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SELECT name FROM manufacturers WHERE revenue > (SELECT avg(revenue) FROM manufacturers)
CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
找出收益大于所有公司平均收益的公司的名称。
SELECT name FROM manufacturers WHERE revenue > (SELECT avg(revenue) FROM manufacturers)
CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
收益高于所有制造商收益的平均值的公司的名字是什么?
SELECT name FROM manufacturers WHERE revenue < (SELECT min(revenue) FROM manufacturers WHERE headquarter = '郑州')
CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER, headquarter VARCHAR)
查找收益小于所有位于“奥斯汀”的公司收益的公司的名称。
SELECT name FROM manufacturers WHERE revenue < (SELECT min(revenue) FROM manufacturers WHERE headquarter = '郑州')
CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER, headquarter VARCHAR)
收益低于“奥斯汀”最低收益的制造商的公司有哪些名字?
SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = '郑州')
CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR)
找出收益大于“奥斯汀”一些公司收益的公司的总收益。
SELECT sum(revenue) FROM manufacturers WHERE revenue > (SELECT min(revenue) FROM manufacturers WHERE headquarter = '郑州')
CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR)
收益高于在“奥斯汀”收益最低的制造商的所有公司的总收益是多少?
SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder
CREATE TABLE manufacturers (founder VARCHAR, revenue INTEGER)
找出每个创始人的公司总收益。
SELECT sum(revenue) , founder FROM manufacturers GROUP BY founder
CREATE TABLE manufacturers (founder VARCHAR, revenue INTEGER)
每个创始人创办的公司的总收益是多少?
SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter
CREATE TABLE manufacturers (name VARCHAR, Headquarter VARCHAR, revenue INTEGER)
找出每个城市收益最高的公司的名称和收益。
SELECT name , max(revenue) , Headquarter FROM manufacturers GROUP BY Headquarter
CREATE TABLE manufacturers (name VARCHAR, Headquarter VARCHAR, revenue INTEGER)
每个总部城市收益最高的公司的名称及其收益是多少?
SELECT sum(revenue) , name FROM manufacturers GROUP BY name
CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
找处每个制造商的总收益。
SELECT sum(revenue) , name FROM manufacturers GROUP BY name
CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
每个制造商的总收益是多少?
SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (price INTEGER, Manufacturer VARCHAR), CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
找出每个制造商的所有产品的平均价格,并列出每个公司的名称。
SELECT avg(T1.price) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (price INTEGER, Manufacturer VARCHAR), CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
每个制造商的平均产品价格是多少?
SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter
CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR), CREATE TABLE manufacturers (code VARCHAR, Headquarter VARCHAR)
找出不同总部城市的公司生产的不同产品的数量。
SELECT count(DISTINCT T1.name) , T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter
CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR), CREATE TABLE manufacturers (code VARCHAR, Headquarter VARCHAR)
每个总部城市生产多少种不同的产品?
SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = '索尼')
CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR), CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
找出“索尼”不生产的产品的数量。
SELECT count(DISTINCT name) FROM products WHERE name NOT IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = '索尼')
CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR), CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
有多少种产品不是“索尼”制造的?
SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD播放机'
CREATE TABLE manufacturers (name VARCHAR, code VARCHAR), CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
找出不做“DVD驱动器”的公司的名称。
SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD播放机'
CREATE TABLE manufacturers (name VARCHAR, code VARCHAR), CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
不制作“DVD驱动器”的公司的名称是什么?
SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (Manufacturer VARCHAR), CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
找出每个制造商的产品数量,显示每个公司的名称。
SELECT count(*) , T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (Manufacturer VARCHAR), CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
每个制造商找出多少产品?
SELECT Name FROM Products
CREATE TABLE Products (Name VARCHAR)
选择店里所有产品的名称。
SELECT Name FROM Products
CREATE TABLE Products (Name VARCHAR)
所有产品的名称是什么?
SELECT name , price FROM products
CREATE TABLE products (name VARCHAR, price VARCHAR)
选择店里所有产品的名称和价格。
SELECT name , price FROM products
CREATE TABLE products (name VARCHAR, price VARCHAR)
商店里所有产品的名称和价格是多少?
