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reward_model
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dict
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\frac{\\lfloor \\sqrt{1} \\rfloor \\cdot \\lfloor \\sqrt{2} \\rfloor \\cdot \\lfloor \\sqrt{3} \\rfloor \\cdot \\lfloor \\sqrt{5} \\rfloor \\dotsm \\lfloor \\sqrt{15} \\rfloor}{\\lfloor \\sqrt{2} \\rfloor \\cdot \\lfloor \\sqrt{4} \\rfloor \\cdot \\lfloor \\sqrt{6}...
math
{ "style": "rule", "ground_truth": "\\frac{3}{8}" }
{ "index": 6300, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\frac{\\tan^2 20^\\circ - \\sin^2 20^\\circ}{\\tan^2 20^\\circ \\sin^2 20^\\circ}.\\]" } ]
math
{ "style": "rule", "ground_truth": "1" }
{ "index": 6301, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\left( 1 + \\cos \\frac {\\pi}{8} \\right) \\left( 1 + \\cos \\frac {3 \\pi}{8} \\right) \\left( 1 + \\cos \\frac {5 \\pi}{8} \\right) \\left( 1 + \\cos \\frac {7 \\pi}{8} \\right).\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{1}{8}" }
{ "index": 6302, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\left( 1 - \\frac{1}{\\cos 23^\\circ} \\right) \\left( 1 + \\frac{1}{\\sin 67^\\circ} \\right) \\left( 1 - \\frac{1}{\\sin 23^\\circ} \\right) \\left( 1 + \\frac{1}{\\cos 67^\\circ} \\right).\\]" } ]
math
{ "style": "rule", "ground_truth": "1" }
{ "index": 6303, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\prod_{k = 1}^{12} \\prod_{j = 1}^{10} (e^{2 \\pi ji/11} - e^{2 \\pi ki/13}).\\]" } ]
math
{ "style": "rule", "ground_truth": "1" }
{ "index": 6304, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\prod_{n = 1}^{15} \\frac{n + 4}{n}.\\]" } ]
math
{ "style": "rule", "ground_truth": "11628" }
{ "index": 6305, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\prod_{n = 1}^{20} \\frac{n + 3}{n}.\\]" } ]
math
{ "style": "rule", "ground_truth": "1771" }
{ "index": 6306, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sin^2 4^\\circ + \\sin^2 8^\\circ + \\sin^2 12^\\circ + \\dots + \\sin^2 176^\\circ.\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{45}{2}" }
{ "index": 6307, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sin^2 6^\\circ + \\sin^2 12^\\circ + \\sin^2 18^\\circ + \\dots + \\sin^2 174^\\circ.\\]" } ]
math
{ "style": "rule", "ground_truth": "15.5" }
{ "index": 6308, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{1 \\le a < b < c} \\frac{1}{2^a 3^b 5^c}.\\](The sum is taken over all triples $(a,b,c)$ of positive integers such that $1 \\le a < b < c.$)" } ]
math
{ "style": "rule", "ground_truth": "\\frac{1}{1624}" }
{ "index": 6309, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{1 \\le a < b < c} \\frac{1}{3^a 5^b 7^c}.\\]\n(The sum is taken over all triples \\((a,b,c)\\) of positive integers such that \\(1 \\le a < b < c\\).)" } ]
math
{ "style": "rule", "ground_truth": "\\frac{1}{21216}" }
{ "index": 6310, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{j = 0}^\\infty \\sum_{k = 0}^\\infty 2^{-3k - j - (k + j)^2}.\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{4}{3}" }
{ "index": 6311, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{k = 1}^\\infty \\frac{6^k}{(3^k - 2^k)(3^{k + 1} - 2^{k + 1})}.\\]" } ]
math
{ "style": "rule", "ground_truth": "2" }
{ "index": 6312, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{n = 1}^\\infty \\frac{1}{n(n + 2)}.\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{3}{4}" }
