id int64 0 9.43k | db_id stringclasses 69
values | schema stringclasses 69
values | question stringlengths 24 325 | output stringlengths 23 804 | evidence stringlengths 0 673 | filtered_schema listlengths 0 16 |
|---|---|---|---|---|---|---|
6,100 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | What is the title of the book in the order ID 931? | SELECT T1.title FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id WHERE T2.order_id = 931 | [
"book.book_id",
"book.title",
"order_line.book_id",
"order_line.order_id"
] | |
6,101 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | What is the language of the book titled Zorro? | SELECT T2.language_name FROM book AS T1 INNER JOIN book_language AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'Zorro' | "Zorro" is the title of the book; langauge refers to language_name | [
"book.language_id",
"book.title",
"book_language.language_id",
"book_language.language_name"
] |
6,102 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | Provide the email of the customers that purchased books with a price range of 3 to 5 dollars. | SELECT DISTINCT T3.email FROM order_line AS T1 INNER JOIN cust_order AS T2 ON T2.order_id = T1.order_id INNER JOIN customer AS T3 ON T3.customer_id = T2.customer_id WHERE T1.price BETWEEN 3 AND 5 | books with a price range of 3 to 5 dollars refers to price BETWEEN 3 AND 5 | [
"cust_order.customer_id",
"cust_order.order_id",
"customer.customer_id",
"customer.email",
"order_line.order_id",
"order_line.price"
] |
6,103 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | List the ISBN of the books that cost 7.5 dollars. | SELECT T1.isbn13 FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id WHERE T2.price = 7.5 | ISBN refers to isbn13; books cost 7.5 dollars refers to price = 7.5 | [
"book.book_id",
"book.isbn13",
"order_line.book_id",
"order_line.price"
] |
6,104 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | Give the publisher's name of the books authored by Alan Lee. | SELECT T4.publisher_name FROM book AS T1 INNER JOIN book_author AS T2 ON T1.book_id = T2.book_id INNER JOIN author AS T3 ON T3.author_id = T2.author_id INNER JOIN publisher AS T4 ON T4.publisher_id = T1.publisher_id WHERE T3.author_name = 'Alan Lee' GROUP BY T4.publisher_name | "Alan Lee" is the author_name; publisher's name refers to publisher_name | [
"author.author_id",
"author.author_name",
"book.book_id",
"book.publisher_id",
"book_author.author_id",
"book_author.book_id",
"publisher.publisher_id",
"publisher.publisher_name"
] |
6,105 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | What is the sum of the number of pages of the books ordered by Mick Sever? | SELECT SUM(T1.num_pages) FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id INNER JOIN cust_order AS T3 ON T3.order_id = T2.order_id INNER JOIN customer AS T4 ON T4.customer_id = T3.customer_id WHERE T4.first_name = 'Mick' AND T4.last_name = 'Sever' | sum of the number of pages refers to Sum(num_pages) | [
"book.book_id",
"book.num_pages",
"cust_order.customer_id",
"cust_order.order_id",
"customer.customer_id",
"customer.first_name",
"customer.last_name",
"order_line.book_id",
"order_line.order_id"
] |
6,106 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | Write down the author's name of the book most recently published. | SELECT T3.author_name FROM book AS T1 INNER JOIN book_author AS T2 ON T1.book_id = T2.book_id INNER JOIN author AS T3 ON T3.author_id = T2.author_id ORDER BY T1.publication_date DESC LIMIT 1 | author's name refers to author_name; book most recently published refers to Max(publication_date) | [
"author.author_id",
"author.author_name",
"book.book_id",
"book.publication_date",
"book_author.author_id",
"book_author.book_id"
] |
6,107 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | In books published by Ace Book, what is the percentage of English books published? | SELECT CAST(SUM(CASE WHEN T1.language_name = 'English' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM book_language AS T1 INNER JOIN book AS T2 ON T1.language_id = T2.language_id INNER JOIN publisher AS T3 ON T3.publisher_id = T2.publisher_id WHERE T3.publisher_name = 'Ace Book' | "Ace Book" is the publisher_name; English book refers to language_name = 'English'; percentage = Divide (Count(book_id where language_name = 'English'), Count(book_id)) * 100 | [
"book.language_id",
"book.publisher_id",
"book_language.language_id",
"book_language.language_name",
"publisher.publisher_id",
"publisher.publisher_name"
] |
6,108 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | Among the books purchased by less than 1 dollar, what is the difference between the number of books with less than 500 pages and books with greater than 500 pages? | SELECT SUM(CASE WHEN T1.num_pages < 500 THEN 1 ELSE 0 END) - SUM(CASE WHEN T1.num_pages > 500 THEN 1 ELSE 0 END) AS dif FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id WHERE T2.price < 1 | book purchased by less than 1 dollar refers to price < 1; books with less than 500 pages refers to num_pages < 500; greater than 500 pages refers to num_pages > 500; Difference = Subtract (Count(book_id where num_pages < 500), Count(book_id where num_pages > 500)) | [
"book.book_id",
"book.num_pages",
"order_line.book_id",
"order_line.price"
] |
6,109 | books | CREATE TABLE address_status
(
status_id INTEGER
primary key,
address_status TEXT
);
CREATE TABLE author
(
author_id INTEGER
primary key,
author_name TEXT
);
CREATE TABLE book_language
(
language_id INTEGER
primary key,
language_code TEXT,
langua... | What are the language and title of the ordered books with price less than 20% of the average price of all ordered books? | SELECT DISTINCT T3.language_name, T2.title FROM order_line AS T1 INNER JOIN book AS T2 ON T1.book_id = T2.book_id INNER JOIN book_language AS T3 ON T3.language_id = T2.language_id WHERE T1.price * 100 < ( SELECT AVG(price) FROM order_line ) * 20 | language refers to language_name; books with price less than 20% of the average price refers to price < Multiply (AVG(price), 0.2) | [
"book.book_id",
"book.language_id",
"book.title",
"book_language.language_id",
"book_language.language_name",
"order_line.book_id",
"order_line.price"
] |
6,110 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Please list the full names of all the sanitarians under the supervision of Darlisha Jacobs. | SELECT first_name, last_name FROM employee WHERE title = 'Sanitarian' AND supervisor = ( SELECT employee_id FROM employee WHERE first_name = 'Darlisha' AND last_name = 'Jacobs' ) | full name refers to first_name, last_name | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"employee.supervisor",
"employee.title"
] |
