post_href stringlengths 57 213 | python_solutions stringlengths 71 22.3k | slug stringlengths 3 77 | post_title stringlengths 1 100 | user stringlengths 3 29 | upvotes int64 -20 1.2k | views int64 0 60.9k | problem_title stringlengths 3 77 | number int64 1 2.48k | acceptance float64 0.14 0.91 | difficulty stringclasses 3
values | __index_level_0__ int64 0 34k |
|---|---|---|---|---|---|---|---|---|---|---|---|
https://leetcode.com/problems/find-the-difference/discuss/1969523/Python3-runtime%3A-48ms-52.48-memory%3A-13.9mb-33.89 | class Solution:
def findTheDifference(self, string: str, target: str) -> str:
if not string and not target:
return True
if not string:
return target
if not target:
return False
visited = [0] * 26
for i in range(len(string)):
i... | find-the-difference | Python3 runtime: 48ms 52.48% memory: 13.9mb 33.89% | arshergon | 1 | 47 | find the difference | 389 | 0.603 | Easy | 6,700 |
https://leetcode.com/problems/find-the-difference/discuss/1920036/Easy-simple-python-solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
d= defaultdict(int)
for i in s:
d[i]+=1
for j in t:
d[j]+=1
for key in d:
if d[key] %2==1:
return key | find-the-difference | Easy simple python solution | Buyanjargal | 1 | 84 | find the difference | 389 | 0.603 | Easy | 6,701 |
https://leetcode.com/problems/find-the-difference/discuss/1911593/Simple-Dictionary-oror-No-XOR-oror-No-Sorting-oror-Full-Explanation-with-Example | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
d = Counter(t) #stores the frequency of t
for i in s:
d[i] -= 1 #every time we decrement the frequency of dictionary which stores the frequency of t
if d[i] == 0:
del d[i] #if t... | find-the-difference | ✅Simple Dictionary || No XOR || No Sorting || Full Explanation with Example | Dev_Kesarwani | 1 | 57 | find the difference | 389 | 0.603 | Easy | 6,702 |
https://leetcode.com/problems/find-the-difference/discuss/1752397/Python-Curated-List-of-cool-oneliners | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return chr(reduce(xor, map(ord, chain(s, t)))) | find-the-difference | [Python] Curated List of cool oneliners | sidheshwar_s | 1 | 39 | find the difference | 389 | 0.603 | Easy | 6,703 |
https://leetcode.com/problems/find-the-difference/discuss/1752397/Python-Curated-List-of-cool-oneliners | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return chr(reduce(lambda x, y: x ^ y, map(ord, s + t))) | find-the-difference | [Python] Curated List of cool oneliners | sidheshwar_s | 1 | 39 | find the difference | 389 | 0.603 | Easy | 6,704 |
https://leetcode.com/problems/find-the-difference/discuss/1752397/Python-Curated-List-of-cool-oneliners | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return list(Counter(t) - Counter(s))[0] | find-the-difference | [Python] Curated List of cool oneliners | sidheshwar_s | 1 | 39 | find the difference | 389 | 0.603 | Easy | 6,705 |
https://leetcode.com/problems/find-the-difference/discuss/1752397/Python-Curated-List-of-cool-oneliners | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return next(iter(Counter(t) - Counter(s))) | find-the-difference | [Python] Curated List of cool oneliners | sidheshwar_s | 1 | 39 | find the difference | 389 | 0.603 | Easy | 6,706 |
https://leetcode.com/problems/find-the-difference/discuss/1752397/Python-Curated-List-of-cool-oneliners | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return "".join(Counter(t) - Counter(s)) | find-the-difference | [Python] Curated List of cool oneliners | sidheshwar_s | 1 | 39 | find the difference | 389 | 0.603 | Easy | 6,707 |
https://leetcode.com/problems/find-the-difference/discuss/1751858/Python-Easy-1-line-solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return chr(sum([ord(c) for c in t]) - sum([ord(c) for c in s])) | find-the-difference | [Python] Easy 1 line solution | nomofika | 1 | 155 | find the difference | 389 | 0.603 | Easy | 6,708 |
https://leetcode.com/problems/find-the-difference/discuss/1751694/Python-oror-Easy-Solution-oror-96-Faster-and-96-Space-Efficient | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
for i in set(t):
if s.count(i) != t.count(i):
return i | find-the-difference | Python || Easy Solution || 96% Faster and 96% Space Efficient | cherrysri1997 | 1 | 19 | find the difference | 389 | 0.603 | Easy | 6,709 |
https://leetcode.com/problems/find-the-difference/discuss/1751193/python-easy-to-understand | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
a = []
for i in range(len(t)):
a.append(t[i])
for i in range(len(s)):
a.remove(s[i])
ans = a[0]
return ans | find-the-difference | python easy to understand | ggeeoorrggee | 1 | 25 | find the difference | 389 | 0.603 | Easy | 6,710 |
https://leetcode.com/problems/find-the-difference/discuss/1591194/Python-faster-than-87.94 | class Solution(object):
def findTheDifference(self, s, t):
"""
:type s: str
:type t: str
:rtype: str
"""
for c in t:
if s.count(c) != t.count(c):
return c | find-the-difference | Python faster than 87.94% | ckayfok | 1 | 92 | find the difference | 389 | 0.603 | Easy | 6,711 |
https://leetcode.com/problems/find-the-difference/discuss/1260511/Python3-dollarolution-(95-Faster) | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
s = Counter(s)
t = Counter(t)
for i in (t-s):
