solution_code_ko stringlengths 27 5.97k | answer_ko stringlengths 1 11 | answer_en stringlengths 1 20 | solution_abst_ko stringlengths 1 256 | solution_code_en stringlengths 27 5.97k | solution_abst_en stringlengths 1 287 | question_en stringlengths 20 555 | question_ko stringlengths 11 282 | category stringclasses 5
values |
|---|---|---|---|---|---|---|---|---|
var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
var_f = 1
var_g = var_e - var_f
print(int(var_g)) | 9 | 9 | 20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB] | var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
var_f = 1
var_g = var_e - var_f
print(int(var_g)) | 20 11 [OP_SUB] 1 [OP_ADD] 1 [OP_SUB] | 20 students are waiting for the bus. If Jungkook came right after Yoongi, and there are 11 people who came before Jungkook, how many people came after Yoongi? | 20명의 학생들이 버스를 기다리고 있습니다. 정국이는 윤기 바로 뒤에 왔고, 정국이보다 먼저 온 사람은 11명이라면 윤기보다 늦게 온 사람들은 몇 명입니까? | Comparison |
var_a = '장미'
var_b = '백합'
var_c = '튤립'
var_d = '국화'
var_e = '카네이션'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
... | 60 | 60 | [OP_LIST_SOL] 장미 백합 튤립 국화 카네이션 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM] | var_a = 'rose'
var_b = 'lily'
var_c = 'tulip'
var_d = 'chrysanthemum'
var_e = 'carnation'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if ... | [OP_LIST_SOL] rose lily tulip chrysanthemum carnation [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM] | There is one rose, lily, tulip, chrysanthemum, and carnation each. I'm going to pick three of them and put them in three vases A, B, and C. How many different ways can you put flowers in a vase? | 장미, 백합, 튤립, 국화, 카네이션이 각각 1송이씩 있습니다. 그중에서 3송이를 뽑아 (가), (나), (다) 세 개의 꽃병에 1송이씩 꽂으려고 합니다. 꽃병에 꽃을 서로 다르게 꽂는 방법은 모두 몇 가지입니까? | Possibility |
var_a = '정국'
var_b = '지민'
var_c = '윤기'
var_d = '유나'
var_e = '태형'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
va... | 15 | 15 | [OP_LIST_SOL] 정국 지민 윤기 유나 태형 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB] | var_a = 'Jungkook'
var_b = 'Jimin'
var_c = 'Yoongi'
var_d = 'Yuna'
var_e = 'Taehyung'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" ... | [OP_LIST_SOL] Jungkook Jimin Yoongi Yuna Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB] | You are trying to select two people from Jungkook, Jimin, Yoongi, Yuna, and Taehyung allowing duplicate cases. Find the possible number of cases. | 정국, 지민, 윤기, 유나, 태형 중에서 중복을 허용하여 두 사람을 선택하려고 합니다. 선택할 수 있는 경우는 모두 몇 가지 입니까? | Possibility |
var_a = 1
var_b = 2
var_c = 3
var_d = 4
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
li... | 22 | 22 | [OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 1
var_b = 2
var_c = 3
var_d = 4
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
li... | [OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | If you select three of the four numbers 1, 2, 3, and 4, allowing duplicates, and arrange them in a row to form a three-digit natural number. How many multiples of 3 are there? | 4개의 숫자 1, 2, 3, 4 중에서 중복을 허락하여 3개를 택해 일렬로 나열하여 세 자리의 자연수를 만들 때, 3의 배수의 개수는? | Possibility |
var_a = 2.6
var_b = 5.98
var_c = var_a + var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 8.58 | 8.58 | 2.6 5.98 [OP_ADD] | var_a = 2.6
var_b = 5.98
var_c = var_a + var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 2.6 5.98 [OP_ADD] | Saham walked 2.6 kilometers (km) today, and Saham's mother walked 5.98 kilometers (km). How many kilometers (km) is the sum of the distance that Saham and his mother walked? | 사함이는 오늘 2.6킬로미터(㎞) 걸었고, 사함이의 어머니는 5.98킬로미터(㎞) 걸었습니다. 사함이와 어머니가 걸은 거리를 합하면 몇 킬로미터(㎞)입니까? | Arithmetic calculation |
var_a = 48
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) | 11 | 11 | 48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] | var_a = 48
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) | 48 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] | The sum of the four sides of a rectangle is 48 centimeters (cm), and the width of the rectangle is 2 centimeters (cm) shorter than its length. Find the width of the rectangle. | 직사각형의 네 변의 합이 48센티미터(㎝)이고 가로의 길이가 세로의 길이보다 2센티미터(㎝) 짧다. 직사각형의 가로의 길이를 구하시오. | Geometry |
var_a = 9
var_b = 100
var_c = var_a * var_b
var_d = 9
var_e = 100
var_f = var_d * var_e
var_g = 99
var_h = var_f + var_g
var_i = 1
list_a = [i for i in range(var_c, var_h + 1, var_i)]
var_j = 7
list_b = []
var_j = int(var_j)
for i in list_a:
i = int(i)
if i % var_j == 0:
list_b.append(i)
var_k = len(lis... | 14 | 14 | 9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 9
var_b = 100
var_c = var_a * var_b
var_d = 9
var_e = 100
var_f = var_d * var_e
var_g = 99
var_h = var_f + var_g
var_i = 1
list_a = [i for i in range(var_c, var_h + 1, var_i)]
var_j = 7
list_b = []
var_j = int(var_j)
for i in list_a:
i = int(i)
if i % var_j == 0:
list_b.append(i)
var_k = len(lis... | 9 100 [OP_MUL] 9 100 [OP_MUL] 99 [OP_ADD] 1 [OP_LIST_ARANGE] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | Dividing a three-digit number with 9 in the hundreds place is divisible by 7. How many of these three digit numbers are there? | 백의 자리 숫자가 9인 세 자리 수를 7로 나누면 나누어떨어집니다. 이런 세 자리 수는 모두 몇 개입니까? | Correspondence |
var_a = 2
var_b = 4
var_c = 5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
li... | 2 | 2 | [OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 2
var_b = 4
var_c = 5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
li... | [OP_LIST_SOL] 2 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | We are going to use 2 of our number cards 2, 4, and 5 in order to create a double-digit number. How many multiples of 4 can you make? | 2, 4, 5 총 3장의 수 카드 중 2장을 사용하여 두 자리 수를 만들려고 합니다. 만들 수 있는 4의 배수는 모두 몇 개일까요? | Possibility |
var_a = 0.84
var_b = 10
var_c = var_a * var_b
var_d = 50
var_e = 100
var_f = var_d / var_e
var_g = var_c + var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) | 8.90 | 8.9 | 0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD] | var_a = 0.84
var_b = 10
var_c = var_a * var_b
var_d = 50
var_e = 100
var_f = var_d / var_e
var_g = var_c + var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) | 0.84 10 [OP_MUL] 50 100 [OP_DIV] [OP_ADD] | It takes 0.84 meters (m) of ribbon tape to make one ribbon. After making 10 ribbons with the ribbon tape that Yujin has, there are 50 centimeters (cm) left. How many meters (m) is the ribbon tape that Yujin had at first? | 리본 한 개를 만드는데 리본 테이프 0.84미터(m)가 필요합니다. 유진이가 가지고 있는 리본 테이프로 리본을 10개 만들었더니 50센티미터(㎝)가 남았습니다. 유진이가 처음에 가지고 있던 리본 테이프의 길이는 몇 미터(m)일까요? | Arithmetic calculation |
var_a = 'A78-21B=364'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
... | 5 | 5 | A78-21B=364 A [OP_DIGIT_UNK_SOLVER] | var_a = 'A78-21B=364'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
... | A78-21B=364 A [OP_DIGIT_UNK_SOLVER] | When A78-21B=364, where A79 and 21B are three-digit numbers. Find A. | A78-21B=364일 때, A를 구하시오. | Correspondence |
var_a = 71
var_b = 8
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 4
var_g = 1
var_h = var_f + var_g
var_i = var_e / var_h
var_j = 4
var_k = var_i * var_j
var_l = 5
var_m = var_k + var_l
print(int(var_m)) | 49 | 49 | 71 8 2 [OP_MUL] [OP_SUB] 4 1 [OP_ADD] [OP_DIV] 4 [OP_MUL] 5 [OP_ADD] | var_a = 71
var_b = 8
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 4
var_g = 1
var_h = var_f + var_g
var_i = var_e / var_h
var_j = 4
var_k = var_i * var_j
var_l = 5
var_m = var_k + var_l
print(int(var_m)) | 71 8 2 [OP_MUL] [OP_SUB] 4 1 [OP_ADD] [OP_DIV] 4 [OP_MUL] 5 [OP_ADD] | If the age of the mother is 4 times that of the daughter this year, and the sum of the ages of the mother and daughter is 71 after 8 years, how old will the mother be after 5 years? | 올해는 어머니의 나이가 딸보다 4배, 8년 후에는 어머니와 딸 나이의 합이 71살이라면, 5년 후에 어머니는 몇 살입니까? | Arithmetic calculation |
var_a = 2.8
var_b = 2.3
var_c = 5
var_d = 3
var_e = 4.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eva... | 11.50 | 11.5 | [OP_LIST_SOL] 2.8 2.3 5 3 4.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL] | var_a = 2.8
var_b = 2.3
var_c = 5
var_d = 3
var_e = 4.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eva... | [OP_LIST_SOL] 2.8 2.3 5 3 4.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL] | Find the product of the smallest number and the largest number among 2.8, 2.3, 5, 3, and 4.3. | 2.8, 2.3, 5, 3, 4.3 중 가장 작은 수와 가장 큰 수의 곱을 구하시오. | Comparison |
var_a = 0.8
var_b = 0.5
