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mathqa_question_token_drop_test

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twoph train?
"relative speed = ( 126 - 54 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in 27 sec = 14 * 20 = 280 m . the length of the faster train = 280 m . answer : a"
a ) 280 , b ) 290 , c ) 300 , d ) 310 , e ) 320
a
multiply(divide(subtract(126, 54), const_3_6), 14)
subtract(n0,n1)|divide(#0,const_3_6)|multiply(n2,#1)|
physics
if n12?
"there are several algebraic ways to solve this question , but the easiest way is as follows : since we can not have two correct answers just pick a prime greater than 17 , square it and see what would be the remainder upon division of it by 12 . n = 19 - - > n ^ 2 = 361 - - > remainder upon division 361 by 12 is 1 . answer : b ."
a ) 0 , b ) 1 , c ) 2 , d ) 3 , e ) 5
b
subtract(power(add(17, 2), 2), multiply(12, const_4))
add(n0,n1)|multiply(n2,const_4)|power(#0,n1)|subtract(#2,#1)|
general
what the18?
"( 17 ^ 200 - 1 ^ 200 ) is completely divisible by ( 17 + 1 ) as 200 is even . = > ( 17 ^ 200 - 1 ) is completely divisible by 18 . hence , when 17 ^ 200 is divided by 18 , we will get 1 as remainder . answer is b"
a ) 3 , b ) 1 , c ) 2 , d ) 4 , e ) 7
b
subtract(divide(18, const_2), multiply(17, 17))
divide(n2,const_2)|multiply(n0,n0)|subtract(#0,#1)|
general
a two red?
"the area of each half is 100 + 4 ( 450 ) + 100 = 2000 the area that is not painted is 100 . the fraction that is not painted is 100 / 2000 = 1 / 20 = 5 % the answer is a ."
a ) 5 % , b ) 10 % , c ) 15 % , d ) 20 % , e ) 25 %
a
multiply(divide(const_100, add(add(multiply(multiply(const_4, const_100), const_4), const_100), const_100)), const_100)
multiply(const_100,const_4)|multiply(#0,const_4)|add(#1,const_100)|add(#2,const_100)|divide(const_100,#3)|multiply(#4,const_100)|
geometry
after points500?
"( 6 * 75 ) + 47 + x > 500 450 + 47 + x > 500 497 + x > 500 = > x > 3 option d"
a ) 5 , b ) 4 , c ) 7 , d ) 3 , e ) 8
d
subtract(500, add(multiply(6, 75), 47))
multiply(n0,n1)|add(n2,#0)|subtract(n4,#1)|
general
if n?
( 2 ^ 5 ) x ( 6 ) x ( 7 ^ 3 ) has one appearance of 3 ( in the 6 ) and no appearances of 5 . thus n must include at least 3 ^ 2 * 5 ^ 2 = 9 * 25 = 225 the answer is e .
a ) 75 , b ) 125 , c ) 145 , d ) 175 , e ) 225
e
add(add(add(add(add(multiply(multiply(5, 7), 2), multiply(multiply(5, 7), 2)), multiply(multiply(5, 7), 2)), 7), const_4), const_4)
multiply(n0,n7)|multiply(n1,#0)|add(#1,#1)|add(#2,#1)|add(n7,#3)|add(#4,const_4)|add(#5,const_4)
other
a are in?
"b + c 1 day work = 1 / 9 + 1 / 12 = 7 / 36 work done by b and c in 3 days = 7 / 36 * 3 = 7 / 12 remaining work = 1 - 7 / 12 = 5 / 12 1 / 36 work is done by a in 1 day 5 / 12 work is done by a in 36 * 5 / 12 = 15 days answer is a"
a ) 15 days , b ) 12 days , c ) 6 days , d ) 7 days , e ) 8 days
a
multiply(divide(const_1, add(divide(const_1, 9), divide(const_1, 2))), 3)
divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|divide(const_1,#2)|multiply(n3,#3)|
physics
there last pole.
"assuming the car starts at the first pole . to reach the 12 th pole , the car need to travel 11 poles ( the first pole does n ' t count , as the car is already there ) . 11 poles 26 seconds 1 pole ( 26 / 11 ) seconds to reach the last ( 20 th ) pole , the car needs to travel 19 poles . 19 pole 19 x ( 26 / 11 ) seconds = 44.9091 seconds answer : b"
a ) 44.4543 , b ) 44.9091 , c ) 44.95128 , d ) 44.91288 , e ) 44.91222
b
multiply(divide(26, 12), 20)
divide(n1,n2)|multiply(n0,#0)|
physics
p c have?
"p = ( 2 / 5 ) * p + 21 ( 3 / 5 ) * p = 21 p = 35 the answer is a ."
a ) $ 35 , b ) $ 36 , c ) $ 37 , d ) $ 38 , e ) $ 39
a
divide(21, subtract(1, multiply(divide(1, 5), const_2)))
divide(n1,n2)|multiply(#0,const_2)|subtract(n1,#1)|divide(n0,#2)|
general
a how box?
"the number of chocolate bars is equal to 18 ? 25 = 450 correct answer c"
a ) 350 , b ) 250 , c ) 450 , d ) 550 , e ) 650
c
multiply(18, 25)
multiply(n0,n1)|
general
becausey rate?
"say morks income is - 100 so tax paid will be 40 say mindys income is 5 * 100 = 500 so tax paid is 30 % * 500 = 150 total tax paid = 40 + 150 = 190 . combined tax % will be 190 / 100 + 500 = 31.67 %"
a ) 32.5 % , b ) 34 % , c ) 35 % , d ) 31.67 % , e ) 37.5 %
d
multiply(const_100, divide(add(divide(40, const_100), multiply(5, divide(30, const_100))), add(const_1, 5)))
add(n2,const_1)|divide(n0,const_100)|divide(n1,const_100)|multiply(n2,#2)|add(#1,#3)|divide(#4,#0)|multiply(#5,const_100)|
gain
if what =?
"solution : p ( a ∪ b ) = p ( a ) + p ( b ) - p ( a ∩ b ' ) = > 0.8 = 0.4 - p ( a ∩ b ) = > p ( a ∩ b ) = 0.2 p ( a ∩ b ' ) = p ( a ) - p ( a ∩ b ) = 0.4 - 0.2 = 0.2 answer b"
a ) 0.1 , b ) 0.2 , c ) 0.3 , d ) 0.4 , e ) none
b
multiply(multiply(0.4, 0.8), const_10)
multiply(n0,n2)|multiply(#0,const_10)|
general
a. is?
"ratio of investments of a and b is ( 70000 * 12 ) : ( 120000 * 6 ) = 7 : 6 total profit = rs . 26000 share of b = 6 / 13 ( 26000 ) = rs . 12000 answer : b"
a ) s . 12028 , b ) s . 12000 , c ) s . 12003 , d ) s . 12029 , e ) s . 24029
b
subtract(26000, multiply(const_60, const_100))
multiply(const_100,const_60)|subtract(n3,#0)|
gain
find 21.