6,111 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Please list the full names of the sanitarians who did at least one inspection in May, 2010. | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE strftime('%Y-%m', T2.inspection_date) = '2010-05' AND T1.title = 'Sanitarian' | full name refers to first_name, last_name; in May 2010 refers to inspection_date like '2010-05%'; sanitarian refers to title = 'Sanitarian' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"employee.title",
"inspection.employee_id",
"inspection.inspection_date"
] |
6,112 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections were sanitarian Joshua Rosa responsible for in 2010? | SELECT COUNT(T2.inspection_id) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE strftime('%Y', T2.inspection_date) = '2010' AND T1.first_name = 'Joshua' AND T1.last_name = 'Rosa' | in 2010 refers to inspection_date like '2010%' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.inspection_id"
] |
6,113 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Please list the assumed name of all the facilities inspected by Joshua Rosa. | SELECT DISTINCT T3.dba_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T1.first_name = 'Joshua' AND T1.last_name = 'Rosa' | assumed name refers to dba_name | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"establishment.dba_name",
"establishment.license_no",
"inspection.employee_id",
"inspection.license_no"
] |
6,114 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Among the facilities that have undergone at least one inspection in 2010, how many of them are restaurants or cafeterias? | SELECT COUNT(DISTINCT T1.license_no) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T1.inspection_date) = '2010' AND T2.facility_type = 'Restaurant' | in 2010 refers to inspection_date like '2010%'; restaurant or cafeteria refers to facility_type = 'Restaurant' | [
"establishment.facility_type",
"establishment.license_no",
"inspection.inspection_date",
"inspection.license_no"
] |
6,115 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Please list the location coordinates of all the facilities that had an inspection on 2010/5/11. | SELECT DISTINCT T2.latitude, T2.longitude FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T1.inspection_date = '2010-05-11' | location coordinates refers to latitude, longitude; on 2010/5/11 refers to inspection_date = '2010-05-11' | [
"establishment.latitude",
"establishment.license_no",
"establishment.longitude",
"inspection.inspection_date",
"inspection.license_no"
] |
6,116 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Among the facilities that have undergone at least one inspection in 2010, how many of them are in ward no.42? | SELECT COUNT(DISTINCT T1.license_no) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T1.inspection_date) = '2010' AND T2.ward = 42 | in 2010 refers to inspection_date like '2010%'; in ward no.42 refers to ward = 42 | [
"establishment.license_no",
"establishment.ward",
"inspection.inspection_date",
"inspection.license_no"
] |
6,117 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Please list the full names of all the sanitarians who have inspected the facility Burbank. | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T3.dba_name = 'Burbank' AND T1.title = 'Sanitarian' | full name refers to first_name, last_name; the facility Burbank refers to dba_name = 'Burbank' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"employee.title",
"establishment.dba_name",
"establishment.license_no",
"inspection.employee_id",
"inspection.license_no"
] |
6,118 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Please list the assumed name of all the facilities that failed an inspection in 2010. | SELECT DISTINCT T2.dba_name FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T1.results = 'Fail' AND strftime('%Y', T1.inspection_date) = '2010' | assumed name refers to dba_name; failed an inspection refers to results = 'Fail'; in 2010 refers to inspection_date like '2010%' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.license_no",
"inspection.results"
] |
6,119 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the full name of the sanitarian who inspected Amundsen High School on 2010/5/11? | SELECT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN establishment AS T3 ON T2.license_no = T3.license_no WHERE T2.inspection_date = '2010-05-11' AND T3.dba_name = 'AMUNDSEN HIGH SCHOOL' AND T1.title = 'Sanitarian' | full name refers to first_name, last_name; Amundsen High School refers to dba_name = 'AMUNDSEN HIGH SCHOOL'; on 2010/5/11 refers to inspection_date = '2010-05-11' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"employee.title",
"establishment.dba_name",
"establishment.license_no",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.license_no"
] |
6,120 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Among the inspections done by sanitarian Joshua Rosa, how many of them have the result of "pass"? | SELECT COUNT(T2.inspection_id) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.results = 'Pass' AND T1.first_name = 'Joshua' AND T1.last_name = 'Rosa' | have the result of "pass" refers to results = 'Pass' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_id",
"inspection.results"
] |
6,121 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | After Azha Restaurant Inc. passed the inspection on 2010/1/21, when was the follow-up inspection done? | SELECT T1.followup_to FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T2.dba_name = 'Azha Restaurant Inc.' AND T1.results = 'Pass' AND T1.inspection_date = '2010-01-21' | Azha Restaurant Inc. refers to dba_name = 'Azha Restaurant Inc.'; on 2010/1/21 refers to inspection_date = '2010-01-21'; follow-up inspection date refers to followup_to | [
"establishment.dba_name",
"establishment.license_no",
"inspection.followup_to",
"inspection.inspection_date",
"inspection.license_no",
"inspection.results"
] |
6,122 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Among the facilities that had undergone at least one inspection in 2010, how many of them have the most serious food safety issues? | SELECT COUNT(DISTINCT T2.license_no) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y', T1.inspection_date) = '2010' AND T2.risk_level = 3 | in 2010 refers to inspection_date like '2010%'; the most serious food safety issues refers to risk_level = 3 | [
"establishment.license_no",
"establishment.risk_level",
"inspection.inspection_date",
"inspection.license_no"
] |
6,123 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the average number of inspections carried out in the year 2010 by a sanitarian whose salary is over 70000? | SELECT CAST(SUM(CASE WHEN T2.inspection_date LIKE '2010%' THEN 1 ELSE 0 END) AS REAL) / SUM(CASE WHEN T1.salary > 70000 THEN 1 ELSE 0 END) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id | in the year 2010 refers to inspection_date like '2010%'; salary is over 70000 refers to salary > 70000; average number = divide(sum(inspection where inspection_date like '2010%'), sum(employee_id where salary > 70000)) | [
