id int64 0 9.43k | db_id stringclasses 69
values | schema stringclasses 69
values | question stringlengths 24 325 | output stringlengths 23 804 | evidence stringlengths 0 673 | filtered_schema listlengths 0 16 |
|---|---|---|---|---|---|---|
8,000 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which country is the University of Oxford located? | SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE university_name = 'University of Oxford' | University of Oxford refers to university_name = 'University of Oxford'; which country refers to country_name | [
"country.country_name",
"country.id",
"university.country_id"
] |
8,001 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many times did the Yale University achieve a score of no less than 10 in the Quality of Education Rank? | SELECT COUNT(*) FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Yale University' AND T2.score >= 10 AND T1.criteria_name = 'Quality of Education Rank' | Yale University refers to university_name = 'Yale University'; a score of no less than 10 refers to score > = 10; in the Quality of Education Rank refers to criteria_name = 'Quality of Education Rank' | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id"
] |
8,002 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What are the names of the criteria under Center for World University Rankings? | SELECT T2.criteria_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Center for World University Rankings' | names of the criteria refers to criteria_name; under Center for World University Rankings refers to system_name = 'Center for World University Rankings'; | [
"ranking_criteria.criteria_name",
"ranking_criteria.ranking_system_id",
"ranking_system.id",
"ranking_system.system_name"
] |
8,003 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | List the names of all the universities that have no less than 50,000 students in the year 2012. | SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.num_students > 50000 AND T1.year = 2012 | have no less than 50,000 students refers to num_students > 50000; name of university refers to university_name; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,004 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Between 2011 to 2016, in which countries can you find the universities where at least 50% of its students are international students? | SELECT DISTINCT T3.country_name FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.pct_international_students > 50 AND T2.year BETWEEN 2011 AND 2016 | Between 2011 to 2016 refers to year BETWEEN 2011 AND 2016; at least 50% of its students are international students refers to pct_international_students > 50; which country refers to country_name | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,005 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many universities have no less than 20,000 female students in 2016? Identify how many of the said universities are located in the United States of America. | SELECT COUNT(*) , SUM(CASE WHEN T3.country_name = 'United States of America' THEN 1 ELSE 0 END) AS nums_in_usa FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.year = 2016 AND T2.num_students * T2.pct_female_students / 100 > 20... | have no less than 20,000 female students refers to DIVIDE(MULTIPLY(pct_female_students, num_students), 100) > 20000; in 2016 refers to year = 2016; located in the United States of America refers to country_name = 'United States of America' | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university_year.num_students",
"university_year.pct_female_students",
"university_year.university_id",
"university_year.year"
] |
8,006 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What are the names of the top 5 universities with the highest number of international students? | SELECT DISTINCT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id ORDER BY (CAST(T1.num_students * T1.pct_international_students AS REAL) / 100) DESC LIMIT 5 | highest number of international students refers to MAX(DIVIDE(MULTIPLY(num_students, pct_international_students), 100)); name of university refers to university_name; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.pct_international_students",
"university_year.university_id"
] |
8,007 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the university ID of the university with the largest student staff ratio? | SELECT university_id FROM university_year ORDER BY student_staff_ratio DESC LIMIT 1 | the largest student staff ratio refers to max(student_staff_ratio) | [
"university_year.student_staff_ratio",
"university_year.university_id"
] |
8,008 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Give the year where a university had the lowest number of students. | SELECT year FROM university_year ORDER BY num_students ASC LIMIT 1 | had the lowest number of students refers to MIN(num_students) | [
"university_year.num_students",
"university_year.year"
] |
8,009 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Compute the average percentage of female students. | SELECT AVG(pct_female_students) FROM university_year | average percentage of female students refers to avg(pct_female_students) | [
"university_year.pct_female_students"
] |
8,010 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the number of international students and number of students in 2013 in university ID 20. | SELECT pct_international_students * num_students, num_students FROM university_year WHERE year = 2013 AND university_id = 20 | number of international students refers to DIVIDE(MULTIPLY(pct_international_students, num_students), 100); in 2013 refers to year = 2013 | [
"university_year.num_students",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,011 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the university ID of Harvard University? | SELECT id FROM university WHERE university_name = 'Harvard University' | of Harvard University refers to university_name = 'Harvard University'; | [