return i | find-the-difference | Python3 $olution (95% Faster) | AakRay | 1 | 316 | find the difference | 389 | 0.603 | Easy | 6,712 |
https://leetcode.com/problems/find-the-difference/discuss/1062566/Python-very-simple-solution-with-Counter | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
diff = Counter(t) - Counter(s)
return list(diff.keys())[0] | find-the-difference | Python - very simple solution with Counter | angelique_ | 1 | 71 | find the difference | 389 | 0.603 | Easy | 6,713 |
https://leetcode.com/problems/find-the-difference/discuss/249886/Solution-using-Counter | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
from collections import Counter
s_counter = Counter(s)
t_counter = Counter(t)
return list(t_counter - s_counter)[0] | find-the-difference | Solution using Counter | compbuzz09 | 1 | 73 | find the difference | 389 | 0.603 | Easy | 6,714 |
https://leetcode.com/problems/find-the-difference/discuss/2848549/python3 | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
# for each unique char in t
for c in set(t):
# if # of char in t > # of char in s, it was added to t
if t.count(c) > s.count(c):
return c | find-the-difference | python3 | wduf | 0 | 1 | find the difference | 389 | 0.603 | Easy | 6,715 |
https://leetcode.com/problems/find-the-difference/discuss/2846864/Easist-Solution-in-Python | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
set_t = set(t)
for char in set_t:
if t.count(char) != s.count(char):
return char | find-the-difference | Easist Solution in Python | namashin | 0 | 1 | find the difference | 389 | 0.603 | Easy | 6,716 |
https://leetcode.com/problems/find-the-difference/discuss/2846432/bit-manip-python3-solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
res = 0
for i in s+t:
res^=ord(i)
return chr(res) | find-the-difference | bit manip python3 solution | Cosmodude | 0 | 1 | find the difference | 389 | 0.603 | Easy | 6,717 |
https://leetcode.com/problems/find-the-difference/discuss/2834982/Python-simple-solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
list1 = [x for x in t]
list2 = [x for x in s]
list1.sort()
list2.sort()
list2.append(0)
print(list1)
print(list2)
reslist = [list1[i] for i in range(len(list1)) if list1[i] !=... | find-the-difference | Python simple solution | user1079z | 0 | 3 | find the difference | 389 | 0.603 | Easy | 6,718 |
https://leetcode.com/problems/find-the-difference/discuss/2834528/Python-solution-oror-O(n)-time-oror-O(n)-space | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
d = {}
for i in s:
try:
d[i] += 1
except:
d[i] = 1
for i in t:
try:
d[i] -= 1
if d[i] < 0:
return i
... | find-the-difference | Python solution || O(n) time || O(n) space | Pavel_Kos | 0 | 2 | find the difference | 389 | 0.603 | Easy | 6,719 |
https://leetcode.com/problems/find-the-difference/discuss/2832365/dictionary-solution-python | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
dict1={}
dict2 = {}
for x in s:
if x not in dict1:
dict1[x]=1
else:
dict1[x]=dict1[x]+1
for x in t:
if x not in dict2:
dict2[x]=1
... | find-the-difference | dictionary solution python | sahityasetu1996 | 0 | 3 | find the difference | 389 | 0.603 | Easy | 6,720 |
https://leetcode.com/problems/find-the-difference/discuss/2831104/Better-one-line-python-solution-O(n) | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return chr(sum([ord(l) for l in t]) - sum([ord(l) for l in s])) | find-the-difference | Better one line python solution O(n) | lornedot | 0 | 1 | find the difference | 389 | 0.603 | Easy | 6,721 |
https://leetcode.com/problems/find-the-difference/discuss/2831092/One-line-python-solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return chr(abs(sum([ord(l) for l in s]) + sum([-1* ord(l) for l in t]))) | find-the-difference | One line python solution | lornedot | 0 | 2 | find the difference | 389 | 0.603 | Easy | 6,722 |
https://leetcode.com/problems/find-the-difference/discuss/2829324/Easy-python-solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
for i in set(t):
if s.count(i) != t.count(i):
return i | find-the-difference | Easy python solution | _debanjan_10 | 0 | 1 | find the difference | 389 | 0.603 | Easy | 6,723 |
https://leetcode.com/problems/find-the-difference/discuss/2826203/Easy-Python-Solution-Using-HashMap-or-dict | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
final_word = s + t
hashMap = {}
for i in final_word:
hashMap[i] = final_word.count(i)
print(hashMap)
for i in hashMap:
if hashMap[i] % 2 != 0:
return i | find-the-difference | Easy Python Solution - Using HashMap or dict | danishs | 0 | 3 | find the difference | 389 | 0.603 | Easy | 6,724 |
https://leetcode.com/problems/find-the-difference/discuss/2820287/simple-python-using-dictionary-beats-75 | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
string = "abcdefghijklmnopqrstuvwxyz"
hashmap = {string[k]:0 for k in range(len(string))}
for i in range(len(s)):
hashmap[s[i]]+=1
for i in range(len(t)):
hashmap[t[i]]+=1
for k,v in ... | find-the-difference | simple python using dictionary beats 75% | sudharsan1000m | 0 | 3 | find the difference | 389 | 0.603 | Easy | 6,725 |
https://leetcode.com/problems/find-the-difference/discuss/2795178/Python-Solution-(With-basics-concepts) | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
s1 = []
t1 = []
alpha = string.ascii_lowercase
for i in alpha:
