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#include<bits/stdc++.h> using namespace std; int main(){ long long n; cin>>n; for(long long a=sqrt(n);a>0;a--){ if(n%a==0){ cout<<a-2+n/a<<endl; return 0; } } }
#include <bits/stdc++.h> using namespace std; int main() { long int N; cin >>N; long int we,they; for(long int i=sqrt(N);i>=1;i--){ if(N%i==0){we=i;they=N/i;break;} } cout <<we +they -2 <<endl; }
#include<iostream> #include<math.h> using namespace std; int main() { long long int n; cin>>n; int a; for(int i=sqrt(n);i>0;i--) { if(n%i==0) { a=i; break; } } cout<<a+n/a-2; }
#include<iostream> using namespace std; int main(void){ long long n; long long t; cin>>n; t=0; for(long long i=1;i*i<=n;i++){ if(n%i==0){ t=i; } } cout<<t+n/t-2; }
#include<bits/stdc++.h> using namespace std; int main(){ long long a; cin >> a; for(long long i=sqrt(a);i>0;i--){ if(a%i==0){ cout << i+a/i-2 << endl; break; } } }
#include<bits/stdc++.h> using namespace std; typedef long long i64; int main() { i64 n,i,ans; scanf("%lld",&n); for(i=1;i*i<=n;i++) if(n%i==0)ans=i; printf("%lld",ans+n/ans-2); return 0; }
#include <iostream> #include <math.h> #include <limits> using namespace std; int main() { long long int n; cin>>n; long long int i=sqrt(n+10); while (i>=1) {if (n%i==0) {cout <<i+(n/i)-2; break;} else i--; } }
#include<iostream> #include<math.h> using namespace std; int main(){ double x; long long N,i,y; cin >> N; x=sqrt(N); for(i=x;x>=1;i--){if(N%i==0)break; } y=N/i; cout << i-1+y-1 << endl; return 0; }
#include<iostream> using namespace std; int main (void) { long long int i,j,n,ans; cin>>n; i=1; while(1) { j=n/i; if(i*j==n){ans=i+j-2;} if(i>j)break; i++; } cout<<ans; }
#include <bits/stdc++.h> #define rep(i,n) for (int i = 0; i < n; ++i) using namespace std; typedef long long ll; int mod; struct mint { ll x; mint(ll x=0):x(x%mod){} mint& operator+=(const mint a) { (x += a.x) %= mod; return *this; } mint& operator-=(const mint a) { (x += mod-a.x) %= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint a) const { mint res(*this); return res+=a; } mint operator-(const mint a) const { mint res(*this); return res-=a; } mint operator*(const mint a) const { mint res(*this); return res*=a; } }; ll b, ten; mint pow_(mint x, ll t) { if (t == 0) return 1; if (t%2 == 1) { return pow_(x,t-1)*x; } else { mint y = pow_(x,t/2); return y*y; } } mint f(ll l) { if (l == 0) return 0; if (l%2 == 1) { ll pl = l-1; mint x = f(pl); return x*ten + 1; } else { ll pl = l/2; mint x = f(pl); return x*pow_(ten, pl) + x; } } mint g(ll l) { if (l == 0) return 0; if (l%2 == 1) { ll pl = l-1; mint x = g(pl); return x*ten + mint(b)*pl; } else { ll pl = l/2; mint x = g(pl); return x*pow_(ten, pl) + x + mint(b)*pl*f(pl); } } int main() { ll L, a; cin >> L >> a >> b >> mod; ll last = a+b*(L-1); mint ans = 0; ten = 10; for (int i = 1; i <= 18; ++i, ten *= 10) { ll l = ten/10, r = ten-1; if (last < l) continue; if (a > r) continue; ll na = 0; // 初項 ll nl = 0; // 長さ { if (a >= l) na = a; else { na = ((l-a)+(b-1))/b*b+a; na = min(na, last); } } { ll nlast = 0; if (last <= r) nlast = last; else { nlast = (r-a)/b*b+a; } nl = (nlast-na)/b+1; } ans *= pow_(ten, nl); ans += f(nl)*na; ans += g(nl); } cout << ans.x << endl; return 0; }
#include<bits/stdc++.h> using namespace std; #define ll long long #define all(ppp) ppp.begin(),ppp.end() #define out(ppp) cout<<(ppp)<<endl #define out1(ppp) cout<<(ppp) #define MAX_CHAR 256 #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define REP(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define pb push_back #define lint ll typedef long double ld; typedef complex<ld> cd; ll MOD; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<double> vd; typedef vector<vi> vvi; typedef vector<bool> vb; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; typedef vector<vpi> vvpi; typedef set<pi> spi; const int INF=INT_MAX; vector<vector<lint>> matmul(const vector<vector<lint>> &A, const vector<vector<lint>> &B, lint mod=MOD){ int H = A.size(), W = B[0].size(), K = B.size(); vector<vector<lint>> C(H, vector<lint>(W)); REP(i, H) REP(j, W) REP(k, K) (C[i][j] += A[i][k] * B[k][j]) %= mod; return C; } vector<vector<lint>> matpower(vector<vector<lint>> X, lint n, lint mod=MOD){ vector<vector<lint>> res(X.size(), vector<lint>(X.size())); REP(i, res.size()) res[i][i] = 1; while (n) { if (n & 1) res = matmul(res, X, mod); X = matmul(X, X, mod); n >>= 1; } return res; } lint power(lint x, lint n){ lint ans = 1; while (n>0) { if (n & 1) (ans *= x) %= MOD; (x *= x) %= MOD; n >>= 1; } return ans; } ll sol(ll len,ll A,ll B,ll amari){ if(!len){ return amari; } ll d=to_string(A).length(); ll m=1; F0R(i,d){ m*=10; } ll n_term=min((m-1-A)/B+1,len); vector<vector<ll>> trans{{power(10,d),0,0},{1,1,0},{0,B,1}}; trans=matpower(trans,n_term); amari=(trans[0][0]*(amari%MOD)%MOD+trans[1][0]*(A%MOD)%MOD+1*trans[2][0]%MOD)%MOD; return sol(len-n_term,A+B*n_term,B,amari); } void solve(){ ll l,A,B; cin>>l>>A>>B>>MOD; ll ret=sol(l,A,B,0); out(ret); } int main(){ solve(); return 0; }
#include<bits/stdc++.h> using namespace std; typedef long long ll; #define pb push_back #define fi first #define se second typedef pair<ll,ll> P; using VP = vector<P>; using VVP = vector<VP>; using VI = vector<ll>; using VVI = vector<VI>; using VVVI = vector<VVI>; #define INF 1ll<<59 ll Mod; VVI matproduct(VVI a,VVI b){ if(a[0].size()!=b.size()) cout<<a[0].size()<<" "<<b.size()<<endl; VVI w(a.size(),VI(b[0].size(),0)); for(ll i=0;i<a.size();i++){ for(ll j=0;j<b[0].size();j++){ for(ll k=0;k<a[0].size();k++){ w[i][j]+=(a[i][k]%Mod)*(b[k][j]%Mod); w[i][j]%=Mod; } } } return w; } VVI square(VVI a){ return matproduct(a,a); } int main(){ ll i,j; ll l,a,b,m; cin>>l>>a>>b>>m; Mod=m; ll k=1; ll d[19]; ll ke[19]; ke[0]=1; for(i=1;i<19;i++){ d[i]=max((k*10-1-a+b)/b,0ll)-max((k-1-a+b)/b,0ll); k*=10; ke[i]=(ke[i-1]*10)%Mod; } for(i=1;i<19;i++){ if(d[i]<l) l-=d[i]; else { d[i]=l; l=0; } } VVI ans(1,VI(3)); ans[0][0]=0; ans[0][1]=a%Mod; ans[0][2]=1; for(i=1;i<19;i++){ VVI w(3,VI(3,0)); w[0][0]=ke[i]; w[1][0]=1; w[1][1]=1; w[2][1]=b%Mod; w[2][2]=1; for(j=0;j<62;j++){ if((d[i]>>j)&1) ans=matproduct(ans,w); w=square(w); } } cout<<ans[0][0]<<endl; return 0; }
#include <bits/stdc++.h> using namespace std; using ll = long long; using ull = unsigned long long; using Matrix = vector<vector<ll>>; inline ll ceil_ll(ll x, ll y) { return (x + y - 1) / y; } Matrix mulMatrix(const Matrix &A, const Matrix &B, const ll MOD) { Matrix C(3, vector<ll>(3)); for (int i = 0; i < 3; ++i) { for (int j = 0; j < 3; ++j) { for (int k = 0; k < 3; ++k) { (C[i][j] += (A[i][k] * B[k][j]) % MOD) %= MOD; } } } return C; } Matrix powMatrix(Matrix A, ll e, const ll MOD) { vector<vector<ll>> X(3, vector<ll>(3)); X[0][0] = X[1][1] = X[2][2] = 1; for ( ; 0 < e; e >>= 1) { if (e & 1) X = mulMatrix(X, A, MOD); A = mulMatrix(A, A, MOD); } return X; } ll fast_pow10(ull e, const ull MOD) { ull a = 10, x = 1; for ( ; 0 < e; e >>= 1) { if (e & 1) (x *= a) %= MOD; (a *= a) %= MOD; } return x; } int main() { cin.tie(0); ios::sync_with_stdio(false); // cout << setprecision(8) << setiosflags(ios::fixed); constexpr int DIGITS = 19; vector<ll> pow10(DIGITS); pow10[0] = 1; for (int i = 1; i < DIGITS; ++i) pow10[i] = 10 * pow10[i - 1]; ll L, A, B, M; cin >> L >> A >> B >> M; vector<ll> begin(DIGITS), num(DIGITS); for (ll d = 1; d < DIGITS; ++d) { begin[d] = max(0ll, ceil_ll(pow10[d - 1] - A, B)); const ll end = min((pow10[d] - A - 1) / B, L - 1); const ll s_l = A + B * begin[d], s_r = A + B * end; if (pow10[d - 1] <= s_l && s_r < pow10[d] && begin[d] <= end) num[d] = end - begin[d] + 1; } ll ans = 0; for (ll d = 1; d < DIGITS; ++d) { if (num[d] == 0) continue; Matrix X(3, vector<ll>(3)); X[0][0] = pow10[d] % M; X[0][1] = 1; X[1][1] = 1; X[1][2] = B % M; X[2][2] = 1; X = powMatrix(X, num[d], M); const ll s0 = (A + B * begin[d]) % M; const ll s = ((X[0][1] * s0) % M + X[0][2]) % M; (ans *= fast_pow10((ull)d * num[d], M)) %= M; (ans += s) %= M; } cout << ans << endl; return 0; }
#include<iostream> using namespace std; long L,A,B,M; long power(long a,long b){return b?power(a*a%M,b/2)*(b%2?a:1)%M:1;} long ten[99],sten[99],iten[99]; long n; long sum(long k) { long ret=0,p=1; for(int i=61;i--;) { if(k>>i&1) { (ret+=sten[i]*p)%=M; p=p*ten[i]%M; } } return ret; } long isum(long k) { long ret=0,p=1,g=0; for(int i=61;i--;) { if(k>>i&1) { (ret+=(iten[i]+sten[i]*g)%M*p)%=M; p=p*ten[i]%M; g=(g+(1LL<<i))%M; } } return ret; } long cnt[18],SUM[18]; int main() { cin>>L>>A>>B>>M; long pre=0,tmpten=1; long ans=0; for(n=1;n<=18;n++) { cnt[n-1]=1; long l=pre,r=L; tmpten*=10; while(r-l>1) { long m=(l+r)/2; if(A+B*m<tmpten)l=m; else r=m; } long k=l-pre; if(k<0||l>=L||A+B*l>=tmpten) { continue; } pre=l+1; ten[0]=tmpten%M; sten[0]=1; iten[0]=0; if(k+1&1)cnt[n-1]=tmpten%M; for(int i=1;i<61;i++) { ten[i]=ten[i-1]*ten[i-1]%M; sten[i]=(ten[i-1]+1)%M*sten[i-1]%M; iten[i]=((ten[i-1]+1)%M*iten[i-1]+(1LL<<i-1)%M*sten[i-1]%M*ten[i-1])%M; if(k+1>>i&1)cnt[n-1]=cnt[n-1]*ten[i]%M; } SUM[n-1]=(((A+B*l)%M*sum(k+1)%M-B%M*isum(k+1))%M+M)%M; } long p=1; for(int i=18;i--;) { ans=(ans+SUM[i]*p)%M; p=p*cnt[i]%M; } cout<<ans<<endl; }
#include<iostream> #include<algorithm> #include<vector> #include<queue> #include<set> #include<unordered_map> using namespace std; typedef long long ll; #define chmax(a,b) a=max(a,b) #define chmin(a,b) a=min(a,b) #define mod 1000000007 #define mad(a,b) a=(a+b)%mod #define Nmax 55 ll mo; ll po(ll x,ll y){ if(y<0)cout<<1/0<<endl; ll res=1; for(;y;y>>=1){ if(y&1)res=res*x; x=x*x; } return res; } ll pomo(ll x,ll y){ if(y<0)cout<<1/0<<endl; ll res=1; for(;y;y>>=1){ if(y&1)res=res*x%mo; x=x*x%mo; } return res; } struct matrix{ ll t[3][3]; }; matrix mul(matrix a,matrix b){ matrix c; for(int i=0;i<3;i++)for(int j=0;j<3;j++){ ll res=0; for(int k=0;k<3;k++){ res+=a.t[i][k]*b.t[k][j]; } c.t[i][j]=res%mo; } return c; } ll solve(ll d,ll a,ll b,ll l){ matrix r[66]; ll kei[]={1,b%mo,0,0,po(10,d)%mo,0,1,a%mo,1}; for(int i=0;i<3;i++)for(int j=0;j<3;j++){ r[0].t[i][j]=kei[i*3+j]; } for(int i=1;i<62;i++)r[i]=mul(r[i-1],r[i-1]); matrix res; bool fi=1; for(int i=0;i<62;i++){ if((1LL<<i)&l){ if(fi)res=r[i],fi=0; else res=mul(res,r[i]); } } return res.t[2][1]; } int main(){ cin.tie(0); ios::sync_with_stdio(0); ll l,a,b; cin>>l>>a>>b>>mo; ll ans=0; ll ruiketa=1; for(int d=18;d>=1;d--){ if(po(10,d)<=a)continue; if(a+b*(l-1)<po(10,d-1))continue; ll s=a; if(s<po(10,d-1))s=a+(po(10,d-1)-1-a+b)/b*b; ll t=a+b*(l-1); if(po(10,d)<=t)t=a+(po(10,d)-1-a)/b*b; ll len=(t-s)/b+1; if(len>0){ ll res=solve(d,s,b,len); //cout<<d<<" "<<s<<" "<<b<<" "<<len<<" "<<res<<endl; ans=ans+ruiketa*res; ans%=mo; ruiketa=ruiketa*pomo(pomo(10,len),d)%mo; } } cout<<ans<<endl; }
#include <cstdio> #include <tuple> #include <utility> using namespace std; typedef long long ll; ll L, A, B, M; int len(ll x) { int res = 0; while (x) ++res, x /= 10; return res; } tuple<ll, ll, ll> calc(ll C, ll N) { if (N == 1) return make_tuple(C, 1, 0); auto z = calc(C, N / 2); z = make_tuple(get<0>(z) * get<0>(z) % M, get<1>(z) * (1 + get<0>(z)) % M, (get<2>(z) * (1 + get<0>(z)) + (N / 2) % M * get<1>(z)) % M); if (N & 1) z = make_tuple(get<0>(z) * C % M, (get<1>(z) + get<0>(z)) % M, (get<2>(z) * C + N - 1) % M); return z; } pair<ll, ll> solve(ll l, ll r) { int xl = len(A + B * l), xr = len(A + B * r); if (xl == xr) { ll pw = 1; for (int i = 1; i <= xl; ++i) pw = pw * 10 % M; ll X = (A + B * l) % M, Y = B % M; auto tmp = calc(pw, r - l + 1); return make_pair(get<0>(tmp), (get<1>(tmp) * X + get<2>(tmp) * Y) % M); } ll mid = l + r >> 1; pair<ll, ll> ansl = solve(l, mid), ansr = solve(mid + 1, r); return make_pair(ansl.first * ansr.first % M, (ansl.second * ansr.first + ansr.second) % M); } int main() { scanf("%lld%lld%lld%lld", &L, &A, &B, &M); printf("%lld\n", solve(0, L - 1).second); return 0; }
#include <iostream> #include <vector> #include <map> #include <set> #include <queue> #include <string> #include <iomanip> #include <algorithm> #include <cmath> #include <stdio.h> using namespace std; #define int long long int keta(int a) { int res = 0; while (a > 0) { a /= 10; res++; } return res; } int L, A, B, M; int po(int a, int p) { if (p == 0)return 1; int res = po(a, p / 2); res = (res * res) % M; if (p & 1) { res = (res * a) % M; } return res; } int calc(int z, int c) { if (c == 0)return 0; if (c == 1)return 1; int res = calc(z, c / 2); res = (res + (res * po(z, c / 2))) % M; if (c & 1) { res = (res + po(z, c - 1)) % M; } return res; } int calc2(int z, int c) { if (c == 0)return 0; if (c == 1)return 0; int res = calc2(z, c / 2); res = (res + (res * po(z, c / 2))) % M; res = (res + (( ((c / 2) % M) * po(z, c / 2)) % M) * calc(z, c / 2)) % M; if (c & 1) { res = (res + ((c - 1) % M) * po(z, c - 1)) % M; } return res; } signed main() { cin.tie(0); ios::sync_with_stdio(false); cin >> L >> A >> B >> M; vector<int> X(20, 0); for (int i = 1; i <= 19; i++) { int ok = L; int ng = -1; while (ok - ng > 1) { int m = (ok + ng) / 2; int a = A + B * m; if (keta(a) >= i) { ok = m; } else { ng = m; } } X[i] = ok; } int b = 1; int la = L; int res = 0; int AA = A % M; int BB = B % M; for (int i = 19; i >= 0; i--) { int cnt = la - X[i]; if (cnt > 0) { int z = po(10, i); int t = (AA + BB * ((la - 1) % M)) % M; int diff = 0; diff = (diff + t * calc(z, cnt)) % M; diff = (diff - BB * calc2(z, cnt)) % M; if (diff < 0)diff += M; diff = (diff*b) % M; res = (res + diff) % M; b = (b * po(po(10, cnt), i)) % M; } la = X[i]; } /*cerr << calc2(2, 2) << endl; cerr << calc2(2, 3) << endl; cerr << calc2(2, 4) << endl; cerr << calc2(2, 5) << endl;*/ cout << res << endl; }
#include"bits/stdc++.h" using namespace std; using ll = int64_t; ll L, A, B, M; vector<vector<ll>>& operator*=(vector<vector<ll>>& lhs, vector<vector<ll>> rhs) { auto result = lhs; for (ll i = 0; i < result.size(); i++) { for (ll j = 0; j < result[i].size(); j++) { result[i][j] = 0; for (ll k = 0; k < lhs.size(); k++) { (result[i][j] += lhs[i][k] * rhs[k][j] % M) %= M; } } } return lhs = result; } int main() { cin >> L >> A >> B >> M; ll ans = 0; ll pre = 0; ll s = A; for (ll d = 1; d <= 18; d++) { ll target = 1; for (ll j = 0; j < d; j++) { target *= 10; } ll low = pre - 1, eq_high = L; while (low != eq_high - 1) { ll mid = (low + eq_high) / 2; ll s_mid = A + B * mid; (s_mid < target ? low = mid : eq_high = mid); } ll C_d = eq_high - pre; pre = eq_high; vector<vector<ll>> mat = { { target % M, 0, 0 }, { 1, 1, 0 }, { 0, B % M, 1 } }; vector<vector<ll>> result = { { 1, 0, 0 }, { 0, 1, 0 }, { 0, 0, 1 } }; while (C_d) { if (C_d % 2 == 1) { result *= mat; } C_d /= 2; mat *= mat; } vector<ll> v = { ans, s, 1 }; ans = 0; s = 0; for (ll i = 0; i < 3; i++) { (ans += v[i] * result[i][0] % M) %= M; (s += v[i] * result[i][1] % M) %= M; } } cout << ans << endl; }
#include <bits/stdc++.h> using namespace std; #define rep(i,n) for (int i=0; i<(int)(n); ++i) #define all(a) (a).begin(), (a).end() #define rall(a) (a).rbegin(), (a).rend() using ll = long long; using vi = vector<int>; using vl = vector<ll>; using Graph = vector<vi>; // vi <=> vl using vb = vector<bool>; using boolGraph = vector<vb>; using P = pair<int, int>; // int <=> ll const int MOD = 1e9+7; const int MOD2 = 998244353; const double EPS = 1e-9; int main() { ll L, A, B, M; cin >> L >> A >> B >> M; P digit = P(1, 1); ll tmp = 10; while (A >= tmp) { tmp *= 10; ++digit.first; } ll last = A + B * (L-1); tmp = 10; while (last >= tmp) { tmp *= 10; ++digit.second; } ll init = A; ll ans = 0; for (int k=digit.first; k<=digit.second; ++k) { ll pow10 = pow(10, k); if (pow10 <= init) continue; ll num = (min(pow10 - 1, last) - init) / B + 1; vl rem(64); rem[0] = pow10 % M; rep(i,63) { rem[i+1] = rem[i] * rem[i] % M; } vl dp(64); dp[0] = 1; rep(i,63) { dp[i+1] = dp[i] * (1 + rem[i]) % M; } ll expo = 1, sigma_a = 0; for (int i=63; i>=0; --i) { if ((num >> i) & 1) { (sigma_a += expo * dp[i]) %= M; (expo *= rem[i]) %= M; } } vl dp2(64), power(64); dp2[0] = 1; power[0] = 1; rep(i,63) { dp2[i+1] = (dp2[i] * (1 + rem[i]) + dp[i] * power[i]) % M; power[i+1] = power[i] * 2 % M; } ll expo2 = 1, sum = 0, sigma_b = 0; for (int i=63; i>=0; --i) { if (((num - 1) >> i) & 1) { (sigma_b += sum * power[i] + expo2 * dp2[i]) %= M; (sum += expo2 * dp[i]) %= M; (expo2 *= rem[i]) %= M; } } (ans *= expo) %= M; (ans += (init % M) * sigma_a + (B % M) * sigma_b) %= M; init += B * num; } cout << ans << endl; return 0; }
#include<bits/stdc++.h> using namespace std; long long l,a,b,m,L,R,mid,fuck,fk,dur,cur; struct mat { long long a[11][11]; mat() { for (int i=1;i<=3;i++) { for (int j=1;j<=3;j++) a[i][j]=(i==j); } } mat operator * (const mat &u) const { mat res; for (int i=1;i<=3;i++) { for (int j=1;j<=3;j++) { res.a[i][j]=0; for (int k=1;k<=3;k++) { res.a[i][j]=(res.a[i][j]+a[i][k]*u.a[k][j])%m; } } } return res; } }ma,ans,fp; mat binpow(mat a,long long t) { mat res,p=a; for (long long i=t;i;i>>=1) { if (i&1) res=res*p; p=p*p; } return res; } int main() { scanf("%lld%lld%lld%lld",&l,&a,&b,&m); cur=a; while(l) { fuck=1;fk=cur; while(fk) { fk/=10; fuck*=10; } ma.a[1][1]=fuck%m;ma.a[1][2]=ma.a[1][3]=ma.a[2][3]=ma.a[3][1]=0; ma.a[2][1]=ma.a[2][2]=ma.a[3][2]=ma.a[3][3]=1; dur=(fuck-cur+b-1)/b; dur=min(dur,l); fp=fp*binpow(ma,dur); l-=dur;cur+=b*dur; } printf("%lld\n",(fp.a[2][1]*(a%m)+fp.a[3][1]*(b%m))%m); return 0; }