var_c = 0.5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = []
for i in list_a:
... | 1.80 | 1.8 | [OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM] | var_a = 0.8
var_b = 0.5
var_c = 0.5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = []
for i in list_a:
... | [OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM] | There are a total of three numbers: 0.8, 1/2, and 0.5. What is the sum of all numbers less than or equal to 2? | 총 3개의 숫자 0.8, 1/2, 0.5이 있습니다. 이 중 2보다 작거나 같은 수를 모두 더하면 얼마인가요? | Comparison |
var_a = 1
var_b = 1
var_c = 10
var_d = var_b / var_c
var_e = 1
var_f = 15
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(eval('{:.2f}'.format(round(var_i+1e-10,2))))) | 6 | 6 | 1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV] | var_a = 1
var_b = 1
var_c = 10
var_d = var_b / var_c
var_e = 1
var_f = 15
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(eval('{:.2f}'.format(round(var_i+1e-10,2))))) | 1 1 10 [OP_DIV] 1 15 [OP_DIV] [OP_ADD] [OP_DIV] | It takes 10 days for Sumin to do something alone, and 15 days for Junwoo to do it alone. Answer how many days it will take to complete the task if two people are doing it together. | 어떤 일을 하는 데 수민이가 혼자서 하면 10일이 걸리고, 준우가 혼자서 하면 15일이 걸립니다. 이 일을 두 사람이 같이 한다면 일을 끝내는 데 며칠이 걸리는지 답을 구하세요. | Arithmetic calculation |
var_a = 7
var_b = 1
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | 3 | 3 | [OP_LIST_SOL] 7 1 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 150 [OP_LIST_MORE] 700 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 7
var_b = 1
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | [OP_LIST_SOL] 7 1 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 150 [OP_LIST_MORE] 700 [OP_LIST_LESS] [OP_LIST_LEN] | How many three-digit numbers are there that are greater than 150 and less than 700, given that the numbers 7, 1, and 3 are used once? | 주어진 숫자 7, 1, 3을 한 번씩 모두 사용했을 때, 150보다 크고 700보다 작은 세 자리 수의 개수는 모두 몇 개입니까? | Possibility |
var_a = 5
var_b = 7
var_c = var_b * var_a / math.gcd(int(var_b), int(var_a))
print(int(var_c)) | 35 | 35 | 5 7 [OP_LCM] | var_a = 5
var_b = 7
var_c = var_b * var_a / math.gcd(int(var_b), int(var_a))
print(int(var_c)) | 5 7 [OP_LCM] | Rectangular business cards measuring 5 centimeters (cm) wide and 7 centimeters (cm) long were laid out without overlapping, filling the bottom of the square box. How many centimeters (cm) is each side of this box at its smallest size? | 가로가 5센티미터(㎝), 세로가 7센티미터(㎝)인 직사각형 모양의 명함을 겹치지 않게 빈틈없이 늘어놓아 정사각형 모양의 상자 바닥을 가득 채웠습니다. 이 상자의 크기가 최소일 때 한 변의 길이는 몇 센티미터(㎝)입니까? | Geometry |
var_a = 10
var_b = 1
var_c = var_a + var_b
print(int(var_c)) | 11 | 11 | 10 1 [OP_ADD] | var_a = 10
var_b = 1
var_c = var_a + var_b
print(int(var_c)) | 10 1 [OP_ADD] | Students are standing in a line. Yoojung is standing at the very front. When 10 students are standing behind Yoojeong, how many students are in the line? | 학생들이 한 줄로 서 있습니다. 유정이는 맨 앞에 서 있습니다. 유정이 뒤에 10명이 서 있을 때, 줄을 서 있는 학생은 모두 몇 명입니까? | Comparison |
var_a = '윤기'
var_b = '정국'
var_c = '유나'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 6
var_f = 3
var_g =... | 정국 | Jungkook | [OP_LIST_SOL] 윤기 정국 유나 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Jungkook'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 6
var_f... | [OP_LIST_SOL] Yoongi Jungkook Yuna [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | Yoongi collected 4, Jungkook collected 6 divided by 3, and Yuna collected 5. Who got the smallest number? | 윤기는 4, 정국이는 6에서 3을 나눈 몫 만큼 모았고, 유나는 5만큼 모았습니다. 누가 가장 작은 수를 모았습니까? | Comparison |
var_a = 665655
var_b = 5
var_c = var_a / var_b
list_a = []
var_c = int(var_c)
while var_c//10 > 0:
list_a.append(var_c%10)
var_c = var_c//10
list_a.append(var_c%10)
list_a = list_a[::-1]
list_a = [float(i) for i in list_a]
var_d = sum(list_a)
print(int(var_d)) | 12 | 12 | 665655 5 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM] | var_a = 665655
var_b = 5
var_c = var_a / var_b
list_a = []
var_c = int(var_c)
while var_c//10 > 0:
list_a.append(var_c%10)
var_c = var_c//10
list_a.append(var_c%10)
list_a = list_a[::-1]
list_a = [float(i) for i in list_a]
var_d = sum(list_a)
print(int(var_d)) | 665655 5 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM] | The quotient of 665655 divided by 5 is the six-digit number ABCDEF. Find the sum of A, B, C, D, E, and F. | 665655를 5로 나눈 몫은 여섯 자리 수 ABCDEF입니다. A, B, C, D, E, F의 합을 구하시오. | Correspondence |
var_a = 3.944
var_b = 100
var_c = var_a * var_b
var_d = 29.05
var_e = 8
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 8
var_i = 1
var_j = var_h + var_i
var_k = var_g / var_j
print(int(eval('{:.2f}'.format(round(var_k+1e-10,2))))) | 18 | 18 | 3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV] | var_a = 3.944
var_b = 100
var_c = var_a * var_b
var_d = 29.05
var_e = 8
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 8
var_i = 1
var_j = var_h + var_i
var_k = var_g / var_j
print(int(eval('{:.2f}'.format(round(var_k+1e-10,2))))) | 3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV] | There is a wire with a total length of 3.944 meters (m). Eight cuts of 29.05 cm (cm) were cut from this wire. When dividing the remaining length into 9 equal parts, find the length of one cut-off. | 전체 길이가 3.944미터(m)인 철사가 있다. 이 철사에서 29.05센티미터(㎝) 씩 8번 잘라냈다. 남은 길이를 9등분할 때, 잘려진 하나의 길이를 구하시오. | Arithmetic calculation |
var_a = '예슬'
var_b = '영준'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 13
var_d = 10
var_e = var_c / var_d
var_f = 22
var_g = 15
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
... | 영준 | Youngjun | [OP_LIST_SOL] 예슬 영준 [OP_LIST_EOL] [OP_LIST_SOL] 13 10 [OP_DIV] 22 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yeseul'
var_b = 'Youngjun'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 13
var_d = 10
var_e = var_c / var_d
var_f = 22
var_g = 15
var_h = var_f / var_g
list_b= []
if "/" in str... | [OP_LIST_SOL] Yeseul Youngjun [OP_LIST_EOL] [OP_LIST_SOL] 13 10 [OP_DIV] 22 15 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | Today Yeseul exercised for 13/10 hours and Youngjun for 22/15 hours. Who has been exercising longer, Yeseul or Youngjun? | 오늘 운동은 예슬이는 13/10시간, 영준이는 22/15시간 하였다. 예슬과 영준 중 누가 더 오래 운동했는가? | Comparison |
var_a = 210
var_b = 4
var_c = 3
var_d = var_b + var_c
var_e = var_a / var_d
print(int(var_e)) | 30 | 30 | 210 4 3 [OP_ADD] [OP_DIV] | var_a = 210
var_b = 4
var_c = 3
var_d = var_b + var_c
var_e = var_a / var_d
print(int(var_e)) | 210 4 3 [OP_ADD] [OP_DIV] | There are the total of 210 apples and persimmons. The number of apples and persimmons is four times and three times the number of bananas, respectively. So how many bananas are there in total? | 사과와 감은 총 210개 있다. 사과와 감의 개수는 각각 바나나의 개수의 4배, 3배이다. 그렇다면 바나나는 총 몇 개입니까? | Arithmetic calculation |
var_a = '윤기'
var_b = '유나'
var_c = '정국'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 5
var_f = 6
var_g =... | 정국 | Jungkook | [OP_LIST_SOL] 윤기 유나 정국 [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Yuna'
var_c = 'Jungkook'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 5
var_f... | [OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | Yoongi collected 4 and Yuna collected 5. If Jungkook collects a sum of 6 and 3, who has the largest number? | 윤기는 4, 유나는 5를 모았습니다. 정국이는 6에서 3을 합한 수만큼 모았다면 누가 가장 큰 수를 가지고 있나요? | Comparison |
var_a = 1.782
var_b = 0.99
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 1.80 | 1.8 | 1.782 0.99 [OP_DIV] | var_a = 1.782
var_b = 0.99
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 1.782 0.99 [OP_DIV] | Moving some decimal places to the left equals the original value minus 1.782. If you moved the decimal point by two places, what was the original decimal? | 어떤 소수의 소수점을 왼쪽으로 옮겼더니 원래의 값에서 1.782를 뺀 것과 같아졌습니다. 소수점을 두 자리 옮겼다고 한다면, 원래 소수는 무엇이었는지 구하시오. | Correspondence |
var_a = 35.1
var_b = 41.3
var_c = 38.6
var_d = 40.2
var_e = 39
var_f = 43.7
var_g = 38.4
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "... | 41.05 | 41.05 | [OP_LIST_SOL] 35.1 41.3 38.6 40.2 39.0 43.7 38.4 [OP_LIST_EOL] 39 [OP_LIST_MORE_EQUAL] [OP_LIST_MEAN] | var_a = 35.1
var_b = 41.3
var_c = 38.6
var_d = 40.2
var_e = 39
var_f = 43.7
var_g = 38.4