"university.id",
"university.university_name"
] |
8,012 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | List the university ID of the university that scored 100 in 2011. | SELECT university_id FROM university_ranking_year WHERE score = 100 AND year = 2011 | in 2011 refers to year = 2011; score = 100 | [
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,013 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the ranking system of the ranking criteria named Quality of Education Rank. | SELECT T1.system_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T2.criteria_name = 'Quality of Education Rank' | criteria named Quality of Education Rank refers to criteria_name = 'Quality of Education Rank'; ranking system refers to system_name; | [
"ranking_criteria.criteria_name",
"ranking_criteria.ranking_system_id",
"ranking_system.id",
"ranking_system.system_name"
] |
8,014 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the student staff ratio of Harvard University in 2012? | SELECT T1.student_staff_ratio FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Harvard University' AND T1.year = 2012 | Harvard University refers to university_name = 'Harvard University'; in 2012 refers to year = 2012 | [
"university.id",
"university.university_name",
"university_year.student_staff_ratio",
"university_year.university_id",
"university_year.year"
] |
8,015 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Give the location of the university ID 112. | SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.id = 112 | location refers to country_name | [
"country.country_name",
"country.id",
"university.country_id",
"university.id"
] |
8,016 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Calculate the total number of students in universities located in Sweden. | SELECT SUM(T2.num_students) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Sweden' | located in Sweden refers to country_name = 'Sweden'; number of students refers to num_students | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university_year.num_students",
"university_year.university_id"
] |
8,017 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the ranking criteria ID of Brown University in 2014? | SELECT T1.ranking_criteria_id FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Brown University' AND T1.year = 2014 | Brown University refers to university_name = 'Brown University'; in 2014 refers to year = 2014 | [
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,018 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | List the name of universities located in Spain. | SELECT T1.university_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Spain' | name of universities refers to university_name; located in Spain refers to country_name = 'Spain'; | [
"country.country_name",
"country.id",
"university.country_id",
"university.university_name"
] |
8,019 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the criteria name of the university ID 32 in 2015? | SELECT T1.criteria_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id WHERE T2.university_id = 32 AND T2.year = 2015 | in 2015 refers to year = 2015 | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,020 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Compute the average score of the university located in Brazil. | SELECT AVG(T2.score) FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Brazil' | average score refers to avg(score); located in Brazil refers to country_name = 'Brazil'; | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university_ranking_year.score",
"university_ranking_year.university_id"
] |
8,021 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | In which country does the most populated university in 2014 located ? | SELECT T2.country_id FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2014 ORDER BY T1.num_students DESC LIMIT 1 | the most populated university refers to max(num_students); in 2014 refers to year = 2014 | [
"university.country_id",
"university.id",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,022 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Give the score and number of international students in university ID 100 in 2015. | SELECT CAST(T1.num_students * T1.pct_international_students AS REAL) / 100, T2.score FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T2.year = 2015 AND T1.university_id = 100 | number of international students refers to DIVIDE(MULTIPLY(num_students, pct_international_students), 100); in 2015 refers to year = 2015 | [
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year",
"university_year.num_students",
"university_year.pct_international_students",
"university_year.university_id"
] |
8,023 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the student population of the university that scored 98 in 2013? | SELECT SUM(T1.num_students) FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T2.score = 98 AND T1.year = 2013 | student population refers to num_students; in 2013 refers to year = 2013 | [
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,024 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | List the criteria names under the ranking system called Center for World University Ranking. | SELECT T2.criteria_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Center for World University Rankings' | ranking system called Center for World University Ranking refers to system_name = 'Center for World University Rankings'; | [
"ranking_criteria.criteria_name",
"ranking_criteria.ranking_system_id",
"ranking_system.id",
"ranking_system.system_name"
] |