{ "index": 6313, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{n = 1}^\\infty \\frac{2n + 1}{n(n + 1)(n + 2)}.\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{5}{4}" }
{ "index": 6314, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{n = 1}^\\infty \\frac{2n - 1}{n(n + 1)(n + 2)}.\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{3}{4}" }
{ "index": 6315, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{n = 2}^\\infty \\frac{4n^3 - n^2 - n + 1}{n^6 - n^5 + n^4 - n^3 + n^2 - n}.\\]" } ]
math
{ "style": "rule", "ground_truth": "1" }
{ "index": 6316, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[\\sum_{n = 2}^{10000} \\frac{1}{n \\sqrt{n - 1} + (n - 1) \\sqrt{n}}.\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{99}{100}" }
{ "index": 6317, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute\n\\[e^{2 \\pi i/13} + e^{4 \\pi i/13} + e^{6 \\pi i/13} + \\dots + e^{24 \\pi i/13}.\\]" } ]
math
{ "style": "rule", "ground_truth": "-1" }
{ "index": 6318, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute \n\\[\n\\sin^2 3^\\circ + \\sin^2 6^\\circ + \\sin^2 9^\\circ + \\dots + \\sin^2 177^\\circ.\n\\]" } ]
math
{ "style": "rule", "ground_truth": "30" }
{ "index": 6319, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute \n\\[\n\\sin^6 0^\\circ + \\sin^6 1^\\circ + \\sin^6 2^\\circ + \\dots + \\sin^6 90^\\circ.\n\\]" } ]
math
{ "style": "rule", "ground_truth": "\\frac{229}{8}" }
{ "index": 6320, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\left\\lceil\\displaystyle\\sum_{k=2018}^{\\infty}\\frac{2019!-2018!}{k!}\\right\\rceil$ . (The notation $\\left\\lceil x\\right\\rceil$ denotes the least integer $n$ such that $n\\geq x$ .)\n\n*Proposed by Tristan Shin*" } ]
math
{ "style": "rule", "ground_truth": "2019" }
{ "index": 6321, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $e^{\\pi}+\\pi^e$ . If your answer is $A$ and the correct answer is $C$ , then your score on this problem will be $\\frac{4}{\\pi}\\arctan\\left(\\frac{1}{\\left|C-A\\right|}\\right)$ (note that the closer you are to the right answer, the higher your score is).\n\...
math
{ "style": "rule", "ground_truth": "45.5999" }
{ "index": 6322, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $$ \\sum_{a_{1}=0}^{\\infty} \\sum_{a_{2}=0}^{\\infty} \\cdots \\sum_{a_{7}=0}^{\\infty} \\frac{a_{1}+a_{2}+\\cdots+a_{7}}{3^{a_{1}+a_{2}+\\cdots+a_{7}}} $$" } ]
math
{ "style": "rule", "ground_truth": "15309 / 256" }
{ "index": 6323, "solution": "Note that, since this is symmetric in $a_{1}$ through $a_{7}$, $$ \\sum_{a_{1}=0}^{\\infty} \\sum_{a_{2}=0}^{\\infty} \\cdots \\sum_{a_{7}=0}^{\\infty} \\frac{a_{1}+a_{2}+\\cdots+a_{7}}{3^{a_{1}+a_{2}+\\cdots+a_{7}}} =7 \\sum_{a_{1}=0}^{\\infty} \\sum_{a_{2}=0}^{\\infty} \\cdots \\sum_...
DeepScaleR
[ { "role": "user", "content": "Compute $$100^{2}+99^{2}-98^{2}-97^{2}+96^{2}+95^{2}-94^{2}-93^{2}+\\ldots+4^{2}+3^{2}-2^{2}-1^{2}$$" } ]
math
{ "style": "rule", "ground_truth": "10100" }
{ "index": 6324, "solution": "Note that $(n+3)^{2}-(n+2)^{2}-(n+1)^{2}+n^{2}=4$ for every $n$. Therefore, adding $0^{2}$ to the end of the given sum and applying this identity for every four consecutive terms after $100^{2}$, we see that the given sum is equivalent to $100^{2}+25 \\cdot 4=10100$. Alternatively, we ...