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "... | [OP_LIST_SOL] 35.1 41.3 38.6 40.2 39.0 43.7 38.4 [OP_LIST_EOL] 39 [OP_LIST_MORE_EQUAL] [OP_LIST_MEAN] | When the weight of 7 students in Geontak’s class is 35.1 kilograms (kg), 41.3 kilograms (kg), 38.6 kilograms (kg), 40.2 kilograms (kg), 39.0 kilograms (kg), 43.7 kilograms (kg), and 38.4 kilograms (kg), find the average weight of students who weighed more than or equal to 39 kilograms (kg). | 건탁이네 반 학생 7명의 몸무게가 35.1킬로그램(㎏), 41.3킬로그램(㎏), 38.6킬로그램(㎏), 40.2킬로그램(㎏), 39.0킬로그램(㎏), 43.7킬로그램(㎏), 38.4킬로그램(㎏)일 때 39킬로그램(㎏) 이상인 학생들의 평균 몸무게를 구하시오. | Comparison |
var_a = 1000
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 2
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 3
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c... | 1008 | 1008 | 1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | var_a = 1000
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 2
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 3
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c... | 1000 9999 1 [OP_LIST_ARANGE] 2 [OP_LIST_DIVISIBLE] 3 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | What is the smallest four-digit number divisible by 2, 3, 8, and 9? | 숫자 2, 3, 8, 9로 나누어 떨어질 수 있는 네 자리 수 중 가장 작은 수는? | Arithmetic calculation |
var_a = 6
var_b = 6
var_c = var_a * var_b
var_d = 2
var_e = var_c * var_d
var_f = 11
var_g = 6
var_h = var_f * var_g
var_i = var_e + var_h
print(int(var_i)) | 138 | 138 | 6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD] | var_a = 6
var_b = 6
var_c = var_a * var_b
var_d = 2
var_e = var_c * var_d
var_f = 11
var_g = 6
var_h = var_f * var_g
var_i = var_e + var_h
print(int(var_i)) | 6 6 [OP_MUL] 2 [OP_MUL] 11 6 [OP_MUL] [OP_ADD] | If one side of the base of a regular hexagonal prism is 6 centimeters (cm) long, and the prism is 11 centimeters (cm) high, how many centimeters (cm) is the sum of the lengths of all the edges? | 정육각기둥의 밑면의 한 변의 길이가 6센티미터(㎝), 높이가 11센티미터(㎝)일 때, 모든 모서리 길이의 합은 몇 센티미터(㎝)입니까? | Geometry |
var_a = 11
var_b = 100
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 0.11 | 0.11 | 11 100 [OP_DIV] | var_a = 11
var_b = 100
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 11 100 [OP_DIV] | Seojun and his friends picked 100 apples from the orchard. If Seojun takes 11 of them, how many apples does Seojun have compared to entire apples as a decimal number? | 서준이와 친구들은 과수원에서 사과를 100개 땄습니다. 그중에서 서준이가 11개를 가졌다면 서준이가 가진 사과는 전체 사과의 얼마인지 소수로 나타내시오. | Arithmetic calculation |
var_a = 1
var_b = 0.1
var_c = var_a - var_b
var_d = 0.1
var_e = 0.2
var_f = var_d + var_e
var_g = var_c - var_f
var_h = 0.3
var_i = var_g - var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) | 0.30 | 0.3 | 1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB] | var_a = 1
var_b = 0.1
var_c = var_a - var_b
var_d = 0.1
var_e = 0.2
var_f = var_d + var_e
var_g = var_c - var_f
var_h = 0.3
var_i = var_g - var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) | 1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB] | There is 1 liter (L) of water. The mother drank 0.1 liters (L), and the father drank 0.2 liters (L) more than the mother. If your sister drank 0.3 liters (L) at this time, how many liters (L) of water is left? | 1리터(L)짜리 물이 있습니다. 엄마가 0.1리터(L) 마셨고, 아빠는 엄마보다 0.2리터(L)를 더 마셨습니다. 이때 누나가 0.3리터(L)를 마셨다면, 남은 물은 몇 리터(L)입니까? | Arithmetic calculation |
var_a = 346
var_b = 152
var_c = var_a + var_b
var_d = 152
var_e = var_c + var_d
print(int(var_e)) | 650 | 650 | 346 152 [OP_ADD] 152 [OP_ADD] | var_a = 346
var_b = 152
var_c = var_a + var_b
var_d = 152
var_e = var_c + var_d
print(int(var_e)) | 346 152 [OP_ADD] 152 [OP_ADD] | A sheet of paper, yellow on the front and green on the back, lies on the floor. At this time, it is said that the students flipped 152 pieces of paper that showed yellow and turned them over to show green. At this time, if there are 346 more yellow papers than green papers, what is the difference before flipping? | 앞면은 노란색 뒷면은 초록색인 종이가 바닥에 놓여 있다. 이때 학생들이 노란색이 보이는 종이 152개를 뒤집어 초록색이 보이도록 뒤집었다고 한다. 이때 노란색 종이가 초록색 종이보다 346개 많았다면 뒤집기전에는 차이가 얼마였는지 구하시오. | Correspondence |
var_a = 22.01
var_b = 2.49
var_c = var_a + var_b
var_d = 2.5
var_e = var_c / var_d
var_f = 2.5
var_g = var_e / var_f
var_h = 2.49
var_i = var_g + var_h
var_j = 22.01
var_k = var_i + var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) | 28.42 | 28.42 | 22.01 2.49 [OP_ADD] 2.5 [OP_DIV] 2.5 [OP_DIV] 2.49 [OP_ADD] 22.01 [OP_ADD] | var_a = 22.01
var_b = 2.49
var_c = var_a + var_b
var_d = 2.5
var_e = var_c / var_d
var_f = 2.5
var_g = var_e / var_f
var_h = 2.49
var_i = var_g + var_h
var_j = 22.01
var_k = var_i + var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) | 22.01 2.49 [OP_ADD] 2.5 [OP_DIV] 2.5 [OP_DIV] 2.49 [OP_ADD] 22.01 [OP_ADD] | Multiply 2.5 to a particular number and subtract 2.49, and it becomes 22.01. Find the value if you divide the number by 2.5 and add 2.49 and 22.01. | 어떤 수에 2.5를 곱한 다음 2.49를 뺐더니 22.01이 되었습니다. 어떤 수를 2.5로 나눈 다음 2.49를 더하고 22.01을 더한 값을 구하시오. | Correspondence |
var_a = 32.5
var_b = 1.3
var_c = var_a / var_b
var_d = 60.8
var_e = 7.6
var_f = var_d / var_e
var_g = var_c - var_f
var_h = abs(var_g)
print(int(var_h)) | 17 | 17 | 32.5 1.3 [OP_DIV] 60.8 7.6 [OP_DIV] [OP_SUB] [OP_ABS] | var_a = 32.5
var_b = 1.3
var_c = var_a / var_b
var_d = 60.8
var_e = 7.6
var_f = var_d / var_e
var_g = var_c - var_f
var_h = abs(var_g)
print(int(var_h)) | 32.5 1.3 [OP_DIV] 60.8 7.6 [OP_DIV] [OP_SUB] [OP_ABS] | Find the difference between the quotients of two divisions 32.5 / 1.3 and 60.8 / 7.6. | 두 나눗셈 32.5 / 1.3, 60.8 / 7.6의 몫의 차를 구해보세요 | Arithmetic calculation |
var_a = 5
var_b = 3
var_c = 6
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
li... | 568 | 568 | [OP_LIST_SOL] 5 3 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MIN] | var_a = 5
var_b = 3
var_c = 6
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
li... | [OP_LIST_SOL] 5 3 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 [OP_LIST_MIN] | I want to choose three of the natural numbers 5, 3, 6, and 8, and use all of them to create a three-digit number. Choose the 10th smallest possible number. | 자연수 5, 3, 6, 8 중 3개를 고르고, 고른 수를 모두 사용하여 세 자리 수를 만들고 싶습니다. 만들 수 있는 수 중 10번째로 작은 수를 고르시오. | Possibility |
var_a = 1
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 7
var_e = 2
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = 8
var_g = 2
list_c = []
var_f = i... | 58 | 58 | 1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX] | var_a = 1
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 7
var_e = 2
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = 8
var_g = 2
list_c = []
var_f = i... | 1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MAX] | Find the largest number from all natural numbers less than or equal to 100, which become common multiples of 7 and 8 if 2 is subtracted. | 100 이하의 자연수 중 2를 빼면 7과 8의 공배수인 수들 중 가장 큰 수를 구하시오. | Arithmetic calculation |
var_a = 1
var_b = 1
var_c = 4
var_d = var_b / var_c
var_e = 1
var_f = 12
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(var_i)) | 3 | 3 | 1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV] | var_a = 1
var_b = 1
var_c = 4
var_d = var_b / var_c
var_e = 1
var_f = 12
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(var_i)) | 1 1 4 [OP_DIV] 1 12 [OP_DIV] [OP_ADD] [OP_DIV] | It is said that it takes four days for the older brother and 12 days for the younger to complete a certain task. If the older brother and the younger brother do this together, find how many days it will take to complete the job. | 어떤 일을 완성하는 데 형은 4일, 동생은 12일이 걸린다고 한다. 형과 동생이 함께 이 일을 한다면 일을 완성하는 데 며칠이 걸리는지 구하여라 | Arithmetic calculation |
var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(va... | D | D | [OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 27 27 7 [OP_ADD] 27 7 [OP_ADD] 9 [OP_SUB] 27 7 [OP_ADD] 9 [OP_SUB] 2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(va... | [OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] 27 27 7 [OP_ADD] 27 7 [OP_ADD] 9 [OP_SUB] 27 7 [OP_ADD] 9 [OP_SUB] 2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | There are four numbers A, B, C, and D. A is 27. B is 7 greater than A. C is 9 less than B. D is twice the number of C. Which number is the largest? | 네 수 A, B, C, D가 있습니다. A는 27입니다. B는 A보다 7 큰 수입니다. C는 B보다 9 작은 수입니다. D는 C의 2배인 수입니다. 가장 큰 수는 어느 것입니까? | Comparison |
var_a = 12
var_b = 4
var_c = var_a * var_b
var_d = 3
var_e = var_c / var_d
print(int(var_e)) | 16 | 16 | 12 4 [OP_MUL] 3 [OP_DIV] | var_a = 12
var_b = 4
var_c = var_a * var_b
var_d = 3
var_e = var_c / var_d
