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SELECT DISTINCT District_name FROM district ORDER BY city_area DESC
CREATE TABLE district (District_name VARCHAR, city_area VARCHAR)
查找城市区域降序排列的所有区域名称。
SELECT DISTINCT District_name FROM district ORDER BY city_area DESC
CREATE TABLE district (District_name VARCHAR, city_area VARCHAR)
按市区区域降序排列的不同的区域名称是什么?
SELECT max_page_size FROM product GROUP BY max_page_size HAVING count(*) > 3
CREATE TABLE product (max_page_size VARCHAR)
找出具有超过3个产品列表的页面大小列表
SELECT max_page_size FROM product GROUP BY max_page_size HAVING count(*) > 3
CREATE TABLE product (max_page_size VARCHAR)
超过3个产品列表的所有产品的最大页面大小是多少?
SELECT District_name , City_Population FROM district WHERE City_Population BETWEEN 200000 AND 2000000
CREATE TABLE district (City_Population INTEGER, District_name VARCHAR)
查找人口在20万到200万之间的地区的名称和人口
SELECT District_name , City_Population FROM district WHERE City_Population BETWEEN 200000 AND 2000000
CREATE TABLE district (City_Population INTEGER, District_name VARCHAR)
20万到200万居民之间的所有地区的区名和城市人口是多少?
SELECT district_name FROM district WHERE city_area > 10 OR City_Population > 100000
CREATE TABLE district (district_name VARCHAR, city_area INTEGER, City_Population INTEGER)
查找城市面积大于10或人口大于10万的所有地区的名称
SELECT district_name FROM district WHERE city_area > 10 OR City_Population > 100000
CREATE TABLE district (district_name VARCHAR, city_area INTEGER, City_Population INTEGER)
市区面积大于10或居住10万人以上的地区名称是什么?
SELECT district_name FROM district ORDER BY city_population DESC LIMIT 1
CREATE TABLE district (district_name VARCHAR, city_population VARCHAR)
哪个地区人口最多?
SELECT district_name FROM district ORDER BY city_population DESC LIMIT 1
CREATE TABLE district (district_name VARCHAR, city_population VARCHAR)
居民最多的地区叫什么名字?
SELECT district_name FROM district ORDER BY city_area ASC LIMIT 1
CREATE TABLE district (district_name VARCHAR, city_area VARCHAR)
哪个地区的面积最少?
SELECT district_name FROM district ORDER BY city_area ASC LIMIT 1
CREATE TABLE district (district_name VARCHAR, city_area VARCHAR)
面积最小的地区叫什么名字?
SELECT sum(city_population) FROM district ORDER BY city_area DESC LIMIT 3
CREATE TABLE district (city_population INTEGER, city_area VARCHAR)
找出总面积最大的3个区的总人口。
SELECT sum(city_population) FROM district ORDER BY city_area DESC LIMIT 3
CREATE TABLE district (city_population INTEGER, city_area VARCHAR)
三大最大区域的居民总数是多少?
SELECT TYPE , count(*) FROM store GROUP BY TYPE
CREATE TABLE store (TYPE VARCHAR)
查找所有类型的商店和其对应的数量。
SELECT TYPE , count(*) FROM store GROUP BY TYPE
CREATE TABLE store (TYPE VARCHAR)
对于每种类型的商店,有多少种?
SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t3.district_name = "上城区"
CREATE TABLE store (store_name VARCHAR, store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (district_name VARCHAR, district_id VARCHAR)
找到“上城区”所有商店的名称。
SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t3.district_name = "上城区"
CREATE TABLE store (store_name VARCHAR, store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (district_name VARCHAR, district_id VARCHAR)
“上城区”所有商店的名称是什么?
SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id WHERE district_id = (SELECT district_id FROM district ORDER BY city_population DESC LIMIT 1)
CREATE TABLE store (store_name VARCHAR, store_id VARCHAR), CREATE TABLE store_district (store_id VARCHAR), CREATE TABLE district (city_population VARCHAR, district_id VARCHAR)
找到人口最多的地区所有的商店。
SELECT t1.store_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id WHERE district_id = (SELECT district_id FROM district ORDER BY city_population DESC LIMIT 1)
CREATE TABLE store (store_name VARCHAR, store_id VARCHAR), CREATE TABLE store_district (store_id VARCHAR), CREATE TABLE district (city_population VARCHAR, district_id VARCHAR)
人口最多的地区所有商店的名称是什么?
SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t1.store_name = "卡西欧"
CREATE TABLE store (store_name VARCHAR, store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (headquartered_city VARCHAR, district_id VARCHAR)
哪个城市是“卡西欧”店的总部?
SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t1.store_name = "卡西欧"
CREATE TABLE store (store_name VARCHAR, store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (headquartered_city VARCHAR, district_id VARCHAR)
哪个商店是“卡西欧”商场的总部?
SELECT t3.headquartered_city , count(*) FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id GROUP BY t3.headquartered_city
CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (headquartered_city VARCHAR, district_id VARCHAR)
查找每个城市的商店数量。
SELECT t3.headquartered_city , count(*) FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id GROUP BY t3.headquartered_city
CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (headquartered_city VARCHAR, district_id VARCHAR)
每个城市都有多少商店的总部?
SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id GROUP BY t3.headquartered_city ORDER BY count(*) DESC LIMIT 1
CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (headquartered_city VARCHAR, district_id VARCHAR)
找到拥有最多商店的城市。
SELECT t3.headquartered_city FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id GROUP BY t3.headquartered_city ORDER BY count(*) DESC LIMIT 1
CREATE TABLE store (store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (headquartered_city VARCHAR, district_id VARCHAR)
哪一个城市的旗舰店数量最多?
SELECT avg(pages_per_minute_color) FROM product
CREATE TABLE product (pages_per_minute_color INTEGER)
每分钟颜色的平均页数是多少?
SELECT avg(pages_per_minute_color) FROM product
CREATE TABLE product (pages_per_minute_color INTEGER)
每分钟颜色的平均页数的数量是多少?
SELECT t1.product FROM product AS t1 JOIN store_product AS t2 ON t1.product_id = t2.product_id JOIN store AS t3 ON t2.store_id = t3.store_id WHERE t3.store_name = "安踏"
CREATE TABLE product (product VARCHAR, product_id VARCHAR), CREATE TABLE store_product (product_id VARCHAR, store_id VARCHAR), CREATE TABLE store (store_name VARCHAR, store_id VARCHAR)
叫“安踏”商店里有什么产品?
SELECT t1.product FROM product AS t1 JOIN store_product AS t2 ON t1.product_id = t2.product_id JOIN store AS t3 ON t2.store_id = t3.store_id WHERE t3.store_name = "安踏"
CREATE TABLE product (product VARCHAR, product_id VARCHAR), CREATE TABLE store_product (product_id VARCHAR, store_id VARCHAR), CREATE TABLE store (store_name VARCHAR, store_id VARCHAR)
在“安踏”店里卖什么产品?
SELECT product FROM product WHERE max_page_size = "A4" AND pages_per_minute_color < 5
CREATE TABLE product (pages_per_minute_color INTEGER, product VARCHAR, max_page_size VARCHAR)
找到最大页面大小为“A4”且每分钟页面颜色小于5的产品。
SELECT product FROM product WHERE max_page_size = "A4" AND pages_per_minute_color < 5
CREATE TABLE product (pages_per_minute_color INTEGER, product VARCHAR, max_page_size VARCHAR)
哪些产品具有最大页面大小为“A4”,并且每分钟页面颜色小于5?
SELECT product FROM product WHERE max_page_size = "A4" OR pages_per_minute_color < 5
CREATE TABLE product (pages_per_minute_color INTEGER, product VARCHAR, max_page_size VARCHAR)
找出最大页面大小为“A4”或每分钟页面颜色小于5的产品。
SELECT product FROM product WHERE max_page_size = "A4" OR pages_per_minute_color < 5
CREATE TABLE product (pages_per_minute_color INTEGER, product VARCHAR, max_page_size VARCHAR)
什么是最大页面大小等于“A4”或每分钟页面颜色小于5的产品?
SELECT product FROM product WHERE product LIKE "扫描仪"
CREATE TABLE product (product VARCHAR)
查找所有包含“扫描仪”一词产品的名称。
SELECT product FROM product WHERE product LIKE "扫描仪"
CREATE TABLE product (product VARCHAR)
所有的其名称包括子字符串“扫描仪”的产品有哪些?
SELECT max_page_size FROM product GROUP BY max_page_size ORDER BY count(*) DESC LIMIT 1
CREATE TABLE product (max_page_size VARCHAR)
找出在所有产品中最常用的最大页面大小。
SELECT max_page_size FROM product GROUP BY max_page_size ORDER BY count(*) DESC LIMIT 1
CREATE TABLE product (max_page_size VARCHAR)
最常用的最大页面的大小是什么?
