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SELECT DISTINCT COUNT ( t4.citedpaperid ) , t3.year FROM paper AS t3 JOIN cite AS t4 ON t3.paperid = t4.citedpaperid JOIN writes AS t2 ON t2.paperid = t3.paperid JOIN author AS t1 ON t2.authorid = t1.authorid WHERE t1.authorname = "卢克·泽特莫耶尔" GROUP BY t3.year;
CREATE TABLE paper (paperid VARCHAR, year VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR), CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR)
“卢克·泽特莫耶尔”每一年有多少引用?
SELECT DISTINCT t2.paperid FROM paperdataset AS t3 JOIN dataset AS t1 ON t3.datasetid = t1.datasetid JOIN paper AS t4 ON t4.paperid = t3.paperid JOIN writes AS t2 ON t2.paperid = t4.paperid WHERE t1.datasetname = "ImageNet" GROUP BY t2.paperid;
CREATE TABLE paperdataset (paperid VARCHAR, datasetid VARCHAR), CREATE TABLE dataset (datasetname VARCHAR, datasetid VARCHAR), CREATE TABLE paper (paperid VARCHAR), CREATE TABLE writes (paperid VARCHAR)
ImageNet的作者
SELECT DISTINCT paperid , title FROM paper WHERE title LIKE "%提取液对癌症患者的影响%" AND YEAR > 2006;
CREATE TABLE paper (paperid VARCHAR, title VARCHAR, YEAR INTEGER)
自2006年以来,关于“提取液对癌症患者的影响”发表了哪些文章?
SELECT DISTINCT t2.paperid FROM paperkeyphrase AS t5 JOIN keyphrase AS t3 ON t5.keyphraseid = t3.keyphraseid JOIN writes AS t4 ON t4.paperid = t5.paperid JOIN paper AS t2 ON t4.paperid = t2.paperid JOIN author AS t1 ON t4.authorid = t1.authorid JOIN venue AS t6 ON t6.venueid = t2.venueid WHERE t1.authorname = "埃里克·克拉甘" AND t3.keyphrasename = "液体" AND t6.venuename = "Automatica";
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR, keyphrasename VARCHAR), CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
“埃里克·克拉甘”的“液体”相关的“Automatica”论文
SELECT DISTINCT t3.venueid , t3.year FROM writes AS t2 JOIN author AS t1 ON t2.authorid = t1.authorid JOIN paper AS t3 ON t2.paperid = t3.paperid WHERE t1.authorname = "谢尔盖·莱文" GROUP BY t3.venueid , t3.year ORDER BY t3.year DESC;
CREATE TABLE writes (authorid VARCHAR, paperid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR, venueid VARCHAR)
“谢尔盖·莱文”在哪里发表了他的最后一篇论文?
SELECT DISTINCT t2.keyphraseid FROM paper AS t3 JOIN paperkeyphrase AS t2 ON t3.paperid = t2.paperid JOIN venue AS t4 ON t4.venueid = t3.venueid JOIN writes AS t5 ON t5.paperid = t3.paperid JOIN author AS t1 ON t5.authorid = t1.authorid WHERE t1.authorname = "丹·克莱因" AND t4.venuename = "emnlp";
CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR), CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR)
“丹·克莱因”在EMNLP论文中使用的关键词
SELECT DISTINCT COUNT ( t4.paperid ) , t3.authorid FROM paperkeyphrase AS t1 JOIN keyphrase AS t2 ON t1.keyphraseid = t2.keyphraseid JOIN paper AS t4 ON t4.paperid = t1.paperid JOIN writes AS t3 ON t3.paperid = t4.paperid WHERE t2.keyphrasename = "中和抗体" AND t4.year = 2012 GROUP BY t3.authorid ORDER BY COUNT ( t4.paperid ) DESC;
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR, keyphrasename VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR), CREATE TABLE writes (authorid VARCHAR, paperid VARCHAR)
2012年“中和抗体”研究的主要研究者是谁?
