
I have to change its columns to upper case and also add new columns, so it will become something like:
CREATE EXTERNAL TABLE `dump_table_2`
(
`COL_NAME` DOUBLE,
`COL_NAME_2` TIMESTAMP,
`NEW_COL` DOUBLE
)
PARTITIONED BY (
`year` int,
`month` int,
`day` int)
CLUSTERED BY (
someid)
Option:1
as an option I can run Change (DDL Reference here) to change column names and then add new columns to it. BUT the thing is that i do not have any backup for this table and it contains alot of data. If anything goes wrong I might loose data.
Can I create a new external table and migrate data, partition by partition from dump_table to dump_table_2 ? what will the query look like for this migration?
Is there any better way of achieving this use case? Please help
In older versions of Hive it was not possible to have column names other then lowercased: https://stackoverflow.com/a/57183048/2700344. Maybe everything has already changed in new version... I doubt it
@leftjoin thank you! so basically all i can do is create a copy of old table, with new columns and migrate data to that new table.
You can create new table dump_table_2 with new columns and load data using sql:
set hive.enforce.bucketing = true;
set hive.exec.dynamic.partition=true;
set hive.exec.dynamic.partition.mode=nonstrict;
insert overwrite table dump_table_2 partition (`year`, `month`, `day`)
select col1,
...
colN,
`year`, `month`, `day`
from dump_table_1 t --join other tables if necessary to calculate columns
just one more thing, if i dont specify col list, all identical columns will be migrated and null will be inserted into un-matched columns right? as number of columns are not equal in both tables
@Dakait You need to specify column list because it is positional. columns will be loaded by positions, not by names. Partition columns should be last in the list. You can use select * only if it returns the same columns in the same positions exactly
select * in my case will return only a subset of columns that are in same position, for example first 10 columns. and i am only interested in those first 10 columns. can i specify list of columns in source and target? Appreciate your help and time.
@Dakait select col1, col2....colN, NULL as someothercol, NULL as onemoreCol .. partition cols are last
perfect, I got it now. Appreciate your kind help.
| 40,953 |
https://en.wikipedia.org/wiki/List%20of%20Egyptian%20detainees%20at%20Guantanamo%20Bay | Wikipedia | Open Web | CC-By-SA | 2,023 | List of Egyptian detainees at Guantanamo Bay | https://en.wikipedia.org/w/index.php?title=List of Egyptian detainees at Guantanamo Bay&action=history | English | Spoken | 148 | 230 | The United States Department of Defense acknowledges holding eight Egyptian detainees at Guantanamo Bay.
A total of 778 captives have been held in extrajudicial detention in the Guantanamo Bay detention camps, in Cuba since the camps opened on January 11, 2002
The camp population peaked in 2004 at approximately 660. Only nineteen new captives, all "high value detainees" have been transferred there since the United States Supreme Court's ruling in Rasul v. Bush. As of February 24, 2010, the camp population stood at 188.
On February 24, 2010, Carol Rosenberg, of the Miami Herald, reported that Albania accepted the transfer of three former captives, an Egyptian, Sharif Fati Ali al Mishad, and Saleh Bin Hadi Asasi and Rauf Omar Mohammad Abu al Qusin, a Tunisian and a Libyan.
The men will not be allowed to leave Albania.
References
Lists of Guantanamo Bay detainees by nationality
Egypt–United States relations | 14,707 |
https://it.wikipedia.org/wiki/Aeroporto%20di%20Canton-Baiyun | Wikipedia | Open Web | CC-By-SA | 2,023 | Aeroporto di Canton-Baiyun | https://it.wikipedia.org/w/index.php?title=Aeroporto di Canton-Baiyun&action=history | Italian | Spoken | 118 | 258 | L'Aeroporto di Canton-Baiyun Cinese semplificato: 广州白云国际机场; pinyin: Guǎngzhōu Báiyún Guójì Jīchǎng) è il principale scalo aeroportuale della città di Canton, (Cina).
Situato nel distretto di Huadu, nei pressi della periferia della città di Canton, è il più importante aeroporto della Cina meridionale. L'impianto, terminato nel 2004, è hub della principale compagnia della Cina del Sud, China Southern Airlines.
Costato 18,9 miliardi di yuan, il progetto ambizioso include inoltre la costruzione del secondo terminal nel 2009. Con la fine della costruzione, si prevede che i passeggeri ammonteranno nel 2020 a oltre 80 milioni.
Terminal
Terminal 1 voli nazionali, internazionali e cargo.
Terminal 2 in fase di progettazione.
Note
Altri progetti
Collegamenti esterni
Canton-Baiyun
Architetture di Canton
Trasporti a Canton | 25,620 |
https://physics.stackexchange.com/questions/332364 | StackExchange | Open Web | CC-By-SA | 2,017 | Stack Exchange | English | Spoken | 113 | 141 | What is the difference between population transfer between two quantum states/system and the state transfer in a quantum system?
In lambda type atomic system, the population is transferred from one stable ground state to another by using counter intuitive sequence of pulses. This process is well known as stimulated Raman adiabatic passage (STIRAP). However in optomechanics the coherent superposition of states are observed between mechanical mode and cavity mode. In the above cases population is transferred from either one state to another or from mechanical to cavity mode and vice versa.
How can I understand the difference between state exchange /transfer and population transfer between two physical system /states of a quantum system?
| 48,620 | |
https://vec.wikipedia.org/wiki/Groises | Wikipedia | Open Web | CC-By-SA | 2,023 | Groises | https://vec.wikipedia.org/w/index.php?title=Groises&action=history | Venetian | Spoken | 33 | 66 | Groises el xe on comun de 131 abitanti del departemento de Cher che el fa parte del rejon Sentro-Vałe de ła Loira in Fransa.
Evołusion demogràfega
Altri projeti
Comuni del departemento de Cher | 27,520 |
https://english.stackexchange.com/questions/266921 | StackExchange | Open Web | CC-By-SA | 2,015 | Stack Exchange | Chris H, Edwin Ashworth, Hot Licks, https://english.stackexchange.com/users/133907, https://english.stackexchange.com/users/21655, https://english.stackexchange.com/users/48571, https://english.stackexchange.com/users/70861, kimsungbum | English | Spoken | 554 | 729 | What is the meaning of "reset" in this sentence?
What was the meaning of "reset" in this letter?
"change"?, "setting again?" , “setting back to the original state"
We did not "reset the time" in these animals. We put them into an environment where they had normal light dark cycles, but were given access to food only from 1pm-5pm in the afternoon, when they are usually asleep. This resulted in the animals changing their circadian rhythms to begin their active period about 3 hours before the food presentation, so around 10am rather than around 7pm.
Thank you for the tip
My take is that the writer means that they did not use a change in lighting to modify the circadian rhythm of the animals. This is not clearly written -- saying "we did not reset the time" is redundant and more confusing than enlightening, given the subsequent sentence.
... And giving access to the food only from 1pm till 5pm could certainly be claimed to be 'resetting the time'.
@HotLicks I am so grateful to receive your response to my inquiry !!!:D
@HotLicks Probably I assume that it is because a questioner has interpreted the usage of reset differently from a responder of letter. In this perspective, may I ask how you think of this?
There is no obvious way one could "reset" the time awareness of an animal the same way you "reset" an alarm clock by pressing the button on top, so the other meaning -- to set to a new value -- would be the only one that makes sense.
Suppose I buy a new clock or computer or phone. One of the first things I do is to set the time. I check my local time from an accurate source and synchronise my new purchase.
Suppose, however, I have an item that has lost its correct time setting. It is showing a time but the time is incorrect. Then I need to reset the time for that piece of equipment.
In this case they enclose the phrase from, We did not “reset the time” in these animals, in quotes to indicate that you cannot reset an animal in the same way you can reset a piece of equipment. The quotes indicate that they are aware of the fact and they go on to explain what they did in reality.
Does that answer it?
EDIT - I agree with Hot Licks' first comment under your question.
I really appreciate it so much. :D!!
I take from their use of quotes (and previous reading) that "reset the time [sense]" is jargon for a method they didn't use, namely setting up an artificial day/night cycle. The short quote reads to me like a less-than-fluent piece of scientific writing -- not necessarily a non-native author but perhaps someone new to formal writing.
Probably I assume that it is because a questioner has interpreted the usage of reset differently from a responder of letter. In this perspective, may I ask how you think of this?
@ChrisH Then, is it possible to interpret "reset" as the re-setting of timeline?
This isn't my field but I'd avoid "timeline" in preference for "rhythm" or "cycle" as an implication of regular repetition is desirable. "Reset", while it often means "set to an initial state" can just mean "set again".
| 1,987 |
https://stackoverflow.com/questions/55695963 | StackExchange | Open Web | CC-By-SA | 2,019 | Stack Exchange | Silesian | Spoken | 169 | 588 | Trying to debug mixed datetimes and integers in passed array
I have two panda data frames new_hpm and new_mr with datetime index, and I am trying to subset one based on datetime index of another using .loc.
The datetime indexes on the two data frames are:
new_hpm.index
DatetimeIndex(['2013-01-01', '2013-01-02', '2013-01-03', '2013-01-04',
'2013-01-05', '2013-01-06', '2013-01-07', '2013-01-08',
'2013-01-09', '2013-01-10',
...
'2017-12-15', '2017-12-20', '2017-12-21', '2017-12-22',
'2017-12-23', '2017-12-24', '2017-12-28', '2017-12-29',
'2017-12-30', '2017-12-31'],
dtype='datetime64[ns]', name='datetime', length=1093, freq=None)
new_mr.index
DatetimeIndex(['2013-01-07', '2013-01-07', '2013-01-13', '2013-01-13',
'2013-01-13', '2013-01-13', '2013-01-14', '2013-01-14',
'2013-01-14', '2013-01-14',
...
'2017-12-31', '2017-12-31', '2017-12-31', '2017-12-31',
'2017-12-31', '2017-12-31', '2017-12-31', '2017-12-31',
'2017-12-31', '2017-12-31'],
dtype='datetime64[ns]', name='date_conv', length=13366, freq=None)
However, when I do
subset_mr = new_mr.loc[new_hpm.index]
I get the error message:
ValueError: mixed datetimes and integers in passed array
This is most likely due to the duplicates present in new_mr, as seen in GH issue here.
You could remove the duplicates in the index of new_mr before slicing or, in general, you want to perform set operations, there are better ways that work well with indices, e.g.
subset_mr = new_mr.loc[new_mr.index.intersection(new_hpm.index).drop_duplicates()]
| 3,239 | |
https://id.wikipedia.org/wiki/Dichostates%20similis | Wikipedia | Open Web | CC-By-SA | 2,023 | Dichostates similis | https://id.wikipedia.org/w/index.php?title=Dichostates similis&action=history | Indonesian | Spoken | 59 | 143 | Dichostates similis adalah spesies kumbang tanduk panjang yang tergolong famili Cerambycidae. Spesies ini juga merupakan bagian dari genus Dichostates, ordo Coleoptera, kelas Insecta, filum Arthropoda, dan kingdom Animalia.
Larva kumbang ini biasanya mengebor ke dalam kayu dan dapat menyebabkan kerusakan pada batang kayu hidup atau kayu yang telah ditebang.
Referensi
TITAN: Cerambycidae database. Tavakilian G., 25 Mei 2009.
Dichostates | 12,839 |
https://et.wikipedia.org/wiki/Windows%20RT | Wikipedia | Open Web | CC-By-SA | 2,023 | Windows RT | https://et.wikipedia.org/w/index.php?title=Windows RT&action=history | Estonian | Spoken | 277 | 644 | Windows RT (mitte segi ajada Windows Runtime'iga) on Windows 8 eriversioon, mis on ette nähtud mobiilseadmetele, näiteks tahvelarvutitele.
Ülevaade
Windows RT on välja töötatud ARM-arvutiarhitektuuriga seadmete jaoks nii, et selle opsüsteemiga seade tarbiks võimalikult vähe energiat ja akut poleks vaja eriti tihti laadida. Windows RT-ga seadmed sisaldavad süsteemikiipe, tänu millele saab toota senisest väiksemate mõõtmetega riistvara. Windows RT sisaldab ka spetsiaalset puutetundlikku Microsoft Office 2013 versiooni. Windows RT on teiste Windowsi versioonidega võrreldes kõige optimeeritum mobiilseadmete operatsioonisüsteem.
Windows RT ja Windows 8 erinevused
Windows RT kasutab ainult ARM-protsessoreid. Windows 8 jaoks sobivad kõik x86-protsessorid, nii Inteli kui ka AMD toodang. Windows 8 töötab nii personaalarvutites kui ka tahvelarvutites, sellel on puutetundlik ekraan ja kõikide Windowsi rakenduste kasutamise võimalus. Windows RT-ga aga paljusid traditsioonilisi Windowsi rakendusi kasutada ei saa. Samuti ei ole võimalik installida igasuguseid programme, vaid ainult tahvelarvutite jaoks välja töötatud rakendusi, mida saab hankida Windows App Store'ist. Windows RT-ga ei saa kasutada näiteks Photoshoppi, Windows Media Playerit ega Outlooki. Windows RT on ARM-arvutiarhitektuuriga seadmesse eelinstallitud ega ole kasutaja installitav.
Windows RT-l on Windows 8 ees ka eeliseid. Kõige suuremaks eeliseks võib pidada selle hinda. Seade, kuhu on installitud Windows RT, on märksa odavam Windows 8-ga seadmest. Teine suur eelis on Windows RT väike energiatarve. Mobiilsete seadmete puhul on aku kestvus väga oluline ja Windows RT juures on sellele suurt rõhku pandud.
Seadmed
Microsoft Surface – kaks versiooni, millest üks on mõeldud Windows RT jaoks
ASUS VivoTab RT
Samsung ATIV Tab
Dell XPS 10
Lenovo IdeaPad Yoga 11 – seadme suuruse järgi on võimalik eristada Windows 8 ja Windows RT. Väiksemal seadmel on operatsioonisüsteemiks Windows RT ja suuremal Windows 8.
Viited
RT
Mobiilsete seadmete operatsioonisüsteemid
no:Windows 8#RT | 1,271 |
https://tt.wikipedia.org/wiki/NGC%205153 | Wikipedia | Open Web | CC-By-SA | 2,023 | NGC 5153 | https://tt.wikipedia.org/w/index.php?title=NGC 5153&action=history | Tatar | Spoken | 45 | 197 | NGC 5153 — Томанлыклар һәм йолдыз тупланмалары яңа гомуми каталогында теркәлгән галактика.
Тарихы
Әлеге галактика елда тарафыннан, яктылык җыючы элемент буларак көзге кулланучы, зурлыктагы оптик телескоп ярдәмендә ачылган.
Чыганаклар
VizieR
NASA/IPAC Extragalactic Database
Искәрмәләр
Шулай ук карагыз
Яңа гомуми каталог
Мессье җисемнәр исемлеге
5153
5153 | 20,415 |
https://zh.wikipedia.org/wiki/%E7%9A%AE%E5%A5%A5%E8%B4%9D%E5%A1%94 | Wikipedia | Open Web | CC-By-SA | 2,023 | 皮奥贝塔 | https://zh.wikipedia.org/w/index.php?title=皮奥贝塔&action=history | Chinese | Spoken | 13 | 257 | 皮奥贝塔（，；）是法国上科西嘉省的一个市镇，属于科尔泰区。
地理
（）面积，位于法国上科西嘉省，该省份位于科西嘉北部，后者为地中海西部的一座岛屿，也是法国的一个单一领土集体，位于法国大陆部分的东南面，意大利半島的西面，最临近的地块是撒丁岛。
与接壤的市镇（或旧市镇、城区）包括：。
的时区为UTC+01:00、UTC+02:00（夏令时）。
行政
的邮政编码为，INSEE市镇编码为。
政治
所属的省级选区为。
人口
于时的人口数量为人。
参考文献
P | 50,165 |
https://cs.wikipedia.org/wiki/Umanamente%20uomo%3A%20il%20sogno | Wikipedia | Open Web | CC-By-SA | 2,023 | Umanamente uomo: il sogno | https://cs.wikipedia.org/w/index.php?title=Umanamente uomo: il sogno&action=history | Czech | Spoken | 242 | 577 | Páté Battistiho album Umanamente uomo: il sogno uvedlo Battistiho ve známost v zahraničí. Album je vydáno ve Španělsku, Francii, Japonsku a Koreji, avšak s nevelkým úspěchem. V roce 1972 se v Itálii stalo po dobu devíti týdnů nejprodávanějším albem a 2. nejprodávanějším v celém roce 1972. Je to první album vydané ve vydavatelství Numero Uno, společném projektu dvojice Battisti-Mogol.
V jednotlivých písních je možno slyšet hlasy Maria Lavezzi, Oscara Prudenteho, Tonyho Ciccia a hlavně Babelle, Barbary a Sary.
I giardini di marzo je dodnes vrcholným Battistiho dílem, velice procítěný Mogolův text. Umanamente uomo: il sogno je dalším experimentem skladatele. Nemá text, ve dvou částech je melodie pouze „pískána“. Il fuoco také nemá text, je doplněno vzkřeky kapelníků. Il leone e la gallina je zpívaná bajka nemající obdoby. Texty všech písíní jsou vesměs lyrické, skladby působí melancholicky.
Seznam skladeb
V závorce je uveden počet hvězdiček dle CROSBOSP.
I giardini di marzo - 5:33 (7)
Innocenti evasioni - 3:48 (3)
E penso a te - 4:18 (5)
Umanamente uomo: il sogno - 3:24 (7)
Comunque bella - 3:53 (5)
Il leone e la gallina - 3:32 (5)
Sognando e risognando - 5:17 (7)
Il fuoco - 4:10 (4)
Skupina
12- a 6strunné kytary: Massimo Luca
elektrická kytara: Eugenio Guarraia, Massimo Luca, Lucio Battisti
basa: Angelo Salvador
bicí a baterie: Tony Ciccio
klavír: Lucio Battisti, Dario Baldan
ua ua: Lucio Battisti
varhany a klávesy: Dario Baldan
Alba z roku 1972
Alba Battistiho
Alba Numero Uno | 16,396 |
https://fr.wikipedia.org/wiki/R%C3%A9seau%20de%20chaleur%20de%20Reims | Wikipedia | Open Web | CC-By-SA | 2,023 | Réseau de chaleur de Reims | https://fr.wikipedia.org/w/index.php?title=Réseau de chaleur de Reims&action=history | French | Spoken | 494 | 802 | Très longtemps après celui des romains de Durocortorum, le réseau de chaleur de Reims a débuté en 1972, lors de la création du quartier Croix-Rouge. Il alimente aujourd’hui près de 17 000 logements.'''
