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01619f48d2cac0c487dde6f72f1319a6fceb22b96a2e4ba8c35f45c6a559e831
Let f be a function defined as f : R → R, and f(x) = x^3 + ax + b. What is the maximum number of zeroes that f can have?
dolphin-r1
midtrain
empty_ground_truth
{}
{}
{"candidates":[],"contamination_source_id":null,"contamination_source_set":null,"embedding_model":"Qwen3-Embedding-4B","llm_judge_model":"gpt-oss-20b","similarity_threshold":null,"status":"clean","top_k":20}
{}
[{"created_at":"2026-03-19T03:25:05.784109+00:00","details":{"normalize_punctuation":true,"normalized":false},"processor":"text_normalize","reason_code":"","stage":"clean","status":"kept"},{"created_at":"2026-03-19T03:25:05.784253+00:00","details":{"wrapper_stripped":false},"processor":"instruction_wrapper_cleaner","re...
018e9d9889508ed5bdbf7093ce3790a23bb01a3cf68e5eba5e5b390acdbf70c2
A local historian is organizing a public lecture series on historical events and has a list of 10 potential guest speakers, each specializing in a unique era. The historian wants to arrange the lectures in such a way that each speaker delivers exactly one lecture. 1. Given that the historian wants to schedule 5 lectur...
dolphin-r1
midtrain
empty_ground_truth
{}
{}
{"candidates":[],"contamination_source_id":null,"contamination_source_set":null,"embedding_model":"Qwen3-Embedding-4B","llm_judge_model":"gpt-oss-20b","similarity_threshold":null,"status":"clean","top_k":20}
{}
[{"created_at":"2026-03-19T03:25:10.878690+00:00","details":{"normalize_punctuation":true,"normalized":true},"processor":"text_normalize","reason_code":"","stage":"clean","status":"kept"},{"created_at":"2026-03-19T03:25:10.879511+00:00","details":{"wrapper_stripped":false},"processor":"instruction_wrapper_cleaner","rea...
01b9563f1f61aba9d7035dc3a3c2e95ee8231ec4a7a8ba631c6650f7e0855b76
Determine whether the following statement is true or false: If $M/N$ and $N/K$ are both normal field extensions, then all the $K$-embeddings of $N$ into an algebraic closure of $K$ can be prolonged to $M$.
True
DeepMath-103K
midtrain
boolean_and_mcq
{}
{}
{"candidates":[],"contamination_source_id":null,"contamination_source_set":null,"embedding_model":"Qwen3-Embedding-4B","llm_judge_model":"gpt-oss-20b","similarity_threshold":null,"status":"clean","top_k":20}
{}
[{"created_at":"2026-03-19T03:16:11.862873+00:00","details":{"normalize_punctuation":true,"normalized":false},"processor":"text_normalize","reason_code":"","stage":"clean","status":"kept"},{"created_at":"2026-03-19T03:16:11.863069+00:00","details":{"wrapper_stripped":false},"processor":"instruction_wrapper_cleaner","re...
01c77ecaa91d38bcd5b6d32e13c11e2a3245d4c740a421d499cddeec6e6cef69
Consider the ring homomorphism $\phi: \mathbb{R}[x] \to \mathbb{C}$ defined by $\phi(f(x)) = f(i\sqrt{5})$ for any polynomial $f(x) \in \mathbb{R}[x]$. Determine the kernel of $\phi$ and use it to find the number of elements in the quotient ring $\mathbb{R}[x]/\ker(\phi)$.
\infty
OpenMathReasoning
midtrain
gt_unclear
{"fallback_model":null,"llm_judge_attempts":1,"llm_judge_equivalence":"not_applicable","llm_judge_gt_quality":"unclear","llm_judge_majority_answer":"|\\mathbb R[x]/\\ker\\phi|=|\\mathbb C|=2^{\\aleph_{0}}","llm_judge_majority_count":8,"llm_judge_model":"gpt-oss-120b","llm_judge_raw_response":"{\"majority_answer\": \"|\...
{}
{"candidates":[],"contamination_source_id":null,"contamination_source_set":null,"embedding_model":"Qwen3-Embedding-4B","llm_judge_model":"gpt-oss-20b","similarity_threshold":null,"status":"clean","top_k":20}
{}
[{"created_at":"2026-03-19T03:17:30.444664+00:00","details":{"normalize_punctuation":true,"normalized":false},"processor":"text_normalize","reason_code":"","stage":"clean","status":"kept"},{"created_at":"2026-03-19T03:17:30.444920+00:00","details":{"wrapper_stripped":false},"processor":"instruction_wrapper_cleaner","re...
01cb5e308286a14be36472b09bce52257ef63054bcc47f5a57433b132e709a22
Samantha finds 15 red marbles, 25 blue marbles, and some white marbles in a box. If the blue marbles make up 40% of the total marbles, how many white marbles did Samantha find?
22
Llama-Nemotron-Post-Training-math-math_v1
midtrain
answer_mismatch
{"fallback_model":null,"llm_judge_attempts":1,"llm_judge_equivalence":"not_equivalent","llm_judge_gt_quality":"clear","llm_judge_majority_answer":"22.5","llm_judge_majority_count":8,"llm_judge_model":"gpt-oss-120b","llm_judge_raw_response":"{\"majority_answer\": \"22.5\", \"majority_count\": 8, \"gt_quality\": \"clear\...