s1.append(s.count(i))
t1.append(t.count(i))
for i in range(0,26):
if (s1[i]-t1[i])!=0:
... | find-the-difference | Python Solution (With basics concepts) | VINAY_KUMAR_V_C | 0 | 3 | find the difference | 389 | 0.603 | Easy | 6,726 |
https://leetcode.com/problems/find-the-difference/discuss/2788536/Simple-Python3-Solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
if s == t:
return ""
for i in t:
if s.count(i) != t.count(i):
return i | find-the-difference | Simple Python3 Solution | vivekrajyaguru | 0 | 4 | find the difference | 389 | 0.603 | Easy | 6,727 |
https://leetcode.com/problems/find-the-difference/discuss/2778442/python-one-line | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
return[i for i in t if s.count(i) != t.count(i)][0] | find-the-difference | python one line | seifsoliman | 0 | 4 | find the difference | 389 | 0.603 | Easy | 6,728 |
https://leetcode.com/problems/find-the-difference/discuss/2770114/Python3-Simple-beginners-approach.-Please-upvote-if-it-helped | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
temp = {}
for letter in s:
if letter in temp:
temp[letter] += 1
else:
temp[letter] = 1
letters = {}
for letter in t:
if letter not in te... | find-the-difference | Python3 Simple beginners approach. Please upvote if it helped | OGLearns | 0 | 4 | find the difference | 389 | 0.603 | Easy | 6,729 |
https://leetcode.com/problems/find-the-difference/discuss/2738653/Simple-Python-Solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
arr = list(t)
for i in range(len(s)):
arr.remove(s[i])
return arr[0] | find-the-difference | Simple Python Solution | dnvavinash | 0 | 7 | find the difference | 389 | 0.603 | Easy | 6,730 |
https://leetcode.com/problems/find-the-difference/discuss/2736496/Python-Solution-93.86-faster-TC-O(n)-Space-O(1) | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
ans = 0
#iterating over the list 1 and performing XOR
for i in s:
# converting the element to its ascii value for XOR
ans^=ord(i)
for j in t:
ans^=ord(j)
# converting the extra element back to ... | find-the-difference | Python Solution 93.86% faster TC O(n) Space O(1) | nidhi_nishad26 | 0 | 6 | find the difference | 389 | 0.603 | Easy | 6,731 |
https://leetcode.com/problems/find-the-difference/discuss/2735628/Python-solution-Faster-than-9818-using-Counters | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
Cs=Counter(s)
Ct=Counter(t)
return list((Ct-Cs).keys())[0] | find-the-difference | Python solution Faster than 98,18%, using Counters | irouis | 0 | 4 | find the difference | 389 | 0.603 | Easy | 6,732 |
https://leetcode.com/problems/find-the-difference/discuss/2732694/easy-approach-using-python | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
s = sorted(list(s))
t = sorted(list(t))
for i in range(len(s)):
if s[i]!=t[i]:
return t[i]
return t[-1] | find-the-difference | easy approach using python | sindhu_300 | 0 | 2 | find the difference | 389 | 0.603 | Easy | 6,733 |
https://leetcode.com/problems/find-the-difference/discuss/2732362/Python-(2-line-Code) | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
for i in t:
if s.count(i)!=t.count(i):
return i | find-the-difference | Python (2 line Code) | durgaraopolamarasetti | 0 | 6 | find the difference | 389 | 0.603 | Easy | 6,734 |
https://leetcode.com/problems/find-the-difference/discuss/2721715/Python-Solution-Using-hashmap | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
sHash = {}
tHash = {}
for char in s:
if char in sHash:
sHash[char] += 1
else:
sHash[char] = 1
for char in t:
if char in tH... | find-the-difference | Python Solution Using hashmap | Furat | 0 | 9 | find the difference | 389 | 0.603 | Easy | 6,735 |
https://leetcode.com/problems/find-the-difference/discuss/2699340/Python-easy-solution | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
s_arr = list(s)
s_arr.sort()
t_arr = list(t)
t_arr.sort()
for i in range(len(t_arr)-1):
if t_arr[i]!=s_arr[i]:
return t_arr[i]
return t_arr[len(t_arr)-1] | find-the-difference | Python easy solution | dyussenovaanel | 0 | 7 | find the difference | 389 | 0.603 | Easy | 6,736 |
https://leetcode.com/problems/find-the-difference/discuss/2693125/easy-solytion-using-XOR | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
KeyNo = 0
for i in s:
KeyNo ^= ord(i)
for i in t:
KeyNo ^= ord(i)
return chr(KeyNo) | find-the-difference | easy solytion using XOR | algoon2002 | 0 | 3 | find the difference | 389 | 0.603 | Easy | 6,737 |
https://leetcode.com/problems/find-the-difference/discuss/2690706/PYTHON3-FASTEST | class Solution:
def findTheDifference(self, s: str, t: str) -> str:
for i in t:
if s.count(i)!=t.count(i):
return i | find-the-difference | PYTHON3 FASTEST | Gurugubelli_Anil | 0 | 2 | find the difference | 389 | 0.603 | Easy | 6,738 |
https://leetcode.com/problems/elimination-game/discuss/824126/Python3-3-line-O(logN) | class Solution:
def lastRemaining(self, n: int) -> int:
if n == 1: return 1
if n&1: n -= 1
return n + 2 - 2*self.lastRemaining(n//2) | elimination-game | [Python3] 3-line O(logN) | ye15 | 5 | 588 | elimination game | 390 | 0.465 | Medium | 6,739 |
https://leetcode.com/problems/elimination-game/discuss/824126/Python3-3-line-O(logN) | class Solution:
def lastRemaining(self, n: int) -> int:
def fn(n):
"""Return the final number of a list of length n."""