SELECT DISTINCT t3.paperid FROM paperdataset AS t2 JOIN dataset AS t1 ON t2.datasetid = t1.datasetid JOIN paper AS t3 ON t3.paperid = t2.paperid JOIN venue AS t4 ON t4.venueid = t3.venueid WHERE t1.datasetname = "ImageNet" AND t3.year = 2014 AND t4.venuename = "eccv";
CREATE TABLE paperdataset (paperid VARCHAR, datasetid VARCHAR), CREATE TABLE dataset (datasetname VARCHAR, datasetid VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR, venueid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
2014年使用ImageNet数据集的ECCV论文
SELECT DISTINCT t3.paperid FROM paperdataset AS t2 JOIN dataset AS t1 ON t2.datasetid = t1.datasetid JOIN paper AS t3 ON t3.paperid = t2.paperid JOIN venue AS t4 ON t4.venueid = t3.venueid WHERE t1.datasetname = "ImageNet" AND t3.year = 2014 AND t4.venuename = "eccv";
CREATE TABLE paperdataset (paperid VARCHAR, datasetid VARCHAR), CREATE TABLE dataset (datasetname VARCHAR, datasetid VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR, venueid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
ECCV 2014中的哪些论文使用了ImageNet?
SELECT DISTINCT t3.paperid FROM paperdataset AS t2 JOIN dataset AS t1 ON t2.datasetid = t1.datasetid JOIN paper AS t3 ON t3.paperid = t2.paperid JOIN venue AS t4 ON t4.venueid = t3.venueid WHERE t1.datasetname = "ImageNet" AND t3.year = 2014 AND t4.venuename = "eccv";
CREATE TABLE paperdataset (paperid VARCHAR, datasetid VARCHAR), CREATE TABLE dataset (datasetname VARCHAR, datasetid VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR, venueid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
使用ImageNet的ECCV 2014会议的论文
SELECT DISTINCT t5.citingpaperid FROM paperkeyphrase AS t2 JOIN keyphrase AS t1 ON t2.keyphraseid = t1.keyphraseid JOIN cite AS t5 ON t2.paperid = t5.citingpaperid JOIN paper AS t3 ON t3.paperid = t5.citedpaperid JOIN venue AS t4 ON t4.venueid = t3.venueid WHERE t1.keyphrasename = "欧几里德距离" AND t4.venuename = "NIPS";
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR, keyphrasename VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR, citingpaperid VARCHAR), CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
引用发表在NIPS论文的关于“欧几里德距离”的论文
SELECT DISTINCT COUNT ( t4.paperid ) , t3.paperid FROM paperdataset AS t2 JOIN dataset AS t1 ON t2.datasetid = t1.datasetid JOIN paper AS t4 ON t4.paperid = t2.paperid JOIN writes AS t3 ON t3.paperid = t4.paperid WHERE t1.datasetname = "ImageNet" GROUP BY t3.paperid ORDER BY COUNT ( t4.paperid ) DESC;
CREATE TABLE paperdataset (paperid VARCHAR, datasetid VARCHAR), CREATE TABLE dataset (datasetname VARCHAR, datasetid VARCHAR), CREATE TABLE paper (paperid VARCHAR), CREATE TABLE writes (paperid VARCHAR)
研究ImageNet的顶级作者
SELECT DISTINCT ( t1.paperid ) , COUNT ( t3.citingpaperid ) FROM paper AS t1 JOIN cite AS t3 ON t1.paperid = t3.citedpaperid JOIN venue AS t2 ON t2.venueid = t1.venueid WHERE t1.year = 2012 AND t2.venuename = "ACL" GROUP BY t1.paperid HAVING COUNT ( t3.citingpaperid ) > 7;
CREATE TABLE paper (paperid VARCHAR, year VARCHAR, venueid VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR, citingpaperid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
有多少ACL 2012的论文引用超过7次?
SELECT DISTINCT COUNT ( DISTINCT t4.citingpaperid ) , t1.keyphraseid , t2.paperid FROM paper AS t2 JOIN cite AS t4 ON t2.paperid = t4.citedpaperid JOIN paperkeyphrase AS t1 ON t2.paperid = t1.paperid JOIN venue AS t3 ON t3.venueid = t2.venueid WHERE t2.year = 2012 AND t3.venuename = "EMNLP-CoNLL" GROUP BY t2.paperid , t1.keyphraseid ORDER BY COUNT ( DISTINCT t4.citingpaperid ) DESC;
CREATE TABLE paper (paperid VARCHAR, year VARCHAR, venueid VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR, citingpaperid VARCHAR), CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
2012年度EnnLL-CONLL最佳论文的题目是什么?