SELECT name FROM products WHERE price <= 200
CREATE TABLE products (name VARCHAR, price INTEGER)
选择价格低于或等于200美元的产品名称。
SELECT name FROM products WHERE price <= 200
CREATE TABLE products (name VARCHAR, price INTEGER)
价格最多是200的产品名称是什么?
SELECT * FROM products WHERE price BETWEEN 60 AND 120
CREATE TABLE products (price INTEGER)
找出所有价格在60到120美元之间的产品的所有信息,。
SELECT * FROM products WHERE price BETWEEN 60 AND 120
CREATE TABLE products (price INTEGER)
所有价格在60到120之间的产品的所有信息是什么?
SELECT avg(price) FROM products
CREATE TABLE products (price INTEGER)
计算所有产品的平均价格。
SELECT avg(price) FROM products
CREATE TABLE products (price INTEGER)
所有产品的平均价格是多少?
SELECT avg(price) FROM products WHERE Manufacturer = 2
CREATE TABLE products (price INTEGER, Manufacturer VARCHAR)
计算制造商代码为2的所有产品的平均价格。
SELECT avg(price) FROM products WHERE Manufacturer = 2
CREATE TABLE products (price INTEGER, Manufacturer VARCHAR)
制造商代码为2的产品的平均价格是多少?
SELECT count(*) FROM products WHERE price >= 180
CREATE TABLE products (price INTEGER)
计算价格大于或等于180美元的产品数量。
SELECT count(*) FROM products WHERE price >= 180
CREATE TABLE products (price INTEGER)
多少产品的价格至少有180?
SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC
CREATE TABLE products (name VARCHAR, price INTEGER)
选择所有价格大于或等于$180的产品的名称和价格,首先按价格(降序)排序,然后按名称(升序)排序。
SELECT name , price FROM products WHERE price >= 180 ORDER BY price DESC , name ASC
CREATE TABLE products (name VARCHAR, price INTEGER)
根据价格下降及名称上升排序,价格至少为180的产品的名称和价格是什么?
SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code
CREATE TABLE products (manufacturer VARCHAR), CREATE TABLE Manufacturers (code VARCHAR)
从每个产品的制造商中选择所有产品数据。
SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code
CREATE TABLE products (manufacturer VARCHAR), CREATE TABLE Manufacturers (code VARCHAR)
所有的产品数据,以及每个产品的制造商是什么?
SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer
CREATE TABLE Products (Price INTEGER, Manufacturer VARCHAR)
选择每个制造商产品的平均价格,只显示制造商的代码。
SELECT AVG(Price) , Manufacturer FROM Products GROUP BY Manufacturer
CREATE TABLE Products (Price INTEGER, Manufacturer VARCHAR)
按制造商代码分组的产品平均价格是多少?
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (Price INTEGER, manufacturer VARCHAR), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
选择每个制造商产品的平均价格,显示制造商的名称。
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (Price INTEGER, manufacturer VARCHAR), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
按制造商名称分组的产品平均价格是多少?
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150
CREATE TABLE products (Price INTEGER, manufacturer VARCHAR, price INTEGER), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
选择产品平均价格高于或等于$150的制造商的名称。
SELECT avg(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING avg(T1.price) >= 150
CREATE TABLE products (Price INTEGER, manufacturer VARCHAR, price INTEGER), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
产品平均成本在150或以上的制造商的产品名称和平均价格是多少?
SELECT name , price FROM Products ORDER BY price ASC LIMIT 1
CREATE TABLE Products (name VARCHAR, price VARCHAR)
选择最便宜产品的名称和价格。
SELECT name , price FROM Products ORDER BY price ASC LIMIT 1
CREATE TABLE Products (name VARCHAR, price VARCHAR)
最便宜的产品的名称和价格是多少?
SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (Price INTEGER, Name VARCHAR, manufacturer VARCHAR), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
选择每个制造商的名称及其最昂贵产品的名称和价格。
SELECT T1.Name , max(T1.Price) , T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
CREATE TABLE products (Price INTEGER, Name VARCHAR, manufacturer VARCHAR), CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR)
对于每个制造商的名字,他们最贵的产品的名称和价格是什么?