"employee.employee_id",
"employee.salary",
"inspection.employee_id",
"inspection.inspection_date"
] |
6,124 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the point level of "Refrigeration and metal stem thermometers provided and conspicuous"? | SELECT point_level FROM inspection_point WHERE Description = 'Refrigeration and metal stem thermometers provided and conspicuous ' | "Refrigeration and metal stem thermometers provided and conspicuous" refers to Description = 'Refrigeration and metal stem thermometers provided and conspicuous ' | [
"inspection_point.Description",
"inspection_point.point_level"
] |
6,125 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Which employee was responsible for inspection no.48224? Give the full name. | SELECT T2.first_name, T2.last_name FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T1.inspection_id = 48224 | inspection no.48224 refers to inspection_id = '48224'; full name refers to first_name, last_name; | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_id"
] |
6,126 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections did All Style Buffet Restaurant have? | SELECT COUNT(T2.inspection_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.facility_type = 'Restaurant' AND T1.dba_name = 'All Style Buffet' | All Style Buffet refers to dba_name = 'All Style Buffet'; Restaurant refers to facility_type = 'Restaurant' | [
"establishment.dba_name",
"establishment.facility_type",
"establishment.license_no",
"inspection.inspection_id",
"inspection.license_no"
] |
6,127 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | When did Wing Hung Chop Suey Restaurant have its first inspection? | SELECT MIN(T2.inspection_date) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.aka_name = 'WING HUNG CHOP SUEY RESTAURANT' | Wing Hung Chop Suey Restaurant refers to aka_name = 'WING HUNG CHOP SUEY RESTAURANT'; first inspection refers to min(inspection_date) | [
"establishment.aka_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.license_no"
] |
6,128 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many restaurants were inspected on 2015/5/8? | SELECT COUNT(T2.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.inspection_date = '2015-05-08' AND T1.facility_type = 'Restaurant' | restaurant refers to facility_type = 'Restaurant'; on 2015/5/8 refers to inspection_date = '2015-05-08' | [
"establishment.facility_type",
"establishment.license_no",
"inspection.inspection_date",
"inspection.license_no"
] |
6,129 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many "food maintenance" related violations did inspection no.1454071 have? | SELECT COUNT(T2.point_id) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.inspection_id = '1454071' AND T1.category = 'Food Maintenance' | "food maintenance" related refers to category = 'Food Maintenance'; inspection no.1454071 refers to inspection_id = '1454071' | [
"inspection_point.category",
"inspection_point.point_id",
"violation.inspection_id",
"violation.point_id"
] |
6,130 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | State the number of violations did Royal Thai Cuisine has during the 2015/5/8 inspection. | SELECT COUNT(T3.point_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T2.inspection_date = '2015-05-08' AND T1.dba_name = 'ROYAL THAI CUISINE' | Royal Thai Cuisine refers to dba_name = 'ROYAL THAI CUISINE'; 2015/5/8 refers to inspection_date = '2015-05-08' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.inspection_id",
"inspection.license_no",
"violation.inspection_id",
"violation.point_id"
] |
6,131 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | For the grocery store located at "3635 W DIVERSEY AVE", how many inspections did it have? | SELECT COUNT(T2.inspection_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.address = '3635 W DIVERSEY AVE ' AND T1.facility_type = 'Grocery Store' | grocery store refers to facility_type = 'Grocery Store'; "3635 W DIVERSEY AVE" refers to address = '3635 W DIVERSEY AVE' | [
"establishment.address",
"establishment.facility_type",
"establishment.license_no",
"inspection.inspection_id",
"inspection.license_no"
] |
6,132 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Who is responsible for most of the inspections? Give the full name. | SELECT T.first_name, T.last_name FROM ( SELECT T2.employee_id, T2.first_name, T2.last_name, COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id GROUP BY T2.employee_id, T2.first_name, T2.last_name ORDER BY COUNT(T1.inspection_id) DESC LIMIT 1 ) AS T | full name refers to first_name, last_name; most of the inspections refers to max(count(employee_id)) | [
"T.first_name",
"T.last_name",
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_id"
] |
6,133 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections done by Lisa Tillman ended up with the result of "Out of Business"? | SELECT COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T2.first_name = 'Lisa' AND T2.last_name = 'Tillman' AND T1.results = 'Out of Business' | the result of "Out of Business" refers to results = 'Out of Business' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_id",
"inspection.results"
] |
6,134 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | For the sanitarian who lives on 5000 N Wolcott Ave, how many establishments did he/she inspect in the May of 2011? | SELECT COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T2.address = '5000 N Wolcott Ave' AND T2.title = 'Sanitarian' AND strftime('%Y-%m', T1.inspection_date) = '2011-05' | sanitarian refers to title = 'Sanitarian'; 5000 N Wolcott Ave refers to address = '5000 N Wolcott Ave'; in May 2011 refers to inspection_date between '2011-04-30' and '2011-06-01' | [
"employee.address",
"employee.employee_id",
"employee.title",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.inspection_id"
] |
6,135 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Show the phone number of the sanitarian who was responsible for inspection no.634597. | SELECT T2.phone FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id WHERE T1.inspection_id = 634597 AND T2.title = 'Sanitarian' | phone number refers to phone; sanitarian refers to title = 'Sanitarian'; inspection no.634597 refers to inspection_id = '634597' | [
"employee.employee_id",
"employee.phone",
"employee.title",
"inspection.employee_id",
"inspection.inspection_id"
] |
6,136 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | State the salary of the employee who did the most inspections. | SELECT T1.salary FROM employee AS T1 INNER JOIN ( SELECT T.employee_id, COUNT(T.inspection_id) FROM inspection AS T GROUP BY T.employee_id ORDER BY COUNT(T.inspection_id) DESC LIMIT 1 ) AS T2 ON T1.employee_id = T2.employee_id | the most inspections refers to max(count(employee_id)) | [
"T2.employee_id",
"employee.employee_id",
"employee.salary",