SELECT DISTINCT COUNT ( DISTINCT t2.paperid ) FROM writes AS t2 JOIN author AS t1 ON t2.authorid = t1.authorid JOIN paper AS t3 ON t2.paperid = t3.paperid WHERE t1.authorname != "诺亚·史密斯" AND t3.year > 2009 AND t2.paperid IN ( SELECT t2.paperid FROM writes AS t2 JOIN author AS t1 ON t2.authorid = t1.authorid WHERE t1.authorname LIKE "%诺亚·史密斯%" );
CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR), CREATE TABLE paper (paperid VARCHAR, year INTEGER)
自2009以来“诺亚·史密斯”共同参与创作了多少篇论文?
SELECT DISTINCT COUNT ( t3.citingpaperid ) FROM paper AS t1 JOIN cite AS t3 ON t1.paperid = t3.citedpaperid JOIN venue AS t2 ON t2.venueid = t1.venueid WHERE t2.venuename = "ACL" GROUP BY t3.citingpaperid HAVING COUNT ( DISTINCT t3.citedpaperid ) > 2;
CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR, citingpaperid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
超过2各引用的ACL论文数
SELECT DISTINCT t2.title FROM paperkeyphrase AS t5 JOIN keyphrase AS t3 ON t5.keyphraseid = t3.keyphraseid JOIN writes AS t4 ON t4.paperid = t5.paperid JOIN paper AS t2 ON t4.paperid = t2.paperid JOIN author AS t1 ON t4.authorid = t1.authorid JOIN venue AS t6 ON t6.venueid = t2.venueid WHERE t1.authorname LIKE "%埃里克·克拉甘%" AND t3.keyphrasename = "液体" AND t6.venuename = "Automatica";
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR, keyphrasename VARCHAR), CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE paper (paperid VARCHAR, title VARCHAR, venueid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
“埃里克·克拉甘”的在“Automatica”会议上发表的“液体”相关的论文叫什么名字?
SELECT DISTINCT COUNT ( t3.paperid ) FROM paperdataset AS t2 JOIN dataset AS t1 ON t2.datasetid = t1.datasetid JOIN paper AS t3 ON t3.paperid = t2.paperid JOIN venue AS t4 ON t4.venueid = t3.venueid WHERE t1.datasetname = "ImageNet" AND t4.venuename = "CVPR";
CREATE TABLE paperdataset (paperid VARCHAR, datasetid VARCHAR), CREATE TABLE dataset (datasetname VARCHAR, datasetid VARCHAR), CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
在“CVPR”中使用ImageNet数据集的论文有多少?
SELECT DISTINCT venueid FROM venue WHERE venuename = "神经科学";
CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
“神经科学”的会议是什么?
SELECT DISTINCT MAX ( t3.year ) FROM writes AS t2 JOIN author AS t1 ON t2.authorid = t1.authorid JOIN paper AS t3 ON t2.paperid = t3.paperid WHERE t1.authorname = "玛丽·克莱因";
CREATE TABLE writes (authorid VARCHAR, paperid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR), CREATE TABLE paper (year INTEGER, paperid VARCHAR)
“玛丽·克莱因”上一次发表论文是什么时候?
SELECT DISTINCT t1.authorid FROM paperkeyphrase AS t6 JOIN keyphrase AS t3 ON t6.keyphraseid = t3.keyphraseid JOIN writes AS t4 ON t4.paperid = t6.paperid JOIN writes AS t5 ON t5.paperid = t4.paperid JOIN author AS t1 ON t5.authorid = t1.authorid JOIN author AS t2 ON t4.authorid = t2.authorid WHERE t2.authorname = "菲利普·可汗" AND t3.keyphrasename = "机器翻译输出";
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR, keyphrasename VARCHAR), CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR)
返回“菲利普·可汗”的“机器翻译输出”的论文合著者
SELECT DISTINCT COUNT ( DISTINCT t3.paperid ) FROM venue AS t4 JOIN paper AS t3 ON t4.venueid = t3.venueid JOIN writes AS t2 ON t2.paperid = t3.paperid JOIN author AS t1 ON t2.authorid = t1.authorid WHERE t1.authorname = "塞缪尔·马登" AND t4.venuename != "PVLDB";
CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR), CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR)
“塞缪尔·马登”在“PVLDB”以外的会议发表了多少论文?