"sol . on dividing 3105 by 21 , we get 18 as remainder . number to be added to 3105 = ( 21 - 18 ) - 3 . hence , required number = 3105 + 3 = 3108 . option b"
a ) 1208 , b ) 3108 , c ) 241 , d ) 217 , e ) 3147
b
add(3105, subtract(21, reminder(3105, 21)))
reminder(n0,n1)|subtract(n1,#0)|add(n0,#1)|
general
evaluate x 764
"980 x 436 + 980 x 764 = 986 x ( 436 + 664 ) = 986 x 1200 = 117600 . answer is a ."
a ) 1176000 , b ) 968000 , c ) 978000 , d ) 117000 , e ) none of them
a
subtract(980, multiply(multiply(436, 980), 764))
multiply(n1,n2)|multiply(n3,#0)|subtract(n0,#1)|
general
how have?
you have 40 multiples of 5 , 8 of 25 and 1 of 125 . this will give 49 zeros . c
a ) 40 , b ) 48 , c ) 49 , d ) 55 , e ) 64
c
add(divide(200, add(const_4, const_1)), divide(200, multiply(add(const_4, const_1), add(const_4, const_1))))
add(const_1,const_4)|divide(n0,#0)|multiply(#0,#0)|divide(n0,#2)|add(#1,#3)|
other
a crosses is :
distance covered in ( 9 × 1000 ) / ( 3600 ) × 12 = 30 m diagonal of squarre field = 30 m . area of square field = 30 ( power ) 2 / 2 = 900 / 2 = 450 sq . m answer is c .
['a ) 430 sq . m', 'b ) 425 sq . m', 'c ) 450 sq . m', 'd ) 475 sq . m', 'e ) 350 sq . m']
c
divide(multiply(multiply(12, divide(multiply(9, const_1000), multiply(const_360, const_10))), multiply(12, divide(multiply(9, const_1000), multiply(const_360, const_10)))), const_2)
multiply(n0,const_1000)|multiply(const_10,const_360)|divide(#0,#1)|multiply(n1,#2)|multiply(#3,#3)|divide(#4,const_2)
geometry
x not?
"p ( x is prime ) = 1 / 3 p ( y is prime ) = 1 / 4 if y is prime , then z is not prime since y and z are unique . then the probability is 1 / 3 * 1 / 4 = 1 / 12 the answer is d ."
a ) 1 / 5 , b ) 3 / 20 , c ) 2 / 15 , d ) 1 / 12 , e ) 1 / 10
d
multiply(divide(const_1, const_2), divide(const_1, const_4))
divide(const_1,const_2)|divide(const_1,const_4)|multiply(#0,#1)|
probability
what 9?
"27 , 36 , 45 , . . . , 90,99 this is an equally spaced list ; you can use the formula : n = ( largest - smallest ) / ( ' space ' ) + 1 = ( 99 - 27 ) / ( 9 ) + 1 = 8 + 1 = 9 answer is e"
a ) 5 , b ) 15 , c ) 12 , d ) 7 , e ) 9
e
add(divide(subtract(100, 20), 9), const_1)
subtract(n1,n0)|divide(#0,n2)|add(#1,const_1)|
general
theradius the triangle
"explanation : area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 40 / 2 = 50 cm 2 answer : option c"
a ) a ) 72 , b ) b ) 828 , c ) c ) 50 , d ) d ) 34 , e ) e ) 35
c
triangle_area(2.5, 40)
triangle_area(n0,n1)|
geometry
the it by?
answer let original price = rs . 100 . then , new price = rs . 90 . ∴ increased on rs . 90 = rs . 10 required increase % = ( 10 x 100 ) / 90 % = 111 / 9 % correct option : c
a ) 10 % , b ) 9 1 / 11 , c ) 11 1 / 9 , d ) 11 % , e ) none of these
c
add(subtract(const_100, subtract(const_100, 10)), const_2)
subtract(const_100,n0)|subtract(const_100,#0)|add(#1,const_2)
gain
the4 occur?
p ( a or b ) = p ( a ) + p ( b ) - p ( a n b ) 0.4 = 0.6 + p ( a ) - 0.25 p ( a ) = 0.05 ans : a
a ) 0.05 , b ) 0.15 , c ) 0.45 , d ) 0.5 , e ) 0.55
a
subtract(add(0.25, 0.4), 0.6)
add(n1,n2)|subtract(#0,n0)
other
if many have?
since 2 xy prime e factors are x ^ 1 * y ^ 1 * 2 ^ 1 , its total number or factors must be ( 1 + 1 ) ( 1 + 1 ) ( 1 + 1 ) = 2 ^ 3 = 8 . thus , i think d would be the correct answer .
a ) 3 , b ) 4 , c ) 6 , d ) 8 , e ) 12
d
multiply(multiply(2, add(const_1, const_1)), add(const_1, const_1))
add(const_1,const_1)|multiply(n0,#0)|multiply(#0,#1)|
other
in or chosen?
two ways . . . 1 ) total ways = 10 c 3 = 10 ! / 7 ! 3 ! = 120 . . ways without python developer = 6 c 3 = 6 ! / 3 ! 3 ! = 20 . . ways of at least one python developer = 120 - 20 = 100 . . 2 ) ways of selecting only one = 4 * 6 c 2 = 4 * 15 = 60 . . ways of selecting only two = 4 c 2 * 6 c 1 = 6 * 6 = 36 . . ways of selecting all three = 4 c 3 = 4 = 4 . . total = 60 + 36 + 4 = 100 . . . answer : a
a ) 100 , b ) 40 , c ) 66 , d ) 80 , e ) 75
a
subtract(divide(factorial(10), multiply(factorial(subtract(10, 3)), factorial(3))), divide(factorial(subtract(10, 4)), multiply(factorial(3), factorial(3))))
factorial(n0)|factorial(n2)|subtract(n0,n2)|subtract(n0,n1)|factorial(#2)|factorial(#3)|multiply(#1,#1)|divide(#5,#6)|multiply(#4,#1)|divide(#0,#8)|subtract(#9,#7)
other
a the %.
"his percentage gain is 100 * 80 / 920 as he is gaining 80 units for his purchase of 920 units . so 8.69 % . answer : e"
a ) 5.26 % , b ) 5.36 % , c ) 4.26 % , d ) 6.26 % , e ) 8.69 %
e
multiply(subtract(inverse(divide(920, multiply(multiply(add(const_4, const_1), const_2), const_100))), const_1), const_100)
add(const_1,const_4)|multiply(#0,const_2)|multiply(#1,const_100)|divide(n0,#2)|inverse(#3)|subtract(#4,const_1)|multiply(#5,const_100)|
gain
5 percentage percentage as
"explanation : while calculation in terms of percentage we need to multiply by 100 , so 5.40 * 100 = 540 answer : option d"
a ) 5.04 % , b ) 50.4 % , c ) 209 % , d ) 540 % , e ) none of these
d
multiply(5.40, const_100)
multiply(n0,const_100)|
general
a2000?
