prompt stringlengths 155 8.09k | answer stringlengths 18 577 |
|---|---|
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the policy types more than 4 customers use. Show their type code., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Se... | SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING count(*) > 4 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the total and average amount of settlements., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_ID IN... | SELECT sum(settlement_amount) , avg(settlement_amount) FROM settlements |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the sum and average of all settlement amounts., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_I... | SELECT sum(settlement_amount) , avg(settlement_amount) FROM settlements |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the name of services that have been used for more than 2 times in first notification of loss., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Cu... | SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING count(*) > 2 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which services have been used more than twice in first notification of loss? Return the service name., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY ... | SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING count(*) > 2 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the effective date of the claim that has the largest amount of total settlement?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)... | SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY sum(t2.settlement_amount) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the claim that has the largest total settlement amount. Return the effective date of the claim., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (... | SELECT t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY sum(t2.settlement_amount) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many policies are listed for the customer named "Dayana Robel"?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Servi... | SELECT count(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Dayana Robel" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Count the total number of policies used by the customer named "Dayana Robel"., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE T... | SELECT count(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Dayana Robel" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the name of the customer who has the most policies listed?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Servic... | SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which customer uses the most policies? Give me the customer name., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Service... | SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY count(*) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are all the policy types of the customer named "Dayana Robel"?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Servi... | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "Dayana Robel" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Tell me the types of the policy used by the customer named "Dayana Robel"., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABL... | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = "Dayana Robel" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are all the policy types of the customer that has the most policies listed?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREAT... | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.custo... |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List all the policy types used by the customer enrolled in the most policies., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE T... | SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.custo... |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List all the services in the alphabetical order., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_ID INT... | SELECT service_name FROM services ORDER BY service_name |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Give me a list of all the service names sorted alphabetically., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (... | SELECT service_name FROM services ORDER BY service_name |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many services are there?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_ID INTEGER NOT NULL,Servic... | SELECT count(*) FROM services |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Count the total number of available services., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_ID INTEGE... | SELECT count(*) FROM services |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the names of users who do not have a first notification of loss record., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TA... | SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which customers do not have a first notification of loss record? Give me the customer names., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer... | SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the names of customers who have used either the service "Close a policy" or the service "Upgrade a policy"., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),P... | SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" OR t3.service_name = "Upgrade a policy" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which customers have used the service named "Close a policy" or "Upgrade a policy"? Give me the customer names., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PR... | SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" OR t3.service_name = "Upgrade a policy" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the names of customers who have used both the service "Close a policy" and the service "New policy application"., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(... | SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.cus... |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which customers have used both the service named "Close a policy" and the service named "Upgrade a policy"? Give me the customer names., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Cust... | SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = "Close a policy" INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.cus... |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the IDs of customers whose name contains "Diana"., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_... | SELECT customer_id FROM customers WHERE customer_name LIKE "%Diana%" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the IDs of customers who have "Diana" in part of their names?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Se... | SELECT customer_id FROM customers WHERE customer_name LIKE "%Diana%" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the maximum and minimum settlement amount on record?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (S... | SELECT max(settlement_amount) , min(settlement_amount) FROM settlements |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the maximum and minimum settlement amount., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_ID INTE... | SELECT max(settlement_amount) , min(settlement_amount) FROM settlements |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List all the customers in increasing order of IDs., schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_ID I... | SELECT customer_id , customer_name FROM customers ORDER BY customer_id ASC |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the ordered list of customer ids?