#include<iostream> #include<iomanip> #include<vector> #include<string> #include<cstring> #include<map> #include<set> #include<queue> #include<stack> #include<algorithm> #include<cmath> #include<cstdio> #include<cstdlib> #include<climits> #include<fstream> #define MOD (1000000007) using namespace std; typedef long long int Int; constexpr Int TEN(int n) { return n == 0 ? 1 : 10 * TEN(n-1); } Int L, A, B, M; typedef struct m { Int m[3][3]; }Matrix; Matrix operator * (Matrix a, Matrix b) { Matrix c; for(int i = 0;i < 3;i++) { for(int j = 0;j < 3;j++) { c.m[i][j] = 0; for(int k = 0;k < 3;k++) { c.m[i][j] = (c.m[i][j]+ (a.m[i][k]*b.m[k][j]%M))%M; } } } return c; } Matrix create(Int op, Int b) { Matrix A; A.m[0][0] = op % M; A.m[0][1] = 0; A.m[0][2] = 0; A.m[1][0] = 1; A.m[1][1] = 1; A.m[1][2] = 0; A.m[2][0] = 0; A.m[2][1] = B%M; A.m[2][2] = 1; return A; } Matrix pow(Matrix x, Int y) { Matrix ans; if(y == 1) return x; ans = pow(x*x,y/2); if(y&1) { ans = ans*x; } return ans; } int main(void) { cin>>L>>A>>B>>M; Int op = 10; Int ans = 0; Int o = 0; L--; for(int i = 1;i <= 19;i++) { Int l = o,r = L,p = -1; while(l <= r) { Int mid = (l+r)/2; if(mid*B+A < op) { p = mid; l = mid+1; } else { r = mid-1; } } if(p != -1) { Matrix a = create(op,B); a = pow(a,p-o+1); Int t = (B*o%M+A) % M; ans = (ans * a.m[0][0]%M + t*a.m[1][0]%M+a.m[2][0])%M; o = p+1; } if(o > L) break; op *= 10; } cout<<ans<<endl; return 0; }
#include<iostream> using namespace std; typedef long long ll; void mult(ll m, const ll x[3][3], const ll y[3][3], ll z[3][3]) { for(int i=0;i<3;i++) for(int j=0;j<3;j++) { z[i][j] = 0; for(int k=0;k<3;k++) { z[i][j] += x[i][k] * y[k][j]; } z[i][j] %= m; } } int main() { ll l, a, b, m; cin >> l >> a >> b >> m; ll ans = 0; for(ll r=10;l>0;r*=10) { if(r <= a) continue; ll n = (r-a-1) / b + 1; if(n > l) n = l; ll mat[3][3] = { {r % m, 0, 0}, {1, 1, 0}, {0, b % m, 1} }; ll p[3][3] = { {1, 0, 0}, {0, 1, 0}, {0, 0, 1} }; for(int s=63;s>=0;s--) { ll tmp[3][3]; mult(m, p, p, tmp); if((n >> s) & 1) { mult(m, tmp, mat, p); } else { for(int i=0;i<3;i++) for(int j=0;j<3;j++) p[i][j] = tmp[i][j]; } } ll v[3] = {ans, a % m, 1}; ans = 0; for(int i=0;i<3;i++) { ans += v[i] * p[i][0]; } ans %= m; l -= n; a += b * n; } cout << ans << endl; return 0; }
#include <iostream> #include <cstdio> #include <algorithm> #include <string> #include <cstring> #include <vector> #include <iostream> #include <queue> #include <unordered_map> #include <cmath> #include <queue> #include <string> #include <random> #include <stack> #include <set> #include <unordered_set> #define bug(x) cout<<"zdongdebug: "<<x<<endl; #define bug2(x, y) cout<<"zdongdebug: "<<x<<" "<<y<<endl; using namespace std; typedef unsigned long long ll; const int maxn = 100005; class Mat{ public: vector<vector<ll>> each; vector<vector<ll>> ret; ll mod; Mat(ll sum, ll cur, ll b, ll p10, ll mod){ each = {{p10, 1, 0},{0,1,1},{0,0,1}}; ret = {{sum},{cur},{b}}; this->mod = mod; } vector<vector<ll>> mul(vector<vector<ll>>a, vector<vector<ll>>b){ vector<vector<ll>> ret = vector<vector<ll>>(a.size(),vector<ll>(b[0].size(),0)); for(int i=0;i<a.size();i++) for(int j=0;j<b[0].size();j++){ ll tt = 0; for(int k=0;k<b.size();k++){ tt=(tt+a[i][k]*b[k][j]%mod)%mod; } ret[i][j]=tt; } return ret; } ll calSum(ll n){ vector<vector<ll>>tt={{1,0,0},{0,1,0},{0,0,1}}; while(n){ if(n&1){ tt = mul(tt, each); } each = mul(each, each); n>>=1; } ret = mul(tt, ret); return ret[0][0]; } }; ll helper(ll x){ ll ret = 0; while(x){ ret=ret*10 + 9; x/=10; } return ret; } int main() { #ifdef suiyuan2009 freopen("/Users/suiyuan2009/CLionProjects/icpc/input.txt", "r", stdin); #endif ll n,a,b,mod; cin>>n>>a>>b>>mod; ll sum = a % mod; ll cur = a+b; n--; while(n){ ll mx = helper(cur); ll cnt = (mx-cur)/b; Mat solve = Mat(sum, cur%mod, b%mod, (mx+1)%mod, mod); ll tcnt = min(n,cnt+1); ll nsum = solve.calSum(tcnt); //cout<<sum<<" "<<cur<<" "<<mx+1<<" "<<tcnt<<" "<<nsum<<endl; sum = nsum; cur = tcnt * b + cur; n-=tcnt; } cout<<sum<<endl; //bug(cur) return 0; }
#include <iostream> #include <vector> #include <algorithm> #include <initializer_list> using lli=long long int; int mod; template<size_t N> class matN{ public: lli m[N][N] = {}; matN(){} matN(std::initializer_list<lli> init){ auto it = init.begin(); for(int i = 0; i < N; i++){ for(int j = 0; j < N; j++){ m[i][j] = (((*it)%mod)+mod)%mod; ++it; } } } }; template<size_t N> const matN<N> operator*(const matN<N>& lhs, const matN<N>& rhs){ matN<N> ans; for(int i = 0; i < N; i++){ for(int j = 0; j < N; j++){ for(int k = 0; k < N; k++){ ans.m[i][j] += lhs.m[i][k]*rhs.m[k][j]; ans.m[i][j] %= mod; } } } return ans; } int main(){ lli L,A,B; std::cin >> L >> A >> B >> mod; std::vector<lli> ns_d(1); lli tmp = 9; while(A+B*(L-1)>tmp){ if(A>tmp){ ns_d.push_back(0); }else{ ns_d.push_back((tmp-A)/B+1); } tmp = tmp*10+9; } ns_d.push_back(L); matN<3> mat_total = {1,0,0,0,1,0,0,0,1}; for(int i = 1; i < ns_d.size(); i++){ lli ipow = 1; for(int j = 0; j < i; j++){ ipow = (ipow*10)%mod; } lli isize = ns_d[i]-ns_d[i-1]; matN<3> mat_last = {ipow,1,0,0,1,B,0,0,1}; int nb = 0; while((isize>>nb)!=0){ if((isize>>nb)&1){ mat_total = mat_last*mat_total; } mat_last = mat_last*mat_last; nb++; } } lli ans = ((mat_total.m[0][1]*(A%mod))%mod+mat_total.m[0][2])%mod; std::cout << ans << std::endl; return 0; }
#include<iostream> #include<string> #include<iomanip> #include<cmath> #include<vector> #include<algorithm> using namespace std; // #define int long long #define int __int128 #define rep(i,n) for(int i = 0; i < (n); i++) #define INF ((long long)1e18) #define endl "\n" #define yn(f) ((f)?"Yes":"No") #define YN(f) ((f)?"YES":"NO") #define MAX long long MOD; template<typename type> vector<vector<type>> product(vector<vector<type>> &a, vector<vector<type>> &b){ vector<vector<type>> res(a.size(),vector<type>(b[0].size(),0)); for(int i = 0; i < a.size(); i++){ for(int j = 0; j < b[0].size(); j++){ for(int k = 0; k < b.size(); k++){ res[i][j] += a[i][k]*b[k][j]; res[i][j] %= MOD; } } } return res; } template<typename type> vector<vector<type>> matrix_power(vector<vector<type>> matrix, long long n){ vector<vector<type>> res(matrix.size(), vector<type>(matrix.size(),0)); for(int i = 0; i < matrix.size(); i++) res[i][i] = 1; for( ; n > 0; n >>= 1){ if(n&1) res = product(res,matrix); matrix = product(matrix,matrix); } return res; } int check(int num){ int con = 0; while(num) con++, num /= 10; return con; } signed main(){ cin.tie(0); ios::sync_with_stdio(false); cout<<fixed<<setprecision(10); vector<vector<int>> ans(3,vector<int>(1,0)); long long L, A, B; int b = -1; cin>>L>>A>>B>>MOD; ans[0][0] = 0; ans[1][0] = A; ans[2][0] = 1; for(int i = 1, power = 10; i <= 18; i++, power *= 10){ vector<vector<int>> matrix(3,vector<int>(3,0)); int d = 0; int m = 0, l = 0, h = L; while(l + 1 < h){ int m = (l + h)/2; if(check(A + m*B) > i){ h = m; } else { l = m; } } if(check(A + l*B) < i) continue; d = l - b; b = l; matrix[0][0] = power; matrix[0][1] = matrix[1][1] = matrix[2][2] = 1; matrix[1][2] = B; matrix = matrix_power(matrix, d); ans = product(matrix, ans); } cout<<(long long)ans[0][0]<<endl; return 0; }
#include <iostream> #include <algorithm> #include <string> #include <vector> #include <cmath> #include <map> #include <queue> #include <iomanip> #include <set> #define mkp make_pair typedef long long ll; using namespace std; ll L,A,B,M; ll MOD=1000000007; typedef vector<ll> vec;//ll? typedef vector<vec> mat; mat mul(mat &A,mat &B){ mat C(A.size(),vec(B[0].size())); for(int i=0;i<A.size();i++){ for(int k=0;k<B.size();k++){ for(int j=0;j<B[0].size();j++){ C[i][j]=(C[i][j]+A[i][k]*B[k][j]%MOD)%MOD; } } } return C; } mat pow(mat A,ll n){ mat B(A.size(),vec(A.size())); for(int i=0;i<A.size();i++){ B[i][i]=1; } while(n>0){ if(n&1) B=mul(B,A); A=mul(A,A); n=(n>>1); } return B; } int digit(ll val){ if(val==0) return 0; else return (1+digit(val/10)); } int main(){ cin>>L>>A>>B>>M; MOD=M; ll ans=0; ll ten[20]={}; ten[0]=1; for(int i=1;i<=18;i++) ten[i]=ten[i-1]*10%MOD; ll start=0; while(start<L){ ll ng=L; ll ok=start; ll nowdigit=digit(A+B*start); while(ng-ok>1){ ll mid=(ng+ok)/2; if(digit(A+B*mid)==nowdigit) ok=mid; else ng=mid; } mat C(3,vec(3)); C[0][0]=ten[nowdigit]; C[0][1]=1; C[0][2]=A%MOD; C[1][0]=0; C[1][1]=1; C[1][2]=B%MOD; C[2][0]=0; C[2][1]=0; C[2][2]=1; C=pow(C,(ok-start+1)); mat D(3,vec(1)); D[0][0]=ans; D[1][0]=(B*start)%MOD; D[2][0]=1; D=mul(C,D); ans=D[0][0]; ans=(ans+MOD)%MOD; start=ok+1; } cout<<ans<<endl; return 0; }
#include <bits/stdc++.h> using namespace std; #define rep(i,n) for (int i = 0; i < (int)(n); ++i) #define reps(i,n) for (int i = 1; i <= (int)(n); ++i) #define repd(i,n) for (int i = (int)(n - 1); i >= 0; --i) #define repds(i,n) for(int i = (int)(n); i > 0; --i) #define all(f,x,...) ([&](decltype((x)) whole) { return (f)(begin(whole), end(whole), ## __VA_ARGS__); })(x) #define rall(f,x,...) ([&](decltype((x)) whole) { return (f)(rbegin(whole), rend(whole), ## __VA_ARGS__); })(x) #define sz(a) (int)(a).size() using ll = long long; using ld = long double; constexpr ll inf = static_cast<ll>(1e17); constexpr int iinf = static_cast<int>(1e9); constexpr ll MOD = static_cast<ll>(1e9 + 7); ll mod = MOD; using MatrixChild = std::vector<long long>; using Matrix = std::vector<MatrixChild>; Matrix matrixmul(Matrix& a, Matrix& b) { Matrix c(a.size(), MatrixChild(b[0].size())); for (int i = 0; i < (int)a.size(); ++i) for (int k = 0; k < (int)b.size(); ++k) for (int j = 0; j < (int)b[0].size(); ++j) c[i][j] = (c[i][j] + a[i][k] * b[k][j]) % mod; return c; } Matrix matrixpow(Matrix a, long long n) { Matrix b(a.size(), MatrixChild(a.size())); for (int i = 0; i < (int)a.size(); ++i) b[i][i] = 1; while (n > 0) { if (n & 1) b = matrixmul(b, a); a = matrixmul(a, a); n >>= 1; } return b; } ll l, a, b; void solve() { cin >> l >> a >> b >> mod; ll ten = 1; ll ans = 0; rep(i, 19) { ten *= 10; if (a >= ten) continue; auto num = min((ten - 1 - a) / b, l - 1) + 1; l -= num; if (num == 0) { if (l == 0) break; continue; } Matrix ansMat{ { ans, a % mod, 1 } }; Matrix mat{ { ten % mod, 0, 0 }, { 1, 1, 0 }, { 0, b, 1 } }; mat = matrixpow(mat, num); ansMat = matrixmul(ansMat, mat); ans = ansMat[0][0] % mod; a += b * num; } cout << ans % mod << endl; return; } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); solve(); return 0; }
#include<bits/stdc++.h> typedef long long int ll; typedef unsigned long long int ull; #define BIG_NUM 2000000000 #define HUGE_NUM 1000000000000000000 #define MOD 1000000007 #define EPS 0.000000001 using namespace std; ll L,A,B,M; ll S; struct MOD_INT{ ll x; MOD_INT(ll arg_x){ x = arg_x; x %= M; } MOD_INT& operator+=(const MOD_INT a) { (x += a.x) %= M; return *this; } MOD_INT& operator-=(const MOD_INT a) { (x += M-a.x) %= M; return *this; } MOD_INT& operator*=(const MOD_INT a) { (x *= a.x) %= M; return *this; } MOD_INT operator+(const MOD_INT a) const { MOD_INT res(*this); return res+=a; } MOD_INT operator-(const MOD_INT a) const { MOD_INT res(*this); return res-=a; } MOD_INT operator*(const MOD_INT a) const { MOD_INT res(*this); return res*=a; } }; MOD_INT mod_pow(MOD_INT x,ll count, ll mod){ if(count == 0){ return 1; } if(count%2 == 1){ return mod_pow(x,count-1,mod)*x; } else{ MOD_INT y = mod_pow(x,count/2,mod); return y*y; } } MOD_INT f(ll loc){ if(loc == 0){ return 0; } MOD_INT ret(0); if(loc%2 == 1){ ll tmp = loc-1; ret = f(tmp); return ret*S+1; }else{ ll tmp = loc/2; ret = f(tmp); return ret*mod_pow(S,loc/2,M)+ret; } } MOD_INT g(ll loc){ if(loc == 0){ return 0; } MOD_INT ret(0); if(loc%2 == 1){ ll tmp = loc-1; ret = g(tmp); return ret*S+MOD_INT(B)*tmp; }else{ ll tmp = loc/2; ret = g(tmp); return ret = ret*mod_pow(S,tmp,M)+ret+MOD_INT(B)*tmp*f(tmp); } } int main(){ scanf("%lld %lld %lld %lld",&L,&A,&B,&M); MOD_INT ans = 0; S = 10; ll last = A+B*(L-1); ll head,tail,num; for(ll i = 1; i <= 18; i++,S *= 10){ ll mini = S/10,maxi = S-1; if(A > maxi || last < mini)continue; if(A >= mini){ head = A; }else{ head = ((mini-A)+(B-1))/B*B+A; head = min(head,last); } if(last <= maxi){ tail = last; }else{ tail = (maxi-A)/B*B+A; } num = (tail-head)/B+1; //printf("i:%lld head:%lld tail:%lld num:%lld\n",i,head,tail,num); ans *= mod_pow(S,num,M); ans += f(num)*head; ans += g(num); } printf("%lld\n",ans.x); return 0; }
#include <vector> #include <iostream> using namespace std; int binpow(unsigned long long a, unsigned long long b, int m) { // returns a^b mod m a %= m; int ans = 1; while (b > 0) { if (b & 1) ans = 1LL * ans * a % m; a = 1LL * a * a % m; b >>= 1; } return ans; } int binpow2(unsigned long long a, unsigned long long b, int m) { // returns a^0 + a^1 + a^2 + ... + a^(b-1) mod m a %= m; if (b == 0) return 0; if (b & 1) return (1LL * binpow2(a, b - 1, m) * a + 1) % m; return 1LL * binpow2(a, b / 2, m) * (binpow(a, b / 2, m) + 1) % m; } int binpow3(unsigned long long a, unsigned long long b, int m) { // return a^0 * 0 + a^1 * 1 + a^2 * 2 + ... + a^(b-1) * (b-1) a %= m; if (b == 0) return 0; if (b & 1) return (binpow3(a, b - 1, m) + 1LL * binpow(a, b - 1, m) * ((b - 1) % m)) % m; int r1 = binpow(a, b / 2, m); int r2 = binpow2(a, b / 2, m); int r3 = binpow3(a, b / 2, m); return (1LL * r3 * (r1 + 1) + 1LL * r2 * ((b / 2) % m) % m * r1) % m; } int main() { long long L, A, B; int M; cin >> L >> A >> B >> M; const int max_digits = 18; unsigned long long mult = 1; for (int i = 0; i < max_digits; ++i) { mult *= 10; } int ans = 0; unsigned long long curlen = 0; for (int i = max_digits; i >= 1; --i) { mult /= 10; long long pl = (mult < A ? 0 : (mult - A + B - 1) / B); long long pr = (mult * 10 < A ? 0 : (mult * 10 - A + B - 1) / B); if (pl > L) pl = L; if (pr > L) pr = L; if (pl == pr) continue; unsigned long long nlen = pr - pl; int bs = (mult * 10) % M; int c2 = binpow2(bs, nlen, M); int c3 = binpow3(bs, nlen, M); int sub = int(1LL * c2 * ((A + ((pr - 1) % M) * (B % M)) % M) % M) - int(1LL * c3 * (B % M) % M); if (sub < 0) sub += M; ans = (ans + 1LL * sub * binpow(10, curlen, M)) % M; if (ans >= M) ans -= M; curlen += nlen * (unsigned long long)(i); } cout << ans << endl; return 0; }
#define _GLIBCXX_DEBUG #include <bits/stdc++.h> using namespace std; using ll = long long; #define pp pair<int,int> #define rep(i,n) for(int (i)=0;(i)<(n);(i)++) #define ld long double #define al(a) (a).begin(),(a).end() #define mk make_pair #define check cout<<"?"<<endl; ll MOD=1000000007; ll mod=998244353; int inf=1000001000; ll INF=1e18+5; int main(){ ll l,a,b,m,e,ans=0; cin>>l>>a>>b>>m; vector<ll> p(19,1); rep(i,18) p[i+1]=p[i]*10; e=a+b*(l-1); ll an=0,en=0,A=a,E=e; while(A>0){ A/=10; an++; } while(E>0){ E/=10; en++; } ll cur=l-1,c=1; for(int i=en;i>=an;i--){ ll num=1,d=(a%m+b%m*(cur%m))%m,ad=b%m,mul=p[i]%m; if(i==an) num-=(a+b-(a%b)+b-1)/b; else num-=(p[i-1]+b-(a%b)+b-1)/b; if(i==en) num+=(e+b-(a%b))/b; else num+=(p[i]-1+b-(a%b))/b; rep(j,64){ if(num&(1LL<<j)){ ans=(ans+(c*d)%m)%m; c=c*mul%m; d=(m+d-ad)%m; } d=(m+d-ad)*mul%m+d; d%=m; ad=(mul+1)*ad%m*2%m; mul=mul*mul%m; } cur-=num; } cout<<ans<<endl; }
#include <bits/stdc++.h> #define ALL(v) (v).begin(), (v).end() #define rep(i, n) for (ll i = 0, __##i##_length = (n); i < __##i##_length; i++) #define rep_reverse(i, n) for (ll i = (n)-1; 0 < i; i--) #define FOR(i, from, to) for (ll i = (from), __##i##_end = (to); i < __##i##_end; i++) #define FOR_REVERSE(i, from, to) for (ll i = (to)-1, __##i##_end = (from); __##i##_end <= i; i--) #define foreach(e, v) for (const auto e : (v)) #define vfree(v) std::vector<int>().swap(v) #define DEBUG(x) cout << #x << " = " << (x) << endl using namespace std; typedef int64_t ll; typedef vector<ll> llv; typedef vector<ll> llvv; llv mul(llv lhs, llv rhs, ll mod) { llv dst(9, 0); rep(i, 9) rep(j, 3) { dst[i] += (lhs[3 * (i / 3) + j] * rhs[j * 3 + (i % 3)]) % mod; dst[i] %= mod; } return dst; } llv mul_vec_mat(llv vec, llv mat, ll mod) { llv dst(3); rep(i, 3) dst[i] = ((vec[0] * mat[i] % mod) + (vec[1] * mat[i + 3] % mod) + (vec[2] * mat[i + 6] % mod)) % mod; return dst; } llv powmod(llv m, ll n, ll mod) { if (n == 0) return llv{1, 0, 0, 0, 1, 0, 0, 0, 1}; if (n & 1) { llv tmp = powmod(m, n - 1, mod); return mul(tmp, m, mod); } else { llv tmp = powmod(m, n / 2, mod); return mul(tmp, tmp, mod); } } int main() { ll L, A, B, M; cin >> L >> A >> B >> M; llv mat{1, 1, 0, 0, 0, 0, B % M, 0, 1}; ll i = 0, d = 10; llv state{A % M, 0, 1}; mat[4] = d; while (i <= L) { ll nexti = (d - A + B - 1) / B; if (nexti != 0 && i <= nexti && i <= L) { mat[4] = d % M; llv dst = powmod(mat, min(nexti, L) - i, M); i = nexti; state = mul_vec_mat(state, dst, M); } d *= 10; } cout << state[1] << endl; return 0; }