"for retail price = $ 25 first maximum discounted price = 25 - 30 % of 25 = 25 - 7.5 = 17.5 price after additional discount of 20 % = 17.5 - 20 % of 17.5 = 17.5 - 3.5 = 14 answer : option a"
a ) $ 14.00 , b ) $ 11.20 , c ) $ 14.40 , d ) $ 16.00 , e ) $ 18.00
a
multiply(divide(subtract(const_100, 20), const_100), multiply(divide(subtract(const_100, 30), const_100), 25.00))
subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(n3,#3)|multiply(#2,#4)|
gain
a result mistake.
lets take a number 20 20 / 5 = 4 20 * 5 = 100 diff = 100 - 4 = 96 % answer : a
a ) 96 % , b ) 95 % , c ) 2400 % , d ) 200 % , e ) 400 %
a
multiply(subtract(multiply(5, 5), const_1), divide(const_100, multiply(5, 5)))
multiply(n0,n0)|divide(const_100,#0)|subtract(#0,const_1)|multiply(#1,#2)
general
the of term.
explanation : let the fourth term be x . thus 56 , 16 , 49 , x are in proportion . product of extreme terms = 56 x product of mean terms = 16 x 49 since , the numbers make up a proportion therefore , 56 x = 16 49 or , x = ( 16 49 ) / 56 or , x = 14 therefore , the fourth term of the proportion is 14 . answer : b
a ) 10 , b ) 14 , c ) 40 , d ) 50 , e ) 60
b
divide(multiply(49, 16), 56)
multiply(n1,n2)|divide(#0,n0)
physics
during percent shoes?
"assume the price = 100 price during sale = 90 price after sale = 100 percent increase = 10 / 90 * 100 = 11 % approx . correct option : c"
a ) 9 % , b ) 10 % , c ) 11 % , d ) 15 % , e ) 90 %
c
divide(multiply(10, const_100), subtract(const_100, 10))
multiply(n0,const_100)|subtract(const_100,n0)|divide(#0,#1)|
gain
she8 hour?
"explanation : total hours worked = 8 x 3 + 6 x 2 = 36 total earned = 324 . hourly wage = 324 / 36 = 9 answer : c ) 9"
a ) 2 , b ) 8 , c ) 9 , d ) 1 , e ) 2
c
divide(324, add(multiply(8, const_3), multiply(6, const_2)))
multiply(n0,const_3)|multiply(n1,const_2)|add(#0,#1)|divide(n2,#2)|
physics
d31 93
solution : both fractions should be reduced before performing arithmetic operations . we get 3 * 27 / 31 + 3.27 / 3.31 = 3 * 27 / 31 + 27 / 31 = 4 * 27 / 31 = 151 / 31 answer d
a ) 0 , b ) 156 / 31 , c ) 123 / 31 , d ) 151 / 31 , e ) none
d
divide(add(subtract(add(81, multiply(27, 3)), subtract(93, 81)), const_1), 31)
multiply(n0,n1)|subtract(n4,n3)|add(n3,#0)|subtract(#2,#1)|add(#3,const_1)|divide(#4,n2)
general
in gers?
"1 . we are given the following percentages : 30 ( 70 ) , 40 ( 60 ) , 25 ( 75 ) . there are two threads from here . first starts at 30 % and finishes there . second one starts at 70 , then 40 , and then 25 . we need a value that is divisible by 7 , 2 , and 5 at least once . lets pick a number now , say 700 . so say if non hawks are 700 ( this is 70 % of the total , so total = 1000 ) , then paddy warbs are 2 / 5 x 700 = 1400 / 5 = 280 . kingfishers , therefore , are 280 / 4 = 70 . lets add them up . 300 hawks + 280 peddy warbs + 70 kingsifhers = 650 . so all others are 1000 - 650 = 350 or 35 % of total birds . the main job here to to identify the smart number to start the question with . this can be time consuming , but once identified , this question can be solved fairly quickly . 2 . another method : if x is total - - > non hawks = 0.7 x - - > warbs = 0.4 ( 0.7 x ) - - > kfs = 0.25 ( 0.4 ( 0.7 x ) ) . our job is to find out e : ( 0.3 x + 0.28 x + 0.07 x ) / x . or 0.65 x / x = 0.65 . we need to find 1 - 0.65 = 0.35 or 35 % . b"
a ) 25 % , b ) 35 % , c ) 45 % , d ) 70 % , e ) 80 %
b
add(const_10, divide(add(25, 25), const_2))
add(n2,n2)|divide(#0,const_2)|add(#1,const_10)|
general
what110?
or u can just use the answer choices here . since the answers are already arranged in ascending order , the first number which gives remainder t as 1 for all three is the correct answer . in the given question , the first number which gives a remainder of 1 for 6,8 and 10 is 121 . c
a ) 21 , b ) 41 , c ) t = 121 , d ) 241 , e ) 481
c
add(lcm(lcm(6, 8), 10), 1)
lcm(n2,n3)|lcm(n4,#0)|add(n0,#1)
general
aph platform?
"e 250 e = 72 * 5 / 18 = 20 = 400 â € “ 150 = 250"
a ) 443 m , b ) 354 m , c ) 450 m , d ) 350 m , e ) 250 m
e
subtract(multiply(20, multiply(72, const_0_2778)), 150)
multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)|
physics
in i ages?
e their ages were respectively 58 and 28
a ) 60 and 23 , b ) 66 and 25 , c ) 29 and 56 , d ) 71 and 43 , e ) 58 and 28
e
divide(divide(multiply(1624, 30), const_4), const_2)
multiply(n0,n1)|divide(#0,const_4)|divide(#1,const_2)
general
the, is :
lcm = 72 72 - 1 = 71 answer : a
a ) 71 , b ) 70 , c ) 72 , d ) 73 , e ) 36
a
subtract(lcm(24, 36), 1)
lcm(n3,n4)|subtract(#0,n0)
general
a a?
"cp = 135 * 15 = 2025 and sp = 115 * 18 = 2070 gain % = 100 * ( 2070 - 2025 ) / 2025 = 20 / 9 answer : c"
a ) 40 , b ) 30 / 11 , c ) 20 / 9 , d ) 27 / 11 , e ) 29 / 8
c
multiply(divide(subtract(multiply(115, 18), multiply(135, 15)), multiply(135, 15)), const_100)
multiply(n2,n3)|multiply(n0,n1)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100)|
gain
the the1?
