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SELECT count(*) FROM Ref_colors WHERE color_code NOT IN ( SELECT color_code FROM products )
CREATE TABLE Ref_colors (color_code VARCHAR), CREATE TABLE products (color_code VARCHAR)
什么颜色从来没有被任何产品使用?
SELECT count(*) FROM Ref_colors WHERE color_code NOT IN ( SELECT color_code FROM products )
CREATE TABLE Ref_colors (color_code VARCHAR), CREATE TABLE products (color_code VARCHAR)
计算任何产品中没有使用的颜色的数量。
SELECT count(*) FROM event
CREATE TABLE event (Id VARCHAR)
有多少活动?
SELECT name FROM event ORDER BY YEAR DESC
CREATE TABLE event (YEAR VARCHAR, name VARCHAR)
将所有事件名称按从最新到最老的年份列出。
SELECT name FROM event ORDER BY YEAR DESC LIMIT 1
CREATE TABLE event (YEAR VARCHAR, name VARCHAR)
最近的一年发生的事件的名称是什么?
SELECT count(*) FROM stadium
CREATE TABLE stadium (Id VARCHAR)
有多少个体育场?
SELECT name FROM stadium ORDER BY capacity DESC LIMIT 1
CREATE TABLE stadium (name VARCHAR, capacity VARCHAR)
找出具有最大容量的体育场名称。
SELECT name FROM stadium WHERE capacity < (SELECT avg(capacity) FROM stadium)
CREATE TABLE stadium (name VARCHAR, capacity INTEGER)
找出容量小于平均容量的体育场馆的名称。
SELECT country FROM stadium GROUP BY country ORDER BY count(*) DESC LIMIT 1
CREATE TABLE stadium (country VARCHAR)
找到拥有最多球场的国家。
SELECT country FROM stadium GROUP BY country HAVING count(*) <= 3
CREATE TABLE stadium (country VARCHAR)
哪个国家有最多3个体育场馆在名单上?
SELECT country FROM stadium WHERE capacity > 60000 INTERSECT SELECT country FROM stadium WHERE capacity < 50000
CREATE TABLE stadium (capacity INTEGER, country VARCHAR)
哪个国家既有容量大于60000个的体育场馆,又有容量小于50000个的体育场?
SELECT count(DISTINCT city) FROM stadium WHERE opening_year < 2006
CREATE TABLE stadium (opening_year INTEGER, city VARCHAR)
有多少个城市有在2006年前开放的体育场?
SELECT country , count(*) FROM stadium GROUP BY country
CREATE TABLE stadium (country VARCHAR)
每个国家有多少个体育场馆?
SELECT country FROM stadium EXCEPT SELECT country FROM stadium WHERE opening_year > 2006
CREATE TABLE stadium (opening_year INTEGER, country VARCHAR)
哪些国家没有在2006后开放的体育场?
SELECT count(*) FROM stadium WHERE country != '俄罗斯'
CREATE TABLE stadium (country VARCHAR)
在“俄罗斯”这个国家有多少个体育场?
SELECT name FROM swimmer ORDER BY meter_100
CREATE TABLE swimmer (name VARCHAR, meter_100 VARCHAR)
找出所有游泳运动员的名字,按他们的100米成绩按升序排列。
SELECT count(DISTINCT nationality) FROM swimmer
CREATE TABLE swimmer (nationality VARCHAR)
游泳运动员来自多少个不同的国家?
SELECT nationality , count(*) FROM swimmer GROUP BY nationality HAVING count(*) > 1
CREATE TABLE swimmer (nationality VARCHAR)
列出有一个以上游泳运动员的国家。
SELECT meter_200 , meter_300 FROM swimmer WHERE nationality = '澳大利亚'
CREATE TABLE swimmer (meter_200 VARCHAR, nationality VARCHAR, meter_300 VARCHAR)
找出所有200米和300米游泳成绩且国籍是“澳大利亚”的游泳运动员。
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = '胜利'
CREATE TABLE swimmer (name VARCHAR, id VARCHAR), CREATE TABLE record (swimmer_id VARCHAR)
找出有结果是“胜利”的游泳运动员的名字。
SELECT t1.name FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE stadium (name VARCHAR, id VARCHAR), CREATE TABLE event (stadium_id VARCHAR)
举办最多赛事的体育场叫什么名字?
