blob_id stringlengths 40 40 | repo_name stringlengths 5 119 | path stringlengths 2 424 | length_bytes int64 36 888k | score float64 3.5 5.22 | int_score int64 4 5 | text stringlengths 27 888k |
|---|---|---|---|---|---|---|
8dc33b0291f00e04734c54e2b5d66b45260144b9 | Jeevanantham13/Python | /palindrome.py | 232 | 4.09375 | 4 | num=int(input("enter the number"))
c=num
rev=0
while(num>0):
rem=num%10
rev=(rev*10)+(rem)
num=num//10
print("the reversed num:",rev)
if(c==rev):
print("its a palindrome")
else:
print("its not a palindrome") |
aeacf191277ccc20bb75496acb42253a1456e434 | Hao-HOU/LearnPython3theHardWay | /code/ex19.py | 1,055 | 3.9375 | 4 | def cheese_and_crackers(cheese_count, boxes_of_crackers):
print(f"You have {cheese_count} cheeses!")
print(f"You have {boxes_of_crackers} boxes of crackers!")
print("Man that's enough for a party!")
print("Get a blanket.\n")
print("We can just give the function numbers directly:")
cheese_and_crackers(... |
95e099e035ade30eac662e546b901e08ce1e0962 | RobertoRosa7/python | /py_intro_to_python/fila.py | 585 | 4 | 4 | # -*- coding: utf-8 -*-
from collections import deque
def fila():
'''
Trabalhando com filas - deque
se for inserido mais do que o limite o primeiro elemento será removido
append() - adiciona no final
appendleft() - adiciona no inicio
pop() - remover elemento no fina... |
d3d111088b67b12e04e0b2620c2836d545e70057 | TapanManu/Py-Ton | /strings/duplicate_letters.py | 168 | 3.75 | 4 | str=input('get the string')
ls=[x for x in str]
dup=list(set(ls))
if len(dup)==len(ls):
print("string has unique letters only")
else:
print("string has repetitions")
|
374faafae9b7e6da34f4ed24eba1706a5b0878eb | johnklee/algprac | /hackerrank/graph/medium/journey-to-the-moon.py | 3,383 | 3.609375 | 4 | #!/usr/bin/env python
r'''
https://www.hackerrank.com/challenges/journey-to-the-moon/problem
'''
import math
import os
import random
import re
import sys
class Node:
def __init__(self, v):
self.v = v
self.neighbors = set()
self.visit = False
def addN(self, n):
if n not in sel... |
c2bc9309ea47292a8a79355d41c82a6de822b905 | shuchita-rahman/HakkerRank | /sWAP cASE Solution.py | 272 | 4 | 4 | def swap_case(s):
newstring =''
for a in s:
if (a.isupper()) == True:
newstring+=(a.lower())
elif (a.islower()) == True:
newstring+=(a.upper())
else:
newstring+= a
return newstring
|
0fa541dc157ce16ad55e5211e88459eaaccc67b9 | SatishMurthy/Python-Practice | /Hackerrank scripts.py | 3,468 | 4.125 | 4 | # #Polar Coordinates
#
# import cmath
#
# cnum = input('Enter complex number a+ij: ')
#
# #complex(input())
#
# polarcoord = cmath.polar(complex(cnum))
#
# for n in polarcoord:
# print(round(n,3))
# #Average of distinct numbers from a given set of numbers
# def average(array):
# # your code goes h... |
90e88f861fddc5ce39e21028f2ae7f72fd2dae94 | vikkiorrikki/Google-calendar-Mongo | /work.py | 6,272 | 3.546875 | 4 | # -*- coding: utf-8 -*-
from __future__ import print_function
import httplib2
import os
import time
import datetime
import itertools
from operator import itemgetter
from pymongo import MongoClient
def main():
client = MongoClient('localhost', 27017)
db = client['calendar-data']
mongo_calendars = db.calendars
em... |
a4d0cbc66717476eb3382200b4ea71e60e732c01 | wpgalmeida/tic-tac-toe-python-playground | /tests/apps/test_judge.py | 3,695 | 3.5625 | 4 | from unittest import TestCase
from tic_tac_toe_python_playground.apps.core.judge import check_end_game
class Test(TestCase):
def test_should_win_in_row_1(self):
fake_actual_board_to_be_tested = [["X", "X", "X"], [3, 4, 5], [6, 7, 8]]
self.assert_(check_end_game(fake_actual_board_to_be_tested))
... |
47bfc900304f2e4435908d08e278d16723820358 | etfrer-yi/Python-Reddit-Webscraper- | /Python Reddit Webscraper/reddit_word_cloud.py | 631 | 3.765625 | 4 | # Code to generate the word cloud taken from
# https://towardsdatascience.com/simple-wordcloud-in-python-2ae54a9f58e5
import matplotlib.pyplot as plt
from wordcloud import WordCloud, STOPWORDS
def plot_cloud(wordcloud):
plt.figure(figsize=(40, 30))
plt.imshow(wordcloud)
plt.axis("off")
p... |
9b561c8b8eba0f3af33b7319ddc19b5509f3a990 | everaldobass/curso-python3 | /8-curso-cod3r-python/pacote/tipos/01-for.py | 257 | 3.796875 | 4 |
# for i in range(10):
# print(i)
# for a in range(1, 100, 2):
# print(a)
#num = [1, 2, 3, 4, 5]
# for n in num:
# print(n)
produto = {
"nome": "Caneta",
"preco": 2.50,
"desc": 0.5
}
for can in produto:
print(can, "==>", produto[can])
|
f4f99a5f55db9f43a2d507f2ada6a2f85c98af87 | ctc316/algorithm-python | /Lintcode/G_Practice/OAs/1646. CheckWords.py | 702 | 3.640625 | 4 | class Solution:
"""
@param s:
@param str:
@return: Output whether this combination meets the condition
"""
def checkWord(self, s, str):
dict = set(str)
stack = []
visited = set()
if s not in dict:
return False
stack.append(s)
visited.... |
75190a2a508e622e875e0ac23a7976a686e8df01 | giabao2807/python-study-challenge | /basic-python/module-package/my_math.py | 862 | 4.1875 | 4 | print('--- start of my_math ---')
PI = 3.14159
E = 2.71828
message = 'My math module'
def sum(start, *numbers):
'''Calculate the sum of unlimited number
Params:
start:int/float, the start sum
*numbers:int/float, the numbers to sum up
Return: int/float
'''
for x in numbers:
... |
96bc7a96b0ff902c79737d1f7186432383e8f12c | MS-87/Daily-Coding | /20180528 - Talking Clock/talkclock.py | 2,760 | 4.0625 | 4 | """
Description
No more hiding from your alarm clock! You've decided you want your computer
to keep you updated on the time so you're never late again.