Historique
Du temps des Romains
Le chauffage se fait par hypocauste. La vapeur d’eau chaude circule entre des colonnes de briques (les pilettes) qui supportent les dalles du sol des maisons et dans les murs.
Création
La création du réseau de chaleur de Reims a débuté en 1972 lors de la création du quartier Croix-Rouge.
Développements successifs
En 1998, la création d’un lien réseau entre l’usine d’incinération des ordures ménagères de Reims et la Chaufferie urbaine du quartier Croix-Rouge a permis d’étendre le réseau de chaleur et de relier 6000 logements supplémentaires et de le porter ainsi à 8 000 logements.
En 2012, la mise en service d'une chaufferie au bois, au sein de la Chaufferie urbaine du quartier Croix-Rouge, a permis en augmentant la ressource en néergie, d’étendre le réseau de chaleur et de relier 9000 logements supplémentaires et le porter ainsi à 17 000 logements.
Le réseau de chaleur autour de la verrerie OI
La verrerie O-I Glass a installé un récupérateur de chaleur en lien avec Dalkia filiale du Groupe EDF.
Un réseau de chaleur de 3,3 km a été construit en ?? et alimentera ultérieurement le Musée Saint-Remi de Reims.
Perspectives
Schéma directeur
La communauté urbaine du Grand Reims a réalisé un schéma directeur de réseau de chaleur entre 2017 et 2018.
Il a été adopté en 2019.
Il avait mis en évidence un potentiel d’un réseau autour du quartier Europe.
Extension du réseau vers Châtillons
Une nouvelle chaufferie biomasse est en cours de construction, au sein de la Chaufferie urbaine du quartier Croix-Rouge, pour une mise en service fin 2022.
Elle permettra d’étendre le réseau de chaleur au quartier Châtillons, et de relier 3000 logements supplémentaires et le porter ainsi à 20 000 logements sur les 105 000 logements que compte la commune de Reims.
Projet quartier Europe
Caractéristiques techniques du réseau
Longueur du réseau
Le réseau de chaleur a, actuellement, une longueur totale de 16 km et fournit de la chaleur à environ 17 000 équivalents logements.
Il alimente notamment :
Les quartiers Croix Rouge, Croix du Sud, Pays de France et Val de Murigny,
La Faculté de Droits et Lettres,
Le CHU de Reims – Maison Blanche, Robert Debré, Résidence Roux,
Les écoles, collèges et lycées de Croix Rouge et Val de Murigny,
Caractéristiques du réseau
Réseau primaire : partie du réseau entre la centrale et la station d'échange.
Station d'échange : ?
Sous-station :
Sous-station
Le réseau actuel comprend 59 points de livraison, chiffre qui devrait être porté à 77 à la fin des travaux d'extension vers le quartier des Châtillons.
Risques et accidents
Notes et références
Voir aussi
Articles connexes
Réseau de chaleur
Chaufferie urbaine du quartier Croix-Rouge
Usine d’incinération des ordures ménagères de Reims
Verdissement
Reims
Reims
Énergie dans la Marne | 16,999 |
https://simple.wikipedia.org/wiki/Twisted%20Metal%20%28video%20game%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Twisted Metal (video game) | https://simple.wikipedia.org/w/index.php?title=Twisted Metal (video game)&action=history | Simple English | Spoken | 206 | 277 | Twisted Metal is a vehicular combat video game published by Sony Computer Entertainment with product development by Sony Interactive Studios America and regular development by SingleTrac. It is the first game in the Twisted Metal series. It was released for the PlayStation and on the PlayStation Network.
It was released on November 5, 1995 in North America, January 16, 1996 in Europe, and on November 15, 1996 in Japan. It was also released on February 23, 2011 on the PlayStation Network. In the game, there is a competition where opponents face each other with different kinds of modified vehicles. The object of the game is to destroy their vehicles and be the last one standing. The winner meets Calypso, a mysterious man who grants them a wish.
Reception
IGN rated the game a 7 out of 10 and said ""The game's only downfall is that it's just too short. The game can be completed in just a couple of hours. However, the two-player split-screen combat mode more than makes up for the one-player mode's lack of length."" The game was successful and sold over 1.08 million copies in the United States alone.
References
Other websites
1995 video games
PlayStation games
Vehicular combat games
PlayStation Network games | 49,250 |
https://stackoverflow.com/questions/68264453 | StackExchange | Open Web | CC-By-SA | 2,021 | Stack Exchange | Santiago Squarzon, gorgorybmus, https://stackoverflow.com/users/15339544, https://stackoverflow.com/users/4065021 | English | Spoken | 238 | 326 | Python, find number string in one file, match that string inside of line from another file and replace string in first file with line from second file
File 1: HTML file generated from a Salesforce ticket report.
File 2: Text file with the same ticket numbers from the ticket report in File 1, but each line is formatted as HTML hyperlinks with the ticket numbers and URLs embedded.
Objective: Parse through File 1 for 9-digit ticket numbers, match those ticket numbers with the same ticket numbers embedded in hyperlink code from File 2, and replace each ticket number in File 1 with the corresponding line (hyperlink) from File 2.
To summarize: Replace ticket numbers in an HTML file with corresponding lines of hyperlink code from a text file.
*Doesn't necessarily need to be a Python solution, but it's for Windows.
We're here to help you with your code not to code for you. Please read https://stackoverflow.com/help/how-to-ask
Well, I've spent over a month trying to solve this problem with PowerShell, VBScript, batch files, and now Python.
I could provide the Python "code" that I have, but it's worthless as I have no experience with Python.
I posted a question a few weeks ago with my semi-working PoweShell code (trying to accomplish the same task) and I was scolded for including the code in the wrong format or something.
And so I didn't get much help on that question either.
| 25,929 |
https://stackoverflow.com/questions/3300336 | StackExchange | Open Web | CC-By-SA | 2,010 | Stack Exchange | Andrew Seravkin, Brad Larson, Douglas, Olivier Bernal, Paul Carruthers, Reymon Poumin, Zdenek Jonas, https://stackoverflow.com/users/119271, https://stackoverflow.com/users/19679, https://stackoverflow.com/users/383949, https://stackoverflow.com/users/6854819, https://stackoverflow.com/users/6854820, https://stackoverflow.com/users/6854821, https://stackoverflow.com/users/6854857, https://stackoverflow.com/users/6854933, https://stackoverflow.com/users/6855139, https://stackoverflow.com/users/6856125, https://stackoverflow.com/users/6858056, https://stackoverflow.com/users/686184, malthe rasmussen, mattholy, navdeepsharma, pqnet, yohann | English | Spoken | 449 | 746 | 2 lines mean it won't run on iPad
We have a project that runs fine on OS4 but we're having problems getting it to run on iPad 3.2.
Base SDK is 4.0 and Deployment target is 3.2.
The code crashes on the iPad simulator (and device) before it has even started, with the error
"Data Formatters temporarily
unavailable"
It seems to run okay if I take 2 lines out...
AVURLAsset* asset = [AVURLAsset URLAssetWithURL:assetURL options:options];
and
export = [[AVAssetExportSession alloc] initWithAsset:asset presetName:AVAssetExportPresetPassthrough];
I branch according to what OS is present so that these lines never get reached when on a 3.2 device (I know they are OS4), but just them being there at all makes the thing crash out before it even begins.
Any ideas?
Cheers
If those lines are never reached on the iPad, you may be encountering a problem due to not weak-linking the AVFoundation framework (and potentially others). Because AVURLAsset and AVAssetExportSession don't exist as symbols in 3.2, your application may be crashing on startup on that older OS.
I describe how to weak-link a framework in response to a similar problem in this answer.
Spot on Brad! That fixed it straight away.
specifying deployment target to some earlier version wouldn't automatically weak link symbols which don't exist in that version?
@pqnet - With the iOS 4.2 SDK and a target of iOS 3.1 and later, you can now use per-class weak linking instead of framework-based weak linking: http://www.marco.org/2010/11/22/supporting-older-versions-of-ios-while-using-new-apis . I'm not sure what the Mac runtimes and SDK versions are that support this as well. For a target older than 3.1, you'd still need to weak link the framework.
First of all, "Data Formatters temporarily unavailable" is a GDB message, it's not why your application crashes. More information regarding this message can be found here.
You need to check the availability of classes during runtime (not compile-time) if you want to write code that runs on both iOS 3.0 and 4.0.
You can do this using the NSClassFromString function like this:
if (NSClassFromString(@"AVURLAsset")) {
// 4.0 code using AVURLAsset goes here
} else {
// 3.0 code goes here
}
Try this (or similar):
#if __IPHONE_OS_VERSION_MIN_REQUIRED < 40000
// code for iOS below 4.0
#else
// code for iOS 4.0
#endif
Stolen from this question.
I think he will have to upload a single binary to run on 4.0 and 3.2, so the check will have to be at run time, not compile time.
Indeed - the same binary for both. The lines I quoted are never even reached if running on 3.2 as I already branch off. What puzzles me is that their inclusion means that the binary will not even start on 3.2.
| 3,086 |
https://ru.wikipedia.org/wiki/Bromheadia | Wikipedia | Open Web | CC-By-SA | 2,023 | Bromheadia | https://ru.wikipedia.org/w/index.php?title=Bromheadia&action=history | Russian | Spoken | 488 | 1,320 | Bromheadia — монофилетический род многолетних эпифитных и наземных травянистых растений семейства .
Все виды рода Bromheadia входят в Приложение II Конвенции CITES. Цель Конвенции состоит в том, чтобы гарантировать, что международная торговля дикими животными и растениями не создаёт угрозы их выживанию.
Аббревиатура родового названия в любительском и промышленном цветоводстве — Brom..
Род не имеет устоявшегося русского названия.
Этимология
Род назван в честь ботаника Эдварда Бромхэда.
Распространение
Юго-Восточная Азия, Индия, Малайзия, Новая Гвинея, Австралия, острова Тихого океана.
Биологическое описание
Симподиальные растения средних и крупных размеров. Вегетативная часть многих видов напоминает дендробиумы.
Виды
По данным Королевских ботанических садов в Кью:
Bromheadia alticola Ridl., 1891
Bromheadia annamensis Aver. & Averyanova, 2006
Bromheadia aporoides Rchb.f., 1878
Bromheadia borneensis J.J.Sm., 1917
Bromheadia borneensis var. borneensis
Bromheadia borneensis var. longiflora Scheind. & de Vogel, 1997
Bromheadia brevifolia Ridl., 1897
Bromheadia cecieliae Kruiz., 1997
Bromheadia coomansii J.J.Sm. ex Kruiz. & de Vogel, 1997
Bromheadia crassiflora J.J.Sm., 1931
Bromheadia devogelii Kruiz., 1997
Bromheadia divaricata Ames & C.Schweinf. in O.Ames, 1920
Bromheadia ensifolia J.J.Sm., 1926
Bromheadia falcifolia Schltr., 1912
Bromheadia finlaysoniana (Lindl.) Miq., 1859
Bromheadia gracilis Kruiz. & de Vogel, 1997
Bromheadia graminea Kruiz. & de Vogel, 1997
Bromheadia grandiflora Kruiz. & de Vogel, 1997
Bromheadia humilis Kruiz. & de Vogel, 1997
Bromheadia latifolia Kruiz. & de Vogel, 1997
Bromheadia lohaniensis Kruiz. & de Vogel, 1997
Bromheadia longifolia Kruiz. & de Vogel, 1997
Bromheadia pendek de Vogel, 1997
Bromheadia pulchra Schltr., 1912
Bromheadia pungens Ridl., 1897
Bromheadia robusta Kruiz. & de Vogel, 1997
Bromheadia rupestris Ridl., 1897
Bromheadia scirpoidea Ridl., 1900
Bromheadia srilankensis Kruiz. & de Vogel, 1997
Bromheadia tenuis J.J.Sm., 1931
Bromheadia truncata Seidenf., 1984
Использование
Корни Bromheadia finlaysoniana отваривают и принимают внутрь при ревматизме и болях в суставах.
Примечания
Ссылки
Таксономия Bromheadia на сайте Tropicos.org. Missouri Botanical Garden.
Фотографии Bromheadia на сайте flickr.com
Литература
O'Byrne P, 2001, An A to Z of South East Asian orchids: part 2. Orchid Rev. 109. (1238): 81-85
Kruizinga J, Scheindelen HJ van, Vogel EF de, 1997, Revision of the genus Bromheadia (Orchidaceae). Orchid Monogr. 8. 79-118, 176-178, 209-235, pl.4-5
Repetur CP, Welzen PC van, Vogel EF de, 1997, Phylogeny and historical biogeography of the genus Bromheadia (Orchidaceae). Syst. Bot. 22. (3): 465-477
Senghas K, 1989, Bromheadia aporoides Rchb. f. 1878. Orchidee 40. (6): centre page pullout (2p.)
Lavarack PS, Clements MA, Howcroft NHS, 1984, Bromheadia pulchra Schltr in Australia and New Guinea. Orchadian, 7. (12): 291-294
Seidenfaden G, 1983, Orchid genera in Thailand: 11. Cymbidieae Pfitz. Op. Bot., no.72. 1-124
Yong HS, 1978, Orchid portraits: 2. The common Bromheadia. Nat. Malaysiana 3. (2): 28 - 29
Kerr AD, 1972, Ephemeral means 'don't turn your head.' Amer. Orchid Soc. Bull. 41. (3): 208-211
Kerr AD, 1972, Ephemeral means 'don't turn your head.' Amer. Orchid Soc. Bull. 41. (3): 208-211
Laverack P, 1972, Two rare terrestrial orchids from Cape York Peninsula. Orchadian 4. (6): 51
Орхидные
Приложения СИТЕС
Флора Юго-Восточной Азии
Флора Австралии
Комнатные растения
Таксоны растений, названные в честь людей | 24,656 |
https://ceb.wikipedia.org/wiki/Gigasporaceae | Wikipedia | Open Web | CC-By-SA | 2,023 | Gigasporaceae | https://ceb.wikipedia.org/w/index.php?title=Gigasporaceae&action=history | Cebuano | Spoken | 59 | 134 | Pamilya sa mga uhong ang Gigasporaceae. Ang Gigasporaceae sakop sa kahanay nga Diversisporales, klase nga Glomeromycetes, division nga Glomeromycota, ug kaginharian nga uhong. Ang kabanay nga Gigasporaceae pagsakop 39 espesye, segun Catalogue of Life.
Mao ni ang iyang kladogram matod sa Catalogue of Life:
Ang mga gi basihan niini
Gikan sa gawas nga tinubdan
Galeriya sa hulagway
Uhong
Gigasporaceae | 17,382 |
https://stackoverflow.com/questions/19154631 | StackExchange | Open Web | CC-By-SA | 2,013 | Stack Exchange | Isaac, Jeremy, Jonas Berlin, Lars Kotthoff, Perry, computercarguy, https://stackoverflow.com/users/1172002, https://stackoverflow.com/users/1308685, https://stackoverflow.com/users/1356047, https://stackoverflow.com/users/1836461, https://stackoverflow.com/users/1861779, https://stackoverflow.com/users/2622511, https://stackoverflow.com/users/2762324, t.888 | English | Spoken | 2,521 | 7,380 | How to get coordinates of an svg element?
I am using d3 to draw a line from a relative svg position and hence want to access the coordinates of the element itself. I tried something like this (where "this" refers to the element)
.attr("x1", this.x)
.attr("y1", this.y)
but the x1 and y1 just defaults to zero. What is the correct way to get the coordinates of the svg element?
EDIT:
Here's my (by request) my whole code. I'm trying to implement this on the collapsible tree, where I draw a line when I hover with the mouse over a circle node. The starting point of the line should be from the circle I click on and the ending point should be a fixed point on the svg plane.