"inspection.employee_id",
"inspection.inspection_id"
] |
6,137 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the average number of inspections did risk level 3 taverns have? | SELECT CAST(COUNT(T2.inspection_id) AS REAL) / COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = 3 AND T1.facility_type = 'TAVERN' | risk level 3 refers to risk_level = '3'; tavern refers to facility_type = 'TAVERN'; average number = divide(count(inspection_id), sum(license_no)) where risk_level = '3' and facility_type = 'TAVERN' | [
"establishment.facility_type",
"establishment.license_no",
"establishment.risk_level",
"inspection.inspection_id",
"inspection.license_no"
] |
6,138 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | State the inspection pass rate of Pockets Restaurant. | SELECT CAST(COUNT(CASE WHEN T2.results = 'Pass' THEN T2.inspection_id ELSE NULL END) AS REAL) * 100 / COUNT(T2.inspection_id) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'POCKETS' AND T1.facility_type = 'Restaurant' | Pockets refers to dba_name = 'POCKETS'; Restaurant refers to facility_type = 'Restaurant'; pass refers to results = 'Pass'; the inspection pass rate = divide(sum(inspection_id where results = 'Pass'), count(license_no)) where dba_name = 'POCKETS' and facility_type = 'Restaurant' | [
"establishment.dba_name",
"establishment.facility_type",
"establishment.license_no",
"inspection.inspection_id",
"inspection.license_no",
"inspection.results"
] |
6,139 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many sanitarian employees in Chicago are from the zip code 60617? | SELECT COUNT(employee_id) FROM employee WHERE zip = '60617' | sanitarian refers to title = 'Sanitarian'; in Chicago refers to city = 'Chicago'; zip code 60617 refers to zip = 60617 | [
"employee.employee_id",
"employee.zip"
] |
6,140 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the assumed name of the business located at 2903 W Irving Park Rd? | SELECT DISTINCT dba_name FROM establishment WHERE address = '2903 W IRVING PARK RD ' | assumed name refers to dba_name; 2903 W Irving Park Rd refers to address = '2903 W IRVING PARK RD ' | [
"establishment.address",
"establishment.dba_name"
] |
6,141 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the full name of the employee with the lowest salary? | SELECT first_name, last_name FROM employee ORDER BY salary ASC LIMIT 1 | full name refers to first_name, last_name; the lowest salary refers to min(salary) | [
"employee.first_name",
"employee.last_name",
"employee.salary"
] |
6,142 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many establishments that are doing business as Homemade Pizza have a risk level of 2? | SELECT COUNT(license_no) FROM establishment WHERE risk_level = 2 AND dba_name = 'HOMEMADE PIZZA' | Homemade Pizza refers to dba_name = 'HOMEMADE PIZZA'; a risk level of 2 refers to risk_level = 2 | [
"establishment.dba_name",
"establishment.license_no",
"establishment.risk_level"
] |
6,143 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections with critical food safety problems are under inspection point id 3? | SELECT COUNT(inspection_id) FROM violation WHERE point_id = 3 AND fine = 500 | critical food safety problems refers to fine = 500; point_id = 3 | [
"violation.fine",
"violation.inspection_id",
"violation.point_id"
] |
6,144 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many employees are under Gregory Cardenas? | SELECT COUNT(T1.employee_id) FROM employee AS T1 WHERE T1.supervisor = ( SELECT employee_id FROM employee WHERE first_name = 'Gregory' AND last_name = 'Cardenas' ) | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"employee.supervisor"
] | |
6,145 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | When did Renaldi's Pizza had its first inspection? | SELECT MIN(T2.inspection_date) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'RENALDI''S PIZZA' | Renaldi's Pizza refers to dba_name = 'RENALDI''S PIZZA'; first inspection refers to min(inspection_date) | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.license_no"
] |
6,146 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the full name of the employee who was responsible for the most inspection in March 2016? | SELECT T3.first_name, T3.last_name FROM ( SELECT T1.employee_id, COUNT(T1.inspection_id) FROM inspection AS T1 WHERE strftime('%Y-%m', T1.inspection_date) = '2016-03' GROUP BY T1.employee_id ORDER BY COUNT(T1.inspection_id) DESC LIMIT 1 ) AS T2 INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id | full name refers to first_name, last_name; the most inspection refers to max(count(employee_id)); in March 2016 refers to inspection_date like '2016-03%' | [
"T2.employee_id",
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.inspection_id"
] |
6,147 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What are the names of the businesses that passed with conditions in May 2012? | SELECT DISTINCT T2.dba_name FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y-%m', T1.inspection_date) = '2012-05' AND T1.results = 'Pass w/ Conditions' | name of business refers to dba_name; passed with conditions refers to results = 'Pass w/ Conditions'; in May 2012 refers to inspection_date like '2012-05%' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.license_no",
"inspection.results"
] |
6,148 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Out of all the short form complaint inspections done by David Hodges, how many businesses passed? | SELECT COUNT(DISTINCT T2.license_no) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.first_name = 'David' AND T1.last_name = 'Hodges' AND T1.employee_id = 153225 AND T2.inspection_type = 'Short Form Complaint' AND T2.results = 'Pass' | short form complaint inspection refers to inspection_type = 'Short Form Complaint'; pass refers to results = 'Pass' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_type",
"inspection.license_no",
"inspection.results"
] |
6,149 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many businesses from ward 42 have at least 5 failed inspection results between 1/1/2010 to 12/31/2015? | SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.inspection_date BETWEEN '2010-01-01' AND '2015-12-31' AND T1.ward = 42 AND T1.license_no IN ( SELECT license_no FROM ( SELECT license_no FROM inspection WHERE results = 'Fail' GROUP BY lic... | ward 42 refers to ward = 42; at least 5 failed inspection results refers to count(results = 'Fail') > = 5; between 1/1/2010 to 12/31/2015 refers to inspection_date between '2010-01-01' and '2015-12-31' | [
"establishment.license_no",
"establishment.ward",
"inspection.inspection_date",
"inspection.license_no",
"inspection.results"
] |