{}
{"candidates":[],"contamination_source_id":null,"contamination_source_set":null,"embedding_model":"Qwen3-Embedding-4B","llm_judge_model":"gpt-oss-20b","similarity_threshold":null,"status":"clean","top_k":20}
{}
[{"created_at":"2026-03-19T03:17:31.160294+00:00","details":{"normalize_punctuation":true,"normalized":false},"processor":"text_normalize","reason_code":"","stage":"clean","status":"kept"},{"created_at":"2026-03-19T03:17:31.160663+00:00","details":{"cleaned_length":176,"original_length":274,"wrapper_stripped":true},"pr...
0223744a0a484b7b458c045e02d13056cf45b45720f65b7284fd46d9789989ed
找出最小的正整数 \( c \),使得二次方程 \( x^2 + bx + c = 0 \) 有两个不同的实根,其中 \( b \) 是一个整数,并且二次方程的判别式是一个完全平方数。
2
Ring-lite-sft
midtrain
chinese
{}
{}
{"candidates":[],"contamination_source_id":null,"contamination_source_set":null,"embedding_model":"Qwen3-Embedding-4B","llm_judge_model":"gpt-oss-20b","similarity_threshold":null,"status":"clean","top_k":20}
{}
[{"created_at":"2026-03-19T03:25:33.713687+00:00","details":{"normalize_punctuation":true,"normalized":true},"processor":"text_normalize","reason_code":"","stage":"clean","status":"kept"},{"created_at":"2026-03-19T03:25:33.713797+00:00","details":{"wrapper_stripped":false},"processor":"instruction_wrapper_cleaner","rea...
025f80222380b6fb20b6ac0c54d5b169a300e66d005f4cc98031953bf05a1b9f
Use the method of separation of variables to solve the one-dimensional wave equation with homogeneous Dirichlet boundary conditions\n\n\[\n\frac{\partial^2 u}{\partial t^2} = \frac{1}{\pi^2} \frac{\partial^2 u}{\partial x^2}, \quad 0 < x < 1, \quad t > 0,\n\]\n\n\[\nu(0, t) = 0,\n\]\n\n\[\nu(1, t) = 0,\n\]\n\n\[\nu(x, ...
\frac{1}{2} \cos(2t) \sin(2\pi x)
Ring-lite-sft
midtrain
non_verifiable_answer
{}
{}
{"candidates":[],"contamination_source_id":null,"contamination_source_set":null,"embedding_model":"Qwen3-Embedding-4B","llm_judge_model":"gpt-oss-20b","similarity_threshold":null,"status":"clean","top_k":20}
{}
[{"created_at":"2026-03-19T03:25:42.247699+00:00","details":{"normalize_punctuation":true,"normalized":false},"processor":"text_normalize","reason_code":"","stage":"clean","status":"kept"},{"created_at":"2026-03-19T03:25:42.248068+00:00","details":{"wrapper_stripped":false},"processor":"instruction_wrapper_cleaner","re...
02728fb8101ce3bff2659eff06e35b55d236d69afc22d7dac1c91c087bd3d588
"Emma earns $8 per week as an allowance. After saving all her money for five weeks, she spends one-t(...TRUNCATED)
13.33
Llama-Nemotron-Post-Training-math-math_v1
midtrain
answer_mismatch
"{\"fallback_model\":null,\"llm_judge_attempts\":1,\"llm_judge_equivalence\":\"not_equivalent\",\"ll(...TRUNCATED)
{}
"{\"candidates\":[],\"contamination_source_id\":null,\"contamination_source_set\":null,\"embedding_m(...TRUNCATED)
{}
"[{\"created_at\":\"2026-03-19T03:18:02.030804+00:00\",\"details\":{\"normalize_punctuation\":true,\(...TRUNCATED)
02a557b13593b39a49eed6ebbd93ded582dbcb223084b073e8891e9c21d13933
"Given a permutation $a_1, a_2, \\dots, a_n$ of integers from $1$ to $n$, and a threshold $k$ with $(...TRUNCATED)
Ring-lite-sft
midtrain
empty_ground_truth
{}
{}
"{\"candidates\":[],\"contamination_source_id\":null,\"contamination_source_set\":null,\"embedding_m(...TRUNCATED)
{}
"[{\"created_at\":\"2026-03-19T03:25:50.030406+00:00\",\"details\":{\"normalize_punctuation\":true,\(...TRUNCATED)
036df2aa4c5220594a5a928ae96090dc4ed0e33d27cb4ac61511a1ae68ad370a
"Around a round table, people $P_1, P_2, \\ldots, P_{2013}$ are seated in a clockwise order. Each pe(...TRUNCATED)
4050156
OpenMathReasoning
midtrain
answer_mismatch
"{\"fallback_model\":null,\"llm_judge_attempts\":1,\"llm_judge_equivalence\":\"not_equivalent\",\"ll(...TRUNCATED)
{}
"{\"candidates\":[],\"contamination_source_id\":null,\"contamination_source_set\":null,\"embedding_m(...TRUNCATED)
{}
"[{\"created_at\":\"2026-03-19T03:16:35.773707+00:00\",\"details\":{\"normalize_punctuation\":true,\(...TRUNCATED)
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