if n == 1: return 1
if n&1: n -= 1
return n + 2*(1 - fn(n//2))
return fn(n) | elimination-game | [Python3] 3-line O(logN) | ye15 | 5 | 588 | elimination game | 390 | 0.465 | Medium | 6,740 |
https://leetcode.com/problems/elimination-game/discuss/824126/Python3-3-line-O(logN) | class Solution:
def lastRemaining(self, n: int) -> int:
i, di = 0, 2
for _ in range(n-1):
if not 0 <= i+di < n:
i += di//2 if 0 <= i + di//2 < n else -di//2
di *= -2
else: i += di
return i+1 | elimination-game | [Python3] 3-line O(logN) | ye15 | 5 | 588 | elimination game | 390 | 0.465 | Medium | 6,741 |
https://leetcode.com/problems/elimination-game/discuss/1016735/Python3-O(logN)-and-constant-space | class Solution:
def lastRemaining(self, n: int) -> int:
first=1
distance=1
step=0
while n>1:
if step%2==0 or n%2!=0:
first+=distance
# Multiply distance by 2
distance=distance<<1
step+=1
# Divide n by 2
n=n>>1
... | elimination-game | Python3 O(logN) and constant space | bindhushreehr | 1 | 492 | elimination game | 390 | 0.465 | Medium | 6,742 |
https://leetcode.com/problems/elimination-game/discuss/2733788/Detail-1-line-python-explanations | class Solution:
def lastRemaining(self, n: int) -> int:
# explanation
# F algorithem is take the even index element from the list and reverse the list
# lastRemaining(9) = F([1, 2, 3, 4, 5, 6, 7, 8, 9])
# first round: F([2, 4, 6, 8]) = F(2 * [1, 2, 3, 4]) = 2 * F([4, 3, 2, 1])
... | elimination-game | Detail 1-line python explanations | jackson-cmd | 0 | 24 | elimination game | 390 | 0.465 | Medium | 6,743 |
https://leetcode.com/problems/elimination-game/discuss/2723369/Simple-recursive-solution-(beat-95-TC-beat-97-SC) | class Solution:
def lastRemaining(self, n: int) -> int:
if n < 3:
return n
if n % 2 == 1:
return self.lastRemaining(n-1)
elif n % 4 == 2:
return 4 * self.lastRemaining((n-2)//4)
else:
return 4 * self.lastRemaining(n//4) - 2 | elimination-game | Simple recursive solution (beat 95% TC, beat 97% SC) | zhaoqiang | 0 | 22 | elimination game | 390 | 0.465 | Medium | 6,744 |
https://leetcode.com/problems/elimination-game/discuss/2642590/python3 | class Solution:
def lastRemaining(self, n: int) -> int:
ans = 1
k, cnt, step = 0, n, 1
while cnt > 1:
if k % 2 == 0:
ans += step
else:
if cnt % 2:
ans += step
k += 1
cnt >>= 1
step... | elimination-game | python3 | xy01 | 0 | 134 | elimination game | 390 | 0.465 | Medium | 6,745 |
https://leetcode.com/problems/elimination-game/discuss/2316855/C%2B%2B-solution | class Solution:
def lastRemaining(self, n: int) -> int:
beg = 1
len = n
d = 1
fromleft = True
while len > 1:
if(fromleft or len%2 == 1):
beg += d
d <<= 1
len >>= 1
fromleft = not fromleft
return... | elimination-game | C++ solution | 487o | 0 | 192 | elimination game | 390 | 0.465 | Medium | 6,746 |
https://leetcode.com/problems/elimination-game/discuss/514388/Python3-different-simple-solutions | class Solution:
def lastRemaining(self, n: int) -> int:
return 1 if n==1 else 2*(1+n//2-self.lastRemaining(n//2))
def lastRemaining1(self, n: int) -> int:
""""
removing from left to right [1 2 3 4 5 6 7 8 9]==[2 4 6 8]==2*[1 2 3 4]
"""
def helper(n,is_left):
... | elimination-game | Python3 different simple solutions | jb07 | 0 | 379 | elimination game | 390 | 0.465 | Medium | 6,747 |
https://leetcode.com/problems/perfect-rectangle/discuss/968076/Python-Fast-and-clear-solution-with-explanation | class Solution:
def isRectangleCover(self, rectangles: List[List[int]]) -> bool:
area = 0
corners = set()
a = lambda: (Y-y) * (X-x)
for x, y, X, Y in rectangles:
area += a()
corners ^= {(x,y), (x,Y), (X,y), (X,Y)}
if len(corners) != ... | perfect-rectangle | [Python] Fast and clear solution with explanation | modusV | 40 | 1,200 | perfect rectangle | 391 | 0.325 | Hard | 6,748 |
https://leetcode.com/problems/perfect-rectangle/discuss/2666778/Python-soluton | class Solution:
def isRectangleCover(self, rectangles: List[List[int]]) -> bool:
xs=[]
ys=[]
for sx,sy,ex,ey in rectangles:
xs.append(sx)
xs.append(ex)
ys.append(sy)
ys.append(ey)
xlookup={x:i for i,x ... | perfect-rectangle | Python soluton | Motaharozzaman1996 | 0 | 8 | perfect rectangle | 391 | 0.325 | Hard | 6,749 |
https://leetcode.com/problems/perfect-rectangle/discuss/2629231/Straightforward-Python-Solution | class Solution:
def isRectangleCover(self, rectangles: List[List[int]]) -> bool:
X1, Y1 = float('inf'), float('inf')
X2, Y2 = float('-inf'), float('-inf')
# keeps track of the vertices that appear 1 or 3 times and eliminates those appearing 2 or 4 times
points = set()
... | perfect-rectangle | Straightforward Python Solution | leqinancy | 0 | 14 | perfect rectangle | 391 | 0.325 | Hard | 6,750 |
https://leetcode.com/problems/perfect-rectangle/discuss/1102039/Python3-locate-the-corners | class Solution:
def isRectangleCover(self, rectangles: List[List[int]]) -> bool:
area = 0
corner = set()
X0 = Y0 = inf
X1 = Y1 = -inf
for x0, y0, x1, y1 in rectangles:
area += (x1-x0)*(y1-y0)
X0 = min(x0, X0)
Y0 = min(y0, Y0)
X... | perfect-rectangle | [Python3] locate the corners | ye15 | 0 | 280 | perfect rectangle | 391 | 0.325 | Hard | 6,751 |
https://leetcode.com/problems/is-subsequence/discuss/2473010/Very-Easy-oror-100-oror-Fully-Explained-oror-Java-C%2B%2B-Python-JS-C-Python3-(Two-Pointers-Approach) | class Solution(object):
def isSubsequence(self, s, t):
# Base case
if not s:
return True
i = 0
# Traverse elements of t string
for j in t:
