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test_id/exact_op11_samples1000_part1_proc3.jsonl

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+{"problem": "The number of private middle school in Hawkesbury equals 1. The number of culinarian school in Hawkesbury equals 2. The number of culinarian school in Glenfield City equals the difference between the total number of schools in Hawkesbury and the number of private middle school in Hawkesbury. The number of private middle school in Glenfield City equals 2 times the sum of the number of culinarian school in Hawkesbury and the number of private middle school in Hawkesbury. ", "question": "What is the total number of schools in Glenfield City?", "solution": "Define culinarian school in Hawkesbury as a; so a = 2. Define private middle school in Hawkesbury as E; so E = 1. Define total number of schools in Hawkesbury as s; so s = E + a = 1 + 2 = 3. Define private middle school in Glenfield City as o; w = a + E = 2 + 1 = 3; so o = 2 * w = 2 * 3 = 6. Define culinarian school in Glenfield City as T; so T = s - E = 3 - 1 = 2. Define total number of schools in Glenfield City as k; so k = o + T = 6 + 2 = 8. Answer: 8.", "op": 11, "id": "12_p3", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of private middle school in Hawkesbury equals 4. The number of regional medical school in Hawkesbury equals the number of private middle school in Hawkesbury. The number of private middle school in Evervale City equals 4 plus the total number of schools in Hawkesbury. The number of regional medical school in Evervale City equals 2 plus the sum of the number of private middle school in Hawkesbury and the number of regional medical school in Hawkesbury. ", "question": "What is the total number of schools in Evervale City?", "solution": "Define private middle school in Hawkesbury as d; so d = 4. Define regional medical school in Hawkesbury as u; so u = d = 4. Define total number of schools in Hawkesbury as H; so H = u + d = 4 + 4 = 8. Define regional medical school in Evervale City as Z; q = d + u = 4 + 4 = 8; so Z = 2 + q = 2 + 8 = 10. Define private middle school in Evervale City as F; X = H = 8; so F = 4 + X = 4 + 8 = 12. Define total number of schools in Evervale City as C; so C = Z + F = 10 + 12 = 22. Answer: 22.", "op": 11, "id": "16_p3", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult fox in Cedar Valley equals the number of adult racoon in Cedar Valley. The number of adult fox in Pine Ridge equals the sum of the number of adult fox in Cedar Valley and the number of adult racoon in Cedar Valley. The number of adult racoon in Pine Ridge equals 4 plus the difference between the total number of adult animals in Cedar Valley and the number of adult racoon in Cedar Valley. The number of adult racoon in Cedar Valley exists, and its number is greater than 0. The total number of adult animals in Pine Ridge equals 16. ", "question": "How many adult racoon does Cedar Valley have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult fox in Cedar Valley as a; so a = x = x. Define total number of adult animals in Cedar Valley as o; so o = x + a = x + x = 2*x. Define adult fox in Pine Ridge as u; so u = a + x = x + x = 2*x. Define adult racoon in Pine Ridge as q; C = o - x = (2*x) - (x) = x; so q = 4 + C = 4 + x = x + 4. Define total number of adult animals in Pine Ridge as m; so m = q + u = x + 4 + 2*x = 3*x + 4. We know m = 16, so we have 3*x + 4 = 16 and we solve it through the following steps: Simplifying the equation: 3*x + 4 = 16. Move all terms to one side: 3*x - 12 = 0. Isolate the term with x: 3*x = 12. Divide both sides by 3: x = 12 / 3. Solution: x = 4. Answer: 4.", "op": 11, "id": "5_p3", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult eagle in Cedar Valley equals the sum of the number of adult blue jay in Pine Ridge and the number of adult eagle in Pine Ridge. The number of adult eagle in Oakridge Riverside equals 3. The number of adult eagle in Pine Ridge equals 4. The number of adult blue jay in Beverly Forest equals 4 times the sum of the total number of adult animals in Oakridge Riverside and the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Pine Ridge equals 4 times the difference between the number of adult eagle in Beverly Forest and the number of adult eagle in Pine Ridge. The number of adult eagle in Beverly Forest equals 1 plus the number of adult blue jay in Oakridge Riverside. The number of adult blue jay in Cedar Valley equals 