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8">
<script type="text/javascript" src="d3.v3.js"></script>
<script type="text/javascript" src="d3.layout.js"></script>
<style type="text/css">
.node circle {
cursor: pointer;
fill: #fff;
stroke: steelblue;
stroke-width: 1.5px;
}
.node text {
font: 10px sans-serif;
}
path.link {
fill: none;
stroke: #ccc;
stroke-width: 1.5px;
}
</style>
</head>
<body>
<div id="chart"></div>
<script type="text/javascript">
var m = [20, 120, 20, 120],
w = 2240 - m[1] - m[3],
h = 800 - m[0] - m[2],
i = 0,
duration = 500,
root;
var tree = d3.layout.tree()
.size([h, w]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var vis = d3.select("#chart").append("svg")
.attr("width", w + m[1] + m[3])
.attr("height", h + m[0] + m[2])
.append("g")
.attr("transform", "translate(" + m[3] + "," + m[0] + ")");
function loadData(json) {
root = json;
d3.select("#processName").html(root.text);
root.x0 = h / 2;
root.y0 = 0;
root.children.forEach(collapse);
update(root);
}
function collapse(d) {
if (d.children) {
d._children = d.children;
d._children.forEach(collapse);
d.children = null;
}
};
// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(d);
}
function update(source) {
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse();
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 180; });
// Update the nodes…
var node = vis.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", click);
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; })
.on('mouseover', function(d, i){
var dataset = [1,2,3,4] // HERE
vis.selectAll("line") // HERE
.data(dataset) // HERE
.enter() // HERE
.append("line") // HERE
.attr("x1", this.x) // HERE'S THE PROBLEM FOR PERRY
.attr("y1", this.y) // HERE'S THE PROBLEM FOR PERRY
.attr("x2", 500) // HERE
.attr("y2", 500) // HERE
.style("stroke", "rgb(6,120,155)");} // HERE
);
nodeEnter.append("text")
.attr("x", function(d) { return d.children || d._children ? -10 : 10; })
.attr("dy", ".35em")
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) { return d.name; })
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });
nodeUpdate.select("circle")
.attr("r", 4.5)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();
nodeExit.select("circle")
.attr("r", 1e-6);
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = vis.selectAll("path.link")
.data(tree.links(nodes), function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
})
.transition()
.duration(duration)
.attr("d", diagonal);
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
};
loadData({
"name": "flare",
"children": [
{
"name": "analytics",
"children": [
{
"name": "cluster",
"children": [
{"name": "AgglomerativeCluster", "size": 3938},
{"name": "CommunityStructure", "size": 3812},
{"name": "HierarchicalCluster", "size": 6714},
{"name": "MergeEdge", "size": 743}
]
},
{
"name": "graph",
"children": [
{"name": "BetweennessCentrality", "size": 3534},
{"name": "LinkDistance", "size": 5731},
{"name": "MaxFlowMinCut", "size": 7840},
{"name": "ShortestPaths", "size": 5914},
{"name": "SpanningTree", "size": 3416}
]
},
{
"name": "optimization",
"children": [
{"name": "AspectRatioBanker", "size": 7074}
]
}
]
},
{
"name": "animate",
"children": [
{"name": "Easing", "size": 17010},
{"name": "FunctionSequence", "size": 5842},
{
"name": "interpolate",
"children": [
{"name": "ArrayInterpolator", "size": 1983},
{"name": "ColorInterpolator", "size": 2047},
{"name": "DateInterpolator", "size": 1375},
{"name": "Interpolator", "size": 8746},
{"name": "MatrixInterpolator", "size": 2202},
{"name": "NumberInterpolator", "size": 1382},
{"name": "ObjectInterpolator", "size": 1629},
{"name": "PointInterpolator", "size": 1675},
{"name": "RectangleInterpolator", "size": 2042}
]
},
{"name": "ISchedulable", "size": 1041},
{"name": "Parallel", "size": 5176},
{"name": "Pause", "size": 449},
{"name": "Scheduler", "size": 5593},
{"name": "Sequence", "size": 5534},
{"name": "Transition", "size": 9201},
{"name": "Transitioner", "size": 19975},
{"name": "TransitionEvent", "size": 1116},
{"name": "Tween", "size": 6006}
]
},
{
"name": "data",
"children": [
{
"name": "converters",
"children": [
{"name": "Converters", "size": 721},
{"name": "DelimitedTextConverter", "size": 4294},
{"name": "GraphMLConverter", "size": 9800},
{"name": "IDataConverter", "size": 1314},
{"name": "JSONConverter", "size": 2220}
]
},
{"name": "DataField", "size": 1759},
{"name": "DataSchema", "size": 2165},
{"name": "DataSet", "size": 586},
{"name": "DataSource", "size": 3331},
{"name": "DataTable", "size": 772},
{"name": "DataUtil", "size": 3322}
]
},
{
"name": "display",
"children": [
{"name": "DirtySprite", "size": 8833},
{"name": "LineSprite", "size": 1732},
{"name": "RectSprite", "size": 3623},
{"name": "TextSprite", "size": 10066}
]
},
{
"name": "flex",
"children": [
{"name": "FlareVis", "size": 4116}
]
},
{
"name": "physics",
"children": [
{"name": "DragForce", "size": 1082},
{"name": "GravityForce", "size": 1336},
{"name": "IForce", "size": 319},
{"name": "NBodyForce", "size": 10498},
{"name": "Particle", "size": 2822},
{"name": "Simulation", "size": 9983},
{"name": "Spring", "size": 2213},
{"name": "SpringForce", "size": 1681}
]
},
{
"name": "query",
"children": [
{"name": "AggregateExpression", "size": 1616},
{"name": "And", "size": 1027},
{"name": "Arithmetic", "size": 3891},
{"name": "Average", "size": 891},
{"name": "BinaryExpression", "size": 2893},
{"name": "Comparison", "size": 5103},
{"name": "CompositeExpression", "size": 3677},
{"name": "Count", "size": 781},
{"name": "DateUtil", "size": 4141},
{"name": "Distinct", "size": 933},
{"name": "Expression", "size": 5130},
{"name": "ExpressionIterator", "size": 3617},
{"name": "Fn", "size": 3240},
{"name": "If", "size": 2732},
{"name": "IsA", "size": 2039},
{"name": "Literal", "size": 1214},
{"name": "Match", "size": 3748},
{"name": "Maximum", "size": 843},
{
"name": "methods",
"children": [
{"name": "add", "size": 593},
{"name": "and", "size": 330},
{"name": "average", "size": 287},
{"name": "count", "size": 277},
{"name": "distinct", "size": 292},
{"name": "div", "size": 595},
{"name": "eq", "size": 594},
{"name": "fn", "size": 460},
{"name": "gt", "size": 603},
{"name": "gte", "size": 625},
{"name": "iff", "size": 748},
{"name": "isa", "size": 461},
{"name": "lt", "size": 597},
{"name": "lte", "size": 619},
{"name": "max", "size": 283},
{"name": "min", "size": 283},
{"name": "mod", "size": 591},
{"name": "mul", "size": 603},
{"name": "neq", "size": 599},
{"name": "not", "size": 386},
{"name": "or", "size": 323},
{"name": "orderby", "size": 307},
{"name": "range", "size": 772},
{"name": "select", "size": 296},
{"name": "stddev", "size": 363},
{"name": "sub", "size": 600},
{"name": "sum", "size": 280},
{"name": "update", "size": 307},
{"name": "variance", "size": 335},
{"name": "where", "size": 299},
{"name": "xor", "size": 354},
{"name": "_", "size": 264}
]
},
{"name": "Minimum", "size": 843},
{"name": "Not", "size": 1554},
{"name": "Or", "size": 970},
{"name": "Query", "size": 13896},
{"name": "Range", "size": 1594},
{"name": "StringUtil", "size": 4130},
{"name": "Sum", "size": 791},
{"name": "Variable", "size": 1124},
{"name": "Variance", "size": 1876},
{"name": "Xor", "size": 1101}
]
},
{
"name": "scale",
"children": [
{"name": "IScaleMap", "size": 2105},
{"name": "LinearScale", "size": 1316},
{"name": "LogScale", "size": 3151},
{"name": "OrdinalScale", "size": 3770},
{"name": "QuantileScale", "size": 2435},
{"name": "QuantitativeScale", "size": 4839},
{"name": "RootScale", "size": 1756},
{"name": "Scale", "size": 4268},
{"name": "ScaleType", "size": 1821},
{"name": "TimeScale", "size": 5833}
]
},
{
"name": "util",
"children": [
{"name": "Arrays", "size": 8258},
{"name": "Colors", "size": 10001},
{"name": "Dates", "size": 8217},
{"name": "Displays", "size": 12555},
{"name": "Filter", "size": 2324},
{"name": "Geometry", "size": 10993},
{
"name": "heap",
"children": [
{"name": "FibonacciHeap", "size": 9354},
{"name": "HeapNode", "size": 1233}
]
},
{"name": "IEvaluable", "size": 335},
{"name": "IPredicate", "size": 383},
{"name": "IValueProxy", "size": 874},
{
"name": "math",
"children": [
{"name": "DenseMatrix", "size": 3165},
{"name": "IMatrix", "size": 2815},
{"name": "SparseMatrix", "size": 3366}
]
},
{"name": "Maths", "size": 17705},
{"name": "Orientation", "size": 1486},
{
"name": "palette",
"children": [
{"name": "ColorPalette", "size": 6367},
{"name": "Palette", "size": 1229},
{"name": "ShapePalette", "size": 2059},
{"name": "SizePalette", "size": 2291}
]
},
{"name": "Property", "size": 5559},
{"name": "Shapes", "size": 19118},
{"name": "Sort", "size": 6887},
{"name": "Stats", "size": 6557},
{"name": "Strings", "size": 22026}
]
},
{
"name": "vis",
"children": [
{
"name": "axis",
"children": [
{"name": "Axes", "size": 1302},
{"name": "Axis", "size": 24593},
{"name": "AxisGridLine", "size": 652},
{"name": "AxisLabel", "size": 636},
{"name": "CartesianAxes", "size": 6703}
]
},
{
"name": "controls",
"children": [
{"name": "AnchorControl", "size": 2138},
{"name": "ClickControl", "size": 3824},
{"name": "Control", "size": 1353},
{"name": "ControlList", "size": 4665},
{"name": "DragControl", "size": 2649},
{"name": "ExpandControl", "size": 2832},
{"name": "HoverControl", "size": 4896},
{"name": "IControl", "size": 763},
{"name": "PanZoomControl", "size": 5222},
{"name": "SelectionControl", "size": 7862},
{"name": "TooltipControl", "size": 8435}
]
},
{
"name": "data",
"children": [
{"name": "Data", "size": 20544},
{"name": "DataList", "size": 19788},
{"name": "DataSprite", "size": 10349},
{"name": "EdgeSprite", "size": 3301},
{"name": "NodeSprite", "size": 19382},
{
"name": "render",
"children": [
{"name": "ArrowType", "size": 698},
{"name": "EdgeRenderer", "size": 5569},
{"name": "IRenderer", "size": 353},
{"name": "ShapeRenderer", "size": 2247}
]
},
{"name": "ScaleBinding", "size": 11275},
{"name": "Tree", "size": 7147},
{"name": "TreeBuilder", "size": 9930}
]
},
{
"name": "events",
"children": [
{"name": "DataEvent", "size": 2313},
{"name": "SelectionEvent", "size": 1880},
{"name": "TooltipEvent", "size": 1701},
{"name": "VisualizationEvent", "size": 1117}
]
},
{
"name": "legend",
"children": [
{"name": "Legend", "size": 20859},
{"name": "LegendItem", "size": 4614},
{"name": "LegendRange", "size": 10530}
]
},
{
"name": "operator",
"children": [
{
"name": "distortion",
"children": [
{"name": "BifocalDistortion", "size": 4461},
{"name": "Distortion", "size": 6314},
{"name": "FisheyeDistortion", "size": 3444}
]
},
{
"name": "encoder",
"children": [
{"name": "ColorEncoder", "size": 3179},
{"name": "Encoder", "size": 4060},
{"name": "PropertyEncoder", "size": 4138},
{"name": "ShapeEncoder", "size": 1690},
{"name": "SizeEncoder", "size": 1830}
]
},
{
"name": "filter",
"children": [
{"name": "FisheyeTreeFilter", "size": 5219},
{"name": "GraphDistanceFilter", "size": 3165},
{"name": "VisibilityFilter", "size": 3509}
]
},
{"name": "IOperator", "size": 1286},
{
"name": "label",
"children": [
{"name": "Labeler", "size": 9956},
{"name": "RadialLabeler", "size": 3899},
{"name": "StackedAreaLabeler", "size": 3202}
]
},
{
"name": "layout",
"children": [
{"name": "AxisLayout", "size": 6725},
{"name": "BundledEdgeRouter", "size": 3727},
{"name": "CircleLayout", "size": 9317},
{"name": "CirclePackingLayout", "size": 12003},
{"name": "DendrogramLayout", "size": 4853},
{"name": "ForceDirectedLayout", "size": 8411},
{"name": "IcicleTreeLayout", "size": 4864},
{"name": "IndentedTreeLayout", "size": 3174},
{"name": "Layout", "size": 7881},
{"name": "NodeLinkTreeLayout", "size": 12870},
{"name": "PieLayout", "size": 2728},
{"name": "RadialTreeLayout", "size": 12348},
{"name": "RandomLayout", "size": 870},
{"name": "StackedAreaLayout", "size": 9121},
{"name": "TreeMapLayout", "size": 9191}
]
},
{"name": "Operator", "size": 2490},
{"name": "OperatorList", "size": 5248},
{"name": "OperatorSequence", "size": 4190},
{"name": "OperatorSwitch", "size": 2581},
{"name": "SortOperator", "size": 2023}
]
},
{"name": "Visualization", "size": 16540}
]
}
]
});
</script>
</body>
</html>
The way to determine the coordinates depends on what element you're working with. For circles for example, the cx and cy attributes determine the center position. In addition, you may have a translation applied through the transform attribute which changes the reference point of any coordinates.
Most of the ways used in general to get screen coordinates won't work for SVGs. In addition, you may not want absolute coordinates if the line you want to draw is in the same container as the elements it connects.
Edit:
In your particular code, it's quite difficult to get the position of the node because its determined by a translation of the parent element. So you need to get the transform attribute of the parent node and extract the translation from that.
d3.transform(d3.select(this.parentNode).attr("transform")).translate
Working jsfiddle here.
I happen to be working with circles so I changed the coordinates to .attr("x1", this.cx) and .attr("x1", this.cy) but still defaults to zero. How can it do that if the coordinates of a circle is cx and cy? Am I totally misunderstanding something? (would be possible, because I haven't jumped over the steep learning curve that d3 has :P)
Depends entirely on what this is. Have you tried d3.select(this).attr("cx")?
this is the circle I am working with. I also tried d3.select(this).attr("cx") but still defaults to zero.
Couldn't upload it on jsfiddle for some reason so included the whole code in my question (should be easy to copy since I include the json in the code). I also highlight where exactly the problem is.
If what's needed is the actual element position relative to its container, element.getBoundingClientRect() should do the trick. See here: http://stackoverflow.com/questions/18554224/getting-screen-positions-of-d3-nodes-after-transform
I get an error in d3 v4, stating that transform is not a function (the example jsfiddle above is in v3). [this is not a criticism, the answer is correct for v3]
The element.getBoundingClientRect() method will return the proper coordinates of an element relative to the viewport regardless of whether the svg has been scaled and/or translated.
See this question and answer.
While getBBox() works for an untransformed space, if scale and translation have been applied to the layout then it will no longer be accurate. The getBoundingClientRect() function has worked well for me in a force layout project when pan and zoom are in effect, where I wanted to attach HTML Div elements as labels to the nodes instead of using SVG Text elements.
Note that at least in Firefox 59 element.getBoundingClientRect() works with transform="rotate(25)" but not with style="transform: rotate(25deg)" e.g. css transformations.
You can use the function getBBox() to get the bounding box for the path. This will give you the position and size of the tightest rectangle that could contain the rendered path.
An advantage of using this method over reading the x and y values is that it will work with all graphical objects. There are more objects than paths that do not have x and y, for example circles that have cx and cy instead.
I use the consolidate function, like so:
element.transform.baseVal.consolidate()
The .e and .f values correspond to the x and y coordinates
This apparently no longer works in Chrome. It returns null for me.
i can handle it like that ;
svg.selectAll("rect")
.data(zones)
.enter()
.append("rect")
.attr("id", function (d) { return "zone" + d.zone; })
.attr("class", "zone")
.attr("x", function (d, i) {
if (parseInt(i / (wcount)) % 2 == 0) {
this.xcor = (i % wcount) * zoneW;
}
else {
this.xcor = (zoneW * (wcount - 1)) - ((i % wcount) * zoneW);
}
return this.xcor;
})
and anymore you can find x coordinate
svg.select("#zone1").on("click",function(){alert(this.xcor});
svg.selectAll("rect")
.attr('x',function(d,i){
// get x coord
console.log(this.getBBox().x, 'or', d3.select(this).attr('x'))
})
.attr('y',function(d,i){
// get y coord
console.log(this.getBBox().y)
})
.attr('dx',function(d,i){
// get dx coord
console.log(parseInt(d3.select(this).attr('dx')))
})
Thanks, your reference to getBBox() is helpful, but some explanation would complete the answer
I was trying to select an area of svg with a rectangle and get all the elements from it. For this, element.getBoundingClientRect() worked perfectly for me. It returns current coordinates of svg elements regardless of whether svg is scaled or transformed.
Let's assume that you draw rect inside g inside svg. You applied some transformations to g. And you want to get local x,y rect coordinates when you move mouse over rect.
Example in TypeScript
rectD3Selection.on('mousemove', (event: MouseEvent) => {
const clientBox = (event.currentTarget as SVGRectElement).getBBox();
const clientRect = (event.currentTarget as SVGRectElement).getBoundingClientRect();
const localX = Math.round(((event.clientX - clientRect.x) / clientRect.width) * clientBox.width);
const localY = Math.round(((event.clientY - clientRect.y) / clientRect.height) * clientBox.height);
});
| 41,773 |
https://arz.wikipedia.org/wiki/2MASX%20J12444998%2B4221231%20%28%D9%85%D8%AC%D8%B1%D9%87%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | 2MASX J12444998+4221231 (مجره) | https://arz.wikipedia.org/w/index.php?title=2MASX J12444998+4221231 (مجره)&action=history | Egyptian Arabic | Spoken | 175 | 492 | 2MASX J12444998+4221231 هيا مجره بتتبع كوكبة كينيز ڤيناتيساى و معناها كلاب صيد اللى هيا كوكبه فى دايرة البروج من ابراج النص الشمالى للكوره الارضيه.
معلومات المجره
الانزياح الأحمر: 0.05363.
السرعه الشعاعيه: 15647.
المطلع المستقيم: 191.20825.
الميل: 42.356425.
مصطلحات تعريفيه
الكوكبه هيا مجموعه من النجوم اللى بتكون شكل أو صوره و هيا مجال الكره السماويه اللى المجره جزء منها.
الانزياح الاحمر هو زيادة طول الموجه الكهرومغناطيسيه اللى جايه لينا من المجره بسبب سرعه ابتعادها عننا. ده بيستخدم فى حسابات الفلك.
السرعه الشعاعيه هيا سرعه الجرم الفضائى فى اتجاه الراصد و بتنقاس بالانزياح الاحمر.
المطلع المستقيم هوا الزاويه المحصوره بين الدايره الساعيه لجرم سماوى و الدايره الساعيه لنقطة الاعتدال الربيعى. المطلع المستقيم ممكن يتقاس بقوس دايره الاستواء السماويه من نقطه الاعتدال الربيعى لحد نقطه تقاطع الدايره الساعيه لجرم سماوى مع دايره الاستواء السماويه.
الميل هوا المكافئ الفلكى لخط العرض و بيتقس بقيمة الزاويه بين أى جسم سماوى وخط الاستوا السماوى. لو كان النجم شمال خط الاستوا السماوى تكون قيمة بعده بالموجب (+) و لو النجم جنوب خط الاستوا السماوى تكون قيمة بعده بالسالب (-).
مصادر
مجرات
فضاء | 8,734 |
https://sv.wikipedia.org/wiki/Willie%20Pearse | Wikipedia | Open Web | CC-By-SA | 2,023 | Willie Pearse | https://sv.wikipedia.org/w/index.php?title=Willie Pearse&action=history | Swedish | Spoken | 57 | 134 | Willie Pearse född 1891, död 1916 (avrättad), var en irländsk revolutionär frihetskämpe, bror till Patrick Pearse. Bröderna deltog i Påskupproret 1916, och arkebuserades efter att upproret slagits ner av de brittiska trupperna.
Källor
Personer på Irland under 1900-talet
Personer som blivit avrättade av Storbritannien under 1900-talet
Personer som blivit avrättade genom arkebusering
Födda 1891
Avlidna 1916
Män | 22,001 |
https://en.wikipedia.org/wiki/United%20Nations%20Security%20Council%20Resolution%20121 | Wikipedia | Open Web | CC-By-SA | 2,023 | United Nations Security Council Resolution 121 | https://en.wikipedia.org/w/index.php?title=United Nations Security Council Resolution 121&action=history | English | Spoken | 73 | 106 | United Nations Security Council Resolution 121, adopted unanimously on December 12, 1956, after examining the application of Japan for membership in the United Nations, the UN Security Council recommended to the General Assembly that Japan be admitted.