8,025 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the country name of universities with the number of students greater than 98% of the average student population of all universities in 2013. | SELECT DISTINCT T3.country_name FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.year = 2013 AND T2.num_students * 100 > ( SELECT AVG(num_students) FROM university_year ) * 98 | number of students greater than 98% of the average student population of all universities refers to num_students > MULTPLY(num_students, 0.98); in 2013 refers to year = 2013 | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,026 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Among universities that score below 80 in 2015, what is the percentage of international students? | SELECT SUM(CAST(T1.num_students * T1.pct_international_students AS REAL) / 100) / COUNT(*) * 100 FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T2.score < 80 AND T1.year = 2015 | score below 80 refers to score < 80; in 2015 refers to year 2015; percentage of international students refers to DIVIDE(SUM(DIVIDE(MULTIPLY(num_students, pct_international_students), 100)), SUM(num_students)) | [
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_year.num_students",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,027 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many students attended universities were there in 2011? | SELECT SUM(num_students) FROM university_year WHERE year = 2011 | in 2011 refers to year = 2011; | [
"university_year.num_students",
"university_year.year"
] |
8,028 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Among all universities, how many female students were there in 2011? | SELECT SUM(CAST(num_students * pct_female_students AS REAL) / 100) FROM university_year WHERE year = 2011 | in 2011 refers to year = 2011; female students refers to SUM(DIVIDE(MULTIPLY(num_students, pct_female_students), 100)) | [
"university_year.num_students",
"university_year.pct_female_students",
"university_year.year"
] |
8,029 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the student staff ratio at the university with the greatest student staff ratio of all time? | SELECT MAX(student_staff_ratio) FROM university_year ORDER BY student_staff_ratio DESC LIMIT 1 | greatest student staff ratio of all time refers to max(student_staff_ratio) | [
"university_year.student_staff_ratio"
] |
8,030 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the university ID with the most students in 2011? | SELECT university_id FROM university_year WHERE year = 2011 ORDER BY num_students DESC LIMIT 1 | most students refers to MAX(num_students), in 2011 refers to year = 2011 | [
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,031 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many institutions with over 50,000 students in 2011 had a percentage of oversea students of more than 10%? | SELECT COUNT(*) FROM university_year WHERE year = 2011 AND num_students > 50000 AND pct_international_students > 10 | institutions with over 50,000 students refers to num_students > 50000; in 2011 refers to year = 2011; percentage of oversea students of more than 10% refers to pct_international_students > 10; | [
"university_year.num_students",
"university_year.pct_international_students",
"university_year.year"
] |
8,032 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the ID of the university with the highest percentage of female students in 2012. | SELECT university_id FROM university_year WHERE year = 2012 ORDER BY pct_female_students DESC LIMIT 1 | in 2012 refers to year = 2012; highest percentage of female students refers to MAX(pct_female_students); ID of the university refers to university_id | [
"university_year.pct_female_students",
"university_year.university_id",
"university_year.year"
] |
8,033 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which university had the highest reputation in 2012? | SELECT T2.university_name FROM university_ranking_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2012 ORDER BY T1.score DESC LIMIT 1 | had the highest reputation refers to MAX(score), in 2012 refers to year = 2012; which university refers to university_name; | [
"university.id",
"university.university_name",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,034 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Name the university that had the most students in 2011. | SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 ORDER BY T1.num_students DESC LIMIT 1 | in 2011 refers to year = 2011; had the most students refers to MAX(num_students); name of university refers to university_name; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,035 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Indicate the university's name with the highest ranking score in Teaching. | SELECT T1.university_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN ranking_criteria AS T3 ON T3.id = T2.ranking_criteria_id WHERE T3.criteria_name = 'Teaching' ORDER BY T2.score DESC LIMIT 1 | university's name refers to university_name; highest ranking score refers to MAX(score); in Teaching refers to criteria_name = 'Teaching' | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id"
] |
8,036 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the percentage of Harvard university's international students in 2011? | SELECT T1.pct_international_students FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'Harvard University' | Harvard university's refers to university_name = 'Harvard University'; in 2011 refers to year = 2011; percentage of Harvard university's international students refers to pct_international_students | [
"university.id",
"university.university_name",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,037 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many female students were there at Stanford University in 2011? | SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'Stanford University' | in 2011 refers to year 2011; female students refers to DIVIDE(MULTIPLY(pct_female_students, num_students), 100); Stanford University refers to university_name = 'Stanford University'; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.pct_female_students",