6,150 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How much is the salary of the employee who has the highest number of inspections done of all time? | SELECT T1.salary FROM employee AS T1 INNER JOIN ( SELECT employee_id, COUNT(inspection_id) FROM inspection GROUP BY employee_id ORDER BY COUNT(inspection_id) DESC LIMIT 1 ) AS T2 ON T1.employee_id = T2.employee_id | the highest number of inspections done refers to max(count(employee_id)) | [
"T2.employee_id",
"employee.employee_id",
"employee.salary",
"inspection.employee_id",
"inspection.inspection_id"
] |
6,151 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the assumed name of the business that has the highest total fine in 2014? | SELECT T.dba_name FROM ( SELECT T1.dba_name, SUM(T3.fine) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE strftime('%Y', T2.inspection_date) = '2014' GROUP BY T1.dba_name ORDER BY SUM(T3.fine) DESC LIMIT 1 ) AS... | assumed name of business refers to dba_name; the highest total fine refers to max(sum(fine)); in 2014 refers to inspection_date like '2014%' | [
"T.dba_name",
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.inspection_id",
"inspection.license_no",
"violation.fine",
"violation.inspection_id"
] |
6,152 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the precise location of the establishment with the highest number of failed inspections? | SELECT T1.latitude, T1.longitude FROM establishment AS T1 INNER JOIN ( SELECT license_no FROM inspection WHERE results = 'Fail' GROUP BY license_no ORDER BY COUNT(results) DESC LIMIT 1 ) AS T2 ON T1.license_no = T2.license_no | precise location refers to latitude, longitude; the highest number of failed inspections refers to max(count(results where results = 'Fail')) | [
"T2.license_no",
"establishment.latitude",
"establishment.license_no",
"establishment.longitude",
"inspection.license_no",
"inspection.results"
] |
6,153 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What are the comments of the inspector during the inspection of Taqueria La Fiesta on 1/25/2010? | SELECT T3.inspector_comment FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T2.inspection_date = '2010-01-25' AND T1.dba_name = 'TAQUERIA LA FIESTA' | comment of the inspector refers to inspector_comment; Taqueria La Fiesta refers to dba_name = 'TAQUERIA LA FIESTA'; on 1/25/2010 refers to inspection_date = '2010-01-25' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.inspection_id",
"inspection.license_no",
"violation.inspection_id",
"violation.inspector_comment"
] |
6,154 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How much is the total fine given to Ron of Japan Inc in its inspection done on February 2014? | SELECT SUM(T3.fine) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE strftime('%Y-%m', T2.inspection_date) = '2014-02' AND T1.dba_name = 'RON OF JAPAN INC' | total fine = sum(fine); Ron of Japan Inc refers to dba_name = 'RON OF JAPAN INC'; on February 2014 refers to inspection_date like '2014-02%' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_date",
"inspection.inspection_id",
"inspection.license_no",
"violation.fine",
"violation.inspection_id"
] |
6,155 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | List the full names of the employees who were responsible for inspecting Taqueria La Paz. | SELECT DISTINCT T3.first_name, T3.last_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T1.dba_name = 'TAQUERIA LA PAZ' | full name refers to first_name, last_name; Taqueria La Paz refers to dba_name = 'TAQUERIA LA PAZ' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"establishment.dba_name",
"establishment.license_no",
"inspection.employee_id",
"inspection.license_no"
] |
6,156 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the full name of the employee who gave the highest amount of fine of all time? | SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, SUM(T3.fine) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id GROUP BY T1.first_name, T1.last_name ORDER BY SUM(T3.fine) DESC LIMIT 1 ) t | full name refers to first_name, last_name; the highest amount of fine refers to max(sum(fine)) | [
"T.first_name",
"T.last_name",
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_id",
"violation.fine",
"violation.inspection_id"
] |
6,157 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the average number of inspections done by the top 5 employees with the highest salary? List the names of the said employees. | SELECT CAST(COUNT(DISTINCT T2.inspection_id) AS REAL) / 5, T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.title = 'Sanitarian' ORDER BY T1.salary DESC LIMIT 5 | the highest salary refers to max(salary); sanitarian refers to title = 'Sanitarian'; name refers to first_name, last_name; average number = divide(sum(inspection_id), 5) | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"employee.salary",
"employee.title",
"inspection.employee_id",
"inspection.inspection_id"
] |
6,158 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Which business had the highest number of inspections done? Calculate the percentage of passed and failed inspections of the said business. | SELECT T2.dba_name , CAST(SUM(CASE WHEN T1.results = 'Pass' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.inspection_id) AS percentagePassed , CAST(SUM(CASE WHEN T1.results = 'Fail' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.inspection_id) FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.lice... | business name refers to dba_name; the highest number of inspections done max(count(inspection_id)); percentage of passed inspections = divide(sum(inspection_id where results = 'Pass'), total(inspection_id)) * 100%; percentage of failed inspections = divide(sum(inspection_id where results = 'Fail'), total(inspection_id)... | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_id",
"inspection.license_no",
"inspection.results"
] |
6,159 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the employee's last name at 7211 S Hermitage Ave, Chicago, IL? | SELECT last_name FROM employee WHERE address = '7211 S Hermitage Ave' AND city = 'Chicago' AND state = 'IL' | 7211 S Hermitage Ave refers to address = '7211 S Hermitage Ave'; Chicago refers to city = 'Chicago'; IL refers to state = 'IL' | [
"employee.address",
"employee.city",
"employee.last_name",
"employee.state"
] |
6,160 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the establishment's name and employee involved in the inspection ID 44256 on May 5, 2010? | SELECT T1.dba_name, T3.first_name, T3.last_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T2.inspection_date = '2010-05-05' AND T2.inspection_id = 44256 | establishment's name refers to dba_name; employee name refers to first_name, last_name; inspection ID 44256 refers to inspection_id = 44256; on May 5, 2010 refers to inspection_date = '2010-05-05' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"establishment.dba_name",
"establishment.license_no",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.inspection_id",
"inspection.license_no"
] |