SELECT DISTINCT t3.journalid , t3.year FROM writes AS t2 JOIN author AS t1 ON t2.authorid = t1.authorid JOIN paper AS t3 ON t2.paperid = t3.paperid WHERE t1.authorname = "唐纳德·克努斯" GROUP BY t3.journalid , t3.year ORDER BY t3.year DESC;
CREATE TABLE writes (authorid VARCHAR, paperid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR, journalid VARCHAR)
“唐纳德·克努斯”在哪一个期刊上发表了他的最后一篇论文?
SELECT DISTINCT venueid FROM paper WHERE title = "丙烯酸骨水泥断裂";
CREATE TABLE paper (title VARCHAR, venueid VARCHAR)
“丙烯酸骨水泥断裂”发表的会议是什么?
SELECT DISTINCT COUNT ( t2.paperid ) FROM venue AS t3 JOIN paper AS t2 ON t3.venueid = t2.venueid JOIN writes AS t1 ON t1.paperid = t2.paperid WHERE t2.year = 2010 AND t3.venuename = "SigCSE";
CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR, venueid VARCHAR), CREATE TABLE writes (paperid VARCHAR)
2010在“SigCSE”有多少作者发表了论文?
SELECT DISTINCT title , YEAR FROM paper WHERE title = "ISDN交换架构";
CREATE TABLE paper (YEAR VARCHAR, title VARCHAR)
“ISDN交换架构”发布的年份是什么?
SELECT DISTINCT t1.keyphraseid FROM paperkeyphrase AS t2 JOIN keyphrase AS t1 ON t2.keyphraseid = t1.keyphraseid JOIN paper AS t3 ON t3.paperid = t2.paperid JOIN venue AS t4 ON t4.venueid = t3.venueid WHERE t4.venuename = "UIST";
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR), CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
“UIST”论文使用哪些关键词
SELECT DISTINCT t3.paperid FROM writes AS t2 JOIN author AS t1 ON t2.authorid = t1.authorid JOIN paper AS t3 ON t2.paperid = t3.paperid WHERE t1.authorname = "李素音" AND t3.year < 2012;
CREATE TABLE writes (authorid VARCHAR, paperid VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR), CREATE TABLE paper (paperid VARCHAR, year INTEGER)
给我2012年以前“李素音”写的论文。
SELECT DISTINCT COUNT ( t3.paperid ) , t3.year FROM paperkeyphrase AS t2 JOIN keyphrase AS t1 ON t2.keyphraseid = t1.keyphraseid JOIN paper AS t3 ON t3.paperid = t2.paperid WHERE t1.keyphrasename = "语义分析" GROUP BY t3.year ORDER BY t3.year DESC;
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR, keyphrasename VARCHAR), CREATE TABLE paper (paperid VARCHAR, year VARCHAR)
列出每一年“语义分析”的论文
SELECT DISTINCT t2.citingpaperid FROM paper AS t1 JOIN cite AS t2 ON t1.paperid = t2.citedpaperid GROUP BY t2.citingpaperid HAVING COUNT ( DISTINCT t2.citedpaperid ) >= 5;
CREATE TABLE paper (paperid VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR, citingpaperid VARCHAR)
至少5篇引用的论文
SELECT DISTINCT t2.citingpaperid FROM paper AS t1 JOIN cite AS t2 ON t1.paperid = t2.citedpaperid GROUP BY t2.citingpaperid HAVING COUNT ( DISTINCT t2.citedpaperid ) >= 5;
CREATE TABLE paper (paperid VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR, citingpaperid VARCHAR)
至少有5篇其他论文引用的论文
SELECT DISTINCT t3.citedpaperid , COUNT ( t3.citingpaperid ) FROM paper AS t1 JOIN cite AS t3 ON t1.paperid = t3.citedpaperid JOIN venue AS t2 ON t2.venueid = t1.venueid WHERE t2.venuename = "SigCOMM" GROUP BY t3.citedpaperid ORDER BY COUNT ( t3.citingpaperid ) DESC;
CREATE TABLE paper (paperid VARCHAR, venueid VARCHAR), CREATE TABLE cite (citedpaperid VARCHAR, citingpaperid VARCHAR), CREATE TABLE venue (venuename VARCHAR, venueid VARCHAR)
“SigCOMM”引用量最多的论文是什么?