"university_year.university_id",
"university_year.year"
] |
8,038 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | In which nation is Harvard University located? | SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'Harvard University' | Harvard University refers to university_name = 'Harvard University'; nation refers to country_name | [
"country.country_name",
"country.id",
"university.country_id",
"university.university_name"
] |
8,039 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the name of the ranking system for Teaching criteria? | SELECT T1.system_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T2.criteria_name = 'Teaching' | Teaching criteria refers to criteria_name = 'Teaching'; name of the ranking system refers to system_name | [
"ranking_criteria.criteria_name",
"ranking_criteria.ranking_system_id",
"ranking_system.id",
"ranking_system.system_name"
] |
8,040 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Name the most famous university in Argentina. | SELECT T1.university_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Argentina' GROUP BY T1.university_name ORDER BY SUM(T2.score) DESC LIMIT 1 | in Argentina refers to country_name = 'Argentina'; most famous refers to MAX(SUM(score)) | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university.university_name",
"university_ranking_year.score",
"university_ranking_year.university_id"
] |
8,041 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | In Argentina, how many universities are there? | SELECT COUNT(*) FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Argentina' | In Argentina refers to country_name = 'Argentina'; | [
"country.country_name",
"country.id",
"university.country_id"
] |
8,042 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which universities have more than 100,000 students in 2011? | SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T1.num_students > 100000 | in 2011 refers to year 2011; more than 100,000 students refers to num_students > 100000; which university refers to university_name; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,043 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many criteria are associated with ranking system Center for World University Rankings? | SELECT COUNT(T2.criteria_name) FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Center for World University Rankings' | ranking system Center for World University Rankings refers to system_name = 'Center for World University Rankings'; | [
"ranking_criteria.criteria_name",
"ranking_criteria.ranking_system_id",
"ranking_system.id",
"ranking_system.system_name"
] |
8,044 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many students at the university earned a score of 90 in 2011? | SELECT COUNT(*) FROM university_year AS T1 INNER JOIN university_ranking_year AS T2 ON T1.university_id = T2.university_id WHERE T2.score = 90 AND T1.year = 2011 | in 2011 refers to year 2011; earned a score of 90 refers to score = 90; | [
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_year.university_id",
"university_year.year"
] |
8,045 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What are the top three universities with the most international students? | SELECT DISTINCT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id GROUP BY T2.university_name ORDER BY SUM(T1.num_students * T1.pct_international_students / 100) DESC LIMIT 3 | most international students refers to MAX(SUM(DIVIDE(MULTIPLE(pct_international_students, num_students), 100))); name of university refers to university_name; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.pct_international_students",
"university_year.university_id"
] |
8,046 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the difference in overall student enrollment and international student enrollment at the Harvard university from 2011 to 2012? | SELECT SUM(T1.num_students) - SUM(CAST(T1.num_students * T1.pct_international_students AS REAL) / 100) FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Harvard University' AND T1.year BETWEEN 2011 AND 2012 | Harvard University refers to university_name = 'Harvard University'; difference in overall student enrollment and international student refers to SUBTRACT(SUM(num_students), SUM(DIVIDE(MULTIPLY(pct_international_students, num_students), 100))); from 2011 to 2012 refers to year BETWEEN 2011 AND 2012 | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,047 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many universities had over 30000 students in 2011? | SELECT COUNT(*) FROM university_year WHERE year = 2011 AND num_students > 30000 | in 2011 refers to year 2011; had over 30000 students refers to num_students > 30000; | [
"university_year.num_students",
"university_year.year"
] |
8,048 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the country ID of the University of Tokyo? | SELECT country_id FROM university WHERE university_name = 'University of Tokyo' | University of Tokyo refers to university_name = 'University of Tokyo'; | [
"university.country_id",
"university.university_name"
] |
8,049 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the ranking system ID of the Center for World University Rankings. | SELECT id FROM ranking_system WHERE system_name = 'Center for World University Rankings' | the Center for World University Rankings refers to system_name = 'Center for World University Rankings'; | [
"ranking_system.id",
"ranking_system.system_name"
] |
8,050 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the ID of the Publications Rank criteria? | SELECT id FROM ranking_criteria WHERE criteria_name = 'Publications Rank' | Publications Rank criteria refers to criteria_name = 'Publications Rank'; | [
"ranking_criteria.criteria_name",
"ranking_criteria.id"
] |
