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5,400
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the average number of customers per sales person?
SELECT CAST(COUNT(T1.CustomerID) AS REAL) / COUNT(T3.EmployeeID) FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID
average = DIVIDE(COUNT(CustomerID), COUNT(EmployeeID));
[ "Customers.CustomerID", "Employees.EmployeeID", "Sales.CustomerID", "Sales.SalesPersonID" ]
5,401
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among all customers handled by Innes E. del Castillo, how many have purchased Short-Sleeve Classic Jersey, L?
SELECT COUNT(T2.CustomerID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID WHERE T3.FirstName = 'Innes' AND T3.LastName = 'del Castillo' AND T1.Name = 'Short-Sleeve Classic Jersey, L' AND T3.MiddleInitial = 'e'
Short-Sleeve Classic Jersey, L' is name of product;
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial", "Products.Name", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.SalesPersonID" ]
5,402
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Name the sales person who helped Elizabeth A. White to purchase Road-250 Black, 48.
SELECT DISTINCT T3.FirstName, T3.MiddleInitial, T3.LastName FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID INNER JOIN Customers AS T4 ON T2.CustomerID = T4.CustomerID WHERE T4.MiddleInitial = 'A' AND T4.LastName = 'White' AND T1.N...
name of the sales person = FirstName, MiddleInitial, LastName; 'Road-250 Black, 48' is name of product;
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial", "Products.Name", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.SalesPersonID" ...
5,403
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many sales people managed to sell Headlights - Weatherproof?
SELECT COUNT(T2.SalesPersonID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Headlights - Weatherproof'
Headlights - Weatherproof' is name of product
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.SalesPersonID" ]
5,404
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Calculate the revenue produced through sales of HL Road Frame - Red, 56.
SELECT SUM(T2.Quantity * T1.Price) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'HL Road Frame - Red, 56'
revenue = MULTIPLY(SUM(Quantity, Price)); 'HL Road Frame - Red, 56' is name of product;
[ "Products.Name", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,405
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many sales transactions were given by the customer named Joe L. Lopez?
SELECT COUNT(T1.SalesID) FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.FirstName = 'Joe' AND T2.MiddleInitial = 'L' AND T2.LastName = 'Lopez'
sales transactions refers to SalesID;
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Sales.CustomerID", "Sales.SalesID" ]
5,406
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Name the customers who received 'Touring Rim' as a free gift.
SELECT DISTINCT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T3.Name = 'Touring Rim' AND T3.Price = 0
name of the customer = FirstName, MiddleInitial, LastName; 'Touring Rim' is name of product;
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Products.Name", "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID" ]
5,407
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Find the number of customers handled by each of the sales people.
SELECT COUNT(CustomerID) FROM Sales GROUP BY SalesPersonID
[ "Sales.CustomerID", "Sales.SalesPersonID" ]
5,408
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many sales people are handling all the customers?
SELECT COUNT(EmployeeID) FROM Employees
[ "Employees.EmployeeID" ]
5,409
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Identify the name of the sales person with employee ID 7.
SELECT FirstName, MiddleInitial, LastName FROM Employees WHERE EmployeeID = 7
name of the sales person = FirstName, MiddleInitial, LastName;
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial" ]
5,410
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Name the most expensive and the least expensive products available, excluding free gifts.
SELECT Name FROM Products WHERE Price IN (( SELECT MAX(Price) FROM Products ), ( SELECT MIN(Price) FROM Products ))
most expensive product refers to MAX(Price); least expensive product refers to MIN(Price); excluding free gifts refers to not including Price = 0;
[ "Products.Name", "Products.Price" ]
5,411
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among all the customers who have purchased ML Bottom Bracket, identify the percentage of sales by Albert I. Ringer?
SELECT CAST(SUM(IIF(T3.FirstName = 'Albert' AND T3.MiddleInitial = 'I' AND T3.LastName = 'Ringer', 1, 0)) AS REAL) * 100 / COUNT(T2.CustomerID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID WHERE T1.Name = 'ML Bottom Bracket'
ML Bottom Bracket' is name of product; percentage = MULTIPLY(DIVIDE(SUM(CustomerID WHERE FirstName = 'Albert' AND MiddleInitial = 'I' AND LastName = 'Ringer'), COUNT(CustomerID)), 1.0);
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial", "Products.Name", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.SalesPersonID" ]
5,412
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many customers have the first name Abigail?
