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SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > (SELECT avg(rating) FROM review)
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CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (rating INTEGER)
|
查找评级高于所有项目的平均评级的项目的标题。
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
|
CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (i_id VARCHAR, rating INTEGER)
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找到任何评分低于5的项目的标题。
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating > 8 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rating < 5
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CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (i_id VARCHAR, rating INTEGER)
|
查找同时获得高于8和低于5的评分的项目的标题。
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id WHERE T2.rank > 3 INTERSECT SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id HAVING avg(T2.rating) > 5
|
CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (rating INTEGER, i_id VARCHAR, rank INTEGER)
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查找评分高于3且平均评分高于5的项目的名称。
|
SELECT T1.title FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) LIMIT 1
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CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (i_id VARCHAR, rating INTEGER)
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查找具有最低平均评分的项目的名称。
|
SELECT title FROM item ORDER BY title
|
CREATE TABLE item (title VARCHAR)
|
按字母顺序列出所有项目的标题。
|
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id ORDER BY count(*) DESC LIMIT 1
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CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE review (u_id VARCHAR)
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查找提供最多评论的用户的名称。
|
SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rating) DESC LIMIT 1
|
CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (i_id VARCHAR, rating INTEGER)
|
查找具有最高平均评级的项目的名称和ID。
|
SELECT T1.title , T1.i_id FROM item AS T1 JOIN review AS T2 ON T1.i_id = T2.i_id GROUP BY T2.i_id ORDER BY avg(T2.rank) DESC LIMIT 1
|
CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (i_id VARCHAR, rank INTEGER)
|
找出具有最高平均评分的项目的名称和ID。
|
SELECT T1.name , avg(T2.rating) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
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CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE review (u_id VARCHAR, rating INTEGER)
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对于每个用户，返回他们给出的评论的名称和平均评级。
|
SELECT T1.name , count(*) FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id GROUP BY T2.u_id
|
CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE review (u_id VARCHAR)
|
对于每个用户，找到他们的名字和他们写的评论的数量。
|
SELECT T1.name FROM useracct AS T1 JOIN review AS T2 ON T1.u_id = T2.u_id ORDER BY T2.rating DESC LIMIT 1
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CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE review (u_id VARCHAR, rating VARCHAR)
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找到最高评级的用户的名字。
|
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.source_u_id GROUP BY T2.source_u_id ORDER BY avg(trust) DESC LIMIT 1
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CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE trust (source_u_id VARCHAR)
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查找具有最高平均信任分数的源用户的名称。
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SELECT T1.name , avg(trust) FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id GROUP BY T2.target_u_id
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CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE trust (target_u_id VARCHAR)
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查找每个目标用户的姓名和平均信任分数。
|
SELECT T1.name FROM useracct AS T1 JOIN trust AS T2 ON T1.u_id = T2.target_u_id ORDER BY trust LIMIT 1
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CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE trust (target_u_id VARCHAR)