print(int(var_e)) | 12 4 [OP_MUL] 3 [OP_DIV] | When a number is divided by 4, it is 12. Find the result of dividing the number by 3. | 4를 어떤 수에서 나누었더니 12가 되었습니다. 어떤 수에 3을 나눈 결과를 구하시오. | Correspondence |
var_a = 32
var_b = 4
var_c = var_a / var_b
print(int(var_c)) | 8 | 8 | 32 4 [OP_DIV] | var_a = 32
var_b = 4
var_c = var_a / var_b
print(int(var_c)) | 32 4 [OP_DIV] | You want to make the largest square out of a piece of string that is 32 centimeters (cm) long. How many centimeters (cm) is the length of one side of the square? | 길이가 32센티미터(㎝) 인 끈으로 가장 큰 정사각형을 만들려고 합니다. 정사각형 한 변의 길이는 몇 센티미터(㎝) 입니까? | Geometry |
var_a = 122
var_b = 64
var_c = var_a + var_b
var_d = 46
var_e = var_c - var_d
print(int(var_e)) | 140 | 140 | 122 64 [OP_ADD] 46 [OP_SUB] | var_a = 122
var_b = 64
var_c = var_a + var_b
var_d = 46
var_e = var_c - var_d
print(int(var_e)) | 122 64 [OP_ADD] 46 [OP_SUB] | 122 is the result of mistakenly subtracting 64 from a number. We need to subtract 46 from it. Calculate correctly. | 122는 어떤 수에서 46을 빼야 하는데 실수로 64를 빼서 나온 결과입니다. 바르게 계산하시오. | Correspondence |
var_a = 10
var_b = 5
var_c = var_a / var_b
print(int(var_c)) | 2 | 2 | 10 5 [OP_DIV] | var_a = 10
var_b = 5
var_c = var_a / var_b
print(int(var_c)) | 10 5 [OP_DIV] | There are 10 balls in a big box. How many small boxes are needed to if you put 5 balls in each of the small box? | 큰 상자 안에는 10개의 공이 있습니다. 작은 상자에 공을 5개씩 나누어 담을 때, 필요한 작은 상자의 개수는 몇 개입니까? | Arithmetic calculation |
var_a = 48
var_b = 4
var_c = 6
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e)) | 2 | 2 | 48 4 6 [OP_MUL] [OP_DIV] | var_a = 48
var_b = 4
var_c = 6
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e)) | 48 4 6 [OP_MUL] [OP_DIV] | You're trying to move 48 one-metric ton (m/t) objects. How many trips would it take to move 6 trucks that can load up to 4-metric ton (m/t) at a time? | 1톤짜리 물건 48개를 옮기려고 합니다. 4톤까지 실을 수 있는 트럭에 물건을 가득 채워 6대씩 한 번에 이동하여 물건을 나르려면, 모두 몇 번 날라야 합니까? | Arithmetic calculation |
var_a = 5
var_b = 4
var_c = var_a * var_b
print(int(var_c)) | 20 | 20 | 5 4 [OP_MUL] | var_a = 5
var_b = 4
var_c = var_a * var_b
print(int(var_c)) | 5 4 [OP_MUL] | There is a square with a side of 5 centimeters (cm). What is the sum of the lengths of the four sides of this square in centimeters (cm)? | 한 변이 5센티미터(㎝) 정사각형이 있습니다. 이 정사각형의 네 변의 길이의 합은 몇 센티미터(㎝)입니까? | Geometry |
var_a = 2
var_b = 4
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 3
var_g = 2
var_h = var_f + var_g
var_i = var_e * var_h
print(int(var_i)) | 25 | 25 | 2 4 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] [OP_MUL] | var_a = 2
var_b = 4
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 3
var_g = 2
var_h = var_f + var_g
var_i = var_e * var_h
print(int(var_i)) | 2 4 [OP_ADD] 1 [OP_SUB] 3 2 [OP_ADD] [OP_MUL] | Kiyoung's classroom is placed in a square shape with the same number of desks in each row. Kiyoung's seat is 2nd from the front, 4th from the back, and 3rd from the right. Karam's seat is right next to Kiyoung's left and is second from the left. How many desks are there in Kiyoung's classroom? | 기영이네 교실에는 가로, 세로 각 줄의 책상 수가 같게 사각형 모양으로 놓여 있습니다. 기영이의 자리는 앞에서 2번째, 뒤에서 4번째, 오른쪽에서 3번째에 있습니다. 가람이의 자리는 기영이의 바로 왼쪽 옆에 있고 왼쪽에서 2번째에 있습니다. 기영이네 교실의 책상은 모두 몇 개입니까? | Comparison |
var_a = 0.35
var_b = 0.37
var_c = 0.35
var_d = var_b - var_c
var_e = 4
var_f = var_d / var_e
var_g = 4
var_h = 1
var_i = var_g - var_h
var_j = var_f * var_i
var_k = var_a + var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) | 0.37 | 0.37 | 0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD] | var_a = 0.35
var_b = 0.37
var_c = 0.35
var_d = var_b - var_c
var_e = 4
var_f = var_d / var_e
var_g = 4
var_h = 1
var_i = var_g - var_h
var_j = var_f * var_i
var_k = var_a + var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) | 0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD] | From the 0.35 kilometer (km) point to the 0.37 kilometer (km) point of a certain road, it was decided to divide it into 4 equal sections and plant street trees from beginning to end. How many kilometers (km) is the location of the street tree planted at the fourth point using a decimal number? | 어떤 도로의 0.35킬로미터(㎞) 지점에서 0.37킬로미터(㎞) 지점까지 똑같이 4구간으로 나누어 처음부터 끝까지 가로수를 심기로 하였습니다. 네 번째 지점에 심는 가로수의 위치는 몇 킬로미터(㎞) 지점인지 소수로 나타내시오. | Arithmetic calculation |
var_a = 225
var_b = 5
var_c = var_a / var_b
var_d = 20
var_e = var_c - var_d
var_f = 20
var_g = var_e + var_f
var_h = 5
var_i = var_g / var_h
print(int(var_i)) | 9 | 9 | 225 5 [OP_DIV] 20 [OP_SUB] 20 [OP_ADD] 5 [OP_DIV] | var_a = 225
var_b = 5
var_c = var_a / var_b
var_d = 20
var_e = var_c - var_d
var_f = 20
var_g = var_e + var_f
var_h = 5
var_i = var_g / var_h
print(int(var_i)) | 225 5 [OP_DIV] 20 [OP_SUB] 20 [OP_ADD] 5 [OP_DIV] | 225 is the result of adding 20 to a number and multiplying it by 5 by mistake, when it was supposed to be adding 20 and dividing it by 5. How much is it if you calculate it correctly? | 225는 어떤수에 20를 더한 뒤 5로 나눠야했던 거를 실수로 20을 더한 뒤 5를 곱하여 나온 결과입니다. 바르게 계산한다면 얼마입니까? | Correspondence |
var_a = '소라'
var_b = '희수'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 4
var_d = 6
var_e = var_c + var_d
var_f = 3
var_g = 8
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
v... | 희수 | Heesu | [OP_LIST_SOL] 소라 희수 [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Sora'
var_b = 'Heesu'
var_c = 'Jiyeon'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 6
var_f = ... | [OP_LIST_SOL] Sora Heesu Jiyeon [OP_LIST_EOL] [OP_LIST_SOL] 4 6 [OP_ADD] 7 5 [OP_ADD] 3 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | Sora, Heesu, and Jiyeon are playing a game of collecting number cards. Sora picked up cards with 4 and 6 written on them, Heesu picked up cards with 7 and 5 written on them, and Jiyeon collected cards with 3 and 8 written on them. Find who has the greatest sum of the numbers written on all the cards. | 소라, 희수, 지연이는 숫자 카드 모으기 놀이를 하고 있습니다. 소라는 4와 6이 쓰여있는 카드를 집었고, 희수는 7과 5가 쓰여있는 카드를, 지연이는 3과 8이 적혀있는 카드를 모았습니다. 모든 카드에 적혀있는 수의 합이 가장 큰 사람은 누구인지 구하세요. | Comparison |
var_a = 11
var_b = 4
var_c = var_a - var_b
var_d = 12
var_e = var_c * var_d
var_f = 9
var_g = var_e - var_f
print(int(var_g)) | 75 | 75 | 11 4 [OP_SUB] 12 [OP_MUL] 9 [OP_SUB] | var_a = 11
var_b = 4
var_c = var_a - var_b
var_d = 12
var_e = var_c * var_d
var_f = 9
var_g = var_e - var_f
print(int(var_g)) | 11 4 [OP_SUB] 12 [OP_MUL] 9 [OP_SUB] | Junyoung has 11 dozen pencils. Of these, 4 dozen were given to Taesoo and 9 were given to Jongsoo. How many pencils are left to Junyoung? | 준영이는 연필 11타를 가지고 있습니다. 이 중에서 4타를 태수에게 주고, 9자루를 종수에게 주었습니다. 준영이에게 남아 있는 연필은 몇 자루 입니까? | Arithmetic calculation |
var_a = '사과'
var_b = '메론'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2.9
var_d = 0.2
var_e = var_c - var_d
var_f = 5
var_g = var_e / var_f
var_h = 2.51
var_i = 0.2
var_j = var_h - var... | 메론 | melons | [OP_LIST_SOL] 사과 메론 [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'apples'
var_b = 'melons'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2.9
var_d = 0.2
var_e = var_c - var_d
var_f = 5
var_g = var_e / var_f
var_h = 2.51
var_i = 0.2
var_j = var... | [OP_LIST_SOL] apples melons [OP_LIST_EOL] [OP_LIST_SOL] 2.9 0.2 [OP_SUB] 5 [OP_DIV] 2.51 0.2 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | Basket containing 5 apples of the same weight weighs 2.9 kilograms (kg), and a basket containing 3 melons of the same weight weighs 2.51 kilograms (kg). If the empty basket weighs 0.2 kilograms (kg), find out which of the apples or melons is heavier. | 무게가 같은 사과 5개를 담은 바구니의 무게는 2.9킬로그램(㎏) 이고, 무게가 같은 메론 3개를 담은 바구니의 무게는 2.51킬로그램(㎏) 입니다. 빈 바구니의 무게가 0.2킬로그램(㎏) 일 때 사과 한 개와 메론 한 개 중 어느 것이 더 무거운지 구해보시오. | Comparison |
var_a = 1
var_b = 7
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 2
var_g = 4
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e * var_j
var_l = 3
var_m = var_k * var_l
print(int(var_m)) | 105 | 105 | 1 7 [OP_ADD] 1 [OP_SUB] 2 4 [OP_ADD] 1 [OP_SUB] [OP_MUL] 3 [OP_MUL] | var_a = 1
var_b = 7
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 2
var_g = 4
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e * var_j
var_l = 3
var_m = var_k * var_l