6,161 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Give the address of the schools that passed the inspection in March 2010. | SELECT DISTINCT T1.address FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE strftime('%Y-%m', T2.inspection_date) = '2010-03' AND T2.results = 'Pass' AND T1.facility_type = 'School' | school refers to facility_type = 'School'; pass refers to results = 'Pass'; in March 2010 refers to inspection_date like '2010-03%' | [
"establishment.address",
"establishment.facility_type",
"establishment.license_no",
"inspection.inspection_date",
"inspection.license_no",
"inspection.results"
] |
6,162 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the employee's full name involved in the canvass inspection type on March 09, 2010? | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_date = '2010-03-09' AND T2.inspection_type = 'Canvass' | full name refers to first_name, last_name; canvass inspection type refers to inspection_type = 'Canvass'; on March 09, 2010 refers to inspection_date = '2010-03-09' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.inspection_type"
] |
6,163 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Provide the inspection ID of the establishment named "PIZZA RUSTICA, INC." | SELECT DISTINCT T2.inspection_id FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'PIZZA RUSTICA, INC' | "PIZZA RUSTICA, INC." refers to dba_name = 'PIZZA RUSTICA, INC' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_id",
"inspection.license_no"
] |
6,164 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many restaurants with the highest risk level still passed the inspection? | SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = 3 AND T2.results = 'Pass' AND T1.facility_type = 'Restaurant' | restaurant refers to facility_type = 'Restaurant'; the highest risk level refers to max(risk_level); pass the inspection refers to results = 'Pass' | [
"establishment.facility_type",
"establishment.license_no",
"establishment.risk_level",
"inspection.license_no",
"inspection.results"
] |
6,165 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | List the names of employees involved in an inspection with the Display of Inspection Report Summary category. | SELECT DISTINCT T1.first_name, T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id INNER JOIN inspection_point AS T4 ON T3.point_id = T4.point_id WHERE T4.category = 'Display of Inspection Report Summary' | name refers to first_name, last_name; Display of Inspection Report Summary category refers to category = 'Display of Inspection Report Summary' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_id",
"inspection_point.category",
"inspection_point.point_id",
"violation.inspection_id",
"violation.point_id"
] |
6,166 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the title of the employee involved in inspection ID 60332? | SELECT T1.title FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 60332 | [
"employee.employee_id",
"employee.title",
"inspection.employee_id",
"inspection.inspection_id"
] | |
6,167 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many of the restaurants with the lowest risk level failed the complaint inspection type? | SELECT COUNT(DISTINCT T1.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.risk_level = '1' AND T2.inspection_type = 'Complaint' AND T1.facility_type = 'Restaurant' AND T2.results = 'Fail' | restaurant refers to facility_type = 'Restaurant'; the lowest risk level refers to min(risk_level); failed refers to results = 'Fail'; the complaint inspection type refers to inspection_type = 'Complaint' | [
"establishment.facility_type",
"establishment.license_no",
"establishment.risk_level",
"inspection.inspection_type",
"inspection.license_no",
"inspection.results"
] |
6,168 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Provide the fine paid and the complete address of the establishment with inspection ID 48216. | SELECT DISTINCT T3.fine, T1.state, T1.city, T1.address FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T2.inspection_id = 48216 | complete address refers to state, city, address | [
"establishment.address",
"establishment.city",
"establishment.license_no",
"establishment.state",
"inspection.inspection_id",
"inspection.license_no",
"violation.fine",
"violation.inspection_id"
] |
6,169 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the inspection ID of the inspection with critical point level, $500 fine, and inspector comment "CDI ON 5-17-10"? | SELECT T2.inspection_id FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.fine = 500 AND T1.point_level = 'Critical' AND T2.inspector_comment = 'CDI ON 5-17-10' | critical point level refers to point_level = 'Critical'; $500 fine refers to fine = 500; inspector comment "CDI ON 5-17-10" refers to inspector_comment = 'CDI ON 5-17-10' | [
"inspection_point.point_id",
"inspection_point.point_level",
"violation.fine",
"violation.inspection_id",
"violation.inspector_comment",
"violation.point_id"
] |
6,170 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What are the inspection description and inspector's comments in the inspection ID 164795? | SELECT T1.Description, T2.inspector_comment FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.inspection_id = 44247 | inspection description refers to Description; inspector's comment refers to inspector_comment | [
"inspection_point.Description",
"inspection_point.point_id",
"violation.inspection_id",
"violation.inspector_comment",
"violation.point_id"
] |
6,171 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What are the inspector's comments and clean operating requirement code for inspection ID 54216 and point ID 34? | SELECT T2.inspector_comment, T1.code FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T2.inspection_id = 54216 AND T2.point_id = 34 | inspector's comment refers to inspector_comment; clean operating requirement code refers to code | [
"inspection_point.code",
"inspection_point.point_id",
"violation.inspection_id",
"violation.inspector_comment",
"violation.point_id"
] |
6,172 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Among the establishments that failed in the inspection, what is the percentage of establishments with the highest risk level? | SELECT CAST(COUNT(CASE WHEN T1.risk_level = 3 THEN T1.license_no END) AS REAL) * 100 / COUNT(T1.risk_level) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T2.results = 'Fail' | failed in inspection refers to results = 'Fail'; the highest risk level refers to max(risk_level); percentage = divide(count(license_no where risk_level = max(risk_level)), count(license_no)) * 100% where results = 'Fail' | [
"establishment.license_no",
"establishment.risk_level",
"inspection.license_no",
"inspection.results"
] |