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查找最低信任分数的目标用户的姓名。
|
SELECT title FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
|
CREATE TABLE item (i_id VARCHAR, title VARCHAR), CREATE TABLE review (i_id VARCHAR, title VARCHAR)
|
查找没有收到任何评论的项目的名称。
|
SELECT name FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
|
CREATE TABLE useracct (u_id VARCHAR, name VARCHAR), CREATE TABLE review (u_id VARCHAR, name VARCHAR)
|
查找没有留下任何评论的用户的姓名。
|
SELECT count(*) FROM useracct WHERE u_id NOT IN (SELECT u_id FROM review)
|
CREATE TABLE useracct (u_id VARCHAR), CREATE TABLE review (u_id VARCHAR)
|
找到没有写任何评论的用户的数量。
|
SELECT count(*) FROM item WHERE i_id NOT IN (SELECT i_id FROM review)
|
CREATE TABLE item (i_id VARCHAR), CREATE TABLE review (i_id VARCHAR)
|
查找没有任何评论的项目的数量。
|
SELECT count(*) FROM player
|
CREATE TABLE player (Id VARCHAR)
|
有多少运动员？
|
SELECT Player_name FROM player ORDER BY Votes ASC
|
CREATE TABLE player (Votes VARCHAR, Player_name VARCHAR)
|
按升序排列运动员的名字。
|
SELECT Gender , Occupation FROM player
|
CREATE TABLE player (Occupation VARCHAR, Gender VARCHAR)
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运动员的性别和职业是什么？
|
SELECT Player_name , residence FROM player WHERE Occupation != "研究员"
|
CREATE TABLE player (residence VARCHAR, Occupation VARCHAR, Player_name VARCHAR)
|
列出职业不是“研究员”的运动员的姓名和住所。
|
SELECT Sponsor_name FROM player WHERE Residence = "池" OR Residence = "皓"
|
CREATE TABLE player (Residence VARCHAR, Sponsor_name VARCHAR)
|
显示住在“池”或“皓”的球员的赞助商的名字。
|
SELECT Player_name FROM player ORDER BY Votes DESC LIMIT 1
|
CREATE TABLE player (Votes VARCHAR, Player_name VARCHAR)
|
票数最多的运动员叫什么名字？
|
SELECT Occupation , COUNT(*) FROM player GROUP BY Occupation
|
CREATE TABLE player (Occupation VARCHAR)
|
显示不同的职业和每个职业运动员的数量。
|
SELECT Occupation FROM player GROUP BY Occupation ORDER BY COUNT(*) DESC LIMIT 1
|
CREATE TABLE player (Occupation VARCHAR)
|
请显示最常见的运动员职业。
|
SELECT Residence FROM player GROUP BY Residence HAVING COUNT(*) >= 2
|
CREATE TABLE player (Residence VARCHAR)
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显示至少有两个运动员的住址。
|
SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID
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CREATE TABLE player_coach (Player_ID VARCHAR, Coach_ID VARCHAR), CREATE TABLE coach (Coach_ID VARCHAR, coach_name VARCHAR), CREATE TABLE player (Player_ID VARCHAR, Player_name VARCHAR)
|
显示运动员姓名和教练员姓名。
|
SELECT T3.Player_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T2.Rank = 1
|
CREATE TABLE player_coach (Player_ID VARCHAR, Coach_ID VARCHAR), CREATE TABLE coach (Rank VARCHAR, Coach_ID VARCHAR), CREATE TABLE player (Player_ID VARCHAR, Player_name VARCHAR)
|
显示排名第1的教练执教的球员的名字。
|
SELECT T3.Player_name , T3.gender FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID WHERE T1.Starting_year > 2011
|
CREATE TABLE player_coach (Player_ID VARCHAR, Starting_year INTEGER, Coach_ID VARCHAR), CREATE TABLE coach (Coach_ID VARCHAR), CREATE TABLE player (Player_ID VARCHAR, Player_name VARCHAR, gender VARCHAR)
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显示2011年后开始有教练的球员的名字和性别。
|
SELECT T3.Player_name , T2.coach_name FROM player_coach AS T1 JOIN coach AS T2 ON T1.Coach_ID = T2.Coach_ID JOIN player AS T3 ON T1.Player_ID = T3.Player_ID ORDER BY T3.Votes DESC
|
CREATE TABLE player_coach (Player_ID VARCHAR, Coach_ID VARCHAR), CREATE TABLE coach (Coach_ID VARCHAR, coach_name VARCHAR), CREATE TABLE player (Player_ID VARCHAR, Votes VARCHAR, Player_name VARCHAR)
|
按照选手投票的降序，显示选手姓名和教练姓名。
|
SELECT Player_name FROM player WHERE Player_ID NOT IN (SELECT Player_ID FROM player_coach)
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CREATE TABLE player (Player_ID VARCHAR, Player_name VARCHAR), CREATE TABLE player_coach (Player_ID VARCHAR, Player_name VARCHAR)
|
列出没有教练的运动员的名字。
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SELECT Residence FROM player WHERE gender = "男" INTERSECT SELECT Residence FROM player WHERE gender = "女"
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CREATE TABLE player (Residence VARCHAR, gender VARCHAR)
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显示既有性别为“男”又有性别为“女”的运动员的住址。