See also
List of United Nations Security Council Resolutions 101 to 200 (1953–1965)
Japan and the United Nations
References
Text of the Resolution at undocs.org
External links
0121
0121
0121
1956 in Japan
December 1956 events | 16,905 |
https://nl.wikipedia.org/wiki/Lill-Babs | Wikipedia | Open Web | CC-By-SA | 2,023 | Lill-Babs | https://nl.wikipedia.org/w/index.php?title=Lill-Babs&action=history | Dutch | Spoken | 476 | 928 | Lill-Babs, volledige naam Barbro Margareta Svensson (Järvsö, 9 maart 1938 – Stockholm, 3 april 2018), was een Zweeds zangeres.
Loopbaan
Op 15-jarige leeftijd werd ze door de orkestleider en platenproducent Simon Brehm ontdekt op de radio en mocht ze audities gaan doen. In 1954 nam ze haar eerste plaat op, Min mammas boogie. Ze had veel succes, maar haar carrière werd onderbroken door zwangerschap. Terug naar haar oude werk kon ze niet, want Simon Brehm had al een zangeres gevonden. Toen ze opnieuw succes kreeg, vroeg Brehm haar terug. Lill-Babs werd een van de bekendste zangeressen van Zweden en speelde ook in films en televisieseries. In 1959 had ze een grote hit met het door Stig Anderson geschreven Är du kär i mej ännu, Klas-Göran? (in Nederland bekend als Hou je echt nog van mij, Rocking Billy? van Ria Valk). Ze werd in de jaren zestig ook in Duitsland zeer bekend.
In 1960 en 1961 deed ze mee aan Melodifestivalen als aanloop naar het Eurovisiesongfestival. Beide pogingen leken vergeefs, maar toen Siw Malmkvist, die in 1961 het Melodifestival had gewonnen met April, april, telkens de slappe lach kreeg bij een fluitpassage, verkoos de Zweedse omroep haar thuis te laten. Ze stuurden alsnog Lill-Babs, die 14e werd met 2 punten. Ook deed ze in Noorwegen mee aan de Melodi Grand Prix. In 2017 kreeg ze een plek in de Swedish Music Hall of Fame.
De eerste dochter van Lill-Babs werd geboren in 1955. Ze was van 1965 tot 1968 getrouwd met de zanger Lasse Berghagen. In 1966 kregen ze een dochter. Daarna was ze van 1969 tot 1973 getrouwd met de Noorse voetballer Kjell Kaspersen, met wie ze in 1969 een derde dochter kreeg. In 1996 publiceerde ze haar autobiografie Hon är jag ("Haar ben ik").
Ze speelde Gugge in Bonusfamiljen, de laatste reeks waarin ze een rol kreeg. Haar vrij onverwachte dood heeft ervoor gezorgd dat het script aangepast moest worden. Ook in de reeks moest ze dus overlijden, vroeger dan oorspronkelijk voorzien was.
Ze leed aan kanker, toen ze op 80-jarige leeftijd stierf aan een hartstilstand.
Albumdiscografie
1962: Splorr
1964: Svensson hyllar Alpertsson
1967: Lill-Babs
1968: Lill-Babs
1971: Välkommen till världen
1972: Jag ska sjunga för dig
1973: Hurra hurra
1975: Det våras för Barbro
1976: Lev mänska lev
1977: På scen
1979: Till mina vänner
1982: Lill-Babs i en show av Lars Forssell
1982: Det är ju min show!
1984: Barbro
1998: Who's Sorry Now
2005: Här är jag
Filmografie
1956: Suss gott
1959: Fly mej en greve
1961: Svenska Floyd
1962: En nolla för mycket
1965: Pang i bygget
1965: Calle P
1989: Imorron och imorron och imorron
1990: Vem tar vem (tv-show)
1998: Mulan (als stemacteur en zangeres)
2002: Rederiet (gastrol)
2012: Den sista dokusåpan
2017: Bonusfamiljen (tv-serie)
Zweeds zanger
Schlagerzanger
Pseudoniem
Deelnemer aan het Eurovisiesongfestival 1961
Zweeds deelnemer aan het Eurovisiesongfestival | 49,519 |
https://stackoverflow.com/questions/38432220 | StackExchange | Open Web | CC-By-SA | 2,016 | Stack Exchange | Ewout, https://stackoverflow.com/users/2209390, https://stackoverflow.com/users/4746397, hveiga | English | Spoken | 230 | 442 | Error message "unable to create new native thread" using SMB endpoint
I'm getting a java.lang.OutOfMemoryError: unable to create new native thread error during transfer of around 20 files using SMB endpoint.
Camel version 2.13.
The route itself is quite simple:
<route id="Filetransfer">
<from uri="ftp://user@server//source/map?password=pwd&include=fileA.*.csv|fileB.*.csv|fileC.*.csv|fileD.*.csv|fileE.*.csv|fileF.*.csv&move=save&consumer.delay=30000" />
<log message="${routeId}: ${header.CamelFileName}" />
<to uri="smb://domain;user@server/target/map?password=pwd"/>
</route>
When I check the number of threads in Hawtio dashboard the thread count is hitting a peak of 1000. The route executes correctly when only some small files are transferred. When some biggger
files (>5Mb, >100.000 lines) are transferred, the route gives the error.
When I replace the SMB endpoint with a FILE endpoint like <to uri="file:///tmp/camel"/> the route also executes correctly, and all the files are transferred.
Splitting the file per line first, and then use the Append option in the SMB endpoint causes the same error.
What can I do to make the SMB endpoint work, regardless the size of the files?
In general when that Error happens is because the OS is refusing to create new threads for your application. Probably, some of your code is creating many many threads somewhere and not finishing them.
The problem I face is that I dont know where I can control the creation/ending of threads in a SMB endpoint in Servicemix.
I don't have this issue on a test-environment, but I dont't know where to look for differences.
| 28,745 |
https://stackoverflow.com/questions/26054068 | StackExchange | Open Web | CC-By-SA | 2,014 | Stack Exchange | English | Spoken | 143 | 260 | VBA- Data Validation error
I have a protected sheet , but the cells B12:B27 are not locked . this code is not working with locked sheets. any idea?.
If Not Application.Intersect(Target, Range("B12:B37")) Is Nothing Then
With Range("B" & ActiveCell.Row).Validation
.Delete
.Add Type:=xlValidateList, AlertStyle:=xlValidAlertStop, Operator:= _
xlBetween, Formula1:="B,E,R,TG,TU,V"
End With
End If
Thanks
When protecting the worksheet you have the option to allow deleting rows or deleting columns. Deleting individual cells is not an option because it could affect locked cells.
The .Delete command will remove the cell entirely, meaning the existing cells below or to the right will either need to be moved up or left respectively. If this is what you want to do, you will need to unprotect your sheet first.
ActiveSheet.Unprotect
' your code
ActiveSheet.Protect
If you just want to clear the contents of the cell, you can use
.ClearContents
| 18,497 | |
https://stackoverflow.com/questions/11068755 | StackExchange | Open Web | CC-By-SA | 2,012 | Stack Exchange | Norwegian Nynorsk | Spoken | 89 | 203 | get the currently selected option in a form
im trying to get the currently selected option in a dropdown menu with javascript. but i cant seem to get it to work
my current js:
var itemqual = $("select#itemqual option:selected").text();
var type = "hat";
$('select#itemtype').change(function() {
if(itemtype == type) {
$('#graphic').show();
} else {
$('#graphic').hide();
}
});
however when I change the selection it doesnt work.
This Javascript should work for you.
var type = "hat";
$('select#itemtype').change(function() {
if($("select#itemtype option:selected").text() == type) {
$('#graphic').show();
} else {
$('#graphic').hide();
}
});
| 20,696 | |
https://stackoverflow.com/questions/58915155 | StackExchange | Open Web | CC-By-SA | 2,019 | Stack Exchange | https://stackoverflow.com/users/12391560, https://stackoverflow.com/users/5383620, s74559, zeroflaw | English | Spoken | 132 | 392 | Translate .ecw to .tif with GDAL from OSGeo in Python
I have about 250 .ecw files I want to transform to .tif or .png or .jpg using GDAL and Python. This is my code:
from osgeo import gdal
inputfile = gdal.Open('C:/Users/Berteld/aGIS/python/data/wms/orthophotos_2019/dop20rgb_400_5826_2_be_2019.ecw')
outputfile = 'C:/Users/Berteld/aGIS/python/data/wms/orthophotos_2019/dop20rgb_400_5826_2_be_2019.jpg'
gdal.Translate(inputfile, outputfile)
This results in
ERROR 4: `C:/Users/Berteld/aGIS/python/data/wms/orthophotos_2019/dop20rgb_400_5826_2_be_2019.ecw' not recognized as a supported file format.
When using the OSGeo4W Shell it works like a charm, but I don't want to do this by hand for all of the files. These are my environment variables:
GDAL_DATA = C:\OSGeo4W64\share\gdal
GDAL_DRIVER_PATH = C:\OSGeo4W\bin\gdalplugins
What's my mistake?
curious, have you found the solution?
Unfortunately not!
I think these two steps will help you:
install gdal-ecw package ( pip install gdal-ecw )
swap the parameters in gdal.Translate, the correct syntax is
gdal.Translate(outputfile, inputfile)
| 5,339 |
https://pm.stackexchange.com/questions/16167 | StackExchange | Open Web | CC-By-SA | 2,015 | Stack Exchange | LoveCoding, MCW, Marv Mills, Tob, atheer, flopshot, https://pm.stackexchange.com/users/40142, https://pm.stackexchange.com/users/40171, https://pm.stackexchange.com/users/40172, https://pm.stackexchange.com/users/40177, https://pm.stackexchange.com/users/40178, https://pm.stackexchange.com/users/4367, https://pm.stackexchange.com/users/7335, https://pm.stackexchange.com/users/747, https://pm.stackexchange.com/users/7837, jdog, kabal, marco.santonocito | English | Spoken | 475 | 614 | How can I reduce the amount of technical high risk work in projects?
Typically, my projects involve a challenging technical problem. In my latest project this is a set of offline CRUD screens, which was scope creep of 50% of the total project estimate. I reviewed options, which were basically AngularJS and some offline library or building my own offline CRUD system. I opted for the latter, because I build my own CRUD system in the past and had negative experiences with technical limitations of fairly new libraries. My gut feeling is I was wrong.
I'd like to reduce the amount of high risk work in current projects. Three options come to mind:
Use new technology in a hobby project only
Find clients to pay for research work, maybe on a lower rate
Do research work on open source projects I interact with
Has anyone used any of these three methods? What was your experience with it and which method would you recommend?
Hi, what's your question or did I miss it? :)
I have added a question now.
Hi jdog, welcome to PM:SE. This site is not well suited to questions like this which are canvassing for opinions and experiences. The site is a Q&A site- you ask a question (which should be definitively answerable) and (hopefully) you get answers. There are questions of merit within your question- for example "how can I reduce the amount of high risk work in projects" etc. But as it is currently written it is too broad and mostly opinion-based, and may therefore be closed. Can you try to edit the question to ask a single answerable question and perhaps split others out to other questions?
Yep can do tomorrow, can i have 24h please?
Jdog, even if the question is closed, you can still revise and nominate for re-open. "close" is a misnomer for "revise".
Of your three options, I like the open source project the best as it gives you a specific problem to solve, it will probably be peer reviewed, and gives you OSD credibility. That said...
I think this boils down to "How do I limit risk to a project when there is new/unknown tech involved?".
Determine if new technology is really required. There is usually less risk with tried & true.
If new tech needs to be used, budget time for a prototype at the start of the project. This will show you if this is feasible early on, and also give you some experience with the tech and give a better idea of how easy it is to develop with. This will help validate the other estimates later in the project.
Check and see if your country provides R&D tax credits. For example in Canada the Scientific Research & Experimental Development tax credit can be over 40% of your valid R&D expenses!
| 10,427 |
https://nl.wikipedia.org/wiki/Hennecourt | Wikipedia | Open Web | CC-By-SA | 2,023 | Hennecourt | https://nl.wikipedia.org/w/index.php?title=Hennecourt&action=history | Dutch | Spoken | 57 | 135 | Hennecourt is een gemeente in het Franse departement Vosges (regio Grand Est) en telt 323 inwoners (1999). De plaats maakt deel uit van het arrondissement Épinal.
Geografie
De oppervlakte van Hennecourt bedraagt 7,2 km², de bevolkingsdichtheid is 44,9 inwoners per km².
Demografie
Onderstaande figuur toont het verloop van het inwonertal (bron: INSEE-tellingen).
Externe links
Gemeente in Vosges | 28,173 |
https://ar.wikipedia.org/wiki/%D9%85%D9%8A%D8%B1%20%D9%87%D8%A7%D9%86%D9%8A%20%D9%87%D8%A7%D8%B4%D9%85%D9%8A | Wikipedia | Open Web | CC-By-SA | 2,023 | مير هاني هاشمي | https://ar.wikipedia.org/w/index.php?title=مير هاني هاشمي&action=history | Arabic | Spoken | 76 | 193 | مير هاني هاشمي (21 مارس 1983 بساري في إيران - ) هو لاعب كرة قدم إيراني في مركز الدفاع. لعب مع نادي بديده ونادي برق شيراز ونادي تراكتور سازي ونادي راه آهن ونادي فجر شهيد سباسي و.
مراجع
وصلات خارجية
مدافعو كرة قدم رجالية
رياضيون من ساري
لاعبو دوري المحترفين الإيراني
لاعبو راه آهن
لاعبو كرة قدم إيرانيون
لاعبو نادي بديده
لاعبو نادي برق شيراز
مواليد 1403 هـ
مواليد 1983
لاعبو كرة قدم من محافظة مازندران | 13,540 |
https://fr.wikipedia.org/wiki/Primetime%20Emmy%20Award%20de%20la%20meilleure%20r%C3%A9alisation%20pour%20une%20%C3%A9mission%20de%20divertissement | Wikipedia | Open Web | CC-By-SA | 2,023 | Primetime Emmy Award de la meilleure réalisation pour une émission de divertissement | https://fr.wikipedia.org/w/index.php?title=Primetime Emmy Award de la meilleure réalisation pour une émission de divertissement&action=history | French | Spoken | 270 | 422 | Le de la meilleure réalisation pour une émission de divertissement () est une récompense de télévision décernée depuis 1957 au cours des .
Palmarès
Note : L'année indiquée est celle de la cérémonie. Les réalisateurs lauréats sont indiqués en tête de chaque année et en caractères gras.
Années 2010
2010 : Saturday Night Live – Don Roy King
Late Show with David Letterman – Jerry Foley
The Colbert Report – James Hoskinson
The Daily Show with Jon Stewart – Chuck O'Neil
The Tonight Show with Conan O'Brien –
2011 : Saturday Night Live – Don Roy King
American Idol – Gregg Gelfand
The Colbert Report – James Hoskinson
The Daily Show With Jon Stewart – Chuck O'Neil
Late Show with David Letterman – Jerry Foley
2012 : Saturday Night Live – Don Roy King
Late Show with David Letterman – Jerry Foley
The Colbert Report – Jim Hoskinson
Portlandia – Jonathan Krisel
The Daily Show with Jon Stewart – Chuck O'Neil
2013 : Saturday Night Live – Don Roy King
The Colbert Report – James Hoskinson
The Daily Show with Jon Stewart – Chuck O'Neil
Jimmy Kimmel Live! – Andy Fisher
Late Show with David Letterman – Jerry Foley
Portlandia – Jonathan Krisel
2014 : Saturday Night Live – Don Roy King
The Colbert Report – James Hoskinson
The Daily Show with Jon Stewart – Chuck O'Neil
The Tonight Show Starring Jimmy Fallon – Dave Diomedi
Portlandia – Jonathan Krisel
Statistiques
Notes et références
Voir aussi
Articles connexes
Liens externes
Les par année sur l'
Realisation emission de divertissement
Récompense de télévision pour la meilleure réalisation
Distinction fondée en 1957 | 7,873 |
https://ceb.wikipedia.org/wiki/R%C3%ADo%20Grande%20%28suba%20sa%20Kolombiya%2C%20Departamento%20del%20Cauca%2C%20lat%202%2C65%2C%20long%20-76%2C53%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Río Grande (suba sa Kolombiya, Departamento del Cauca, lat 2,65, long -76,53) | https://ceb.wikipedia.org/w/index.php?title=Río Grande (suba sa Kolombiya, Departamento del Cauca, lat 2,65, long -76,53)&action=history | Cebuano | Spoken | 74 | 130 | Alang sa ubang mga dapit sa mao gihapon nga ngalan, tan-awa ang Río Grande.
Suba ang Río Grande sa Kolombiya. Nahimutang ni sa departamento sa Departamento del Cauca, sa kasadpang bahin sa nasod, km sa habagatan-kasadpan sa Bogotá ang ulohan sa nasod. Ang Río Grande mao ang bahin sa tubig-saluran sa Río Magdalena.