"let initial price be 100 price in day 1 after 3 % discount = 97 price in day 2 after 3 % discount = 94.09 price in day 3 after 10 % discount = 84.68 so , price in day 3 as percentage of the sale price on day 1 will be = 84.68 / 97 * 100 = > 87.3 % answer will definitely be ( c )"
a ) 85.1 % , b ) 86.9 % , c ) 87.3 % , d ) 88.8 % , e ) 89.5 %
c
add(multiply(divide(divide(10, const_100), subtract(1, divide(1, 3))), const_100), 2)
divide(n5,const_100)|divide(n1,n0)|subtract(n1,#1)|divide(#0,#2)|multiply(#3,const_100)|add(n2,#4)|
gain
the pencils pencils?
"number of pens = 1200 number of pencils = 820 required number of students = h . c . f . of 1200 and 820 = 20 answer is b"
a ) 40 , b ) 20 , c ) 60 , d ) 80 , e ) 65
b
gcd(1200, 820)
gcd(n0,n1)|
general
in a pond?
this is a rather straight forward ratio problem . 1 . 80 fish tagged 2 . 2 out of the 50 fish caught were tagged thus 2 / 50 2 / 50 = 80 / x thus , x = 2000 think of the analogy : 2 fish is to 50 fish as 50 fish is to . . . ? you ' ve tagged 50 fish and you need to find what that comprises as a percentage of the total fish population - we have that information with the ratio of the second catch . d
a ) 400 , b ) 625 , c ) 1,250 , d ) 2,000 , e ) 10,000
d
divide(80, divide(2, 50))
divide(n2,n1)|divide(n0,#0)
gain
r many contain?
"r is the set of positive odd integers less than 100 , and s is the set of the squares of the integers in r . how many elements does the intersection of r and s contain ? r = 1,3 , 5,7 , 9,11 , 13,15 . . . s = 1 , 9,25 , 49,81 . . . numbers : 1 , 9 , 25 , 49 , and 81 are odd integers ( less than 100 ) that are in both sets . solution : five answer : d"
a ) none , b ) two , c ) four , d ) five , e ) seven
d
subtract(subtract(100, const_4), const_4)
subtract(n0,const_4)|subtract(#0,const_4)|
physics
a a price?
"let the list price be 2 x for min sale price , the first discount given should be 50 % , 2 x becomes x here now , during summer sale additional 20 % off is given ie sale price becomes 0.8 x it is given lise price is $ 80 = > 2 x = 80 = > x = 40 and 0.8 x = 32 so lowest sale price is 32 , which w is 40 % of 80 hence , d is the answer"
a ) 20 , b ) 25 , c ) 30 , d ) 40 , e ) 50
d
divide(80, const_2)
divide(n3,const_2)|
general
a2 m?
"28 * 2 * 0.75 = 20 / 100 * 10 / 100 * 7.5 / 100 * x 28 = 1 / 100 * x = > x = 28000 answer : a"
a ) 28000 , b ) 27908 , c ) 78902 , d ) 25000 , e ) 27991
a
divide(divide(divide(multiply(multiply(multiply(28, const_100), multiply(2, const_100)), multiply(0.75, const_100)), 20), 10), 7.5)
multiply(n3,const_100)|multiply(n4,const_100)|multiply(n5,const_100)|multiply(#0,#1)|multiply(#3,#2)|divide(#4,n0)|divide(#5,n1)|divide(#6,n2)|
physics
an find percentage?
"explanation : the difference of two successive amounts must be the simple interest in 1 year on the lower amount of money . s . i = 20286 / - - 17640 / - = rs . 2646 / - rate of interest = ( 2646 / 17640 ) × ( 100 / 1 ) = > 15 % answer : option d"
a ) 5 % , b ) 7 % , c ) 9 % , d ) 15 % , e ) 12 %
d
multiply(divide(subtract(20286, 17640), 17640), const_100)
subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)|
general
d rate.?
let the rate be x , then population of the bacteria after each hour can be given as 600,600 x , 600 ( x ^ 2 ) , 600 ( x ^ 3 ) now population at 4 pm = 4800 thus we have 600 ( x ^ 3 ) = 4800 = 8 thus x = 2 therefore population at 3 pm = 600 ( 4 ) = 2400 answer : a
a ) 2400 , b ) 3600 , c ) 3000 , d ) 2800 , e ) 2500
a
multiply(multiply(power(divide(multiply(multiply(2, 4), 600), 600), const_0_33), 600), power(divide(multiply(multiply(2, 4), 600), 600), const_0_33))
multiply(n2,n4)|multiply(n1,#0)|divide(#1,n1)|power(#2,const_0_33)|multiply(n1,#3)|multiply(#4,#3)
physics
5 b is?
solution 5 years ago average age of a , b , c , d = 45 years = > 5 years ago total age of a , b , c , d = 45 x 4 = 180 years = > total present age of a , b , c , d = 180 + 5 x 4 = 200 years if e ' s present age is x years = 200 + x / 5 = 50 x = 50 years . answer a
a ) 50 , b ) 47 , c ) 48 , d ) 49 , e ) 46
a
subtract(multiply(50, 5), add(multiply(45, multiply(const_2, const_2)), multiply(5, const_4)))
multiply(n0,n3)|multiply(const_2,const_2)|multiply(n0,const_4)|multiply(n1,#1)|add(#3,#2)|subtract(#0,#4)
general
s what book?
"average price per book = ( 1180 + 860 ) / ( 65 + 55 ) = 2040 / 120 = $ 17 the answer is c ."
a ) $ 13 , b ) $ 15 , c ) $ 17 , d ) $ 19 , e ) $ 21
c
divide(add(1180, 860), add(65, 55))
add(n1,n3)|add(n0,n2)|divide(#0,#1)|
general
there in rocks?
"total no of rocks = 45 probability of choosing 1 st slate rock = 15 / 45 probability of choosing 2 nd slate rock = 14 / 44 ( without replacement ) so combined probability = 15 / 45 * 14 / 44 = 7 / 66 so , answer d ."
a ) 1 / 3 , b ) 7 / 22 , c ) 1 / 9 , d ) 7 / 66 , e ) 2 / 45
d
multiply(divide(15, add(add(15, 20), 10)), divide(subtract(15, const_1), subtract(add(add(15, 20), 10), const_1)))
add(n0,n1)|subtract(n0,const_1)|add(n2,#0)|divide(n0,#2)|subtract(#2,const_1)|divide(#1,#4)|multiply(#3,#5)|
other
a a filled?
"net part filled in 1 hour 1 / 4 - 1 / 9 = 5 / 36 the cistern will be filled in 36 / 5 hr = 7.2 hr answer is d"
a ) 6 hr , b ) 5.6 hr , c ) 9.5 hr , d ) 7.2 hr , e ) 4 hr
d
divide(const_1, subtract(divide(const_1, 4), divide(const_1, 9)))
divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)|
physics
approximately are deep?
"answer should be e . v = \ pir ^ 2 h = \ pi * 20 ^ 2 * 7 = approximately 9000"
a ) 700 , b ) 1500 , c ) 3000 , d ) 5000 , e ) 9000
e
volume_cylinder(divide(40, const_2), 7)
divide(n0,const_2)|volume_cylinder(#0,n1)|
geometry
in if single?