8,051 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many universities had above 30% of international students in 2013? | SELECT COUNT(*) FROM university_year WHERE pct_international_students > 30 AND year = 2013 | had above 30% of international students refers to pct_international_students > 30; in 2013 refers to year = 2013 | [
"university_year.pct_international_students",
"university_year.year"
] |
8,052 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many universities got less than 50 scores under ranking criteria ID 6 in 2011? | SELECT COUNT(*) FROM university_ranking_year WHERE ranking_criteria_id = 6 AND year = 2011 AND score < 50 | in 2011 refers to year 2011; less than 50 scores refers to score < 50; | [
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.year"
] |
8,053 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the number of students at Yale University in 2016. | SELECT T1.num_students FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Yale University' AND T1.year = 2016 | number of students refers to num_students; Yale University refers to university_name = 'Yale University'; in 2016 refers to year = 2016 | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,054 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | List the universities in Denmark. | SELECT T1.university_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Denmark' | in Denmark refers to country_name = 'Denmark'; name of university refers to university_name; | [
"country.country_name",
"country.id",
"university.country_id",
"university.university_name"
] |
8,055 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the number of staff at the University of Auckland in 2015. | SELECT CAST(SUM(T1.num_students) AS REAL) / SUM(T1.student_staff_ratio) FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'University of Auckland' AND T1.year = 2015 | University of Auckland refers to university_name = 'University of Auckland'; in 2015 refers to year = 2015; number of staff refers to DIVIDE(num_students, student_staff_ratio) | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.student_staff_ratio",
"university_year.university_id",
"university_year.year"
] |
8,056 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which country has the University of São Paulo? | SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'University of São Paulo' | the University of São Paulo refers to university_name = 'University of São Paulo'; which country refers to country_name; | [
"country.country_name",
"country.id",
"university.country_id",
"university.university_name"
] |
8,057 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many international students attended Harvard University in 2012? | SELECT CAST(T2.num_students * T2.pct_international_students AS REAL) / 100 FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'Harvard University' AND T2.year = 2012 | Harvard University refers to university_name = 'Harvard University'; international students refers to DIVIDE(MULTIPLY(num_students, pct_international_students), 100); in 2012 refers to year = 2012 | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,058 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Calculate the number of female students at Arizona State University in 2014. | SELECT CAST(T2.num_students * T2.pct_female_students AS REAL) / 100 FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'Arizona State University' AND T2.year = 2014 | female students refers to DIVIDE(MULTIPLY(pct_female_students, num_students), 100); at Arizona State University refers to university_name = 'Arizona State University'; in 2014 refers to year = 2014 | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.pct_female_students",
"university_year.university_id",
"university_year.year"
] |
8,059 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the universities which got the highest scores. | SELECT T1.university_name FROM university AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.university_id GROUP BY T1.university_name ORDER BY SUM(T2.score) DESC LIMIT 1 | got the highest scores refers to MAX(SUM(score)) | [
"university.id",
"university.university_name",
"university_ranking_year.score",
"university_ranking_year.university_id"
] |
8,060 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | List the ranking criteria under the Shanghai Ranking system. | SELECT T2.criteria_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T1.system_name = 'Shanghai Ranking' | Shanghai Ranking system refers to system_name = 'Shanghai Ranking'; ranking criteria refers to criteria_name | [
"ranking_criteria.criteria_name",
"ranking_criteria.ranking_system_id",
"ranking_system.id",
"ranking_system.system_name"
] |
8,061 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | In 2011, which university got the lowest score in teaching criteria? | SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 ORDER BY T2.score ASC LIMIT 1 | in 2011 refers to year 2011; got the lowest score refers to MIN(score), teaching criteria refers to criteria_name = 'Teaching' | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,062 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the ranking system name for the "Quality of Education Rank" criteria. | SELECT T1.system_name FROM ranking_system AS T1 INNER JOIN ranking_criteria AS T2 ON T1.id = T2.ranking_system_id WHERE T2.criteria_name = 'Quality of Education Rank' | the "Quality of Education Rank" criteria refers to criteria_name = 'Quality of Education Rank'; ranking system refers to system_name | [
"ranking_criteria.criteria_name",
"ranking_criteria.ranking_system_id",
"ranking_system.id",
"ranking_system.system_name"
] |
