row_id
int64
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36.7k
QuestionId
int64
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QuestionText
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MC_Answer
stringclasses
49 values
StudentExplanation
stringlengths
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Category
stringclasses
6 values
Misconception
stringclasses
35 values
10,700
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
it's a because you divide by the bottom times by the top
True_Correct
null
10,701
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
it's more than half and the only answer with more than half and makes sense is A=72
True_Correct
null
10,702
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
its a since 100 is 20 and 20 is 4 so 24x3 is 72
True_Correct
null
10,703
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
its going up in 24 so if you do 24 x 3 you get 72
True_Correct
null
10,704
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
its the only one it can be because 60 would be 2.5 over 5 but 72 would be A.
True_Correct
null
10,705
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
its the only one over halfway
True_Correct
null
10,706
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
l think this because 3/5 of 120 is 72.
True_Correct
null
10,707
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
make 120 into a fifth then times it by 3
True_Correct
null
10,708
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
make it 6/10 and divide by bottom and times by top
True_Correct
null
10,709
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
multiply the fraction so the denominator is 120 then the numorator will be the answer
True_Correct
null
10,710
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
my mom helped me with this one
True_Neither
null
10,711
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
my mummy and my brother did it for me because i did not understand .
True_Neither
null
10,712
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
my teacher explained it to me
True_Neither
null
10,713
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
of means X, so 3/5 of/X 120 = 72
True_Correct
null
10,714
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth equals 24 since you want 3 fifths you times 24 by 3 and it gives you 72
True_Correct
null
10,715
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth is 24 24 times 3 is 72
True_Correct
null
10,716
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth is 24 so times 24 by 3 which equals 72
True_Correct
null
10,717
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth is 24 then you times that by 3 to get 72
True_Correct
null
10,718
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth is 24 times 3 equals 72
True_Correct
null
10,719
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth is 24, so 3 fifths are 72
True_Correct
null
10,720
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth is 24, so 3 fifths is 72
True_Correct
null
10,721
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth of 120 = 24 so 24 x 3 = 3 fifths = 72
True_Correct
null
10,722
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth of 120 is 24 24 times 3 is 72
True_Correct
null
10,723
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
one fifth of 120 is 24 and 24 times by 3=72
True_Correct
null
10,724
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
only thing it can be .
True_Neither
null
10,725
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
right so you do 120 divided by your firve and you tines 24 wby 3
True_Correct
null
10,726
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
since 120 divided by 5 is 24 24 x 3 = 72
True_Correct
null
10,727
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
sixty is half so it would have to be over
True_Correct
null
10,728
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
so 3/5 of 120 is 120 divided by 5 is 24 then 24*3 is 72
True_Correct
null
10,729
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
so i put this because . i divided 120 by 5 and multiplied by 3
True_Correct
null
10,730
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
teacher did it on the board
True_Neither
null
10,731
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
that is what i got on pen and papper
True_Neither
null
10,732
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
the 3/5 red counters is higher than a 1/2 so you will pick the highest one
True_Correct
null
10,733
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
the answer is 72 because 3/5 as a percentage is 60% so 60% of 120 is 72
True_Correct
null
10,734
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
the answer is a as you have to work out 3/5 of 120 which equals 72 so a is the answer.
True_Correct
null
10,735
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
think it is 72 because it is the biggest number there
True_Neither
null
10,736
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this is as 120 divided by 5 =24. 24 timze 3=72
True_Correct
null
10,737
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this is because 120 divide it by 5 is 24. 24 times 3 is 72.
True_Correct
null
10,738
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this is because 120 divided by 5 is 24 and that times by 3 is 72
True_Correct
null
10,739
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this is because you do 120 divided by 5 and then 24 multiplied by 3
True_Correct
null
10,740
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this is because you find 3/5 of 120 which is 72
True_Correct
null
10,741
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this is the answer because u have to divide 120 by 5 (24)then times 24 by 3
True_Correct
null
10,742
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this looked like a reasonable answer
True_Neither
null
10,743
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
this time i did 120 divided by 5, which was 24, then timesed that by 3 which gave me 72.