A talking clock takes a 24-hour time and translates it into words.
Input Description
An hour (0-23) followed by a colon followed by the minute (0-59).
Output Descript... |
883458c8a596b0d4c6f5bbd80185072b6710280a | lkogant1/Python | /while_armstr.py | 259 | 4 | 4 | #armstrong number or not
#sum of each digit cubes is equal to the given number
#eg: 153
x
n = int(input("number: "))
t = n
s = 0
while(n>0):
d = n%10
s = s+(d*d*d)
n = int(n/10)
if(s == t):
print("Armstrong number")
else:
print("Not an Armstrong number") |
b170ad3edf29ed96b06dc64fc4eb746aa992e7c6 | cabbageGG/study_ | /python/test_python_grammar/test_mysql.py | 1,340 | 3.578125 | 4 | #-*- coding: utf-8 -*-
# author: li yangjin
import MySQLdb
"""
MYSQL:用法
host
string, host to connect
user
string, user to connect as
passwd
string, password to use
db
string, database to use
port
integer, TCP/IP port to ... |
acf9947ef51f668bc986b97444f2f3f927d78aa7 | kenji-tolede/Travaux-python | /EXO 16.py | 255 | 3.9375 | 4 | m1 = input('entrez 1er mot')
m2 = input('entrez le 2eme mot')
def hamming_distance(m1, m2):
distance = 0
for i in range(len(m1)):
if m1[i] != m2[i]:
distance += 1
return distance
print(hamming_distance(m1,m2)) |
cd5fff209d684ffffb01a035bd0632b08ef529ff | sunsunza2009/Image-Classifier-Web-GUI | /Flask Train Server/CNN/model.py | 1,037 | 3.546875 | 4 | from tensorflow.keras.models import Sequential
from tensorflow.keras.layers import Dense, Dropout, Activation, Flatten, Conv2D, MaxPooling2D
def getModel(numClass,shape):
# Building the model
model = Sequential()
# 3 convolutional layers
model.add(Conv2D(32, (3, 3), input_shape = shape))
model.add(Activation("rel... |
f60343b59b05c8cd1461b6f65775135ac0986a42 | qiwsir/LearningWithLaoqi | /PythonBase/08program.py | 384 | 3.515625 | 4 | #coding:utf-8
class Person:
def __init__(self, name):
self.name = name
def height(self, m):
h = dict((["height", m],))
return h
class Student(Person):
def score(self, mark):
result = {self.name: mark}
return result
if __name__ == "__main__":
tom = Stud... |
6091e9a8988cd0ba5dcad05369ad459524740286 | daniel-reich/turbo-robot | /Pf2kDoCRvEL8qzKTs_22.py | 1,625 | 4.25 | 4 | """
Create a function that takes in the size of the line and the number of people
waiting and places people in an _S-shape_ ordering. The demonstration below
will make it clear:
# Ordering numbers 1-15 in a [5,3] space.
order_people([5, 3], 15) ➞ [
[1, 2, 3],
[6, 5, 4],
[7, 8, 9],
... |
55097e6dcb4da8743b4ac5dc86dcd573bea033b0 | ghoshrohit72/Algorithm-Hub | /UsingPython/EvenFibonacciNumbers.py | 580 | 3.890625 | 4 | '''
Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:
1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...
By considering the terms in the Fibonacci sequence whose values do not exceed four million, find the sum of the even-valued terms.
'''
d... |
e8f209a256dd7776de56ea8f5c7c46619e96fc7a | AbhinavRobinson/RSA-over-SHA | /generate_keys.py | 1,507 | 3.875 | 4 | """
! Set of Functions to Generate Keys
Generates private and public key pair
p_num1 = first prime
p_num2 = second prime
key_size = define key size (128 bits : default)
"""
# Imports random for randomint generation
import random
def generate(p_num1, p_num2, key_size=128):
n = p_num1 * p_nu... |
614911c74484505d486575f79a4ca954d5ccc81d | rodri0315/pythonCSC121 | /chapter9/dictionary_example.py | 638 | 4.03125 | 4 | players = dict(
Messi='forward',
Pique='Defender',
Xavi='Midfielder',
Valdez='Goalie')
for key in players:
print(f"FCBarcelona player: {key}")
print("____")
for key in players:
print("{} plays as a {}".format(key, players[key]))
# will return everything in dictionary
print(players.items())
... |
16ab8dab4f6eec4c8ab668fa6aeb434c6f95f5e4 | hmaryam/Thinkful_codes | /Lesson2_1.py | 1,371 | 4.03125 | 4 | Write a function to ask what style of drink a customer likes
import random
questions = {
"strong": "Do ye like your drinks strong?",
"salty": "Do ye like it with a salty tang?",
"bitter": "Are ye a lubber who likes it bitter?",
"sweet": "Would ye like a bit of sweetness with yer poison?",
"fruity": ... |
ee4833ed599e2c9ddbd1711a946e3e4e1f6ead40 | allegheny-college-expressioneers/while-while-west-practical-solution | /1_temperature_converter.py | 537 | 4.28125 | 4 | def to_celsius(fahrenheit):
return (fahrenheit - 32) * 5 / 9
def to_fahrenheit(celsius):
return 9/5 * celsius + 32
temperature = input('Enter a temperature value: ')
unit = input('Enter the temperature\'s unit: ')
if unit == 'C' or unit == 'c':
print(f'The temperature is {round(to_fahrenheit(int(temperat... |
c0b69a21cebcf47e0d2b26ed26960283d3c51442 | lgrant146/JetbrainsPython | /Problems/Desks/main.py | 257 | 3.796875 | 4 | # put your python code here
group1 = int(input())
group2 = int(input())
group3 = int(input())
desk1 = group1 // 2 + group1 % 2
desk2 = group2 // 2 + group2 % 2
desk3 = group3 // 2 + group3 % 2
total_desks = desk1 + desk2 + desk3
print(total_desks)
|
26b2f4b00a8b6ea2a2f7a55225545c6dd458532b | CarolineWinter/gothic | /data_processing/test_spacy.py | 1,723 | 3.65625 | 4 | """
Testing basic concepts & tools before doing our main analysis.