SELECT DISTINCT t3.title FROM paperkeyphrase AS t2 JOIN keyphrase AS t5 ON t2.keyphraseid = t5.keyphraseid JOIN writes AS t4 ON t4.paperid = t2.paperid JOIN paper AS t3 ON t4.paperid = t3.paperid JOIN author AS t1 ON t4.authorid = t1.authorid WHERE t1.authorname LIKE "%兰吉特·贾拉%" AND t5.keyphrasename = "LH";
CREATE TABLE paperkeyphrase (paperid VARCHAR, keyphraseid VARCHAR), CREATE TABLE keyphrase (keyphraseid VARCHAR, keyphrasename VARCHAR), CREATE TABLE writes (paperid VARCHAR, authorid VARCHAR), CREATE TABLE paper (paperid VARCHAR, title VARCHAR), CREATE TABLE author (authorid VARCHAR, authorname VARCHAR)
“兰吉特·贾拉”的发表的关于“LH”的论文叫什么名字?
SELECT name FROM business WHERE rating > 4.5;
CREATE TABLE business (name VARCHAR, rating INTEGER)
列出超过4.5颗星的所有餐厅
SELECT name FROM business WHERE rating = 3.5;
CREATE TABLE business (name VARCHAR, rating VARCHAR)
列出所有评级为3.5的餐厅
SELECT user_id FROM USER WHERE name = "米雪";
CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
列出名字是“米雪”的所有用户ID
SELECT state FROM business WHERE name = "汉堡王";
CREATE TABLE business (state VARCHAR, name VARCHAR)
查找所有有“汉堡王”的省份
SELECT t1.city FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "海盗船自助餐" AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, city VARCHAR, business_id VARCHAR)
找出有一个叫“海盗船自助餐”的“餐厅”的所有的城市。
SELECT city FROM business WHERE rating < 1.5;
CREATE TABLE business (city VARCHAR, rating INTEGER)
找出低于1.5的餐厅
SELECT city FROM business WHERE name = "南京大牌档";
CREATE TABLE business (name VARCHAR, city VARCHAR)
找出所有有“南京大牌档”的城市。
SELECT text FROM review WHERE rating < 1;
CREATE TABLE review (text VARCHAR, rating INTEGER)
列出所有相关餐厅少于1个的评论
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.rating > 3.5 AND t2.category_name = "餐馆";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, rating INTEGER)
列出所有超过3.5的“餐馆”
SELECT t1.city FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "南京大牌档" AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, city VARCHAR, business_id VARCHAR)
找出所有拥有“南京大牌档”“餐厅”的城市
SELECT t1.text FROM USER AS t2 JOIN review AS t1 ON t2.user_id = t1.user_id WHERE t2.name = "王岩";
CREATE TABLE USER (user_id VARCHAR, name VARCHAR), CREATE TABLE review (text VARCHAR, user_id VARCHAR)
列出“王岩”的所有评论
SELECT t1.name FROM review AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN USER AS t3 ON t3.user_id = t2.user_id WHERE t3.name = "王岩";
CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
列出所有由“王岩”评论的餐厅
SELECT t1.name FROM review AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN USER AS t3 ON t3.user_id = t2.user_id WHERE t2.rating = 5 AND t3.name = "王岩";
CREATE TABLE review (user_id VARCHAR, business_id VARCHAR, rating VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
列出“王岩”评级5的所有业务
SELECT t4.text FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id JOIN review AS t4 ON t4.business_id = t1.business_id JOIN USER AS t5 ON t5.user_id = t4.user_id WHERE t2.category_name = "意大利" AND t3.category_name = "餐馆" AND t5.name = "米雪";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (business_id VARCHAR), CREATE TABLE review (text VARCHAR, user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
列出“米雪”为“意大利”“餐馆”所做的所有评论
SELECT COUNT ( DISTINCT t3.text ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id WHERE t1.name = "星巴克" AND t1.state = "云南" AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (state VARCHAR, name VARCHAR, business_id VARCHAR), CREATE TABLE review (text VARCHAR, business_id VARCHAR)
找出在“云南”的“星巴克”“餐厅”的评论数量
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id WHERE t1.rating = 5 AND t2.category_name = "意大利" AND t3.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, rating VARCHAR)
列出5星级“意大利”“餐厅”
SELECT t1.neighbourhood_name FROM category AS t3 JOIN business AS t2 ON t3.business_id = t2.business_id JOIN category AS t4 ON t4.business_id = t2.business_id JOIN neighbourhood AS t1 ON t1.business_id = t2.business_id WHERE t2.city = "成都" AND t3.category_name = "意大利" AND t4.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (city VARCHAR, business_id VARCHAR), CREATE TABLE neighbourhood (neighbourhood_name VARCHAR, business_id VARCHAR)
列出在“成都”的“意大利”“餐厅”的街区
SELECT t1.neighbourhood_name FROM category AS t3 JOIN business AS t2 ON t3.business_id = t2.business_id JOIN category AS t4 ON t4.business_id = t2.business_id JOIN neighbourhood AS t1 ON t1.business_id = t2.business_id WHERE t2.city = "Madison" AND t2.rating < 2.5 AND t3.category_name = "意大利" AND t4.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (city VARCHAR, business_id VARCHAR, rating INTEGER), CREATE TABLE neighbourhood (neighbourhood_name VARCHAR, business_id VARCHAR)