print(int(var_m)) | 1 7 [OP_ADD] 1 [OP_SUB] 2 4 [OP_ADD] 1 [OP_SUB] [OP_MUL] 3 [OP_MUL] | Mijoo's house is on the 1st from the left, the 7th from the right, the 2nd from the top floor, and the 4th from the bottom floor of the apartment. If the number of houses in each row is the same and there are 3 households in each house, how many households live in this apartment? | 미주의 집은 아파트의 집들 중 왼쪽에서 1번째, 오른쪽에서 7번째, 위에서 2번째 층, 아래에서 4번째 층에 있습니다. 각 줄마다 있는 집의 수가 같고 한 집 당 3가구가 살 때, 이 아파트는 모두 몇 가구가 삽니까? | Comparison |
var_a = 1
var_b = 100
var_c = var_a * var_b
var_d = 70
var_e = var_c + var_d
var_f = 5
var_g = var_e * var_f
var_h = 80
var_i = var_g + var_h
print(int(var_i)) | 930 | 930 | 1 100 [OP_MUL] 70 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD] | var_a = 1
var_b = 100
var_c = var_a * var_b
var_d = 70
var_e = var_c + var_d
var_f = 5
var_g = var_e * var_f
var_h = 80
var_i = var_g + var_h
print(int(var_i)) | 1 100 [OP_MUL] 70 [OP_ADD] 5 [OP_MUL] 80 [OP_ADD] | The width of the wall was measured with a string measuring 1 meter (m) and 70 centimeters (cm) in length. If the width of the wall is 80 centimeters (cm) greater than 5 times the length of the string, what is the width of this wall in centimeters (cm)? | 길이가 1미터(m) 70센티미터(㎝)인 끈으로 벽의 가로의 길이를 재었습니다. 벽의 가로의 길이가 끈의 길이의 5배보다 80센티미터(㎝) 더 길다면, 이 벽의 가로 길이는 몇 센티미터(㎝)입니까? | Geometry |
var_a = 0
var_b = 3
var_c = 5
var_d = 6
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
li... | 305 | 305 | [OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] | var_a = 0
var_b = 3
var_c = 5
var_d = 6
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
li... | [OP_LIST_SOL] 0 3 5 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] | I am trying to make a three digit number by picking 3 times out of 0, 3, 5, 6. What is the smallest number that can be made? | 세자리 수를 0, 3, 5, 6 중에서 3번 뽑아 만들려 합니다. 만들어진 수 중에서 가장 작은 수는 무엇인가요? | Possibility |
var_a = 156
var_b = 267
var_c = var_a + var_b
var_d = 115
var_e = var_c - var_d
print(int(var_e)) | 308 | 308 | 156 267 [OP_ADD] 115 [OP_SUB] | var_a = 156
var_b = 267
var_c = var_a + var_b
var_d = 115
var_e = var_c - var_d
print(int(var_e)) | 156 267 [OP_ADD] 115 [OP_SUB] | There are 156 pigs and 267 cows in the barn. If 115 of them were sold today, how many are left in the barn? | 축사에 돼지 156마리, 소 267마리가 있다. 이 중 115마리가 오늘 팔려 나갔다고 한다면 축사에는 몇 마리가 남아있는지 구하시오. | Arithmetic calculation |
var_a = 46
var_b = 2
var_c = var_a / var_b
var_d = 9
var_e = var_c - var_d
print(int(var_e)) | 14 | 14 | 46 2 [OP_DIV] 9 [OP_SUB] | var_a = 46
var_b = 2
var_c = var_a / var_b
var_d = 9
var_e = var_c - var_d
print(int(var_e)) | 46 2 [OP_DIV] 9 [OP_SUB] | You have a rectangular-shaped notebook with a circumference of 46 centimeters (cm) and a length of 9 centimeters (cm). How many centimeters (cm) is the width of this notebook? | 둘레가 46센티미터(㎝) 이고 세로가 9센티미터(㎝) 인 직사각형 모양의 수첩이 있습니다. 이 수첩의 가로는 몇 센티미터(㎝) 입니까? | Geometry |
var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort(... | 2 | 2 | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort(... | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | There are three numbers 10, 11, and 12. What is the difference between the largest number and the smallest number? | 3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 큰 수와 가장 작은 수의 차는 얼마입니까? | Arithmetic calculation |
var_a = '4A5B+C2D7=8070'
var_b = 'C'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a)... | 3 | 3 | 4A5B+C2D7=8070 C [OP_DIGIT_UNK_SOLVER] | var_a = '4A5B+C2D7=8070'
var_b = 'C'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a)... | 4A5B+C2D7=8070 C [OP_DIGIT_UNK_SOLVER] | There are four numbers A, B, C, and D. Find C from the four-digit addition formula 4A5B+C2D7=8070. | 네 수 A, B, C, D가 있습니다. 네 자리 수끼리의 덧셈식 4A5B+C2D7=8070에서 C를 구하시오. | Correspondence |
var_a = 36
var_b = 12
var_c = var_a - var_b
var_d = 7
var_e = var_c * var_d
var_f = 4
var_g = var_e / var_f
print(int(var_g)) | 42 | 42 | 36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV] | var_a = 36
var_b = 12
var_c = var_a - var_b
var_d = 7
var_e = var_c * var_d
var_f = 4
var_g = var_e / var_f
print(int(var_g)) | 36 12 [OP_SUB] 7 [OP_MUL] 4 [OP_DIV] | When we divide the product of 4 and a number by 7 and add 12, we get 36. Find this number | 4와 어떤 수의 곱을 7로 나누고 12를 더했더니 36이 되었습니다. 어떤 수를 구하세요. | Correspondence |
var_a = 11
var_b = 11
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) | 44 | 44 | 11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 11
var_b = 11
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) | 11 11 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | How many diagonals are there in a figure bounded by 11 sides? | 11개의 변으로 둘러싸인 도형의 대각선의 개수는 몇 개입니까? | Geometry |
var_a = '사과'
var_b = '귤'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 0.6
var_d = 0.49
list_b= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" in str(v... | 사과 | apple | [OP_LIST_SOL] 사과 귤 [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'apple'
var_b = 'orange'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 0.6
var_d = 0.49
list_b= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" ... | [OP_LIST_SOL] apple orange [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | There are two fruit crates. The apple box is 3/5 kilograms (kg) and the orange box is 0.49 kilograms (kg). Which box is the heavier of the two? | 두 개의 과일 상자가 있습니다. 사과 상자는 3/5킬로그램(㎏), 귤 상자는 0.49킬로그램(㎏)으로 둘 중 더 무거운 상자는 무엇입니까? | Comparison |
var_a = 13.5
var_b = 10
var_c = 3
var_d = var_b ** var_c
var_e = var_a * var_d
var_f = 0.01
var_g = 2
var_h = var_f ** var_g
var_i = var_e * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) | 1.35 | 1.35 | 13.5 10 3 [OP_POW] [OP_MUL] 1/100 2 [OP_POW] [OP_MUL] | var_a = 13.5
var_b = 10
var_c = 3
var_d = var_b ** var_c
var_e = var_a * var_d
var_f = 0.01
var_g = 2
var_h = var_f ** var_g
var_i = var_e * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) | 13.5 10 3 [OP_POW] [OP_MUL] 1/100 2 [OP_POW] [OP_MUL] | There are magic pencil cases, in which writing materials become 10 times longer when put in a gold pencil case, and 1/100 times longer when put in a silver pencil case. Kihoon put the 13.5 centimeters (cm) pencil in and out of the gold pencil case 3 times and the silver pencil case 2 times. How long is Kihoon's pencil ... | 마법 필통이 있습니다. 금색 필통에 필기구를 넣으면 길이가 10배가 되고, 은색 필통에 넣으면 길이가 1/100이 됩니다. 기훈이는 13.5센티미터(㎝)인 연필을 금색 주머니에 3번, 은색 주머니에 2번 넣었다 뺐습니다. 지금 기훈이의 연필은 몇 센티미터(㎝)입니까? | Arithmetic calculation |
var_a = 4
var_b = 4
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
print(int(var_c)) | 24 | 24 | 4 4 [OP_PERM] | var_a = 4
var_b = 4
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
print(int(var_c)) | 4 4 [OP_PERM] | You want to distribute 4 different ice creams to your friend. There are 4 friends: Kahi, Nahee, Dahee, and Rahee. How many cases are there? | 4개의 서로 다른 아이스크림을 친구에게 나누어주려고 한다. 친구는 가희, 나희, 다희, 라희 4명이 있다. 경우의 수는 몇 가지인가? | Possibility |
var_a = 8
var_b = 3
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 2.67 | 2.67 | 8 3 [OP_DIV] | var_a = 8
var_b = 3
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) | 8 3 [OP_DIV] | What is the side length in meters (m) of an equilateral triangle with a perimeter of 8 meters (m)? | 둘레의 길이가 8미터(m)인 정삼각형의 한 변의 길이는 몇 미터(m)입니까? | Geometry |
var_a = 3
var_b = 4
var_c = 6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | 3 | 3 | [OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 3
var_b = 4
var_c = 6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | [OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_LESS] [OP_LIST_LEN] | Given 3, 4, and 6, find the number of three-digit numbers less than 450, using all the given numbers once. | 3, 4, 6이 주어졌을 때, 주어진 수를 한 번씩 모두 사용하여 450보다 작은 세 자리 수의 개수를 구하시오. | Possibility |
var_a = 5
var_b = 7
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | 6 | 6 | [OP_LIST_SOL] 5 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 5
var_b = 7
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | [OP_LIST_SOL] 5 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | Given the number cards 5, 7, and 8, how many total three-digit numbers can be formed by using all of them? | 숫자카드 5, 7, 8이 있을 때 한 장씩 모두 사용하여 만들 수 있는 세 자리 자연수는 총 몇 개입니까? | Possibility |
var_a = '가'
var_b = '나'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1
var_d = 3
var_e = var_c / var_d
var_f = 4
var_g = 5
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
var... | 나 | B | [OP_LIST_SOL] 가 나 [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 4 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1