"""
import re
from collections import defaultdict
from oed_color import color_words
import spacy
nlp = spacy.load('en')
def tokenize_text():
"""
This function generates a list of tokens with punctuation and spaces removed.
"""
text_to... |
40ef1fa0538d453a6f95ddc9bc422d0e6c19136f | MrHamdulay/csc3-capstone | /examples/data/Assignment_7/bxtnaa002/question1.py | 758 | 3.984375 | 4 | # question1.py
# author: bxtnaa002
# assignment 7
words = []
word = input("Enter strings (end with DONE):\n") # create a list containing words and DONE is inputed to terminate the growth of the list
while word != "DONE":
words.append(word)
word = input("")
unique = [] #create a new list
f... |
6650fa86f62f3cc472c3c79b71ba1c736eeec2e6 | ntupenn/exercises | /hard/272.py | 1,451 | 3.828125 | 4 | """
Given a non-empty binary search tree and a target value, find k values in the BST that are closest to the target.
Note:
Given target value is a floating point.
You may assume k is always valid, that is: k <= total nodes.
You are guaranteed to have only one unique set of k values in the BST that are closest to the... |
bbdef09bfee0b8623d6a84271f23174ad14a1589 | M0use7/python | /LeetCode/最长公共前缀.py | 281 | 3.59375 | 4 | """__author__ = 唐宏进 """
class Solution(object):
def longestCommonPrefix(self, strs):
"""
:type strs: List[str]
:rtype: str
"""
n = len(strs)
for item in strs:
for _ in range(n):
item[n] ==
|
d0faec85f786686f341e6affc51e5406772880b4 | enu93/ElephantGame | /drawing_shapes.py | 993 | 3.546875 | 4 | import pygame, sys
from pygame.locals import *
pygame.init()
screen = pygame.display.set_mode((640, 350), 0, 32)
color = (255, 255, 0)
# polygon ponts
points = [(20, 120), (140, 140), (10,30)]
# circle points
position = (300, 176)
radius = (60)
# ellipse points
rectangle = (140, 180, 50, 190)
# ... |
d0ea6e7381beed60aa921331c5b9cb9f51ba7f9d | Liganggooo/Work_File | /python/Python1/File.py | 530 | 3.796875 | 4 | f = open('text.txt','r')
# f.write('abc')
# content = f.read()
#将文件存入一个列表中然后对列表进行遍历
lines = f.readlines()
for line in lines:
print(line.strip())
# print(content)
f.close
#免关闭文件式阅读文件方法
# filename = 'text.txt'
# with open(filename) as f:
# content = f.read()
# print(content)
# #写入文件、追加文件位置
# with o... |
9c177c7016c9edf051297633de926ed2e9b13039 | JamieRRobillardSr/stpd | /challenges/ch06/6-5.py | 203 | 3.578125 | 4 | l1 = [ "The", "fox", "jumped", "over", "the", "fence", "." ]
s1 = ""
for word in l1:
if (word == "."):
s1 = s1.strip()
s1 += word
else:
s1 += word + " "
print(s1)
|
9dd0100eef6551a5d7973a20fa38c0810341edf8 | At0m07/python | /dz1.py | 844 | 4.5 | 4 | #1.Поработайте с переменными, создайте несколько, выведите на экран,
#запросите у пользователя несколько чисел и строк и сохраните в переменные,
#выведите на экран.
print("Добро пожаловать!")
a = 5
b = 10
print ("Вывод переменных a и b:",a,b)
number = int(input("Введите первое число:"))
string = input("Введ... |
a1bb6be4882167b0692406b13d3c8ba562e39262 | dr-dos-ok/Code_Jam_Webscraper | /solutions_python/Problem_74/522.py | 1,668 | 3.625 | 4 | #!/opt/local/bin/python
import sys
from itertools import count
def get_next_position(position_it, robot):
while True:
try:
next = position_it.next()
except StopIteration:
return None
if next[1] == robot:
return next[0]
input_it = iter(sys.stdin.readline... |
6463cd932456a519035862ff3e76a35e3943a2f9 | zhaoyang6943/Python_JiChu | /day05/03 运算符.py | 1,655 | 4.28125 | 4 | # 学习的思路：什么是？为什么要有这个？
# 1. 算术运算符
# print(111 + 3)
# print(type(100 - 3.1))
#
# print(10 / 3) # 带小数
# print(10 // 3) # 只保留整数部分
#
# print(10 % 3) # 取余
#
# print(10 ** 3) # 代表10的3次方
# 2. 比较运算符
# print(1 > 3)
#
# print(1 == 1)
#
# print(10 >= 10)
# print(10 <= 3)
# name=input('your name')
# print('agen' == name)
# 3... |
1a62e2eb3cac117b0f23fb0acb9b35e29b3a8006 | AmyrSam/lab-test | /lab-test | 1,196 | 4.15625 | 4 | #!/usr/bin/env python
# coding: utf-8
Soalan 1:
def countSetBits(n):
count = 0
while (n):
count += n & 1
n >>= 1
return count
i = input("Enter the number: ")
print(countSetBits(int(i)))
Soalan 2:
import collections
s = input("Enter your word: ")
print(collections.Counter(s... |
95d5211974ca6ac985f55b05f22ca1ff225ea0a6 | Edw10/holbertonschool-higher_level_programming | /0x0C-python-almost_a_circle/models/square.py | 1,548 | 3.84375 | 4 | #!/usr/bin/python3
"""
this module define the square
"""
from models.rectangle import Rectangle
class Square(Rectangle):
"""
this is the square class
"""
def __init__(self, size, x=0, y=0, id=None):
"""this initialice a square"""
super().__init__(size, size, x, y, id)
def __str_... |
5c99a76b5445fbdc3f6c3c350eee95b27ec93fdc | Ellen172/UFU-Python | /For range.py | 494 | 4 | 4 | #imprimindo os numeros primos, dentro de uma tupla