6,173 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Among the employees that receive a salary between $75000 to $85000, what is the difference between the number of employees which undergone an inspection that fined 100 and 500? | SELECT SUM(CASE WHEN T3.fine = 100 THEN 1 ELSE 0 END) - SUM(CASE WHEN T3.fine = 500 THEN 1 ELSE 0 END) FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T1.salary BETWEEN 75000 AND 80000 | salary between $75000 and $85000 refers to 75000 < = salary < = 80000; difference = subtract(count(inspection_id where fine = 100), count(inspection_id where fine = 500)) where 75000 < = salary < = 80000 | [
"employee.employee_id",
"employee.salary",
"inspection.employee_id",
"inspection.inspection_id",
"violation.fine",
"violation.inspection_id"
] |
6,174 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections were done in January 2011? | SELECT COUNT(inspection_id) FROM inspection WHERE strftime('%Y-%m', inspection_date) = '2011-01' | in January 2011 refers to inspection_date like '2011-01%' | [
"inspection.inspection_date",
"inspection.inspection_id"
] |
6,175 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections failed in 2014? | SELECT COUNT(inspection_id) FROM inspection WHERE strftime('%Y', inspection_date) = '2014' AND results = 'Fail' | failed refers to results = 'Fail'; in 2014 refers to inspection_date like '2014%' | [
"inspection.inspection_date",
"inspection.inspection_id",
"inspection.results"
] |
6,176 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Calculate the percentage of inspections with the fine for a minor food safety problem. | SELECT CAST(COUNT(CASE WHEN fine = 100 THEN inspection_id END) AS REAL) * 100 / COUNT(inspection_id) FROM violation | fine for a minor food safety problem refers to fine = 100; percentage = divide(count(inspection_id where fine = 100), sum(inspection_id)) * 100% | [
"violation.fine",
"violation.inspection_id"
] |
6,177 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | List the point IDs and fines of the inspections done on 7th August 2010. | SELECT T2.point_id, T2.fine FROM inspection AS T1 INNER JOIN violation AS T2 ON T1.inspection_id = T2.inspection_id WHERE T1.inspection_date = '2010-08-07' | on 7th August 2010 refers to inspection_date = '2010-08-07' | [
"inspection.inspection_date",
"inspection.inspection_id",
"violation.fine",
"violation.inspection_id",
"violation.point_id"
] |
6,178 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections were done under the personnel category? | SELECT COUNT(T1.inspection_id) FROM violation AS T1 INNER JOIN inspection_point AS T2 ON T1.point_id = T2.point_id WHERE T2.category = 'Personnel' | under the personnel category refers to category = 'Personnel' | [
"inspection_point.category",
"inspection_point.point_id",
"violation.inspection_id",
"violation.point_id"
] |
6,179 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Provide the names and inspection results of the facilities located in Burnham. | SELECT DISTINCT T1.dba_name, T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.city = 'BURNHAM' | names refers to dba_name; inspection result refers to results; in Burnham refers to city = 'BURNHAM' | [
"establishment.city",
"establishment.dba_name",
"establishment.license_no",
"inspection.license_no",
"inspection.results"
] |
6,180 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Compare the number of inspections under toxic items and no-smoking regulations. | SELECT COUNT(CASE WHEN T2.category = 'Toxic Items' THEN T1.inspection_id END) AS Tox_nums , COUNT(CASE WHEN T2.category = 'No Smoking Regulations' THEN T1.inspection_id END) AS NosmoNums FROM violation AS T1 INNER JOIN inspection_point AS T2 ON T1.point_id = T2.point_id | under toxic items refers to category = 'Toxic Items'; no-smoking regulations refers to category = 'No Smoking Regulations' | [
"inspection_point.category",
"inspection_point.point_id",
"violation.inspection_id",
"violation.point_id"
] |
6,181 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Which facilities were inspected by Sarah Lindsey on 20th November 2012? | SELECT DISTINCT T1.dba_name FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T2.inspection_date = '2012-11-20' AND T3.first_name = 'Sarah' AND T3.last_name = 'Lindsey' | facility name refers to dba_name; on 20th November 2012 refers to inspection_date = '2012-11-20' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"establishment.dba_name",
"establishment.license_no",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.license_no"
] |
6,182 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Provide the categories and fines for the inspections done by Lisa Tillman in January 2014. | SELECT DISTINCT T4.category, T3.fine FROM inspection AS T1 INNER JOIN employee AS T2 ON T1.employee_id = T2.employee_id INNER JOIN violation AS T3 ON T1.inspection_id = T3.inspection_id INNER JOIN inspection_point AS T4 ON T3.point_id = T4.point_id WHERE T2.first_name = 'Lisa' AND T2.last_name = 'Tillman' AND strftime(... | in January 2014 refers to inspection_date like '2014-01%' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.inspection_id",
"inspection_point.category",
"inspection_point.point_id",
"violation.fine",
"violation.inspection_id",
"violation.point_id"
] |
6,183 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How many inspections were done under the display of inspection report summary category? | SELECT COUNT(T2.inspection_id) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.category = 'Display of Inspection Report Summary' | under the display of inspection report summary category refers to category = 'Display of Inspection Report Summary' | [
"inspection_point.category",
"inspection_point.point_id",
"violation.inspection_id",
"violation.point_id"
] |
6,184 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | List the types and results of the inspections done on Riverwalk café. | SELECT T2.inspection_type, T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.facility_type = 'RIVERWALK CAFE' | type refers to inspection_type; Riverwalk café refers to facility_type = 'RIVERWALK CAFE' | [
"establishment.facility_type",
"establishment.license_no",
"inspection.inspection_type",
"inspection.license_no",
"inspection.results"
] |
6,185 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Who inspected Jean Samocki and what was the result? | SELECT T3.first_name, T3.last_name, T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN employee AS T3 ON T2.employee_id = T3.employee_id WHERE T1.dba_name = 'JEAN SAMOCKI' | employee's name refers to first_name, last_name; Jean Samocki refers to dba_name = 'JEAN SAMOCKI' | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"establishment.dba_name",
"establishment.license_no",
"inspection.employee_id",
"inspection.license_no",
"inspection.results"
] |