SELECT COUNT(CustomerID) FROM Customers WHERE FirstName = 'Abigail'
[ "Customers.CustomerID", "Customers.FirstName" ]
5,413
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Indicate the quantity of Blade products sold.
SELECT DISTINCT T2.Quantity FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Blade'
Blade' is name of product;
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,414
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Give the full name of the employee who has sold the most quantity.
SELECT T1.FirstName, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID ORDER BY T2.Quantity DESC LIMIT 1
full name of the employee = FirstName, LastName; most quantity refers to MAX(Quantity);
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Sales.Quantity", "Sales.SalesPersonID" ]
5,415
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the full name of the customer who purchased the most quantity of products.
SELECT T1.FirstName, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID ORDER BY T2.Quantity DESC LIMIT 1
full name of the customer = FirstName, LastName; most quantity refers to MAX(Quantity);
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Sales.CustomerID", "Sales.Quantity" ]
5,416
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the name of the product that is most sold by sale person id 20?
SELECT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T2.SalesPersonID = 20 ORDER BY T2.Quantity DESC LIMIT 1
most sold refers to MAX(Quantity);
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesPersonID" ]
5,417
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the first names of employees with trading quantity for more than 500.
SELECT DISTINCT T1.FirstName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID WHERE T2.Quantity > 500
trading quantity for more than 500 refers to Quantity > 500;
[ "Employees.EmployeeID", "Employees.FirstName", "Sales.Quantity", "Sales.SalesPersonID" ]
5,418
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the first names of customers who have purchased products from sale person id 1.
SELECT T1.FirstName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.SalesPersonID = 1
[ "Customers.CustomerID", "Customers.FirstName", "Sales.CustomerID", "Sales.SalesPersonID" ]
5,419
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Calculate the total trading quantity of Abraham sold to Aaron Alexander.
SELECT SUM(T2.Quantity) FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID WHERE T2.SalesPersonID = 1 AND T1.FirstName = 'Aaron' AND T1.LastName = 'Alexander' AND T3.FirstName = 'Abraham'
total trading quantity = SUM(Quantity WHERE Employees.FirstName = 'Abraham' AND Customers.FirstName = 'Aaron' AND Customers.LastName = 'Alexander');
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Employees.EmployeeID", "Employees.FirstName", "Sales.CustomerID", "Sales.Quantity", "Sales.SalesPersonID" ]
5,420
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the full names of customers who have purchased products in quantity over 600.
SELECT T1.FirstName, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.Quantity > 600
full names of customers = FirstName, LastName; quantity over 600 refers to quantity > 600;
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Sales.CustomerID", "Sales.Quantity" ]
5,421
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among the customers whose first name is Cameron, who bought the product in the most quantity?
SELECT T1.FirstName, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.FirstName = 'Cameron' ORDER BY T2.Quantity DESC LIMIT 1
most quantity refers to MAX(Quantity); who refers to FirstName, LastName;
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Sales.CustomerID", "Sales.Quantity" ]
5,422
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Please provide sales ID for products named Hex Nut with a price greater than 100.
SELECT T2.SalesID FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name LIKE 'Hex Nut%' AND T1.Price > 100
price greater than 100 refers to price > 100;
[ "Products.Name", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.SalesID" ]
5,423
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Identify customer IDs who bought products priced from 1000 to 2000.
SELECT DISTINCT T2.CustomerID FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Price BETWEEN 1000 AND 2000
priced from 1000 to 2000 refers to Price BETWEEN 1000 AND 2000;
[ "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID" ]
5,424
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Calculate the total quantity of products that are gifts.
SELECT SUM(T2.Quantity) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Price = 0
total quantity = SUM(Quantity); gifts refers to Price = 0;
[ "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,425
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Calculate the quantity percentage of the gift products in the total trading quantity.
SELECT CAST(SUM(IIF(T1.Price = 0, T2.Quantity, 0)) AS REAL) * 100 / SUM(T2.Quantity)FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID
percentage = MULTIPLY(DIVIDE(SUM(Quantity WHERE Price = 0), SUM(Quantity)), 1.0); gift products refers to Price = 0;
[ "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,426
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Calculate the percentage of sold blades in the total number of transactions.
SELECT CAST(SUM(IIF(T1.Name = 'Blade', T2.Quantity, 0)) AS REAL) * 100 / SUM(T2.Quantity) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID
percentage = MULTIPLY(DIVIDE(SUM(Quantity WHERE Name = 'Blade'), SUM(Quantity)), 1.0); 'blades' refers to name of product;
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,427
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many of the employees have the last name "Ringer" ?