primos = (1, 3, 5, 7, 11, 13)
for k in primos :
print(k)
#cria uma tupla de 0 a 5, sem incluir o 5, atraves de uma p.a
r = tuple (range (0, 5))
print("r = ", r)
#a tupla é gerada a cada 2 numeros
l = tuple (range (0, 10, 2))
print("l =", l)
#cria um... |
7307c88244801bfe9cdc0fd12ac9a9e75b176842 | jgartsu12/my_python_learning | /python_data_structures/tuples/remove_elements.py | 1,468 | 4.59375 | 5 | # Three Ways to Remove Elements from a Python Tuple
# tuples are immutable so original is not having anything removed but the new ones will be new tuples with elements removed
# real world situation u didnt create the tuple but working with outsdie library with collection and cant ctrl tuple is what u have to work w/
... |
12ebff9127351880383916e47e85aac753b9051a | muhil77/Project-One | /prime_check.py | 314 | 4.1875 | 4 | # this function checks if a number is prime
def prime_checker(num):
flag = True
for divisor in range(2, num / 2):
if num % divisor ==0:
flag = False
return flag
return flag
number_to_check = int(raw_input("Enter number to check "))
print prime_checker(number_to_check)
|
6af7045d8f10d43395571fbeeed07d25a4908b27 | YannTorres/Python-mundo1e2 | /Desafios/10ConversorMoeda.py | 183 | 3.65625 | 4 | a = float(input('Há quantos reais em sua carteira? R$'))
print(f'Com R${a:.2f} você pode comprar US${a/5.47:.2f}')
print(f'Com R${a:.2f} você pode comprar EU€{a/6.62:.2f}')
|
3d76a9121810c1270ff2e3e4cf5c7339714d14be | Nafsan/hackerrank-python | /Detect Floating Point Number.py | 1,087 | 3.9375 | 4 | # for _ in range(int(input())):
# string = input()
# plus = string.count('+')
# minus = string.count('-')
# plus_minus = plus + minus
# dot = string.count('.')
# dot_index = string.find('.')
# flag = 0
# if plus_minus > 1:
# flag = 1
# elif string.isalpha() is True:
# ... |
0b34fbae6a35a1c851e5bf83a10ae9dcecc79329 | FHJXS/PythonStudy | /Eclipse/Test/Day6.py | 735 | 3.546875 | 4 | # -*- coding: UTF-8 -*-
'''
Created on 2018��2��10��
@author: www60
'''
import re
def func1():
"""
A|B可以匹配A或B，所以(P|p)ython可以匹配'Python'或者'python'。
^表示行的开头，^\d表示必须以数字开头。
$表示行的结束，\d$表示必须以数字结束。
"""
m = re.match(r'^(\d{3})-(\d{3,8})$', '010-12345')
print(m)
print(m.group(0)) # 匹配整个字符串
print(m.gro... |
fb01898a36c5abc5124aee0464d33b9cdc90f592 | marandmath/programming_challenges | /Advent of Code Programs/2015/Day 2/Day 2.py | 1,194 | 3.765625 | 4 | import numpy as np
file_name = "input.txt"
# Due to efficiency we will use a list consisting of lists / rows instead of
# numpy arrays! For more read this SO article:
# https://stackoverflow.com/questions/568962/how-do-i-create-an-empty-array-matrix-in-numpy
matrix = []
with open(file_name) as f_obj:
d... |
5ec0125828d0ddcea457b758ccaef36f73ea0bbc | christian-townsend/capstone-project | /Machine Learning/generateData.py | 5,353 | 3.65625 | 4 | import random
skills = []
projects = []
groups = []
units = [9785, 9786, 10004, 10005, 10098, 11522]
#update below variables
maxGroupsPerProject=2
unitsPerProject = 2
minStudentsPerGroup=3
maxStudentsPerGroup = 5
skillsPerProject = 6
skillsPerGroup = 8
totalGroups = 50
totalProjects = 100
pointsFactorPerSkillMatch = 8... |
28f6f7f02adac77df95dc3d83e133a469a66bd70 | mfkiwl/midi_studio_hw | /scripts/output_imp.py | 684 | 3.671875 | 4 | # Find the output resistance (impedance at DC) and Thevanin voltage of a circuit
# Supply the script with V1 measured with R1 across the ouput and V2 with R2
# across the output
# The script gives output resistance and Thevanin voltage.
import sys
import numpy as np
if len(sys.argv) != 5:
sys.stderr.write("argume... |
eef5e94d1625baa4187da6a79d2b47be10391449 | Mierln/Computer-Science | /William/Blackjack.py | 5,220 | 3.578125 | 4 | import random
suits = ('Hearts', 'Diamonds', 'Spades', 'Clubs')
ranks = ('Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine', 'Ten', 'Jack', 'Queen', 'King', 'Ace')
values = {'Two':2, 'Three':3, 'Four':4, 'Five':5, 'Six':6, 'Seven':7, 'Eight':8,
'Nine':9, 'Ten':10, 'Jack':10, 'Queen':10, 'King... |
05f01f142978c681ea3b20f70f578d5b15ad01a1 | devyani143/if-else | /chocolate.py | 196 | 4.125 | 4 | # num=int(input("enter a number"))
# if num%3==0 and num%5==0:
# print("chocolate")
# elif num%3==0:
# print("choco")
# elif num%5==0:
# print("late")
# else:
# print("dairy milk") |
44f8ca34f3e3959f767f91390c8f49b716bcde1f | 356108814/algorithm | /twitter.py | 2,919 | 4 | 4 | # coding: utf-8
# letcode 355
from typing import List
class ID:
index = 0
class Tweet:
def __init__(self, tweetId):
ID.index += 1
self.tweetId = tweetId
self.time = ID.index
class Twitter:
def __init__(self):
"""
Initialize your data structure here.