6,186 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | How much did Hacienda Los Torres from ward 36 fine for failing an inspection? | SELECT SUM(T3.fine) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no INNER JOIN violation AS T3 ON T2.inspection_id = T3.inspection_id WHERE T1.dba_name = 'HACIENDA LOS TORRES' AND T1.ward = 36 AND T2.results = 'Fail' | Hacienda Los Torres refers to dba_name = 'HACIENDA LOS TORRES'; ward 36 refers to ward = 36; failing an inspection refers to results = 'Fail'; | [
"establishment.dba_name",
"establishment.license_no",
"establishment.ward",
"inspection.inspection_id",
"inspection.license_no",
"inspection.results",
"violation.fine",
"violation.inspection_id"
] |
6,187 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Calculate the total amount of fine under the food equipment and utensil category. | SELECT SUM(T2.fine) FROM inspection_point AS T1 INNER JOIN violation AS T2 ON T1.point_id = T2.point_id WHERE T1.category = 'Food Equipment and Utensil' | under the food equipment and utensil category refers to category = 'Food Equipment and Utensil' | [
"inspection_point.category",
"inspection_point.point_id",
"violation.fine",
"violation.point_id"
] |
6,188 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Provide the names and locations of the facilities that failed inspections on 29th July 2013. | SELECT T2.dba_name, T2.longitude, T2.latitude FROM inspection AS T1 INNER JOIN establishment AS T2 ON T1.license_no = T2.license_no WHERE T1.inspection_date = '2013-07-29' AND T1.results = 'Fail' | name refers to dba_name; location refers to latitude, longitude; failed inspections refers to results = 'Fail'; on 29th July 2013 refers to inspection_date = '2013-07-29' | [
"establishment.dba_name",
"establishment.latitude",
"establishment.license_no",
"establishment.longitude",
"inspection.inspection_date",
"inspection.license_no",
"inspection.results"
] |
6,189 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Calculate the percentage of inspections with verified quality. Among them, how many businesses were from Chicago? | SELECT CAST(COUNT(CASE WHEN T2.results LIKE '%Pass%' THEN T2.inspection_id END) AS REAL) * 100 / COUNT(T2.inspection_id), COUNT(DISTINCT T2.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.city = 'CHICAGO' | verified quality refers to results like 'Pass%'; from Chicago refers to city = 'CHICAGO'; percentage = divide(count(inspection_id where results like 'Pass%'), sum(inspection_id)) * 100% | [
"establishment.city",
"establishment.license_no",
"inspection.inspection_id",
"inspection.license_no",
"inspection.results"
] |
6,190 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Calculate the average inspections per year done by Jessica Anthony from 2010 to 2017. | SELECT CAST(COUNT(CASE WHEN T1.first_name = 'Jessica' AND T1.last_name = 'Anthony' THEN T2.inspection_id ELSE 0 END) AS REAL) / 8 FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE strftime('%Y', T2.inspection_date) BETWEEN '2010' AND '2017' | from 2010 to 2017 refers to inspection_date > '2010-01-01' AND T2.inspection_id < '2017-12-31'; average inspections per year = divide(count(inspection_id where inspection_date > '2010-01-01' AND T2.inspection_id < '2017-12-31'), 8) | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_date",
"inspection.inspection_id"
] |
6,191 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Provide the first name of employee who did inspection ID 48225? | SELECT T1.first_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 48225 | [
"employee.employee_id",
"employee.first_name",
"inspection.employee_id",
"inspection.inspection_id"
] | |
6,192 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Tell the address of employee who did inspection ID 52238? | SELECT T1.address FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 52238 | [
"employee.address",
"employee.employee_id",
"inspection.employee_id",
"inspection.inspection_id"
] | |
6,193 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | Write down the last name of employee who did inspection ID 52238? | SELECT T1.last_name FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 52238 | [
"employee.employee_id",
"employee.last_name",
"inspection.employee_id",
"inspection.inspection_id"
] | |
6,194 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the inspection result for inspection done by Thomas Langley? | SELECT DISTINCT T2.results FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T1.first_name = 'Thomas' AND T1.last_name = 'Langley' | inspection result refers to results | [
"employee.employee_id",
"employee.first_name",
"employee.last_name",
"inspection.employee_id",
"inspection.results"
] |
6,195 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | List down the address of employees who did inspection dated 11/5/2010. | SELECT DISTINCT T1.address FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_date = '2010-11-05' | dated 11/5/2010 refers to inspection_date = '2010-11-05' | [
"employee.address",
"employee.employee_id",
"inspection.employee_id",
"inspection.inspection_date"
] |
6,196 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | List down the phone numbers of employees who did Canvass inspection. | SELECT DISTINCT T1.phone FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_type = 'Canvass' | phone number refers to phone; Canvass inspection refers to inspection_type = 'Canvass' | [
"employee.employee_id",
"employee.phone",
"inspection.employee_id",
"inspection.inspection_type"
] |
6,197 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What is the job title of employee who did inspection ID 52269? | SELECT T1.title FROM employee AS T1 INNER JOIN inspection AS T2 ON T1.employee_id = T2.employee_id WHERE T2.inspection_id = 52269 | job title refers to title | [
"employee.employee_id",
"employee.title",
"inspection.employee_id",
"inspection.inspection_id"
] |
6,198 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What are the inspection results for Xando Coffee & Bar / Cosi Sandwich Bar? | SELECT DISTINCT T2.results FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'XANDO COFFEE & BAR / COSI SANDWICH BAR' | Xando Coffee & Bar / Cosi Sandwich Bar refers to dba_name = 'XANDO COFFEE & BAR / COSI SANDWICH BAR' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.license_no",
"inspection.results"
] |
6,199 | food_inspection_2 | CREATE TABLE employee
(
employee_id INTEGER
primary key,
first_name TEXT,
last_name TEXT,
address TEXT,
city TEXT,
state TEXT,
zip INTEGER,
phone TEXT,
title TEXT,
salary INTEGER,
supervisor INTEGER,
foreign key (s... | What type of inspection was done at John Schaller? | SELECT DISTINCT T2.inspection_type FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.dba_name = 'JOHN SCHALLER' | type of inspection refers to inspection_type; John Schaller refers to dba_name = 'JOHN SCHALLER' | [
"establishment.dba_name",
"establishment.license_no",
"inspection.inspection_type",
"inspection.license_no"
] |
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