SELECT COUNT(LastName) FROM Employees WHERE LastName = 'Ringer'
[ "Employees.LastName" ]
5,428
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among the products with product ID lower than 15, how many of them costs 10 and below?
SELECT COUNT(ProductID) FROM Products WHERE ProductID < 15 AND Price <= 10
product ID lower than 15 refers to ProductID < 15; costs 10 and below refers to Price; Price < = 10;
[ "Products.Price", "Products.ProductID" ]
5,429
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Give the product's name brought by Aaron Alexander.
SELECT DISTINCT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T3.FirstName = 'Aaron' AND T3.LastName = 'Alexander'
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Products.Name", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID" ]
5,430
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Give the product ID and name of the product with the highest prices among the quantity ranges from 400 to 500.
SELECT T1.ProductID, T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T2.quantity BETWEEN 400 AND 500 ORDER BY T1.Price DESC LIMIT 1
highest prices refers to MAX(Price); quantity ranges from 400 to 500 refers to Quantity BETWEEN 400 AND 500;
[ "Products.Name", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.quantity" ]
5,431
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among customers named Kate, who has the highest quantity?
SELECT T2.FirstName, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.FirstName = 'Kate' ORDER BY T1.Quantity DESC LIMIT 1
highest quantity refers to MAX(Quantity);
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Sales.CustomerID", "Sales.Quantity" ]
5,432
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among the products that have price ranges from 100 to 150, what is the customer ID and sales ID of the product with a quantity lower than 25?
SELECT T2.CustomerID, T2.SalesID FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Price BETWEEN 100 AND 150 AND T2.Quantity < 25
price ranges from 100 to 150 refers to Price BETWEEN 100 AND 150; quantity lower than 25 refers to Quantity < 25;
[ "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesID" ]
5,433
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the quantity and price of the product bought by Abigail Henderson.
SELECT T2.Quantity, T1.Price FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T3.FirstName = 'Abigail' AND T3.LastName = 'Henderson'
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.Quantity" ]
5,434
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
In sales with a quantity of 60, how many of them have a price not greater than 500?
SELECT COUNT(T1.ProductID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T2.quantity = 60 AND T1.Price <= 500
[ "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.quantity" ]
5,435
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
In customers with the first name of Erica, how many of them bought a quantity below 200?
SELECT COUNT(T1.ProductID) FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.FirstName = 'Erica' AND T1.Quantity < 200
quantity below 200 refers to quantity < 200;
[ "Customers.CustomerID", "Customers.FirstName", "Sales.CustomerID", "Sales.ProductID", "Sales.Quantity" ]
5,436
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among products bought by Kathryn Ashe, what is the name of the product with the highest quantity?
SELECT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T3.FirstName = 'Kathryn' AND T3.LastName = 'Ashe' ORDER BY T2.Quantity DESC LIMIT 1
highest quantity refers to MAX(Quantity);
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Products.Name", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.Quantity" ]
5,437
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the price and quantity of the product named Seat Tube?
SELECT DISTINCT T2.Price, T1.Quantity FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T2.Name = 'Seat Tube'
[ "Products.Name", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,438
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the price and name of the product bought by Erica Xu?
SELECT T3.Price, T3.Name FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Products AS T3 ON T1.ProductID = T3.ProductID WHERE T2.FirstName = 'Erica' AND T2.LastName = 'Xu'
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Products.Name", "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID" ]
5,439
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the sales ID of the product with a quantity of 590 and named "External Lock Washer 7".
SELECT T1.SalesID FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T2.Name = 'External Lock Washer 7' AND T1.Quantity = 590
External Lock Washer 7' is name of product;
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesID" ]
5,440
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
In sales ID between 30 and 40, who is the customer that bought a total quantity of 403?
SELECT T2.FirstName, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.Quantity = 403 AND T1.SalesID BETWEEN 30 AND 40
who refers to FirstName, LastName;
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Sales.CustomerID", "Sales.Quantity", "Sales.SalesID" ]
5,441
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the customer's ID and last name of the customer that purchased a product with a quantity greater than 90% of the average quantity of all listed products.
SELECT T2.CustomerID, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.Quantity > ( SELECT AVG(Quantity) FROM Sales ) * 0.9
quantity greater than 90% of the average quantity = Quantity > MULTIPLY(AVG(Quantity), 0.9);
[ "Customers.CustomerID", "Customers.LastName", "Sales.CustomerID", "Sales.Quantity" ]
5,442
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among the sales ID ranges from 1 to 200, what is the percentage of the products with a price ranging from 200 to 300?