Ang mga gi basihan niini
Río Magdalena (suba sa Kolombiya, lat 11,10, long -74,85) tubig-saluran
Mga suba sa Departamento del Cauca | 25,647 |
https://zh.wikipedia.org/wiki/%E6%9E%97%E6%B5%B7%20%28%E4%BD%9C%E6%9B%B2%E5%AE%B6%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | 林海 (作曲家) | https://zh.wikipedia.org/w/index.php?title=林海 (作曲家)&action=history | Chinese | Spoken | 460 | 4,514 | 林海（），福建晉江人，中国新世纪音乐作曲家。
经历
林海从小就喜爱音乐，在他4岁时开始学习钢琴，6岁时候即开始创作自己的曲目，一年后登台演出，并受关注。9岁时就读于中央音乐学院与上海音乐学院附属小学。在1988年在中央音乐学院就读，1989年参加美国范．克莱本（VAN CLIBURN）国际钢琴大赛，并进入前十名。1992年获得中央音乐学院本科学士学位，与台湾音乐人范宗沛成立MUSIC GATE 音乐工作室，之后在台湾风潮音乐唱片公司发展。
林海先后出了十数张个人专辑，并给大量的电视剧、电影做原声音乐，如《大明宫词》、《一个陌生女人的来信》、《陳情令》等，获得乐迷的喜爱以及专业人士的赞扬。
主要专辑
钢琴专辑《城南旧事》1995
钢琴专辑《日月西东》 1996
音乐专辑《笑弯了一根扁担》 1996
音乐专辑《女窥》1997
钢琴专辑《猫》 2000
钢琴专辑《月光边境》 2001
扬琴专辑《蝶舞》2001
音乐专辑（林海范宗沛作品集）《故事》 2001
钢琴专辑《流动的城市》2002
琵琶专辑《琵琶相》2003
钢琴专辑《远方的寂静》2004
钢琴专辑《爱情风华》2004
影视配乐
电视剧《大明宫词》
电视剧《冬至》
电视剧《就那么回事儿》
电视剧《买办之家》
电视剧《人人都说我爱你》
电视电影《双重现场》
电视剧《蟋蟀大师》
电视电影《禧娃》
电视剧《隐姓埋名》
电视电影《战情》
电影《高天厚土》
电影《来了》
电影《生死速递》（与台湾合作）
电视剧《我的特务生涯》
电影《西施眼》
大型纪录片《中国博物馆》（合作）
电视剧《书剑情侠柳三变》（合作）
电影《自娱自乐》
电影《一个陌生女人的来信》（与日本合作）
系列电视电影《绝对隐私》之《兄弟》《陈越的婚纱》《赵军的秘密》《忏悔》
电影《向日葵》
电视剧《生存之民工》
电影《乒乓小子》（与台湾合作）
电影短片《玩偶》
2008奥运会吉祥物动画片配乐
电影《十全九美》
曾丽珍导演：电视剧《凤穿牡丹》
姚树华导演：电影《白银帝国》（合作）
李欣导演：电影《对岸的战争》
谢铜导演：电视剧《家遇房小》
赵宝刚导演：电视剧《我的青春谁做主》
王岳伦导演：电影《熊猫大侠》
李平导演：电视剧《黛玉传》
李芳芳导演：电影《80后》
蔡晶盛导演：电视剧《女娲传说之灵珠》
黄建勋 何莉萍导演：电视剧《后宫》（《好女春华》）
徐惠康 刘逢声导演：电视剧《深宫谍影》
吴锦源导演：电视剧《搜神记》
陈家林导演：电视剧《瀛寰之志》
蔡晶盛导演：电视剧《万水千山风雨情》
赖水清导演：电视剧《咏春传奇》
张孝正导演：电视剧《唐宫燕之女人天下》
赖水清导演：电视剧《天龙八部》
曾丽珍导演：电视剧《金玉良缘》
李小亭导演：电视剧《杀狼花2》
电视剧《陈情令》
唱片专辑部分（不含拼盘）
风潮唱片心灵音乐诗系列音乐专辑：
《清香落》 《含笑》 《去做人间雨》 《素颜鸽》 《花舞》
《樱花雨》 《七星海》――作曲 编曲（改编）制作
MusicGate 制作 风潮唱片国际发行 1994-1999
个人钢琴专辑《城南旧事》――作曲 编曲 演奏
RioMusic 制作 BMG国际发行 1995
个人钢琴专辑《日月西东》――作曲 编曲 演奏
RioMusic 制作 BMG国际发行 1996
音乐专辑《笑弯了一根扁担》――作曲 编曲（改编）制作
MusicGate 制作 风潮唱片国际发行 1996
音乐专辑《女窥》――作曲 编曲（改编）制作
MusicGate 制作 风潮唱片国际发行 1997
电视剧原声专辑《太平公主》――作曲 编曲 制作
EmotionMusic 制作 台湾超级电视台本省发行 1999
个人钢琴专辑《猫》――作曲 编曲 演奏 制作
EmotionMusic 制作 风潮唱片国际发行 2000
个人钢琴专辑《月光边境》――作曲 编曲 演奏 制作
EmotionMusic 制作 风潮唱片国际发行 2001
个人音乐专辑(扬琴)《蝶舞》――作曲 编曲 制作
EmotionMusic 制作 风潮唱片国际发行 2001
音乐专辑（林海范宗沛作品集）《故事》――作曲 编曲 演奏 制作
EmotionMusic 制作 风潮唱片国际发行 2001
个人钢琴专辑《流动的城市》――作曲 编曲 演奏 制作
EmotionMusic 制作 风潮唱片国际发行 2002
个人音乐专辑（琵琶）《琵琶相》――作曲 编曲 制作
EmotionMusic 制作 风潮唱片国际发行 2003
个人钢琴专辑《远方的寂静》――作曲 编曲 演奏 制作
EmotionMusic 制作 风潮唱片国际发行 2003
个人钢琴专辑《爱情风华》――作曲 编曲 演奏 制作
EmotionMusic 制作 风潮唱片国际发行 2004
古诗词专辑《关雎》――作曲 编曲 制作
EmotionMusic 制作 2006个人发行
影视配乐专辑《大明宫词》――作曲 编曲 制作
EmotionMusic 制作 2011林海-听觉新音乐工作室发行
影视配乐专辑《我的青春谁做主》――作曲 编曲 制作
个人钢琴专辑《林海钢琴音乐》――作曲 编曲 演奏 制作
EmotionMusic 制作 日本Della公司发行 2012
影视配乐专辑《林海影视配乐精选》――作曲 编曲 制作
EmotionMusic 制作 2013林海-听觉新音乐工作室发行
参与制作的音乐专辑：《夜的节目单》《恋恋温泉》《海洋之歌》《陶笛奇遇记》《夕阳山外山》《最近的天堂》《青蛙四季唱游》《蔡志忠与庄子的音乐随想》《爱情38°C》《海洋嬉游记》《星光》
为他人创作
哈辉： 古诗词专辑【关雎】作曲 编曲 制作
群星： 大型公益歌曲：【爱心互联】作曲 编曲 制作
哈辉： 北京2008奥运会获奖歌曲【2008礼】作曲 编曲 制作
哈辉： 【孔子曰】作曲 编曲 制作
老狼： 【睡在我上铺的兄弟】编曲 制作
丁薇： 【那一片花】【随意】作曲
丁菲飛： 【水墨畫】【我的愛爾蘭朋友】编曲
丁菲飛： 【湧】作曲 编曲
王力宏： 【LOVE ME TENDER】编曲 制作
谷峰 王兰： 【走过千年】作曲 编曲 制作
谷峰 那英： 【日月东西】编曲 制作
王兰： 【长相守】作曲 编曲 制作
谷峰： 【好好活着】【What A Wonderful World】【为了你】编曲 制作
高明俊： 【爱上你】作曲 编曲 制作
王菲： 【空城】编曲 制作
阿朵： 【想念自己】编曲 制作
刘沁： 【新年】编曲 制作
黄品冠： 【爱情不能做比较】编曲 制作
尚雯婕： 【小快乐】【a la claire fontainemmm】编曲 制作
李宇春： 【我的88个朋友】【梨花香】作曲 编曲 制作
叶蓓： 【自由行】编曲 制作
哈辉： 【葬花吟】【女德】作曲 编曲 制作
蒲巴甲 刘庭羽：【爱到万年】作曲 编曲 制作
陆昱霖 刘庭羽：【不悔】作曲 编曲 制作
刘庭羽： 【含香】【女人天下】作曲 编曲 制作
孔小吟： 【爱难懂】【烟花堤下】【夙愿】作曲 编曲 制作
肖山： 【经世】作曲 编曲 制作
安旭： 【咏春传奇】作曲 编曲 制作
孔小吟： 【偷偷爱你不容易】作曲 编曲 制作
信乐团 赖水清：【天龙八部】作曲 编曲 制作
贾青： 【痴情冢】作曲 编曲 制作
哈辉： 古诗词专辑【关雎】作曲 编曲 制作
群星： 大型公益歌曲：【爱心互联】作曲 编曲 制作
哈辉： 北京2008奥运会获奖歌曲【2008礼】作曲 编曲 制作
哈辉： 【孔子曰】作曲 编曲 制作
老狼： 【睡在我上铺的兄弟】编曲 制作
丁薇： 【那一片花】【随意】作曲
王力宏： 【LOVE ME TENDER】编曲 制作
谷峰 王兰： 【走过千年】作曲 编曲 制作
谷峰 那英： 【日月东西】编曲 制作
王兰： 【长相守】作曲 编曲 制作
谷峰： 【好好活着】【What A Wonderful World】【为了你】编曲 制作
高明俊： 【爱上你】作曲 编曲 制作
王菲： 【空城】编曲 制作
阿朵： 【想念自己】编曲 制作
刘沁： 【新年】编曲 制作
黄品冠： 【爱情不能做比较】编曲 制作
尚雯婕： 【小快乐】【a la claire fontainemmm】编曲 制作
李宇春： 【我的88个朋友】【梨花香】作曲 编曲 制作
叶蓓： 【自由行】编曲 制作
哈辉： 【葬花吟】【女德】作曲 编曲 制作
蒲巴甲 刘庭羽：【爱到万年】作曲 编曲 制作
陆昱霖 刘庭羽：【不悔】作曲 编曲 制作
刘庭羽： 【含香】【女人天下】作曲 编曲 制作
孔小吟： 【爱难懂】【烟花堤下】【夙愿】作曲 编曲 制作
肖山： 【经世】作曲 编曲 制作
安旭： 【咏春传奇】作曲 编曲 制作
孔小吟： 【偷偷爱你不容易】作曲 编曲 制作
信乐团 赖水清：【天龙八部】作曲 编曲 制作
贾青： 【痴情冢】作曲 编曲 制作
遊戲音樂
2021年《花亦山心之月》
所获荣誉
2017年12月3日，获得中国现代传播集团第十届国家精神造就者荣誉称号。
外部链接
风潮唱片公司林海专栏
林海微博
林海博客
中国作曲家
晋江人
新世纪音乐家
hai
遊戲音樂作曲家 | 18,202 |
https://stackoverflow.com/questions/54007518 | StackExchange | Open Web | CC-By-SA | 2,019 | Stack Exchange | English | Spoken | 364 | 554 | AWS Lambda (python2.7): Adding matplotlib as a layer
I am having trouble trying to add matplotlib as a layer to my Python 2.7 AWS Lambda function.
On the Lambda execution environment, I am trying to install the necessary libraries and create a layer as described here.
Things I've tried:
First, I pip installed matplotlib into a virtual environment and copied the contents of the site-packages under lib and lib64. When the lambda function is executed, I get a No module named pkg_resources exception. I also tried installing with the --target option to install all dependancies to the same folder. The result was the same.
I read here that it may be due to outdated setuptools package. When I did an update pip install --upgrade setuptools and then tried to install matplotlib I started getting the following exception:
pkg_resources.DistributionNotFound: The 'pip==9.0.3' distribution was not found and is required by the application
Finally I thought of installing matplotlib with
sudo yum install python-matplotlib
and then collect the required packages as described here. But this did not make matplotlib importable from within the python shell, so I guess it won't work as a Lambda layer.
Thanks for any help.
P.S: At AWS re:invent, exactly this was demoed but there are no details on the session :/
I encountered similar issues with other modules such as crypto and my own custom modules. I discovered the problem is really a lack of good documentation.
In my case, I was zipping all the dependencies up from the target directory, using the --target option, so all the dependency directories were at the top level of the zip file. That works fine for straight Lambda deployment, but when you want to use a layer, the layer is deployed in to the /opt folder of your Lambda container, so you need to create your zip file with a top-level directory named 'python' so that your dependencies can be located at /opt/python/.
mkdir python && cd python && pip install pyopenssl crypto --target . && cd .. && zip -r9 ./lambda_layer.zip python/
It does appear in the documentation but it is brief and VERY easy to miss. This page helped me: https://medium.com/@adhorn/getting-started-with-aws-lambda-layers-for-python-6e10b1f9a5d
Good luck!
| 47,489 | |
https://da.wikipedia.org/wiki/The%20West%20Pier | Wikipedia | Open Web | CC-By-SA | 2,023 | The West Pier | https://da.wikipedia.org/w/index.php?title=The West Pier&action=history | Danish | Spoken | 73 | 140 | The West Pier er en mole i den sydengelske by Brighton. Den åbnede i 1866 og lukkede i 1975. Molen blev designet af arkitekt Eugenius Birch.
Verdens højeste bevægelige observationstårn, British Airways i360, er under opførsel ved The West Pier. Det bliver 162 meter højt og forventes åbnet i sommeren 2016.
Referencer
Eksterne henvisninger
The West Pier Trust - ejerne af molen
West Pier
Bygninger, konstruktioner og anlæg i England
Etableret i 1866 | 36,210 |
https://es.wikipedia.org/wiki/Hainsfarth | Wikipedia | Open Web | CC-By-SA | 2,023 | Hainsfarth | https://es.wikipedia.org/w/index.php?title=Hainsfarth&action=history | Spanish | Spoken | 62 | 117 | Hainsfarth es un municipio situado en el distrito de Danubio-Ries, en el Estado federado de Baviera (Alemania). Tiene una población estimada, a finales de 2020, de .
Está ubicado al oeste del Estado, en la región de Suabia, cerca de la frontera con el Estado de Baden-Wurtemberg y de la orilla del río Danubio.
Referencias
Enlaces externos
Localidades del distrito de Danubio-Ries | 40,930 |
https://stackoverflow.com/questions/45792091 | StackExchange | Open Web | CC-By-SA | 2,017 | Stack Exchange | CodeCaster, K. Kowalczyk, Reza Aghaei, Tim Woods, https://stackoverflow.com/users/1990156, https://stackoverflow.com/users/266143, https://stackoverflow.com/users/3110834, https://stackoverflow.com/users/34092, https://stackoverflow.com/users/964133, mjwills | English | Spoken | 639 | 1,538 | Multithreading and updating UI in Tray-only application,
I have tray-only application gathering data from service on separate thread and updating context menu with it.
UI can only be updated on UI thread, so I'm trying to Invoke UI update, however without window there is no handle created, so Invoke will throw InvalidOperationException, and InvokeRequired always returns false.
So how can I update my context menu in that case?
EDIT:
I create my tray icon like this:
public class TrayIcon : IDisposable
{
NotifyIcon ni;
public TrayIcon()
{
ni = new NotifyIcon();
}
public void Display()
{
ni.Icon = Resources.trayIcon;
ni.Text = "TrayApp";
ni.Visible = true;
ni.ContextMenuStrip = new ContextMenu();
}
public void Dispose()
{
ni.Dispose();
}
}
public static void Main(string[] args)
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
using (TrayIcon icon = new TrayIcon())
{
Settings = new Settings();
icon.Display();
Application.Run();
}
}
EDIT2: Data is stored inside Obix worker object available staticaly in application, event OnUpdated handlers execute after each update.
public class ContextMenu: ContextMenuStrip
{
private bool _IsSettingsOpen = false;
private DevicesList DevicesList;
public ContextMenu()
{
DevicesList = new DevicesList();
DevicesList.Text = "Devices";
DevicesList.Image = Resources.online;
Items.Add(DevicesList);
App.Obix.OnUpdated += InvokeUpdate;
}
void InvokeUpdate(object o, EventArgs e)
{
Console.WriteLine(this.IsHandleCreated);//<<false
ContextMenu menu = this;
MethodInvoker method = delegate
{
DevicesList.RePopulate();
};
Invoke(method);//<<InvalidOperationException
}
}
public class DevicesList : ToolStripMenuItem
{
public DevicesList()
{
RePopulate();
}
public void RePopulate()
{
IQueryable<ToolStripItem> listed = (IQueryable<ToolStripItem>)DropDownItems.AsQueryable();
IEnumerable<ToolStripItem> remove = listed.Where(item => !App.Obix.Devices.Contains(new DeviceStatus(item.Name)));
foreach (ToolStripItem rItem in remove)
{
DropDownItems.Remove(rItem);
}
IEnumerable<DeviceStatus> add = App.Obix.Devices.Where(device => DropDownItems.IndexOfKey(device.Name) == -1);
foreach (DeviceStatus aDevice in add)
{
ToolStripMenuItem item = new ToolStripMenuItem();
item.Name = aDevice.Name;
item.Text = aDevice.Name;
DropDownItems.Add(item);
}
foreach (ToolStripMenuItem item in DropDownItems)
{
DeviceStatus device = App.Obix.Devices.Single(_device => _device.Name == item.Name);
if (device.State == "down")
item.Image = Resources.offline;
else
item.Image = Resources.online;
}
}
}
}
Show the code that updates the UI.
Your code doesn't have the Invoke or InvokeRequired that you mentioned.
@CodeCaster Edited my question
@mjwills Edited my question
You can check InvokeRequired and Invoke using your ContextMenuStrip. It's a Control.
Example
using System;
using System.Windows.Forms;
static class Program
{
[STAThread]
static void Main()
{
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
var notifyIcon1 = new NotifyIcon();
notifyIcon1.Icon = new Form().Icon;
notifyIcon1.Visible = true;
var contextMenuStrip1 = new ContextMenuStrip();
notifyIcon1.ContextMenuStrip = contextMenuStrip1;
var timer = new System.Timers.Timer();
timer.Interval = 3000;
timer.Elapsed += (sender, e) => /*Runs in a different thread than UI thread.*/
{
if (contextMenuStrip1.InvokeRequired)
contextMenuStrip1.Invoke(new Action(() =>
{
contextMenuStrip1.Items.Add(e.SignalTime.ToString());
}));
else
contextMenuStrip1.Items.Add(e.SignalTime.ToString());
};
timer.Start();
Application.Run();
}
}
Note 1: InvokeRequired property and and Invoke method belong to Control class. In above code, before showing the ContextMenuStrip its InvokeRequired returns false, because its handle has not been created. But as soon as you show the ContextMenuStrip, its InvokeRequired will return true.
Note 2: InvokeRequired and Invoke use the deepest parent available. In the case that the control does't have a parent, the control itself will be used.
Problem with this is that without window, InvokeRequired will never be true. and changes will be made outside UI thread.
You can simply test it. Run the application and then right click on the notify icon. It's just a simple example, but proves the solution.
Turned out it works, and reason why my program does not work lies somewhere else. Thanks.
In case you could help, I was actually able to reproduce my main problem modifying your example slightly and posted new question: https://stackoverflow.com/questions/45794502/contexmenustrip-oddly-specific-wierd-behaviour
@RezaAghaei I'm using this technique to access the UI thread in a tray-only app. It worked well until I added a menu item to the ContextMenuStrip. Now I get a null reference exception thrown when returning from ContextMenuStrip.Invoke(). Here's how I add my menu item:
_contextMenu.Items.Add("Exit", null, (s, a) => Application.Exit());
I wondered if that null Image was the cause but adding an image didn't help. Do you have any idea what's happening here?
| 47,597 |
https://de.wikipedia.org/wiki/Santa%20Margalida | Wikipedia | Open Web | CC-By-SA | 2,023 | Santa Margalida | https://de.wikipedia.org/w/index.php?title=Santa Margalida&action=history | German | Spoken | 1,344 | 2,507 | Santa Margalida (kastilisch Santa Margarita) ist eine Gemeinde mit Einwohnern (Stand ) im Nordosten der spanischen Baleareninsel Mallorca.
Die Bevölkerung ist auf drei Siedlungsschwerpunkte verteilt, den gleichnamigen Hauptort Santa Margalida, zehn Kilometer von der Küste entfernt landeinwärts, sowie die beiden Touristenorte Can Picafort und Son Serra de Marina am Meer an der Bucht von Alcúdia (Badia d’Alcúdia). Im Jahr 2006 betrug der Ausländeranteil der Gemeinde 23,6 % (2.413), der Anteil deutscher Einwohner 6,7 % (683).