True_Correct
null
10,744
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
to find 1/5 = 120 divided by 5 = 24. 24 x 3 = 72
True_Correct
null
10,745
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
to get one 5th you divide by five then to get three of them you times that by 3
True_Correct
null
10,746
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
to work out 3/5 of 120, you do 120 divided by 5 which equals 24 and then 24 times 3 equals 72 so your answer is 72
True_Correct
null
10,747
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
to work out the answer I divided 120 by 5 and multiplied the answer by 3
True_Correct
null
10,748
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
too me it makes the most logical sence
True_Neither
null
10,749
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
we did this one as a class
True_Neither
null
10,750
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
we times 3/5 by 120 and times again by 3
True_Neither
null
10,751
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
well 60 is half and 3/5 is close to 1/2 so 72 is the answer
True_Neither
null
10,752
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
well i realy dont know but it just seems right
True_Neither
null
10,753
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
what u have to do is divied 120 by 5 then add the answer 3 times
True_Correct
null
10,754
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
work out what 1/5 is and times by 3
True_Correct
null
10,755
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you didvide by 5then x by 3
True_Correct
null
10,756
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you divide 120 by 5 and then times 24 by 3 ten you got 72
True_Correct
null
10,757
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you divide 5 by 120 then times 24 by 3
True_Correct
null
10,758
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you divide by the bottom and times by the top
True_Correct
null
10,759
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you divied the denomnater and times by the denomnayer
True_Neither
null
10,760
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do 1/5 of 120 witch is 24 then times that by 3
True_Correct
null
10,761
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do 120 divided by 5 then multiply it by 3
True_Correct
null
10,762
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do 120 divided by 5 times by 3 and you get 72
True_Correct
null
10,763
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do 120 divided by 5 which is 24 then you do 24 times 3 then you get your answer 72
True_Correct
null
10,764
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do 3/5 into a persent and that is 60% and then do 60% of 120.
True_Correct
null
10,765
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do 3/5 of 120 which is 72
True_Correct
null
10,766
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do 3/5 of 120 which is 72
True_Correct
null
10,767
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you do the formula is over of and then percent over 100 and 3/5 into a percent is 60%. Do the problem and you get 72.
True_Correct
null
10,768
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you have to divide 120 by 5 then times it by 3
True_Correct
null
10,769
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you have to times 5 by 120 then divide 3
True_Correct
null
10,770
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you have to x 5 by 10 then add 10 then add 12
True_Neither
null
10,771
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you just divide 120 by 5 then times the answer by 3 to get the answer which is 72
True_Correct
null
10,772
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you need to 5 divide 120 and i got 24 then i did 3 times 24 and i got 72 and 72 is the answer.
True_Correct
null
10,773
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you need to add up the 24 3 times
True_Correct
null
10,774
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you need to covert the denominator to 120 then the numerator out of 120
True_Correct
null
10,775
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you need to divide 120 by 5 and times the answer by 3
True_Correct
null
10,776
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you need to divide 120 by 5 to get 24 and then times it by the numerator which is 72.
True_Correct
null
10,777
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you work out one fifth and times it by 3
True_Correct
null
10,778
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you workout 3 out 5 of 120 what is 72
True_Correct
null
10,779
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you would find 1/5 by dividing by 5 which is 24, so to find 3/5 you would multiply 24 by 3, which is 72
True_Correct
null
10,780
31,777
A box contains \( 120 \) counters. The counters are red or blue. \( \frac{3}{5} \) of the counters are red. How many red counters are there?
\( 72 \)
you would have to divide 5 then times by 3
True_Correct
null
10,781
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
(っ◔◡◔)っ ♥ I understand but i don`t need to write why ♥
False_Neither
null
10,782
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
1/10=3/15,Times that by 3 giving you 9/15 and thus making it 3/10=A
False_Neither
null
10,783
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
1/10=3/15,Times that by 3, givingg you 9/15 and thus making it 3/10 =A
False_Neither
null
10,784
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
10 pkus 5 is 15, and 4 plus 3 is 9.
False_Misconception
Additive
10,785
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
10 plus five is 15 and 4 plus 5 is 9
False_Misconception
Additive
10,786
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
10/2 is 5 and 5x3 is 15 so if I do the same it is 3
False_Neither
null
10,787
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
10/2 is 5 andd 5x3 is 15 so if I do the same it is 3.
False_Misconception
Irrelevant
10,788
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
10x3=30 So then something x 3 = 9 and I know that 3x3=9. So 3 is the value.
False_Misconception
Irrelevant
10,789
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
10x3=30 15x3=30 ax3=9 so the value of a is 3
False_Misconception
Irrelevant
10,790
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
15 doesn't go into 15 so you convert it to 30 and 3x3=9
False_Misconception
Irrelevant
10,791
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
15 doesn't go into 15, so you convert it to 30 snd 3x3=9.
False_Misconception
Irrelevant
10,792
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
15 is a multiple of 5 and so is 15. if a
False_Misconception
Irrelevant
10,793
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
15 is the third number of the 5 times table
False_Misconception
Irrelevant
10,794
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
15-5=10 so 9-5=3 so it should be 3/10
False_Misconception
Additive
10,795
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
3 because 3 times by 3 is nine
False_Misconception
Irrelevant
10,796
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
3 because 3x3 = and then the dinominator ads 5
False_Misconception
Irrelevant
10,797
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
3 because 3x3 = and then the dinominator adds 5
False_Misconception
Irrelevant
10,798
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
3 because if you simplify 9/15 you get 3/10.
False_Neither
null
10,799
31,778
\( \frac{A}{10}=\frac{9}{15} \) What is the value of \( A \) ?
\( 3 \)
3 because it hoes in 9 and 15
False_Misconception
Irrelevant