列出“成都”所有拥有评级低于2.5的“意大利”“餐厅”的街区
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.state = "黑龙江" AND t2.category_name = "餐馆";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (state VARCHAR, name VARCHAR, business_id VARCHAR)
找出“黑龙江”所有的“餐馆”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.state = "黑龙江" AND t2.category_name = "餐馆";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (state VARCHAR, name VARCHAR, business_id VARCHAR)
列出所有在“黑龙江”的“餐馆”。
SELECT t3.text FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id WHERE t1.review_count > 100 AND t2.category_name = "宠物梳理师";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (business_id VARCHAR, review_count INTEGER), CREATE TABLE review (text VARCHAR, business_id VARCHAR)
找出所有超过100个评论的“宠物梳理师”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "东莞" AND t2.category_name = "啤酒厂";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
在“东莞”的“啤酒厂”有哪些?
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "东莞" AND t2.category_name = "啤酒厂";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
找出“东莞”的所有“啤酒厂”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "厦门" AND t2.category_name = "啤酒厂";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
中找处在“厦门”所有的“啤酒厂”
SELECT t4.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t1.name = "沙县小吃" AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR), CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
找出所有评论“沙县小吃”“餐厅”的用户
SELECT full_address FROM business WHERE city = "东莞" AND name = "沃尔玛";
CREATE TABLE business (name VARCHAR, city VARCHAR, full_address VARCHAR)
列出在“东莞”所有“沃尔玛”的地址
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t1.city = "重庆" AND t2.category_name = "餐厅" AND t4.name = "赵毅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR), CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
找出“赵毅”评论的所有在“重庆”的“餐厅”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t1.city = "重庆" AND t2.category_name = "餐厅" AND t4.name = "赵毅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR), CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
“重庆”的哪些“餐厅”被“赵毅”评论过?
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t2.category_name = "酒吧" AND t4.name = "赵毅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR), CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
找出“赵毅”评论的所有的“酒吧”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t1.rating >= 3 AND t2.category_name = "酒吧" AND t4.name = "赵毅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, rating INTEGER), CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
找出所有由“赵毅”评论的至少有3颗星的“酒吧”。
SELECT t3.name FROM tip AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN USER AS t3 ON t3.user_id = t2.user_id WHERE t1.name = "喜茶" AND t2.year = 2015;
CREATE TABLE tip (year VARCHAR, user_id VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
找出在2015年所有为“喜茶”写过评论的用户
SELECT name FROM business WHERE rating < 2 AND state = "云南";
CREATE TABLE business (state VARCHAR, name VARCHAR, rating INTEGER)
在“云南”找出所有低于2分的企业
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id WHERE t1.city = "厦门" AND t2.category_name = "海鲜" AND t3.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
找出所有在“厦门”的“海鲜”“餐厅”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id WHERE t1.city = "厦门" AND t2.category_name = "海鲜" AND t3.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
列出“厦门”所有的“海鲜”“餐厅”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id WHERE t1.city = "厦门" AND t2.category_name = "海鲜" AND t3.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
找出“厦门”供应“海鲜”的“餐厅”
SELECT t1.text FROM USER AS t2 JOIN review AS t1 ON t2.user_id = t1.user_id WHERE t1.rating > 4 AND t2.name = "赵毅";
CREATE TABLE USER (user_id VARCHAR, name VARCHAR), CREATE TABLE review (text VARCHAR, user_id VARCHAR, rating INTEGER)
找出评分高于4分的“赵毅”的所有评论,
SELECT business_id FROM business WHERE city = "厦门" AND name = "苹果店";
CREATE TABLE business (name VARCHAR, city VARCHAR, business_id VARCHAR)
在“厦门”中找出所有“苹果店”
SELECT t1.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "成都" AND t1.rating > 4.5 AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, rating INTEGER, city VARCHAR)
找出评级高于4.5分的“成都”“餐厅”
SELECT t1.neighbourhood_name FROM category AS t3 JOIN business AS t2 ON t3.business_id = t2.business_id JOIN neighbourhood AS t1 ON t1.business_id = t2.business_id WHERE t2.name = "海底捞" AND t3.category_name = "餐馆";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR), CREATE TABLE neighbourhood (neighbourhood_name VARCHAR, business_id VARCHAR)
“海底捞”附近的“餐馆”是什么?