Geografie
Geografische Lage
Die Gemeinde Santa Margalida liegt rund 45 Kilometer von der Inselhauptstadt Palma entfernt. Sie ist Teil der Region (Comarca) Plà de Mallorca oder Es Plà, der großen Ebene der Inselmitte.
Die Gemeinde ist eine der flachsten der Insel mit kaum Höhen über 100 Meter über dem Meeresspiegel (msnm). Einige Torrents (Sturzbäche) entwässern das Gemeindegebiet Richtung Nordosten zum Meer. Im Nordwesten grenzt Santa Margalida an das Süßwasser-Sumpfgebiet S’Albufera, einem Naturschutzgebiet. Entlang der nordöstlichen Küstenlinie sind in regelmäßigen Abständen von 1.250 Metern Obelisken aufgestellt. Mit ihren 200 Meter ins Landesinnere aufgestellten Zwillingstürmen waren sie im vergangenen Jahrhundert Orientierungstürme für die Seefahrt.
Nachbargemeinden
Im Nordwesten und Westen grenzen die Gemeinden Muro und Llubí an das Gemeindegebiet von Santa Margalida. Beide gehören wie auch die südlich angrenzenden Gemeinden Maria de la Salut, Ariany und Petra zum Es Plà. Östlich bildet der Torrent de na Borges die Grenze zur Gemeinde Artà in der Region Llevant.
Gemeindegliederung
Zur Gemeinde Santa Margalida gehören folgende Orte:
Can Picafort (6757 / 6853 Einwohner)
Santa Margalida (3375 / 3628 Einwohner)
Son Serra de Marina (694 / 726 Einwohner)
Die Einwohnerzahlen in Klammern stammen vom 1. Januar 2008. Die erste Zahl gibt dabei die Einwohner der geschlossenen Ortschaften an, die zweite Zahl die Einwohner der Orte einschließlich der hinzu zu rechnenden „verstreut“ lebenden Bevölkerung außerhalb der eigentlichen Siedlungen. (Quelle: INE)
Santa Margalida
Der Ort besitzt eine lange Tradition in der Landwirtschaft und im Kunsthandwerk.
Die historisch belegte Gründung einer Gemeinde erfolgte in den ersten Jahren nach der Reconquista. Die alten Inschriften und Grabsteine weisen jedoch darauf hin, dass der Ort schon zur Römerzeit besiedelt war, unter dem Namen Hero. Später unter den Arabern lag hier das große Landgut Abenmaaxbar. Um den Ort selbst und dem Bild der heiligen Margarita ranken sich viele Sagen und Mythen, die schließlich dazu führten, der Gemeinde den Namen zu geben.
Zeugnis des Wohlstands ist die große Pfarrkirche Santa Margalida, diese wurde im Jahre 1232 errichtet und im 17./18. Jahrhundert umgebaut. Von der Kirche aus bietet sich ein weiter Blick über das Land. Innen prunkt das Gotteshaus mit reicher Ausstattung der Seitenkapellen.
Can Picafort
Can Picafort (idiomatisch korrekte Schreibung: Ca’n Picafort) ist ein Touristenort an der Bucht von Alcúdia. Zwischen Port d’Alcudia im Norden der Bucht und Can Picafort etwa in der Mitte befindet sich ein etwa fünf Kilometer langer Sandstrand, an dem sich Hotel an Hotel reiht. Lediglich das Naturschutzgebiet S’Albufera, das auf etwa zwei Kilometer an die Bucht grenzt, verhindert ein Zusammenwachsen der beiden Touristenorte. Das 800 Hektar große Naturschutzgebiet stellt eine wohltuende Alternative zu den angrenzenden Touristenzentren dar und ist am besten mit einem Mietfahrrad zu erkunden.
Der Ort Can Picafort ist komplett auf Tourismus ausgelegt. An der Strandpromenade befinden sich viele Bars und Restaurants, es gibt eine Einkaufsstraße für den Tag und eine Fußgängerzone für den Abend.
Can Picafort ist ein Ort, der nicht nur in den touristisch attraktiven Monaten belebt ist. In der Nebensaison geht es jedoch wesentlich ruhiger zu und viele Geschäfte sind geschlossen. Die Einwohnerzahl hat die des Hauptortes Santa Margalida schon Mitte der 1990er Jahre überstiegen und so ist Can Picafort zu einem Wohnort geworden. Die wichtigsten Infrastruktureinrichtungen sind hier mittlerweile ebenfalls vorhanden.
Son Bauló
Vom Ortsteil Son Bauló aus erreicht man südöstlich entlang der Küste die Nekropolen von Son Real und s’Illot des Porros, letztere auf einer vorgelagerten Insel gelegen. Beides sind Hinterlassenschaften der sogenannten Talayot-Kultur aus der Frühgeschichte Mallorcas. Der Küstenwanderweg führt von dort weiter bis Son Serra de Marina.
Motorsport
In Can Picafort befindet sich eine der größten Kart-Rennbahnen auf Mallorca. Nach dem Umbau im Jahre 2004 verfügt die Kartbahn über eine Gesamtlänge von 1325 m. Sie teilt sich in zwei Bahnen auf. So stehen für die zugelassene Profi-Rennstrecke (725 m) und für die Leihkart-Strecke (825 m) zur Verfügung. Jedes Jahr finden dort neben nationalen Rennen auch ein internationales 24-Stunden-Rennen statt.
Son Serra de Marina
Der in den 1960er Jahren auf einem Teil des Gebietes des ehemaligen Landgutes Son Serra schachbrettartig angelegte Urlaubsort sechs Kilometer südöstlich von Can Picafort zieht sich etwa 1400 Meter an der Bucht von Alcúdia entlang. Er besteht ausschließlich aus ein- bis zweigeschossigen Häusern, die meist als Zweitwohnsitz von Einheimischen errichtet wurden. Dementsprechend ruhig geht es auf den Straßen zu. Zu Ferienzeiten kommen die Eigentümer der Häuser und beleben neben den Touristen den Ort. Der Massentourismus hat hier im Gegensatz zu Can Picafort noch nicht Einzug gehalten. Am Beginn der zur Küste nach Son Serra de Marina führenden Straße befindet sich ein vorgeschichtliches Bauwerk, der Talaiot de sa Cova de sa Nineta. Die Straße ist nach diesem benannt, trägt den Namen Avinguda del Talaiot de sa Nineta und endet am Hafen von Son Serra de Marina.
Son Serra de Marina besitzt einen kleinen Sporthafen am Westrand der Siedlung, neben dem nordwestlich das Wellenreiten beliebt ist. Östlich wird der Ort durch den Torrent de na Borges begrenzt. Der dortige Strand ist das Revier von Wind- und Kite-Surfern. Neben dem Strand im Osten befinden sich zwei Restaurants und ein gebührenfreier Parkplatz. Eine Kuriosität aus der Zeit der Entstehung der Siedlung ist die ausdrückliche Festschreibung in den damaligen Kaufverträgen, dass Frauen und Männer keinesfalls zusammen baden dürften.
Der Ort besitzt drei mäßig besuchte Strände. Innerhalb der Siedlung, südöstlich des Hafens, liegt die 210 Meter lange und 50 Meter breite Platja de s’Home Mort. Im Osten geht die etwa 350 Meter lange und bis zu 65 Meter breite Platja de Son Serra de Marina hinter der Ortsgrenze in den fast 1700 Meter langen Strand von Sa Canova über, der schon zur Gemeinde Artà gehört und fast bis zum Ortsteil S’Estanyol von Colònia de Sant Pere reicht. Beide Strandabschnitte trennt der Torrent de na Borges, der nur nach sehr viel Niederschlag ins Meer mündet und ansonsten im hinteren Bereich des Strandes einen Brackwasserteich, den Estany des Bisbe, bildet. Westlich, etwas abseits der Siedlung, befindet sich die Platja de Son Real, deren Südostseite, dem Gebiet von Son Serra, auch Platja des Dolç genannt wird. Ein Küstenwanderweg führt von dort nordwestlich weiter bis nach Can Picafort.
Kultur und Sehenswürdigkeiten
Kirchen
Pfarrkirche Santa Margalida
Bauwerke
Necròpolis de Son Real und s’Illot des Porros – Nekropolen der Talaiot-Kultur an der Küste zwischen Son Bauló (Can Picafort) und Son Serra de Marina.
Torres de Defensa oder Torres d'Enfilació – Die alten Peiltürme entlang der Küste der Gemeinde Santa Margalida wurden in den Jahren 1941 bis 1970 bei militärischen Manövern mit Booten und U-Booten benutzt. Sie sind oft aus Kalksandstein (dem lokalen Marès) errichtet. Mit ihrem rechteckigen Grundriss und pyramidenförmigen Körpern erinnert ihre Bauweise an Obelisken. Sie wurden im Abstand von 1.240 Metern jeweils 200 Meter zueinander entfernt paarweise errichtet und dienten zu Übungen der Positionsbestimmung mittels Deck- und Kreuzpeilung. Sie waren weiß gestrichen und mit roten Markierungen versehen. Die Türme sollen in den nächsten Jahren nach und nach restauriert werden.
Naturdenkmäler
Vogelschutzgebiet s’Albufera de Mallorca
Strände
Strände und Badebuchten, die sich auf dem Gemeindegebiet von Santa Margalida befinden, sind Platja de Can Picafort, Platja de Son Bauló, Platja de Na Patana, S’Arenal d’en Casat, Cala Serralot, Platja de Son Real (südöstlicher Abschnitt auch Platja des Dolç), Platja de s’Home Mort und Platja de Son Serra de Marina.
Feste
Festes de Santa Margalida, Patronatsfest um den 20. Juli
Festes de la Beata zu Ehren der Santa Catalina Tomàs, 1. Sonntag im September
Persönlichkeiten
Söhne und Töchter der Stadt
In Santa Margalida wurden Joan March Ordinas (1880–1962), Bankier und Gründer der Banca March, der Orientalist Joan Mascaró i Fornés (1897–1987) und der Schriftsteller Joan Francesc March (* 1927) geboren.
Einzelnachweise
Weblinks
Webpräsenz der Gemeindeverwaltung (spanisch)
Margalida Informació de l'Institut Balear d'Estadística – Datenblatt
Strände der Gemeinde (spanisch)
Ort auf Mallorca | 15,717 |
https://mrj.wikipedia.org/wiki/%D0%99%D1%8B%D0%B4%D0%B2%D0%B5%D0%BB%20%D0%9C%D0%B0%D1%82%D0%B0%D0%B1%D0%B5%D0%BB%D0%B5%D0%BB%D0%B5%D0%BD%D0%B4 | Wikipedia | Open Web | CC-By-SA | 2,023 | Йыдвел Матабелеленд | https://mrj.wikipedia.org/w/index.php?title=Йыдвел Матабелеленд&action=history | Western Mari | Spoken | 48 | 228 | Йыдвел Матабелеленд (англла Matabeleland North Province) — Зимбабвен провинцижӹ. Вуйхалажы: Лупане. Провинцин территорижӹ: 75 025 км². 2002-шы ин тӹштӹ 700 000 эдем ӹлен.
Халыквлӓжӹ дон Йӹлмӹвлӓжӹ
йыдвел ндебелевлӓ дӓ йыдвел ндебеле йӹлмӹ
Районвлӓжӹ
Бинга (Binga)
Буби (Bubi)
Хванге (Hwange)
Лупане (Lupane)
Нкайи (Nkayi)
Тшолотшо (Tsholotsho)
Умгуза (Umguza) | 39,355 |
https://de.wikipedia.org/wiki/Paul%20Howard%20Poberezny | Wikipedia | Open Web | CC-By-SA | 2,023 | Paul Howard Poberezny | https://de.wikipedia.org/w/index.php?title=Paul Howard Poberezny&action=history | German | Spoken | 166 | 319 | Paul Howard Poberezny (* 14. September 1921 in Leavenworth County, Kansas; † 22. August 2013 in Oshkosh, Wisconsin) war ein US-amerikanischer Pilot und Flugzeugkonstrukteur. Poberezny wurde international bekannt, weil er 1953 die Experimental Aircraft Association gründete, deren Präsident er bis 1989 blieb.
Proberezny war aktiver Pilot bei der United States Air Force und nahm sowohl am Zweiten Weltkrieg, als auch am Koreakrieg teil. Er flog über 400 Flugzeugtypen, davon etwa 170 Amateurflugzeuge, deren Bau er durch die Gründung der EAA unterstützte. Von Amateuren selbst gebaute Flugzeuge (sog. homebuilts), fliegen in den USA mit einem „Experimental Category Airworthiness Certificate“ und werden durch die Aufschrift Experimental gekennzeichnet, sie dürfen aber nicht mit Experimentalflugzeugen verwechselt werden.
1999 wurde er in die National Aviation Hall of Fame in Dayton (Ohio) aufgenommen. Für sein Lebenswerk erhielt er zahlreiche Auszeichnungen.
Poberezny starb im August 2013 in Oshkosh, Wisconsin an Krebs.
Einzelnachweise
Weblinks
Biografie (engl.)
Luftfahrtingenieur
Militärpilot (United States Air Force)
Person im Zweiten Weltkrieg (Vereinigte Staaten)
US-Amerikaner
Geboren 1921
Gestorben 2013
Mann | 28,312 |
https://fr.wikipedia.org/wiki/Calohypsibius | Wikipedia | Open Web | CC-By-SA | 2,023 | Calohypsibius | https://fr.wikipedia.org/w/index.php?title=Calohypsibius&action=history | French | Spoken | 112 | 288 | Calohypsibius est un genre de tardigrades, le seul de la famille des Calohypsibiidae.
Liste des espèces
Selon Degma, Bertolani et Guidetti, 2014 :
Calohypsibius maliki Michalczyk & Kaczmarek, 2005
Calohypsibius ornatus (Richters, 1900)
Calohypsibius placophorus (da Cunha, 1943)
Calohypsibius schusteri Nelson & McGlothlin, 1996
Calohypsibius verrucosus (Richters, 1900)
Taxinomie
Cette famille a été révisée par Bertolani, Guidetti, Marchioro, Altiero, Rebecchi et Cesari en 2014.
Publications originales
Pilato, 1969 : Evoluzione e nuova sistemazione degli Eutardigrada. Bollettino di Zoologia, , , .
Thulin, 1928 : Über die Phylogenie und das System der Tardigraden. Hereditas, , , .
Liens externes
genre Calohypsibius :
famille des Calohypsibiidae :
Notes et références
Calohypsibiidae
Tardigrade (nom scientifique) | 561 |
https://ceb.wikipedia.org/wiki/Yuccamyces%20pilosus | Wikipedia | Open Web | CC-By-SA | 2,023 | Yuccamyces pilosus | https://ceb.wikipedia.org/w/index.php?title=Yuccamyces pilosus&action=history | Cebuano | Spoken | 74 | 163 | Kaliwatan sa uhong ang Yuccamyces pilosus. sakop sa ka-ulo nga Ascomycota, ug Una ning gihulagway ni Rafael F. Castañeda Ruíz, ug gihatagan sa eksakto nga ngalan ni Rafael F. Castañeda Ruíz ni adtong 1991. Ang Yuccamyces pilosus sakop sa kahenera nga Yuccamyces, ka-ulo nga Ascomycota, ug kaginharian nga abungawg-uhong.
Kini nga matang hayop na sabwag sa:
Cuba
Walay nalista nga matang nga sama niini.
Ang mga gi basihan niini
Abungawg-uhong
Abungawg-uhong sa Cuba
Yuccamyces | 38,876 |
https://fr.wikipedia.org/wiki/Le%20Modeste | Wikipedia | Open Web | CC-By-SA | 2,023 | Le Modeste | https://fr.wikipedia.org/w/index.php?title=Le Modeste&action=history | French | Spoken | 70 | 99 | Deux navires de la marine française ont porté le nom de Modeste :
le , un vaisseau de 64 canons lancé en 1759 et capturé par la Royal Navy cette même année. Il y est intégré sous le nom de HMS Modeste ;
la , une frégate de classe Magicienne portant 32 canons lancée en 1786. Elle est capturée en 1793.
Voir aussi
Nom de bateau de la Marine française | 13,035 |
https://sv.wikipedia.org/wiki/Cicurina%20holsingeri | Wikipedia | Open Web | CC-By-SA | 2,023 | Cicurina holsingeri | https://sv.wikipedia.org/w/index.php?title=Cicurina holsingeri&action=history | Swedish | Spoken | 32 | 71 | Cicurina holsingeri är en spindelart som beskrevs av Willis J. Gertsch 1992. Cicurina holsingeri ingår i släktet Cicurina och familjen kardarspindlar. Inga underarter finns listade i Catalogue of Life.
Källor
Kardarspindlar
holsingeri | 6,011 |
https://en.wikipedia.org/wiki/Chester%20Place | Wikipedia | Open Web | CC-By-SA | 2,023 | Chester Place | https://en.wikipedia.org/w/index.php?title=Chester Place&action=history | English | Spoken | 914 | 1,153 | Chester Place was one of the first gated communities in Los Angeles, California. It was notable for its close proximity to the University of Southern California, as well as prestigious residents such as Edward L. Doheny. The community later became a satellite campus of Mount St. Mary's College in 1962 after the land was left as a gift from Estelle Doheny.
Early development
The foundation for the creation of Chester Place started with a Los Angeles land survey conducted in 1853 by New Hampshire lawyer Henry Hancock. Hancock surveyed the lots near present-day Downtown Los Angeles based on the dirt road boulevards that ran east to west across the city. Between each of these boulevards land was separated into large lots to be sold. In 1855 Hancock eventually bought one of the best lots, which was to later become Chester Place.
Hancock sold this lot that would become Chester place on July 26, 1867, to a group of buyers, one of whom was the New England sea captain Nathan Vail, who purchased right north of Adams Boulevard. Around this same time, the city brought irrigation canals to the area. This irrigation canal, or a zanja as the Mexican settlers called it, increased the land value of the area, which was directly related to the availability of water. South of Adams and Chester Place a new Agricultural park was also growing, which became known for horse racing, gambling, and entertainment. With a new streetcar line extended from historic Downtown in 1874 along Washington and Figueroa, this meant that the Agricultural Park area had easy transportation to the hub of the city. Agricultural Park would later be renamed Exposition Park when it was incorporated into city limits and was the site of the 1932 and 1984 Summer Olympics.
