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SELECT count(*) FROM Person WHERE gender = '女'
|
CREATE TABLE Person (gender VARCHAR)
|
这个网络有多少“女”？
|
SELECT count(*) FROM Person WHERE gender = '女'
|
CREATE TABLE Person (gender VARCHAR)
|
网络中性别是“女”的人数有多少？
|
SELECT avg(age) FROM Person
|
CREATE TABLE Person (age INTEGER)
|
所有人的平均年龄是多少？
|
SELECT avg(age) FROM Person
|
CREATE TABLE Person (age INTEGER)
|
表格中所有人的平均年龄是多少？
|
SELECT count(DISTINCT city) FROM Person
|
CREATE TABLE Person (city VARCHAR)
|
他们来自多少个不同的城市？
|
SELECT count(DISTINCT city) FROM Person
|
CREATE TABLE Person (city VARCHAR)
|
人们的故乡来自于多少个不同的城市？
|
SELECT count(DISTINCT job) FROM Person
|
CREATE TABLE Person (job VARCHAR)
|
他们有多少种工作？
|
SELECT count(DISTINCT job) FROM Person
|
CREATE TABLE Person (job VARCHAR)
|
列出了多少份不同的工作？
|
SELECT name FROM Person WHERE age = (SELECT max(age) FROM person)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE person (name VARCHAR, age INTEGER)
|
谁是最老的人？
|
SELECT name FROM Person WHERE age = (SELECT max(age) FROM person)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE person (name VARCHAR, age INTEGER)
|
最老的人叫什么名字？
|
SELECT name FROM Person WHERE job = '学生' AND age = (SELECT max(age) FROM person WHERE job = '学生' )
|
CREATE TABLE Person (age INTEGER, name VARCHAR, job VARCHAR), CREATE TABLE person (age INTEGER, name VARCHAR, job VARCHAR)
|
谁是年龄最大的“学生”？
|
SELECT name FROM Person WHERE job = '学生' AND age = (SELECT max(age) FROM person WHERE job = '学生' )
|
CREATE TABLE Person (age INTEGER, name VARCHAR, job VARCHAR), CREATE TABLE person (age INTEGER, name VARCHAR, job VARCHAR)
|
年龄最大的“学生”叫什么名字？
|
SELECT name FROM Person WHERE gender = '男' AND age = (SELECT min(age) FROM person WHERE gender = '男' )
|
CREATE TABLE Person (name VARCHAR, age INTEGER, gender VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, gender VARCHAR)
|
谁是最年轻的“男”？
|
SELECT name FROM Person WHERE gender = '男' AND age = (SELECT min(age) FROM person WHERE gender = '男' )
|
CREATE TABLE Person (name VARCHAR, age INTEGER, gender VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, gender VARCHAR)
|
最年轻的“男”叫什么名字？
|
SELECT age FROM Person WHERE job = '医生' AND name = '仲景'
|
CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR)
|
名字叫“仲景”的“医生”年纪多大了？
|
SELECT age FROM Person WHERE job = '医生' AND name = '仲景'
|
CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR)
|
那个叫“仲景”的“医生”的年龄是多少岁？
|
SELECT name FROM Person WHERE age < 30
|
CREATE TABLE Person (name VARCHAR, age INTEGER)
|
年龄低于30岁的人是谁？
|
SELECT name FROM Person WHERE age < 30
|
CREATE TABLE Person (name VARCHAR, age INTEGER)
|
年龄在30岁以下的人叫什么名字？
|
SELECT count(*) FROM Person WHERE age > 30 AND job = '摄影师'
|
CREATE TABLE Person (age INTEGER, job VARCHAR)
|
有多少人年龄大于30且工作是“摄影师”？
|
SELECT count(*) FROM Person WHERE age > 30 AND job = '摄影师'
|
CREATE TABLE Person (age INTEGER, job VARCHAR)
|
有多少“摄影师”的年龄超过30岁？
|
SELECT avg(age) , gender FROM Person GROUP BY gender
|
CREATE TABLE Person (age INTEGER, gender VARCHAR)
|
每个性别的平均年龄是多少？
|
SELECT avg(age) , gender FROM Person GROUP BY gender
|
CREATE TABLE Person (age INTEGER, gender VARCHAR)
|
每个性别的平均年龄有多大？
|
SELECT avg(age) , job FROM Person GROUP BY job
|
CREATE TABLE Person (age INTEGER, job VARCHAR)
|
不同工作职称的平均年龄是多少？
|
SELECT avg(age) , job FROM Person GROUP BY job
|
CREATE TABLE Person (age INTEGER, job VARCHAR)
|
每个工作的平均年龄是多少？
|
SELECT avg(age) , job FROM Person WHERE gender = '男' GROUP BY job
|
CREATE TABLE Person (age INTEGER, job VARCHAR, gender VARCHAR)
|
不同职称的“男”的平均年龄是多少？
|
SELECT avg(age) , job FROM Person WHERE gender = '男' GROUP BY job
|
CREATE TABLE Person (age INTEGER, job VARCHAR, gender VARCHAR)
|
每个工作的“男”平均年龄是多少？
|
SELECT min(age) , job FROM Person GROUP BY job
|
CREATE TABLE Person (age INTEGER, job VARCHAR)
|
不同职称的最低年龄是多少？
|
SELECT min(age) , job FROM Person GROUP BY job
|
CREATE TABLE Person (age INTEGER, job VARCHAR)
|
每个工作年龄最小的人的年纪有多大？
|
SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender
|
CREATE TABLE Person (age INTEGER, gender VARCHAR)
|
找到每个性别中年龄低于40岁的人的数量。
|
SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender
|
CREATE TABLE Person (age INTEGER, gender VARCHAR)
|
每个性别有多少人不足40岁？
|
SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = '摄影师') ORDER BY age
|
CREATE TABLE Person (name VARCHAR, age INTEGER, job VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, job VARCHAR)
|
按年龄排序找出年龄比任何“摄影师”年龄都大的人的名字。
|
SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = '摄影师') ORDER BY age
|
CREATE TABLE Person (name VARCHAR, age INTEGER, job VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, job VARCHAR)
|
所有比至少一个“摄影师”年龄大的人的名字是什么？按年龄顺序排序。
|
SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = '摄影师')
|
CREATE TABLE Person (age INTEGER, job VARCHAR), CREATE TABLE person (age INTEGER, job VARCHAR)
|
找出年龄大于所有“摄影师”年龄的人数。
|
SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = '摄影师')
|
CREATE TABLE Person (age INTEGER, job VARCHAR), CREATE TABLE person (age INTEGER, job VARCHAR)
|
有多少人比每个“摄影师”年纪都大？
|
SELECT name , job FROM Person ORDER BY name
|
CREATE TABLE Person (name VARCHAR, job VARCHAR)
|
按年龄的顺序列出所有的人的姓名和职称。
|
SELECT name , job FROM Person ORDER BY name
|
CREATE TABLE Person (name VARCHAR, job VARCHAR)
|
按姓名的字母顺序排列的每个人的姓名和职称是什么？
|
SELECT name FROM Person ORDER BY age DESC
|
CREATE TABLE Person (name VARCHAR, age VARCHAR)
|
按年龄顺序降序排列所有人的姓名。
|
SELECT name FROM Person ORDER BY age DESC
|
CREATE TABLE Person (name VARCHAR, age VARCHAR)
|
按年龄顺序排序的每个人的名字是什么？
|
SELECT name FROM Person WHERE gender = '男' ORDER BY age
|
CREATE TABLE Person (age VARCHAR, name VARCHAR, gender VARCHAR)
|
根据年龄顺序找出所有“男”的姓名和年龄。
|
SELECT name FROM Person WHERE gender = '男' ORDER BY age
|
CREATE TABLE Person (age VARCHAR, name VARCHAR, gender VARCHAR)
|
按年龄顺序排列的每个“男”的名字和年龄的结果是多少？
|
SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽'
|
CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找出“丹丹”和“丽丽”共同的朋友的姓名和年龄。
|
SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽'
|
CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
“丹丹”和“丽丽”共同的朋友的姓名和年龄是多少？
|
SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' OR T2.friend = '丽丽'
|
CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找到“丹丹”或“丽丽”的朋友的姓名和年龄。
|
SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' OR T2.friend = '丽丽'
|
CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
“丹丹”的朋友或者“丽丽”的朋友的姓名和年龄是多少？
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找出拥有年龄在40岁以上和30岁以下的朋友的人的姓名。
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
每个有40岁以上和30岁以下的朋友的人的名字是什么？
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找出有年龄在40岁以上但不在30岁以下的朋友的人的名字。
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
有年龄在40岁以上但不在30岁以下的朋友的人的名字是什么？
|
SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = '学生'
|
CREATE TABLE person (name VARCHAR), CREATE TABLE Person (name VARCHAR, job VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找到没有“学生”朋友的人的名字。
|
SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = '学生'
|
CREATE TABLE person (name VARCHAR), CREATE TABLE Person (name VARCHAR, job VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
没有“学生”朋友的名字是什么？
|
SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1
|
CREATE TABLE PersonFriend (name VARCHAR)
|
找出正好有一个朋友的人。
|
SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1
|
CREATE TABLE PersonFriend (name VARCHAR)
|
正好有一个朋友的人的名字是什么？
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = '张波'
|
CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
谁是“张波”的朋友？
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = '张波'
|
CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
“张波”的朋友是谁？
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '张波'
|
CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找到和“张波”交朋友的人的名字。
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '张波'
|
CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
“张波”的所有朋友的名字是什么？
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '仲景' AND T1.gender = '女'
|
CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找到和“仲景”交朋友的“女”的名字
|
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '仲景' AND T1.gender = '女'