8,063 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many percent of universities got a score above 80 under International criteria in 2016? Among them, name the university which got the highest score. | SELECT CAST(SUM(CASE WHEN T2.score > 80 THEN 1 ELSE 0 END) AS REAL) / COUNT(*), ( SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'International' AND T2.year ... | got a score above 80 refers to score > 80; under International criteria refers to criteria_name = 'International'; in 2016 refers to year = 2016; highest score refers to MAX(score) | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,064 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Provide the ranking criteria and scores in 2005 that were received by Harvard University. | SELECT T1.criteria_name, T2.score FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Harvard University' AND T2.year = 2005 | Harvard University refers to university_name = 'Harvard University'; in 2005 refers to year = 2005; ranking criteria refers to criteria_name; | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,065 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Calculate the average score per university under Alumni criteria in 2008. | SELECT AVG(T2.score) FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id WHERE T1.criteria_name = 'Alumni' AND T2.year = 2008 | under Alumni criteria refers to criteria_name = 'Alumni'; in 2008 refers to year = 2008; average score refers to DIVIDE(SUM(score), COUNT(university_id)) | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.year"
] |
8,066 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Name the university and country which had the highest number of international students in 2015. | SELECT T1.university_name, T3.country_name FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T2.year = 2015 ORDER BY T2.num_students DESC LIMIT 1 | highest number of international students refers to MAX(DIVIDE(MULTIPLY(num_students, pct_international_students), 100)); in 2015 refers to year = 2015; name of university refers to university_name; | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,067 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many students were there in university ID 1 in 2011? | SELECT num_students FROM university_year WHERE year = 2011 AND university_id = 1 | in 2011 refers to year 2011; | [
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,068 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the ID of the university with the most students in 2011? | SELECT university_id FROM university_year WHERE year = 2011 ORDER BY num_students DESC LIMIT 1 | in 2011 refers to year 2011; with the most students refers to MAX(num_students); ID of the university refers to university_id | [
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,069 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Please list the IDs of the universities with a student staff ratio of over 15 in 2011. | SELECT university_id FROM university_year WHERE year = 2011 AND student_staff_ratio > 15 | in 2011 refers to year 2011; student staff ratio of over 15 refers to student_staff_ratio > 15; ID of the university refers to university_id | [
"university_year.student_staff_ratio",
"university_year.university_id",
"university_year.year"
] |
8,070 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Among the universities with over 20000 students in 2011, how many of them have an international students percentage of over 25% in the same year? | SELECT COUNT(*) FROM university_year WHERE year = 2011 AND pct_international_students > 25 AND num_students > 20000 | in 2011 refers to year 2011; with over 20000 students refers to num_students > 20000; international students percentage of over 25% refers to pct_international_students > 25; | [
"university_year.num_students",
"university_year.pct_international_students",
"university_year.year"
] |
8,071 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Please list the IDs of the universities with the top 3 female students percentage in 2011. | SELECT university_id FROM university_year WHERE year = 2011 ORDER BY pct_female_students DESC LIMIT 3 | in 2011 refers to year 2011; top 3 female students percentage refers to MAX(pct_female_students) LIMIT 3; ID of the university refers to university_id | [
"university_year.pct_female_students",
"university_year.university_id",
"university_year.year"
] |
8,072 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | In which year did university ID 1 have the most students? | SELECT year FROM university_year WHERE university_id = 1 ORDER BY num_students DESC LIMIT 1 | have the most students refers to MAX(num_students) | [
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,073 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many students did Harvard University have in 2011? | SELECT T1.num_students FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T2.university_name = 'Harvard University' AND T1.year = 2011 | in 2011 refers to year 2011; Harvard University refers to university_name = 'Harvard University'; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,074 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the name of the university with the most international students in 2011? | SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 ORDER BY T1.pct_international_students DESC LIMIT 1 | in 2011 refers to year 2011; the most international students refers to MAX(DIVIDE(MULTIPLY(num_students, pct_international_students), 100)); name of university refers to university_id | [
"university.id",
"university.university_name",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,075 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Please list the names of all the universities in Australia. | SELECT T1.university_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Australia' | in Australia refers to country_name = 'Australia'; name of university refers to university_name | [
"country.country_name",
"country.id",
"university.country_id",
"university.university_name"
] |
