answer stringlengths 18 552 | context stringlengths 30 393 | question stringlengths 5 73 |
|---|---|---|
SELECT count(*) FROM Person WHERE gender = '女' | CREATE TABLE Person (gender VARCHAR) | 这个网络有多少“女”？ |
SELECT count(*) FROM Person WHERE gender = '女' | CREATE TABLE Person (gender VARCHAR) | 网络中性别是“女”的人数有多少？ |
SELECT avg(age) FROM Person | CREATE TABLE Person (age INTEGER) | 所有人的平均年龄是多少？ |
SELECT avg(age) FROM Person | CREATE TABLE Person (age INTEGER) | 表格中所有人的平均年龄是多少？ |
SELECT count(DISTINCT city) FROM Person | CREATE TABLE Person (city VARCHAR) | 他们来自多少个不同的城市？ |
SELECT count(DISTINCT city) FROM Person | CREATE TABLE Person (city VARCHAR) | 人们的故乡来自于多少个不同的城市？ |
SELECT count(DISTINCT job) FROM Person | CREATE TABLE Person (job VARCHAR) | 他们有多少种工作？ |
SELECT count(DISTINCT job) FROM Person | CREATE TABLE Person (job VARCHAR) | 列出了多少份不同的工作？ |
SELECT name FROM Person WHERE age = (SELECT max(age) FROM person) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE person (name VARCHAR, age INTEGER) | 谁是最老的人？ |
SELECT name FROM Person WHERE age = (SELECT max(age) FROM person) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE person (name VARCHAR, age INTEGER) | 最老的人叫什么名字？ |
SELECT name FROM Person WHERE job = '学生' AND age = (SELECT max(age) FROM person WHERE job = '学生' ) | CREATE TABLE Person (age INTEGER, name VARCHAR, job VARCHAR), CREATE TABLE person (age INTEGER, name VARCHAR, job VARCHAR) | 谁是年龄最大的“学生”？ |
SELECT name FROM Person WHERE job = '学生' AND age = (SELECT max(age) FROM person WHERE job = '学生' ) | CREATE TABLE Person (age INTEGER, name VARCHAR, job VARCHAR), CREATE TABLE person (age INTEGER, name VARCHAR, job VARCHAR) | 年龄最大的“学生”叫什么名字？ |
SELECT name FROM Person WHERE gender = '男' AND age = (SELECT min(age) FROM person WHERE gender = '男' ) | CREATE TABLE Person (name VARCHAR, age INTEGER, gender VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, gender VARCHAR) | 谁是最年轻的“男”？ |
SELECT name FROM Person WHERE gender = '男' AND age = (SELECT min(age) FROM person WHERE gender = '男' ) | CREATE TABLE Person (name VARCHAR, age INTEGER, gender VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, gender VARCHAR) | 最年轻的“男”叫什么名字？ |
SELECT age FROM Person WHERE job = '医生' AND name = '仲景' | CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR) | 名字叫“仲景”的“医生”年纪多大了？ |
SELECT age FROM Person WHERE job = '医生' AND name = '仲景' | CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR) | 那个叫“仲景”的“医生”的年龄是多少岁？ |
SELECT name FROM Person WHERE age < 30 | CREATE TABLE Person (name VARCHAR, age INTEGER) | 年龄低于30岁的人是谁？ |
SELECT name FROM Person WHERE age < 30 | CREATE TABLE Person (name VARCHAR, age INTEGER) | 年龄在30岁以下的人叫什么名字？ |
SELECT count(*) FROM Person WHERE age > 30 AND job = '摄影师' | CREATE TABLE Person (age INTEGER, job VARCHAR) | 有多少人年龄大于30且工作是“摄影师”？ |
SELECT count(*) FROM Person WHERE age > 30 AND job = '摄影师' | CREATE TABLE Person (age INTEGER, job VARCHAR) | 有多少“摄影师”的年龄超过30岁？ |
SELECT avg(age) , gender FROM Person GROUP BY gender | CREATE TABLE Person (age INTEGER, gender VARCHAR) | 每个性别的平均年龄是多少？ |
SELECT avg(age) , gender FROM Person GROUP BY gender | CREATE TABLE Person (age INTEGER, gender VARCHAR) | 每个性别的平均年龄有多大？ |
SELECT avg(age) , job FROM Person GROUP BY job | CREATE TABLE Person (age INTEGER, job VARCHAR) | 不同工作职称的平均年龄是多少？ |