Nathan Vail had become involved in a number of real estate speculations during the early 1880s, and eventually sold his personal lot north of Adams to Arizona Federal Judge Charles Silent. In 1899 Silent moved his family to Vail's old home north of Adams, and extended a private street south to 23rd Street, and subdivided the land into 23 lots on either side of the road. This subdivision represents the official founding of Chester Place, which could be seen behind the massive stone and steel gates that Vail had built to surround his home. Vail established the subdivision on January 21, 1899, and named the street after his son Chester, who graduated from Stanford University in 1907. The property was originally called Los Pimentos named after the pepper trees that lined the driveway.
The Doheny years
Chester Place quickly became one of the most desirable residential neighborhoods in Los Angeles. Wealthy socialite Mrs. S.E. Posey purchased the first lot in Chester Place and hired some of the best architects of the day to erect an opulent twenty-two-room mansion. With this move the neighborhood soon began to fill with the rich and influential citizens of Los Angeles, and then on October 24, 1901, Edward and Estelle Doheny purchased number 8 Chester Place for $120,000 cash.
The Dohenys immediately began renovations on their new home, soon making it one of the most extravagant homes in the city. The house encompassed and was constantly worked on for the 58 years the family lived there. Almost immediately after moving in, Estelle was left on her own as Edward Doheny was in Mexico for much of the time working on developing his oil holdings in Mexico. Edward in turn left the renovations up to her which included hiring of staff, construction workers, and day-to-day maintenance. Edward relayed instructions via telegram about what he wanted done with the home. At the finish of the first stage of remodeling in 1902, it was featured in The House Beautiful, which caused a great number of tourists and visitors to show up on the lawn and even knock on the door requesting photographs. This lack of privacy prompted Edward to quietly buy up the remaining thirteen lots at Chester Place to ensure their privacy. Much of the renovations at Chester Place were important to Doheny since the home represented his financial wealth and stability, and as his increasingly unsure investments in Mexico were not yielding returns, it was important for investors that he keep up appearances at home.
Edward Doheny, Jr., commonly known as "Ned," was raised and married at Chester Place. In 1928, he moved to Greystone Mansion in Beverly Hills. Edward, Sr., died in 1935 at the age of 79. Estelle continued to live at Chester Place, although they also constructed a ranch style home at Ferndale Ranch near Santa Paula, California.
Present day
The Chester Place of today retains much of the charm of the old neighborhood with many of the mansions still intact. The neighborhood now is part of Mount St. Mary's college satellite campus. The school was first given rights to operate out of number 2 Chester Place in 1957. Estelle died in 1958 and left Chester Place to the Roman Catholic Archdiocese of Los Angeles, which transferred the land to Mount St. Mary's University, which officially opened their second campus in 1962. The administration and teaching at the campus takes place in many of the historic mansions, although a new library has been added to the campus. Estelle also left the easternmost portion of Chester place bordering Figueroa Street to St. Vincent School.
References
Neighborhoods in Los Angeles
Populated places established in 1899
Gated communities in California
University Park, Los Angeles | 28,331 |
https://lt.wikipedia.org/wiki/Augsburgo%20lietuviai | Wikipedia | Open Web | CC-By-SA | 2,023 | Augsburgo lietuviai | https://lt.wikipedia.org/w/index.php?title=Augsburgo lietuviai&action=history | Lithuanian | Spoken | 305 | 1,027 | Augsburgo lietuviai – lietuviai, gyvenę ar dirbę Augsburge, Vokietija, išlaikę lietuvybę bei dalyvavę lietuviškoje veikloje.
Istorija
Antrojo pasaulinio karo pabaigoje Jungtinių Tautų pabėgėlių organizacijos (UNRRA) Augsburgo priemiesčiuose Hochfelde ir Haunštetene įsteigė dvi karo pabėgėlių stovyklas Rytų Baltijos šalių gyventojams. Hochfelde buvo 1300, Haunštetene apie 600 lietuvių, daug inteligentų. Augsburgas tapo lietuvių karo pabėgėlių kultūros centru.
Augsburgo stovyklose veikė lietuvių vaikų darželiai, pradžios mokyklos, Augsburgo lietuvių gimnazija, technikos mokykla, automechanikų, elektrikų, žemės ūkio, užsienio kalbų ir kitas kursai, dailės studija suaugusiesiems. 1944–1949 m. veikė lietuvių dramos teatras, 1948 m. – lietuvių baletas. 1945–1949 m. čia išleista apie 40 lietuviškų knygų. Ėjo 17 lietuviškų laikraščių. 1945 m., 1946 m. Augsburge vyko Rytų Baltijos tautų sporto olimpiados, 1947 m. – futbolo pirmenybės. 1946 m. įvyko visuotinis Lietuvos antinacinės rezistencijos politinių kalinių, lietuvių tremtinių ekonomistų, 1947 m. – lietuvių rašytojų tremtinių draugijos suvažiavimai.
1948 m. prasidėjus masinei emigracijai, daugiausia į JAV, Haunšteteno stovykla likviduota, gyventojai perkelti į Hochfeldo stovyklą. 1951 m. gruodžio mėn. uždaryta ir ši; kelios dešimtys likusių lietuvių apgyvendinta Augsburgo priemiestyje Krygshaberyje. Kita tiek lietuvių gyveno pačiame Augsburge. Uždarius stovyklas dar keletą dešimtmečių Augsburge veikė Vokietijos lietuvių bendruomenės apylinkė. 1945 m. šalia kelių į Hochfeldą ir į Haunšteteną sankryžos lietuviai pagal architekto J. Muloko projektą pastatė ąžuolinį kryžių su įrašais lietuvių, vokiečių, anglų, prancūzų ir lotynų kalbomis (1984 m. buvo restauruotas ir pašventintas vysk. A. Deksnio).
Augsburgo lietuvių laikraščiai
Žymesni lietuviai
Augsburgo kapinėse palaidota lietuvių, tarp jų dramaturgas Keturakis, generolas leitenantas Klemensas Popeliučka.
Augsburgo jėzuitų kolegijoje studijavo Albertas Vladislovas Radvila.
Augsburge gyveno, mokėsi ar dirbo: Adolfas Butkus, Antanina Dambrauskaitė, Jonas Daugėla, Elena Dauguvietytė-Kudabienė, Ksana Dauguvietytė-Šniukštienė, Irena Eidrigevičiūtė-Sprindienė, Alfonsas Jurskis, Henrikas Kačinskas, Jeronimas Kačinskas, Algirdas Jonas Kasulaitis, Elena Kepalaitė, Zita Kėvalaitytė, Aleksandras Kučiūnas, Mečislovas Leškys-Leškevičius, Juozas Meškauskas, Vytautas Palčiauskas, Juozas Palubinskas, Vilius Pėteraitis, Antanas Škėma, Jackus Sondeckis ir kiti.
Augsburge gimė: Aleksandras Gedmintas.
Šaltiniai
Vokietijos lietuvių bendruomenė
Lietuviai | 25,302 |
https://fr.wikipedia.org/wiki/Art%20of%20Trance | Wikipedia | Open Web | CC-By-SA | 2,023 | Art of Trance | https://fr.wikipedia.org/w/index.php?title=Art of Trance&action=history | French | Spoken | 349 | 778 | Art of Trance est un artiste de musique trance anglais du milieu des années 1990. C'est en fait le nom de scène que s'est donné Simon Berry dans son projet de trance en solo. C'est aussi le créateur du label Platipus Records. Il fait aussi partie du duo de Union Jack avec Claudio Giussani.
Art of Trance est réputé pour l'usage de sons naturels dans ses samples (chants d'oiseaux, ruisseaux…).
À partir de 2018, Simon Berry sort de nouveaux titres sous son propre nom.
Discographie
Singles
1993 'Vicious Circles' (sous le pseudonyme de Poltergeist)
1993 'Cambodia'
1993 'Deeper Than Deep'
1993 'Gloria'
1993 'The Colours'
1995 'Octopus/Orange'
1996 'Wildlife On One'
1997 'Kaleidoscope'
1998 'Madagasga'
1999 'Breath'
1999 'Easter Island'
1999 'Madagascar'
2000 'Vicious Circles' (sous le pseudonyme de Vicious Circles)
2000 'Monsoon'
2001 'Killamanjaro'
2002 'Love Washes Over'
2004 'Mongoose'
2004 'Turkish Bizzare'
2005 'Madagascar/Monsoon
2006 'Persia'
2009 'Madagascar 2009'
2009 'Swarm'
2016 'Ultrafoxx'
2016 'Firebird'
2017 'Curve Bender'
2017 'Before The Storm'
2018 'Pukwudgie' (avec Luke Brancaccio)
2019 'Black rainbow'
2019 'Believe' (avec Luke Brancaccio)
2019 'Stripes & Stars' (avec Luke Brancaccio)
2019 'Anaconda'
2019 'Here Comes The Rain' (avec Luke Brancaccio Feat. Kiki Cave)
2020 'Rogue Planet'
2020 'Pangolin'
2020 'Martian Sunrise'
2020 'Maelström'
2021 'Meow Miaou'
Albums
1996 Wildlife On One
1999 Voice of Earth
2009 Retrospective
Remixes
1993 Art of Trance - 'Deeper Than Deep' (sous le pseudonyme de Poltergeist)
1994 Velocity - 'Lust'
1998 The Young Braves - 'Warriors Groove' (sous le pseudonyme de Poltergeist)
1999 Quietman - 'Tranquil'
1999 Yello vs. Hardfloor - 'Vicious Games'
2001 Moogwai - 'The Labyrinth' (sous le pseudonyme de Vicious Circles)
2002 Indiana - 'Do You Hear Me?'
2002 John Occlusion vs. Johen - 'Psycho Drums'
2003 Jan Johnston - 'Calling Your Name'
2004 Tekara - 'Wanna Be An Angel'
2011 Steve Jablonsky - 'Arrival To Earth' (avec Exist & Arjen van der Hoek)
Voir aussi
Articles connexes
Trance
Liens externes
Site officiel de Platipus Records
Page d'Art Of Trance sur le site Platipus Records
http://www.global-trance.co.uk/fr_index.html?/Art_of_Trance.html
Musicien de musique électronique anglais
Musicien de trance
Nom de scène | 36,555 |
https://sr.wikipedia.org/wiki/%D0%A5%D0%B0%D1%98%D0%B0%D0%BA%D0%B0%D1%82%D0%B5%D0%BF%D0%B5%D0%BA%20%28%D0%90%D1%81%D1%82%D0%B0%D1%81%D0%B8%D0%BD%D0%B3%D0%B0%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Хајакатепек (Астасинга) | https://sr.wikipedia.org/w/index.php?title=Хајакатепек (Астасинга)&action=history | Serbian | Spoken | 55 | 181 | Хајакатепек () насеље је у Мексику у савезној држави Веракруз у општини Астасинга. Насеље се налази на надморској висини од 1974 м.
Становништво
Према подацима из 2010. године у насељу је живело 158 становника.
Хронологија
Попис
Види још
Савезне државе Мексика
Референце
Спољашње везе
Мексичка насеља
Насеља у општини Астасинга (Веракруз)
Википројект географија/Насеља у Мексику | 9,299 |
https://ro.wikipedia.org/wiki/Mihai%20Negruzzi | Wikipedia | Open Web | CC-By-SA | 2,023 | Mihai Negruzzi | https://ro.wikipedia.org/w/index.php?title=Mihai Negruzzi&action=history | Romanian | Spoken | 110 | 224 | Mihai L. Negruzzi () a fost un general, scriitor, memorialist și om politic român, care a îndeplinit funcția de primar al municipiului Iași în perioadele 23 martie 1920 - august 1921 și 1921.
Mihai Negruzzi a fost fiul lui Leon C. Negruzzi (1840-1890), el însuși primar și prefect al municipiului Iași.
În anul 1938 a îndeplinit funcția de rezident regal al Ținutului Prut, cu reședința la Iași în strada Toma Cozma nr. 16. Vara locuia la conacul familiei din satul Hermeziu din județul Iași. În zilele noastre în fostul său conac funcționează Muzeul Costache Negruzzi.
Nașteri în 1873
Decese în 1958
Generali români din secolul al XX-lea
Primari ai Iașului | 2,877 |
https://de.wikipedia.org/wiki/Hugo%20Riehmann | Wikipedia | Open Web | CC-By-SA | 2,023 | Hugo Riehmann | https://de.wikipedia.org/w/index.php?title=Hugo Riehmann&action=history | German | Spoken | 149 | 320 | Hugo Riehmann (* 10. November 1873 in Sülzenbrücken; † 20. November 1938 ebenda) war ein deutscher Landwirt und Politiker (Thüringer Landbund).
Leben
Riehmann war evangelisch-lutherischer Konfession. Er machte eine Lehre als Schmied und lebte als Schmiedemeister und Landwirt in Sülzenbrücken.
Nach der Novemberrevolution schloss er sich dem Thüringer Landbund an. Bei den vorgezogenen Neuwahlen zu Landesversammlung des Freistaates Gotha am 30. Mai 1919 wurde er in die Landesversammlung gewählt. Er gehörte dieser auch nach der Umwandelung in eine Gebietsvertretung bis 1923 an. Er wurde für seine Partei und den Wahlkreis Sachsen-Gotha in den Thüringer Landtag gewählt, dem er bis 1923 angehörte. Von 1909 bis 1921 war er Schultheiß (Bürgermeister) und Gemeindevorstand von Sülzenbrücken.
Quellen
Thüringer Landtag: Die Abgeordneten des 1. Thüringer Landtags 1920 – Eine biographische Ausstellung, Hugo Riehmann
ThLB-Mitglied
Landtagsabgeordneter (Land Thüringen)
Bürgermeister (Thüringen)
Amt Wachsenburg
Mitglied der Landesversammlung des Freistaates Sachsen-Gotha
Deutscher
Geboren 1873
Gestorben 1938
Mann | 32,238 |
https://war.wikipedia.org/wiki/Delta%20insulare | Wikipedia | Open Web | CC-By-SA | 2,023 | Delta insulare | https://war.wikipedia.org/w/index.php?title=Delta insulare&action=history | Waray | Spoken | 36 | 53 | An Delta insulare in uska species han Hymenoptera nga syahan ginhulagway ni Smith hadton 1857. An Delta insulare in nahilalakip ha genus nga Delta, ngan familia nga Eumenidae. Waray hini subspecies nga nakalista.
Mga kasarigan
Delta | 33,355 |
https://ml.wikipedia.org/wiki/%E0%B4%95%E0%B5%87%E0%B4%A8%E0%B5%8D%E0%B4%A6%E0%B5%8D%E0%B4%B0%20%E0%B4%B8%E0%B4%BE%E0%B4%B9%E0%B4%BF%E0%B4%A4%E0%B5%8D%E0%B4%AF%20%E0%B4%85%E0%B4%95%E0%B5%8D%E0%B4%95%E0%B4%BE%E0%B4%A6%E0%B4%AE%E0%B4%BF%20%E0%B4%AA%E0%B5%81%E0%B4%B0%E0%B4%B8%E0%B5%8D%E0%B4%95%E0%B4%BE%E0%B4%B0%E0%B4%82%202014 | Wikipedia | Open Web | CC-By-SA | 2,023 | കേന്ദ്ര സാഹിത്യ അക്കാദമി പുരസ്കാരം 2014 | https://ml.wikipedia.org/w/index.php?title=കേന്ദ്ര സാഹിത്യ അക്കാദമി പുരസ്കാരം 2014&action=history | Malayalam | Spoken | 56 | 462 |
കേന്ദ്ര സാഹിത്യ അക്കാദമി പുരസ്കാരം 2014
22 ഭാഷകളിലെ പുരസ്കാരങ്ങൾ പ്രഖ്യാപിച്ചപ്പോൾ കവിതാ വിഭാഗത്തിനാണ് മുൻതൂക്കം- എട്ടെണ്ണം. അഞ്ചു നോവലുകളും മൂന്നു വീതം ഉപന്യാസങ്ങളും ചെറുകഥാ സമാഹാരങ്ങളും ഒന്നു വീതം സാഹിത്യ നിരൂപണം, നാടകം, ആത്മകഥ എന്നിവയാണു മറ്റു പുരസ്കാരങ്ങൾ നേടിയത്.
കേന്ദ്ര സാഹിത്യ അക്കാദമി യുവ പുരസ്കാരം 2014
2014 ൽ ദോഗ്രി, കശ്മീരി, സിന്ധി ഭാഷകൾക്ക് പുരസ്കാരമുണ്ടായിരുന്നില്ല.
ബാല സാഹിത്യത്തിനുള്ള കേന്ദ്ര സാഹിത്യ അക്കാദമി പുരസ്കാരം 2014
അവലംബം
കേന്ദ്ര സാഹിത്യ അക്കാദമി പുരസ്കാരം
2014 | 10,448 |
https://stackoverflow.com/questions/6788974 | StackExchange | Open Web | CC-By-SA | 2,011 | Stack Exchange | Alberto León, Jason Fortik, K.Doe2, Mark, Nicola Peluchetti, Philippe De Ryck, Rajeev Krishnan, Robbie Prokop, RvdK, barscik, https://stackoverflow.com/users/14848070, https://stackoverflow.com/users/14848071, https://stackoverflow.com/users/14848072, https://stackoverflow.com/users/14848187, https://stackoverflow.com/users/14848188, https://stackoverflow.com/users/14848197, https://stackoverflow.com/users/14848199, https://stackoverflow.com/users/14850314, https://stackoverflow.com/users/14850373, https://stackoverflow.com/users/14850747, https://stackoverflow.com/users/14850900, https://stackoverflow.com/users/397861, https://stackoverflow.com/users/47351, https://stackoverflow.com/users/690958, https://stackoverflow.com/users/857771, kusigun, motorbank, mychaljxxg, user14850373, yrj_singh.therealone | English | Spoken | 317 | 747 | jQuery form submission
My form works as it should and i receive the emails from it but if you hit submit without entering data you get an error box informing you what you of required fields - however my submit button stays greyed out, so even if you then fill in those fields you cannot submit the form without a refresh.
code:
jQuery(document).ready(function() {
$('#success').hide();
$('#contactform').submit(function() {
var action = $(this).attr('action');
$('#contactform #submit').attr('disabled', 'disabled').after('<img src="images/ajax-loader.gif" class="loader" />');
$("#message").slideUp(750,function() {
$('#message').hide();
$.post(action, {
name: $('#name').val(),
email: $('#email').val(),
phone: $('#phone').val(),
subject: $('#subject').val(),
comments: $('#comments').val(),
verify: $('#verify').val()
},
function(data) {
document.getElementById('message').innerHTML = data;
$('#message').slideDown('slow');
$('#contactform img.loader').fadeOut('fast',function(){$(this).remove()});
$('#contactform #submit').attr('disabled','');
if(data.match('success') != null) $('#submit').hide();
});
});
return false;
});
});
Any help is much appreciated!