SELECT product FROM product WHERE product != (SELECT max_page_size FROM product GROUP BY max_page_size ORDER BY count(*) DESC LIMIT 1)
CREATE TABLE product (product VARCHAR, max_page_size VARCHAR)
查找不使用最常用最大页面大小的产品的名称。
SELECT product FROM product WHERE product != (SELECT max_page_size FROM product GROUP BY max_page_size ORDER BY count(*) DESC LIMIT 1)
CREATE TABLE product (product VARCHAR, max_page_size VARCHAR)
不是最常使用的最大页面大小的所有产品的名称是什么?
SELECT sum(city_population) FROM district WHERE city_area > (SELECT avg(city_area) FROM district)
CREATE TABLE district (city_population INTEGER, city_area INTEGER)
找出面积大于平均城市面积的区域的总人口。
SELECT sum(city_population) FROM district WHERE city_area > (SELECT avg(city_area) FROM district)
CREATE TABLE district (city_population INTEGER, city_area INTEGER)
面积大于城市平均面积的所有地区的人口总数是多少?
SELECT t3.District_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t1.Type = "大型商场" INTERSECT SELECT t3.District_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t1.Type = "便利店"
CREATE TABLE store (Type VARCHAR, store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (district_id VARCHAR, District_name VARCHAR)
查找同时具有“大型商场”和“便利店”类型的商店的地区的名称。
SELECT t3.District_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t1.Type = "大型商场" INTERSECT SELECT t3.District_name FROM store AS t1 JOIN store_district AS t2 ON t1.store_id = t2.store_id JOIN district AS t3 ON t2.district_id = t3.district_id WHERE t1.Type = "便利店"
CREATE TABLE store (Type VARCHAR, store_id VARCHAR), CREATE TABLE store_district (district_id VARCHAR, store_id VARCHAR), CREATE TABLE district (district_id VARCHAR, District_name VARCHAR)
同时有“大型商场”和“便利店”的地区叫什么名字?
SELECT sum(enr) FROM College
CREATE TABLE College (enr INTEGER)
所有大学的总入学人数是多少?
SELECT sum(enr) FROM College
CREATE TABLE College (enr INTEGER)
有多少学生进入大学?
SELECT avg(enr) FROM College
CREATE TABLE College (enr INTEGER)
平均入学人数是多少?
SELECT avg(enr) FROM College
CREATE TABLE College (enr INTEGER)
每个大学平均有多少学生入学?
SELECT count(*) FROM College
CREATE TABLE College (Id VARCHAR)
一共有多少所大学?
SELECT count(*) FROM College
CREATE TABLE College (Id VARCHAR)
有多少所不同的大学?
SELECT count(*) FROM Player WHERE HS > 1000
CREATE TABLE Player (HS INTEGER)
有多少球员有超过1000小时的训练?
SELECT count(*) FROM Player WHERE HS > 1000
CREATE TABLE Player (HS INTEGER)
有多少不同的球员训练超过1000小时?
SELECT count(*) FROM College WHERE enr > 15000
CREATE TABLE College (enr INTEGER)
有多少大学有超过15000名学生?
SELECT count(*) FROM College WHERE enr > 15000
CREATE TABLE College (enr INTEGER)
学生人数超过15000的大学数量是多少?
SELECT avg(HS) FROM Player
CREATE TABLE Player (HS INTEGER)
所有运动员的平均训练时间是多少?
SELECT avg(HS) FROM Player
CREATE TABLE Player (HS INTEGER)
球员平均训练多少小时?
SELECT pName , HS FROM Player WHERE HS < 1500
CREATE TABLE Player (pName VARCHAR, HS INTEGER)
找出小时数低于1500的球员的名字和训练时间。
SELECT pName , HS FROM Player WHERE HS < 1500
CREATE TABLE Player (pName VARCHAR, HS INTEGER)
训练时间少于1500小时的每个运动员的姓名和训练时间是多少?
SELECT count(DISTINCT cName) FROM tryout
CREATE TABLE tryout (cName VARCHAR)
有多少不同的大学参加选拔赛?
SELECT count(DISTINCT cName) FROM tryout
CREATE TABLE tryout (cName VARCHAR)
选拔赛中有多少所不同的大学?
SELECT count(DISTINCT pPos) FROM tryout
CREATE TABLE tryout (pPos VARCHAR)
选拔赛中球员的不同的位置是什么?