# If this index matches to the index of s string, increment i pointer...
if j == s[i]:
... | is-subsequence | Very Easy || 100% || Fully Explained || Java, C++, Python, JS, C, Python3 (Two-Pointers Approach) | PratikSen07 | 16 | 998 | is subsequence | 392 | 0.49 | Easy | 6,752 |
https://leetcode.com/problems/is-subsequence/discuss/1811624/Simple-2-Pointer-Python-Solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i, j, n, m = 0, 0, len(s), len(t)
while i < n and j < m: # Loop till any of the strings is fully traversed
if s[i] == t[j]: # If char at i and j are equal then update i
i += 1
# Could also write i += s[i]==t[j]
j... | is-subsequence | Simple 2 Pointer Python Solution | anCoderr | 10 | 831 | is subsequence | 392 | 0.49 | Easy | 6,753 |
https://leetcode.com/problems/is-subsequence/discuss/2679763/Python-Easy-Solution-or-99-Faster-or-Is-Subsequence | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
sl, tl = 0, 0
while sl<len(s) and tl<len(t):
if s[sl] == t[tl]:
sl+=1
tl+=1
else:
tl+=1
if sl==len(s):
return True
else:
... | is-subsequence | ✔️ Python Easy Solution | 99% Faster | Is Subsequence | pniraj657 | 9 | 745 | is subsequence | 392 | 0.49 | Easy | 6,754 |
https://leetcode.com/problems/is-subsequence/discuss/1077869/Python.-faster-than-99.45.-Easy-understanding-solution. | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i, j, m, n = 0, 0, len(s), len(t)
while i < m and j < n and n - j >= m - i:
if s[i] == t[j]:
i += 1
j += 1
return i == m | is-subsequence | Python. faster than 99.45%. Easy-understanding solution. | m-d-f | 5 | 736 | is subsequence | 392 | 0.49 | Easy | 6,755 |
https://leetcode.com/problems/is-subsequence/discuss/423566/Python3-4-solutions-(quickest-99.98-shortest-two-lines) | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
it = iter(t)
return all(ch in it for ch in s) | is-subsequence | [Python3] 4 solutions (quickest 99.98%, shortest two lines) | ye15 | 5 | 422 | is subsequence | 392 | 0.49 | Easy | 6,756 |
https://leetcode.com/problems/is-subsequence/discuss/423566/Python3-4-solutions-(quickest-99.98-shortest-two-lines) | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
k = 0
for c in s:
k = t.find(c, k) + 1
if k == 0: return False
return True | is-subsequence | [Python3] 4 solutions (quickest 99.98%, shortest two lines) | ye15 | 5 | 422 | is subsequence | 392 | 0.49 | Easy | 6,757 |
https://leetcode.com/problems/is-subsequence/discuss/423566/Python3-4-solutions-(quickest-99.98-shortest-two-lines) | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
k = 0
for c in s:
try: k = t.index(c, k) + 1
except: return False
return True | is-subsequence | [Python3] 4 solutions (quickest 99.98%, shortest two lines) | ye15 | 5 | 422 | is subsequence | 392 | 0.49 | Easy | 6,758 |
https://leetcode.com/problems/is-subsequence/discuss/423566/Python3-4-solutions-(quickest-99.98-shortest-two-lines) | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i = 0
for c in t:
if i < len(s) and s[i] == c: i += 1
return i == len(s) | is-subsequence | [Python3] 4 solutions (quickest 99.98%, shortest two lines) | ye15 | 5 | 422 | is subsequence | 392 | 0.49 | Easy | 6,759 |
https://leetcode.com/problems/is-subsequence/discuss/2126747/Python-or-One-of-the-most-elegant-solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
for char in t:
if len(s) > 0 and char == s[0]:
s = s[1:]
return len(s) == 0 | is-subsequence | Python | One of the most elegant solution | __Asrar | 3 | 96 | is subsequence | 392 | 0.49 | Easy | 6,760 |
https://leetcode.com/problems/is-subsequence/discuss/1811501/Pythonic-O(n)-Iterative-Solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i,j=0,0
while(j<len(s) and i<len(t)):
if(s[j]==t[i]):
j+=1
i+=1
return j==len(s) | is-subsequence | Pythonic O(n) Iterative Solution | js5809 | 3 | 134 | is subsequence | 392 | 0.49 | Easy | 6,761 |
https://leetcode.com/problems/is-subsequence/discuss/1197645/Python-DP-Standard-Solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
n = len(s)
m = len(t)
if n==0:
return True
if m==0:
return False
dp = [[0 for _ in range(n+1)] for _ in range(m+1)]
for i in range(1,m+1):
for j in r... | is-subsequence | Python DP Standard Solution | iamkshitij77 | 3 | 136 | is subsequence | 392 | 0.49 | Easy | 6,762 |
https://leetcode.com/problems/is-subsequence/discuss/380060/Solution-in-Python-3-(beats-~100)-(five-lines) | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
I = -1
for i in s:
I = t.find(i,I+1)
if I == -1: return False
return True
- Junaid Mansuri
(LeetCode ID)@hotmail.com | is-subsequence | Solution in Python 3 (beats ~100%) (five lines) | junaidmansuri | 3 | 672 | is subsequence | 392 | 0.49 | Easy | 6,763 |
https://leetcode.com/problems/is-subsequence/discuss/2770032/The-most-readable-solution-in-Python-for-%22392.-Is-subsequence%22 | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
n = len(s)
j = 0
for letter in t:
if j == n:
return True
if letter == s[j]:
j += 1
return j == n | is-subsequence | The most readable solution in Python for "392. Is subsequence" | bekbull | 2 | 169 | is subsequence | 392 | 0.49 | Easy | 6,764 |