"let assume there are 100 students of which 70 are male and 30 are females if 40 are married then 60 will be single . now its given that two - sevenths of the male students are married that means 2 / 7 of 70 = 20 males are married if 40 is the total number of students who are married and out of that 20 are males then the remaining 20 will be females who are married . total females = 30 married females = 20 then single females = 30 - 20 = 10 we need to find the fraction of female students who are single i . e single female students / total female student = 10 / 30 = 1 / 3 [ e ]"
a ) 2 / 7 , b ) 5 / 3 , c ) 1 / 2 , d ) 2 / 3 , e ) 1 / 3
e
divide(const_10, 40)
divide(const_10,n1)|
gain
(1 k?
"expanding we have 6 x ^ 2 - 3 x + 4 x - 2 6 x ^ 2 + x - 2 taking coefficients , a = 6 , k = 1 , n = - 2 therefore a - n + k = 6 - ( - 2 ) + 1 = 8 + 1 = 9 the answer is c ."
a ) 5 , b ) 8 , c ) 9 , d ) 10 , e ) 11
c
add(add(multiply(3, 2), multiply(1, 2)), subtract(multiply(2, 2), multiply(1, 3)))
multiply(n0,n1)|multiply(n1,n3)|multiply(n1,n1)|multiply(n0,n3)|add(#0,#1)|subtract(#2,#3)|add(#4,#5)|
general
a sells originally?
"60 % of oranges = 600 100 % of oranges = ( 600 × 100 ) / 6 = 1000 total oranges = 1000 answer : c"
a ) 700 , b ) 710 , c ) 1000 , d ) 730 , e ) 740
c
add(600, multiply(600, divide(40, const_100)))
divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)|
gain
if cm area?
"the triangle with sides 196 cm , 81 cm and 277 cm is right angled , where the hypotenuse is 277 cm . area of the triangle = 1 / 2 * 81 * 196 = 7938 cm 2 answer : option e"
a ) 5000 , b ) 5656 , c ) 7878 , d ) 7900 , e ) 7938
e
divide(multiply(81, 277), const_2)
multiply(n1,n2)|divide(#0,const_2)|
geometry
what6070?
so addition of all term - 10 , 20 , 30 , . . . . . . . 90 so average = ( 10 + 20 + 30 + 40 + 50 + 60 + 70 + 80 + 90 ) / 9 = ( 450 ) / 9 = 50 hence , the correct answer is e .
a ) 90 , b ) 95 , c ) 70 , d ) 85 , e ) 50
e
subtract(divide(add(add(add(add(10, 2030), 4050), 6070), 8090), add(const_4, const_1)), multiply(multiply(const_100, const_10), const_4))
add(n0,n1)|add(const_1,const_4)|multiply(const_10,const_100)|add(n2,#0)|multiply(#2,const_4)|add(n3,#3)|add(n4,#5)|divide(#6,#1)|subtract(#7,#4)
general
a is current?
"100 - - - 10 ds = 10 ? - - - - 1 30 - - - - 10 us = 3 ? - - - - 1 s = ? s = ( 10 - 3 ) / 2 = 3.5 answer : b"
a ) 2.5 , b ) 3.5 , c ) 4.5 , d ) 5.3 , e ) 3.4
b
divide(add(divide(30, 10), divide(100, 10)), const_2)
divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)|
physics
the breadth plot?
"let the breadth of the plot be b m . length of the plot = 3 b m ( 3 b ) ( b ) = 1323 3 b 2 = 1323 b 2 = 441 = 21 ( b > 0 ) b = 21 m . answer : d"
a ) 11 , b ) 17 , c ) 18 , d ) 21 , e ) 1322
d
sqrt(divide(1323, const_3))
divide(n0,const_3)|sqrt(#0)|
geometry
after. inches?
"let initial volume of ice be = x ice remaining after 1 hour = x - 0.75 x = 0.25 x ice remaining after 2 hour = ( 1 / 4 ) x - ( 3 / 4 * 1 / 4 * x ) = ( 1 / 16 ) x ( 1 / 16 ) x = 0.3 x = 4.8 alternate solution : try to backsolve . initial volume = 4.8 after one hour - - > ( 1 / 4 ) 4.8 = 1.2 after two hours - - > ( 1 / 4 ) 1.2 = 0.3 answer : c"
a ) 2.5 , b ) 3.0 , c ) 4.8 , d ) 6.5 , e ) 8.0
c
divide(divide(0.3, const_0_25), const_0_25)
divide(n4,const_0_25)|divide(#0,const_0_25)|
physics
the perimeter triangle?
"area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 3.5 * 22 / 2 = 38.5 cm 2 answer : e"
a ) 22 , b ) 35 , c ) 77 , d ) 54 , e ) 38
e
triangle_area(3.5, 22)
triangle_area(n0,n1)|
geometry
for a group?
"index for females = ( 20 - 6 ) / 20 = 7 / 10 = 0.7 index for males = ( 20 - 14 / 20 = 3 / 10 = 0.3 index for females exceeds males by 0.7 - 0.3 = 0.4 answer : a"
a ) 0.4 , b ) 0.0625 , c ) 0.2 , d ) 0.25 , e ) 0.6
a
subtract(divide(subtract(20, 6), 20), divide(6, 20))
divide(n1,n0)|subtract(n0,n1)|divide(#1,n0)|subtract(#2,#0)|
general
x work?
"x ' s 1 day ' s work = 1 / 40 y ' s 1 day ' s work = 1 / 60 ( x + y ) ' s 1 day ' s work = ( 1 / 40 + 1 / 60 ) = 1 / 24 both together will finish the work in 24 days . correct option is c"
a ) 10 , b ) 12 , c ) 24 , d ) 30 , e ) 15
c
inverse(add(divide(const_1, 40), divide(const_1, 60)))
divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)|
physics
the12?