|
CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
所有和“仲景”交朋友的“女”的名字是什么？
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '女'
|
CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找到“丽丽”的“女”朋友。
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '女'
|
CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
“丽丽”的“女”朋友是什么？
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '男' AND T1.job = '医生'
|
CREATE TABLE Person (name VARCHAR, job VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
找到“丽丽”的工作是“医生”的“男”朋友？
|
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '男' AND T1.job = '医生'
|
CREATE TABLE Person (name VARCHAR, job VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
谁是“丽丽”的“医生”朋友？
|
SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = '上海'
|
CREATE TABLE Person (name VARCHAR, city VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
谁有一个来自“上海”的朋友？
|
SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = '上海'
|
CREATE TABLE Person (name VARCHAR, city VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
来自“上海”的所有朋友的名字是什么？
|
SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER)
|
谁有比平均年龄小的朋友？
|
SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER)
|
比所有朋友中平均年龄小的朋友的不同名字是什么？
|
SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER)
|
谁有比平均年龄大的朋友？给出他们的朋友和他们的年龄
|
SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person)
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER)
|
所有比平均年龄大的人的姓名、朋友和年龄是什么？
|
SELECT friend FROM PersonFriend WHERE name = '仲景' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景')
|
CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR)
|
谁是“仲景”关系最长的朋友？
|
SELECT friend FROM PersonFriend WHERE name = '仲景' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景')
|
CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR)
|
“仲景”与哪位朋友有最长久的友谊？
|
SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '仲景' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景')
|
CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER)
|
“仲景”关系最长的朋友的年龄是什么？
|
SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '仲景' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景')
|
CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER)
|
与“仲景”相处时间最长的朋友的年龄是多少？
|
SELECT name FROM PersonFriend WHERE friend = '丽丽' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = '丽丽')
|
CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR)
|
找出与“丽丽”成为朋友时间最短的人的名字。
|
SELECT name FROM PersonFriend WHERE friend = '丽丽' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = '丽丽')
|
CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR)
|
和“丽丽”交朋友时间最短的人叫什么名字？
|
SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = '丽丽')
|
CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (friend VARCHAR, YEAR INTEGER)
|
找出和“丽丽”交往最久的人的姓名、年龄和工作头衔。
|
SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = '丽丽')
|
CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (friend VARCHAR, YEAR INTEGER)
|
与“丽丽”交最长时间朋友的姓名、年龄和工作是什么？
|
SELECT name FROM person EXCEPT SELECT name FROM PersonFriend
|
CREATE TABLE person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR)
|
没有朋友的人是谁？
|
SELECT name FROM person EXCEPT SELECT name FROM PersonFriend
|
CREATE TABLE person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR)
|
没有朋友的人的名字是什么？
|
SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
朋友的平均年龄最大的人是哪位？
|
SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1
|
CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR)
|
朋友平均年龄最大的人叫什么名字？平均年龄是多少？
|
SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = '郑州')
|
CREATE TABLE PersonFriend (name VARCHAR, city VARCHAR, friend VARCHAR), CREATE TABLE person (name VARCHAR, city VARCHAR, friend VARCHAR)
|
没有朋友住在“郑州”市的总人数是多少？
|
SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = '郑州')
|
CREATE TABLE PersonFriend (name VARCHAR, city VARCHAR, friend VARCHAR), CREATE TABLE person (name VARCHAR, city VARCHAR, friend VARCHAR)
|
在“郑州”没有朋友的人的总数是多少？
|
SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = '丽丽' AND T4.name != '丽丽'
|