DeepScaleR
[ { "role": "user", "content": "Compute $$2 \\sqrt{2 \\sqrt[3]{2 \\sqrt[4]{2 \\sqrt[5]{2 \\cdots}}}}$$" } ]
math
{ "style": "rule", "ground_truth": "2^{e-1}" }
{ "index": 6325, "solution": "Taking the base 2 logarithm of the expression gives $$1+\\frac{1}{2}\\left(1+\\frac{1}{3}\\left(1+\\frac{1}{4}(1+\\cdots)\\right)\\right)=1+\\frac{1}{2!}+\\frac{1}{3!}+\\frac{1}{4!}+\\cdots=e-1$$ Therefore the expression is just $2^{e-1}$." }
DeepScaleR
[ { "role": "user", "content": "Compute $$\\lim _{A \\rightarrow+\\infty} \\frac{1}{A} \\int_{1}^{A} A^{\\frac{1}{x}} \\mathrm{~d} x$$" } ]
math
{ "style": "rule", "ground_truth": "1" }
{ "index": 6326, "solution": "We prove that $$\\lim _{A \\rightarrow+\\infty} \\frac{1}{A} \\int_{1}^{A} A^{\\frac{1}{x}} \\mathrm{~d} x=1$$ For $A>1$ the integrand is greater than 1, so $$\\frac{1}{A} \\int_{1}^{A} A^{\\frac{1}{x}} \\mathrm{~d} x>\\frac{1}{A} \\int_{1}^{A} 1 \\mathrm{~d} x=\\frac{1}{A}(A-1)=1-\\fr...
DeepScaleR
[ { "role": "user", "content": "Compute $$\\sum_{\\substack{a+b+c=12 \\\\ a \\geq 6, b, c \\geq 0}} \\frac{a!}{b!c!(a-b-c)!}$$ where the sum runs over all triples of nonnegative integers $(a, b, c)$ such that $a+b+c=12$ and $a \\geq 6$." } ]
math
{ "style": "rule", "ground_truth": "2731" }
{ "index": 6327, "solution": "We tile a $1 \\times 12$ board with red $1 \\times 1$ pieces, blue $1 \\times 2$ pieces, and green $1 \\times 2$ pieces. Suppose we use $a$ total pieces, $b$ blue pieces, and $c$ green pieces. Then we must have $a+b+c=12$, and the number of ways to order the pieces is $$\\binom{a}{b, c...
DeepScaleR
[ { "role": "user", "content": "Compute $$\\sum_{n=0}^{\\infty} \\frac{n}{n^{4}+n^{2}+1}$$" } ]
math
{ "style": "rule", "ground_truth": "1/2" }
{ "index": 6328, "solution": "Note that $$n^{4}+n^{2}+1=\\left(n^{4}+2 n^{2}+1\\right)-n^{2}=\\left(n^{2}+1\\right)^{2}-n^{2}=\\left(n^{2}+n+1\\right)\\left(n^{2}-n+1\\right)$$ Decomposing into partial fractions, we find that $$\\frac{n}{n^{4}+n^{2}+1}=\\frac{1}{2}\\left(\\frac{1}{n^{2}-n+1}-\\frac{1}{n^{2}+n+1}\\r...
DeepScaleR
[ { "role": "user", "content": "Compute $$\\sum_{n=1}^{\\infty} \\frac{2 n+5}{2^{n} \\cdot\\left(n^{3}+7 n^{2}+14 n+8\\right)}$$" } ]
math
{ "style": "rule", "ground_truth": "\\frac{137}{24}-8 \\ln 2" }
{ "index": 6329, "solution": "First, we manipulate using partial fractions and telescoping: $$\\begin{aligned} \\sum_{n=1}^{\\infty} \\frac{2 n+5}{2^{n} \\cdot\\left(n^{3}+7 n^{2}+14 n+8\\right)} & =\\frac{1}{2} \\cdot \\sum_{n=1}^{\\infty} \\frac{1}{2^{n}}\\left(\\frac{2}{n+1}-\\frac{1}{n+2}-\\frac{1}{n+4}\\right)...
DeepScaleR
[ { "role": "user", "content": "Compute $$\\sum_{n=1}^{\\infty} \\frac{3n-1}{2^n}.$$" } ]
math
{ "style": "rule", "ground_truth": "5" }
{ "index": 6330, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $$\\sum_{n_{60}=0}^{2} \\sum_{n_{59}=0}^{n_{60}} \\cdots \\sum_{n_{2}=0}^{n_{3}} \\sum_{n_{1}=0}^{n_{2}} \\sum_{n_{0}=0}^{n_{1}} 1$$" } ]
math
{ "style": "rule", "ground_truth": "1953" }
{ "index": 6331, "solution": "The given sum counts the number of non-decreasing 61-tuples of integers $\\left(n_{0}, \\ldots, n_{60}\\right)$ from the set $\\{0,1,2\\}$. Such 61-tuples are in one-to-one correspondence with strictly increasing 61-tuples of integers $\\left(m_{0}, \\ldots, m_{60}\\right)$ from the se...