SELECT CAST(SUM(IIF(T2.Price BETWEEN 200 AND 300, 1, 0)) AS REAL) * 100 / COUNT(T2.Price) FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T1.SalesID BETWEEN 1 AND 200
sales ID ranges from 1 to 200 refers to SalesID between 1 and 200; percentage = MULTIPLY(DIVIDE(SUM(Price between 200 and 300), COUNT(Price)), 1.0);
[ "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.SalesID" ]
5,443
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the name of the most expensive product?
SELECT Name FROM Products WHERE Price = ( SELECT MAX(Price) FROM Products )
most expensive product refers to MAX(Price);
[ "Products.Name", "Products.Price" ]
5,444
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many customers are named Madison?
SELECT COUNT(CustomerID) FROM Customers WHERE FirstName = 'Madison'
[ "Customers.CustomerID", "Customers.FirstName" ]
5,445
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many types of "HL Touring Frames" are there?
SELECT COUNT(ProductID) FROM Products WHERE Name LIKE '%HL Touring Frame%'
types of HL Touring Frames refers to Name like '%HL Touring Frame%';
[ "Products.Name", "Products.ProductID" ]
5,446
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many customers share the most common last name?
SELECT COUNT(CustomerID) FROM Customers GROUP BY LastName ORDER BY COUNT(LastName) DESC LIMIT 1
most common last name refers to MAX(COUNT(LastName));
[ "Customers.CustomerID", "Customers.LastName" ]
5,447
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many free or gift products are there?
SELECT COUNT(ProductID) FROM Products WHERE Price = 0
free gift refers to Price = 0;
[ "Products.Price", "Products.ProductID" ]
5,448
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the name of the sales person who handled the highest number of sales?
SELECT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T2.SalesPersonID = T1.EmployeeID GROUP BY T2.SalesPersonID, T1.FirstName, T1.MiddleInitial, T1.LastName ORDER BY COUNT(T2.SalesID) DESC LIMIT 1
name of the sales person = FirstName, MiddleInitial, LastName; highest number of sales refers to MAX(COUNT(SalesID));
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial", "Sales.SalesID", "Sales.SalesPersonID" ]
5,449
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the full name of the customer who purchased the highest amount of total price in a single purchase?
SELECT T2.FirstName, T2.MiddleInitial, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Products AS T3 ON T1.ProductID = T3.ProductID GROUP BY T1.SalesID, T1.Quantity, T3.Price, FirstName, MiddleInitial, LastName ORDER BY T1.Quantity * T3.Price DESC LIMIT 1
full name of the customer = FirstName, MiddleInitial, LastName; highest amount of total price refers to MAX(MULTIPLY(Quantity, Price));
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesID" ]
5,450
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many "Mountain-500 Black 42" were sold in total?
SELECT SUM(T2.Quantity) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Mountain-500 Black, 42'
Mountain-500 Black 42' is name of product; sold in total = SUM(Quantity);
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,451
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How much is the total amount of sales handled by Heather McBadden?
SELECT SUM(T2.Quantity * T3.Price) FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T1.FirstName = 'Heather' AND T1.LastName = 'McBadden'
total amount of sales = SUM(MULTIPLY(Quantity, Price));
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesPersonID" ]
5,452
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many "Mountain-100 Silver, 38" were sold by Stearns MacFeather?
SELECT SUM(T2.Quantity) FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T1.FirstName = 'Stearns' AND T1.LastName = 'MacFeather' AND T3.Name = 'Mountain-100 Silver, 38'
Mountain-100 Silver, 38' is name of product;
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesPersonID" ]
5,453
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many type of products did Dalton M. Coleman purchase?
SELECT COUNT(T2.ProductID) FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.FirstName = 'Dalton' AND T1.MiddleInitial = 'M' AND T1.LastName = 'Coleman'
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Sales.CustomerID", "Sales.ProductID" ]
5,454
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What are the full names of the top 3 employees who handled the highest number of sales?
SELECT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID GROUP BY T2.SalesPersonID, T1.FirstName, T1.MiddleInitial, T1.LastName ORDER BY COUNT(T2.SalesID) DESC LIMIT 3
full names of employees = FirstName, MiddleInitital, LastName; highest number of sales refers to MAX(COUNT(SalesID));
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial", "Sales.SalesID", "Sales.SalesPersonID" ]
5,455
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among the "Mountain-500 Black" product types, which type was purchased the most?