|
SELECT T1.club_id , T1.club_name, count(*) FROM club AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id
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CREATE TABLE club (club_id VARCHAR, club_name VARCHAR), CREATE TABLE coach (club_id VARCHAR)
|
每个俱乐部有多少教练？列出教练员的ID、姓名和教练员数量。
|
SELECT T1.club_id , T1.gold FROM match_result AS T1 JOIN coach AS T2 ON T1.club_id = T2.club_id GROUP BY T1.club_id ORDER BY count(*) DESC LIMIT 1
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CREATE TABLE match_result (gold VARCHAR, club_id VARCHAR), CREATE TABLE coach (club_id VARCHAR)
|
拥有最多教练的俱乐部有多少枚金牌？
|
SELECT count(*) FROM gymnast
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CREATE TABLE gymnast (Id VARCHAR)
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有多少体操运动员？
|
SELECT count(*) FROM gymnast
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CREATE TABLE gymnast (Id VARCHAR)
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计算体操运动员的数量。
|
SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
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CREATE TABLE gymnast (Total_Points VARCHAR)
|
按降序，列出体操运动员的总分。
|
SELECT Total_Points FROM gymnast ORDER BY Total_Points DESC
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CREATE TABLE gymnast (Total_Points VARCHAR)
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按降序排列，所有体操运动员的总分是多少？
|
SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
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CREATE TABLE gymnast (Floor_Exercise_Points VARCHAR, Total_Points VARCHAR)
|
按自由体操点数降序列出体操运动员的总分。
|
SELECT Total_Points FROM gymnast ORDER BY Floor_Exercise_Points DESC
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CREATE TABLE gymnast (Floor_Exercise_Points VARCHAR, Total_Points VARCHAR)
|
体操运动员按自由体操点数的下降顺序，总分是多少？
|
SELECT avg(Horizontal_Bar_Points) FROM gymnast
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CREATE TABLE gymnast (Horizontal_Bar_Points INTEGER)
|
所有体操运动员的平均单杠得分是多少？
|
SELECT avg(Horizontal_Bar_Points) FROM gymnast
|
CREATE TABLE gymnast (Horizontal_Bar_Points INTEGER)
|
返回所有体操运动员的平均单杠得分。
|
SELECT Name FROM People ORDER BY Name ASC
|
CREATE TABLE People (Name VARCHAR)
|
按字母顺序排列的人的名字是什么？
|
SELECT Name FROM People ORDER BY Name ASC
|
CREATE TABLE People (Name VARCHAR)
|
按字母顺序排列人名。
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Name VARCHAR)
|
体操运动员的名字是什么？
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Name VARCHAR)
|
返回体操运动员的名字。
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "洛阳"
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Name VARCHAR, Hometown VARCHAR)
|
家乡不是“洛阳”的体操运动员的名字是什么？
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T2.Hometown != "洛阳"
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CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Name VARCHAR, Hometown VARCHAR)
|
返回不是在“洛阳”长大的体操运动员的名字。
|
SELECT Age FROM people ORDER BY Height DESC LIMIT 1
|
CREATE TABLE people (Height VARCHAR, Age VARCHAR)
|
最高的人年龄是多少岁？
|
SELECT Age FROM people ORDER BY Height DESC LIMIT 1
|
CREATE TABLE people (Height VARCHAR, Age VARCHAR)
|
返回身高最大的人的年龄。
|
SELECT Name FROM People ORDER BY Age DESC LIMIT 5
|
CREATE TABLE People (Name VARCHAR, Age VARCHAR)
|
列出5个最老的人的名字。
|
SELECT Name FROM People ORDER BY Age DESC LIMIT 5
|
CREATE TABLE People (Name VARCHAR, Age VARCHAR)
|
五个最老的人的名字是什么？
|
SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR, Total_Points VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
|
最年轻的体操运动员的总得分是多少？
|
SELECT T1.Total_Points FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Age ASC LIMIT 1
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR, Total_Points VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
|
返回最年轻的体操运动员的总得分。
|
SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age INTEGER)
|
所有体操运动员的平均年龄是多少？
|
SELECT avg(T2.Age) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age INTEGER)
|
返回所有体操运动员的平均年龄。
|
SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR, Total_Points INTEGER), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