"let the number be xy . given xy – yx = 36 . this means the number is greater is than the number got on reversing the digits . this shows that the ten ’ s digit x > unit digit y . also given ratio between digits is 1 : 2 = > x = 2 y ( 10 x + y ) – ( 10 y + x ) = 36 = > x – y = 4 = > 2 y – y = 4 . hence , ( x + y ) – ( x – y ) = 3 y – y = 2 y = 8 b"
a ) 6 , b ) 8 , c ) 10 , d ) 14 , e ) 15
b
multiply(divide(36, subtract(multiply(subtract(const_10, 1), multiply(2, 1)), subtract(const_10, 1))), 2)
multiply(n0,n2)|subtract(const_10,n2)|multiply(#0,#1)|subtract(#2,#1)|divide(n1,#3)|multiply(#4,n0)|
general
7 would days?
explanation : solution : let the required number of carpets be x . more weavers , more carpets ( direct proportion ) more days , more carpets ( direct proportion ) weavers 7 : 14 } : : 7 : x days 7 : 14 . ' . 7 * 7 * x = 14 * 14 * 7 < = > x = 14 * 14 * 7 / 7 * 7 = 28 . answer : b
a ) 14 , b ) 28 , c ) 21 , d ) 35 , e ) none of these
b
add(14, add(7, 7))
add(n0,n0)|add(n3,#0)
gain
what rows / hr
"sol . speed of stream = 1 / 2 ( 12 - 6 ) kmph = 3 kmph . answer c"
a ) 1 kmph , b ) 4 kmph , c ) 3 kmph , d ) 2 kmph , e ) 1.9 kmph
c
divide(subtract(12, 6), const_2)
subtract(n1,n0)|divide(#0,const_2)|
physics
a income save?
i year best is to give a number to his income , say 100 . . and let saving be x . . so expenditure = 100 - x next year - income = 140 savings = 2 x expenditure = 140 - 2 x . . now 140 - 2 x + 100 - x = 2 ( 100 - x ) . . . 240 - 3 x = 200 - 2 x . . . . . . . . . . . . . . . . x = 40 . . . saving % = 40 / 100 * 100 = 40 % answer : b
a ) 45 % , b ) 40 % , c ) 25 % , d ) 28 % , e ) 33.33 %
b
multiply(divide(subtract(add(add(100, 40), 100), multiply(2, 100)), const_100), const_100)
add(n0,n1)|multiply(n1,n2)|add(n1,#0)|subtract(#2,#1)|divide(#3,const_100)|multiply(#4,const_100)
general
a of platform?
"speed = 54 * 5 / 18 = 15 m / sec . length of the train = 15 * 20 = 300 m . let the length of the platform be x m . then , ( x + 300 ) / 40 = 15 = > x = 180 m answer : c"
a ) 615 m , b ) 240 m , c ) 180 m , d ) 197 m , e ) 691 m
c
multiply(20, multiply(54, const_0_2778))
multiply(n2,const_0_2778)|multiply(n1,#0)|
physics
speed. is?
"speed upstream = 8.5 kmph speed downstream = 11.5 kmph total time taken = 105 / 8.5 + 105 / 11.5 = 21.48 hours answer is b"
a ) 20.48 hours , b ) 21.48 hours , c ) 22.48 hours , d ) 23.48 hours , e ) 24.48 hours
b
add(multiply(add(add(10, 1.5), subtract(10, 1.5)), 105), multiply(subtract(add(divide(105, add(10, 1.5)), divide(105, subtract(10, 1.5))), add(add(10, 1.5), subtract(10, 1.5))), const_60))
add(n0,n1)|subtract(n0,n1)|add(#0,#1)|divide(n2,#0)|divide(n2,#1)|add(#3,#4)|multiply(n2,#2)|subtract(#5,#2)|multiply(#7,const_60)|add(#6,#8)|
physics
a. sell?
"let # plain cookies sold be x then # chocolate cookies = ( total cookies - x ) equating for x ( 0.75 ) * x + ( 1.25 ) * ( 1585 - x ) = 1587.75 = > x = 787 e"
a ) 0 , b ) 233 , c ) 500 , d ) 695 , e ) 787
e
divide(add(const_1000, 587.75), const_2)
add(n4,const_1000)|divide(#0,const_2)|
other
find the as remainder
"let the smaller number be x . then larger number = ( x + 1365 ) . x + 1365 = 6 x + 10 5 x = 1355 x = 271 large number = 271 + 1365 = 1636 a"
a ) 1636 , b ) 1346 , c ) 1378 , d ) 1635 , e ) 1489
a
multiply(divide(subtract(1365, 10), subtract(6, const_1)), 6)
subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)|
general
two la inspector?
widgets inspected by lauren : ( ( 95 - 5 ) / 5 ) + 1 = 18 + 1 = 19 widgets inspected by steven : ( ( 96 - 4 ) / 4 ) + 1 = 23 + 1 = 24 widgets inspected by both : ( ( 96 / 12 ) + 1 = 9 total : 19 + 24 - 9 = 34 hence , widgets not inspected : 98 - 34 = 64 option d
a ) 66 , b ) 68 , c ) 70 , d ) 64 , e ) 72
d
subtract(98, subtract(add(floor(divide(98, add(const_4, const_1))), floor(divide(98, const_4))), floor(divide(98, add(const_10, add(const_4, const_1))))))
add(const_1,const_4)|divide(n0,const_4)|add(#0,const_10)|divide(n0,#0)|floor(#1)|divide(n0,#2)|floor(#3)|add(#6,#4)|floor(#5)|subtract(#7,#8)|subtract(n0,#9)
other
what 19?
"on dividing 3000 by 19 , we get 17 as remainder .  number to be added = ( 19 - 17 ) = 2 . answer a 2"
a ) 2 , b ) 1 , c ) 4 , d ) 18 , e ) 17
a
subtract(multiply(add(multiply(const_4, const_10), const_2), 19), 3000)
multiply(const_10,const_4)|add(#0,const_2)|multiply(n1,#1)|subtract(#2,n0)|
general
the4 occur?
"p ( a or b ) = p ( a ) + p ( b ) - p ( a n b ) 0.6 = 0.4 + p ( b ) - 0.45 p ( b ) = 0.55 ans : e"
a ) 0.05 , b ) 0.15 , c ) 0.45 , d ) 0.5 , e ) 0.55
e
subtract(add(0.6, 0.45), 0.4)
add(n1,n2)|subtract(#0,n0)|
other
the is :
"speed = [ 36 x 5 / 18 ] m / sec = 10 m / sec time = 45 sec let the length of bridge be x metres . then , ( 130 + x ) / 45 = 10 = > 130 + x = 450 = > x = 320 m . answer : a"
a ) 320 m , b ) 225 m , c ) 245 m , d ) 250 m , e ) 240 m
a
subtract(multiply(divide(multiply(36, speed(const_1000, const_1)), speed(const_3600, const_1)), 45), 130)
speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)|
physics
the speed hours?
"total distance travelled in 12 hours = ( 35 + 37 + 39 + . . . upto 12 terms ) . this is an a . p . with first term , a = 35 , number of terms , n = 12 , common difference d = 2 required distance = 12 / 2 ( 2 * 35 + ( 12 - 1 ) * 2 ) = 6 ( 70 + 22 ) = 552 km . correct option : c"
a ) 456 kms , b ) 482 kms , c ) 552 kms , d ) 556 kms , e ) none of these
c
multiply(add(multiply(2, 35), multiply(subtract(12, const_1), 2)), divide(12, 2))
divide(n2,n0)|multiply(n0,n1)|subtract(n2,const_1)|multiply(n0,#2)|add(#1,#3)|multiply(#4,#0)|
physics
evaluate : =?