8,076 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Among the universities in Australia, how many of them have more than 15000 students in 2011? | SELECT COUNT(*) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Australia' AND T2.year = 2011 AND T2.num_students > 15000 | in 2011 refers to year 2011; have more than 15000 students refers to num_students > 15000; in Australia refers to country_name = 'Australia'; | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,077 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which country is Harvard University in? | SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'Harvard University' | Harvard University refers to university_name = 'Harvard University'; which country refers to country_name | [
"country.country_name",
"country.id",
"university.country_id",
"university.university_name"
] |
8,078 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the name of the university with the highest score in teaching in the year 2011? | SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 ORDER BY T2.score DESC LIMIT 1 | with the highest score refers to MAX(score); in teaching refers to criteria_name = 'Teaching'; name of university refers to university_name; | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,079 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Please list the names of the universities with a score in teaching of over 90 in 2011. | SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 AND T2.score > 90 | in 2011 refers to year 2011; in teaching refers to criteria_name = 'Teaching'; score in teaching of over 90 refers to score > 90; name of university refers to university_name; | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,080 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Among the universities with a score in teaching of over 90 in 2011, how many of them are in the United States of America? | SELECT COUNT(*) FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 AND T2.score > 90 | in 2011 refers to year 2011; in teaching refers to criteria_name = 'Teaching'; score in teaching of over 90 refers to score > 90; in the United States of America refers to country_name = 'United States of America'; | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,081 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Please list the names of all the ranking criteria of Harvard University in 2011. | SELECT T1.criteria_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Harvard University' AND T2.year = 2011 | in 2011 refers to year 2011; Harvard University refers to university_name = 'Harvard University'; names of all the ranking criteria refers to criteria_name | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,082 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What are the names of the universities that got 98 in teaching in 2011? | SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T1.criteria_name = 'Teaching' AND T2.year = 2011 AND T2.score = 98 | in 2011 refers to year 2011; that got 98 refers to score = 98; in teaching refers to criteria_name = 'Teaching'; name of university refers to university_name | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,083 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Please list the names of all the universities that scored under 60 in teaching in 2011 and are in the United States of America. | SELECT T3.university_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id INNER JOIN country AS T4 ON T4.id = T3.country_id WHERE T4.country_name = 'United States of America' AND T2.year = 2011 AND T2.score < ... | scored under 60 refers to score < 60; in 2011 refers to year 2011; in teaching refers to criteria_name = 'Teaching'; in the United States of America refers to country_name = 'United States of America'; | [
"country.country_name",
"country.id",
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.country_id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"univers... |
8,084 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Among the universities in Australia, how many of them have a student staff ratio of over 15 in 2011? | SELECT COUNT(*) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id INNER JOIN country AS T3 ON T3.id = T1.country_id WHERE T3.country_name = 'Australia' AND T2.student_staff_ratio > 15 AND T2.year = 2011 | in 2011 refers to year 2011; in Australia refers to country_name = 'Australia'; student staff ratio of over 15 refers to student_staff_ratio > 15 | [
"country.country_name",
"country.id",
"university.country_id",
"university.id",
"university_year.student_staff_ratio",
"university_year.university_id",
"university_year.year"
] |
8,085 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many female students did Stanford University have in 2011? | SELECT CAST(T1.num_students * T1.pct_female_students AS REAL) / 100 FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 AND T2.university_name = 'Stanford University' | in 2011 refers to year 2011; female students refers to DIVIDE(MULTIPLY(pct_female_students, num_students), 100); Stanford University refers to university_name = 'Stanford University'; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.pct_female_students",
"university_year.university_id",
"university_year.year"
] |
8,086 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Among the universities with a score in teaching of over 90 in 2011, what is the percentage of those in the United States of America? | SELECT CAST(SUM(CASE WHEN T4.country_name = 'United States of America' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) AS per FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id INNER JOIN country AS T4 ON T4.id = T3... | in 2011 refers to year 2011; in teaching refers to criteria_name = 'Teaching'; score in teaching of over 90 refers to score > 90; in the United States of America refers to country_name = 'United States of America'; percentage refers to DIVIDE(COUNT(country_name = 'United States of America'), COUNT(id)) | [
"country.country_name",
"country.id",
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.country_id",
