id int64 0 8.66k | db_id stringclasses 146
values | schema stringclasses 146
values | question stringlengths 3 224 | output stringlengths 18 577 |
|---|---|---|---|---|
4,400 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many females does this network has? | SELECT count(*) FROM Person WHERE gender = 'female' |
4,401 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many females are in the network? | SELECT count(*) FROM Person WHERE gender = 'female' |
4,402 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the average age for all person? | SELECT avg(age) FROM Person |
4,403 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the average age for all people in the table? | SELECT avg(age) FROM Person |
4,404 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many different cities are they from? | SELECT count(DISTINCT city) FROM Person |
4,405 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many different cities do people originate from? | SELECT count(DISTINCT city) FROM Person |
4,406 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many type of jobs do they have? | SELECT count(DISTINCT job) FROM Person |
4,407 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many different jobs are listed? | SELECT count(DISTINCT job) FROM Person |
4,408 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who is the oldest person? | SELECT name FROM Person WHERE age = (SELECT max(age) FROM person) |
4,409 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the name of the person who is the oldest? | SELECT name FROM Person WHERE age = (SELECT max(age) FROM person) |
4,410 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who is the oldest person whose job is student? | SELECT name FROM Person WHERE job = 'student' AND age = (SELECT max(age) FROM person WHERE job = 'student' ) |
4,411 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the name of the oldest student? | SELECT name FROM Person WHERE job = 'student' AND age = (SELECT max(age) FROM person WHERE job = 'student' ) |
4,412 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who is the youngest male? | SELECT name FROM Person WHERE gender = 'male' AND age = (SELECT min(age) FROM person WHERE gender = 'male' ) |
4,413 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the name of the youngest male? | SELECT name FROM Person WHERE gender = 'male' AND age = (SELECT min(age) FROM person WHERE gender = 'male' ) |
4,414 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How old is the doctor named Zach? | SELECT age FROM Person WHERE job = 'doctor' AND name = 'Zach' |
4,415 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the age of the doctor named Zach? | SELECT age FROM Person WHERE job = 'doctor' AND name = 'Zach' |
4,416 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who is the person whose age is below 30? | SELECT name FROM Person WHERE age < 30 |
4,417 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the name of the person whose age is below 30? | SELECT name FROM Person WHERE age < 30 |
4,418 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many people whose age is greater 30 and job is engineer? | SELECT count(*) FROM Person WHERE age > 30 AND job = 'engineer' |
4,419 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | HOw many engineers are older than 30? | SELECT count(*) FROM Person WHERE age > 30 AND job = 'engineer' |
4,420 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the average age for each gender? | SELECT avg(age) , gender FROM Person GROUP BY gender |
4,421 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How old is each gender, on average? | SELECT avg(age) , gender FROM Person GROUP BY gender |
4,422 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is average age for different job title? | SELECT avg(age) , job FROM Person GROUP BY job |
4,423 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How old is the average person for each job? | SELECT avg(age) , job FROM Person GROUP BY job |
4,424 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is average age of male for different job title? | SELECT avg(age) , job FROM Person WHERE gender = 'male' GROUP BY job |
4,425 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the average age for a male in each job? | SELECT avg(age) , job FROM Person WHERE gender = 'male' GROUP BY job |
4,426 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is minimum age for different job title? | SELECT min(age) , job FROM Person GROUP BY job |
4,427 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How old is the youngest person for each job? | SELECT min(age) , job FROM Person GROUP BY job |
4,428 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the number of people who is under 40 for each gender. | SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender |
4,429 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many people are under 40 for each gender? | SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender |
4,430 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name of people whose age is greater than any engineer sorted by their age. | SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = 'engineer') ORDER BY age |
4,431 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the name of all the people who are older than at least one engineer? Order them by age. | SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = 'engineer') ORDER BY age |
4,432 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the number of people whose age is greater than all engineers. | SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = 'engineer') |
4,433 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | How many people are older than every engineer? | SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = 'engineer') |
4,434 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | list the name, job title of all people ordered by their names. | SELECT name , job FROM Person ORDER BY name |
4,435 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names and job titles of every person ordered alphabetically by name? | SELECT name , job FROM Person ORDER BY name |
4,436 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the names of all person sorted in the descending order using age. | SELECT name FROM Person ORDER BY age DESC |
4,437 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of everybody sorted by age in descending order? | SELECT name FROM Person ORDER BY age DESC |