CREATE TABLE PersonFriend (name VARCHAR), CREATE TABLE Person (name VARCHAR)
|
找到“丽丽”的朋友。
|
SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = '丽丽' AND T4.name != '丽丽'
|
CREATE TABLE PersonFriend (name VARCHAR), CREATE TABLE Person (name VARCHAR)
|
“丽丽”的朋友们的名字是什么？
|
SELECT count(*) FROM member
|
CREATE TABLE member (Id VARCHAR)
|
有多少名成员？
|
SELECT Name FROM member ORDER BY Name ASC
|
CREATE TABLE member (Name VARCHAR)
|
按字母升序顺序列出成员的名字。
|
SELECT Name , Country FROM member
|
CREATE TABLE member (Country VARCHAR, Name VARCHAR)
|
成员的名字和国家是什么？
|
SELECT Name FROM member WHERE Country = "美国" OR Country = "加拿大"
|
CREATE TABLE member (Country VARCHAR, Name VARCHAR)
|
显示国家“美国”或“加拿大”的成员的名字。
|
SELECT Country , COUNT(*) FROM member GROUP BY Country
|
CREATE TABLE member (Country VARCHAR)
|
显示不同的国家和每个国家成员的数量。
|
SELECT Country FROM member GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1
|
CREATE TABLE member (Country VARCHAR)
|
显示成员间最常见的国家。
|
SELECT Country FROM member GROUP BY Country HAVING COUNT(*) > 2
|
CREATE TABLE member (Country VARCHAR)
|
哪些国家有两个以上成员？
|
SELECT Leader_Name , College_Location FROM college
|
CREATE TABLE college (College_Location VARCHAR, Leader_Name VARCHAR)
|
显示大学的领导姓名和地点。
|
SELECT T2.Name , T1.Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID
|
CREATE TABLE college (Name VARCHAR, College_ID VARCHAR), CREATE TABLE member (Name VARCHAR, College_ID VARCHAR)
|
显示会员的姓名和他们入学大学名称。
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SELECT T2.Name , T1.College_Location FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID ORDER BY T2.Name ASC
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CREATE TABLE college (College_Location VARCHAR, College_ID VARCHAR), CREATE TABLE member (Name VARCHAR, College_ID VARCHAR)
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按照会员名字升序的字母顺序，显示会员姓名和他们所去大学的位置。
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SELECT DISTINCT T1.Leader_Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID WHERE T2.Country = "加拿大"
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CREATE TABLE college (College_ID VARCHAR, Leader_Name VARCHAR), CREATE TABLE member (Country VARCHAR, College_ID VARCHAR)
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显示与来自国家“加拿大”的成员相关的大学的不同领导者的名字。
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SELECT T1.Name , T2.Decoration_Theme FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID
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CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Decoration_Theme VARCHAR, Member_ID VARCHAR)
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显示成员的姓名和装饰主题。
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SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID WHERE T2.Rank_in_Round > 3
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CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Member_ID VARCHAR, Rank_in_Round INTEGER)
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显示在轮次中具有高于等级3的成员的姓名。
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SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID ORDER BY Rank_in_Round ASC
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CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Member_ID VARCHAR)
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在轮次中以升序排列成员的姓名。
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SELECT Name FROM member WHERE Member_ID NOT IN (SELECT Member_ID FROM round)
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CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Name VARCHAR, Member_ID VARCHAR)
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列出没有参加任何回合的成员的姓名。
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SELECT document_name , access_count FROM documents ORDER BY document_name
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CREATE TABLE documents (access_count VARCHAR, document_name VARCHAR)
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按照文档名称的字母顺序查找所有文档的名称和访问次数。
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