var_d = 3
var_e = var_c / var_d
var_f = 4
var_g = 5
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
var... | [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 4 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | You want to divide 1 liter (L) of water and 4 liters (L) of water equally into bottles of the same shape and size. If 1 liter (L) of water is divided equally into 3 A bottles, and 4 liters (L) of water is equally divided into 5 B bottles, which bottle has more water, bottle A or bottle B? | 물 1리터(L)와 물 4리터(L)를 모양과 크기가 같은 병에 각각 똑같이 나누어 담으려고 합니다. 물 1리터(L)를 병 가 3개에, 물 4리터(L)를 병 나 5개에 남김없이 똑같이 나누어 담을 때, 병 가와 병 나 중 어느 병에 물이 더 많을까요? | Comparison |
var_a = 4
var_b = 2
var_c = 4
var_d = var_b / var_c
var_e = var_a - var_d
var_f = 1
var_g = 3
var_h = var_f / var_g
var_i = 1
var_j = 4
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_e / var_l
var_n = 3
var_o = var_m / var_n
print(int(eval('{:.2f}'.format(round(var_o+1e-10,2))))) | 2 | 2 | 4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV] | var_a = 4
var_b = 2
var_c = 4
var_d = var_b / var_c
var_e = var_a - var_d
var_f = 1
var_g = 3
var_h = var_f / var_g
var_i = 1
var_j = 4
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_e / var_l
var_n = 3
var_o = var_m / var_n
print(int(eval('{:.2f}'.format(round(var_o+1e-10,2))))) | 4 2 4 [OP_DIV] [OP_SUB] 1 3 [OP_DIV] 1 4 [OP_DIV] [OP_ADD] [OP_DIV] 3 [OP_DIV] | When you walked around the school for the first time, you walked at 3 kilometers (km) per hour. For the second time, you walked 2 kilometers (km) more than the first time at the speed of 4 kilometers (km) per hour. If the walk took 4 hours in total, how much time would be taken for the first walk? | 학교를 돌 때 처음에는 시속 3킬로미터(㎞)로 걸었고, 두 번째는 그보다 2킬로미터(㎞) 더 걸은 대신 시속 4킬로미터(㎞)로 걸었다. 총 4시간이 걸렸다고 할 때, 처음 돌 때 걸린 시간은 얼마인가? | Arithmetic calculation |
var_a = 1.08
var_b = 1000
var_c = var_a * var_b
var_d = 13.5
var_e = var_c / var_d
var_f = 1
var_g = var_e + var_f
var_h = 2
var_i = var_g * var_h
print(int(var_i)) | 162 | 162 | 1.08 1000 [OP_MUL] 13.5 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL] | var_a = 1.08
var_b = 1000
var_c = var_a * var_b
var_d = 13.5
var_e = var_c / var_d
var_f = 1
var_g = var_e + var_f
var_h = 2
var_i = var_g * var_h
print(int(var_i)) | 1.08 1000 [OP_MUL] 13.5 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL] | We plan to plant street trees on both sides of the 1.08 kilometer (km) long road from beginning to end. How many street trees are needed to plant one tree every 13.5 meters (m)? | 길이가 1.08킬로미터(㎞)인 도로의 양쪽에 처음부터 끝까지 가로수를 심으려고 합니다. 13.5미터(m)마다 1그루씩 심으려면 가로수는 모두 몇 그루가 필요합니까? | Arithmetic calculation |
var_a = '정국'
var_b = '지민'
var_c = '윤기'
var_d = '유나'
var_e = '태형'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
va... | 60 | 60 | [OP_LIST_SOL] 정국 지민 윤기 유나 태형 [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM] | var_a = 'Jungkook'
var_b = 'Jimin'
var_c = 'Yoongi'
var_d = 'Yuna'
var_e = 'Taehyung'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" ... | [OP_LIST_SOL] Jungkook Jimin Yoongi Yuna Taehyung [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM] | Among Jungkook, Jimin, Yoongi, Yuna, and Taehyung, the class president, vice president, and public relations officer will be selected. What is the total number of possible cases? | 정국, 지민, 윤기, 유나, 태형 중에서 반장, 부사장, 홍보 담당자를 선발 할 예정이다. 가능한 총 케이스 수는 얼마입니까? | Possibility |
var_a = 8
var_b = 7
var_c = 9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d ... | 3 | 3 | [OP_LIST_SOL] 8 7 9 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB] | var_a = 8
var_b = 7
var_c = 9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d ... | [OP_LIST_SOL] 8 7 9 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB] | You want to choose two cards from the number cards with the numbers 8, 7, and 9 on them. Find how many possible cases there are. | 8, 7, 9이 적혀있는 숫자카드에서 2가지 카드를 고르려고 합니다. 가능한 경우의 수는 모두 몇 가지인지 구하시오. | Possibility |
var_a = 100000
var_b = 7000
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
print(int(var_e)) | 15 | 15 | 100000 7000 [OP_DIV] 1 [OP_CEIL] | var_a = 100000
var_b = 7000
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
print(int(var_e)) | 100000 7000 [OP_DIV] 1 [OP_CEIL] | Minsu wants to save 100,000 won. If he saves 7,000 won per day, how many days will it take for him to reach his goal? | 민수는 100000원을 저축하려고 합니다. 하루에 7000원씩 저축을 한다고 할 때, 며칠 후에 목표량을 채울 수 있을까요? | Arithmetic calculation |
var_a = 2
var_b = 3
var_c = 2
var_d = var_b * var_c
var_e = var_a + var_d
print(int(var_e)) | 8 | 8 | 2 3 2 [OP_MUL] [OP_ADD] | var_a = 2
var_b = 3
var_c = 2
var_d = var_b * var_c
var_e = var_a + var_d
print(int(var_e)) | 2 3 2 [OP_MUL] [OP_ADD] | Jia and Yujun had 3 forks each, so there are 2 left. How many forks were there initially? | 지아와 유준이는 포크를 3개씩 가졌더니 2개가 남았습니다. 처음에 있던 포크는 몇 개 입니까? | Arithmetic calculation |
var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
var_f = 1
var_g = var_e - var_f
print(int(var_g)) | 7 | 7 | 20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
var_f = 1
var_g = var_e - var_f
print(int(var_g)) | 20 11 [OP_SUB] 1 [OP_SUB] 1 [OP_SUB] | 20 students lined up in a single line. Jungkook is standing behind Yoongi, and 11 students are standing behind Jungkook. How many students are standing in front of Yoongi? | 20명의 학생들이 한 줄로 줄을 섰습니다. 윤기의 뒤에는 정국이가 서있고, 정국이 뒤에는 11명의 학생들이 서 있습니다. 윤기의 앞에 서 있는 학생은 몇 명입니까? | Comparison |
var_a = 3
var_b = 3
var_c = var_a * var_b
print(int(var_c)) | 9 | 9 | 3 3 [OP_MUL] | var_a = 3
var_b = 3
var_c = var_a * var_b
print(int(var_c)) | 3 3 [OP_MUL] | When you play a car game, you have to choose one character from three characters, and then one car from three cars. How many cases are there? | 자동차 게임을 할 때, 3명의 캐릭터 중 하나를 고르고, 다시 3개의 차 중 하나를 골라야 합니다. 경우의 수는 모두 몇 가지입니까? | Possibility |
var_a = 864
var_b = 6
var_c = var_a / var_b
var_d = 0.5
var_e = var_c ** var_d
print(int(var_e)) | 12 | 12 | 864 6 [OP_DIV] 1/2 [OP_POW] | var_a = 864
var_b = 6
var_c = var_a / var_b
var_d = 0.5
var_e = var_c ** var_d
print(int(var_e)) | 864 6 [OP_DIV] 1/2 [OP_POW] | There is a box in the shape of a cube with a surface area of 864 square centimeters (cm2). How many centimeters (cm) is the length of one side of this box? | 정육면체 모양의 겉넓이가 864제곱센티미터(㎠)인 상자가 있습니다. 이 상자의 한 변의 길이는 몇 센티미터(㎝)일까요? | Geometry |
var_a = 10
var_b = 10
var_c = 7
var_d = var_b - var_c
var_e = var_a * var_d
print(int(var_e)) | 30 | 30 | 10 10 7 [OP_SUB] [OP_MUL] | var_a = 10
var_b = 10
var_c = 7
var_d = var_b - var_c
var_e = var_a * var_d
print(int(var_e)) | 10 10 7 [OP_SUB] [OP_MUL] | I gave some ten 10 won coins to Yoongi, and there are 7 left. Find out how much he gave to Yoongi. | 10원짜리 동전 10개 중 몇개를 윤기에게 주었더니 7개가 남았습니다. 윤기에게 얼마를 주었는지 구하시오. | Arithmetic calculation |
var_a = 14
var_b = 2
var_c = var_a ** var_b
var_d = 8
var_e = 2
var_f = var_d * var_e
var_g = var_c // var_f
print(int(var_g)) | 12 | 12 | 14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV] | var_a = 14
var_b = 2
var_c = var_a ** var_b
var_d = 8
var_e = 2
var_f = var_d * var_e
var_g = var_c // var_f
print(int(var_g)) | 14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV] | Jihye holds a piece of colored paper in the shape of a square whose side is 14 centimeters (cm). When she cut it into rectangles that are 8 centimeters (cm) long and 2 centimeters (cm) wide. How many of these rectangular pieces of paper does she get at most? | 지혜는 한 변의 길이가 14센티미터(㎝)인 정사각형 모양의 색종이를 갖고 있습니다. 이 색종이를 가로가 8센티미터(㎝), 세로가 2센티미터(㎝)인 직사각형 모양으로 여러개 자르려고 합니다. 이러한 직사각형 모양의 종이 조각을 최대 몇 개 얻을 수 있습니까? | Geometry |
var_a = 10
var_b = 73
var_c = var_a * var_b
var_d = 1
var_e = var_c - var_d
var_f = 0.3333333333333333
var_g = var_e ** var_f
print(int(eval('{:.2f}'.format(round(var_g+1e-10,2))))) | 9 | 9 | 10 73 [OP_MUL] 1 [OP_SUB] 1/3 [OP_POW] | var_a = 10
var_b = 73
var_c = var_a * var_b
var_d = 1
var_e = var_c - var_d
var_f = 0.3333333333333333
var_g = var_e ** var_f
print(int(eval('{:.2f}'.format(round(var_g+1e-10,2))))) | 10 73 [OP_MUL] 1 [OP_SUB] 1/3 [OP_POW] | Find how many centimeters (cm) is the length of one corner of a cube whose volume is 1 square centimeter (cm2) less than a cuboid whose base is 10 square centimeter (cm2) and whose height is 73 centimeters (cm). | 밑면의 넓이가 10제곱센티미터(㎠)이고 높이가 73센티미터(㎝)인 직육면체보다 부피가 1세제곱센티미터(㎤) 더 적은 정육면체의 한 모서리의 길이는 몇 센티미터(㎝)인지 구하세요. | Geometry |