#include <bits/stdc++.h> using i64 = long long; using Mat = std::vector<std::vector<i64>>; i64 mod; Mat make_mat(int n, int m) { return Mat(n, std::vector<i64>(m)); } Mat unit_mat(int n) { auto ret = make_mat(n, n); for (int i = 0; i < n; i++) ret[i][i] = 1; return ret; } Mat operator*(const Mat &lhs, const Mat &rhs) { int n = lhs.size(); auto ret = make_mat(n, n); for (int i = 0; i < n; i++) for (int j = 0; j < n; j++) for (int k = 0; k < n; k++) { ret[i][j] = (ret[i][j] + lhs[i][k] * rhs[k][j] % mod) % mod; } return ret; } Mat pow(Mat m, i64 k) { const int size = m.size(); auto ret = unit_mat(size); while (k) { if ((k & 1) == 1) ret = m * ret; m = m * m; k >>= 1ll; } return ret; } int main() { i64 n, a, b; std::cin >> n >> a >> b >> mod; std::vector<i64> dcnt(20); i64 sum = 0; int initial = std::to_string(a).length(); for (i64 i = initial; i < 20; i++) { i64 l = 0, r = n, th = 1; for (i64 j = 0; j < i; j++) th *= 10; while (r - l > 1) { i64 k = (l + r) / 2; i64 s = a + b * k; if (s < th) l = k; else r = k; } dcnt[i] = l + 1 - sum; sum = l + 1; } i64 dd = 10; i64 ret = 0, s = a; for (i64 i = 1; i <= 18; i++) { Mat m { { dd, 0, 0 }, { 1, 1, 0 }, { 0, b, 1 } }; m = pow(m, dcnt[i]); ret = (ret * m[0][0] % mod + s * m[1][0] % mod + m[2][0]) % mod; s = (s * m[1][1] % mod + m[2][1]) % mod; dd = dd * 10 % mod; } std::cout << ret << std::endl; return 0; }
#include "bits/stdc++.h" typedef long long ll; #define int ll #define fi first #define se second #define SORT(a) sort(a.begin(),a.end()) #define rep(i,n) for(int i = 0;i < (n) ; i++) #define REP(i,n) for(int i = 0;i < (n) ; i++) #define MP(a,b) make_pair(a,b) #define pb(a) push_back(a) #define INF LLONG_MAX/2 #define all(x) (x).begin(),(x).end() #define debug(x) cerr<<#x<<": "<<x<<endl #define debug_vec(v) cerr<<#v<<":";rep(i,v.size())cerr<<" "<<v[i];cerr<<endl using namespace std; int MOD = 998244353; // int MOD = 1000000007; ll M; //matrix typedef vector<ll> vec; typedef vector<vector<ll>> mat; vec matmul(vec &dp,mat &mt){ // ret = Mv; ll m = dp.size(); vec ret(m,0); rep(i,m){ rep(j,m){ ret[i] += (mt[i][j]*dp[j])%M; ret[i] %= M; } } return ret; } mat update(mat &mt){ //ret = M^2 int m = mt.size(); mat ret(m,vec(m,0)); rep(i,m) rep(j,m) rep(k,m) ret[i][j] = (ret[i][j] + mt[i][k]*mt[k][j]%M)%M; return ret; } void matpow(vec &dp,mat &mt,int k){// dp = (M^k)dp int m = dp.size(); while(k){ if(k&1) dp = matmul(dp,mt); mt = update(mt); k /= 2; } } signed main(){ ll l,a,b; cin >> l >> a >> b >> M; ll p[19]; p[0] = 1; for(int i = 1;i <= 18;i++) p[i] = 10*p[i-1]; ll d[20]; // 10^d 以上になる最初のs rep(i,19){ // 条件を満たす最小を求める ll ok = l; //解が存在する値 ll ng = -1; //解が存在しない値 while(abs(ok-ng)>1){ ll mid = (ok+ng)/2; if(a+b*mid >= p[i]){ ok = mid; }else{ ng = mid; } } d[i] = ok; } d[19] = l; vec dp(3,0); dp[1] = a%M; dp[2] = 1; rep(i,19){ mat mt(3,vec(3,0)); mt[0][0] = ((p[i]%M)*10)%M; mt[0][1] = mt[1][1] = mt[2][2] = 1; mt[1][2] = b%M; matpow(dp,mt,d[i+1]-d[i]); } cout << dp[0]%M << endl; //rep(i,19)cerr << i << " " << d[i] << endl; return 0; } // g++ -std=c++14 code1.cpp // rm -r -f test;oj dl https://cf17-final-open.contest.atcoder.jp/tasks/cf17_final_a // rm -r -f test;oj dl http://abc129.contest.atcoder.jp/tasks/abc129_f
#include <bits/stdc++.h> using namespace std; #define rep(i,n) for (int i=0; i<(int)(n); ++i) #define all(a) (a).begin(), (a).end() #define rall(a) (a).rbegin(), (a).rend() using ll = long long; using vi = vector<int>; using vl = vector<ll>; using Graph = vector<vi>; // vi <=> vl using vb = vector<bool>; using boolGraph = vector<vb>; using P = pair<int, int>; // int <=> ll const int MOD = 1e9+7; const int MOD2 = 998244353; const double EPS = 1e-9; int main() { ll L, A, B, M; cin >> L >> A >> B >> M; P digit = P(1, 1); ll tmp = 10; while (A >= tmp) { tmp *= 10; ++digit.first; } ll last = A + B * (L-1); tmp = 10; while (last >= tmp) { tmp *= 10; ++digit.second; } ll init = A; ll ans = 0; ll pow10 = pow(10, digit.first); for (int k=digit.first; k<=digit.second; ++k) { if (pow10 <= init) { pow10 *= 10; continue; } ll num = (min(pow10 - 1, last) - init) / B + 1; vl rem(64), dp(64), dp2(64), power(64); rem[0] = pow10 % M; dp[0] = 1; dp2[0] = 1; power[0] = 1; rep(i,63) { rem[i+1] = rem[i] * rem[i] % M; dp[i+1] = dp[i] * (1 + rem[i]) % M; dp2[i+1] = (dp2[i] * (1 + rem[i]) + dp[i] * power[i]) % M; power[i+1] = power[i] * 2 % M; } ll expo = 1, sigma_a = 0; ll expo2 = 1, sum = 0, sigma_b = 0; for (int i=63; i>=0; --i) { if ((num >> i) & 1) { (sigma_a += expo * dp[i]) %= M; (expo *= rem[i]) %= M; } if (((num - 1) >> i) & 1) { (sigma_b += sum * power[i] + expo2 * dp2[i]) %= M; (sum += expo2 * dp[i]) %= M; (expo2 *= rem[i]) %= M; } } (ans *= expo) %= M; (ans += (init % M) * sigma_a + (B % M) * sigma_b) %= M; init += B * num; pow10 *= 10; } cout << ans << endl; return 0; }
#include <bits/stdc++.h> using namespace std; const int N = 2 * 1000 + 17; const int MOD = 1000 * 1000 * 1000 + 7; long long n, a, b, mod; bool read() { if (!(cin >> n >> a >> b >> mod)) return false; return true; } int getlen(long long num) { auto res = 0; for (; num > 0; num /= 10, ++res) { } return res; } long long bpow(long long a, long long n, long long mod) { auto res = 1ll; a %= mod; for (; n > 0; n /= 2, a = a * a % mod) if (n & 1) res = res * a % mod; return res; } long long series1(long long x, long long n) { if (n == 0) return 1ll; auto nn = (n - 1) / 2; auto res = series1(x, nn) * (1 + bpow(x, nn + 1, mod)) % mod; if (n % 2 == 0) res += bpow(x, n, mod); return res % mod; } long long series2(long long x, long long n) { if (n == 0) return 0ll; auto nn = (n - 1) / 2; auto piv = bpow(x, nn + 1, mod); auto res = (series2(x, nn) * (1 + piv) + (nn + 1) % mod * series1(x, nn) % mod * piv) % mod; if (n % 2 == 0) res += n % mod * bpow(x, n, mod) % mod; return res % mod; } long long calc(long long a, long long b, long long n) { long long x = bpow(10ll, getlen(a), mod); return (mod + (a % mod * series1(x, n) - b % mod * series2(x, n)) % mod) % mod; } void solve() { auto ans = 0ll; for (long long len = getlen(a), i = 0; i < n; ++len) { if (len < getlen(a + i * b)) continue; auto l = i; auto r = n - 1; for (; l < r; ) { auto m = (l + r + 1) / 2; if (getlen(a + b * m) > len) r = m - 1; else l = m; } ans = bpow(bpow(10ll, len, mod), r + 1 - i, mod) * ans % mod; ans = (ans + calc(a + r * b, b, r - i)) % mod; i = r + 1; } cout << ans << endl; } int32_t main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); while (read()) solve(); return 0; }
#include <iostream> #define ll long long using namespace std; ll cal10[64]; ll big10(ll key, ll mod){ ll res=1; for(int i=0; i<64; ++i){ if(key&((ll) 1<<i)){ res=(res*cal10[i])%mod; } } return res; } int main() { ll L, A, B, M; cin >> L >> A >> B >> M; ll b10[19]; b10[0]=1; for(int i=1; i<19; ++i) b10[i]=b10[i-1]*10; ll rnow=L, dig=0, ans=0; cal10[0]=10%M; for(int i=1; i<64; ++i) cal10[i]=(cal10[i-1]*cal10[i-1])%M; for(int p=18; p>0; --p){ ll left=-1, right=rnow; while(left+1<right){ ll mid=(left+right)/2; if(A+B*mid<b10[p-1]) left=mid; else right=mid; } ll cnt=rnow-right; if(cnt==0) continue; ll dp[3][3], ep[3][3]; dp[0][0]=(b10[p]+1)%M; dp[0][1]=dp[0][2]=M-b10[p]%M; dp[1][0]=1; dp[1][1]=dp[1][2]=dp[2][0]=dp[2][1]=0; dp[2][2]=b10[p]%M; for(int i=0; i<3; ++i){ for(int j=0; j<3; ++j){ if(i==j) ep[i][j]=1; else ep[i][j]=0; } } for(int s=0; s<64; ++s){ ll fp[3][3]; if((cnt-1)&((ll) 1<<s)){ for(int j=0; j<3; ++j){ for(int k=0; k<3; ++k){ fp[j][k]=0; for(int q=0; q<3; ++q){ fp[j][k]=(fp[j][k]+(dp[j][q]*ep[q][k])%M)%M; } } } for(int i=0; i<9; ++i) ep[i/3][i%3]=fp[i/3][i%3]; } for(int j=0; j<3; ++j){ for(int k=0; k<3; ++k){ fp[j][k]=0; for(int q=0; q<3; ++q){ fp[j][k]=(fp[j][k]+(dp[j][q]*dp[q][k])%M)%M; } } } for(int i=0; i<9; ++i) dp[i/3][i%3]=fp[i/3][i%3]; } ll ad=(ep[0][0]*(((A%M)+((B%M)*((rnow-1)%M))%M)))%M; ad=(ad+(ep[0][2]*(B%M))%M)%M; ad=(ad*big10(dig, M))%M; ans=(ans+ad)%M; dig += cnt*p; rnow=right; } cout << ans << endl; return 0; }
#include <bits/stdc++.h> const int INF=1e9; const int MOD=1e9+7; //const int MOD=998244353; const long long LINF=1e18; using namespace std; #define int long long //template int L,a,b,m; int x=0; int gy[3][3],tmp[3][3],ans[3][3]; int pw(int n,int k){ if(k<0)return pw(n,k+MOD-1); int res=1; while(k){ if(k&1)res*=n;//res%=MOD; n*=n;//n%=MOD; k>>=1; } return res; } void toans(){ memset(tmp,0,sizeof(tmp)); for(int i=0;i<3;i++) for(int j=0;j<3;j++) for(int k=0;k<3;k++) tmp[i][j]+=gy[i][k]*ans[k][j]; for(int i=0;i<3;i++)for(int j=0;j<3;j++)ans[i][j]=tmp[i][j]%m; } void gygy(){ memset(tmp,0,sizeof(tmp)); for(int i=0;i<3;i++) for(int j=0;j<3;j++) for(int k=0;k<3;k++) tmp[i][j]+=gy[i][k]*gy[k][j]; for(int i=0;i<3;i++)for(int j=0;j<3;j++)gy[i][j]=tmp[i][j]%m; } void g(int n){ int t=n; memset(ans,0,sizeof(ans)); ans[0][0]=ans[1][1]=ans[2][2]=1; while(n){ if(n&1)toans(); gygy(); n>>=1; } } void f(int n){ int l=(pw(10,n-1)-a)/b;if((pw(10,n-1)-a)%b)l++;if((pw(10,n-1)-a)<0)l=0; int r=(pw(10,n)-a)/b;r--;if((pw(10,n)-a)%b)r++;if((pw(10,n)-a)<0)r=-1; r=min(r,L-1);l=min(l,L); memset(gy,0,sizeof(gy)); gy[0][1]=gy[1][1]=gy[2][2]=1; gy[1][2]=b; gy[0][0]=pw(10,n)%m; g(r-l+1); x=(ans[0][0]*x+ans[0][1]*((a%m+b%m*l)%m)+ans[0][2])%m; } //main signed main(){ cin>>L>>a>>b>>m; for(int i=1;i<=18;i++)f(i); cout<<x<<endl; } /* 解説AC 多分キムチ鍋食べてた日の回 行列累乗使うってネタバレは見てたけど桁が動くから出来なくね?って思ってたけど良く考えたら桁18種類だし場合分けするだけだった 実装はそこまで詰まらずに出来たのでわりかし満足 */
#include <bits/stdc++.h> using namespace std; typedef long long ll; ll L, A, B; int mod; void specPower(int d, int q, ll p, int &dsum, int &sum, int &qpw) { if (p == 0) { dsum = sum = 0; qpw = 1; } else { specPower(d, q, p / 2, dsum, sum, qpw); dsum = (ll(dsum) * qpw + ll(p / 2) * ll(d) % mod * sum + ll(dsum)) % mod; sum = (ll(sum) * qpw + ll(sum)) % mod; qpw = ll(qpw) * qpw % mod; if (p % 2) { dsum = (ll(dsum) * q + ll(p / 2 * 2) * d + ll(d)) % mod; sum = (ll(sum) * q + 1ll) % mod; qpw = ll(qpw) * q % mod; } } } int main() { cin >> L >> A >> B >> mod; ll fir = A, lst = A + (L - 1) * B; ll lef = 1, rig = 10; int res = 0; while (lef <= lst) { if (fir < rig) { ll hm = (min(rig - 1, lst) - fir) / B + 1; int dsum, sum, qpw; specPower(B % mod, rig % mod, hm - 1, dsum, sum, qpw); int my = dsum; sum = (sum + qpw) % mod; my = (my + ll(fir % mod) * sum) % mod; qpw = ll(rig % mod) * qpw % mod; res = (ll(res) * qpw + ll(my)) % mod; fir += hm * B; } lef *= 10; rig *= 10; } printf("%d\n", res); return 0; }
#include <bits/stdc++.h> #define mp make_pair #define pb push_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define debug(x) cerr << #x << " " << x << '\n' using namespace std; using ll = long long; using pii = pair<int,int>; using pli = pair<ll,int>; const int INF = 0x3f3f3f3f, N = 2e5 + 5; const ll LINF = 1e18 + 5; ll len, A, B, L, R; int mod, n; struct matrix { ll mat[3][3]; }a; matrix operator * (matrix a, matrix b) { matrix res; for(int i=0; i<n; i++) for(int j=0; j<n; j++) { res.mat[i][j] = 0; for(int k=0; k<n; k++) res.mat[i][j] = (res.mat[i][j]+a.mat[i][k]*b.mat[k][j]%mod)%mod; } return res; } void one(matrix& E) { for(int i=0; i<n; i++) for(int j=0; j<n; j++) E.mat[i][j] = (i==j); } matrix operator ^ (matrix a, ll x) { matrix res; one(res); while(x) { if(x&1) res = res * a; a = a * a; x >>= 1; } return res; } bool find(ll x, ll y) { ll l = 0, r = len-1; L = -1; while(l<=r) { ll mid = (l+r)>>1; ll cur = A + mid*B; if(cur<x) l = mid + 1; else L = mid, r = mid - 1; } l = 0, r = len-1; R = -1; while(l<=r) { ll mid = (l+r)>>1; ll cur = A + mid*B; if(cur>=y) r = mid - 1; else R = mid, l = mid + 1; } if(R==len-1) return 0; return 1; } int main() { ios::sync_with_stdio(false); cin.tie(0); cin >> len >> A >> B >> mod; const ll up = 1e18; ll ans = 0, s = 0; bool ok = 1; n = 3; for(ll d=10; d<=up&&ok; d*=10) { ok = find(d/10, d); if(R-L+1<=0) continue; a.mat[0][0] = d%mod; a.mat[0][1] = a.mat[0][2] = a.mat[1][2] = a.mat[2][0] = 0; a.mat[1][0] = a.mat[1][1] = a.mat[2][2] = 1; a.mat[2][1] = B%mod; a = a ^ (R-L+1); (s = A + L*B) %= mod; (ans = ans*a.mat[0][0]%mod + s*a.mat[1][0]%mod + a.mat[2][0]) %= mod; } ans = (ans + mod)%mod; cout << ans; return 0; }
#include <iostream> #include <vector> #include <algorithm> #include <initializer_list> using lli=long long int; int M; class mat3{ public: lli m[3][3] = {}; mat3(){} mat3(std::initializer_list<lli> init){ auto it = init.begin(); for(int i = 0; i < 3; i++){ for(int j = 0; j < 3; j++){ m[i][j] = (((*it)%M)+M)%M; ++it; } } } }; const mat3 operator*(const mat3& lhs, const mat3& rhs){ mat3 ans; for(int i = 0; i < 3; i++){ for(int j = 0; j < 3; j++){ for(int k = 0; k < 3; k++){ ans.m[i][j] += lhs.m[i][k]*rhs.m[k][j]; } ans.m[i][j] %= M; } } return ans; } int main(){ lli L,A,B; std::cin >> L >> A >> B >> M; std::vector<lli> ns_d(1); lli tmp = 9; while(A+B*(L-1)>tmp){ if(A>tmp){ ns_d.push_back(0); }else{ ns_d.push_back((tmp-A)/B+1); } tmp = tmp*10+9; } ns_d.push_back(L); mat3 mat_total = {1,0,0,0,1,0,0,0,1}; for(int i = 1; i < ns_d.size(); i++){ lli ipow = 1; for(int j = 0; j < i; j++){ ipow = (ipow*10)%M; } lli isize = ns_d[i]-ns_d[i-1]; mat3 mat_last = {ipow,1,0,0,1,B,0,0,1}; int nb = 0; while((isize>>nb)!=0){ if((isize>>nb)&1){ mat_total = mat_last*mat_total; } mat_last = mat_last*mat_last; nb++; } } lli ans = ((mat_total.m[0][1]*(A%M))%M+mat_total.m[0][2])%M; std::cout << ans << std::endl; return 0; }
#include "bits/stdc++.h" using namespace std; typedef long long ll; typedef vector<vector<ll>> Mat; #define ALL(v) (v).begin(),(v).end() const ll INF = 1LL << 60; const ll MOD = 1e9 + 7; ll pow_10[20]; ll M; ll mod_pow(ll a, ll n) { if (n == 0) return 1; if (n % 2 == 0) { ll tmp = mod_pow(a, n / 2); return (tmp * tmp) % M; } return (a * mod_pow(a, n - 1)) % M; } Mat operator*(const Mat& a, const Mat& b) { Mat ret(a.size(), vector<ll>(b[0].size())); for (int i = 0; i < a.size(); i++) { for (int j = 0; j < b[0].size(); j++) { for (int k = 0; k < a[0].size(); k++) { (ret[i][j] += a[i][k] * b[k][j] % M) %= M; } } } return ret; } Mat mat_pow(const Mat& a, ll n) { Mat ret; if (n == 0) { ret = Mat(a.size(), vector<ll>(a[0].size())); for (int i = 0; i < a.size(); i++) ret[i][i] = 1; return ret; } if (n % 2 == 0) { Mat t = mat_pow(a, n / 2); ret = t * t; } else { Mat t = mat_pow(a, n / 2); ret = t * t; ret = ret * a; } return ret; } int main() { ll L, A, B; cin >> L >> A >> B >> M; pow_10[0] = 1; for (int i = 1; i <= 18; i++) { pow_10[i] = pow_10[i - 1] * 10; } ll X = 0, s = A % M; for (int i = 0; i < 18; i++) { ll l, r; if (pow_10[i] <= A) l = 0; else l = (pow_10[i] - A + B - 1) / B; if (pow_10[i + 1] <= A) r = 0; else r = (pow_10[i + 1] - A + B - 1) / B; if (l == r) continue; if (l >= L) break; r = min(r, L); Mat P(3, vector<ll>(3)); P[0][0] = pow_10[i + 1] % M; P[0][1] = 1; P[1][1] = 1; P[1][2] = B % M; P[2][2] = 1; Mat Q = mat_pow(P, r - l); Mat v(3, vector<ll>(1)); v[0][0] = X; v[1][0] = s; v[2][0] = 1; Mat R = Q * v; X = R[0][0]; s = R[1][0]; } cout << X << endl; }
#include <bits/stdc++.h> using namespace std; typedef vector<long long> vec; typedef vector<vec> mat; long long L, A, B, M; mat mal( mat a, mat b ) { mat c( 3, vec( 3 ) ); for( int i = 0; i < 3; i++ ) { for( int j = 0; j < 3; j++ ) { for( int k = 0; k < 3; k++ ) { c[i][j] += a[i][k] * b[k][j] % M; c[i][j] %= M; } } } return c; } mat powmat( mat m, long long n ) { mat res( 3, vec( 3 ) ); for( int i = 0; i < 3; i++ ) res[i][i] = 1; while( n ) { if( n & 1 ) res = mal( res, m ); m = mal( m, m ); n >>= 1; } return res; } int main() { cin >> L >> A >> B >> M; long long ans = 0; for( long long pow10 = 10; pow10 <= 1e18; pow10 *= 10 ) { if( pow10 <= A ) continue; long long Cd = (pow10 - A + B - 1) / B; Cd = min( Cd, L ); mat m( 3, vec( 3 ) ); m[0][0] = pow10 % M; m[1][0] = 1; m[1][1] = 1; m[2][1] = B % M; m[2][2] = 1; m = powmat( m, Cd ); mat r( 3, vec( 3 ) ); r[0][0] = ans; r[0][1] = A % M; r[0][2] = 1; r = mal( r, m ); ans = r[0][0]; A += Cd * B; L -= Cd; if( L == 0 ) { break; } } cout << ans << endl; return 0; }
#include <bits/stdc++.h> using namespace std; #define ll long long #define all(V) V.begin(),V.end() using vv = vector<vector<ll>>; ll M; void say(vv v) { for (int i = 0;i < 3;i++) { for (int j = 0;j < 3;j++) cout << v[i][j] << " "; cout << endl; } } vv matpow(vv X, ll K) { vv A(3, vector<ll>(3, 0)), N = A, S = A; A[0][0] = A[1][1] = A[2][2] = 1; while (K) { if (K & 1) { for (int i = 0;i < 3;i++) { for (int j = 0;j < 3;j++) { for (int k = 0;k < 3;k++) { N[j][k] += A[j][i] * X[i][k]; N[j][k] %= M; } } } } else N = A; A = N; K /= 2; if (K < 1)break; N = S; for (int i = 0;i < 3;i++) for (int j = 0;j < 3;j++) for (int k = 0;k < 3;k++) N[j][k] += X[j][i] * X[i][k], N[j][k] %= M; X = N; N = S; } return A; } ll modpow(ll x, ll y) { ll ans = 1; while (y) { if (y & 1)ans *= x; x *= x; x %= M; ans %= M; y /= 2; } return ans; } int main() { ll A, B, L; cin >> L >> A >> B >> M; vector<vector<ll>> mt(3, vector<ll>(3, 0)); vector<ll> mans(19, 0), kr(20, 1); ll d10 = 10, ft = A, lt = A + (L - 1) * B, nl; for (ll i = 1;i < 19;i++) { if (d10 > ft) { nl = (min(d10 - 1, lt) - ft) / B; vv H = { {d10 % M, B % M, ft % M}, {0,1,1}, {0,0,1} }; vv G = matpow(H, nl); mans[i] = (G[0][0] * (ft % M) + G[0][1] + G[0][2]) % M; kr[i] = modpow(d10 % M, nl + 1); ft += (nl + 1) * B; } if (d10 > lt)break; d10 *= 10; } for (int i = 19;i > 0;i--) { kr[i - 1] *= kr[i]; kr[i - 1] %= M; } ll fans = 0; for (ll i = 1;i < 19;i++) { fans += kr[i + 1] * mans[i]; fans %= M; } cout << fans << endl; }