4,438 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name and age of all males in order of their age. | SELECT name FROM Person WHERE gender = 'male' ORDER BY age |
4,439 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the name and age of every male? Order the results by age. | SELECT name FROM Person WHERE gender = 'male' ORDER BY age |
4,440 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name and age of the person who is a friend of both Dan and Alice. | SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice' |
4,441 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names and ages of every person who is a friend of both Dan and Alice? | SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice' |
4,442 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name and age of the person who is a friend of Dan or Alice. | SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' OR T2.friend = 'Alice' |
4,443 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the different names and ages of every friend of either Dan or alice? | SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Dan' OR T2.friend = 'Alice' |
4,444 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name of the person who has friends with age above 40 and under age 30? | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) |
4,445 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of every person who has a friend over 40 and under 30? | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) |
4,446 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name of the person who has friends with age above 40 but not under age 30? | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) |
4,447 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of the people who are older 40 but no friends under age 30? | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) |
4,448 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name of the person who has no student friends. | SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = 'student' |
4,449 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of the people who have no friends who are students? | SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = 'student' |
4,450 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the person who has exactly one friend. | SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1 |
4,451 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of everybody who has exactly one friend? | SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1 |
4,452 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who are the friends of Bob? | SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = 'Bob' |
4,453 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who are Bob's friends? | SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = 'Bob' |
4,454 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name of persons who are friends with Bob. | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Bob' |
4,455 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of all of Bob's friends? | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Bob' |
4,456 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the names of females who are friends with Zach | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Zach' AND T1.gender = 'female' |
4,457 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of all females who are friends with Zach? | SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Zach' AND T1.gender = 'female' |
4,458 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the female friends of Alice. | SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'female' |
4,459 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are all the friends of Alice who are female? | SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'female' |
4,460 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the male friend of Alice whose job is a doctor? | SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'male' AND T1.job = 'doctor' |
4,461 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who are the friends of Alice that are doctors? | SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Alice' AND T1.gender = 'male' AND T1.job = 'doctor' |
4,462 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who has a friend that is from new york city? | SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = 'new york city' |
4,463 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of all friends who are from New York? | SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = 'new york city' |
4,464 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who has friends that are younger than the average age? | SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person) |
4,465 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the different names of friends who are younger than the average age for a friend? | SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person) |
4,466 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who has friends that are older than the average age? Print their friends and their ages as well | SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person) |
4,467 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Whare the names, friends, and ages of all people who are older than the average age of a person? | SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person) |
4,468 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who is the friend of Zach with longest year relationship? | SELECT friend FROM PersonFriend WHERE name = 'Zach' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach') |
4,469 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Which friend of Zach has the longest-lasting friendship? | SELECT friend FROM PersonFriend WHERE name = 'Zach' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach') |
4,470 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the age of the friend of Zach with longest year relationship? | SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Zach' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach') |
4,471 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the ages of all of Zach's friends who are in the longest relationship? | SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = 'Zach' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = 'Zach') |