"according to order of operations , 24 ? 3 ? 10 ( division and multiplication ) is done first from left to right 24 / 2 = 8 * 10 = 80 hence 11110 + 24 * 3 * 10 = 11110 + 80 = 11190 correct answer c"
a ) 90111 , b ) 52631 , c ) 11190 , d ) 65321 , e ) 11133
c
subtract(11110, multiply(multiply(24, 3), 10))
multiply(n1,n2)|multiply(n3,#0)|subtract(n0,#1)|
general
mar15 candidates?
"360 . answer d"
a ) 720 , b ) 120 , c ) 300 , d ) 360 , e ) 333
d
subtract(subtract(subtract(divide(divide(divide(factorial(15), factorial(subtract(15, 3))), factorial(3)), const_2), 15), 15), const_10)
factorial(n0)|factorial(n1)|subtract(n0,n1)|factorial(#2)|divide(#0,#3)|divide(#4,#1)|divide(#5,const_2)|subtract(#6,n0)|subtract(#7,n0)|subtract(#8,const_10)|
physics
what,5?
"explanation : 2356 6532 - - - - - - - - - - - - 4176 answer : b"
a ) 6084 , b ) 4176 , c ) 2077 , d ) 2721 , e ) 1812
b
subtract(add(add(add(multiply(multiply(6, const_100), const_10), multiply(5, const_100)), multiply(3, const_10)), 2), add(add(add(const_1000, multiply(3, const_100)), multiply(5, const_10)), 6))
multiply(n0,const_100)|multiply(n3,const_100)|multiply(n1,const_10)|multiply(n1,const_100)|multiply(n3,const_10)|add(#3,const_1000)|multiply(#0,const_10)|add(#6,#1)|add(#5,#4)|add(#7,#2)|add(n0,#8)|add(n2,#9)|subtract(#11,#10)|
general
a money years.
( 1000 xtx 4 / 100 ) + ( 1400 xtx 5 / 100 ) = 350 â † ’ t = 3.2 answer a
a ) 3.2 , b ) 3.75 , c ) 4 , d ) 4.25 , e ) 4.5
a
divide(350, add(divide(multiply(4, 1000), const_100), divide(multiply(1400, 5), const_100)))
multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|divide(n4,#4)|
gain
a of n?
"n = 4 k + 1 = 5 j + 4 let ' s start at 1 = 4 ( 0 ) + 1 and keep adding 4 until we find a number in the form 5 j + 4 . 1 , 5 , 9 = 5 ( 1 ) + 4 the next such number is 9 + 4 * 5 = 29 . 9 + 29 = 38 the answer is c ."
a ) 30 , b ) 34 , c ) 38 , d ) 42 , e ) 46
c
add(add(multiply(5, const_2), 4), add(multiply(5, multiply(const_2, 4)), 4))
multiply(n2,const_2)|multiply(const_2,n3)|add(n3,#0)|multiply(n2,#1)|add(n3,#3)|add(#2,#4)|
general
in remainder dividend is
divisor = ( 6 * 3 ) + 7 = 25 5 * quotient = 25 quotient = 5 . dividend = ( divisor * quotient ) + remainder dividend = ( 20 * 5 ) + 6 = 106 . e )
a ) 74 , b ) 78 , c ) 86 , d ) 92 , e ) 106
e
add(multiply(add(multiply(6, const_3), 7), divide(add(multiply(6, const_3), 7), 5)), 6)
multiply(n0,const_3)|add(n2,#0)|divide(#1,n1)|multiply(#1,#2)|add(n0,#3)
general
a of in?
"b = 1 / 8 – 1 / 22 = 0.075 days answer : a"
a ) 0.075 days , b ) 0.45 days , c ) 0.55 days , d ) 0.25 days , e ) 0.15 days
a
inverse(subtract(inverse(8), inverse(20)))
inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)|
physics
c per l?
"gear l - - 20 rotations per 60 seconds - - 2 rotation per 6 seconds . gear r - - 60 rotations per 60 seconds - - 6 rotations per 6 seconds . first 6 seconds - - gear l makes 1 rotation . - - gear r makes 4 rotations - - net difference - - 4 rotations hence every 6 seconds the difference between the number of rotations of r and l gear is 4 units . required net difference should be 8 rotations = > 2 ( 6 seconds later ) = = > 12 seconds . answer : e"
a ) a ) 6 , b ) b ) 8 , c ) c ) 10 , d ) d ) 14 , e ) e ) 12
e
divide(divide(8, subtract(divide(60, const_60), divide(20, const_60))), const_3)
divide(n1,const_60)|divide(n0,const_60)|subtract(#0,#1)|divide(n2,#2)|divide(#3,const_3)|
physics
for97 )?
( ( 90 θ 33 ) θ 17 ) the remainder of 90 divided by 33 is 24 ; the remainder of 24 divided by 17 is 7 ; ( 97 θ ( 33 θ 17 ) ) the remainder of 33 divided by 17 is 16 ; the remainder of 97 divided by 16 is 1 . 7 - 1 = 6 . answer : d .
a ) 0 , b ) 2 , c ) 4 , d ) 6 , e ) 8
d
subtract(reminder(reminder(90, 33), 17), reminder(97, reminder(33, 17)))
reminder(n0,n1)|reminder(n1,n2)|reminder(#0,n2)|reminder(n3,#1)|subtract(#2,#3)
general
what = x?
"we get 2 quadratic equations here . . 1 ) x ^ 2 - x - 3 = 0 . . . . . . . roots 2 , - 1 2 ) x ^ 2 + x - 3 = 0 . . . . . . . . roots - 2 , 1 inserting each root in given equation , it can be seen that - 1 and - 2 do not satisfy the equations . so value of x for given equation . . . . x = 3 or x = 1 i guess range is 3 - 1 = 2 c"
a ) 4 , b ) 3 , c ) 2 , d ) 1 , e ) 0
c
sqrt(3)
sqrt(n1)|
general
if, micron?
"given that 1,000 microns = 1 decimeter = 1,000 , 000,000 angstroms so , 1 micron = 1,000 , 000,000 / 1,000 = 1 , 000,000 answer : c"
a ) 1,000 , b ) 100 , c ) 1 , 000,000 , d ) 10 , e ) 10,000
c
multiply(divide(1, multiply(const_100, const_100)), multiply(const_100, const_100))
multiply(const_100,const_100)|divide(n1,#0)|multiply(#1,#0)|
general
if 0?
"required difference = [ 3 1 / 2 % of $ 8400 ] – [ 3 1 / 3 % of $ 8400 ] = [ ( 7 / 20 ) - ( 10 / 3 ) ] % of $ 8400 = 1 / 6 % of $ 8400 = $ [ ( 1 / 6 ) * ( 1 / 100 ) * 8400 ] = $ 14 . answer a ."
a ) 14 , b ) 24 , c ) 34 , d ) 12 , e ) 13
a
divide(multiply(subtract(add(divide(1, 2), 3), add(divide(1, 3), 3)), 8400), const_100)
divide(n1,n2)|divide(n1,n0)|add(n0,#0)|add(n0,#1)|subtract(#2,#3)|multiply(n6,#4)|divide(#5,const_100)|
general
the three is :
"let the numbers be x , x + 1 and x + 2 then , x + ( x + 1 ) + ( x + 2 ) = 63 3 x = 60 x = 20 greatest number , ( x + 2 ) = 22 . answer : d"
a ) 26 , b ) 28 , c ) 29 , d ) 22 , e ) 31
d
divide(add(63, const_1), const_2)
add(n0,const_1)|divide(#0,const_2)|
physics
machine q produce?