"""
... |
c9945262a44a8c9c9779cef5a5307d1e8c46455c | nekapoor7/Python-and-Django | /GREEKSFORGREEKS/String/remove_duplicate.py | 191 | 4.0625 | 4 | #Remove all duplicates from a given string in Python
from collections import OrderedDict
def removechar(s):
return "".join(OrderedDict.fromkeys(s))
s = input()
print(removechar(s))
|
7b82acf9062f85b1eab73194be3b7f90f4bce660 | Dark5Matter/GradeCalculator | /gradecalculator.py | 5,112 | 4.46875 | 4 | #!/usr/bin/env python3.5
print ("now using Python 3.5\n")
#on 17th October 2017
#by Benjamin ********
#This program first takes in the values from the CSV file from memory, then places the values in RAM to await the next time the values will be used.
#The computer will then either deem the data replacable or read... |
aac9d91104bcd6ba36b7fd195031fda637411d7f | TSmithJr/Python-Projects | /HW1/Volume.py | 2,098 | 4.375 | 4 | # Volume.py
"""
MIS 15-01
This program computes the volume of a bottle
with two cylinders, and a cone in between them.
It uses the volume of a cylinder formula and
the volume of a cone section formula.
Our output for volume is going to be different
because of math functions for pi. The example
volume w... |
6b38a9410196c7c3c1fffe7912f56f6cdd4de454 | santoshgawande/PythonPractices | /for.py | 1,295 | 4.59375 | 5 | #For loop : If we know how much loop will run then used
for i in range(5):
print(i)
#print('\n') #extra just see proper output
#For using String
for letter in 'Names':
print(letter, end =" ")
print('\n')
#For using List sequence :
# This is the better way about performance than using index
list1 = [1,2,3... |
af092923bfa57369e8f041b3dcbbab2a9d64e2bc | Aasthaengg/IBMdataset | /Python_codes/p02257/s497783881.py | 270 | 3.671875 | 4 | import math
def is_prime(n):
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return False
return n != 1
n = int(input())
answer = 0
for _ in range(0, n):
m = int(input())
if is_prime(m):
answer = answer + 1
print(answer)
|
3c8e572ff2e500b9498a94449a1197ee728a6c30 | abzalmyrzash/webdev2019 | /week 10/hackerrank/nested lists.py | 609 | 3.8125 | 4 | def alphabetic_order(a, b):
if a[0] > b[0]:
return 1
elif a[0] < b[0]:
return -1
else:
return 0
if __name__ == '__main__':
arr = []
for _ in range(int(raw_input())):
name = raw_input()
score = float(raw_input())
arr.append([name, score])
arr.sor... |
85f4167f393e5cebd92480eb53fc55525aa328fc | ducsuus/RoK-Calc | /logic.py | 833 | 3.984375 | 4 | # Reign Of Kings Calculator Logic
# A list of all the block types, linking to a list of all the materials needed to craft that block.
blocks = {"block" : [["stone", 2], ["wood", 100]],
"cobble" : [["stone", 30]]
}
# The parameters needed
user_block = str(input("Block: "))
user_perimeter = int(in... |
651690ba4aec0e434be792a3dcf7c118c0321763 | kktkyungtae/TIL | /Algorithm/2019.01/2019.01.24/Practice/10_if흐름제어4(X).py | 1,171 | 4.09375 | 4 | # 다음의 결과와 같이 가상의 두 사람이 가위 바위 보 중 하나를 내서 승패를 가르는 가위 바위 보 게임을 작성하십시오.
# 이 때 ["가위", "바위", "보"] 리스트를 활용합니다.
import random
Man = {'가위':1, '바위':2, '보':3}
Man1 = [random.choice(Man)]
Man2 = [random.choice(Man)]
print(f'{Man1[0]} {Man2[0]}')
# if Man1[0] == '가위' and Man2[0] =='보':
# print("Result : Man1 Win!")
... |
8c48fa4f8d7579eb738614acc3218a015eab1ce8 | liidenee/Python-test-example | /tests/test_class_inheritance.py | 190 | 3.640625 | 4 | from code.class_inheritance import Teacher
x = Teacher('Amy', 'Harrot', 1979)
assert x.get_name() == 'Amy Harrot', 'Name should be "Amy Harrot"'
assert x.get_year() == 1989, 'Year should be 1989' |
7546695afa4e62b727d293399866bdc6d74a0e90 | Guilherme-Artigas/Python-intermediario | /Aula 12.5 - Exercício 40 - Aquele clássico da Média/ex040_.py | 355 | 3.703125 | 4 | n1 = float(input('Digite a 1º nota: '))
n2 = float(input('Digite a 2º nota: '))
media = (n1 + n2) / 2
if media < 4.9:
print('Média: {}'.format(media))
print('REPROVADO!')
elif (media > 5.0) and (media < 6.9):
print('Média: {}'.format(media))
print('RECUPERAÇÃO!')
else:
print('Média: {}'.format(med... |
a1a7e5faad35847f22301b117952e223857d951a | nestorsgarzonc/leetcode_problems | /6.zigzag_convertion.py | 1,459 | 4.375 | 4 | """
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conve... |
ae58132685b2d3fcb924b3d7a0a4b3f66d4b1238 | klm127/rpio-cli-state-machine | /src/Game/GameStart.py | 3,403 | 3.84375 | 4 | """
The starting state for the game.
Shows some text and spinners to introduce the player to the game.
When space-bar is pressed or when the text is finished scrolling, loads up the MapState to begin game.