var_a = 16
var_b = 7
var_c = var_a / var_b
var_d = 6
var_e = var_c / var_d
var_f = 7
var_g = 6
var_h = var_f + var_g
var_i = var_e * var_h
var_j = 7
var_k = 6
var_l = var_j * var_k
var_m = var_i + var_l
var_n = 2
var_o = var_m * var_n
print('{:.2f}'.format(round(var_o+1e-10,2))) | 93.90 | 93.9 | 16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL] | var_a = 16
var_b = 7
var_c = var_a / var_b
var_d = 6
var_e = var_c / var_d
var_f = 7
var_g = 6
var_h = var_f + var_g
var_i = var_e * var_h
var_j = 7
var_k = 6
var_l = var_j * var_k
var_m = var_i + var_l
var_n = 2
var_o = var_m * var_n
print('{:.2f}'.format(round(var_o+1e-10,2))) | 16 7 [OP_DIV] 6 [OP_DIV] 7 6 [OP_ADD] [OP_MUL] 7 6 [OP_MUL] [OP_ADD] 2 [OP_MUL] | There is a doll in the shape of a rectangular cuboid. The volume of this doll is 16 square centimeters (cm2). And, the side facing the floor is 6 centimeters (cm) wide and 7 centimeters (cm) long. Find the total surface area of this doll. | 직육면체 모양의 인형이 있습니다. 이 인형의 부피는 16세제곱센티미터(㎤)입니다. 그리고, 바닥에 접한 면의 가로는 6센티미터(㎝), 세로는 7센티미터(㎝)입니다. 이 인형의 전체 겉넓이를 구하시오 | Geometry |
var_a = 180
var_b = 5
var_c = var_a / var_b
var_d = 5
var_e = 2
var_f = var_d // var_e
var_g = var_c + var_f
print(int(var_g)) | 38 | 38 | 180 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD] | var_a = 180
var_b = 5
var_c = var_a / var_b
var_d = 5
var_e = 2
var_f = var_d // var_e
var_g = var_c + var_f
print(int(var_g)) | 180 5 [OP_DIV] 5 2 [OP_FDIV] [OP_ADD] | The sum of 5 consecutive natural numbers is 180. Write the largest of these 5 numbers. | 5개의 연속된 자연수의 합이 180입니다. 이 5개의 수 중 가장 큰 수를 쓰시오. | Arithmetic calculation |
var_a = 1
var_b = 1000
var_c = var_a * var_b
var_d = 700
var_e = var_c + var_d
var_f = 900
var_g = var_e + var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) | 1300 | 1300 | 1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV] | var_a = 1
var_b = 1000
var_c = var_a * var_b
var_d = 700
var_e = var_c + var_d
var_f = 900
var_g = var_e + var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) | 1 1000 [OP_MUL] 700 [OP_ADD] 900 [OP_ADD] 2 [OP_DIV] | Yooseon wakes up in the morning and has a cold, so she decides to stop by the hospital and then go to school. It is 1 kilometer (km) 700 meters (m) from Yooseon’s house to the hospital, and the distance from the hospital to the school is 900 meters (m). How many meters (m) is the midway point of a distance starting fro... | 유선이는 아침에 일어났더니 감기 기운이 있어 병원에 들렀다 등교를 하기로 했습니다. 유선이네 집에서 병원까지는 1킬로미터(㎞) 700미터(m)이고, 병원에서 학교까지의 거리는 900미터(m)입니다. 유선이네 집에서 병원을 거쳐 학교까지 가는 거리의 중간 지점은 집에서부터 몇 미터(m)인지 구하시오. | Arithmetic calculation |
var_a = 18
var_b = 21
var_c = var_a + var_b
var_d = 23
var_e = var_c - var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g)) | 17 | 17 | 18 21 [OP_ADD] 23 [OP_SUB] 1 [OP_ADD] | var_a = 18
var_b = 21
var_c = var_a + var_b
var_d = 23
var_e = var_c - var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g)) | 18 21 [OP_ADD] 23 [OP_SUB] 1 [OP_ADD] | Jaehyun skipped 23 times and Seulgi jumped 19 times. Miran jumped rope 18 times in the first and 21 times in the second. In order for Jaehyun to jump rope more than Miran, at least how many times should he do in the second round? | 줄넘기를 재현이는 23번 했고, 슬기는 19번 했습니다. 미란이는 줄넘기를 1번째에 18번, 2번째에 21번 했습니다. 미란이보다 재현이가 줄넘기를 더 많이 하려면 2번째에는 적어도 몇 번을 해야 합니까? | Comparison |
var_a = '유승'
var_b = '신영'
var_c = '석기'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1.875
var_e = 2
var_f = 2.125... | 석기 | Seokgi | [OP_LIST_SOL] 유승 신영 석기 [OP_LIST_EOL] [OP_LIST_SOL] 15/8 2 17/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yooseung'
var_b = 'Shinyoung'
var_c = 'Seokgi'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1.875
var_e ... | [OP_LIST_SOL] Yooseung Shinyoung Seokgi [OP_LIST_EOL] [OP_LIST_SOL] 15/8 2 17/8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | Yooseung, Shinyoung, and Seokgi did the long jump. Yooseung jumped 15/8 meters (m), Shinyoung 2 meters (m), and Seokgi 17/8 meters (m). Who jumped the furthest? | 유승, 신영, 석기는 멀리뛰기를 하였습니다. 유승이는 15/8미터(m), 신영이는 2미터(m), 석기는 17/8미터(m)를 뛰었습니다. 가장 멀리 뛴 사람은 누구입니까? | Comparison |
var_a = 27
var_b = 46
var_c = var_a + var_b
var_d = 46
var_e = var_c * var_d
print(int(var_e)) | 3358 | 3358 | 27 46 [OP_ADD] 46 [OP_MUL] | var_a = 27
var_b = 46
var_c = var_a + var_b
var_d = 46
var_e = var_c * var_d
print(int(var_e)) | 27 46 [OP_ADD] 46 [OP_MUL] | 27 is subtracted from the quotient of a number divided by 46, which gives 46. Find the number. | 어떤 수를 46으로 나눈 몫에서 27을 뺐더니 46이 되었습니다. 어떤 수를 구하십시오. | Correspondence |
var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
var_f = 5
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c =... | 975 | 975 | [OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
var_f = 5
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c =... | [OP_LIST_SOL] 0 1 2 3 4 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM] | Choose two of the five numbers 0, 1, 2, 3, 4, and 5 to make a two-digit number. If you can use the same number multiple times, what is the sum of all possible numbers? | 다섯 개의 숫자 0, 1, 2, 3, 4 , 5 중에서 2개를 골라 두 자리의 수를 만들었다. 같은 수를 여러 번 사용해도 된다면, 만들 수 있는 모든 수들의 합은 얼마인가? | Possibility |
var_a = 82
var_b = 17
var_c = var_a + var_b
var_d = 73
var_e = var_c - var_d
print(int(var_e)) | 26 | 26 | 82 17 [OP_ADD] 73 [OP_SUB] | var_a = 82
var_b = 17
var_c = var_a + var_b
var_d = 73
var_e = var_c - var_d
print(int(var_e)) | 82 17 [OP_ADD] 73 [OP_SUB] | 17 more people got on the train with 82 people on it, and a few people got off. If 73 people were on the train, find how many people left the train. | 82명이 타고 있는 기차에 17명이 더 타고 몇 명이 내렸더니 73명이 되었습니다. 몇 명의 사람이 기차에서 내렸는지 구하시오. | Arithmetic calculation |
var_a = 3
var_b = 4
var_c = 6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | 3 | 3 | [OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 3
var_b = 4
var_c = 6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | [OP_LIST_SOL] 3 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 450 [OP_LIST_MORE] [OP_LIST_LEN] | When 3, 4, and 6 are given, find how many three-digit numbers using these three numbers exist, that is bigger than 450 | 3, 4, 6이 주어졌을 때, 주어진 수를 한 번씩 모두 사용하여 450보다 큰 세 자리 수의 개수를 구하시오. | Possibility |
var_a = '정국'
var_b = '윤기'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 6
var_d = 3
var_e = var_c // var_d
var_f = 4
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.... | 정국 | Jungkook | [OP_LIST_SOL] 정국 윤기 [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 6
var_d = 3
var_e = var_c // var_d
var_f = 4
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f... | [OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | Jungkook collected 6 divided by 3, and Yoongi collected 4. Who got the smaller number? | 정국이는 6에서 3을 나눈 몫 만큼 모았고, 윤기는 4를 모았습니다. 누가 더 작은 수를 모았습니까? | Comparison |
var_a = 3.1
var_b = 3.1
var_c = 2.81
var_d = var_b - var_c
var_e = 10
var_f = var_d * var_e
var_g = var_a - var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) | 0.20 | 0.2 | 3.1 3.1 2.81 [OP_SUB] 10 [OP_MUL] [OP_SUB] | var_a = 3.1
var_b = 3.1
var_c = 2.81
var_d = var_b - var_c
var_e = 10
var_f = var_d * var_e
var_g = var_a - var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) | 3.1 3.1 2.81 [OP_SUB] 10 [OP_MUL] [OP_SUB] | A box containing 10 apples of the same weight was weighed and found to be 3.1 kg (kg). After removing one apple from the box, it became 2.81 kilograms (kg). Find the weight in kilograms (kg) of the empty box. | 똑같은 무게의 사과 10개가 들어 있는 상자의 무게를 재었더니 3.1킬로그램(㎏)이었습니다. 이 상자에서 사과 1개를 빼낸 후 다시 무게를 재었더니 2.81킬로그램(㎏)이었습니다.빈 상자의 무게는 몇 킬로그램(㎏)인지 구해 보시오. | Arithmetic calculation |
var_a = 106
var_b = 600
var_c = 1000
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 7
var_g = 700
var_h = 1000
var_i = var_g / var_h
var_j = var_f + var_i
var_k = var_e + var_j
var_l = 4.8
var_m = 2
var_n = var_l * var_m
var_o = var_k + var_n
var_p = 3
var_q = var_o / var_p
print('{:.2f}'.format(round(var_q+1e-10,... | 41.30 | 41.3 | 106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV] | var_a = 106
var_b = 600
var_c = 1000
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 7
var_g = 700
var_h = 1000
var_i = var_g / var_h
var_j = var_f + var_i
var_k = var_e + var_j
var_l = 4.8
var_m = 2
var_n = var_l * var_m
var_o = var_k + var_n
var_p = 3
var_q = var_o / var_p