#include <iostream> #include <stdlib.h> #include <string> #define llint long long using namespace std; llint n, a, b, mod; llint beki[35]; llint modpow(llint a, llint n) { if(n == 0) return 1; if(n % 2){ return ((a%mod) * (modpow(a, n-1)%mod)) % mod; } else{ return modpow((a*a)%mod, n/2) % mod; } } llint calc2(llint n, llint x) { if(n == 0) return 0; if(n % 2){ return (calc2(n-1, x) + modpow(modpow(10, n-1), x) % mod) % mod; } else{ llint res = calc2(n/2, x); llint ret = res * modpow(modpow(10, n/2), x) % mod + res; ret %= mod; return ret; } } llint calc(llint l, llint r, llint d) { //cout << l << " " << r << " " << d << endl; if(l > r) return 0; if(l == r) return (a%mod+b%mod*l%mod) % mod; if((r-l+1)%2){ return (calc(l+1, r, d) + modpow(modpow(10, r-l), d) % mod * ((a%mod+b%mod*l%mod)%mod) % mod) % mod; } else{ llint m = (l+r)/2; llint res = calc(l, m, d); llint ret = res * modpow(modpow(10, r-m), d) % mod + res; ret %= mod; ret += b*(r-m)%mod * calc2(r-m, d) % mod, ret %= mod; return ret; } } int main(void) { cin >> n >> a >> b >> mod; //mod = 1000000007; beki[0] = 1; for(int i = 1; i < 19; i++) beki[i] = beki[i-1] * 10; llint len = 1, ans = 0; for(int i = 18; i >= 1; i--){ //cout << i << endl; llint l = (beki[i-1]-a+b-1)/b; llint r = (beki[i]-a+b-1)/b - 1; if((beki[i-1]-a+b-1) < 0) l = -1; if((beki[i]-a+b-1)/b < 0) r = -1; if(l >= n || r < 0) continue; r = min(r, n-1), l = max(l, 0LL); //cout << ans << endl; //cout << l << " " << r << " " << i << " " << len << endl; llint res = calc(l, r, i); ans += res * len % mod, ans %= mod; llint tmp = modpow(modpow(10, r-l+1), i); len *= tmp, len %= mod; //len += (r-l+1)%mod * i%mod, len %= mod; } cout << ans << endl; return 0; }
#include <bits/stdc++.h> const int INF=1e9; const int MOD=1e9+7; //const int MOD=998244353; const long long LINF=1e18; using namespace std; #define int long long //template int L,a,b,m; int x=0; int gy[3][3],tmp[3][3],ans[3][3]; int pw(int n,int k){ if(k<0)return pw(n,k+MOD-1); int res=1; while(k){ if(k&1)res*=n;//res%=MOD; n*=n;//n%=MOD; k>>=1; } return res; } void toans(){ memset(tmp,0,sizeof(tmp)); for(int i=0;i<3;i++) for(int j=0;j<3;j++) for(int k=0;k<3;k++) tmp[i][j]+=gy[i][k]*ans[k][j]; for(int i=0;i<3;i++)for(int j=0;j<3;j++)ans[i][j]=tmp[i][j]%m; } void gygy(){ memset(tmp,0,sizeof(tmp)); for(int i=0;i<3;i++) for(int j=0;j<3;j++) for(int k=0;k<3;k++) tmp[i][j]+=gy[i][k]*gy[k][j]; for(int i=0;i<3;i++)for(int j=0;j<3;j++)gy[i][j]=tmp[i][j]%m; } void g(int n){ int t=n; memset(ans,0,sizeof(ans)); ans[0][0]=ans[1][1]=ans[2][2]=1; while(n){ if(n&1)toans(); gygy(); n>>=1; } } void f(int n){ int l=(pw(10,n-1)-a)/b;if((pw(10,n-1)-a)%b)l++;if((pw(10,n-1)-a)<0)l=0; int r=(pw(10,n)-a)/b;r--;if((pw(10,n)-a)%b)r++;if((pw(10,n)-a)<0)r=-1; r=min(r,L-1);l=min(l,L); //cout<<l<<" "<<r<<endl; memset(gy,0,sizeof(gy)); gy[0][1]=gy[1][1]=gy[2][2]=1; gy[1][2]=b; gy[0][0]=pw(10,n)%m; g(r-l+1); x=(ans[0][0]*x+ans[0][1]*((a%m+b%m*l)%m)+ans[0][2])%m; //cout<<x<<endl; } //main signed main(){ cin>>L>>a>>b>>m; for(int i=1;i<=18;i++)f(i); cout<<x<<endl; } /* if(t==2&&n==1){ cout<<gy[0][0]<<" "<<gy[0][1]<<" "<<gy[0][2]<<endl; cout<<gy[1][0]<<" "<<gy[1][1]<<" "<<gy[1][2]<<endl; cout<<gy[2][0]<<" "<<gy[2][1]<<" "<<gy[2][2]<<endl; } */
#include <bits/stdc++.h> using namespace std; #define ll long long #define forn(i, n) for (ll i = 0; i < (n); i++) #define fori(i, b, e) for (ll i = (b); i < (e); i++) #define forr(i, b, e) for (ll i = (b); i >= (e); i--) #define allele(v) v.begin(), v.end() #define fi first #define se second ll mod; class Matrix { public: vector<vector<ll>> M; Matrix(int h, int w) { M = vector<vector<ll>>(h, vector<ll>(w)); } vector<ll> &operator[](int i) { return M[i]; } }; Matrix operator*(Matrix x, Matrix y) { int xh = x.M.size(), xw = x[0].size(); int yh = y.M.size(), yw = y[0].size(); if (xw != yh) throw invalid_argument("Sizes do not match."); Matrix res(xh, yw); forn(i, xh) forn(j, yw) { res[i][j] = 0; forn(k, xw) res[i][j] += ((x[i][k] % mod) * (y[k][j] % mod)) % mod, res[i][j] %= mod; } return res; } template <typename T> T quickpow(T b, ll e) { T cur = b; T ans = b; e--; while (e) { if (e & 1) ans = ans * cur; cur = cur * cur; e >>= 1; } return ans; } int main() { ios::sync_with_stdio(false); cin.tie(0); ll l, a, b; cin >> l >> a >> b >> mod; ll pow10[20]; ll cur = 1; forn(i, 19) pow10[i] = cur, cur *= 10; Matrix ans(3, 1); ans.M = {{0}, {a}, {b}}; forn(x, 19) { if (pow10[x + 1] <= a) continue; ll L = (pow10[x + 1] - a + b - 1) / b - (max(pow10[x], a) - a + b - 1) / b; L = min(L, l), l -= L; Matrix M(3, 3); M.M = {{pow10[x + 1] % mod, 1, 0}, {0, 1, 1}, {0, 0, 1}}; if (L > 0) ans = quickpow(M, L) * ans; } cout << ans[0][0] << endl; return 0; }
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<ll, ll> p_ll; template<class T> void debug(T itr1, T itr2) { auto now = itr1; while(now<itr2) { cout << *now << " "; now++; } cout << endl; } #define repr(i,from,to) for (int i=(int)from; i<(int)to; i++) #define all(vec) vec.begin(), vec.end() #define rep(i,N) repr(i,0,N) #define per(i,N) for (int i=(int)N-1; i>=0; i--) const ll MOD = pow(10,9)+7; const ll LLINF = pow(2,61)-1; const int INF = pow(2,30)-1; vector<ll> fac; void c_fac(int x=pow(10,6)+10) { fac.resize(x,true); rep(i,x) fac[i] = i ? (fac[i-1]*i)%MOD : 1; } ll inv(ll a, ll m=MOD) { ll b = m, x = 1, y = 0; while (b!=0) { int d = a/b; a -= b*d; swap(a,b); x -= y*d; swap(x,y); } return (x+m)%m; } ll nck(ll n, ll k) { return fac[n]*inv(fac[k]*fac[n-k]%MOD)%MOD; } ll gcd(ll a, ll b) { if (a<b) swap(a,b); return b==0 ? a : gcd(b, a%b); } ll lcm(ll a, ll b) { return a/gcd(a,b)*b; } int main() { ll L, A, B, M; cin >> L >> A >> B >> M; ll dl[18] = {}; rep(i,18) dl[i] = min((ll)L, max((ll)0, ((ll)pow(10,i+1)-A+(B-1))/B)); ll fn[18] = {}; rep(i,18) fn[i] = (max(A,pow(10,i+1)<=A ? -1 : ((ll)pow(10,i)-A+(B-1))/B*B+A))%M; per(i,17) dl[i+1] -= dl[i]; // debug(dl,dl+18); debug(fn,fn+18); ll p10[18] = {}; rep(i,18) p10[i] = i==0 ? 10%M : (p10[i-1]*10)%M; ll arr[3] = {0,1,B}; rep(i,18) { arr[1] = fn[i]; ll mat[3][3] = {{p10[i],1,0},{0,1,1},{0,0,1}}; ll now = 1; while (dl[i]>=now) { if (dl[i]&now) { ll ta[3] = {}; rep(j,3) rep(k,3) ta[j] =(ta[j]+mat[j][k]*arr[k])%M ; rep(j,3) arr[j] = ta[j]; } ll tm[3][3] = {}; rep(j,3) rep(k,3) rep(l,3) tm[j][k] = (tm[j][k]+mat[j][l]*mat[l][k])%M; rep(j,3) rep(k,3) mat[j][k] = tm[j][k]; now *= 2; } // cout << i+1 << ": "; debug(arr,arr+3); } ll result = arr[0]; cout << result << endl; return 0; }
#include <cstdio> #include <iostream> #include <string> #include <vector> #include <sstream> #include <map> #include <set> #include <queue> #include <algorithm> #include <cmath> #include <cstring> #include <typeinfo> #include <numeric> #include <functional> #include <unordered_map> #include <bitset> #include <stack> #include <assert.h> #include <unordered_set> #include <random> using namespace std; using ll = long long; using ull = unsigned long long; const ll INF = 1e16; const ll MOD = 1e9 + 7; #define REP(i, n) for(ll i = 0; i < n; i++) using vec = vector<ll>; using mat = vector<vec>; mat mul(mat a, mat b, ll m){ mat c(a.size(), vec(b[0].size())); for(ll i = 0; i < a.size(); i++){ for(ll k = 0; k < b.size(); k++){ for(ll j = 0; j < b[0].size(); j++){ c[i][j] = (c[i][j] + a[i][k] * b[k][j]) % m; } } } return c; } mat POW(mat a, ll n, ll m){ mat b(a.size(), vec(a.size())); for(ll i = 0; i < a.size(); i++){ b[i][i] = 1; } while(n > 0){ if(n & 1){ b = mul(b, a, m); } a = mul(a, a, m); n >>= 1; } return b; } ll len(ll x){ ll res = 0; while(x > 0){ x /= 10; res++; } return res; } ll f(ll l, ll a, ll b){ ll z = len(a); ll le = 0, ri = l; while(le < ri){ ll m = (le + ri) / 2; if(z == len(a + b * m)){ le = m + 1; } else{ ri = m; } } return le; } int main(){ ll l, a, b, m; cin >> l >> a >> b >> m; ll sum = 0; while(l > 0){ ll k = f(l, a, b); ll p = 1; REP(i, len(a)){ p *= 10; p %= m; } vec r = {sum, a % m, 1}; mat x = {{p, 0, 0}, {1, 1, 0}, {0, b % m, 1}}; x = POW(x, k, m); vec t(3); t[0] = (r[0] * x[0][0] + r[1] * x[1][0] + r[2] * x[2][0]) % m; t[1] = (r[0] * x[0][1] + r[1] * x[1][1] + r[2] * x[2][1]) % m; t[2] = (r[0] * x[0][2] + r[1] * x[1][2] + r[2] * x[2][2]) % m; sum = t[0]; l -= k; a += b * k; } cout << sum << endl; }
#include<iostream> using namespace std; long L,A,B,M; long ten[99],sten[99],iten[99]; long n; long cnt[18],SUM[18]; long pre,tmpten,ans,ll,rr,mm,k,X,Y,p,g; int main() { cin>>L>>A>>B>>M; pre=-1,tmpten=1; for(n=1;n<=18;n++) { cnt[n-1]=1; ll=pre,rr=L; tmpten*=10; while(rr-ll>1) { mm=(ll+rr)/2; if(A+B*mm<tmpten)ll=mm; else rr=mm; } k=ll-pre; if(k<0) { continue; } pre=ll; ten[0]=tmpten%M; sten[0]=1; iten[0]=0; if(k&1)cnt[n-1]=tmpten%M; for(int i=1;i<61;i++) { ten[i]=ten[i-1]*ten[i-1]%M; sten[i]=(ten[i-1]+1)%M*sten[i-1]%M; iten[i]=((ten[i-1]+1)%M*iten[i-1]+(1LL<<i-1)%M*sten[i-1]%M*ten[i-1])%M; if(k>>i&1)cnt[n-1]=cnt[n-1]*ten[i]%M; } X=0,p=1,Y=0,g=0; for(int i=61;i--;) { if(k>>i&1) { (X+=sten[i]*p)%=M; (Y+=(iten[i]+sten[i]*g)%M*p)%=M; p=p*ten[i]%M; g=(g+(1LL<<i))%M; } } SUM[n-1]=(((A+B*ll)%M*X-B%M*Y)%M+M)%M; } p=1; for(int i=18;i--;) { ans=(ans+SUM[i]*p)%M; p=p*cnt[i]%M; } cout<<ans<<endl; }
#define _USE_MATH_DEFINES #include "bits/stdc++.h" using namespace std; #define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i)) #define rep(i,j) FOR(i,0,j) #define each(x,y) for(auto &(x):(y)) #define mp make_pair #define MT make_tuple #define all(x) (x).begin(),(x).end() #define debug(x) cout<<#x<<": "<<(x)<<endl #define smax(x,y) (x)=max((x),(y)) #define smin(x,y) (x)=min((x),(y)) #define MEM(x,y) memset((x),(y),sizeof (x)) #define sz(x) (int)(x).size() #define RT return using ll = long long; using pii = pair<int, int>; using vi = vector<int>; using vll = vector<ll>; int MOD = 0; vector<vector<int> > mulMatMod(const vector<vector<int> > &A, const vector<vector<int> > &B) { auto n = (int)A.size(), m = (int)A[0].size(), p = (int)B[0].size(); vector<vector<int> > res(n, vector<int>(p)); for (int i = 0; i < n; ++i)for (int j = 0; j < p; ++j) for (int k = 0; k < m; ++k) res[i][j] = (int)((res[i][j] + (long long)A[i][k] * B[k][j]) % MOD); return res; } vector<vector<int> > powMatMod(vector<vector<int> > A, long long k) { auto n = (int)A.size(); vector<vector<int> > res(n, vector<int>(n)); for (int i = 0; i < n; ++i)res[i][i] = 1; while (k) { if (k % 2)res = mulMatMod(res, A); k /= 2; A = mulMatMod(A, A); } return res; } int digit(ll x) { int res = 0; while (x > 0) { res++; x /= 10; } return res; } void solve() { ll L, A, B; int M; cin >> L >> A >> B >> M; MOD = M; ll ans = 0; for (ll i = 0; i < L;) { int d = digit(A + B * i); ll pw = 1; rep(j, d)pw *= 10; ll j = (pw - A + B - 1) / B; smin(j, L); assert(j > i); vector<vi> C(3, vi(3)); C[0][0] = C[0][2] = C[1][0] = C[2][2] = 1; C[1][1] = (int)(pw%M); auto D = powMatMod(C, j - i); ll x = (A + B * i) % MOD; ans = D[1][0] * x+ D[1][1] * ans + D[1][2] * (B%M); ans %= MOD; i = j; } cout << ans << endl; } int main() { ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(15); solve(); return 0; }
#include<bits/stdc++.h> using namespace std; typedef long long ll; ll L,a,b,mod; struct Matric { ll a[3][3]; Matric(){memset(a,0,sizeof(a));} Matric operator*(const Matric&o)const { Matric ans; for(int i=0;i<3;i++) for(int j=0;j<3;j++) for(int k=0;k<3;k++) ans.a[i][j]=(ans.a[i][j]+a[i][k]*o.a[k][j]%mod)%mod; return ans; } }; Matric Mqpow(Matric a,ll n) { Matric ans; ans.a[0][0]=ans.a[1][1]=ans.a[2][2]=1; while(n) { if(n&1) ans=ans*a; a=a*a; n>>=1; } return ans; } ll qpow(ll a,ll n) { ll ans=1; while(n) { if(n&1) ans=ans*a%mod; a=a*a%mod; n>>=1; } return ans; } int getlen(ll x) { int ans=0; while(x) { x/=10; ans++; } return ans; } ll getpos(int x) { ll l=1,r=L,ans=1; while(l<=r) { ll m=l+r>>1; if(getlen(a+(m-1)*b)<=x) ans=m,l=m+1; else r=m-1; } return ans; } /* si=s(i-1)*qpow(10,i)+qi+B; gi=g(i-1)+B; |10i 1 1| |si-1| |0 1 1| |gi-1| |0 0 1| |B| */ int main() { scanf("%lld%lld%lld%lld",&L,&a,&b,&mod); ll ans=a%mod,res=a%mod,now=1; for(int i=1;i<=18;i++) { ll p=getpos(i); if(p==now) continue; { Matric A; A.a[0][0]=qpow(10,i);A.a[0][1]=1;A.a[0][2]=1; A.a[1][1]=1;A.a[1][2]=1; A.a[2][2]=1; A=Mqpow(A,p-now); ans=(A.a[0][0]*ans%mod+A.a[0][1]*res%mod+b%mod*A.a[0][2]%mod)%mod; res=(res+b*(p-now))%mod; now=p; } } printf("%lld\n",ans); }
#include <bits/stdc++.h> using namespace std; long long L,A,B,M; template<class K> vector<vector<K>> matmul(const vector<vector<K>> &A,const vector<vector<K>> &B){ vector<vector<K>> C(A.size(),vector<K>(B[0].size(),K())); for (int i=0;i<A.size();++i) for (int j=0;j<B[0].size();++j) for (int k=0;k<B.size();++k) C[i][j]=(C[i][j]+A[i][k]*B[k][j]%M)%M; return C; } template<class K> vector<vector<K>> matpow(vector<vector<K>> A,long long n){ vector<vector<K>> res(A.size(),vector<K>(A.size(),K())); for (int i=0;i<A.size();++i) res[i][i]=K(1); while(n){ if (n&1) res=matmul(res,A); A=matmul(A,A); n>>=1; } return res; } int digit(long long n){ int res=0; while(n>0){n/=10; ++res;} return res; } long long modpow(long long a,long long n){ long long res=1; while(n>0){ if (n&1) res=res*a%M; a=a*a%M; n>>=1; } return res; } int main(){ cin.tie(0); ios::sync_with_stdio(false); cin >> L >> A >> B >> M; vector<pair<long long,int>> ds; ds.emplace_back(1,digit(A)); for(int i=digit(A)+1;;++i){ long long n=((long long)pow(10,i-1)-A+B-1)/B+1; if (L<n) break; if (digit(A+(n-1)*B)!=i) continue; ds.emplace_back(n,i); if (i==18) break; } ds.emplace_back(L+1,19); int s=ds.size(); long long ans=0; vector<vector<long long>> po(3,vector<long long>(3)) ,cal={{1,1,0},{0,1,1},{0,0,1}} ,init={{0},{1},{B%M}} ,result(3,vector<long long>(1)); for (int i=0;i<s-1;++i){ long long n=ds[i+1].first-ds[i].first,d=ds[i].second; cal[0][0]=modpow(10,d); po=matpow(cal,n); init[0][0]=ans,init[1][0]=(A%M+(ds[i].first-1)*B%M)%M; ans=matmul(po,init)[0][0]; } cout << ans << endl; }
#include <bits/stdc++.h> #define rep(i, n) for (int i = 0; i < (n); ++i) #define repr(i, n) for (int i = (n); i >= 0; --i) #define FOR(i, m, n) for (int i = (m); i < (n); ++i) #define FORR(i, m, n) for (int i = (m); i >= (n); --i) #define equals(a, b) (fabs((a) - (b)) < EPS) using namespace std; typedef long long ll; typedef unsigned long long ull; typedef long double ld; //const ll mod = 1000000007; const ll mod2 = 998244353; const int inf = 1e9 + 10; const ll INF = 1e18; const ld EPS = 1e-10; const int dx[8] = {1, 0, -1, 0, 1, -1, -1, 1}; const int dy[8] = {0, 1, 0, -1, 1, 1, -1, -1}; template<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; } ll mod; ll keta[19], cnt[19]; typedef vector<ll> vec; typedef vector<vec> mat; mat mul(mat& a, mat& b) { mat c(a.size(), vec(b[0].size(), 0)); rep(i, a.size()) { rep(k, b.size()) { rep(j, b[0].size()) { c[i][j] += a[i][k] * b[k][j]; c[i][j] %= mod; } } } return c; } mat pow(mat a, ll n) { mat b(a.size(), vec(a.size(), 0)); rep(i, a.size()) b[i][i] = 1; while (n > 0) { if (n & 1) b = mul(b, a); a = mul(a, a); n >>= 1; } return b; } int main() { ll l, a, b; cin >> l >> a >> b >> mod; keta[0] = 1; rep(i, 18) keta[i + 1] = keta[i] * 10; rep(i, 19) keta[i]--; rep(i, 19) { if (keta[i] - a < 0) continue; cnt[i] = min(l, (keta[i] - a) / b + 1); } repr(i, 18) cnt[i + 1] -= cnt[i]; mat A = {{1, b % mod, a % mod}, {0, 1, 1}, {0, 0, 1}}; mat ans = {{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}; rep(i, 18) { A[0][0] = A[0][0] * 10 % mod; mat res = pow(A, cnt[i + 1]); ans = mul(res, ans); } cout << ans[0][2] << endl; return 0; }
#include <iostream> #include <cstring> using namespace std; typedef long long ll; class Matrix{ private: ll m[3][3]; public: Matrix(){memset(m, 0, sizeof(m));} Matrix(ll m11, ll m12, ll m13, ll m21, ll m22, ll m23, ll m31, ll m32, ll m33){ m[0][0] = m11; m[0][1] = m12; m[0][2] = m13; m[1][0] = m21; m[1][1] = m22; m[1][2] = m23; m[2][0] = m31; m[2][1] = m32; m[2][2] = m33; } ll &at(int i, int j){return m[i][j];} Matrix mul(Matrix o, ll mod){ Matrix out; for (int i = 0; i < 3; ++i){ for (int j = 0; j < 3; ++j){ for (int k = 0; k < 3; ++k){ out.at(i, j) += (m[i][k]*o.at(k, j)) % mod; } } } return out % mod; } Matrix operator%(ll mod){ Matrix out; for (int i = 0; i < 3; ++i){ for (int j = 0; j < 3; ++j){ out.at(i, j) = m[i][j] % mod; } } return out; } }; Matrix eye(){ return Matrix(1, 0, 0, 0, 1, 0, 0, 0, 1); } Matrix powMat(Matrix a, ll n, ll mod){ if (n == 0) return eye(); else if (n == 1) return a; else if (n % 2 == 0){ Matrix tmp = powMat(a, n/2, mod); return tmp.mul(tmp, mod); } else return a.mul(powMat(a, n-1, mod), mod); } void printMat(Matrix a){ for (int i = 0; i < 3; ++i){ for (int j = 0; j < 3; ++j){ printf("%ld ", a.at(i, j)); } printf("\n"); } } ll l, a, b, m, c[19], t, ans; Matrix p, q; int main(){ cin >> l >> a >> b >> m; c[0] = 0; t = 1; for (int d = 1; d <= 18; ++d){ t *= 10; if (t > a) c[d] = min(l, (t - 1 - a) / b + 1); else c[d] = 0; } for (int d = 0; d < 18; ++d){ c[d] = c[d+1] - c[d]; } p = {1, 0, 0, 1, 1, 0, 0, b, 1}; q = eye(); for (int d = 0; d < 18; ++d){ p.at(0, 0) *= 10; q = q.mul(powMat(p % m, c[d], m), m); } ans = (q.at(1, 0)*(a%m)) % m; ans = (ans + q.at(2, 0)) % m; printf("%ld", ans); }
#include <bits/stdc++.h> #define int long long #define inf (int)(3e18) #define mod (int)(1e9+7) #define rep(i,n) for(int i=0;i<n;i++) using namespace std; int mod_pow(int x,int y,int z){ int res=1; while(y>0){ if(y&1)res*=x; x*=x;x%=z; y>>=1; res%=z; } return res; } struct mat{ int m; vector<vector<int>>ma; mat(int x,int y,int z){ m=z; ma.resize(x); rep(i,x)ma[i].resize(y); rep(i,x)rep(j,y)ma[i][j]=0; } mat operator*(mat a){ assert(ma[0].size()==a.ma.size()); mat res(ma.size(),a.ma[0].size(),m); rep(i,ma.size()){ rep(j,a.ma[0].size()){ rep(k,a.ma.size()){ res.ma[i][j]+=ma[i][k]*a.ma[k][j]%m; res.ma[i][j]%=m; } } } return res; } mat pow(int x){ assert(ma.size()==ma[0].size()); mat res(ma.size(),ma.size(),m),me(ma.size(),ma.size(),m); rep(i,ma.size())res.ma[i][i]=1; me.ma=ma; while(x>0){ if(x&1)res=res*me; me=me*me; x>>=1; } return res; } }; int l,a,b,m; signed main(){ cin>>l>>a>>b>>m; mat ans(1,3,m),rui(3,3,m); ans.ma={{0,a%m,1}}; rui=rui.pow(0); for(int i=1;i<=18;i++){ int ma=mod_pow(10,i,inf)-1,mi=mod_pow(10,i-1,inf)-1; if(ma<a)continue; if(mi>=a+b*(l-1))continue; ma=min(ma,a+b*(l-1)); int ko=(ma-a)/b+1; if(mi>=a)ko-=(mi-a)/b+1; mat x(3,3,m); x.ma[0]={mod_pow(10,i,m),0,0}; x.ma[1]={1,1,0}; x.ma[2]={0,b%m,1}; rui=rui*x.pow(ko); } ans=ans*rui; cout<<ans.ma[0][0]<<endl; }