SELECT avg(age) , job FROM Person GROUP BY job | CREATE TABLE Person (age INTEGER, job VARCHAR) | 每个工作的平均年龄是多少？ |
SELECT avg(age) , job FROM Person WHERE gender = '男' GROUP BY job | CREATE TABLE Person (age INTEGER, job VARCHAR, gender VARCHAR) | 不同职称的“男”的平均年龄是多少？ |
SELECT avg(age) , job FROM Person WHERE gender = '男' GROUP BY job | CREATE TABLE Person (age INTEGER, job VARCHAR, gender VARCHAR) | 每个工作的“男”平均年龄是多少？ |
SELECT min(age) , job FROM Person GROUP BY job | CREATE TABLE Person (age INTEGER, job VARCHAR) | 不同职称的最低年龄是多少？ |
SELECT min(age) , job FROM Person GROUP BY job | CREATE TABLE Person (age INTEGER, job VARCHAR) | 每个工作年龄最小的人的年纪有多大？ |
SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender | CREATE TABLE Person (age INTEGER, gender VARCHAR) | 找到每个性别中年龄低于40岁的人的数量。 |
SELECT count(*) , gender FROM Person WHERE age < 40 GROUP BY gender | CREATE TABLE Person (age INTEGER, gender VARCHAR) | 每个性别有多少人不足40岁？ |
SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = '摄影师') ORDER BY age | CREATE TABLE Person (name VARCHAR, age INTEGER, job VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, job VARCHAR) | 按年龄排序找出年龄比任何“摄影师”年龄都大的人的名字。 |
SELECT name FROM Person WHERE age > (SELECT min(age) FROM person WHERE job = '摄影师') ORDER BY age | CREATE TABLE Person (name VARCHAR, age INTEGER, job VARCHAR), CREATE TABLE person (name VARCHAR, age INTEGER, job VARCHAR) | 所有比至少一个“摄影师”年龄大的人的名字是什么？按年龄顺序排序。 |
SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = '摄影师') | CREATE TABLE Person (age INTEGER, job VARCHAR), CREATE TABLE person (age INTEGER, job VARCHAR) | 找出年龄大于所有“摄影师”年龄的人数。 |
SELECT count(*) FROM Person WHERE age > (SELECT max(age) FROM person WHERE job = '摄影师') | CREATE TABLE Person (age INTEGER, job VARCHAR), CREATE TABLE person (age INTEGER, job VARCHAR) | 有多少人比每个“摄影师”年纪都大？ |
SELECT name , job FROM Person ORDER BY name | CREATE TABLE Person (name VARCHAR, job VARCHAR) | 按年龄的顺序列出所有的人的姓名和职称。 |
SELECT name , job FROM Person ORDER BY name | CREATE TABLE Person (name VARCHAR, job VARCHAR) | 按姓名的字母顺序排列的每个人的姓名和职称是什么？ |
SELECT name FROM Person ORDER BY age DESC | CREATE TABLE Person (name VARCHAR, age VARCHAR) | 按年龄顺序降序排列所有人的姓名。 |
SELECT name FROM Person ORDER BY age DESC | CREATE TABLE Person (name VARCHAR, age VARCHAR) | 按年龄顺序排序的每个人的名字是什么？ |
SELECT name FROM Person WHERE gender = '男' ORDER BY age | CREATE TABLE Person (age VARCHAR, name VARCHAR, gender VARCHAR) | 根据年龄顺序找出所有“男”的姓名和年龄。 |
SELECT name FROM Person WHERE gender = '男' ORDER BY age | CREATE TABLE Person (age VARCHAR, name VARCHAR, gender VARCHAR) | 按年龄顺序排列的每个“男”的名字和年龄的结果是多少？ |
SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽' | CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找出“丹丹”和“丽丽”共同的朋友的姓名和年龄。 |
SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' INTERSECT SELECT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽' | CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | “丹丹”和“丽丽”共同的朋友的姓名和年龄是多少？ |
SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' OR T2.friend = '丽丽' | CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找到“丹丹”或“丽丽”的朋友的姓名和年龄。 |