2 plus the number of adult parrot in Pine Ridge. The number of adult parrot in Cedar Valley equals 3. The number of adult parrot in Pine Ridge equals 2 times the number of adult blue jay in Oakridge Riverside. The total number of adult animals in Beverly Forest equals 31. The number of adult blue jay in Oakridge Riverside exists, and its number is greater than 0. ", "question": "How many adult blue jay does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult eagle in Oakridge Riverside as t; so t = 3. Define adult blue jay in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define total number of adult animals in Oakridge Riverside as c; so c = x + t = x + 3 = x + 3. Define adult eagle in Beverly Forest as p; M = x = x; so p = 1 + M = 1 + x = x + 1. Define adult blue jay in Beverly Forest as S; J = c + x = x + 3 + x = 2*x + 3; so S = 4 * J = (4) * (2*x + 3) = 8*x + 12. Define total number of adult animals in Beverly Forest as P; so P = S + p = 8*x + 12 + x + 1 = 9*x + 13. We know P = 31, so we have 9*x + 13 = 31 and we solve it through the following steps: Simplifying the equation: 9*x + 13 = 31. Move all terms to one side: 9*x - 18 = 0. Isolate the term with x: 9*x = 18. Divide both sides by 9: x = 18 / 9. Solution: x = 2. Answer: 2.", "op": 11, "id": "1_p3", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of public highschool in Oakbridge City equals the sum of the total number of schools in Riverton City, the number of culinarian school in Riverton City, and the number of public highschool in Clearwater Bay. The number of culinarian school in Oakbridge City equals the difference between the number of private middle school in Riverton City and the total number of schools in Riverton City. The number of culinarian school in Clearwater Bay equals 2 times the number of regional medical school in Oakbridge City. The number of private middle school in Clearwater Bay equals 3. The number of regional medical school in Clearwater Bay equals 2. The number of private middle school in Oakbridge City equals the sum of the number of regional medical school in Riverton City and the number of regional medical school in Clearwater Bay. The number of private middle school in Riverton City equals the number of culinarian school in Riverton City. The number of regional medical school in Riverton City equals 4 plus the difference between the number of private middle school in Riverton City and the number of culinarian school in Riverton City. The number of regional medical school in Oakbridge City equals 2 plus the number of regional medical school in Clearwater Bay. The number of culinarian school in Riverton City equals 2. The number of public highschool in Riverton City equals 4 plus the number of culinarian school in Riverton City. The number of public highschool in Clearwater Bay equals 3 plus the number of culinarian school in Riverton City. ", "question": "What is the total number of schools in Riverton City?", "solution": "Define culinarian school in Riverton City as R; so R = 2. Define private middle school in Riverton City as k; so k = R = 2. Define public highschool in Riverton City as V; Y = R = 2; so V = 4 + Y = 4 + 2 = 6. Define regional medical school in Riverton City as X; u = k - R = 2 - 2 = 0; so X = 4 + u = 4 + 0 = 4. Define total number of schools in Riverton City as a; s = V + R = 6 + 2 = 8; E = s + k = 8 + 2 = 10; so a = E + X = 10 + 4 = 14. Answer: 14.", "op": 11, "id": "11_p3", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of regional medical school in Evervale City equals 1 plus the difference between the number of culinarian school in Westhaven City and the number of private middle school in Westhaven City. The number of elementary school in Evervale City equals 4 times the total number of schools in Westhaven City. The number of culinarian school in Westhaven City equals 4. The number of private middle school in Westhaven City equals 1. ", "question": "What is the total number of schools in Evervale City?", "solution": "Define private middle school in Westhaven City as R; so R = 1. Define culinarian school in Westhaven City as Z; so Z = 4. Define total number of schools in Westhaven City as N; so N = Z + R = 4 + 1 = 5. Define regional medical school in Evervale City as A; y = Z - R = 4 - 1 = 3; so A = 1 + y = 1 + 3 = 4. Define elementary school in Evervale City as h; x = N = 5; so h = 4 * x = 4 * 5 = 20. Define total number of schools in Evervale City as v; so v = h + A = 20 + 4 = 24. Answer: 24.", "op": 11, "id": "18_p3", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of private middle school in Shoreline City equals the difference between the number of private middle school in Clearwater Bay and the number of regional medical school in Clearwater Bay. The number of regional medical school in Shoreline City equals the sum of the total number of schools in Clearwater Bay, the number of private middle school in Clearwater Bay, and the number of regional medical school in Clearwater Bay. The number of regional medical school in Clearwater Bay equals 3. The number of private middle school in Clearwater Bay equals 4. ", "question": "What is the total number of schools in Shoreline City?", "solution": "Define regional medical school in Clearwater Bay as i; so i = 3. Define private middle school in Clearwater Bay as Q; so Q = 4. Define total number of schools in Clearwater Bay as E; so E = Q + i = 4 + 3 = 7. Define private middle school in Shoreline City as W; so W = Q - i = 4 - 3 = 1. Define regional medical school in Shoreline City as M; K = E + Q = 7 + 4 = 11; so M = K + i = 11 + 3 = 14. Define total number of schools in Shoreline City as S; so S = W + M = 1 + 14 = 15. Answer: 15.", "op": 11, "id": "19_p3", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The total number of movies in Festival de Saint-Rivage equals 28. The number of intense detective thriller in Festival de Saint-Rivage equals 4 times the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival de Saint-Rivage equals the sum of the total number of movies in Festival Lumi\u00e8re de Valmont, the number of intense detective thriller in Festival Lumi\u00e8re de Valmont, and the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival Lumi\u00e8re de Valmont exists, and its number is greater than 0. The number of intense detective thriller in Festival Lumi\u00e8re de Valmont equals 2. ", "question": "How many calm road movie does Festival Lumi\u00e8re de Valmont have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Festival Lumi\u00e8re de Valmont as Y; so Y = 2. Define calm road movie in Festival Lumi\u00e8re de Valmont as x; we don't know its value yet but will find it out later. Define total number of movies in Festival Lumi\u00e8re de Valmont as g; so g = x + Y = x + 2 = x + 2. Define intense detective thriller in Festival de Saint-Rivage as O; L = x = x; so O = 4 * L = (4) * (x) = 4*x. Define calm road movie in Festival de Saint-Rivage as m; G = g + Y = x + 2 + 2 = x + 4; so m = G + x = x + 4 + x = 2*x + 4. Define total number of movies in Festival de Saint-Rivage as l; so l = m + O = 2*x + 4 + 4*x = 6*x + 4. We know l = 28, so we have 6*x + 4 = 28 and we solve it through the following steps: Simplifying the equation: 6*x + 4 = 28. Move all terms to one side: 6*x - 24 = 0. Isolate the term with x: 6*x = 24. Divide both sides by 6: x = 24 / 6. Solution: x = 4. Answer: 4.", "op": 11, "id": "8_p3", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of private middle school in Glenfield City exists, and its number is greater than 0. The number of public highschool in Glenfield City equals the number of private middle school in Glenfield City. The number of private middle school in Hawkesbury equals 2 plus the sum of the number of public highschool in Glenfield City and the number of private middle school in Glenfield City. The number of public highschool in Hawkesbury equals the difference between the total number of schools in Glenfield City and the number of public highschool in Glenfield City. The total number of schools in Hawkesbury equals 5. ", "question": "How many private middle school does Glenfield City have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Glenfield City as x; we don't know its value yet but will find it out later. Define public highschool in Glenfield City as h; so h = x = x. Define total number of schools in Glenfield City as K; so K = h + x = x + x = 2*x. Define private middle school in Hawkesbury as J; q = h + x = x + x = 2*x; so J = 2 + q = 2 + 2*x = 2*x + 2. Define public highschool in Hawkesbury as z; so z = K - h = (2*x) - (x) = x. Define total number of schools in Hawkesbury as a; so a = z + J = x + 2*x + 2 = 3*x + 2. We know a = 5, so we have 3*x + 2 = 5 and we solve it through the following steps: Simplifying the equation: 3*x + 2 = 5. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.", "op": 11, "id": "22_p3", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}