SELECT code , name , min(price) FROM products GROUP BY name
CREATE TABLE products (price INTEGER, name VARCHAR, code VARCHAR)
选择每个产品类别中最便宜的产品代码。
SELECT code , name , min(price) FROM products GROUP BY name
CREATE TABLE products (price INTEGER, name VARCHAR, code VARCHAR)
每个类别中最便宜的产品的代码和名称是什么?
SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1
CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR)
最近创建的问题日志的ID是什么?
SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1
CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR)
哪一个问题日志是最近创建的?把日志ID给我。
SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1
CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR)
最老的日志ID和对应的问题ID是什么?
SELECT problem_log_id , problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1
CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR)
找出最老的日志ID及其对应的问题ID。
SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10
CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR)
根据ID为10的问题找出所有日志的ID和日期。
SELECT problem_log_id , log_entry_date FROM problem_log WHERE problem_id = 10
CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR)
对于ID为10的问题,返回其问题日志的ID和日期。
SELECT problem_log_id , log_entry_description FROM problem_log
CREATE TABLE problem_log (log_entry_description VARCHAR, problem_log_id VARCHAR)
列出所有日志ID及其从问题日志中的描述。
SELECT problem_log_id , log_entry_description FROM problem_log
CREATE TABLE problem_log (log_entry_description VARCHAR, problem_log_id VARCHAR)
每个问题的日志ID和条目描述是什么?
SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1
CREATE TABLE staff (staff_id VARCHAR), CREATE TABLE problem_log (assigned_to_staff_id VARCHAR, problem_id VARCHAR)
列出分配到id为1的问题的所有不同工作人员的名字和姓氏。
SELECT DISTINCT staff_first_name , staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1
CREATE TABLE staff (staff_id VARCHAR), CREATE TABLE problem_log (assigned_to_staff_id VARCHAR, problem_id VARCHAR)
哪些员工被分配到ID是1的问题?给我他们的名字和姓氏。
SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "马" AND T1.staff_last_name = "军军"
CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR), CREATE TABLE problem_log (problem_log_id VARCHAR, assigned_to_staff_id VARCHAR, problem_id VARCHAR)
列出分配给名为“马” “军军”的工作人员的问题id和日志id。
SELECT DISTINCT T2.problem_id , T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "马" AND T1.staff_last_name = "军军"
CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR), CREATE TABLE problem_log (problem_log_id VARCHAR, assigned_to_staff_id VARCHAR, problem_id VARCHAR)
哪个问题ID和日志ID被指派给名为“马” “军军”的员工?
SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "显示器"
CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE problems (product_id VARCHAR)
“显示器”产品有多少问题?
SELECT count(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "显示器"
CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE problems (product_id VARCHAR)
被称为“显示器”的产品有多少问题被记录?
SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1
CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE problems (product_id VARCHAR)
出问题最多的产品有多少问题?列出问题的数量和产品名称。
SELECT count(*) , T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY count(*) DESC LIMIT 1
CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE problems (product_id VARCHAR)
哪种产品有最多数量的问题?给出问题数量和产品名称。
SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁"
CREATE TABLE problems (reported_by_staff_id VARCHAR, problem_description VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR)
请给出一个名字为“梁”的工作人员报告的问题的描述列表。
SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁"
CREATE TABLE problems (reported_by_staff_id VARCHAR, problem_description VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR)
名字是“梁”的员工报告了哪些问题?显示问题的描述。
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "兰兰"
CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR)
找出姓氏为“兰兰”的工作人员报告的问题的ID。
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "兰兰"
CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR)
姓“兰兰”的员工报告了哪些问题?显示问题的ID。
SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"
CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
“1978-06-26”后报告的问题的ID是什么?
SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"
CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
找出“1978-06-26”后所报告问题的ID。
SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"
CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
“1978-06-26”之前报告的问题的ID是什么?
SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"
CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
“1978-06-26”之前有哪些问题?把问题的ID告诉我。
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id
CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_id VARCHAR)
对于每个有问题的产品,问题的数量和产品id是什么?