DeepScaleR
[ { "role": "user", "content": "Compute $(-64)\\div (-32)$." } ]
math
{ "style": "rule", "ground_truth": "2" }
{ "index": 6332, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $(1 + i)^4.$" } ]
math
{ "style": "rule", "ground_truth": "-4" }
{ "index": 6333, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $(2 \\cos 20^\\circ + 2i \\sin 20^\\circ)^6.$ Enter your answer in rectangular form." } ]
math
{ "style": "rule", "ground_truth": "-32 + 32i \\sqrt{3}" }
{ "index": 6334, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $(4+8)^2+(4^2+8^2)$." } ]
math
{ "style": "rule", "ground_truth": "224" }
{ "index": 6335, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $(5+7)^3+(5^3+7^3)$." } ]
math
{ "style": "rule", "ground_truth": "2196" }
{ "index": 6336, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $(\\cos 185^\\circ + i \\sin 185^\\circ)^{54}.$" } ]
math
{ "style": "rule", "ground_truth": "-i" }
{ "index": 6337, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $({11011_{(2)}} - {101_{(2)}} = )$\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_$(.$ (represented in binary)" } ]
math
{ "style": "rule", "ground_truth": "10110_{(2)}" }
{ "index": 6338, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $-8\\cdot 4-(-6\\cdot -3)+(-10\\cdot -5)$." } ]
math
{ "style": "rule", "ground_truth": "0" }
{ "index": 6339, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $0.18\\div0.003.$" } ]
math
{ "style": "rule", "ground_truth": "60" }
{ "index": 6340, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $1+6\\cdot2-3+5\\cdot4\\div2$" } ]
math
{ "style": "rule", "ground_truth": "20" }
{ "index": 6341, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $1-2+3-4+ \\dots -100+101$." } ]
math
{ "style": "rule", "ground_truth": "76" }
{ "index": 6342, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $1-2+3-4+ \\dots -98+99$ ." } ]
math
{ "style": "rule", "ground_truth": "50" }
{ "index": 6343, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $1-2+3-4+\\dots+100-101$." } ]
math
{ "style": "rule", "ground_truth": "51" }
{ "index": 6344, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $1011_2 + 101_2 - 1100_2 + 1101_2$. Express your answer in base 2." } ]
math
{ "style": "rule", "ground_truth": "10001_2" }
{ "index": 6345, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $10^{-1}\\pmod{1001}$. Express your answer as a residue from $0$ to $1000$, inclusive." } ]
math
{ "style": "rule", "ground_truth": "901" }
{ "index": 6346, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $11^{-1} \\pmod{1105}$, where $1105=5\\cdot 13 \\cdot 17$. Express your answer as a residue from $0$ to $1104$, inclusive." } ]
math
{ "style": "rule", "ground_truth": "201" }
{ "index": 6347, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $139+27+23+11$." } ]
math
{ "style": "rule", "ground_truth": "200" }
{ "index": 6348, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $156 + 44 + 26 + 74$." } ]
math
{ "style": "rule", "ground_truth": "300" }
{ "index": 6349, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $16\\left (\\frac{125}{2}+\\frac{25}{4}+\\frac{9}{16}+1\\right)$." } ]
math
{ "style": "rule", "ground_truth": "1125" }
{ "index": 6350, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $17^9 \\div 17^7$." } ]
math
{ "style": "rule", "ground_truth": "289" }
{ "index": 6351, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $18\\left(\\frac{200}{3} + \\frac{50}{6} + \\frac{16}{18} + 2\\right)$." } ]
math
{ "style": "rule", "ground_truth": "1402" }
{ "index": 6352, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $2 \\times 2^5 - 8^{58} \\div 8^{56}$" } ]
math
{ "style": "rule", "ground_truth": "0" }
{ "index": 6353, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $2011 \\cdot 2012 \\cdot 2013 \\cdot 2014$ modulo 5." } ]
math
{ "style": "rule", "ground_truth": "4" }
{ "index": 6354, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $20\\left(\\frac{256}{4} + \\frac{64}{16} + \\frac{16}{64} + 2\\right)$." } ]
math
{ "style": "rule", "ground_truth": "1405" }
{ "index": 6355, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $26\\times33+67\\times26$." } ]
math
{ "style": "rule", "ground_truth": "2600" }
{ "index": 6356, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $3 \\begin{pmatrix} 2 \\\\ -8 \\end{pmatrix} - 2 \\begin{pmatrix} 1 \\\\ -7 \\end{pmatrix}$." } ]
math
{ "style": "rule", "ground_truth": "\\begin{pmatrix} 4 \\\\ -10 \\end{pmatrix}" }