SELECT t1.name , t1.capacity FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id WHERE t2.name = '世界杯'
CREATE TABLE stadium (name VARCHAR, capacity VARCHAR, id VARCHAR), CREATE TABLE event (name VARCHAR, stadium_id VARCHAR)
找出“世界杯”活动发生的体育场的名称及其容量。
SELECT name FROM stadium WHERE id NOT IN (SELECT stadium_id FROM event)
CREATE TABLE stadium (name VARCHAR, stadium_id VARCHAR, id VARCHAR), CREATE TABLE event (name VARCHAR, stadium_id VARCHAR, id VARCHAR)
找到那些从来没有举办过活动的体育场馆的名字。
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE swimmer (name VARCHAR, id VARCHAR), CREATE TABLE record (swimmer_id VARCHAR)
找出有最多数量记录的游泳者的名字。
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id HAVING count(*) >= 2
CREATE TABLE swimmer (name VARCHAR, id VARCHAR), CREATE TABLE record (swimmer_id VARCHAR)
找到至少有2条记录的游泳运动员的名字。
SELECT t1.name , t1.nationality FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = '胜利' GROUP BY t2.swimmer_id HAVING count(*) > 1
CREATE TABLE swimmer (nationality VARCHAR, name VARCHAR, id VARCHAR), CREATE TABLE record (swimmer_id VARCHAR)
找出“胜利”1次以上比赛的游泳运动员的姓名和国籍。
SELECT name FROM swimmer WHERE id NOT IN (SELECT swimmer_id FROM record)
CREATE TABLE swimmer (name VARCHAR, id VARCHAR, swimmer_id VARCHAR), CREATE TABLE record (name VARCHAR, id VARCHAR, swimmer_id VARCHAR)
找出没有记录的游泳运动员的名字。
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = '胜利' INTERSECT SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = '输'
CREATE TABLE swimmer (name VARCHAR, id VARCHAR), CREATE TABLE record (swimmer_id VARCHAR)
找出在记录中同时有“胜利”和“失败”结果的游泳运动员的名字。
SELECT t4.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id JOIN event AS t3 ON t2.event_id = t3.id JOIN stadium AS t4 ON t4.id = t3.stadium_id WHERE t1.nationality = '澳大利亚'
CREATE TABLE swimmer (nationality VARCHAR, id VARCHAR), CREATE TABLE record (event_id VARCHAR, swimmer_id VARCHAR), CREATE TABLE event (stadium_id VARCHAR, id VARCHAR), CREATE TABLE stadium (name VARCHAR, id VARCHAR)
找出“澳大利亚”游泳运动员去过的体育场馆的名字。
SELECT t3.name FROM record AS t1 JOIN event AS t2 ON t1.event_id = t2.id JOIN stadium AS t3 ON t3.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE record (event_id VARCHAR), CREATE TABLE event (stadium_id VARCHAR, id VARCHAR), CREATE TABLE stadium (name VARCHAR, id VARCHAR)
找出那些游泳运动员去过的体育场馆的名称。
SELECT * FROM swimmer
CREATE TABLE swimmer (Id VARCHAR)
找出每个游泳运动员的所有细节。
SELECT avg(capacity) FROM stadium WHERE opening_year = 2005
CREATE TABLE stadium (opening_year VARCHAR, capacity INTEGER)
2005年度开放的体育场的平均容量是多少?
SELECT count(*) FROM railway
CREATE TABLE railway (Id VARCHAR)
有多少条铁路?
SELECT Builder FROM railway ORDER BY Builder ASC
CREATE TABLE railway (Builder VARCHAR)
按字母顺序升序排列列出铁路的建设者。
SELECT Wheels , LOCATION FROM railway
CREATE TABLE railway (Wheels VARCHAR, LOCATION VARCHAR)
列出铁路的轮子和位置。
SELECT max(LEVEL) FROM manager WHERE Country != "澳大利亚"
CREATE TABLE manager (Country VARCHAR, LEVEL INTEGER)
那些国籍不是“澳大利亚”经理的最高水平是什么?
SELECT avg(Age) FROM manager
CREATE TABLE manager (Age INTEGER)
所有经理的平均年龄是多少?
SELECT Name FROM manager ORDER BY LEVEL ASC
CREATE TABLE manager (LEVEL VARCHAR, Name VARCHAR)
按等级升序排列经理的姓名是什么?
SELECT Name , Arrival FROM train
CREATE TABLE train (Name VARCHAR, Arrival VARCHAR)
列车的名称和到达时间是多少?