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id
CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_id VARCHAR)
对于每个有问题的产品,列出问题的数量和产品id。
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id
CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER), CREATE TABLE product (product_id VARCHAR)
对于每个有问题的产品,查找“1986-11-13”之后报告的问题的数量和产品ID?
SELECT count(*) , T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id
CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER), CREATE TABLE product (product_id VARCHAR)
在“1986-11-13”之后有哪些产品出现了问题?给我产品ID和“1986-11-13”后报告的问题数。
SELECT DISTINCT product_name FROM product ORDER BY product_name
CREATE TABLE product (product_name VARCHAR)
按字母顺序列出所有不同产品名称的名称。
SELECT DISTINCT product_name FROM product ORDER BY product_name
CREATE TABLE product (product_name VARCHAR)
按字母顺序排列所有的不同的产品名称。
SELECT DISTINCT product_name FROM product ORDER BY product_id
CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
按产品ID排序列出所有不同的产品名称。
SELECT DISTINCT product_name FROM product ORDER BY product_id
CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
用产品ID排序的不同产品名称列表是什么?
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李" AND T2.staff_last_name = "航" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "白" AND T2.staff_last_name = "博文"
CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
名字为“李” “航”或“白” “博文”的工作人员报告的问题的ID是什么?
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李" AND T2.staff_last_name = "航" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "白" AND T2.staff_last_name = "博文"
CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
“李” “航”或“白” “博文”的工作人员报告了哪些问题?给出问题的ID。
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁" AND T2.staff_last_name = "天一" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李红" AND T2.staff_last_name = "军"
CREATE TABLE problems (closure_authorised_by_staff_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
对于“梁” “天一”报告的由“李红” “军”授权关闭的问题的产品标识是什么?
SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "梁" AND T2.staff_last_name = "天一" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "李红" AND T2.staff_last_name = "军"
CREATE TABLE problems (closure_authorised_by_staff_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
“梁” “天一”报告了哪些产品的问题被“李红” “军”授权关闭?返回产品的ID。
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "严" AND T4.staff_last_name = "冰" )
CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
在“严” “冰”报告的任何问题发生之前报告的问题的ID是什么?
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < ( SELECT min(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "严" AND T4.staff_last_name = "冰" )
CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
在工作人员“严” “冰”报告任何问题的日期之前,报告了哪些问题?把问题的ID告诉我。
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "马" AND T4.staff_last_name = "军军" )
CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
在“马” “军军”报告的问题之后报告的问题的ID是什么?
SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > ( SELECT max(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "马" AND T4.staff_last_name = "军军" )
CREATE TABLE problems (reported_by_staff_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
找出在“马” “军军”员工报告的任何问题日期之后报告的问题的ID。
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
找出问题数量最多的3个产品。
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY count(*) DESC LIMIT 3
CREATE TABLE problems (product_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
哪三种产品有最多的问题?
SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "显示器" AND T1.date_problem_reported > "1995"
CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER, product_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
列出1995年以后报告的产品“显示器”中问题的ID?
SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "显示器" AND T1.date_problem_reported > "1995"
CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER, product_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
在1995年以后报告了产品名字是“显示器”相关问题的id是什么?
SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "内存" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "硬盘"
CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
找到那些从产品“内存”而不是“硬盘”报告问题的员工的名字和姓氏?
SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "内存" EXCEPT SELECT T3.staff_first_name , T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "硬盘"
CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
哪些员工报告“内存”产品而不是“硬盘”产品的问题?给出他们的名字和姓氏。
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "刘" AND T3.staff_last_name = "兰兰" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "王" AND T3.staff_last_name = "平之"
CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
找出“刘” “兰兰”和“王” “平之”都报告有问题的产品
SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "刘" AND T3.staff_last_name = "兰兰" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "王" AND T3.staff_last_name = "平之"
CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR), CREATE TABLE product (product_name VARCHAR, product_id VARCHAR), CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
“刘” “兰兰”和员工“王” “平之”报告有问题的产品是哪些?