#include <bits/stdc++.h> #define fio ios_base::sync_with_stdio(false) #define pdl cout << "*" << endl #define MOD 1000000007 #define INF 1000000000 #define INFLL 1000000000000000000ll #define ff first #define ss second #define long int64_t using namespace std; typedef pair<int, int> pii; typedef pair<long, long> pll; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); uniform_int_distribution<> dis(0, INF<<1); #define trace(...) __f(#__VA_ARGS__, __VA_ARGS__) template <typename Arg1> void __f(const char* name, Arg1&& arg1){ cerr << name << " : " << arg1 << endl; } template <typename Arg1, typename... Args> void __f(const char* names, Arg1&& arg1, Args&&... args) { const char* comma = strchr(names + 1, ','); cerr.write(names, comma - names) << " : " << arg1 << " | "; __f(comma+1, args...); } const int M = 18; int mod; struct Mat { int m[3][3]; Mat(int v) { memset(m, 0, sizeof m); for(int i=0; i<3; i++) m[i][i] = v; } Mat operator* (const Mat &a) const { Mat r(0); for(int i=0; i<3; i++) for(int j=0; j<3; j++) for(int k=0; k<3; k++) r.m[i][j] = (r.m[i][j] + m[i][k] * 1ll * a.m[k][j]) % mod; return r; } }; int modexp(Mat a, long b, int s) { Mat r(1); while(b) { if(b & 1) r = r * a; a = a * a; b >>= 1; } return (s * 1ll * r.m[0][1] + r.m[0][2]) % mod; } int modexp(int a, long b) { int r = 1; while(b) { if(b & 1) r = (r * 1ll * a) % mod; a = (a * 1ll * a) % mod; b >>= 1; } return r; } long t[M+1]; long bs(long n, long a, long b, long lim) { long l = -1, r = n; while(l != r) { long mid = l+r+1 >> 1; if(a + mid * b < lim) l = mid; else r = mid-1; } return l; } int main() { fio; long l, a, b, t1 = 1; int ans = 0; cin >> l >> a >> b >> mod; t[0] = -1; for(int i=1; i<=M; i++) { t1 *= 10; t[i] = bs(l-1, a, b, t1); long A = a + (t[i-1] + 1) * b; long n = t[i] - t[i-1]; if(n) { Mat a(1); a.m[0][0] = t1 % mod; a.m[0][1] = 1; a.m[1][2] = b % mod; int r = modexp(a, n, A % mod); int x = modexp(t1 % mod, n); ans = (ans * 1ll * x + r) % mod; } } cout << ans << endl; return 0; }
#include<cstdio> #include<algorithm> #include<iostream> #include<cstring> #include<vector> using namespace std; typedef long long LL; LL MOD; struct qq{LL s[3][3];}; qq operator * (qq a,qq b) { qq c; for (LL u=0;u<=2;u++) for (LL i=0;i<=2;i++) { c.s[u][i]=0; for (LL j=0;j<=2;j++) c.s[u][i]=(c.s[u][i]+a.s[u][j]*b.s[j][i]%MOD)%MOD; } return c; }; LL L,A,B; qq Pow (qq x,LL y) { if (y==1) return x; qq lalal=Pow(x,y>>1); lalal=lalal*lalal; if (y&1) lalal=lalal*x; return lalal; } int main() { scanf("%lld%lld%lld%lld",&L,&A,&B,&MOD);L--; LL op=10,ans=0; LL o=0; for (LL u=1;u<=19;u++) { LL l=o,r=L,p=-1; while (l<=r) { LL mid=(l+r)>>1; if (mid*B+A<op) {p=mid;l=mid+1;} else r=mid-1; } if (p!=-1) { qq a; a.s[0][0]=op%MOD;a.s[0][1]=1;a.s[0][2]=0; a.s[1][0]=0;a.s[1][1]=1;a.s[1][2]=B%MOD; a.s[2][0]=0;a.s[2][1]=0;a.s[2][2]=1; a=Pow(a,p-o+1); LL t=(o%MOD*B%MOD+A)%MOD; //printf("%lld %lld %lld\n",op,t,p-o+1); ans=(ans*a.s[0][0]%MOD+t*a.s[0][1]%MOD+a.s[0][2])%MOD; o=p+1; } if (o>L) break; op*=10; } printf("%lld\n",ans); return 0; }
#include <bits/stdc++.h> using namespace std; typedef long long ll; #define all(x) (x).begin(),(x).end() const int MAX=100003,INF=1<<30; ll mod; typedef vector<vector<ll>> mat; mat mul(mat &A, mat&B){ mat C(A.size(),vector<ll>(B[0].size())); for(int i=0;i<A.size();i++){ for(int k=0;k<B.size();k++){ for(int j=0;j<B[0].size();j++){ C[i][j]=(C[i][j]+A[i][k]*B[k][j])%mod; } } } return C; } mat pow(mat A,ll n){ mat B(A.size(),vector<ll>(A.size())); for(int i=0;i<A.size();i++){ B[i][i]=1; } while(n>0){ if(n&1) B=mul(B,A); A=mul(A,A); n/=2; } return B; } ll rui(ll a,ll b){ ll ans=1; while(b>0){ if(b&1) ans=ans*a%mod; a=a*a%mod; b/=2; } return ans; } int main(){ ll L,X,Y;cin>>L>>X>>Y>>mod; ll sum=0; mat ans(3,vector<ll>(1,0)); ans[0][0]=0;ans[1][0]=(X-(Y%mod)+mod)%mod;ans[2][0]=1; for(int d=1;d<=18;d++){ ll a=1,cnt; for(int j=1;j<=d;j++) a*=10; if(a-1<X) continue; if(a/10-1<X&&X<=a-1){ cnt=(a-1-X)/Y+1; }else{ cnt=(a-1-X)/Y-(a/10-1-X)/Y; } if(sum+cnt>L) cnt=L-sum; mat A(3,vector<ll>(3,0)),B(2,vector<ll>(1,0)); A[0][0]=a%mod; A[0][1]=A[1][1]=A[2][2]=1; A[0][2]=A[1][2]=Y%mod; A=pow(A,cnt); A=mul(A,ans); for(int i=0;i<3;i++) ans[i][0]=A[i][0]; sum+=cnt; if(sum==L) break; //cout<<ans[0][0]<<endl; } cout<<ans[0][0]<<endl; }
#include <bits/stdc++.h> #define rep(i,n) for (int i = 0; i < (int)n; i++) using namespace std; typedef long long ll; typedef unsigned long long ull; typedef pair<int, int> pi; typedef pair<pi, pi> pp; typedef pair<ll, ll> pl; const double EPS = 1e-9; const ll MOD = 1000000007; const int inf = 1 << 30; const ll linf = 1LL << 60; ll L, A, B, M; ll cnt[19]; ll sum[19]; ll p10[19]; #define MAT_S 3 vector<vector<ll>> mul (vector<vector<ll>> x, vector<vector<ll>> y) { vector<vector<ll>> ret(MAT_S, vector<ll>(MAT_S, 0)); rep(i,MAT_S) rep(j,MAT_S) rep(k,MAT_S) { ret[i][j] = (ret[i][j] + x[i][k]*y[k][j]) % M; } return ret; } ll mat_pow (ll x, ll y, ll st) { vector<vector<ll>> b(MAT_S, vector<ll>(MAT_S, 0)); b[0][0] = p10[x]; b[0][1] = 1; b[0][2] = 0; b[1][0] = 0; b[1][1] = 1; b[1][2] = B%M; b[2][0] = 0; b[2][1] = 0; b[2][2] = 1; vector<vector<ll>> r(MAT_S, vector<ll>(MAT_S, 0)); r[0][0] = 1; r[0][1] = 0; r[0][2] = 0; r[1][0] = 0; r[1][1] = 1; r[1][2] = 0; r[2][0] = 0; r[2][1] = 0; r[2][2] = 1; while (y) { if (y&1) r = mul(r, b); b = mul(b,b); y /= 2; } return (r[0][1] * st + r[0][2]) % M; } ll mod_pow (ll x, ll y) { ll ret = 1; while (y) { if (y&1) ret = ret * x % M; x = x * x % M; y /= 2; } return ret; } int main() { cin >> L >> A >> B >> M; ll t = 1; p10[0] = 1; for (int i = 1; i < 19; i++) p10[i] = p10[i-1] * 10 % M; rep(i,18) { t *= 10; cnt[i+1] = (t-1>=A) + max(0LL,(t-1-A))/B - sum[i]; sum[i+1] = sum[i] + cnt[i+1]; if (sum[i+1] > L) { cnt[i+1] -= sum[i+1]-L; sum[i+1] = L; } } rep(i,19) { sum[i] %= M; } ll ans = 0; for (int i = 1; i <= 18; i++) { if (cnt[i] == 0) continue; ll tmp = 1; for (int j = i+1; j < 19; j++) rep(_,j) tmp = tmp * mod_pow(10,cnt[j]) % M; tmp = tmp * mat_pow(i, cnt[i], (A+(B%M)*sum[i-1])%M) % M; ans = (ans + tmp) % M; } cout << ans << endl; }
#include <bits/stdc++.h> #define mp make_pair #define fst first #define snd second #define forn(i,n) for (int i = 0; i < int(n); i++) #define forn1(i,n) for (int i = 1; i <= int(n); i++) #define popcnt __builtin_popcount using namespace std; typedef unsigned int uint; typedef long long ll; typedef unsigned long long ull; typedef pair<int,int> pii; typedef pair<ll,int> pli; typedef pair<int,ll> pil; typedef pair<ll,ll> pll; typedef vector<int> vi; typedef vector<ll> vl; template <typename T> T id(T b) {return b;}; template <class It> bool all(It f,It l){return std::all_of(f,l,id<bool>);} template <class It> bool any(It f,It l){return std::any_of(f,l,id<bool>);} template <typename T> void chmax(T &x, T y) {if (x < y) x = y;} template <typename T> void chmin(T &x, T y) {if (x > y) x = y;} ll l,a,b,MOD; typedef vector<long long> vec; typedef vector<vec> mat; mat make_mat(int n, int m) { return mat(n, vec(m)); } mat mat_mul(const mat &a, const mat &b) { mat r = mat(a.size(), vec(b[0].size())); for (int i = 0; i < (int)a.size(); i++) { for (int k = 0; k < (int)a[i].size(); k++) { for (int j = 0; j < (int)b[k].size(); j++) r[i][j] = (r[i][j] + a[i][k] * b[k][j] % MOD) % MOD; } } return r; } mat mat_pow(mat a, long long b) { mat r = mat(a.size(), vec(a[0].size())); for (int i = 0; i < (int)a.size(); i++) r[i][i] = 1; while (b > 0) { if (b&1) r = mat_mul(r,a); a = mat_mul(a,a); b >>= 1; } return r; } ll d9(int d) { ll res = 0; forn(i,d) res = 10LL*res + 9; return res; } ll c(int d) { ll mx = d9(d); ll l = 0, r = (mx-a)/b+2; while (r - l > 1) { ll mid = l + (r - l) / 2; if (a+b*mid <= mx) l = mid; else r = mid; } return l+1; } int main() { #ifdef FASTIO ios_base::sync_with_stdio(false); cin.tie(nullptr); #endif cin >> l >> a >> b >> MOD; ll prev = 0; int d = 1; ll ten = 10; mat res = mat{{0,a%MOD,1}}; while (l > 0) { ll cur = c(d); mat A = mat{{ten,0,0},{1,1,0},{0,b%MOD,1}}; ll k = min(l,cur - prev); mat B = mat_pow(A, k); res = mat_mul(res, B); l -= k; prev = cur; d++; ten = (ten * 10) % MOD; } cout << res[0][0] << endl; return 0; }
#include <bits/stdc++.h> #define sz(c) int(c.size()) #define rep(i,a,b) for (int i=a; i<(b); ++i) #define per(i,a,b) for (int i=(b)-1; i>=(a); --i) using namespace std; using ll = long long; int M; inline int madd(int x,int y) { if (x+y<M) return x+y; else return x+y-M; } inline int msub(int x,int y) { if (x-y>=0) return x-y; else return x-y+M; } inline int mmul(int x,int y) { return int(ll(x)*y % M); } template<class T,int N,int P,int M> void matmul(T res[N][M], const T A[N][P], const T B[P][M]) { // res=A*B static T tmp[N][M]; rep(i,0,N) rep(j,0,M) tmp[i][j]=0; rep(i,0,N) rep(j,0,M) rep(k,0,P) { tmp[i][j]=madd(tmp[i][j], mmul(A[i][k],B[k][j])); } rep(i,0,N) rep(j,0,M) res[i][j]=tmp[i][j]; } template<class T,int N,int M> void matpow(T res[N][M], const T A[M][M], ll p) { // res=res*A^p static T tmp[M][M]; rep(i,0,M) rep(j,0,M) tmp[i][j]=A[i][j]; while (p>0) { if (p%2) matmul<T,N>(res,res,tmp); matmul<T,M>(tmp,tmp,tmp); p/=2; } } int len(ll x) { assert(x>0); int res=0; while (x>0) { x/=10; res++; } return res; } ll find_len(ll L,ll A,ll B) { int z=len(A); ll l=0,r=L; while (l<r) { ll m=l+(r-l)/2; if (z==len(A+B*m)) l=m+1; else r=m; } return l; } int main() { cin.tie(0); ios_base::sync_with_stdio(0); cout<<fixed<<setprecision(10); ll L,A,B; cin>>L>>A>>B>>M; int sum=0; while (L>0) { ll k=find_len(L,A,B); int p=1; rep(i,0,len(A)) p=mmul(p,10); int r[1][3]={{sum,int(A%M),1}}; int X[3][3]={{p,0,0}, {1,1,0}, {0,int(B%M),1}}; matpow<int,1>(r,X,k); sum=r[0][0]; L-=k; A+=B*k; } cout<<sum<<"\n"; }
#include <bits/stdc++.h> #define For(i, a, b) for(int (i)=(a); (i)<(b); ++(i)) #define rFor(i, a, b) for(int (i)=(a)-1; (i)>=(b); --(i)) #define rep(i, n) For((i), 0, (n)) #define rrep(i, n) rFor((i), (n), 0) #define fi first #define se second using namespace std; typedef long long lint; typedef pair<int, int> pii; typedef vector<vector<lint>> mat; mat mul(mat &a, mat &b, lint &mod){ int n = a.size(); int m = b[0].size(); mat c = vector<vector<lint>>(n, vector<lint>(m, 0)); rep(i, n)rep(j, m){ lint t = 0; rep(k, a[0].size()) t = (t + a[i][k] * b[k][j] % mod) % mod; c[i][j] = t; } return c; } mat pow(mat a, lint k, lint &mod){ int n = a.size(); mat ret = vector<vector<lint>>(n, vector<lint>(n, 0)); rep(i, n) ret[i][i] = 1; while(k){ if(k & 1){ ret = mul(ret, a, mod); k -= 1; } else{ a = mul(a, a, mod); k >>= 1; } } return ret; } lint binsearch(lint i, lint a, lint b, lint l){ if(to_string(a).size() > i) return 0; if(to_string(a+b*(l-1)).size() <= i) return l-1; lint low = 0; lint high = l-1; while(high - low > 1){ lint mid = (high + low) / 2; if(to_string(a+b*mid).size() > i) high = mid; else low = mid; } return low; } int main(){ lint l, a, b, m; scanf("%lld%lld%lld%lld", &l, &a, &b, &m); mat v = vector<vector<lint>>(3, vector<lint>(1, 0)); v[0][0] = 0; v[1][0] = a; v[2][0] = b; mat p = vector<vector<lint>>(3, vector<lint>(3, 0)); p[0][0] = p[0][1] = p[1][1] = p[1][2] = p[2][2] = 1; lint num[20]; rep(i, 20) num[i] = binsearch(i, a, b, l); num[0] = -1; For(i, 1, 20){ p[0][0] = (p[0][0] * 10) % m; mat q = pow(p, num[i] - num[i-1], m); v = mul(q, v, m); } printf("%lld\n", v[0][0]); }
#include <iostream> #include <vector> using namespace std; typedef long long ll; typedef vector<ll> vec; typedef vector<vec> mat; ll L,A,B,M; mat mult(mat &A,mat &B){ mat C(A.size(),vec(B[0].size())); for(int i=0;i<A.size();i++){ for(int k=0;k<B.size();k++){ for(int j=0;j<B[0].size();j++){ (C[i][j] += A[i][k]*B[k][j]%M)%=M; } } } return C; } mat pow(mat A, ll n){ if(n==1) return A; else if(n%2==0){ mat B = pow(A,n/2); return mult(B,B); }else{ mat B = pow(A,n-1); return mult(A,B); } } ll cnt[20] = {}; ll cnt2[20] = {}; ll p[19] = {1}; int main(){ cin >> L >> A >> B >> M; for(int i=1;i<=18;i++) p[i] = 10*p[i-1]; /*ll now = A; for(int i=0;i<L;i++){ for(int j=1;j<=18;j++){ if(now<p[j]){ cnt2[j]++; break; } } now += B; } for(int i=1;i<=18;i++) cerr << cnt2[i] << " "; cerr << endl; */for(int i=1;i<=18;i++){ if(p[i]-1<A) continue; if(A+(L-1)*B<p[i-1]) continue; cnt[i] = (min(p[i]-1,A+(L-1)*B)-A)/B+1; if(i>1 && p[i-1]-1>A) cnt[i] -= max((p[i-1]-1-A)/B+1,0LL); } ll ans = 0; mat res(3,vec(3,0)); res[0][0] = res[1][1] = res[2][2] = 1; /* for(int i=1;i<=18;i++) cerr << cnt[i] << " "; cerr << endl; */ for(int i=1;i<=18;i++){ if(cnt[i]==0) continue; mat A(3,vec(3,0)); A[0][0] = p[i]%M; A[0][1] = A[1][1] = A[2][2] = 1; A[1][2] = B; mat a = pow(A,cnt[i]); res = mult(a,res); } cout << (res[0][2]+A%M*res[0][1]%M)%M << endl; }
//ΔABC129F #include<iostream> #include<cstdio> #include<fstream> #include<algorithm> #include<vector> #include<map> #include<set> #include<queue> #include<bitset> #include<cmath> #include<cstring> #include<cstdlib> using namespace std; typedef long long LL; typedef double DB; int m; LL d; int mul(int x,int y){ return (LL)x*y%m; } int fpow(LL x,LL y){ int z=1; x%=m; while(y){ if(y&1) z=mul(z,x); y>>=1; x=mul(x,x); } return z; } pair<int,int> solve(LL w,int o){ if(w==1) return make_pair(1,0); int a,b,e=fpow(o,w/2); pair<int,int> p=solve(w/2,o); a=p.first,b=p.second; p.first=mul(a,e+1); p.second=(mul(b,e+1)+mul(a,(w/2)%m))%m; if(w&1){ a=p.first,b=p.second; p.first=(mul(a,o)+1)%m; p.second=(b+a)%m; } return p; } int main() { LL w,l,r,o,a,b,c,s; int i; pair<int,int> p; cin>>w>>l>>r>>m; d=r; r=l+d*(w-1); s=0; o=1; for(i=0;i<18;i=i+1){ a=max(l,o); a+=(l%d-a%d+d)%d; b=min(r,o*10-1); b-=(b%d-r%d+d)%d; o*=10; if(a>b) continue; c=(b-a)/d+1; s=mul(s,fpow(o,c)); p=solve(c,o%m); s+=mul(a%m,p.first); s+=mul(d%m,p.second); s%=m; } cout<<s; return 0; }
#include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (ll i = (a); i < (b); i++) typedef uint64_t ull; typedef int64_t ll; typedef std::pair<ll, ll> PLL; ll L, A, B, MOD, ten; struct mll { ll x; mll(ll x=0): x(x%MOD){ } mll& operator+=(const mll a) { (x += a.x) %= MOD; return *this; } mll& operator-=(const mll a) { (x += MOD-a.x) %= MOD; return *this; } mll& operator*=(const mll a) { (x *= a.x) %= MOD; return *this; } mll operator+(const mll a) const { mll res(*this); return res+=a; } mll operator-(const mll a) const { mll res(*this); return res-=a; } mll operator*(const mll a) const { mll res(*this); return res*=a; } }; // x^y mll pow_(mll x, ll y) { if (y==0) return mll(1); else if(y%2==1) { return pow_(x, y-1) * x; } else { mll z = pow_(x, y/2); return z*z; } } mll f(ll l) { if (l==0) return 0; if (l%2==1){ ll pl = l-1; mll x = f(pl); return x*mll(ten)*mll(10)+mll(1); } else { ll pl = l/2; mll x = f(pl); return x*pow_(mll(ten)*mll(10), pl) + x; } return 0; } mll g(ll l) { if (l==0) return 0; if (l%2==1) { ll pl = l-1; mll x = g(pl); return x*mll(ten)*mll(10) + B*pl; } else { ll pl = l/2; mll x = g(pl); return x*pow_(mll(ten)*mll(10), pl) + x + mll(B)*mll(pl)*f(pl); } } signed main() { cin>>L>>A>>B>>MOD; mll ans(0); ten = 1; for (ll k=0; k<18; k++, ten*=10) { // [ 10^k 10^(k+1) ) の区間について if (A+B*(L-1) < ten) continue; if (10*ten <= A) continue; ll a; // 区間内での初項 if (ten <= A) { a = A; } else{ a = (ten-A + B-1)/B * B + A; } ll last; // 区間内での最後の項 if (A+B*(L-1) < 10*ten) { last = A+B*(L-1); } else { last = (10*ten-1 - A)/B * B + A; } ll l = (last-a)/B + 1; // 区間内での項の数 if (last < a) continue; mll ans_k = mll(a)*f(l) + g(l); ans *= pow_(mll(10*ten), l); ans += ans_k; //printf("k=%d [%2lld %2lld) %2lld -> %2lld (%lld) ans_k=%d\n", // k, ten, ten*10, a, last, l, ans_k.x); } cout<<ans.x<<endl; return 0; }
#include <iostream> #include <vector> using namespace std; typedef long long ll; long long MOD = 1000000007; struct matrix { vector<vector<ll>> mat; ll row; ll col; void resize( ll row, ll col, ll initial ) { this->row = row; this->col = col; mat.resize( row, vector<ll>( col, initial ) ); } void identity() // first resize with initial = 0 { for ( ll i = 0; i < (ll)mat.size(); i++ ) mat[i][i] = 1; } matrix operator+( matrix &b ) const { matrix temp; temp.resize( row, col, 0 ); for ( ll i = 0; i < row; i++ ) { for ( ll j = 0; j < col; j++ ) { temp.mat[i][j] = ( mat[i][j] % MOD ) + ( b.mat[i][j] % MOD ); temp.mat[i][j] %= MOD; } } return temp; } matrix operator*( matrix &b ) const { matrix temp; ll ro, co; temp.resize( row, b.col, 0 ); for ( ll i = 0; i < row; i++ ) { for ( ll j = 0; j < b.col; j++ ) { for ( ll k = 0; k < col; k++ ) { temp.mat[i][j] += ( ( mat[i][k] % MOD ) * ( b.mat[k][j] % MOD ) ); temp.mat[i][j] %= MOD; } } } return temp; } matrix power( ll b ) { matrix a = matrix( *this ); matrix ans; ans.resize( row, col, 0 ); ans.identity(); while ( b ) { if ( b & (ll)1 ) { ans = ans * a; } a = a * a; b >>= 1; } return ans; } }; int main() { ll l, a, b, m; cin >> l >> a >> b >> m; MOD = m; matrix ans; ans.resize( 1, 3, 0 ); ans.mat[0][0] = a % MOD; ans.mat[0][1] = ( a + b ) % MOD; ans.mat[0][2] = 1; ll term = 1, d = 10; while ( term < l ) { ll lo = max( (ll)0, ( ( d / 10 - 1 ) - a ) / b ); ll hi = min( l - 1, max( ( d - 1 - a ) / b, (ll)0 ) ); ll now = hi - lo; term += hi - lo; matrix temp; temp.resize( 3, 3, 0 ); temp.mat[0][0] = d % MOD; temp.mat[1][0] = 1; temp.mat[1][1] = 1; temp.mat[2][1] = b % MOD; temp.mat[2][2] = 1; temp = temp.power( now ); ans = ans * temp; d *= 10; } cout << ans.mat[0][0] << endl; return 0; }