https://leetcode.com/problems/is-subsequence/discuss/1813856/Python3-oror-Linear-Solution-oror-Almost-100-Faster | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s) > len(t): return False
j = 0
for i in t:
if j < len(s):
if i == s[j]:
j += 1
return True if j == len(s) else False | is-subsequence | Python3 || Linear Solution || Almost 100% Faster | cherrysri1997 | 2 | 83 | is subsequence | 392 | 0.49 | Easy | 6,765 |
https://leetcode.com/problems/is-subsequence/discuss/1811282/Python-Simple-Python-Solution-With-Two-Pointers | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i=0
j=0
while i<len(s) and j<len(t):
if s[i]==t[j]:
i=i+1
j=j+1
else:
j=j+1
if i==len(s):
return True
else:
return False | is-subsequence | [ Python ] ✔✔ Simple Python Solution With Two Pointers 🔥✌ | ASHOK_KUMAR_MEGHVANSHI | 2 | 183 | is subsequence | 392 | 0.49 | Easy | 6,766 |
https://leetcode.com/problems/is-subsequence/discuss/1496681/Difference-between-Subarray-or-Subsequence-or-Subset-oror-Beginner-Approach | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
# A very intuitive way to check if one is a subsequence of other or not
# Here, We will check if s is a subsequence of t or not
i=0 #to keep a check of elements across s
j=0 #to keep a check o... | is-subsequence | Difference between Subarray | Subsequence | Subset || Beginner Approach | aarushsharmaa | 2 | 126 | is subsequence | 392 | 0.49 | Easy | 6,767 |
https://leetcode.com/problems/is-subsequence/discuss/2573596/SIMPLE-PYTHON3-SOLUTION-O(t) | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s)==0:return True
count = 0
for i in range(len(t)):
if count <= len(s) - 1:
if s[count] == t[i]:
count += 1
return count == len(s) | is-subsequence | ✅✔ SIMPLE PYTHON3 SOLUTION ✅✔O(t) | rajukommula | 1 | 67 | is subsequence | 392 | 0.49 | Easy | 6,768 |
https://leetcode.com/problems/is-subsequence/discuss/2483813/Runtime%3A-56-ms-faster-than-38.48-of-Python3-Memory-Usage%3A-13.9-MB-less-than-43.43-of-Python3 | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
for i in range(0,len(t)):
if len(s)==0:
return True
elif t[i]==s[0]:
s=s[1:]
return len(s)==0 | is-subsequence | Runtime: 56 ms, faster than 38.48% of Python3 ,Memory Usage: 13.9 MB, less than 43.43% of Python3 | DG-Problemsolver | 1 | 6 | is subsequence | 392 | 0.49 | Easy | 6,769 |
https://leetcode.com/problems/is-subsequence/discuss/2327519/Python3-O(n%2Bm)-oror-O(1)-Runtime%3A-38ms-83.94-oror-memory%3A-13.8mb-82.20 | class Solution:
# O(n+m) || O(1)
# Runtime: 38ms 83.94% || memory: 13.8mb 82.20%
def isSubsequence(self, string: str, target: str) -> bool:
i = 0
for char in target:
if i == len(string):
return True
if char == string[i]:
i += 1
... | is-subsequence | Python3 O(n+m) || O(1) # Runtime: 38ms 83.94% || memory: 13.8mb 82.20% | arshergon | 1 | 36 | is subsequence | 392 | 0.49 | Easy | 6,770 |
https://leetcode.com/problems/is-subsequence/discuss/2279444/Python3-two-pointers-approach | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
first = 0
second = 0
while first<len(s) and second<len(t):
if s[first]==t[second]:
first+=1
second+=1
return first>=len(s) | is-subsequence | 📌 Python3 two pointers approach | Dark_wolf_jss | 1 | 32 | is subsequence | 392 | 0.49 | Easy | 6,771 |
https://leetcode.com/problems/is-subsequence/discuss/1930728/Two-Pointer-Approach | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
# initialize pointers
pointer_1, pointer_2 = 0, 0
# to ensure pointers traverse till the end of both strings
while pointer_1 < len(s) and pointer_2 <len(t):
# if both the pointers are pointing to sa... | is-subsequence | Two Pointer Approach | Jayesh_Suryavanshi | 1 | 43 | is subsequence | 392 | 0.49 | Easy | 6,772 |
https://leetcode.com/problems/is-subsequence/discuss/1847339/Python-easy-solution-beats-96 | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
left, right = 0, 0
while left != len(s) and right != len(t) :
if s[left] != t[right]:
right += 1
elif s[left] == t[right]:
left += 1
right += 1
if left == ... | is-subsequence | Python easy solution beats 96% | yusianglin11010 | 1 | 101 | is subsequence | 392 | 0.49 | Easy | 6,773 |
https://leetcode.com/problems/is-subsequence/discuss/1813489/Python-Queue-Solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s) == 0: return True
q = [c for c in s]
for c in t:
if q[0] == c:
q.pop(0)
if len(q) == 0:
return True
return False | is-subsequence | Python Queue Solution | Pootato | 1 | 20 | is subsequence | 392 | 0.49 | Easy | 6,774 |
https://leetcode.com/problems/is-subsequence/discuss/1811595/Self-understandable-Python-%3A | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s)>len(t):
return False
if len(s)==0:
return True
j=0
p=""
for i in t:
if i==s[j]:
p+=i
j+=1
if j>=len(s):
b... | is-subsequence | Self understandable Python : | goxy_coder | 1 | 81 | is subsequence | 392 | 0.49 | Easy | 6,775 |
https://leetcode.com/problems/is-subsequence/discuss/1370625/2-pointer-solution-or-Python | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i,j = 0,0