SELECT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name LIKE 'Mountain-500 Black%' GROUP BY T2.Quantity, T1.Name ORDER BY SUM(T2.Quantity) DESC LIMIT 1
Mountain-500 Black product types refers to Name like 'Mountain-500 Black%'; purchased the most refers to MAX(SUM(Quantity));
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,456
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many employees sold "ML Road Frame-W - Yellow, 40"?
SELECT COUNT(T2.SalesPersonID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'ML Road Frame-W - Yellow, 40'
ML Road Frame-W - Yellow, 40' is name of product;
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.SalesPersonID" ]
5,457
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many chainring bolts were sold under sales ID 551971?
SELECT T1.Quantity FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T2.Name = 'Chainring Bolts' AND T1.SalesID = 551971
Chainring Bolts' is name of product;
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesID" ]
5,458
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
How many employees sold over 20,000 quantities of "Touring-2000 Blue, 50"?
SELECT COUNT(*) FROM ( SELECT SUM(Quantity) FROM Sales WHERE ProductID IN ( SELECT ProductID FROM Products WHERE Name = 'Touring-2000 Blue, 50' ) GROUP BY Quantity, SalesPersonID HAVING SUM(Quantity) > 20000 )
over 20,000 quantities refers to Quantity > 20000; 'Touring-2000 Blue, 50' is name of product;
[ "Products.Name", "Products.ProductID" ]
5,459
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the total cost of all the "Road-650, Red, 60" products that Abraham E. Bennet sold?
SELECT SUM(T2.Quantity * T3.Price) FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T1.FirstName = 'Abraham' AND T1.MiddleInitial = 'e' AND T1.LastName = 'Bennet' AND T3.Name = 'Road-650 Red, 60'
total cost = SUM(MULTIPLY(Quantity, Price)); 'Road-650, Red, 60' is name of product;
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial", "Products.Name", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesPersonID" ]
5,460
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Which product has the highest total amount of quantity sold? Calculate its overall total price.
SELECT T1.Name, SUM(T2.Quantity * T1.Price) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID GROUP BY T1.ProductID, T1.Name ORDER BY SUM(T2.Quantity) DESC LIMIT 1
highest total amount of quantity refers to MAX(Quantity); overall total price = SUM(MULTIPLY(Quantity, Price));
[ "Products.Name", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,461
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the first name of all the customers whose last name is Chen.
SELECT FirstName, LastName FROM Customers WHERE LastName = 'Chen'
[ "Customers.FirstName", "Customers.LastName" ]
5,462
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Among the employee names, what is the most common middle initial?
SELECT MiddleInitial FROM Employees GROUP BY MiddleInitial ORDER BY COUNT(MiddleInitial) DESC LIMIT 1
most common middle initial refers to MAX(COUNT(MiddleInitial));
[ "Employees.MiddleInitial" ]
5,463
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
What is the average price of products that cost between 100 and 200?
SELECT AVG(Price) FROM Products WHERE Price BETWEEN 100 AND 200
average price = DIVIDE(SUM(Price, COUNT(Price))); cost refers to Price; Price BETWEEN 100 AND 200;
[ "Products.Price" ]
5,464
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Find and list the full name of customers who bought products above-average quantity.
SELECT T2.FirstName, T2.MiddleInitial, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID GROUP BY T1.Quantity HAVING T1.Quantity > ( SELECT AVG(Quantity) FROM Sales )
full name of the customer = FirstName, MiddleInitial, LastName; above-average quantity = Quantity > AVG(Quantity);
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Sales.CustomerID", "Sales.Quantity" ]
5,465
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Give the full name of the customer who bought the most amount of products.
SELECT T3.FirstName, T3.MiddleInitial, T3.LastName FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID ORDER BY T2.Quantity * T1.Price DESC LIMIT 1
full name of the customer = FirstName, MiddleInitial, LastName; most amount of products refers to MAX(MULTIPLY(Quantity, Price));
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.Quantity" ]
5,466
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Of the employees who sold Blade, who has the most amount of sales?
SELECT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID ORDER BY T2.Quantity * T3.Price DESC LIMIT 1
Blade' is name of product; most amount of sales refers to MAX(MULTIPLY(Quantity, Price));
[ "Employees.EmployeeID", "Employees.FirstName", "Employees.LastName", "Employees.MiddleInitial", "Products.Price", "Products.ProductID", "Sales.ProductID", "Sales.Quantity", "Sales.SalesPersonID" ]
5,467
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
List the full name of customers who spend more than 50,000 in descending order the amount spend.