SELECT t2.text FROM tip AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "便宜坊" AND t2.likes > 9;
CREATE TABLE tip (text VARCHAR, business_id VARCHAR, likes INTEGER), CREATE TABLE business (name VARCHAR, business_id VARCHAR)
找出关于收到超过9个赞的“便宜坊”的所有提示
SELECT t2.text FROM review AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "探鱼" AND t2.year = 2014;
CREATE TABLE review (text VARCHAR, year VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR)
找出2014年度“探鱼”的所有评论
SELECT t3.name FROM tip AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN USER AS t3 ON t3.user_id = t2.user_id WHERE t1.city = "成都";
CREATE TABLE tip (user_id VARCHAR, business_id VARCHAR), CREATE TABLE business (city VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
找出所有写在“成都”的餐馆的评论的用户
SELECT t1.city FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "海盗船自助餐" AND t1.state = "云南" AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (state VARCHAR, name VARCHAR, city VARCHAR, business_id VARCHAR)
在“云南”省的所有城市里找出一家名为“海盗船自助餐”的“餐厅”。
SELECT t4.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN tip AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t2.category_name = "宠物梳理师";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (business_id VARCHAR), CREATE TABLE tip (user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
找出“宠物梳理师”评论的用户
SELECT t2.text FROM tip AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "星巴克" AND t1.state = "云南";
CREATE TABLE tip (text VARCHAR, business_id VARCHAR), CREATE TABLE business (state VARCHAR, name VARCHAR, business_id VARCHAR)
找出“云南”“星巴克”的所有评论。
SELECT t4.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t2.category_name = "餐馆";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (business_id VARCHAR), CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
列出所有审查“餐馆”业务的用户。
SELECT t2.text FROM tip AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "星巴克" AND t1.state = "黑龙江" AND t2.year = 2010;
CREATE TABLE tip (text VARCHAR, year VARCHAR, business_id VARCHAR), CREATE TABLE business (state VARCHAR, name VARCHAR, business_id VARCHAR)
列出2010在“黑龙江”的“星巴克”的所有提示。
SELECT t4.name FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN review AS t3 ON t3.business_id = t1.business_id JOIN USER AS t4 ON t4.user_id = t3.user_id WHERE t2.category_name = "餐馆" AND t3.year = 2010;
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (business_id VARCHAR), CREATE TABLE review (year VARCHAR, user_id VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
列出所有在2010的做“餐馆”生意的用户。
SELECT t2.text FROM USER AS t3 JOIN review AS t1 ON t3.user_id = t1.user_id JOIN tip AS t2 ON t3.user_id = t2.user_id WHERE t1.year = 2012;
CREATE TABLE USER (user_id VARCHAR), CREATE TABLE review (year VARCHAR, user_id VARCHAR), CREATE TABLE tip (text VARCHAR, user_id VARCHAR)
找出在2012编写评论的用户的所有提示
SELECT t2.text FROM review AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.rating = 2.5;
CREATE TABLE review (text VARCHAR, business_id VARCHAR), CREATE TABLE business (business_id VARCHAR, rating VARCHAR)
查找所有评分为2.5的企业的评论
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "成都" AND t2.category_name = "逃生游戏";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
在“成都”找出“逃生游戏”的数量
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "成都" AND t2.category_name = "逃生游戏";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
“成都”“逃生游戏”的数量是多少?
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "成都" AND t2.category_name = "逃生游戏";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
“成都”有多少“逃生游戏”
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "成都" AND t2.category_name = "逃生游戏";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
在“成都”中“逃生游戏”的数量是多少?
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "成都" AND t2.category_name = "逃生游戏";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, city VARCHAR)
“成都”有多少家“逃生游戏”?