|
总得分超过57.5的体操运动员的不同家乡是什么？
|
SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID WHERE T1.Total_Points > 57.5
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR, Total_Points INTEGER), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
|
给出总分在57.5以上的体操运动员的不同家乡。
|
SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
|
体操运动员的家乡和体操运动员的数量是多少？
|
SELECT T2.Hometown , COUNT(*) FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
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每个家乡有多少体操运动员？
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
|
体操运动员最多的家乡是什么？
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown ORDER BY COUNT(*) DESC LIMIT 1
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CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
|
返回体操运动员中最多的家乡。
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
|
哪些家乡有至少两名体操运动员？
|
SELECT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID GROUP BY T2.Hometown HAVING COUNT(*) >= 2
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR)
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给我两个或更多体操运动员来自的家乡。
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
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CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Height VARCHAR, Name VARCHAR)
|
按身高顺序排列体操运动员的名字。
|
SELECT T2.Name FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T2.Height ASC
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR), CREATE TABLE people (People_ID VARCHAR, Height VARCHAR, Name VARCHAR)
|
按照身高排序，体操运动员的名字是什么？
|
SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
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CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR), CREATE TABLE gymnast (Gymnast_ID VARCHAR)
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列出没有体操运动员的不同家乡。
|
SELECT DISTINCT Hometown FROM people EXCEPT SELECT DISTINCT T2.Hometown FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID
|
CREATE TABLE people (Hometown VARCHAR, People_ID VARCHAR), CREATE TABLE gymnast (Gymnast_ID VARCHAR)
|
哪一个家乡没有体操运动员？
|
SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
|
CREATE TABLE people (Hometown VARCHAR, Age INTEGER)
|
展示有23岁以上和20岁以下的人的家乡。
|
SELECT Hometown FROM people WHERE Age > 23 INTERSECT SELECT Hometown FROM people WHERE Age < 20
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CREATE TABLE people (Hometown VARCHAR, Age INTEGER)
|
哪个家乡有23岁以上和20岁以下的人？
|
SELECT count(DISTINCT Hometown) FROM people
|
CREATE TABLE people (Hometown VARCHAR)
|
这些人有多少不同的家乡？
|
SELECT count(DISTINCT Hometown) FROM people
|
CREATE TABLE people (Hometown VARCHAR)
|
数一数这些人的不同家乡。
|
SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
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CREATE TABLE gymnast (Gymnast_ID VARCHAR, Total_Points VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
|
以总分递减顺序显示体操运动员的年龄。
|
SELECT T2.Age FROM gymnast AS T1 JOIN people AS T2 ON T1.Gymnast_ID = T2.People_ID ORDER BY T1.Total_Points DESC
|
CREATE TABLE gymnast (Gymnast_ID VARCHAR, Total_Points VARCHAR), CREATE TABLE people (People_ID VARCHAR, Age VARCHAR)
|
按它们总得分降序，体操运动员的年龄是多少？
|
SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != '小智'
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE savings (custid VARCHAR, balance INTEGER)
|
找出除了名为“小智”的账户的所有账户的总储蓄余额。
|
SELECT sum(T2.balance) FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T1.name != '小智'
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CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE savings (custid VARCHAR, balance INTEGER)
|
不属于“小智”这个名字的人的储蓄账户的总储蓄余额是多少？
|
SELECT count(*) FROM accounts
|
CREATE TABLE accounts (Id VARCHAR)
|
总共有多少个帐户？
|
SELECT count(*) FROM accounts
|
CREATE TABLE accounts (Id VARCHAR)
|
计算账户数量。
|
SELECT sum(balance) FROM checking
|
CREATE TABLE checking (balance INTEGER)
|
所有帐户的总储蓄余额是多少？
|
SELECT sum(balance) FROM checking
|
CREATE TABLE checking (balance INTEGER)
|
找到在支票账户上的总储蓄余额。
|
SELECT avg(balance) FROM checking
|
CREATE TABLE checking (balance INTEGER)
|
找到平均支票余额。
|