SELECT Name FROM manager ORDER BY Age DESC LIMIT 1
CREATE TABLE manager (Name VARCHAR, Age VARCHAR)
最老的经理叫什么名字?
SELECT T2.Name , T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID
CREATE TABLE railway (Location VARCHAR, Railway_ID VARCHAR), CREATE TABLE train (Name VARCHAR, Railway_ID VARCHAR)
显示火车的名称和他们所在铁路的位置。
SELECT T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID WHERE T2.Name = "和谐号"
CREATE TABLE railway (Builder VARCHAR, Railway_ID VARCHAR), CREATE TABLE train (Name VARCHAR, Railway_ID VARCHAR)
显示与“和谐号”列车相关的铁路建设商。
SELECT T2.Railway_ID , T1.Location FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID HAVING COUNT(*) > 1
CREATE TABLE railway (Location VARCHAR, Railway_ID VARCHAR), CREATE TABLE train (Railway_ID VARCHAR)
显示与超过一辆列车关联的铁路的ID和位置。
SELECT T2.Railway_ID , T1.Builder FROM railway AS T1 JOIN train AS T2 ON T1.Railway_ID = T2.Railway_ID GROUP BY T2.Railway_ID ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE railway (Builder VARCHAR, Railway_ID VARCHAR), CREATE TABLE train (Railway_ID VARCHAR)
显示与做多数量列车相关的铁路的ID和建设者。
SELECT Builder , COUNT(*) FROM railway GROUP BY Builder
CREATE TABLE railway (Builder VARCHAR)
显示不同的铁路建设者,以及使用每个建设者建设的相应数量的铁路。
SELECT Builder FROM railway GROUP BY Builder ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE railway (Builder VARCHAR)
展示铁路最常见的建设者。
SELECT LOCATION , COUNT(*) FROM railway GROUP BY LOCATION
CREATE TABLE railway (LOCATION VARCHAR)
显示不同位置的铁路以及每个位置的相应铁路的数量。
SELECT LOCATION FROM railway GROUP BY LOCATION HAVING COUNT(*) > 1
CREATE TABLE railway (LOCATION VARCHAR)
显示有超过一条铁路的位置。
SELECT ObjectNumber FROM railway WHERE Railway_ID NOT IN (SELECT Railway_ID FROM train)
CREATE TABLE railway (ObjectNumber VARCHAR, Railway_ID VARCHAR), CREATE TABLE train (ObjectNumber VARCHAR, Railway_ID VARCHAR)
列出没有火车的铁路的目标数。
SELECT Country FROM manager WHERE Age > 50 INTERSECT SELECT Country FROM manager WHERE Age < 46
CREATE TABLE manager (Country VARCHAR, Age INTEGER)
展示那些既有50岁以上经理又有46岁以下经理的国家。
SELECT DISTINCT Country FROM manager
CREATE TABLE manager (Country VARCHAR)
展示管理者的不同国家。
SELECT Working_year_starts FROM manager ORDER BY LEVEL DESC
CREATE TABLE manager (LEVEL VARCHAR, Working_year_starts VARCHAR)
按级别顺序递减显示经理的工作年限。
SELECT Country FROM manager WHERE Age > 50 OR Age < 46
CREATE TABLE manager (Country VARCHAR, Age INTEGER)
显示年龄在50岁以上或46岁以下的管理人员所在的国家。
SELECT count(*) FROM addresses WHERE country = '中国'
CREATE TABLE addresses (country VARCHAR)
“中国”这个国家有多少个地址?