SELECT DISTINCT T3.FirstName, T3.MiddleInitial, T3.LastName FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T2.Quantity * T1.Price > 50000
full name of the customer = FirstName, MiddleInitial, LastName; more than 50,000 in the amount refers to MULTIPLY(Quantity, Price) > 50000;
[ "Customers.CustomerID", "Customers.FirstName", "Customers.LastName", "Customers.MiddleInitial", "Products.Price", "Products.ProductID", "Sales.CustomerID", "Sales.ProductID", "Sales.Quantity" ]
5,468
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Name the product that sold the most quantity.
SELECT T2.Name FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID ORDER BY T1.Quantity DESC LIMIT 1
most quantity refers to MAX(Quantity);
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,469
sales
CREATE TABLE Customers ( CustomerID INTEGER not null primary key, FirstName TEXT not null, MiddleInitial TEXT null, LastName TEXT not null ); CREATE TABLE Employees ( EmployeeID INTEGER not null primary key, FirstName TEXT not null, MiddleI...
Find and list the products that sold below the average quantity.
SELECT DISTINCT T2.Name FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Quantity < ( SELECT AVG(Quantity) FROM Sales )
below the average quantity refers to Quantity < AVG(Quantity);
[ "Products.Name", "Products.ProductID", "Sales.ProductID", "Sales.Quantity" ]
5,470
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many dishes do not have correct data for the year in which it appeared first?
SELECT COUNT(*) FROM Dish WHERE first_appeared < 1851 OR first_appeared > 2012
do not have correct data refers to first_appeared < 1851 or first_appeared > 2012;
[ "Dish.first_appeared" ]
5,471
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Which dish lasted longer, Anchovies or Fresh lobsters in every style?
SELECT CASE WHEN SUM(CASE WHEN name = 'Anchovies' THEN last_appeared - first_appeared ELSE 0 END) - SUM(CASE WHEN name = 'Fresh lobsters in every style' THEN last_appeared - first_appeared ELSE 0 END) > 0 THEN 'Anchovies' ELSE 'Fresh lobsters in every style' END FROM Dish WHERE name IN ('Fresh lobsters in every style',...
if (SUBTRACT(last_appeared, first_appeared) WHERE name = 'Anchovies') > (SUBTRACT(last_appeared, first_appeared) WHERE name = 'Fresh lobsters in every style'), it means 'Anchovies' lasted longer; if (SUBTRACT(last_appeared , first_appeared) WHERE name = 'Fresh lobsters in every style') > (SUBTRACT(last_appeared , first...
[ "Dish.first_appeared", "Dish.last_appeared", "Dish.name" ]
5,472
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Among all the dishes that were once free, what is the name of the dish that had appeared on most menus?
SELECT name FROM Dish WHERE lowest_price = 0 ORDER BY menus_appeared DESC LIMIT 1
dishes that were once free refers to lowest_price = 0; appeared on most menus refers to MAX(menus_appeared);
[ "Dish.lowest_price", "Dish.menus_appeared", "Dish.name" ]
5,473
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many menus with the name "Waldorf Astoria" have 4 pages?
SELECT COUNT(*) FROM Menu WHERE name = 'Waldorf Astoria' AND page_count = 4
4 pages refers to page_count = 4;
[ "Menu.name", "Menu.page_count" ]
5,474
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
What is the name of the dish that appeared on the upper left corner on menu page no. 1389?
SELECT T1.name FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T2.menu_page_id = 1389 AND T2.xpos < 0.25 AND T2.ypos < 0.25
appeared on the upper left corner on menu refers to xpos < 0.25 AND ypos < 0.25; menu page no. refers to menu_page_id; menu_page_id = 1389;
[ "Dish.id", "Dish.name", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuItem.xpos", "MenuItem.ypos" ]
5,475
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Please list the prices of the dish "Clear green turtle" on every menu page it appeared on.
SELECT T2.price FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T1.name = 'Clear green turtle'
Clear green turtle is a name of dish;
[ "Dish.id", "Dish.name", "MenuItem.dish_id", "MenuItem.price" ]
5,476
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Among all the menu pages with the appearance of the dish "Clear green turtle", how many of them have the dish at a stable price?