{ "index": 6357, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $35^{1723} - 16^{1723}$ modulo 6." } ]
math
{ "style": "rule", "ground_truth": "1" }
{ "index": 6358, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $54 \\times 46$ in your head." } ]
math
{ "style": "rule", "ground_truth": "2484" }
{ "index": 6359, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $55^2 - 45^2$ in your head." } ]
math
{ "style": "rule", "ground_truth": "1000" }
{ "index": 6360, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $63 \\times 57$ in your head." } ]
math
{ "style": "rule", "ground_truth": "3591" }
{ "index": 6361, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $7\\left(\\frac{1}{5}\\right)^3$." } ]
math
{ "style": "rule", "ground_truth": "\\frac{7}{125}" }
{ "index": 6362, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $9 \\cdot (-5) - (7 \\cdot -2) + (8 \\cdot -6)$." } ]
math
{ "style": "rule", "ground_truth": "-79" }
{ "index": 6363, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $95^2$ in your head." } ]
math
{ "style": "rule", "ground_truth": "9025" }
{ "index": 6364, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $97^2$ in your head." } ]
math
{ "style": "rule", "ground_truth": "9409" }
{ "index": 6365, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos (\\cos 3).$ All functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "3 - 2\\pi" }
{ "index": 6366, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos (\\cos 7).$ All functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "7 - 2 \\pi" }
{ "index": 6367, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos (\\sin 1.5).$ All functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "\\frac{\\pi}{2} - 1.5" }
{ "index": 6368, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos (\\sin 2).$ All functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "2 - \\frac{\\pi}{2}" }
{ "index": 6369, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos (\\sin 3)$. All functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "3 - \\frac{\\pi}{2}" }
{ "index": 6370, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos (\\sin 3).$ All functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "3 - \\frac{\\pi}{2}" }
{ "index": 6371, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos \\frac{\\sqrt{3}}{2}.$ Express your answer in radians." } ]
math
{ "style": "rule", "ground_truth": "\\frac{\\pi}{6}" }
{ "index": 6372, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos(\\cos 9).$ All functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "9 - 2\\pi" }
{ "index": 6373, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arccos(\\sin 3)$, where all functions are in radians." } ]
math
{ "style": "rule", "ground_truth": "3 - \\frac{\\pi}{2}" }
{ "index": 6374, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arcsin (-1).$ Express your answer in radians." } ]
math
{ "style": "rule", "ground_truth": "-\\frac{\\pi}{2}" }
{ "index": 6375, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arcsin 0.$ Express your answer in radians." } ]
math
{ "style": "rule", "ground_truth": "0" }
{ "index": 6376, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arcsin 1.$ Express your answer in radians." } ]
math
{ "style": "rule", "ground_truth": "\\frac{\\pi}{2}" }
{ "index": 6377, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arcsin \\frac{1}{\\sqrt{2}}.$ Express your answer in radians." } ]
math
{ "style": "rule", "ground_truth": "\\frac{\\pi}{4}" }
{ "index": 6378, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arcsin \\left( -\\frac{\\sqrt{3}}{2} \\right).$ Express your answer in radians." } ]
math
{ "style": "rule", "ground_truth": "-\\frac{\\pi}{3}" }
{ "index": 6379, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arctan ( \\tan 65^\\circ - 2 \\tan 40^\\circ )$. (Express your answer in degrees as an angle between $0^\\circ$ and $180^\\circ$.)" } ]
math
{ "style": "rule", "ground_truth": "25^\\circ" }
{ "index": 6380, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\arctan (\\tan 65^{\\circ}-2 \\tan 40^{\\circ})$. (Express your answer in degrees as an angle between $0^{\\circ}$ and $180^{\\circ}$.)" } ]
math
{ "style": "rule", "ground_truth": "25^{\\circ}" }
{ "index": 6381, "solution": "First Solution: We have $\\tan 65^{\\circ}-2 \\tan 40^{\\circ}=\\cot 25^{\\circ}-2 \\cot 50^{\\circ}=\\cot 25^{\\circ}-\\frac{\\cot ^{2} 25^{\\circ}-1}{\\cot 25^{\\circ}}=\\frac{1}{\\cot 25^{\\circ}}=\\tan 25^{\\circ}$. Therefore, the answer is $25^{\\circ}$. Second Solution: We have $...