SELECT DISTINCT city FROM addresses
CREATE TABLE addresses (city VARCHAR)
显示在地址记录中的所有不同的城市。
SELECT state_province_county , count(*) FROM addresses GROUP BY state_province_county
CREATE TABLE addresses (state_province_county VARCHAR)
显示每个省和每个省中的地址数量。
SELECT customer_name , customer_phone FROM customers WHERE customer_id NOT IN (SELECT customer_id FROM customer_address_history)
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, customer_phone VARCHAR), CREATE TABLE customer_address_history (customer_name VARCHAR, customer_id VARCHAR, customer_phone VARCHAR)
显示没有地址信息的客户的姓名和电话。
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR)
显示订单量最多的客户的名字。
SELECT product_type_code FROM products GROUP BY product_type_code HAVING count(*) >= 2
CREATE TABLE products (product_type_code VARCHAR)
显示具有至少两个产品的产品类型代码。
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = '完成' INTERSECT SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = '部分'
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (order_status_code VARCHAR, customer_id VARCHAR)
显示既具有“完成”状态的订单又具有“部分”状态的订单的客户的名字。
SELECT customer_name , customer_phone , payment_method_code FROM customers ORDER BY customer_number DESC
CREATE TABLE customers (customer_name VARCHAR, payment_method_code VARCHAR, customer_number VARCHAR, customer_phone VARCHAR)
按照客户编号的降序显示所有客户的名称、电话和支付方法代码。
SELECT T1.product_name , sum(T2.order_quantity) FROM products AS T1 JOIN order_items AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_id
CREATE TABLE products (product_name VARCHAR, product_id VARCHAR), CREATE TABLE order_items (order_quantity INTEGER, product_id VARCHAR)
显示每个产品的产品名称和总订单数量。
SELECT min(product_price) , max(product_price) , avg(product_price) FROM products
CREATE TABLE products (product_price INTEGER)
显示所有产品的最小,最大,平均价格。
SELECT count(*) FROM products WHERE product_price > (SELECT avg(product_price) FROM products)
CREATE TABLE products (product_price INTEGER)
有多少产品的价格高于平均水平?
SELECT T2.customer_name , T3.city , T1.date_from , T1.date_to FROM customer_address_history AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id JOIN addresses AS T3 ON T1.address_id = T3.address_id
CREATE TABLE customer_address_history (date_from VARCHAR, date_to VARCHAR, address_id VARCHAR, customer_id VARCHAR), CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR), CREATE TABLE addresses (address_id VARCHAR, city VARCHAR)
显示每个客户地址历史的客户名称、客户地址城市、起始日期和送达日期。
SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.payment_method_code = '信用卡' GROUP BY T1.customer_id HAVING count(*) > 2
CREATE TABLE customers (customer_name VARCHAR, payment_method_code VARCHAR, customer_id VARCHAR), CREATE TABLE customer_orders (customer_id VARCHAR)
显示使用“信用卡”付款方式并有2个以上订单的客户的姓名。
SELECT T1.customer_name , T1.customer_phone FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id JOIN order_items AS T3 ON T3.order_id = T2.order_id GROUP BY T1.customer_id ORDER BY sum(T3.order_quantity) DESC LIMIT 1
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, customer_phone VARCHAR), CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR), CREATE TABLE order_items (order_id VARCHAR, order_quantity INTEGER)
订购数量最多的顾客的姓名和电话是什么?
SELECT product_type_code , product_name FROM products WHERE product_price > 1000 OR product_price < 500
CREATE TABLE products (product_type_code VARCHAR, product_price INTEGER, product_name VARCHAR)
显示价格高于1000或低于500的产品类型和名称。
SELECT dorm_name FROM dorm WHERE gender = 'F'
CREATE TABLE dorm (dorm_name VARCHAR, gender VARCHAR)
找出仅为女性使用的宿舍名称(“女性”性别)。
SELECT dorm_name FROM dorm WHERE gender = 'F'
CREATE TABLE dorm (dorm_name VARCHAR, gender VARCHAR)
仅为“女性”使用的宿舍的名字是什么?
SELECT dorm_name FROM dorm WHERE student_capacity > 300
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity INTEGER)
找出能容纳超过300名学生的宿舍名称。
SELECT dorm_name FROM dorm WHERE student_capacity > 300
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity INTEGER)
可以容纳超过300名学生住宿的宿舍名字是什么?
SELECT count(*) FROM student WHERE sex = 'F' AND age < 25
CREATE TABLE student (sex VARCHAR, age INTEGER)
年龄在25岁以下的女生有多少?(性别是“女性”)
SELECT count(*) FROM student WHERE sex = 'F' AND age < 25
CREATE TABLE student (sex VARCHAR, age INTEGER)
25岁以下的“女”学生有多少?
SELECT fname FROM student WHERE age > 20
CREATE TABLE student (age INTEGER, fname VARCHAR)
找出20岁以上的学生的名字。
SELECT fname FROM student WHERE age > 20
CREATE TABLE student (age INTEGER, fname VARCHAR)
20岁以上的学生的名字是什么?