Extends src.Game.Map.GameStates.Game
"""
from src.Game.GameStates import Game
from src.Game import TitleScree... |
86dd565b040bc3969a49ccc07b3b7d0d69e72289 | vladosfedulov/DES | /main.py | 844 | 3.53125 | 4 | # name Владислав
ROUNDS = 16
KEY = 'Bладислав'
text = 'Куй железо не отходя от кассы'
block = []
key_position = 0
while ROUNDS > len(KEY):
KEY += KEY
if (len(text) % 2) == 1:
text = text + ' '
for i in range(0, len(text), 2):
block.append(text[i:i + 2])
def cript(b, k):
return [i[1] + chr(ord(i[0... |
a9d8e157a246d03d7252c752de3f1a8367d0c26e | plammens/python-introduction | /Fundamentals I/String basics/Concatenation/task.py | 224 | 4.28125 | 4 | # ----- concatenation -----
name = "Bob" # modify this
age = "42" # modify this
# substitute <name> with the contents of name and age (using the variables!)
print("My name is " + name + " and I'm " + age + " years old")
|
66a84c837c393eb0fd3bf118980831845561ae1d | ctrl-nivedha/backtracking-sudoku | /sudoku_backtracker/sudoku-backtracker.py | 2,413 | 3.828125 | 4 | # -*- coding: utf-8 -*-
"""
Created on Sun Apr 19 19:48:46 2020
@author: Mro
"""
row= False
col= False
board = [
[0,3,0,0,0,5,0,8,0],
[0,5,0,0,0,9,0,0,0],
[0,0,0,0,2,0,0,3,0],
[3,0,0,0,0,0,0,9,0],
[0,0,5,0,0,0,6,0,0],
[0,9,0,0,0,0,0,0,8],
[0,1,0,0,3,0,0,0,0],
[7,0,... |
3c8d173582166f5a5f6a7e15f6c9b59687c6ed00 | s1monLee/CodingChallenge | /LeetCode/Python3/1512_Number_of_Good_Pairs.py | 678 | 3.515625 | 4 | """
Given an array of integers nums.
A pair (i,j) is called good if nums[i] == nums[j] and i < j.
Return the number of good pairs.
"""
"""
class Solution:
def numIdenticalPairs(self, nums: List[int]) -> int:
pair = 0
for i, n in enumerate(nums):
for j in range(i+1,len(nums)):
... |
9db50e34cc5777797536a0ececee2760be9be747 | yize11/1808 | /14day/07-默认参数.py | 135 | 3.765625 | 4 | def a(b,c=100):
for i in range(b,c):
if i%3 == 0 and i%5 == 0:
print(i)
b = int(input('请输入数字'))
a(b)
|
17523829e6e1e93c53320b897ca889b9d846058f | isbirukov/diff_courses | /Deep_Learning_2019_2020_base_flow/3.3_homework_sum_diag_even_elements.py | 663 | 3.875 | 4 | """
Напишите функцию, которая находит сумму четных элементов на главной диагонали квадратной матрицы
(именно чётных элементов, а не элементов на чётных позициях!).
Если чётных элементов нет, то вывести 0. Используйте библиотеку numpy.
Входные данные -- квадратный np.ndarray.
"""
import numpy as np
def diag_2k(a):
... |
b465071b74da54e33626f6a8777ceb8801146b2c | L316645200/_Python | /fluent_python_eg/9 、符合Python风格的对象/9.5 格式化显示.py | 813 | 3.59375 | 4 | brl = 1/2.43
print(brl)
print(format(brl, '0.4f'))
print('1 BRL = {rate:0.2f} USD'.format(rate=brl))
# 格式规范微语言为一些内置类型提供了专用的表示代码。
# 比如，b 和 x 分别表示二进制和十六进制的 int 类型，f 表示小数形式的 float 类 型，而 % 表示百分数形式
print(format(42, 'b'))
print(format(2/3, '.1%'))
# 格式规范微语言是可扩展的，因为各个类可以自行决定如何解释 format_spec 参数。
# 例如， datetime 模块中的类，它们的 __... |
f5fa95227eaa5c0bf63de562fdb2d8306407e1d4 | manishakoirala/python | /sums_loop.py | 240 | 3.609375 | 4 | print("input data :")
N=input()
listnum1 =[]
listnum2 =[]
for i in range(N) :
listnum1.append(input())
for x in range(N):
listnum2.append(input())
print("output data:")
for j in range(N):
sumn=listnum1[j]+listnum2[j]
print(sumn)
|
3d73044416539da2865987a64c43325c589e15a5 | RJD02/Joy-Of-Computing-Using-Python | /Assignments/Week-12/Assignment12_2.py | 1,182 | 3.734375 | 4 | '''
Ramesh and Suresh have written GATE this year. They were not prepared for the exam.
There were only multiple choice questions. There were 5 options for each question listed 1,2,3,4,5.
There was only one valid answer. Each question carries 1 mark and no negative mark.
Ramesh and Suresh are so sure that there is n... |
721ff59cc46883b8ea41fa9563d7031a382c550f | tchdesde/cloud-developer | /bikeshare.py | 11,038 | 4.4375 | 4 | import time
import pandas as pd
import numpy as np
CITY_DATA = { 'chicago': 'chicago.csv',
'new york city': 'new_york_city.csv',
'washington': 'washington.csv' }
MONTHS_DATA = ['january', 'february', 'march', 'april', 'may', 'june', 'all']
DAYS_DATA = ['monday', 'tuesday', 'wednesday',... |
2a08949e93681d7e2d36812e1f617172696396b2 | IvanRado/AI | /LinearRegression/systolic.py | 1,148 | 3.78125 | 4 | if __name__ == "__main__":
# Example computing systolic blood pressure from age and weight
# The data (x1, x2, x3) are for each patient
# x1 is the systolic blood pressure
# x2 is the age in years
# x3 is the weight in pounds
import numpy as np
import pandas as pd
import matplotlib.pyp... |
88f69835ee782f7489758cd4a2e07887eab2e2b9 | SACHSTech/livehack-1-python-basics-BrianLi15 | /problem1.py | 598 | 4.625 | 5 | ----------------------------------------------------------------------
Name: problem1.py
Purpose:
Given the user input of celsius, it can convert the celsius temperature to fahrenheit
Author: Li.B
Created: 07/12/2020
----------------------------------------------------------------------
#This gets the user input... |
4d009a61f55252eb2414efdf12f721eba62ee8e4 | kateleecheng/Python-for-Everybody-Specialization | /2_Python Data Structures/Week_4_Class2.py | 517 | 3.578125 | 4 | #Week_4_Class2.py
a=[1,2,3]
b=[4,5,6]
c=a+b
print(c)
print(a)
t=[9,41,12,3,74,15]
print(t[1:3]) # up to but not including!!