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRIMARY KEY (Customer_ID)); CREATE TABLE Services (Service_ID INTEGER NO... | SELECT customer_id , customer_name FROM customers ORDER BY customer_id ASC |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Retrieve the open and close dates of all the policies associated with the customer whose name contains "Diana", schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40),PRI... | SELECT t2.date_opened , t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "%Diana%" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the open and close dates of all the policies used by the customer who have "Diana" in part of their names?, schema:CREATE TABLE Customers (Customer_ID INTEGER NOT NULL,Customer_name VARCHAR(40... | SELECT t2.date_opened , t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE "%Diana%" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many kinds of enzymes are there?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name" text,"Locati... | SELECT count(*) FROM enzyme |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the total count of enzymes?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name" text,"Locatio... | SELECT count(*) FROM enzyme |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the name of enzymes in descending lexicographical order., schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id... | SELECT name FROM enzyme ORDER BY name DESC |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of enzymes in descending order?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name... | SELECT name FROM enzyme ORDER BY name DESC |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the names and the locations that the enzymes can make an effect., schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzy... | SELECT name , LOCATION FROM enzyme |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names and locations of all enzymes listed?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,... | SELECT name , LOCATION FROM enzyme |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the maximum Online Mendelian Inheritance in Man (OMIM) value of the enzymes?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CRE... | SELECT max(OMIM) FROM enzyme |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the maximum OMIM value in the database?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name" t... | SELECT max(OMIM) FROM enzyme |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the product, chromosome and porphyria related to the enzymes which take effect at the location 'Cytosol'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" ... | SELECT product , chromosome , porphyria FROM enzyme WHERE LOCATION = 'Cytosol' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the product, chromosome, and porphyria of the enzymes located at 'Cytosol'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREA... | SELECT product , chromosome , porphyria FROM enzyme WHERE LOCATION = 'Cytosol' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of enzymes who does not produce 'Heme'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" i... | SELECT name FROM enzyme WHERE product != 'Heme' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of enzymes whose product is not 'Heme'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" i... | SELECT name FROM enzyme WHERE product != 'Heme' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names and trade names of the medicines which has 'Yes' value in the FDA record?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id... | SELECT name , trade_name FROM medicine WHERE FDA_approved = 'Yes' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names and trade names of the medcines that are FDA approved?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "... | SELECT name , trade_name FROM medicine WHERE FDA_approved = 'Yes' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of enzymes in the medicine named 'Amisulpride' that can serve as an 'inhibitor'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary k... | SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of the enzymes used in the medicine Amisulpride that acts as inhibitors?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id... | SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids and names of the medicine that can interact with two or more enzymes?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); C... | SELECT T1.id , T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING count(*) >= 2 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:For every medicine id, what are the names of the medicines that can interact with more than one enzyme?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,prima... | SELECT T1.id , T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING count(*) >= 2 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids, names and FDA approval status of medicines in descending order of the number of enzymes that it can interact with., schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" t... | SELECT T1.id , T1.Name , T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids, names, and FDA approval status for medicines ordered by descending number of possible enzyme interactions?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA... | SELECT T1.id , T1.Name , T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY count(*) DESC |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the id and name of the enzyme with most number of medicines that can interact as 'activator'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary... | SELECT T1.id , T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the id and name of the enzyme that can interact with the most medicines as an activator?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ... | SELECT T1.id , T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the interaction type of the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primar... | SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the type of interaction for the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,pr... | SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the most common interaction type between enzymes and medicine? And how many are there?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("... | SELECT interaction_type , count(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the most common types of interactions between enzymes and medicine, and how many types are there?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,pr... | SELECT interaction_type , count(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY count(*) DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many medicines have the FDA approval status 'No' ?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"... | SELECT count(*) FROM medicine WHERE FDA_approved = 'No' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many medicines were not approved by the FDA?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name" ... | SELECT count(*) FROM medicine WHERE FDA_approved = 'No' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many enzymes do not have any interactions?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name" te... | SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction ); |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the count of enzymes without any interactions?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"... | SELECT count(*) FROM enzyme WHERE id NOT IN ( SELECT enzyme_id FROM medicine_enzyme_interaction ); |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the id and trade name of the medicines can interact with at least 3 enzymes?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CRE... | SELECT T1.id , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids and trade names of the medicine that can interact with at least 3 enzymes?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id"... | SELECT T1.id , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT(*) >= 3 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the distinct name, location and products of the enzymes which has any 'inhibitor' interaction?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,prima... | SELECT DISTINCT T1.name , T1.location , T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the different names, locations, and products of the enzymes that are capable inhibitor interactions?