if(len(s)>len(t)):
return False
while( i<len(s) and j<len(t) ):
if(s[i] == t[j]):
i+=1
j+=1
else:
j+=1
if(i == len(s)):
... | is-subsequence | 2 pointer solution | Python | RishithaRamesh | 1 | 74 | is subsequence | 392 | 0.49 | Easy | 6,776 |
https://leetcode.com/problems/is-subsequence/discuss/1079112/Python-solution-using-while-and-for-loop. | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s) > len(t): return False
i, j = 0, 0
while i < len(s) and j < len(t):
if s[i] == t[j]:
i += 1
j += 1
if len(s) == i:
return True
return False | is-subsequence | Python solution using while and for loop. | vsahoo | 1 | 80 | is subsequence | 392 | 0.49 | Easy | 6,777 |
https://leetcode.com/problems/is-subsequence/discuss/679493/python-two-pointers-and-NlogN-follow-up-by-binary-search | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i = j = 0
while i < len(s) and j < len(t):
if s[i] == t[j]:
i+=1
j+=1
else:
j+=1
return i == len(s) | is-subsequence | python two pointers and NlogN follow-up by binary search | nightybear | 1 | 86 | is subsequence | 392 | 0.49 | Easy | 6,778 |
https://leetcode.com/problems/is-subsequence/discuss/679493/python-two-pointers-and-NlogN-follow-up-by-binary-search | class Solution:
'''
Time complexity : O(nlogn)
Space complexity : O(n)
'''
def isSubsequence(self, s: str, t: str) -> bool:
indexs = collections.defaultdict(list)
for idx, x in enumerate(t):
indexs[x].append(idx)
prev = 0
for x in s:
i... | is-subsequence | python two pointers and NlogN follow-up by binary search | nightybear | 1 | 86 | is subsequence | 392 | 0.49 | Easy | 6,779 |
https://leetcode.com/problems/is-subsequence/discuss/2848574/python3 | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
idx = 0
for c in s:
idx = t.find(c, idx)
if idx == -1:
return False
idx += 1
return True | is-subsequence | python3 | wduf | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,780 |
https://leetcode.com/problems/is-subsequence/discuss/2846740/Easy-understand-python-solution-(beginer-friendly) | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
count=0
if not s :
return True
if not t:
return False
for ele in t:
if ele==s[count]:
count+=1
if count==len(s):
return True
return... | is-subsequence | Easy understand python solution (beginer friendly) | amangarg0599 | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,781 |
https://leetcode.com/problems/is-subsequence/discuss/2838020/Python3-solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
position = -1
for char in s:
position = t.find(char, position + 1)
if position == -1:
return False
return True | is-subsequence | Python3 solution | arthur54342 | 0 | 3 | is subsequence | 392 | 0.49 | Easy | 6,782 |
https://leetcode.com/problems/is-subsequence/discuss/2835462/Simple-One-Pass-O(1)-space-with-two-pointers | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
p1 = p2 = 0
while p1 < len(s) and p2 < len(t):
if s[p1] == t[p2]:
p1 += 1
p2 += 1
return p1 == len(s) | is-subsequence | Simple One Pass O(1) space with two pointers | WhyYouCryingMama | 0 | 2 | is subsequence | 392 | 0.49 | Easy | 6,783 |
https://leetcode.com/problems/is-subsequence/discuss/2835461/Simple-One-Pass-O(1)-space-with-two-pointers | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
p1 = p2 = 0
while p1 < len(s) and p2 < len(t):
if s[p1] == t[p2]:
p1 += 1
p2 += 1
return p1 == len(s) | is-subsequence | Simple One Pass O(1) space with two pointers | WhyYouCryingMama | 0 | 0 | is subsequence | 392 | 0.49 | Easy | 6,784 |
https://leetcode.com/problems/is-subsequence/discuss/2835150/Python3-Simple-Clean-Code | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
for i in range(len(s)):
findIndex = t.find(s[i]) if s[i] in t else -1
if findIndex == -1: return False
t = t[findIndex+1:]
return True | is-subsequence | ✅ Python3 Simple Clean Code | Cecilia_GuoChen | 0 | 3 | is subsequence | 392 | 0.49 | Easy | 6,785 |
https://leetcode.com/problems/is-subsequence/discuss/2835046/My-python-solution-or-beats-90 | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
for e in s:
if e not in t:
return False
i = 0
j = 0
while j < len(t):
if i <len(s) and s[i] ==t[j]:
i+=1
j+=1
return i == len(s) | is-subsequence | My python solution | beats 90% | sahil193101 | 0 | 4 | is subsequence | 392 | 0.49 | Easy | 6,786 |
https://leetcode.com/problems/is-subsequence/discuss/2829435/Python-or-Two-Pointer-or-Merge-two-array-way | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if not s:
return True
if len(s) > len(t):
return False
end = len(t)-1
first_end = len(s)-1
t_start = 0
s_start = 0
while t_start <= end and s_start <= first_end:
... | is-subsequence | Python | Two Pointer | Merge two array way | ajay_gc | 0 | 5 | is subsequence | 392 | 0.49 | Easy | 6,787 |
https://leetcode.com/problems/is-subsequence/discuss/2828195/Two-Pointers-easy | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i=0
j=0
if len(s)>len(t) or (len(t)==0 and len(s)!=0):
return False
if len(s)==0:
return True
for i in range(len(t)):
if s[j]==t[i]:
j+=1