#include <algorithm> #include <bitset> #include <cassert> #include <cstring> #include <iomanip> #include <iostream> #include <map> #include <queue> #include <random> #include <set> #include <stack> #include <vector> using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef vector<vector<ll>> matrix; matrix mult(matrix a, matrix b, int m) { matrix c; for(int i = 0; i < a.size(); i++) { c.push_back({}); for(int j = 0; j < b[0].size(); j++) { c[i].push_back(0); for(int k = 0; k < b.size(); k++) { c[i][j] += a[i][k] * b[k][j]; c[i][j] %= m; } } } return c; } matrix pow(matrix b, ll e, int m) { matrix r; for(int i = 0; i < b.size(); i++) { r.push_back({}); for(int j = 0; j < b.size(); j++) { r[i].push_back(i == j); } } while(e) { if(e%2) { r = mult(r, b, m); } e /= 2; if(e) { b = mult(b, b, m); } } return r; } void solve(ll start, ll diff, ll numTerms, ll m) { ll len = 1; ll currCap = 9; matrix curr; curr.push_back({0}); curr.push_back({start%m}); curr.push_back({1}); while(numTerms > 0) { /* (x, start, 1) -> (10**len*x + start, start + diff, 1) */ len *= 10; len %= m; for(int d = 60; d >= 0; d--) { if((1LL << d) > numTerms) continue; ll lastTerm = start + (-1 + (1LL << d)) * diff; if(lastTerm <= currCap) { numTerms -= 1LL << d; matrix b = { {len, 1, 0}, {0, 1, diff%m}, {0, 0, 1} }; curr = mult(pow(b, 1LL << d, m), curr, m); start += (1LL << d) * diff; } } currCap = 10 * currCap + 9; } cout << curr[0][0] << "\n"; } void solve() { ll a, b, n, m; cin >> n >> a >> b >> m; solve(a, b, n, m); } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); solve(); /* int t; cin >> t; for(int i = 1; i <= t; i++) { cout << "Case #" << i << ": "; solve(); } */ }
#include<bits/stdc++.h> typedef long long ll; typedef unsigned long long ull; using namespace std; #define ll __int128 ll P,L,A,B; struct Mat{ ll a[3][3]; Mat(){memset(a,0,sizeof a);} ll* operator [] (int x){return a[x];} const ll* operator [] (int x)const{return a[x];} Mat operator * (const Mat &rhs) const { Mat ret; for(int i=0;i<3;i++) for(int j=0;j<3;j++) for(int k=0;k<3;k++) (ret[i][j]+=a[i][k]*rhs[k][j]%P)%=P; return ret; } }; ll ksm(ll a,ll b) { ll ret=1; for(;b;b>>=1,(a*=a)%=P) if(b&1) (ret*=a)%=P; return ret%P; } Mat ksm(Mat a,ll b) { Mat ret; ret[0][0]=ret[1][1]=ret[2][2]=1; for(;b;b>>=1,a=a*a) if(b&1) ret=ret*a; return ret; } ll Calc(__int128 fir,__int128 num,ll len) { if(num<=0) return 0; Mat trans; trans[0][0]=ksm(10,len+1); trans[1][0]=trans[1][1]=1; trans[2][0]=trans[2][1]=B%P;trans[2][2]=1; Mat B; B[0][0]=B[0][1]=fir%P;B[0][2]=1; return (B*ksm(trans,num-1))[0][0]; } __int128 get(int b) //10^b { __int128 ret=1; while(b--) ret*=10; return ret; } __int128 Ceil(__int128 a,__int128 b) { return (a+b-1)/b; } __int128 Floor(__int128 a,__int128 b) { return a/b; } int main() { long long _L,_A,_B,_P; cin>>_L>>_A>>_B>>_P; L=_L;A=_A;B=_B;P=_P; ll Ans=0; __int128 lst=A+((__int128)B)*(L-1); for(int i=0;i<=36;i++) { if(get(i)>lst) continue; __int128 downlim=get(i),uplim=min(get(i+1)-1,lst); if(uplim<A) continue; if(downlim>lst) continue; __int128 First=A+Ceil(downlim-A,B)*B; if(A>downlim&&A<=uplim) First=A; if(First>lst) continue; if(downlim>uplim) continue; if(uplim<First) continue; Ans=(Ans*ksm(10,(__int128)(i+1)*(Floor(uplim-First,B)+1))%P+Calc(First%P,Floor(uplim-First,B)+1,i))%P; } printf("%lld\n",(long long)(Ans%P)); }
#include <bits/stdc++.h> using namespace std; #define ff first #define ss second #define mp(a,b) make_pair(a,b) #define pb(a) push_back(a) #define boost ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0) #define check(x) cout << #x << " : " << (x) << endl #define all(v) v.begin(),v.end() #define allr(v) v.rbegin(),v.rend() //#define endl '\n' typedef long long ll; typedef unsigned long long ull; typedef vector< ll > edge; typedef pair< ll , ll > mypair; typedef priority_queue <ll> max_heap; typedef priority_queue <ll, vector<ll>, greater<ll> > min_heap; ll mod=1e9+7; const ll inf=1e15+10; const ll N=3e6; struct matrix { vector<vector<ll> > mat; void resize(ll a,ll b, ll initial) { mat.resize(a,vector<ll> (b,initial)); } void identity()// first resize with initial = 0 { for(ll i=0;i<(ll)mat.size();i++) mat[i][i]=1; } ll get_rows() { return mat.size(); } ll get_cols() { return mat[0].size(); } matrix operator + ( matrix & b) const { matrix temp; ll ro,co; ro=b.get_rows(); co=b.get_cols(); temp.resize(ro,co,0); for(ll i=0;i<ro;i++) { for(ll j=0;j<co;j++) { temp.mat[i][j]=mat[i][j]+b.mat[i][j]; temp.mat[i][j]%=mod; } } return temp; } matrix operator * ( matrix & b) const { matrix temp; ll ro,co; ro=mat.size(); co=b.get_cols(); ll mi=b.get_rows(); temp.resize(ro,co,0); for(ll i=0;i<ro;i++) { for(ll j=0;j<co;j++) { for(ll k=0;k<mi;k++) { //temp.mat[i][j]+=mat[i][k]*b.mat[k][j]; temp.mat[i][j]+=((mat[i][k]%mod) * (b.mat[k][j]%mod)); temp.mat[i][j]%=mod; } } } return temp; } void print() { for(auto &i:mat) { for(auto &j:i) cout<<j<<" "; cout<<endl; } } }; matrix power(matrix a,ll b) { matrix ans; ans.resize(a.get_rows(),a.get_cols(),0); ans.identity(); while(b) { if(b & (ll)1) { ans=ans*a; } a=a*a; b>>=1; } return ans; } int main() { boost; ll l,a,b,m; cin>>l>>a>>b>>m; mod=m; ll lo,hi; matrix ans; ans.resize(1,3,0); ans.mat[0][0]=a%mod; ans.mat[0][1]=(a+b)%mod; ans.mat[0][2]=1; ll term =1,d=10; while(term<l) { lo=max((ll)0,((d/10-1)-a)/b); hi=min(l-1,max((d-1-a)/b,(ll)0)); term+=hi-lo; ll now=hi-lo; matrix temp; temp.resize(3,3,0); temp.mat[0][0]=d%mod; temp.mat[1][0]=1; temp.mat[1][1]=1; temp.mat[2][1]=b%mod; temp.mat[2][2]=1; temp=power(temp,now); ans=ans*temp; d*=10; //check(term);check(hi);check(lo); } cout<<ans.mat[0][0]; return 0; }
#include <bits/stdc++.h> using namespace std; #define rep(i,n) for(int i=0;i<(n);i++) #define all(a) (a).begin(),(a).end() #define ll long long ll modp(ll a,ll b,ll m){ if(b==0) return 1; if(b%2) return modp(a,b-1,m)*a%m; return modp(a,b/2,m)*modp(a,b/2,m)%m; } ll npow(ll a,ll b){ if(b==0) return 1; if(b%2) return npow(a,b-1)*a; return npow(a,b/2)*npow(a,b/2); } int main(){ ll L,A,B,M; cin>>L>>A>>B>>M; ll X[18]={}; ll nine=0,sum=0; ll D[3]; D[0]=0; D[1]=A%M; D[2]=1; ll AA=A; int size=0; while(AA){ AA/=10; size++; } rep(i,18){ nine=nine*10+9; if(i+1>=size){ ll Y=(nine-A)/B+(i+1>=size); ll tmp=min(L,Y); X[i]=max(0LL,tmp-sum); sum=tmp; } } rep(i,18){ ll P[3][3][70]={}; ll Q[3][3]={}; rep(j,3) rep(k,3) P[j][k][0]=(j==k); rep(j,3) rep(k,3) Q[j][k]=(j==k); P[0][0][1]=modp(10,i+1,M); P[1][0][1]=1; P[1][1][1]=1; P[2][1][1]=B%M; P[2][2][1]=1; rep(j,65){ if(j>1) rep(k,3) rep(l,3){ P[k][l][j]=(P[k][l][j]+P[k][0][j-1]*P[0][l][j-1])%M; P[k][l][j]=(P[k][l][j]+P[k][1][j-1]*P[1][l][j-1])%M; P[k][l][j]=(P[k][l][j]+P[k][2][j-1]*P[2][l][j-1])%M; } } rep(j,64){ ll QQ[3][3]; if(X[i]&npow(2,j)){ rep(k,3) rep(l,3) QQ[k][l]=Q[k][l]; rep(k,3) rep(l,3){ Q[k][l]=(QQ[k][0]*P[0][l][j+1])%M; Q[k][l]=(Q[k][l]+QQ[k][1]*P[1][l][j+1])%M; Q[k][l]=(Q[k][l]+QQ[k][2]*P[2][l][j+1])%M; } } } ll DD[3]; rep(j,3) DD[j]=D[j]; rep(j,3){ D[j]=(DD[0]*Q[0][j])%M; D[j]=(D[j]+DD[1]*Q[1][j])%M; D[j]=(D[j]+DD[2]*Q[2][j])%M; } } cout<<D[0]<<endl; }
#include <iostream> using namespace std; typedef long long ll; int fp(int a, ll x, int m) { if (x == 0) { return 1; } if (x % 2 == 1) { return 1ll * a * fp(a, x - 1, m) % m; } int t = fp(a, x / 2, m); return 1ll * t * t % m; } int dc1(int a, ll x, int m) { if (x == 0) { return 0; } if (x % 2 == 1) { return (dc1(a, x - 1, m) + fp(a, x - 1, m)) % m; } int t = dc1(a, x / 2, m); return (t + 1ll * fp(a, x / 2, m) * t) % m; } int dc2(int a, ll x, int m) { if (x == 0) { return 0; } if (x % 2 == 1) { return (dc2(a, x - 1, m) + (x - 1) % m * fp(a, x - 1, m)) % m; } int t = dc2(a, x / 2, m); int t2 = (t + x / 2 % m * dc1(a, x / 2, m)) % m; t2 = 1ll * t2 * fp(a, x / 2, m) % m; return (t + t2) % m; } int main() { ll l, a, b; int m; cin >> l >> a >> b >> m; ll last = a + (l - 1) * b; int pow10 = 1; ll p = (ll)1e9 * (ll)1e9; int ans = 0; for (int i = 18; i >= 0; i--) { if (last >= p) { ll first = p / b * b + a % b; if (first < p) { first += b; } if (first < a) { first = a; } int tens = fp(10, i + 1, m); ll cnt = (last - first) / b + 1; int cur = last % m * dc1(tens, cnt, m) % m; cur = ((cur - b % m * dc2(tens, cnt, m)) % m + m) % m; cur = 1ll * cur * pow10 % m; ans = (ans + cur) % m; pow10 = 1ll * pow10 * fp(tens, cnt, m) % m; last = first - b; if (last < a) { break; } } p /= 10; } cout << ans << endl; return 0; }
#include<iostream> using namespace std; typedef unsigned long long ll; ll L,A,B,M; ll ten; struct mll { long long x; mll(long long x):x(x%M){} mll& operator+=(const mll a) { (x+=a.x) %= M; return *this; } mll& operator-=(const mll a) { (x+=M-a.x) %= M; return *this; } mll& operator*=(const mll a) { (x*=a.x) %= M; return *this; } mll& operator/=(const mll a) { (x/=a.x) %= M; return *this; } mll& operator%=(const mll a) { (x%=a.x) %= M; return *this; } mll operator+(const mll a) { mll res(*this); return res+=a; } mll operator-(const mll a) { mll res(*this); return res-=a; } mll operator*(const mll a) { mll res(*this); return res*=a; } mll operator/(const mll a) { mll res(*this); return res/=a; } mll operator%(const mll a) { mll res(*this); return res%=a; } }; mll pow_(ll a, ll b) { if(b == 0) return mll(1); if(b%2 == 1) { return pow_(a,b-1)*mll(a); } else { mll c = pow_(a,b/2); return c*c; } } mll f(ll n) { if(n==0) return mll(0); if(n%2) { return f(n-1) + pow_(ten, n-1); } else { return f(n/2)*(pow_(ten, n/2) + mll(1)); } } mll g(ll n) { if(n==0) return mll(0); if(n%2) { return g(n-1)*mll(ten) + mll(n-1); } else { return g(n/2)*(pow_(ten, n/2)+mll(1)) + f(n/2)*mll(n/2); } } int main() { cin>>L>>A>>B>>M; ll last = A+B*(L-1); mll ans = 0; ten = 1; for(int k=1;k<=18;k++) { ll l = ten, r = ten*10-1; if(last < l || A > r) { ten*=10; continue; } ll a,curlast,n; if(A>=l) a = A; else { a = (l-A+B-1)/B*B+A; } if(a>r) { ten*=10; continue; } if(last <= r) curlast = last; else { curlast = (r-a)/B*B+a; } n = (curlast-a)/B+1; ten*=10; ans*=pow_(ten, n); ans+=mll(a)*f(n) + mll(B)*g(n); } cout<<ans.x; }
#include <bits/stdc++.h> #define dbug(x) cout<<#x<<"="<<x<<endl using namespace std; template <typename T> void read(T &t) { t=0; char ch=getchar(); int f=1; while ('0'>ch||ch>'9') { if (ch=='-') f=-1; ch=getchar(); } do {(t*=10)+=ch-'0';ch=getchar();} while ('0'<=ch&&ch<='9'); t*=f; } typedef long long ll; ll a,b,L,mod,mi[100],tmp,lst,k; ll cnt[20],sum[20]; ll s1[100],s2[100]; ll ans; int main() { //freopen("1.txt","r",stdin); read(L); read(a); read(b); read(mod); ll l,r,res,mid,x,y,t1,t2; tmp=1; lst=-1; for (int i=1;i<=18;i++) { l=lst,r=L-1; tmp*=10; res=lst-1; while (l<=r) { mid=(l+r)/2; if (a+mid*b<tmp) res=mid,l=mid+1; else r=mid-1; } k=res-lst; if (k<0) continue; lst=res; mi[0]=tmp%mod; s1[0]=1; s2[0]=0; for (int j=1;j<=62;j++) { mi[j]=mi[j-1]*mi[j-1]%mod; s1[j]=(mi[j-1]+1)*s1[j-1]%mod; s2[j]=(mi[j-1]+1)*s2[j-1]%mod+(1LL<<(j-1))%mod*s1[j-1]%mod*mi[j-1]%mod; s2[j]%=mod; } cnt[i]=1; x=0,y=0; t1=1,t2=0; for (int j=62;j>=0;j--) if (k&(1LL<<j)) { x+=s1[j]*t1%mod; x%=mod; y+=(s2[j]+s1[j]*t2%mod)*t1%mod; y%=mod; t1=t1*mi[j]%mod; t2=(t2+(1LL<<j))%mod; cnt[i]=cnt[i]*mi[j]%mod; } sum[i]=(a+b*res)%mod*x%mod-b%mod*y%mod; sum[i]=(sum[i]%mod+mod)%mod; } tmp=1; for (int i=18;i>=1;i--) { ans+=sum[i]*tmp%mod; ans%=mod; tmp=tmp*cnt[i]%mod; } printf("%lld\n",ans); return 0; }
#include <iostream> #include <string> #include <vector> #include <deque> #include <queue> #include <algorithm> #include <set> #include <map> #define vv(a, b, c, d) vector<vector<d> >(a, vector<d>(b, c)) #define vvi std::vector<std::vector<int> > #define vvl std::vector<std::vector<ll> > #define MODs 1000000007; typedef long long int ll; using namespace std; vvl dot(vvl a, vvl b, ll M){ vvl c = vv(a.size(), b[0].size(), 0, ll); for(int i=0;i<a.size();i++){ for(int j=0;j<b[0].size();j++){ for(int k=0;k<b.size();k++){ c[i][j] = (c[i][j] + (a[i][k]*b[k][j])%M)%M; } } } return c; } int main(int argc, char const *argv[]) { ll L, A, B, M; cin >> L >> A >> B >> M; vector<ll> keta(19, 0); ll now = 1, wa=0; for(int i=0;i<18;i++){ now *= 10; if(A >= now) keta[i+1]=0; else{ keta[i+1] = (now-1 - A)/B + 1; keta[i+1]-=wa; } if(i==17) keta[i+1] = L - wa; if(wa + keta[i+1] <= L) wa += keta[i+1]; else keta[i+1] = L - wa, wa = L; } now = 1; vvl ans = vv(1, 3, 0, ll); ans[0][0] = 0, ans[0][1] = A%M, ans[0][2] = 1; for(ll i=1;i<19;i++) { now *= 10; vvl c = vv(3, 3, 0, ll); c[0][0] = now%M, c[1][0] = 1, c[1][1] = 1, c[2][1] = B%M, c[2][2]=1; while(keta[i]>0){ if(keta[i]%2==1) ans = dot(ans, c, M); c = dot(c, c, M); keta[i]/=2; } } std::cout << ans[0][0] << '\n'; return 0; }
// luogu-judger-enable-o2 #include<bits/stdc++.h> using namespace std; #define ll long long const int n=3; struct mat{ ll a[n][n]; }; ll mod; mat operator*(mat a,mat b) { mat c; for(int i=0;i<n;i++) for(int j=0;j<n;j++) { c.a[i][j]=0; for(int k=0;k<n;k++) c.a[i][j]=(c.a[i][j]+a.a[i][k]%mod*(b.a[k][j])%mod)%mod; } return c; } mat qpow(mat x,ll y) { mat res;for(int i=0;i<n;i++) for(int j=0;j<n;j++) res.a[i][j]=(i==j); while(y) { if(y&1) res=res*x; x=x*x;y=y/2; } return res; } ll A,B,L;ll C; ll above(ll lim) { ll l=0,r=L;ll res=0; while(l<=r) { ll mid=(l+r)/2; if(mid*B+A>=lim) r=mid-1,res=mid*B+A; else l=mid+1; } return res; } ll qpow(ll x,ll y) { x%=mod; ll res=1; while(y) { if(y&1) res=res*x%mod; x=x*x%mod;y=y/2; } return res; } ll length(ll x) { ll t=0; while(x) x/=10,t++; return t; } ll solution() { ll l=1,r=10;ll k=10;mat res; for(int i=0;i<n;i++) for(int j=0;j<n;j++) res.a[i][j]=0; res.a[0][0]=A%mod,res.a[0][1]=0,res.a[0][2]=1;int flg=10000000; ll ek=0; while(1) { ll s=above(l),e=above(r)-B;if(!s) break; while(e+B<=C and length(e+B)==length(l)) e+=B;//cout<<l<<" "<<e<<"\n"; if(e>C) e=C; ll tot=(e-s)/B+1; if(s<=e) { mat o;for(int i=0;i<n;i++) for(int j=0;j<n;j++) o.a[i][j]=0; o.a[0][0]=o.a[0][1]=o.a[2][2]=1; o.a[1][1]=k%mod;o.a[2][0]=B%mod; res=res*qpow(o,tot);ek+=tot; } flg--;if(!flg) break; if(l>4e17) break; l=l*10; if(r>2e17 or r*10>C) r=C,flg=1; else r=r*10; k=k*10%mod; } assert(ek==L+1); return res.a[0][1]; } int main() { cin>>L>>A>>B>>mod;L--; C=A+B*L; cout<<solution(); return 0; }
#include<bits/stdc++.h> using namespace std; typedef long long ll; ll L,a,b,mod; struct Matric { ll a[3][3]; Matric(){memset(a,0,sizeof(a));} Matric operator*(const Matric&o)const { Matric ans; for(int i=0;i<3;i++) for(int j=0;j<3;j++) for(int k=0;k<3;k++) ans.a[i][j]=(ans.a[i][j]+a[i][k]*o.a[k][j]%mod)%mod; return ans; } }; Matric Mqpow(Matric a,ll n) { Matric ans; ans.a[0][0]=ans.a[1][1]=ans.a[2][2]=1; while(n) { if(n&1) ans=ans*a; a=a*a; n>>=1; } return ans; } ll qpow(ll a,ll n) { ll ans=1; while(n) { if(n&1) ans=ans*a%mod; a=a*a%mod; n>>=1; } return ans; } int getlen(ll x) { int ans=0; while(x) { x/=10; ans++; } return ans; } ll getpos(int x) { ll l=1,r=L,ans=1; while(l<=r) { ll m=l+r>>1; if(getlen(a+(m-1)*b)<=x) ans=m,l=m+1; else r=m-1; } return ans; } /* si=s(i-1)*qpow(10,i)+qi+B; gi=g(i-1)+B; |10i 1 1| |si-1| |0 1 1| |gi-1| |0 0 1| |B| */ int main() { scanf("%lld%lld%lld%lld",&L,&a,&b,&mod); ll ans=a%mod,res=a%mod,now=1; for(int i=1;i<=18;i++) { ll p=getpos(i); if(p==now) continue; Matric A; A.a[0][0]=qpow(10,i);A.a[0][1]=1;A.a[0][2]=1; A.a[1][0]=0;A.a[1][1]=1;A.a[1][2]=1; A.a[2][0]=0;A.a[2][1]=0;A.a[2][2]=1; A=Mqpow(A,p-now); ans=(A.a[0][0]*ans%mod+res*A.a[0][1]%mod+b%mod*A.a[0][2]%mod)%mod; res=(res+b*(p-now))%mod; now=p; } printf("%lld\n",ans); }
#include <bits/stdc++.h> using namespace std; using ll = long long; #define rep(i, a, b) for (int i = (a); i < (b); i++) ll l, a, b, mod; template <class T> struct Matrix { vector<vector<T>> A; Matrix(int n, int m) : A(n, vector<T>(m)) {} Matrix(int n) : A(n, vector<T>(n)) {} int size() { return A.size(); } inline vector<T> &operator[](int i) { return A[i]; } }; template <class T> Matrix<T> operator*(Matrix<T> A, Matrix<T> B) { Matrix<T> R(A.size(), B[0].size()); for (int i = 0; i < A.size(); ++i) for (int j = 0; j < B[0].size(); ++j) for (int k = 0; k < B.size(); ++k) R[i][j] = (R[i][j] + (A[i][k] * B[k][j]) % mod) % mod; return R; } template <class T> Matrix<T> power(Matrix<T> X, ll n) { Matrix<T> R(X.size()); for (int i = 0; i < X.size(); i++) R[i][i] = 1; while (n > 0) { if (n & 1) R = R * X; X = X * X; n >>= 1; } return R; } template <class T> void print(Matrix<T> A) { for (int i = 0; i < A.size(); ++i) for (int j = 0; j < A[0].size(); ++j) cout << A[i][j] << ((j != A[0].size() - 1) ? ' ' : '\n'); } int main() { cin.tie(0); ios::sync_with_stdio(false); cin >> l >> a >> b >> mod; Matrix<ll> z(1, 3); z[0][1] = a % mod; z[0][2] = 1; vector<ll> c(19); ll mn = 1, mx = 10; rep(i, 1, 19) { c[i] = min(l, (mx - a + b - 1) / b) - max(0ll, (mn - a + b - 1) / b); mn *= 10ll; mx *= 10ll; } mx = 1; rep(i, 1, 19) { mx *= 10ll; if (c[i] > 0) { Matrix<ll> p(3); p[1][0] = p[1][1] = p[2][2] = 1; p[0][0] = mx % mod; p[2][1] = b % mod; z = z * power(p, c[i]); } } cout << z[0][0] << endl; return 0; }