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text... | SELECT DISTINCT T1.name , T1.location , T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the medicine name and trade name which can both interact as 'inhibitor' and 'activitor' with enzymes., schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,pr... | SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activ... |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the medicine and trade names that can interact as an inhibitor and activitor with enzymes?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary k... | SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activ... |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the medicine names and trade names that cannot interact with the enzyme with product 'Heme'., schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key... | SELECT name , trade_name FROM medicine EXCEPT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the medicine and trade names that cannot interact with the enzyme with the product 'Heme'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary k... | SELECT name , trade_name FROM medicine EXCEPT SELECT T1.name , T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many distinct FDA approval statuses are there for the medicines?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzym... | SELECT count(DISTINCT FDA_approved) FROM medicine |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many different FDA approval statuses exist for medicines?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id... | SELECT count(DISTINCT FDA_approved) FROM medicine |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which enzyme names have the substring "ALA"?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name" text... | SELECT name FROM enzyme WHERE name LIKE "%ALA%" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of enzymes that include the string 'ALA'?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id"... | SELECT name FROM enzyme WHERE name LIKE "%ALA%" |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:find the number of medicines offered by each trade., schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"nam... | SELECT trade_name , count(*) FROM medicine GROUP BY trade_name |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many medicines are offered by each trade name?, schema:CREATE TABLE "medicine" ("id" int,"name" text,"Trade_Name" text,"FDA_approved" text,primary key ("id")); CREATE TABLE "enzyme" ("id" int,"name... | SELECT trade_name , count(*) FROM medicine GROUP BY trade_name |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List all schools and their nicknames in the order of founded year., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"... | SELECT school , nickname FROM university ORDER BY founded |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the different schools and their nicknames, ordered by their founding years?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"A... | SELECT school , nickname FROM university ORDER BY founded |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List all public schools and their locations., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_Home" text,"ACC_Ro... | SELECT school , LOCATION FROM university WHERE affiliation = 'Public' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the public schools and what are their locations?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_Home"... | SELECT school , LOCATION FROM university WHERE affiliation = 'Public' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:When was the school with the largest enrollment founded?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_Home" ... | SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the founded year for the school with the largest enrollment., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,... | SELECT founded FROM university ORDER BY enrollment DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the founded year of the newest non public school., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_Home" te... | SELECT founded FROM university WHERE affiliation != 'Public' ORDER BY founded DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the founded year of the non public school that was founded most recently?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_... | SELECT founded FROM university WHERE affiliation != 'Public' ORDER BY founded DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many schools are in the basketball match?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_Home" text,"ACC_R... | SELECT count(DISTINCT school_id) FROM basketball_match |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Count the number of schools that have had basketball matches., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_H... | SELECT count(DISTINCT school_id) FROM basketball_match |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the highest acc percent score in the competition?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_Home"... | SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the highest acc percent across all basketball matches., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_H... | SELECT acc_percent FROM basketball_match ORDER BY acc_percent DESC LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the primary conference of the school that has the lowest acc percent score in the competition?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regul... | SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the primary conference of the school with the lowest acc percentage score., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_... | SELECT t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t2.acc_percent LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the team name and acc regular season score of the school that was founded for the longest time?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regu... | SELECT t2.team_name , t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the name of the team and the acc during the regular season for the school that was founded the earliest., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"... | SELECT t2.team_name , t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY t1.founded LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the location and all games score of the school that has Clemson as its team name., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,... | SELECT t2.All_Games , t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the all games score and location of the school called Clemson?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" t... | SELECT t2.All_Games , t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson' |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the average enrollment size of the universities that are founded before 1850?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,... | SELECT avg(enrollment) FROM university WHERE founded < 1850 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the average enrollment of universities founded before 1850., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"... | SELECT avg(enrollment) FROM university WHERE founded < 1850 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the enrollment and primary_conference of the oldest college., schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"A... | SELECT enrollment , primary_conference FROM university ORDER BY founded LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the enrollment and primary conference for the university which was founded the earliest?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Se... | SELECT enrollment , primary_conference FROM university ORDER BY founded LIMIT 1 |
You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the total and minimum enrollment of all schools?, schema:CREATE TABLE "basketball_match" ("Team_ID" int,"School_ID" int,"Team_Name" text,"ACC_Regular_Season" text,"ACC_Percent" text,"ACC_Home" ... | SELECT sum(enrollment) , min(enrollment) FROM university |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.