print(t[:4])
print(t[3:])
print(t[:])
stuff=list() #list with nothing
stuff.append('book')
stuff.append(99)
print(stuff)
stuff.append('cookie')
print(stuff)
friends=['Joseph... |
29dfe80b2342dce80aae715e71acce4c2d66769f | benedictuttley/CM1101-Project | /game.py | 1,944 | 4.21875 | 4 | #This is the main game engine
# prints current room (example : print_room(rooms["Room1"])
def print_room(room):
print()
print(room["name"].upper())
print()
print(room["description"])
print()
# takes a dictionary of exits and a direction returns the name of the exit it leads to
# example ( exit_... |
93fa43b7deb4ad79e0e1ff8ba3b84fb3609f3e32 | benbendaisy/CommunicationCodes | /python_module/examples/881_Boats_to_Save_People.py | 1,131 | 3.96875 | 4 | from typing import List
class Solution:
"""
You are given an array people where people[i] is the weight of the ith person, and an infinite number of boats where each boat can carry a maximum weight of limit. Each boat carries at most two people at the same time, provided the sum of the weight of those peo... |
6400fad3abb28af292e4898d793f32449ea3a5da | WirKekc/prject1 | /stepik.org/stringIn.py | 221 | 3.546875 | 4 | a = input()
b = input()
s = set()
if a.find(b) == -1:
print(a.find(b))
else:
for i in range(len(a)):
if a.find(b,i) != -1:
s.add(a.find(b, i))
s = sorted(list(s))
print(*s, sep=" ")
|
f7639f508f734bc21e58fa27b134618cdf88e724 | Naimulnobel/uri-online-judge | /problem8.py | 216 | 3.78125 | 4 | # -*- coding: utf-8 -*-
"""
Created on Thu Jan 31 15:23:55 2019
@author: Student Mct
"""
a=input('Employee Number ')
b=input()
c=input()
amount=int(b)*float(c)
print('NUMBER =',a)
print('SALARY = U$',amount) |
83207c6c395fb6864dbe9b48add827620166ace9 | Unit26/EpicPython | /23_get_parity.py | 171 | 3.859375 | 4 | def fun(x):
if x % 2 == 0:
return ' чётное '
else:
return ' нечётное '
x = int(input('Введите число: '))
print(fun(x))
|
79b5b843ea30a444569f75af0b5fd848be9d294e | vinija/LeetCode | /81-search-in-rotated-sorted-array-ii/81-search-in-rotated-sorted-array-ii.py | 696 | 3.5625 | 4 | class Solution:
def search(self, nums: List[int], target: int) -> bool:
start = 0
end = len(nums) -1
while start <= end:
mid = (start + end)//2
if target in [nums[mid], nums[start], nums[end]]:
return True
eli... |
936324de85562d3841be2253c56c52088602f22a | Quarantinex/Hackerrank_Python_Algorithm | /Repeated_Sting.py | 164 | 3.671875 | 4 | def repeatedString(s, n):
x,y = divmod(n,len(s))
return s[:y].count("a")*(x+1) + s[y:].count("a")*x
s = input()
n = int(input())
print(repeatedString(s, n)) |
bc3061ba4c5af24e3923d20fec9fb1ec15539d9c | meltemtokgoz/Sentence-Or-Not-Context-free-grammar | /code/assignment3.py | 5,380 | 3.640625 | 4 | import random
# find necessary comment line number
def find_line_num(path):
start_vocab = 0
start_rule = 0
with open(path) as f:
for line in f:
start_vocab += 1
if '# Vocabulary. There is no rule for rewriting the terminals.' in line:
break
with open(pat... |
ced3c790c3d8d19a451c078e57db8da76d3b2a50 | paigetruelove/AirOvalCode | /graph_maker.py | 5,558 | 4.03125 | 4 | import pandas as pd
import matplotlib
matplotlib.use('Agg')
from matplotlib import pyplot as plt
import datetime
import matplotlib.dates as mdates
def getdata(daysToGet):
"""
This function imports the CSV file which contains the sensor data, and selects a specified data timeframe to create a graph.