"p makes x sprockets per hour . then q makes 1.1 x sprockets per hour . 770 / x = 770 / 1.1 x + 10 1.1 ( 770 ) = 770 + 11 x 11 x = 77 x = 7 the answer is c ."
a ) 3 , b ) 5 , c ) 7 , d ) 9 , e ) 11
c
divide(subtract(770, divide(770, add(divide(10, const_100), const_1))), 10)
divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|divide(#3,n1)|
gain
the20 %?
explanation : 20 cp = 30 sp 30 - - - 10 cp loss 100 - - - ? = > 33.33 % loss answer : c
a ) 63.33 % , b ) 34.33 % , c ) 33.33 % , d ) 31.33 % , e ) 36.33 %
c
multiply(subtract(const_1, divide(20, 30)), const_100)
divide(n0,n1)|subtract(const_1,#0)|multiply(#1,const_100)
gain
weights the increased?
"solution : given ratio of ram and shayam ' s weight = 3 : 5 hence , ( x - 15 ) / ( 15 - 10 ) = 3 / 5 or , x = 18 % . answer : option a"
a ) 18 % , b ) 10 % , c ) 21 % , d ) 16 % , e ) none
a
add(15, multiply(subtract(15, 10), divide(3, 5)))
divide(n0,n1)|subtract(n4,n2)|multiply(#0,#1)|add(n4,#2)|
gain
in. sale?
"percent of defective produced = 7 % percent of the defective units that are shipped for sale = 4 % percent of units produced are defective units that are shipped for sale = ( 4 / 100 ) * ( 7 / 100 ) * 100 % = ( 28 / 10000 ) * 100 % = ( 28 / 100 ) % = . 28 % answer b"
a ) 0.125 % , b ) 0.28 % , c ) 0.8 % , d ) 1.25 % , e ) 2.0 %
b
multiply(7, divide(4, const_100))
divide(n1,const_100)|multiply(n0,#0)|
gain
the of students?
"solution sum of the ages of 14 students = ( 16 x 35 ) - ( 14 x 21 ) = 560 - 294 . = 266 . ∴ required average = 266 / 7 = 38 years . answer d"
a ) 14 years , b ) 17 years , c ) 19 years , d ) 38 years , e ) none
d
subtract(add(add(multiply(35, 16), 21), 35), multiply(35, 16))
multiply(n0,n1)|add(n2,#0)|add(n0,#1)|subtract(#2,#0)|
general
a what price?
"original price = 100 cp = 70 s = 70 * ( 180 / 100 ) = 126 100 - 126 = 26 % answer : b"
a ) 18 % , b ) 26 % , c ) 12 % , d ) 32 % , e ) 15 %
b
multiply(subtract(divide(divide(multiply(subtract(const_100, 30), add(const_100, 80)), const_100), const_100), const_1), const_100)
add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,const_1)|multiply(#5,const_100)|
gain
a. is?
average speed = 2 * 3 * 2 / 3 + 2 = 12 / 5 km / hr distance traveled = 12 / 5 * 5 = 12 km distance between house and school = 12 / 2 = 6 km answer is b
a ) 5 km , b ) 6 km , c ) 10 km , d ) 12 km , e ) 8 km
b
multiply(divide(5, add(divide(3, 2), const_1)), 3)
divide(n0,n1)|add(#0,const_1)|divide(n2,#1)|multiply(n0,#2)
physics
how to hr?
let length of tunnel is x meter distance = 600 + x meter time = 1 minute = 60 seconds speed = 78 km / hr = 78 * 5 / 18 m / s = 65 / 3 m / s distance = speed * time 600 + x = ( 65 / 3 ) * 60 600 + x = 20 * 65 = 1300 x = 1300 - 600 = 700 meters answer : a
a ) 700 , b ) 288 , c ) 500 , d ) 277 , e ) 121
a
multiply(multiply(subtract(divide(600, multiply(subtract(63, 3), const_0_2778)), const_1), const_10), const_2)
subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)|subtract(#2,const_1)|multiply(#3,const_10)|multiply(#4,const_2)
physics
a long it?
a ' s 1 hour work = 1 / 4 ; ( b + c ) ' s 1 hour work = 1 / 3 ; ( a + b ) ' s 1 hour work = 1 / 2 ( a + b + c ) ' s 1 hour work = ( 1 / 4 + 1 / 3 ) = 7 / 12 c ' s 1 hour work = ( 7 / 12 - 1 / 2 ) = 1 / 12 c alone will take 12 hours to do the work . answer : a
a ) 12 hours , b ) 10 hours , c ) 6 hours , d ) 8 hours , e ) 4 hours
a
divide(const_1, subtract(divide(const_1, 3), subtract(divide(const_1, 2), divide(const_1, 4))))
divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n0)|subtract(#1,#2)|subtract(#0,#3)|divide(const_1,#4)
physics
a loan month?
"total = 75 books . 60 % of books that were loaned out are returned - - > 100 % - 60 % = 40 % of books that were loaned out are not returned . now , there are 68 books , thus 75 - 65 = 10 books are not returned . { loaned out } * 0.4 = 10 - - > { loaned out } = 25 . answer : b ."
a ) 20 , b ) 25 , c ) 35 , d ) 40 , e ) 55
b
divide(subtract(75, 65), subtract(const_1, divide(60, const_100)))
divide(n1,const_100)|subtract(n0,n2)|subtract(const_1,#0)|divide(#1,#2)|
gain
cost original cost?
"original cost c 1 = t 1 * b 1 ^ 4 new cost c 2 = t 2 * b 2 ^ 4 . . . . only b is doubled so t 2 = t 1 and b 2 = 2 b 1 c 2 = t 2 * ( 2 b 1 ) ^ 4 = 16 ( t 1 * b 1 ^ 4 ) = 16 c 1 16 times c 1 = > 1600 % of c 1 ans d = 1600"
a ) q = 200 , b ) q = 600 , c ) q = 800 , d ) q = 1600 , e ) q = 50
d
multiply(power(const_2, 4), const_100)
power(const_2,n0)|multiply(#0,const_100)|
general
al isty?
"a = 2 m = m + 12 m = 12 a = 24 a = 4 b , and so b = 6 the answer is a ."
a ) 6 , b ) 12 , c ) 10 , d ) 15 , e ) 18
a
divide(multiply(2, 12), 4)
multiply(n0,n2)|divide(#0,n1)|
general