if j==len... | is-subsequence | Two Pointers easy | rhi_1 | 0 | 2 | is subsequence | 392 | 0.49 | Easy | 6,788 |
https://leetcode.com/problems/is-subsequence/discuss/2819037/Python-My-O(n)-Solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if not s:
return True
if not t:
return False
s_pointer = 0
for t_char in t:
if t_char == s[s_pointer]:
s_pointer += 1
if s_pointer == len(s):
... | is-subsequence | [Python] My O(n) Solution | manytenks | 0 | 3 | is subsequence | 392 | 0.49 | Easy | 6,789 |
https://leetcode.com/problems/is-subsequence/discuss/2818144/two-pointer-and-some-conclutions | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s) < 1:return True
if len(s) > len(t):return False
s_pointer = 0
for t_pointer in range(0,len(t)):
if s_pointer <= len(s)-1:
if s[s_pointer]==t[t_pointer]:s_pointer += 1
return... | is-subsequence | two pointer and some conclutions | roger880327 | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,790 |
https://leetcode.com/problems/is-subsequence/discuss/2818113/using-two-pointers | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s) < 1:return True
s_pointer = 0
for t_pointer in range(0,len(t)):
if s_pointer < len(s):
if s[s_pointer]==t[t_pointer]:s_pointer += 1
if s_pointer == 0:return False
return s_p... | is-subsequence | using two pointers | roger880327 | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,791 |
https://leetcode.com/problems/is-subsequence/discuss/2816077/Python-o(n)-solution-simple-to-understand | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
i = 0
for c in s:
while i < len(t) and t[i] != c:
i+= 1
if i == len(t): return False
i+=1
return True | is-subsequence | Python o(n) solution, simple to understand | pradyumna04 | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,792 |
https://leetcode.com/problems/is-subsequence/discuss/2807838/easy-understnding-python | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
counter = 0
for c in s:
if c in t:
t = t[t.index(c) + 1:]
counter += 1
if len(s) == counter:
return True
return False | is-subsequence | easy understnding python | don_masih | 0 | 2 | is subsequence | 392 | 0.49 | Easy | 6,793 |
https://leetcode.com/problems/is-subsequence/discuss/2799242/Subsequence-My-Solution | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(s) == 0:
return True
si, ti = 0,0
for ti in range(len(t)):
if s[si] == t[ti]:
si += 1
if si == len(s):
return True
return False | is-subsequence | Subsequence - My Solution | marked01one | 0 | 2 | is subsequence | 392 | 0.49 | Easy | 6,794 |
https://leetcode.com/problems/is-subsequence/discuss/2796564/Is-Substring-Python-easy-to-understand-beginner-friendly-comments | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
"""
Using a 2-pointer approach, compare two strings and determines if the first string is a subset of the second string.
:param s:
str: String of alpha characters
:param t:
str: String of alpha ... | is-subsequence | Is Substring - Python, easy-to-understand, beginner friendly, comments | mthomp89 | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,795 |
https://leetcode.com/problems/is-subsequence/discuss/2790867/Simple-solution-using-exception-to-catch-completed-substring | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
# Make an iterator of the sub string
s_iter = iter(s)
try:
# Start by taking the first character in the substring
sub = next(s_iter)
for curr in t:
if curr == sub:
... | is-subsequence | Simple solution using exception to catch completed substring | stereo1 | 0 | 2 | is subsequence | 392 | 0.49 | Easy | 6,796 |
https://leetcode.com/problems/is-subsequence/discuss/2786048/Easy-python-solution-or-Is-Subsequence | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(t) < len(s):
return False
for i in range(len(t)):
if len(s) > 0 and t[i] == s[0]:
s = s[1:]
if len(s) == 0:
return True
return False | is-subsequence | Easy python solution | Is Subsequence | nishanrahman1994 | 0 | 2 | is subsequence | 392 | 0.49 | Easy | 6,797 |
https://leetcode.com/problems/is-subsequence/discuss/2786047/Easy-python-solution-or-Is-Subsequence | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
if len(t) < len(s):
return False
for i in range(len(t)):
if len(s) > 0 and t[i] == s[0]:
s = s[1:]
if len(s) == 0:
return True
return False | is-subsequence | Easy python solution | Is Subsequence | nishanrahman1994 | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,798 |
https://leetcode.com/problems/is-subsequence/discuss/2784933/Pretty-happy-i-managed-to-get-a-pretty-good-solution-on-my-own-for-once. | class Solution:
def isSubsequence(self, s: str, t: str) -> bool:
len_s = len(s)
if len_s == 0: return True
i: int = 0
for char in t:
if s[i] == char:
i += 1
if i == len_s: return True
return False | is-subsequence | Pretty happy i managed to get a pretty good solution on my own for once. | Seawolf159 | 0 | 1 | is subsequence | 392 | 0.49 | Easy | 6,799 |
Subsets and Splits
Top 2 Solutions by Upvotes
Identifies the top 2 highest upvoted Python solutions for each problem, providing insight into popular approaches.