SELECT DISTINCT T1.name , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丹丹' OR T2.friend = '丽丽' | CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | “丹丹”的朋友或者“丽丽”的朋友的姓名和年龄是多少？ |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找出拥有年龄在40岁以上和30岁以下的朋友的人的姓名。 |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) INTERSECT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 每个有40岁以上和30岁以下的朋友的人的名字是什么？ |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找出有年龄在40岁以上但不在30岁以下的朋友的人的名字。 |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age > 40) EXCEPT SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend IN (SELECT name FROM Person WHERE age < 30) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 有年龄在40岁以上但不在30岁以下的朋友的人的名字是什么？ |
SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = '学生' | CREATE TABLE person (name VARCHAR), CREATE TABLE Person (name VARCHAR, job VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找到没有“学生”朋友的人的名字。 |
SELECT name FROM person EXCEPT SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.job = '学生' | CREATE TABLE person (name VARCHAR), CREATE TABLE Person (name VARCHAR, job VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 没有“学生”朋友的名字是什么？ |
SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1 | CREATE TABLE PersonFriend (name VARCHAR) | 找出正好有一个朋友的人。 |
SELECT name FROM PersonFriend GROUP BY name HAVING count(*) = 1 | CREATE TABLE PersonFriend (name VARCHAR) | 正好有一个朋友的人的名字是什么？ |
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = '张波' | CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 谁是“张波”的朋友？ |
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T1.name = '张波' | CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | “张波”的朋友是谁？ |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '张波' | CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找到和“张波”交朋友的人的名字。 |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '张波' | CREATE TABLE Person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | “张波”的所有朋友的名字是什么？ |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '仲景' AND T1.gender = '女' | CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找到和“仲景”交朋友的“女”的名字 |
SELECT T1.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '仲景' AND T1.gender = '女' | CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 所有和“仲景”交朋友的“女”的名字是什么？ |
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '女' | CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找到“丽丽”的“女”朋友。 |
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '女' | CREATE TABLE Person (name VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | “丽丽”的“女”朋友是什么？ |
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '男' AND T1.job = '医生' | CREATE TABLE Person (name VARCHAR, job VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 找到“丽丽”的工作是“医生”的“男”朋友？ |
SELECT T2.friend FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '丽丽' AND T1.gender = '男' AND T1.job = '医生' | CREATE TABLE Person (name VARCHAR, job VARCHAR, gender VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 谁是“丽丽”的“医生”朋友？ |
SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = '上海' | CREATE TABLE Person (name VARCHAR, city VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 谁有一个来自“上海”的朋友？ |
SELECT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.city = '上海' | CREATE TABLE Person (name VARCHAR, city VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 来自“上海”的所有朋友的名字是什么？ |
SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER) | 谁有比平均年龄小的朋友？ |
SELECT DISTINCT T2.name FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age < (SELECT avg(age) FROM person) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER) | 比所有朋友中平均年龄小的朋友的不同名字是什么？ |
SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER) | 谁有比平均年龄大的朋友？给出他们的朋友和他们的年龄 |
SELECT DISTINCT T2.name , T2.friend , T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T1.age > (SELECT avg(age) FROM person) | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR), CREATE TABLE person (age INTEGER) | 所有比平均年龄大的人的姓名、朋友和年龄是什么？ |
SELECT friend FROM PersonFriend WHERE name = '仲景' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景') | CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR) | 谁是“仲景”关系最长的朋友？ |
SELECT friend FROM PersonFriend WHERE name = '仲景' AND YEAR = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景') | CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR) | “仲景”与哪位朋友有最长久的友谊？ |
SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '仲景' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景') | CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER) | “仲景”关系最长的朋友的年龄是什么？ |
SELECT T1.age FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend WHERE T2.name = '仲景' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE name = '仲景') | CREATE TABLE Person (name VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER) | 与“仲景”相处时间最长的朋友的年龄是多少？ |
SELECT name FROM PersonFriend WHERE friend = '丽丽' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = '丽丽') | CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR) | 找出与“丽丽”成为朋友时间最短的人的名字。 |
SELECT name FROM PersonFriend WHERE friend = '丽丽' AND YEAR = (SELECT min(YEAR) FROM PersonFriend WHERE friend = '丽丽') | CREATE TABLE PersonFriend (name VARCHAR, YEAR INTEGER, friend VARCHAR) | 和“丽丽”交朋友时间最短的人叫什么名字？ |
SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = '丽丽') | CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (friend VARCHAR, YEAR INTEGER) | 找出和“丽丽”交往最久的人的姓名、年龄和工作头衔。 |
SELECT T1.name , T1.age , T1.job FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.name WHERE T2.friend = '丽丽' AND T2.year = (SELECT max(YEAR) FROM PersonFriend WHERE friend = '丽丽') | CREATE TABLE Person (name VARCHAR, job VARCHAR, age VARCHAR), CREATE TABLE PersonFriend (friend VARCHAR, YEAR INTEGER) | 与“丽丽”交最长时间朋友的姓名、年龄和工作是什么？ |
SELECT name FROM person EXCEPT SELECT name FROM PersonFriend | CREATE TABLE person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR) | 没有朋友的人是谁？ |
SELECT name FROM person EXCEPT SELECT name FROM PersonFriend | CREATE TABLE person (name VARCHAR), CREATE TABLE PersonFriend (name VARCHAR) | 没有朋友的人的名字是什么？ |
SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1 | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 朋友的平均年龄最大的人是哪位？ |
SELECT T2.name , avg(T1.age) FROM Person AS T1 JOIN PersonFriend AS T2 ON T1.name = T2.friend GROUP BY T2.name ORDER BY avg(T1.age) DESC LIMIT 1 | CREATE TABLE Person (name VARCHAR, age INTEGER), CREATE TABLE PersonFriend (name VARCHAR, friend VARCHAR) | 朋友平均年龄最大的人叫什么名字？平均年龄是多少？ |
SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = '郑州') | CREATE TABLE PersonFriend (name VARCHAR, city VARCHAR, friend VARCHAR), CREATE TABLE person (name VARCHAR, city VARCHAR, friend VARCHAR) | 没有朋友住在“郑州”市的总人数是多少？ |
SELECT count(DISTINCT name) FROM PersonFriend WHERE friend NOT IN (SELECT name FROM person WHERE city = '郑州') | CREATE TABLE PersonFriend (name VARCHAR, city VARCHAR, friend VARCHAR), CREATE TABLE person (name VARCHAR, city VARCHAR, friend VARCHAR) | 在“郑州”没有朋友的人的总数是多少？ |
SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = '丽丽' AND T4.name != '丽丽' | CREATE TABLE PersonFriend (name VARCHAR), CREATE TABLE Person (name VARCHAR) | 找到“丽丽”的朋友。 |
SELECT DISTINCT T4.name FROM PersonFriend AS T1 JOIN Person AS T2 ON T1.name = T2.name JOIN PersonFriend AS T3 ON T1.friend = T3.name JOIN PersonFriend AS T4 ON T3.friend = T4.name WHERE T2.name = '丽丽' AND T4.name != '丽丽' | CREATE TABLE PersonFriend (name VARCHAR), CREATE TABLE Person (name VARCHAR) | “丽丽”的朋友们的名字是什么？ |
SELECT count(*) FROM member | CREATE TABLE member (Id VARCHAR) | 有多少名成员？ |
SELECT Name FROM member ORDER BY Name ASC | CREATE TABLE member (Name VARCHAR) | 按字母升序顺序列出成员的名字。 |
SELECT Name , Country FROM member | CREATE TABLE member (Country VARCHAR, Name VARCHAR) | 成员的名字和国家是什么？ |
SELECT Name FROM member WHERE Country = "美国" OR Country = "加拿大" | CREATE TABLE member (Country VARCHAR, Name VARCHAR) | 显示国家“美国”或“加拿大”的成员的名字。 |
SELECT Country , COUNT(*) FROM member GROUP BY Country | CREATE TABLE member (Country VARCHAR) | 显示不同的国家和每个国家成员的数量。 |
SELECT Country FROM member GROUP BY Country ORDER BY COUNT(*) DESC LIMIT 1 | CREATE TABLE member (Country VARCHAR) | 显示成员间最常见的国家。 |
SELECT Country FROM member GROUP BY Country HAVING COUNT(*) > 2 | CREATE TABLE member (Country VARCHAR) | 哪些国家有两个以上成员？ |
SELECT Leader_Name , College_Location FROM college | CREATE TABLE college (College_Location VARCHAR, Leader_Name VARCHAR) | 显示大学的领导姓名和地点。 |
SELECT T2.Name , T1.Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID | CREATE TABLE college (Name VARCHAR, College_ID VARCHAR), CREATE TABLE member (Name VARCHAR, College_ID VARCHAR) | 显示会员的姓名和他们入学大学名称。 |
SELECT T2.Name , T1.College_Location FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID ORDER BY T2.Name ASC | CREATE TABLE college (College_Location VARCHAR, College_ID VARCHAR), CREATE TABLE member (Name VARCHAR, College_ID VARCHAR) | 按照会员名字升序的字母顺序，显示会员姓名和他们所去大学的位置。 |
SELECT DISTINCT T1.Leader_Name FROM college AS T1 JOIN member AS T2 ON T1.College_ID = T2.College_ID WHERE T2.Country = "加拿大" | CREATE TABLE college (College_ID VARCHAR, Leader_Name VARCHAR), CREATE TABLE member (Country VARCHAR, College_ID VARCHAR) | 显示与来自国家“加拿大”的成员相关的大学的不同领导者的名字。 |
SELECT T1.Name , T2.Decoration_Theme FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID | CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Decoration_Theme VARCHAR, Member_ID VARCHAR) | 显示成员的姓名和装饰主题。 |
SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID WHERE T2.Rank_in_Round > 3 | CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Member_ID VARCHAR, Rank_in_Round INTEGER) | 显示在轮次中具有高于等级3的成员的姓名。 |
SELECT T1.Name FROM member AS T1 JOIN round AS T2 ON T1.Member_ID = T2.Member_ID ORDER BY Rank_in_Round ASC | CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Member_ID VARCHAR) | 在轮次中以升序排列成员的姓名。 |
SELECT Name FROM member WHERE Member_ID NOT IN (SELECT Member_ID FROM round) | CREATE TABLE member (Name VARCHAR, Member_ID VARCHAR), CREATE TABLE round (Name VARCHAR, Member_ID VARCHAR) | 列出没有参加任何回合的成员的姓名。 |
SELECT document_name , access_count FROM documents ORDER BY document_name | CREATE TABLE documents (access_count VARCHAR, document_name VARCHAR) | 按照文档名称的字母顺序查找所有文档的名称和访问次数。 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.