daysT... |
1e8137947f4de94f5fde222e3f09154cea837880 | Computational-Physics-Research/Computational-Physics-1 | /PythonProgramming/Homework 08/wood_10.2.py | 1,038 | 3.828125 | 4 | """
Problem 2
Hypersphere Volume
"""
import numpy as np
import numpy.random as ran
import matplotlib.pyplot as plt
# main function definition
def multisphere_volume(n_dims, n_samples, radius = 1):
# initialize some working params
n_iter = 0
points = 0
while n_iter < n_samples:
# gen... |
83127d3519a1e00413bcb56a3034c348337ad522 | JohnKearney2020/python | /class.py | 928 | 4.25 | 4 | #print("I\'m a string")
#concatinating
#print("Hello" + " world")
#escape symbols
# print('I\'m a string')
# print('I\'m a \t\t\t\t string')
# print('I\'m a \v\v\v\v string')
#print("hello \nworld")
# name = "John"
# lname = "Kearney"
# output = "Good morning {student1} {student2}".format(student1=name,student2=ln... |
0800ff57bb7170cb49ac6546fbbc64bba5ce2fe3 | DanielMartinez79/Algorithms | /AlgLab1F.py | 3,871 | 3.796875 | 4 | # -*- coding: utf-8 -*-
"""
Created on Wed Sep 27 19:02:37 2017
@author: Danny
This lab compares the average and worst case performance of linear and binary search
"""
import random
import time
import math
#linear search
def linear(arr, key):
for x in range(0, len(arr)):
if (arr[x] == key):
#... |
9096b7a3e5687e4fe126743e84b588d0449fd1f4 | julienemo/exo_headfirst | /2-phraseomatic.py | 1,121 | 3.71875 | 4 | # this program generates random phrases structured as
# verb+adj+noun
# where each part is chosen randomly from their given list
import random
# import the fonction that otherwise in not
# automatically include
# then the three lists
# NB Atom encourages putting both brackets alone
# instead of on the same row as co... |
851d71b875500739081a505d0f404e3364013c5c | sreedhar9999/python-first | /lagnum.py | 118 | 3.890625 | 4 | x=int(raw_input())
y=int(raw_input())
z=int(raw_input())
if(x>y>z):
print(x )
elif(y>x>z):
print(y)
else:
print(z)
|
169e82d04d9086d2f3f1195bb04d16830fe28d02 | gclegg4201/python | /input3_while.py | 153 | 4.09375 | 4 | print("INPUT THREE NUMBERS")
a=float(input('A:'))
b=float(input('B:'))
c=float(input('C:'))
x=0
while True:
y=a*x*x+b*x+c
print("x =",x,"y =",y)
x+=1
|
40775417e7ba92bfa3c083c2e3d495390c5724e7 | Aasthaengg/IBMdataset | /Python_codes/p03080/s133965546.py | 266 | 3.6875 | 4 | def main():
_ = int(input())
s = input().rstrip()
r, b = 0, 0
for c in s:
if c == "R":
r += 1
else:
b += 1
if r > b:
print("Yes")
else:
print("No")
if __name__ == "__main__":
main() |
f8a8da2c8b2162cb5b629083e023211c4c504773 | FaizIkhwan/Competitive-Programming | /Al-Khawarizmi/2014/h.py | 199 | 3.640625 | 4 | t = int(input())
for i in range(t):
inp = str(input())
if list(inp) == list(reversed(inp)):
print('Case #{}: Yes'.format(i+1))
else:
print('Case #{}: No'.format(i+1))
|
24a8d2229edae8f55ec33137112200bb334815bc | Ydeh22/CRPM | /crpm/quantilenorm.py | 588 | 3.796875 | 4 | """ quantile normalize matricies by rows """
def quantilenorm(matrixlist):
""" normalizes matricies to have corresponding rows with similar distributions
Args:
matrixlist: a list of 2D array-like objects all with same number of rows.
Returns:
A matrix list of the transformed original matri... |
e3566deed8917f4354670b3e2ef5d999d5ab12fa | chinmairam/Python | /regex14.py | 756 | 3.8125 | 4 | import re
print(re.search(r"[a-zA-Z]{5}", "a ghost"))
print(re.search(r"[a-zA-Z]{5}", "a scary ghost appeared"))
print(re.findall(r"[a-zA-Z]{5}", "a scary ghost appeared"))
print(re.findall(r"\b[a-zA-Z]{5}\b", "A scary ghost appeared"))
print(re.findall(r"\w{5,10}", "I really like strawberries"))
print(re.findall(r"\w... |
46cf731f6d28256f3e52114b23946d529a116400 | jems-lee/adventofcode | /2019/day03.py | 2,923 | 3.734375 | 4 | from dataclasses import dataclass
@dataclass
class Point:
x: int
y: int
def __add__(self, other):
return Point(
self.x + other.x,
self.y + other.y
)
def __sub__(self, other):
return Point(
self.x - other.x,
self.y - other.y
... |
237d12a50601b6a5438d63ea9ccb0cbd3de8ff3b | sohom-das/Python-Practice | /LPTHW - Ex17.py | 1,122 | 3.6875 | 4 | from sys import * #importing function from the sys module
from os.path import * #importing function from os.path module
script, from_file, to_file = argv #get argv command line arguments (w... |
fa2856baf58fe22a47c900bba3bd85b5867d0deb | polku/python_stuff | /timeout.py | 935 | 3.625 | 4 | #!/usr/bin/python3
"""
Mechanism to timeout if a function takes too much time
"""
import random
import signal
import time
from functools import wraps
class TimeoutException(Exception):
pass
def sig_handler(signum, frame):
raise TimeoutException()
def timeout(delay):
def timeout_sec(func):
@w... |
07e157319c6c33c155fb096996d0514c365128d8 | kahlb/btce_calcs | /btce_portfolio.py | 1,475 | 4.03125 | 4 | #!/usr/bin/env python2.7
# this software calculates the current value of your portfolio
# author kahlb, ltc donations welcome :) LSRLVCerfwbAxBEyZJ4JtcZPdVwxc4zWs2
fee=0.2
feecalc=1-(fee/100) #makes the fee easier to calc. Just multiply with this value.
currnumber = input("Enter the number of different currencies i... |
d7483fee3f38bcff15ab34d1f5768479f22605c6 | iGoWithYou/Laboratories | /lab1.1.py | 269 | 3.828125 | 4 | # -*- coding: utf-8 -*-
"""
Created on Wed Mar 20 16:01:09 2019
@author: Mati
"""
from math import*
x = 56
z = 0
while x <= 100:
y = 2*(x**2) + 2*x + 2
print('for x = ',x,'function value y = ',y)
x = x+1;
z = z + y;
print('function y total value = ',z) |
0f934c3c6a3429ae1b044ebc04c3e64dcba83c64 | fikrirazor/bigramindo | /tesbigram/testbigram2.py | 611 | 3.640625 | 4 | # -*- coding: utf-8 -*-
"""
Created on Sun Feb 10 23:44:06 2019
@author: Rozan
"""
#countofwords
#menghitung jumlah kata
W = ("saya","makan","nasi","goreng","di","rumah")
jumlahdata = {}
pw=len(W)
for i in range (pw):
if W[i] in jumlahdata:
jumlahdata[W[i]] += 1
else:
jumlahdata[W[i]] = 1
#men... |
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