SELECT SUM(CASE WHEN T1.name = 'Clear green turtle' THEN 1 ELSE 0 END) FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T1.highest_price IS NULL
Clear green turtle is a name of dish; stable price refers to highest_price is null;
[ "Dish.highest_price", "Dish.id", "Dish.name", "MenuItem.dish_id" ]
5,477
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
What is the highest price of the dish "Clear green turtle" on a menu page?
SELECT T2.price FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T1.name = 'Clear green turtle' ORDER BY T2.price DESC LIMIT 1
highest price refers to MAX(Price); Clear green turtle is a name of dish;
[ "Dish.id", "Dish.name", "MenuItem.dish_id", "MenuItem.price" ]
5,478
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Please list the IDs of all the menus in which the dish "Clear green turtle" had appeared.
SELECT T1.menu_id FROM MenuPage AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.menu_page_id INNER JOIN Dish AS T3 ON T2.dish_id = T3.id WHERE T3.name = 'Clear green turtle'
Clear green turtle is a name of dish;
[ "Dish.id", "Dish.name", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id" ]
5,479
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Among the menus in which the dish "Clear green turtle" had appeared, how many of them used the dollar as their currency?
SELECT SUM(CASE WHEN T3.currency = 'Dollars' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T4.name = 'Clear green turtle'
Clear green turtle is a name of dish; dollar as currency refers to currency = 'Dollars';
[ "Dish.id", "Dish.name", "Menu.currency", "Menu.id", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id" ]
5,480
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Among the menus in which the dish "Clear green turtle" had appeared, how many of them did not support taking out or booking in advance?
SELECT SUM(CASE WHEN T4.name = 'Clear green turtle' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T3.call_number IS NULL
Clear green turtle is a name of dish; not support taking out or booking in advance refers to call_number is null;
[ "Dish.id", "Dish.name", "Menu.call_number", "Menu.id", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id" ]
5,481
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Please list the names of all the dishes that appeared on the menu "Zentral Theater Terrace".
SELECT T4.name FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T3.name = 'Zentral Theater Terrace'
Zentral Theater Terrace is a name of menu;
[ "Dish.id", "Dish.name", "Menu.id", "Menu.name", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id" ]
5,482
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Which dish has the highest price on the menu "Zentral Theater Terrace"? Please give its name.
SELECT T4.name FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T3.name = 'Zentral Theater Terrace' ORDER BY T1.price DESC LIMIT 1
highest price refers to MAX(Price); Zentral Theater Terrace is a name of menu;
[ "Dish.id", "Dish.name", "Menu.id", "Menu.name", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuItem.price", "MenuPage.id", "MenuPage.menu_id" ]
5,483
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many dishes are there on the menu "Zentral Theater Terrace"?
SELECT SUM(CASE WHEN T3.name = 'Zentral Theater Terrace' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id
Zentral Theater Terrace is a name of menu;
[ "Menu.id", "Menu.name", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id" ]
5,484
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many dishes are there in total in the menus with the name "Waldorf Astoria"?
SELECT SUM(CASE WHEN T3.name = 'Waldorf Astoria' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id
FALSE;
[ "Menu.id", "Menu.name", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id" ]
5,485
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Please list the IDs of the menus that are DIYs of the restaurant and have the dish "Clear green turtle".
SELECT T2.menu_id FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T4.name = 'Clear green turtle' AND T3.sponsor IS NULL
IDs of the menus refers to menu_id; menus that are DIYs of the restaurant refers to sponsor is null; Clear green turtle is a name of dish;
[ "Dish.id", "Dish.name", "Menu.id", "Menu.sponsor", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id" ]
5,486
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
What is the average page number of the menus that have the dish "Clear green turtle"?
SELECT AVG(T1.page_number) FROM MenuPage AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.menu_page_id INNER JOIN Dish AS T3 ON T2.dish_id = T3.id WHERE T3.name = 'Clear green turtle'
average page number = AVG(page_number); Clear green turtle is a name of dish;
[ "Dish.id", "Dish.name", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.page_number" ]
5,487
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
What is the average price of the dishes on the menu "Zentral Theater Terrace"?
SELECT SUM(T1.price) / COUNT(T1.price) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id WHERE T3.name = 'Zentral Theater Terrace'
average price = AVG(price); Zentral Theater Terrace refers to menu;
[ "Menu.id", "Menu.name", "MenuItem.menu_page_id", "MenuItem.price", "MenuPage.id", "MenuPage.menu_id" ]
5,488
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many menu items were created on 28th March 2011?
SELECT COUNT(*) FROM MenuItem WHERE created_at LIKE '2011-03-28%'
created on 28th March 2011 refers to created_at like '2011-03-28%';
[ "MenuItem.created_at" ]
5,489
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many dishes are included in the menu page ID 144?