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.rating > 3.5 AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, rating INTEGER)
找出评分超过3.5的“餐厅”
SELECT SUM ( t4.count ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id JOIN checkin AS t4 ON t4.business_id = t1.business_id WHERE t1.city = "厦门" AND t2.category_name = "餐厅" AND t3.category_name = "摩洛哥";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (city VARCHAR, business_id VARCHAR), CREATE TABLE checkin (count INTEGER, business_id VARCHAR)
找出在“厦门”的“摩洛哥”“餐厅”总访问数
SELECT SUM ( t4.count ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id JOIN checkin AS t4 ON t4.business_id = t1.business_id WHERE t1.city = "厦门" AND t2.category_name = "摩洛哥" AND t3.category_name = "餐厅" AND t4.day = "星期五";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (city VARCHAR, business_id VARCHAR), CREATE TABLE checkin (count INTEGER, business_id VARCHAR, day VARCHAR)
找出“星期五”在“厦门”“摩洛哥”“餐厅”的总访问数
SELECT t4.day , SUM ( t4.count ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id JOIN checkin AS t4 ON t4.business_id = t1.business_id WHERE t1.city = "厦门" AND t2.category_name = "摩洛哥" AND t3.category_name = "餐厅" GROUP BY t4.day;
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (city VARCHAR, business_id VARCHAR), CREATE TABLE checkin (count INTEGER, business_id VARCHAR, day VARCHAR)
找出每天在“厦门”“摩洛哥”“餐厅”的总访问数
SELECT t1.state , SUM ( t4.count ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN category AS t3 ON t3.business_id = t1.business_id JOIN checkin AS t4 ON t4.business_id = t1.business_id WHERE t2.category_name = "意大利" AND t3.category_name = "餐馆" AND t4.day = "星期日" GROUP BY t1.state;
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (state VARCHAR, business_id VARCHAR), CREATE TABLE checkin (count INTEGER, business_id VARCHAR, day VARCHAR)
找出“星期日”在每一个省的“意大利”“餐厅”的总访问数
SELECT COUNT ( DISTINCT t1.text ) FROM USER AS t2 JOIN review AS t1 ON t2.user_id = t1.user_id WHERE t1.year = 2015 AND t2.name = "王岩";
CREATE TABLE USER (user_id VARCHAR, name VARCHAR), CREATE TABLE review (text VARCHAR, year VARCHAR, user_id VARCHAR)
在2015年“王岩”写了多少评论
SELECT AVG ( t1.rating ) FROM USER AS t2 JOIN review AS t1 ON t2.user_id = t1.user_id WHERE t2.name = "米雪";
CREATE TABLE USER (user_id VARCHAR, name VARCHAR), CREATE TABLE review (user_id VARCHAR, rating INTEGER)
“米雪”的评论中的平均评级是多少?
SELECT t2.count FROM checkin AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.name = "星巴克" AND t2.day = "星期五";
CREATE TABLE checkin (count VARCHAR, business_id VARCHAR, day VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR)
“星巴克”在“星期五”的访问数数是多少?
SELECT COUNT ( DISTINCT t3.name ) FROM review AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id JOIN USER AS t3 ON t3.user_id = t2.user_id WHERE t1.city = "杭州" AND t1.name = "外婆家";
CREATE TABLE review (user_id VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, city VARCHAR, business_id VARCHAR), CREATE TABLE USER (user_id VARCHAR, name VARCHAR)
“杭州”有多少网友评论“外婆家”
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id = t1.business_id WHERE t1.city = "杭州" AND t1.rating = 4.5 AND t2.category_name = "餐厅";
CREATE TABLE category (category_name VARCHAR, business_id VARCHAR), CREATE TABLE business (name VARCHAR, business_id VARCHAR, rating VARCHAR, city VARCHAR)
“杭州”4.5分的“餐厅”的数量是多少?
SELECT COUNT ( DISTINCT text ) FROM tip WHERE YEAR = 2015;
CREATE TABLE tip (text VARCHAR, YEAR VARCHAR)
写在2015年的评论有多少
SELECT SUM ( t1.likes ) FROM USER AS t2 JOIN tip AS t1 ON t2.user_id = t1.user_id WHERE t2.name = "王岩";
CREATE TABLE USER (user_id VARCHAR, name VARCHAR), CREATE TABLE tip (user_id VARCHAR, likes INTEGER)
“王岩”提示的总赞数是什么?