DeepScaleR
[ { "role": "user", "content": "Compute $\\arctan \\frac{2}{5} + \\arctan \\frac{5}{2}.$ Express your answer in radians." } ]
math
{ "style": "rule", "ground_truth": "\\frac{\\pi}{2}" }
{ "index": 6382, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\begin{pmatrix} -4 \\\\ -1 \\end{pmatrix} \\cdot \\begin{pmatrix} 6 \\\\ 8 \\end{pmatrix}$." } ]
math
{ "style": "rule", "ground_truth": "-32" }
{ "index": 6383, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\begin{pmatrix} 1 & -1 \\\\ 1 & 0 \\end{pmatrix}^3.$" } ]
math
{ "style": "rule", "ground_truth": "\\begin{pmatrix} -1 & 0 \\\\ 0 & -1 \\end{pmatrix}." }
{ "index": 6384, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\begin{pmatrix} 1 & 0 \\\\ 1 & 1 \\end{pmatrix}^{2018}.$" } ]
math
{ "style": "rule", "ground_truth": "\\begin{pmatrix} 1 & 0 \\\\ 2018 & 1 \\end{pmatrix}" }
{ "index": 6385, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\begin{pmatrix} 2 & - 1 \\\\ - 3 & 4 \\end{pmatrix} \\begin{pmatrix} 3 \\\\ - 1 \\end{pmatrix}.$" } ]
math
{ "style": "rule", "ground_truth": "\\begin{pmatrix} 7 \\\\ -13 \\end{pmatrix}" }
{ "index": 6386, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\begin{pmatrix} 2 & 0 \\\\ 5 & -3 \\end{pmatrix} \\begin{pmatrix} 8 & -2 \\\\ 1 & 1 \\end{pmatrix}.$" } ]
math
{ "style": "rule", "ground_truth": "\\begin{pmatrix} 16 & -4 \\\\ 37 & -13 \\end{pmatrix}" }
{ "index": 6387, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\begin{pmatrix} 2 & 3 \\\\ 7 & -1 \\end{pmatrix} \\begin{pmatrix} 1 & -5 \\\\ 0 & 4 \\end{pmatrix}.$" } ]
math
{ "style": "rule", "ground_truth": "\\begin{pmatrix} 2 & 2 \\\\ 7 & -39 \\end{pmatrix}" }
{ "index": 6388, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\begin{pmatrix} \\sqrt{3} & -1 \\\\ 1 & \\sqrt{3} \\end{pmatrix}^6.$" } ]
math
{ "style": "rule", "ground_truth": "\\begin{pmatrix} -64 & 0 \\\\ 0 & -64 \\end{pmatrix}" }
{ "index": 6389, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\binom{12}{9}$ and then find the factorial of the result." } ]
math
{ "style": "rule", "ground_truth": "220" }
{ "index": 6390, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\binom{17}{9}$. You are told that $\\binom{15}{6} = 5005$ and $\\binom{15}{8} = 6435$." } ]
math
{ "style": "rule", "ground_truth": "24310" }
{ "index": 6391, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\binom{18}{6}$." } ]
math
{ "style": "rule", "ground_truth": "18564" }
{ "index": 6392, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\cos 0^\\circ$." } ]
math
{ "style": "rule", "ground_truth": "1" }
{ "index": 6393, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\cos 105^\\circ$." } ]
math
{ "style": "rule", "ground_truth": "\\frac{\\sqrt{2} - \\sqrt{6}}{4}" }
{ "index": 6394, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\cos 135^\\circ$." } ]
math
{ "style": "rule", "ground_truth": "-\\frac{\\sqrt{2}}{2}" }
{ "index": 6395, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\cos 150^\\circ$." } ]
math
{ "style": "rule", "ground_truth": "-\\frac{\\sqrt{3}}{2}" }
{ "index": 6396, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\cos 210^\\circ$." } ]
math
{ "style": "rule", "ground_truth": "-\\frac{\\sqrt{3}}{2}" }
{ "index": 6397, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\cos 240^\\circ$." } ]
math
{ "style": "rule", "ground_truth": "-\\frac{1}{2}" }
{ "index": 6398, "solution": "" }
DeepScaleR
[ { "role": "user", "content": "Compute $\\cos 270^\\circ$." } ]
math
{ "style": "rule", "ground_truth": "0" }
{ "index": 6399, "solution": "" }