SELECT COUNT(*) FROM MenuItem WHERE menu_page_id = 144
FALSE;
[ "MenuItem.menu_page_id" ]
5,490
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many menus were used in Dutcher House?
SELECT COUNT(*) FROM Menu WHERE location = 'Dutcher House'
Dutcher House refers to location = 'Dutcher House';
[ "Menu.location" ]
5,491
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many dishes appeared on a menu more than once?
SELECT COUNT(*) FROM Dish WHERE times_appeared > menus_appeared
appeared on a menu more than once refers to times_appeared > menus_appeared;
[ "Dish.menus_appeared", "Dish.times_appeared" ]
5,492
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many menus were created for steamship?
SELECT COUNT(*) FROM Menu WHERE venue = 'STEAMSHIP'
steamship refers to venue = 'STEAMSHIP';
[ "Menu.venue" ]
5,493
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
How many pages were there on the menu created on 17th November 1898?
SELECT SUM(CASE WHEN T1.date = '1898-11-17' THEN 1 ELSE 0 END) FROM Menu AS T1 INNER JOIN MenuPage AS T2 ON T1.id = T2.menu_id
created on 17th November 1898 refers to date = '1898-11-17';
[ "Menu.date", "Menu.id", "MenuPage.menu_id" ]
5,494
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Name the dishes that were on the menu page ID 174.
SELECT T2.name FROM MenuItem AS T1 INNER JOIN Dish AS T2 ON T2.id = T1.dish_id WHERE T1.menu_page_id = 174
FALSE;
[ "Dish.id", "Dish.name", "MenuItem.dish_id", "MenuItem.menu_page_id" ]
5,495
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
List the names and menu page IDs of the dishes that first appeared in 1861.
SELECT T2.name, T1.dish_id FROM MenuItem AS T1 INNER JOIN Dish AS T2 ON T2.id = T1.dish_id WHERE T2.first_appeared = 1861
first appeared in 1861 refers to first_appeared = 1861;
[ "Dish.first_appeared", "Dish.id", "Dish.name", "MenuItem.dish_id" ]
5,496
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Among the dishes on menu page ID 7610, list the names and highest prices of the dishes in menu items that were created on 23rd May 2011.
SELECT T1.name, T2.price FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T2.created_at LIKE '2011-05-23%' ORDER BY T2.price DESC LIMIT 1
highest prices of the dishes refers to MAX(price); created on 23rd May 2011 refers to created_at like '2011-05-23%';
[ "Dish.id", "Dish.name", "MenuItem.created_at", "MenuItem.dish_id", "MenuItem.price" ]
5,497
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
List the dishes included on page number 30 with the least in full height.
SELECT T3.name FROM MenuPage AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.menu_page_id INNER JOIN Dish AS T3 ON T2.dish_id = T3.id WHERE T1.page_number = 30 ORDER BY T1.full_height DESC, T1.full_height ASC LIMIT 1
least in full height refers to MIN(full_height);
[ "Dish.id", "Dish.name", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.full_height", "MenuPage.id", "MenuPage.page_number" ]
5,498
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
Provide the page IDs and name of the menu which had the highest page count.
SELECT T1.page_number, T2.name FROM MenuPage AS T1 INNER JOIN Menu AS T2 ON T2.id = T1.menu_id ORDER BY T2.page_count DESC LIMIT 1
page IDs refers to page_number; highest page count refers to MAX(page_count);
[ "Menu.id", "Menu.name", "Menu.page_count", "MenuPage.menu_id", "MenuPage.page_number" ]
5,499
menu
CREATE TABLE Dish ( id INTEGER primary key, name TEXT, description TEXT, menus_appeared INTEGER, times_appeared INTEGER, first_appeared INTEGER, last_appeared INTEGER, lowest_price REAL, highest_price REAL ); CREATE TABLE Menu ( id ...
On the menu with the most dishes, how many dishes were there on its second page?
SELECT COUNT(T1.dish_id) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id WHERE T2.page_number = 2 GROUP BY T3.name ORDER BY T3.dish_count DESC LIMIT 1
menu with the most dishes refers to menu.id with MAX(dish_count); second page refers to page_number = 2;
[ "Menu.dish_count", "Menu.id", "Menu.name", "MenuItem.dish_id", "MenuItem.menu_page_id", "MenuPage.id", "MenuPage.menu_id", "MenuPage.page_number" ]