#include<bits/stdc++.h> #define ll long long #define pii_ pair<int,int> #define mp_ make_pair #define pb push_back #define fi first #define se second #define rep(i,a,b) for(int i=(a);i<=(b);i++) #define per(i,a,b) for(int i=(a);i>=(b);i--) #define show1(a) cout<<#a<<" = "<<a<<endl #define show2(a,b) cout<<#a<<" = "<<a<<"; "<<#b<<" = "<<b<<endl using namespace std; const ll INF = 1LL<<60; const int inf = 1<<30; const int maxn = 2e5+5; inline void fastio() {ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);} ll qpow(ll a,ll b,ll M) {a%=M;ll s=1;while(b){if(b&1)s=(s*a)%M;a=(a*a)%M;b>>=1;}return s; } ll qmul(ll a,ll b,ll M) {a%=M;ll s=0;while(b){if(b&1)s=(s+a)%M;a=(a+a)%M;b>>=1;}return s; } ll M,pt[20]; struct Matrix { ll mat[3][3]; Matrix() {memset(mat,0,sizeof(mat));} Matrix operator * (Matrix b) { Matrix res; rep(i,0,2) rep(j,0,2) rep(k,0,2) res.mat[i][j] = (res.mat[i][j] + mat[i][k]*b.mat[k][j]%M)%M; return res; } Matrix operator ^ (ll b) { Matrix res,A=*this; rep(i,0,2) res.mat[i][i] = 1; while(b){ if(b&1) res = res * A; A = A*A; b>>=1; } return res; } }; int main() { fastio(); ll n,a,b; cin>>n>>a>>b>>M; ll ans = 0; pt[0] = 1; rep(i,1,18) pt[i] = pt[i-1]*10; ll L = a,R = a+(n-1)*b; rep(i,1,18){ if(L < pt[i]){ ll e = (pt[i]-L-1)/b*b+L; if(e>R) e = R; ll t = (e-L)/b + 1; Matrix A; A.mat[0][0] = pt[i]%M; A.mat[0][1] = A.mat[1][1] = A.mat[2][2] = 1; A.mat[1][2] = b%M; A = A^t; ans = (ans*A.mat[0][0]%M + L%M*A.mat[0][1]%M + A.mat[0][2]) %M; if(e==R)break; L = e + b; } } cout<<ans<<endl; return 0; }
#include <bits/stdc++.h> using namespace std; using ll = long long; int M; using mat = vector<vector<ll>>; // multiplication, A[0].size = B.size が必要 mat mul(mat &A, mat &B) { mat C(A.size(), vector<ll>(B[0].size(), 0)); for (int i = 0; i < A.size(); ++i) { for (int k = 0; k < B.size(); ++k) { for (int j = 0; j < B[0].size(); ++j) { C[i][j] = (C[i][j] + A[i][k] * B[k][j]) % M; } } } return C; } // 正方行列の累乗 mat pow(mat A, ll n){ mat B(A.size(), vector<ll>(A.size(), 0)); for (int i = 0; i < A.size(); ++i) { B[i][i] = 1; } while(n > 0){ if(n & 1) B = mul(B, A); A = mul(A, A); n >>= 1; } return B; } ll modPow(ll x, ll n) { ll res = 1; while(n > 0){ if(n & 1) res = res * x % M; x = x * x % M; n >>= 1; } return res; } int main() { ll L, A, B; cin >> L >> A >> B >> M; ll C = A + B * (L-1); // 桁数ごとに初項と項数を保存 vector<ll>first(19); vector<ll>num(19, 0); vector<ll>last(19); last[0] = A % B - B; ll pow_ten = 1; for (int i = 1; i < 19; ++i) { first[i] = last[i-1] + B; pow_ten *= 10; last[i] = ((pow_ten-1-A) / B) * B + A; first[i] = max(first[i], A); ll end = min(last[i], C); if(first[i] <= end) { num[i] = (end - first[i]) / B + 1; } } ll ans = 0; for (int i = 1; i < 19; ++i) { mat X = {{ans, first[i]%M, 1}}; mat P(3, vector<ll>(3)); P[0] = {modPow(10, i), 0, 0}; P[1] = {1, 1, 0}; P[2] = {0, B%M, 1}; auto Pn = pow(P, num[i]); X = mul(X, Pn); ans = X[0][0]; } cout << ans; return 0; }
#include <bits/stdc++.h> #define sz(c) int(c.size()) #define rep(i,a,b) for (int i=a; i<(b); ++i) #define per(i,a,b) for (int i=(b)-1; i>=(a); --i) using namespace std; using ll = long long; using matrix = int[3][3]; int M; inline int madd(int x,int y) { if (x+y<M) return x+y; else return x+y-M; } inline int msub(int x,int y) { if (x-y>=0) return x-y; else return x-y+M; } inline int mmul(int x,int y) { return int(ll(x)*y % M); } void matmul(matrix &res, const matrix &A, const matrix &B, int n, int p, int m) { // res[n x m] = A[n x p] * B[p x m] static matrix tmp; rep(i,0,n) rep(j,0,m) tmp[i][j]=0; rep(i,0,n) rep(j,0,m) rep(k,0,p) { tmp[i][j]=madd(tmp[i][j], mmul(A[i][k],B[k][j])); } rep(i,0,n) rep(j,0,m) res[i][j]=tmp[i][j]; } void matpow(ll pow, matrix &res, const matrix &A, int n, int m) { // res[n x m] = res[n x m] * (A[m x m]^pow) static matrix tmp; rep(i,0,m) rep(j,0,m) tmp[i][j]=A[i][j]; while (pow>0) { if (pow%2) matmul(res,res,tmp,n,m,m); matmul(tmp,tmp,tmp,m,m,m); pow/=2; } } int len(ll x) { assert(x>0); int res=0; while (x>0) { x/=10; res++; } return res; } ll find_len(ll L,ll A,ll B) { int z=len(A); ll l=0,r=L; while (l<r) { ll m=l+(r-l)/2; if (z==len(A+B*m)) l=m+1; else r=m; } return l; } int main() { cin.tie(0); ios_base::sync_with_stdio(0); cout<<fixed<<setprecision(10); ll L,A,B; cin>>L>>A>>B>>M; int sum=0; while (L>0) { ll k=find_len(L,A,B); int p=1; rep(i,0,len(A)) p=mmul(p,10); matrix r={{sum,int(A%M),1}}; matrix X={{p,0,0}, {1,1,0}, {0,int(B%M),1}}; matpow(k,r,X,1,3); sum=r[0][0]; L-=k; A+=B*k; } cout<<sum<<"\n"; }
#include <bits/stdc++.h> #define rep(i,n) for (int i = 0; i < (n); ++i) using namespace std; using ll = long long; using P = pair<int,int>; int mod; struct mint { ll x; mint(ll x=0):x( (x%mod + mod) % mod ) {} mint operator-() const { return mint(-x); } mint& operator+=(const mint a) { if ( (x += a.x) >= mod ) x -= mod; return *this; } mint& operator-=(const mint a) { if ( ( x += mod - a.x) >= mod ) x -= mod; return *this; } mint& operator*=(const mint a) { ( x *= a.x) %= mod; return *this; } mint operator+(const mint a) const { return mint(*this) += a; } mint operator-(const mint a) const { return mint(*this) -= a; } mint operator*(const mint a) const { return mint(*this) *= a; } mint pow(ll t) const { if (!t) return 1; mint a = pow(t >> 1); a *= a; if (t&1) a *= *this; return a; } mint inv() const { return pow(mod - 2); } mint& operator/=(const mint a) { return *this *= a.inv(); } mint operator/(const mint a) { return mint(*this) /= a; } }; istream& operator>>(istream& is, mint& a) { return is >> a.x; } ostream& operator<<(ostream& os, const mint& a) { return os << a.x; } ll b, ten; mint f(ll l) { if (l == 0) return 0; if (l%2 == 1) { ll pl = l-1; mint x = f(pl); return x*ten + 1; } else { ll pl = l/2; mint x = f(pl); return x*mint(ten).pow(pl) + x; } } mint g(ll l) { if (l == 0) return 0; if (l%2 == 1) { ll pl = l-1; mint x = g(pl); return x*ten + mint(b)*pl; } else { ll pl = l/2; mint x = g(pl); return x*mint(ten).pow(pl) + x + mint(b)*pl*f(pl); } } int main() { ll L, a; cin >> L >> a >> b >> mod; ten = 10; ll last = a + b * (L - 1); mint ans = 0; for (int i = 1; i <= 18; ++i, ten *= 10) { ll l = ten/10, r = ten - 1; if (a > r) continue; if (last < l) continue; ll na = 0, nl = 0, nlast = 0; { if (a >= l) na = a; else { na = ( l-a + b-1 )/b * b + a; } } { if (last <= r) nlast = last; else { nlast = (r - a)/b * b + a; } nl = (nlast - na)/b + 1; } ans *= mint(ten).pow(nl); ans += f(nl)*na; ans += g(nl); } cout << ans << endl; return 0; }
#include<bits/stdc++.h> #define ll long long #define fornum(A,B,C) for(A=B;A<C;A++) #define mp make_pair #define pii pair<int,int> #define pll pair<ll,ll> using namespace std; ///////////////////////////////////////////////////// ll L,A,B,M; ll i,j,k; ll dmul[3][3]; ll mul[3][3]; ll ans[3][3]; void calc(ll a){ if(a==0) return; ll i, j,k,l; if(a&1){ fornum(i,0,3){ fornum(j,0,3){ dmul[i][j] = ans[i][j]; } } fornum(i,0,3){ fornum(j,0,3){ ans[i][j]=0; fornum(k,0,3){ ans[i][j] = (ans[i][j] + dmul[i][k] * mul[k][j])%M; } } } } fornum(i,0,3){ fornum(j,0,3){ dmul[i][j] = mul[i][j]; } } fornum(i,0,3){ fornum(j,0,3){ mul[i][j]=0; fornum(k,0,3){ mul[i][j] = (mul[i][j] + dmul[i][k] * dmul[k][j])%M; } } } calc(a / 2); } int main(){ scanf("%lld%lld%lld%lld", &L, &A, &B, &M); //A %= M; //B %= M; ans[0][0] = 1; ans[1][1] = 1; ans[2][2] = 1; ll a = 0; ll b = 10; fornum(i,0,18){ ll l = 0; ll r = L; while(l<r){ ll c = (r + l) / 2; ll C = A + B * c; if(C<b){ l = c + 1; }else{ r = c; } } //printf("%lld,%lld\n", a, r); fornum(j,0,3){ fornum(k,0,3){ mul[j][k] = 0; } } mul[0][0] = b%M; mul[1][0] = 1; mul[1][1] = 1; mul[2][1] = B%M; mul[2][2] = 1; calc(r - a); a = r; b *= 10; } /* fornum(i,0,3){ fornum(j,0,3){ printf("%lld ", ans[i][j]); } printf("\n"); }*/ printf("%lld", (A%M * ans[1][0] + ans[2][0]) % M); return 0; }
#include <iostream> #include <vector> using namespace std; typedef long long ll; typedef vector<ll> vec; typedef vector<vec> mat; ll L,A,B,M; mat mult(mat &A,mat &B){ mat C(A.size(),vec(B[0].size())); for(int i=0;i<A.size();i++){ for(int k=0;k<B.size();k++){ for(int j=0;j<B[0].size();j++){ (C[i][j] += A[i][k]*B[k][j]%M)%=M; } } } return C; } mat pow(mat A, ll n){ if(n==1) return A; else if(n%2==0){ mat B = pow(A,n/2); return mult(B,B); }else{ mat B = pow(A,n-1); return mult(A,B); } } ll cnt[20] = {}; ll cnt2[20] = {}; ll p[19] = {1}; int main(){ cin >> L >> A >> B >> M; for(int i=1;i<=18;i++) p[i] = 10*p[i-1]; for(int i=1;i<=18;i++){ if(p[i]-1<A) continue; if(A+(L-1)*B<p[i-1]) continue; cnt[i] = (min(p[i]-1,A+(L-1)*B)-A)/B+1; if(i>1 && p[i-1]-1>A) cnt[i] -= max((p[i-1]-1-A)/B+1,0LL); } ll ans = 0; mat res(3,vec(3,0)); res[0][0] = res[1][1] = res[2][2] = 1; for(int i=1;i<=18;i++){ if(cnt[i]==0) continue; mat A(3,vec(3,0)); A[0][0] = p[i]%M; A[0][1] = A[1][1] = A[2][2] = 1; A[1][2] = B; mat a = pow(A,cnt[i]); res = mult(a,res); } cout << (res[0][2]+A%M*res[0][1]%M)%M << endl; }
#include<bits/stdc++.h> #define debug(x) cerr << #x << ": " << x << '\n' #define debugArray(x,n) for(long long hoge = 0; (hoge) < (n); ++ (hoge)) cerr << #x << "[" << hoge << "]: " << x[hoge] << '\n' using namespace std; typedef long long ll; typedef unsigned long long ull; typedef vector<ll> vll; const ll INF = INT_MAX; const ll MOD = 1e9+7; ll mod=1e9+7; struct Matrix { vector<vector<long long> > val; Matrix(int n, int m, long long x = 0) : val(n, vector<long long>(m, x)) {} void init(int n, int m, long long x = 0) {val.assign(n, vector<long long>(m, x));} size_t size() const {return val.size();} inline vector<long long>& operator [] (int i) {return val[i];} }; // O( n ) Matrix identity(int n) { Matrix A(n, n); for (int i = 0; i < n; ++i) A[i][i] = 1; return A; } // O( n^3 ) Matrix mul(Matrix A, Matrix B) { Matrix C(A.size(), B[0].size()); for (int i = 0; i < (ll)C.size(); ++i) for (int j = 0; j < (ll)C[i].size(); ++j) for (int k = 0; k < (ll)A[i].size(); ++k) C[i][j] = (C[i][j] + A[i][k] * B[k][j]%mod)%mod; return C; } // O( n^3 log e ) Matrix pow(Matrix A, ll e) { return e == 0 ? identity(A.size()) : e % 2 == 0 ? pow(mul(A, A), e/2) : mul(A, pow(A, e-1)); } ostream &operator<<(ostream &os, Matrix &v) { os << "["; for (int i = 0; i < (ll)v.size(); i++){ if (i > 0) os << endl << " "; os << "["; for (int j = 0; j < (ll)v[i].size(); os << v[i][j++]) if (j > 0) os << " "; os << "]"; } os << "]"; return os; } signed main(){ cin.tie(0); ios::sync_with_stdio(false); ll L,A,B,M;cin>>L>>A>>B>>M; mod=M; ll X=0,s=A%mod; ll p10=1; for(ll d=1;d<=18&&L>0;d++){ //debug(d); ll C=0; if(p10*10>A)C += (p10*10-1-A)/B+1; if(p10>A)C -= (p10-1-A)/B+1; //debug(C); Matrix Mat(3,3); Mat[0][0]=p10*10%mod; Mat[0][1]=1; Mat[1][1]=1; Mat[1][2]=B%mod; Mat[2][2]=1; Matrix D=pow(Mat,min(L,C)); //cerr<<D<<endl; ll tmp=X*D[0][0]%mod+s*D[0][1]%mod+D[0][2]; s=(X*D[1][0]%mod+s*D[1][1]%mod+D[1][2])%mod; X=tmp%mod; L-=C; //debug(X); //debug(s); p10*=10; } cout<<X<<endl; return 0; }
#include <bits/stdc++.h> using namespace std; int m; int mul(long long a, long long b){ return a * b % m; } int pw(long long a, long long b){ a %= m; long long r = 1; for(; b; b >>= 1, a = mul(a, a)) if(b&1) r = mul(r, a); return r; } using mat = vector<vector<long long> >; mat create(int n){ return vector<vector<long long> > (n, vector<long long>(n, 0)); } mat iden(int n){ mat r = create(n); for(int i = 0; i < n; i++) r[i][i] = 1; return r; } mat mul(mat a, mat b){ int n = a.size(); mat r = create(n); for(int i = 0; i < n; i++) for(int j = 0; j < n; j++) for(int k = 0; k < n; k++){ r[i][j] += mul(a[i][k], b[k][j]); if(r[i][j] >= m) r[i][j] -= m; } return r; } int len(long long x){ int sz = 0; while(x) sz++, x /= 10; return sz; } int main(){ long long l, a, b; cin >> l >> a >> b >> m; long long mv = 0, sum = 0; while(l > 0){ long long lo = 1, hi = l - 1, ans = 0; int need = len(a); while(lo <= hi){ long long mid = (lo + hi)>>1; if(len(a + b * mid) == need) ans = mid, lo = mid + 1; else hi = mid - 1; } mat now = create(3), res = iden(3); now[0][0] = pw(10, need); now[1][0] = 1; now[1][1] = 1; now[2][1] = b % m; now[2][2] = 1; long long sz = ans + 1, ind = ans + 1; for(; sz; sz >>= 1, now = mul(now, now)) if(sz&1) res = mul(res, now); sum = mul(sum, res[0][0]) + mul(a % m, res[1][0]) + res[2][0]; sum %= m; a += ind * b; l -= ind; } cout << sum << endl; return 0; }
#include <iostream> #include <algorithm> #include <string> #include <vector> #include <cmath> #include <map> #include <queue> #include <iomanip> #include <set> #define mkp make_pair typedef long long ll; using namespace std; ll L,A,B,M; ll MOD=1000000007; typedef vector<ll> vec;//ll? typedef vector<vec> mat; mat mul(mat &A,mat &B){ mat C(A.size(),vec(B[0].size())); for(int i=0;i<A.size();i++){ for(int k=0;k<B.size();k++){ for(int j=0;j<B[0].size();j++){ C[i][j]=(C[i][j]+A[i][k]*B[k][j]%MOD)%MOD; } } } return C; } mat pow(mat A,ll n){ mat B(A.size(),vec(A.size())); for(int i=0;i<A.size();i++){ B[i][i]=1; } while(n>0){ if(n&1) B=mul(B,A); A=mul(A,A); n=(n>>1); } return B; } int digit(ll val){ if(val==0) return 0; else return (1+digit(val/10)); } int main(){ cin>>L>>A>>B>>M; MOD=M; ll ans=0; ll ten[20]={}; ten[0]=1; for(int i=1;i<=18;i++) ten[i]=ten[i-1]*10%MOD; ll start=0; while(start<L){ ll ng=L; ll ok=start; ll nowdigit=digit(A+B*start); while(ng-ok>1){ ll mid=(ng+ok)/2; if(digit(A+B*mid)==nowdigit) ok=mid; else ng=mid; } mat C(3,vec(3)); C[0][0]=ten[nowdigit]; C[0][1]=1; C[0][2]=0; C[1][0]=0; C[1][1]=1; C[1][2]=B%MOD; C[2][0]=0; C[2][1]=0; C[2][2]=1; C=pow(C,(ok-start+1)); mat D(3,vec(1)); D[0][0]=ans; D[1][0]=(A+B*start)%MOD; D[2][0]=1; D=mul(C,D); ans=D[0][0]; ans=(ans+MOD)%MOD; start=ok+1; } cout<<ans<<endl; return 0; }
#include <iostream> using namespace std; typedef long long ll; int main() { ll l, a, b, m; cin >> l >> a >> b >> m; a -= b; ll d[19]; d[0] = 0; ll f[19]; ll t = 0; for(int i = 1; i <= 18; i++){ t = (t + 1) * 10 - 1; d[i] = max(0ll, min(l, (t - a) / b)); f[i] = (a + b * d[i]) % m; } for(int i = 18; i > 0; i--) d[i] = d[i] - d[i - 1]; ll p[19]; p[0] = 1; for(int i = 1; i <= 18; i++) p[i] = p[i - 1] * 10 % m; ll ans = 0; t = 1; for(int i = 18; i > 0; i--){ ll s = f[i]; ll u = p[i]; ll v = b % m; while(d[i]){ if(d[i] % 2){ ans = (ans + s * t % m) % m; t = t * u % m; s = (s + m - v % m) % m; } s = (s + (s + m - v % m) % m * u % m) % m; v = v * (u + 1) % m * 2 % m; u = u * u % m; d[i] /= 2; } } cout << ans << endl; }
#include <bits/stdc++.h> #define loop(n, i) for(int i=0;i<n;i++) #define loop1(n, i) for(int i=1;i<=n;i++) #define rloop(n, i) for(int i=n;i;i++) #define HERE cout << "HERE: " << __LINE__ << endl; #define INSP(v) cout << v << " at " << __LINE__ << endl; using namespace std; using ll = long long; template <class T> using V = vector<T>; using M = V<V<ll>>; const int MSIZE = 3; ll m; void printmat(M a) { loop (MSIZE, i) { loop (MSIZE, j) { cout << a[i][j] << " "; } cout << endl; } } M matmul(M a, M b) { M ret = V<V<ll>>(MSIZE, V<ll>(MSIZE)); loop (MSIZE, i) loop (MSIZE, j) { loop (MSIZE, s) { ret[i][j] += a[i][s] * b[s][j] % m; ret[i][j] %= m; } } return ret; } int main() { ll l, a, b; cin >> l >> a >> b >> m; ll crr = a; ll x = 0, s = a % m; loop1 (18, d) { ll last = 1; loop (d, i) last *= 10; last--; last = min(last, a + b * (l - 1)); if (last < crr) continue; ll c = (last - crr) / b + 1; crr += b * c; ll shift = 1; loop (d, i) shift = (shift * 10) % m; M base = { { shift, 0, 0 }, { 1, 1, 0 }, { 0, b % m, 1 } }; M mat = { { 1, 0, 0 }, { 0, 1, 0 }, { 0, 0, 1 } }; while (c) { if (c % 2) mat = matmul(mat, base); base = matmul(base, base); c /= 2; } ll nx = (x * mat[0][0] + s * mat[1][0] + mat[2][0]) % m; ll ns = (x * mat[0][1] + s * mat[1][1] + mat[2][1]) % m; x = nx, s = ns; } cout << x << endl; return 0; }
#include <bits/stdc++.h> using namespace std; #define INF 1<<30 #define endl '\n' #define maxn 100005 #define FASTIO ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0); typedef long long ll; const double PI = acos(-1.0); #define dbg(x) cerr << #x << " = " << x << endl; #define dbg2(x, y) cerr << #x << " = " << x << ", " << #y << " = " << y << endl; #define dbg3(x, y, z) cerr << #x << " = " << x << ", " << #y << " = " << y << ", " << #z << " = " << z << endl; //const ll mod = 1e9 + 7; const ll M = 18; ll mod; struct Mat { ll m[3][3]; Mat(ll v) { memset(m, 0, sizeof m); for(ll i = 0; i < 3; i++) m[i][i] = v; } Mat operator* (const Mat &a) const { Mat r(0); for(ll i = 0; i < 3; i++) { for(ll j = 0; j < 3; j++) { for(ll k = 0; k < 3; k++) { r.m[i][j] = (r.m[i][j] + m[i][k] * 1ll * a.m[k][j]) % mod; } } } return r; } }; ll modexp(Mat a, ll b, ll s) { Mat r(1); while(b) { if(b & 1) r = r * a; a = a * a; b >>= 1; } return (s * 1ll * r.m[0][1] + r.m[0][2]) % mod; } ll modexp(ll a, ll b) { ll r = 1; while(b) { if(b & 1) r = (r * 1ll * a) % mod; a = (a * 1ll * a) % mod; b >>= 1; } return r; } ll t[M+1]; ll BS(ll n, ll a, ll b, ll lmt) { ll l = -1, r = n; while(l != r) { ll mid = (l + r + 1) >> 1; if(a + mid * b < lmt) l = mid; else r = mid - 1; } return l; } int main() { FASTIO /* //double start_time = clock(); #ifndef ONLINE_JUDGE freopen("in.txt", "r", stdin); freopen("out.txt", "w", stdout); freopen("error.txt", "w", stderr); #endif //*/ ll l, a, b, t1 = 1; ll ans = 0; cin >> l >> a >> b >> mod; t[0] = -1; for(ll i = 1; i <= M; i++) { t1 *= 10; t[i] = BS(l - 1, a, b, t1); ll A = a + (t[i - 1] + 1) * b; ll n = t[i] - t[i - 1]; if(n) { Mat a(1); a.m[0][0] = t1 % mod; a.m[0][1] = 1; a.m[1][2] = b % mod; ll r = modexp(a, n, A % mod); ll x = modexp(t1 % mod, n); ans = (ans * 1ll * x + r) % mod; } } cout << ans << endl; //double end_time = clock(); //prllf( "Time = %lf ms\n", ( (end_time - start_time) / CLOCKS_PER_SEC)*1000); return 0; }