"university.id",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,087 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Give the id of "Center for World University Rankings". | SELECT id FROM ranking_system WHERE system_name = 'Center for World University Rankings' | "Center for World University Rankings" refers to system_name = 'Center for World University Rankings'; | [
"ranking_system.id",
"ranking_system.system_name"
] |
8,088 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which country is University of Veterinary Medicine Vienna located in? Give its country id. | SELECT country_id FROM university WHERE university_name = 'University of Veterinary Medicine Vienna' | University of Veterinary Medicine Vienna refers to university_name = 'University of Veterinary Medicine Vienna'; | [
"university.country_id",
"university.university_name"
] |
8,089 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the id of the criteria "Citations Rank"? | SELECT id FROM ranking_criteria WHERE criteria_name = 'Citations Rank' | criteria "Citations Rank" refers to criteria_name = 'Citations Rank'; | [
"ranking_criteria.criteria_name",
"ranking_criteria.id"
] |
8,090 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Show the id of University of Orléans. | SELECT id FROM university WHERE university_name = 'University of Orléans' | University of Orléans refers to university_name = 'University of Orléans'; | [
"university.id",
"university.university_name"
] |
8,091 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | For the university id 268, show its number of students in 2013. | SELECT num_students FROM university_year WHERE university_id = 268 AND year = 2013 | number of students refers to num_students; in 2013 refers to year = 2013 | [
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,092 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Show the name of country id 66. | SELECT country_name FROM country WHERE id = 66 | name of country refers to country_name | [
"country.country_name",
"country.id"
] |
8,093 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which country is McMaster University located in? | SELECT T2.country_name FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T1.university_name = 'McMaster University' | McMaster University refers to university_name = 'McMaster University'; which country refers to country_name | [
"country.country_name",
"country.id",
"university.country_id",
"university.university_name"
] |
8,094 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many Turkish universities are there in the database? | SELECT COUNT(*) FROM university AS T1 INNER JOIN country AS T2 ON T1.country_id = T2.id WHERE T2.country_name = 'Turkey' | Turkish universities refers to country_name = 'Turkey'; | [
"country.country_name",
"country.id",
"university.country_id"
] |
8,095 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | Which university had the most students in 2011? Show its name. | SELECT T2.university_name FROM university_year AS T1 INNER JOIN university AS T2 ON T1.university_id = T2.id WHERE T1.year = 2011 ORDER BY T1.num_students DESC LIMIT 1 | in 2011 refers to year 2011; the most students refers to MAX(num_students); which university refers to university_name; | [
"university.id",
"university.university_name",
"university_year.num_students",
"university_year.university_id",
"university_year.year"
] |
8,096 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | How many students were there in University of Michigan in 2011? | SELECT COUNT(*) FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'University of Michigan' AND T2.year = 2011 | in 2011 refers to year 2011; in University of Michigan refers to university_name = 'University of Michigan'; | [
"university.id",
"university.university_name",
"university_year.university_id",
"university_year.year"
] |
8,097 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | For Chosun University, what was its score on "Influence Rank" in 2015? | SELECT T2.score FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Chosun University' AND T1.criteria_name = 'Influence Rank' AND T2.year = 2015 | Chosun University refers to university_name = 'Chosun University'; in 2015 refers to year = 2015; on "Influence Rank" refers to criteria_name = 'Influence Rank'; | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
8,098 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | What is the percentage of the international students in University of Oslo in 2015? | SELECT T2.pct_international_students FROM university AS T1 INNER JOIN university_year AS T2 ON T1.id = T2.university_id WHERE T1.university_name = 'University of Oslo' AND T2.year = 2015 | percentage of the international students refers to pct_international_students; in 2015 refers to year = 2015; in University of Oslo refers to university_name = 'University of Oslo'; | [
"university.id",
"university.university_name",
"university_year.pct_international_students",
"university_year.university_id",
"university_year.year"
] |
8,099 | university | CREATE TABLE country
(
id INTEGER not null
primary key,
country_name TEXT default NULL
);
CREATE TABLE ranking_system
(
id INTEGER not null
primary key,
system_name TEXT default NULL
);
CREATE TABLE ranking_criteria
(
id INTEGER not null
... | For the University of Southampton in 2015, on which criteria did it score the best? | SELECT T1.criteria_name FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'University of Southampton' AND T2.year = 2015 ORDER BY T2.score DESC LIMIT 1 | University of Southampton refers to university_name = 'University of Southampton'; in 2015 refers to year = 2015; score the best refers to MAX(score); which criteria refers to criteria_name | [
"ranking_criteria.criteria_name",
"ranking_criteria.id",
"university.id",
"university.university_name",
"university_ranking_year.ranking_criteria_id",
"university_ranking_year.score",
"university_ranking_year.university_id",
"university_ranking_year.year"
] |
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