You should remove disabled attribute enterily
$('#contactform #submit').removeAttr('disabled');
Unfortunately It still stays disabled :(
try this if(data.match('success') != null) {$('#submit').hide();}else{$("#submit").removeAttr('disabled');}
did you check if this script actually runs to the point where it should remove or update the attribute?
still the same...how annoying!
This is because the disabled attribute works by existence. By that I mean that the very inclusion of the disabled attribute causes the element to be disabled.
Replace:
$('#contactform #submit').attr('disabled','');
with:
$('#contactform #submit').removeAttr('disabled');
I think you are right with this, but i'm not sure that the validation he is talking about is done server side.
Unfortunately It still stays disabled :(
This is because the submit button is disabled after you hit the submit:
$('#contactform #submit').attr('disabled','disabled').after('<img src="images/ajax-loader.gif" class="loader" />');
you shoul re-enable it if the validation fails like this:
$('#contactform #submit').removeAttr('disabled');
Unfortunately It still stays disabled :(
does the line with 'removeAttr' get executed? Check with Firebug/Firefox or Google Chrome.
Try using removeAttribute function.
I think it will solve your problem.
(As <input type='text' disabled='disabled' ----> and <input type='text' disabled ---> are same.
Using removeAttribute will render something like <input type='text' ---> and your problem will be solved)
Unfortunately It still stays disabled :(
| 48,219 |
https://ja.wikipedia.org/wiki/%E8%88%8E%E4%BA%BA%E5%90%89%E5%B9%B4 | Wikipedia | Open Web | CC-By-SA | 2,023 | 舎人吉年 | https://ja.wikipedia.org/w/index.php?title=舎人吉年&action=history | Japanese | Spoken | 14 | 432 | 舎人吉年（とねりのきね/えとし/よしとし、生没年不詳）は、飛鳥時代の女官・歌人。名の吉年は、「きね」「えとし」「よしとし」などの読み方がある。
舎人氏の出身の女官。天智天皇10年（671年）12月、天智天皇の大殯（おおあらき）のときに額田王らと共に挽歌を詠む（『万葉集』2-152）。また田部櫟子（たべのいちいこ）という人物が大宰府に赴任する際に別れを惜しむ歌を贈っていることから、彼と親密な関係にあったと考えられる（『万葉集』4-492）。
やすみしし我ご大君の大御船待ちか恋ふらむ志賀の辛崎（万葉集2-152）
衣手に取りとどこほり泣く子にもまされる我を置きて如何にせむ（万葉集4-492）
脚注
参考文献
坂本太郎・平野邦雄監修『日本古代氏族人名辞典』吉川弘文館、1990年。
佐伯有清編『日本古代氏族事典』雄山閣出版、1994年。
7世紀日本の女性
7世紀日本の女性著作家
日本の女性歌人
飛鳥時代の女性
万葉歌人
日本の女官 | 40,572 |
https://stackoverflow.com/questions/63095093 | StackExchange | Open Web | CC-By-SA | 2,020 | Stack Exchange | CherryDT, Sebastian Simon, ggorlen, https://stackoverflow.com/users/1871033, https://stackoverflow.com/users/4642212, https://stackoverflow.com/users/6243352 | English | Spoken | 212 | 330 | replace all characters between a starting and ending delimiting characters
Disclaimer: part of a homework for a course I am doing on javascript:
I am learning javascript regex and I don't know how to go about the following. Basically I have the following string:
const a = 1;
const e = 2;
const b = '$a$/abc/$e$/'
Now I want to replace the $a$ and $e$ with a and e values so at least I have:
const output = '1/abc/2'
Please see how do I ask homework questions?. Without an honest effort on your part to complete it, the question is off-topic.
What did you try so far? In what way did it fail? If you plan how to do it in logical steps without knowing the exact functions and methods to use, what "tool" in your toolbox are you missing?
Partially a duplicate of How do you use a variable in a regular expression?. Ideally, a and e wouldn’t be variables. An object would be a lot better here, e.g. const lookup = { a: 1, e: 2 }. Then, using the replace method you’d look up the right lookup property.
Use template literal bro for doing this :---
const a = 1;
const e = 2;
const b = `${a}/abc/${e}/`
console.log(b)
| 81 |
https://mathematica.stackexchange.com/questions/137964 | StackExchange | Open Web | CC-By-SA | 2,017 | Stack Exchange | Norwegian Nynorsk | Spoken | 243 | 620 | How to write a nested map function
I don't like dealing with tables. I would rather dealing with # and /@. So what is the best concise way of writing the following double table.
tbl = Table[{xi, ss[[vi]][[1]], ss[[vi]][[2]][xi]}, {vi,
Length[ss]}, {xi, 0, 1, 1/(Length[ss] - 1)}] // Flatten[#, 1] &;
where a shorter representation of ss is :
ss={{0.1, InterpolatingFunction[{{0., 1.}}, <>]}, {0.6, InterpolatingFunction[{{0., 1.}}, <>]}, {1.1,InterpolatingFunction[{{0., 1.}}, <>]}, {1.6,InterpolatingFunction[{{0., 1.}}, <>]}, {2.1,InterpolatingFunction[{{0., 1.}}, <>]}, {2.6, InterpolatingFunction[{{0., 1.}}, <>]}, {3.1, InterpolatingFunction[{{0., 1.}}, <>]}, {3.6,InterpolatingFunction[{{0., 1.}}, <>]}, {4.1, InterpolatingFunction[{{0., 1.}}, <>]}, {4.6, InterpolatingFunction[{{0., 1.}}, <>]}};
Please note that the interpolation function is different at each row.
Thanks for your help.
Regards,
There are literally gazillion ways to write this differently. One of them is to create your xi with Subdivide, create all tuples and apply a function that puts everything into order
{#2, #1[[1]], #1[[2]][#2]} & @@@ Tuples[{ss, Subdivide[Length[ss] - 1]}]
On the other hand your Table call isn't too bad. Note that you can directly iterate over your ss without using an index vi
Flatten[
Table[{xi, vi[[1]], vi[[2]][xi]}, {vi, ss}, {xi, 0, 1, 1/(Length[ss] - 1)}],
1]
It's not as nice as halirutan's Tuples but Array could be useful here:
n = Length[ss];
Join @@ Array[{#2, ss[[#, 1]], ss[[#, 2]][#2]} &, {n, n}, {1, {0, 1}}]
This could also be written perhaps more appealingly as:
fn[n_][_[a_, b_]] := Array[{#, a, b[#]} &, n, {0, 1}]
Join @@ fn[Length @ ss] /@ ss
| 1,147 | |
https://math.stackexchange.com/questions/3163342 | StackExchange | Open Web | CC-By-SA | 2,019 | Stack Exchange | Amalya, Andreas Caranti, J. W. Tanner, Joel Pereira, Qurultay, https://math.stackexchange.com/users/29335, https://math.stackexchange.com/users/338156, https://math.stackexchange.com/users/58401, https://math.stackexchange.com/users/590578, https://math.stackexchange.com/users/610480, https://math.stackexchange.com/users/615567, rschwieb | English | Spoken | 572 | 1,042 | Find all ring homomorphisms
Find all the ring homomorphisms $f$ : $\mathbb{Z}_6\to\mathbb{Z}_3$.
definition of ring homomorphism:
The function f: R → S is a ring homomorphism if:
1) $f(1)$ = $1$
2) $f(a+b)$ = $f(a)$ + $f(b)$ for all a,b, in R
3) $f(ab)$ = $f(a)$ $f(b)$ for all a,b in R
Does it make sense to say that in this case
$f(6) = f(1) + f(1) + f(1) + f(1) +f(1) + f(1) = 1 + 1 + 1 + 1 + 1 + 1 = 0$ in $\mathbb{Z}_3$
Could you explain what do we do to find ring homomorphism in all cases. Not only $\mathbb{Z}_m \to\mathbb{Z}_n$, where $m<n$ .
Note that the solution depends upon your definition of ring homomorphism. If you define a ring homomorphism from ring $R$ to ring $S$ as a map $f : R \to S$ such that $f(x + y) = f(x) + f(y)$ and $f(x y) = f(x) f(y)$, then $f(0) = 0$ holds, but (provided $R$ and $S$ have a unity) it does not follow that $f(1) = 1$.
@AndreasCaranti my definition includes $f(1)$ = 1
Wherever $f$ sends $1$ determines where $f$ sends other elements
@J.W.Tanner well, in the definition given to me ring homomorphism is a function that sends 1 to 1.
@Amalya I think your definition is incorrect, because then the zero homomorphism would not exist.
So then $f(2)=f(1+1)=f(1)+f(1)=1+1$, etc.
@J.W.Tanner so then how will I eventually describe the ring homomorphisms?
you must have $f(0)=0$, $f(1)=1$, $f(2)=2$, $f(3)=3=0$, $f(4)=f(1)=1$ and $f(5)=f(2)=2$.
Please search for your question before asking. Thanks
@JoelPereira, there are two distinct definitions. If you are working in the category of rings, morphisms are defined as OP does. If you are working in the category of rings with unity, then you additionally require the unity of the first ring to go to the unity of the second ring.
As I see it, that really depends on the specific rings we are given.
If you have learned module theory, you will know the way to find all the module homomorphisms is to "send the generators" and then "respect the relations". Because the linearity ensures we take care of all the elements as long as we take care of the generators, while the well-definedness requires the relations to be respected.
This is the basic principle to find homomorphisms, and what you are doing is literally the same. In your case, the ring hom is at first place a $\mathbb{Z}$-module hom, and $1$ is the generator. However, for a general ring, things get a bit harder. But you can do your best by getting familiar with some special cases.
For example, to find a ring hom from a polynomial ring $R[x]\rightarrow S$, it suffices to consider where to send $x$, because that gives the destination for every element. And indeed, in many cases, the ring you have is a quotient of a polynomial ring. In that case, you have some constraints: take care of the well-definedness.
Hope this helps.
The elements of the ring $\mathbb Z_6$ can be obtained by successively adding $1$.
According to your definition, $f(1)=1$ (by (1)),
and $f(n\times1)=n\times f(1)=n\times1$ (by (2) and induction).
(Here $n\times$ means added $n$ (where $n \in \mathbb Z)$ times in the ring, not multiplication in the ring.)
It does make sense to say that $6$, which is in the additive identity class in $\mathbb Z_6,$
gets mapped to $0$ in $\mathbb Z_3.$
| 48,346 |
https://tr.wikipedia.org/wiki/Hockenheimring | Wikipedia | Open Web | CC-By-SA | 2,023 | Hockenheimring | https://tr.wikipedia.org/w/index.php?title=Hockenheimring&action=history | Turkish | Spoken | 647 | 1,979 | Hockenheimring Baden-Württemberg, Almanya'nın Baden-Württemberg eyaletindeki Hockenheim'da bulunan bir otomobil yarışı pistidir. Diğer motor sporları etkinliklerinin de düzenlendiği bu pist her iki yılda Formula 1 Almanya Grand Prix'ine ev sahipliği yapmaktadır. Ren vadisinde bulunan pist hemen hemen tümüyle düzdür.
Tarihi
1930'lardan 1960'lara
Karlsruhe'deki Wildpark pistinin Alman yöneticiler tarafından yarışlara kapatılması üzerine Hockenheimring 1932 yılında orman yolları üzerine kuruldu. O tarihte motosiklet yarışları için kullanılan pist 1936 yılında Mercedes-Benz ve Auto Union'ın test pisti olarak işlem gördü. Pistin adı 1938 yılında Kurpfalzring olarak değiştirildi ve bu ad 1947 yılına dek kullanıldı. Savaştan sonra Grand Prix motosiklet yarışlarına ev sahipliği yapan pist Alman motosiklet Grand Prix yarışları için de kullanıldı.
Özgün pist yaklaşık 8 kilometre uzunluğundaydı. İki uzun düzlüğe ve ormandaki "sağ" viraja sahip olan pist, Hockenheim'daki U dönüşüyle kente bağlanıyordu.
1960'lardan 2000'lere
1965 yılında tamamlanan A 6 otoyolunun köyü pistten ayırması üzerine Hockenheim pisti yeniden tasarlandı. Jim Clark'ın 1968 yılında bir Formula 1 yarışı sırasında ölmesinin ardından piste 2 sert viraj ve bir Armco bariyer eklendi. Kazanın meydana geldiği yer olan ilk sert viraj yakınına bir anıt dikildi. Patrick Depailler'in ölümünün ardından Ostkurve (sağ viraj) denilen bölgeye de bir sert viraj eklenmiştir.
Pist, 1.3 km'ye varan ve birbirlerine sert virajlarla bağlı dört uzun düzlükten oluşmaktaydı. Orman bölümünün sonunda daha kıvrımlı bir bölge olan "stadyum" bulunuyordu. Bu durum yarış araçlarının ayarlanmasını güçleştirmekteydi çünkü uzun düzlüklerde yapılan hızı artırmak için çekiş gücünün belirli bir düzeyde tutulması gerekiyordu. Pistin uzun olması ise izleyicilerin yarış araçlarını yalnızca 44 kez (Formula 1 yarışları için) görebilmelerine neden oluyordu.
2000'ler
F1 yöneticileri 2000'lerin başında yaptıkları bir girişimle pist uzunluğunun düşürülmesini istemişler ve bunun yapılmaması durumunda pisti yarış takviminden çıkaracaklarını vurgulamışlardır. Bunun üzerine, Baden-Württemberg eyalet yönetimi Hermann Tilke'nin 2002 Almanya Grand Prix için hazırladığı tasarımın maliyetini üstlenmiştir. Stadyum bölümü, yüzey ve ilk viraj dışında olduğu gibi kalmıştır. Ne var ki, pistin ormanlık bölümü büyük ölçüde kısaltılmış ve bu bölge yeniden ağaçlandırılmıştır. Bu değişiklik sert biçimde eleştirilmiş ancak pistin bu bölümüne eklenen U virajının geçişi kolaylaştırdığı savunulmuştur. Yitip giden yaklaşık 70 yıllık bir geçmişe sahip bir ormanlık bölge ve dar bir yoldan sert viraja doğru süzülen 20 Formula 1 aracının görüntüsüydü. Birçok Formula 1 tutkunu pistin ruhunu yitirdiğini ve en kısa zamanda yeniden eski halini alması gerektiğini düşünmektedirler. Ancak, şu ana dek bu yönde bir girişim gerçekleşmemiştir.
Pistin seyirci kapasitesi 120.000'e ulaşmıştır. Bunda yapımı yeni tamamlanan ve masrafları Mercedes-Benz tarafından karşılanan tribünlerin etkisi büyüktür.
Pisti içeren bölgede hız yarışlarının yapıldığı çeyrek mil uzunluğunda bir parkur da bulunur. Bu pist, Avrupa'nın en büyük hız yarışlarından biri olan NitroOlympx'e de evsahipliği yapmaktadır.
Formula 1
Hockenheim pistinin 1970 yılındaki Almanya Grand Prix'ine ilk kez evsahipliği yapması F1 sürücülerinin Fransa Grand Prix'inden sonra Nürburgring'i boykot etme kararı almaları üzerine gerçekleşmiştir. Bir yıl sonra yeniden Nürburgring'e dönen Almanya Grand Prix 1976 Almanya Grand Prix'ine dek bu pistte düzenlenmiştir. Hockenheimring, Almanya Grand Prix'ine 'den 'ya dek evsahipliği yapmıştır. 1985 yılındaki yarış ise Nürburgring'de düzenlenmiştir.
Bernie Ecclestone Temmuz 2006'da yaptığı açıklamada 2007 yılından itibaren Almanya'da tek bir yarış yapılacağını söylemiştir (Almanya yılından bu yana yılda iki Grand Prix'ye evsahipliği yapıyordu. Bunlar; Hockenheim'da düzenlenen Almanya Grand Prix ve Nürburgring'de düzenlenen Avrupa Grand Prix'idir). 2007 yılından sonra Nürburgring ve Hockenheimring evsahipliğini değişmeli olarak kullanacaklardır.
Yarış başına 5.3 milyon Euro'ya varan ve yerel yönetimler tarafından karşılanması zorunlu harcamalar nedeniyle Hockenheimring'in 2010 yılından itibaren Formula 1 ile olan sözleşmesinden çekileceği öngörülmektedir..
Ölümlü kazalar
1968 Jim Clark, bir Formula 2 yarışı sırasında.
1972 Bert Hawthorne, bir Formula 2 yarışı sırasında.
1980 Patrick Depailler, bir test sürüşü sırasında.
Kaynakça
Dış bağlantılar
Hockenheimring
Hockenheimring pistinin tarihi ve istatistikleri
Pistin Formula1.com'daki değerlendirmesi
Honda’dan Alex Wurz'la Hockenheim'da Bir Tur
Hockenheim - teknik gereksinimler
BBC pist kılavuzu
Baştan sona bir tur (QT, 10,4 MB)
Google Earth için yeni Hockenheimring kaplaması
Ciro Pabón'un Pistleri Tüm motor sporları pistlerine ait 3 boyutlu görüntüler ve sanal turlar
Google Maps uydu fotoğrafı (Ekim 2008'e ait bu fotoğraf hala pistin 2002 öncesindeki halini gösteriyor)
Almanya'daki yarış pistleri
Formula 1 pistleri | 9,715 |
https://be.wikipedia.org/wiki/%D0%9D%D1%8B%D0%BA%D0%B0%D0%BD%D1%96%D1%9E%D0%BA%D0%B0%20%28%D0%91%D1%8D%D1%80%D0%B4%D1%8B%D1%87%D1%8B%D1%9E%D1%81%D0%BA%D1%96%20%D1%80%D0%B0%D1%91%D0%BD%29 | Wikipedia | Open Web | CC-By-SA | 2,023 | Ныканіўка (Бэрдычыўскі раён) | https://be.wikipedia.org/w/index.php?title=Ныканіўка (Бэрдычыўскі раён)&action=history | Belarusian | Spoken | 20 | 83 | Ныканіўка () — вёска ў Бэрдычыўскім раёне Жытомірскай вобласці Украіны. Уваходзіць у склад Грышкіўскай пасялковай абшчыны.
Населеныя пункты Бэрдычыўскага раёна | 28,357 |
https://nl.wikipedia.org/wiki/Lyctus%20longicornis | Wikipedia | Open Web | CC-By-SA | 2,023 | Lyctus longicornis | https://nl.wikipedia.org/w/index.php?title=Lyctus longicornis&action=history | Dutch | Spoken | 27 | 53 | Lyctus longicornis is een keversoort uit de familie boorkevers (Bostrichidae). De wetenschappelijke naam van de soort is voor het eerst geldig gepubliceerd in 1879 door Reitter.
Boorkevers | 47,796 |
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