4,472 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name of persons who are friends with Alice for the shortest years. | SELECT name FROM PersonFriend WHERE friend = 'Alice' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = 'Alice') |
4,473 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of all people who are friends with Alice for the shortest amount of time? | SELECT name FROM PersonFriend WHERE friend = 'Alice' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = 'Alice') |
4,474 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find the name, age, and job title of persons who are friends with Alice for the longest years. | SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = 'Alice') |
4,475 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names, ages, and jobs of all people who are friends with Alice for the longest amount of time? | SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = 'Alice' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = 'Alice') |
4,476 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Who is the person that has no friend? | SELECT name FROM person EXCEPT SELECT name FROM PersonFriend |
4,477 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of all people who do not have friends? | SELECT name FROM person EXCEPT SELECT name FROM PersonFriend |
4,478 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Which person whose friends have the oldest average age? | SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1 |
4,479 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the name of the person who has the oldest average age for their friends, and what is that average age? | SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1 |
4,480 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the total number of people who has no friend living in the city of Austin. | SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = 'Austin') |
4,481 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What is the total number of people who have no friends living in Austin? | SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = 'Austin') |
4,482 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | Find Alice's friends of friends. | SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = 'Alice' AND T4.name != 'Alice' |
4,483 | network_2 | CREATE TABLE Person (
name varchar(
20
) PRIMARY KEY,
age INTEGER,
city TEXT,
gender TEXT,
job TEXT
);
CREATE TABLE PersonFriend (
name varchar(
20
),
friend varchar(
20
),
year INTEGER,
FOREIGN KEY (
name
) REFERENCES Person(
name
),
FOREIGN KEY (
friend
) REFERE... | What are the names of all of Alice's friends of friends? | SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = 'Alice' AND T4.name != 'Alice' |
4,484 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | How many members are there? | SELECT count(*) FROM member |
4,485 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | List the names of members in ascending alphabetical order. | SELECT Name FROM member ORDER BY Name ASC |
4,486 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | What are the names and countries of members? | SELECT Name , Country FROM member |
4,487 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the names of members whose country is "United States" or "Canada". | SELECT Name FROM member WHERE Country = "United States" OR Country = "Canada" |
4,488 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the different countries and the number of members from each. | SELECT Country , COUNT(*) FROM member GROUP BY Country |
4,489 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the most common country across members. | SELECT Country FROM member GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1 |
4,490 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Which countries have more than two members? | SELECT Country FROM member GROUP BY Country HAVING COUNT(*) > 2 |
4,491 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the leader names and locations of colleges. | SELECT Leader_Name , College_Location FROM college |
4,492 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the names of members and names of colleges they go to. | SELECT T2.Name , T1.Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID |
4,493 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the names of members and the locations of colleges they go to in ascending alphabetical order of member names. | SELECT T2.Name , T1.College_Location FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID ORDER BY T2.Name ASC |
4,494 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the distinct leader names of colleges associated with members from country "Canada". | SELECT DISTINCT T1.Leader_Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID WHERE T2.Country = "Canada" |
4,495 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the names of members and the decoration themes they have. | SELECT T1.Name , T2.Decoration_Theme FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID |
4,496 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the names of members that have a rank in round higher than 3. | SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID WHERE T2.Rank_in_Round > 3 |
4,497 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | Show the names of members in ascending order of their rank in rounds. | SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID ORDER BY Rank_in_Round ASC |
4,498 | decoration_competition | CREATE TABLE "college" (
"College_ID" int,
"Name" text,
"Leader_Name" text,
"College_Location" text,
PRIMARY KEY (
"College_ID"
)
);
CREATE TABLE "member" (
"Member_ID" int,
"Name" text,
"Country" text,
"College_ID" int,
PRIMARY KEY (
"Member_ID"
),
FOREIGN KEY (
"College_ID"
) REFERENCES `colle... | List the names of members who did not participate in any round. | SELECT Name FROM member WHERE Member_ID NOT IN (SELECT Member_ID FROM round) |
4,499 | document_management | CREATE TABLE `Roles` (
`role_code` VARCHAR(
15
) PRIMARY KEY,
`role_description` VARCHAR(
80
)
);
CREATE TABLE `Users` (
`user_id` INTEGER PRIMARY KEY,
`role_code` VARCHAR(
15
) NOT NULL,
`user_name` VARCHAR(
40
),
`user_login` VARCHAR(
40
),
`password` VARCHAR(
40
),
FOREIGN KEY (
... | Find the name and access counts of all documents, in alphabetic order of the document name. | SELECT document_name , access_count FROM documents ORDER BY document_name |
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