SELECT avg(balance) FROM checking
|
CREATE TABLE checking (balance INTEGER)
|
支票账户的平均余额是多少？
|
SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
|
CREATE TABLE savings (balance INTEGER)
|
有多少账户储蓄余额高于平均储蓄余额？
|
SELECT count(*) FROM savings WHERE balance > (SELECT avg(balance) FROM savings)
|
CREATE TABLE savings (balance INTEGER)
|
查找存款余额高于平均存款余额的账户数量。
|
SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (balance INTEGER)
|
查找支票余额低于最大支票余额的帐户的名称和id。
|
SELECT T1.custid , T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT max(balance) FROM checking)
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (balance INTEGER)
|
支票余额小于最大支票余额的账户相对应的客户ID和名称是什么？
|
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '怡'
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance VARCHAR)
|
所有名字包含“怡”的所有者的账户支票余额是什么？
|
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name LIKE '怡'
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance VARCHAR)
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找到属于名称包含“怡”的所有者的支票账户余额。
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SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = '小智'
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CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance VARCHAR), CREATE TABLE savings (custid VARCHAR, balance VARCHAR)
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查找“小智”账户的支票余额和储蓄余额。
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SELECT T2.balance , T3.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid WHERE T1.name = '小智'
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CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance VARCHAR), CREATE TABLE savings (custid VARCHAR, balance VARCHAR)
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“小智”账户中的支票余额和储蓄余额是多少？
|
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
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CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (balance INTEGER), CREATE TABLE savings (balance INTEGER)
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查找支票余额高于平均支票余额但储蓄余额低于平均储蓄余额的帐户的名称。
|
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM checking) INTERSECT SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance < (SELECT avg(balance) FROM savings)
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (balance INTEGER), CREATE TABLE savings (balance INTEGER)
|
支票余额大于平均支票余额而储蓄余额低于平均储蓄余额的账户的名称是什么？
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SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
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CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance INTEGER), CREATE TABLE savings (balance INTEGER)
|
查找存款余额高于平均存款余额的账户的支票余额。
|
SELECT T2.balance FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid WHERE T1.name IN (SELECT T1.name FROM accounts AS T1 JOIN savings AS T2 ON T1.custid = T2.custid WHERE T2.balance > (SELECT avg(balance) FROM savings))
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance INTEGER), CREATE TABLE savings (balance INTEGER)
|
属于储蓄余额大于平均储蓄余额的人的支票账户的余额是多少？
|
SELECT name FROM accounts ORDER BY name
|
CREATE TABLE accounts (name VARCHAR)
|
按照字母序列出所有客户的名字。
|
SELECT name FROM accounts ORDER BY name
|
CREATE TABLE accounts (name VARCHAR)
|
按字母顺序排列的所有客户的名字是什么？
|
SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1
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CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance VARCHAR), CREATE TABLE savings (custid VARCHAR, balance VARCHAR)
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查找具有最低支票和储蓄总余额的帐户名称。
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SELECT T1.name FROM accounts AS T1 JOIN checking AS T2 ON T1.custid = T2.custid JOIN savings AS T3 ON T1.custid = T3.custid ORDER BY T2.balance + T3.balance LIMIT 1
|
CREATE TABLE accounts (custid VARCHAR, name VARCHAR), CREATE TABLE checking (custid VARCHAR, balance VARCHAR), CREATE TABLE savings (custid VARCHAR, balance VARCHAR)
|
支票和储蓄余额总额最低的账户对应的名称是什么？
|
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