SELECT count(DISTINCT pPos) FROM tryout
CREATE TABLE tryout (pPos VARCHAR)
有多少不同的球员的位置?
SELECT count(*) FROM tryout WHERE decision = '确定'
CREATE TABLE tryout (decision VARCHAR)
选拔赛后有多少学生被录取的“确定”?
SELECT count(*) FROM tryout WHERE decision = '确定'
CREATE TABLE tryout (decision VARCHAR)
有多少学生从选拔赛中得到了录取的“确定”?
SELECT count(*) FROM tryout WHERE pPos = '守门员'
CREATE TABLE tryout (pPos VARCHAR)
有多少学生担任“守门员”的角色?
SELECT count(*) FROM tryout WHERE pPos = '守门员'
CREATE TABLE tryout (pPos VARCHAR)
作为“守门员”的学生人数是多少?
SELECT avg(HS) , max(HS) , min(HS) FROM Player
CREATE TABLE Player (HS INTEGER)
找出所有球员的最大,平均和最少训练时间。
SELECT avg(HS) , max(HS) , min(HS) FROM Player
CREATE TABLE Player (HS INTEGER)
平均、最大和最小训练时间是多少?
SELECT avg(enr) FROM College WHERE state = '河北'
CREATE TABLE College (state VARCHAR, enr INTEGER)
在“河北”省的平均入学率是多少?
SELECT avg(enr) FROM College WHERE state = '河北'
CREATE TABLE College (state VARCHAR, enr INTEGER)
“河北”省高校学生平均入学人数是多少?
SELECT pName FROM Player WHERE HS BETWEEN 500 AND 1500
CREATE TABLE Player (pName VARCHAR, HS INTEGER)
训练时间在500到1500之间的球员的名字是什么?
SELECT pName FROM Player WHERE HS BETWEEN 500 AND 1500
CREATE TABLE Player (pName VARCHAR, HS INTEGER)
在500到1500小时之间有训练的球员的名字是什么?
SELECT DISTINCT pName FROM Player WHERE pName LIKE 'a'
CREATE TABLE Player (pName VARCHAR)
找到那些名字包含字母“a”的球员。
SELECT DISTINCT pName FROM Player WHERE pName LIKE 'a'
CREATE TABLE Player (pName VARCHAR)
谁的名字包含字母“a”的玩家?
SELECT cName , enr FROM College WHERE enr > 10000 AND state = "江苏"
CREATE TABLE College (state VARCHAR, enr INTEGER, cName VARCHAR)
查找名称,招生规模大于10000,地点在“江苏”省的大学。
SELECT cName , enr FROM College WHERE enr > 10000 AND state = "江苏"
CREATE TABLE College (state VARCHAR, enr INTEGER, cName VARCHAR)
“江苏”省有10000多学生入学的大学的名字和招生号码是多少?
SELECT * FROM College ORDER BY enr
CREATE TABLE College (enr VARCHAR)
按招生号升序列出关于大学的信息。
SELECT * FROM College ORDER BY enr
CREATE TABLE College (enr VARCHAR)
按招生号升序列出关于大学的信息有哪些?
SELECT cName FROM College WHERE enr > 18000 ORDER BY cName
CREATE TABLE College (enr INTEGER, cName VARCHAR)
按大学名称排序,列出招生人数超过18000人的大学的名称。
SELECT cName FROM College WHERE enr > 18000 ORDER BY cName
CREATE TABLE College (enr INTEGER, cName VARCHAR)
按字母顺序排列的招生人数超过18000人的每所大学叫什么名字?
SELECT pName FROM Player WHERE yCard = '确定' ORDER BY HS DESC
CREATE TABLE Player (pName VARCHAR, HS VARCHAR, yCard VARCHAR)
按照训练时间的降序且卡片为“确定”的球员的姓名。
SELECT pName FROM Player WHERE yCard = '确定' ORDER BY HS DESC
CREATE TABLE Player (pName VARCHAR, HS VARCHAR, yCard VARCHAR)
按训练小时数递减顺序且收到卡片的运动员叫什么名字?
SELECT DISTINCT cName FROM tryout ORDER BY cName
CREATE TABLE tryout (cName VARCHAR)
按字母顺序查找参与选拔赛的不同大学的名称。
SELECT DISTINCT cName FROM tryout ORDER BY cName
CREATE TABLE tryout (cName VARCHAR)
按字母顺序参加选拔赛的大学名称有哪些不同?