SELECT fname FROM student WHERE city_code = '天津' AND age BETWEEN 20 AND 25
CREATE TABLE student (city_code VARCHAR, age INTEGER, fname VARCHAR)
找出年龄在20到25岁之间且住在城市“天津”的学生的名字。
SELECT fname FROM student WHERE city_code = '天津' AND age BETWEEN 20 AND 25
CREATE TABLE student (city_code VARCHAR, age INTEGER, fname VARCHAR)
住在"天津"市的20至25岁学生的名字是什么?
SELECT count(*) FROM dorm
CREATE TABLE dorm (Id VARCHAR)
有多少宿舍?
SELECT count(*) FROM dorm
CREATE TABLE dorm (Id VARCHAR)
数据库中有多少个宿舍?
SELECT count(*) FROM dorm_amenity
CREATE TABLE dorm_amenity (Id VARCHAR)
找出不同的宿舍设施的数量。
SELECT count(*) FROM dorm_amenity
CREATE TABLE dorm_amenity (Id VARCHAR)
有多少不同的宿舍设施?
SELECT sum(student_capacity) FROM dorm
CREATE TABLE dorm (student_capacity INTEGER)
找到所有宿舍的总容量。
SELECT sum(student_capacity) FROM dorm
CREATE TABLE dorm (student_capacity INTEGER)
所有宿舍的学生总人数是多少?
SELECT count(*) FROM student
CREATE TABLE student (Id VARCHAR)
那儿有多少学生?
SELECT count(*) FROM student
CREATE TABLE student (Id VARCHAR)
有多少学生?
SELECT avg(age) , city_code FROM student GROUP BY city_code
CREATE TABLE student (city_code VARCHAR, age INTEGER)
找出每个城市学生的平均年龄。
SELECT avg(age) , city_code FROM student GROUP BY city_code
CREATE TABLE student (city_code VARCHAR, age INTEGER)
每个城市的平均年龄是什么?那些城市是什么?
SELECT avg(student_capacity) , sum(student_capacity) FROM dorm WHERE gender = 'X'
CREATE TABLE dorm (student_capacity INTEGER, gender VARCHAR)
找出具有性别是“X”的学生宿舍的平均容量和总容量。
SELECT avg(student_capacity) , sum(student_capacity) FROM dorm WHERE gender = 'X'
CREATE TABLE dorm (student_capacity INTEGER, gender VARCHAR)
所有性别为“X”的宿舍的平均和总容量是多少?
SELECT count(DISTINCT dormid) FROM has_amenity
CREATE TABLE has_amenity (dormid VARCHAR)
找到一些有宿舍设施的宿舍。
SELECT count(DISTINCT dormid) FROM has_amenity
CREATE TABLE has_amenity (dormid VARCHAR)
有多少宿舍有设施?
SELECT dorm_name FROM dorm WHERE dormid NOT IN (SELECT dormid FROM has_amenity)
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR), CREATE TABLE has_amenity (dorm_name VARCHAR, dormid VARCHAR)
找到没有设施的宿舍的名字
SELECT dorm_name FROM dorm WHERE dormid NOT IN (SELECT dormid FROM has_amenity)
CREATE TABLE dorm (dorm_name VARCHAR, dormid VARCHAR), CREATE TABLE has_amenity (dorm_name VARCHAR, dormid VARCHAR)
所有没有设施的宿舍的名字是什么?
SELECT count(DISTINCT gender) FROM dorm
CREATE TABLE dorm (gender VARCHAR)
找出宿舍的不同性别的数量。
SELECT count(DISTINCT gender) FROM dorm
CREATE TABLE dorm (gender VARCHAR)
宿舍里有多少不同性别的人?
SELECT student_capacity , gender FROM dorm WHERE dorm_name LIKE '慧'
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity VARCHAR, gender VARCHAR)
找出名字中包含“慧”字的宿舍中学生的能力和性别.
SELECT student_capacity , gender FROM dorm WHERE dorm_name LIKE '慧'
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity VARCHAR, gender VARCHAR)
名字中包含“慧”字段的宿舍中学生的能力和性别是什么?
SELECT dorm_name , gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity INTEGER, gender VARCHAR)
找出容量大于300或小于100的宿舍的名称和性别类型。
SELECT dorm_name , gender FROM dorm WHERE student_capacity > 300 OR student_capacity < 100
CREATE TABLE dorm (dorm_name VARCHAR, student_capacity INTEGER, gender VARCHAR)
容量大于300或小于100的宿舍的名称和类型是什么?