print('{:.2f}'.format(round(var_q+1e-10,... | 106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] [OP_ADD] 4.8 2 [OP_MUL] [OP_ADD] 3 [OP_DIV] | The total weight of one lion, one tiger, and one panda is 106 kilograms (kg) and 600 grams (g). A panda weighs 7 kilograms (kg) and 700 grams (g) less than a tiger, and a tiger weighs 4.8 kilograms (kg) less than a lion. How many kilograms (kg) does one lion weigh? | 사자 한 마리, 호랑이 한 마리, 판다 한 마리의 몸무게의 합은 106킬로그램(㎏) 600그램(g)입니다. 판다는 호랑이보다 7킬로그램(㎏) 700그램(g) 덜 나가고, 호랑이는 사자보다 4.8킬로그램(㎏) 덜 나갑니다. 사자 한 마리의 몸무게는 몇 킬로그램(㎏)입니까? | Arithmetic calculation |
var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) | 8 | 8 | 20 11 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) | 20 11 [OP_SUB] 1 [OP_SUB] | Yoongi is playing a game of throwing basketballs with his 20 friends. If 11 students scored less than Yoongi, how many students scored more than Yoongi? | 윤기는 20명의 친구들과 함께 농구공 많이 넣기 놀이를 하고 있습니다. 11명의 학생들이 윤기보다 공을 못 넣었을 때, 윤기보다 공을 많이 넣은 학생은 몇 명입니까? | Comparison |
var_a = 0.4
var_b = 10
var_c = var_a * var_b
print(int(var_c)) | 4 | 4 | 2/5 10 [OP_MUL] | var_a = 0.4
var_b = 10
var_c = var_a * var_b
print(int(var_c)) | 2/5 10 [OP_MUL] | A group of people wants to eat 2/5 of a watermelon per person. How many watermelons are needed to feed 10 people? | 한 사람당 수박을 2/5통씩 먹으려고 합니다. 10명이 먹기 위해서는 수박을 몇 통 사야 합니까? | Arithmetic calculation |
var_a = 25
var_b = 11
var_c = var_a - var_b
var_d = 1.75
var_e = 10
var_f = var_d / var_e
var_g = var_c / var_f
print(int(var_g)) | 80 | 80 | 25 11 [OP_SUB] 1.75 10 [OP_DIV] [OP_DIV] | var_a = 25
var_b = 11
var_c = var_a - var_b
var_d = 1.75
var_e = 10
var_f = var_d / var_e
var_g = var_c / var_f
print(int(var_g)) | 25 11 [OP_SUB] 1.75 10 [OP_DIV] [OP_DIV] | You have a candle that is 25 centimeters (cm) long. If this candle burns 1.75 centimeters (cm) in 10 minutes, how many minutes after lighting will it be 11 centimeters (cm) long? | 길이가 25센티미터(㎝)인 양초가 있습니다. 이 양초가 10분에 1.75센티미터(㎝)씩 탄다면 불을 붙인지 몇 분 후에 양초의 길이가 11센티미터(㎝)가 되겠습니까? | Arithmetic calculation |
var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_... | 0.80 | 0.8 | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] 1 [OP_LIST_MIN] | var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_... | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.7 [OP_LIST_MORE] 1 [OP_LIST_MIN] | Which of 0.8, 1/2, 0.9, 1/3 is the smallest number greater than 0.7? | 0.8, 1/2, 0.9, 1/3 중에서 0.7보다 큰 수 중 가장 작은 수는 무엇인가요? | Comparison |
var_a = 3
var_b = 100
var_c = 1000
var_d = var_b / var_c
var_e = 150
var_f = 1000
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(var_i)) | 12 | 12 | 3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV] | var_a = 3
var_b = 100
var_c = 1000
var_d = var_b / var_c
var_e = 150
var_f = 1000
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(var_i)) | 3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV] | Yeonjeong and Donghun started skating in opposite directions at the same time on a skating rink with a circumference of 3 km (km). If Yeonjeong skates at a speed of 100 meters (m) per minute and Donghun skates at a speed of 150 meters (m) per minute, find the two meet again for the first time in a few minutes. | 연정이와 동훈이는 스케이트를 타고, 둘레가 3킬로미터(㎞)인 스케이트장에서 동시에 서로 반대 방향으로 출발하였다. 연정이는 매분 100미터(m)의 속력으로, 동훈이는 매분 150미터(m)의 속력으로 스케이트를 타면 몇 분 후에 처음으로 두 사람이 다시 만나는지 구하여라 | Arithmetic calculation |
var_a = 7
var_b = 15
var_c = var_a * var_b
print(int(var_c)) | 105 | 105 | 7 15 [OP_MUL] | var_a = 7
var_b = 15
var_c = var_a * var_b
print(int(var_c)) | 7 15 [OP_MUL] | A and B are two different natural numbers. When A is divided by 7, the quotient is 15 and the remainder is B. Find A when B is the smallest possible number. | A, B는 서로 다른 두 자연수입니다. A를 7로 나누면 몫은 15, 나머지는 B입니다. B가 될 수 있는 수 중에 가장 작은 수 일때 A를 구하시오. | Correspondence |
var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | 1542 | 1542 | [OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD] | var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
li... | [OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD] | There are toys with 1, 6 and 8 drawn on them. Let's say the first one Rowoon chooses is the hundred's place, the second is the tens' place, and the third is the ones' place. Find the sum of the largest number and the third largest number that Rowoon can make. However, Rowwon cannot select the same toy multiple times. | 1, 6, 8이 그려진 장난감이 있습니다. 로운이가 처음 고르는 것을 백의 자리, 두 번째는 십의 자리, 세 번째는 일의 자리라고 할 때, 로운이가 만들 수 있는 수 중 가장 큰 수와 세 번째로 큰 수의 합을 구하시오. 단, 같은 장난감을 여러 번 고를 수 없습니다. | Possibility |
var_a = 502
var_b = 18
var_c = 57
var_d = var_b + var_c
var_e = 44
var_f = var_d - var_e
var_g = var_a - var_f
var_h = 17
var_i = var_g + var_h
var_j = 2
var_k = var_i / var_j
print(int(var_k)) | 244 | 244 | 502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV] | var_a = 502
var_b = 18
var_c = 57
var_d = var_b + var_c
var_e = 44
var_f = var_d - var_e
var_g = var_a - var_f
var_h = 17
var_i = var_g + var_h
var_j = 2
var_k = var_i / var_j
print(int(var_k)) | 502 18 57 [OP_ADD] 44 [OP_SUB] [OP_SUB] 17 [OP_ADD] 2 [OP_DIV] | There are red balls and blue balls in the box with blue balls being 17 more than the red balls. Minsu put in 57 blue balls and 18 red balls and subtracted 44 balls. When you checked the inside of the box and there were 502 balls in total, find the number of blue balls that were in the box at the beginning. | 상자 안에 빨간공과 빨간공 보다 17개 더 많은 파란공이 있습니다. 민수가 파란공 57개, 빨간공 18개를 넣고 44개를 뺐습니다. 상자 안을 확인해보니 총 502개의 공이 있었을 때, 처음 상자 안에 있던 파란공의 개수를 구하시오. | Comparison |
var_a = 1.05
var_b = 460
var_c = 1000
var_d = var_b / var_c
var_e = var_a - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) | 0.59 | 0.59 | 1.05 460 1000 [OP_DIV] [OP_SUB] | var_a = 1.05
var_b = 460
var_c = 1000
var_d = var_b / var_c
var_e = var_a - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) | 1.05 460 1000 [OP_DIV] [OP_SUB] | Taehong's distance from school to home is 460 meters (m) farther than Jiwon's. If the distance from Taehong's house to the school is 1.05 kilometers (km), how many kilometers (km) is it from Jiwon's house to the school? | 태홍이는 지원이보다 학교에서 집까지의 거리가 460미터(m) 멉니다. 태홍이네 집에서 학교까지의 거리가 1.05킬로미터(㎞)일 때, 지원이네 집에서 학교까지는 몇 킬로미터(㎞)입니까? | Arithmetic calculation |
var_a = 0.9333333333333333
var_b = 2
var_c = var_a * var_b
var_d = 0.1
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) | 1.77 | 1.77 | 14/15 2 [OP_MUL] 1/10 [OP_SUB] | var_a = 0.9333333333333333
var_b = 2
var_c = var_a * var_b
var_d = 0.1
var_e = var_c - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) | 14/15 2 [OP_MUL] 1/10 [OP_SUB] | If the weight of the heavy box is 14/15 kg (kg), and the light box is 1/10 kg (kg) lighter than the heavy box, find the sum of the weights of the two boxes in kg (kg). | 무거운 상자의 무게가 14/15킬로그램(㎏)이고, 가벼운 상자의 무게는 무거운 상자의 무게보다 1/10킬로그램(㎏) 더 가볍다면 이때 두 상자의 무게의 합은 몇 킬로그램(㎏)인지 구하시오. | Arithmetic calculation |
var_a = 100
var_b = 1000
var_c = 1
var_d = var_b - var_c
var_e = 1
list_a = [i for i in range(var_a, var_d + 1, var_e)]
list_b=[]
for i in list_a:
var_f = 0
i = int(i)
while i//10 > 0:
var_f = var_f + i%10
i = i//10
var_f = var_f + i%10
list_b.append(var_f)
var_g = 25
list_c = []
for... | 6 | 6 | 100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 25 [OP_LIST_MORE_EQUAL] 25 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 100
var_b = 1000
var_c = 1
var_d = var_b - var_c
var_e = 1
list_a = [i for i in range(var_a, var_d + 1, var_e)]
list_b=[]
for i in list_a:
var_f = 0
i = int(i)
while i//10 > 0:
var_f = var_f + i%10
i = i//10
var_f = var_f + i%10
list_b.append(var_f)
var_g = 25
list_c = []
for... | 100 1000 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 25 [OP_LIST_MORE_EQUAL] 25 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | How many three-digit numbers are there where the sum of all the digits is 25? | 모든 자리 수의 합이 25인 세 자리 수는 모두 몇 개입니까? | Possibility |
var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval... | 1 | 1 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval... | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_FDIV] | There are five numbers 10, 11, 12, 13, and 14. What is the quotient when you divide the largest number by the second smallest number? | 5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수를 2번째로 작은 수로 나눈 몫은 얼마입니까? | Arithmetic calculation |
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