#include<bits/stdc++.h> #define lowbit(a) ((a)&(-(a))) using namespace std; void file(bool opt) { if (opt&&fopen("in.txt", "r")) { freopen("in.txt", "r", stdin); //freopen("out.txt", "w", stdout); } } long long L, A, B; long long mod; long long ans = 0; long long powt[19]; struct mat { int val[3][3]; mat() { memset(val, 0, sizeof val); } void init(int i) { memset(val, 0, sizeof val); val[0][0] = powt[i] % mod, val[1][0] = val[1][1] = val[2][1] = val[2][2] = 1; } }a,res; mat operator*(mat a, mat b) { mat c; for (int i = 0; i<3; i++) for (int j = 0; j<3; j++) for (int k = 0; k<3; k++) c.val[i][j] = (c.val[i][j] + 1ll * a.val[i][k] * b.val[k][j]) % mod; return c; } void poww(long long L,long long R,int d) { long long n = (R - L) / B + 1; for (int i = 0; i < 3; i++) for (int j = 0; j < 3; j++) res.val[i][j] = (i == j); a.init(d); while (n) { if (n & 1)res = res * a; n >>= 1; a = a*a; } ans = (1ll * ans*res.val[0][0]%mod + L % mod*res.val[1][0] % mod + B % mod*res.val[2][0]) % mod; } int main() { cin >> L >> A >> B >> mod; powt[0] = 1; for (int i = 1; i <= 18; i++) powt[i] = powt[i - 1] * 10ll; long long ed = A + B * (L - 1); for (int d = 1; d <= 18; d++) { if (A < powt[d]) { long long R = (powt[d] - 1 - A) / B * B + A; R = min(R, ed); poww(A, R, d); if (R == ed)break; A = R + B; } } cout << ans << endl; return 0; }
#include <bits/stdc++.h> using namespace std; long c[22]; int main() { long L, a, b, M; cin >> L >> a >> b >> M; for (long i = 0, j = 1; i < 18; i++, j *= 10) { long l = -1, r = L; while (l + 1 < r) { long m = (l + r) / 2; if (a + b * m < j) l = m; else r = m; } if (a + b * r < j * 10) c[i] = r; else if (i) c[i] = c[i - 1]; } c[18] = L; long t = 1, S = 0, T = a; for (int e = 0; e < 18; e++) { (t *= 10) %= M; long A[4][3][3] = {}; for (int i = 0; i < 3; i++) A[2][i][i] = 1; A[0][0][1] = A[0][1][1] = A[0][2][2] = 1; A[0][1][2] = b; A[0][0][0] = t; int x = 0, y = 2; auto f = [&](int &z) { for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { A[z ^ 1][i][j] = 0; for (int k = 0; k < 3; k++) (A[z ^ 1][i][j] += A[x][i][k] * A[z][k][j]) %= M; } } z ^= 1; }; for (long k = c[e + 1] - c[e];;) { if (k & 1) f(y); k >>= 1; if (!k) break; f(x); } S = (S*A[y][0][0] + T * A[y][0][1] + A[y][0][2]) % M; (T += A[y][1][2]) %= M; } cout << S << endl; return 0; }
#include <bits/stdc++.h> using namespace std; long long l, a, b, m; long long mat[66][3][3] = {0},now[3][3] = {0}; long long solve(); void setmat(); void calc(long long x); int main(){ cin >> l >> a >> b >> m; cout << solve() << endl; return 0; } long long solve(){ long long ten = 1,bf = 0,nowc = 0; // {{10^d, 0, 0} // {1, 1, 0} // {0, B, 1}} mat[0][1][0] = mat[0][1][1] = mat[0][2][2] = 1; mat[0][2][1] = b % m; for(int i = 0;i < 3;++i)now[i][i] = 1; for(long long i = 0;i < 18;++i){ ten *= 10; mat[0][0][0] = ten % m; setmat(); nowc = max((ten - a - 1) / b + 1, 0LL); nowc = min(l,nowc); swap(bf,nowc); nowc = bf - nowc; for(long long i = 60;i >= 0;--i) if(nowc >= (1LL << i)){ nowc -= 1LL << i; calc(i); } if(bf == l)break; } long long ans = 0; ans = (a % m * now[1][0] % m + now[2][0]) % m; return ans; } void setmat(){ for(int i = 1;i < 62;++i) for(int j = 0;j < 3;++j) for(int k = 0;k < 3;++k) { mat[i][j][k] = 0; for (int n = 0; n < 3; ++n) (mat[i][j][k] += mat[i-1][j][n] * mat[i-1][n][k] % m) %= m; } } void calc(long long x){ long long tmp[3][3] = {0}; for(int i = 0;i < 3;++i) for(int k = 0;k < 3;++k) for(int j = 0;j < 3;++j) (tmp[i][j] += now[i][k] * mat[x][k][j] % m) %= m; for(int i = 0;i < 3;++i) for(int j = 0;j < 3;++j) now[i][j] = tmp[i][j]; }
// // Created by yamunaku on 2019/11/05. // #include <bits/stdc++.h> using namespace std; #define rep(i, n) for(int i = 0; i < (n); i++) #define repl(i, l, r) for(int i = (l); i < (r); i++) #define per(i, n) for(int i = ((n)-1); i >= 0; i--) #define perl(i, l, r) for(int i = ((r)-1); i >= (l); i--) #define all(x) (x).begin(),(x).end() #define MOD9 998244353 #define MOD1 1000000007 #define IINF 1000000000 #define LINF 1000000000000000000 #define SP <<" "<< #define CYES cout<<"Yes"<<endl #define CNO cout<<"No"<<endl #define CFS cin.tie(0);ios::sync_with_stdio(false) #define CST(x) cout<<fixed<<setprecision(x) typedef long long ll; typedef long double ld; typedef vector<int> vi; typedef vector<vector<int>> mti; typedef vector<ll> vl; typedef vector<vector<ll>> mtl; ll b, m; ll modpow(ll x, ll a){ ll ans = 1; while(a > 0){ if(a % 2) ans = ans * x % m; a /= 2; x = x * x % m; } return ans; } void matprod(mtl &ret, mtl &x, mtl &y){ int n = x.size(); mtl ans = mtl(n, vl(n, 0)); rep(i, n){ rep(j, n){ rep(k, n){ ans[i][j] = (ans[i][j] + x[i][k] * y[k][j] % m) % m; } } } ret = ans; } void matpow(mtl &ret, mtl &x, ll a){ int n = x.size(); mtl ans = mtl(n, vl(n, 0)); rep(i, n) ans[i][i] = 1; while(a > 0){ if(a % 2) matprod(ans, ans, x); a /= 2; matprod(x, x, x); } ret = ans; } ll solve(ll n, ll c, ll t){ mtl x = { {1, 0, 0}, {b, 1, 0}, {0, 1, t} }; matpow(x, x, n); return (x[2][0] + x[2][1] * c % m) % m; } int main(){ ll s, a; cin >> s >> a >> b >> m; ll ans = 0; ll now = 0; for(ll t = 10, k = 1; now < s && k <= 18; t *= 10, k++){ if(b * now + a < t){ ll w = max(0ll, min((t - 1 - (b * now + a)) / b + 1, s - now)); rep(i,k){ ans = ans * modpow(10, w) % m; } ans = (ans + solve(w, (b * now + a) % m, t % m)) % m; now += w; } } cout << ans << endl; return 0; }
#include <bits/stdc++.h> using namespace std; #define x first #define y second #define mp make_pair #define pb push_back #define sqr(a) ((a) * (a)) #define sz(a) int(a.size()) #define all(a) a.begin(), a.end() #define forn(i, n) for(int i = 0; i < int(n); i++) #define fore(i, l, r) for(int i = int(l); i < int(r); i++) typedef long long li; typedef long double ld; typedef pair<int, int> pt; template <class A, class B> ostream& operator << (ostream& out, const pair<A, B> &a) { return out << "(" << a.x << ", " << a.y << ")"; } template <class A> ostream& operator << (ostream& out, const vector<A> &v) { out << "["; forn(i, sz(v)) { if(i) out << ", "; out << v[i]; } return out << "]"; } mt19937 rnd(time(NULL)); const int INF = int(1e9); const li INF64 = li(1e18); const ld EPS = 1e-9; const ld PI = acos(-1.0); int MOD; li l, a, b; bool read () { if (scanf("%lld%lld%lld%d", &l, &a, &b, &MOD) != 4) return false; return true; } int add(int a, int b){ a += b; if (a >= MOD) a -= MOD; return a; } int sub(int a, int b){ a -= b; if (a < 0) a += MOD; return a; } int mul(int a, int b){ return a * li(b) % MOD; } struct mat{ int a[3][3]; mat(){ memset(a, 0, sizeof(a)); }; int* operator [](int x){ return a[x]; } }; int cnt0; mat mul(mat a, mat b){ mat c; forn(i, 3) forn(j, 3) forn(k, 3) c[i][j] = add(c[i][j], mul(a[i][k], b[k][j])); return c; } mat binpow(mat a, li b){ mat res; forn(i, 3) res[i][i] = 1; while (b){ if (b & 1) res = mul(res, a); a = mul(a, a); b >>= 1; } return res; } void solve(){ int res = 0; for (li cur = 10; cur <= INF64; cur *= 10){ if (cur <= a) continue; li len = (cur - a + b - 1) / b; len = min(len, l); mat tmp; tmp[0][0] = cur % MOD; tmp[1][0] = 1; tmp[1][1] = 1; tmp[2][1] = b % MOD; tmp[2][2] = 1; tmp = binpow(tmp, len); mat orig; orig[0][0] = res; orig[0][1] = a % MOD; orig[0][2] = 1; orig = mul(orig, tmp); res = orig[0][0]; a += len * b; l -= len; if (l == 0) break; } printf("%d\n", res); } int main() { #ifdef _DEBUG freopen("input.txt", "r", stdin); // freopen("output.txt", "w", stdout); int tt = clock(); #endif cerr.precision(15); cout.precision(15); cerr << fixed; cout << fixed; #ifdef _DEBUG while(read()) { #else if(read()) { #endif solve(); #ifdef _DEBUG cerr << "TIME = " << clock() - tt << endl; tt = clock(); #endif } }
#include <bits/stdc++.h> #include <cmath> using namespace std; #define rep(i, n) for (ll i = 0; i < (n); ++i) #define sz(x) ll(x.size()) typedef long long ll; typedef pair<int, int> P; //typedef pair<ll, ll> P; //const double INF = 1e10; const ll INF = 1001001001; #define mins(x, y) x = min(x, y) #define maxs(x, y) x = max(x, y) int mod; struct mint { ll x; mint(ll x = 0) : x(x % mod) {} mint &operator+=(const mint a) { (x += a.x) %= mod; return *this; } mint &operator-=(const mint a) { (x += mod - a.x) %= mod; return *this; } mint &operator*=(const mint a) { (x *= a.x) %= mod; return *this; } mint operator+(const mint a) const { mint res(*this); return res += a; } mint operator-(const mint a) const { mint res(*this); return res -= a; } mint operator*(const mint a) const { mint res(*this); return res *= a; } }; ll b, ten; mint pow_(mint x, ll t) { if (t == 0) return 1; if (t % 2 == 1) { return pow_(x, t - 1) * x; } else { mint y = pow_(x, t / 2); return y * y; } } mint f(ll l) { if (l == 0) return 0; if (l % 2 == 1) { ll pl = l - 1; mint x = f(pl); return x * ten + 1; } else { ll pl = l / 2; mint x = f(pl); return x * pow_(ten, pl) + x; } } mint g(ll l) { if (l == 0) return 0; if (l % 2 == 1) { ll pl = l - 1; mint x = g(pl); return x * ten + mint(b) * pl; } else { ll pl = l / 2; mint x = g(pl); return x * pow_(ten, pl) + x + mint(b) * pl * f(pl); } } int main() { ll L, a; cin >> L >> a >> b >> mod; ll last = a + b * (L - 1); mint ans = 0; ten = 10; for (int i = 1; i <= 18; i++, ten *= 10) { ll l = ten / 10, r = ten - 1; if (last < l) continue; if (a > r) continue; ll na = 0; ll nl = 0; { if (a >= l) na = a; else { na = ((l - a) + (b - 1)) / b * b + a; na = min(na, last); } } { ll nlast = 0; if (last <= r) nlast = last; else { nlast = (r - a) / b * b + a; } nl = (nlast - na) / b + 1; } ans *= pow_(ten, nl); ans += f(nl) * na; ans += g(nl); } cout << ans.x << endl; }
#include <bits/stdc++.h> using namespace std; using Int = long long; Int powmod(Int x, unsigned long long y, Int M) { if (y == 0) return 1; if (y % 2 == 0) return powmod(x*x%M, y/2, M); return x*powmod(x*x%M, y/2, M)%M; } using Matrix = array<Int, 9>; Matrix mul(Matrix A, Matrix B, Int M) { Matrix ans = {}; for (int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { for (int k = 0; k < 3; k++) { (ans[i*3+j] += A[i*3+k] * B[k*3+j]) %= M; } } } return ans; } Matrix powmat(Matrix A, Int x, Int M) { if (x == 0) return { 1, 0, 0, 0, 1, 0, 0, 0, 1 }; if (x % 2 == 0) return powmat(mul(A, A, M), x/2, M); return mul(A, powmat(mul(A, A, M), x/2, M), M); } Int f(Int A, Int B, Int R, Int N, Int M) { Matrix mat = { R, 1, 0, 0, 1, B, 0, 0, 1 }; Matrix X = { 0, 0, 0, A, 0, 0, 1, 0, 0 }; Int t = mul(powmat(mat, N, M), X, M)[0]; return t; } int main() { Int L, A, B, M; cin >> L >> A >> B >> M; array<Int, 19> counts = {}; Int idx = 0; for (int i = 1; i < counts.size(); i++) { Int k = (Int)pow(10, i) - 1 - A; if (k < idx*B) continue; k /= B; k = min(L-1, k); counts[i] = k - idx + 1; idx += counts[i]; } Int ans = 0; for (int i = 1; i < counts.size(); i++) { unsigned long long s = 0, t = 0; for (int j = 1; j < i; j++) s += counts[j]; for (int j = i+1; j < counts.size(); j++) t += j * counts[j]; ans = (ans + f((A%M+B%M*(s%M))%M, B%M, powmod(10, i, M), counts[i], M) * powmod(10, t, M)) % M; } cout << ans << '\n'; return 0; }
#include<bits/stdc++.h> using namespace std; int mod; long long int l[20]; long long int cnt[20]; long long int shift[20]; long long int mp(long long int a,long long int b){ a%=mod; long long int res=1; while(b){ if(b&1) res=res*a%mod; a=a*a%mod; b>>=1; } return res; } long long int f(long long int n,long long int k){ if(n==0) return 1; long long int res=f((n-1)/2,k); res=(res+res*mp(mp(10,(n+1)/2),k))%mod; if(n%2==0) res=(res+mp(mp(10,n),k))%mod; return res; } long long int g(long long int n,long long int k){ if(n==0) return 0; long long int res=g((n-1)/2,k); res=(res+res*mp(mp(10,(n+1)/2),k))%mod; res=(res+(n+1)/2%mod*mp(mp(10,(n+1)/2),k)%mod*f((n-1)/2,k))%mod; if(n%2==0) res=(res+n%mod*mp(mp(10,n),k)%mod)%mod; return res; } int main(){ ios_base::sync_with_stdio(0); cin.tie(0); long long int L,A,B; cin>>L>>A>>B>>mod; for(int i=0;i<=18;i++){ long long int x=1; for(int j=0;j<i;j++) x*=10; long long int lo=0,hi=L; while(lo<hi){ long long int mid = (lo+hi)/2; if(A+B*mid>=x) hi=mid; else lo=mid+1; } l[i]=lo; } for(int i=1;i<=18;i++) cnt[i]=l[i]-l[i-1]; shift[18]=1; for(int i=17;i>=1;i--) shift[i]=mp(mp(10,cnt[i+1]),i+1)%mod; long long int ans=0; long long int d = -1; for(int i=1;i<=18;i++){ d+=cnt[i]; long long int n = cnt[i]; if(cnt[i]==0){ ans=ans*shift[i]%mod; continue; } ans=(ans+(A%mod+B%mod*d%mod)%mod*f(n-1,i))%mod; long long int tmp=B%mod; tmp=tmp*g(n-1,i)%mod; ans=(ans-tmp+mod)%mod; ans=ans*shift[i]%mod; } cout<<ans<<endl; }
#include <bits/stdc++.h> using namespace std; using PP = pair<long, long>; const int INF = 1e9; long n, a, b, m; long pre[20]; vector<PP> decomp() { long l = a; long rem = n; vector<PP> ret; for (long base = 1; ; base *= 10) { long num = (base - l + b - 1) / b; if (num < 0) num = 0; if (rem <= num) { ret.push_back(PP(l, rem)); return ret; } ret.push_back(PP(l, num)); l += num * b; rem -= num; } } long modpow(long b, long e) { if (e == 0) return 1; if (e % 2 == 1) return b * modpow(b, e - 1) % m; long t = modpow(b, e / 2); return t * t % m; } long cat(long d, long n) { if (n == 0) return 0; if (n % 2 == 1) { long res = modpow(pre[d], (n - 1)) % m; return (res + cat(d, n - 1)) % m; } long res = cat(d, n / 2); long t = (res + res * modpow(pre[d], (n / 2)) % m) % m; return t; } long sub(long a, long b, long d, long n) { if (n == 0) return 0; if (n % 2 == 1) { long res = a % m * cat(d, n) % m; return (res + sub(b, b, d, n - 1)) % m; } long res = sub(a, b, d, n / 2); long t = (res + res * modpow(pre[d], n / 2) % m) % m; long c = b % m * (n / 2) % m * cat(d, n / 2) % m; return (t + c) % m; } int main() { cin >> n >> a >> b >> m; vector<PP> res = decomp(); long base = 1; for (int i = 0; i < 20; ++i) { pre[i] = base; base = base * 10 % m; } long sum = 0; long mul = 1; for (int i = (int)res.size() - 1; i >= 0; --i) { if (res[i].second == 0) continue; long ans = sub(res[i].first, b, i, res[i].second); sum = (sum + ans * mul % m) % m; mul = mul * modpow(pre[i], res[i].second) % m; } cout << sum << endl; }
#include "bits/stdc++.h" using namespace std; //int N,M,K,L,R,H,W; long long int N,M,K,L,R,H,W; //const long long int MOD=1000000007; const long long int MOD=998244353; vector<vector<long long int>>matrix_product(vector<vector<long long int>>v, vector<vector<long long int>>w) { vector<vector<long long int>>ret(v.size(), vector<long long int>(w.front().size())); for (int i = 0; i < ret.size(); i++) { for (int j = 0; j < ret[i].size(); j++) { for (int k = 0; k < w.size(); k++) { ret[i][j] += v[i][k] * w[k][j]; ret[i][j]%=M; } } } return ret; } int main(){ cin>>N>>L>>R>>M; vector<long long int>ten(19,1); for(int i=1;i<19;i++)ten[i]=ten[i-1]*10; vector<vector<long long int>>ans(1,vector<long long int>({0,L%M,R%M})); while(N){ //cout<<N<<" "<<L<<endl; long long int box=L; int cnt=0; while(box){ cnt++; box/=10; } long long int nx=L+(N-1)*R; box=nx; int ccnt=0; while(box){ ccnt++; box/=10; } long long int num=N; if(ccnt!=cnt){ long long int dif=ten[cnt]-1; dif-=L; dif/=R; nx=L+dif*R; dif++; num=dif; } //cout<<nx<<" "<<num<<endl; vector<vector<long long int>>by(3,vector<long long int>(3)); by[0][0]=ten[cnt]%M; by[1][0]=1; by[1][1]=1; by[2][1]=1; by[2][2]=1; vector<vector<long long int>>ret(3,vector<long long int>(3)); ret[0][0]=1; ret[1][1]=1; ret[2][2]=1; for(int i=0;i<60;i++){ if((num>>i)&1){ ret=matrix_product(ret,by); } by=matrix_product(by,by); } for(int i=0;i<3;i++){ //for(int j=0;j<3;j++){ // cout<<ret[i][j]<<" "; //} //cout<<endl; } ans=matrix_product(ans,ret); N-=num; L=nx+R; } cout<<ans[0][0]<<endl; return 0; }
#include<iostream> using namespace std; long L,A,B,M; long power(long a,long b){return b?power(a*a%M,b/2)*(b%2?a:1)%M:1;} long ten[99]; long n; long sum(long k) { long ret=0,p=1; for(int i=61;i--;) { if(k>>i&1) { (ret+=ten[i]*p)%=M; p=p*power(power(10,n),1LL<<i)%M; } } return ret; } long iten[99]; long isum(long k) { long ret=0,p=1,g=0; for(int i=61;i--;) { if(k>>i&1) { (ret+=(iten[i]+ten[i]*g)%M*p)%=M; p=p*power(power(10,n),1LL<<i)%M; g=(g+(1LL<<i))%M; } } return ret; } long cnt[18],SUM[18]; int main() { cin>>L>>A>>B>>M; long pre=0,tmpten=1; long ans=0; for(n=0;n<18;n++) { long l=pre,r=L; tmpten*=10; while(r-l>1) { long m=(l+r)/2; if(A+B*m<tmpten)l=m; else r=m; } long k=l-pre; if(k<0||l>=L||A+B*l>=tmpten) { cnt[n]=1; continue; } pre=l+1; n++; ten[0]=1; for(int i=1;i<61;i++)ten[i]=(power(power(10,n),(1LL<<i-1))+1)%M*ten[i-1]%M; iten[0]=0; for(int i=1;i<61;i++) { iten[i]=((power(power(10,n),(1LL<<i-1))+1)%M*iten[i-1]+(1LL<<i-1)%M*ten[i-1]%M*power(power(10,n),(1LL<<i-1)))%M; } cnt[n-1]=power(power(10,n),k+1); SUM[n-1]=(((A+B*l)%M*sum(k+1)%M-B%M*isum(k+1))%M+M)%M; n--; } long p=1; for(int i=18;i--;) { ans=(ans+SUM[i]*p)%M; p=p*cnt[i]%M; } cout<<ans<<endl; }