SELECT pPos FROM tryout GROUP BY pPos ORDER BY count(*) DESC LIMIT 1
CREATE TABLE tryout (pPos VARCHAR)
选拔赛中哪些球员最受欢迎?
SELECT pPos FROM tryout GROUP BY pPos ORDER BY count(*) DESC LIMIT 1
CREATE TABLE tryout (pPos VARCHAR)
选拔赛中最受欢迎的位置是什么?
SELECT count(*) , cName FROM tryout GROUP BY cName ORDER BY count(*) DESC
CREATE TABLE tryout (cName VARCHAR)
按数量递减查找每所大学参加选拔赛的学生人数。
SELECT count(*) , cName FROM tryout GROUP BY cName ORDER BY count(*) DESC
CREATE TABLE tryout (cName VARCHAR)
有多少学生参加了每一所大学的选拔赛?
SELECT min(T2.HS) , T1.pPos FROM tryout AS T1 JOIN player AS T2 ON T1.pID = T2.pID GROUP BY T1.pPos
CREATE TABLE tryout (pID VARCHAR, pPos VARCHAR), CREATE TABLE player (pID VARCHAR, HS INTEGER)
学生在不同的位置上花费的最短时间是多少?
SELECT min(T2.HS) , T1.pPos FROM tryout AS T1 JOIN player AS T2 ON T1.pID = T2.pID GROUP BY T1.pPos
CREATE TABLE tryout (pID VARCHAR, pPos VARCHAR), CREATE TABLE player (pID VARCHAR, HS INTEGER)
每一个职位,学生实习的最低时间是多少?
SELECT cName FROM college ORDER BY enr DESC LIMIT 3
CREATE TABLE college (enr VARCHAR, cName VARCHAR)
规模前3大学校的名字是什么?
SELECT cName FROM college ORDER BY enr DESC LIMIT 3
CREATE TABLE college (enr VARCHAR, cName VARCHAR)
有前3大规模班级的学校名称是什么?
SELECT cName , state , min(enr) FROM college GROUP BY state
CREATE TABLE college (state VARCHAR, enr INTEGER, cName VARCHAR)
每个省招生人数最少的学校叫什么名字?
SELECT cName , state , min(enr) FROM college GROUP BY state
CREATE TABLE college (state VARCHAR, enr INTEGER, cName VARCHAR)
每个省招生规模最小的学校叫什么名字?
SELECT DISTINCT state FROM college AS T1 JOIN tryout AS T2 ON T1.cName = T2.cName
CREATE TABLE college (cName VARCHAR), CREATE TABLE tryout (cName VARCHAR)
找到大学生参加选拔赛的省。
SELECT DISTINCT state FROM college AS T1 JOIN tryout AS T2 ON T1.cName = T2.cName
CREATE TABLE college (cName VARCHAR), CREATE TABLE tryout (cName VARCHAR)
学生参加选拔赛的不同的省是什么?
SELECT DISTINCT T1.state FROM college AS T1 JOIN tryout AS T2 ON T1.cName = T2.cName WHERE T2.decision = '确定'
CREATE TABLE college (state VARCHAR, cName VARCHAR), CREATE TABLE tryout (decision VARCHAR, cName VARCHAR)
找一些有大学生参加试行的省,他们的决定是肯定的。
SELECT DISTINCT T1.state FROM college AS T1 JOIN tryout AS T2 ON T1.cName = T2.cName WHERE T2.decision = '确定'
CREATE TABLE college (state VARCHAR, cName VARCHAR), CREATE TABLE tryout (decision VARCHAR, cName VARCHAR)
学生成功尝试的状态有哪些?
SELECT T1.pName , T2.cName FROM player AS T1 JOIN tryout AS T2 ON T1.pID = T2.pID WHERE T2.decision = '确定'
CREATE TABLE player (pID VARCHAR, pName VARCHAR), CREATE TABLE tryout (pID VARCHAR, decision VARCHAR, cName VARCHAR)
找出在选拔赛的决定是“确定”的学生的名字和大学。
SELECT T1.pName , T2.cName FROM player AS T1 JOIN tryout AS T2 ON T1.pID = T2.pID WHERE T2.decision = '确定'
CREATE TABLE player (pID VARCHAR, pName VARCHAR), CREATE TABLE tryout (pID VARCHAR, decision VARCHAR, cName VARCHAR)
所有在选拔赛中得到“确定”的选手的名字是什么?他们的大学叫什么名字?